#help-13

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elder elm
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<@&286206848099549185>

cedar kilnBOT
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regal pivot
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Just to double check the answer for this is - scr3/4 correct?

regal pivot
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And this work would be correct?

hollow trail
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yes

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(you did forget a square on the cos at the start)

regal pivot
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Ok thx I appreciate it

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sour tiger
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I’m trying to find what the length would be for this problem. I found what the width is, and input it into the equation where length is written in terms of w, but it equals zero

hollow trail
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you solved w for the assumption a = 0

sour tiger
hollow trail
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well if you want to find the max of a function, you probably want to find its critical points

sour tiger
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So would I take the derivative of the area function?

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I feel like I need the derivative of something

hollow trail
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the derivative of the area function with respect to width would give you the width for which the area has a maximum or minimum

sour tiger
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I got w=75

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I got the answer! Thanks

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delicate patio
cedar kilnBOT
delicate patio
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help please

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i am not able to do it

cedar cypress
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Do you know Baye's theorem

delicate patio
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P(Female | Successful Candidate) = P(Successful Candidate | Female) x P(Female)/P(Successful Candidate)

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i am not able to find P(Successful Candidate | Female)

delicate patio
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P(Female) = 2/5
P(Successful Candidate) = 1/2

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how can i find the last using the data given

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i tried taking the total candidates as 120

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got the final answer answer as 7/12

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but i dont know how to find P(Successful Candidate | Female) directly

cedar cypress
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you can set up an equation based on the given information,
let the total candidates be N
N/2 is the total number of successful candidates,
N/2 = .4N x female success probability + .6N x male success probability
.4N x female success probability = 1.4 x .6N x male sucess probability
this will give you your numerator in terms of the denominator and hence your answer

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you can see that the 'N' has no practical use

delicate patio
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i am a bit confused sorry

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like what would the numerator be

cedar cypress
delicate patio
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what would the male sucess probability be

cedar cypress
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we dont need that if you look at the equations

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we can elmiinate that

delicate patio
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i got this same value when i took N = 120

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so yes it is independent of N

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hmmmm

cedar cypress
cedar cypress
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and no change will happen

delicate patio
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can you elaborate please

delicate patio
cedar cypress
delicate patio
cedar cypress
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my point was we dont to solve for the 'exact value' as we just want the ratio

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say i give you 2x+5=18, sure you can separately solve for x, but we dont need to if we want to evaluate an expression like (2x+5)/6, we can directly go 18/6

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nevertheless you will arrive the answer both ways

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im just recommending something to minimize calculation

delicate patio
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thankyouu

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just got bit confused by 'directly'

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😅

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thankyou

cedar kilnBOT
#

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crimson sedge
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Five times the sum of x and 5 is 8 less than twice x. Solve for x.

crimson sedge
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!status

cedar kilnBOT
#
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5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
crimson sedge
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1

cedar cypress
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write what theyve given you in a maths equation

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translate english to math

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five times (the sum of x and 5) is 8 less than (twice x)

earnest geyser
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@crimson sedge

crimson sedge
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.close

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frigid sinew
cedar kilnBOT
frigid sinew
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for the series here, i wrote out the partial sum

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but i cant find a pattern

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is it a harmonic serie?

cerulean sail
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Check the sequence first, I'd suggest catGiggle

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(the sequence doesn't go to infinity, but if it did, it would also allow you to conclude something about the series!)

frigid sinew
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i think it goes to -4.5

cerulean sail
frigid sinew
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ahhh

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right right

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btw the way i determine sequences is by putting n to 9999999 on my calculator uhm

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idk if its the right way to

cerulean sail
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Well, that can work at times, but sometimes can be misleading catGiggle

frigid sinew
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what could be another way

cerulean sail
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One thing you [should] know is that if a series converges, the sequence it's made up of must converge to zero, so if you have the sequence not converging to zero, the series must diverge somehow

cerulean sail
frigid sinew
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then lima_n = 0?

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ah okay yeahh im struggling with notations sometimes

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tysm!

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again

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.close

cedar kilnBOT
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vapid grotto
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Would I find the hypotnus using a^2+b^2=c^

spiral hull
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Yes

cosmic narwhal
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worldly walrus
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How do I calculate sin(2theta)

cedar kilnBOT
worldly walrus
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I don’t know what double angle formula is

hollow trail
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the double angle formula is $\sin(2\theta) = 2\sin(\theta)\cos(\theta)$

wraith daggerBOT
worldly walrus
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Oh okay

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ty!

