#help-13

1 messages · Page 336 of 1

queen ice
#

5
6

#

Make sure the order stays the same, it’s important here

#

Now how about the fourth

tame sleet
#

8

#

6

#

6, 8

queen ice
#

So we have

Bottom length: 3 4 5 6
Side length: 2 4 6 8

#

Do you see a pattern here?

tame sleet
#

add 2 to sides add 1 to length?

queen ice
#

Indeed

#

Can you express the two with a formula? One for the sides and one for the bottom

#

In terms of n

tame sleet
#

n +1 n + 2

queen ice
#

Not quite

#

n isn’t the last element

#

n is the index of the element

#

So if you have a formula n+2 for example, the first element would be 3 (cause n=1), the second 4 (cause n=2) etc

#

But the +2 is already quite close. For the first element, how many times have we added 2 to 0?

#

Considering that the first element is 2

tame sleet
#

?

queen ice
#

Once

#

0+2 =2

#

How many times do we add 2 to get the second element (4)?

queen ice
#

@tame sleet

cedar kilnBOT
#

@tame sleet Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

burnt siren
#

the final answer was 3 sqrt 21 for both SU and TU, but squareroot 189 isn’t 3 x 21? 9 x 21 equals 189 so how did it simplify that way?

burnt siren
#

in the sense of, how did square root 189 simplify into 3 sqrt 21?

cedar kilnBOT
#

@burnt siren Has your question been resolved?

brave nimbus
cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

compact gulch
#

Can someone tell me why when proving the Probability Generating function of a Binomial and Poisson distribution they take the summation from r = 0

compact gulch
#

But for Geometric and Uniform distribution it is from r = 1

drifting marlin
#

I assume those latter two are such that P(X=0) = 0

cedar kilnBOT
#

@compact gulch Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

solar vector
#

.reopen

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

devout zealot
#

Is this normal

cedar kilnBOT
devout zealot
#

Click to see full picture

hollow trail
#

well if you get an equation that is always true at the end, then the solutions to that equation are all x (for which the equation makes sense in the first place)

devout zealot
#

So all x greater than 0

azure swift
#

yeah

#

which should make sense

#

since the rules you used as an equality are true for all positive x

#

this in turn i think might give a helpful perspective on the rules

#

as theyre merely equations that holds for most x's

devout zealot
#

thank you

cedar kilnBOT
#

@devout zealot Has your question been resolved?

#
Channel closed

Closed by @devout zealot

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

tall brook
#

Is my notation correct? I'm trying to define two parameters for a dataset (x). The first is "the percent of datapoints below 6" and the second is "the number of datapoints where both that point and the next point are below 6".

vivid wadi
#

as long as you clarify, any notation is correct

tall brook
#

Oh, is that right? Sorry, math isn't my major so I assumed this sort of thing was more rigid ^^;

#

Thanks!

#

.close

cedar kilnBOT
#
Channel closed

Closed by @tall brook

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

stark bronze
#

Why is the third term dervied to 0? Is it because it has no x term and is treated as a constant?

hollow trail
#

yes, 7y^2 is a constant for the purposes of differentiating with respect to x

stark bronze
#

thanks so much!

#

.close

cedar kilnBOT
#
Channel closed

Closed by @stark bronze

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

#
Channel closed

Closed by @lucid escarp

Use .reopen if this was a mistake.

lucid escarp
#

How do I get this last value

hollow trail
#

use the x-intercept

lucid escarp
#

yes but idk how to use it

hollow trail
#

well you know that (1/4, 0) is a point on your graph

lucid escarp
#

is it just 1/2

hollow trail
#

how do you get 1/2?

lucid escarp
#

0.5/2 = 1/4

#

because you set all the x as 0

hollow trail
#

no, that's the y-intercept

#

the x intercept is where you set y = 0

lucid escarp
#

so how should i approach this

hollow trail
#

plug in x = 1/4, and set your function equal to 0

#

because x = 1/4, y = 0 is a point on your function

lucid escarp
#

like as a variable

hollow trail
#

maybe you should call it something else, but you are trying to solve for it

lucid escarp
#

ok thank you

#

.close

#

oop already closed

#

.reopen

#

.close

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

compact quest
cedar kilnBOT
compact quest
#

<@&286206848099549185>

#

is my approach correct?

heady gate
#

Hm

compact quest
cedar kilnBOT
#

@compact quest Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

orchid jewel
#

what does defines the function mean?

cedar kilnBOT
south tundra
#

In this case it means which equation describes the assignment rule of f, i.e., what formula does f(x) have

orchid jewel
south tundra
#

Yes, the picture shows the graph of y = f(x) and you are asked to find the f(x)

south tundra
#

Yeah

orchid jewel
#

Im confused about this too

#

this is from my SAT practice test

south tundra
#

Ah they are showing the graph of y = f(x) + 14, I misread that

#

So you need to subtract 14 from -x/4 + 2

orchid jewel
south tundra
#

Same thing

orchid jewel
#

but when I graphed C. its not the same as the picture shown

south tundra
#

Again, it's not supposed to be the same

#

The picture shows the graph of y = f(x) + 14

orchid jewel
south tundra
#

Yes, and subtracting 14 from that will give you f(x)

orchid jewel
#

is it asking me what turns y = f(x) + 14 into Y=Mx + B formula??

#

if so I understand now

south tundra
#

Where y = mx + b gives you the given graph, yes

orchid jewel
#

ok tysm

#

.close

cedar kilnBOT
#
Channel closed

Closed by @orchid jewel

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

junior stratus
cedar kilnBOT
junior stratus
#

How.

noble stump
#

how do i calculate a sum of n factorials?

junior stratus
#

, rotate

wraith daggerBOT
junior stratus
noble stump
#

1!+2!+3!+4!+........+n!

