help-13

[vernal kite]

oh whoops

alr

[wicked mantle]

..

[vernal kite]

x^2

[wicked mantle]

How about AB?

[vernal kite]

1+x+x^2

[wicked mantle]

Do you know how to assume two terms that one is greater than the other( a>b)?

[vernal kite]

nope

[wicked mantle]

Assume a-b>0
If the case is not valid, then the answer will be on the other side

[vernal kite]

does it have something to do a+b > c
b + c > a
c + a > b

or is that different

[wicked mantle]

Different

[vernal kite]

alr

[wicked mantle]

Try it out first

[vernal kite]

its a perfect square

x^2 + x + 1 - 3x > 0

oh wait no

no it isnt

whoops

[wicked mantle]

I guess yk what to do next, right?

[vernal kite]

factorise

[wicked mantle]

yessss

[vernal kite]

x = 1

which is larger than 0

so therefore ab is larger than 3qr

[wicked mantle]

Valid, the assumption was true

[vernal kite]

what does it mean in the second part

determine when equality occurs

[wicked mantle]

Draw the pic of the graph first

Of that arquatic function

[vernal kite]

x int is 1

y int is 1

[wicked mantle]

yep

When x=1

The equality becomes true

[vernal kite]

could it also be x is larger than or equal to 1

[wicked mantle]

Look at this graph

There is only one condition that equality is true

[vernal kite]

ohhhhh

i get what u mean

alrlr

[wicked mantle]

Any questions left?

[vernal kite]

for now nope

[wicked mantle]

Alr

Gl fam

[vernal kite]

oh wella cttually

[wicked mantle]

Type
.close
To close the channel

[wicked mantle]

ye?

[vernal kite]

i have one mroe

[wicked mantle]

Sure

[vernal kite]

the things not sending gimme a sec

[wicked mantle]

Okay

[vernal kite]

so with this question, i’ve proved the 4 triangles, how can i prove it’s a rhombus now

[wicked mantle]

First, prove that the four sides of the "unknown" graph are the same

[vernal kite]

so ps, pr, sr and rq?

[wicked mantle]

Second, prove that the diagonals of the "unknown" graph are vertical to each other

[wicked mantle]

yes

I just realized that you don’t need second part lol

The first part is just enough

gl, ping me when you’re done

[vernal kite]

@wicked mantle does it hjave something to do with pythag?

[wicked mantle]

Pythag?

yes

[vernal kite]

pythagoras theorem

so (so)^2 + (po)^2 = (sp)^2

and if we replicate that in all four triangles

each side of the rhombus is the same

[wicked mantle]

yep

Correct

[vernal kite]

so would i say since all sides are equal

therefore pqrs is a rhombus

[cedar kiln]

@vernal kite Has your question been resolved?

Channel closed

Closed by @vernal kite

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[glossy vale]

When writing a sequence, do u need to write it by order or by most to least? If there is a repeat term, do u write it twice?

[dire geode]

sequence of what

and for what purpose

[glossy vale]

We have an assignment which asks us to find the first 5 terms of a sequence whose general term is insert formula

[dire geode]

depends on the formula

[glossy vale]

I believe I posted the exact assignment yesterday

I'm just confused as to how I should write the sequence

See the terms are supposed to be -2, 1, 0, 1, 32 do I write it that way or does it have to be least to most? So, -2, 0, 1, 32 no repeated terms?

@dire geode

[dire geode]

.

[glossy vale]

Oh its an=(n - 3)^n

[dire geode]

for what n

[glossy vale]

Depends on which number of a sub so 1, 2, 3, 4, 5

[dire geode]

yea then your answer should be in order of n = 1, 2, 3,...

a1, a2, a3, ...

[glossy vale]

Okay, got it. Thanknyou!

.close

[cedar kiln]

Channel closed

Closed by @glossy vale

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[queen canyon]

Please help I don’t understand how to get these two answers I’m grade 10

I’m stuck on where to even start I k no w these will be on test and forget. Everything else was easy with conjugated but I think this is similar where u multiple by both denominator and numerator but after that I don’t know

[crimson sedge]

.close

[cedar kiln]

Channel closed

Closed by @digital spoke

Use .reopen if this was a mistake.

[hearty arch]

start your question in an open thread. someone will be able to help you there

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gray oasis]

Help me understand a.)

[dire geode]

,rotate

[dire geode]

which equation doesn't make sense first

[gray oasis]

The first one below a

[cinder shard]

its just poor working out. f(x) = cos, f' = -sin

They should have wrote f(x) = cos on that line, OR f'(x) = d(cosx)/dx

[dire geode]

there's a mistake in the notes on that line

[gray oasis]

Where?

[dire geode]

f'(x) = cos x is wrong

[gray oasis]

Why?

