help-13

[cedar kiln]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[halcyon junco]

.close

[cedar kiln]

Channel closed

Closed by @halcyon junco

Use .reopen if this was a mistake.

[crimson delta]

why do you think it starts at -3 and ends at 9

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

Guys

[crimson sedge]

when i do an application

what significant figures should I choose?

To make the answer accurate?

[steep lark]

what do you mean?

[summer otter]

https://en.wikipedia.org/wiki/Significant_figures

[crimson sedge]

like how do i know what significant figure to choose

in a application

ik how using more significant figures, or more decimals willl improve my accuracy

but idk what to set it

[summer otter]

could you show what type of application you are dealing with?

[crimson sedge]

this was what i said

and this what i got as my feedback

and yes i didnt really talk about the choice I MADE

and was just talking about the concept of the significant figures

but Im wondering what significant figure should i have choose in the beginning to make my point more accurate

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[distant sail]

№3. The figure shows a graph of the transition of water from one aggregate state to the other

[distant sail]

1. Write down which process the plots correspond to:

?

[cedar kiln]

@distant sail Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[old echo]

i need help with graphing y=13x/7 + 13, thank u!

[young current]

do you have the value of x?

thats very crucial

[runic garnet]

@young current huh?

[old echo]

no

[young current]

im wrong

my bad

[old echo]

heres what i've done so far

!status

[cedar kiln]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[old echo]

2

[vapid kernel]

This is a line. You only need two points and draw a straight line to draw it.

[floral trout]

U want to plot the graph?

[old echo]

yes

[old echo]

i do

so

[floral trout]

Put value of y 0

[old echo]

alr

[floral trout]

U get value of x on solving

[old echo]

so y= 0 x= 13

[floral trout]

Thats one point x,0

Yes

[floral trout]

No

[old echo]

ufff

[floral trout]

Calculate again

[old echo]

y=13

WAIT WHAT

OK

SORRY

[floral trout]

This is the equation right?

[old echo]

line 2

i think theyre the same so yea

i replaced the x with 0

[old echo]

it gave me 13

[floral trout]

So that will be one point

[old echo]

x or y

[floral trout]

X=0
Y=13

[old echo]

oh

[floral trout]

Now put y=0

[old echo]

right

[floral trout]

Ull get val of x

[old echo]

wait im confused

help

[floral trout]

Where are u confused

I got all day

🐛

[old echo]

wheres y

[floral trout]

Y is in the equation

The equation has 2 variables

X and y

If u assume value of 1 variable

[old echo]

oh yea

[floral trout]

Ull get value of the other variable on solving the equation

[old echo]

so

13/7+0

[floral trout]

The given equation is a line

[old echo]

?

[floral trout]

To plot the graph of a line u must have 2 points

So to get the 2 points first u assume value of x and solve for value of y this way u get x,y which is point 1

Now assume any value of y and solve for value of x

[old echo]

so my point 1 is 0,13

[floral trout]

Yessss

Good job

[old echo]

and point 2?

is kinda comfusing

[floral trout]

Solve it urself

Tell me what ur doing

Ima tell u where u going wrong

[old echo]

i made a table

i put y as 0

[floral trout]

Yes

So now 13x/7+13=0

Right?

[old echo]

yes

[floral trout]

So now can u solve for x?

[old echo]

idk

[floral trout]

Its an equation with one variable

U can solve it

[old echo]

right

[floral trout]

Do u know how to?

[old echo]

so how do i

no i dont

[floral trout]

Ok so substract 13 on both sides

U know this method?

[old echo]

no

[floral trout]

Ok ima teach u

So what u have to do is

Take everything expect x on the other side

There are 2 sides in an equation

The left hand side

And the right hand side

If do something on one side and do the same thing on the other side the equation remains the same

For example

If u subtract 13 on left side and then subtract 13 on the right side

The equation remains the same

So in this equation

U first take 13 on the other side

By subtracting 13 on both sides

[old echo]

which 13 do i take left or right

[floral trout]

The 13 that is getting added to 13x/7

[old echo]

okay

[floral trout]

U take it to other side first

By subtracting 13 on both sides

Do that and tell me what u are left with

[old echo]

7x+26?

[floral trout]

No

Check this out

U understand it?

So now we have 13x/7 = -13

What grade are u in it will make it easier for me to teach u

Ill know what terms to use and what not to

[old echo]

8th

[floral trout]

Alr

U get it?

What i did

[old echo]

yes

[floral trout]

Now tell me what is in division and what is in multiplication with x

[old echo]

huh

[floral trout]

In this equation

[old echo]

ah

13(x)/7

[floral trout]

Ok so 13 is in multiplication and 7 is getting divided

So now what ull have to do is

[old echo]

yes

[floral trout]

Divide 13 on both sides

And multiply 7 on both sides

Do that and tell me what's left

[old echo]

-1 and

uh

WIAT

WAITTT

do i neglect x

or assume

[floral trout]

U dont have to do anything to x

[old echo]

kay

[floral trout]

Just divide 13 on both sides and after that multiply 7 on both sides

And tell me the equation that is left

[old echo]

13/7 is a decimal

[floral trout]

No its a fraction

[old echo]

okay

[floral trout]

U dont have to solve it

[old echo]

i meant the answer

oh

[floral trout]

So what do u get

[old echo]

so 13/-13?