#

do i just use gamma function?

slender ginkgo
slender ginkgo
junior stratus
#

How

#

I cant conjugate or apply new terms

#

It comes out diff

slender ginkgo
#

?

#

It’s splitting fraction

junior stratus
vague sparrow
#

I think of it as adding 0 in a fancy was in the numerator as: sqrt(5) - sqrt(5)

junior stratus
#

Now why the fuck did I not think of that

vague sparrow
#

catshrug dont be so harsh on yourself, math has a lot of tricks

cedar kilnBOT
#

@junior stratus Has your question been resolved?

junior stratus
#

.close

cedar kilnBOT
#
Channel closed

Closed by @junior stratus

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

stoic crystal
cedar kilnBOT
stoic crystal
#

Determine if the series ( \sum_{n=1}^{\infty} \left( \frac{4^n}{9^{n+1}} - \frac{3^{n+1}}{4^n} \right) ) is convergent, and if so, calculate its sum.

wraith daggerBOT
#

938c2cc0dcc05f2b68c4287040cfcf71

stoic crystal
#

,, \sum_{n=1}^{\infty} \left( \frac{4^n}{9^{n+1}} - \frac{3^{n+1}}{4^n} \right) \ \frac{1}{9}\sum_{n = 1}^{\infty} \left(\frac{4}{9}\right)^n - 3\sum_{n=1}^{\infty} \left(\frac{3}{4}\right)^n \ \textbf{I am trying to calculate the sum of the geometric series }

#

a1 = 1/9 x 4/9

#

a2 = 3 x 3/4

#

r1 = 4/9

#

r2 = 3/4

wraith daggerBOT
#

938c2cc0dcc05f2b68c4287040cfcf71

stoic crystal
#

,, \begin{cases} a_1 = \frac{1}{9} \cdot \frac{4}{9} \\ a_2 = 3 \cdot \frac{3}{4} \\ r_1 = \frac{4}{9} \\ r_2 = \frac{3}{4} \end{cases}

#

,, \textbf{sum of infinte geometric series} \ = \frac{a}{1-r}

wraith daggerBOT
#

938c2cc0dcc05f2b68c4287040cfcf71

#

938c2cc0dcc05f2b68c4287040cfcf71

stoic crystal
#

,, \textbf{sum :} \ \frac{1}{9} \cdot \frac{4/81}{1 - \frac{4}{9}} -3 \frac{9/4}{ 1 - \frac{3}{4}} \ = \left[\frac{1}{9} \cdot \frac{4}{81} \cdot \frac{1}{1-\frac{4}{9}} \right] - \left[3 \cdot \frac{9}{4} \cdot \frac{1}{1- \frac{3}{4}}\right] \ = \left[\frac{1}{9} \cdot \frac{4}{81} \cdot \frac{9}{5} \right] - \left[ 3 \cdot \frac{9}{4} \cdot 4 \right] \ = \left[ \frac{4}{81} \cdot \frac{1}{5} \right] - \left[3 \cdot 9 \right] \ = \frac{4}{81 \cdot 5} - 27 = - \frac{10931}{405}

#

,, \textbf{Auxiliary Calculation 1: } \ \frac{1}{1 - \frac{4}{9}} = \frac{9}{5} \ \textbf{Auxiliary Calculation 2: } \ \frac{1}{1-\frac{3}{4}} = 4

wraith daggerBOT
#

938c2cc0dcc05f2b68c4287040cfcf71

#

938c2cc0dcc05f2b68c4287040cfcf71

stoic crystal
#

so the sum is

#

$\textbf{Sum} \cong -26.99012346$

wraith daggerBOT
#

938c2cc0dcc05f2b68c4287040cfcf71

stoic crystal
#

,calc -401/45

wraith daggerBOT
#

Result:

-8.9111111111111
stoic crystal
#

xd

#

I made a mistake somewhere

#

or maybe I did not idk

cedar kilnBOT
#

@stoic crystal Has your question been resolved?

cedar kilnBOT
#

@stoic crystal Has your question been resolved?

dreamy void
#

,w Sum[(4^n/9^(n+1)-3^(n+1)/4^n),{n,1,inf}]

dreamy void
#

,calc 4/81 * (1/(1-4/9)) - 9/4 *(1/(1-3/4))

wraith daggerBOT
#

Result:

-8.9111111111111
dreamy void
#

Now you did it here a second time which lead to the wrong result

stoic crystal
#

thank u bacc

#

.solved

cedar kilnBOT
#
Channel closed

Closed by @stoic crystal

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

half glacier
#

hello

cedar kilnBOT
half glacier
#

need help for this

#

i transformed to 2sin(2x-pi/6)<=-1

#

x = 0+2kpi and 2pi/3 + 2kpi then idk what to do

pastel vault
#

first of all, the period of this equation is pi, cause 2pi/2 = pi

#

so should be x = 0 + kpi and x = 2pi/3 + kpi

#

since 2 is positive, that means we have a normal-looking sine graph, so it increases from x = 0
(cause when x = pi/6, you get y = 0)

#

so we don't want the region between x = 0 and 2pi/3

#

we want the region between 2pi/3 and pi

#

so 2pi/3 + pi k <= x <= pi k is our answer, for $k \in \mathbb Z$

wraith daggerBOT
#

south's secret twin brother

pastel vault
#

we didn't have to test x = pi/6 specifically: any nice value works

half glacier
#

hmm

half glacier
pastel vault
half glacier
#

i dont get why the period is pi

clear ember
#

which has a period of 2pi

half glacier
#

yes

clear ember
#

sin(2x) is sin(x) but compressed

#

so whatever that used to happen at pi (for example)

#

now happens at pi/2

#

so the whole "cycle" is just half of what it used to be

half glacier
#

yeah so the period is pi because of the 2 in 2x ?

