help-13

[bleak viper]

what

[crimson sedge]

how is it increasing here

[crimson sedge]

wut

[bleak viper]

i have the same question as you

[crimson sedge]

this is a calc bc test no way the scoring guidelines are wrong

[bleak viper]

how did the interval convert into close bracket from open bracket

nvm

its right

[crimson sedge]

what

[crimson sedge]

wait what

[bleak viper]

nvm its not

or is it

what

im confused

[crimson sedge]

wrong graph?

[bleak viper]

oh yeah its correct because for f(x-) to be increasing f(x-) < f(x)

so f(x) is also included

as fai said

[crimson sedge]

oh so the logic is that

the thing after it is smaller

wait no what

bruh i'mma kms

[crimson sedge]

it isnt.

[crimson sedge]

but it is

[crimson sedge]

it isnt

they have the answer as open bracquet

yea

it isnt increasing at {-2}

so then why not do ) instead of ]

[bleak viper]

its increasing from [-2 to -6]

[crimson sedge]

aaaaaaa

i am talking about f' graph

[crimson sedge]

why

f is increasing when f'(x) is > 0 no

[crimson sedge]

fx is increasing at -2

but the graph you sent, isnt.

[bleak viper]

oh the graph is f'

[crimson sedge]

yup

[bleak viper]

i thought it was f

smh

[crimson sedge]

nvm

[crimson sedge]

how is f(-2) increasing if f'(-2) = 0

you mean f(-2)?

😵‍💫

[bleak viper]

its not

i was thinking the graph is of f

[crimson sedge]

ya

bcz f(-2 +h) > (f-2)

i just realized i am using h

you understand what h means right?

[bleak viper]

but the graph is of f'(x)

[crimson sedge]

yea

[bleak viper]

if f'(x) = 0 its not increasing

[crimson sedge]

sure some really small value

[bleak viper]

and f'(x) at -2 is 0

so not increasing at -2

[crimson sedge]

h tends to zero

[crimson sedge]

how can that be

wait

f(-2) would be like a max

[bleak viper]

now im confused too

[crimson sedge]

i'm going to be really pissed if i miss a mark on the exam because of this bullshit

[bleak viper]

💀

[crimson sedge]

bro cn u help

i'm really clueless on this

i going to grab the rope

you are indeed right

my bad

i thought -2 was an end point

wait so scoring guideline is wrong

yup

bruh literally hundreds of thousands of people have used that scoring guideline how is college board still choking

clowboard

[crimson sedge]

well thanks for your time

i hope all this confusion disappears when i start my maths degree

.close

lmao

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[subtle hinge]

it is given that f(x,y) = f(2x+2y, 2y-2x)
and g(x) = f(2^x,0)

[subtle hinge]

is it possible to find g(x) or f(x,y) explicitly

[mighty shuttle]

f(x,y) is a function in two variables ?

let u=2x+2y, t=2x-2y may help

[subtle hinge]

yea

[subtle hinge]

ig u will get back the same thing again but in tersm of u and t

[mighty shuttle]

hmm

what's the OG question?

[subtle hinge]

the original question is much simpler, it was to find the periodicity of g(x) whch can be done without findind the functions but i want to see how the functions look

<@&286206848099549185>

[mighty shuttle]

I'm not too sure

sorry

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[half nexus]

A biologist is studying the growth of a particular species of algae. She writes the following equation to show the radius of the algae, f(d), in mm, after d days:

f(d) = 11(1.01)d

Part A: When the biologist concluded her study, the radius of the algae was approximately 11.79 mm. What is a reasonable domain to plot the growth function? (4 points)

Part B: What does the y-intercept of the graph of the function f(d) represent? (2 points)

Part C: What is the average rate of change of the function f(d) from d = 2 to d = 7, and what does it represent? (4 points)

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[odd beacon]

hi so im supposed to find the algebraic expression to describe this sequence when i looked at the answers it says its 6 - n?? and i dont understand how it is that answer

[livid hound]

are you sure its saying 6-n?

[odd beacon]

yes

the answers are below

[livid hound]

provided answer is wrong

[odd beacon]

thats what i thought

is it wait

[livid hound]

were you able to get something else?

[odd beacon]

yes

8-n

[livid hound]

yes

[odd beacon]

okay thanks!

.close

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[gray wedge]

Im not sure how to go about question 2. Ik i need to use the formula for sd grouped data but i dont want to start making calculations w this amount of data b4 getting into it

wait not sd, mean formula

[cedar kiln]

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[gray wedge]

.close

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[long mauve]

please help me understand how do I draw the graph for this, there's something I'm clearly missing because I don't get it at all

[crimson sedge]

first one is quad

waht

im so dmb

[long mauve]

this is the closest I've gotten to the real answer of the graph for x^2-x

[crimson sedge]

wa

2 isnt a

[proud arrow]

draw the graph for x^2-x in the interval [0,2]

then

[crimson sedge]

root of x2 - x

[proud arrow]

draw the graph of x-1 in the interval (2,4]

[livid hound]

intercepts are already wrong
doesn't look symmetrical either

[long mauve]

isn't that what I did here? @proud arrow

[crimson sedge]

no..

