#help-13

1 messages · Page 234 of 1

plucky owl
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Yes, then you found what BOC is

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Now you want to find the other angle plus BOC to make 90

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The other angle is what the problem is asking for

drifting isle
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If x plus boc =195 and the supplementary angle is 180 then isn’t the difference 15

plucky owl
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I don't think you're understanding

drifting isle
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Uhhhh

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Aob is an angle and boc is and angle and together they make 180•

plucky owl
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Do you get that <AOB + <BOC = 180 because it says they are supplementary?

drifting isle
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Yes

plucky owl
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Then the next statement asks about the compliment of <BOC

drifting isle
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Right

plucky owl
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And complimentary angles add to 90

drifting isle
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Wait

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So

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Is it saying

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There are to complimentary angles inside the 180 degrees right

plucky owl
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No

drifting isle
plucky owl
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It's saying that there is an angle that is the compliment with <BOC, what is that compliemented angle

crimson sedge
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<BOC is in two separate equations. It's important to keep them separate.

drifting isle
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Hmmm

plucky owl
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Let me summarize again, the problem says <AOB and <BOC are supplementary angles, meaning <AOB + <BOC = 180

drifting isle
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Yep

plucky owl
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Now it's wanting you to find the compliment of BOC, meaning BOC would also be in an equation involving complimentary angles

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So <BOC + z = 90

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Do you get that?

drifting isle
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Boc+z =90?

plucky owl
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I used z to as a placeholder variable for the other angle that is compliment with BOC

crimson sedge
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Since the complementary angle is not specified, you can call it by any variable you like

drifting isle
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Okay im confused about the 90 degree part because all I think is that there are two angles in 180 degrees and together they add 180 because they are inside of the 180 degree but one could be 80 and one could be 100 but I know that one is x-15 which doesn’t mean much to me and I don’t know where this 90 degree is coming from

plucky owl
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Because the problem says, "what is the measure of the compliment of <BOC"

crimson sedge
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they are separate criteria

plucky owl
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Compliment referring to complimentary angles

drifting isle
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So it’s saying there’s a complimentary angle inside the supplementary one?

plucky owl
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Not necessarily

crimson sedge
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supplementary angle is like equation 1 with 180 degrees and <BOC
complementary angle is only concerned with <BOC and some unknown angle, say z
<BOC appears in both equations, but what you want is z

plucky owl
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It's saying that <BOC is supplement with <AOB

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But <BOC is also compliment with some other angle, z

drifting isle
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Can someone draw a picture

plucky owl
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You don't necessarily need a diagram. Just follow what I'm trying to explain

drifting isle
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Im trying im getting confused

plucky owl
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Let me summarize again, the problem says <AOB and <BOC are supplementary angles, meaning <AOB + <BOC = 180
That makes sense to you so far. The next statement of the problem says what is the measure of the compliment of <BOC
Compliment, as stated, in that context is complimentary angles, so <BOC is a complimentary angle with some other angle. Because you don't know said angle, you can use a variable, I used z. So that means z + <BOC = 90

drifting isle
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Okay but I don’t have anything to work with if x+boc = 90 how am I suppose to work stuff out further

plucky owl
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Your goal is to find z

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Using my explanation

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You have two equations <AOB + <BOC = 180 and z + <BOC = 90

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The overall goal is to find z

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Which is the compliment of BOC

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Using the first equation <AOB + <BOC = 180, you can find what BOC is in terms of x

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Basically what you did here

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Then using z + <BOC = 90, and BOC = 195 - x, you can find what z is

drifting isle
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Jesus Christ, give me a second

plucky owl
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Which part is still not making sense?

drifting isle
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One second

crimson sedge
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I'm going to guess the x is the problem

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we aren't trying to find x. but it's basically got to work through the formulas

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the angle you seek is going to have x in its formula. try to just move it along through the process without trying to figure out what x is

plucky owl
# drifting isle

Not quite but almost, specifically this part. You wrote BOC + z = 90 then did 90 = 195 - x, which I'm assuming you replaced BOC with 195 - x

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But where is the z

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That z is the angle the expression that the problem is asking for

drifting isle
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Ahhhh

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Ummm

plucky owl
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No

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z does not equal 90

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And x does not equal 105

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Start back with BOC + z = 90

drifting isle
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It’s so hard

plucky owl
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As mentioned, z is expression the problem is asking for

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What does BOC equal to?

drifting isle
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90

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Wait

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A portion of 90

plucky owl
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No

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You found what BOC is equal to, when you used it in the supplementary part

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BOC = 195 - x

crimson sedge
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take a few breaths, relax if you can. the more we push for something, sometimes the further away it gets

drifting isle
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I don’t know how you guys find it so easy

crimson sedge
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the calmer you can get breathing and the mind, the more in focus this'll be

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it's difficult for me. you were quite into this before i figured it out

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I taught univ calc for 15+ yrs for an online math program. this problem is a challenge

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so please don't feel bad

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breathe a bit, take the pressure off, look at it again, step by step

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(by taught, think TA type position, not full prof)

drifting isle
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Hmmm

plucky owl
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I think the overall complication is you are trying to relate, BOC as both a supplementary and complimentary angle, for the same one diagram

drifting isle
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What do you mean

plucky owl
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You're basically finding that purple angle

drifting isle
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Why do you have two

crimson sedge
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might be easier if BOC wasn't over 90 in blue...

drifting isle
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So there’s only one picture right

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This one

crimson sedge
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it's can be 1 picture ... gets crowded. One key point is that the angle you're looking for, z, doesn't need to be in the figure above. It could point to the lower right. It doesn't have to be inside the 180

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that lower right one will take me a minute for the software cause I have to use precise points 😦

drifting isle
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So your saying the angle z is not even in that picture!

