tulip tinsel
s steps to the right
#help-13
limber snow
Up,Right,Right,Up,Right,Right,Up,Right,Right
Need to find ways to reorder Up and Right which would be
(3)!(6)!
and we have 9 letters in total
=(9!)/(3! 6!) = 84 = 9C3
right
flint plinth
looks good
trail agate
I’m not sure what I’m doing wrong in trying to find the absolute minimum. Will send my calculations too in one second.
trail agate
livid hound
,rotate
wraith daggerBOT
trail agate
I feel like I’ve punched in every relevant number and tried every result I’ve found with no success. Is there a glaring error I’m overlooking?
feral sapphire
I’m not sure what I’m doing wrong in trying to find the absolute minimum. Will s...
wait why is the function different on the two images
livid hound
what are the soluitions to
6(x+8)(x-2) = 0
trail agate
Oops, to clarify: the second screenshot is the “sample problem” I’m trying to follow along with.
sinful bay
where's the calculation for x=2
trail agate
Not on my paper, but I’ve done it in my calculator. It gave me -23 which it’s also not accepting as correct
livid hound
you didn't enter into your calc properly
trail agate
Trying again…been bumping into syntax issues with this thing when powers are concerned
Gave me -95 this time. Looks like it finally worked. 
Thanks for the sanity check!
.close
cedar kilnBOT
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tired escarp
how do i do number 1
cedar kilnBOT
@tired escarp Has your question been resolved?
gilded mesa
Time is independent variable and cost is dependent because it depends on time
More time more cost
tired escarp
so whats the equation?""????????\
gilded mesa
Equation will be
Cost =0.50 x time
cedar kilnBOT
@tired escarp Has your question been resolved?
sharp hornet
I might be missing some integrals foundation. Where did the (Y) on the third step come from?
sharp hornet
I thought that as the integral is empty on the second step, it would be zero
uneven iron
$\int dy = y + C$
wraith daggerBOT
Rub05
sharp hornet
.close
cedar kilnBOT
tired escarp
Equation will be
Cost =0.50 x time
so it would be x =0.50t
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tender jay
hi
tender jay
i am stuck on all of it
wraith daggerBOT
faiyrose
tender jay
which question is this for
?
ok
what are the rules for the rest if you know them?
cedar kilnBOT
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umbral arrow
Is there any trick I can do to find this on pen and paper
this seems pretty chaotic to do
cedar kilnBOT
@umbral arrow Has your question been resolved?
umbral arrow
<@&286206848099549185>
cedar kilnBOT
@umbral arrow Has your question been resolved?
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wraith moat
Hello! I tried using Euler's substitution, but it seems like it gets even more complicated, how do I solve this?
mighty shuttle
complete the square first
wraith moat
Okay, and what do I do next?
I don't think you are supposed to solve it by completing the square
Since we have the square root
And I don't see how that will help
It is not a fraction
A simple root
Indeed if it were a fraction, we could have completed the square and than make a u substitution and from there we would have a direct formula of integration
fast lotus
Okay, and what do I do next?
what did u get after completing the square?
@wraith moat
wraith moat
3(x+1)^2 + 4
fast lotus
put that 3 inside only
or is it 3x+1?
oh nvm
yea send that 3 inside of the square
what will u get?
wraith moat
wraith moat
oh, yeah
And we have direct integration from here
Thanks
Have a good day
.close
cedar kilnBOT
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austere dune
can someone help me with this quesiton pls ^^^
cedar kilnBOT
can someone help me with this quesiton pls ^^^
mighty shuttle
,rotate
wraith daggerBOT
mighty shuttle
!original
cedar kilnBOT
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
wraith daggerBOT
austere dune
idk if this graph is a translated version of cos or sin
mighty shuttle
can be either one
mighty shuttle
yes
austere dune
sry if i spelt it wrong
so im guessing the equation of this graph would be y = -sin(x-20)?
am i right?
bcuz the actual answer is y = cos(x+70) degrees
mighty shuttle
yes
austere dune
wait so ur saying both the answers are correct?
austere dune
oh
mighty shuttle
I could be wrong though
austere dune
wait so ur not sure abt the answer
mighty shuttle
not 100%
austere dune
wdym?
austere dune
ye
austere dune
ye the graph is shifted towards the right
mighty shuttle
why?
austere dune
bcuz the sine graph is reflected?
austere dune
oh so there r actually two solutions
mighty shuttle
I'm bad a trig
austere dune
oh u uni?
worldly chasm
There are an infinite number of solutions
mighty shuttle
going to start uni this year
worldly chasm
There are 4 that use only one sin or one cos
austere dune
There are an infinite number of solutions
oh interesting
feral sapphire
There are an infinite number of solutions
-90<d<90
worldly chasm
Even with that restriction, there are infinite solutions of the form A sin(x - C) + B cos(x - D)
austere dune
wait i don't understand
worldly chasm
it's just a silly pedantic math fight
feral sapphire
Even with that restriction, there are infinite solutions of the form A sin(x - C...
