help-13

[dreamy void]

,w plot y = sqrt(sin(x)) between 0 and pi

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by adoniszgks

[dreamy void]

ok mb

,,r^2(x) = \sin(x) \implies r(x) = \sqrt{\sin(x)}

[wraith dagger]

𝔸dωn𝓲²s

[dreamy void]

but it would be again some kind of ball or "mountain"

some spherical object

yea

the rest should do able

41. notice y^4 = (y^2)^2

and so on

just draw the stuff

if it's in terms of y draw a y to x coordinate system

[pseudo trellis]

this works as my answer?

[dreamy void]

else in terms of x

as usual

x to y coordinate

system

[pseudo trellis]

my handwriting is incredible

this is why i type everything

[dreamy void]

not a half

[dreamy void]

indeed

[pseudo trellis]

oop

[dreamy void]

what is it after rotation?

that's it

[pseudo trellis]

ah yeah

[dreamy void]

it's not half a footbal after a rotation

or sphere

[pseudo trellis]

right yeah

okay so draw the next problem?

[dreamy void]

yea

they are easy

[pseudo trellis]

how would i draw such a thing?

[dreamy void]

you can refer to them as parabolas

,w plot x = y^2 and x = y^100

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by adoniszgks

[dreamy void]

the higher AND still even the exponent goes

ther more it gets wider

do you get the idea?

[pseudo trellis]

i think so

[dreamy void]

good

it doesnt need to be perfect

[pseudo trellis]

so we graph x=y^4?

[dreamy void]

y^4 is a little less wider than y^8 that's all

yea

it's two radius

so common region!

[pseudo trellis]

then do we do x=-y^8

[dreamy void]

no

you fell into the trap

(y²)²

and

(y^4)²

remember the square!

It's R²(y) - r²(y) always

in the integrand

[pseudo trellis]

wot

[dreamy void]

😭

[pseudo trellis]

oh so we're graphing x=y^2

[dreamy void]

yes

[pseudo trellis]

and x=-y^4

[wraith dagger]

𝔸dωn𝓲²s

[dreamy void]

keep this in mind!

so your functions are squared

[dreamy void]

that's why I did after all sqrt(sin(x))!

[pseudo trellis]

ahhhh

like so?

[dreamy void]

Is the minus part?

[pseudo trellis]

x=-y^4

[dreamy void]

Look at this

[pseudo trellis]

i put it but icloud slow

OH

wait

[dreamy void]

You are drawing

R(x) and r(x)

Not R(x)² and - r(x)²

[pseudo trellis]

i see

so y=x^4

is what we're drawing

[dreamy void]

Well other way

But doesn matter technically

Since it's in term of y

Do it in terms of y

[pseudo trellis]

yeahyeah

[dreamy void]

y to x system

Accept it

[pseudo trellis]

lol

okay i got those drawn

[dreamy void]

It's not evil

Show

[pseudo trellis]

i thonk

[dreamy void]

From 0 to 1

Draw it

Mark the region

Between 0 and 1

[pseudo trellis]

on the x-axis?

lmao i drew it the wrong way

i guess not the "wrong" way, but i meant to draw it in terms of x

[dreamy void]

No

It's right

Just this

Now what is this solid looking like

Around the y-axis

[dreamy void]

😭

why

[pseudo trellis]

lmao

i see what it would look like if i rotate it around the y-axis

it's like half a football 💀

[dreamy void]

No

It's like a funnel

[pseudo trellis]

yeah that's the right word

[dreamy void]

This could be misleading thinking it's around x = 1 but it's about x = 0

[dreamy void]

Draw it in terms of y man

It was not difficult

I meant you to just add what I added

Not draw it into a x to y system

[pseudo trellis]

😭 my brain doesn't function when it's like that

im bound to make mistakes when i draw it in terms of y

[dreamy void]

Ohhhhhhh

I cant seem to find any

You did it flawlessly

STOP OVERTHIBKING

[pseudo trellis]

lmao

[dreamy void]

2 YEAR OLDS DONT OVERTHUNK

😂

[pseudo trellis]

lmao okokokokokokok

3 more problems

[dreamy void]

The rest is doable

[pseudo trellis]

that i don't think are terribly difficult maybe

yeah those are pretty easy

[dreamy void]

🥱

[pseudo trellis]

48

it's just doing the volume integral with variables, no?

[dreamy void]

Yes

It's a straight line

Around x = 0

[pseudo trellis]

:P

[dreamy void]

Betwern y = 0 and y = r

In terms of y

[pseudo trellis]

oop

yeah you're right

[dreamy void]

Since axis of rev is vertical

[pseudo trellis]

is that really the answer? 😂

or do we have to expand it and stuff

[dreamy void]

r < h

[pseudo trellis]

yeah

[dreamy void]

Wait

The line goes through

(R,0) and (r,h)

[pseudo trellis]

yeah

wait so two integrals?