[proud arrow]

0 to 2 is right

from that point draw x-1

line

like for 3 outputs 2

for 4 its 3

[long mauve]

but that's not right

[crimson sedge]

how is 0 to 2 right...

[proud arrow]

huh

[crimson sedge]

the graph in [0,2] should be of "x^2 - x

[proud arrow]

how is it wrong

x(x-2)

oh

[crimson sedge]

bcz that graph has 2 as a root

yup lmao

[proud arrow]

wait so its correct?

[long mauve]

this is the correct graph, I don't get how am I supposed to get to that

[crimson sedge]

x(x-1)

[proud arrow]

oh shit mb im misreading all the time

sorry

sorry

sorry

[crimson sedge]

you're alr

[proud arrow]

make it till 2

and then use x-1 graph for values after 2 to 4

[long mauve]

?

[livid hound]

have you ever made graphs of parabolas before?

[long mauve]

this is my first

[livid hound]

have you ever graphed anything before

[long mauve]

for some reason it's the first exercise for drawing a graph of a parabola in my schoolbook

[livid hound]

i'd recommend first watching a guide to graphing parabolas

if you don't know what something is supposed to look like,
making a table of values is a good idea
here, key components of your graph of y=x^2-x
would be intercepts, axis of symmetry

[cedar kiln]

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[dull cedar]

Is this right

Should it be -8

Or 8

[cedar kiln]

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[woeful spruce]

I’m confused why are the options all inequalities?

[obtuse shale]

How will you solve (x)(x+10(x+2)(x+3)(x+4)=(x+5)

[cedar kiln]

@woeful spruce Has your question been resolved?

[woeful spruce]

.close

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[median hedge]

How would I solve this

[median hedge]

Sorry I didn’t see you typing other guy

[median hedge]

I know the area is 1/2ab but i’m not sure how to get the other sides

[tight whale]

theres a formula side of ((larger)/side of (smaller) )^2 = area of larger/ area of smaller

so it will be (6/2)^2

which is 9 = area of larger / 5

a = 45

[median hedge]

I’m not understanding this part it might be because i’m on mobile so it looks compressed but wym with ((larger)/side of (smaller))

[tight whale]

do uk the formulas for similarity

[median hedge]

Nope but i can google

[tight whale]

should i dm?

[median hedge]

Yea you can

.close

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[tight whale]

add me as a friend @median hedge

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[gleaming juniper]

Can you check my school project?

[gleaming juniper]

Like

[hollow totem]

Just send it

[gleaming juniper]

Ill send you the guidelines and my project and you make sure I did everything right, cuz I feel like I did but Im worried

oh ok my bad

one sec

The guidelines ^

My project ^

Idk why it sent like that...It wouldnt lemme just copy paste idk

Gotta expand my conclusion tho

[hollow totem]

I see some problem with ur project

Lowkey u cant define what is "too much TV"

In a sense by claiming:

"So to turn my original claim into a mathemtical statement lets says my idea of too much TV per week is 20 hours."

Anyone can p-hacking the "too much tv" as any number so the p-value will be exactly what they want

Everything else looks correct

[gleaming juniper]

So I should say like "The claim id like is people watch about 20 hours of tv a week on average?"

[hollow totem]

You shouldn't claim that

You should claim "The average people watch .... hour of TV per week"

In your case 20

Then using statistic to either confirm or disclaim the original statement

[gleaming juniper]

ohhhh

So it should be like a statement not like a guess

[hollow totem]

Yep

[gleaming juniper]

Even its a lie and we know it but alright

[hollow totem]

Yep

Thats the point of statistic

In a sense, your claim should be quantative? Dont use "too much" or "too little", use a number instead

[gleaming juniper]

right right ok I got you

[hollow totem]

👍

[gleaming juniper]

Wait thats all that was wrong with my project?

[hollow totem]

Unless u made any mistake with the calculation

The overall structure looks okay-ish

[gleaming juniper]

okay-ish? 😭

[hollow totem]

yeah

There's tons of problem with it if its for a Probablity and Statistic college level course

[gleaming juniper]

...

It issssss tho

[hollow totem]

Is it..? 💀

[hollow totem]

LMAO

[gleaming juniper]

https://tenor.com/view/dead-sad-pouting-rain-overdramatic-gif-5377165

Whats wrong with it? 😭 ACK

[hollow totem]

The pool of data is too "small"?

[gleaming juniper]

She said we needed minimum 30 so I did 30

I choose not to do more work

[hollow totem]

Hmm

Maybe that's be alright

95% of confidence seems okay

[gleaming juniper]

👀 Where you get 95% at? cuz I thought I put like...5%

[hollow totem]

...

significance level + confidence = 100%

[gleaming juniper]

..........where...where you get confidence at? 😭

[hollow totem]

So if u consider 95% confidence level with the statistic, the significance = 100 -95 = 5%

[gleaming juniper]

ooooh true true ok I got you

[hollow totem]

Well

Assume all the calculation is correct, and the sample size of 30 is okay-ish, I think its good to go

Although

Maybe

nvm

[snow yacht]

help pls

[gleaming juniper]

Wait no finish?

