Pls help
#help-13
tawny garden
viscid mason
is it 112/9
viscid mason
You can write this as (1/2 + 1/9) / (1/16)
opaque root
viscid mason
BRO
tawny garden
How u guys so smart 😭
viscid mason
sorry
viscid mason
How u guys so smart 😭
in which grade are you in ?
tawny garden
8
viscid mason
bro read your textbook for exponents ad powers and fractions , you will understand it
cedar kilnBOT
@tawny garden Has your question been resolved?
chrome turtle
How do you problems like finding number of 4 digits mumber with the digits in increasing order ex 1234 is valid but 1254 is not
nimble mountain
you start by taking a number and seeing how many possibilities that eliminates
chrome turtle
oh
prisma gull
How do you problems like finding number of 4 digits mumber with the digits in in...
Are you asking how to implement it as a computer program ?
nimble mountain
eg you can start with the first digit being 1, then subsequent digits can be 1 to 9
chrome turtle
eg you can start with the first digit being 1, then subsequent digits can be 1 t...
yes i thought of this way but
sturdy rose
How do you problems like finding number of 4 digits mumber with the digits in in...
is there no other restriction
chrome turtle
isn't that a bit lon
nimble mountain
if the first digit is 8 the subsequent digits can be 8 or 9
chrome turtle
is there no other restriction
no
chrome turtle
if the first digit is 8 the subsequent digits can be 8 or 9
Yes but that wouldn't be a valid number cause they must be increasing
ithink
The highest number can be 6789 i think
nimble mountain
oh. strictly increasing? yea adjust it accordingly then
chrome turtle
I see so case by case is the only option?
sturdy rose
I see so case by case is the only option?
yes
it is fairly easy tho
idk if you have solved ncert, but theres a question of flags at the end of 3rd exercise or something
uses the same analogy
chrome turtle
Oh
sturdy rose
That is a question of flag and colours
but this one is roughly based on the same idea
move one ahead by ditching the last one
you can solve this by writing down numbers from 1 to 9
and then drawing a line under every 4 digit number greater than the previous
unless i am missing something and 6 is not the answer
chrome turtle
why am i seeing a lot casework
123 (456789) then same for 124 (56789)
Am i approaching this a wrong way?
split pike
Am i approaching this a wrong way?
does the nos have to be consec like 1234
or 1245 is valid?
split pike
nice
chrome turtle
that is how i am getting a lot of casework
chrome turtle
Soz
sturdy rose
How do you problems like finding number of 4 digits mumber with the digits in in...
i dont get it
if the digits are in increasing order
is 1357 allowed ?
chrome turtle
Yess
chrome turtle
sturdy rose
Is your binomial strong?
chrome turtle
I dont know if im at advanced level yet in that
sturdy rose
I dont know if im at advanced level yet in that
word pisses me off so bad
okay
there are two ways
cases
and logic
chrome turtle
yes
sturdy rose
the answer is simply 9C4
chrome turtle
chrome turtle
okay
sturdy rose
if you cant solve it in 4 days, you can ask again
cedar kilnBOT
nimble mountain
sad
cedar kilnBOT
Available help channel!
nimble mountain
.close
cedar kilnBOT
sturdy rose
@chrome turtle take a hint
selection is in your hand, permutations arent
chrome turtle
Alright I'll try tyy
chrome turtle
<@945280472739618846> take a hint
selection is in your hand, permutations arent
Broo 💀 💀 💀
Ty
cedar kilnBOT
Available help channel!
chrome turtle
I got it just now
cedar kilnBOT
I got it just now
cedar kilnBOT
crimson sedge
cedar kilnBOT
Available help channel!
zinc pagoda
Is my calculation correct?
cedar kilnBOT
Is my calculation correct?
sturdy rose
Is my calculation correct?
depends on ur calc
which u can also verify using a calculator..
but still 51X51
its correct
cedar kilnBOT
@zinc pagoda Has your question been resolved?
umbral mirage
Hi, I got this equation. I thought there would be an asymptote at y=0, as x^2 is larger than x. But there isnt, can anyone explain to me why?
lavish lily
why would there be an asymptote at y=0?
did you mean x = 0
even then there wouldnt be an aysmptote
umbral mirage
because in a rational function, when the denominator has a higher power than the numerator, the asymptote is at y=0
true violet
because in a rational function, when the denominator has a higher power than the...
if you mean a horizontal asymptote you should be right
gusty forum
Hi, I got this equation. I thought there would be an asymptote at y=0, as x^2 is...
