#help-13
1 messages · Page 225 of 1
but still you get an expression in x mixed with a t, but wait I think I see, maybe I should use that formula before the substitution?
ohhhhhhhhhhhhhhh
So I need some intuitive help guys,
Suppose you got a string of arbitrary length using the characters A B C D,such that they appear in the same frequency, 25% each
Would the permutations and combinations of A B C D also have the same frequency?
Damn that's actually pretty simple 😂
you need to post your question in an available channel
Integrate it like usual and replace the T
I don't understand
And yeah you should occupy an empty channel instead
Wait I'll close this one then
You also did pretty well, when given some of the wrong procedure you know the right rule and whatnot
Yw
Thanks 😄
Allright I'll close the channel now, again thanks a lot for your help :)
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need some help please
What is y' differentiated with respect to?
Oh
but idk if its gonna work
Go on
one sec
so ive written it in the form x' = Ax
where the vector x is (x,y,z)
we can see there are two block diagonal matrices
maybe we can solve them both
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can anyone help with no. 4?
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I have this hidden markov chain and am trying to calculate the probability of X2, how do i go about doing this?
i also have this prior information
@raven sandal Has your question been resolved?
16
What do you mean by 16
1/6
Could you explain how you get that though?
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LMK if you need translations. I need help to tackle this problem
(click on pictures for full size)
do you know how to expand the determinant along a row or column?
no I do not know of the Laplace expansion
perhaps I should read about it, would it be useful?
you should since there are very few other ways of finding the det of a general size matrix
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is it possible to have a harmonic function f:R^d->R and a function g:R->R such that g∘f is a harmonic function and G is not affine, if so provide an example and if not make a proof
@twin orbit Has your question been resolved?
to start investigating the claim, compute $\Delta(g\circ f)$ for $f$ harmonic and $g\in C^2$
Roketsune Janiku
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when you find the elimination matricies of a matrix A, why do you essentially multiply them backwards
"Matrix action" is done right to left
This is so they're seen as functions
Kind of like how f(g(x)) has g act on x, then f act on that
If A and B are matricies, and x is a column vector, then ABx is applying the effect of B, then applying the effect of A onto x
okay this makes sense
what also confuses me is like
so now we want to find the E's that belong to A
but then why do you take the inverse, starting at E3,1
$(A B )^{-1} = B^{-1} A^{-1}$ Multiply on both sides by B then A
Tobi
Seems to look related to de-morgan laws with "break the line flip the sign" actually here its more like "take the inverse change the order"
In your case its a few more steps with same idear
this was super hlepful
hmm im still confused why
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Hello, I need help with this question. I'm not sure what it means that I should use the dot product to solve this. I have attempted to do c_1b_1+c_2b_2+c_3*b_3 = <1,1,1> then set up a system of equations out of it and solve for c3 that way, however I didn't get the correct answer
Show your work, and if possible, explain where you are stuck.
I think i got it
vdotb_3=(b_1+b_2+b_3)dotb_3
Since bi's are orthogonal, their dot product will be zero
vdotb3 is 3+0+1=4
b_3dotb_3 is 3^2+1^2=10*c_1
10c_1=4
c_1=0.4
I mean c_3
Comparing coefficients?
disregard
i dont understand why you did b_3 dot b_3
, w solve a+b+3c=1, 2a-5b=1 and - 3a-3b+c=1
@vestal fern should have worked, c is c_3
Exploit the fact that they are orthogonal vectors and also question mentioned that
yeah but
normally you dot another vector
like b_2 dot b_3
instead of b_3 dot b_3
and that is why im confused
b2 dot b3 will result in a zero, you can't calculate the value of c3 with that
ok thanks for your help, I think I understand
do you know how to do the second part? I have no idea
I think it has something to do with normalizing right?
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confused.. can someone explain?
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
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Hi I need to multiple these together to get the answer below but I don’t know how to start
So I think it’s just √16w for the first left one right?