clear ember
#

if you're concerned with the formula

wraith daggerBOT
half glacier
#

yeah whats the formula

clear ember
#

the period = 2pi/(coefficient of x) or 2pi/b

half glacier
#

2p/b

#

ok ty

#

@clear ember

#

so the solution are this ?

cedar kilnBOT
#

@half glacier Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

proven stirrup
cedar kilnBOT
proven stirrup
#

<@&286206848099549185>

#

the function isnt surjective right so does that mean that the inverted funciton doesnt exist?

cedar kilnBOT
# proven stirrup <@&286206848099549185>

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

#

@proven stirrup Has your question been resolved?

proven stirrup
#

<@&286206848099549185>

cedar rampart
#

i think it does exist

#

cause its injective

#

so it would be b

cedar kilnBOT
#

@proven stirrup Has your question been resolved?

proven stirrup
#

doesnt it need to be surjective too

#

i think it does

#

and it isnt

gray sleet
#

Each different letter in this addition problem stands for a different digit. A letter stands for the same digit everywhere it appears. Find the value of TEST. HE+SET+THE = TEST

cedar kilnBOT
#

@proven stirrup Has your question been resolved?

proven stirrup
#

isnt there anyone who is sure of an answer

proven stirrup
#

.CLOSE

#

.close

cedar kilnBOT
#
Channel closed

Closed by @proven stirrup

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

velvet mauve
cedar kilnBOT
velvet mauve
#

Look at 3a, i have the vertical and horizontal asymptotes

#

As well as the x and y intercepts

#

But im confused on how to actually graph the function

#

Could someone explain it to me?

cedar kilnBOT
#

@velvet mauve Has your question been resolved?

velvet mauve
#

.close

cedar kilnBOT
#
Channel closed

Closed by @velvet mauve

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

signal grail
#

Hello, everyone,
Could anyone please help me out to understand, is it possible to complete this task without plotting ? I dont really want to relay only on plotting, I hope there is some algebraic way to complete this

cedar kilnBOT
#

@signal grail Has your question been resolved?

signal grail
#

<@&286206848099549185>

vivid wadi
#

as 9 is part of the domain, it should be continuous at 9, but the limit as x approaches 9 of f(x) from the left is different from the limit as it approaches from the right

cedar kilnBOT
#

@signal grail Has your question been resolved?

cedar kilnBOT
#

@signal grail Has your question been resolved?

#
Channel closed

Closed by @signal grail

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

sturdy parcel
#

<@&286206848099549185> can u guys explain proportionality to me?

sturdy parcel
#

pls

#

.close

cedar kilnBOT
#
Channel closed

Closed by @sturdy parcel

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

cedar kilnBOT
#

@wheat sphinx Has your question been resolved?

#
Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

versed nova
#

We model a speed control system for a bicycle using a chain, a front sprocket (P) with a radius R = 10 cm, and several rear sprockets (P₁) with different radii r₁ between 2 cm and 8 cm. The front and rear sprockets are connected by a non-slip chain. (See Figure 1)

  • Let ω be the angular velocity of the front sprocket (P) and ω₁ the angular velocity of a rear sprocket (P₁) with radius r₁.
    Show that: ω₁ = (R/r₁)ω (1 pt)
  • 2.1. Calculate the number of turns n₁ made by the rear sprocket P₁ with radius r₁ = 2 cm when the front sprocket makes one turn.
    2.2. Let nᵢ be the number of turns made by the rear sprocket (Pᵢ) with radius rᵢ corresponding to the maximum value of rᵢ. Calculate nᵢ
versed nova
#

<@&286206848099549185>

cedar kilnBOT
#

@versed nova Has your question been resolved?

versed nova
#

<@&268886789983436800>

celest seal
#

please dont ping mods for math help

#

have you considered posting what you've tried and where you're stuck so people know how to help you?

versed nova
#

.close

cedar kilnBOT
#
Channel closed

Closed by @versed nova

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

dark mason
#

Need help with induction proof.

cedar kilnBOT
#

@dark mason Has your question been resolved?

dark mason
#

<@&286206848099549185>

cedar kilnBOT
#

@dark mason Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

ancient vector
cedar kilnBOT
ancient vector
#

How to proceed?

hollow trail
#

are there any simplifications you could apply to the numerator?

ancient vector
#

I'm trying to cancel out the h on the bottom but unsure what to do

#

Can't just shove in 0

#

It's been a while since I used this method. Totally forget what I can do

hollow trail
#

ok well are there any subtractions that might be performed?

ancient vector
#

Not sure what ur asking to be honest

hollow trail
#

if i had 3 + x - 3, could you simplify that?

ancient vector
#

I think I need to do something to top n bottom

#

Ok simplify

#

Multiply top n bottom by conjugate?

hollow trail
#

yes

#

but you must simplify first

#

what is 1 - 1?

ancient vector
#

0

#

Got it....

hollow trail
#

great 👍

ancient vector
#

.close

cedar kilnBOT
#
Channel closed

Closed by @ancient vector

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

cursive perch
#

Trig questions, How would you solve this question? I don't understand what ratio to use since its not a right angle triangle

crimson sedge
#

Hello is this the right chat to ask statistics questions? Please educate me

dreamy void
#

the available channels are shown without name

crimson sedge
#

Can someone please help me with my assignment?

cedar kilnBOT
vivid radish
cursive perch
vivid radish
cursive perch
#

oh! thanks 😭

#

.close

cedar kilnBOT
#
Channel closed

Closed by @cursive perch

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

calm trail
#

When water freezes, its volume increases by 10.1%. a) If 150 L of water freezes, what is the increase in volume? b) Estimate the original volume of water frozen if the increase in volume is 22 L.

