#help-13

1 messages · Page 225 of 1

verbal gust
#

You literally have CSC²(x) there

coral swallow
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but still you get an expression in x mixed with a t, but wait I think I see, maybe I should use that formula before the substitution?

verbal gust
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Nonono

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t⁴ * (cot²(x) +1) dt

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X*

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Remember that cot(x) is still t

coral swallow
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ohhhhhhhhhhhhhhh

verbal gust
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With that you can turn cot²(x) into t²

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Yes

light night
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So I need some intuitive help guys,

Suppose you got a string of arbitrary length using the characters A B C D,such that they appear in the same frequency, 25% each

Would the permutations and combinations of A B C D also have the same frequency?

coral swallow
#

Damn that's actually pretty simple 😂

coral swallow
verbal gust
#

Integrate it like usual and replace the T

coral swallow
#

Yes from there I think I got it

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Thank you so much dude

verbal gust
coral swallow
#

Wait I'll close this one then

verbal gust
#

Yw

coral swallow
#

Thanks 😄

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Allright I'll close the channel now, again thanks a lot for your help :)

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.close

cedar kilnBOT
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pale lake
#

need some help please

slow jewel
#

What is y' differentiated with respect to?

pale lake
#

i have an idea

slow jewel
#

Oh

pale lake
#

but idk if its gonna work

slow jewel
#

Go on

pale lake
#

one sec

pale lake
#

where the vector x is (x,y,z)

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we can see there are two block diagonal matrices

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maybe we can solve them both

crimson sedge
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thats cot^4x csc^4x

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which is cot^4x(cot^2x+1)^2

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expand and integrate

cedar kilnBOT
#

@pale lake Has your question been resolved?

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small radish
#

can anyone help with no. 4?

cedar kilnBOT
small radish
#

.close

cedar kilnBOT
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raven sandal
#

I have this hidden markov chain and am trying to calculate the probability of X2, how do i go about doing this?

raven sandal
#

i also have this prior information

cedar kilnBOT
#

@raven sandal Has your question been resolved?

raven sandal
#

What do you mean by 16

hazy oxide
#

1/6

raven sandal
#

Could you explain how you get that though?

cedar kilnBOT
#

@raven sandal Has your question been resolved?

cedar kilnBOT
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@raven sandal Has your question been resolved?

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still barn
#

LMK if you need translations. I need help to tackle this problem

still barn
#

(click on pictures for full size)

crimson delta
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do you know how to expand the determinant along a row or column?

still barn
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no I do not know of the Laplace expansion

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perhaps I should read about it, would it be useful?

calm sierra
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you should since there are very few other ways of finding the det of a general size matrix

still barn
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ok I will look into it, thanks!

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!close

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.close

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twin orbit
#

is it possible to have a harmonic function f:R^d->R and a function g:R->R such that g∘f is a harmonic function and G is not affine, if so provide an example and if not make a proof

cedar kilnBOT
#

@twin orbit Has your question been resolved?

calm sierra
#

to start investigating the claim, compute $\Delta(g\circ f)$ for $f$ harmonic and $g\in C^2$

wraith daggerBOT
#

Roketsune Janiku

cedar kilnBOT
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errant wasp
#

when you find the elimination matricies of a matrix A, why do you essentially multiply them backwards

errant wasp
#

like this

upper abyss
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"Matrix action" is done right to left

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This is so they're seen as functions

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Kind of like how f(g(x)) has g act on x, then f act on that

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If A and B are matricies, and x is a column vector, then ABx is applying the effect of B, then applying the effect of A onto x

errant wasp
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okay this makes sense

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what also confuses me is like

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so now we want to find the E's that belong to A

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but then why do you take the inverse, starting at E3,1

clever sinew
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$(A B )^{-1} = B^{-1} A^{-1}$ Multiply on both sides by B then A

wraith daggerBOT
clever sinew
#

Seems to look related to de-morgan laws with "break the line flip the sign" actually here its more like "take the inverse change the order"

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In your case its a few more steps with same idear

errant wasp
errant wasp
cedar kilnBOT
#

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cedar kilnBOT
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vestal fern
#

