#help-13

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cedar kilnBOT
#
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kindred hornet
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what would the limit be, im confused?

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quasi orchid
#

I had "solved" the problem using the slope formula on the coordinate plane below, but I am still unsure if I was correct so I wanted clarification (For the rate of change/slope)

cedar kilnBOT
#

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quasi orchid
#

<@&286206848099549185>

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@quasi orchid Has your question been resolved?

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cedar kilnBOT
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upper wave
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Really do not understand this one

cedar kilnBOT
main needle
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for logs you basically view numbers are the product of their factors, like 150 is 2*3*5*5

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it would make way more sense if you were asked to find log_2 (150), and there's a property that lets you flip that, 1/log_a(b) = log_b(a)

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basically "if 150 to the x power is 2, then 2 is the xth root of 150"

upper wave
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ohhh i think i kinda get it

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let me give it a shot

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well i got log_abd^2 (a) = x, and i think I have to use a property to get rid of the log then solve, but I'm not sure how to do that without using log_a (c) = b --> a^b=c

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because if i use that x becomes an exponent so I cant really solve for it

main needle
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hmmm yea you'll never need to go from log to exponent here, just use the above thing and log(ab)=log(a)+log(b)

upper wave
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wait what do i do from 1/log_a abd^2 = x

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sorry im a bit confused

main needle
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like you figure out log_2(2*3*5*5), and with that you do 1/ to get the answer

upper wave
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ohhhhhh ok i got it fr now

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let me work it out

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i got 1/6.25 or 0.16

main needle
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hmm I get 1/7

upper wave
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hmm let me do it again

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oh yeah i got that too just made a typo in calcullator

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thanks so much for the help!

cedar kilnBOT
#

@upper wave Has your question been resolved?

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quaint totem
#

i need help with this

cedar kilnBOT
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quaint totem
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  1. i dont know where to begin
cedar kilnBOT
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@quaint totem Has your question been resolved?

quaint totem
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bruhh

ancient quarry
quaint totem
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sas

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ive gone this far

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but aleks is kinda sped

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here are previous steps

quaint totem
ancient quarry
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you have AB congr BC, the have that angle A = ang C, you have AD = EC right

quaint totem
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ye

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i got it now

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i jjust had switch the equation around

cedar kilnBOT
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cedar kilnBOT
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small sinew
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can anyone help me with this physics problem?

AM radio signals are broadcast at frequencies between 544.0 kHz and 1605.0 kHz (kilohertz) and travel 3.00 βœ• 108 m/s.
(a) What is the range of wavelengths for these signals? (Enter the wavelengths from shortest to longest.)
(b) FM frequencies range between 88.0 MHz and 108 MHz (megahertz) and travel at the same speed. What is the range of FM wavelengths?

onyx dove
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!status

cedar kilnBOT
#
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onyx dove
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you know how to find wavelengths?

small sinew
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itsss velocity /frequency rightt?

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got it t

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cedar kilnBOT
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violet brook
cedar kilnBOT
violet brook
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this is a rly simple question

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but

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for part 3

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ik its gonna be

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separate grant to everyone else (g, not g is 1/9 and not g, g is 1/9 giving the correct answer of 2/9)

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but why doesnt this work

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ignore the big cross

cedar kilnBOT
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@violet brook Has your question been resolved?

violet brook
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<@&286206848099549185>

ancient quarry
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having a hard time reading your work give me one second

violet brook
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sorry i can rewrite it

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give me a sec

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oh my days i figured it out

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i didnt multiply the 4/9 w the 1/8

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.close

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cedar kilnBOT
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lime igloo
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I need to show that La is in Aut(G), so I'm trying to show that La is an isomorphism, but I have not been able to do thatπŸ₯²

abstract thicket
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dam

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idk those stuff lol

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im in yr9

rigid lava
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Is a an element of G?

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@lime igloo

lime igloo
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I guess it is.

rigid lava
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What does your proof look like so far

lime igloo
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I need to show La is a homomorphism.

rigid lava
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Ok so

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What does La(xy) look like

lime igloo
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xya^-1

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And I need xa^-1 ya^-1.

rigid lava
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Oh uh

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Your La is a typo

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Didn't notice since I'm on mobile

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It should be La(x) = axa^-1

lime igloo
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Yeah, thats what I was thinking.

rigid lava
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Yeah, multiplication by a fixed element is not an automorphism lmao

lime igloo
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Thanks mate.

rigid lava
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this mapping is called conjugation and is a very special automorphism

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np lmk if you get stuck

lime igloo
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I'm really sorry if I sound rude, English is not my mother tongue as you may notice.

rigid lava
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Uh

lime igloo
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I mean, why it's special?

rigid lava
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Many many reasons

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it shows up a lot

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On phone so lazy but a big one you'll learn about later is something called group actions

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you can Google these and read for yourself

lime igloo
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Okay okay.

