help-13

[nimble ibex]

so my current equation is

35^2 / 2= v^2 / 2 +mgrsin(theta)

which i can rearrange to get v^2 = 35^2-25g sin(theta)

[rich field]

im getting this

[nimble ibex]

so using mv^2/r that should get me R right?

[rich field]

and the normal

normal + mv²/r = R

[nimble ibex]

whats the normal?

ah

[rich field]

youll get mgsin theta

[nimble ibex]

mgsin(theta)

rightttt

[rich field]

yeah

[nimble ibex]

and that makes the three

thank you

[rich field]

yeah

[nimble ibex]

Have a great day!

[rich field]

same to you!

[nimble ibex]

.close

[cedar kiln]

Channel closed

Closed by @nimble ibex

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[marsh pond]

Any suggestions for how to solve?

parallel, not perpendicular

.close

[cedar kiln]

Channel closed

Closed by @marsh pond

Use .reopen if this was a mistake.

[crimson sedge]

big hint: the normal of the parallel plane is also the normal of the plane you want to find

[marsh pond]

.reopen

[cedar kiln]

✅

[marsh pond]

wait so couldn't I just copy the exact same plane equation and just change the constant?

or would it only work with a certain constant

due to the point

I think I understand now

we just need to find the constant, that's all that will change

but not any constant

i will do the math to find that

.close

[cedar kiln]

Channel closed

Closed by @marsh pond

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[winged grail]

Did I do this right?

[muted bear]

sounds good

[nimble mountain]

sounds

[muted bear]

good

[crimson sedge]

can anyone expain the logic behind it ? i can't understand how he did it

[nimble mountain]

consider a rectangle

[crimson sedge]

aah got it

thanks

[nimble mountain]

[winged grail]

Alr thanks everyone

[nimble mountain]

[winged grail]

.close

[cedar kiln]

Channel closed

Closed by @winged grail

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[meager pike]

Anyone understand this

I'm talking about the calculations

Lol

.close

[cedar kiln]

Channel closed

Closed by @meager pike

Use .reopen if this was a mistake.

[mighty drift]

yeah we all just pretend to
Welcome

nah jk, but sometimes it do be like that

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tranquil arch]

how do you show that in a normed space $(X, |\cdot |)$ over the field $\mathbb{K}$, the sequence $(\alpha_n x)_n \to y$ where $\alpha_n \in \mathbb{K}$, $x\in X$ must mean that $y$ is a scalar multiple of $x$

[wraith dagger]

CoolShot

[tranquil arch]

i.e. a sequence of scalar multiples of a vector (if it converges) must converge to a scalar multiple of the vector

[mighty drift]

this is equivalent to saying that a 1D vector space is closed

[mighty drift]

there's many ways to go about proving this

for instance, that linear maps are continuous, and for every subspace, you can represent it as the kernel of a linear map

[tranquil arch]

i attempted a basic proof but couldnt really finish it

i should have probably mentioned K = R or C this would probably simplify it

but then i think i can show that a_n is convergent

[tranquil arch]

would this approach work?

[mighty drift]

do you know that ax -> a is continuous (with domain the line generated by x) ?

[mighty drift]

if you can show this, it works

[tranquil arch]

well |a_n - a_m| ||x|| = || a_n x - a_m x || = || a_n x - y + y - a_m x || ≤ || a_n x - y || + || a_m x - y || which is bounded by some positive number after some N, so |a_n - a_m| is cauchy and C is complete, so convergent

i feel like im making some mistake here but i cant find one

[mighty drift]

it's not the sequence of differences that is cauchy

[tranquil arch]

oh oops its just a_n that is cauchy

[mighty drift]

being explicit about that "some positive number" being any positive epsilon, no matter how small
Otherwise it doesn't imply Cauchy ?

[tranquil arch]

yes right

i guess the problem is that ||x|| must be positive here

if it is zero then it works anyway but this works for positive

ok then thanks i figured the proof out

.close

[cedar kiln]

Channel closed

Closed by @tranquil arch

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[smoky heart]

A+b+c

[idle tusk]

original problem pls

[smoky heart]

(a+b+c)^2

[idle tusk]

!xy

[cedar kiln]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[idle tusk]

do you need to simplify

[smoky heart]

Yes

[idle tusk]

hint: (a+b+c)^2 = ((a+b)+c)^2

first consider (a+b) as an atomic thing

then use (x+y)^2 = x^2 + 2xy + y^2

[cedar kiln]

@smoky heart Has your question been resolved?

[river steppe]

этот сервер предназначен для плохих слов

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[charred hedge]

Not sure what differential equation to make with this info

can anyone help?

[upper abyss]

Differentiate the equation for the track, in terms of t.