but its stated that its in one of the 3 forms
austere dune
pendantic?
worldly chasm
but its stated that its in one of the 3 forms
ah! in that case my bad, I should read better.
worldly chasm
pendantic?
pedantic just means overly or annoyingly picky or detail oriented.
feral sapphire
wait i don't understand
there are multiple solutions for c i believe
austere dune
pedantic just means overly or annoyingly picky or detail oriented.
oh
austere dune
there are multiple solutions for c i believe
how?
feral sapphire
@austere dune which part do you need help for?
feral sapphire
how?
it could be done by shifting sin to the left a bit or shifting cos right by a bit
which gives u two possibilities
i think in both case d is between -90 and 90
austere dune
There are an infinite number of solutions
but i still don't understand how there r infinite number of solutions
feral sapphire
<@1145030740535427102> which part do you need help for?
hint: for a,b,c,d on the graph, draw the sin(x) graph on there, and see how much you need to shift it
worldly chasm
There aren't given the restrictions
feral sapphire
but i still don't understand how there r infinite number of solutions
i think its a misunderstanding
worldly chasm
There are infinite solutions, but only if you do not restrict the values of d, or if you allow combinations of sin and cos
because those are disallowed by the problem, there are only finitely many
sometimes two and sometimes one
cedar kilnBOT
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river latch
is the answer (−∞,−3)∪(−3,0)∪(0,2)∪(2,∞) correct?
cedar kilnBOT
is the answer (−∞,−3)∪(−3,0)∪(0,2)∪(2,∞) correct?
mighty shuttle
,w factorise x^3+x^2-6x
wraith daggerBOT
river latch
I am confused
mighty shuttle
,w factorise x^2+6x+9
wraith daggerBOT
mighty shuttle
I am confused
what's confusing you?
worldly cave
it actually is continuous on -3
mighty shuttle
this is soemthing called a removable discontinuity
mighty shuttle
is the answer (−∞,−3)∪(−3,0)∪(0,2)∪(2,∞) correct?
looks right
,w domain of (x^2+6x+9)/(x^3+x^2-6x)
wraith daggerBOT
worldly cave
yeah sorry it's not continuous at -3 because it is not defined there
But you could expand it
mighty shuttle
it's a removable discontinuity
worldly cave
bascially both limits exists and are the same however the value f(x) doesnt exist
river latch
thank you
is the removable discontinuity at x= -3
and is the non-removable discontinuties at x=0 and x=2?
river latch
both the numerator and the denominator are zero at x=−3
river latch
the numerator is not zero but the denominator is zero
lavish turtle
is the matrix representation of T in standard bases equal to the matrix below?
lavish turtle
$\begin{bmatrix}
2 & 1 & 0\
0 & 3 & -4
\end{bmatrix}$
wraith daggerBOT
yelo ᓚᘏᗢ
lavish turtle
teacher said this, but i think she had a miscalculation for T(e1)
flint plinth
yea should be [2 0], not [1 0] (assuming f1 and f2 are the standard bases of R^2, which is not stated in the screenshot)
and "defined" instead of "deifned" haha
cedar kilnBOT
@lavish turtle Has your question been resolved?
cedar kilnBOT
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half cypress
more of a question but do sedenions have any sort of use or applications?
floral arrow
half cypress
interesting but idk about wikipedia
can they also be used to represent rotations just like quaternions and octonions?
sinful bay
interesting but idk about wikipedia
What? They've literally cited the papers they're referencing
cedar kilnBOT
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dreamy void
Is $(\mathbb{N}_0, \circ)$ a group and we define $a \circ b := \abs{a-b} \text{ (for snosepsh: } a,b \in \mathbb{N}_0).\$
I managed to show that the operation is closed.
$\$
However I am stuck at showing the associativity.
$\$
Let $a,b,c \in \mathbb{N}_0$. Then $$ (a\circ b) \circ c = a \circ (b \circ c)$$
wraith daggerBOT
𝔸dωn𝓲²s
feral sapphire
Is $(\mathbb{N}_0, \circ)$ a group and we define $a \circ b := \abs{a-b} \text{ ...
is the problem "show this is a group" or "is this a group"?
sinful bay
is the problem "show this is a group" or "is this a group"?