= -1

[floral trout]

Yes what us it

Yesss

Yess

Now multiply 7 on bs

[old echo]

bs

?

[floral trout]

Both sides

[old echo]

7(-13)=91

7(13) = 91

[floral trout]

Noo

[old echo]

uhh

[floral trout]

Multiply 7 with -1

[old echo]

OHHH

[floral trout]

That u just got

[old echo]

-7

[floral trout]

Yeahhhh

Yeas

[old echo]

-1,-7

OOOOOO

[floral trout]

So the complete equation is

[floral trout]

No

[old echo]

-7,-1

[floral trout]

We assumed y to be?

We did that couple mins ago

[old echo]

0

[floral trout]

-7 is correct

Yes

So point 2 will be

[old echo]

0,-7

[floral trout]

X is -7

And y is 0

So point 2 will be

[floral trout]

Check again

Very close

[old echo]

point 2: -7,0

[floral trout]

Yes

And point 1 is

[old echo]

0,13

[floral trout]

Yes

So now plot these two points on graph

Then connect those points

[old echo]

oh alright

i got it from here

thank u so much!

.close

[cedar kiln]

Channel closed

Closed by @old echo

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lofty horizon]

I dont understand how to work out a

[dusty idol]

Ive once seen a definition of gcf involving lcm

Here, i found it

Now could you look into how you would formulate the lcm of Q and R

[lofty horizon]

is there not a simpler way of doing it. I have never seen this formula before. i am not good at remeberiing formulas

[dusty idol]

There could be but I don't know of any other, that would make sense also since they are asking you to find the LCM after.

But ive tried solving your question with that formula and the answer seems to be correct

[dusty idol]

Here is the link regarding this, in case you find yourself interested in it https://www.chilimath.com/lessons/introductory-algebra/product-of-gcf-and-lcm/

[lofty horizon]

ok i will have look. thanks. .close

.close

[cedar kiln]

Channel closed

Closed by @lofty horizon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[uneven gyro]

can some help me with radical in maths im in the 8 grde but pls in call

[sonic thicket]

Isnt that just 0? Since the largest term $\frac{\sqrt{n}}{(n+1)(\sqrt{n})}$ tends to 0?

[wraith dagger]

Adarsh

[lyric wren]

Idts thats how it works

[gritty viper]

It indeed is not how it works

@sacred grail any ideas?

what's the play when we have a sum inside a limit

he's probably asleep

[cedar kiln]

@lyric wren Has your question been resolved?

[gritty viper]

bring the denominator inside the summation

Actually, first replace the n+1 with n

You can do this by multiplying by (n+1)/n, which doesn't change the value of the limit since (n+1)/n has a limit of 1

[gritty viper]

The problem is the number of terms increases as n increases

So the "largest term" ends up actually having a negligible contribution to the sum

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[opaque bane]

Is this x= 6

[past wind]

yea

[opaque bane]

Ok thanks

.close

[cedar kiln]

Channel closed

Closed by @opaque bane

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[slim gorge]

can anyone help me figure this out or set it up

[slim gorge]

I only need n = 5 and n = 10

[vagrant elbow]

are you meant to do it by hand?

[slim gorge]

calculator, but figuring out the summation

like what would be the subinterval lengths

.close

[cedar kiln]

Channel closed

Closed by @slim gorge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[autumn tusk]

i don't understand how to draw level curves of T

[autumn tusk]

it should just simplify to
100e^-t^2 correct?

if i use these 2 identities

x^2+y^2 = 1

so T would be dependent only on the variable t really, i think i can draw it like this

how would this translate to drawing as a surface on x y plane?

[slim gorge]

before subsituting, try finding the level curves first by setting T as k

[autumn tusk]

i dont kno what means setting T as k

a constant?

[slim gorge]

yes

[autumn tusk]

if i try to isolate x and y i have
-ln(k/100) = x^2+y^2

ssssooo .... i have a constant on the left side, and a parabola on the right.

[slim gorge]

what does the equation you found depict?

[autumn tusk]

not sure if i see this correctly. it would be the set of points at some height on z basically. so a circle

for different k different sizes of circles

[slim gorge]

yep

[autumn tusk]

can i see as a plane slicing the 3d parabola?

i mean the intersection

[slim gorge]

not completely sure what you're asking sorry

your solution on the xy plane would just be circles of different sizes otherwise it would be slices through the surface yeah

[autumn tusk]

this equation represent the set of points of the parabola at a certain height

the height is .. what i have on the left side ? not sure

no the height would be k

[slim gorge]

yep, I forgot to mention but we set z = k at first

[autumn tusk]

yea, not the left side, but k

[slim gorge]

yep

so it would be circles at height k

[autumn tusk]

last thing, i'm not sure about this step

i did it cause i was trying to solve for variables

but... i mean i usually solve for 1. this is trying to isolate both on one side

it's kinda new to me

i was treating both as 1 variable

but if they weren't in separate places in the equation i would have to do more steps... and not sure if i could succeed

[slim gorge]

I assume problems wouldn't give you equations which are extremely hard to manipulate, which is why this problem has x^2+y^2 which would lead you to the circles

[autumn tusk]

ok but is the idea correct?

trying to isolate both vars?

or is there another reasoning behind

[slim gorge]

it would probably complicate it most of the time

for most problems I believe you can just set z as any constant

so let's say in this problem T=0

wait sorry that wouldn't work

but let's say you just set T = 1

you could just graph that function itself and repeat based on what's required

@autumn tusk does this make sense?