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.close

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polar linden
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how do i solve this?

cedar kilnBOT
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@polar linden Has your question been resolved?

polar linden
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no

tawny grove
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hi

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@polar linden

polar linden
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hello

tawny grove
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!status

cedar kilnBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
polar linden
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1

tawny grove
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first write the equation for the formula for cylinder

polar linden
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soo pi^2h

tawny grove
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Vbox = (π)(R^2)(H) = 25π

polar linden
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oops yeah

tawny grove
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And write volume of box

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V = (L)(W)(H)

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and we don't know any of these quantities, L, W, and H but we can substitute with variables we defined up there

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V = (2R)(2R)(H)

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simplify the expression

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V = 4(R^2)(H)

polar linden
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wait im lost

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where did 2r come from

tawny grove
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how so

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Since cylinder perfectly fits in box

polar linden
tawny grove
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One radius is half the width of the box

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So 2R is the width of the box

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we can infer based on "fits perfectly inside the box"

polar linden
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i understand

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nevermind

tawny grove
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Okay so now we have two equations:

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Vcylinder = (π)(R^2)(H) = 25π

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Vbox = 4(R^2)(H)

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Now you have these two equations, can you solve?

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Vbox = 4(R^2)(H)

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(π)(R^2)(H) = 25π

polar linden
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im not sure how to

tawny grove
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No problem

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  1. Vbox = 4(R^2)(H)
  2. (π)(R^2)(H) = 25π

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Using equation 2), we can solve for (R^2)(H)

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(R^2)(H) = (25π)/(π) = 25

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Subbing back in equation 1), we can find Vbox

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4(R^2)(H) = 4(25) = 100 cm^3

polar linden
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ah

untold plover
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i think you're making him lost.

polar linden
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no i understand

untold plover
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help

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WAIT

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nevermind

polar linden
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okay thank you : )

cedar kilnBOT
#

@polar linden Has your question been resolved?

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cobalt grotto
#

stupid question but like how are we using ft^3 in a 2D problem

cobalt grotto
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Are we just assuming the tank is 10x10x10?

fast lotus
cobalt grotto
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I only have ft^2 measurements

fast lotus
cobalt grotto
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I have done it before with a semicircle

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But this is more complex

fast lotus
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i got no idea sryy

cedar kilnBOT
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cedar kilnBOT
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@cobalt grotto Has your question been resolved?

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turbid harbor
#

Can anyone help me check whether my logical equivalence is correct?

cedar kilnBOT
#

@turbid harbor Has your question been resolved?

upper abyss
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What's in that picture is all true

turbid harbor
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is it?

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My truth table says otherwise

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oh freak

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I put negation q

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not p

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mb

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my truth table is not equal

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So I guess it is not logical equivalence unless my eye deceive me

turbid harbor
#

.close

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swift saffron
#

$7^{8^{9}}$ mod 1000

cedar kilnBOT
wraith daggerBOT
#

matchafrappucino

cedar kilnBOT
#

@swift saffron Has your question been resolved?

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crimson sedge
#

Hello

cedar kilnBOT
crimson sedge
#

Need help solving this

quaint epoch
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the formula for circumference of a circle is 2πr

crimson sedge
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Yeah

quaint epoch
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r = 23 m as given in the question

crimson sedge
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It’s a daily practice

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2(3.14 x 23)

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?

quaint epoch
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2 x 3.14 (π) x 23

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yea same thing

crimson sedge
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That’s 144.4

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Not an answer here

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138.2

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Oh I’m looking at the wrong question lmao

quaint epoch
#

lol

crimson sedge
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I have another one

quaint epoch
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yes?

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oh the 10th one?

crimson sedge
#

Nope

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(0/360) x 2TTr = TT/180

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?

wraith daggerBOT
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faiyrose

crimson sedge
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I do this on a calculator?

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Can you explain more ?

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I would assume so

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Yes

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270

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Not a selectable answer ?

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Oh

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What

wraith daggerBOT
#

faiyrose

crimson sedge
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How do I read this

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Wait I’m an idiot it literally tells me

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Haha 😂

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How do I do a pie sign on laptop

wraith daggerBOT
#

faiyrose

crimson sedge
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The final answer I got was 18.8

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But it didn’t come up

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As an answer

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I did this

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270/360 x 2pi x 4

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How do I convert 18.8 to terms of pi

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Ohhh

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6 pi

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Alright one more

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@orchid field 35

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What

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I don’t understand sorry

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Kk

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It’s 85 angle?

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So

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Same equation as before but 275/360?

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Or wait that’s not even what it’s asking

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The answer is 85 eight?

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Right*

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Okay last one lol

crimson sedge
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I’ll show you after we solve this one

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One of the other ones is

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Trigonometry

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Kk

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What about this one

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lol what’s the answer

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Or explain what a minor arc is

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An arc whose measure is less than 180 degrees google says

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So MN and LP?

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PL*

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And

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LM NP?

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How would LM be more than 180 degrees?

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Ok

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@orchid field are you ready for trig?