Doesn't make much of a difference
You have to do the same work
dreamy void
My progress:
\begin{align*}
(a\circ b) \circ c &= a \circ (b \circ c) \
\Leftrightarrow \abs{\abs{a-b}-c} &= \abs{a-\abs{b-c}} \
\Leftrightarrow (\abs{a-b}-c)^2 &= (a-\abs{b-c})^2 \
\Leftrightarrow (a-b)^2-2\abs{a-b}c+c^2 &= a^2-2a\abs{b-c}+(b-c)^2 \
\end{align*}
dreamy void
is the problem "show this is a group" or "is this a group"?
Is this a group
So it may or may not be
feral sapphire
You have to do the same work
just in case we dont straight up try and prove something that isn't true
sinful bay
just in case we dont straight up try and prove something that isn't true
Yeah I guess "is this a group" means an answer could be "it isn't"
feral sapphire
Is this a group
and for clarification N_0 is set of naturals including 0 right?
dreamy void
and for clarification N_0 is set of naturals including 0 right?
yes
wraith daggerBOT
𝔸dωn𝓲²s
dreamy void
I tried one and my gut said maybe it's true
feral sapphire
I tried one and my gut said maybe it's true
u should try more
strong hint: ||1,2,3||
dreamy void
I won't open it yet
feral sapphire
I won't open it yet
there are a couple different cases, and you would agree that the cases are separated by the ordering of a,b,c right?
maybe try different a,b,c with different ordering
feral sapphire
you got it?
dreamy void
a = 2
b = 1
c = 1
feral sapphire
yeah!
dreamy void
||2-1|-1| = 0
|2-|1-1|| = 2
dreamy void
strong hint: ||1,2,3||
I actually tried a = 1, b = 2 and c = 3 maybe I miscaluted lol
yea!
rigid lava
feral sapphire
||1-2|-3|=2 and |1-|2-3||=0
feral sapphire
lmao
can relate when one silly mistake takes me hours to figure out
cedar kilnBOT
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vestal island
this may seem stupid, but if $a > \min(b, c)$, then $1/a < \max(1/b, 1/c)$?
wraith daggerBOT
generic username
sinful bay
this may seem stupid, but if $a > \min(b, c)$, then $1/a < \max(1/b, 1/c)$?
Yes, can you prove that?
vestal island
if $a > \min(b, c)$, then $a > b$ and $a > c$, then $1/a < 1/b$ and $1/a < 1/c$
wraith daggerBOT
generic username
sinful bay
if $a > \min(b, c)$, then $a > b$ and $a > c$, then $1/a < 1/b$ and $1/a < 1/c$
This isn't quite right
sinful bay
We could, for example, have $b<a<c$
vestal island
like suppose b < c
wraith daggerBOT
خرشوف
sinful bay
a without loss of generality?
Yes
cedar kilnBOT
wraith daggerBOT
habibjr.
Compile Error! Click the 
reaction for more information.
(You may edit your message to recompile.)
sinful bay
Is there any information about the value of u_1
Well, if u_1 is 0, it's undefined, and if it's positive then it's not too hard
Sorry, had to go do something
Are you aware of the fact that decreasing sequences with lower bounds converge
sinful bay
**habibjr.**
Compile Error! Click the <:errors:504266556054962196> reaction for ...
Does it seem like this is eventually decreasing if u_1 is positive (and does it seem like it's lower bounded)
Well, let's start with lower bounded
Do you see why that must be true
Well, what do you think a lower bound might be
Right
Now how do you think we should go about showing that it's eventually decreasing
sinful bay
**habibjr.**
Compile Error! Click the <:errors:504266556054962196> reaction for ...
Oh shit I'm really sorry, I seem to have made a calculation error
It won't converge
The sequence of even terms will be arbitrarily close, and the sequence of odd terms will be arbitrarily close
But the sequence overall won't, I don't think
dusk shuttle
I am struggling to figure out how I could calculate this using a double integral. Whilst I know what f(x,y) is, how do I figure out the region of integration here?
glad peak
I am struggling to figure out how I could calculate this using a double integral...
Graph the 2 surfaces and I’d recommend using spherical coordinates
mortal hemlock
polar is in 2d, spherical is in 3d
dull oxide
and im supposed to actually use polar here
x²+y²=r²
dusk shuttle
would that be the region of integration?
dusk shuttle
polar is in 2d, spherical is in 3d
ye but generally for these types of questions youd get a region in 2d that would be your region of integration and you use polar to evaluate a double integral involving only x and y
dull oxide
would that be the region of integration?
You need to find the bounds for r
It would be where your sphere and parabaloid intersect
dusk shuttle
so the region of integration would be determined by the region of intersection?
dull oxide
yes
cedar kilnBOT
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fleet inlet
Suppose I have an event which can either be a 'win' or 'lose' with probability 1/X of being 'win'. Is there any way I can randomly generate the number of times the event would need to occur to get Y number of wins?
fleet inlet
obviously i could just literally trigger the event until I get Y number of wins, but I feel like there must be a better way
dull oxide
Suppose I have an event which can either be a 'win' or 'lose' with probability 1...