[autumn tusk]

mm no sorry

[slim gorge]

because there are infinite level curves, so often the problem will only ask you to draw or find a specific few by giving you the constant it wants; if not, then I assume you could just draw a few as the pattern does show and solving for the actual equation is often quite complicated when it's not cases like the problem you provided

[autumn tusk]

i think my questio is

in a equation with 1 variable, i need to solve for x.
in here i have tried to solve for x and y at the same time.

does this makes sense? it kinda does and doesnt to me.

[slim gorge]

I think I get what you're trying to say

solving for each variable independently isn't necessary because we only need to find a level CURVE

[autumn tusk]

yes but i've never heard in my life of solving for 2 variables together

i feel i'm making things up

[slim gorge]

you're not solving for the variables

just the curve

[autumn tusk]

mmm ok so i'm just manipulating the equation to have it easier to see to my human brain

[slim gorge]

yep

[autumn tusk]

ok now it works

i still have a doubt though.

if T in the end is a function of one variable

the grap of T is just a curve, right?

i can't really make the connection with 3d.
the 2 variables really are not 2 variables., it's one.

maybe i do. not super clear the reasoning. it's more a graphical idea i have in mind

ill keep thinking about it

thanks!

.close

[cedar kiln]

Channel closed

Closed by @autumn tusk

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[raw sluice]

Hello, can somebody help me with part b?

[cedar kiln]

@raw sluice Has your question been resolved?

[raw sluice]

<@&286206848099549185>

[cedar kiln]

@raw sluice Has your question been resolved?

[cedar kiln]

@raw sluice Has your question been resolved?

[raw sluice]

.close

[cedar kiln]

Channel closed

Closed by @raw sluice

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wraith slate]

Hello can I get help with this?

[cedar kiln]

@wraith slate Has your question been resolved?

[wraith slate]

<@&286206848099549185>

[cedar kiln]

@wraith slate Has your question been resolved?

[cedar kiln]

@wraith slate Has your question been resolved?

[cedar kiln]

@wraith slate Has your question been resolved?

[cedar kiln]

@wraith slate Has your question been resolved?

[vapid kernel]

Still need help with this?

[wraith slate]

Yes

[vapid kernel]

What have you done so far? You can write two equations (the sum and the product) and you got a and r as unknowns to solve.

[wraith slate]

I'm not sure if this is correct

But this is as far i got

[vapid kernel]

,ask 158=a+ar+ar^2 and 74088=a^3r^3

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by kexanone

[vapid kernel]

Looks like you got them 😄

[wraith slate]

Thank you

[vapid kernel]

Oh wait, why is this c?

instead of a

[wraith slate]

The question said abc

That's why

Oh wait

No

Wrote it wrong

[vapid kernel]

Nah, I just got irritated by the symmetry of the solutions for a second 😅

[wraith slate]

Oh

.close

[cedar kiln]

Channel closed

Closed by @wraith slate

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[autumn current]

I have to prove that f(x) > 0 for all x>0. Its given that f(0) = 0. I proved that f'(x) > 0 for all x>0. Is that proof enough to satisfy the question?

[cedar kiln]

@autumn current Has your question been resolved?

[autumn current]

.close

[cedar kiln]

Channel closed

Closed by @autumn current

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jovial whale]

The author here says the more modest a theory is, the more likely it is to be true. He offers his informal reasoning as follows:

The less modest a theory is, the more are more ways it could be false, and hence less ways it could be true.
The less a hypothesis says that might be false (that is, the more modest it is), the more likely it is a priori that the hypothesis is true.

I also attached an image of his explanation. Can someone explain what the formal derivation for this is?

He applies this to the following example. That the P(particle-ism) is less modest than Pr(particle-ism plus an additional claim), and therefore that Pr(particle-ism) is less than Pr(particle-ism plus an additional claim).

[cedar kiln]

@jovial whale Has your question been resolved?

[dire geode]

Try uhhh #proofs-and-logic

[jovial whale]

is that chan for probability proofs too

[cedar kiln]

@jovial whale Has your question been resolved?

[cedar kiln]

@jovial whale Has your question been resolved?

[jovial whale]

<@&286206848099549185>

[cedar kiln]

@jovial whale Has your question been resolved?

[cedar kiln]

@jovial whale Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[plain granite]

is there a way to find out what the radiuses are if we know that the distance between O and O_1 is 36?

the triangles are also similar

[split wraith]

is that 5x/13 the hypotenuse?