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I thought it was between b and c

plucky owl
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No, it's complimentary with BOC

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Not between B and C

crimson sedge
drifting isle
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Omg

crimson sedge
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that's why captain's using 2 sketches

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seeing it all in one is an omg moment

drifting isle
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What the hell

crimson sedge
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if you can keep them separate, its' easier. one sketch for each scenario, supplementary, complementary

drifting isle
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I thought I was trying to find aob and boc which are percentages of 180 degrees

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Angles

crimson sedge
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you need boc to find the goal

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the goal is z

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and z is not on the supplementary setup

plucky owl
drifting isle
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So im finding 2 angles, the angle that makes up 180 degrees and the angle that compliments the angle that makes 180

plucky owl
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There, I made BOC the same color so it's not confusing

plucky owl
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It's 90

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The second 180 is suppose to be 90

drifting isle
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Oh yea

plucky owl
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But you use the first diagram I have, to find the expression for BOC

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Then using the second diagram, and BOC, you can find z

drifting isle
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Are we able to find the angles of aob and boc without the compliment of boc first

crimson sedge
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i get the feeling you're trying to find numbers for all 3 angles

drifting isle
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Yep

plucky owl
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If you're trying to find actual values, that's not what you are doing

crimson sedge
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that path heads to a wall

plucky owl
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You are finding the expression

drifting isle
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What do you mean expression

plucky owl
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It's in terms of variables

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It's going to have variables

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There is no set value

crimson sedge
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each angle will have an x in it somewhere. we cannot find the exact angle numbers without more information

drifting isle
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Okay that’s a relief because I thought you could and I didn’t know how. So I’m actually not even looking for a angle

plucky owl
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You are looking for an angle

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It's just not a value

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It's an expression

crimson sedge
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in a sense, we want one particular angle, but it cannot be a number like 20 degrees

drifting isle
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So a possibility of an angle?

plucky owl
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The possible equation for that angle

drifting isle
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Okay that i understand

plucky owl
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Do you understand what you are solving for now?

drifting isle
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Possible variables that can fit the angles

plucky owl
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You don't need multiple variables, use the image I provided

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Can you find the expression for BOC?

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In the blue image

drifting isle
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Yea

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It’s equal to -x+195

plucky owl
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More specifically, BOC = -x + 195

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That's the equation

drifting isle
plucky owl
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,rotate

wraith daggerBOT
plucky owl
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Now using the fact that BOC = -x + 195 and BOC + z = 90

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Can you find what z is equal to?

drifting isle
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1 sec

crimson sedge
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you're on the path. you can do it 🙂

drifting isle
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Tryingggg

plucky owl
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Where are you stuck?

drifting isle
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Just looking at boc=-x+195 and boc-z =90 I think if I minus boc from z maybe the leftover will be what z is equal 2 but I don’t want to make another mistake so I’m thinking

plucky owl
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First it should be BOC + z = 90

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And second what if I said something like h = -x + 195 and h + z = 90, if you were to use both equations, can you find z?

drifting isle
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I think I can

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Sorry

plucky owl
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If you were to use this, h = -x + 195 and h + z = 90, in the second equation, you can replace h with -x + 195, do you see that?

crimson sedge
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It's down to a system of equations like algebra. We use the angle info to make the equations. Then it's algebra.

drifting isle
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Okay I think I almost have it

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I think it’s wrong

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I’m just breaking down

plucky owl
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Look at your answer choices

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Is there one that matches that expression?

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You have z = -105 + x

drifting isle
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Yeah I messed it up

plucky owl
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No you didn't

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Addition is commutative

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z = -105 + x is the same as z = x + -105 which is z = x - 105

drifting isle
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So it’s correct

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I just thought because it didn’t say z=

plucky owl
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The z is used to represent the angle, the problem is primarily looking for the expression

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The equation is z = ....
The question wanted the ... part

drifting isle
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Okay, thanks so much for the help, it just seems like it’s going to be really tuff stuff from here on

crimson sedge
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in the hand calculation, you need parenthesis.

drifting isle
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I didn’t even realise what it was asking for

crimson sedge
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sometimes, that's the hardest part of a problem

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in math, in life

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what is it we are trying to do?

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if we can lock that down, sometimes the rest just goes into focus on its own

drifting isle
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Hmmm

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And I thought geometry was going to be easy

crimson sedge
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and it's really difficult when problems jumble stuff up like a puzzle and the pieces seem to go together when they shouldn't

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take your time with it, I'm sure it'll be easy when you've got the hang of it

plucky owl
drifting isle
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By the way how did you know it wasn’t asking for set values so I can know in the future

plucky owl
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And that BOC related to a supplement and compliment

plucky owl
crimson sedge
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same reason you had so much frustration, couldn't find an x

plucky owl
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So you know it's not set values already

crimson sedge
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Captain knows math, so Captain can tell by seeing x

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you and I had to hit the wall first

drifting isle
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Hmmm

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Can anyone can really really good at math

crimson sedge
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everyone's good at some aspect of it

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many without realizing it

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it's tough problems that can send some people packing and avoiding it

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you worked through it and that takes a lot of strength to keep going with us, thank you

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I look on here and there's tons of problems I've never seen or thought about before

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and then I see one and I'm like, I can help with that

drifting isle
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Well thanks for helping

crimson sedge
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I've watched people in life give up on stuff, that builds walls and limits what they can do later

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work through the challenges, keep trying, stick with it

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and you'll open more doors than you may realize possible now

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and in more than math

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I congratulate you on this problem and getting to the end of it! 🙂

drifting isle
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Thanks 🙏 I’ll keep trying

drifting isle
crimson sedge
drifting isle
#

.close

cedar kilnBOT
#
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cedar kilnBOT
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ripe wasp
cedar kilnBOT
ripe wasp
#

I got the minimum area = 28/4+pi

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I initially thought you sub the minimum area into the given area equation and find x and sub that in the perimeter equation to get r but I was wrong

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so not really sure how to move forward from here

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uhh

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ello

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<@&286206848099549185>

tawdry pelican
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x = 5.6m ?