You're never guaranteed to win.
fleet inlet
yeah
i know
like i'm looking to generate a number of times it takes to win in a probabilistic distributon
e.g. I generate 'it took 5 attempts to get Y number of wins'
cedar kilnBOT
@fleet inlet Has your question been resolved?
haughty kayak
Hi
haughty kayak
really?
anyways
y = cos2t
dy/dx = -2sint right?
wait
d2t/dt
then 2
-2sin2t
.close
cedar kilnBOT
haughty kayak
yeah ?
haughty kayak
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yes?
anyways, im stuck on another buzz
lol
dy/dt
y = 4/t
how do I find out dy/dt
median ore
so write it out in exponential form so y = 4*t^-1
then move the -1 to the coefficient side
and replace the exponent with -1-1 which is -2
so dy/dt = -4*t^-2
median ore
uhhh dyk how to derivitive?
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weak granite
So
patent belfry
Are we considering 0
weak granite
No
So the derivative of this
First
We can use quotient rule
(Im asking if its possible)
celest seal
you can, yes
weak granite
Second we can use product rule
celest seal
how you write a function doesnt affect the derivative
sure, division by X is the same as multiplying by 1/X
weak granite
sure, division by X is the same as multiplying by 1/X
Aha
Third we can use chain rule
patent belfry
Second we can use product rule
isnt this how quotient rule is derived
celest seal
yes
weak granite
Okay yeah
patent belfry
Okay yeah
All methods of deriving make the same results bc you are taking the same limit in all cases
weak granite
I just wanted to know if a derivative question can be solved in multiple ways
Ok so which way is tge fastest
Chain or product or quotient
celest seal
in this case, the fastest will be simplifying and then differentiating.
if i couldn't do that for some reason, i'd probably use the product rule, but not necessarily because it's the "fastest" - it's just what i find easiest
(i do not have the quotient rule memorized)
weak granite
in this case, the fastest will be simplifying and then differentiating.
Nah nah i dont want that (i couldnt think of a question that could have multiaple ways to solve it execpt this one sooo)
weak granite
So what if we grabbed the limit as x approaches 0
Again
Dont simplify
And dont use anytging but lhopitals
Now we use power rule
Yeah
patent belfry
And dont use anytging but lhopitals
Using l’hopitals to take a derivative is crazy ngl
weak granite
Using l’hopitals to take a derivative is crazy ngl
Its a limit.
patent belfry
Its a limit.
but why?
celest seal
in general, changing the way you write something wont affect the outcome of applying a mathematical operation to it
so regardless of whether you write it as (x² + x)/x or (x² + x)*(1/x) or x + 1
or whatever
weak granite
in general, changing the way you write something wont affect the outcome of appl...
Yes but i feel like- we cant apply quotient when its a limit
patent belfry
Yes but i feel like- we cant apply quotient when its a limit
yes bc ur taking the limit not the derivative
weak granite
yes bc ur taking the limit not the derivative
Im using lhopitals to get the limit
patent belfry
Im using lhopitals to get the limit
thats circular reasoning then bc u need the derivative to use l’hopitals
weak granite
so regardless of whether you write it as (x² + x)/x or (x² + x)*(1/x) or x + 1
I feel like this is limited when it comes to limits. Like- i cant use product or quotient when its a limit
The reason why i opened this was to grt a better understanding of derivatives and lhopitals
celest seal
i do not understand what you mean
those are rules for derivatives
if the process of computing a limit involves taking a derivative, then you can use these rules to compute the derivative
usually the process of computing a limit does not involve taking a derivative, but in some cases it can (namely, when l'hopital's rule applies)
i feel like you might be misapplying l'hopital's rule
weak granite
if the process of computing a limit involves taking a derivative, then you can u...
Mhmmmmm ok i understand. So you mean everything could be derived in any way as long as i follow the rules like- derivatio bc of x-1 i can use product and quotient rule here
patent belfry
Saying why doesnt the quotient rule apply to limits is like saying why doesnt the quotient rule apply to dividing
patent belfry
Mhmmmmm ok i understand. So you mean everything could be derived in any way as l...
Yes bc it comes down to the same limit
weak granite
Yes bc it comes down to the same limit
Okay. I thought constants cant be considered as “g(x)” in product or quotient rule etc.
Completly dorgetting about smth like
F(x)=1
Ok ty you two
.close
cedar kilnBOT
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rare furnace
a 7kg block is moving at 6.5m/s when it hits a rough horizontal surface with a coefficient of friction of 0.35. if the block slides to a stop how far does it travel
can someone help me solve this please?
rare furnace
i don't know where to start
cedar kilnBOT
@rare furnace Has your question been resolved?
brave orchid
a 7kg block is moving at 6.5m/s when it hits a rough horizontal surface with a c...
