help-13

[covert cipher]

xy^2dx + yx^2dy

[covert cipher]

similarly xdy-ydx

[devout wing]

that's what i did, also tried case 3. but it's not working

[covert cipher]

try analysing this

it looks maybe like the product rule?

multiply and divide that by 2, and you get 1/2( y^2 2xdx + x^2 2ydy)

[devout wing]

i also found out that the integrating factor is 1/x²+y². so it will be exact DE. but then i don't know how

[covert cipher]

honestly even im stumped, sorry

the -y in the original question made this very hard, otherwise it seemed alr

im getting the equation x^3dx + 1/2d(x^2y^2) + x^2d(y/x) + y^3dy = 0

except i cant figure out how to integrate the third term

[cedar kiln]

@devout wing Has your question been resolved?

[devout wing]

it's ok, thanks anyway for trying @covert cipher

i need help with 3b please 🙏🏻

[cedar kiln]

@devout wing Has your question been resolved?

[thick wadi]

The product rule was the correct idea, but you want to actually take x in terms of y rather than y in terms of x, I think. So write:

(x^3 + xy^2 - y) dx/dy + (y^3 + x^2y + x) = 0

y^3 + (x^2 y +xy^2 dx/dy) + x^3 dx/dy + (x - y dx/dy) = 0

Wait hang on

Nope this is wrong sorry

[cedar kiln]

@devout wing Has your question been resolved?

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[lucid iris]

i don't know if i have set up right

im very confused on this problem

[cedar kiln]

@lucid iris Has your question been resolved?

[lucid iris]

<@&286206848099549185>

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@lucid iris Has your question been resolved?

[lucid iris]

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[swift estuary]

how do i do this

[swift estuary]

so its (-oo, 3) u ( 3, oo)

[sly abyss]

apologies

it does

what value of x

does sqrt x-3=5

aka when does x-3=25

what value of x

[swift estuary]

i tried (-oo, 28) u ( 28, oo). it didnt work

[sly abyss]

bc

(-oo, 28)

isnt right

what is the sqrt of a negative number

does it exist

?

[swift estuary]

no

[sly abyss]

so

what must x be greater than

or equal to

to make the expression sqrt x-3 > or equal to 0

[swift estuary]

so x is greater than or equal to three so its [3,oo)?

[sly abyss]

but

remember

x cant equal 28

[swift estuary]

(-oo,3] u [3,28) u (28,oo) ?

[sly abyss]

no

x has to be greater than 3 still

or equal to

[swift estuary]

I have no idea what it could be

[sly abyss]

greater than or equal to 3 not equal to 28

what does that look like that

[sly abyss]

2/3 of this answer is correct

[swift estuary]

is it just [3,28) u (28,oo)?

[sly abyss]

yes

[swift estuary]

.close

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[shut sapphire]

how can i tell the limit doesn't exist without looking at the graph

[pseudo pilot]

for a value bigger than 4 numerator is positive and denominator is also positive (a bit bigger than 0)

for a value smaller than 4 numerator is positive and denominator is negative (a bit smaller than 0)

[last girder]

I'm not fully sure, but I guess you can check where the function is discontinious? In this example since there's an asymptote at 4 you auto know there's a break in the graph. Then you check for value greater and less than 4 to see which way it's going.

[shut sapphire]

https://tenor.com/view/praying-crying-downfall-sad-tears-praying-gif-7785197299162436598

.close

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[dreamy patrol]

Hello, can someone please help with this? I asked ~30-45 mins ago, but nobody answered, and when I left to do something, channel closed 😦

[dusk goblet]

integration by parts

[dreamy patrol]

Ik that but like

How

Which v which u

[dusk goblet]

u = tan^2n

[dreamy patrol]

If you’re sure….

[dusk goblet]

see the tan^2n-1

that should give you the hint

[dreamy patrol]

Okee

I’ll open again if it don’t work

.close

[cedar kiln]

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[dreamy patrol]

Thanks btw

[dusk goblet]

wait

i just looked at their solution again

[dreamy patrol]

huh

[dusk goblet]

well work it out first i guess

the u might be wrong

i’ll work it out too

[dreamy patrol]

i'll try

lemme know if you find smt

i'm a pretty slow worker tho 😭

[dusk goblet]

so the tan^(2n-2) is what made me think of it

$\tan^{2n}(x) = \tan^{2n-2}(x) \cdot \tan^2(x)$

[wraith dagger]

knief

[dreamy patrol]

Hey someone else said that earlier

[dusk goblet]

and tan^2(x) = sec^2(x) - 1

so let’s try that

[dreamy patrol]

Okay, I'll try that

[dusk goblet]

because if we want to integrate

we’ll need a sec^2

for a du

[dreamy patrol]

yk it's a tough problem when your paper looks like it's been in a warzone

[dusk goblet]

so we have $\tan^{2n-2}(x) \sec^2(x) - \tan^{2n-2}(x)$

[wraith dagger]

knief

[dusk goblet]

but in the integral of course

yes?

