#help-13

1 messages · Page 283 of 1

timid sparrow
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but i dont know whats the next step with the 2nd part

lethal jungle
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i asked first not

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bro

coral jewel
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open a new one

lethal jungle
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yeah but no one answered my question

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how do i open a new one

coral jewel
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wheres the sqrt

ruby tree
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umm you raised to the power of 2 kinda incorrectly i think. before doing so you should get the sqrt3/3 cos(x) to the other side together with the 1

timid sparrow
coral jewel
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yeah you essentially turned this into a sqrt function

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seems complicated to me

ruby tree
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you should leave the sqrt alone in one side

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and it will just go

timid sparrow
coral jewel
ruby tree
coral jewel
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nuh uh, thats gonna introduce redundant roots

coral jewel
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which you have to retest it into the original equation again

ruby tree
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oh well yes obv

timid sparrow
coral jewel
ruby tree
coral jewel
#

like i said, this is less than ideal, and you are FAR better off trying my approach

timid sparrow
timid sparrow
coral jewel
#

ok so can you resend the original equation

timid sparrow
coral jewel
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alright

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this is under a form

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$a\sin x+b\cos x=c$

wraith daggerBOT
#

فطر

coral jewel
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and theres a general formula for these type of equations

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are you following so far?

timid sparrow
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ye

coral jewel
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right

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can you identify what is a, and what is b in your question?

timid sparrow
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1 and square of 3 / 3

coral jewel
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correct

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now, divide both side by $\sqrt{a^2+b^2}$

wraith daggerBOT
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فطر

timid sparrow
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why is that

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i did not understand that part

coral jewel
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like i said, this is a formula

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how people proved it is beyond me

timid sparrow
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ok

coral jewel
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what is $\sqrt{a^2+b^2}$?

wraith daggerBOT
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فطر

timid sparrow
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pythagoras theorem?

coral jewel
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no

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im asking the result

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you got a = 1, b = sqrt3/3

coral jewel
timid sparrow
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square root of (4/3)

coral jewel
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so $\frac{2\sqrt3}3$

wraith daggerBOT
#

فطر

timid sparrow
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ye

coral jewel
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it will work out, trust

timid sparrow
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ok

coral jewel
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tell me what you got

timid sparrow
coral jewel
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can you rationalize the denominator

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that'd be easier to work with

timid sparrow
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ye

coral jewel
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send me what you got again

timid sparrow
coral jewel
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reduce it bru

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you got 3/6

timid sparrow
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1/2

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same thing

coral jewel
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ok anyway

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so the final equation is

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$\cos{\frac{\pi}6}\sin x+\sin{\frac{\pi}6}\cos x= \frac{\sqrt3}2$

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now

timid sparrow
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ye

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remove the 1/2 on both sides i assume

coral jewel
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no no no

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this is exactly what we want

timid sparrow
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how?

coral jewel
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can you tell me cos(?) = sqrt3/2?

timid sparrow
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pi/6

coral jewel
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and sin(?)=1/2?

timid sparrow
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pi/6

coral jewel
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do you see what im getting at here

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which means, this can be rewritten as

wraith daggerBOT
#

فطر

coral jewel
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can you apply the angle addition formula now?

timid sparrow
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sin(pi/6 + x) = square root of 3 / 2

coral jewel
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well, not -

timid sparrow
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ye my bad

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ok i understood that

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but isnt this too complicated

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lol

coral jewel
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its not

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its elegant

timid sparrow
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too many steps bruh

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but thank you

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do you know any easier way?

coral jewel
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its because i guided you literally step by step

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this is quite literally the easiest way to tackle any question in this form

timid sparrow
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i just didnt know that thing of dividing by square root of a squared plus b squared

coral jewel
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now that you know

coral jewel
timid sparrow
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ye i can

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but my teacher is way too strict with the formulas we can use

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so i have to see if he will allow me to use this one

coral jewel
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right, do what you must

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!done

cedar kilnBOT
#

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timid sparrow
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thank you

#

.close

cedar kilnBOT
#
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cedar kilnBOT
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crimson sedge
#

can someone help me how to solve the quotient rule

onyx oyster
crimson sedge
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here is the example

onyx oyster
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so you want to know how to apply it?

crimson sedge
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i get it a little bit but i still get confused when the given is long

onyx oyster
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or how to prove it

crimson sedge
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yeah

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let me send the another wxample with no answer

digital cliff
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you can prove it with the product rule relatively easily

crimson sedge
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this one

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im watching it rn on yt but im confused cus of the given 😓

sonic thistle
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wasn't the quotient rule an pllication of the chain rule