calm trail
#

help me pls

#

<@&286206848099549185>

merry solstice
calm trail
#

b)

#

b) Estimate the original volume of water frozen if the increase in volume is 22 L.

merry solstice
#

let the amount of water be X

calm trail
#

ok

merry solstice
#

we knnow it expands by 10.1%

calm trail
#

ye

merry solstice
#

so

#

X+10.1%*X=22

#

1.101x=22

#

x=19.98

calm trail
#

Can u also help with a)

#

@merry solstice

#

<@&286206848099549185>

merry solstice
#

but substitute 150 as x cause it's given

#

150+10.1%*150=(volume)

#

volume=16.51

calm trail
#

Isnt the increase of volume 15.15?

cedar kilnBOT
#

@calm trail Has your question been resolved?

cedar kilnBOT
#

@calm trail Has your question been resolved?

calm trail
#

@merry solstice

cedar kilnBOT
#

@calm trail Has your question been resolved?

cedar kilnBOT
#

@calm trail Has your question been resolved?

cedar kilnBOT
#

@calm trail Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

oak kayak
#

S

cedar kilnBOT
swift badger
#

hello.

oak kayak
#

How do I express this quadratic step by step into vertex form?

mossy cloud
#

i'm sorry im french so our expressions are different

#

oh you mean la forme canonique ?

oak kayak
oak kayak
mossy cloud
#

dw

#

wait a sec i'll do a step by step explanation

oak kayak
#

Thanks

#

I’m very noob at this

dense grove
mossy cloud
mossy cloud
mossy cloud
cedar kilnBOT
#

@oak kayak Has your question been resolved?

cedar kilnBOT
#

@oak kayak Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

echo timber
#

need help

cedar kilnBOT
#

Please don't occupy multiple help channels.

onyx reef
#

Pick 2 coordinates apply the formula

echo timber
vivid wadi
#

it's calculated with rise/run

#

where rise is change in y and run is change in x

echo timber
#

Yes I know that

#

But how can i find it

vivid wadi
#

rise/run

#

find two point

echo timber
#

5 and 7?

vivid wadi
onyx reef
#

Make sure u got the right coordinates

#

0,5 and 7,0

vivid wadi
echo timber
vivid wadi
#

its not clear its ar 0.5

onyx reef
#

Yea wait

#

7s not exact

vivid wadi
onyx reef
#

Try (0,5) and 4,2

#

Yea

vivid wadi
echo timber
#

Okay

#

If i have those points what now?

onyx reef
#

Apply the formula

echo timber
#

Ok i got it

#

.close

cedar kilnBOT
#
Channel closed

Closed by @echo timber

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lone lagoon
cedar kilnBOT
lone lagoon
#

I'm stuck with this one.

urban pulsar
#

What do you need to find

lone lagoon
#

Well, I get 7/√35* √5

#

And the problem is, yeah, I can replace that with √7*5

#

BUT THAT'S NOT A NOTABLE ANGLE!

lone lagoon
#

So, I know the formula

urban pulsar
#

I am working

lone lagoon
#

But like

#

7 cannot be cancelled with √7

urban pulsar
#

The answer is root 7/5

#

You are correct

urban pulsar
lone lagoon
#

That's not an angle xD

urban pulsar
#

Cos inverse

#

Of the value

#

Is the angle u get

#

Use a calculator

lone lagoon
#

Cos inverse?

#

They don't let you use calculators

crude quest
#

yes what formula are you using?

urban pulsar
#

0.490883 radian

lone lagoon
urban pulsar
#

Then just write arc cosine (root7/3)

#

That’s enough

crude quest
#

wouldnt it be dot product, not cross

lone lagoon
#

Based

#

Yeah.

#

afaik, it would be dot product

#

mostly because

#

the formula is based on doc product

#

Cross code doesn't involve cos, so you wouldn't be able to use the

urban pulsar
#

You can do it with cross also if you use sin

crude quest
#

yeah but its easier to do it with dot

urban pulsar
#

Dot product is easier

#

Yeahh

#

28.1255 degrees is your answer

#

@lone lagoon

lone lagoon
#

Oh I see

#

Thank you!

crude quest
#

ud prolly just leave it as a function of arccos if u cant use a calculator tho

#

im assuming on an exam

lone lagoon
#

Yeah.

#

@urban pulsar are derivates and primitives and integrals going to kill me

#

=[

urban pulsar
#

It is easy

#

You will get used to it

lone lagoon
#

BASED

urban pulsar
#

Close this channel and dm me

#

Let’s talk there

lone lagoon
#

. close

#

.close

cedar kilnBOT
#
Channel closed

Closed by @lone lagoon

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

onyx pollen
#

if $X$ and $Y$ are banach spaces is the closed and bounded ball ${\Lambda\in B(X,Y)|,||\Lambda||\leq M}$ compact

wraith daggerBOT
onyx pollen
#

i think this follows from banach steinhaus but im not sure

#

if not true in general then what about the case where Y=C so we are looking at a ball in the dual of some banach space (especially an Lp space)

#

real analysis is so hard

dire geode
onyx pollen
#

but i was told to ask here

#

i will ask in the one for the book i am reading

dire geode
#

And that's because you asked generically where to ask questions

onyx pollen
#

okay

dire geode
#

Feel free to stay

#

But you're better off asking a better targeted audience

onyx pollen
# wraith dagger **goat**

<@&286206848099549185> it has been 15 minutes this is my 15 minute ping to <@&286206848099549185> please help me with this problem

feral ice
#

¿Qué onda?

onyx pollen
pallid knoll
#

What can I help you with?

onyx pollen
wraith daggerBOT
pallid knoll
#

Oh shit

onyx pollen
#

basically does bounded imply totally bounded in this setting? if not what about when we require Y=C or Y=R or X=Lp

#

i think it should follow from banach steinhaus but im not sure

pallid knoll
#

What area of math is this?

onyx pollen
#

calculus

#

im kidding its real analysis

#

but people told me real analysis is meant to just be calculus so this is probably just calculus eventually

pallid knoll
#

The first calc class in my uni program had a little real analysis sprinkled in

onyx pollen
#

this class is real analysis class

#

but my friend told me real analysis is just calculus

onyx pollen
#

so maybe my calculus class just didnt do enough

#

because i dont remember learning about bounded operators in calculus

#

but i also skipped calculus 1 so maybe thats where you learn it

pallid knoll
#

bruh first time even hearing that word

onyx pollen
#

no nevermind heine borel is just Rn

pallid knoll
#

isn’t real analysis usually associated with like PhD studies?