Or would it be rooted so it would be √ 4w
You'd have to take the 4 out of the square root to do that
sqrt(16w)=sqrt(16)*sqrt(w)=4sqrt(w)
Ah I see
Though I don't think it requires you to simplify (unless the question specifically states that)
Because sqrt(8) could become 2sqrt(2) and sqrt(u^5) could become u^2sqrt(u)
But I'm getting ahead of myself
I’m thinking it’s √2u^-1?
Be careful...
In the 3rd square on the top row, the u^5 is inside the square root
It has an odd power, so that would be a bit of an issue
Try getting the bottom square's u^4 inside the square root instead
Am I smart enough for this?
jan Lapiwin
Can you get the u inside the square root?
Uh... No
It needs to stay equal
Let's try something else
$\sqrt{2u^2}$
jan Lapiwin
Can you get the u^2 outside the square root?
I’ll be honest with you I don’t know how to
Okay, let's try one last thing
$\sqrt{u^2}$
jan Lapiwin
Get rid of the square root
The closest thing I could think of is multiply it?
Wait
Wait
Do we just square it then?
Square from both sides
What? No
Okay okay, one last chance
$\sqrt{u}^2$
jan Lapiwin
Simplify this
Does it just become u
jan Lapiwin
Simplify this
Is it just u again?
jan Lapiwin
Yeah to be honest
$\sqrt{u^2}=u$
jan Lapiwin
jan Lapiwin
Makes sense?
@high goblet Well, just as I did here I guess
That's what I mean
But how do we get the u^4 then
Let's do something simpler
First I wnat to confirm you can do this:
$\sqrt{2u^2}=?$
jan Lapiwin
@high goblet Has your question been resolved?
You know what, maybe I am keeping you guessing a bit too much
$\sqrt{2u^2}=\sqrt{2}u$
jan Lapiwin
Well actually we nearly always put the u at the front for aesthetic reasons but you get the point
And similarily:
$\sqrt{2u^4}=\sqrt{2}u^2$
jan Lapiwin
(If you have trouble understanding that one, just realise u^4=(u^2)^2)
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Hi, do you know how to solve this integral?
!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
ok can you show your work
But I do not know how to work out that 7/4
ok so do you know that $\int{\frac{dx}{x^2+a^2}}=\frac{tan^{-1}(\frac{x}{a})}{a}$?
calculus is fun
that's one loooong integral sign
No it is my first time seeing this
Is there some prove
Because I might be asked
then what integral do you know that results in arctan
1/(x^2+1)
ok so from $\int{\frac{dx}{x^2+a^2}}$ take $a^2$ as a common factor in the denom what do you get
calculus is fun
so in the denom I would get x^2/a^2 + 1
is multiplied by this
so overall you have 1/[a^2[(x/a)^2+1]]
this is under the integral sign
wrt x
so now 1/a^2 is a constant
you can "drag" it outside the integral sign since it is a constant multiplied by the integrated function
this gives$\frac{1}{a^2}\int{\frac{dx}{(\frac{x}{a})^2+1}}$
calculus is fun
now from here what can you do
try this
@latent hazel
are you there
sorry for the ping but i need to go sleep soon
thats why
yes I think I managed to calculate it so thank you very much for help
calculus is fun
is this what you got ?
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np you did the whole work
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!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
do you know the definition of uniform continuous ? if yes, can you please write it up
for all ε>0, there exists a δ>0 st. for all x,y in (a,b), 0< |x-y| < δ => |f(x) - f(y)| < ε
nice
so lets take $x_1,...,x_n\in(a,b)$ such that $(a,b)\subset \bigcup (x_i-\delta/2, x_i+\delta/2)$
everg
why?
i ll draw a quick picture to show the geoemtric idea
in the picture, the dots's height are values f(x1) f(x2) f(x3)
because every interval has diameter equal to delta
we know that the function restricted e.g. in the red interval is near to the red dot (at most it moves away espilon from the red dot)
ok...
everg
now for every $x$ in $(a,b)$ there is an $x_i$ such that $|x_1-x|<\delta$
everg
hence $|f(x)-f(x_i)|<\epsilon\implies |f(x)|<|f(x_i)|+\epsilon$
everg
implies $f(x)<M+\epsilon\implies \sup f(x)< M+\epsilon<\infty$
everg
but don't we want to show that f is bounded on R, not (a,b)?