[charred hedge]

ah I see

Thank you

.close

[cedar kiln]

Channel closed

Closed by @charred hedge

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sharp lotus]

so i think it helps if you think about multiplication of the complex numbers as being a dilation (like a streteching) together with a rotation

and when you write the numbers in that re^i theta form you can see immediately what the stretching factor is and what the rotation is

so if you have two numbers and you multiply them together (z and w) you would basically be multiplying their "r's" and adding their angles

so z * z would become r^2 e^(i (theta+ theta))

so what would be the magnitude (the r) in front of z^5 ?

yeah exactly, but the problem is also giving that z^5 = 2z which we can write as 2re^itheta, so this basically gives is r^5 = 2r

so we know from one hand the magnitude of z^5 is r^5, but we are also that the magnitude is 2r

since the magnitude of the number 2z is just twice that of z

i dont understand the left side of your equation

$z=re^{i\theta}$

[wraith dagger]

Soosh

[sharp lotus]

so when we raise to 5th power, because of thinking independently of the "dilation of the magnitude and addition of the angles" we can think of it as:

$z^5=(r)(r)(r)(r)(r)e^{i(\theta+\theta+\theta+\theta+\theta)}=r^5e^{i5\theta}$

[wraith dagger]

Soosh

[sharp lotus]

but we are also given z^5 = 2z, namely z^5 is a complex number that if you think of it as a R2 vector is in the same direction as z, which isn't trivial because most complex numbers when you are raising them to a power will be rotating them to some other random direction, but the magnitude is twice as much

$r^5e^{i5\theta}=2z=2re^{i\theta}$

[wraith dagger]

Soosh

[sharp lotus]

so all were doing now is like matching up the magnitudes (r^5 = 2r)

you can factor

and keep in mind r is real and positive

r^5 -2r = 0
r(r^4-2) = 0
now use diff. of squares:
r(r^2-sqrt 2 )(r^2+sqrt 2) = 0

so the right factor can't give us any real positive roots we can ignore that as well as r = 0 so look at
r^2 - sqr 2 = 0
use diff of squares again
(r - 4th root of 2)(r + 4th root 2) = 0
and the only positive real root seems to be r = 4th root of 2

[sharp lotus]

now for theta, probably technically i shouldnt write theta on the right side of this, cause really whats happening is we are rotating by theta and we've gone all the way through 2pi and now come out to the same angle if that makes sense

and the problem gives you some range of values for theta

0 < theta < 2 so you know you are rotating counter clockwise (positive radians direction) with every multiplication

so you have something like 5theta = theta + 2pi
or 5theta = theta + 4pi
etc

but if theta < 2 you can't get all the way up to 4pi so basically the only option is
$5\theta = \theta + 2\pi$

[wraith dagger]

Soosh

[sharp lotus]

and thats easy to solve for theta

so basically z is some complex number where the angle is in first quadrant

when we are multiplying it by itself, we basically are adding some counterclockwise rotation of theta and also styretching (see every z^2 etc is growing in length until z^5 will be in the exact same direction as z but twice as long)

yeah so if 0 < theta < 2
then 0 < 5theta < 10

4pi = ~12 something so, this angle cannot possibly have made 2 full turns (4pi) is what i was trying to say

theta < 2 is given in the problem statement

so the only equation that would be valid would be 5theta = theta + 2pi

and that just gives us theta = pi/4 which checks out (i drew it with pi/4 in mind also, that's just at 45 degrees between the axes)

anyway long story short, this problem shows why this re^itheta form is useful and interesting with complex numbers, because when you are multiplying two numbers together you can directly see oh i just multiply their magnitudes together, add up their angles and thats the result of the multiplication, which you cannot see in the a+ bi form directly

but geometrically this is what multiplying two complex numbers is: a dilation/stretch + a rotation

oh im dumb lol

[sharp lotus]

ok actually do the math correctly on this ^

4theta = 2pi, theta = pi/2 lol

i dunno why i was drawing pi/4 but was doing rotations of pi/2

but er yeah z is actually along y axis and then yeah its angle is pi/2 and each rotation is pi/2, oops

😅

it isnt though!

pi is 180 =\

but degrees are kinda crappy

worth getting used to radians

after basic geometry everything is just radians and for good reason 😄

its nice because for example:
if you have some angle theta around unit circle, then the arc length associated with that is the exact same measure

arc length of pi/2 radian angle is also just pi/2 length etc.

circle of radius 1, what the whole sin \ cos thing is based on

cos being the values of x of points on the unit circle and sin being the values of y of the points

for the unit circle yes

[cedar kiln]

Channel closed

Closed by @vagrant sedge

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cedar kiln]

@scarlet prism Has your question been resolved?

[scarlet prism]

<@&286206848099549185>

[cedar kiln]

@scarlet prism Has your question been resolved?

[cedar kiln]

@scarlet prism Has your question been resolved?

Channel closed

Closed by @scarlet prism

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

i dont really know what to do

This is new to me

<@&286206848099549185> I don't get it

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[limber basin]

Why is pt s not x,-y but x,y?

[cerulean sail]

,rccw

[limber basin]

any clues 🥲

[cerulean sail]

"Just because", basically(!) It's the point they chose to start off with, so they chose to label it as (x,y)

[limber basin]

So it doesnt matter, i can treat it as x, -y?

[cerulean sail]

Wellllll, for the purposes of what they're asking you, not really: you're starting at S, not P

(if it was more general, then you could)

[limber basin]

So what would the other coords be 😭

[limber basin]

Like would point p be the opposite of s and it would be x, -y… 😭

[cerulean sail]

Yep, point P would end up being (x, -y)

[limber basin]

I suppose q is -x, y then

-x,-y

[cerulean sail]

Yep

[limber basin]

Okk thanks

.close

[cedar kiln]

Channel closed

Closed by @limber basin

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cedar kiln]

@long crow Has your question been resolved?