[dreamy void]

So

lol

[pseudo trellis]

my brain is not braining

[dreamy void]

Ohhh right i am dumb

y = mx + b

m = y1 - y2 / x1 - x2

m = h-0 / r-R = h/r-R

[pseudo trellis]

right

[dreamy void]

,,y = \frac{h}{r-R}x + b

[wraith dagger]

𝔸dωn𝓲²s

[dreamy void]

Now we would plug in (R,0) since it's simpler

,,0 = \frac{h}{r-R}R + b \iff b = -\frac{h}{r-R}R

[wraith dagger]

𝔸dωn𝓲²s

[dreamy void]

So

[wraith dagger]

𝔸dωn𝓲²s

[dreamy void]

Ok good

[pseudo trellis]

sure lol

[dreamy void]

Now we would do this in terms of y

You can do that

[pseudo trellis]

what do i do?

[dreamy void]

Try to solve for x

[pseudo trellis]

$x=\frac{y(r-R)}{h}+R$

[wraith dagger]

Someone

[pseudo trellis]

is that what I needed to do?

[dreamy void]

I trust it's right

Yea

Then integration from 0 to h

It's around y=0 so good

[dreamy void]

We would get this shape

[dreamy void]

Looking at this

Makes sense?

[pseudo trellis]

yeah

i think

[dreamy void]

Ok good

[pseudo trellis]

so that is the answer?

[dreamy void]

Square it

[pseudo trellis]

ah yes

[dreamy void]

The whole

,, V = \pi \int_0^h \left ( \frac{y(r-R)}{h}+R \right )^2 : \dd y

[dreamy void]

Yea

Wait

[wraith dagger]

𝔸dωn𝓲²s

[dreamy void]

Yeah (it's 6 am)

[pseudo trellis]

okay okay okay

[dreamy void]

Since R > r then r - R < 0 so the slope is negative makes sense

[pseudo trellis]

2 more "similar" problems 💀

49 & 50

[dreamy void]

Looking at that

I trust me

[dreamy void]

NO

[pseudo trellis]

wot

[dreamy void]

I need to sleep

[pseudo trellis]

lmao

okokokok

[dreamy void]

It's 6 am almost

I helped your at least 2 hours

[pseudo trellis]

yesyesyesyes all good

[dreamy void]

Do you want to take advantage of me

😭

[pseudo trellis]

thank you thank you thank you thank you thank you

[dreamy void]

You can add me, I like you

good night

[pseudo trellis]

good night!!! ❤️

.solved

[cedar kiln]

Channel closed

Closed by @pseudo trellis

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

[umbral shell]

.close

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[trim sierra]

how can i do this?

step by step

[harsh flare]

Can anyone solve this elaborately ? Step by step completely

[trim sierra]

.cdot

.close

[cedar kiln]

Channel closed

Closed by @trim sierra

Use .reopen if this was a mistake.

[harsh flare]

<@&286206848099549185>

[dull oxide]

!15m

[cedar kiln]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[dull oxide]

!occupied

[cedar kiln]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[harsh flare]

ohh ok I didn't see my bad

[trim sierra]

.close

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[blissful flare]

How do i find d^2 * z of function z=tg(2x^2 - y)

[cedar kiln]

@blissful flare Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cedar kiln]

@twilit crag Has your question been resolved?

Channel closed

Closed by @twilit crag

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[frozen pier]

For #3 the answer is C and I was wondering why

[earnest geyser]

,rotate

[cedar kiln]

@frozen pier Has your question been resolved?

[frozen pier]

<@&286206848099549185>

[fast lotus]

what are the 11in and 8.5in?

l and b of page?

[frozen pier]

im assuming yeah

[fast lotus]

ok so

do u know tht moment of inertia is maximum along perpendicular to plane of sheet?

[frozen pier]

no i didnt really know that

[fast lotus]

ever heard of perpendicular axis theorem?

[frozen pier]

yeah we did that in this test

[fast lotus]

yea wht is tht?

[frozen pier]

actually i think it was parralell axis theorem

[fast lotus]

oh not tht

perpendicular axis theorem

[frozen pier]

id assume its just the parallel axis theorem but for the perpendicular axis

[fast lotus]

nop

[frozen pier]

oh okay

[fast lotus]

both are different

ok lemme explain

assume u have a page

along xy plane

[frozen pier]

okay

[fast lotus]

ok so assume u r rotating it along z axis

the paper's center is at origin

@frozen pier mhm?