Sure, are you a good artist?
It might help you out a little if you draw the block and the floor
rare furnace
how would that help?
rare furnace
It might help you out a little if you draw the block and the floor
i don't know which equations to use
brave orchid
i don't know which equations to use
Ahh okay
rare furnace
Sure, are you a good artist?
were you being sarcastic?
brave orchid
So you can find the friction using the weight and the friction coefficient
brave orchid
were you being sarcastic?
Oh no, but it definitely helps to draw all physics problems
So step 1: we'll wanna find the acceleration from friction (since it's slowing the block down)
step 2: using the acceleration and speed to find total position
Sound good?
rare furnace
Sound good?
is a = g(sinθ - μcosθ) how you find the acceleration from the friction?
i've never seen this in my life but that's what google says
brave orchid
i've never seen this in my life but that's what google says
All good, that formula's referring to when the block's on a slope
Here, I got a photo for ya
brave orchid
i've never seen this in my life but that's what google says
Here's kinda what it looks like right?
Which way does friction go in this situation?
brave orchid
Perfect!
brave orchid
but idk i don't know how friction works
Nah it's all good
When you're riding a bike and you hold the breaks, do you speed up or slow down?
rare furnace
slow down
novel rain
brave orchid
but isn't F the net force and not the friction force?
Correct
WEll here, we actually need it for the equation part
We're now ready to solve
Friction force = (0.35) mg
mg is just the gravity force
It's weird, but it implies that the heavier an object is, the stronger the gravity is
patent belfry
so 0.35mg = ma?
yeah the force of friction is 0.35mg
rare furnace
yes
patent belfry
counterintuitively, the friction force doesnt depend on speed
brave orchid
And what's your slope aka m? It's the friction coefficient
rare furnace
so a=3.43?
brave orchid
Lemme check
brave orchid
so a=3.43?
Yessirrr
You got it
Well obviously it's going backwards so I guess if we think of velocity as + then we'll make acceleration -
rare furnace
how do we use acceleration and speed to find the position?
brave orchid
Aha good question
rare furnace
acc + speed = position?
brave orchid
So there are a few formulas we can use
patent belfry
d = vt + 1/2*at^2
brave orchid
d = vt + 1/2*at^2
There's another one we can use that might be easier I think :)
rare furnace
we don't have the time though do we?
brave orchid
So, how much physics have you covered so far by the way? Did you guys cover things like ball dropping?
brave orchid
we don't have the time though do we?
Yeah, so we'll use one without time
patent belfry
oh shit i forgor
brave orchid
In fact we have a handful we can use
patent belfry
we dont know time we know final velocity
brave orchid
I'll show the one we can use
(If you're ever in a pinch with these look up "SUVAT equations")
patent belfry
wheres the final velocity + initial velocity + acceleration + displacement one
brave orchid
patent belfry
bottom one
brave orchid
We'll just use the one on the bottom
brave orchid
bottom one
Yup yup
patent belfry
ah yeah i remember i hated that one since i could never remember it back in the day
rare furnace
So, how much physics have you covered so far by the way? Did you guys cover thin...
i don't know exactly what you mean. tbh i'm just trying to pass this class and then i'm gonna go learn math completely from the beginning on my own and then go back to college so i actually understand something because i'm always so confused whenever i take a math or physics class
brave orchid
i don't know exactly what you mean. tbh i'm just trying to pass this class and t...
Lol it's okay
We've all been there brother
patent belfry
i don't know exactly what you mean. tbh i'm just trying to pass this class and t...
have yall learnt about kinematics
brave orchid
I mean luckily you don't need much
rare furnace
have yall learnt about kinematics
no
brave orchid
Ahhh
rare furnace
just kinetic energy
rare furnace
we haven't learned any of these equations and we don't have t anyway
brave orchid
we haven't learned any of these equations and we don't have t anyway
Yeah true, but usually you just use the bottom one if you don't have time
brave orchid
So v refers to final speed, and v_0 refers to starting speed
brave orchid
the ke is 147.875J
I mean hey you're at least cooking like a physicist lmao
We'll use the bottom equation if that's okay
I recommend having a sticky note in your book or something with those equations so they become easy to use
I do have a question for you: when the block eventually comes to a halt, what is its final speed?
Don't worry, it's not a trick question
patent belfry
we haven't learned any of these equations and we don't have t anyway
if you intuitively understand the first 2 you can derive the rest
rare furnace
I do have a question for you: when the block eventually comes to a halt, what is...