how does one master this discord mathematics lingo?
wdym with lingo ?
that language you speak to generate the math synboks
symbols
it truly appears as if it is divine
you don't want to master it, like with anything else, it becomes not worth the effort much earlier
that is latex, i am a university so i know by my onw
ok
striker try this
https://texnique.xyz/ you can learn some basis latex lines
A LaTeX Typesetting Game
(a) talks about (a,b)
ok any ideas ?
unfortunately no; existence proofs have always stumped me
everg
if $x\in (\delta,2\delta)$ then $|f(x)|<|f(\delta)|+\epsilon<|f(0)|+\epsilon+\epsilon$
everg
i dont follow
by unifotm cont
isnt it then |f(x) - f(y)| < eps?
$|f(x)|-|f(0)|<|f(x)-f(0)|<\epsilon$
everg
are you ok with (1) then ?
give me a moment
is it passed that moment ?
sorry, I'm really not following this
how are we getting these inequalities?
it's non-obvious to me, even though i feel like it shouldnt be
I suppose I should start with the right-side inequality
why is |f(x)| < eps
everg
now is it better ?
everg
everg
but the reverse triangle inequality is | |x| - |y| | <= |x-y| no?
the use b=f(x)-f(0) and a=-f(0)
ok im good with this one
whats going on in 2 and 3?
(2) is just like (1) but in (delta, 2delta) instead of (0,delta)
ok, got it
(3) is just (2)+(1) ok ?
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✅
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help with lagranges multipliers
yh i did it wrong
@runic garnet have you done this the same
thus far
oh its root of 2/5**
no need to solve a numerical answer for lambda, but lemme see
no its still wrong
those two equations right under "solve for x and y"
yh
well -3/2 lamda?
with lambda in numerator or denominator?
lol
i've dont the same in y have i not
how do u do it then
$-3 = 2x\lambda \newline \newline 4 = 2y \lambda \newline \newline \frac {-3}{2x} = \frac 2y$
Stephen
what
ok so u have x = -3y/4
and x^2 + y^2 = 1
plug in the first into the second
then just solve
u plugged in both x and y, whats the point
u cant solve if u do this obv
x = -3y/4
x^2 + y^2 = 1
ok now find the points: (x,y,z) and (x,y,z)
how do i find z
ur given f(x,y) are you not?
why every combo? u found y = 4/5 and y = -4/5, find which value of x goes with y = 4/5 and y = -4/5
why isnt it the negative one
how do i find x from equation with no x in them?
y = 4/5 and we have x = -3y/4
plug in y into that equation
to solve for x
idk, am i not being clear or smth lol
you're probably being clear, i am just missing something
if y=4/5 and x=-3y/4
how can i solve for this equation:
4/5 = -3y/4 and find x?
nono
just tell me how u got that
$y = \frac 45 \newline \newline x = \frac {-3y}{4}$
Stephen
yes, i agree
so if y = 4/5, what would u do to find the value of x here
ik im just repeating but maybe the latex makes it more obvious
like we are given the value of y
if u put that value of y into the equation x = -3y/4 , what do u get
oh
you meant it like so
lets see
Can i write in latex here or is it only you?
anyone can do it
👍
z sorry
yea, z = 5 for (-.6,0.8)
-6?
i had to use lagrange multipliers to find the max and min
under some condition
which was x^2+y^2=1
yea so u got the values of the max and min
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A cylinder has a radius of x+4 units and a height of 6 units greater. Express the volume of the cylinder as a polynomial function.
I suppose the height can be expressed as x+10?
It's asking for a whole polynomial
Express the volume of cylinder by given information
Then it is done
I don't understand how do to that, that's why I'm asking
Ok
Do you know how to find the volume of cylinder with its radius and height given to you
Something wrong in the grammar
Then let me teach you how to calculate the volume
It should be very intuitive, that you will never forget once you learnt it
okay thank you
Given the radius of the cylinder is x+4
Could you tell me the bottom area of the cylinder?
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Why is the answer not -9?