[frozen pier]

oh yeah im following

[fast lotus]

okay

so the moment of inetia

along z axis is equal to moment of inertia along x and y axis combined

[frozen pier]

alright

.close

[cedar kiln]

Channel closed

Closed by @frozen pier

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[heavy crypt]

Two teams A and B play games until one team has won 4 games. A tie does not exist. The probability of A winning is 0.7 if it plays on its own field and 0.3 if it plays on the opponent's field. The first two matches are played on B's field, the next three on A's field and the last two on B's field.
(a) What is the probability that A wins after 4 matches?
(b) What is the probability that A wins after 5 matches?

[heavy crypt]

,rotate

[heavy crypt]

so I choose one position out of the 2 where they lose on the opponents field and then if they would’ve lost on their own field

And I calculated it and got 0,18375 but answer says 0,17052

it’s for b

2*0.7*0.3*0.7^3 + 3*0.3*0.7^2*0.3^2

[lilac rune]

let me try

[heavy crypt]

and what did you do?

[lilac rune]

@heavy crypt i got 0.17052

[heavy crypt]

what did u do?

[lilac rune]

wait a min

20.70.30.7^3 + 30.30.7^20.3^2

u did this right

uhh

did you exclude the case

where the first 4 games are won by a

and 5th is won by b

??

[heavy crypt]

ah

[lilac rune]

you shouldnt take this case

since the game would be stopped when a wins the first four games

since it is given that a wins only after 5 games

[heavy crypt]

how did i take that tho if i say that out of the 3 competitions on the second field one of them is a loss?

[lilac rune]

i didnt understand you

the 3 competion cases are these
3rdgame 4thgame 5th game
A WON A LOST A WON
A LOST A WON A WON

[heavy crypt]

yeah but what about the first and second game because if you lose the first one and then win all the rest

then you won after five matches

same for the second game

[lilac rune]

YES

im saying first 2 cases of ur answer are right

the answer should be
2 * 0.7 * 0.3 * 0.7^3 + 2 * 0.3 * 0.7^2 * 0.3^2

[heavy crypt]

ok i get it

ty

[lilac rune]

ur welcome

[heavy crypt]

.close

[cedar kiln]

Channel closed

Closed by @heavy crypt

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[civic whale]

I know how to solve this equation, but, how would I come to the results of k = 5 and l = -4?

[cedar kiln]

@civic whale Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lilac flame]

3x +(y^2)i = 1-2i^2

[lilac flame]

what is the value of x

is it 1?

[modern sparrow]

why did you think it was 1?

[lilac flame]

1-2i^2 becomes 3 right?

so 3 + 0i

and we can compare that way?

[sand cradle]

Yes, but is there any more context?

What are x, y?

Just real numbers?

[lilac flame]

y is complex i assume

[modern sparrow]

oh yh I didn't see the ^2, that's right

[lilac flame]

so am i right?

is it 1?

[sand cradle]

Why would it be?

Ah, you are comparing coefficients

[lilac flame]

well 3x +(y^2)i = 3 +0i

i had this question on the test today

[sand cradle]

Assuming that x and y are both reals, yes

[modern sparrow]

if y is real, then y^2 is real, so (y^2)*i is purely imaginary, and 3x is purely real, then what you've done is right. But if y is complex, then y^2 is complex (real and imaginary parts) so then no you're not

[lilac flame]

what would be value of x then?

[sand cradle]

1 is correct, as you said

[modern sparrow]

write $y = a+bi$, then $y^2 = a^2 - b^2 +2abi$, so $iy^2 = -2ab + i(a^2-b^2)$

[wraith dagger]

lgkoo

[sand cradle]

^ this is in case y is complex. Whether it is or not should be stated in the exercise

[lilac flame]

it wasnt

[modern sparrow]

you just said it is

[lilac flame]

i also said i assume lol

my mathematical knowledge is lacking

😭

[sand cradle]

I would assume both x and y are real

[modern sparrow]

same

[lilac flame]

then y is 0 and x is 1

[modern sparrow]

yah

[lilac flame]

thank you

.close

[cedar kiln]

Channel closed

Closed by @lilac flame

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hazy aspen]

This question

[hazy aspen]

<@&286206848099549185>

[lilac rune]

physics wallah nice

[hazy aspen]

Yes

Had a milestone test today, got 228/300

[hazy aspen]

Now tell the the solution

[runic garnet]

whatve u tried

[hazy aspen]

I have tried many things but they are not even close to reaching the solution

I tried taking constants out, taking uat+2 as x

Im not clear with u substitution

[runic garnet]

taking x = uat + 2 works

what will u do from there

[hazy aspen]

I have no idea

I watched Khan academy u substitution videos where they take certain things as x or u, but didn't really get the whole concept

[runic garnet]

wait whats the upper bound on the integral

[wicked stag]

Its option 4

[hazy aspen]

I know but how

[wicked stag]

!nosols

[cedar kiln]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[wicked stag]

Its quite easy

Consider uat + 2 = x

Or (ua)dt=dx

[hazy aspen]

Just for clarification, this test took place yesterday in offline mode, I'm not cheating in test or homework

[hazy aspen]

What's the reason tho

[wicked stag]

Who cares bro !