because at x=0 f(x) = 0
a slightly more accurate reason would be that the denominator here is always defined (as x^2+1 = 0 has no real solution)
and horizontal asymptotes for rational functions come when you have a denominator that can be undefined and the denominator is a linear function
true violet
because at x=0 f(x) = 0
a slightly more accurate reason would be that the denom...
oh i thought horizontal asymptotes were the behavior of the function as it tended to infinity/-infinity my bad
near sapphire
Hi guys
near sapphire
I need help in this
How to find the measure of unknown marked angle or arc
<@&286206848099549185>
cedar kilnBOT
@near sapphire Has your question been resolved?
near sapphire
Damn
cedar kilnBOT
@near sapphire Has your question been resolved?
gentle abyss
how would u do this integer?
cedar kilnBOT
how would u do this integer?
gentle abyss
yeah i've done so its (x^2+1)(x-1)(x+1)
raw gulch
how would u do this integer?
you need to decompose the given rational function into the sum of partial fractions and then integrate
marsh lake
you need to decompose the given rational function into the sum of partial fracti...
yeah this
open a new channel
raw gulch
yeah i've done so its (x^2+1)(x-1)(x+1)
yes, it is ok, and next write your given function f in a following way:
$f\left( x \right)=\frac{A}{x-1}+\frac{B}{x+1}+\frac{Cx+D}{x^{2}+1}\text{ }\text{ }\text{ etc}$
wraith daggerBOT
Joanna Angel
marsh lake
**Joanna Angel**
wait why is it Cx+D
raw gulch
yeah i've done so its (x^2+1)(x-1)(x+1)
find A, B, C, D, and then integrate
raw gulch
wait why is it Cx+D
because denominator in third fraction cant be factored in real set
sharp folio
yes
raw gulch
wait why is it Cx+D
then we write general form of the linear function over such unfactored trinomial
sharp folio
everytime that the las fraction odesent have a real rest we use Cx + D
marsh lake
ohhh
gentle abyss
.close
eternal pollen
you can't write
dBi + W
right?? that doesn't make any sense
cedar kilnBOT
you can't write
dBi + W
right?? that doesn't make any sense
tropic oxide
context?
eternal pollen
it's a question about antennas
"A transmitter system has a power of 13 W, no line loss and an antenna gain of 39.0 dBi. Assume that the transmitting antenna is replaced with an isotropic antenna and that the line is still lossless. What must the transmitter power be for the signal to be as strong as it was along the previous main lobe? Give the answer in watts."
and I wasn't sure how to do it so I asked chatgpt to see what it did, and I had a feeling that it wasn't going to be able to do it
and I was kinda right
cuz the first time it gave me 7955.28 W
tropic oxide
gpt is not to be trusted
eternal pollen
yeah
tropic oxide
i personally dont know what dBi stands for so oops
wintry prism
you can't write
dBi + W
right?? that doesn't make any sense
well dBi is dimensionless because it's a ratio so you can't add it to watts
eternal pollen
then I asked why it sett G_{iso} to 0 dBi
and it changed the answer to 7956.28 W
then I asked if it was sure
then it changed it to 52 W
eternal pollen
well dBi is dimensionless because it's a ratio so you can't add it to watts
yeah, that's what I thought
you have to convert it to watts first
right?
eternal pollen
well dBi is dimensionless because it's a ratio so you can't add it to watts
so do you know how to do the question?
crimson sedge
hi
wintry vault
!redir
cedar kilnBOT
This channel is only for on-topic discussion. Please take casual conversation to #discussion or #chill.
@crimson sedge Has your question been resolved?
dire geode
i needed help with math
cedar kilnBOT
@crimson sedge Has your question been resolved?
soft lark
cedar kilnBOT
daring kelp
draw the situation
daring kelp
where's the tree
soft lark
the 56
daring kelp
from where you're standing and looking up at the tree, there's 56 feet to the base of the tree
cedar kilnBOT
@soft lark Has your question been resolved?
obsidian fox
Question can someone explain step by step ( e.g any equations used) on how to do this?
crimson sedge
which
idle tusk
Question can someone explain step by step ( e.g any equations used) on how to do...
is there a picture missing?
idle tusk
well
you have a base, and 4 triangular faces
they all sum up to be the surface area
the base is a square - what's the area of a square?
all triangle faces are equilateral triangles - what's the area of an equilateral triangle?
obsidian fox
all triangle faces are equilateral triangles - what's the area of an equilateral...