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and the product rule

digital cliff
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product rule is more derived from the limit definition of derivatives as far as im aware

crimson sedge
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this my solving idk if its right i got confused mid way

digital cliff
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,rccw

wraith daggerBOT
digital cliff
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your derivatives are wrong for u and v, and i dont like the way youve written it either

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saying u=u' and v=v' is incorrect process

crimson sedge
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how is that wrong

digital cliff
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tell me how you got 4 and 3x

crimson sedge
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ok so i got the 4 by multiplying the 2 to its x^2 and i got the 3x by applying the power rule

digital cliff
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youre not doing either thing right

crimson sedge
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how so 😢

digital cliff
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2x^2-4x+5 differentiated to 4x-4

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by the power rule

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x^3+10x^2 goes to 3x^2+20x

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x^n -> nx^(n-1) remember

crimson sedge
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so the derivatives of u is 4x-4 and for the v is 3x^2+20x

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is that right

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?????

digital cliff
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si

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i think you should review power rule a bit more before looking at the quotient rule

crimson sedge
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wait

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can u answer that one for me

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dw its just an example my reviewer

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not a hw or smth

digital cliff
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,w differentiate (2x^2-4x+5)/(x^3+10x^2)

digital cliff
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the factoring on the bottom is they factored out x from inside the bracket

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

cedar kilnBOT
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brazen girder
#

Can someone knows how to create truth table about this? Thank you

orchid panther
#

Start by drawing two columns and 4 rows for the 4 possible truth values for p and q

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p q
0 0
1 0
0 1
1 1
For example

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Then the other columns would be the other different statements

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For example youd have one column for p <-> q implies (not p or q), another for p implies (q and p) and so on

cedar kilnBOT
#

@brazen girder Has your question been resolved?

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brazen girder
orchid panther
#

Wdym

cedar kilnBOT
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buoyant jackal
#

Please help me with this one

cedar kilnBOT
buoyant jackal
#

I tried a lot but can't be even close to the answers

digital cliff
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99=3^2*11
12=3*2^2

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make a and b fulfill the remaining factors needed for 99

buoyant jackal
digital cliff
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im doing prime factors

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12=2^2 * (3) and 99 is 3^2*11
so a and b need to have 3 and 11 as factors

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not both, just either or

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then again it wouldnt matter

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if 12ab has the prime factorisation of 99 as a factor, then it is a multiple of 99

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is what im getting at

rigid lava
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i think it means

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a,b are digits

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with 12ab being a 4 digit number

buoyant jackal
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a = 8
b = 7

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is the answer

digital cliff
rigid lava
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anyway

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use divisibility rules for 99 = 9 * 11

buoyant jackal
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like it means 99 * something = 12ab

rigid lava
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yes

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use divisibility rules

buoyant jackal
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hmm so it is

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99 * 13 = 1287

rigid lava
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i mean sure

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works also

buoyant jackal
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okkk

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there is one more

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i know like y will be odd

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y = (763 - 2x)/3

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by this

rigid lava
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why is that odd

buoyant jackal
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see

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wait

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sorry y = positive

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oh, i got it

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Can you plot root over root n on number line?

cedar kilnBOT
#

@buoyant jackal Has your question been resolved?

cedar kilnBOT
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sweet badger
#

this question is from the topic differentiability....Can sm1 help me understand this question ..and help me solve this question.....

final crag
#

this is really not readable at all but you can find dy/dx by noting dy/dx = (dy/dt) / (dx/dt)

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and then find d^2y/dx^2 by differentiating that again

sweet badger
final crag
#

what have you tried?

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you have $\frac{dx}{dt} = ap \cos pt$ for example

wraith daggerBOT
#

OssihLikesBlue

final crag
#

you can similarly find $\frac{dy}{dt}$ and then $\frac{dy}{dx} = \frac{\frac{dy}{dt}}{\frac{dx}{dt}}$ and then differentiate that with respect to $x$ to get $\frac{d^2y}{dx^2}$

wraith daggerBOT
#

OssihLikesBlue

final crag
#

@sweet badger

sweet badger
#

ohh ....Thank you

cedar kilnBOT
#

@sweet badger Has your question been resolved?

cedar kilnBOT
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balmy yoke
#

need help with e)

cedar kilnBOT
balmy yoke
#

my answer is -16/21

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but in my answer key its -16/63

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but I double checked and all my steps look correct

mental trail
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show your work

balmy yoke
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ok

digital cliff
#

what did you get for tan x and tan y

balmy yoke
#

,rotate

wraith daggerBOT
mental trail
#

How did you add up the fractions on top?