#

like one of the final bosses of math

onyx pollen
#

i dont know im in this class because my friend told me its easy

#

basically just calculus

#

<@&286206848099549185> it has been 15 minutes again

swift badger
#

wsp

arctic hare
#

fr

onyx pollen
# swift badger wsp

if $X$ and $Y$ are banach spaces is the closed and bounded ball ${\Lambda\in B(X,Y)|,||\Lambda||\leq M}$ compact

wraith daggerBOT
round nacelle
cedar kilnBOT
#

@onyx pollen Has your question been resolved?

onyx pollen
#

no it hasnt been resolved yet

#

<@&286206848099549185> another 15 minutes

swift badger
#

Sorry

#

esp

#

wsp*

onyx pollen
# swift badger wsp*

if $X$ and $Y$ are banach spaces is the closed and bounded ball ${\Lambda\in B(X,Y)|,||\Lambda||\leq M}$ compact

wraith daggerBOT
swift badger
#

Ok so

#

in gerneral

#

no

#

a closed and bounded ball

#

is finite-dimensional

onyx pollen
#

it doesnt hold in general metric spaces i know but is it false in all infinte dimensional spaces

swift badger
#

idk what else t say

cedar kilnBOT
#

@onyx pollen Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

brisk shell
#

Can someone help me with this question pls is it just trial and error if so I’ve found 4 solutions do you think that’s all of the possible solutions?

brisk shell
#

<@&286206848099549185>

jovial marlin
#

what a weird question, what is this class called?

#

and by weird question i mean the M4 question. not ur question of asking for help

brisk shell
#

It’s from 10 th class mathematics

#

Could u help me pls if u can

austere dune
#

!status

cedar kilnBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
brisk shell
#

I got an answer and want to confirm if it’s right

jovial marlin
#

ngl I have never seen a question ask about the correct decimal place of some number in an addition problem

brisk shell
#

Oh alr

jovial marlin
#

its such a weird question to ask someone

brisk shell
#

True ig

jovial marlin
#

sorry chief, I hope someone else can help u out

brisk shell
#

Ty anyway

crimson sedge
#

(This is really just trial and error)

brisk shell
#

It’s not rly a proper solution I just did trial and error and got

#

Oh okay ty

#

I’ll send it now

#

1 second

jovial marlin
brisk shell
#

This is what I got

jovial marlin
#

hmm

#

oo nvm i misinterprete dthe question

#

oof

#

i was thinking that one decimal is incorrect and u need to change only one of them, not 4 out of the five

cedar kilnBOT
#

@brisk shell Has your question been resolved?

brisk shell
#

@crimson sedge

#

La’dies washroom pls help

jovial marlin
#

in class did u learn anything that could help u solve this? have u done similar problems before? I feel like there should be a way to solve this without brute forcing it

dire geode
#

,rotate

wraith daggerBOT
#

Couldn't find an attached image in the last 10 messages.

dire geode
#

pain

austere dune
#

<@&286206848099549185>

arctic hare
#

what seems to be the problem

austere dune
#

read the prev msg

arctic hare
arctic hare
#

oh damn thats long ago

austere dune
#

ye

arctic hare
#

the answer will have 3 decimal places not 2

austere dune
#

there r multiple answers

#

but is there any other way to approach this question without using brute forcing

#

?

arctic hare
#

i dont think soi

#

u just need to sum it up

austere dune
#

there has to be bcuz i think there r abt 576 combinations where u can switch the decimal places around

#

using combinatorics

arctic hare
#

uh

austere dune
#

and i don't think brute forcing is an efficient way

arctic hare
#

actually waait no its not gonna be 3 decimal places the decimal in 38.627 is wrong should be 386.27

austere dune
#

it can also be 3.8627

arctic hare
#

i doubt it

#

wait maybe not

#

there is infact a lot of ways to do this

#

wait no

#

it HAS to be 386.27

#

right???

#

yes

#

wait or the 4000 one

#

im confsuing myself

#

but also only 386.27 is the decimal assuming 4508.57 is the correct decimal

#

or vice versa

#

im gonna stop talikng

jovial marlin
#

This question is soo weird

#

I cant find an easy way to solve it without brute forcing it by guessing and checking

#

Sorry that i couldnt help :<

shy ice
#

Maybe go through the ways for each of the 4 cases where one is the correct decimal, so eg find out the ways when the 1st is the correct, then the 2nd, then 3rd then 4th. So considering the case where the 1st is correct, you can just add it on to the result (4508.57+47.5=4556.07) and then work out the possible shifts in the other 3. Then do the same for rest. I guess this doesn't really explain how to find all the ways without trial and error but it at least simplifies it a bit.

jovial marlin
#

for the higher math helpers that want to take a crack at the problem. I generalized the problem and got the following

#

where chi and C are just some constants that we can determine based on the given starting numbers of the question

#

so essentially the problem becomes solving for each n in this part of the math, since we know what each x and what C is. (also each n is an integer and represents the number of digits u need to shift each decmial point)

