help-13

[barren dove]

It’s like 90/x’…? Idk

[tepid sail]

does a change

[barren dove]

Is it at a number?

So 20

[tepid sail]

a doesn't change so da/dt is 0

[barren dove]

Oh lmao 😞

[tepid sail]

ur good lmao

I'm just p bad at explaining

[barren dove]

no ur fine dw

[tepid sail]

so we get something like

2x * x' = 2y * y'

and we are trying to solve for y'

"what rate is the player's distance changing at that instant"

so y' is what we are looking for

[barren dove]

So we isolate y’?

[tepid sail]

mhm

[barren dove]

So 2x*x’/2y

=y’

[tepid sail]

why do we still have the 2?

[barren dove]

Oh shi

My b

[tepid sail]

ur chilling

[barren dove]

So that

Ignore mt scribbled

My scribbles**

[tepid sail]

so we need to know x, x' and y

let's start with x and x' (hint: they are given in the problem)

[barren dove]

x is 20?

[tepid sail]

great

[barren dove]

So is x’ just nothing

[tepid sail]

x' is given in the problem

[barren dove]

30 then

[tepid sail]

great lol

[barren dove]

Over 90 lmao

[tepid sail]

if x = 20, and a = 90

what does that make y equal to?

[barren dove]

Y= 90

And then like once u divide everything is it 60/9?

[tepid sail]

hmm

try again

use pythogorean

[barren dove]

600/90 😞

[tepid sail]

hint: y^2 = x^2 + a^2

[barren dove]

Oh so 90^2

[tepid sail]

but x = 20

so really y is equal to $\sqrt{20^2 + 90^2}$

[wraith dagger]

nosqldb

[barren dove]

what happened to the 30

[tepid sail]

,w calc \sqrt{20^2 + 90^2}

[wraith dagger]

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[tepid sail]

dw it's still there

we are just solving for y

[barren dove]

Oh okay

[tepid sail]

now we have everything we need for the equation

plug it all in!

[barren dove]

Is it that

[tepid sail]

should be

pls check

I could make a silly or sm

[barren dove]

Like plug in calculator?

[tepid sail]

submit the answer?

idk

should be good tho

[barren dove]

It says wrong:((

[tepid sail]

what did you type in

[barren dove]

i simplified it as well n it j gave wrong for both

600/10 sqrt85

[tepid sail]

like send a ss

[tepid sail]

give me a second prob a silly mistake

[barren dove]

Okiee

[tepid sail]

can you put a negative in there

[barren dove]

Yep

That is the right one

Why is it negative??

[tepid sail]

lol the distance is obv decreasing 😭

I'm so sorry

[barren dove]

Lolll

Dont worry

Tysm

[tepid sail]

ofc have a fun night

[barren dove]

🙏🙏

u too

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[dim sail]

Use gaussian elimination to solve the following linear systems that all have a unique solution. (the second image is the answers)

[dim sail]

to do gaussian elimination ik you have to get it into REF but shouldn't the diagnols all be 1's?

and below the 1's it should be 0 but if you look at the last matrix of each example in the answers, none of them are in REF

im confused about that

how do you know when to stop? or how do you know you applied the right operation to get to the next matrix?

[cedar kiln]

@dim sail Has your question been resolved?

[dim sail]

like for the very last matrix the last row is 0 0 -2

[cedar kiln]

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[cedar kiln]

@dim sail Has your question been resolved?

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[wraith trellis]

hello

[wraith trellis]

there is no measures for the angles here but imagine there were

how would you solve for x

if angle 1 was like 11x +108

and angle 2 was x^2 + x + 10

these numbers dont work im just making them up

oh and quad. ABCD is a parallelogram

we dont know that BC bisects angle

[cedar kiln]

@wraith trellis Has your question been resolved?

[cedar kiln]

@wraith trellis Has your question been resolved?

[wraith trellis]

<@&286206848099549185>

[cedar kiln]

@wraith trellis Has your question been resolved?

[silk hound]

What do you want to find ?

[wraith trellis]

solve for x.

u can give angle 1

numbers like

11x + 108

and angle 2 is

x^2 + x + 10

these numbers dont actually work im just saying random ones cus

its from a quiz i forgot the numbers

[silk hound]

BC or BD ?