[dreamy patrol]

uh

Okay

I think

[dusk goblet]

so we can write the integral as follows

$\int \tan^{2n-2}(x) \sec^2(x) dx - \int \tan^{2n-2}(x)dx$

[wraith dagger]

knief

[dusk goblet]

yes?

this is what made me think of this

see the integral of tan^2n-2

that’s already part of our answer

[dreamy patrol]

ok

hang on

[dusk goblet]

now we just need to manipulate the left

[dreamy patrol]

how did you transform the tan^2x to sec^2x - tan^(2n-2)x

[dusk goblet]

simple u sub

[dreamy patrol]

sorry, idk how to use the bot

[dusk goblet]

$\tan^2(x) + 1 = \sec^2(x)$

[wraith dagger]

knief

[dreamy patrol]

yeah

[dusk goblet]

so tan^2(x) = sec^2(x) - 1

[dreamy patrol]

yes

[dusk goblet]

and ^

[dreamy patrol]

yes

[dusk goblet]

i replaced tan^2 with sec^2 - 1

then distributed the tan^2n-2

[dreamy patrol]

OH

distribution

ofc

right, right, go on

[dusk goblet]

so now we already have the right side in our solution

we need a u sub

for the left

since the derivative of tan is sec^2

which we have

[dreamy patrol]

YOU'RE SO RIGHT

[dusk goblet]

can you do it from here?

[dreamy patrol]

thank you thank you thank you

I think so

[dusk goblet]

what do you think the u is

[dreamy patrol]

If i can't i'm dropping the course lol

def tan^(2n-2)x

[dusk goblet]

nope

[dreamy patrol]

goddammit

[dusk goblet]

u = tan(x)

[dreamy patrol]

imma commit toaster bath

ok

[dusk goblet]

see how they divide by 2n-1

[dreamy patrol]

power rule

right

[dusk goblet]

2n-1 = (2n-2)+1

[dreamy patrol]

x and n and all this is frying my brain

[dusk goblet]

$\int x^m dx= \frac{x^{m+1}}{m+1}$

[wraith dagger]

knief

[dreamy patrol]

Yes

Okay

[dusk goblet]

so u = tan(x)

du =?

[dreamy patrol]

I've got it from here (prolly), i'm just bad at handling multiple variables

sec^2x

[dreamy patrol]

I'm sure this will go well in Calc 3

[dusk goblet]

just wait my friend

just wait

😹😹

[dreamy patrol]

The history of this channel stays, right?

So i can close it safely?

[dusk goblet]

yea

mhm

[dreamy patrol]

K cool

tysm tysm

[dusk goblet]

you’re welcome

[dreamy patrol]

.close

welp

what

.close

ok

[cedar kiln]

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[faint dust]

n

[faint dust]

rrrm

nvm

.close

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[faint dust]

.reopen

[cedar kiln]

✅

[faint dust]

i dont understbd how to derive to this

[remote trail]

,rotate

[cedar kiln]

@faint dust Has your question been resolved?

[carmine bronze]

Do you know the equation for calculating the height?

[faint dust]

is it v^2=vox^2+2a(x-x0)

i think i kinda got somewhere

https://gyazo.com/c11e4c3e34ac6352e8696daa76f99982

thne vx^2 got blurred out by the circle but

i used that and replaced the vx^2 with vi^2 and cancelled out the (x-x0)

so it was vi^2 = vxo^2+2g

then solved for vxo^2 and got

vi^2/2g

idk if i derived it right tho

it was kinda a airball

[carmine bronze]

Looks correct.

[faint dust]

https://gyazo.com/06f3659996466deb290d0137a453d269

[carmine bronze]

Kind of weird that they gave you the initial velocity yet none of the answers take it into account though. 🤔

[faint dust]

idk i just replaced V^2x with Vi^2 and it looked close enough

[carmine bronze]

At the maximum height, the velocity of the bowling pin will be zero.

[faint dust]

ohh thats why we solving for that one

[carmine bronze]

Do you understand why the velocity at the maximum height would be zero?

[faint dust]

ye

becuase its like

its the point where its not going up or down

cuz it goes up reaches the max height at 0 then falls down again?