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just differentiate the area A and find value of x for which it is minimun, comes out to be x = 5.6m

cedar kilnBOT
#

@ripe wasp Has your question been resolved?

cedar kilnBOT
#
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tawdry pelican
#

isn't my answer correct?

cedar kilnBOT
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hybrid prawn
#

how to prove that the limit of f(x) when x aproches 0 is the same as f(-x)

hybrid prawn
#

am only given its domain ]-a;a[

tropic oxide
#

you want to prove $\lim_{x \to 0} f(x) = \lim_{x \to 0} f(-x)$?

wraith daggerBOT
crimson sedge
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this is impossible to be true for all f

hybrid prawn
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yea dont worry i just got it lol

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not its not

opal basin
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Maybe they assume the left limit exists

bold hinge
#

Assuming f is continuous?

opal basin
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not sure if they would be equal if both don't exist

hybrid prawn
#

whell its told that it is continous

dull oxide
cedar kilnBOT
# hybrid prawn whell its told that it is continous

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

hybrid prawn
#

xy what ?

#

anywasy thanks guys for the help

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god bless you

#

.close

cedar kilnBOT
#
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crimson sedge
#

how to get this to 4^(r+2) - 4 ??

cedar kilnBOT
carmine dock
#

Try factor out 4

uneven iron
#

You can't

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Unless what you have is an equation

crimson sedge
uneven iron
#

There you have x = 1

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Oh

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I thought "x" wasn't a multiplication simbol

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Factor 4^(r+1)

carmine dock
#

Write 4^(r+1) as 4*4^r

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Factor out the 4 and it should be clear

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Oh wait

crimson sedge
carmine dock
#

Uhh it’s not that complicated

uneven iron
carmine dock
#

1 (4^(r+1)) + 3(4^(r+1)) = 4(4^(r+1)) = 4^(r+2)

crimson sedge
uneven iron
#

Wrong

#

$4^{r+1} ( 1 + 3 ) - 4$

wraith daggerBOT
crimson sedge
#

thank u

#

.close

cedar kilnBOT
#
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rain olive
fervent jackal
#

which question of the quiz?

rain olive
#

its about cartesian coodinates

fervent jackal
#

is it the 4th question?

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I think we can try constructing a formula for it

rain olive
#

ill send you screenshot

fervent jackal
#

yeah that is right

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what is the question here

rain olive
#

we're agree from 0,0 to 1,1 takes 3 not 2

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sorry

fervent jackal
#

why does it take 3?

rain olive
#

oh yes my bad

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ya ya

#

youre right

fervent jackal
#

$n+\sum_{k=1}^{n}2k$

wraith daggerBOT
#

lebesgue

fervent jackal
#

I think this should be the formula

rain olive
#

yes this the patter i was looking for

fervent jackal
#

if k is odd then it ends up on the y axis, if its even it ends up on the x axis

rain olive
#

oh yes cool

fervent jackal
#

but idk how to do case curly brackets in latex

#

but does that solve your question?

rain olive
#

yes super

fervent jackal
#

can you close the forum then?

rain olive
#

in addition you helped me to get the pattern sequence

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thank you so much

fervent jackal
#

can you do .solved?

fervent jackal
rain olive
#

solved

fervent jackal
#

.close

#

i mean

rain olive
#

how to?

fervent jackal
#

just type .close

#

".close"

rain olive
#

.close

cedar kilnBOT
#
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cedar kilnBOT
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civic coral
#

I have a explanation about why the power of complex numbers is restricted in the realm of integer, and i need people to check on it

civic coral
#

so here's my explanation:
expressions like "z^(1/n) where n is integer" are ambiguous.
It is due to the fact that when the power of a complex number is a fraction (let's say z^(1/n)), it will possess more than one points on the complex plane that can be used to denote z^(1/n).

As a matter of fact, these points, which represent z^(1/n) on the plane, can all be converted into z after being raised to the n'th power.

However, if you describe "the nth root of z" by saying it is equivalent to z^(1/n), we wouldn't be able to know which of the points that you're referring to.

Therefore, to avoid such a awkward situation, we restrict the "n" which is the power of z in the realm of integer.

crystal raptor
#

It's not that we say n must be an integer, we certainly can talk about nth roots of complex numbers. We either conventionally take z^1/n to be the nth root of z with the smallest argument (or some other convention) or we accept the fact that nth roots are multivalued functions

civic coral
crystal raptor
#

It's what we do with say 2^1/2

civic coral
#

I think im going to post the session about "z^n" on my textbook.