[wraith dagger]

riemann

riemann

[gray oasis]

Yes

f'(cosx) = -sinx right?

@dire geode

[dire geode]

that's the wrong notation

$f'(x) = (cos(x))' = -sin(x)$

[wraith dagger]

riemann

[gray oasis]

Ah okay okayy

How about for the second line?

[dire geode]

what about it

m = slope

slope at a point = derivative at a point

[cinder shard]

the function 'm' is not defined.

When you write f(input) that is the function named f, and an input you are passing to it.

You seem to not understand function notation fully. Scratching up on that should help you

You should write f'(pi/2) instead and calculate. Then say let the tangent be y, g(x) or another name and define it as y=mx+c. Then say that the gradient of the tangent, m, is equal to f'(pi/2).

[gray oasis]

Where did -1 came from?

[cedar kiln]

@gray oasis Has your question been resolved?

[dire geode]

do you know special values for sin function

in particular that one

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[open mauve]

Help

[cedar kiln]

@open mauve Has your question been resolved?

[open mauve]

@old ridge

[cedar kiln]

@open mauve Has your question been resolved?

[open mauve]

<@&286206848099549185>

[delicate yarrow]

<@&286206848099549185>

[crimson sedge]

why?

[delicate yarrow]

hello are you braindead

their question still hasnt been answered

[cedar kiln]

@open mauve Has your question been resolved?

[open mauve]

<@&286206848099549185>

[crimson sedge]

I know but what is your problem?

[crimson sedge]

that is different person

[open mauve]

I mean he refers to my question, and this is kinda my slot too XD

[open mauve]

<@&286206848099549185>

So... anyone?

[cedar kiln]

@open mauve Has your question been resolved?

[spice pilot]

@open mauve

i got u

[open mauve]

Hello

You can help?

[cedar kiln]

@open mauve Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[royal loom]

$g^{(n)}(x)=p_n(1/x)e^{-1/x}$ for $x>0$ and some degree $2n$ polynomial $p_n$

[wraith dagger]

Austin

[royal loom]

I am trying to prove this by induction but I keep getting stuck on the degree part at the end

the base case I've done

suppose it is true that g^(m)(x)=p_m(1/x)e^(-1/x) where that polynomial is degree 2m

then

g^(m+1)(x)= (p_m(1/x))' * -1/x^2 + 1/x^2 e^(-1/x)

[flint plinth]

are you going to make us guess what g might be

[royal loom]

g doesn't matter

but it's e^(-1/x)

for x>0

[flint plinth]

well what are you trying to prove then

[royal loom]

just this statement about g

okay maybe g does matter

[flint plinth]

"g doesn't matter"

[royal loom]

but like it's fine

XD

[royal loom]

and then from this, like p_m(1/x)' will be degree 2m+1

and then multiply by the 1/x^2 and it will give 2m+3

which I don't want

it should be 2m+2

but I don't see a mistake

$$g(x)=e^{\frac{-1}{x}} \quad x>0$$

[wraith dagger]

Austin

[royal loom]

$$g'(x)=\frac{1}{x^2}e^{\frac{-1}{x}}$$

[wraith dagger]

Austin

[royal loom]

Suppose $g^{m}(x)=p_m\left(\frac{1}{x}\right)e^{\frac{-1}{x}}$ where $p_m$ is degree $2m$

[wraith dagger]

Austin

[royal loom]

Then $$g^{m+1}(x)=\left(p_m\left(\frac{1}{x}\right)\right)'\cdot \frac{-1}{x^2} + \frac{1}{x^2}e^{\frac{-1}{x}}$$

[wraith dagger]

Austin

[royal loom]

and I have no idea how this new thing is supposed to match up with the degree we want

[cedar kiln]

@royal loom Has your question been resolved?

[royal loom]

.close

[cedar kiln]

Channel closed

Closed by @royal loom

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[drifting dove]

"A woman’s necklace of pearls broke while (rule 2).
A third of the pearls rolled onto the floor,
one-fifth was scattered on the bed,
she herself retrieved one-sixth,
and her lover picked up one-tenth.
If only six pearls remained on the string,
how many pearls did the necklace have?"
Found this in my book

[drifting dove]

Seems like algebra, but im not sure where to start

The name of the poem is elementary arithmetic

So... 💀

[dusty path]

So for this question, you will be adding fractions. Start off by taking all of your fractions and adding them. From there, you can obtain the lowest common denominator. From there, solving this is a matter of adding the numerators, then simplifying your final fraction (if possible, which it should be due to the context of the question involving whole objects).

[drifting dove]

Idk whar that means

Domeone help

<@&286206848099549185>

[dusty path]

I apologise for not answering for a while. So you understand that this is a fractions problem, right?

[drifting dove]

No

This is a necklace problem

[dusty path]

Well yes, it is a necklace problem involving fractions.