Oh do you just use 3d trig to get the perpendicular height
obsidian fox
Area of equilateral triangle = half x base x height
idle tusk
obsidian fox
Oh wait
cedar kilnBOT
cedar kilnBOT
Available help channel!
bright sorrel
If R is the relation R\{0}xR\{0} defined as xRy -> |x|+|y|=|x+y|
prove that it's transitive
bright sorrel
right so let's include another variable in the relation z
we get
|x|+|y|=|x+y|
|y|+|z|=|y+z|
our professor explained it very vaguely
he said that we have to prove that |x|+|z|=|x+z| but that's not the vague part
he said that for x and y to be in relation, they have to have the same sign
then he said that if x>0 and y<0 then |x|+|y|=x-y, but |x|+|y|=|x+y|
and he just said that now we have xRz
and I wasn't that confused in my whole life
how did he prove that xRz?
crystal raptor
once you have that the relation is just "x and y have the same sign", then if you know x and y have the same sign and y and z have the same sign, do you see how to conclude?
bright sorrel
uhh, not yet I guess
I don't understand how that proves that they are in relation
xRz I mean
crystal raptor
do you understand that the relation is now xRy if and only if x and y have the same sign
this is equivalent
crystal raptor
right but also if they do have the same sign then they are related, you can and should check this
crystal raptor
then he said that if x>0 and y<0 then |x|+|y|=x-y, but |x|+|y|=|x+y|
they have to have the same sign because of this argument yes
but it is also true that if they have the same sign then they are related
so now you know xRy if and only if x and y have the same sign
it is the same relation
crystal raptor
and hopefully it is then clear that if xRy and yRz then xRz
bright sorrel
it is, but it's so simple it easily slips through
it's just one of those moments in math where it's so simple it just slips through
crystal raptor
yeah it happens
static egret
Can you find n for 1.2=1.04^n without using log
cedar kilnBOT
Can you find n for 1.2=1.04^n without using log
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
opal basin
autumn fox
There is an integer solution to 1.2 ≈ 1.04ⁿ though, if you accept approximate values
So you could just multiply 1.04 by itself until it's approximately 1.2
crimson sedge
cedar kilnBOT
muted bear
heres a qeird question: do you play fortnite or any game with a compass?
not your channel
crimson sedge
u dident help me man
muted bear
and it makes sense
muted bear
!noadvert
cedar kilnBOT
Please do not advertise your help channel or thread in other parts of the server. There are many people who need help, so advertising can quickly turn into spam.
muted bear
anyway
cedar kilnBOT
Please do not advertise your help channel or thread in other parts of the server. There are many people who need help, so advertising can quickly turn into spam.
muted bear
why i say that is because those numbers refer to you rbearing
muted bear
you always go from north and go clockwise
crimson sedge
what do think i tried for the last 20m
muted bear
ok
slim quiver
Hi there, MaAt
muted bear
lets look at bearing from A to B
crimson sedge
67?
slim quiver
North is 0 degrees, and due east is 90 degrees
muted bear
yes
slim quiver
The acute angle in the pink section represents the bearing to the target
From 0, you don't quite make it to a perfect right angle at 90, so this makes sense
The angle from the target back to you, however, is NOT represented by the blue section, since the angle back to you would be 180 degrees flipped from your bearing to the target
Note that the 113 degrees is from a counterclockwise rotation - not a clockwise one
You can either subtract the 113 from 360 (a full circle) = 247
Or you can add 180 to your bearing to the target; 67 + 180 = 247
crimson sedge
i dont understand
slim quiver
Ok, no problem.. can you be more specific, though? What concept is getting you tripped up?
crimson sedge
like how to get the answer as ive never done this topic before and it appered on my work
slim quiver
Are you familiar with a compass and North, East, South, West directions?
crimson sedge
yes
slim quiver
Ok - And you know that North is "up" and East is "right" on a standard map, right?
crimson sedge
yes
slim quiver
Great - Now, you're also aware that we take that full circle and divide it up into 360 degrees, so that 0 degrees is North and 90 degrees is East (and 180 degrees is South and 270 degrees is West)
Which means that 360 degrees is the same direction as 0 degrees, right?
crimson sedge
in the same context yes
slim quiver
Ok.. do you know what a "bearing" is?