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Thanks.

rigid lava
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Np

lime igloo
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.close

cedar kilnBOT
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cedar kilnBOT
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ionic finch
cedar kilnBOT
ionic finch
#

when we find a general solution of matrix using row reduced form

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does it mean the the rows below it can zeros, but not written ?
ie, the other equations are 0x1 + 0x2 + 0x3 =0

ionic finch
# ionic finch

ie, i can see it as square matrix when solving equations?

hollow trail
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you could, but it wouldn't be particularly useful

ionic finch
# ionic finch

this will immediately mean the system has infinite many solutions right?

hollow trail
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as long as it is consistent, yes

ionic finch
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if a matrix is an row echlon form, then i should only look whether it have 0=b (b!=0) or not right?

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to determine consitency

hollow trail
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that would indicate it is inconsistent, yes

ionic finch
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say a system is consistent

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how to determine if it has infinte or unique solution?

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what's the idea behind looking at pivots?

hollow trail
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we know that a solution will be unique only if there are as many independent equations as there are unknowns

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but we can't immediately tell if equations really are independent, or if one equation is really just the sum of scalar multiples of the other equations (what we call a linear combination)

ionic finch
hollow trail
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when we row reduce, even though the equations look different, we can guarantee they have the same set of solutions

hollow trail
# ionic finch what if we have more equations that the variables?

if there are more equations than variables, then either:

  1. The system is inconsistent, this is usually the case
  2. the system is consistent, this must mean that some of the equations are linearly dependent (i.e. they are a linear combination of the other equations), meaning the number of independent equations is the same or less than the number of unknowns
ionic finch
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I have this problem, i need to determine if it's consistent and have unique solution

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i think it's consistent

hollow trail
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assuming the last column is the constants, then that seems correct

ionic finch
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dark box is non zero

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star can be anything (including zero)

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does it have unique solution?

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i was just thinking x3 is a free variable

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but now i think it's a system of 2 unknowns

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so last column is just there for no reason.

hollow trail
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the last column is there because it is the constants

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you need it to know if the system is consistent

ionic finch
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my reasoning it's consistent as each pivot column has a non zero pivot

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and they are basic variables not free

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more like since there are no 0=1 situtation, i can safely back track

hollow trail
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consistency is just whether it has any contradictory rows like 0 = something

hollow trail
ionic finch
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makes sense

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so it's unique

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as well

cedar kilnBOT
#

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Available help channel!

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Remember:
β€’ Ask your math question in a clear, concise manner.
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cerulean pine
cedar kilnBOT
cerulean pine
#

please can i get help with b

fringe mauve
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well splitting a group of people into two teams of 5 is the same as saying how many ways are there to choose 5 ppl

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cause the other 5 are automatically in the other team

cerulean pine
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oh but the answer is not the same in a and b

fringe mauve
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so its not just 10C5

cerulean pine
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no

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the ans is 126 for some reason

fringe mauve
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i think its cause there are repetitions

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because the groups arent defined as like group A or B

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so when u do 10C5 u get groups that repeat twice

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cause 126 is 10C5/2

cerulean pine
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ohhh ok

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thank you very much!

#

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cedar kilnBOT
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violet brook
#

how and why is the derivative of s = ut + (1/2)at^2 equal to u + at

violet brook
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i mean

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s = ut + (1/2)at^2 is one of the equations of motion

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taking ds/dt gives the first equation of motion v = u + at

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but how does taking ds/dt give v

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.close

cedar kilnBOT
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#
Available help channel!

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Remember:
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bronze pond
cedar kilnBOT
bronze pond
#

I have worksheets to do but I have 0 clue on angles

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<@&286206848099549185>

gusty bison
#

Hi

bronze pond
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Hi

frank carbon
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There's Co-Interior, Corresponding angles

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There's two more I forgot the name of

bronze pond
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my teacher assigned them

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i have 0 idea on angles

frank carbon
bronze pond
frank carbon
#

Ok

frank carbon
# gusty bison Hi

Fridge you might have to take this one over because I'm not good at angles

bronze pond
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im in year 8 rn 😭

scenic brook
bronze pond
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idk the answer 😭

west glade
#

wait which one tho

bronze pond
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this 1 is the first page

west glade
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number 3?

bronze pond
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number 3 and number 4

west glade
#

ok um

west glade
bronze pond
#

i just need the answers rn

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😭

west glade
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angle A would be congruent to 75 degrees

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number 3 says to find the values of abcd

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vertical angle is a full circle if im explaining this correctly, so a would be 75 degrees, because the opposite side of the angle is always congruent

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like up and down and left and right

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congruent

bronze pond
west glade
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since vertical angle is a circle or smth, you need to subtract 75 degrees with 180 degrees to find the value of C

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C and D have the same value as far as i know

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B has the same value as A

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so just solve

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its just subtracting and adding

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also i cant clearly see number 4

bronze pond
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number 4 dont need i ended up doing it myself for number 4

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thank u for number 3 3_yayheart

west glade
#

πŸ‘

west glade
cedar kilnBOT
#

@bronze pond Has your question been resolved?

cedar kilnBOT
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full forum
cedar kilnBOT
full forum
#

For b, I get different value from the answer if I use P and Q to get the diameter, and devide that by two to get radius

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Why is it??