#

De Moivre theorem:
$z^n = r^n [cos(n\theta)+isin(n\theta)]$ where n has to be integer

crystal raptor
#

\theta

civic coral
#

god using texit to convey my thought makes me sweating so bad

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So

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So it is written on my textbook

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However, the theorem would work as well when n is fraction

crystal raptor
#

Think you also mean nθ

civic coral
#

ohh

wraith daggerBOT
#

Please Correct My Grammar

civic coral
#

so the possible reason for the writer to say that n must be integer

crimson delta
crystal raptor
crystal raptor
civic coral
#

"pretty much" I think I will consider it as "exactly"

crystal raptor
#

Ig we just cry

civic coral
crystal raptor
#

Ye

civic coral
#

I think I have already checked on them before

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and it says that n has to be integer as well

#

ohh

crystal raptor
civic coral
#

there is some new shit on your picture

crystal raptor
#

Which is essentially what you were saying

civic coral
crystal raptor
#

Under failure for non integer powers

civic coral
#

I have another question tho

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How I express the nth roots of z

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in which z is a complex

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through math terms?

crystal raptor
#

Scroll down on wiki

civic coral
#

to say that "z^(1/n) is the nth roots of z" seems pretty intuitive in my opinion

crystal raptor
#

Well it depends what you mean by "express"

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You can certainly write z^1/n to describe a set along as you clearly say that's what you're doing

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But would be safer to just write { w | w^n = z}

civic coral
#

what a perfect expression

#

I have no questions now, thank you the sum of AC

crystal raptor
#

Welcome!

civic coral
#

.close

cedar kilnBOT
#
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last jungle
cedar kilnBOT
vague rapids
#

didn't you come with the same question yesterday?

mighty shuttle
# last jungle Q117?

Don't have paper with me right now so I can't guide you through all the steps but perhaps start by finding A and B

#

@last jungle

last jungle
#

Yes

mighty shuttle
#

After you have 3 points you should have enough information to find the 4th point and this 2a+b

last jungle
#

Diagram?

vague rapids
last jungle
#

Yes next?

iron scarab
last jungle
iron scarab
#

its deleted this year relax

mighty shuttle
vague rapids
#

only the answer?

last jungle
#

No I want the process

vague rapids
#

so like are you able to find equation of tangent?

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use the formula yy1=2a(x+x1)

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here a is 2, y1 is -4 and x1 is 2

last jungle
#

One minute

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t=-1

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Eq of tangent

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formula

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yt=x+at²

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??

#

.close

cedar kilnBOT
#
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dense ridge
cedar kilnBOT
dense ridge
#

Do i divide 1000 by 150 ×100

#

Or 150 by 1000 ×100

olive crescent
#

well if you had 500ml, then it would be 50%

#

500ml is 50% of 1000

iron scarab
dense ridge
#

Ohh oki thx so i get 15%

#

Correct?

iron scarab
#

yup

dense ridge
#

Thx

#

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cedar kilnBOT
#
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edgy flint
#

What happens to the cos(2x) and why is sin chosen as the u substitute?

edgy flint
#

Just below now solving:

slow jewel
#

Ah

rocky harness
#

Because the derivative of sin(2x) is 2cos(2x)

#

You can choose your u=cos(2x) also

edgy flint
#

It just seems like cos(2x) and du are disregarded

silver oxide
#

wdym

rocky harness
#

cos(2x)dx is du/2

#

So theyve put du/2 in the place of cos(2x)dx

slow jewel
edgy flint
#

Oh so the cos(2x) from the du is the same one from the original expression?

slow jewel
#

Yes

edgy flint
#

And if I used u=cos(2x) the final expression would have to be multiplied by - 1/2?

slow jewel
#

It would be -1/2 int (u du), yes

edgy flint
#

Ok thanks

slow jewel
#

Np

slow jewel
edgy flint
#

I got confused and thought that du was completely separate from the original expression

slow jewel
#

I see

edgy flint
#

Anyway thanks

#

.close

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bright sorrel
#

could someone help me understand this?

cedar kilnBOT
bright sorrel
#

so for the numerator I suppose 2^n+1=2^n * 2

#

so the two 2^n cancel out

#

but then how is the sinuses

#

how do we get to 2/3

#

do I have to use that

#

lim x->inf sin(x)/x=1?

stoic gale
#

yes

bright sorrel
#

man

#

I simplified it rn and it checks out

#

thanks

stoic gale
#

thats how the sin's 'cancel' out, leaving you with pi/3^n/ pi/3^(n+1), giving 1/3

#

cool

bright sorrel
#

tysm

#

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wraith daggerBOT
silver fable
#

you need to find ax+b first (find a and b)

crimson sedge
#

plug it into the inequality and solve for x 👍

#

Well substitute in then start moving stuff about

#

You’re probably going to have to form a quadratic

#

then solve the quadratic

silver fable
#

quadratic ? how ?

#

u'll get a function >0 solve it using calculus.

crimson sedge
#

that function might be a quadratic 😨😨

silver fable
#

$x\sqrt{6-x}-\frac{7}{4}x+\frac{15}{4} > 0$

wraith daggerBOT
#

Adam Chebil

cedar kilnBOT
#
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lone plinth
#

solve this using this video pleasehttps://www.youtube.com/watch?v=6rXByMcuAyI

This calculus video tutorial provides a basic introduction into integrating rational functions using the partial fraction decomposition method. Partial fraction decomposition is the process of breaking a single complex fraction into multiple simpler fractions. The integrals of many rational functions lead to a natural log function with absolut...