Is has an minimum
-2+4-3=-1
My bad
Let me see
Is b/-2a = -1? Am I doing math wrong?
Y isn’t it -4?
I got -1 as the maximum too
Can u show me
But the way I finding it is quite different from yours
You need to use a formula b/-2a
Oh damn
Let me try your method
Terrific
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can i have help
im doing linear inequalities with two variables and i plugged in all the multi choice ordered number pairs they gave me and none were true
and i just cant figure out what to do
it says "Which of the following points lies in the solution set of the inequality y ≥ 3x + 10
(1) (1, 10)
(2) (-1, 3)
(3) (4, 20)
(4) (2, 18)
i plugged 1, in for 1, -1 in for 2, 4 in for 3, and 2 in for 4 and none of them were true
because 1 is 13, and 10 is not ≥ 13
because 2 is 7 and 3 is not ≥ 7
because 3 is 22 and 20 is not ≥ 22
OHHH WAIT
i switched up 4 i think
i put 16≥18 and its supposed to be 18≥16
nice lol
thanks @crimson sedge
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Looks like you wrote down the same answer 3 times
You didn't actually plug in k=0,1,2
Do that
yea im working on it
yea when doing this problem i don't think it ever took this long thats why im curious if i did anything wrong so far
,rotate
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@ancient vector Has your question been resolved?
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im confused
christ that has awful wording
so what I'm getting from it is that this graph is of the derivative function
and so when you find the area underneath the curve and all that you should be able to apply 2FTC to find F(1) and F(7)
what is 2FTC?
2nd fundamental theorem of calculus
oh
Triaxyz
so its the area or whatever
yes
of F(0) - minus the ones i find
so for example integral from 0 to 1 is the area of that triangle
which is equal to F(1) - F(0)
okay
then you solve for F(1)
so -1.5-5
I'd imagine it is
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So I have a function f(x,y,z)=ax^2 - by^2 - 3zx+yz where a and b are parameters. I found the Hessian matrix but the question I am trying to answer is, "Determine if there are conditions on a,b that would make f concave in some region of R3. If so, what conditions and what region?" Any guidance or help on this would be great!
I originally found the leading principal minors and was going to create the conditions off of that but thinking of it, i dont believe that would work(?)
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@outer pelican Has your question been resolved?
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How is $\frac{1}{\mid x \mid \sqrt{1-x^{2}}}$ the derivative of arcsec(x)? The domain of this function is (-1,1) while the domain for arcsec is $(-\infty,-1) \cup (1, \infty)$. How would I find the derivative of arcsec at, say x=85?
smidgin
its x^2-1 in the sqrt
Yeah, I just realised, the first answer on google being wrong doesn't help
Thanks!
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This is calculus 3.
I need help on 38.
I know I have to use this equation
using polar coordinates because this is a circle
I know
r(t) = <x,y,z> = <rcost, rsint, z> = <4cost, 4sint, 5>
and I found r'(t)
i don't understand how
F(r(t)) = <20sint, 40 cost, e^16sintcost>
from my teacher's solution below
<@&286206848099549185>
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hey can someone help me with this? i already started it but im a bit lost of what to do enxt (antidifferentiation)
$u=1-\ln\left(x\right)\to du=\frac{dx}{-x}$
Combustion
no
you didn't
if you did, these x's would be gone and this whole thing would be negative
yeah you did do that
im so confused cuz my other classmates also did the same beginning process as shown on the right and our teacher said it was right
what you did is right
but you forgot this step
Combustion
so i take out the negative one from the integral sign

what i have so far is
idk if that thing will work for me too
$2∫{2}\frac{x(u)^2}-1 ∫{(1-u)^2}\frac{x(u)^2}\cdot du
helpp
ill just take a picture
wait thats 1/x(u)^2 cuz i moved the 2 out
is this right
what do i do next
Combustion
remember that dx/x = -du, so there should be no x left
ohhhh
and this should also have a negative one
yep
so both were merged at this point rigth
yeah
our teacher didnt discuss it and just gave us a seatwork right away assuming we read in advanance
and then expand (1-u)^2
oh okok hold on
ohh like what i did on the top right except it shouldve been just (u)^2 left and theres -1 on the outside

i already split them up
can i use the ln thing with this format now
or do i still haev to do further anipulations
manipulations*
since its u^2
1/u^2 can be easily integrated using the power rule
yep
wait how do i do that, do i recriprocate it so u is on numerator?