[long crow]

can someone help guide me im not sure what to do exactly. I suspect i need to take the laplace transform of P(D) but im not sure where to start. if someone could give me the first few steps i think i may be good...

[short blade]

well they tell you how to do it

use induction

consider the case where P(D) is of 0th order and prove the equality is true
then assume the above is true for P(D) of nth order, and prove it is true for n+1th order

[long crow]

i forgot how to use induction

[short blade]

https://www.khanacademy.org/math/algebra-home/alg-series-and-induction/alg-induction/v/proof-by-induction
if you feel like watching a video about it this is a good one. otherwise you can wait and hopefully someone will explain induction

[long crow]

Wait so for 0th order wouldnt it be equivalent to the laplace of y wrt s? Which eould just be equal to t? Is this related to the laplace transform of polynomials which is n factorial over s to the n plus. 1?

[cedar kiln]

@long crow Has your question been resolved?

[cedar kiln]

@long crow Has your question been resolved?

[long crow]

.close

[cedar kiln]

Channel closed

Closed by @long crow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

hint: at its peak the velocity is 0

[feral heart]

ah~ so...

304?

[crimson sedge]

no

so first of all

take the derivative of h(t) so you can get the vertical velocity

[feral heart]

oh

so 0=-4.90^(2) + 3610+304.

[crimson sedge]

no

[feral heart]

or 0=-4.9t^(2) + 361t+304.

[crimson sedge]

still no

you haven't taken the derivative

[feral heart]

oh...I am really dumb give a sec to look everything over again

[crimson sedge]

,, \dv t\9[\Big]{-4.9t^2 + 361t +304} = {???}

[feral heart]

74.50 is my new time so do I plug that tim for t? is that what your saying?

[crimson sedge]

do you know derivatives

or no

[feral heart]

kinda

[crimson sedge]

so we know h(t)

but we don't know v(t)

v(t) = h'(t)

so we take rhe derivative of h to get v(t)

and then we find t from v(t) = 0 which is t_1 for example

and then evaluate h(t_1)

[feral heart]

ok

[crimson sedge]

that's the entire question's steps

[crimson sedge]

so like, i guess i need to ask you again what do u think this is

this is also a kinematic equation if you dont want derivatives

[feral heart]

witch kinematic equation? I know that better.

[crimson sedge]

aight

,, \6ht = h_0 + v_0t - \412gt^2

[feral heart]

I need to say this just be sure but what I am working on is Graphing Quadratics

[crimson sedge]

you dont need to graph anything

[feral heart]

yeah but this is a Graphing Quadratics thing that it falls under

[crimson sedge]

i mean the question seems purely algebraic. You can directly find the vertex of the quadratic without all the stuff we did but that doesn't seem really intuitive for me

but you can graph h(t) in desmos and see where it peaks if you want that

[feral heart]

ah if it will help get the answer then sure

[crimson sedge]

for the quadratic $\6fx = ax^2 + bx + c$ the vertex of the quadratic is [
x_{\t{ver.}} = -\4b{2a}
]

[crimson sedge]

if you want like a direct plug and chug you can do this

[feral heart]

now this makes sense

h(t)=-4.9t^(2) + 361t+304

=-361/2(4.9)=-36.83673469

lol 69

[crimson sedge]

[feral heart]

is that wrong?!?!?!?

[crimson sedge]

you missed a - there

[feral heart]

where?

[crimson sedge]

a = -4.9

[feral heart]

oh~

=-361/2(-4.9)=36.83673469

[crimson sedge]

aight

[feral heart]

there we go that looks better

[crimson sedge]

evaluate h(36.837)

and that's it

nop

[feral heart]

ah!

[crimson sedge]

t = 36.837

[feral heart]

right I mean to write that lol 😅

-4.936.837^(2) + 36136.837+304= 6953.030119

[crimson sedge]

aight

lets verify

,w maximise -4.9x^2 +361x + 304

[feral heart]

but Round answer to 2 decimal places it be 6953.03

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by qylooo

[crimson sedge]

,w evaluate 681397/98

[feral heart]

oh I hate math~

lol 69

[crimson sedge]

ok so 6953

[feral heart]

I will put that in lol

[crimson sedge]

no

waiy

[feral heart]

get it~?

it was pun

lol

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by qylooo

[crimson sedge]

yeah 6953.03 is correct

[feral heart]

yeah I got this

[crimson sedge]

now pray your school's obsession with significant figures and rounding doesnt bite you in the ass

try with the .03

[feral heart]

ok

IT ALL GOOD!!!!!!

[crimson sedge]

WOOOO

[feral heart]

Sorry for being so dumb! 😂

[crimson sedge]

nah its okay

[feral heart]

69 saves the day!

[crimson sedge]

btw you know the vertex of a quadratic so this was like a direct plug and chug but if you have some random function instead here and you need to minimise/maximise it you havr to use derivatives and whatnot

so you shuld learn that

[crimson sedge]

[royal loom]

nice

[feral heart]

Who are you?!?!?!?!