#

I cannot find a way to solve this without guessing and checking

#

I don't think it's possible to solve this question without brute force

#

@brisk shell u don't have to follow what I just did there, im using more advanced tools to solve the problem so other higher math people can see it better at a glance

#

hopefully someone can see this and maybe come up with a solution that doesnt involve guessing

#

<@&286206848099549185>

#

do u know what textbook/workbook this problem came from? I wana figure out what the purpose of this question is

#

also technically from what I see there are technically inifnite ways to shift the decimals for 4 of the numbers to make the sum work out x.x

#

so i really don't know what the prof wants you to do here

cedar kilnBOT
#

@brisk shell Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

austere dune
#

.reopen

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

cedar kilnBOT
#

@austere dune Has your question been resolved?

cedar kilnBOT
#

@austere dune Has your question been resolved?

cedar kilnBOT
#

@austere dune Has your question been resolved?

austere dune
#

<@&286206848099549185>

jovial marlin
#

You are cheating. @brisk shell

#

@austere dune

crimson sedge
cedar kilnBOT
#

@austere dune Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

crimson sedge
#

hey yall i got a quick question on where I can find a video on this to help me out or someone to explain it to me

crimson sedge
#

some examples

#

i have a test tmmrow and i was sick for a long time so I wasnt able to study, so some quick help would be appreciated

#

i actually prefer video format because i learn better that way

#

end behavior of piecewise functions is the topic

crimson sedge
#

so im confused

#

ye

#

those are piece wise functions

#

basically, different x-value domains have different functions associated with them

#

based on your limit, you need to figure out which function you need to use

#

for example in the first one, you would 1/(x+2) for the limit to -infinity and 1/(x-2) for the limit to +infinity

#

does that make sense?

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

bitter lily
#

im doing this question, but im kinda stuck,

i know i have to use Pythagorus theorem but im just unsure on how to do the equation

i dont want to use ai to help me, i just need someone to explain how i would do this so i understand and can do this equation fluently

cedar kilnBOT
#

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

bitter lily
#

im sorry but im already using this channel

#

no no its ok

bleak viper
#

2 triangles

#

use pythagoras theorem for each

bitter lily
#

do i need to do 14m for the base or just their respective bases?

bleak viper
#

respective bases

oblique flare
bitter lily
bitter lily
wraith daggerBOT
#

Astar777

bitter lily
#

ahhhh that makes alot more sense now

#

thank you guys

cedar kilnBOT
bitter lily
#

.close

cedar kilnBOT
#
Channel closed

Closed by @bitter lily

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

rough scroll
#

Hello! I'm currently working on a Trig question for my pre calculus 11 course and am unsure of how to solve this specific question (it is using Sine/Cosine law). I apologize for my photo being a bit low quality! I cannot figure out how to find X for this equation.

crimson sedge
#

seems to be a law of cosines problem though

rough scroll
crimson sedge
#

o ok cool

rough scroll
#

The only text given is to determine the length of X

#

I figured it was Cosine law but I am unsure of how to input the information into the formula with how the question is set up if that makes sense?

crimson sedge
#

so the original information is the two angles?

#

and side AB?

crimson sedge
bleak viper
#

i think thats b

rough scroll
#

small b, I apologize for my handwriting

crimson sedge
#

ah okay mb

rough scroll
#

Its ok!

crimson sedge
#

ugh my parents turned off router

#

so annoying

rough scroll
#

LMAO thats evil😭

crimson sedge
#

yea 1 sec

rough scroll
#

All good! Take your time:)

crimson sedge
#

just checking

#

is AB 180?

rough scroll
#

Yes

crimson sedge
#

dang

#

ignore the implicit differentiation that was someone else's problem

#

lol

rough scroll
#

LOL all good!

#

So it would be a law of Sine question?

crimson sedge
#

yeah

#

since you have an opposite angle side pair

#

does it make sense?

rough scroll
#

That makes sense! I guess my only question would be how you got the angle for B?

crimson sedge
#

well

#

angles in a triangle add up to 180 and since you already have 2 the 3rd is easy to find

rough scroll
#

okok! that makes sense, thank you!:)

crimson sedge
#

perfect

rough scroll
#

I seem to have forgotten that...

crimson sedge
#

ye all good

rough scroll
#

I appreciate your help:)

crimson sedge
#

yeah your welcome!

#

i gtg sleep now tho, cya

rough scroll
#

Goodnight!:)

#

.close

cedar kilnBOT
#
Channel closed

Closed by @rough scroll

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

woeful flower
#

Can anyone explain to me on how to do this?

clear umbra
cedar kilnBOT
#

@woeful flower Has your question been resolved?

woeful flower
clear umbra
woeful flower
#

Oh and then what?

#

I've grouped them into like 30-39
40-49
50-59....

clear umbra
#

then find which class has the most data

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

ebon grove
#

how did we figure out the point of intersection?

hollow trail
#

solve for y in the equation above, then plug in to one of the curves to solve for x

ebon grove
mighty shuttle
ebon grove
mighty shuttle
cedar kilnBOT
#

@ebon grove Has your question been resolved?

#
Channel closed

Closed by @ebon grove

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

vernal sentinel
#

"a) find the number of ways in which alvaro can paint his back door and his front door in a different colour if he has 14 colours of paint to choose from.
b) in how many ways could alvaro do this if he also considered painting them the same colour?"

guys, for b, why is the answer 14^2 = 196? i don't understand why we need to square it

pulsar lily
#

14 choices for the front door, 14 choices for the back door, and the choices are independent

worn olive
#

For a:

Alvaro has 14 options for painting his back door. When it comes to painting his front door, he can choose any of the other 13 colours, except for the one he painted the back door with.