[wraith trellis]

BD sorry

[silk hound]

Since it's a parallelogram, angle ABC = 11x+108 = 60

X=48/11

[wraith trellis]

why does it equal 60

[silk hound]

Think why. It's actually a basic proeprty of parallelgram.

[wraith trellis]

idk

sorry

@silk hound hello

[silk hound]

Check on the internet: prove that the angles of the parallelogram are either 60° or 120°.

[wraith trellis]

thats only if u know its a rhombus

[cedar kiln]

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[sleek parcel]

How do I answer this question
4a^2-9ac+5c^2
I have searched it up and this first step shows something like this
(4a^2-4ac)+(-5ac+5c^2)
Where do you get the -4ac and -5ac from?
Is it because -4ac -5ac = -9ac in the question?
HELP pls

[bold vine]

to your last question: yes

[sleek parcel]

so then what would be after that?

[bold vine]

factor what's in each set of parentheses

[sleek parcel]

ohh ok thank you

.close

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[verbal hare]

i dont understans 2-23

[verbal hare]

how can there be n coordinates when the basis consists of r vectors where n!=r is possible

why is the coordinate vector not just $b_i=c_i$

[wraith dagger]

>_<

[verbal hare]

since that is the coefficient of the ith basis vector $p_i$

[wraith dagger]

>_<

[crystal raptor]

The p_j are vectors themselves, so you have to add up the corresponding coordinate from all of them (multiplied by the number c_j)

Try playing with an example matrix like

1 2 3 4
5 6 7 8
9 1 2 3

The p_j are just the rows

Well, once you row reduce it

[verbal hare]

but does that matter when we look at them as the basis for our row space

[crystal raptor]

Im not sure what you mean

[verbal hare]

p_i are the basis vectors of our row space and all v in our row space are then linear combinations of our p_i
but wouldnt that imply that [v]_B has r elements and not n

maybe im misunderstanding something

[verbal hare]

since B has r elements

[crystal raptor]

It's possible that only r of the n coordinates are non zero yeah if r < n, but these are still size n vectors

It's some subspace of R^n that is isomorphic to R^r

[crystal raptor]

Yeah you are essentially doing this isomorphism

But 2.23 is writing down the (1,1,6) coordinates in R^3 in terms of the matrix entries and coefficients

[verbal hare]

so not the coordinates relative to the basis consisting of p_i?

[crystal raptor]

No 2.23 is with respect to the standard basis in R^n

[verbal hare]

oh

thank you

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[verbal hare]

.reopen

[cedar kiln]

✅

[verbal hare]

does that mean we look at beta as an element of R^n and not an element of the row space since the standart basis doesnt have to be contained in the row space?

[crystal raptor]

We are just writing the coordinates in terms of the std basis, not claiming the std basis is in the subspace

[verbal hare]

ok

ty

[crystal raptor]

If you read on they go on to write β in the p_i basis

[verbal hare]

ah

.close

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[crystal raptor]

So the b_ki are the coordinates you wanted originally and in your pic

[cedar kiln]

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[quasi timber]

how do i prove differentiability

[cedar kiln]

@quasi timber Has your question been resolved?

[nimble mulch]

dissect the map into its component, form partial derivatives and show their continuity

if the partial derivatives of f's components are continuous for any a, then f is differentiable at a

@quasi timber are thee there 🐣

[cedar kiln]

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[soft apex]

can anyone guide me through the process of answering this?

[royal loom]

simplify it first

[soft apex]

Alright hold on

ik u said simplify but i wanna ask if im on the right track first

is this correct

[royal loom]

assuming that you did keep-change-flip

and then just expanded

sure

[soft apex]

correct?

[soft apex]

Yeah

then what

do i use quotient rule here?

@royal loom sorry for the ping

[royal loom]

yes

or

you can spliit it up first into pieces

and only do power rules

[soft apex]

how do i "split it up"

[royal loom]

(a+b)/c=a/c+b/c

[silk hound]

Better not to.

[soft apex]

how come

[silk hound]

Just simplify the original equation and then use quotient rule.

[soft apex]

like this? or individual

[royal loom]

individual

[soft apex]

ah mb

[royal loom]

you will get cancellation of powers of x

[soft apex]

wait

[royal loom]

on some

[soft apex]

i see

alright wait

[royal loom]

and then you can use the power rule on whatever is left

[soft apex]

is this correct

[royal loom]

do you really need someone to check that step for you?