[carmine bronze]

Yes, it stops travelling upwards and starts travelling downwards. For that moment, its velocity is zero.

[faint dust]

tysm

[carmine bronze]

yw

[faint dust]

.close

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[frozen rune]

oh

uhh

[jovial kite]

awesomer

[frozen rune]

good luck

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[marsh pond]

how should i solve this?

[crimson sedge]

Well you’re looking for the local max of f(t) so you’d need to find the derivative of f(t)

Notice when you take the derivative of both sides you just get the function inside the integral

[marsh pond]

nvm, i got it

-12

[marsh pond]

but i solved it differently

i used diamond method on numerator

t = -12

how would you solve it with derivative?

[dire geode]

This wouldn't work in general for problems like this

If the numerator were 1 for example and the denominator were the same

[cedar kiln]

@marsh pond Has your question been resolved?

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[nimble mountain]

what if addition distributes over multiplication

[nimble mountain]

say we have a field(or ring). minus the distributive property. and replaced it with a+(bc)=(a+b)(a+c)

would this be well defined or?

[digital cliff]

what would (bc)+a look like then

[nimble mountain]

rings and fields have addition being abelian. so the same

[digital cliff]

but by how youve defined it, would it not (taking a=1a)
be (bc)+a=[(bc)+1][(bc)+a]

[nimble mountain]

yea it could be as well.

is there an issue with that?

i believe there is no issues unless we can derive nonsense from it

aka a contradiction

or everything being a point

[digital cliff]

im just not sure you could consider them equal for general elements,
it implies [(bc)+1] is the identity, but i assumed 1 was the identity

if thats an issue

[nimble mountain]

sorry how did u get bc+1 to be the identity?

its more like, multiplying bc+1 to bc+a does nothing

while the definition of a multiplicative identity would be multiplying on the left or right of all elements leave it the same

similar to how given a matrix with all eigenvalues being 1, multiplying that by itself many times does nothing

hi sno

[sacred grail]

1 + 0*1 = (1 + 0)(1 + 1) = 2 so 0 = 1

[nimble mountain]

thank you

snow and Azo

.close

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[fossil coral]

I need help with this, Im a little unsure. Do I isolate the 2x first, before applying the exponent?

[fossil coral]

hmm

[brazen dagger]

You need to replace x in f(x) by g(x) , for an example

g(x) = x+1
(f°g)(x) = 2(x+1)```

[fossil coral]

huh

[fossil coral]

I dont get why, but I understand the math

[brazen dagger]

What is g(x) value in my example?

[fossil coral]

x+1

[brazen dagger]

What is f(x) value

[fossil coral]

hm i see now

2x

[brazen dagger]

So we replaced the x in f(x) by g(x) value that is (x+1)

So 2x became 2(x+1)

[fossil coral]

ok

[brazen dagger]

If g(x) was x²+1
Then f(x) would have become 2(x²+1)

[fossil coral]

🤔

[brazen dagger]

[fossil coral]

Had a bad feeling this is probably not going well

[brazen dagger]

You will get an equation in terms of x not a number

[brazen dagger]

What do you not understand here @fossil coral

[fossil coral]

ok let me finish writing it

[brazen dagger]

What did you do ??
7(5x²+5x)????

[fossil coral]

:) Ah. Yep. Wasnt right, i figured.

What i did was,

i canceled out the x from 2x+5 by dividing

then i add the 2+5 to get 7

[brazen dagger]

Whyyy, there is no cancellation

[fossil coral]

hm.

[brazen dagger]

Did you understand this or not

[fossil coral]

oh. thought you divided 2x by x

to cancel the x

[brazen dagger]

No

There is no division or cancellation

[fossil coral]

k

[brazen dagger]

Let me give you one more example

g(x) = x²+1
(f°g)(x) = (x²+1)+1```

[fossil coral]

f(x) = 2x+5
g(x) = 5x²+5x
(f°g)(x) = (5x²+55x)+2+5

dam it

that 5555x fuck

[brazen dagger]

No

[fossil coral]

curse this glitched auto correct

meant for 55x To be 5x

[brazen dagger]

Still wrong

f°g(x) =2(g(x)) +5```

You need to replace x with g(x) buddy

[fossil coral]

oh.

hmm

2(5x^2 +5x) +5

[brazen dagger]

Yes

[fossil coral]

So, PEMDASing the 2, (10x^2 + 10x) +5

erm do i factor it nenext?

[brazen dagger]

No , they are not asking for a solution

Just f°g(x)

[fossil coral]

oh.

thank you!

