#help-13
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open a new one
wheres the sqrt
umm you raised to the power of 2 kinda incorrectly i think. before doing so you should get the sqrt3/3 cos(x) to the other side together with the 1
shit i forgot about that
well not if you get it to the side thats what i am saying
you should leave the sqrt alone in one side
and it will just go
ok i will try that
you are asking to square both side?
yeah
nuh uh, thats gonna introduce redundant roots
what?
which you have to retest it into the original equation again
oh well yes obv
what is a redundant root
but with my approach you dont need to, in fact retesting root is less than ideal...
well idk if you get him to understand your way then sure
squaring both hand will introduce roots that is true on squared, but necessarily isnt for the original equation
like i said, this is less than ideal, and you are FAR better off trying my approach
like when you have negative numbers?
could you explain in simpler terms
ok so can you resend the original equation
فطر
ye
1 and square of 3 / 3
فطر
ok
what is $\sqrt{a^2+b^2}$?
فطر
pythagoras theorem?
so what is this?
square root of (4/3)
so $\frac{2\sqrt3}3$
فطر
ye
now, divide each hand of your original equation with this
it will work out, trust
ok
tell me what you got
this
ye
send me what you got again
ok anyway
so the final equation is
$\cos{\frac{\pi}6}\sin x+\sin{\frac{\pi}6}\cos x= \frac{\sqrt3}2$
now
how?
can you tell me cos(?) = sqrt3/2?
pi/6
and sin(?)=1/2?
pi/6
فطر
can you apply the angle addition formula now?
sin(pi/6 + x) = square root of 3 / 2
well, not -
its because i guided you literally step by step
this is quite literally the easiest way to tackle any question in this form
i just didnt know that thing of dividing by square root of a squared plus b squared
now that you know
anyway, can you take it on from here now?
ye i can
but my teacher is way too strict with the formulas we can use
so i have to see if he will allow me to use this one
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can someone help me how to solve the quotient rule
like prove it?
here is the example
so you want to know how to apply it?
i get it a little bit but i still get confused when the given is long
or how to prove it
you can prove it with the product rule relatively easily
product rule is more derived from the limit definition of derivatives as far as im aware
this my solving idk if its right i got confused mid way
,rccw
your derivatives are wrong for u and v, and i dont like the way youve written it either
saying u=u' and v=v' is incorrect process
how is that wrong
tell me how you got 4 and 3x
ok so i got the 4 by multiplying the 2 to its x^2 and i got the 3x by applying the power rule
youre not doing either thing right
how so 😢
2x^2-4x+5 differentiated to 4x-4
by the power rule
x^3+10x^2 goes to 3x^2+20x
x^n -> nx^(n-1) remember
si
i think you should review power rule a bit more before looking at the quotient rule
wait
can u answer that one for me
dw its just an example my reviewer
not a hw or smth
,w differentiate (2x^2-4x+5)/(x^3+10x^2)
the factoring on the bottom is they factored out x from inside the bracket
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Can someone knows how to create truth table about this? Thank you
Start by drawing two columns and 4 rows for the 4 possible truth values for p and q
p q
0 0
1 0
0 1
1 1
For example
Then the other columns would be the other different statements
For example youd have one column for p <-> q implies (not p or q), another for p implies (q and p) and so on
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Yeah but how do you if its true or false ?
Wdym
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Please help me with this one
I tried a lot but can't be even close to the answers
what?
we can write directly as 9 * 11 and 3 * 4??
im doing prime factors
12=2^2 * (3) and 99 is 3^2*11
so a and b need to have 3 and 11 as factors
not both, just either or
then again it wouldnt matter
if 12ab has the prime factorisation of 99 as a factor, then it is a multiple of 99
is what im getting at
ah
like it means 99 * something = 12ab
okkk
there is one more
i know like y will be odd
y = (763 - 2x)/3
by this
why is that odd
see
wait
sorry y = positive
oh, i got it
Can you plot root over root n on number line?