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4/3 - 12/5 definitely isn't -16/5

digital cliff
#

how were you cancelling in an addition?

mental trail
#

'simplifying 3 with -12' is something you do with multiplication, not addition

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for addition, you put everything on the same denominator

balmy yoke
#

right, silly me

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thanks

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alr I get the right answer now 👍

#

ima close this

#

.close

cedar kilnBOT
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crimson sedge
#

How can i show this limit

cedar kilnBOT
crimson sedge
#

Maybe using lhopitals?

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

crimson sedge
#

<@&286206848099549185>

ruby tree
#

but idk where that would lead

crimson sedge
#

The denominator stays 0

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

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amber oriole
#

Hi can sm1 explain the approach to this problem?

amber oriole
#

like let's say I pick a chairperson from the committee
well then there would be n choices
and then out of the (n-1) ppl, i make a comittee of any size
why would it be 2^(n-1)?
on the left hand side, if I pick k ppl to form a committe from an n large group, then the number of ways to pick those k ppl would be nCk
and then from those k ppl I chose a chairperson, there would be k choices to pick a chairperson
but then why is there a summation sign on the left?

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<@&286206848099549185>

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<@&286206848099549185>

fathom night
amber oriole
#

ohhhh

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how about the summation?

fathom night
#

For the summation the committee size can range from 1 to n

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So you account for committees of all possible sizes

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From k=1 to n

amber oriole
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OHHHH

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cuz u want to dtermine the total possible

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number of ways

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but k can go from 1 to n

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so u need to sum over to get the total possible

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ok ok

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aight thank u

fathom night
#

👍

amber oriole
#

.close

cedar kilnBOT
#
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amber oriole
#

thank u so muhc

#

lifesaver

cedar kilnBOT
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opaque bane
cedar kilnBOT
opaque bane
#

Please help

modern compass
opaque bane
#

C d e was my first thought

modern compass
#

so which objects meet that definition, or which can you exclude because they fail?

opaque bane
#

But it kept giving me wrong

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A and b are not prisms

modern compass
#

are the cross sections of C constant?

opaque bane
#

But for my answer I put d and e but it said I was wrong

modern compass
opaque bane
#

Ah I see

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So it’s a, d, e

modern compass
#

Also, because one face of C is larger than the back face, if you cut it perpendicularly (which you should be doing) the cross sections won't be constant

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C is the bottom part of a very tall, narrow square pyramid.

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so it is not a prism.

opaque bane
modern compass
#

yes

opaque bane
#

It’s so mind boggling

opaque bane
modern compass
#

maybe it's excluding D?

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Not sure why that'd be wrong though.

opaque bane
#

Same

cedar kilnBOT
#

@opaque bane Has your question been resolved?

cedar kilnBOT
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@opaque bane Has your question been resolved?

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crimson sedge
cedar kilnBOT
crimson sedge
#

????

modern compass
#

do you know about Riemann sums?

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

crimson sedge
cedar kilnBOT
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orchid valley
#

how would i go about solving this? i dont know where I went wrong because i followed the accompanying video

crimson sedge
#

f^n(a)(x-a)^n/n!

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Then find the pattern with that

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Then the interval of convergence is found by taking lim n—> inf a(n+1)/a(n)

cerulean sail
#

(what may help more is if you can relate the original function to something that's "close enough" to something you know the power series for, then use that...)

orchid valley
crimson sedge
#

which fuynction

crimson sedge
opal schooner
#

$\sum_{n=0}^{\infty} ax^n = \frac{a}{1-x}$

wraith daggerBOT
#

Triaxyz

opal schooner
#

-1<x<1

crimson sedge
#

i mean if he doesnt know the formula for power series

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why would he use the fast way

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to use substitution and such

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u havew to understand the mechanismns

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to an extent

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for substitution

cerulean sail
opal schooner
#

because taylor series expansion is unnecessarily complicated for a function like this

orchid valley
#

yea i havent learned taylor series yet

crimson sedge
#

i think for someone who doesnt know the formula

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the fast way

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is dumb

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yes then learn the formula

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haha

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dont do substituion stuff yet

opal schooner
#

🤨

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you usually learn geometric series before taylor

crimson sedge
#

do it 3 times then just find the pattern and eventually learn

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the subsitution

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stuff

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@orchid valley

orchid valley
crimson sedge
#

you already did polar/parametric?

opal schooner
#

then dw about doing taylors if you havent covered it

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you know geometric series yes?

orchid valley
#

yes

opal schooner
#

zhats literally all you need then

opal schooner
orchid valley
opal schooner
#

,w x / (15x^2 + 1) = (x/15)*(1 / (1-(- x ^2 / 15)))

opal schooner
#

1sec

opal schooner
#

when you distirbute this, you get $\frac{x}{15+x^2}$ which is not f(x)

wraith daggerBOT
#

Triaxyz

orchid valley
#

ah thats true

cedar kilnBOT
#

@orchid valley Has your question been resolved?