[snow yacht]

i need S.A

[gleaming juniper]

get outtttttt my chat room Ive come here 3 times this is the first time ive been helped immediately

[snow yacht]

huhh

[gleaming juniper]

The rest of the time I gotta wait like 7 hours

open your own room please

[snow yacht]

i just needed help

[gleaming juniper]

#help-6

[hollow totem]

If i recall correctly, there's a least amount of sample size to use certain confidence level to claim "the average ...."

but if ur teacher said its okay for 30 sample thats probably fine

[gleaming juniper]

Oh ok, then ill just say "The average of our sample" and play it safe or no?

[hollow totem]

Sound lame LMAO

Use average people

[gleaming juniper]

ACK

[hollow totem]

For my course, our sample size is 8000 -ish 💀

[gleaming juniper]

8000?!!!!!!!?!??!?!?!?

[hollow totem]

And our claim is for the city alone

[hollow totem]

Yeah, its ANOVA

[gleaming juniper]

How yall question 8k people? 😭

8k is insane

[hollow totem]

Cars

[gleaming juniper]

🧍

[hollow totem]

We claimed "There's a significant relation between the purchase of EV and the density of EV charger"

[gleaming juniper]

ooooooo that kinda eats

[hollow totem]

WE ATE LMAO

Get a 9.5 out of 10 for that project

[gleaming juniper]

LUCKY 😭 Im hoping for bout a 75% all I ask

[hollow totem]

Give it a better structure?

[gleaming juniper]

Wym?

[hollow totem]

Like first section, second section etc

[gleaming juniper]

OH dont worry bout that too much, Imma put it on prezi so it should be pretty right now its just in my stickynote

[hollow totem]

Well good luck

[gleaming juniper]

Alright, If you think its good Im all set then

Thank yoooooou

Byeeeeee

What? 😭

.close

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[young copper]

graphically i can determine the limit is zero... how do i do this (algebraically?)

[brisk dirge]

Divide the numerator and denominator by 7^n

[royal loom]

multiply top and bottom by 1/(3^n)

[brisk dirge]

(3/7) is a number smaller than 1 so when it's raised to infinite power it'll be zero

[misty dome]

hi

i want to lern math

can you?

[brisk dirge]

You can only ask individual questions here, and create your own help channel

!help

[cedar kiln]

To ask for mathematics help on this server, please open your own help channel or help thread. See #❓how-to-get-help for instructions.

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[round ledge]

i have a question about quadratic function transformation

[cedar kiln]

Please don't occupy multiple help channels.

[round ledge]

i

basically we know that 2f(x) means a vertical stretch by 2

and f(2x) means a horizontal strectch by 1/2

[ashen shard]

f(2x) is a horizontal strech of 1/2

[round ledge]

however when in a vertex form : a(x-b)^2+c a determines the strecth

but is it vertical or horizontal stretch ?

[ashen shard]

it is a mix of both

[round ledge]

for example on this exercise they ask us to name the transformations

in this case a = -2 so should i say vertical strecth by 2 or horizontal ?

[ashen shard]

you can probably get away with just saying a stretch

[round ledge]

lmfao

i could

get half the points lol

[ashen shard]

idk what to say

because changing the a-value wont result in a purely vertical or a purely horizontal stretch

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[lavish ridge]

hello

[lavish ridge]

i am trying to run some values(in mathematica) in the zeta function which are quite big, and i am getting an underflow,

is there a fix for this?

[dawn junco]

well maybe the values are just too damn small

could you show a screenshot of the error?

(with the offending code)

[dawn junco]

N is Zeta ?

and what's %17 here ?

[dawn junco]

unless there's a way to increase the precision of floating point numbers in mathematica, you're screwed

[lavish ridge]

n is like a function ig that returns a numerical vlaue

[dawn junco]

ah ok

and %17 contains your zeta value ig

[lavish ridge]

yea

can i like choose a precision

and run the thing

[dawn junco]

so it's a closed form value in %17 ?

[lavish ridge]

yea

wait i think i know whats the issue

i need to change the precision

right

[dawn junco]

there's a setprecision command

yea

[lavish ridge]

thank u

.closed

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[dawn junco]

.reopen

[cedar kiln]

✅

[dawn junco]

I want to see the result lol

@lavish ridge

[cedar kiln]

@lavish ridge Has your question been resolved?

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[vital wasp]

Could someone explain why getting the antiderivative of B results in negative?

[vital wasp]

this is question C

I just get ln(100-B) and not negative

[crimson sedge]

Why the ln part is negative?

[mellow relic]

chain rule

[vital wasp]

yeah

[mellow relic]

that's literally their question lol

[crimson sedge]

Nvm

[mellow relic]

what would the derivative of -ln|100-B| be

[vital wasp]

uhm

derivative of ln is 1/x

[south hemlock]

take u=100-B

[vital wasp]

-1/(100-B)?