[plain granite]

well

it is not a right triangle

but yes

[split wraith]

right, missread that sorry

i believe its possible

wait

[plain granite]

yea it is, just forgot how to find it

[split wraith]

i made another mistake in my working

brain is clearly taking a break tonight

[oblique flare]

radii are equals every where in the circle you can make a right angle

[plain granite]

can you say that Z = R?

you can only make a right triangle if it is built on diameter no?

[split wraith]

the problem with a right triangle would be that u lose the variable of x that you are given

[plain granite]

AB is a chord by the way

forgot to mention that

not the entire thing but

u get the idea

[oblique flare]

is there any other info like ZOB
being right angled ?

[plain granite]

oh

Z is a side

it is a radius

the only information given is that

the distance between O and O_1 = 36

[oblique flare]

so z+r=36 noted

[split wraith]

waht im currently tryna work out is using sin rule on both the triangles to find different expressions for x

[plain granite]

so we can say 36 - z right

[oblique flare]

this too

[split wraith]

oh right lol

[plain granite]

yea

the thing is that

[split wraith]

that makes things easier

[plain granite]

when you make a ratio

[split wraith]

if we have that we have a ratio no?

[plain granite]

it doesn't add up

[split wraith]

oh right

[plain granite]

yea I tried making a ratio

you get 2 unknowns, Z and R

x's cancel out

[oblique flare]

rewriting r as 36-z would help

[plain granite]

oh

[split wraith]

well triangle on the left would be 13/5 times bigger than triangle on the right if my brain isn't pulling another stupid

[plain granite]

you can say that here no?

[oblique flare]

no

for the other radius

[plain granite]

I remember we did something like that in class

[oblique flare]

yep but for the radius of the other circle

[plain granite]

yeah doesn't really make sense

yea i'll rewrite it

I was thinking of using a circle theorem but

arcs don't really help here

[oblique flare]

just rewrite one of them not both

cuz it’ll keep only one variable rather than two

[plain granite]

oh I see

thats smart

[split wraith]

is left triangle radius 26

right triangle 10?

[plain granite]

oh

we can just ratio then

[plain granite]

yea

that's the answer

[split wraith]

aight sick

[plain granite]

oh you just

[split wraith]

ill try and take a picture of my working

[plain granite]

rewrite as 36 - r

and then just ratio

[split wraith]

i took a diff approach

i got the chord length to be

13/18 for the first circle, then the second circle was 5/18

[plain granite]

I see

I have no idea how to do it your way tho 🤣

seems like you took the hard approach

[split wraith]

haha

let me take picture

it makes sense in my head

[plain granite]

I wrote this ratio

[split wraith]

but my brian works funny so idk lol

[plain granite]

thanks for spotting that

[plain granite]

huh

[split wraith]

idk if that makes sense bc i was just jotting down what i thought lol

[plain granite]

where'd you get the values from?

[split wraith]

so my values

[plain granite]

like 13/8

[split wraith]

13/18

its because

i have 13/13 for the top half

then bottom part is

5/13

[plain granite]

huuuh

[split wraith]

you have a total length of 18/13

[plain granite]

i'm confused on how'd you get the value of radius via a chord 🤣

geometry moment

[split wraith]

let me try and rewrite it lol

[oblique flare]

13/13=1x

[plain granite]

oh

its a bit of a confusing way of doing it

[oblique flare]

just to make the fraction simpler

[split wraith]

idk if that helps at all lol

im not a very good teacher in the slightest

[plain granite]

the greatest teacher in geometry is experience from what I see 🤣

[split wraith]

yes def lol

i think its just going through enough examples that you can form a ratio

where each part of that chord is a fraction of the whole length

then because similar triangles

that ratio carries throuhg every length measurement

[oblique flare]

ngl hate geometry

[plain granite]

I'll keep your method in mind

[split wraith]

idm it

the problem comes

when you have to do vector proofs

[plain granite]

gotta learn it for entrance exams 🤣

[split wraith]

they r terrible

i got my final test for the hardest maths course u can take in high school australia on monday and was studying for it just b4 this lol

[plain granite]

ironically I think those type of questions are considered the high point ones

thank you both for the help 👍

[split wraith]

ofc :)'

glad i could be of any assitance

[plain granite]

i'll keep your method in mind, looks interesting

cya 👋

[split wraith]

sounds good haha

comes in handy

cya

[plain granite]

.close

[cedar kiln]

Channel closed

Closed by @plain granite

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gentle light]

for part B why does it have to be -3i

[gentle light]

the box is meant to say pi

so its pi / 4

[pastel vault]

cause of the arg condition

[cedar kiln]

@gentle light Has your question been resolved?

[gentle light]

Wdym

i thought that statemnet meant that just if u multiply them together the angle of the complex number formed lets call it z3 is pi/4

[pastel vault]

oh wait I misread sorry

[pastel vault]

so basically you need z2 to be in the fourth quadrant

cause the arguments add

[gentle light]

is that bottem right

[pastel vault]

z1 has an argument more than pi/4 (2 + 2i has that argument and it's above that point)

[pastel vault]

yep

[gentle light]

so it has to be -3i to make the angle lesser

[pastel vault]

yeah

the other alternative is -15 + 3i

that would be adding an obtuse angle to the argument

[gentle light]

oh i seee

isnt it 15 + 3i?