[lilac rune]

@hazy aspen sorry i havent been able to reply , internet issue

[lilac rune]

haha ya its just a bot

[wicked stag]

If you can visualise you would know the answer in one step

[crimson sedge]

why do you think?

[hazy aspen]

How do you know what we have to take as u or x

[wicked stag]

Its actually 1/a+x form

So its integration will be ln(a+x)

[hazy aspen]

Hold on

Let's start from the start

So we can take u out

[crimson sedge]

dm karu?

[hazy aspen]

Theek h

[wicked stag]

@crimson sedge yeah bro can help better i think

[lilac rune]

hey again

[broken pond]

I WNT A HELP

[wicked stag]

@broken pond can i know what help you wnt

@broken pond bro gave this name after watching The Devil Consipiracy, im 101% sure

@lilac rune hi

[broken pond]

CAN ANYONE TELL THE PYTHAGOREAN TRIPLET WHOSE ONE NUMBER IS 12

[wicked stag]

Yeah

Its 5 ,12,13

[median lantern]

5 12 13

Oops sniped

[broken pond]

NO WRONG ANSWER

CAN YOU TELL YOUR ANSWER WITH WHOLE PROCEES

[median lantern]

Huh it's well known

[lilac rune]

12 35 37

[broken pond]

NO STILL WRONG

[wicked stag]

Yeah another one

You know one thing ?

[lilac rune]

12 16 20

[wicked stag]

When the majority says the wrong answer , it becomes the correct answer.

[broken pond]

NO

[wicked stag]

No === yes

[lilac rune]

bruh whats the answer then?

[broken pond]

THE CORRECT ANSWER IS 9,12,15

[median lantern]

[wicked stag]

^

@broken pond i hate lucifer

[cedar kiln]

@hazy aspen Has your question been resolved?

[cedar kiln]

@hazy aspen Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[deep coral]

can anyone possibly help me with biology?? idk if thats the right serv for this but i need help with punnett squares

[mighty shuttle]

is this a test?

[deep coral]

no its homework

[mighty shuttle]

ok

which square do you need help with

[deep coral]

well tbh i don’t get any of it

but the first ones

[mighty shuttle]

do you know what a punnet square is

what an allele is

[deep coral]

no-

[fading pewter]

damn we got biology in a math server before GTA 6

[mighty shuttle]

better learn that first then

[mighty shuttle]

this is sort of maths

it;s kind of logical

[fading pewter]

combinatorics

[mighty shuttle]

yeah

[fading pewter]

[mighty shuttle]

we don't give out answers on this server

[deep coral]

oh

[mighty shuttle]

we guide you to the answer

so you have to know what you're dealing with, so please learn what a punnet sqaure is first

[deep coral]

i see ty for tryna help tho

[mighty shuttle]

and alleles too

[deep coral]

.close

[cedar kiln]

Channel closed

Closed by @deep coral

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dreamy junco]

Can someone explain to me how to do a double integral with a ring behind it over the surface area of a sphere?

[cedar kiln]

@dreamy junco Has your question been resolved?

[cedar kiln]

@dreamy junco Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sand valve]

Can i do it simplier then just .(x-1)(x+1)(x-2)?

[solar vector]

You mean for solving for x?

Like can you do it simpler than clearing out the fractions by multiplying by (x-1)(x+1)(x-2) on both sides?

[sand valve]

yes

[solar vector]

There might be shortcuts here and there but none come to mind to me off the top of my head.

Clearing out fractions is sort of the most common trick since it works in a large variety of situations.

[sand valve]

but in this example where there are more than one of those numbers, i can just multiply it with one of them?

for example there are 2 underlined red Xs, but i will just use one

[serene umbra]

No in 99% of the cases

The point of multiplying is to get the euqation in the form of a polynomial, which is easier to solve

The teacher who made the problem had an polynomial, done partial fractions, gave them to you

they want you to undo that

if you know what partial fractions are

[serene umbra]

I should have said, he factored the polynomial, and divided by some factor

but all you need to know is that there is no "tricks" other than multiplying to get rid of fractions

[cedar kiln]

@sand valve Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[frank bronze]

i dont understand

[bright fiber]

Well it wants you to say something about it's velocity

[native heath]

What is the velocity of a particle?

[bright fiber]

and how the velocity behaves

[native heath]

Given its position.

[bright fiber]

so how would you go about finding the velocity?