6.5m/s
nvm that's not right
i have no idea
rare furnace
no
patent belfry
i have no idea
okay, the block has come to a halt because friction won over. Whats its speed now
brave orchid
nvm that's not right
It's all good
brave orchid
0
Lol yeah
So we just say it went from 6.5 m/s to 0 m/s
And we know a = -3.43
Now, just plug those bad boys into the bottom equation and you just solve for x
Et voila! Physics
brave orchid
0 = 6.5^2 + 2(3.43)(x)
Perfect!
rare furnace
why is a -3.43?
brave orchid
why is a -3.43?
Oh because friction is negative right? It slows things down
If it was positive then friction would speed things up (also we know that it goes from 6.5 to 0 so it has to be slowing the block down)
patent belfry
Oh because friction is negative right? It slows things down
because we assume right to be positive and left to be negative
brave orchid
If friction sped things up then we'd all be screwed lol
patent belfry
its a notational thing
rare furnace
i got 35.39m but that's not an option
brave orchid
i got 35.39m but that's not an option
Oops, not quite
patent belfry
i got 35.39m but that's not an option
you wrote the sign of acceleration incorrectly
brave orchid
Oh I think he just did 6.5^2 - 2(3.43)
rare furnace
thank you so much guys you are so kind
rare furnace
thank you
brave orchid
Yeah no probs man
rare furnace
why do you tutor people here?
brave orchid
why do you tutor people here?
Because I have no life
rare furnace
lol
brave orchid
Kidding, it's just the weekend
rare furnace
i was thinking if i ever get to an advanced enough level in math i'll do it so i can try to internalize everything but rn i can't
and it would be an easy way to find problems
brave orchid
and it would be an easy way to find problems
Oh yeah totally
I think it's all mental block stuff
Once you click, you click yk?
rare furnace
i figured out how to learn spanish after 1.5 years of frusturation and giving up several times so ik i can learn it i just need enough time and the right teachers
hopefully khan academy works
.close
cedar kilnBOT
cedar kilnBOT
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barren bridge
Hi i have a question in a research topic that ive studied im working in
we are given a randomized trial of 5 people who are given 2 varities of vaso constrictors
with thier subsequent BP values
would it help me to Use a ANOVA table to analyize the the entire poplation and then split it into 2 groups?
if not what other method can i use
to specify it is a randomized trial and i only have a standard deviation threshold to go off splitting the two groups
cedar kilnBOT
Hi i have a question in a research topic that ive studied im working in
we are g...
@barren bridge Has your question been resolved?
idle rain
you can use ANOVA to test whether there is a difference among the treatment group or not
but for small n, I would not say you should do anova
barren bridge
but i dont know which patient gets which drug though
the table will give the set of variances
idle rain
do you expect some difference?
barren bridge
apparently there is supposed to be a distinct difference
The worst part our prof has asked us to do a dry run with dummy values and not given us any data
im basically softlocked in a topic ive never studied before 💀
idle rain
I mean, you can do propensity score matching maybe
make a classifier (or in this case, discriminator) to discriminate two classes (treat, not treat) and use the estimate probability to match the group
barren bridge
Ohhh you got further reading on this somewhere?
idle rain
I think PSM is more of like Causal inference method so you can start from there
because we don't know the treatment assignment but we kinda know that they are different (from some covariates). That means both distribution should be distinct.
idle rain
ok...
barren bridge
its almost like one data set has more erratic values than the other
and we need to find that difference
idle rain
but that is one of the method you can do
you can try bootstrap
and with bootstrap and discriminator, you can do anova
barren bridge
ohk will google that
idle rain
Like, you might want to dig deep into literature on what people has done. But I think you need to bootstrap first then perform your analysis
You use discriminator to determine the class based on covariates (features basically... other measurement that you have from the sample)
And use the assigned class as the treatment/no treatment kind of classification.
That will be your class for ANOVA
and with bootstrap, you will have substantial distribution of the data
barren bridge
ohk so determine covariate classes
then the set of variables
then run an anova only on the between case
because running calculations within the patients data is useless?
idle rain
it is not useless
depends on what you need
you might want to see whether there is a difference within the group or not
barren bridge
Oh ohk got it
cool ill proceed with this and trouble you if i get stuck elsewhere
can i?
idle rain
not really. but you can always create help channel
idle rain
you might want to see whether there is a difference within the group or not
and to clarify, I meant for 0 treatment effect here
because you only have one data (either that person taking drug or not)
but to determine the treatment effect, you need two
that might also require regression
and your question might fit in #advanced-stats or #probability-statistics room
cedar kilnBOT
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Available help channel!
crimson sedge
Someone please help me with this
cedar kilnBOT
Someone please help me with this
crimson sedge
<@&286206848099549185>
cedar kilnBOT
@crimson sedge Has your question been resolved?
crimson sedge
In first 2 parts, the normal distance formula will be applied
the coordinates are given
simple ?