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formal pasture
#

how do i find irc of this

cedar kilnBOT
formal pasture
#

instantaneus rate of change

low holly
#

You can use the quotient rule to find the derivative here

formal pasture
#

but dont u use

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the original

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equation

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to find instantaneus rate of chnage

low holly
#

instantaneous rate of change is just the derivative of the function i believe

formal pasture
#

like this?

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im using limits

low holly
#

Yeah that works too

formal pasture
#

okay and i sub in

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my point

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when i simplify it?

low holly
#

But you're missing a minus sign in between

formal pasture
#

oh yesyes

low holly
#

And wait

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That's not how to do it

formal pasture
#

like what do i do with this

low holly
#

( f(v+h) - f(v) )/ h

formal pasture
#

yea

low holly
#

f(v+h) is adding h to v, not adding h to f(v)

formal pasture
#

wdym

#

isnt that what i did

low holly
#

suppose it was easier and f(v) = 1/v

formal pasture
#

what do i change

low holly
#

what would f(v+h) be?

formal pasture
#

im confused

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isnt that

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just my equation

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plus h

low holly
#

That would be f(v)+h

formal pasture
#

so where do i add h

low holly
#

to v

formal pasture
#

every v?

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theres a few v

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s

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on top

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and bottom

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of the fraction

low holly
#

Well yes, f(v+h) is evaluating the function f at the number (v+h), which is a different number than (v)

formal pasture
#

so i add v to all?

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like this

#

😭

low holly
#

For example, if $f(x) = \frac1x$, then $f(x+h)=\frac{1}{x+h}$

wraith daggerBOT
#

π=√g

low holly
formal pasture
#

thats my fraction

#

,rotate 270

wraith daggerBOT
formal pasture
#

like rhis?

low holly
#

You're adding h to v, not v^2 remember

#

(and you have to put parentheses for the numerator)

formal pasture
#

,rotate 270

wraith daggerBOT
formal pasture
#

like this?

low holly
#

$$\frac{1600 (v+h)}{(v+h)^2 + 6400}$$

wraith daggerBOT
#

π=√g

formal pasture
#

oh

#

didnt u say

#

dont add to v^2

low holly
#

Yeah, add to v

formal pasture
#

why r we squaring h

low holly
#

Basically replace all the v with v+h

formal pasture
#

okk

#

,rotate 270

wraith daggerBOT
formal pasture
#

so like this

low holly
#

Yeah but good luck working with that

formal pasture
#

eevbecrvr

low holly
#

Are you sure you need to use limits to prove this?

formal pasture
#

yes

low holly
#

Ok well, expand the square, then put both fractions on the same denominator, add the terms in the numerator, and simplify

cedar kilnBOT
#

@formal pasture Has your question been resolved?

cedar kilnBOT
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lilac knot
#

.close

#

.claim

mental eagle
#

Hello! I'm trying to figure out how to isolate y" in this diffeq. I've used the langmuir-blodgett relation for the e^x but im quite stuck on the rest. I can't use numerical methods, and must do it algebraically

mental eagle
#

I would be happy to clarify the problem if the handwriting is unclear

cedar kilnBOT
#

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crimson sedge
#

pls help with how to start this related rates

crimson sedge
#

dv/dt = 20

#

we need to find dSA/dt when x = 10

acoustic quartz
#

Do you know the formula for volume of a cube

crimson sedge
#

A = side * length

#

Volume*

#

ok

#

So if volume = side * length

#

And the equation for a side is x^2

#

Then try to get surface area

#

In that equation

#

Ok

#

sorry I am still a bit lost

#

V=x^3

#

Surface area = 6x^2

#

Solve for x^2

#

Plug into volume

#

Perhaps that will help

#

but I need to take the derviative

#

when do I do that

#

When you relate the two

acoustic quartz
#

U can derive volume of cube formula

#

then plug in what u know

#

dv / dt = 3s^2 ds/dt

#

sides are 10, dv is 20

crimson sedge
#

Find ds/dt by deriving S = 6x^2

acoustic quartz
crimson sedge
#

Ahh ok so ds/dt = 12x

#

We need to be careful here

#

Dv/dt = side length ^2 dsidelength/dt

#

And Dsyrface area/dt = 12x dx/dt

#

if you call both s you will confuse urself

#

Make the lengths a variable

#

And make the surface area a different variable

acoustic quartz
#

cause when i did it i got 8

crimson sedge
#

ok thanks

#

Let me attempt

acoustic quartz
crimson sedge
#

dV/dt = 3x^2 dx/dt

#

dS/dt = 12x dx/dt

#

dV/dt = x/4 dS/dt

crimson sedge
acoustic quartz
crimson sedge
#

I got 8

#

As well

crimson sedge
acoustic quartz
#

i see

crimson sedge
#

i did it like this. v=x^3. dv/dt = 3x^2(dx/dt) I solve for dx/dt. then I differintate surface area = 6x^2/ so we get ds/dt = 12x(dx/dt) I subsisute the value of dx/dt and the value of x = 10