[royal loom]

Austin

[feral heart]

lol well, bye Austin and Qylo I will close now. Thank you for helping a dumb person like me! ❤️

[royal loom]

Glad I could help

[feral heart]

/close

[royal loom]

.end

[feral heart]

?close

[royal loom]

/end

[feral heart]

.close

[cedar kiln]

Channel closed

Closed by @feral heart

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lavish perch]

Hi guys. Please can someone help me solve this?

[late lotus]

It’s basically sum of previous two terms + 5

I think you got that

Whats the problem

[lavish perch]

Okay thank you very much I was just making sure that I’m on the right track. Thank you kindly I’m extremely grateful for your help 🙏🏼🙏🏼🙏🏼🙏🏼🙏🏼

[sharp lotus]

i think you need to double check the top 2 rows though (the first row you wrote in seems fine), you have 26 and 28 there so what is 26 + 28 + 5?

[lavish perch]

It would be 59 🙏🏼

[late lotus]

The handwriting is beautiful

[lavish perch]

Then 28+34+5 will be 67

[lavish perch]

Really bad so sorry about that

[late lotus]

It’s ok as long as the answer is correct

[cedar kiln]

@lavish perch Has your question been resolved?

Channel closed

Closed by @lavish perch

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid tiger]

can someone please tell me what i am supposed to do here I cant sit here and answer a million questions i have an exam in two days and i really need to move on from this practice exam question

[cedar kiln]

Please don't occupy multiple help channels.

[timid tiger]

<@&286206848099549185>

[covert talon]

IDK

[hot crag]

!15m

[cedar kiln]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[hot crag]

please don't ping us that early

[sharp lotus]

it would also help if you posted the whole question 😐

all you've posted is some premise without a question

[timid tiger]

oh mb

[short blade]

what are r1 and r2

[cedar kiln]

@timid tiger Has your question been resolved?

[timid tiger]

this is the question <@&286206848099549185>

[desert musk]

U can apply the formula for magnitude of cross and dot product.

[short blade]

there is an equation that relates a dot product to the angle between the vectors

do you know what that is?

[timid tiger]

ok yes i did this but there is always a piece missing

for example if i use the cos one

its root 2= [v][u]costheta

if i use the sin one its

root6=[v][u]sintheta

[short blade]

right

[desert musk]

Divide both

[short blade]

divide the two equations

root 6/root 2 = tan(theta)

[timid tiger]

ohhhhhh

so theta=arctan root6/root2?

[short blade]

yes

[timid tiger]

omg ty

nice

that makes sense

[desert musk]

Respectfully there is minus too

[short blade]

missed that, but yes there is a negative sign on the root2

[timid tiger]

ok wait wym there is a negative on the root 2

oh

i see now nvm

ty

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[still fable]

Hey

[still fable]

How I can solve this

[cedar kiln]

@still fable Has your question been resolved?

[still fable]

<@&286206848099549185>

[covert talon]

what this.

[still fable]

Integral

[covert talon]

not clear. the number and X

[still fable]

What you mean

Sry, I don’t speak English

I hope you can help me find the integral

[covert talon]

i mean. is there a clear and complete integral. i cannt see

[still fable]

I mean this option was given to us by the teacher, I don't know how to proceed. I wanted to decompose the denominator, but I can't do it

[covert talon]

correct？

[still fable]

Yep

[covert talon]

wtf. so complex https://www.integral-calculator.com/

[still fable]

She gave us number 4. A = 4 and B = 6. I hope I got to that right

[covert talon]

my godness.

anyone made it.

[still fable]

I did the first and second task

but I can't do the third and fourth

Ohh

<@&286206848099549185>

[cedar kiln]

@still fable Has your question been resolved?

[still fable]

<@&286206848099549185>

[cedar kiln]

@still fable Has your question been resolved?

[cedar kiln]

@still fable Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rugged kestrel]

I was able to show and conclude all that, I was just wondering, if I have T(x)=Ax, can I write
T^-1 as T^-1(x)= A^-1 x ?

it might be a rlly basic question, im j making sure

[cedar kiln]

@rugged kestrel Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dim terrace]

How do you do normal distribution on your fx-991ex calculator for this question:

[cedar kiln]

@dim terrace Has your question been resolved?

[cedar kiln]

@dim terrace Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[royal loom]

you're not nawal..

[solid juniper]

lmao

[royal loom]

[crimson sedge]

do you know $\ds y = y_0 + v_{0y}t -\412gt^2$

[pearl palm]

damn physics

[crimson sedge]

its a kinematic equation yes

[pearl palm]

only chapter of physics i like is optics

and electricity

[crimson sedge]

so basically, you want to find when the ball hits again

meaning when y = 0

(vertical height is 0 metres)

so your problem is $\ds y_0 + v_{0y}t -\412gt^2 = 0$

[crimson sedge]

set the origin to be 0 and y_0 disappears

you want to find the time now

initial height

you can define it however you want, y_0 = 0 is fine here

yes

v_0y is the initial speed in the vertical direction specifically

since velocity is a vector

you flipped them here

yeah

also

it's not -9.8

the - next to the 1/2 already implicitly deals with the direction of gravity

,w 27sin(60 degrees)t -1/2(9.8)t^2 = 0

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by qylooo

[crimson sedge]

u messed up

[cedar kiln]

Channel closed

Closed by @vagrant sedge

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[thin compass]

how to do this im losing my mind

[cedar kiln]

@thin compass Has your question been resolved?