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this question is from the topic differentiability....Can sm1 help me understand this question ..and help me solve this question.....
this is really not readable at all but you can find dy/dx by noting dy/dx = (dy/dt) / (dx/dt)
and then find d^2y/dx^2 by differentiating that again
yeah so use this
what have you tried?
you have $\frac{dx}{dt} = ap \cos pt$ for example
OssihLikesBlue
you can similarly find $\frac{dy}{dt}$ and then $\frac{dy}{dx} = \frac{\frac{dy}{dt}}{\frac{dx}{dt}}$ and then differentiate that with respect to $x$ to get $\frac{d^2y}{dx^2}$
OssihLikesBlue
@sweet badger
ohh ....Thank you
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need help with e)
my answer is -16/21
but in my answer key its -16/63
but I double checked and all my steps look correct
show your work
ok
what did you get for tan x and tan y
how were you cancelling in an addition?
'simplifying 3 with -12' is something you do with multiplication, not addition
for addition, you put everything on the same denominator
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How can i show this limit
Maybe using lhopitals?
@crimson sedge Has your question been resolved?
<@&286206848099549185>
maybe idk try make the fractions like fractions and then lhopitals
but idk where that would lead
The denominator stays 0
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Hi can sm1 explain the approach to this problem?
like let's say I pick a chairperson from the committee
well then there would be n choices
and then out of the (n-1) ppl, i make a comittee of any size
why would it be 2^(n-1)?
on the left hand side, if I pick k ppl to form a committe from an n large group, then the number of ways to pick those k ppl would be nCk
and then from those k ppl I chose a chairperson, there would be k choices to pick a chairperson
but then why is there a summation sign on the left?
<@&286206848099549185>
<@&286206848099549185>
For the remaining (n-1) people there's 2 choices of whether they're included or not so 2^(n-1)
For the summation the committee size can range from 1 to n
So you account for committees of all possible sizes
From k=1 to n
OHHHH
cuz u want to dtermine the total possible
number of ways
but k can go from 1 to n
so u need to sum over to get the total possible
ok ok
aight thank u
👍
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Please help
what do you have for a definition of prism?
Opposite sides are equal and cross section is constant
C d e was my first thought
so which objects meet that definition, or which can you exclude because they fail?
are the cross sections of C constant?
If it was rotated yes but in this form no
But for my answer I put d and e but it said I was wrong
apply that reasoning to A
Also, because one face of C is larger than the back face, if you cut it perpendicularly (which you should be doing) the cross sections won't be constant
C is the bottom part of a very tall, narrow square pyramid.
so it is not a prism.
Would this be the final answer?
yes
Idk what to do now
Same
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????
do you know about Riemann sums?
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how would i go about solving this? i dont know where I went wrong because i followed the accompanying video
Use the power series formula
f^n(a)(x-a)^n/n!
Then find the pattern with that
Then the interval of convergence is found by taking lim n—> inf a(n+1)/a(n)
(what may help more is if you can relate the original function to something that's "close enough" to something you know the power series for, then use that...)
this the formula?
is that even practical for this function?
which fuynction
no this is the formula
$\sum_{n=0}^{\infty} ax^n = \frac{a}{1-x}$
Triaxyz
-1<x<1
i mean if he doesnt know the formula for power series
why would he use the fast way
to use substitution and such
u havew to understand the mechanismns
to an extent
for substitution
(also if you know this, you know the power series for related functions, such as 1/(1 + x) and ln(1 + x)
)
because taylor series expansion is unnecessarily complicated for a function like this
yea i havent learned taylor series yet
i think for someone who doesnt know the formula
the fast way
is dumb
yes then learn the formula
haha
dont do substituion stuff yet
do it 3 times then just find the pattern and eventually learn
the subsitution
stuff
@orchid valley
yeah taylor series is literally the last thing in my class lol
you already did polar/parametric?
then dw about doing taylors if you havent covered it
you know geometric series yes?
yes
zhats literally all you need then
try turning your function into the right hand side of this format
i got
,w x / (15x^2 + 1) = (x/15)*(1 / (1-(- x ^2 / 15)))
1sec
they are not the same
when you distirbute this, you get $\frac{x}{15+x^2}$ which is not f(x)
Triaxyz
ah thats true
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how do i find irc of this
instantaneus rate of change
You can use the quotient rule to find the derivative here
instantaneous rate of change is just the derivative of the function i believe
Yeah that works too
But you're missing a minus sign in between
oh yesyes
like what do i do with this
( f(v+h) - f(v) )/ h
yea
f(v+h) is adding h to v, not adding h to f(v)
suppose it was easier and f(v) = 1/v
what do i change
what would f(v+h) be?