or do i keep it on donminator
since the power rule for integration is the u^n+1 over n+1?
or am i mistaken
yeah sure you can do that
then ill ask u to verify if thats okay
did i do it right?
sorry its quite long and i didnt do the other one yet i did the first one first
you have to remove the integration sign
but yeah that's right
for the second one you expand (1-u)^2
ohh yeah im sorry i always do this mistake
ohh okok hold on
thank you so much btw this really means alot

did i expand it right? also is it right what i did on the left side or do i have to wait until i do the right side
we already integrated u^-2, you can't integrate 1/-u again
yes
we split them up again
into three?
yes
then i do the same process?
yep
yep
and so i take it out?
no we still have to integrate it
ohh okok
what happens to 2u/u^2 if i take 2 out its still gonna be u/u^1 right not 1/u^2?
Combustion
don't forget the negative 1 applies to everything, not just the first 2/u^2
also
integral of -1/u is -ln(|u|)
ohh yeah i forgot the -1 from the beginning
i think this was already integrated
from 1/u^2 i did the product rule and so it became -1/u
yupp i actually integrated it again by mistake on this part but u brought it up
ohhh i see
so for that one i do the ln thing
yep
oki oki hold on
hold on
what did u mean again by the -1 applies on everything
like i switch all their signs at the end?
or just for the -2 part
yeah because we had this $-1\int_{ }^{ }\frac{u^{2}-2u+1}{u^{2}}du$
Combustion
ohh so i should have multiplied it here? i did -1 x 2 making it -2
i shouldnt have had*
yes
nice!
omggg really
yep good job
ooo thank you!!!
have a good day
?
that's right
thank u so so so much!!!!! have a nice day bless you!!!!
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I'll denote theta by @ here for convenience.
To find the Z-transform of sin(n@) or cos(n@), the common strategy that everybody uses seems to be to equate the real and imaginary parts of the Z-transform of (e^i@)^n.
But I think this is just not valid because how do we know that Z{cos(n@} and Z{sin(n@)} are real?
Moreover, we also need to be sure that the corresponding expressions that occur on the right (when finding Z{(e^i@)^n}) are also real.
We can equate Re. and Im. parts of two complex numbers a+ib and c+id but don't we need to be sure that a, b, c, and d are all real in the first place?
My question is whether or not I'm right in raising this question?
I have seen an alternate way to just compute using the exponential expression of cosine and sine, with which I don't see any problem.
i don't really know what a z-transform is, but as a guess: is it generally true that the z transform of a real number is a real number?
No.
The Z-transform of a function f(n) defined for integers n is, sum over all n of f(n)/z^n.
Where z is a non-zero complex number.
So in most cases the Z-transform is actually not real.
hmmm
ok maybe a slight variant of this strategy works: you can also compute the z-transform of (e^-i@)^n, and then e^i@ + e^-i@ = 2cos(@) and e^i@ - e^-i@ = 2isin(@)
but yeah it sounds like just splitting it into real and imaginary parts doesn't make much sense if you don't already know that the result is going to be a real number
hmm..
I still want a more expertise answer but I thank you nevertheless for your help.
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This is from the bluebook sat practice test, it's not homework
I just don't understand this
@crimson sedge Has your question been resolved?
do you know that a diameter split a circle in half
does that ring a bell
What does that give us?
If the circle is split in half then that split the circumference and the area
Ohh i see
I solved it in another way already but that seems much easier
It's 48pi right?