▶ Play video
cedar kilnBOT
tropic oxide
#

we won't do your homework for you.

lone plinth
#

its not my homework

#

I just dont know how to solve this

#

as its not shown in the video

tropic oxide
#

do you want to be taken through how to solve it

#

or did you ONLY want someone to just hand you the solution

lone plinth
#

I want to know how to solve such integrals

peak minnow
#

partial fractions prob

lone plinth
#

Ye Ik that

crimson sedge
lone plinth
#

holy shit

#

are u stupid

#

go read what I wrote

#

before typing. I said they dont bring that up in the video in exactly those kind of integrals and yet u try to be picky for no reason

tropic oxide
#

do you want to be taken through how to solve it
you haven't answered with an unambiguous "yes" to this

lone plinth
#

baiting for no reason

crimson sedge
#

Probably didnt get mentioned bcs u dont need partial fractions for it?

#

just by looking i dont think u need them

#

it looks like (3x-1)^-2

lone plinth
#

It's a exercise in the chapter about it but I tried doing it the way It was shown in the video but I dont get to the right answear

crimson sedge
#

which doesnt need partial fractions to solve

#

you can insult me if you want, but that won't take you any further to your solution

as for the video, it's redundant to send it if it has nothing to do with the problem

#

(because it does have nothing to do with this problem)

#

u can solve it with partial fractions though

#

you could, but it would be a waste of time

pure cloak
#

I need help with linear functions

crimson sedge
#

just waste of time bcs theres ways 10x faster

cerulean harness
cedar kilnBOT
lone plinth
#

so I put the whole thing below as (u)^2 and move it to the top so it becomes (u)^-2?

silver fable
lone plinth
#

so (1-3x)^2 and (u)^2 to (u)^-2

#

ok I see now it how you do it thanks

#

but If I would wnat to solve it with partial fractions how would I do it

crimson sedge
#

it's literally in the video

#

go watch it

#

before asking any more questions related to it

lone plinth
#

someone useful help me please as I get the wrong answer

crimson sedge
#

yes chances are, me, who has helped hundreds of people is less useful than you, who can't solve a basic integral

#

i digress

tropic oxide
#

so we can diagnose what you are doing wrong

lone plinth
#

legit these guys are helpers and are just trying to bait me I dont get it

#

If you dont want to help dont bother texting here

tropic oxide
#

i for one do want to help

#

but you're not cooperating

lone plinth
#

I mean the other guy not you sorry

tropic oxide
#

you're like a patient who goes to the doctor and complains about a sore throat but then when the doctor asks to see your throat you refuse and say he's baiting you

#

that's what it looked like

lone plinth
tropic oxide
#

anyway im gonna repeat

#

,rccw

wraith daggerBOT
tropic oxide
#

ah, your factorization is wrong

#

or rather

#

no your factorization is correct

#

but the way you set up the partial fractions afterward

#

that's what is wrong

#

(1-3x)^2 ≠ (1-3x)(1+3x)

lone plinth
#

oh ye

#

so is it like A/(1-3x)^2 only

#

in that case

tropic oxide
#

it would be A/(1-3x) + B/(1-3x)^2

#

but you would get A=0 anyway

#

and you would just be right back to square one

silver fable
# lone plinth so is it like A/(1-3x)^2 only

why do u want to use PFD? to integrate 1/(ax^2+bx+c) u only use PFD if the discriminant b^2-4ac>0
if it's <0 u complete the square and do u-sub, if it's =0 u do u-sub directly

tropic oxide
#

so to conclude and reiterate: partial fraction decomposition won't help, and even if you try it anyway, it will literally do nothing for you.

lone plinth
tropic oxide
#

it is indeed not meant to be solved like that.

slim jasper
#

Don't speak in meme gifs in a help channel, please. If you can't attempt to correct the helpee in a respectful way, it's better not to say anything.

lone plinth
#

Alright thanks for the help

cedar kilnBOT
#

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toxic coral
cedar kilnBOT
toxic coral
#

i know angles in a triangle add up to 180 degrees

#

annd i know b + c = the corner line

#

and i know c = d(the alternate angle)

#

so how do i do this

#

also b is correspoding to e

#

oh wait

#

i got the answer

#

bye

abstract laurel
toxic coral
#

.close

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wispy shoal
#

in this example i got 1/0^-, i know its not the right answer, what sould i consider doing?

violet flume
#

well its divergent right

#

could you just show its unbounded

marble pagoda
#

Does it equal -∞

#

?

violet flume
#

what?

#

1^--1 what does this mean

marble pagoda
#

Is this correct?

violet flume
#

well you are inventing notation so you have to explain to me what it means

wispy shoal
#

when lets say x approches 1 from the left side

#

or it means its close to beeing 1 but never, its number like 0.999999999999........

#

but never is*

marble pagoda
#

but we don't get this

#

lemme send you a screen shot

violet flume
#

im talking about what you sent initially

violet flume
#

sure, its divergent

#

so how you show that is up to you

#

i suggested you show its unbounded

#

do you get what i mean?