#

Related rates is all about finding equations that relate the two

#

Things

#

That are changing

#

With respect to eachother

#

@crimson sedge @acoustic quartz thank you for the help

#

now I got it

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

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final hornet
cedar kilnBOT
final hornet
#

!status

cedar kilnBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
sly abyss
#

System of equations

final hornet
sly abyss
#

Or quite frankly

#

The easiest way to do this problem with a calc

#

Is exponential regression

inland stirrup
#

Do two points define a unique exponential?

sly abyss
#

Ye

#

You can write mutiple ways tho

#

but likely it’s just y= a x b^x

final hornet
#

can we get of b^-2 by multiple b^-1 on both side

sly abyss
#

?

final hornet
#

1/8=a*b^-2

#

to get rid of -2

inland stirrup
#

Wat about y = ab^cx?

sly abyss
#

no

#

Don’t

final hornet
#

Okay

inland stirrup
#

Why not?

sly abyss
#

Just write it as a systems of equations

#

It’s a two step problem0

sly abyss
#

But why

#

Just keep it as a simple equation

final hornet
#

...

sly abyss
#

@final hornet

#

Set up a systems of equations

inland stirrup
#

U can also do y = ab^cx +d?

sly abyss
#

Bro

#

Why tho

#

Why not just make it in the form of a x b^x

#

It’s whole numbers

#

If you do that way

#

a and b are both whole numbers

inland stirrup
#

Because idk if two points will uniquely define an exponential function

sly abyss
#

Bros

#

It does

#

You can find a function that satisfies

#

The question

#

With 2 points

inland stirrup
#

But is it unique?

#

Is there more?

sly abyss
#

Find a formula

#

The questions says

#

Keep it simple.

#

@final hornet

#

What have you tried?

final hornet
#

Sorry I got a bit distracted with the dicussion

sly abyss
#

No worries

inland stirrup
#

We still need to figure out the uniqueness

sly abyss
#

All due respect the problem isn’t asking anything about that

tender beacon
#

use this

sly abyss
#

That’s what I was tell them

#

To do

#

And this brother is babbling about uniqueness

inland stirrup
sly abyss
#

Yes

#

It says find a function

inland stirrup
#

Idkkkk

#

Seems strange

sly abyss
#

I would just set it up like this

#

Sry I don’t have my Apple Pencil rn

inland stirrup
#

If you add plus c youll get all of the possible equations

#

Cuz youll have theree variable and two equations right?

sly abyss
#

Man just find the simplest equation

inland stirrup
#

That really wouldnt be right

#

You need to show all of them

sly abyss
#

I don’t think you read the question once again

#

It says “Find A function”

inland stirrup
#

It also says "open response"

sly abyss
#

And there is space

#

For one equation

inland stirrup
#

They want the student to talk about all the possible functions

sly abyss
#

Bro 😭

final hornet
#

So could we remove b^-2 with * b^2?

sly abyss
#

nah I wouldn’t do that

#

Easiest way

#

Divide the top of an bottom

#

So you have 128/.125= a/a x b^5

#

1024

#

b^5

#

b=4

#

128= a x 4^3

#

128=64a

#

a =2 , b=4

#

Sorry I have to go soon

#

So I just told you the answer but

#

f(x)=2(4)^x

inland stirrup
#

General form

sly abyss
#

Have fun and go solve that yourself

inland stirrup
#

Bruhh, its the proper solution

sly abyss
#

Not the proper solution

#

It says find a formula

#

Standard form of an exponential

#

Is y= a(b)^x

inland stirrup
#

U are forgetting about the other solutions

sly abyss
#

Ok go and find these other solutions and report back to me

#

I’m going to find the easiest solution

#

Because the problem asks for one solution

inland stirrup
#

Problem did not say anything about standard form

#

Its an open response question

sly abyss
#

Bro you are getting on my nerve 😭opencry

inland stirrup
#

Just for education try to find the general solution

sly abyss
inland stirrup
#

Find a and b in terms of c and d

#

Or u can do the other way around

inland stirrup
sly abyss
#

Ye have fun with that

final hornet
inland stirrup
final hornet
#

@sly abyss Should I leave this open or close?

sly abyss
#

You can close

sly abyss
#

But i just try to help in an easy way

inland stirrup
#

U should at least tell that its not unique

final hornet
#

.close

cedar kilnBOT
#
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cedar kilnBOT
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pale creek
cedar kilnBOT
pale creek
#

hi

#

all i get is 8/x and its wrong

feral isle
#

Ok so

#

Try factorizing the numerator in the first parenthesis

#

And the denominator in the second parenthesis

#

Result should be -4 I think

pale creek
#

some people say the answer should be c

prisma gull
#

how do you factor (x^2-4)?