[pastel vault]

no cause b/a = -0.2

[gentle light]

a^2 + b^2 = 234 and a = -3

[pastel vault]

that's only one solution

oh wait a can't be 3 or -3

it's b that can be 3 or -3

[gentle light]

Yh

[cedar kiln]

@gentle light Has your question been resolved?

[gentle light]

.CLOSE

.close

[cedar kiln]

Channel closed

Closed by @gentle light

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[random grove]

if I write W as a span of two vectors does that show that W is a subspace?

[random grove]

and is that true for all sets of vectors? that writing them as a span of vectors makes them a subspace?

[dawn junco]

if you manage to do that, yes it's fine

[random grove]

cool ty, just to make sure im doing this right
I wrote W = {(x, -2x+3z, z) in R3 : x, z, in R} = spanR = {(1, -2, 0), (0, 3, 1)} is this correct??

I know that I can show the 0 vector is in W, that W is closed under both addition and multiplication but I am trying to find a basis. My plan was to write it as a span of vectors and then show the vectors in the span are linearly independent

[dawn junco]

W = span {(1,-2,0), (0, 3, 1)} yes

[random grove]

beause W = span{(1,-2,0), (0,3,1)} does that make this a spanning set also ?

[dawn junco]

what is "this" ?

[random grove]

span{(1,-2,0), (0,3,1)} spans all of W (because it is equal) so it is a spanning set

[dawn junco]

sure

[random grove]

ty !

.clos

.close

[cedar kiln]

Channel closed

Closed by @random grove

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sinful zephyr]

Piyush and Ajit together can complete a work in 3 days. They started together but aftet 2 days Ajit left the work. If the work is completed after 2 days, Piyush alone can complete it in how many days?

[limber dawn]

how was the work completed quicker if ajit left in the middle?

If the work is completed after 2 days,

does this mean 2 more days?

[idle crystal]

2 days after that 2

[sinful zephyr]

I have solution for this, but i cant understand the concept, can someone explain it to me?
Solution:
Piyush and ajit work = 3 days
One day work = 1/3

2 dats work together = 1/3 × 2 = 2/3

Remaining work = 1 - 2/3 = 3-2/3 = 1/3

Remaining worj completed by piyush 2 days

Piyush one day work = 1/3 - 1/2 = 1/6
Therefore answer is 6 days

[limber dawn]

ok

[idle crystal]

you can think of this as distance and time

[sinful zephyr]

Like?

[limber dawn]

this also seems legit

[sinful zephyr]

It is my teacher solution, but i cant understand how it works

[limber dawn]

ah ok

[idle crystal]

i will try to rewrite this so its easier

[limber dawn]

they use a bit of logic

[sinful zephyr]

I wasnt present in class when teacher was explaining this

[limber dawn]

👍

[sinful zephyr]

I amnt so smart

[limber dawn]

i think you will get it

it starts with the idea that, if they work together and can do it in 3 days, then in each day they work together, they get 1/3 of the work done

copter will probably explain it

[idle crystal]

Solution:
Piyush and ajit completes the work in 3 days
so Piyush and ajit completes s/3 in a day (let s denote the original work)
then, in 2 days the work completed in 2s/3
and theres s/3 work to be done

piyush completes s/3 in 2 days, so
piyus completes s/6 in 1 day
Thus, in 6 days piyush completes the work

[sinful zephyr]

Why did we put 2s/3?

Wait hmmm

[idle crystal]

1 day ~ s/3
2 days ~ 2 x s/3

[sinful zephyr]

I get it now!

So they both do work in x/3 days (x total work)

Then in 2 days = 2x/3

To find alone piyush work
We x/3 x 2 = x/6

I guess

Then isnt ajit one day work is x/6 too?

Am i right?

[idle crystal]

seems right

[sinful zephyr]

Oh alright

Thanks man

.Close

.close

[cedar kiln]

Channel closed

Closed by @sinful zephyr

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[devout cape]

i found the caracteristique polynomial to be of degree 2 but correct me if am wrong i know i need a one with degree 3 at least so i can fined 3 roots to construct the diagonal matrix i founed it to be -x^2 + 3x + 2 and im realy confused rn

[digital cliff]

how did you get one of degree 2

| x -1 -1
|-1 x -1
|-1 -1 x

x(x^2-1)+(-x-1)-(1+x)
x(x-1)(x+1)-(x+1)-(x+1)
(x+1)[x(x-1)-2]
(x+1)[x^2-x-2]
(x+1)^2 (x-2)

[devout cape]

oh sorry ma bad forget to multiplya the x

on the first line

[digital cliff]

ah

[devout cape]

it work now

ty

.close

[cedar kiln]

Channel closed

Closed by @devout cape

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torpid vessel]

chat i need some help

[dreamy void]

what have you tried

[torpid vessel]

y+16=1/2(m-16)

[dreamy void]

uhm

[gritty viper]

some positive vs negative errors

what's point slope form?

in general

also your m should be an x

wait no there's no sign errors

your m should just be an x

[torpid vessel]

delta math says it wrong

oh nvm yall right

thanks

[gritty viper]

np

[dreamy void]

yea

i just checked

[cedar kiln]

@torpid vessel Has your question been resolved?