[thin compass]

<@&286206848099549185>

[dapper raven]

Is T just defined as the transpose or the matrix to the power of T?

[thin compass]

transpose

[dapper raven]

the nullspace of transpose is just a single matrix

and i think you can just use the standard basis for the range right?

because transpose reaches everything in M

[thin compass]

then what about these

b23

[dapper raven]

the nullspace is all vectors x1 x2 x3 where all those entries are equal to 0

x1 + 2x2 = 0

and x2 +x3 = 0

and -x1 + 2x3 = 0

any vector in R3 satisfying those equations is in the nullspace

and then using those equations you can find a proportion of the entries

and then define a basis for them using independent entries

[thin compass]

this is so far what i did

im stuck

[dapper raven]

you now have 4 equations to solve

and solving those will give you the proportions for x1, x2, and x3

which in that proportion

for example, not the answer, but it would be something like any multiple of (2,3,7)

which in this case immediately gives a basis

but in your case it might not

and you have to decide on a basis

for example you could have

that in order for the image of the vector to be the zero vector there is a relation between x1 and x2 which might be 2:1 so one of the basis vectors is (2,1,0) and then the other one is just (0,0,1) to complete the basis

in your case there is a single basis vector spanning the entire nullspace

i hope that helps

[thin compass]

uh

i dont understand the null part

[dapper raven]

ok so your image of the map

is a matrix

with the four entries

and in order to get the 0 matrix

all entries need to be 0

and when the output is the 0 matrix the input is the nullspace

aka kernel

of a map

that make sense?

[thin compass]

yes

[dapper raven]

right so you know that the output matrix has to equal 0 in all entries

meaning

$x_1 + 2 x_2 = 0$ and $-x_1 + 2 x_3 = 0$ and $x_2 + x_3 = 0$ and $x_1 + 2 x_2 = 0$ again

[wraith dagger]

Katharine

[dapper raven]

still good?

[thin compass]

ye

[dapper raven]

ok so in order for the vector $(x_1, x_2, x_3)$ to be in the nullspace of $L$ the entries: $x_1$, $x_2$, and $x_3$ have to fulfil those equations

[wraith dagger]

Katharine

[thin compass]

ye

[dapper raven]

which means for example

lets take the first equation

$x_1 = -2 x_2$

[wraith dagger]

Katharine

[dapper raven]

so the vector has to at least be

$(-2 x_2, x_2, x_3)$

[wraith dagger]

Katharine

[dapper raven]

that make sense?

[thin compass]

ye

[dapper raven]

next equation

$x_1 = 2 x_3$

[wraith dagger]

Katharine

[dapper raven]

meaning the vector is of the form

[thin compass]

ah ok

[dapper raven]

$(-2 x_2, x_2, - x_2)$

[wraith dagger]

Katharine

[dapper raven]

and in the answers they chose x_2 to be -1

but you can choose it to be anything

[thin compass]

ah okok

so there does not need to be a fixed answer for null

[dapper raven]

what do you mean?

[thin compass]

like this part can have different answers

[dapper raven]

yes as long as they fulfil this

this is because you are asked to give a basis

and a basis multiplied by 2 is also a basis

or -1

or 7985034752098347509283475

although the last one might be completely infuriating to work with

[thin compass]

okok

[dapper raven]

as long as your answer is

[thin compass]

wait quick recap of how i do these type of questions

[dapper raven]

$\lambda \begin{pmatrix} 2 \ -1 \ 1 \end{pmatrix}$

[wraith dagger]

Katharine

[dapper raven]

if your answer can be written as this

then you have given the correct basis vector

a correct basis vector

and the correct basis

[thin compass]

okk

[dapper raven]

what you want to do for these type of questions

is figure out what the nullspace is

in terms of relations between entries of vectors

or maybe it is clear that only a single matrix can give you the 0 matrix

like in the first question

try to find the nullspace

[thin compass]

what about the range

[dapper raven]

and after you understand what it is

similar idea

try to find it and understand it

and when you understand it you can try to find a basis for it

[thin compass]

ok

[dapper raven]

what you did in b23 was not bad

[thin compass]

how would u do it

[dapper raven]

for the nullspace i would do it like i explained

for the range i would basically try to do what you did

[thin compass]

okok

[dapper raven]

and look for linear dependency

i don't know if you saw it but you can represent 1 of the 3 found matrices as a linear combination of the other 2

which is why the basis of the range has 2 matrices

instead of three or more

because you get three out

and 1 is linearly dependent on the other 2

[thin compass]

ahh i see ok

ty

[cedar kiln]

@thin compass Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[eager wraith]

how would we factor 10w^2 - 31w + 15

[eager wraith]

<@&286206848099549185>

oh wait i forgot

it’s 15 mins

[brittle terrace]

do you know vietas formula

sum of roots = -b/a
product of roots = c/a

[eager wraith]

no but basically were taught to find it by finding the possible factors

i’ll send an image

but i don’t get

like i did all the factors

oh

wait

hold up

gimme a sec

ik what i did wrong i think

wait yea no i don’t get it

ok wait i gtg actually

[cedar kiln]

@eager wraith Has your question been resolved?