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Better quality

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.close

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ashen shard
#

An ellipse has foci at $(9, 20)$ and $(49, 55)$ in the $xy$-plane and is tangent to the $x$-axis. What is the length of its major axis?

wraith daggerBOT
#

Dork9399

ashen shard
#

!status

cedar kilnBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
ashen shard
#

I'm on step 1

cedar kilnBOT
#

@ashen shard Has your question been resolved?

ashen shard
#

<@&286206848099549185>

ashen shard
#

<@&286206848099549185>

ashen shard
#

<@&286206848099549185> please

buoyant latch
ashen shard
#

i know that every point has to be the same distance away from both the foci

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but i don't know how to make the equation of a rotated ellipse

buoyant latch
#

How would you construct the equation of a normal ellipse

ashen shard
#

(x-h)^2/a^2 + (y-k)^2/b^2 = 1

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@buoyant latch

cedar kilnBOT
#

@ashen shard Has your question been resolved?

peak lynx
#

This eclipse is not vertical or horizontal
So list the equation from the definition of eclipse is more intuitive
Eclipse is the orbit of the point whose sum of distance with foci is constant
This constant=the length of major axis=2a

earnest geyser
cedar kilnBOT
#

@ashen shard Has your question been resolved?

ashen shard
earnest geyser
#

I'm not too sure

ashen shard
#

The distance would be $\sqrt{(x-9)^2 + (y-20)^2} + \sqrt{(x-49)^2 + (y-55)^2}$

wraith daggerBOT
#

Dork9399

ashen shard
#

At the x-axis, that is

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$\sqrt{(x-9)^2 + 20^2} + \sqrt{(x-49)^2 + 55^2}$

wraith daggerBOT
#

Dork9399

ashen shard
#

Then we know that there exists a number such that this equation has only one solution for x

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karmic terrace
#

Hello

cedar kilnBOT
karmic terrace
#

what is this equation called / how do you derive it? (the x = ab/a+b part)

cedar kilnBOT
#

@karmic terrace Has your question been resolved?

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@karmic terrace Has your question been resolved?

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solid pivot
#

hi i need some help with this question, is there a faster way to expand the brackets?

solid pivot
#

this is for lagrange interpolation

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expand brackets for the x

cedar kilnBOT
#

@solid pivot Has your question been resolved?

solid pivot
#

nvm i thought of a method

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topaz saddle
cedar kilnBOT
topaz saddle
#

for 2 here)

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i did this for 1)

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but for 2, its asking to prove there exists some graph G with a max of 49 edges

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how would i go about that?

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im confused

modern compass
#

Either, find such a graph and give it as an example, or show that constructing such a graph is possible.

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that'd be my first guess anyway.

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And, for clarity, you aren't showing the graph has 49 edges, your showing the longest path in the graph is 49 edges.

topaz saddle
#

ive been hinted to try to think about splitting 3000 students into partitions of size 50, and 3000 is divisible by 50.

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so i was thinking of maybe using this

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to prove the longest path is 49 edges

modern compass
#

sounds like a good start. If the groups are partitioned into sizes of 50, can you say what sort of graph would be necessary to represent the connections in each group?

topaz saddle
#

a complete graph of 50 students? so each student (or vertex) is directly connected to every other student in the group i think

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tried partioning 3000 into 600 groups, each group is 50

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@modern compass thoughts?

modern compass
#

if you connect the complete graphs, then I can make a path between them to have more than 49 edges.

topaz saddle
#

since were trying to show the longest path in G is 49 edges

modern compass
#

yes

topaz saddle
#

how else would we approach this then

modern compass
#

why are you connecting those groups of 50 friends?

topaz saddle
#

i thought it'd help prove having at least 49edges

topaz saddle
#

then i cant take this approach anymore

modern compass
#

ok, first, are you proving at least 49 edges, or a maximum of 49 edges.
because those are opposite things.

topaz saddle
#

I completed proving at least 49 edges here , using proof by contradiction ( i think its right, not sure)

#

as of right now

#

im trying to provve

topaz saddle
#

maximum

#

of 49 edges

modern compass
cedar kilnBOT
#

@topaz saddle Has your question been resolved?

topaz saddle
#

i misinterpreted it

topaz saddle
#

would connecting each group with another with just one edge help

#

meaning selecting one student from each group and connecting them to one student in another group

modern compass
#

you shouldn't connect the groups at all.
I can use any edge between groups to make a longer path, because each group already has a path of 49

topaz saddle
#

ah ok

#

im not quite sure on how else to prove this

topaz saddle
#

or completely off

modern compass
#

take what you wrote, and don't connect the groups. There's nothing that says the groups need to be connected.

topaz saddle
#

im not connecting the groups anymore

modern compass
#

yes, you're complete graphs on 50 vertices is fine. But each group should be disconnected from eachother.

topaz saddle
#

disconnected

#

okok

#

will redo

modern compass
#

that works

cedar kilnBOT
#

@topaz saddle Has your question been resolved?

cedar kilnBOT
#
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sage oracle
cedar kilnBOT
sage oracle
#

I can't figure this one out

opaque root
#

Figure out what

sage oracle
#

I have to simplfiy it to one trig function

opaque root
#

Have u tried anything?