That would be f(v)+h
so where do i add h
to v
Well yes, f(v+h) is evaluating the function f at the number (v+h), which is a different number than (v)
For example, if $f(x) = \frac1x$, then $f(x+h)=\frac{1}{x+h}$
π=√g
Almost, why is there v^2 + h in the bottom?
like rhis?
You're adding h to v, not v^2 remember
(and you have to put parentheses for the numerator)
like this?
$$\frac{1600 (v+h)}{(v+h)^2 + 6400}$$
π=√g
Yeah, add to v
why r we squaring h
Basically replace all the v with v+h
so like this
Yeah but good luck working with that
eevbecrvr
Are you sure you need to use limits to prove this?
yes
Ok well, expand the square, then put both fractions on the same denominator, add the terms in the numerator, and simplify
then
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Hello! I'm trying to figure out how to isolate y" in this diffeq. I've used the langmuir-blodgett relation for the e^x but im quite stuck on the rest. I can't use numerical methods, and must do it algebraically
I would be happy to clarify the problem if the handwriting is unclear
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pls help with how to start this related rates
Do you know the formula for volume of a cube
Relate the sides to volume by using side lengths
A = side * length
Volume*
ok
So if volume = side * length
And the equation for a side is x^2
Then try to get surface area
In that equation
Ok
sorry I am still a bit lost
V=x^3
Surface area = 6x^2
Solve for x^2
Plug into volume
Perhaps that will help
but I need to take the derviative
when do I do that
When you relate the two
U can derive volume of cube formula
then plug in what u know
dv / dt = 3s^2 ds/dt
sides are 10, dv is 20
Find ds/dt by deriving S = 6x^2
Would u also be able to find it deriving volume?
Ahh ok so ds/dt = 12x
We need to be careful here
Dv/dt = side length ^2 dsidelength/dt
And Dsyrface area/dt = 12x dx/dt
if you call both s you will confuse urself
Make the lengths a variable
And make the surface area a different variable
Wait whatd u get as an answer
cause when i did it i got 8
lmk what u get
i got 8
Whats happening here?
All the substitution
i see
i did it like this. v=x^3. dv/dt = 3x^2(dx/dt) I solve for dx/dt. then I differintate surface area = 6x^2/ so we get ds/dt = 12x(dx/dt) I subsisute the value of dx/dt and the value of x = 10
Related rates is all about finding equations that relate the two
Things
That are changing
With respect to eachother
@crimson sedge @acoustic quartz thank you for the help
now I got it
No worries
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!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
System of equations
Or quite frankly
The easiest way to do this problem with a calc
Is exponential regression
Do two points define a unique exponential?
can we get of b^-2 by multiple b^-1 on both side
?
Wat about y = ab^cx?
Okay
Why not?
...
U can also do y = ab^cx +d?
Bro
Why tho
Why not just make it in the form of a x b^x
It’s whole numbers
If you do that way
a and b are both whole numbers
Because idk if two points will uniquely define an exponential function
Find a formula
The questions says
Keep it simple.
@final hornet
What have you tried?
Sorry I got a bit distracted with the dicussion
No worries
We still need to figure out the uniqueness
All due respect the problem isn’t asking anything about that
Oh so any random exponential function that satisfy both points will work?
If you add plus c youll get all of the possible equations
Cuz youll have theree variable and two equations right?
Man just find the simplest equation
It also says "open response"
They want the student to talk about all the possible functions
Bro 😭
So could we remove b^-2 with * b^2?
nah I wouldn’t do that
Easiest way
Divide the top of an bottom
So you have 128/.125= a/a x b^5
1024
b^5
b=4
128= a x 4^3
128=64a
a =2 , b=4
Sorry I have to go soon
So I just told you the answer but
f(x)=2(4)^x
Have fun and go solve that yourself
Bruhh, its the proper solution
Not the proper solution
It says find a formula
Standard form of an exponential
Is y= a(b)^x
U are forgetting about the other solutions
Ok go and find these other solutions and report back to me
I’m going to find the easiest solution
Because the problem asks for one solution
Bro you are getting on my nerve 😭
Just for education try to find the general solution
Read
Ye have fun with that
@sly abyss Ty I try your method
There no way u a mathematician
@sly abyss Should I leave this open or close?