[brazen dagger]

No problem

[cedar kiln]

If you are done with this channel, please mark your problem as solved by typing .close

[fossil coral]

.close

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[odd sierra]

sry

[odd sierra]

how is milk not homogenous

like it is like water and salt no?

[dreamy void]

#linear-algebra

[odd sierra]

bunch of things within the milk but u just see the milk

oh

[drifting marlin]

no don't post in there

[bleak viper]

not really

[clear umbra]

i think hes asking about chemistry and science lol

[bleak viper]

u can see fat globules rise to top

when you pour milk in a glass

its not uniformly mixed

so its heterogenous

[odd sierra]

oh

ok make sense thnx

[plain ridge]

doesn't rlly matter what you can see with your eyes

[odd sierra]

ah

[dreamy void]

are you blind

[plain ridge]

what💀

but yeah just because things appear homogenous doesn't mean they're a solution at a molecular level or whatever

[bleak viper]

i saw what you deleted

[odd sierra]

lol

[plain ridge]

why's everyone shitposing in this thread dawg💀

[west path]

#competition-math

[dreamy void]

i thought the question to begin with was weird 💀

but chemestry forgot about it

[odd sierra]

Ok

[hollow trail]

the milk you find in the grocery store has undergone a process called homogenization which makes it homogeneous. but milk in its natural state is heterogeneous because it has fat (oil) in water and by default the cream (fat) layer rises to the top

[odd sierra]

Oh ok

Thanks everyone

.close

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[gaunt coral]

How to do algebra

[nimble mountain]

wdym algebra

[gaunt coral]

algebra

[normal cipher]

huh

[nimble mountain]

group theory?

[gaunt coral]

like math

[normal cipher]

wdym

oh math

[nimble mountain]

or understanding how to use variables as numbers?

[gaunt coral]

ya

[nimble mountain]

do u have a specific question to go with it?

[gaunt coral]

like. x =5y

y is 7

[bleak viper]

and you want to find x?

[gaunt coral]

ya

[bleak viper]

substitute y=7 in x=5y

[gaunt coral]

ok

[normal cipher]

x=5*7=35

[gaunt coral]

huh

.close

[cedar kiln]

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[gaunt coral]

how do i make this free again im done

Available i meant

.reopen

[cedar kiln]

✅

[gaunt coral]

.done

.Finished

[bleak viper]

you just .close the channel

[gaunt coral]

.close

[cedar kiln]

Channel closed

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[gaunt coral]

gn

[bleak viper]

gn

[cedar kiln]

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[fossil coral]

Im not sure how to solve this

[summer otter]

what will be f(-1)

[fossil coral]

um.

1/x ?

[summer otter]

no

[fossil coral]

idk tbh, how do u find f(-1) ?

[clear umbra]

do you know how to read piecewise function definitions?

[fossil coral]

Sort of. I struggle with them

[summer otter]

it is given that that f(x) is a peicewise function see the value of x and check what should you take

[clear umbra]

every function has a range of x values that it accepts only

then just see what your input is, and which function allows it

[fossil coral]

so for 1/x , whatever that goes in the x for x > 3 has to be larger than 3

[clear umbra]

yes

[summer otter]

yep

[fossil coral]

hm

[hot crag]

is -1:

a. less than -3, i.e. -1 < -3
b. between 3 and -3 (inclusive), i.e. -3 < -1 < 3
c. greater than 3, i.e. -1 > 3

[fossil coral]

a. no.
b. erm. yes?
c. no

[hot crag]

yeah you're right

[hot crag]

now that's what i derived directly from this

what this says

is when x > 3
use that definition

when x is b/w -3 and 3 use another one

etc

so here, since -1 is between 3 and -3, you use definition 2

[fossil coral]

definition 2?

[hot crag]

in here

by that i mean the second expression

[hot crag]

?

[fossil coral]

the one in the middle with the 9 and the

[hot crag]

yeah what about that

it's correct if that's what you're asking about

[fossil coral]

k

now i get what you guys meant

.close

[cedar kiln]

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[rare nimbus]

how is the answer is a in question (b)?

[rare nimbus]

I came to the conclusion where infinity * 0

[cedar kiln]

@rare nimbus Has your question been resolved?

[cedar kiln]

@rare nimbus Has your question been resolved?

[drifting marlin]

two things:

1. you forgot to account for the a when you did your initial u-sub
2. you can compute the limit of -ue^(-u) and get something more useful than infinity*0

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[torn oriole]

How would one solve the inequality on paper: $\sqrt{x^2 + 6x + 9} \geq 5 - |x|$, without having to do much work?