[tepid sail]

necklace problem but sure

[drifting dove]

Sure

[tepid sail]

go on please

[dusty path]

You have your set of fractions. To get the total number of beads, you must add the fractions, and in order to add fractions with different denominators, as shown in the problem, you want to make all the fractions have the same denominator.

[drifting dove]

What denomonator

I try 60

[dusty path]

The denominators of all of your fractions. You want to make the denominators of all fractions the same denominator.

[drifting dove]

Or maybe 30

I got 24/30

Waitt

[cedar kiln]

@drifting dove Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[bold ermine]

what's a factor theroem

[spice kraken]

factor theorem states that if (x-a) is a factor of f(x), f(a) = 0

[cedar kiln]

@bold ermine Has your question been resolved?

Channel closed

Closed by @bold ermine

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[acoustic helm]

hello

[acoustic helm]

there was a test question i wasn't able to solve, i cant remember all the components but it goes like this:

the equation of asymptotes of a hyperbola are y=± (4/3)x

However, the focal points are (0,10), (0, -10)

The part that confused me was the focal points

because i thought the focal points would be: a^2 +b^2 = c^2 ---> ±√(a^2 +b^2) = c

but it doesnt work in this case

Please and help and thank you!

.close

[cedar kiln]

Channel closed

Closed by @acoustic helm

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

[vague falcon]

Whats 1+1?

[sharp lotus]

https://blog.plover.com/math/PM.html

[vague falcon]

Whats up?

[sharp lotus]

consult Whitehead and Russell

[vague falcon]

nah i do t need that i need 1+1?

[dire geode]

<@&268886789983436800>

[vague falcon]

No actually

[slate lintel]

1+1 = 2 day timeout, please do not troll in help channels

[vague falcon]

I dint

[slate lintel]

.close

[solid juniper]

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mossy pivot]

Whered i go wrong

og question

my answer

[spice kraken]

it's not (4sint)(3cost)

don't use product rule

[mossy pivot]

oh

ohh

wait chain rule

idk hwy i did product rule

wait

wait yeah then how do i get g'

[spice kraken]

g'(t)=8(4sint+3cost)^3(4sint+3cost)'

now just find derivative of 4sint+3cost

[mossy pivot]

ohhh

[spice kraken]

wait Ityped wrong

lemme fix

ok

[mossy pivot]

got it

4cost-3sint

[spice kraken]

yep

[mossy pivot]

.close

[cedar kiln]

Channel closed

Closed by @mossy pivot

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[granite hare]

I'm working on this discrete math problem

and I know I have to find the least common multiple of the two numbers, but I'm not really sure why that works

[slate lintel]

it might help you to write down the times that each of them return to the start

like the first one returns at 2:04, 2:08, ...

[fair geyser]

some numbers are common multiples of 4 and 6
for example 300 is 75×4 and also 50×6
the first number like that is the least common multiple

[granite hare]

Like this
2:04 -> 2:08 -> 2:12
2:06 -> 2:12

and then i would notice that they both meet at 2:12

and 12 is the LCM of 6 and 4

[slate lintel]

and if you keep listing them out

you'll see that they meet at every common multiple of 6 and 4

[granite hare]

so they'd meet again at 24

then 36

i think i see now

thank you both

.close

[cedar kiln]

Channel closed

Closed by @granite hare

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wary tangle]

could anyone help me with this question? ive got no idea where i go from here💀thanks in advancee :)

[cedar kiln]

@wary tangle Has your question been resolved?

[wary tangle]

.close

[cedar kiln]

Channel closed

Closed by @wary tangle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vernal kite]

for question 2, is there anything that i’ve done wrong so far? i’m not sure what to do after the last step i did

[vague rapids]

how did u write angle DEA =150?

[vernal kite]

co interior angles

[tender wharf]

that's for parallel

[vernal kite]

180 - angle edc

[vernal kite]

ohhh

[vague rapids]

are those parallel

[vernal kite]

nope

i was wondering why

but is dec 30 degrees still?

i mean

angle edc

[tender wharf]

yes

[vernal kite]

but we cant find angle dea

[vague rapids]

what I'd suggest is start from the Left most of the diagram

assume angle HBG to be x

then by using properties of triangles, try to label each angle in terms of x until you get to angle GDE

[vernal kite]

would angle hbg + angle hgb = angle hgf

[vague rapids]

no

that would be equal to angle GHF

[vernal kite]

ohhh alr

so angle ghf is 2x then

[vague rapids]

well you don't need to ask "if that is equal to that"

Just keep in mind that sum of all angles in a triangle is 180 degrees and sum of angles of a linear pair is 180

[vernal kite]

i got angle bed = 8x

[vague rapids]

well that is not what you should get

check your working

[vernal kite]

so ghf = 2x

fgd = 4x

and then angle bed = 8x

[vague rapids]

are you sure?