[mellow relic]

actually yeah u sub might make it easier to understand

[mellow relic]

you forgot to apply the chain rule

[vital wasp]

oh wait chain rule

[mellow relic]

mhm

[vital wasp]

forgot there's chainrule for antiderivative

[south hemlock]

saying chain rule is making it complicated, but its faster means of understanding

[vital wasp]

i forgot how chain rule for antiderivative works :/

it's like

opposite of derivative

[mellow relic]

yeah sometimes you just need to take the derivative of your guessed antiderivative and check if it works

[vital wasp]

so it's like 1/b in (bx)

[mellow relic]

this is probably the easiest way to think about, that way you don't need to try to do chain rule for the antiderivative

[vital wasp]

hum ok

thanks for the help guys

.close

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[stiff zodiac]

I was given a topic for reporting in statistics, and it said that it is all about "factoring DOE with a factor and a blocking variable". can i have a rundown of the said topic?

[cedar kiln]

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[stiff zodiac]

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[long veldt]

is my sketch and bounds right for my integral

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[patent venture]

any topology help?

prove that the set of n x n matrices with integer entries is a closed, discrete subspace of n x n mats with real entries (given standard topology)

[patent venture]

not sure where to begin

(please ping / reply)

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[crimson sedge]

how to get help?

[proud arrow]

just post your question

[crimson sedge]

my question is how to get help?
(not in this server, but how to get mathematical help in general)

[weak otter]

name checks out

[weak otter]

google, youtube

[proud arrow]

are people below 12 allowed on discord

🙏

[crimson sedge]

xd

"can kids play 18+ games?"
there you got the answer

[proud arrow]

In the United States, the average age of a 6th grader is typically between 11-12 years old.
In the UK, the average age of a Year 6 student is typically between 10-11 years old.
In Australia, the average age of a Year 6 student is typically between 11-12 years old.
In Japan, the average age of a 6th grader is typically around 11-12 years old.

[crimson sedge]

any ways who cares

[slate lintel]

gone

[crimson sedge]

can you drop help , or should I continue my search?

[proud arrow]

ah

what help

do you require

[crimson sedge]

I stated my answer

how can i get help?

[proud arrow]

in maths?

[crimson sedge]

in mathematics

yeah sure

[proud arrow]

search the question up in google

or ask here

#❓how-to-get-help

you may aswell try books that suit you for practice

[crimson sedge]

I will check that channel , I will come to tell if the information was satisfactory

[proud arrow]

or youtube videos

[crimson sedge]

what is the final advice if that does not work?

[proud arrow]

move on and retry some other day

[crimson sedge]

I have no so much time to wait other year for help

where could i go to search for more advice for help?

.close

[cedar kiln]

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[proud arrow]

you donthave to wait

1 year

[proud arrow]

ask here, ask google, ask a teacher, review a book or a video

[crimson sedge]

I am gonna try , but I will look for a more powerful help technique
and when I find it, I will have all the help I need.
xD

[cedar kiln]

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[sage timber]

hey!

[sage timber]

For any pair of functions f(n), g(n), if f(n) = Ωg(n) , then log f(n) = Ω log(g(n)) . i know its false logically but

whats a counterexample i could use??

also this is cs math so if im in the wrong place! sorry!

basically this question kind of boils down to if i take the limit of f/g i should get infinity/positive constant and for the limit of log f / log g i should get a 0

i've been like dying trying to find a function and simply have hit a wall

<@&286206848099549185> sorry for the ping!

[weak otter]

You’re too nice

Closest I can come up with is x^2/x

Limits to infinity but log version limits to 2

[sage timber]

yeah since it's a positive constant that means it goes into the former case of being in omega sadly

thank u for the help tho!

[weak otter]

Don’t know omega notation

Best I can do 🤷‍♂️gl

[sage timber]

fair enough! no worries! thanks!

do i close this chat then?

[weak otter]

Someone that knows could come around

Most people are asleep now though

[proud arrow]

what does omega do

[sage timber]

so basically the definition of
f(n)=Ω(g(n)), implies that f(n) grows at least as fast as g(n) for large n.

which means that i need to prove that f grows as fast as g while log f doesnt grow as fast as log g

[proud arrow]

by word "growing" can i assume it means rate of change

of that function

[sage timber]

yep

[proud arrow]

so then differentiation should work..

[sage timber]

wait i might have given u wrong information. growing more of means how quickly or slowly a function increases based on the input value

[proud arrow]

can i assume f(n) = n^2 and g(n) = n^3

[sage timber]

yeah

we can use any functions even constants

[proud arrow]

so if i take both of them to be constant functions

they do not grow at all

for any value of n

[sage timber]

we cant use n^2 though because n^2 grows slower than n^3 and we need f to grow atleast as fast as g

[proud arrow]

ohh okay

then can i assume them to be x^2 and 2x^2

[sage timber]

but log of both of them is essentially 2 log n so we'd be back to square one again

[proud arrow]

in this, by f(n) = omega(g(n)) you mean f(n) = growth-rate of g(n)?

[proud arrow]

right

[sage timber]

f(n) >= c.g(n)

where c >0

[proud arrow]

c is constant?

[sage timber]

yep

[cedar kiln]

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[worldly bluff]

Ive completed part a and b

a) y=-1/2+11/2

b) B(1, -5)

im struggling with C

so far ive gotton C(2, 4) as my answer

textbook says the answer is C(2, 7)

wait

.close

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[bronze phoenix]

how come we don't use t=-4 when integrating this?

is it because it's negative?

like shouldn't it be like this essentially?