[wraith dagger]

Bishop

[raven shard]

could start by factoring x^2 + 6x + 9

[torn oriole]

I did

(x + 3)^2

[bleak viper]

so x + |x| >= 2

[raven shard]

no

very important square root of (x + 3)^2 is |x + 3|

[stable hull]

sqrt(a²) = |a|

[bleak viper]

i keep forgetting this 💀

[torn oriole]

Oh thats how

Yea i think thats all what i will need for now

Ty

[raven shard]

yw

[torn oriole]

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[cyan loom]

how is the answer to this A? i can clearly see that the variability is larger for the chinstrap penguins

[cyan loom]

or do we consider those extra pink dots as outliers?

[tranquil oracle]

yeah the outliers diagnosis should be correct

the point of variability is to talk about the general population

you can check how variability is defined too

[cedar kiln]

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[sudden vessel]

I need help with these 2 questions

Idk how to start

[sudden vessel]

can anyone help out?

I'd appreciate it

[cedar kiln]

@sudden vessel Has your question been resolved?

[cerulean star]

radii and tangents are perpendicular

oh

typo here (of course there is)

that calculation is HALF of x

so double that

@sudden vessel

11a is a trick question

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[sudden vessel]

Hmm

[cedar kiln]

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[sudden vessel]

How

[cerulean star]

You are alrady given the number of rotations, this first part of the problem is only asking you to convert that angle to radians.

[sudden vessel]

What about the 2nd part

[cedar kiln]

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[ember pecan]

minimum number of dogs that have a mass of more than 26kg

would just be 5, because you assume all the ones in the 20-30 range are <26

and maxmium would similarly be 16, because you assume they're all >26

[crimson sedge]

Oh

Wait what

i think i overcomplicated it

Ur so smart omg

[ember pecan]

:)

[crimson sedge]

can u close this one

[radiant scaffold]

type .close

[crimson sedge]

.close

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[foggy basin]

I think I messed up the calculations 🤣

[crimson sedge]

-4-2i

[foggy basin]

Ohhh yeah, I forgot to note that at the top one

[crimson sedge]

try re-expanding this too

$(a+b)^2 = a^2 + 2ab + b^2 \neq a^2 + b^2$

[wraith dagger]

icannotdoanymorecauchy

[foggy basin]

OHHHHH

I will try that then!!! Thank you so so much

.close

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[cunning prawn]

ive got the asnwer to part b which is 127.65625-4.9(t^2-1.25)^2

[cunning prawn]

i just have no idea how to do ci and cii

i have a clue tho

ive figures out how to do cii but not ci

cii is 128m and 1.25 seconds

<@&286206848099549185>

[dire geode]

Do you know what height ground level is

[rotund yacht]

what did you say for a?

[cunning prawn]

120 is the height the ball is dropped from

since t=0

[cunning prawn]

id assume 0

[rotund yacht]

How does this fulfill A - B(t - C)?

[cunning prawn]

because you have to complete the square

so

wait lemme show u what i done

[rotund yacht]

But, t^2 ≠ t

[cunning prawn]

yes

this is the right answer ive checked with the answer scheme

i also had my doubts

sorry

i meant to write 127.65625-4.9(t-1.25)^2

not t^2

[dire geode]

Use this and the interpretation of ground level to get an equation

[rotund yacht]

oh ok

[cunning prawn]

is this where u start

[rotund yacht]

what is h(t) when ball is thrown, and what is h(t) when it reaches ground?

[cunning prawn]

120 and 0

[rotund yacht]

ya, so now how do you get the time when ball is thrown and the time when ball reaches ground?

[cunning prawn]

no idea🤕

[rotund yacht]

right, so what is h(t)?

[cunning prawn]

120

wait

[cunning prawn]

do u do this equation but replace 0 and 120

[rotund yacht]

ya, that's one way I would think of doing it.

[cunning prawn]

ill try it now

i got it wrong

the answer is 6.35

[rotund yacht]

how'd u do it?

[cunning prawn]

and i got 1.25 +- 1.25

[rotund yacht]

why did you think that was the answer?

[cunning prawn]

yh

[rotund yacht]

I guess I mean, how did you come to that answer.

[cunning prawn]

was i meant to subtract 120 at the beginning

that would give the same answer nvm

[rotund yacht]

I would've plugged in 0 and 120 for h(t), and then subtracted the two times I got for them. Because that is (the instant the ball is thrown - the instant it reaches the ground)

[cunning prawn]

omg

dude

i was just thinking that

lmao

but would i get 2 answers

[rotund yacht]

You wouldn't.