[vernal kite]

i can't solve it

[vague rapids]

This aint nothing too hard

[vernal kite]

how is it not 4x

2x+2x

[vague rapids]

well 180= angle HGB+ angle FGH+ angle FGD

[vernal kite]

6x - 180

[cedar kiln]

@vernal kite Has your question been resolved?

[green mulch]

X is 4.2 something

[vernal kite]

no

[green mulch]

X is 6

[vernal kite]

yes

[green mulch]

U got it?

[vernal kite]

nope

[green mulch]

Should I explain?

[vernal kite]

yes please

[green mulch]

Just a sec

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[vernal kite]

.reopen

[cedar kiln]

✅

[green mulch]

So now in EBD 4x + x + 150= 180

5x = 30

So x = 6

Ask me if I don't understand anything

[vernal kite]

how is angle fgd = 3x

isn't the sum of two opposite interior angles = one exterior angle

[green mulch]

Let fgd be y

Then x + 180-4x + y = 180

Solve for y and u would get y = 3x

[green mulch]

Yes but here the angle is not the complete ext angle

Got it?

[vernal kite]

is y just 180 - 4x + x?

oh wait nvm

[green mulch]

Yeah...

[vernal kite]

yea i get it

[green mulch]

Btw which grade question is this

I just wanna know

[vernal kite]

grade 10

or year 10

[green mulch]

Ohh

[vernal kite]

im in australia

this is tuition homework

[green mulch]

Noice

I am in grade 9 htw

Btw*

[vernal kite]

in aus?

[green mulch]

In India

[vernal kite]

oh wow

thats like

[green mulch]

We love maths for some reason

[vernal kite]

year 12 here

[green mulch]

Oh

I didn't know that

[vernal kite]

all asians do

[green mulch]

How old are u btw?

[vernal kite]

cant tell u

[green mulch]

True

[green mulch]

K np its just that the year system is confusing

[vernal kite]

yea it is

im gonna close this channel

thx for the answer

[green mulch]

Npp

Byee

[vernal kite]

cya

.close

[cedar kiln]

Channel closed

Closed by @vernal kite

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

in the derivation of $\ds\vj T = \dv[\vj r]s$

[crimson sedge]

we can say the following:

\begin{align*}
\vj T &= \4{\dv*[\vj r]t}{\3{\8{\dv*[x]t}^2+\8{\dv*[y]t}^2+\8{\dv*[z]t}^2}} \qq \0r{\8[\bigg]{s = \int_\alpha^\beta\3{\8{\dv[x]t}^2+\8{\dv[y]t}^2+\8{\dv[z]t}^2}\dd t}} \\
&= \4{\dv*[\vj r]t}{\dv*[s]t}
\end{align*}

[crimson sedge]

but the problem is that u have to makea beta vary right?

[hollow trail]

usually you would define it as s = integral from alpha to t of some dummy variable

[crimson sedge]

right

and i guess u have to place some conditions

like the curve has to be simple and smooth

(smooth: continuous and not 0. simple: does not cross itself)

[hollow trail]

i don't think it necessarily needs to be simple

[crimson sedge]

wouldnt it just go on an infinite loop if it was non-simple?

since the integral is like directed

@sacred grail you said something about this like 2 years ago to me can u tell me again

[sacred grail]

idk what the question is

[crimson sedge]

like, can we define the arc length of a non-simple curve

[cedar kiln]

@crimson sedge Has your question been resolved?

Channel closed

Closed by @lone wigeon

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[azure marsh]

Part d

I dont know how to derive the middle expression

[spice kraken]

integral represent area

[azure marsh]

yep

integral gives the first and last expression

i was thinking rectangles

[spice kraken]

yes

[azure marsh]

sum of rectangles gives middle

but i tried

didnt get anywhre

[spice kraken]

what did you get

[azure marsh]

so 1/2 + 1/3 +1/4 +.......... 1/k is the sum of the rectangles

after that no idea how to simplify it

[spice kraken]

??

how'd you get recipricols

[azure marsh]

im dumb

sorry

i get it

ln(k!)

is sum of rectanfles

got it thanks

.close

[cedar kiln]

Channel closed

Closed by @azure marsh

Use .reopen if this was a mistake.

[azure marsh]

Part bi

I get the gradient but not sure how to use part a

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[split raven]

help how do i solve for this?

[spice kraken]

parallel mean same slope

perpendicular mean slopes multiply to -1

[split raven]

ohh

but how do i solve it? turning it to sif? solving one by one?