You can close
I’m not at all
But i just try to help in an easy way
U should at least tell that its not unique
.close
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Ok so
Try factorizing the numerator in the first parenthesis
And the denominator in the second parenthesis
Result should be -4 I think
(x+2)(x-2) difference of two squares
3(x-2)
great thanks
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Hi, I have a question about vector functions.
Why is derivative of speed d|v(t)|/dt not equal to magnitude of acceleration |a(t)|?
just like speed is distance/time shouldn't magnitude of acceleration be speed/time?
e.g when solving for min/max speeds setting d|v(t)|/dt = 0 would solve for t value where min/max occurs but why cant you just set |a(t)| = 0 to solve for t
when i tried doing this, i got difference answers
you can have a nonzero acceleration when the speed isn't changing, because acceleration can change direction as well as speed
e.g. if an object is moving in a circle at constant speed it has a constant nonzero magnitude of acceleration (to change direction), but its speed is constant, so the derivative of speed is 0
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hello
merp
need help
a family have 5 childrens. the oldest age 2 times the youngest, while 3 others age less 3 years from the oldest, 4 more years then the youngest, and less 5 years from the oldest. If the average of their age is 16 years, so the quadrat of difference between 2nd child and 3rd child is:
sorry if bad translate
so my answer is:
please ping!
what happened?
uhhhh
one more e in the 3rd box should fix the rest
2e+2e-3+e-4+2e-5+e
like that?
yeah the answer allow .5...
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for the third paragraph
what does it mean for the notations?
like what is g(x) refers to?
what is the "x"?
TIA
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Hi guys, for b)ii), im struggling to algebraically manipulate it into the form.
Comparing coefficients, -(1 + i) = -1 - i is z0
And indeed the conjugate of z0 is -1 + i = -(1 - i)
And also you can see what r^2 is from this: be careful of the minus sign
hmm
r^2 is one
wait
r^2=-1 so r=i?
ah I see, I wasn't really using part a) which made it 10x more difficult than it needed to be
wait what am i saying
r is real smh
Yep
oh what
but isn't this saying that the modulus of a point shifted is r, so r must be real?
We're in the complex plane so the radius can actually be an imaginary number
It's saying the radius is in a dimension perpendicular to the xy-plane
Like the circle will be vertical
the answers say the radius is 1, im guessing its the same thing?
Yeah so of course you have to take the modulus of i so 1
ah
This is the graph of f(z) = z^2 + 1 for when z is a complex number
We're using the 3rd dimension to represent what happens when z has an imaginary part
And y is still the output of the function
So that explains the vertical circle part
I should say the radius vector here
although
this would make the equality in a) not entirely true would it?
it would have to be |r|^2 ?
Nah so there -r^2 = 0
So r = 0
Yeah so it would just be a single point
A degenerate circle
dang circles can be degens too
Yep
So it comes naturally from the definition
You just have to ask the right questions to see what maths tells you about those weird situations
True
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Henlo, I'm kinda stuck on this question
They ask to simplify
So what are key theorems for exponents/indices?
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By rotation of axis, eliminate xy term. Identify the conic and its elements
Supposed to be a hyperbola, but i can't seem to remove X and Y terms to get that
Would like help in here
are you trying to solve the equation at the very top
Idk bro
This is the question
And the one I'm trying to solve is a part of this
<@&286206848099549185>
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when would you go from rectangular to spherical coordinates
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think of the transformations being made
first of all you have -x
which does what?
-x makes a reflection along the y axis
four units to the left
which moves it 3 units up
and that's all you need 😉
🙂
first flip, then move 4 then add 3
what would it look like if i reflected it along the y axis
yes
gladly
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5n^2 +12n+6=0
@stone tulip
@stone tulip ?