Channel closed

Closed by @torpid vessel

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fickle viper]

Anyone know gradient descent? 3a is kinda confusing for me

[fickle viper]

Not sure where to start to show this odd function is convex

[crimson sedge]

what is <,> here ?

[fickle viper]

Dot product I think

[crimson sedge]

hm wich dot product ?

and what dimension ?

[fickle viper]

Yeah thats what I'm confused about too

[crimson sedge]

this is not given data ?

[dawn junco]

Well it's obviously in R^d given the shape of the vectors

Should be the standard dot prod

[fickle viper]

I guess we just assume that w matches with x

[dawn junco]

They tell w is in R^d anyway

No need to assume

[fickle viper]

Oh LOL

I missed tghat

[crimson sedge]

so maybe u can derivate 2 time with repect to w

[fickle viper]

Is that the best method?

[crimson sedge]

idk

[fickle viper]

And what does that do for us.

[crimson sedge]

if second derivative is >0 it is convex

[mental trail]

gradient descent is always $x_{k+1} = x_k -\alpha_k\nabla f(x_k)$

[wraith dagger]

rafilou is not not born in 2003

[fickle viper]

Agreed

I think 2nd derivative might work

I just never did it with this weird formula

[mental trail]

in d dimensions there is no 'second derivative'

there is only hessian

[fickle viper]

???

Why he said this then

[dawn junco]

It's just some formula, you'll survive

[mental trail]

idk

[fickle viper]

So same concept? Just weird formula?

[dawn junco]

Yes

It's always the same process if you want gradient and hessian

[crimson sedge]

with partial derivatives ?

[cedar kiln]

@fickle viper Has your question been resolved?

[cedar kiln]

@fickle viper Has your question been resolved?

[fickle viper]

Can I have help with setup of the derivative

Do I just expand all of it or is there a simpler way

[fickle viper]

Wait cant i just check if log(1+e^-z) is convex

[fickle viper]

.close

[cedar kiln]

Channel closed

Closed by @fickle viper

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[forest mauve]

hey sorry to bother but I have a quick question that im perplexed about on the answer, the question is:

you have to roll 5 dice, what amount do you have to roll over for it to be over 50%

[digital cliff]

of...

[forest mauve]

of the total of 5 dice which is 30

[digital cliff]

i feel like im not really getting the nuance of the question, unless its just literally 'over 15'

[forest mauve]

okay that's what i thought but I have friends who are literally saying it's 17.5 so basically 18 and over they're not trolling

[digital cliff]

rolling a 16 is the lowest you can go to achieve it

then anything above does it by default

[forest mauve]

Okay thank you!

[livid oriole]

nah

you have 5 dice

theres no zero in a dice roll

lowest you can roll is a 5

5 would be the new zero

@digital cliff

[digital cliff]

...

The lowest to be above 15

Oh crap

Wait no

[livid oriole]

yeah

[digital cliff]

Wait yeah

[livid oriole]

ok bro

[digital cliff]

You got me

[livid oriole]

yeah

[forest mauve]

SO WHATS THE ANSWER

[livid oriole]

18 over

[forest mauve]

what is the answer

i need it from @digital cliff

[digital cliff]

Theyre right, 18 to be above 50% within the constraint of what is actually possible to roll

Over 15 if just to get over 50% of the highest total is numerically

[forest mauve]

okay thanks

[cedar kiln]

@forest mauve Has your question been resolved?

Channel closed

Closed by @forest mauve

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[whole spear]

I have a question about Parseval formula. I have a fourier series and was told to solve another seriessum using Parseval formula

[whole spear]

The function f is given to be even

I'm told to evaluate these two limits

I have solved the first one which I was supposed to solve by any means necessary

second one, I was supposed to use Parseval formula

My issue is that my professor handed it back to me just stating ''wrong''

so I'm not sure where I went wrong? And I've been looking back at my calculations

I have written some stuff in swedish in free text, which is just clarifying what I'm doing for the teacher

But I begin by solving the left hand side (VL)

and then HL (right hand side)

This is solving the right hand side, and then equating left hand side = right hand side

Feel free to ask me questions, and I'll elaborate

I just want a fresh pair eyes that might see something I'm missing? Cuz I've been staring at it for hours

<@&286206848099549185>

[cedar kiln]

@whole spear Has your question been resolved?

[dawn junco]

you typo'd your parseval at the beginning

[whole spear]

How?

[dawn junco]

everything else but the equation at the end seems correct

[whole spear]

Could you elaborate to me, where I went wrong in my formula? so it's 1/2 a0^2?

[dawn junco]

yeah that's what I just wrote

[whole spear]

hmm

let me google, how could I miss that half? o,o

[dawn junco]

well maybe your prof typo'd in their course materials

or you just forgot

[whole spear]

crazy

it is true

🤦‍♂️

[dawn junco]

I mean I took my screenshot from wikipedia, it's almost surely correct

[whole spear]

Yeaa, I also took it from wikipedia

so yea I mean, formulas match

[dawn junco]

and now this gets you the same answer as wolfram alpha

[whole spear]

and another thing to clarify, a0

in the fourier series it's 2/pi

[dawn junco]

so I guess we now have the proof that your prof doesn't read when the final answer is incorrect

[whole spear]

but fourier series is defiend a0/2

so I have to multiply by two right?