#

He has 14 different ways to paint the front door, and then 13 ways to paint the back door. So together, there's 14x13 total arrangements.

#

For b:

It's very similar, but since it allows repetition (the same colour on both doors), we don't have to take away the option we painted the first door with. Therefore, Alvaro has 14 ways to paint the front door, and 14 ways to paint the back door. That's 14x14 total arrangements

#

So the question doesn't usually prompt you to square anything, but in this case the total number of arrangements is just equal to 14^2

#

@vernal sentinel

vernal sentinel
#

OHHH

worn olive
#

!! you're okay !!

vernal sentinel
#

i understand it now

worn olive
#

good!

vernal sentinel
#

i always stick with using nPr without knowing the reason

worn olive
#

Yeah, that's one of the only types of questions where you can't use nPr haha

vernal sentinel
#

btw i have another question

worn olive
#

Or I suppose you could do (14P1)^2 😆

vernal sentinel
#

"find how many of the arrangements of four letters from A, B, C, D, E and F contain the letter A"

vernal sentinel
worn olive
#

So, the way I see it:

#

-. -. -. -.
That's your four options.
For the first, you have 6 choices
For the second, five choices
For the third, four choices
For the fourth, three choices
Hence 6P4

#

But since there's 6 letters and 4 spaces, one particular letter will only be chosen 4/6 (= 2/3) of the time

#

Or, putting it another way: Since there is 2/3 the amount of spaces compared to letters, a specific letter will only be in 2/3 the total number of arrangements

vernal sentinel
worn olive
#

Okay what about this:

#

Let's find the total number of arrangements. That's 6P4=360.

#

Now, let's remove A and put it to the side for now. That leaves us with {B, C, D, E, F}. We're going to arrange those five letters into the same four spaces

#

Let's find the total number of arrangements for those letters:

For the first space, you have 5 choices
For the second space, you have 4 choices
For the third space, you have 3 choices
For the fourth space, you have 2 choices

So that's 5P4, which is 120.

#

360 (total number of arrangements) - 120 (total number of arrangements when excluding the letter A) = 240 (total number of arrangements that include the letter A)

vernal sentinel
#

OHH I UNDERSTANDDD

worn olive
#

🙏

#

You got this

#

(Don't worry I hated permutations when I was in high school)

vernal sentinel
worn olive
#

All good, hopefully that helps you

vernal sentinel
#

helped me alottt

worn olive
#

good to hear!

vernal sentinel
#

i'll close the channel

#

thanku sm once again

worn olive
#

okay! bye forever

#

that's okay haha

vernal sentinel
#

.close

cedar kilnBOT
#
Channel closed

Closed by @vernal sentinel

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

analog jackal
#

Given a geometric series with the 2nd term = 6 and the sum to infinity = 18. Determine the sum of the first 4 terms.

Can someone help? How are you supposed to use infinity in a math question???

pastel vault
analog jackal
pastel vault
analog jackal
# pastel vault yes

how are you supposed to find the first term using the ones at the top though?

pastel vault
wraith daggerBOT
#

south's secret twin brother

pastel vault
#

try subbing in the 1st equation into the 2nd

#

(you need to rearrange the 1st equation to isolate a variable)

analog jackal
pastel vault
wraith daggerBOT
#

south's secret twin brother

pastel vault
#

this is a quadratic!

#

now expand and solve for r

#

then you can find a

#

then the sum of the first 4 terms is $a + ar + ar^2 + ar^3 = \frac{a (1 - r^4)}{1 - r}$

wraith daggerBOT
#

south's secret twin brother

analog jackal
pastel vault
analog jackal
pastel vault
analog jackal
pastel vault
#

there's a problem with the question

analog jackal
#

???

pastel vault
#

impossible values as in not real numbers

analog jackal
pastel vault
analog jackal
#

.close

cedar kilnBOT
#
Channel closed

Closed by @analog jackal

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

worn olive
#

I'm on the last question. Unsure as to what to do next.

worn olive
#

This is what I've got

cedar kilnBOT
#

@worn olive Has your question been resolved?

worn olive
#

<@&286206848099549185>

crimson sedge
#

@worn olive

#

The answer is 24

worn olive
#

hello

#

how did you do that

#

you're lying aren't you 😭

cedar kilnBOT
#

@worn olive Has your question been resolved?

cedar kilnBOT
#

@worn olive Has your question been resolved?

tardy remnant
cedar kilnBOT
#

@worn olive Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

floral narwhal
#

Hi, i had a question my friend taught me to solve ( find x) this and he said the first step was to discard everything under the line (x + 5).

Is that true

fair geyser
#

maybe

#

he's saying that's the first step of his method, it's possible

#

he's just not mistaken about his own method

floral narwhal
#

yeah and then just solving the y = 4 * x + 1

floral narwhal
fair geyser
#

maybe he introduces it back at sme point

floral narwhal
#

nah he just said it doesnt matter

fair geyser
#

ok tell him i said it's not true

floral narwhal
#

what would be the appropriate method

mental trail
#

If you're solving for (4x+1)/(x+5) = 0, then in THAT case the only way is for the numerator to be 0, so you would have 4x+1 = 0

#

when the other side is different from 0, you can't disregard the denominator

#

if you want to "get rid of" the denominator, you have to multiply it out on both sides

#

as for example (4x+1)/(x+5) = y

#

getting rid of the denominator means multiplying by it, so let's multiply both sides by x+5:

#

(x+5) * (4x+1)/(x+5) = (x+5)y

#

4x+1 = (x+5)y

#

then I'm assuming you want to solve for x, so now we can isolate x

#

so (.....) * x = ....

#

and the rest is hopefully straightforward

brave nimbus
mental trail
#

of course not accounting for potential omission of parentheses

cedar kilnBOT
#

@floral narwhal Has your question been resolved?