sage oracle
#

I have tried to do the math inside of the parentheses

opaque root
#

Show what u did

sage oracle
#

I did it on a random page in a notebook it is probably long gone I can quickly try doing it again though

opaque root
#

Ok do it again

bronze frost
#

$sin(x)=cos^2(x)-1$ ?

wraith daggerBOT
sage oracle
#

it isn't squared

bronze frost
#

ye

#

one sec

#

expand left two brackets first

#

then its pretty simple i think

opaque root
#

!nosols

cedar kilnBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

sage oracle
#

and I don't know how to do the math inside of the parentheses becauwse I am no realizing that I found a found denominator when they already had one

#

oh you cancled the cos and sec?

opaque root
bronze frost
#

1/cos x hence cos x * sec x = 1

bronze frost
sage oracle
#

I see how you got that

#

I just wrote it down

#

but then how do you mutiple the other things together

bronze frost
#

like this (a+b)(c+d) = ac + ad + bc + bd

#

have you done this sort of before?

sage oracle
#

probably a long time ago

bronze frost
#

so your equation is something like this

(a+b)(c+d)(e)

where a = 1, b = -cos, c = 1, etc ... you get the idea

so do the (c+d)(e) part first, find out its (cos x + 1)

now you have

(1 - cos x) ( cos x + 1)

#

from here you might be able spot this is something called the "difference of two sqaure"

#

so that is to say its
1 - cos^2 x

#

then we use the indetity $sin^2 x + cos^ 2x = 1$ to get that this is sin^2 x

sage oracle
#

yeah I think I see it

#

if we do that since it is now squared we can do the idenitiy so the answer is sin^2x

#

that helped a lot thank you

bronze frost
#

no problem, good luck

sage oracle
#

.close

cedar kilnBOT
#
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dire tundra
cedar kilnBOT
dire tundra
#

Why do use quotient rule

#

When finding for the change of V

#

Why couldn't I just take the derivative of r^3? Since I thought if there coefficient and a single variable that was possible?

stone mountain
cedar kilnBOT
#

@dire tundra Has your question been resolved?

livid hound
#

who's telling you to use quotient rule here?

cedar kilnBOT
#
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paper stone
#

Hey

cedar kilnBOT
paper stone
#

What is Pie

flint plinth
#

it is like cake

hollow trail
#

,w pie

wraith daggerBOT
hollow trail
#

that's a lot of calories

flint plinth
#

oddly specific for a generic "pie"

#

exactly 303 mg of sodium

#

what if it is a salt pie

cedar kilnBOT
#

@paper stone Has your question been resolved?

cedar kilnBOT
#
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β€’ Show your work, and if possible, explain where you are stuck.
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dusty raptor
#

would the correct answer be the first or 2nd photo?

raven shard
#

the first is definitely wrong

#

the second seems legit

dusty raptor
#

i shifted the n so that it would = 1

#

in the first one

#

but i couldve just been wrong w n in the beginning

#

2nd photo is before my shift

quaint totem
dusty raptor
#

YES

#

i have one more attempt

#

save me someone

quaint totem
#

im only in trig and im 8th so i cant rly help

#

sry lmao

#

wasit to practice another and see how webassign do it

dusty raptor
#

im gonna go for the 2nd one

quaint totem
#

alright gl

dusty raptor
#

I GOT IT RIGHT LETS GOOOOOOOOOOOO

#

.close

cedar kilnBOT
#
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cedar kilnBOT
#
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β€’ Show your work, and if possible, explain where you are stuck.
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slow fiber
#

How many ways are there to split 20 cookies among 4 friends
so that at least one of them gets at most 2 cookies? - could I have a hint

nimble mulch
#

How many ways are there to split 20 cookies among 4 friends if everyone gets >=3 cookies?

#

How many ways are there to split 20 cookies among 4 friends with at least one having <=2 cookies = the first line above minus the second line above

#

so you can regard the opposite case

#

if you know the amount of ways for the opposite case, then you also know how many there are for the case itself

#

is the procedure clear or does something remain vague? :)

slow fiber
nimble mulch
slow fiber
#

I see, so if we have n cookies and 4 friends but actually 3 friends, we should have something like

#

20 + 4 - 1 and from that pick 3

sharp frigate
#

at most

#

2 cookies

crimson sedge
#

im doing it manually right now

#

I hope im not wasting my time lmao and i dont make a mistake

#

Okay Im done I likely made a mistake somwehere but Ive got it at 60

#

Ill check to make sure I didnt make any mistakes but lmk if thats correct

sharp frigate
#

what no??? its literally the task

slow fiber
#

could you sort of giive me another hint

sharp frigate
#

OHHH

slow fiber
#

can you guys please go to another channel?

sharp frigate
#

sorry sorry

nimble mulch
#

How many ways are there to distribute the 20 cookies among four friends

crimson sedge
nimble mulch
slow fiber
#

is it not 20 pick 4

nimble mulch
#

so the friends may end up with the same amounts even if you distributed them in a different order

slow fiber
#

Ahh im really sorry

#

im still sort of confused

nimble mulch
#

because this problem is synonymous to placing 3 bars among 20 objects

#

which is the same as putting 20 objects into 4 groups

slow fiber
#

I never learned whatever this bars and stars thing is

nimble mulch
#

which means for the initial case you have C(20+4-1, 4-1) = C(23, 3)

nimble mulch
#

distributing objects

slow fiber
#

kinda what is bars and stars

nimble mulch
#

e.g. for a smaller sample size, let's look at 5 objects

#

and 3 groups

#

then we'd have 5 stars:

#

*****

#

and we can place 2 bars

#

to distribute them into 3 groups

#

for instance:

#

**|*|**

#

now the first group has 2

#

the second has 1

#

the third has 2

slow fiber
#

I understand that makes sense

nimble mulch
#

kk

#

and that's just like ordering objects which are equal

#

since we added 3 objects

slow fiber
nimble mulch
#

we have a total of 20+3 = 23

#

and we choose three positions

#

so C(23, 3)

nimble mulch
#

we have a total of 23 objects (20 stars, 3 bars) or equivalently: (20 cookies, 4 groups = 3 group separations)

nimble mulch
#

neat, and then we just choose three positions

slow fiber
#

we are on the same page

nimble mulch
#

which depending on which approach you like more

#

you can either do via combinations

#

so we choose three positions from among 23:

#

C(23, 3)

#

or via permutations:

#

we oder 23 objects, of which 20 are the same and 3 are the same:

#

23! / (20! * 3!)

#

whichever you feel is more intuitive you can choose :)

slow fiber
#

Hmm

#

Which might be easier to understand

nimble mulch
#

have you not had permutations / combinations yet?

slow fiber
#

Not in class, just really binomial

#

but ik the difference

#

one has order that matters, one doesnt

nimble mulch
#

kk, we can pick the permutations then, at least I find them easier in most cases

#

so the quick crashcourse on permutations are two different cases

#

you either order objects with repeating ones

#

or you order objects without repeating ones

#

for instance, take a password consisting of 5 symbols, each from 0-9

#

then that would be a permutation WITH repetitions

#

since we can use the same object (number) multiple types

#

and the amount of ways for that would be 10^5

#

since we have 10 objects

#

and 5 positions

#

so the first position has 10 options

#

the second position has 10 options

#

third as well

#

etc.

#

so the amount of ways = 10 * 10 * 10 * 10 * 10 = 10^5

slow fiber
nimble mulch
#

neat, and then come the permutations without repetitions

#

so for instance let's say we have 10 different letters

#

and we want to know the amount of ways to arrange them

#

well then the first position can have 10 different options

#

but the second position then only has 9, since one option will have been taken by the first position

#

meaning at the third position we have 8 options

#

and for the fourth position 7 options

#

etc.

#

amount of ways to order 10 objects at 10 positions = 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 = 10!

#

that principle is crucial

#

now what if we still have 10 letters, but only 5 positions?

#

well then again the first position has 10 options

#

second has 9 options

#

etc.

#

and the fifth position has 6 options

#

amount of ways to order 10 objects at 5 positions = 10 * 9 * 8 * 7 * 6

#

and the trick to write this in a smaller form is to write 10! / 5!

#

because the 5! get rid of the * 5 * 4 * 3 * 2 * 1 from the 10!

slow fiber
#

Okay cool sounds good

nimble mulch
#

ok and the last basic part is having duplicate objects

#

so for instance what if we want to order 10 letters at 10 positions

#

but 2 of them are the same

#

then the principle is to divide by n! where n is the size of the duplicate group

#

meaning here we have 10! / 2! ways to order them

#

another example: we want to arrange 10 letters, but 4 of them are the same and another 3 of them are the same

#

then there are 10! / (4! * 3!) ways to order them

#

and now you may also see the parallel to our former problem

#

we had 20 stars

#

3 bars

#

(or 20 cookies and 3 group divisions)

#

meaning we have 23 objects

#

of which 20 repeat

#

and 3 repeat

#

so the amount of ways to arrange them is 23! / (20! * 3!) <<< by permutation

#

= Amount of ways to distribute 20 cookies among 4 friends

#

so far clear right

slow fiber
#

Gotcha

nimble mulch
#

kk

#

now we can calculate the opposite case: Amount of ways to distribute 20 cookies among 4 friends where all of them have >=3 cookies

#

if all of them have at least 3 cookies, well then we can use that as our starting condition for the calculation

#

meaning each of the friends already has 3 cookies

#

and we only need to distribute 20 - 4 * 3 = 8 cookies

#

8 cookies among 4 friends

#

(8 stars & 3 bars)

#

just like before, there are 11! / (8! * 3!) ways to arrange them

#

was I too hasty or is it understandable

slow fiber
#

okay because 8 cookies to distribute freely, after you do 20 - 4 * 3 right

nimble mulch
#

yup!