[native heath]

yeah maybe dont answer it straight up

[serene umbra]

alright

[native heath]

yes remove that

[frank bronze]

waht is going on

[native heath]

What is the velocity vector given a position vector

[native heath]

Oh you don't have vectors

Just ignore the word 'vector' there

[frank bronze]

velocity is undefined, position is t = 1

[bright fiber]

Do you know how to get velocity function from position function?

[native heath]

No it's not

[frank bronze]

yes

derive it

[bright fiber]

Good

then do so

[frank bronze]

why

[native heath]

...

[bright fiber]

Because you need to find out some information about the velocity

no?

[native heath]

You wanna find the velocity

that's why

[frank bronze]

hold on

basically

i need to plug in 1 into position, and plug in one into veolocty and then see if they match signs

yes ?

[native heath]

no.

You need to find the velocity function

then plug in 1

and see the sign

[frank bronze]

yeah so plug in 1 to velocity

[bright fiber]

Don't plug in 1 into anything

until you derive

you'll also need acceleration

[frank bronze]

waht

cao

i quit

.close

[cedar kiln]

Channel closed

Closed by @frank bronze

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vernal pebble]

hey

[vernal pebble]

im confused for this question why they included the y axis of (4,2k) as it not needed

[serene umbra]

did you find $$\frac{d^2 y}{dx^2}$$ regardless?

[wraith dagger]

violet

[serene umbra]

in terms of k? (and x, of course)?

[vernal pebble]

ye

[serene umbra]

I guess you just plug in 4 for x, should be done

[vernal pebble]

but whats the use of 2k

theres no part b or anything

[modern sparrow]

they just like to throw it in for no reason. The end.

[serene umbra]

not sure, it doesn't serve any purpose, the fact is, if you put x = 4 in the original curve you get y = 2k

so yea

"for completeness", i suppose

[vernal pebble]

okay thanks

.close

[cedar kiln]

Channel closed

Closed by @vernal pebble

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

what is the relation between metric spaces, linear vector spaces, and normed vector spaces? are there theorems that connect them or similar versions of them in each of these spaces?

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cedar kiln]

Please don't occupy multiple help channels.

[subtle harbor]

what are you supposed to use to calculate

what software

[brittle frigate]

ti 84 calc

stuff like this i think

[subtle harbor]

https://www.youtube.com/watch?v=Ycz-taXvEKY

if you need help doing the commands and finding them

but sampling distribution has a known distribution given population stdev

[brittle frigate]

so it would be 18/sqrt of 61?

[brittle frigate]

i think i got that

[subtle harbor]

that's not the population standard deviation

[brittle frigate]

so what do i do for b

this is what i did for C

[cedar kiln]

@brittle frigate Has your question been resolved?

[cedar kiln]

@brittle frigate Has your question been resolved?

[brittle frigate]

<@&286206848099549185>

[cedar kiln]

@brittle frigate Has your question been resolved?

[hazy aspen]

Remember doing that in my 10th grade it's pretty easy

The dominant trait takes over recessive trait

[brittle frigate]

.close

[cedar kiln]

Channel closed

Closed by @brittle frigate

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pseudo merlin]

How do i draw this diagram

[upbeat dune]

If you take the base to be 34
What will the height be ?

[pseudo merlin]

wdym

im start the drawing like this

but idk which side to put the mumbers on

[upbeat dune]

Draw one of the sides flat with the ground

[pseudo merlin]

wait why

im just use formula 1/2ansinc

1/2absinC

[pseudo merlin]

?

[upbeat dune]

Then doit

[pseudo merlin]

But that just finds the angle

But the angle can also be 180-sinC

And that applies to all of them doesnt it

[pseudo merlin]

And i can also use cosine law to find the length of the other side

Wait but since that since is the longest side

Then the angle opposite that side

Is obtuse

Oh!!!!

.close

[cedar kiln]

Channel closed

Closed by @pseudo merlin

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[slate garden]

How do i do part 2

[slate garden]

How do i know k cuts at 0

[cedar kiln]

@slate garden Has your question been resolved?

[sudden anchor]

why is that needed

tell ur complete idea

[slate garden]

Basically just sub in y=kx

Use the discriminate

But the answer says

K=0 is also a solution

[sudden anchor]

yup

when u apply the condition on discriminant

you will get D >= 0

so k = 0 will satisfy as inequality will be satisfied

[slate garden]

What’s D?

I thought that means it has one root

As well

If it equals o

[cedar kiln]

@slate garden Has your question been resolved?

Channel closed

Closed by @slate garden

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[near acorn]

in integrals with the partial fractions descompositions
is the same to say

$\frac{A}{(something)} + \frac{Bx + C}{(something}$
and \newline
$\frac{Ax+b}{(something)} + \frac{C}{(something)}$

[wraith dagger]

Juan

[near acorn]

thtats the same thing?