[soft apex]

o wait wrong ss

[soft apex]

<@&286206848099549185>

[grand bane]

bro what an abomination of a question this is

[hot crag]

it's really not that bad

[hot crag]

anyway, you're here, right?

[soft apex]

that's unfinished

im here

what's next? :')

[hot crag]

xD

first, it'd help if you simplified the powers and moved the constants to the side

[wraith dagger]

ren

[hot crag]

@soft apex done??

[soft apex]

does it have to be a decimal

or can i keep it as a fraction

[hot crag]

doesn't matter

[soft apex]

is it like this

[hot crag]

yes

btw, change the ones with powers on the bottom to negative exponents

[soft apex]

like this?

[hot crag]

no no no

that won't matter

[soft apex]

Oh only the ones with variables?

[hot crag]

e.g. for $\frac{20}{3x^2}$, change that to $\frac{20}{3} x^{-2}$

[wraith dagger]

ren

[soft apex]

is it ok that i already applied power rule to the simplified ones

[hot crag]

??

oh, you mean the 5x and the 70/3??

yea sure

[soft apex]

yea

[soft apex]

thanks

[soft apex]

is this correct?

[hot crag]

one sec

yes

nice

now, you know the power rule, right??

[soft apex]

yes

[hot crag]

what is it?

[hot crag]

what is that the derivative of

[soft apex]

is this the answer your looking for?

i slightly dont get the question

[hot crag]

yes

basically ur tryna say (ax^n)' = anx^(n-1), right

[soft apex]

yes

[hot crag]

where n and a are any number/constants

[hot crag]

good

now the thing is, a and n can be quite literally anything

so use that

(hint: even negative numbers work!)

[soft apex]

is this correct?

[hot crag]

one second

yes!

absolutely

gj

!done

[cedar kiln]

If you are done with this channel, please mark your problem as solved by typing .close

[soft apex]

final?

[hot crag]

what about the 5?

[soft apex]

oops i forgot mb

[hot crag]

but other than that yes

nice work

[soft apex]

wait can i ask something

[hot crag]

sure

why does it work?

[soft apex]

nope

[hot crag]

okay

then what

[soft apex]

why is it different from the answer mathway gave :')

[hot crag]

hang on, what

seems correct i mean

are you sure you inputted the right question

everything works, except for the 400 at the end. that should be 400x^8

and positive

[hot crag]

okay

are you sure you factorized it correctly

,w expand ((x^2+5)((2x^3+5)(7x+4)+7x^3))/(3x^4)

[wraith dagger]

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[soft apex]

this is my entire solution

[hot crag]

...

okay hang on

i'll read thru it, but i need to go rn
i'll be back in around 10 minutes, sorry

[soft apex]

alright thank you ren

[hot crag]

in the meantime, you can also ping helpers bc it might be a little more

but i'll b as fast as i can

[soft apex]

ill try to keep the channel alive

thank you thank you

[hot crag]

",w" is the cmd for wolframalpha, by the way

sorry lol
i'll b quick

[soft apex]

thank you , no worries

[cedar kiln]

@soft apex Has your question been resolved?

[hot crag]

sorry, hey, im back

@soft apex

[soft apex]

hi ren

[hot crag]

sorry

took a while :(

[soft apex]

no problemm

[hot crag]

well, as i see it, your expansion appears correct

im just checking it out once more

well yep got it

you had 100/(3x^4) = (100/3)x^-4

instead, you replaced that with (100x^4)/3

that's your only error

otherwise, it's correct

which is why the 400 and stuff was off

!done

[cedar kiln]

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[hot crag]

@soft apex do .close

[cedar kiln]

@soft apex Has your question been resolved?

[soft apex]

ill try that, thank you!

[cedar kiln]

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[hot crag]

okay

[cedar kiln]

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[frigid sinew]

why isnt it 2 here

[opaque root]

What have you tried?

[frigid sinew]

i would try drugs at this point

but yeah i dont get it i never saw this kind of question

[opaque root]

Try with usub 2x

Then adjust the integral

[frigid sinew]

wait what

usub?

[frigid sinew]

also what does thi smean

[silk hound]

Take 2x = t

2dx = dt

F(2x) = F(t)

At x = 2, t = 4
At x = 0, t = 0

[cedar kiln]

@frigid sinew Has your question been resolved?