[eager wraith]

no you educational brat

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[upper abyss]

You could reasonably add the 15 terms here

Oh wait, that says k = 5 on the bottom. That's weird, there's no k in there

Or maybe 3n + 26 is supposed to be a constant, and you're adding that constant to itself 15 times

[cedar kiln]

Channel closed

Closed by @slender bridge

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[echo cedar]

hello i need help with bernoulli equation

[echo cedar]

how do i solve for v2

<@&286206848099549185>

[cedar kiln]

@echo cedar Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sturdy ferry]

Someone help

[dawn umbra]

Try this

[sturdy ferry]

Ok

[dawn umbra]

Try to bring rhs to LHS and try proving it to be 0

[sturdy ferry]

Uh

[raven shard]

ur generally not allowed to do that

[dawn umbra]

Oh.

[sturdy ferry]

My teacher always showed us to make one side equal to the other

[raven shard]

for these kinds of proof problems ur supposed to only manipulate one side

[sturdy ferry]

Yeah

Word

So what do I do

[dawn umbra]

Ok then

Let's see

[sturdy ferry]

I’m lost

[dawn umbra]

Cot²x is?

[sturdy ferry]

Cos squared over sin squared

[dawn umbra]

Cos²x/sin²x right?

[raven shard]

on LHS i suggest convert everything into sine and cosine

[dawn umbra]

Yes

Try

[raven shard]

after that u can prob do it on ur own

in general, when working with tan/cot/sec/csc, it is a good idea to convert into sine and cosine

[sturdy ferry]

Ok but can you stay with me just in case

[dawn umbra]

Now take cos²x common on the numerator

[sturdy ferry]

And like check my work

Ok I’m stuck

[dawn umbra]

What do you get?

[sturdy ferry]

This

Should I get common denominators

[dawn umbra]

Take cos²x common

Yes

[sturdy ferry]

Ok

Like this?

[dawn umbra]

What do you get

That's not what I mean by taking cos²x common

[sturdy ferry]

How is that common

Bro who is this

[dawn umbra]

Say (a³/c)+(a²/d)

[sturdy ferry]

Excuse me you’re trespassing into this channel

It’s OCCUPIED

[modern gull]

ahh i just joined i didnt know

[sturdy ferry]

Nah I’m kidding

[modern gull]

im very sorry. my apologies

[sturdy ferry]

Apology accepted

Don’t let it happen again

Anyways Vincent

[dawn umbra]

If I take a² common, it would be a²{(a/c)+(1/d)}

[sturdy ferry]

Ah

[dawn umbra]

What do you call it in your country?

[sturdy ferry]

I’m gonna be honest I got no clue what you’re saying

I’m from America

[dawn umbra]

💀👍

But.

Did you understand what I meant by taking common

[sturdy ferry]

Nope

You give me college professor vibes

[dawn umbra]

What I mean to say is that a/b+a/c is the same as a(1/b+1/c)

Perhaps paper might help?

[sturdy ferry]

Nah bro imma chat gpt this John

Oh yeah

I get what you’re saying

[dawn umbra]

Yes

Now that we're clear, let's proceed

You have (cos²x/sin²x)-cos²x

You can have cos²x common

[sturdy ferry]

Hey Vincent

Uh my mom is calling me

Thanks for helping me have a great night

[dawn umbra]

[cedar kiln]

@sturdy ferry Has your question been resolved?

Channel closed

Closed by @sturdy ferry

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lean oar]

need help solving this

[lean oar]

Formulas

[cedar kiln]

@lean oar Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lethal burrow]

Idk how to find the explicit form.
The implicit form is : (5y²+4)½/5 = x²/2 + C
from 2- a)

<@&286206848099549185>

[tawny grove]

hi

can you translate the problem?

[lethal burrow]

i just explained it ...

[tawny grove]

the problem looks like calculus with derivatives

do you mean implicit differentiation? or...

I'm not sure what' you're asking about

[dawn umbra]

They mean to find y I guess

That's explicit form

[lethal burrow]

yes

[lethal burrow]

I want the explicit form

[tawny grove]

oh so nothing to do with the calculus?

[lethal burrow]

did u do the differential equation ?

[tawny grove]

what do you mean did I do the differential equaiton?

[dawn umbra]

Which question from the page, I don't seem to find it

[lethal burrow]

The question is not that important.

I already find the implicit form.

But i got stuck to find the explicit form.

[dawn umbra]

That all is left is to simplify

[lethal burrow]

Imma send a photo of what i did

[dawn umbra]

Yes please

[lethal burrow]

.rotate

how to rotate ?

,rotate

[lethal burrow]

@dawn umbra

i got stuck after this

[dawn umbra]

Lord.

Yeah

Just take the square root yeah?

[lethal burrow]

u see well right ? I see well from my computer.