#

we assume they already have 3 cookies each

#

so we only need to distribute 8 to know how many ways there are for that case

#

now you may wonder why we even did the above

#

it's because now when we have the opposite amount of ways

#

we can calculate the initial amount: Amount of ways to distribute 20 cookies among 4 friends where at least one of them has <= 2 cookies

#

I'll denote these three amount with letters so that I don't have to write the full sentences twice: :D

#

X: Amount of ways to distribute 20 cookies among 4 friends

#

Y: Amount of ways to distribute 20 cookies among 4 friends where all of them have >=3 cookies

#

Z: Amount of ways to distribute 20 cookies among 4 friends where at least one of them has <= 2 cookies

#

and then you may notice that X - Y = Z πŸ¦‡

#

which is the meaning behind the opposite case

#

because X are all ways to distribute them

#

Y are all ways IF NOT some condition

#

Z are all ways IF some condition

#

meaning Y + Z = X, or rewritten, X - Y = Z

#

and we're looking for Z!

slow fiber
#

This is such a good summary, I really appreciate you so. much right now

nimble mulch
#

np :)

#

so why did we not just directly calculate Z?

#

because it's actually a lot harder than calculating X & Y

#

so I highly recommend remembering this opposite approach

slow fiber
#

Yeah, that makes a lot of sense

#

Okay, I get the general idea. Im going to really think about this and then formulate my proof

#

thank you so so. much

nimble mulch
#

sure, here the inserted values btw:

#

X = 23! / (20! * 3!)

#

Y = 11! / (8! * 3!)

#

Z = 23! / (20! * 3!) - 11! / (8! * 3!)

#

and a little piece I just wrote as reward :P

#

gl!

slow fiber
#

thank you and nice piano!!!

#

This was so helpful, really i genuinely appreciate it

#

.close

cedar kilnBOT
#
Channel closed

Closed by @slow fiber

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#
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Remember:
β€’ Ask your math question in a clear, concise manner.
β€’ Show your work, and if possible, explain where you are stuck.
β€’ After 15 minutes, feel free to ping <@&286206848099549185>.
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Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lucid lantern
#

I js need help on how to do these problems like explaining it in details and stuff

winter apex
#

And you know that all 4 angles must add up to 360

#

So that means 360 - (59*2) = the top angles x2

lucid lantern
#

Which number is that one?

winter apex
#

#1

lucid lantern
#

Oh I got 121 for that

winter apex
#

It tells us the two sides are equal

#

121 is right, yeah

lucid lantern
#

Not sure if it was correct

#

Cuz I have a geo test tmrw I was js wondering if we can do one for each section

winter apex
#

Because 360 - 59*2 is 242,

242/2 = 121

lucid lantern
#

Can we do 3 for first section?

winter apex
#

Yeah

#

You know that the two side angles must add up to 180,

lucid lantern
#

Yeah I js wanna know like stepby step

winter apex
#

It gives you one side angle

lucid lantern
#

Yeah

winter apex
#

so 180-130=x

lucid lantern
#

You can keep talkin ima take notes

winter apex
#

You're good

#

#4 I'm not too sure why they're asking you about it, it's a rectangle on that side, so the angle has to be 90.

This is proven in #3, where both side angles must be 180, so if 1 is 90, then the other one is 180-90

lucid lantern
#

Mmm okay okay

lucid lantern
winter apex
#

#5 and #6 should be the same across both diagonals I would think

winter apex
lucid lantern
#

Mmm okay

winter apex
#

Sorry for the bad drawing

lucid lantern
#

Nah you’re good

#

So how do we get to 121 exactly? Like k know how but I js wanna know how you would do it

winter apex
#

Because WVY and WXY are identical

We know that 180-59 must solve for WVY

Another way of proving this is

360 - 59+59 must be equal to 2x such that

2x=242

Dividing both sides by 2 gives us x=121

lucid lantern
#

Mmmm

#

Is there any like tricks behind it to you get the answer?

winter apex
#

180 - 59 = 121

lucid lantern
#

Ohhh

winter apex
#

I just stated 2 ways, the 2nd one definitely more complicated for the same answer

lucid lantern
#

What about 4?

#

Or sorry 2

winter apex
#

The angles on the bottom and top are equal to eachother

lucid lantern
#

Right

winter apex
#

So x (?) is 145

lucid lantern
#

So we have to find x

winter apex
#

The answer would just be 145

#

Since the two angles are equal

lucid lantern
#

Ohhhhh

winter apex
#

I just said x as I use x for the answer

#

? = 145

lucid lantern
#

For 3 we have to find H right

winter apex
#

Yeah

#

What can you tell me about 3?

lucid lantern
#

Both side angles might be 180?

#

Or

winter apex
#

Yeah,

lucid lantern
#

Would it js be 90?

winter apex
#

Well on number 3, we have the angle 130

lucid lantern
#

Yeah

winter apex
#

So 130 + ? = 180

lucid lantern
#

50

winter apex
#

Yeah

lucid lantern
#

So it would be 50

winter apex
#

Yeah

lucid lantern
#

What about 5 or 6 in the next section how would you explain it

winter apex
#

The diagonal, assuming 2 sides are the same, will always be the same on both

lucid lantern
#

Right

winter apex
#

15 is your answer

lucid lantern
#

Oh is it js that?

winter apex
#

Yeah

lucid lantern
#

Is XV=YW?