What
How do I do that
Plug in the values to this formula for the first two
the coordinates can be identified from the given graph
B (1500,600)
C (-300,-500)
That makes no sense
huh?
wdym-
Wait
What ones y2
And y1
Put x2= -300, x1 = 1500 , y2=-500 , y1 = 600
Okay okay
1210000
Not really-
Oh!
Erm
Let me try again
the final answer will be 1800 smthng
What about a
crimson sedge
What about a
ehh?
We are solving a part only -
Oh yeah
I got
2109.502
wait lemme check up mine solution then
Okayy
excuse the writing due to pc-
but u got smthng like this ??
cedar kilnBOT
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Available help channel!
crimson sedge
How did u get that
cedar kilnBOT
How did u get that
crimson sedge
How did u get that
its shown-
crimson sedge
the final ans will be 1800.05 (approx)
Wait how is mine and urs different
crimson sedge
Wait how is mine and urs different
totally yep
check it once
Huh
wait up-
something wrong
u got something like this correct
I have no clue
what did u solve??
show
I just puta bunch of stuff in a calculator
Let me try again
Ahh solve it urself haha calculator won't help
crimson sedge
I got
2109.502
this one rightt
my bad
Ohhhh
Okay okay
Thank uuu
What abt the second one
yep
wait up lemme read
its the simlar to A only
tryna plug into the same formula
OH WAIT-
Mid point formula
Oh okay okay
One sec
x2 =-300
x1 = 1300
y2 = -500
y1 =1000
Did I do it wrong
for C it should be -300,-500
(x,y)
What u mean
cedar kilnBOT
@crimson sedge Has your question been resolved?
next sedge
cedar kilnBOT
next sedge
I got 26.95N
Got marked as wrong
I chat gpted it
i got the same
So idk what i did wrong
or teach marked it wrong
next sedge
vf^2=vi^2+2ad
plug in the numbers
17.64=0.72a
a=24.5/m/s^2\
fnet=ma
fnet=1.1(24.5)
fnet =26.95
flint plinth
did you account for the fact that part of the acceleration is due to gravity?
next sedge
Oh
flint plinth
i think your answer would be right if there was no gravity
flint plinth
well the value of a that you calculated, 24.5 m/s^2
that's the combined acceleration caused by you and by gravity
so in other words, your acceleration (call it capital A) minus gravity (call it g) equals 24.5
so A = 24.5 + g
= 24.5 + 9.8
calculate that and use it instead in your formula
i think it should work
oops fixed the sign
next sedge
so 37.73N?
cedar kilnBOT
@next sedge Has your question been resolved?
vale topaz
How would you write mapping notation for a radical function? I don't have a specific example on hand but just wanted to knwo how it would look from a general function.
wraith daggerBOT
Bob l'éponge
vale topaz
isnt there a square root on the Y tho
vagrant elbow
what
vale topaz
wait let me find exmaple
vagrant elbow
[ x \mapsto \s x ]
wraith daggerBOT
Bob l'éponge
vagrant elbow
like this you mean?
vale topaz
like if u had a question like f(x) = 2(x-2)^1/2 + 3, how would you go about mapping thins
vale topaz
cause what i was told initially for a regular radical function y = x^1/2 is that x --> x but y--> y^1/2
.close
twin wave
Patrick boughg an electric car under the hire purchase schmee with a monthly payment of 1600 over 5 years and a down payment of 9% of the cash price. If the cash price of the electric car is 60000 find
The annual rate of interest of the hire purchase scheme
twin wave
is the answer 27.97
cedar kilnBOT
@twin wave Has your question been resolved?
cedar kilnBOT
@twin wave Has your question been resolved?
outer meadow
i got 13.8% instead, you got any steps/workings?
twin wave
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cedar kilnBOT
wraith daggerBOT
fweth
heady frigate
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graceful zephyr
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@heady frigate Has your question been resolved?
lean wigeon
u can easily solve this with trigonometry.
Apply sine function: sin(44°) = BC/AC
Rearrange to find AC: AC = BC / sin(44°)
Calculate AC: AC = 198 / sin(44°) ≈ 285.25
Round to the nearest whole number: AC ≈ 285m
outer meadow
its the horizontal distance not distance so you're actually looking at tangent
sry to interrupt
lean wigeon
no problem, u r right
if we already have the two values of pythagoras, just set up an equation
285² = 198² + x²
carmine kraken
I suggest you keep it at 285.25 because rounding in the middle of the steps can cause some issues sometimes
Especially because it is being squared
So the difference will be intensified
Even though it seems small at first
lean wigeon
with 285.25, i found 205.33m
carmine kraken
What about without the .25
cedar kilnBOT
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Available help channel!