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Do you now someone that can

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@orchid field

mighty shuttle
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is this a test?

crimson sedge
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No it’s not a test

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@mighty shuttle

mighty shuttle
#

ok

crimson sedge
#

Can you help me?

mighty shuttle
#

I'm trying to solve a problem of my own rn, sorry

crimson sedge
#

<@&286206848099549185>

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

crimson sedge
#

Hello?

radiant scaffold
#

Yo if you could show a clear photo of the whole question thatd be great

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

crimson sedge
#

@radiant scaffold

radiant scaffold
#

Ok

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So we have an angle and a value

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So what can we use with those two to find another side

crimson sedge
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I don’t know

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This is my first lesson on trigonometry

radiant scaffold
#

Ok

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Theres an abbreviation thats fairly liked

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Its SOH CAH TOA

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Sin = opposite/hypotenuse

crimson sedge
#

Ok

radiant scaffold
#

Cos=adjacent/hypotenuse

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Tan= opposite/hypotenuse

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Which of these three would be useful to find AB

crimson sedge
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Cos

radiant scaffold
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Yep

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Plug the values in the calc and tell me what you find

crimson sedge
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The values

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Where do I find those

radiant scaffold
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Ok

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Whats the angle

crimson sedge
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Uh

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90

radiant scaffold
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The other angle

crimson sedge
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45

radiant scaffold
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Yes

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No

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Sorry its 40

crimson sedge
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40 lol

radiant scaffold
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Ok

crimson sedge
#

So that’s one number now what

radiant scaffold
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So cos40= AB/BC Right?

crimson sedge
#

What’s the equation

radiant scaffold
crimson sedge
#

60 ft

radiant scaffold
#

Yep

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So now we only have 1 unknown value

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Can you rearrange the equation cos40 = 60/AB to solve for

crimson sedge
#

How ?

radiant scaffold
#

:||

crimson sedge
#

lol

radiant scaffold
#

How good are you at algebra

crimson sedge
#

Not good

radiant scaffold
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Ok

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Makes sense

crimson sedge
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That’s what online math does to you :/

radiant scaffold
#

If you have this, you normally want to cancel out anything that's happening to the unknown value

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So in this one, AB Is being divided by 60

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In order to make it just AB, what do you think we should do

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Fuck

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Wait

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Sorry

crimson sedge
#

lol

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Do you know algebra haha 😂

radiant scaffold
#

Wrong way around

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Damn im being stupid today

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Anyway the thing you normaly do with these is make AB not a denominator

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This means multiplying both sides by AB

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Can you write the equation for that

crimson sedge
#

Hmm

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Nope

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Couldn’t find anything online

radiant scaffold
#

Ok

#

Lets start off with a small algebra question instead

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Cause algebra is the foundation, its best to get better at it now then later

crimson sedge
#

Kk

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We gotta hurry because I need to move on to history

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We got like 10 minutes

radiant scaffold
#

Damn ok

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If you have x+2=3, what does x equal

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Quick fire just tell me if you dont know

crimson sedge
#

1

radiant scaffold
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Yess

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And you did that by?

crimson sedge
#

-2

radiant scaffold
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Exactly

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Then if you have 2x=4

crimson sedge
#

dk

radiant scaffold
#

You did that because its the opposite of +2 right?

crimson sedge
#

-4

radiant scaffold
crimson sedge
#

Yeah

radiant scaffold
#

So then whats the opposite of multiplying by 2

crimson sedge
#

2

cedar kilnBOT
#
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crimson sedge
#

Divide by 2

radiant scaffold
#

Yess

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Reopen it btw

crimson sedge
#

.reopen

cedar kilnBOT
#

radiant scaffold
#

Ok

#

Does that make sense?

crimson sedge
#

Yeah

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Now back to math problem

radiant scaffold
#

So if you have AB as a denominator, you want to get rid of the fraction right?

crimson sedge
#

Yes

radiant scaffold
#

If the thing on the right divides it by AB, what do you think you should do

crimson sedge
#

AB are letters though how do we divide by letters?

radiant scaffold
#

Its like x

crimson sedge
#

Ok

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60/x

radiant scaffold
#

Yes

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Ill just tell you cause youre on a time crunch

crimson sedge
#

:/

radiant scaffold
#

Youll timex both sides by AB(or call it x idk)

crimson sedge
#

Ok

radiant scaffold
#

Then you get a beautiful equation of ABcos40=60

crimson sedge
#

60x/x ?