winter apex
#

Yup

lucid lantern
#

Ohhh

#

Okay

#

We can do any for the last section

winter apex
#

I wanna look at 7 and 9

#

Starting with 7

#

Resending this so I don't have to scroll up lol

lucid lantern
#

Yeah np

winter apex
#

We know that SU and RT are the same

lucid lantern
#

Yes

winter apex
#

So 4x-3=13

lucid lantern
#

Why’s that?

winter apex
#

I didn't need to do that, sorry

#

Because 4x-3 is SU

#

We're solving for x

lucid lantern
#

No worries what if it’s not the same?

winter apex
#

We see that in 9

lucid lantern
#

Ohh

winter apex
#

Looking at 7 for now though

#

What can we do to solve for x on 4x-3=13

lucid lantern
winter apex
#

Yeah

#

Looking at 9

#

If we didn't have any equation in the top left

#

What would the angle have to be?

#

(Same as question 1)

lucid lantern
#

180?

winter apex
#

What about 180?

lucid lantern
#

I’m not sure how to explain it but like

#

I get the concept sort of

winter apex
#

If I asked you this

#

How would you solve for ?

lucid lantern
#

Mmm

winter apex
#

If angle F and angle G are the same

#

And G+H=180

#

How would you solve for F?

unkempt tartan
#

That's not the time for this, bro. We're here to talk about becoming an alpha, not geometry. Stay focused!

lucid lantern
#

Lemme take notes rq

#

What 😭

winter apex
#

You're good man

split crane
lucid lantern
#

E is also 75 but the inside adds up to 180 righ

split crane
#

Sorry for inturupting @winter apex

lucid lantern
#

180-75

#

So 105?

winter apex
#

Yeah

lucid lantern
#

Yeah?

winter apex
#

So, now bringing back the equation

unkempt tartan
lucid lantern
#

Wait is 105 right

unkempt tartan
#

I didn't realize it was running on this server

winter apex
#

24x+9 must equal 105

lucid lantern
#

Oh ok ok

unkempt tartan
#

I'll leave the server for rn until I get the issue fixed

#

Sorry everyone

winter apex
#

You're good zucc

lucid lantern
#

E and H is the same and F and G is the same

#

Righ

winter apex
#

Yeah

#

Looking at question 9

lucid lantern
#

But where did 24x comes from?

lucid lantern
winter apex
#

Look at question 9

#

You solved for the top right angle

#

But the equation on question 9 is 24x+9

lucid lantern
#

Ohh

winter apex
#

So 24x+9=105

lucid lantern
winter apex
#

Do you have access to calculators in geometry by chance?

lucid lantern
#

Wait why is it not

#

24x + 9 +75 = 180?

winter apex
#

It is

lucid lantern
winter apex
split crane
winter apex
lucid lantern
#

Ohhh

winter apex
lucid lantern
#

so it’s 180 - 84

winter apex
#

Yeah

#

24x=(180-84)

lucid lantern
#

Ohhh

#

Gimme a sec I’ll brb

winter apex
#

You're good

split crane
#

Wait so if number 9 is like that does that mean that number 10 would be 10x+21+79=180?

split crane
split crane
#

yea

winter apex
#

x=8

lucid lantern
#

But yeah we can use calculator

split crane
#

Plug in and find the value

winter apex
split crane
#

I hopped in here because I was also struglling with this topic thanks fcor the help bro I got a geo test

winter apex
#

You're good man

split crane
#

I think I get the texas ti 32 or sum

winter apex
#

Dang

#

Our school gives us TI84s, fancy graphing calculators lol

lucid lantern
winter apex
lucid lantern
#

But I think that’s it but idk can we do one more? I’m a lil worry

winter apex
#

Yeah sure, I can make one up real quick if you'd like

lucid lantern
#

Fs

#

Then you can explain it I’ll take notes

#

Also is it coo if I dm later if ion get a certain part?

lucid lantern
#

Bet bet

winter apex
#

@split crane Since you're also doing this, could you also solve this out?

split crane
#

yes ofc

winter apex
#

Wait 1 second

lucid lantern
#

Also added u

split crane
#

so would it not be

#

oh alr

winter apex
#

Sorry, I messed up the problem lol

#

Same concept but

split crane
#

lol its ok

#

Can I do the dollar sign to setup the equestion as a pic

#

equation

winter apex
#

Yeah sure

split crane
#

alr

winter apex
#

dollar sign on both sides

split crane
#

Messed up

winter apex
#

Here's one more

split crane
#

$so 4x+4+24=180$

wraith daggerBOT
#

Donutttt12344

split crane
#

$4x+28=180$

wraith daggerBOT
#

Donutttt12344

winter apex
#

Sorry, may I stop you rq?

split crane
#

yes ofc

winter apex
#

They are on the same side.. what can you tell me about those two angles?

split crane
#

there equal?

winter apex
#

Yeah

split crane
#

Wait so would I subtract like 180-4 -24?

winter apex
#

You don't need 180 here

split crane
#

omg

lucid lantern
#

Why tho?

winter apex
#

If they're equal, then

#

4x+4=24

lucid lantern
#

Ohhhh

split crane
#

T_T

#

x=6

winter apex
#

Almost

#

20/4

split crane
#

x=5

winter apex
#

Yeah

lucid lantern
#

So for that problem it’s x=5

split crane
#

48?

winter apex
split crane
#

wait 24

winter apex
#

You're solving for x here

split crane
#

oh

#

then its just 5

winter apex
#

Yeah

split crane
#

My b

winter apex
lucid lantern
#

That’s it right?

winter apex
#

Yeah

#

Here's another one

split crane
#

lets go

winter apex
#

This is gonna be a bigger number

split crane
#

so this would use 180 correct?

winter apex
#

Yeah

lucid lantern
#

So 6x-12=60?