[dire geode]

Show the two answers

[cunning prawn]

so if h(t) = 120 i got 2.5 or 0

and if h(t) = 0 i got 1.25 +-sqrt20.05

[dire geode]

Which one of these is physically meaningful

[cunning prawn]

idk

120 right

[dire geode]

Aren't you doing ci)

[dire geode]

Read ci again and see which of these answers makes sense

[cunning prawn]

so it would be 0

[dire geode]

No

[cunning prawn]

bruhhh

[dire geode]

At time t=0, the height is 120

[cunning prawn]

hollup

so do u substitute 0 for t

in the equation that = 120

[dire geode]

To do ci? No

To do part a)? Yes

[cunning prawn]

i mean i got part a

which is 120

[rotund yacht]

Mb, you don't need to set h(t) = 120.

[cunning prawn]

im lost

[rotund yacht]

Because, at h(t) = 120, t = 0. Since we haven't thrown it yet or just started throwing it.

and we don't need to subtract 0

now, if you set h(t) = 0, what do you get?

[cunning prawn]

i think this

[rotund yacht]

Okay, so you're doing the quadratic formula there?

[cunning prawn]

ye

but thats hwne h(t) = 120

[rotund yacht]

You messed up ur arithmetic

[rotund yacht]

Oh okay, so if u set it to 0, then?

mb, I jumped the gun ig.

What happens if you set h(t) = 0?

[cunning prawn]

i get this

[rotund yacht]

but ya, sqrt(26.0522959184) + 1.25 is the right answer

[cunning prawn]

ok

so if i mess my mental maths in the test

im gonna cry

[rotund yacht]

lmao

But the part we missed was what t = when h(t) = 120, and after rereading, it makes sense that t = 0

B/c 0 seconds have elapsed.

[cunning prawn]

yh

alr

thanks guys

.close

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[vivid shard]

What do I need to do in order to get the second 'division'

Fraction

How do I need to 'reform' it

.close

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[strange jay]

Question : prove that the product of three consecutive natural whole numbers is dividable by 3

[odd verge]

Try calling the first one 'n'

I don't think much is required

[dusk finch]

i honestly dont think that's gonna be helpful

if you were thinking about expanding it

[odd verge]

Not really

I already figured out expansion doesn't help

[dusk finch]

In general, product of numbers is divisible by a prime p iff some number in the product is divisible by p

or specificaly
Product of numbers is divisible by 3, iff at least one of the numbers in the product is divisible by 3

[odd verge]

There's no 3 consecutive natural numbers which doesn't contain a number divisible by 3

Multiplication by 3 is just repeated addition of 3

[strange jay]

Ok thank you so much

[cedar kiln]

@strange jay Has your question been resolved?

[cedar kiln]

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[fervent depot]

can someone help me with this?

[cerulean sail]

Which one? And what's the aim?

[fervent depot]

number 7

want to find second derravitive

@cerulean sail

[cerulean sail]

Cool, so are you happy that if you differentiated dy/dx with respect to x, you get the second derivative d^2y/dx^2?

[fervent depot]

i dont know if i derived the first one proberly

[cerulean sail]

The xy^2? If so, you didn't

[fervent depot]

breh

i use chain rule right?

[cerulean sail]

Product and chain rules

[fervent depot]

i need some help i did it wrong

nvm i need help with anothe rquesrion

<@&286206848099549185>

[dusk goblet]

did you differentiate f

in terms of g and h

@fervent depot

[fervent depot]

let me show you the work

@dusk goblet

[dusk goblet]

dawg

what

[fervent depot]

i used the chainr ule

chain rule

[dusk goblet]

what if f’

in terms of g and h

[fervent depot]

-15

[dusk goblet]

bruh

[dusk goblet]

^

[fervent depot]

ok doing it again

@dusk goblet

[dusk goblet]

yes

holy pings

is that where your name comes from

i thought it had to do with penguins

[fervent depot]

lol

yes it is from pingu

my bad for the pings

[dusk goblet]

huh

💀

anyways

$f’(x) = g’(h(x)) \cdot h’(x)$

[wraith dagger]

knief

[dusk goblet]

we want f’(2)

[fervent depot]

yes that is what i put in

yes

[dusk goblet]

so $f’(2) = g’(h(2)) \cdot h’(2)$

[wraith dagger]

knief

[dusk goblet]

h(2) = 3

h’(2) = -1

g’(3) = -4

so 4

make sense

[fervent depot]

wait why did you put g' of 3

[dusk goblet]

because h(2) = 3

g’(h(2)) = g’(3)

[fervent depot]

oh brehhhhh

wait let me do that agan

oh i got 4

[dusk goblet]

good man

🤝🏻

[fervent depot]

i need help wit this one

[dusk goblet]

your derivative is wrong

but it won’t matter

[fervent depot]

how can ii find the deravtive

[dusk goblet]

$h’(x) = 3(f(x))^2 \cdot f’(x)$

[wraith dagger]

knief

[fervent depot]

sheesh forgot the 2

i keep on making the same mistake

is it f(b) -f(a)/b-a?