[frigid sinew]

.close

[cedar kiln]

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[frigid sinew]

is what i did wrong

[subtle harbor]

you may need to put it in terms of pi

you should be able to just write 'pi' in webwork and it'll pop up

@frigid sinew

,calc 2/pi

[wraith dagger]

Result:

0.63661977236758

[frigid sinew]

isnt this what i wrote

[subtle harbor]

so write 2/pi instead of the decimal

[frigid sinew]

ah

still not this

[subtle harbor]

OH WAIT

average value

[frigid sinew]

yes

[subtle harbor]

thats what /pi does

ok

hmm

is there like a symbol dropdown

try doing 2/ \pi

does \pi make it into pi symbol

[frigid sinew]

no its just pi

usually

and it works

[subtle harbor]

wait...

cos(0) is 1

lmao

so the lower bound doesn't disappear

@frigid sinew

[frigid sinew]

yes

lower bound?

do you think it might be bc i forgot a -

[subtle harbor]

so you should have $\f{-2}{\pi}(\cos(\pi)^{5}-\cos(0)^{5})$

[frigid sinew]

wait

cos(0) is 1

omg

i forgot

[wraith dagger]

🫎 MSC2020 55N31 (Moosey) 🫎

[subtle harbor]

yes

[frigid sinew]

i got 1.273

[frigid sinew]

from this

[subtle harbor]

yes

but try

the exact

so instead of 2/pi

what should it be

[frigid sinew]

i would assume its

4/pi right

?

[subtle harbor]

yes

[frigid sinew]

ahh nice ty

oh btw could you help me with this

i have 0 clue i put 2 and obv its wrnog

ive never even seen this type of question

[subtle harbor]

treat it like a u-sub

[frigid sinew]

yeah im confused by that statemtnt as well someone siad that

[subtle harbor]

u=2x

[frigid sinew]

yes

[subtle harbor]

so if x=0 and x=2 are the bounds

what are the bounds in terms of u

@frigid sinew

[frigid sinew]

if bounds means like a and b

then

[subtle harbor]

yes

[frigid sinew]

u is also 0,2?

[subtle harbor]

bounds are in terms of x, but we would like them to be in terms of u for this problem

[subtle harbor]

u=2x

if x=0, what does u=

if x=2 what does u=

[frigid sinew]

so 0, 4?

[subtle harbor]

yes

now what would our integral look like if we made it in terms of u

integral of f(2x)dx from 0 to 2

[frigid sinew]

would it change to 0,4 or

[subtle harbor]

it changes from 0 to 4 once we do the u-sub

what you've been doing so far is substituting back in terms of x at the end once you're finished with the u-sub

you also have the choice of keeping it in terms of u and changing the bounds to be in terms of u and evaluating that

[frigid sinew]

so is it just integral of u

[subtle harbor]

you let u=2x right

[frigid sinew]

is it 2x^2

[subtle harbor]

what

[frigid sinew]

i just integrated u

[subtle harbor]

don't integrate you

u*

you are getting confused

[frigid sinew]

ahh

[subtle harbor]

if u=2x, then du=2dx

which means 1/2 du =dx yes?

now, what does that mean we have so far

[frigid sinew]

ah thats what you mean okk ok

yes

so we have

u du /2

right

[subtle harbor]

no...

$\int_{0}^{2}f(2x),dx=\int_{0}^{4}\f{1}{2} (?) ,du$

[wraith dagger]

🫎 MSC2020 55N31 (Moosey) 🫎

[subtle harbor]

note we only changed 2x to be u

so what should be in place of the ?

[frigid sinew]

okay wait so we changed 2x to u

[subtle harbor]

yes

[frigid sinew]

i cant think of anything else than u in that ?

[subtle harbor]

f(2x)

what does this become if u=2x

@frigid sinew

[frigid sinew]

f(u)?

[subtle harbor]

YES

[frigid sinew]

oh

but if its f(u) what do we do with it

[subtle harbor]

$\f{1}{2}\int_{0}^{4} f(u) ,du$

[wraith dagger]

🫎 MSC2020 55N31 (Moosey) 🫎

[subtle harbor]

now notice something

there's nothing special about the variable 'u' here

we could make it anything

u,w,z

what would be a useful variable to make it into...

[subtle harbor]

for solving this

[frigid sinew]

x?

[subtle harbor]

yes!

$\f{1}{2}\int_{0}^{4} f(x) ,dx$

[wraith dagger]

🫎 MSC2020 55N31 (Moosey) 🫎

[subtle harbor]

and what does THIS equal

[frigid sinew]

F(4) -F(0)?