[spice kraken]

yes find the slope and see if it meet the requirement

[split raven]

alright

is letter b right for no.7? @spice kraken

[spice kraken]

I don't think so

[split raven]

im confused

[spice kraken]

what are the slopes you calculated

[split raven]

x - 2y = 2
-> y = 1/2x - 1

a. y = 1/2x - 5/2
b. y = x + 1
c. y = -2x + 3
d. y = -2/3x + 3

[spice kraken]

the slope is 1/2

[split raven]

oops

[spice kraken]

b has slope of 1

[split raven]

what

[spice kraken]

y = 1/2x - 1 has slope of 1/2

[split raven]

yea

if perpendicular it has to be -1/2 but none of the slopes in the choices are

[spice kraken]

we want the slopes to multiply to -1

we would actually want -2

since -2/2=-1

[split raven]

yea

so what now

[spice kraken]

well which option has slope of -2

[split raven]

c

[cedar kiln]

@split raven Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cloud igloo]

2x + y = 1000
how do I find the highest possible value of xy?

[cloud igloo]

ping me if you respond, I am not having this chat open

[earnest socket]

solve for one in terms of hte other

[cloud igloo]

what does f(z,y) mean? I have only worked with equations with 3 unknowns on paper

[raw gulch]

x should be was writign very fast

[raw gulch]

that is function, not the equation, write it in yoru exercise book and find its maximum, that is all

[cloud igloo]

I dont fully understand whats being done here, can you explain it step by step?

oh wait

[raw gulch]

your new function gj is a quadratic function, its expression is a parabola opens down, so it reaches its maximum at the vertex

find coordinates its vertex

then you get where x is reched and value fo max that is all

[cloud igloo]

I came to the answer x = 250 and y = 500, is that correct?

[raw gulch]

right, i was not calculatin the est in my mind, so if yo wroe correct then all is ok

maximum si reached at x = 250 and its max value = 500

\thsi way , it shud be written in an exercise book

[cloud igloo]

alright, ty

.close

[cedar kiln]

Channel closed

Closed by @cloud igloo

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[abstract wolf]

hey I needed some help with this question

[proud vortex]

so

avery

the tank has a 1cm thick wall

to find the volume of the material

u need 2 radii

one is 1m

[abstract wolf]

ummm

[proud vortex]

other is 1m + 1cm

[abstract wolf]

👀

[proud vortex]

now you apply the regular formula for the volume of cylinder but replace r square

with r1 square - r2 square

r1 being 1m

[abstract wolf]

why

tho

😭

[proud vortex]

oops its a hemispehre

hmm sorry

wait ill solve it for ya

[abstract wolf]

okie tyy

[abstract wolf]

lol its fine

(im just in 9th grade :,)) )

[proud vortex]

now could you solve the rest

[abstract wolf]

i cant see the third part :((

[proud vortex]

no its just dots

you have to calculate it

[abstract wolf]

sorry

uh

nonono

not that part

the

thing after volume of the material

[abstract wolf]

ok thanks!!

but why subtracting tho

i still dont get it

[crimson sedge]

I assume cuz ur finding the volume only of the outer wall of the tank

[abstract wolf]

ohh

thanks

[crimson sedge]

i suck at following along but

yh

ur subtracting the empty inside

from the full volume

to js find the iron leftover

u get it?

[abstract wolf]

loool its fine :))

[abstract wolf]

yeah!!

and thanks once again!

[crimson sedge]

ofc

[abstract wolf]

.close

[cedar kiln]

Channel closed

Closed by @abstract wolf

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[green vault]

Hi, is reverse matrix the same thing with inverse matrix?

[green vault]

And what does this phrase mean?
infinite reverse right-handed perspective projection matrix

.close

[cedar kiln]

Channel closed

Closed by @green vault

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[quick flume]

Is this correct?

[quick flume]

It’s an exponential equation

[mild sundial]

no

the exponent rule says $a^{x+y} = a^x*a^y$

[wraith dagger]

swerriee

[quick flume]

Like so?

[mild sundial]

how did you get 6^x

[mild sundial]

you can take 2^x common

[quick flume]

4*2^x-2

Idk

Tell me then what to do next

[mild sundial]

do this

$x*a^x - a^x = a^x(x-1)$

[wraith dagger]

swerriee

[mild sundial]

nooo that was just an example

[mild sundial]

in place of x we have 2^2

The rest of it is correct

[mild sundial]

correct

[quick flume]

And what do I do next

[mild sundial]

simplify further

[quick flume]

How do I get 32 to exponential form

[mild sundial]

take lcm of 32

[quick flume]

2?

Alright doesnt matter

[mild sundial]

its like this

[quick flume]

And could you help me with this one aswell?

[quick flume]

Yeah I got it

[mild sundial]

bring sqroot to the other side and apply the quadratic formula

wait

[mild sundial]

is it 7^x or 7x?

[quick flume]

7^x^2

Is that possible to solve then?