[dusk goblet]

instantaneous brother

not average

[fervent depot]

what is the formula for it

[dusk goblet]

brother

it’s the derivative

[dusk goblet]

^

instantaneous rate of change is the derivative

[fervent depot]

but how can i find it on a graph?

[dusk goblet]

pingu

it’s asking for the derivative

[dusk goblet]

^

they gave line segments

you can find the slope of that can’t you

the derivative/slope of a line is constant

[fervent depot]

i dont understand

[dusk goblet]

$h’(2) = 3(f(2))^2 \cdot f’(2)$

[wraith dagger]

knief

[dusk goblet]

just find f’(2) and f(2)

what’s f(2)

[fervent depot]

f(2) is 1

[dusk goblet]

yes

and what’s f’(2)

[fervent depot]

will it be 0?

wait do i use the point slope formula?

[dusk goblet]

why point slope

and no not zero

what’s the slope of a line

the formula

[fervent depot]

rise/run?

1/2

[dusk goblet]

yea

[fervent depot]

i got the same answer using the f(b)-f(a)/b-a

was that just luck?

[dusk goblet]

that’s the slope formula.

that’s how you find f’(2)

so no it’s not luck

[fervent depot]

arent we suppose to find f'(2)?

[dusk goblet]

it’s the same as y2-y1/x2-x1

yea

2

[fervent depot]

so the answer was 3/2?

[dusk goblet]

yea

[fervent depot]

i habe a problem with this one aswell

[cedar kiln]

@fervent depot Has your question been resolved?

[fervent depot]

.close

[cedar kiln]

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[dusty raptor]

can someone check my work for question 4.40?

[cedar kiln]

@dusty raptor Has your question been resolved?

[dire geode]

why are you doing u-sub. just expand like you did earlier

this usub is wrong

[cedar kiln]

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[fickle kraken]

I would like to know if my answer makes sense to this system, if x^3 is a free variable, therefore what would it value be?

[dreamy void]

@dusk goblet so this a quiz too huh

[dusk goblet]

could be but isn’t as obvious as the one before

[dreamy void]

ah now it could be

[dusk goblet]

the 1 point is telling

covers the title

i wouldn’t be surprised

probably is

@fickle kraken you need help with your quiz?

[dreamy void]

that's more of an argument

[dusk goblet]

^

[fickle kraken]

Yeah

That would be amazing @dusk goblet @dreamy void

[dusk goblet]

so it’s a quiz

we got you bro

[dreamy void]

<@&268886789983436800>

[dusk goblet]

😹😹😹

clockwork

[fickle kraken]

It's an exercise from a site, is it allowed? Im not sure about the rule

@dusk goblet @dreamy void

[dusk goblet]

nah you said it’s a quiz

we got you

🤝🏻

[dreamy void]

see this is what i meant

it could be an exercise in form of a quiz

i am just trying to act in good faith

and not ping mods for every occasion

just because it might be

[dusk goblet]

i don’t

lol

only when they bite the bait

[dreamy void]

i dont see the bait

[fickle kraken]

Oh right I see, then Quizze questions are forbidden in this server, I guess that makes sense, but my worry here is that I have a hard time understanding parametric vector form so Im trying to have an idea here LOL

[cedar kiln]

@fickle kraken Has your question been resolved?

[cedar kiln]

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[waxen kraken]

Hi, I have some confuse in stable, unstable and asymptotically stable in equilibrium point in system of ODE. I want to know the difference between I find the eiganvalue of it to see if it is stable and unstable and using lyapunvo function to show that, What's the difference between this two methods

[cedar kiln]

@waxen kraken Has your question been resolved?

[cedar kiln]

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[wild patio]

I’m confused

Do I do sodium +1

[viral monolith]

This is chemistry not math

[bleak viper]

sodium ion?

[wild patio]

Get out the channel if ur not helping

[wild patio]

That’s all it’s asking?

[empty spear]

It’s called sodium ion

[wild patio]

With a space

Or no

[bleak viper]

with a space

[empty spear]

It’s just asking for name

[bleak viper]

Na+ isnt sodium tho

its sodium ion

maybe thats why

[wild patio]

Last one isn’t chlorine ion

Says wrong

Chloride?