[subtle harbor]

we have this integral defined already

[subtle harbor]

look back at the problem

@frigid sinew

[frigid sinew]

ohh

wait

okay so

[frigid sinew]

how did this stretch to 0,4

from 0,2

[subtle harbor]

u=2x

x=0, x=2 => u=0, u=4

[frigid sinew]

is there a name for it

ive never seen it

[subtle harbor]

this is just subbing into the bounds

it's another way to evaluate u-sub integrals

[subtle harbor]

like i said up here

[frigid sinew]

oh

wait its weird ive never seen that

and its in my exercise

okay anyway

final answer here should be 1

my teacher puts stuiff we will learn in the future in current exercises and its weirdly confusing

okay ty!

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[shy isle]

I dont understand the second step

I understand that you can separate the multiplications and such in the first part but where does (3(4x^2-x)+5x(8x-1)) come from

[ionic finch]

factor

notice both terms has $x^2(4x^2-x)^4$

[wraith dagger]

Dubs

[ionic finch]

so you can use factor the term out

or equivalently using distributive property

[shy isle]

im having a hard time seeing this, where did the parenthesis starting at 3 in the second row come from

$x^2\left(4x^2-x\right)^43\left(4x^3-x\right)+x^2\left(4x^2-x\right)^45x\left(8x-1\right)$

[wraith dagger]

Tjocko

[shy isle]

would this be a correct step in between the first and last row?

sorry first and second row

[ionic finch]

yes

It is legal but not really helpful

[shy isle]

what rule would I factor this with?

[ionic finch]

a(b+c)= ab+ ac

so what you have in hand is the right side

so you can pull out the common factor and replace it with the left side

[shy isle]

oooh wait is $a=x^2(4x^2-x)^4$

[wraith dagger]

Tjocko

[ionic finch]

yeah, that’s the way to put

[shy isle]

now I understand, thank you a lot I will remember you when I write my finals

[ionic finch]

:)

good luck with your exams

[shy isle]

thank you

.close

[cedar kiln]

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[minor rover]

help!!

[mental trail]

hi, do you know what it means for to curves to be normal to each other?

for example if we had two curves y = f(x) and y = g(x), what does it mean for those curves to be normal to one another?

[cedar kiln]

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[knotty saffron]

Am i differentiating this correctly?

[knotty saffron]

It says with respect to T but there is no T in the equation

[dire geode]

indeed, the question is leaving out information

$V = V(r), r = r(t)$

[wraith dagger]

riemann

[knotty saffron]

Okay. Im just unsure what to do

[dire geode]

i'm just guessing here since it's unclear, but it's worth a try

[knotty saffron]

Okay shoot me

[dire geode]

Use this and find dV/dt using chain rule

[knotty saffron]

i dont see any case that involves the chain rule

like do i solve implicitly??

like where i would add a d/dt at the end of r^2

[dire geode]

$V = V(r) = V(r(t))$

[wraith dagger]

riemann

[dire geode]

,tex .diff rules

[wraith dagger]

riemann

[knotty saffron]

So put the t inside of the v' funciton?

[dire geode]

second to last

[dire geode]

plug r(t) into V(r) yes

[knotty saffron]

I see and i understand the rule i guess i just dont see any pattern'

i need to learn how to draw equations with this robot lol

[dire geode]

what pattern are you talking about

[knotty saffron]

would it be like

[dire geode]

you see this right?

[knotty saffron]

just a placewhere i can use the chain rule

[knotty saffron]

ive seen that before

[dire geode]

that's the second to last row

[knotty saffron]

yea basic chain rule

[dire geode]

and you see this?

[knotty saffron]

okay so ill take the function thats already in the box

i already differentiated the inside?

like whats the inside and whats the outside is my main question

or do i just put one function inside of the other

[dire geode]

this is the outside function

[knotty saffron]

its the derivative of the outside keeping the inside the same

[dire geode]

yea so write that out

[knotty saffron]

So when i differentiate that

$4/5pir^3$

[wraith dagger]

WingManUp06

[knotty saffron]

thats like

wait

my outside function is $$4pir^2$

[wraith dagger]

WingManUp06
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[knotty saffron]

i mean $4pir^2$

[wraith dagger]

WingManUp06

xd_senBugha

[short stratus]

Kinda like a function to track the volume of air in a balloon after its mouth is opened or something like that

[knotty saffron]

Yeah thats what were working on

stuff like that'

[wraith dagger]

xd_senBugha

[short stratus]

Now can you move further?