[plain ridge]

what's the whole question

[cedar kiln]

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[surreal wind]

Need some desperate help w this for a grade

[blissful gale]

Think of the general exponential formula

And then choose data to find the parameters

[surreal wind]

Im really not sure since I was absent during these lessons because I was sick and this assignment is late and I have to turn it in for a grade

[nova snow]

is dis a test?

[surreal wind]

No

Delta Math

Past homework

[rigid lava]

there's a watch video and show examples button so unlikely

[blissful gale]

$Ae^{a t} + C$

[wraith dagger]

ScarletPizza

[blissful gale]

Try use this to get the missing values

[surreal wind]

im lost

[blissful gale]

So at t=0. What should the value be

[surreal wind]

101

[blissful gale]

Yep so use the formula to make it 101 at t=0

[surreal wind]

would

182(3)+101 be equal to the bacteria at 16 hours?

[blissful gale]

I'm not sure. But it should be related to an exponential

[surreal wind]

i rly gotta get this done and i have no idea how to do this

[blissful gale]

So at t=0 we have $A = 101$

[wraith dagger]

ScarletPizza

[surreal wind]

i understand that

[blissful gale]

Now keep that and plug in t=1

To get the exponential part

[surreal wind]

u have to use t= in the equation?

[blissful gale]

You need t=1

So you'd get $101e^{a} = 109$

[wraith dagger]

ScarletPizza

[blissful gale]

Then solve for a

[surreal wind]

how would I solve for a?

[blissful gale]

Take the log

[surreal wind]

the lok is the 101e part?

Log

[blissful gale]

Do you know how to take logarithms?

[surreal wind]

Im lost in math rn I missed alot of school from bein sick

alot of absences

[blissful gale]

Ah okay

So log is the inverse to the exponential

[surreal wind]

so it wld be negative?

Or opposite

[blissful gale]

I'll write it down

[surreal wind]

ty man

[blissful gale]

There's some of it

[surreal wind]

ty for writing that down just confusing for me since math is my worst subject

[blissful gale]

Yeah no worries

You just have to make sure the points lie on the linr

Here's the working

@surreal wind

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[coral jewel]

There are 13 students from a school, in which there are 8 male 12th grade students, 3 female 12th grade students and 2 male 11th grade students. Randomly choose 3 students, calculate the probability for there are males and females, as well as 12th grade students and 11th grade students in those 3 students.

[coral jewel]

not sure how to approach this

[lyric leaf]

your information is actually exhaustive which is pretty weird for these questions lol

[coral jewel]

i actually eliminated some redundant information lol

[lyric leaf]

you should be fine approaching this with probability of something = number of occurrances / total occurrances

[coral jewel]

yeah i tried, but the problem is there are too many cases to account for

[lyric leaf]

but can you post the original quesiton, just in case? this is written in a strange form

[lyric leaf]

how do you mean

[coral jewel]

There are 13 students in a high school that has achieved Outstanding Students award, in which the 12th grade department has 8 male students and 3 female students, the 11th grade department has 2 male students. Randomly choose 3 students to give awards, calculate the probability for the roster to have both males and females, as well as both grade 12 and grade 11 students.

[lyric leaf]

that's a little different a premise since initially you just asked for P(males), P(females) and P(grade 11), P(grade 12)

[coral jewel]

i tried doing complementary counting, and i need to calculate the occurance of picking only male 12, only female 12, only male 12 and female 12, only male 12 and male 11, only female 12 and male 11

[lyric leaf]

are you familiar with probability trees

[coral jewel]

essentially its the same, i just remove the context

[lyric leaf]

you should be able to consider every case with one

[lyric leaf]

the answers will be very different

[coral jewel]

no, never heard

[lyric leaf]

lets create one then, i'll show you how they can be helpful

first, some questions for you

lets focus on male/female right now

if i picked one student of this group randomly, what is the probability they are male

that is to say, there are 13 students, 10 are male. what is the probability if i pick 1 they are male

[lyric leaf]

actually, huh, sure, i can explain it using this kind of method if you wish too

[coral jewel]

hmmm

10/13?

[lyric leaf]

do you mean out of 23

yes

10/13

[coral jewel]

typo

right

[lyric leaf]

again lets focus on the male/female problem and write our total winners like this

'MMF'
MFM'
FFM'
etc

[coral jewel]

shouldnt we also need to take account of teh grade?

[lyric leaf]

the questions are technically seperate

and we can arrive at them seperately

[coral jewel]

separate?

its all 1 question

with 1 answer only

[lyric leaf]

P(roster has both male and female) and P(roster has both 11 and 12)

oh you want the P(male and female) AND P(11 and 12)

okay thats fine

[coral jewel]

yes

[lyric leaf]

we still work these out seperately

and then use the rule that P(X AND Y) = P(X) * P(Y)

[coral jewel]

aight, so what of this here?

[lyric leaf]

you can write your total winners in this kind of form;
MMM = male male male
MMF = male male female etc

[coral jewel]

hm yes

[lyric leaf]

what you want is to find the probability that there is at least one M and at least one F

[coral jewel]

so, take P(male) * P (female)?