[cedar kiln]

@near acorn Has your question been resolved?

[near acorn]

.close

[cedar kiln]

Channel closed

Closed by @near acorn

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[golden thicket]

reduce fraction

[golden thicket]

I have no idea how to shorten this

[modern sparrow]

notice that $a = (a^{\frac{1}{2}})^2$ and similarly for $b$

[wraith dagger]

lgkoo

[modern sparrow]

so a and b should be viewed as smth squared

[golden thicket]

but in the end the answer will be sqrt a + sqrt b

[modern sparrow]

yeah that's right

[golden thicket]

but

i have only this

answers

[modern sparrow]

wait, do you understand how this clue helps with the question first of all?

[golden thicket]

not really

[modern sparrow]

ok, so since the question has a^(1/2) and b^(1/2)

the best thing to do is to re-write a as (a^(1/2) )^2

so that we have
$\frac{(a^{\frac{1}{2}})^2 - (b^{\frac{1}{2}})^2}{a^{\frac{1}{2}} - b^{\frac{1}{2}}}$

[wraith dagger]

lgkoo

[golden thicket]

yes I understand this

but I don’t quite understand how this helps

[modern sparrow]

now to make a substitution, say x = a^(1/2) and y = b^(1/2), and see if you spot anything

[golden thicket]

x^2-y^2 / x-y = x+y

[modern sparrow]

yup

now substitute back x and y

[golden thicket]

a^1/2 + b^1/2 ?

[modern sparrow]

yup

do you know what $a^{\frac{1}{2}}$ is?

[wraith dagger]

lgkoo

[golden thicket]

sqrt a?

[modern sparrow]

yeah

[golden thicket]

oh I understood everything, thanks for helping, I didn’t see it until the end

[modern sparrow]

np

[golden thicket]

.close

[cedar kiln]

Channel closed

Closed by @golden thicket

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hoary parrot]

Is this possible to factor without a calculator? I'm not concerned about the inequality rn, just want to factor that quartic

[fallen moat]

you can first use factor theorem to check for zeros of the polynomial, and then use long division to factorize it

[hoary parrot]

I've tried that

but no values I put in f(x) would give remainder 0

[fallen moat]

interesting, lemme try

[hoary parrot]

Is there any other way?

I'm trying comparing coefficients, with multiplying 2 quadratics with unknown variables, but that seems ways too lengthy

[fallen moat]

i tried x=-1

[hoary parrot]

did you get 2 as a remainder?

[fallen moat]

4(-1)⁴+4(-1)³-3(-1)²-4(-1)+1
=4-4-3+4+1
=2

[hoary parrot]

its -3

[fallen moat]

nope

[hoary parrot]

not +3

[fallen moat]

oh

[hoary parrot]

-3(-1)² = -3

[fallen moat]

mybad

[hoary parrot]

yeah np

[fallen moat]

haha

yea, it's 2

time to try some more interesting

4(1/2)⁴+4(1/2)³-3(1/2)²-4(1/2)+1
=1/4+1/2-3/4-1/2+1
=1/2

hmmm

[hoary parrot]

for 1/2 I got -1

[fallen moat]

ohhh

[hoary parrot]

4/8 is 1/2

for the x^3

[fallen moat]

my bad

[hoary parrot]

np np

happens to the best of us 😂

[fallen moat]

rip

i have one more method

i usually do this when i cant factor

[hoary parrot]

what's the method,

[fallen moat]

i will look for similarities for the ⁴,³,² terms and ²,¹,⁰ terms

4x⁴+4x³ and -3x²-4x are a little bit similar, so I'll try to construct 2 terms and try to make them similae

but it doesn't seem to work...

[hoary parrot]

This is kind of annoying me, let me put it into desmos and see the x-intercepts

[fallen moat]

sure

[hoary parrot]

oh yeah

ok

there's 2 real roots

and they are decimals

[fallen moat]

interesting

[hoary parrot]

but like, not like 1/2, 1/3 or 1/4

[opaque root]

Are you trying to factor over what

[hoary parrot]

don't think they can be represented as fractions

[fallen moat]

time to do the xy

[hoary parrot]

?

[fallen moat]

!xy

[cedar kiln]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[hoary parrot]

this is the question

[fallen moat]

interesting

[hoary parrot]

doesn't really give much more information

[opaque root]

You do not factor the second one

[hoary parrot]

Then how do you solve it?

do you need a calculator?