#

also 3x-6?

bleak flame
bleak flame
feral isle
#

aaaaa in that sense

#

answer is c

prisma gull
cedar kilnBOT
#

@pale creek Has your question been resolved?

pale creek
#

.close

cedar kilnBOT
#
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civic meteor
#

Hi, I have a question about vector functions.
Why is derivative of speed d|v(t)|/dt not equal to magnitude of acceleration |a(t)|?

civic meteor
#

just like speed is distance/time shouldn't magnitude of acceleration be speed/time?

#

e.g when solving for min/max speeds setting d|v(t)|/dt = 0 would solve for t value where min/max occurs but why cant you just set |a(t)| = 0 to solve for t

#

when i tried doing this, i got difference answers

hollow trail
#

you can have a nonzero acceleration when the speed isn't changing, because acceleration can change direction as well as speed

#

e.g. if an object is moving in a circle at constant speed it has a constant nonzero magnitude of acceleration (to change direction), but its speed is constant, so the derivative of speed is 0

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#

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sweet ridge
#

hello

cedar kilnBOT
sweet ridge
#

merp

#

need help

#

a family have 5 childrens. the oldest age 2 times the youngest, while 3 others age less 3 years from the oldest, 4 more years then the youngest, and less 5 years from the oldest. If the average of their age is 16 years, so the quadrat of difference between 2nd child and 3rd child is:

#

sorry if bad translate

#

so my answer is:

#

please ping!

fallen moat
#

took me 5mins to read lol

sweet ridge
#

is this right?

#

oh wait

#

i just realize somethig

fallen moat
sweet ridge
#

uhhhh

fallen moat
#

you mean you need to find the quadrat of difference between 2nd and 3rd?

#

21-19?

sweet ridge
#

one more e in the 3rd box should fix the rest

fallen moat
#

2e+2e-3+e-4+2e-5+e
like that?

sweet ridge
#

yeah

#

so it would be 8e

fallen moat
#

yea, but then e will be 10.5?

#

would it be valid for 0.5?

sweet ridge
#

yeah the answer allow .5...

fallen moat
#

goooood!

#

then case solved!

sweet ridge
#

okay

#

TenQ

#

see you sooner!

#

.close

cedar kilnBOT
#
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covert raptor
cedar kilnBOT
covert raptor
#

for the third paragraph
what does it mean for the notations?

#

like what is g(x) refers to?

#

what is the "x"?

#

TIA

cedar kilnBOT
#

@covert raptor Has your question been resolved?

covert raptor
#

.close

cedar kilnBOT
#
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magic solar
#

Hi guys, for b)ii), im struggling to algebraically manipulate it into the form.

pastel vault
#

And also you can see what r^2 is from this: be careful of the minus sign

magic solar
#

hmm

#

r^2 is one

#

wait

#

r^2=-1 so r=i?

#

ah I see, I wasn't really using part a) which made it 10x more difficult than it needed to be

#

wait what am i saying

#

r is real smh

pastel vault
magic solar
#

oh what

#

but isn't this saying that the modulus of a point shifted is r, so r must be real?

pastel vault
#

We're in the complex plane so the radius can actually be an imaginary number

pastel vault
#

Like the circle will be vertical

magic solar
#

the answers say the radius is 1, im guessing its the same thing?

pastel vault
pastel vault
magic solar
#

ah

pastel vault
# pastel vault

This is the graph of f(z) = z^2 + 1 for when z is a complex number

#

We're using the 3rd dimension to represent what happens when z has an imaginary part

#

And y is still the output of the function

#

So that explains the vertical circle part

pastel vault
magic solar
#

although

#

this would make the equality in a) not entirely true would it?

#

it would have to be |r|^2 ?

pastel vault
#

So r = 0

#

Yeah so it would just be a single point

#

A degenerate circle

magic solar
#

dang circles can be degens too

pastel vault
#

Yep

#

So it comes naturally from the definition

#

You just have to ask the right questions to see what maths tells you about those weird situations

magic solar
#

I see

#

bit beyond my scope i must say

pastel vault
#

True

magic solar
#

anyways thanks for broadening my horizons i guess 🙂

#

.close

cedar kilnBOT
#
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foggy estuary
#

Henlo, I'm kinda stuck on this question

cedar kilnBOT
foggy estuary
#

They ask to simplify

candid mason
#

So what are key theorems for exponents/indices?

cedar kilnBOT
#

@foggy estuary Has your question been resolved?