[lyric leaf]

not quite, that would give you the probabiltiy of choosing 2 students one after the other, one being male one being female

[coral jewel]

wait we're choosing 3 students here

so what im supposed to calculate is the probability theres at least 1 m and 1 f in those 3?

[lyric leaf]

sorry something has come up for me and i have to leave, i will leave you with this idea:

[coral jewel]

so like you said, we will need to divide cases, like MMF, MFM, FMM, FFM, FMF, MFF

[lyric leaf]

the only probabilites that dont have at least one M and oen F are

MMM and FFF

so do 1 - P(MMM)+P(FFF)

this will gives you P(Male and Female)

[coral jewel]

right, complementary counting

[lyric leaf]

do a similar result for 12 and 11

[coral jewel]

right, let me try that

[lyric leaf]

hope this helps

[coral jewel]

yeah it did

[lyric leaf]

also remember

P(MMM) is not (10/13)^3

it is 10/13 * 9/12 * 8/11

as you are removing one from the pool each time

[coral jewel]

yup

[lyric leaf]

👍

and watch out for 11th grade one

as there are only 2 11th grades so you cant do the method 1:1

[coral jewel]

right

[cedar kiln]

@coral jewel Has your question been resolved?

[cedar kiln]

@coral jewel Has your question been resolved?

[coral jewel]

yes

[cedar kiln]

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[abstract furnace]

I have a curve y=2x^3-x+2

[abstract furnace]

the gradient is 5

one set of coordinates is -1,1

how do I find out another set of coordinates this curve passes through at the gradient of 5

[void glen]

take the derivative and set it equal to 5

[abstract furnace]

Got the answer thanks

.close

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[mighty shuttle]

<@&268886789983436800> troll

[kindred venture]

this question is stupid because there are 2 correct answers

[bleak viper]

nah

theres only 1

4th one

[gloomy jungle]

well how do I solve it

[normal shore]

but 0<= 0 ?0 can be equal to 0

[bleak viper]

just check the options

lets take the a < 0 option

take any a less than 0

for example -3

[kindred venture]

a >= 1 is not incorrect

[bleak viper]

now put this in the equation

[kindred venture]

its just incomplete

[bleak viper]

but its excluding 0

which is a solution too

[kindred venture]

yes but its not incorrect. It doesnt ask which MUST be true. its just asking what satisfies the original inequality

[bleak viper]

well yeah

but you always choose the best option

also incomplete solution can also mean its wrong

[kindred venture]

agreed, doesnt mean the question isnt bad

[bleak viper]

because it doesnt include all the solutions

[kindred venture]

i agree, but the question is bad because there are 2 options that satisfy the original inequality

[normal shore]

maybe the question indeed has more than one answer

[kindred venture]

so its not incorrect to choose a>=1

[gloomy jungle]

no it only has one answer

[normal shore]

yikes

[gloomy jungle]

option 4 in the answerkey

[bleak viper]

well, lets say domain of a given function is {1,2} - {0}

in options theres 2 options {1,2} - {0} and {1,2}

you can argue {1,2} is just incomplete

[kindred venture]

both are correct

in this case the -{0} is redundant tbh

[bleak viper]

nop

the domain doesnt include zero

if u miss that when its in option

its incorrect

[kindred venture]

bro {1,2} already excludes 0

[bleak viper]

oh nvm

i tried to make a point but didnt see what i chose

my bad

[gloomy jungle]

this conversation was so funny

[kindred venture]

xD

[bleak viper]

💀

but yeah 2 options satisfy

but you choose the better option

[kindred venture]

4 is correct yeh

thats the best option

[gloomy jungle]

no no I agree with you astar but you chose such a lousy example

[kindred venture]

but i still hold a grudge against the question writer

[bleak viper]

i didnt realise {1,2} already excludes zero 💀

[gloomy jungle]

lmaooo

.close

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[dark magnet]

yo, if my original function is 1 and i have studied it, (asymptotes, extreme points, intercepts), what's the relation between the extreme point of f(x) (original) and of g(x) (transformed, 1/f(x))

[dark magnet]

.close

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[cerulean fiber]

So, let me translate: Find the radius and the convergence interval of the following powerseries.
I tried the (4) and I'm not sure if my solution is correct, sending it now.

[chrome quail]

correct

I wouldve used trhe root test, but this works too

[cerulean fiber]

They teached us to solve these kind of exercises always with the ratio test.

[chrome quail]

yeah no problem, go with whatever you're comfortable with.

[neon void]

why do you need to test this series?

[cerulean fiber]

To find where it converges

[neon void]

it's a geometric series so it converges when $|\frac{|x - 2|}{10}| < 1$

[wraith dagger]

kelsny

[neon void]

dont really need a test for this

[cerulean fiber]

I didn't tought of that, but the result is the same, isn't it?

[neon void]

yeah it is

im just saying you could go directly to the inequality by definition since it's geometric

[cerulean fiber]

Yeah correct, I didn't notice that its geometric

[neon void]

1 and 2 are also geometric

if you can write the term as r^n or a(r^n) it's geometric

[cerulean fiber]

What bothers me is that:
Basically with the ratio test we found c.
As you can see by the notes, when ρ = c |x - a| < 1, the series converges and
when ρ = c |x - a| > 1 the series diverges.
We have to test separately c*|x-a| = 1.
If c = |x| / 10, ρ = |x| |x| / 10 = x^2 / 10
x^2 < 10 when -sqrt(10) < x < sqrt(10)
and
x^2 > 10 when x > sqrt(10) and x < - sqrt(10)
????