[lethal burrow]

when i check the answer

it said like this and i dont understand how

[dawn umbra]

This is the answer given by the computer?

[lethal burrow]

no by the book

it is the one where it writes « solutiion explicite » in 2- a)

[dawn umbra]

What's wrong with that exactly?

[lethal burrow]

idk where it comes the /20

[dawn umbra]

You got the same implicit answer, I assume?

[lethal burrow]

yes

[dawn umbra]

Ok, let me try

[lethal burrow]

k

[dawn umbra]

It's just algebraic manipulation

[lethal burrow]

ik but idk how to do at the end

[dawn umbra]

It's not a big deal bro

C is an arbitrary constant

[lethal burrow]

yes ?

is my calculs are good ?

until the y² ?

[dawn umbra]

Yeah

Explicit answers do not mean much

Because we end up finding c afterall

[lethal burrow]

yea

[dawn umbra]

When you put for (x,y)

[lethal burrow]

well i will try to find the answer

.close

[cedar kiln]

Channel closed

Closed by @lethal burrow

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

can someone explain what the circled step is

I dont get it

[short blade]

they just joined the cos(x) terms and the sin(x) terms

[crimson sedge]

oh yess i can see that now

what ab the right side though?

oh

is it because we are given a value with the cos on the orignal equation? but there is nothing mentioned for sin so its just zero for sin?

[short blade]

yes

[crimson sedge]

oh bet you are a life saver like fr

thxs so much

.close

[cedar kiln]

Channel closed

Closed by @atomic tendon

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hexed vortex]

i’m not sure if i’m solving for y correctly

[undone epoch]

This is the same for solving e^-x

[hexed vortex]

i’m not following

are you saying e^-y is the same thing as solve for that, if so I know that i’m just not sure if i’m solving it right

the steps i’m not to sure about

[undone epoch]

You’ll get -e^(-y) +c

[cedar kiln]

@hexed vortex Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[prime island]

how do you even begin to solve this?

[coral jewel]

divide both the numerator and denominator by x

watch out, as x approaches -inf, |x| = -x

[prime island]

why divide by x?

[coral jewel]

thats the standard way to do rational limit

[prime island]

oh okay

is this right?

[coral jewel]

divide in the sqrt as wel

[prime island]

like this?

[coral jewel]

no

$x=\sqrt{x^2}$

[wraith dagger]

Fungus 34A05

[prime island]

ohh i thought i couldnt just take it out if its being subtracted from

[valid night]

You are right

[prime island]

so what should i do different from this

[solid juniper]

another way to look at it is $\sqrt{x^2-2} = \sqrt{x^2(1-2/x^2)} = \sqrt{x^2}\sqrt{1-2/x^2}= -x\sqrt{1-2/x^2}$

err

[wraith dagger]

slayla

[prime island]

is this right?

[solid juniper]

doing that here, the x’s cancel

[prime island]

i guess i get rid of the dividing x on the top and remove the 1?

like this?

[agile bramble]

Thats correct

[prime island]

what should I do after this point?

[agile bramble]

But x goes to negative infinity right

[prime island]

yeaah

[agile bramble]

since x < 0, square root of x^2 is -x

[prime island]

riight i see

[agile bramble]

So

Holon imma just show you

Lemme write

Here @prime island

At this point you can substitute the x

c/infinity is 0, where c is a constant

[prime island]

did we put in the square root of x^2 because there's a square rooted x in this problem?

[agile bramble]

yeah, there’s a square root of x^2

so since thats the highest power

we used square root of x^2

To make the other numbers be in the form of 1/x

[agile bramble]

then you can use this property

[prime island]

ooooooooohhhhh

i see

and then it becomes -2 + 1 / -1

[agile bramble]

Mhm

[prime island]

wait so

if you divide the root x^2-2

by root of x^2

you can put them all under the same root?

[agile bramble]

yep

[prime island]

ooooh ok

[valid night]

Learn the radial rules

[agile bramble]

square root of 7 x square root of 4 is square root of 28

You can multiply them if they’re under a root

[prime island]

Ive got it thank you for teaching me!!

.close

[cedar kiln]

Channel closed

Closed by @prime island

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tough karma]

im not understanding why the lower limit of dy is x^2 and upper limit is 2x

and not vice versa

when doing dy, we are taking small increments in the y axis and seeing how x changes with y right??

[short blade]

the bounds of integration tell you what area you want to integrate over

note that we want the area between y = 2x and y = x^2

if you plot this out on the xy plane, you whould get something resembling this

where the blue line is y=2x, and the red is y=x^2

now you always implicitly assume x is moving right and y moves upwards

[tough karma]

yes

[short blade]

so the area can be described by

0 <= x <= 2

and

x^2 <= y <= 2x

[tough karma]

ahh i get it

i was making a mistake

tysm

.close

[cedar kiln]

Channel closed

Closed by @tough karma

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[marsh rain]

Hi I was wonderinghow to do part c and if i did a and b correctly

[cedar kiln]

@marsh rain Has your question been resolved?

[cedar kiln]

@marsh rain Has your question been resolved?

[cedar kiln]

@marsh rain Has your question been resolved?

[cedar kiln]

@marsh rain Has your question been resolved?