[opaque root]

Doesn’t look like you can do manually, unless i am missing something, let me check the solutions quickly

Doesn’t look like

Give me more time

[dusk finch]

Is this the solution?

it seems like applied quartic formula

[opaque root]

It is the solution

I was thinking about trig sub but i cant find which one

Or maybe a subtitution that eliminates the cubic term

[dusk finch]

trig sub?

hm?

this feels like it doesnt have nice solution

[opaque root]

Yep lol

[dusk finch]

approximate solution is x in (-inf, 0.226) union (0.852, inf)

@hoary parrot this doesnt have a nice factorization unfortunately

[opaque root]

Like x=2cos(h) maybe

[raven shard]

i assume the last plus is supposed to be a minus

[dusk finch]

hmm i havent seen trig subs in polynomial inequalities yet

[opaque root]

Maybe separating x^3 +3x^3 and -x -3x

[raven shard]

it makes no sense for trig sub to be the intended approach here when the previous sub-problem is directly factorable

(and judging by the answer wolfram gave it also most certainly doesn't work)

[opaque root]

Yes i assumed it was probably a typo before but i am now in mode einstein lol

[cedar kiln]

@hoary parrot Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[coral jewel]

Let there be 2 positive real numbers $x, y$ such that [
2(x^2+y^2+4)+\log_{2022}\left(\frac2x+\frac2y\right)=\frac12(xy-4)^2
]
Calculate $\frac{y}x$ as $x+4y$ reaches its minimum

[coral jewel]

not sure what to do tbh

[cedar kiln]

@coral jewel Has your question been resolved?

[vagrant elbow]

Id consider writing in terms of x + y and xy only

since you can AMGM between those

and get a relation for x + 4y

[coral jewel]

amgm?

[vagrant elbow]

[ \f{a + b}{2} \geq \s{ab} ]

[wraith dagger]

Sadie Carnot (η > 1)

[coral jewel]

oh cauchy inequality

seems good, ill try that out

[vagrant elbow]

arithmetic on the left

geometric mean on the right

AMGM

[sacred grail]

,w expand 2(x^2 + y^2 + 4) - 1/2(xy - 4)^2

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by tearfox

[sacred grail]

this is straight up just 2(x + y)^2 - 1/2 (xy)^2

naively if you just want to satisfy the condition
[ 4(x + y)^2 = x^2 y^2 ]
and minimise $x + 4y$, you're just looking for
[ 6(x + y) = 2xy^2 - \f12 x^2 y ]

[sacred grail]

completely ignoring the log term

rearranging gives something like
[ 12(x + y) = xy(4y - x), \quad 2(x + y) = xy \Implies 6 = 4y - x ]

[sacred grail]

,w 2(x + y) = xy, 6 = 4y - x

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by tearfox

[sacred grail]

,w 2(x^2 + y^2 + 4) + log_2022(2/x + 2/y) - 1/2(xy - 4)^2 where x = 6, y = 3

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by tearfox

[sacred grail]

its actually on the curve

[cedar kiln]

@coral jewel Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pseudo merlin]

for the last question how come its 1-300/630

[fathom night]

$P(X \ge 1) = 1 - P(X=0)$

[wraith dagger]

Akuma

[nimble veldt]

630 is explained in (I), 300 is explained in the last question.

[pseudo merlin]

burt 330

[pseudo merlin]

ermmmmmmm

[nimble veldt]

you asked for 1-300/630, 630 comes from (i), 300 is explained here:

[pseudo merlin]

naur i asked why its that

why do we do 1 - subtract dat

[nimble veldt]

the probabiltiy having at least one anniversary card = 1 - probability having no anniversary card.

[pseudo merlin]

ya

i got dat but

[pseudo merlin]

ohh

ohhh

u are right!!

thank u

.close

[cedar kiln]

Channel closed

Closed by @pseudo merlin

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[craggy stratus]

Hi everyone

[craggy stratus]

Currently reading about matrixes and well, I am struggling a bit about when they're not quadratic and what their properties become then

The questions we get is in the form of if you have a matrix A where m < n, which of the following statements are guaranteed to be true

and then for example the rows in A are linearly independent so that the equation Ax = y for each y that is a real number there's always at least one solution

Are there any good resources online to get familiar with this? I feel like our textbook just isn't.. comprehensible enough

If it's about quadratic matrixes then I feel a lot more comfortable, but I think I struggle with knowing what it means to have for example 3 rows and 2 columns

is it that you have 2 vectors in R^3? In which case they can never be a base, so then you wouldn't be able to get all y in R^3

and then in this case, if it's that m < n, that means we have 2 rows and 3 columns, in which case we'd have a linearly dependent vector in r^2 from the columns

would just like to ask for some guidance on where to find resources that explains (preferably visually) in great detail how to treat such a matrix xd

i think what makes me confused is that im not sure if I can treat the rows AND columns as vectors / planes or what is going on :/

[tawdry pelican]

https://youtu.be/pznlOVse1qk?si=m34kW7A5nvZTzGEM

https://youtu.be/balnbHX3Vdc?si=LAzFaKj7TYHPVKpZ

[craggy stratus]

thank you a ton

you're an angel

wish you an amazing week <33

.close

[cedar kiln]

Channel closed

Closed by @craggy stratus

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stuck solstice]

Is this correct?