[cedar kiln]

@cerulean fiber Has your question been resolved?

[cedar kiln]

@cerulean fiber Has your question been resolved?

[cedar kiln]

@cerulean fiber Has your question been resolved?

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[void sand]

!status

[cedar kiln]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[void sand]

1

I suppose I can say that I tried comparing to the harmonics, and to the inverse square roots, but that didn't work

I also tried converting to an integral, but came up short when I couldn't integrate it quickly lol

so now I'm back to square one, and pretty clueless as to what to do

[uncut ridge]

It's easily integrable tbf

ln(n) = t \newline
$\frac{1}{n} dn = dt$ \newline
$\int \frac{1}{1+t^2} dt$

[wraith dagger]

penguin

[void sand]

huh.

that is pretty simple...

argh lmfao

[uncut ridge]

yeah it is indeed

[void sand]

maybe I'm too scared of integration

[uncut ridge]

you'll get better with practice!

[void sand]

I never want to do any integrals after this semester ever again lol

[mighty shuttle]

Get a few books full of integrals IMO

[void sand]

no

[uncut ridge]

😭
it's fun tho, at first it's hard

[void sand]

I hate them

I would compute Jordan bases any day over integrals 😭

[uncut ridge]

I thought you were talking about the International Mathematics Olympiad (IMO) lol

[mighty shuttle]

lol

[void sand]

istg I hate calculus

[mighty shuttle]

I was going to suggest a problem book in mathematical analysis

[void sand]

I don't like real analysis either lmao

[mighty shuttle]

That's just full of integrals

[uncut ridge]

So which book do you recommend?

[mighty shuttle]

A problem book in mathematical analysis by GN berman

[uncut ridge]

Alr tysm

[void sand]

tbf I am almost done with intro analysis now

there's not really a need for me to do more

@mighty shuttle how do you do integrals without going insane

[mighty shuttle]

I took maths in 11th and 12th to study calculus

and they're fun

[autumn fox]

Just wait until you hear about this lad named Lebesgue

[void sand]

I'll do Lebesgue theory soon!

[mighty shuttle]

just use fun books

[void sand]

differential forms are first

[void sand]

also, I hate analysis

so I might postpone Lebesgue for a long time

[autumn fox]

This is just integration but waaaaaaaay more tedious

[void sand]

I'm aware lol

wait Mikkel

[autumn fox]

Waiting

[void sand]

do you have experience with diff forms stuff

is it bad

[autumn fox]

No idea

Perchance

[void sand]

aiohwfhowgnong2o4ign2oi4ng2

[autumn fox]

That translates to I have no idea what it means in my language

[void sand]

to which question

[void sand]

this one?

[void sand]

or this one?

[autumn fox]

This

[void sand]

ah

[mighty shuttle]

I could give you some nice ones

[void sand]

I don't want to do any more

[mighty shuttle]

they will be pretty elementary for you though(given that you're a 1st year student)

[autumn fox]

Just watch enough BPRP

[void sand]

bprp doesn't do anything I'm interested in

too much calculus, not enough linear algebra

[autumn fox]

Are you an engineer

[void sand]

no

[mighty shuttle]

$\int \frac{dx}{\sin^3\left(x\right)}$

[wraith dagger]

ƒ(Why am. I here)=misery

[mighty shuttle]

to start off

[autumn fox]

Okay, good

[mighty shuttle]

start off with fun problems like this

[void sand]

physicsrocks, I am not doing any more

[mighty shuttle]

and work your way up to harder ones

[void sand]

I do math and physics, if you care

[autumn fox]

Physics is fine

Engineering is immoral

[void sand]

I've started to dislike physics too though

[mighty shuttle]

nah, shouldn't have said that

[void sand]

I wanna do linear algebra for the rest of my life istg

[chrome delta]

what's the point of working through a book full of integrals

[autumn fox]

The engineers' revolution and its consequences have been a disaster for linear algebra notation

[chrome delta]

[void sand]

I see no point either

[mighty shuttle]

It's fun

[void sand]

what notation

[autumn fox]

All of it

[void sand]

hmm

[autumn fox]

Massacred by engineers since day 1

[void sand]

what notation in particular upsets you

[autumn fox]

Let the set V be a vector spa- shutupshutupshutupshutupshutup

[void sand]

I mean, I see no issues with that

most of algebra is written like that anyways

anyways, I should close this channel now

thanks everyone

.close

[cedar kiln]

Channel closed

Closed by @void sand

Use .reopen if this was a mistake.

[cedar kiln]

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[fathom star]

Ive had to ask about this before but it was doing it with polar graphs

[bright fiber]

what seems to be the problem?

[fathom star]

it should be a full circle shouldnt it?