shy rapids
i'm not sure what to do
cedar kilnBOT
i'm not sure what to do
shy rapids
i expanded (x-1)(x-2)
to get
x^2 -3x + 2
not sure what to do from there, or if that is the correct thing to do
slow jewel
First you'll need to find a and b
You can use the info given in the q to do that
1 and 2 are the roots
Or solutions
Use that
kindred venture
not even necessary
idle rain
formula is not necessary here
kindred venture
if a is a root of a polynomial f, f(a) = 0
substitute x = 1 and x = 2 into the polynomial
idle rain
if you know a and b, you can get the third one
which does not requires you to know specific formula
kindred venture
we dont need to find a and b here
true but Vieta's formulae are a bit advanced
shy rapids
I am only a GCSE student, this looks like a different language to me 😅
slow jewel
I am only a GCSE student, this looks like a different language to me 😅
It's ok, there's more than one way for this
shy rapids
substitute x = 1 and x = 2 into the polynomial
i'll start by doing this
and equall-ing them to each other, as they are both 0?
idk, let's just see what numbers i get first
do i do a simultaneous equation?
i got:
a + b = 0
and
4 + 2a + b = 0
i got a = -4
and b = 4
now i will just divide
slow jewel
Nvm
shy rapids
it's okay!
slow jewel
Are you aware of long division of polynomials?
shy rapids
i divided x^3 - x^2 - 4x +4 by x - 2 , and i got x^2 + x - 2
shy rapids
Are you aware of long division of polynomials?
yup!
slow jewel
i divided x^3 - x^2 - 4x +4 by x - 2 , and i got x^2 + x - 2
Now divide this by x-1
shy rapids
i got (x + 2)!
slow jewel
Right
shy rapids
so third solution is -2?
shy rapids
Yay! How do i close this thread?
undone halo
.close
slow jewel
.close
shy rapids
.close
cedar kilnBOT
slow jewel
Nice
shy rapids
awesome!
Thanks :P
I'll probably be coming here for more help in the future!
I am not the smartest, so I'm sorry that you have to put up with me 😝
slow jewel
Thanks :P
I'll probably be coming here for more help in the future!
I am not the...
It's all cool, dw
cedar kilnBOT
Available help channel!
lapis aurora
Hello can anyone help me with this using cosine or sine rule really need it urgent
mortal hemlock
what can you say about GH and WH?
lapis aurora
right angle triangle?
mortal hemlock
what about their lengths
lapis aurora
they are equal
mortal hemlock
exactly
so set x=WH=GH
now, what can you say about the bigger triangle?
FH, GH and FG
mortal hemlock
do you know pythagoras?
lapis aurora
yes
lapis aurora
so sqrt116 = 6x^2 + x^2 ?
swift terrace
close
swift terrace
(sqrt116)^2 = (6+x)^2+x^2
swift terrace
so that's kinda cheating 
mortal hemlock
they are equal
i think thats contained in this part, cos and sin rule
lapis aurora
which can be solved by cosine rule or sine rule
like a hard question
but do they use cosine or sine rule in this?
cuz there was no need of it
mortal hemlock
to prove that WH=GH, yes
i think so at least
because you use the fact that the angle is 45
swift terrace
if you want the question to appear harder, just removee the whole right side triangle
lapis aurora
hmm
swift terrace
that's basically the rule of cos
you "complete" the triangle into a right angle one
and do the exact process you just did
lapis aurora
hmm
lapis aurora
hmm
swift terrace
looks quite familiar no?
a^2+b^2 is the pythagoras
-2ab*cos(gamma) is the process you do to find the x in this situation
it only turned out beutiful because the angle was 45 deg
lapis aurora
is that for year 12 that formula?
lapis aurora
yeah cuz ivnt seen that formula yet
mortal hemlock
yes
swift terrace
Yeah
lapis aurora
btw any idea where i could get some harder questions with explained sollutions for like thoes questions?
swift terrace
first understand the Sin/cosine laws...
lapis aurora
just asking if any idea or else is alg
swift terrace
then you`d know what is hard 😉
swift terrace
these questions aren't inheritly hard because all you do is input the numbers into the equation
mortal hemlock
you know the sin(alpha)/a = sin(beta)/b = sin(gamma)/c one?
lapis aurora
you know the sin(alpha)/a = sin(beta)/b = sin(gamma)/c one?
nah
we didnt learn that yet
mortal hemlock
which sin/cos rule do you know then
mortal hemlock
yeah, thats the one i said
mortal hemlock
but i used alpha, beta, and gamma
lapis aurora
i got confused with the gamma and beta
swift terrace
AB=AC
all the three angles from B are equal,
AB =15
Angle A = 42 deg
find BE and BD
lapis aurora
one min lemme draw it
cedar kilnBOT
@lapis aurora Has your question been resolved?