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lol

radiant scaffold
crimson sedge
#

Yeah ok

radiant scaffold
#

So then whats the next step

crimson sedge
#

Now what

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Idk

radiant scaffold
#

Lets write it like this

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For x to be alone, what would you do

crimson sedge
#

I’ve never done a trigonometry problem before

radiant scaffold
radiant scaffold
crimson sedge
#

So

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What do we do

radiant scaffold
#

Same concept

#

:||

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Ok

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We divide both sides by cos40

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That makes AB alone right?

crimson sedge
#

I got 2 minutes to do all three questions :/

crimson sedge
radiant scaffold
radiant scaffold
crimson sedge
#

-89

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89.96

radiant scaffold
#

Nope

#

Somethings wrong

crimson sedge
#

60/cos40 ?

radiant scaffold
#

Should look like this

crimson sedge
#

60 / cos(40 radians)

radiant scaffold
#

Not radians, this is degrees

crimson sedge
#

Still -89

radiant scaffold
#

Did you change the calculator mode

crimson sedge
#

Sending picture

#

It’s on google calculator

radiant scaffold
#

Ah

#

How did google stuff up that bad

#

Uhh type 60/cos(40 degrees)

#

Lets see what happens

crimson sedge
#

Ok

#

Internet bad

radiant scaffold
#

Brother go off to history, if you need help after on these just dm me if the help closes

crimson sedge
#

78

radiant scaffold
crimson sedge
#

78

radiant scaffold
#

Thats how far the dude walked

#

Now go to history mate

crimson sedge
#

Wait but how do I show work

radiant scaffold
radiant scaffold
cedar kilnBOT
#

@crimson sedge Has your question been resolved?

wild geode
# crimson sedge

So, basically, for question 2, you'll be doing the same thing using the tangent function. So, the equation would be
Because
SOH**|CAH|**TOA
Tangent function is t=opposite/adjacent
Just like the sine function is
s=opposite/hypotenuse
The equation for Tangent is
tan(40°)= AC/BC

Because you need to find AC.
solve for AC by multiplying BC to both sides leaving you with
BC(tan(40))=AC

Question 3
I'd just think about it visually.
If you travel 5ft per second
Then use your path (AB)
Divide (AB) by 5 and you'll find seconds
If bro travels 3ft per second
Use bro's (BC)
Divide BC by 3 and you'll find seconds

cedar kilnBOT
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fossil pewter
#

Why is the partial derrivative in regards to z this diagonal matrix?

fossil pewter
#

When I did this I just said derrivative of sin(z) = cos (z)

crimson sedge
cedar kilnBOT
#

@fossil pewter Has your question been resolved?

cedar kilnBOT
#

@fossil pewter Has your question been resolved?

next palm
#

Because z, by its definition is an E-dimensional vector

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dark orbit
#

Lets say that from pipe water is poured out to cube of side A , ideal situation such that water is equally distributed and no water flows out, what should be the flow of water such that the height of the water level is increasing with rate x? (Variable form)
now, dV/dt = 3A²x im getting by differentiating function of volume
But, i tried in a different method
take a thin slice of cube, which will be a cuboid of height dA and A² as its surface (top view square A^2 shud be its area)
then volume is A^2 dA
of that cuboid, and that is also the volume that will be filled with x rate,
with this im getting A^2 x, what did i do wrong?

dark orbit
#

please help

#

pretty simple doubt ik

drifting matrix
dark orbit
drifting matrix
#

(typo)

dark orbit
#

hmm

#

so whats wrong in 3A^2 x method

#

OHH

#

volume of filled water is not A^3

#

gotcha

#

.close

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crimson sedge
#

The figure shows parallel lines AB and DE, ∠BAC = 30°, ∠CDE = 50°. Calculate the size of the angle ACD.

crimson sedge
#

I got 80 is it correct?

dark orbit
#

yes

crimson sedge
#

.close

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minor seal
#

Hey

cedar kilnBOT
minor seal
#

I wanna solve acos(x) + bsin(x) >= 0

#

a,b in IR*

raven shard
#

u have to combine a cosx + b sinx into a single sinusoid

minor seal
#

By factoring by $\sqrt{a^2+b^2}$ I get cos(x-\theta)$ with $\theta$ a reel such as

wraith daggerBOT
#

Akti
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

minor seal
#

I'm stuck here, there is something to do with arctan but I'm kinda lost about it, never dealt much with those before

#

Depending on a,b signs

#

I tested and should get those results, but idk how to prove it

wraith daggerBOT
cedar kilnBOT
#

@minor seal Has your question been resolved?

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#

@minor seal Has your question been resolved?