[cedar kiln]

@marsh rain Has your question been resolved?

[cedar kiln]

@marsh rain Has your question been resolved?

[gentle pecan]

Hey @marsh rain I was playing around with this on stream today. I think I can help with (a) and (b) but was unsure what (c) was asking tbh

[wraith dagger]

twitch.tv/pencenter

[gentle pecan]

So I feel confident based on your work that you understand part (a). For part (b) what did you end up getting?

Also there is likely an error in part (c), the third term is missing a $\sin$

[wraith dagger]

twitch.tv/pencenter

[marsh rain]

Hello! I actually just woke up rn so it'll take a little bit for me to get back to you . Thank you so much though!

[marsh rain]

Ohh in that case would you know how to solve it?

[marsh rain]

for (b) my answers on the far bottom of the age. product of a bunch of quadratic factors following the rule (z^2-2cos(2npi/(2n+1))x+1)

[rose cliff]

How would you do Part c

[marsh rain]

im wondering too. i think i just need to know where to go from b since it says hence

[gentle pecan]

Yeah I wasnt sure what was going on in part (c) but my chat definitely thought there was a potential error

[gentle pecan]

Right this seems good!

Im sure the cosines I got simplify somehow, I was just too lazy to do it 😅

[marsh rain]

thats all good. i might ping the helpers to see if anyone has any idea

<@&286206848099549185>

[thorny turtle]

whar is this written on

[cedar kiln]

@marsh rain Has your question been resolved?

[peak bone]

N belongs to?

For part c

[marsh rain]

is this a question about the question itself. bc i have no clue sorry

[zenith folio]

please help

<@&286206848099549185>

[peak bone]

Aw man

[worldly chasm]

!occupied

[cedar kiln]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[sacred trellis]

B is a matrix of order (3*2), where aij= 3i-2j
1<=i<=3
1<=j<=2
Express B in matrix form

!occupied

[cedar kiln]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[crimson sedge]

@marsh rain

you got the answer?

[marsh rain]

Nope but I might just close it atp

[crimson sedge]

hmm

i might be able to help

i saw how you proceeded it

its actually right

like i have a more of a solution mindset

and 3rd expression also rings a bell

but i wanna know do you have the answer

like the expression?

the thing is if you have to do the cube root of 1 its possible

or if you have to do 4th root of 1 its possible

but its too vague

but worry not i have solution for that as well

its basically asking about the roots of 1

[marsh rain]

Yeah I'm just blanking on what exactly to do 😭 also I might be a bit unresponsive right now since i have an English essay due tomorrow but pls give some insights if u have any

[crimson sedge]

ok no problem

i can totally help with this

im sure

so i think you shouldnt keep this channel held up anymore

[marsh rain]

Are you asking if we can work with it in the solution? I think we can

[crimson sedge]

coz its been open for quite some time

[crimson sedge]

i like to do it that way

[marsh rain]

Yeah it's been a couple of days lmfao

[crimson sedge]

coz i can get whether you can understand it properly or not

[crimson sedge]

so close it for now

and open it later or

dm me

i can help

take your time no rush

im just giving you options dont think of me as a creep pls

lol

[marsh rain]

Okayy tysm is it okay if I get back to u tomorrow

[crimson sedge]

ok no problem

[marsh rain]

Lmfao no worries just want help

Thanks!

.close

[crimson sedge]

yeah thanks

[cedar kiln]

Channel closed

Closed by @marsh rain

Use .reopen if this was a mistake.

[warm jackal]

Help.. How did they get (x-3) (x-2) 🥲

Please teach me how to factor huhuhu

[dense tree]

What I have done in the above steps is, first I've broken down -5x into two terms in such a way, that if I multiply the two split terms I will get the same product as if I multiplied the square and constant.
I.e. (-2x)(-3x) = 6x²
And (x²)(6) = 6x²

Then, I've taken common terms between the first two and last two terms.
And the last step is taking common the terms again

[crimson sedge]

u need help?

or is ur doubt solved?

@warm jackal do u need help?

[warm jackal]

No need, thank youu!

[mortal forum]

!done

[cedar kiln]

If you are done with this channel, please mark your problem as solved by typing .close

[mortal forum]

@warm jackal !done

[worldly chasm]

The channel is already closed

It was never opened for Hylexia

@mortal forum @orchid field

[bleak flax]

@rawra .close this channel

[cerulean sail]

@bleak flax

[jolly swan]

.close

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[chilly raft]

How do you do differentials?

[cedar kiln]

@chilly raft Has your question been resolved?

[cedar kiln]

@chilly raft Has your question been resolved?

[chilly raft]

<@&286206848099549185>

[chilly raft]

<@&286206848099549185> sorry to be a bother but can I please get help I don't get any of it

[cedar kiln]

@chilly raft Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tight thorn]

Hello all

[tight thorn]

How to solve: cos(arcsin(sqrt(2)/3)

NO idea where to begin this one…

Please help. Struggling. -Joebeard

@idle tusk

Spoke to Moses. He said you might be able to help. Moses says: “Hello Arte”

🙂

[wraith dagger]

sssssssssssvvvvvvvvvvccccccccccc

[cedar kiln]

@tight thorn Has your question been resolved?