(Sorry for the dumb questions.. just trying to figure out what's getting you stumped)
crimson sedge
no i dont
slim quiver
OK! So, if you're facing North, you are facing a bearing of 0 degrees... a "bearing" is just a fancy way of saying "Which direction"
slim quiver
So the bearing to the target is 67 degrees, because it's just 67 degrees clockwise from North
crimson sedge
yep
slim quiver
Now, pretend you're standing at B, and where you were previously standing is A
A is now slightly behind you and to the left, which means it has to be between 180 and 270
slim quiver
So if we're going around the circle clockwise, we're looking at that large orange chunk at 247 degrees
crimson sedge
yes
slim quiver
And that is the bearing from B back to A
crimson sedge
yes
slim quiver
Cool.. have any questions or thoughts?
crimson sedge
now im trying to figure out the answer
slim quiver
Those are the answers
crimson sedge
sorry its just ive got like a problem with my mind
slim quiver
No, you're fine
crimson sedge
so A is 67?
slim quiver
The bearing, or direction, from A towards B is 67 degrees
Because if you're standing at A, B is slightly ahead of you and to the right... clockwise, it's 67 degrees
If you're standing at A and facing North, I should specify
crimson sedge
sorry
slim quiver
You're fine
crimson sedge
i just dont understand whole
slim quiver
Copying this down so I don't have to keep scrolling up
So you're standing at A and you're looking straight ahead at North
I'm at B and I'm also looking straight ahead at North
crimson sedge
ok
slim quiver
Better yet, pretend we're standing on two parallel lines that go straight North
crimson sedge
ok this i understand
slim quiver
If you raise your arm and point at me, the angle between the line you're standing on and your arm is 67 degrees
crimson sedge
ok
slim quiver
Which means the bearing from the direction you are facing towards me is 67 degrees
crimson sedge
does that mean the same for b to a
slim quiver
Nope, because remember, B is to the right of A, but A is to the left of B
We're on opposite sides from one another
crimson sedge
ohh
slim quiver
You'd raise your right arm to point at me... but I'd have to raise my left arm to point at you
You'd point slightly in front of you... I'd point slightly behind me
crimson sedge
yep
crimson sedge
180?
crimson sedge
yay
slim quiver
Ok, so... if your bearing to me is 67, and my bearing to you is exactly opposite
What is my bearing to you? Add 180 to your bearing to me
slim quiver
Bingo
crimson sedge
thanks
slim quiver
And a full circle is 360, right?
crimson sedge
yes
slim quiver
Ok, so notice the blue and orange sections under B
You see how the orange section is that 247?
slim quiver
Awesome, bud
crimson sedge
thanks ryan
slim quiver
One sec!
Sorry... just noticed that your assignment has one other little bit of instruction
The bearing to me would be 067, not just 67
crimson sedge
?
slim quiver
No problem
slim quiver
Does 67 work instead?
crimson sedge
wait give me a min or two
slim quiver
Ok
slim quiver
That should be correct..
slim quiver
Very similar problem, eh? X and Y are similar to A and B from before
slim quiver
Nope, because this time the purple section is outside the angle
Before, the pink 67 was in the angle NAB right?
crimson sedge
yeah
slim quiver
This time the purple section is in the angle YX...
So you've got to find the missing angle NXY
crimson sedge
so 360-104?
slim quiver
No.. remember, North is 0 and South is...
crimson sedge
man ive been doing this for like an hour and i need sleep can u give me the answer
slim quiver
The bearing from X to Y is 180 - 104
76
But the question asks for the bearing from Y to X
So it's 180 degrees flipped, right?
crimson sedge
yes
slim quiver
What's the opposite direction from 76 degrees?
crimson sedge
idk man im half asleep rn
slim quiver
There may be something wrong with the program
These are a few of the most common compass bearings
slim quiver
Yep... best of luck
cedar kilnBOT
@placid panther Has your question been resolved?
pure oak
How to solve 8=3^x?
cedar kilnBOT
How to solve 8=3^x?
pure oak
How can I undo this equation and figure it out?
high spruce
have you covered logarithms?
pure oak
briefly but im not sure how to work it
high spruce
is there something you're particular confused about
because if you just want to learn about logarithms I'd recommend just watching a video
crimson sedge
How to solve 8=3^x?
what is the "opposite" function of 3^x?
crimson sedge
Hi
cedar kilnBOT
@crimson sedge Has your question been resolved?
crimson sedge
No
cedar kilnBOT
crimson sedge
.reopen
cedar kilnBOT
✅
elder lodge
i cant read that language
crimson sedge
Theres english
elder lodge
oh yeh
wraith daggerBOT
crimson sedge
wraith daggerBOT
elder lodge
wait is gradient just length
crimson sedge
wait is gradient just length
Ye ik
elder lodge
wut its clear
crimson sedge
crimson sedge
wut its clear
It is clear-
Welp is it clearer now?