#

@marble pagoda im not sure where your confusion is if not

#

photomath is doing a weird intermediary step i dont think is necessary but whatever

wispy shoal
#

ok, thanks!!

scenic brook
wispy shoal
#

its confusing to us because its something that our professor explained poorly

violet flume
#

oh, are you both asking the same question here?

marble pagoda
wispy shoal
#

@scenic brookyee thats what i mean

marble pagoda
#

we rn practicing together

violet flume
#

okay okay

#

so yea, i mean to go through it

#

the 1^- means that x is always less than 1

wispy shoal
#

ye

violet flume
#

it gets close to 1, but from below

#

you should look at a graph, if you can

#

,w Plot[ (1+Log[x])/(x-1) ]

marble pagoda
#

it's ln

violet flume
#

do you see the asymptote?

marble pagoda
#

nvm

#

yeah

violet flume
marble pagoda
#

ye yei k

violet flume
#

okay so

#

were approach it from the left

#

so visually it looks like -inf makes sense

#

okay

#

so if you agree its divergent

wispy shoal
#

im still young in this area of mathematics so this is what i picture it does this makes sense??

violet flume
#

i dont really understand what its supposed to be saying

#

do you both believe that this function goes to infinity in the limit?

scenic brook
wispy shoal
#

ooohhh

#

i got it

#

im so dum xD then i get 1/-0.00000000001 it goes to the - infinity

scenic brook
#

you can watch 100 limits to understand limits, you know 🙂

wispy shoal
#

but i stopped one step earlier cuz i taught its 1/0 jesus am I dumb

#

thanks for help guys!

scenic brook
cedar kilnBOT
#

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amber sonnet
#

I need help with evaluating the integral of 4 * sqrt(1+4x^2) dx, with bounds of integration being from 0 to sqrt(2). I have tried using u-sub (u = 1 + 4x^2), but then I end up with 4 * sqrt(u) * 1/(8x) du

tropic oxide
#

yeah that u-sub won't help

#

you want a trig or maybe a hyperbolic sub

amber sonnet
#

Okay, i'll have to look those up

#

Thank you

cedar kilnBOT
#

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errant tendon
#

Without drawing venn diagrams and without formal proof so by pure intuition if I have two sets S=(A intersection Bc) union (C intersection Dc)
T=(A intersection Bc intersection Dc) union (C intersection Bc intersection Dc). I have proven that T is a subset of S and it's cordrect but i don't truly understand the intuitivness behind it

errant tendon
#

the proof isn't the issue it's the fact that to me it makes no sense that a bigger set is a subset of a smaller set

crystal raptor
#

wdym "bigger set"

errant tendon
#

well T has one more element in each parenthesis

crystal raptor
#

okay but the more sets you intersect the "smaller" the set becomes

errant tendon
#

yes but an an interseection between those three sets is a set with the elements that belong in all those three sets

crystal raptor
#

so they belong to any two of them

errant tendon
#

wdym

crystal raptor
#

e.g. $X \cap Y \cap Z \subseteq X \cap Y$

wraith daggerBOT
crystal raptor
#

if you are an element of all 3 then you are an element of any two

errant tendon
#

oh i am neurologically disabled i see now

#

sometimes my neurological issues make it impossible to see such thingsd

#

that makes perfect sense

crimson sedge
errant tendon
#

because i can't see them properly

crimson sedge
#

They let you see everything at once in a way that is easy to process mentally

crystal raptor
#

yeah this would have been easy to see in a venn diagram tbh

errant tendon
#

i have amongst other things perception issues

crimson sedge
errant tendon
#

oh i got cerebral palsy

#

which is why i can't draw venn's

crimson sedge
#

Ah, problems with visuals?

errant tendon
#

the lines get all muddled up in my head

crimson sedge
#

I see

errant tendon
#

yea

#

been doing this without any visual help all through highschool and now my third year of ug

#

ty peeps

#

.close

cedar kilnBOT
#
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grand crystal
cedar kilnBOT
grand crystal
#

I have the answer, it's 1/64, but I don't understand.

steel heart
#

What part of this you don't understand?

grand crystal
#

My approach was to figure out the chances of those 4 squares making a diamond inside a 2x2 grid.
The chances that the square is in the right position is 1/4, and for all of them it would be 1/4^4 = 1/256
But now I don't know what to do for the 3x3

#

Oh wait don't I just multiply it by 4 because the 2x2 diamond can be in any 4 positions in the 3x3 grid?

#

I understand now

#

.close

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gritty escarp
#

How do I prove that the matrixes

1 0 1 2
2 1 and 0 1

are a subspace of M4(R)

orchid panther
#

@gritty escarp you mean form a subspace?

sage forge
gritty escarp
#

yeah both of those

#

Im having trouble with subspaces since in my university we dont use that span thing

orchid panther
#

Well i assume they want by asking you that to prove that the vector space (matrix space in this case) generated by those two matrices would be a subspace of M4(R), in that case just prove that you have 0 is contained in that set, as well as that it is stable by linear combination

gritty escarp
#

but then wouldn't any two matrices form a subspace

orchid panther
#

Yea pretty much

#

You can prove it for any one, two, three, four whatever matrices

#

(Definition of the Vect() that generates vector subspaces)

gritty escarp
#

so here b) is a subspace and a) isn't

orchid panther
#

Well for a what are they asking for

#

A subspace of what

#

(I assume those to be polynomials)

#

(But which degree)

#

Also

gritty escarp
#

Well, the question itself is "Determine the vectorial subspaces of P(X) and Mn,m(R)"

orchid panther
#

For b)

#

Did you mean M2(R)

gritty escarp
#

yeah I meant M2,2(R)

orchid panther
#

Oh alright

gritty escarp
#

my bad

orchid panther
#

a) depends on if its K[X] or K_n[X] with some n in N

#

(And if n is superior to 1-2 or not)

gritty escarp
#

can I decompose the polynomials into vectors by the way?

a) would become something like (1,0,1) + a(x,0.0) + b(0,x^2,0) + c(0,0,x^3) ?