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rancid cipher
#

im checking my work with Symbolab and my final answer doesn't match and it's not equal to theirs. I've checked my work it looks fine to me but I could very much be overlooking it. Can someone please review it

cedar kilnBOT
#

@rancid cipher Has your question been resolved?

modern compass
rancid cipher
#

oh yea haha ur right

#

thank you

modern compass
#

you can rewrite and factor out a 2 to get rid of the 1/2 in front, but those should still be divided by 5 and 3

rancid cipher
#

yes i c, i think imma sperate them so i can solve... i need to slow down lmao thank you

#

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delicate patio
cedar kilnBOT
delicate patio
#

i completed the square

#

how do I find the centre now?

rough terrace
#

(1,-1)?

delicate patio
cedar kilnBOT
#

@delicate patio Has your question been resolved?

cedar kilnBOT
#

@delicate patio Has your question been resolved?

sharp pike
delicate patio
sharp pike
#

Search up the ellipse equation form

#

You want it like that

#

Or wait

#

Nevermind that won't work

delicate patio
delicate patio
#

<@&286206848099549185>

delicate patio
#

<@&286206848099549185>

timber zinc
timber zinc
#

you want to know how

#

it is easy

radiant scaffold
#

do you know it?

timber zinc
#

first you have y+1=0 so you find out that y=-1 and x+y=0 you gonna have x=1

queen loom
#

@delicate patio , if u udnerstand then close the channel

#

👍

delicate patio
#

.close

cedar kilnBOT
#
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steep charm
#

How do i read this in my head? As far i can tell the fancy g is just a G and not a greek letter or anything, and the circle with a cross is just called a "CIRCLED TIMES"

steep charm
#

Also a little econfused by that sentence, is ⊗ just the same as × (which is just multiply right?)

cedar kilnBOT
#

@steep charm Has your question been resolved?

void wasp
#

This G is a set. It could also be any letter you want. To differentiate it a little bit from normal letters used for Area, volume and so on, they write it a little fancy sometimes

steep charm
#

So in your head how would you read G := (G, ⊗)

void wasp
#

The other symbol stands for an operation. It doesn't have to be multiplication. It could also be addition, subtraction, Division, Modulo. Like basically anything you want

gusty forum
#

⊗ is not the same as × in this scenario, × is also not multiplication but instead the cartesian product
{fancy G} × {fancy G} represents the cartesian product between fancy G and fancy G

steep charm
#

is : like "where"?
"Consider a set g and an operation ⊗ where for all combinations of two sets G, G, the result is a set G"?

void wasp
void wasp
gusty forum
#

also you're not mapping to the same set, but anyways

void wasp
wraith daggerBOT
void wasp
#

And the operation: +

steep charm
#

I see

#

i think i get it

#

G := (G, ⊗)
What does this notation mean exactly?

#

The group on the set G and operation (cricle cross)?

void wasp
void wasp
#

So if you consider my example with the whole numbers:

$\mathbb{Z} \times \mathbb{Z} \to \mathbb{Z}$

With the Operation +

wraith daggerBOT
void wasp
#

Then we could pick a number for the first set (3) and the second set (-2). And we get the Cartesian product for.example (3,-2)

#

Which we then use our operation on (+) which gives us (1) which is in Z.

cedar kilnBOT
#

@steep charm Has your question been resolved?

#
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abstract pagoda
#

HELP

cedar kilnBOT
abstract pagoda
#

how do you get Yk

#

the solutions give y(0) = 0.5, y(1) = 1 and y(2) = 0.5

#

but how

hidden mural
#

whats y

abstract pagoda
abstract pagoda
hidden mural
#

theres no f

abstract pagoda
hidden mural
#

alright

abstract pagoda
#

i get it all appart from the substitution at the end

abstract pagoda
#

how did they get 1/2

#

and 1

hidden mural
#

not 0.5

abstract pagoda
#

its 1/2

#

its the same

abstract pagoda
hidden mural
#

y(0) = f(0) = 1

abstract pagoda
#

Yk is not f(k)

#

because then u cant do Y(2)

#

for the 3rd term

hidden mural
#

literally i don't see a Y

#

or Y_k

abstract pagoda
hidden mural
#

ok it's y_k

abstract pagoda
#

yeah

#

but wtf does that mean

#

how does y_0 = 1/2

hidden mural
#

well y_k = f(x_k)

abstract pagoda
#

okay but then u have the same issue

#

x_0 = root(3)/2

#

so f(x_0) = root (-5/4)

hidden mural
#

f(x0) = sqrt( 1 - 3/4)

abstract pagoda
#

its squared?

hidden mural
#

= sqrt( 1/4 )

abstract pagoda
hidden mural
#

yes

abstract pagoda
#

omg

#

i cant do math

hidden mural
#

fr

abstract pagoda
#

i did root 3 ^2 = 9

#

lmao

hidden mural
#

jk

abstract pagoda
#

okay

#

ty

#

thanks

hidden mural
#

welcome

abstract pagoda
#

ily

#

.close

cedar kilnBOT
#
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sturdy ferry
#

Please help

#

Anything

cedar kilnBOT
sturdy ferry
cedar kilnBOT
#

@sturdy ferry Has your question been resolved?

torpid cipher
#

what do you need help with

sturdy ferry
torpid cipher
#

can you take a photo directly from above

#

so i can see better

cedar kilnBOT
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scenic nest
#

I need guidance on how to study my intro to discrete math material for my uni exam

scenic nest
#

Here are the topics I need to cover

Combinatorics
Multiplication principle
Addition principle
Pigeonhole principle
Permutations and combinations (with and without repetition)
Solving problems involving combinatorial principles