[whole spear]

Yup

That's unreal how lazy he is

[dawn junco]

yeah indeed I have no issue with that

[whole spear]

This assignment has been holding me hostage since friday

😭

Seems like you've done complex analysis, are you familiar by weistrass M-test by any chance? You've been super super helpful

[dawn junco]

well I skimmed through the beginning of visual complex analysis but that's essentially nothing

but tbf it's not like I had a class with fourier stuff ever (like I watched a video series abt fourier + skimming wikipedia here and there, that's how I pass as someone decent with fourier crap, but I just know the very basics)

[dawn junco]

heard about it but no I don't remember what it is

[whole spear]

It's a test to determine uniform convergence of a series of functions

I did a typo in my hand in, and he commented on it, but I'm not sure if it was a mistake in typo that he was dissatisfied or if I applied the test wrong. I'm pretty much trying to reverse engineer his stingy comments

[dawn junco]

ok I mean I can look

if it's just "fel" reverse-engineering I can try ig

[whole spear]

Let me take a pic

So first I take absolute value of the fourier series

From assignment

wait one moment, let me just rethink what is going on

exactly

So I take the absolute value of the fourier series, but I generalize it

I then rewrite it to sin

[dawn junco]

yeah I agree with the guy your k's and your t's look too similar

[whole spear]

now, my question is

in the 1-cos(kt) I wrote in the numerator

am I supposed to write something other than t? like x?

so kx?

[dawn junco]

it should be 1-cos(2k) tho

[whole spear]

hmm, I thought of just keeping it general, but tbh writing it into 1-cos(2k) works just as fine

and then the cos(kt) stays the way it does, the one which we're multiplying with

[dawn junco]

it just looks like a damn typo tbh

[whole spear]

Yea, so the argument that stays the same, I then argue that this is smaller than 2/k^2

that is a known convergent p series

[dawn junco]

yeah

[whole spear]

But what is confusing me

is the question

''You are not supposed to summerise over t?''

on the bottom

[dawn junco]

cause it completely seems like you just wrote 2/t^2

[dawn junco]

^

[whole spear]

so you think that is just related to it

[whole spear]

oh

So that's why

He thinks my k is a t?

[dawn junco]

yeah

[whole spear]

Okay, I'll correct it then

[dawn junco]

like this thing screams 2/t^2 to me

nothing else

[whole spear]

😔

[dawn junco]

just have a bigger bar for your k's or something

[whole spear]

Yea doing that rn

crazy your diy complex analysis reading by yourself

is more helpful than the average lecturer

[dawn junco]

I mean I'm not helping with the complex analysis

I'm helping with typography

much easier

[whole spear]

hahahaha

[dawn junco]

cause your argument is fine, the problem is k vs t

[whole spear]

Do you understand the language? o,o?

or you just decipher from the math

[dawn junco]

based myself mostly on this

mostly looking at the math otherwise yeah

I google translated the first comment of your prof tho, to be sure

[whole spear]

got it

Thank you, I'll rewrite all typos and correct the stuff we talked about

And reread through my solutions and rehand it in

You've been very helpful thank you

[dawn junco]

so you can resubmit as much as you want or something ?

[whole spear]

Well, they haven't told us how much we can resubmit it

But he told me to resubmit it

I need to pass this assignment

to be allowed to take the exam

in 2 weeks

[dawn junco]

sounds nice of them tbh

at least they're not like, haha you got a shit grade on this assignment, no other submission gbye

see ya next year

[whole spear]

I mean we have 5 computer exams + this assignment. You need to pass these to be allowed to do the exam

then the exam will pretty much be your whole grade

So yea, we've had 6 weeks of lectures

each week has been 1 computer exam

last week was assignment, now 2 weeks of exam season, we're lucky and ended up being on the final day of the exam season

if that makes sense

[dawn junco]

well it's how it works at your place, it's not like I can contest that fact

but yeah it's a bit like how they do in germany (at least from what I gathered from some german users around here)

[whole spear]

Ya I mean germany is just over the sea, so wouldn't be suprised

[dawn junco]

yea it's close

[whole spear]

But most our courses has ''obligatory moments'' which you need to complete to be allowed to do the exam

they mean nothing for your final grade

but I guess it's their way of trying to help student stay on track

[dawn junco]

also less crap exams to correct

[whole spear]

most likely

Have you studied or do you study anything?

[dawn junco]

finishing masters in CS rn

[whole spear]

Do CS do that much math?

Or you just have done it yourself?