[quick flume]

.

[mild sundial]

You will get the answer in terms of log then

and root smh

[quick flume]

So how do I do it

.close

[cedar kiln]

Channel closed

Closed by @quick flume

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pliant pine]

this may seem like a silly question but

[pliant pine]

if u had a convergent sequence with limit L s. t. for all epsilon > 0, |an - L| < epislon for all n => N

why does it also follow that |an - L| < epsillon/2 for all n => N

or is there a way to prove it

[azure horizon]

it's true that |a_n - L| < e

so if you want |a_n - L| < f/2

then you can let e = f/2

and then that just works

[pliant pine]

but then wouldnt e just be restricted to the values of f/2

[azure horizon]

?

ok so: for all e > 0, there exists N st. n > N => |a_n - L| < e

[pliant pine]

yes

[azure horizon]

so suppose you want |a_n - L| < f/2

let e = f/2

[pliant pine]

ohh then u set e = f/2

and it still works

[azure horizon]

yeah it's like

a relabelling

[pliant pine]

how would this change for something like

2e tho

[azure horizon]

well it just works

i mean you could say the reverse thing

[pliant pine]

like does it follow that for all e > 0, there exists N st. n > N => |a_n - L| < e

[azure horizon]

ok so: for all f > 0, there exists N st. n > N => |a_n - L| < f

so if f = 2e

there exists N st. n > N => |a_n - L| < 2e

[pliant pine]

wait i perhaps asked the wrong qu

i want the converse of that statement

eg if < 2e then does it follow for all < e

[azure horizon]

yes

ok so: for all f > 0, there exists N st. n > N => |a_n - L| < 2f

you want |a_n - L| < e

so let e = f/2

then for all e > 0, there exists N st. n > N => |a_n - L| < 2f = e

like

the point is that if you can make this thing as small as you like

then you can just make it twice as small

sorta??

[pliant pine]

oh icic

one more qu

when u say for every e > 0, |a_n - L| < e for all n => N, it doesnt imply |an - L| = 0 for all n => N right?

[azure horizon]

absolutely not

for example just take like

[pliant pine]

then why do they do they do it in this proof

[azure horizon]

1, 1/2, 1/3, 1/4, 1/5

[pliant pine]

(last line)

unless im mis understandin

[azure horizon]

they're talking about the limits there

the limits are not the same as the sequence

ok so

take 1, 1/2, 1/3, 1/4, 1/5

[pliant pine]

yes

[azure horizon]

as one sequence

and then take -1, -1/2, -1/3, -1/4, -1/5 as another

basic

then the differences are

2, 1, 2/3, 2/4, 2/5,

none of these are ever 0

but the limits

the limit of the first one is 0

and the limit of the second one is 0

[pliant pine]

yes

[azure horizon]

and 0-0 = 0

the differences go to 0 but aren't 0

the limit of the differences is 0

[pliant pine]

waza

[azure horizon]

or something like that

[pliant pine]

but if the differences go to 0 isnt that the same thing as saying an becomes L...

ohh

[azure horizon]

no

[pliant pine]

go to

so it goes to L

but doesnt become L

[azure horizon]

gets arbitrarily close

like, as close as you like

but never touches

[pliant pine]

wait but then why do they conclude |M - L| = 0 tho

[azure horizon]

ok so

let the limit of the differences in my example be like D

so D is the limit of 2, 1, 2/3, 2/4, 2/5, ...

[pliant pine]

yes

[azure horizon]

then we can say

D < 2

D < 1

D < 2/3

D < 2/4

in fact

D < 2/n for all n

but a number that isn't negative that's smaller than 2/n for every n

has to be 0

because if D was positive then you could find 2/n smaller than D

but D < 2/n for all n

[pliant pine]

i am followin somewhat

i think this the type of thing which i need to let sit for a before it clicks

lol

[azure horizon]

yeah basically

[pliant pine]

also apologies if i ask a lot of qus

i tend to lol

[pliant pine]

oh wait i think im understanding

the reason we say |an - L| is because if an tends to L, a_n will always get arbitrarily close to L but never actually approach it

hence the for all epsilon > 0, |a_n - L| < epsilon bla bla

however since L and M are fixed real numbers, if we say for all epsilon > 0, |L - M| < epsilon for all n => N, then this implies that |L - M| = 0 because unlike a_n which tends to the limit L, these are fixed real numbers

therefore the only way for them to be < epsilon for all epsilon > 0, is for |L - M| = 0

is that right @azure horizon ?

[cedar kiln]

@pliant pine Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[open flame]

hello , i have a question in my book that should be similar to this : but its a triangle that should be solved to find X

[open flame]

who can help?

[subtle hinge]

didnt u just get the vallue of x

[open flame]

no i meant its similar to this

question is :Question : find x that makes the triangle larger or equal to 20

[subtle hinge]

u mean area of triangle or perimeter of tiangle?