[bleak viper]

yes

[empty spear]

Yeah chloride

Chloride ion

[wild patio]

It was just chloride

[empty spear]

Oh shi

[bleak viper]

yeah Cl- is chloride

[wild patio]

How do i find this

Ik Be and Mg are the only ones in the second period

[dusk goblet]

which has a +2 oxidation state

[wild patio]

Come agian

[dusk goblet]

or both are right?

[wild patio]

Can only be one

[dusk goblet]

no i meant both ions are +2

it probably has to do with electronegativity

or something

[hollow trail]

whichever is more electronegative

[dusk goblet]

yea

[wild patio]

I think Be

[empty spear]

The closer to F the more electronegative

[wild patio]

Which G

F*

[bleak viper]

from when is Mg in second period

[dusk goblet]

electronegativity increases up and to the right in the periodic table if that helps

[wild patio]

It is

[bleak viper]

its in 2nd group

not 2nd period

[empty spear]

Yeah with F being the most electronegative

[wild patio]

Same thing

[empty spear]

Fluorine

[bleak viper]

not the same thing

[dusk goblet]

oh true lol

[hollow trail]

period is row, group is column

[wild patio]

Do it would be F

[dusk goblet]

so it’s Be then

[wild patio]

It’s closest to the right

[dusk goblet]

they said second period so there’s only one answer

[empty spear]

Wait knife

[wild patio]

F?

[empty spear]

Why isn’t it oxygen?

[wild patio]

Because G is after it

[empty spear]

It needs 2 to fill octet

[wild patio]

F

[empty spear]

Or am I trippin

[dusk goblet]

ohhh i read that wrong

i thought it said form a bond with an ion with -2 charge

[dusk goblet]

nah you’re right

[wild patio]

So is it F?

[dusk goblet]

no

F forms an ion with -1 charge

[empty spear]

Oxygen I believe

[dusk goblet]

yea oxygen

[wild patio]

How do i find the most common charge ion

Of an element

[bleak viper]

check valence electrons

[wild patio]

So Bromine

Would be

-1

[bleak viper]

yes

[wild patio]

And Rb+1

Sulfur is -2 right

Or is it 0

[bleak viper]

yes

[bleak viper]

-2, yes

[wild patio]

And Al got to be 3

+3

[bleak viper]

yes

[wild patio]

Pretty sure the top is correct

What formula are they asking there’s multiple

[bleak viper]

potassium fluoride (KF)

[wild patio]

Yea ik that

But is it the name or symbols

[bleak viper]

it says formula

so KF

[wild patio]

Bro

The top was wrong

[bleak viper]

what top

[wild patio]

The anions one

[bleak viper]

wdym

[wild patio]

Right here bro

The top part

I think it’s only one K and one F

[bleak viper]

its just showing cations and anions

[wild patio]

I did that

I was supposed to put the right one in

[bleak viper]

what

i dont get what you're trying to say

[wild patio]

I’m supposed to do that

[bleak viper]

do what

[wild patio]

This

I put one in each one

[bleak viper]

oh like that

[wild patio]

I did +3K and F-3

And it said wrong

[bleak viper]

is it 1 K and 2 F

[wild patio]

Why would it be that

That’s not neutral

[bleak viper]

idk

3 K and 3 F is neutral but it said its wrong

[wild patio]

<@&286206848099549185>

Is it just asking for 1K and 1F

[zealous turret]

hi

wbat

whats the q?

[wild patio]

Just double checking

.close

[cedar kiln]

Channel closed

Closed by @wild patio

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

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[queen sundial]

for this derivative i got 2secxtanx

[crimson sedge]

👋

[queen sundial]

then i plug in 2pi/3

[crimson sedge]

Correct

[dire halo]

Yes now 2secxtanx will be your gradient of the tangent

[crimson sedge]

Next step?

[dire halo]

And plug into formula

[queen sundial]

would it be 4root3

[dire halo]

😭

I think you should attempt it

Before asking

[queen sundial]

is it not correct 😭

[dire halo]

I don’t have mt calculator with me right now but the steps u r doing are correct

[queen sundial]

OHHH wait i c why i got it wrong

it asks for the equation

dude i cant i hate this website

[dire halo]

HAHA

its ok

[dreamy void]

you can't hate anyone because you are always happy

[queen sundial]

LMFAO

no im actually banging my head against the wall rn :D

what is the optimal amount of sleep time before test

[dreamy void]

😂 🥹

sleep as much as needed

[queen sundial]

😭 how much is that

im debating whether i should stay up later