gritty escarp
#

and I think they do it in the next exercise

orchid panther
#

Well if its K[X] its a subspace with no problems

#

As K[X] is itself a vector space

gritty escarp
#

the only other polynomial in the exercise is this one

#

which by my understanding is also a subspace then?
then what would be an exemple of a polynomial that is not a subspace

orchid panther
#

Question states to "determine" right

gritty escarp
#

Yes

orchid panther
#

So i think they want a specific form of the subspaces

#

If thats the case for the matrix example it would be:
a+b 2b
2a a+b
With a, b in R

gritty escarp
#

which contains 0 and is stable by linear combination

#

therefore a subspace, correct?

orchid panther
#

Of course by definition of the Vect() (or span i think its called), but you can verify it if you want

#

And youd do the same for the polynomials

gritty escarp
#

Well I guess that cleared my doubts up

#

thanks man

#

.close

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#
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crimson sedge
#

is the PDF of a continuous random variable the equivalent to the PMF of a discrete random variable?

crimson sedge
#

as in like i know it's not exactly the same

#

but

#

if u had like P(X = 3) would it be equal to subbing in x = 3 into the PDF function

#

and the output is the number P(X = 3) ?

upper abyss
#

They're very similar concepts, to the point where the notation is even matched up

crimson sedge
#

so am i right to say that if i had P(X = a) for some a in the real numbers then it's the same as subbing in x = a into the PDF function

#

(for a continuous rv)

upper abyss
#

Not in that case, no. You'd want the area under the pdf between X = a and X = a

#

As continuous distributions express probabilities in terms of integrals

#

And discrete ones are in terms of sums

crimson sedge
#

unless im misunderstanding

upper abyss
#

Yep, you understand perfectly!

crimson sedge
#

ohh

#

yea

#

it would practically be 0

upper abyss
#

There's no way to roll "an exact real number", the probability is 0.

crimson sedge
#

cz it's almost impossible to get the exact infinity small point

#

ye

cedar kilnBOT
#

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vapid mauve
cedar kilnBOT
vapid mauve
#

<@&286206848099549185>

dire geode
cedar kilnBOT
# vapid mauve <@&286206848099549185>

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

slow jewel
#

-y=0.44?

#

Or y=0.44?

vapid mauve
#

-y

slow jewel
#

And x² is 1.44?

vapid mauve
#

Yes

slow jewel
#

Ok

#

Are you allowed to use a calculator?

vapid mauve
#

Yes why not

slow jewel
#

Just sub the values of x² and y in x²(x²+y)²⁰¹ then

tropic oxide
#

^

slow jewel
#

if -y= 0.44 then y=-0.44

tropic oxide
#

wait you won't even need a calculator for this lol

#

it's trivial

#

just plug and chug

#

in fact you don't even need to know that x ≥ 0

#

this letter x however

#

looks hideous

#

and you should never write the letter x with this shape

slow jewel
#

And added 0.44 instead

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Bruh

vapid mauve
#

Who can help me to find the answer

steel heart
#

C'mon it's easy just substitute the values

plucky merlin
#

1.44(1.44 - 0.44)^201

vapid mauve
#

.close

cedar kilnBOT
# plucky merlin 1.44(1.44 - 0.44)^201

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

#

@vapid mauve Has your question been resolved?

quick cipher
# vapid mauve .close

Want me to close it? I'll try, but if it doesn't, pls click/press the checkmark in this message.

quick cipher
#

.close

#

Yep doesnt work

quick cipher
cedar kilnBOT
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cedar kilnBOT
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austere dune
#

can someone help me with this question pls

cedar kilnBOT
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unkempt moat
#

how to find side length of this square hypotenuse is 3

vernal minnow
#

what are the 30 and 60?

#

also can we make assumptions about any of the angles here? Is that a right triangle? Is it equilateral?

unkempt moat
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30 and 60 degree

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angle

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s

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Isosceles right triangle

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no not that one

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the one which has 30 and 60 degree angles

vernal minnow
#

so the smaller ones are both isosceles right triangles while the big one is not?

unkempt moat
#

A square is drawn in an isosceles right triangle, as two of its vertices lie on the hypotenuse, the other two vertices. Find the side of the square if the hypotenuse is known to be 3

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yeah i think my drawing is wrong

#

it should be 45 45 degree each right?

vernal minnow
#

" an isosceles right triangle" since the sum of inner angles is 180° the two outer angles are 45° ones

unkempt moat
#

ok and how to find square side length

vernal minnow
#

the AAA theorem should apply

#

if all three angles of two triangles are equal, the triangles are "similar"

unkempt moat
#

so 3x=3 x=1?

vernal minnow
#

we can solve the shorter sides of the whole triangle pythagoras, utilizing that a=b and so a²+b²=2a²=2b²
c²=3 => 2a²=3 => a²=3/2 => a=b=sqrt(3/2)

vernal minnow
#

similar in this case means the proportions of the sides within each triangle to each other are the same

unkempt moat
#

but triangle has those angles 45 45 90

vernal minnow
#

so the side-length of the square is x

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and since we get isosceles right trriangles in each corner, their other cathetus must be x as well

#

so 3x=3 <=> x=1

unkempt moat
#

okay

#

thank you so much

vernal minnow
#

happy to help!

unkempt moat
#

.close

cedar kilnBOT
#
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normal shore
cedar kilnBOT
normal shore
#

is there any other way to find AB other than cosine rule?

#

since its 3 marks, shudnt be too long..?