Discrete Probability
Experiment, sample space, and events
Finite probability space
Equi-probable spaces
Conditional probability
Mutually exclusive and independent events
Applying probability concepts to solve problems

Graph Theory
Graph models
Graph isomorphism
Degrees of vertices
Paths and cycles in graphs
Euler's theorem and its applications
Bipartite graphs and their properties

#

I have tried using my textbook, online resources, etc but I keep getting myself confused and frustrated

candid mason
#

So the first thing to figure out what it is you are getting confused about

torpid cipher
scenic nest
scenic nest
scenic nest
#

I overthink a lot, and it hasn't helped me in this module especially

candid mason
scenic nest
#

How should I take notes, or do I just read and solve questions? i have a habit of taking notes but it doesnt help during solving questions

candid mason
#

Try down key definitions and theorem. Number each page and store them in a folder for future reference

#

In addition you should do exercises

scenic nest
#

thank you

scenic nest
crystal raptor
#

If you have past exam papers it's worth going through them and figuring out what it is you don't know

candid mason
#

logic, set theory, proofs at the bare minimum

scenic nest
cedar kilnBOT
#

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tender sundial
#

I am supposed to show that |det(M)|^2 <= product of (the sums of (each row of M elementwise squared)). I'm fairly certain the path forward is that the determinant of the LU of M is the product of the diagonals of L and U (one of which is all 1s). Which means that the left hand side is just the square of the product of the diagonal of U. Intuitively because of the absolute value we know each element on the right hand side is positive, so I think we know that the RHS is >= the product of the diagonal elements of U. Does that sound right?

tender sundial
#

The problem of course I can't quite figure out is that I'm not sure how to deal with the squaring of each element on the right hand side.

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#

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@tender sundial Has your question been resolved?

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crimson sedge
#

i am not familiar with this type. can anyone help? (*e^1/s)

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@crimson sedge Has your question been resolved?

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pure quartz
#

Hello

cedar kilnBOT
pure quartz
#

Can someone help me how to ssolve this conditional probability problem?

fast lotus
#

P(A/B) also P of A given B is defined as P(AintersectionB)/P(B)

pure quartz
#

Yes i tried that however my results was the ff:

P [ (Y = 3) intersection (Y>=2) ] / P [ ( Y>=2 ) ]

#

which just results to the same numerator and denominator

fast lotus
#

Yes

#

It shouldn't

#

Lemme c

pure quartz
#

oh wait i saw where i went wrong

fast lotus
#

Oh

pure quartz
#

lemme retry again and see if i got it

fast lotus
pure quartz
#

my answer is not in the choices

#

i tried to solve the conditional problem by

P [ Y = 3 ] / ( P [ Y = 3 ] + P [ Y = 2 ]

#

then i solved for P [Y=3] and P[Y=2]

#

P [ Y=3 ] = f (1,3) + f (2,3) + f (3,3) = 41/56

#

P [ Y=2 ] = f (1,2) + f (2,2) = 13/56

#

then my answer was 41/54

#

which was not in the choices

#

can someone help me where i went wrong?

granite knoll
#

why are you calculating the probability that Y equals 2?

#

the condition is Y is at least 2

pure quartz
#

i solved for P(Y>=2) by adding P(Y=3) and P(Y=2)

#

is that not correct?

#

T-T

granite knoll
#

oh, Y is only from 1 to x

#

hmm

pure quartz
#

awwww i see

#

oh wait im confused

#

did i not incorporate it in the equations correctly?

granite knoll
pure quartz
#

i got it

#

the answers C

#

thank youuuu

#

.close

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#
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night karma
#

Are these (red marked) elements of O(n)?

cedar kilnBOT
kindred venture
#

doesn't that depend on what n is tending towards?

night karma
#

Hm we have no n given

fair geyser
#

the one with log is not O(n)

#

is it?

drifting matrix
#

it is

night karma
#

Ok my thought was everything that is "below" O(n) is in O(n)

#

but then I was wrong I guess

fair geyser
#

oh duh

night karma
#

maybe because O(log n) has values that O(n) doesn't have

drifting matrix
#

uhhh

fair geyser
#

so the middle left is O(n)

fair geyser
drifting matrix
#

neither is the top right sum

fair geyser
#

but it could be the wrong answer if you have a better option

night karma
#

okay can you explain why, I didn't understood it:/

drifting matrix
fair geyser
#

the sum in the middle right says (n² - n) / 2

#

or +

night karma
#

It's said that f(n) <= c * g(n)

fair geyser
#

probably plus, it doens;t matter

#

it just says something that's obviously not O(n), but infdirectly

drifting matrix
night karma
#

but I don't know how I can find out the n0 and c

drifting matrix
#

I really think you need to work with the definition or otherwise this is just guesswork for you

drifting matrix
night karma
#

rip

drifting matrix
#

If you work through examples you can aquire the skill.