#
Channel closed

Closed by @floral narwhal

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

formal nest
#

is t and 1/t linearly independant ?

cedar kilnBOT
formal nest
#

the wronskian = -1/t^2

#

so yea they are

#

but k1 t + k2 1/t = 0

#

when k1=1 and k2=-1 with x=1 gives zero

mental trail
#

but is the FUNCTION k1 t + k2 1/t equal to the zero function?

formal nest
#

i dont understand

formal nest
mental trail
#

is k1 t + k2 1/t = 0 for every t

formal nest
#

it has to be for every t ?

mental trail
#

well yeah

formal nest
#

hmm

mental trail
#

they're linearly independent functions

#

meaning any non-zero linear combination of the FUNCTIONS

#

will give you a function that isn't the 0 function

#

the 0 function being 0(x) = 0 for every x

formal nest
#

so its not the same thing as for vectors ?

mental trail
#

functions are vectors

#

but for two vectors to be linearly independent

formal nest
mental trail
#

does this make k1A + k2B the zero vector?

formal nest
#

it gives (0,-1)

mental trail
#

yup

formal nest
#

OOOOOOOO

mental trail
#

so just because you looked at the first coordinate and it was 0

#

doesn't make the whole thing the 0 vector

formal nest
#

ok, so basically

#

I simply listen to the wronskian ?

mental trail
#

yep

#

the wronskian already tells you if f and g are LI or not

#

if the wronskian is 0 anywhere, it's 0 everywhere and the functions aren't LI

#

otherwise, f and g are LI

#

meaning that for any k1 and k2

#

k1f + k2g cannot be the zero function (zero vector), except if k1 = k2 = 0

cedar kilnBOT
#

@formal nest Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

wise galleon
#

is there a way to compress multiple numbers into one number and add something to it, a set of instructions as it were on how to decompress the numbers, like taking 209, 151, 102, adding them to get 462 and tacking on another number that can tell you how to get the original numbers from the 462?

distant kite
#

That's an encryption

distant kite
wise galleon
#

if they were primes it would be super easy, but they can be any number

#

<@&286206848099549185>

cedar kilnBOT
#

@wise galleon Has your question been resolved?

languid forum
#

there's a GitHub for that in python, but I don't remember the name fuck

#

where they help you to convert à list of number into an encryption

cedar kilnBOT
#

@wise galleon Has your question been resolved?

cedar kilnBOT
#

@wise galleon Has your question been resolved?

potent fractal
#

All elements of $\mathbb{Z}^n$ can be enumerated by "walking in spirals" from the origin (a common argument that is often used to prove that $\mathbb{Q}$ is countable, for example)
Denote $s_{n,k}$ the $k$-th element of $\mathbb{Z}^n$. We can write all $s_{n,k}$ in an infinite table like so:
$$s_{1,1} \ s_{1,2} \ s_{1,3} \ \dots$$
$$s_{2,1} \ s_{2,2} \ s_{2,3} \ \dots$$
$$s_{3,1} \ s_{3,2} \ s_{3,3} \ \dots$$
We can then repeat the spiral argument and assign a unique number to each $s_{n,k}$.

wraith daggerBOT
#

EQUENOS

potent fractal
#

However, this is far from a good algorithm. A more adequate approach in programming involves the fact that integers in applications are typically bounded

#

I'm pretty sure there're multiple efficient algorithms for different applications

wise galleon
#

so like find -or design- an algorithm that can assign single numbers to a whole set of numbers?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

crimson sedge
cedar kilnBOT
crimson sedge
#

The directions are: “you are given the explicit formula for an arithmetic sequence. Find the first 3 terms of the sequence and the term named in the problem.

#

I know this is probably easy but i forgot

slender ginkgo
#

just plug n in

crimson sedge
#

?

celest void
#

sub 34 for n

crimson sedge
#

OHHH

#

now i remember

celest void
#

lol

crimson sedge
#

thank you

celest void
#

np

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

#
Channel closed

Closed by @fading dirge

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

spice jungle
#

how do i find the derivative of a function? like how does x² become 2x?

rare vault
#

in general, there are a bunch of identities you can apply to find derivatives, but they are all fundementally from the "limit definition of the derivative"

spice jungle
pseudo merlin
#

yt

rare vault
#

google em as you need em

spice jungle
#

nice

rare vault
#

first result is this, and it has a few useful ones

spice jungle
#

thank you so much

rare vault
#

you are ɰelcome

spice jungle
#

.close

cedar kilnBOT
#
Channel closed

Closed by @spice jungle

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

rare oasis
#

I want to solve the DE 1/2 y'' + 9/2 y = cos 3t. We get the complimentary solution y = a cos 3t + b sin 3t.
Variation of parameters is inconvenient to use for this problem, and I want to solve it with the annihilator method, but the annihilator for cos(3t) is D^2 + 9.
We rewrite the DE as y'' + 9y = 2 cos (3t)
When we multiply the annihilator to both sides of the DE we get (D^2 + 9)(D^2 + 9) y = 0.
I don't think I obtain any information about the form of the particular solution from the new DE, since the new roots introduced by the annihilator in the characteristic equation are the same as the roots that form the complimentary solution. Or, do I proceed with the repeated complex roots similar to repeated real roots? That is, is the solution to the new DE
y = a cos(3t) + b sin(3t) + c t cos(3t) + d t sin(3t) ?
If this does work, do I always proceed with repeated complex roots by multiplying on an extra t for each time it repeats?

cedar kilnBOT
#

@rare oasis Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

#

@harsh yoke Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

ocean robin
#

Where Do I start

cedar kilnBOT
ocean robin
#

Work so far

slender ginkgo
#

find the relationship

#

between altitude, area, and base

#

@ocean robin