[open flame]

i dont get it please help

.close

[cedar kiln]

Channel closed

Closed by @open flame

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[serene bison]

shoudn't it be

$8(3-2x)^-4/7$

[wraith dagger]

Daddy Goat

[serene bison]

how is it positive

[dire geode]

yup that's a typo

[serene bison]

he continued on solving it as it is lmao

[open yew]

typo

[dire geode]

can you share the video

[serene bison]

https://youtu.be/B1YkgNDbx5o?si=w0NzDNkINiK7atGD&t=764

[dire geode]

thanks

[serene bison]

i put the time stamp read just play it

[dire geode]

rare organic chem L

[serene bison]

real

bro wants me to fail my math test 😂

good thing i noticed immediately tho!

[dire geode]

most of his videos are good

[serene bison]

yep he is my favorite, very chill guy

so wait is the answer

$d/dx 52/7 ^7sqrt{3-2x ^11}$

[wraith dagger]

Daddy Goat

[serene bison]

bruh

[runic garnet]

,rotate

[runic garnet]

try not to say d/dx = the original function

u wanna do

$\frac d{dx} [8(3-2x)^{-\frac 47}]$

anyways

[serene bison]

oh you mean the {}?

[runic garnet]

this

ok so look at ur application of the chain rule

when u took the derivative of the inner function

3-2x

whats the derivative of that

[serene bison]

ah wait, -2 yeh

i missed that

[runic garnet]

ye

[serene bison]

give me a sec

[wraith dagger]

Stephen

[runic garnet]

also howd u get 52?

[serene bison]

,rotate

[serene bison]

I multiplied 2 with -4/7 and then

56/7 - 8/7

[runic garnet]

but that 8 in front is being multiplied to the expression

its 8 * -4/7 * -2

[serene bison]

Oh yeh that should have been done first

[runic garnet]

ur final answer looks good now, just make sure u have parentheses around (3-2x) otherwise it looks like 3-2x^11

[serene bison]

Aight, I will try to rationalise it rn and send the simplified form

[runic garnet]

why rationalize?

thats the simplest form ur gonna get

[serene bison]

idk what if my teacher asks me that during the exam

[runic garnet]

then do it, but u wont be able to rationalize this

[serene bison]

ok well thank you for the help man 💪🏽

.close

[cedar kiln]

Channel closed

Closed by @serene bison

Use .reopen if this was a mistake.

[runic garnet]

dang

u deadlift 550 at 17

thats crazy

[serene bison]

https://tenor.com/view/sam-sulek-sam-sulek-gif-tik-tok-gymtok-gif-9739246323956231374

[serene bison]

appreciate you gang.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pulsar vault]

part b, i worked out part a using cosine rule and have length ac but have no idea how to work out length dc

[slow jewel]

,rrcw

,rccw

[slow jewel]

Ig you can equate the power of the point(X) along AX and DX

[pulsar vault]

what do you mean equating the power of the point

[slow jewel]

From the external point X, if a line is drawn to a circle intersecting at one or more points then product (BX)(AX) is a constant

Have you ever come across anything like that?

[pulsar vault]

im 14 bro 😭

[pulsar vault]

no

[raven shard]

it sounds more intimidating than it actually is

[pulsar vault]

is this not calculus stuff

[pulsar vault]

makes sense

[cedar kiln]

@pulsar vault Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

i dont understand how theres so many (x-6)^2

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hasty warren]

could someone please help me? // check for convergence/divergence of series

[cedar kiln]

@hasty warren Has your question been resolved?

[dire geode]

expand the denominator then compare the highest powers of the numerator and denominator

[cedar kiln]

@hasty warren Has your question been resolved?

[hasty warren]

can u please write it out for me rq?

[dire geode]

no do it yourself

[hasty warren]

yeah but i dont know how

can i just use cauchy

[cedar kiln]

@hasty warren Has your question been resolved?

[cedar kiln]

@hasty warren Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[uncut roost]

hello can someone explain this

[uncut roost]

like how are they doing that

[lost gyro]

pretty sure that's just direct application of power rule

[patent belfry]

Yeah

[uncut roost]

it is but im not sure whats going on

[lost gyro]

d/dx(x^n) = nx^(n-1)

[patent belfry]

Do you know why the power rule is true

[uncut roost]

no i dont

only if its not 0

n =/= 0

[patent belfry]

So what do you not understand completely

[uncut roost]

what is happening in the first step

they found the derivitive of x^4

which is 3x^4

[lost gyro]

4x^3 but yes

[uncut roost]

oops

i wrote it backwards

[lost gyro]

so what's confusing

[uncut roost]

then whats happening in the second step

[patent belfry]

Thats the other rule that i forgot the name of where you can take constants on a temporary vacation outside the derivative

So it can see the world

[uncut roost]

wow

why is it on vacation

[patent belfry]

Its overstressed being in a function

Thats hard work for a poor constant

[uncut roost]

that is so sad

i understand now

he is a constant so he is worth nothing

[lost gyro]

do you have a textbook...reading it would probably help

[uncut roost]

he is USELESS!