[knotty saffron]

Let me think

[knotty saffron]

is this kind of like 2nd derivative?

wait no your multiplying

[short stratus]

No

[knotty saffron]

so i use that function

the only function i was give

[short stratus]

You find the derivative of the function

[knotty saffron]

and differentiate it twice

[short stratus]

Then multiply by Dr/dt

[short stratus]

No you dont

[knotty saffron]

Okay

rn my derivative with respect to R is 4pi*r^2

[wraith dagger]

xd_senBugha

[short stratus]

So you first evaluate the derivative with respect to r

Then multiply the rate of change of r with respect to time (t)

@knotty saffron do you understand what i just said?

[knotty saffron]

sorry i was away from my PC

I kind of do

So on the right of the sign

i just leave the dr/dt

[short stratus]

Yeah

Rn youre just missing a term of dr/dt

[knotty saffron]

im sending a picture

[knotty saffron]

whats messing me up is that

there is no T in the equation

[short stratus]

Look at this

[knotty saffron]

derivative of R with respect to T

[short stratus]

You're wrong here

[knotty saffron]

Okay

[short stratus]

You're finding out the second derivative

We don't need that

[knotty saffron]

so i just replace the function

[short stratus]

You do this

[knotty saffron]

okay so when ive done that

[short stratus]

You're done

[knotty saffron]

it should look like the very bottom row?

of this?

[short stratus]

That would give you the answer

Yeah

That's it

[knotty saffron]

Ohh okay i see

thats kinda werid

weird

ill ask my teacher about it

thanks for the help tho

[short stratus]

You can find the derivative of anything with respect to anything else

You just gotta multiply the rate of change of thing with respect to whatever you're finding the derivative of

^ something to keep in mind in the future

[knotty saffron]

Okay

this is def something i need to work on

[short stratus]

Like you did in this case

Multiplied the derivative with the rate of change of radius with time

!done

[cedar kiln]

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[knotty saffron]

!done

[cedar kiln]

If you are done with this channel, please mark your problem as solved by typing .close

[knotty saffron]

.close

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[pseudo merlin]

hello

[pseudo merlin]

is there any way of understanding why the segment formula is like dis

i need to memorise it easily

[chrome delta]

you can derive it

if you want

[pseudo merlin]

what is derive?

[chrome delta]

make it from scratch

[pseudo merlin]

hmm how so

[chrome delta]

you know that one revolution is 2 pi radians right?

[pseudo merlin]

yes

bc 180 is 1 pi right

[chrome delta]

and you know that the circumference of a circle with radius r is

2pi * r

circumference here is analogous to arc length of the entire circle

[pseudo merlin]

wait sorry

[chrome delta]

sure

[chrome delta]

?

[pseudo merlin]

for question c i did (2 pi - 4.5) x 7.8

and its wrong

[chrome delta]

i thought we were deriving the formula lol

[pseudo merlin]

oh i think i give up LOL

[chrome delta]

,, s = r \theta

[wraith dagger]

nyxie9151

[pseudo merlin]

like to be honest its easier to memorise than to understand the deriving stuff

[chrome delta]

yeah what you did is correct lol

[chrome delta]

it's pretty easy

it's just ratios

and you'll always remember it

cuz if u forget then you can make it

but your choice

[pseudo merlin]

i got 11.56 but the answer is 13.9

and my calculator is in radians

should i try on my other calculator

[chrome delta]

it's 13.9

dw

i mean your work is right so you should trust yourself

,w (2 pi - 4.5) * 7.8

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by nyxie9151

[pseudo merlin]

wth

whats wrong with my calculator

[chrome delta]

why are you using the inferior calc

when u have a better one

right next to it

[pseudo merlin]

what its also wrong

[chrome delta]

lol what

[pseudo merlin]

its too hard to use

the inferior one is essier to use

except for like graphing and using cosine law

[chrome delta]

put it like

2 * pi

[pseudo merlin]

whats the difference

[chrome delta]

i have no idea

how the calculator interprets the thing

[pseudo merlin]

what the fish

[chrome delta]

now use 3.14 instead of pi

what are we going to see now lmao

[pseudo merlin]

bruh

[oblique flare]

you are writing 4.8 instead of 4.5

[pseudo merlin]

oh.