[cedar kiln]

@stuck solstice Has your question been resolved?

[cedar kiln]

@stuck solstice Has your question been resolved?

[cedar kiln]

@stuck solstice Has your question been resolved?

[cedar kiln]

@stuck solstice Has your question been resolved?

[gritty viper]

Yeah that's right

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[autumn nebula]

hola

[autumn nebula]

i’m not quite sure how we could sketch the points MN and NX seen in question 20. could someone please help with this?

<@&286206848099549185>

[cedar kiln]

@autumn nebula Has your question been resolved?

[autumn nebula]

<@&286206848099549185>

pls ong

ong

omg

[crimson sedge]

hey

[autumn nebula]

yo

Yo

YO

[crimson sedge]

wyd

[autumn nebula]

WHATS GOOD

[crimson sedge]

nun

[autumn nebula]

i need some help

[crimson sedge]

let me check

[autumn nebula]

aight bet

[crimson sedge]

how u do 19

is 20 both rays

[autumn nebula]

what

idk we just have to do 20

i’m not even sure

what to do

idk how to really sketch points

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[autumn nebula]

idiot

[autumn nebula]

.reopen

[autumn nebula]

<@&286206848099549185>

[cerulean sail]

[make sure you reply to the bot next time it asks you, with ❌]

[autumn nebula]

GOD PLEASE

HELO ME

HELP ME

ILL DO ANYTHING

I Locs you

CHARTBIT PLS HELP

[cerulean sail]

Honestly I don't know

Do you have any more context to that question at all?

[autumn nebula]

It just says

sketch the figure

described

[cerulean sail]

What's the examples 3 and 4?

[autumn nebula]

it’s not related to it

like at all

how do we usually

sketch these type of ooints

@cerulean sail

sorry for the ping

u said to ping tho in ur bio

[cerulean sail]

I did

And I really don't know what they're looking for tbh - that said, why to they say you should see those examples if it isn't related(?)

[autumn nebula]

Idk

[autumn nebula]

<@&286206848099549185>

please…

i can’t

[gleaming imp]

May I see the example 3 and 4?

[autumn nebula]

I OVENYOY

I LOVE YOU

YES SIR

[gleaming imp]

Alright lol

[autumn nebula]

i’m so grateful

i’ve been waiting

for 3 hours

for a helper

[eager wraith]

@gleaming imp have you seen the examples

?

this is my other acc btw

honestly i think im just gonna quit

i cant keep waiting

[gleaming imp]

Ok so

for exercise 17, you can simply draw a plane (denoted as P) and a line (denoted as l) intersecting at any point on the line.

[eager wraith]

I just need it for

20

and 22

[gleaming imp]

Bruv

hold on

[eager wraith]

sorry i forgot to say that

mb

oh wait

i did

this was my attempt for 20

idk if that’s right

[gleaming imp]

nah i dont think so

[eager wraith]

oh

[gleaming imp]

I believe you have to draw two vectors, MN and NX

with thir tails at the same initial point

wwhich is M

[eager wraith]

how do we do that

[gleaming imp]

just draw one vector on top of other

[eager wraith]

yeah uh

whats a vector

[gleaming imp]

:))

[eager wraith]

i mean

sorry

i know what it is

but like

how to draw it

[gleaming imp]

---------->

[eager wraith]

wait

oh

so two lines on top of each other

[gleaming imp]

Exactly

[eager wraith]

so

like this

like this

u may need to flip

it

[gleaming imp]

no...

[eager wraith]

so wait

[gleaming imp]

MN> and NX>

[eager wraith]

u want me to just draw

[gleaming imp]

right?

[eager wraith]

a parallel line

[eager wraith]

he’s

yes

[gleaming imp]

wat

Okay

so whats in commin in that 2 vectors?

[eager wraith]

they share

N

[gleaming imp]

"n"

Exactly

so Starting from N point

draw 2 lines

and yk what to label them

[eager wraith]

omg my storageh

ok

lemme send

[gleaming imp]

Okay

[gleaming imp]

vectors

what indicates a vector that it's a vector?

[eager wraith]

a point

[gleaming imp]

DIRECTION

so u need arrow head

[eager wraith]

ok

Wdym

arrow hwad

head

[eager wraith]

oh

[gleaming imp]

Yeah

[gleaming imp]

And u don't plot the point labels on the line btw, On either the arrow or starting point

[gleaming imp]

Bruh,no

[eager wraith]

ok wait

could u sketch it and show me