Try using Quadratic formula, rational root theorem, factorization by middle term splitting or by completing the square to find the values of n
a. RRT isn't necessary
b. factorization is just unnessary
c. CTS is tedious with this and jjust is
Forgot to dm you..
sure
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✅
ren
@hot crag ? :))
?
ye?
You told me to come back here so you could help
U do -6 to start out?
ren
uh
one sec
alr
simplify
also
one thing's wrong
you wrote -(12)^2 outside the sqrt
it's -b not -b^2
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alr
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I’m so confused on how to do this, I know log2x is x=2^y but I do not know how to multiply the -2 or add the 4. I keep getting the wrong graph.
it would be easier to come up with some points to plot and connect the dots
How though
plug in x values into the function
so let's take x=2 for example
what would -2 log_2(x) + 4 be
That’s what I been trying to do but I keep getting it wrong I did -2(2^1)+4 and it gave me the wrong answer
so log_2(x) = 1
the log_2 asks "what number do I raise 2 by to get this number"
so if u wanna do log_2(2), you're asking "what number do I raise 2 by to get 2"
the answer is 1 right
so log_2(2) = 1
(not 2^1)
yeah, you're finding the right answer but you're plugging in 2^y instead of y
don't worry about the entire function for now
what is log_2(4)
2^4? Idk
the log_2 asks "what number do I raise 2 by to get this number"
so if u wanna do log_2(4), you're asking "what number do I raise 2 by to get 4"
what is log_2(4)
2
yeah
now we have that function y = -2 log_2(x) + 4
what do you get if you plug in x=4
Ok I think I get it
Thank you that was very helpful
yeah np
I have another problem but it’s kind of different can I send it
Yes
Idk how to do that
Can you guess what the first step would be
I think that’s the number the graph almost touches
Yeah
Since for log(x); x must > 0
so x -1 must always > 0; thus x > 1
also
log base 2 also gives us a clue
as log_2(2) = 1
We can probably guess the shape of the graph to look like this
Log_2(1) is 0?
Thats too
For graphing problem, the question tends to want u to find special point/feature of the function
For this region, we can argue since the growth of the log function is extremely small, and the different of x is small too
We could just assume, the graph looks like a line
So it will look like this
Ok got it thanks 👍
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guys i need urgent help with stereometry. Im preparing for a test and started revising just fine until i run into the same problem again and again and again. The problem is about finding the distance between a point and a plain. Im struggling to understand how do i find where the intersection is, or when it is given - what to do with it. Here is one of the problems ive been stuck on.
- In a cube ABCDA1B1C1D1 point M is the center of the edge A1D1=1 and point N is from edge D1C1 such that D1N = 2C1N. Find the distance between point B1 and the plain (MBN)
I know that i need to build a triangle with the perpendicular but where and how I have no clue
heres a very messy image of what ive drawn so far (sorry its rotated)
@pulsar schooner Has your question been resolved?
i just solved a problem not too different from this but again i assumed. I needd a specific method that tells me how and why i do what i do. I will write this new problem down here and then my solve. If you can please tell me why it worked out because i have no idea what i did
2)the base of a pyramid ABCDM is the rhombus ABCDS. The outer edge (idk the english term) BM is perpendicular to the base plain. The side and the diagonal BD of the rhombus are equal to 4 and the distance from point B to the outer plain CDM is equal to the square root of 3. Find the volume of the pyramid
solution) so starting off i found the altitude of the rhombus to be equal to 2sqrt of 3. Than i built a triangle BHM with point B1 laying on HM being the point which connects the plain CDM with point B at a 90 degree angle ( a perpendicular) and H such that BH is the altitude of the rhombus. From there using pythogor's theorem i found HB1 to be equal to 3 and using equalatheral triangles (BHB1 and BHM) i found BM to be 2. Than i jsut plugged everythign in the formula for the volume.
My main concern is why did buildign triangle BHM work
what says that the altitude of the rhombus lies on the same plain as the distance between B and CDM. For me it was just intuition but i need a certain proof that i can understand and use without overthinking it
and what do i do in the case of the first question where i have no idea where to build the triangle
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Hello sorry I lost the channel I previously was on
Many apologies
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hey