...

sorry its 1:50am

[chrome delta]

bruh

[oblique flare]

understandable

[pseudo merlin]

ok i shoukd sleep

[chrome delta]

it's 2:50 for me lol

anyway

okay yeah well that was stupid

[pseudo merlin]

am?

[chrome delta]

yes

[pseudo merlin]

,time

[wraith dagger]

The current time for nutgun. is 01:51 AM (AWST) on Sat, 02/03/2024.

[pseudo merlin]

oh

[chrome delta]

,time

[wraith dagger]

You haven't set your timezone! Set it using the interactive timezone picker with ,ti --set.

[pseudo merlin]

are u aus?

[chrome delta]

no japan

[pseudo merlin]

oh

where is japan

[chrome delta]

:V

[pseudo merlin]

😭😭

im drowning in work

i have chemistry physics i have to finish an english novel and im doing 2 math courses

[chrome delta]

Lol yeah it's alot of work

i'm taking a bunch of electives as well

but my brain isn't working rn

lol

[pseudo merlin]

.close

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[oak sonnet]

hi this should be a simple question. somehow I have pressed some keys in overleaf and my editor is now right aligned as visible in picture. does anyone know hwo to switch the text alignment back. cheers

[oak sonnet]

cannot find anything online about this

.close

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[fickle flint]

Need help solving or collecting ideas about Traveling salesman problem, but with time windows that need to be visited as long as possible, so an array of objects with longitude, latitude, start time and end time, and clusters where the total travel time is relatively the lowest to the time present. Objects can appear in multiple clusters, but only once in each.

This is how the data looks:

[cedar kiln]

@fickle flint Has your question been resolved?

[fickle flint]

<@&286206848099549185>

[cedar kiln]

@fickle flint Has your question been resolved?

[cedar kiln]

@fickle flint Has your question been resolved?

[brazen geode]

[cedar kiln]

@fickle flint Has your question been resolved?

[fickle flint]

<@&286206848099549185>

[worldly chasm]

@fickle flint it might be that a solution for that sort of problem might not even exist.

Or if a solution does exist, it might be significantly less optimal than a traditional traveling salesman problem.

So heuristic solutions that approximate traveling salesman problems are probably not applicable.

I'd approach this by writing a brute forcer that works for small N first, then test any ideas I'd have against it to make sure it returns reasonable results.

Because this seems to be optimizing a single day's stops N probably isn't much higher than a dozen or so. And so the brute forcer might be all that you need.

[cedar kiln]

@fickle flint Has your question been resolved?

[fickle flint]

It could be a variation of the prize-collecting traveling salesman.

[cedar kiln]

@fickle flint Has your question been resolved?

[cedar kiln]

@fickle flint Has your question been resolved?

[nimble mulch]

Could you specify the exact problem definition? Currently it's unclear how the clusters have a purpose in relation to the main problem

[fickle flint]

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[fickle flint]

Got it

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[forest kindle]

how do i do this physics question?

[cedar kiln]

@forest kindle Has your question been resolved?

[forest kindle]

my average speed is 11.97m/s

and my time down the straight is 4.18s

<@&286206848099549185>

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@forest kindle Has your question been resolved?

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@forest kindle Has your question been resolved?

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[tribal sphinx]

helpppp how do i solve this

[brave copper]

isolate x 💯

[tribal sphinx]

the x between the parenthesis?

[eager parcel]

i mean what is f(x)

[tribal sphinx]

there's no other info

[eager parcel]

lol

i mean all u can do is combine the integrals

it’s like

the integral of f(x) from 1->3 wrt dx

just make it one integral with bounds 1-> 3

that’s all u can do rly

[tribal sphinx]

so f_1 ^3 f(x)dx

[eager parcel]

show me on paper

or like whiteboard if you have

[tribal sphinx]

yes one moment

[eager parcel]

we r just rewriting the integral not solving

[tribal sphinx]

like this?

[eager parcel]

if that’s a 1 at the bottom

yes

[tribal sphinx]

yes that's 1

[eager parcel]

then yes

that’s it

[tribal sphinx]

it's easier than i thought!!

thank you so much!!!!

[eager parcel]

np

yes it is

[tribal sphinx]

.close

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[wind sphinx]

what is 95x times 4563

[split pike]

?