#

Oh wait

split crane
#

6x-12+60=180

lucid lantern
#

Why would this one use 180?

split crane
#

x=22?

split crane
winter apex
#

A+B=180

#

B=C

#

A=D

#

So, we can infer that

#

A+C=180

#

Since B and C are the same

#

A + (B or C) = 180

split crane
#

My head is actually exploding

winter apex
#

Yeah

lucid lantern
#

Ohhh

winter apex
#

I'm sorry if I'm going too fast

lucid lantern
#

Nah you’re good

split crane
#

yea you good

winter apex
#

If I had asked you this

#

How would you solve it (Bom)

split crane
#

we could like solve one seperate from each other and not put are answer and wait till were both ready?

lucid lantern
#

Lemme write it gimme a sec

split crane
#

Bom that good wit you

winter apex
#

Let me help Bom real quick with this one and I'll send two problems seperate

split crane
#

yea I gotchu

lucid lantern
#

So I’ll js do this and I’ll come back and see the steps by steps y’all did?

split crane
#

alr

lucid lantern
#

Y’all can keep goin I gotta change rn

winter apex
# winter apex

@lucid lantern

We know that A+B must be equal to 180 as the angles is turning around

Logically, if you were following the line, if you turn on A and B, you'd be making a 180 turn

lucid lantern
#

I’ll come back and do the problem Ina bit

winter apex
#

So 180-60 must equal x

#

Now, the equation states that 6x-12=B

#

And since B is 120,

#

6x-12=120

lucid lantern
#

120?

#

Ohhh

#

Right

winter apex
#

Add 12 from both sides gives you

6x=132

split crane
#

wait so that mean if you add 12 to 120 it equals 132 then devide by 6 to get 22

lucid lantern
#

18

#

?

split crane
winter apex
#

You're right

#

Sorry

winter apex
#

Sorry, I made a small mistake

#

Add to both sides

lucid lantern
winter apex
#

Yeah I can rq

split crane
#

$6x-12=120$

wraith daggerBOT
#

Donutttt12344

lucid lantern
#

Ohhh

split crane
#

$120+12=132$

wraith daggerBOT
#

Donutttt12344

split crane
#

$6x=132/6=22$

wraith daggerBOT
#

Donutttt12344

winter apex
#

You know that A+C = 180

#

So $60+6x-12=180$

wraith daggerBOT
#

Unparalleled

lucid lantern
#

Ohh okay tysm

#

I’ll come back if anything confuses me

winter apex
#

Of course, always here if I can help

#

Want a slightly harder one Donut?

split crane
#

I came in here not knowing the slightest bit of how to do this

#

you tought everything I know about this lol

split crane
winter apex
split crane
#

so

#

c=180

#

$4x+7+72=180$

wraith daggerBOT
#

Donutttt12344

split crane
#

$4x+39$

wraith daggerBOT
#

Donutttt12344

split crane
#

=180\

#

=180

#

$180-39$

wraith daggerBOT
#

Donutttt12344

winter apex
#

Sorry, may I ask where 39 came from?

split crane
#

Tbh I have no clue lol

#

it shoulve been 72+7

#

79

split crane
#

$4x=101$

wraith daggerBOT
#

Donutttt12344

split crane
#

$4x/4=101/4=25.25?$

wraith daggerBOT
#

Donutttt12344

split crane
#

decimal

winter apex
#

Yup :3

split crane
#

W

#

This test finna be easy

#

unless if it has these

#

lemme get a pic

winter apex
#

This is how I've been making them lol

#

I'm just plugging numbers in and seeing if it works nicely

winter apex
split crane
#

these are my enemy

#

I HATE THEM

winter apex
#

Those suck]

split crane
#

ikr

winter apex
#

$5y-1=5x+9$

wraith daggerBOT
#

Unparalleled

split crane
#

lemme cook rq

winter apex
#

$5y=5x+8$

wraith daggerBOT
#

Unparalleled

split crane
#

..

winter apex
#

Oh wait

#

It tells us it's 116

split crane
#

is that a 180 degree realtion

winter apex
#

I was solving it like a system of equations, my bad dude

split crane
#

you good

#

so would it be a supp relation

#

with 116

winter apex
#

$5y-1=116$

#

$5x+9=116$

wraith daggerBOT
#

Unparalleled

#

Unparalleled

split crane
#

OH

#

wait thats light work

winter apex
#

Yeah

#

Works out nicely

split crane
#

wait so just the setup part is scary

winter apex
#

The setup isn't that bad

split crane
#

you know what the Triangle sum therom is?