night karma
#

yea maybe I can find more examples

drifting matrix
#

For example 13n + 15/n + 17/n² <= 13n + 15 + 17 = 13n + 32

#

you estimate first using constant terms

drifting matrix
#

then your thing <= 13n + 32 <= (13+32)n (g(n) is just n)

night karma
#

hmm okay what I understand so far is:

13n + 15/n + 17/n² <= c * n
and then I need a n0 for that the c * n is equal
let's say n0 = 1
13/1 + 15/1 + 17/1² = 13+15+17 = 45
now I insert n0 in the other equation with a c, for example c = 45
so I have 45 * 1

then we found out it's O(n)

#

okay I think it's basically the same as you wrote but in another format

drifting matrix
#

you need to make sure that

#

f(n) <= 45g(n)

night karma
#

but then I'm also only guessing a n and c ( with my approach)

drifting matrix
#

it's true but I am not sure if you actually realize this

night karma
#

so 45 <= 47?

drifting matrix
#

em stick with 45, although it doesn't matter

#

if you find any number, every bigger number will work too

night karma
#

okay but usually I search for the smallest n0 possible I think

so let's say 42✓n + 0.1n <= c * n

now I have the problem of finding the c and n... I can try to put in something that is possible to solve

42 ✓4 + 0.1* 4 <= c* 4
84.4 <= c* 4
Now I need a c for that it's 84.4
84.4 <= 21.4 * 4

so this one is also O(n)

#

now I can try another one
the sum in the left bottom corner

it's n * ✓n <= c * n maybe

n0 = 4
4 * 2 <= 2 * 4

Also O(n) lol

drifting matrix
drifting matrix
drifting matrix
#

for all n after your n0

#

obviously it is true for a single n

night karma
#

n needs to be > n0?

#

I will watch some videos now about it, I'll come back later

#

.close

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#
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shrewd panther
#

I've been stuck on this for awhile now, my brain isn't braining today and i've gotten so many wrong answers </3

My math teacher doesn't explain as well but i still try </33

cedar cypress
#

what have you tried

shrewd panther
#

I've tried doing Slope but i kept getting the weong answer

#

wrong*

cedar cypress
#

wdym by tried slope

shrewd panther
#

My math teacher has only been teaching slopem he always goes back to it everytime we finish a new math unit

cedar cypress
#

you wish to use the pythagorean theorem here

shrewd panther
#

sure

cedar cypress
#

do you know what it states

shrewd panther
#

For A, It's asking the distance

#

the top says "Each unit respresents 1 meter"

cedar cypress
#

i meant to ask do you know the pythagorean

shrewd panther
#

i kind of do but i kinda don't at the same time

cedar cypress
#

this

shrewd panther
#

yea i know it

cedar cypress
#

can you try to use it here?

shrewd panther
#

the O doesn't seem to mean anything i think thats why i feel confused

cedar cypress
#

the O is the origin, it seems like you're having trouble with the coordinate system

#

and not the geometry

#

but regardless just use what they gave you

shrewd panther
#

Alr

cedar cypress
#

each unit is 1 metre

#

count how many units

#

and go from there

shrewd panther
#

Would B be a half because of how it is or would it still count as 1

cedar cypress
#

point B is at the end of the unit line there

#

so we will count that as a full unit

#

we only worry about the horizontal distance

#

and then the vertical

neon grotto
shrewd panther
#

Ohh

#

would B be 12 meters?

cedar cypress
#

CB you should call it

#

and its 13 i believe

neon grotto
#

13

cedar cypress
shrewd panther
#

ohh alr

cedar cypress
#

unless you meant the small letter 'b'

#

referring to my diagram

#

of the right angled triangle

shrewd panther
#

theres a right angle at the A and C

cedar cypress
#

angle(ACB) is a right angle yes

shrewd panther
#

would C and A be somewhat 3 or 4

#

my brain is a lil fried

cedar cypress
#

how many boxes do you see

#

between A and C

#

3 or 4

shrewd panther
#

i see 3

cedar cypress
#

yes

#

so its 3m

shrewd panther
#

C = 12 + 3?