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peak minnow
cedar kilnBOT
peak minnow
#

By rotation of axis, eliminate xy term. Identify the conic and its elements

#

Supposed to be a hyperbola, but i can't seem to remove X and Y terms to get that

#

Would like help in here

delicate elm
#

are you trying to solve the equation at the very top

peak minnow
#

This is the question

#

And the one I'm trying to solve is a part of this

#

<@&286206848099549185>

cedar kilnBOT
#

@peak minnow Has your question been resolved?

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slow fiber
#

when would you go from rectangular to spherical coordinates

cedar kilnBOT
#

@slow fiber Has your question been resolved?

slow fiber
#

.close

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river silo
cedar kilnBOT
river silo
#

i dont know how to do this, without f(x) being defined

#

like f(x)=x^2

swift terrace
#

think of the transformations being made

#

first of all you have -x

#

which does what?

river silo
#

-x makes a reflection along the y axis

swift terrace
#

exactly

#

thank you have +4 to th x value

#

which moves theh graph where?

river silo
#

four units to the left

swift terrace
#

exactly

#

and then +3 to the total function, which does what?

river silo
#

which moves it 3 units up

swift terrace
#

and that's all you need 😉

river silo
#

🙂

swift terrace
#

first flip, then move 4 then add 3

river silo
# river silo

what would it look like if i reflected it along the y axis

swift terrace
#

the peak point would be 1,-4

#

can you see visualize it?

river silo
#

yes

swift terrace
river silo
swift terrace
#

yep

#

then 4 to the left, and 3 up and you are set

river silo
#

i see

#

thanks for the help 🙂

swift terrace
#

gladly

river silo
#

.close

cedar kilnBOT
#
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stone tulip
#

5n^2 +12n+6=0

cedar kilnBOT
swift terrace
#

is that the question?

#

solve for n?

crimson sedge
#

@stone tulip

hot crag
#

@stone tulip ?

split pike
# stone tulip 5n^2 +12n+6=0

Try using Quadratic formula, rational root theorem, factorization by middle term splitting or by completing the square to find the values of n

stone tulip
#

Hi yall sorry

#

Oh hey @hot crag

hot crag
stone tulip
#

Forgot to dm you..

hot crag
#

yea i noticed lol

#

hyd

stone tulip
#

I’m ok. Still trying to get my darn math grade up

#

Can I just dm you @hot crag ?

hot crag
#

sure

stone tulip
#

.close

cedar kilnBOT
#
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hot crag
#

.reopen

cedar kilnBOT
#

hot crag
#

@stone tulip

#

anyway

#

you already know quadratic formula

wraith daggerBOT
stone tulip
#

@hot crag ? :))

hot crag
#

?

hot crag
stone tulip
#

You told me to come back here so you could help

hot crag
#

yes

#

so use the quadratic formula

#

and show me ur working

stone tulip
#

U do -6 to start out?

hot crag
#

??

#

why

wraith daggerBOT
stone tulip
#

Ohhhh a,b,c oki

hot crag
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uh

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one sec

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alr

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simplify

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also

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one thing's wrong

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you wrote -(12)^2 outside the sqrt

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it's -b not -b^2

stone tulip
#

Alr, @hot crag I gotta go, I’ll dm ya again

#

.close

cedar kilnBOT
#
Channel closed

Closed by @stone tulip

Use .reopen if this was a mistake.

hot crag
#

alr

cedar kilnBOT
#
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paper sentinel
#

I’m so confused on how to do this, I know log2x is x=2^y but I do not know how to multiply the -2 or add the 4. I keep getting the wrong graph.

jolly jay
paper sentinel
#

How though

jolly jay
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plug in x values into the function

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so let's take x=2 for example

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what would -2 log_2(x) + 4 be

paper sentinel
#

That’s what I been trying to do but I keep getting it wrong I did -2(2^1)+4 and it gave me the wrong answer

jolly jay
#

so log_2(x) = 1
the log_2 asks "what number do I raise 2 by to get this number"

#

so if u wanna do log_2(2), you're asking "what number do I raise 2 by to get 2"

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the answer is 1 right

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so log_2(2) = 1

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(not 2^1)

paper sentinel
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I thought log_2x equals x=2^y

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I just plugged a random number in

jolly jay
#

yeah, you're finding the right answer but you're plugging in 2^y instead of y

paper sentinel
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I don’t understand why -2(2^y)+4 isn’t working

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Like isn’t it the same thing

jolly jay
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don't worry about the entire function for now

what is log_2(4)

paper sentinel
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2^4? Idk

jolly jay
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the log_2 asks "what number do I raise 2 by to get this number"