Can we proceed to answer the question?
elder lodge
isnt it just like square root of 65
crimson sedge
Huh
Im not sure how to answer the question im stuck at finding the coordinate of D
elder lodge
its just 2,-4
crimson sedge
Ok
But how do i do the equation-
Yo can someone help me out
Ima bit stuck here
<@&286206848099549185>
I did
But i have othe math question that i need help with
Hollon
I have been waitin since 7.40
Its 8.15
elder lodge
uh
crimson sedge
Can ya pls explain
elder lodge
im just guessing its a right triangles and the coordinates match up because the problem probably has other info from another place
because the stuff given isnt enough to say
crimson sedge
Ye
Let me try doin it
Wait
Is it possible
If i do like this
.clise
.close
azure dock
how do i know what to use? sin? cos? tan?
cedar kilnBOT
how do i know what to use? sin? cos? tan?
elder lodge
y2 is 4 not -4
elder lodge
how do i know what to use? sin? cos? tan?
use soh cah toa
here
so the opposite side to the right angle
is the hypotenuse
h
label it
elder lodge
so
you have
h and a
it matches with second two letters of
cah
so you use cosine
boom
cosine(51)=10/x
plug it in
azure dock
is the labeling correct
elder lodge
yes
azure dock
so i use what x stands for? in this case its h and then 10 = a
so ah = cos
is that right
elder lodge
yes
soh cah toa
s is sine
if you have opposite and hypotonuse use sine
if you have adjacent and hypotonuse use cosine
and if you have adjacent and opposite use tangent
elder lodge
uh
you cant multiply the 10
you have to get uh
cos(51)x=10
by multiplying both sides
and then
azure dock
by multiplying both sides
wym
elder lodge
by x
azure dock
oh
elder lodge
and then
you divide both sides by cos(51)
so you get x=10/cos(51)
i mean cos51
oop
azure dock
yes
elder lodge
and calculator it
vast nacelle
i need help regarding super basic trigonometry
cedar kilnBOT
i need help regarding super basic trigonometry
orchid pilot
take tan of both sides
vast nacelle
wot
orchid pilot
so you get tan() < tan(x) < tan()
zenith sail
It's not
orchid pilot
its not indeed
zenith sail
tan is positive in quadrants 1 and 3
orchid pilot
false
vast nacelle
aint no way
orchid pilot
its positive and negative
elder lodge
oh ok
i think yours might be right i used the wrong mode on calculator if your still looking
vast nacelle
i dont get an exercise then
if sinx + cosx = 1/5
calculate tg(x/2)
and it goes into a quadratic formula and we end up with this
versed shuttle
i think yours might be right i used the wrong mode on calculator if your still l...
lmao bro
versed shuttle
i feel so bad
💀 how you know this stuf
elder lodge
💀 how you know this stuf
no the stuff before
zenith sail
no the stuff before
Shadow is using this help channel now. Please don't clog it up
vast nacelle
2kpi < x < pi + 2kpi <=> kpi < x/2 < pi/2 + kp <=> tg(x/2)>0 => tg(x/2)=2
pi + 2kpi < x < 2pi + 2kpi <=> pi/2 + kpi < x/2 < pi + kpi <=> tg(x/2)<0 => tg(x/2)=-1/3
this is what is written
in the solutin
elder lodge
Shadow is using this help channel now. Please don't clog it up
alr mb
vast nacelle
i'll rewrite everything so it's easier to see
i dont get an exercise then
if sinx + cosx = 1/5
calculate tg(x/2)
and it goes into a quadratic formula and we end up with this
tg(x/2) = -1/3 or 2
and this is what is written in solution
2kpi < x < pi + 2kpi <=> kpi < x/2 < pi/2 + kp <=> tg(x/2)>0 => tg(x/2)=2
pi + 2kpi < x < 2pi + 2kpi <=> pi/2 + kpi < x/2 < pi + kpi <=> tg(x/2)<0 => tg(x/2)=-1/3
orchid pilot
2kpi < x < pi + 2kpi <=> kpi < x/2 < pi/2 + kp <=> tg(x/2)>0 => tg(x/2)=2
pi + 2...
this is true
orchid pilot
Why is for pi + 2kpi < x < 2kpi it always positive?
i dont see this in the solution
vast nacelle
i meant,
2kpi < x < pi + 2kpi
from the solution i figured this was implied ?
that 2kpi < x < pi + 2kpi is always positive for tg(x),
and pi + 2kpi < x < 2pi + 2kpi is always negative ?