The only information you're given here is PS arc and PQ arc
Which if you combine both of them it makes the arc of half a circle
Yes
Stick to what you think is correct, I can stop here or do you want to keep going
Alright
You're welcome
No i get it now
Ty
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Hello
How could I find the derivative of e^(2*(x-1))?
chain rule
derivative of function with input unmodified, times the derivative of the input
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Hey guys, I am just curious about this trivia I found. Does anyone have any idea whats going on?
first one is a question about logic
the truth table that you're asked for is that of:
q AND (NOT p)
if p is true, then NOT p is false
the same way, if p is false, NOT p is true
for the whole proposition to be true, q needs to be true, and (NOT p) needs to be also true
the second is a question about operations with sets, specifically union of sets.
The union of two sets is another set, which contains the elements of both sets
So A U C contains every element in A and every element in C
@brave loom Has your question been resolved?
Much appreciated
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So I checked and its diff-able at 0
but for 4 I check by the limit definition of derivative from left and right cause |x^2-4x|
is it -4sin4 from left and 4sin4 from right?
im not sure how to delete the | | sign when its limit from the left
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what did you find when you started that up
Im finding tutorials on how to solve it if it has an equation like f(x)=x^3−5x^2+17^x−13
but i dont have that so i dont necissarily know what to do still
this says that its 4-51=0 i presume but i dont know what i need to do to see what else is also 0
i just need some help explaining it :[
that doesn't sound like you're looking up what was recommended
show me
The complex conjugate zeros, or roots, theorem, for polynomials, enables us to find a polynomial's complex zeros in pairs. If a complex number is a zero then so is its complex conjugate. We learn the theorem and illustrate how it can be used for finding a polynomial's zeros. We also work through some typical exam style questions.
this is one of the ones i looked at
another one
what you want is mentioned multiple times
is it? okay, ill have to reread it. i was just hoping to recieve one on one help i guess
for a polynomial with real coefficients,
if a complex number is a zero, so is its complex conjugate
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If I encounter a difficult math question, how should I begin to solve it. Let's say I know all math behind the topic of it, let's say deriviate. How do I start solving it?
that's very broad
i would say split the task into subproblems and/or visualize it with a graphing calculator, if applicable
listing off what you know/given in the problem is always helpful
and your objective
So if the topic is deriviate I should think how to solve it with deriviate stuff?
Sadly, there is no true one task-solving method. If there were, there wouldn't be all these 100 Million USD open questions. But, if you are able to specify more, you can begin to tread beaten paths in the particular branch you exist on. Look at similiar problems, maybe their easier version, a generalized example to unravel some sort of pattern. There always is going to be a degree of specificity, which will dictate your approach somewhat, and sometimes, that is good to break.
like for a related rates problem, it'd be useful to list off the formulas related to the problem (i.e. if you got a sphere and something with volume mentioned, probably good to write down formula for volume of a sphere)
It is also good to know your theory, and, at any point, if you feel totally lost, it's ok to ✨ ask ✨
and if you know the radius, know the rate of change of volume or radius, basically just write down all of your knowns and givens from the problem. :)
English is not my first language so I have to ask what does "begin to tread beaten paths in particular branch" mean in this context
ok
Sorry, I was being kinda vague. I just meant look for what you need on the internet, a particular book, an excercise sheets. Check definitions, theroems, corollaries. Simplify your example. It is likely people have done your sort of math before.
Ah I understand, So I should write down formulas related to the topic, write down what I know, use the Internet to understand the question?
Is undergraduate lower level of education than pre university?
I'm not familiar with that term, hence the question
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Pls help me solve this quick
@unkempt crater Has your question been resolved?
yes
I managed to get something along the terms where OP = RS yet idk if thats true
tbh I am so lost
Can you explain what you wrote below the diagram
I can't understand it
Value of RS Compared to OQ
I need to calculate RS
THis is what I have so far but I need to find the value and idk if this is even corect
it is not a prism
wait
then that doesn't make any sence
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i am not sure exactly how to begin this but i sketched thr triangle so far
<@&286206848099549185>
@minor acorn Has your question been resolved?
@gleaming path
what does average value of 9 means?
i am not sure, its just given in the problem
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I don't rlly get 1/3 of the bacteria duplicates
I think that each minute there are 1/3 more bacteria
Is less than 100000
Exactly
50,000(4/3)^t < 100,000
👍👍
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