#

so if u wanna do log_2(4), you're asking "what number do I raise 2 by to get 4"

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what is log_2(4)

paper sentinel
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2

jolly jay
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yeah

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now we have that function y = -2 log_2(x) + 4

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what do you get if you plug in x=4

paper sentinel
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2

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Wait

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Oh hold on

#

0

jolly jay
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yeah

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that's correct

paper sentinel
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Ok I think I get it

jolly jay
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yeah

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now you can do the same for a bunch of x-values

paper sentinel
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Thank you that was very helpful

jolly jay
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yeah np

paper sentinel
#

I have another problem but it’s kind of different can I send it

weak otter
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Yes

paper sentinel
weak otter
#

If it’s easier for you, you can just solve for x

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And graph that

paper sentinel
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Idk how to do that

weak otter
#

Can you guess what the first step would be

hollow totem
#

I have a question, @paper sentinel do u know what an asymptote is?

#

thats may help

paper sentinel
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I think that’s the number the graph almost touches

hollow totem
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Since for log(x); x must > 0

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so x -1 must always > 0; thus x > 1

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also

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log base 2 also gives us a clue

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as log_2(2) = 1

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We can probably guess the shape of the graph to look like this

paper sentinel
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Log_2(1) is 0?

hollow totem
#

For graphing problem, the question tends to want u to find special point/feature of the function

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For this region, we can argue since the growth of the log function is extremely small, and the different of x is small too

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We could just assume, the graph looks like a line

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So it will look like this

paper sentinel
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Ok got it thanks 👍

cedar kilnBOT
#

@paper sentinel Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

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#
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pulsar schooner
#

guys i need urgent help with stereometry. Im preparing for a test and started revising just fine until i run into the same problem again and again and again. The problem is about finding the distance between a point and a plain. Im struggling to understand how do i find where the intersection is, or when it is given - what to do with it. Here is one of the problems ive been stuck on.

  1. In a cube ABCDA1B1C1D1 point M is the center of the edge A1D1=1 and point N is from edge D1C1 such that D1N = 2C1N. Find the distance between point B1 and the plain (MBN)
pulsar schooner
#

I know that i need to build a triangle with the perpendicular but where and how I have no clue

#

heres a very messy image of what ive drawn so far (sorry its rotated)

cedar kilnBOT
#

@pulsar schooner Has your question been resolved?

pulsar schooner
#

i just solved a problem not too different from this but again i assumed. I needd a specific method that tells me how and why i do what i do. I will write this new problem down here and then my solve. If you can please tell me why it worked out because i have no idea what i did

#

2)the base of a pyramid ABCDM is the rhombus ABCDS. The outer edge (idk the english term) BM is perpendicular to the base plain. The side and the diagonal BD of the rhombus are equal to 4 and the distance from point B to the outer plain CDM is equal to the square root of 3. Find the volume of the pyramid

#

solution) so starting off i found the altitude of the rhombus to be equal to 2sqrt of 3. Than i built a triangle BHM with point B1 laying on HM being the point which connects the plain CDM with point B at a 90 degree angle ( a perpendicular) and H such that BH is the altitude of the rhombus. From there using pythogor's theorem i found HB1 to be equal to 3 and using equalatheral triangles (BHB1 and BHM) i found BM to be 2. Than i jsut plugged everythign in the formula for the volume.

#

My main concern is why did buildign triangle BHM work

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what says that the altitude of the rhombus lies on the same plain as the distance between B and CDM. For me it was just intuition but i need a certain proof that i can understand and use without overthinking it

#

and what do i do in the case of the first question where i have no idea where to build the triangle

cedar kilnBOT
#

@pulsar schooner Has your question been resolved?

pulsar schooner
#

<@&286206848099549185> anyone have an idea or do I close

#

.close

cedar kilnBOT
#
Channel closed

Closed by @pulsar schooner

Use .reopen if this was a mistake.

#
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coral fulcrum
cedar kilnBOT
coral fulcrum
#

Calculate the angle between the two tangents

#

can i get a help ?

#

.close

cedar kilnBOT
#
Channel closed

Closed by @coral fulcrum

Use .reopen if this was a mistake.

cedar kilnBOT
#
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crimson sedge
cedar kilnBOT
#

Please don't occupy multiple help channels.

crimson sedge
#

Hello sorry I lost the channel I previously was on

royal loom
#

@crimson sedge Sir please stick to #help-36

crimson sedge
#

Many apologies

royal loom
#

All is well

#

.close

cedar kilnBOT
#
Channel closed

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#
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Ask your math question in a clear, concise manner.
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shut pier
#

hey

cedar kilnBOT