orchid pilot
yeah and they are both true
vast nacelle
well you are not very helpful
zenith sail
Notice that it's implying tg(x/2)>0, not tg(x)>0
vast nacelle
i clearly just dont undesrtand fundamental trig shit
zenith sail
If x is between 0 and pi,
then x/2 is between 0 and pi/2
between 0 and pi/2, tg is positive (first quadrant)
so tg(x/2)>0
zenith sail
vast nacelle
i used
btw
my own method
which was
first calculating cosx, which i got to be either 8/10 or -3/5
and then getting tg(x/2) with the formula tg(x/2) = +-sqrt((1-cosx)/(1+cosx))
but i dont think i can really determine plus or minus this way
@zenith sail
pls
cedar kilnBOT
@vast nacelle Has your question been resolved?
cedar kilnBOT
@vast nacelle Has your question been resolved?
fiery ermine
what in the flippity flip is this? and how do I solve it
cedar kilnBOT
what in the flippity flip is this? and how do I solve it
@fiery ermine Has your question been resolved?
fiery ermine
<@&286206848099549185>
cedar kilnBOT
@fiery ermine Has your question been resolved?
cedar kilnBOT
@fiery ermine Has your question been resolved?
topaz monolith
Vector a is not parallel to vector b,Vector m=2a+3b Vector n=-1/2a-1/3b Ask: Is vector n parallel to vector m?
cedar kilnBOT
Vector a is not parallel to vector b,Vector m=2a+3b Vector n=-1/2a-1/3b Ask: Is ...
Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.
@topaz monolith Has your question been resolved?
topaz monolith
<@&286206848099549185>
tame zodiac
Did you learn cross product of vector?
tame zodiac
Answer first?
topaz monolith
Yes
tame zodiac
no, not parallel
topaz monolith
Thanks!Then you can tell me why
topaz monolith
Their directions are the same(or competely different)
tame zodiac
yes, that's one for geometrical property
do you know how to express that arithmatically?
topaz monolith
No
tame zodiac
we express it as "a is parallel to b if and only if we can scale a to match the b"
in other word
a=kb form
where k is not 0
and a and b is vector
topaz monolith
I see
tame zodiac
so if we can write a=kb with k not being 0, then a and b is parallel
tame zodiac
yes no k exists that meets m=kn
If a and b is non zero
and not parallel to each other
if a or b is zero vector, or if a is parallel to b, then answer changes
can you figure out why?
tame zodiac
what if a is parallel to b?
tame zodiac
It seems like you got it
topaz monolith
😁
tame zodiac
any more questions?
tame zodiac
np
topaz monolith
.close
analog lichen
cedar kilnBOT
analog lichen
How do i do b)
i think its recursive formula
and i did explicit formula which is different from this
slate lintel
a and b are pretty much the same problem just with different numbers
analog lichen
a and b are pretty much the same problem just with different numbers
for a i got 1,3,11,43,171
and b) i got1,4,10,22,46
slate lintel
for b) why did you start at 1?
analog lichen
bc i dont really know how to do this and got the outline from a)
so i just try to use it for b
and dont know if its right or not
slate lintel
for each of these you want to list the terms like
$u_1 = ? \ u_2 = ? \ u_3 = ? \ u_4 = ? \ u_5 = ?$
wraith daggerBOT
hayley
analog lichen
yes
slate lintel
so that will be the first term
analog lichen
also are we on a or b
analog lichen
see how it tells you u1 = something
yes
analog lichen
so is this right?
slate lintel
for b, what is u1?
analog lichen
for a i got 1,3,11,43,171
this
slate lintel
your answer for a is correct
analog lichen
b is not right?
slate lintel
b is not correct
analog lichen
okay its bc i dont know how to do these tbh
slate lintel
analog lichen
this is what i got for b: 2,6,14,30,62
slate lintel
where'd this 2 come from
analog lichen
good organization though, i like the neatness
hopefully this is right, now : 2,5,11,23,47
slate lintel
yeah that looks right to me!
cedar kilnBOT
cedar kilnBOT
Available help channel!
foggy hinge
ABCD is a trapezoid with AB and CD being the parallell sides. AB=140, AD=80, CD=50 and Angle A=75°. Find Angle B and the length of BC.
foggy hinge
Im not quite sure how to approach this problem.
harsh zephyr
maybe draw a diagram
split pike
Im not quite sure how to approach this problem.