[bright fiber]

should it?

are you sure it should?

x^2 + y^2 = 10 is a full circle

if you want to solve it for y

it becomes y = +- sqrt(10 - x^2)

what you have graphed is just +sqrt(10 - x^2)

which is the top half of the circle

you're missing the other half, which is - sqrt(10 - x^2)

x^2 + y^2 = 10 is not equivalent to y = +sqrt(10 - x^2)

[fathom star]

Is there a +- option on the calculator?

[bright fiber]

I think you just have to add it as a separate graph

since x^2 + y^2 = 10 is technically not a function

[fathom star]

alright then. Guess I can go from there

just gotta get teh solution set

.close

[cedar kiln]

Channel closed

Closed by @fathom star

Use .reopen if this was a mistake.

[fathom star]

Thanks btw

[cedar kiln]

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Remember:
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• Show your work, and if possible, explain where you are stuck.
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[wind sentinel]

I don’t understand the answer to this - how did they get the sigma notation from those set of numbers

[smoky idol]

Do you know what the sigma notation means

[wind sentinel]

Yes

[smoky idol]

Then what isn‘t clear about this equality?

[wind sentinel]

The expression

[smoky idol]

They summed up n=1, 2, 3 etc

That‘s what Sigma means

[wind sentinel]

I don’t understand how they got the expression

I know

[smoky idol]

This is highly confusing. You can‘t know how the Sigma notation works but not know how it works at the same time

[wind sentinel]

Bruh

How did they get the expression from the set of numbers

[smoky idol]

Oh, it‘s the reciprocal of all odd numbers

How do you represent odd numbers? Even + 1

And even is 2n

[smoky idol]

Sorry I was thinking the other way around, that is my bad.

[wind sentinel]

That is not what I am asking

[smoky idol]

It answers exactly this

They saw that it was the sum of the reciprocal of odd numbers

Sum = sigma, reciprocal = 1/something, odd = 2n + 1

[wind sentinel]

I am asking how from the set of numbers added did they get the expression 1/ 2n plus 1

[smoky idol]

And I told you just that

[wind sentinel]

That is not the answer I am looking for

I know the numerator they got 1 because it’s all 1 but for the demointator how is it 2n plus 1 because for an example 3 times 2 plus 1 is 7 not 5

[smoky idol]

Plug in n=2 you get 1/5

[wind sentinel]

Please stop helping me u aren’t understanding

<@&286206848099549185>

[wanton sail]

why are you multiplying by 3?

[wind sentinel]

Because that’s the first term In the demonitators

.close

[cedar kiln]

Channel closed

Closed by @wind sentinel

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[cedar kiln]

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Remember:
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• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hidden fog]

Find the number of real solutions of the equation x^2+11x-10=0 using the discriminant

[hidden fog]

<@&286206848099549185>

[cedar kiln]

Please do not ping individual helpers unprompted.

[unique valley]

!15m

[cedar kiln]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[unique valley]

i meant that

anyway

what have you tried?

[hidden fog]

nothing

i just want the answer

[unique valley]

we re here to guide you

do you know what discriminant is?

[hidden fog]

no

[unique valley]

do you know quadratic formula?

[hidden fog]

vaguely

idk how to use it

[unique valley]

learning how to use it should be first you do, before even attempting thsi question

tbh

[hidden fog]

it’s just an assignment i gotta do

[unique valley]

im not gonna help you if youre not gonna put the work in

if you want answers use google or whatever

[hidden fog]

💀

i already tried

what do i gotta do

ok i got it

[subtle gulch]

This might help

[hidden fog]

alr cool

[unique valley]

yeah use that

[hidden fog]

so now what

[unique valley]

it says in the image

[subtle gulch]

Honestly snake cant we just find D and finish it?

D>0 kinda thing?

[hidden fog]

my answer options are 1 2 3 4

[unique valley]

if you wanna finish it i let you

[subtle gulch]

See the last 3 lines in the pic I sent u

If u use that u will get the ans

[subtle gulch]

No no, i just meant do we need to use the quadratic eq or not. Sorry if it came out rude

[hidden fog]

can you walk me thru it

[subtle gulch]

Can u first name ur a, b and c?

See the pic and decide

[hidden fog]

a is x2 b is 11x and c is -10?

[subtle gulch]

No

Try again

[hidden fog]

💀

[unique valley]

i wasnt mad dont worry, we do not need to use quadratic, but its helpful to know it, to know what discriminant is and why it gives you number of sols

[subtle gulch]

Oh ok. I understand now. Thank you

[subtle gulch]

Please tally ur eq and the one in the pic

[hidden fog]

what’s my eq

[wraith dagger]

faiyrose

[hidden fog]

wth

[hidden fog]

is this not what i said?

would it be 0 then?

wth does that mean

times the exponent?

[unique valley]

x^2=1*x^2

[subtle gulch]

2a=2 wht is a?

[hidden fog]

4?

[subtle gulch]

Not to be mean but are you doing this on purpose?

[hidden fog]

💀💀💀💀

do i actually sound that dumb

i have no idea what that means

[hidden fog]

oh it’s 2

oh ok

in this instance x is 2

💀

[median lantern]

2a = 2 divide both sides by 2, a = 1

[hidden fog]

oh

1

oh gotchu

[median lantern]

$\sqrt{b^2 - 4ac}$

[wraith dagger]

w