[dawn junco]

I've done a lot myself yea

it's just kinda disjoint math in CS for the most part

[whole spear]

Makes sense

[dawn junco]

mostly discrete stuff, not a lot of fourier series

[whole spear]

Ya, I'm in engineering hence why I need to do a lot of this

cuz this apparently becomes super important in the future when modelling

[dawn junco]

for PDEs they're pretty useful yeah

that's why fourier came up w/ them iirc

heat equation and stuff

[whole spear]

ya, that's what I read in the introduction for fourier in my book

we'll see when they begin having us implement it in future courses

[dawn junco]

and then there's good ole data compression

not fourier stuff itself but related ideas at least

[whole spear]

Yea

Well thank you for the help. You've been super helpful. I should get some proper sleep now haha

[dawn junco]

aight good night

[whole spear]

You too

.close

[cedar kiln]

Channel closed

Closed by @whole spear

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[proper bison]

does anyone know if i can name a variable something just to make it mroe readable for me? like i want to name "a" as price of potatoes and "f" price of cucumbers

[proper bison]

this is desmos

[dry temple]

desmos notation kinda sucks

you just have to make giant subscripts

i think there's a option to just write text on a line, so maybe documenting your variables with comments is a better altnerative

[livid hound]

you could also use letters associated with what they represent
p for potatioes
c for cucumbers
etc

to make notes on a separate line
start with
"

e.g.

[cedar kiln]

@proper bison Has your question been resolved?

[proper bison]

yep tq notes seem good enough although not perfect

[cedar kiln]

Channel closed

Closed by @proper bison

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fringe mauve]

a monic cubic polynomial P(x), when didvided by $x^2 + 4$ leaves a remainder of $x + 8$ and when divided by x leaves a remainder of -4. Find the polynomial in expanded form.

[wraith dagger]

Big Chicken

[modest cairn]

what have you done so far

[fringe mauve]

formed two equations

[modest cairn]

let's see the equations

also quick questionare do you know what monic and cubic means

[fringe mauve]

P(x) = q(x)(x^2 + 4) + (x+8)

and P(x) = g(x)(x)-4

[fringe mauve]

yh

[modest cairn]

can you write two different q(x)

[fringe mauve]

now what

[modest cairn]

now for the first q(x) what do know about its degree

[fringe mauve]

its linear

and g(x) is a quadratic

[modest cairn]

cool cool

[modest cairn]

give me a genreal form

for it

and uh use properties of the monic

[fringe mauve]

ax + b

[modest cairn]

what is a?

[fringe mauve]

1

[modest cairn]

perf

what does that equation look like now

mr chicken

[fringe mauve]

P(x) = (x+b)(x^2 + 4) + (x+8)

[modest cairn]

hmm

now can you help me with an equation for the second one

[fringe mauve]

did u just change ur pfp

[modest cairn]

no

[fringe mauve]

it was gardevoir before and now its a cheetah

[modest cairn]

what's your wifi speed

[fringe mauve]

and P(x) = (x^2 + px + q)(x)-4

[fringe mauve]

idk like 100mbps

[modest cairn]

that might be the issue

[fringe mauve]

?

[modest cairn]

expand this out

[modest cairn]

expand this out

[modest cairn]

the wifi prob messing with the pfp

[fringe mauve]

bx^2 + x^3 + 4b + 5x + 8

[fringe mauve]

x^3 + px^2 + qx - 4

[modest cairn]

4b + 8 = -4

solve for the rest

[fringe mauve]

wait what

[modest cairn]

b is a constnat no?

[fringe mauve]

what about p and q

[modest cairn]

well if you have b

then you know

p

cuz p = b

[fringe mauve]

and q = 5

so b is -3

and i have my answer

[modest cairn]

word

[fringe mauve]

thanks bro

[modest cairn]

ofc ofc

[fringe mauve]

.close

[cedar kiln]

Channel closed

Closed by @fringe mauve

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[blazing zephyr]

status 1

[worldly chasm]

@blazing zephyr hint: consider what would be implied if d is smaller than p_n, then it would necessarily be composed of prime factors from the list of p_i.

[blazing zephyr]

"it would necassrily be composed of prime factors from the list of p_i" what does this mean?

[worldly chasm]

d's prime factorization

[blazing zephyr]

hm

i dont see what that would imply unfortunately

[worldly chasm]

So let's say the difference is c, and d|c.

If d contains p_j, then c also contains p_j. Recall c = Π_i a_i - Π_i b_i and p_j is a factor in exactly one of these terms.

[blazing zephyr]

hm

oh wait say d contains $p_j$, that mwans c contains $p_j$, so you can factor out $p_j$ from $\prod_{1}^{h}a_i^{\alpha_i}-\prod_{1}^{k}b_i^{\beta_i}$, but since only one of them has it, it cannot be factored, so c cannot have $p_j$, so thats a contradiction?

[worldly chasm]

Yup

Precisely

[wraith dagger]

Skill_Issue

[blazing zephyr]

alr thanks

im gonna close this, ill open a new one later when i get home cause i want to fully write the solution tyy <3

.close

[cedar kiln]

Channel closed

Closed by @blazing zephyr

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wintry jackal]

How do I find a? Ik how to find everything else expect a.

[wintry jackal]

General form: Y=a(k(x-d) +c

D AND C are the graph vertex

That’s all ik

[dire geode]

Do you know what x^3 looks like around 0?

[dire geode]

What is this supposed to be?

What's k

[wintry jackal]

K is horizontal stretch / compression