Draw the figure
foggy hinge
Do i need to take measurements to solve it? Thought it could be done with trigonometry
slate lintel
you'll never need to get out your ruler and protractor for a trig problem if that's what you're asking
foggy hinge
Ye i got confused since they asked me to draw, im not sure how to approach it to find the measurements I’m being asked to find.
slate lintel
there's the braindead method where you apply a coordinate system to it
and figure out the coordinates of B and C
cedar kilnBOT
Available help channel!
bright sorrel
so I have this matrix
cedar kilnBOT
so I have this matrix
bright sorrel
Ax=0
where A=
(6 1 0 0)
(0 0 0 0)
(-6 -1 0 0)
(21 0 0 21)
it's the matrix of some linear operator
and I have to find the fundamental system of solutions
the way they have taught us before is make it into a homogenous system of equations
apply parameters of the quantity of (#variables)-(#equations)
Ax should become
(6x x 0 0)
(0 0 0 0)
(-6x -x 0 0)
(21x 0 0 21x)
Is this equal to
6xy1+xy2=0
-6xy1-xy2=0
21xy1+21xy4=0
3 equations 3 variables
no parameters?
steel cloak
Hi, if A is 4x4, then you get 4 equations (as you have) and 4 variables x_1, x_2 x_3 and x_4. The equation you got only has 2 variables.
The first equation becomes 6x_1 + x_2 = 0.
bright sorrel
The first equation becomes 6x_1 + x_2 = 0.
yes, but it has x
that's Ax=0
in the means of finding its own vector
steel cloak
I might have misunderstood
bright sorrel
that's alright
steel cloak
Right, this is above my level.
cedar kilnBOT
@bright sorrel Has your question been resolved?
bright sorrel
<@&286206848099549185>
bright sorrel
<@&286206848099549185>
thorn hare
?
cedar kilnBOT
@bright sorrel Has your question been resolved?
quick zealot
@bright sorrel please send the question in jpeg format
cedar kilnBOT
bright sorrel
<@923268887909384202> please send the question in jpeg format
sorry, it's been way over an hour
cedar kilnBOT
Available help channel!
ornate schooner
How do you find B coordinates?
cedar kilnBOT
How do you find B coordinates?
fickle trellis
Do you know vectors...?
ornate schooner
Do you know vectors...?
Yes
I just suck at trig, like I don't know the formula to do this but I know all the data is there
fickle trellis
If you wanna do it using trig...
The easier way would be to find AB
Recall than $\tan{\theta}=\frac{\text{perpendicular}}{\text{base}}=\frac{\text{opposite}}{\text{adjacent}}$
wraith daggerBOT
ornate schooner
theta being the C angle?
fickle trellis
Yea, in this case.
ornate schooner
Ok so first I need to find hypotenuse I think doing AC*tan(theta). This give me hypotenuse length and then with that I can find B
Then AB = √(AC² - CB²)
How would you do it with vectors? @fickle trellis
fickle trellis
Ummm
fickle trellis
Ok so first I need to find hypotenuse I think doing AC*tan(theta). This give me ...
This isn't what you'd do, no
Let's do a lil work.
fickle trellis
actually this give me AB nvm its what I need
Yep, thats what I meant
AC(tan theta) doesnt give u the hypotenuse
So, here's the thing...
This is our situation rn isn't it
ornate schooner
and B angle is 90
fickle trellis
So can you tell me something about C
Hold up
i got the names messed up
There!
Okay so...
Can you tell me something about B, maybe.
Without solving or anything
Like, try to tell me... what should be the x-coordinate of B
ornate schooner
Well Bx = Ax
so -50
So really we are only looking for By, so basically where B is sitting on that "perpendicular line to AC going through A"
cedar kilnBOT
@ornate schooner Has your question been resolved?
mint smelt
hi
mint smelt
how do istart
livid hound
start what
tropic oxide
if you mean to ask how to start your help channel: you already did
post your question(s)
@mint smelt
cedar kilnBOT
@mint smelt Has your question been resolved?
mint smelt
cedar kilnBOT
cedar kilnBOT
✅
mint smelt
this is my question and its in frnsh but what it says is that a,b are positive , and i need to show that a+b+1/ab>=3
cedar kilnBOT
@mint smelt Has your question been resolved?
mint smelt
Ok ill try thx
woven idol
cedar kilnBOT
@woven idol Has your question been resolved?
dire geode
if f is even, then we dont need even functions, so why is b = 0 and not a = 0
Sine is odd
dire geode
also howd they make this step
Use product to sum formula from trig
woven idol
Sine is odd
yeah
and it says the Fourier series of an even function doesnt need any even functions for its construction
so it doesnt need any cosines
cedar kilnBOT
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cedar kilnBOT
cedar kilnBOT
Available help channel!