#

or is B the =

cedar cypress
#

refer this

#

just compare

#

and use small letters for sides please since weve already assigned the capital ones to points

shrewd panther
#

alr

#

12 to the power of 2, we jut do 12x12 to get us 144

#

oh ait

#

its 13

#

C = 196 + 9?

neon grotto
neon grotto
shrewd panther
#

ohh wait i get it now

#

i think i can do it on my own now

#

.close

cedar kilnBOT
#
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cedar kilnBOT
#
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tropic kestrel
#

I am doing this and I don’t understand stand it (I am in 8th)

neon void
#

use variables instead of images

#

x + y + z = 58
1 * x = z
y * y = 64

tropic kestrel
#

Oh okay that’s makes more sense

#

.close

cedar kilnBOT
#
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cedar kilnBOT
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nova snow
cedar kilnBOT
nova snow
#

Hi so the formula that I've used is (n!/n^n)x^n

#

And I've still gotten it wrong

#

Can someone please help

elfin hemlock
cedar kilnBOT
#

@nova snow Has your question been resolved?

cedar kilnBOT
#
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cedar kilnBOT
#
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runic garden
#

Hello could someone help me with this question please? Determine the values of θ if 0 ≤ θ ≤ 2pi given that cosθ = −0.3178

runic garden
#

I am just confused on how I should start this question

royal loom
#

If the output of cosine is negative

#

What quadrants could you be in

runic garden
#

2 and 3

royal loom
#

Okay

#

The inverse cosine function has a limited domain

#

Do you know where it’s limited to?

runic garden
#

No

royal loom
#

Say that you wanted to know the cosine inverse of 0

#

How would you know if it should be pi/2, or 3pi/2, or 5pi/2, etc…

#

Well the first thing you can do is restrict to values in between 0 and 2pi

#

But then the issue is that

#

cos(pi/2) = 0

#

And

#

cos(3pi/2)=0

#

Right?

#

😓 so what should the inverse be

runic garden
#

no clue 😦

royal loom
#

The solution is to restrict to values between 0 and pi

#

Then the only option is that cos^(-1)(0)=pi/2

#

But if you wanted to recover information from the other quadrants

#

Like say you knew you were in quadrant 3

#

And you did cosine inverse

#

You know that it only thinks that you’re in quadrant 1 or 2

#

So whatever output value it gives you, just add the appropriate angle to rotate it to quadrant 3

runic garden
#

still no clue sorry

#

im doing an online class and im looking thru the content right now

#

I think its missing some of the stuff you're talking about

#

so I will reteach myself the content with youtube

#

sorry about that

royal loom
#

Well when you look at cos(theta)=-.3178

#

Taking the cosine inverse of both sides

#

theta = cos^(-1)(-.3178)

#

But you have to be careful because, cosine inverse has a restriction, and you might have to adjust the result

#

That was my point

runic garden
#

thank you

toxic totem
#

can you only solve this through inverse cos?

#

is there not another way??

royal loom
#

If it’s a value on the unit circle

#

But it doesn’t look like something I’m familiar with atleast

toxic totem
#

well too bad

cedar kilnBOT
#

@runic garden Has your question been resolved?

#
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#
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oblique prawn
cedar kilnBOT
oblique prawn
#

why is it not -2

#

1/(0-1)-1/(2-1)=-2

toxic totem
#

why would it be

oblique prawn
#

the integral = -1/(x-1)

#

when u evaluate from 0 to 2 u get -2

violet flume
#

,w Integrate[ 1 / (x^2 - 2*x + k ), {x,0,2} ]

oblique prawn
oblique prawn
violet flume
#

yes it does

oblique prawn
#

oh idk then

wraith daggerBOT
violet flume
#

wolfram gimme a fuckin break come on

oblique prawn
#

,w integrate 1/(x²-2x+k)

oblique prawn
oblique prawn
#

bruh when k=1 this is undefined

#

why tho

violet flume
#

man my fucking internet im going to lose my mind

violet flume
#

,w complete the square x^2-2x+k

violet flume
#

,w integrate (k + (x-1)^2 - 1 )^(-1)

#

prolly say the same

violet flume
#

either way,

#

,w integrate (x^2 -2x+1)^(-1)

violet flume
#

this is the problem

oblique prawn
#

ye

violet flume
#

so just use this

oblique prawn
#

you get -2 tho

#

the answer is ∞

violet flume
#

maybe they want you to take the limit of the general integrand

oblique prawn
#

look

#

,w integrate 1/(x²-2x+1) from 0 to 2

violet flume
#

right

#

because it has an asymptote at x=1

oblique prawn
#

OHHHH

#

wait do u have to like factor

#

1/(x-1)²

violet flume
#

1s

#

woah oooh i got an all-letter share link

#

stachcmmip

#

,w integrate (x-2x-1/2)^(-1)

violet flume
#

hmm looks like its non-convergent from at least k=1 to k=0

oblique prawn
#

ye ty

#

.close

cedar kilnBOT
#
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cedar kilnBOT
#
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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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marble ermine
#

Hello, if A is a commutative ring and rad(A) is the set of niplotent elements of A, how can I discribe the nilpotent elements of A/rad(A)?

mental trail
#

if a is a nilpotent element of A/rad(A), that means that there exists some x in A, cl(x) = a, and x^m is in rad(A) for some m...

marble ermine
#

yes