#

.clos

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.close

cedar kilnBOT
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vagrant tundra
cedar kilnBOT
vagrant tundra
next hornet
#

What have you tried

tropic oxide
#

which part(s)

next hornet
#

Ok i guess i should ask if you know what absolute values are

vagrant tundra
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-2 will become +

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but if it's x-2, i reckon we can't just take x+2 can we?

vagrant tundra
#

will it be
x + a = 2x + a?
so 3x =?

tropic oxide
#

you will have two cases, one for x>=-a and the other for x<-a

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and in the first case the equation will resolve to that

#

but from x+a=2x+a you probably should not be getting 3x=(something)?

vagrant tundra
#

what I did was,
x + a = 2x + a
and then I moved the a to the left side and the x to the right side

tropic oxide
#

"moved"...

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first off do you know what absolute values are at all

vagrant tundra
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I think

tropic oxide
#

gtg sorry

vagrant tundra
#

oh nw

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<@&286206848099549185>

crimson sedge
vagrant tundra
#

i dont get what to do

crimson sedge
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X=0 in 7a

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(-(x + a) = 2x + a)

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Then
-x-a=2x+a

vagrant tundra
crimson sedge
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If

vagrant tundra
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WRONG ANSWERS

crimson sedge
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What should we find here

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1 a is 4

vagrant tundra
#

ignore that, i'll try to learn the topic once

crimson sedge
vagrant tundra
#

TYU

crimson sedge
cedar kilnBOT
#

@vagrant tundra Has your question been resolved?

cedar kilnBOT
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solar cipher
#

In each section, there are two triangles. Which sections are the two triangles congruent?

solar cipher
#

I think every section’s 2 triangles are congruent; but that seems to obvious so idk

manic escarp
#

!status

cedar kilnBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
solar cipher
#

s.a.s

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a.s.a

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AAA

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SSS

manic escarp
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yeah all those. theorems

solar cipher
#

yeah I’m aware and I think I answered my question correctly, but I want to double check

manic escarp
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can you show me your answers

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or what you did to get them

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you dont need to show me all of them just show me one or two

solar cipher
#

My answer is that all of them are congruent

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every section

manic escarp
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uh

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can you translate the bit at the top

solar cipher
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Sure

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In each section, say if the triangles are indeed congruent. Explain your answer

manic escarp
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ok yeah so all of them are congruent

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but you need to explain why

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i.e which theorem proves it

solar cipher
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Top far left - SAS
Bottom far left - SAS
Middle top - SAS
Middle bottom - SAS (they share a side)

manic escarp
#

yeah those are right

solar cipher
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Top right - ASA
Bottom right - ASA

manic escarp
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you get the idea so you should be fine for similar questions

solar cipher
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Yeah but

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The only thing is

manic escarp
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?

solar cipher
#

In other questions (not this one) it tells me to write a mathematical explanation, idk if it’s only in my country or it’s taught in other countries too

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Idk how to really explain it but I have no idea how to write congruency in mathematical language

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Like how to prove congruency

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If that makes sense

manic escarp
#

generally i think it wants you to explain how that theorem matches up with the two triangles

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in my country, or at least my teacher

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they would make a chart

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give me a sec ill show you

solar cipher
#

Yeahhh exactly

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That’s what I’m talking about

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I just haven’t really been listening so idk how to really make a chart

manic escarp
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youd have a chart similar to this

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on the left side you'd give a statement(i.e △ABC≅△DEF)

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and on the right side the proof would be congruency proven with SAS or another theorem

solar cipher
#

Yeahh that’s what I’m talking about

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That’s exactly what I’m talking about

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But with something like this (hold on the pic is sending) how do you prove this:

manic escarp
#

for the first question(topleft most) ill fill the chart so you can understand better and you can do the rest

solar cipher
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How do you use the chart to prove that ABD is congruent to CBE

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A=C is given, AD = CE is given

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How do I prove that the E and D are equal though

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in that chart

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sorry for my English typing skills if it’s an inconvenience

manic escarp
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its perfectly fine

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can you tell me what type of triangle is △BDE

solar cipher
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Scalene

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I think it’s called that in English

manic escarp
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describe it

solar cipher
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All three sides are different

manic escarp
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in this case

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angle D=E right

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if those two angles are the same then that means its an isosceles

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isosceles has two sides of the equal length or two angles that are equal

solar cipher
#

It’s not given to us that A=D or C=E

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so how would knowing that D=E prove that both triangles are isosceles

manic escarp
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if you look at the two given interior angles of BDE

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they both have two dashes on them meaning the angles are the same

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if two angles are the same in a triangle, the triangle is an isosceles

solar cipher
#

Ohh yeah

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Yeah I see what you mean

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But how can I prove like

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The outer part of D=E angles

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Are the same

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If that makes sense

manic escarp
#

what is the angle of a flat line

solar cipher
#

180

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I get what you’re saying

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How do I write that in the chart tho

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Do I just explain it

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Like how

manic escarp
#

first you'd write that △BDE is an isosceles triangle

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proof= angle D=E

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then as second statement

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BD=BE because △BDE is isosceles

solar cipher
#

Ye

manic escarp
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you can write 180-D=180-E because D=E

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write

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angle BDA=angle BEC as statement

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and as proof you would write D=E so 180-E=180-D=BDA=BEC

solar cipher
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ohhh ok that’s perfect

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thanks a lot

manic escarp
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np

solar cipher
#

mind if I send you a friend request?

manic escarp
#

i used to hate these questions because there was less math more explaining and english

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go ahead

#

dms are open

solar cipher
#

alright bet

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thanks a lot man

manic escarp
#

np

solar cipher
#

you truly helped me

#

🙂

#

have a good rest of your day

#

$close

#

.close

cedar kilnBOT
#
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daring needle
#

im working with proofs and parallel lines

cedar kilnBOT
#

@daring needle Has your question been resolved?