jolly sapphire
((1 + i)/(1-sqrt(3)i))^2024
cedar kilnBOT
((1 + i)/(1-sqrt(3)i))^2024
jolly sapphire
can someone solve this?
raw gulch
((1 + i)/(1-sqrt(3)i))^2024
$\text{I can give you such a hint:}\\z^{n}=\left| z \right|^{n}\cdot \left( \cos\text{}n\varphi +i\sin\text{}n\varphi\right)\text{ }\text{ where }\text{ }\varphi=argz$
wraith daggerBOT
Joanna Angel
raw gulch
i.e. the application of de Moivre's formula
cedar kilnBOT
@jolly sapphire Has your question been resolved?
cedar kilnBOT
@jolly sapphire Has your question been resolved?
jolly sapphire
so in my case it would look like this: ((sqrt(2)(cos(1/4pi) + isin(1/4pi))/(2(cos(2/3pi) + isin(2/3pi)))^2024? Or?
p.s sorry I don't know latex
@raw gulch
raw gulch
so in my case it would look like this: ((sqrt(2)(cos(1/4pi) + isin(1/4pi))/(2(co...
2 /3 pi is wrong argument, , beucase z = 1-i sqr( 3 ) is located in fourth quadrant
crimson vector
Understanding index trickery: I want to fully understand how one goes from $\sum_{i=0}^n\sum_{j=0}^m a_{i+j}$ to $\sum_{k=0}^{n+m}\sum_{i=0}^k a_k$
wraith daggerBOT
HelixKirby
cedar kilnBOT
@crimson vector Has your question been resolved?
crimson vector
<@&286206848099549185>
dim urchin
we can start by expanding the first double sum,
we have $\sum_{i=0}^n\sum_{j=0}^m a_{i+j}$. Let's rewrite the inner sum by substituting $j$ with $k=i+j$:
$\sum_{i=0}^n\sum_{j=0}^m a_{i+j} = \sum_{i=0}^n\sum_{k=i}^{i+m} a_k$.
now, we can switch the order of summation:
$\sum_{i=0}^n\sum_{k=i}^{i+m} a_k = \sum_{k=0}^{n+m}\sum_{i=0}^k a_k$.
so, we have successfully transformed $\sum_{i=0}^n\sum_{j=0}^m a_{i+j}$ into $\sum_{k=0}^{n+m}\sum_{i=0}^k a_k$.
wraith daggerBOT
clovercat.
crimson vector
Is this ChatGPT? Can you explain how to do it without having to switch the sums?
I understand that if I think of k as a function of i and j, and fix $i$, then $k=i+0$ and $k=i+m$ are the new bounds, but what if we start with $k=i+j$, so that we know that $k=0$ to $m+n$ already, how would we figure out what $j=k-i$ runs from?
wraith daggerBOT
HelixKirby
scenic steppe
I understand that if I think of k as a function of i and j, and fix $i$, then $k...
k = j +i(k ranges from 0 to m+n)
j=k-i
put k = 0
j=0-i =-i
again put k = m+n
j= (m+n) - i
therefore we can say that j is from -i to (m+n)-i when k ranges from 0 to m+n
crimson vector
Is there more to it than that? The final inner sum goes from 0 to k, how do we get to that from -i to m+n-i?
cedar kilnBOT
@crimson vector Has your question been resolved?
cedar kilnBOT
@crimson vector Has your question been resolved?
queen marsh
Find the square of triangle AOB and square of sector AOB
cedar kilnBOT
Find the square of triangle AOB and square of sector AOB
queen marsh
If someone can help I will be extremely grateful
queen marsh
yes thats what I meant
English is not my first language so it might be a bit of trouble communicating sorry
livid hound
is d supposed to be the diameter?
queen marsh
yes I believe so
livid hound
can you first determine the size of the red angle?
queen marsh
sorry this is my first time doing this problem as we just started learning it today so I am almost completley lost
livid hound
do you know the relation between the measure of an arc and its respective central angle
can you first determine the size of tha blue angl;e
queen marsh
The measure of an arc is always given in degrees.
So, if you have a central angle in a circle, the arc it subtends will have the same measure in degrees? Thats a little of what I know
livid hound
The measure of an arc is always given in degrees.
radians can be used as a unit
but yes, that blue central angle will have the same measure as that arc,
i.e. will also be 60°
from that can you determine the red angle i indicated earlier
queen marsh
S means area of a figure right?