😢

but he only beileves hes useless

[patent belfry]

#constantslivesmatter

[uncut roost]

he is not actually useless

[patent belfry]

Yes

[uncut roost]

(what is the next step)

[lost gyro]

@uncut roost
https://math.libretexts.org/Bookshelves/Calculus/Calculus_(OpenStax)/03%3A_Derivatives/3.03%3A_Differentiation_Rules

Just read this. This clears up everything you're asking. From there, it's plug and chug with the power rule

[patent belfry]

He comes home from the vacation after the student finishes the derivative with a new sense of self worth and freedom

[uncut roost]

WOW!

how do you know if he has to go on vacation or not

[lost gyro]

I'm just going to leave cause I'm cringing at this conversation

[uncut roost]

LMAO

no wait

DONT LEAVE!

@lost gyro how do you know if the constant has to go out

[patent belfry]

Generally you want to get the multiplication constants out of the derivative

Sadly the fate of the addition constants in this case is death from overworking

But multiplication constants can go outside the derivatice

And it becomes easier to solve

[uncut roost]

so if it was

so if it was 1/2 + 4x^3

he cant leave?

[patent belfry]

Yep

[uncut roost]

wait where is the vacation place

[patent belfry]

He gets reduced to zero

[uncut roost]

where is he even going

[patent belfry]

Outside the derivative sign, symbolizing his dream of escaping work and going to the places of his dreams

Whether it be hawaii, or maybe a nice cruise ship in mexico

Whatever it desires

[uncut roost]

but where is the derivitve sign

and why didnt they do that in that step

[patent belfry]

Its implied

They just skipped a step

[lost gyro]

it's not implied... it's indicated by the f'(x)

[uncut roost]

does he have to leave?

[patent belfry]

Yes but moving it out of the derivative and back in is implied

[patent belfry]

Yes he does

[uncut roost]

always?

[patent belfry]

Yea

[uncut roost]

lets look at the second question

[patent belfry]

Same thing again basically

[uncut roost]

why cant you multipy the 4 with the 1/2

for the first question

[patent belfry]

You can

They do that

To get 2x^3

[uncut roost]

cant they do that for the second step too

[patent belfry]

Thhe second question you mean

They do do that

[uncut roost]

yes

[patent belfry]

They do 6*2/3

[uncut roost]

no

multiply it from the top

the little top part multiplied by the first number

the exponent

[patent belfry]

Yea

They multiply those 2

[uncut roost]

no they didnt

they f ' (x) it

only the x^4

🤬

WHY DID THEY MAKE THIS TECHNIQUE

okay

i understand now

[patent belfry]

Wym

[uncut roost]

x^4 = 4x^3

[patent belfry]

Yes

Then times 1/2

And the second one

x^2/3=2/3x^-1/3

[uncut roost]

its a different tecnique

i understand now

[patent belfry]

Same technique

Different application

[uncut roost]

okay

thank yo

you

:)

[cedar kiln]

@uncut roost Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[uncut roost]

hello i need help

[uncut roost]

with the first one

do i factor it?

[spice kraken]

You can expand it

[uncut roost]

okay

thank ypu

[cedar kiln]

@uncut roost Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

Can someone explain this to me?

[crimson sedge]

I dont understand any of it

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

@crimson sedge Has your question been resolved?

Channel closed

Closed by @sand locust

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[plush ferry]

I have to factor by completing the square and I swear I did everything right but apparently the answer key says I’m wrong (second pic)

[plush ferry]

Nvm I used found a way to solve the process so I could see my mistake

.close

[cedar kiln]

Channel closed

Closed by @plush ferry

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed by @honest pelican

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[azure marsh]

Part b

Length of AB = AC = 2root(14)

[hidden vapor]

1)Apply herons
2) BC let be base
Write equation of BC and drop a perpendicular from A and find its length and 1/2 b * h

Kinda like this

[cedar kiln]

@azure marsh Has your question been resolved?

Channel closed

Closed by @azure marsh

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[spice kraken]

notice that n choose k is the number of subsets of S with k elements

[cedar kiln]

@honest torrent Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pseudo merlin]

If a quadrilateral has 2 pairs of parallel sides then the opposite sides are congruent

[pseudo merlin]

The converse to this is If the opposite sides of a quadrilateral are congruent, then it has 2 pairs of parallel sides?

Is this false?

Maybe a counterexample could be a rhombus?