[wind sphinx]

what is 2 + 2

man what

stfu

you disgusting shit

stop pls

im trying to learn math

pls

PLS

stop

Admin

ADMIN

ADMIn

ADMIN

ADMIN

[eager parcel]

what the hell man

[wind sphinx]

ADMIN

HELP

HE IS TYPING OME DISGUSTIONG STUFF

thanks

nu uh

stop pls

ADMIN

BAN him

[cedar kiln]

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[main needle]

.close

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[zenith wraith]

Any ideas on how I would solve this?
I think I get the first question where I just need to find an equation based on the provided line.
what about the second one? How I would even go about it?

[cedar kiln]

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Please don't occupy multiple help channels.

[kindred agate]

????

this is the question?

from school?

also I think you should answer this

yes

and?

yes

how old are you?

what

my guy

fuck do you mean "?"

I asked you a question

also

try to be nice to others

bruv

they are trying to help

also yes

what

?

lmfao

you trynna get banned my guy?

are you high?

💀

alr whatever

lmfaoo

what does dence mean

dense you mean

got it

[calm sierra]

.close

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[kindred agate]

lmao

ban?

[calm sierra]

they left before i decided

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[uncut idol]

why this is 11s ?. i think it should be 5s... no?
i am learning basic at math BTW

[void glen]

you have to factor out the denominator

so we have to expand (s+3)^2 and 5(s+3)

then we can combine like terms

[sharp lotus]

have you learned FOIL? what do you get when you multiply out (aka FOIL) the (s+3)^2 ?

[uncut idol]

Oh wow i understand now thanks! 🙂

[uncut idol]

yes but i am not good with it. so it's s^2 + 6s +9 right?

thanks a lot now i just learned that thing called FOIL. haha

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[willow seal]

I need help with a integration question

[willow seal]

I don't get the last 2 parts

How do you make the numerator the derivative of the denominator

[drowsy sage]

Have you done Partial Fraction Decomposition yet?

[willow seal]

No

Is that required in a level maths

[drowsy sage]

Not sure what that entails.. American, here.. but it's discussed in our Algebra classes, and then used in Calculus

Ah.. maybe by another name.. factoring the denominator into two (in your case.. sometimes more, depending on the degree of the denominator) and setting A and B as numerators in a set of fractions that's equal to the initial equation?

[willow seal]

Oh yes we have done this

But how could i apply that to the question that i sent

[drowsy sage]

What'd you get in part i

[willow seal]

P is 3 and q is 1

[drowsy sage]

I'm not sure what they're trying to do with the trig substitution

but to answer your question directly, you can't make the numerator the derivative of the denominator here.. but if you decompose the fraction, remember what the integral of 1/x is

[willow seal]

Ln x

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[unborn current]

Why doesn't ln(x) let the quotient rule work, ive already figured out what I should've done but still don't get why this doesn't work

[crimson sedge]

is that 10 in the numerator

[unborn current]

Yes

[crimson sedge]

the derivative of 10 is 0

[unborn current]

Ah

Welp

[crimson sedge]

the ln x in the numerators just 0

[unborn current]

Thank you

[crimson sedge]

gg

[unborn current]

Oof

.close

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[mild sail]

so i know to check the number of triangles i need to get a second angle for a new set of answers

but how do i do that?

so far I did:

13/sin60 = 15/sinc
sinc=15sin60/13
C=87.8

now how do i get the second angle?

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[tall saffron]

What would the x intercept be in radians?

[next timber]

Tangent of what equals zero?

[tall saffron]

0

[next timber]

Bingo

[tall saffron]

Is there a method to find any random x-intercept on a tangent graph?

[next timber]

Wdym

[tall saffron]

I just have issues with scaling. That's really it.

[tall saffron]

^

[tall saffron]

Like here, we have it as pi/6 instead of pi/2.

[next timber]

What's your question, I'm not following

How to scale properly or smth related to zeroes

[tall saffron]

Finding the zeros kind of ties in with my issue with scaling.

Main focus really, is scaling with radians.

[next timber]

Whats the issue with the way you scale them?

[cedar kiln]

@tall saffron Has your question been resolved?

[tall saffron]

Yes.

[tall saffron]

.close

[cedar kiln]

Channel closed

Closed by @tall saffron

Use .reopen if this was a mistake.

[cedar kiln]

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[limpid brook]

how do i find the x intercepts omg bruhh

like u put it in quadratic formula