Hello, I need help with this question. I'm not sure what it means that I should use the dot product to solve this. I have attempted to do c_1b_1+c_2b_2+c_3*b_3 = <1,1,1> then set up a system of equations out of it and solve for c3 that way, however I didn't get the correct answer

cedar kilnBOT
#

Show your work, and if possible, explain where you are stuck.

shut tapir
#

I think i got it

vestal fern
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c_1 + c_2 +3c_2 = 1 -> c_1 = -c_2 - c_3
2(-c_2 - c_3) -5c_2 = 1 ->

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nice

shut tapir
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vdotb_3=(b_1+b_2+b_3)dotb_3

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Since bi's are orthogonal, their dot product will be zero

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vdotb3 is 3+0+1=4

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b_3dotb_3 is 3^2+1^2=10*c_1

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10c_1=4

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c_1=0.4

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I mean c_3

shut tapir
vestal fern
vestal fern
shut tapir
#

, w solve a+b+3c=1, 2a-5b=1 and - 3a-3b+c=1

wraith daggerBOT
shut tapir
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@vestal fern should have worked, c is c_3

shut tapir
vestal fern
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yeah but

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normally you dot another vector

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like b_2 dot b_3

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instead of b_3 dot b_3

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and that is why im confused

shut tapir
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b2 dot b3 will result in a zero, you can't calculate the value of c3 with that

vestal fern
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ok thanks for your help, I think I understand

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do you know how to do the second part? I have no idea

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I think it has something to do with normalizing right?

shut tapir
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Uhh

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No idea about that

vestal fern
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ok

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i'll leave it open if someone else wants to help

cedar kilnBOT
#

@vestal fern Has your question been resolved?

vestal fern
#

.close

cedar kilnBOT
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errant turret
#

confused.. can someone explain?

cedar kilnBOT
elfin hill
#

what is coefficient thing

cedar kilnBOT
# elfin hill

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

errant turret
#

.close

cedar kilnBOT
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cedar kilnBOT
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high goblet
#

Hi I need to multiple these together to get the answer below but I don’t know how to start

high goblet
crimson sedge
#

We'll do it step-by-step

high goblet
#

Or would it be rooted so it would be √ 4w

crimson sedge
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sqrt(16w)=sqrt(16)*sqrt(w)=4sqrt(w)

high goblet
#

Ah I see

crimson sedge
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Though I don't think it requires you to simplify (unless the question specifically states that)

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Because sqrt(8) could become 2sqrt(2) and sqrt(u^5) could become u^2sqrt(u)

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But I'm getting ahead of myself

high goblet
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True , so would it just be √16w for now then?

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And then the middle being √8u^5

crimson sedge
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Yeah, that works

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mhm

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What about the top right?

high goblet
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I’m thinking it’s √2u^-1?

crimson sedge
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Be careful

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In the lower square, the u^4 is outside the square root

high goblet
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Hmmm

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So it’s more like √2 u^-1

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Rather than being in it

crimson sedge
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In the 3rd square on the top row, the u^5 is inside the square root

high goblet
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True

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I don’t know how to get it out though

crimson sedge
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It has an odd power, so that would be a bit of an issue

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Try getting the bottom square's u^4 inside the square root instead

high goblet
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Inside the square root

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Am I too dumb for this

crimson sedge
crimson sedge
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$\sqrt{2}u$

wraith daggerBOT
#

jan Lapiwin

crimson sedge
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Can you get the u inside the square root?

high goblet
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You mean like √u?

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Wait so is it just √2u?

crimson sedge
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It needs to stay equal

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Let's try something else

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$\sqrt{2u^2}$

wraith daggerBOT
#

jan Lapiwin

crimson sedge
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Can you get the u^2 outside the square root?

high goblet
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I’ll be honest with you I don’t know how to

crimson sedge
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$\sqrt{u^2}$

wraith daggerBOT
#

jan Lapiwin

crimson sedge
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Get rid of the square root

high goblet
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The closest thing I could think of is multiply it?

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Wait

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Wait

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Do we just square it then?

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Square from both sides

crimson sedge
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Okay okay, one last chance

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$\sqrt{u}^2$

wraith daggerBOT
#

jan Lapiwin

crimson sedge
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Simplify this

high goblet
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Does it just become u

crimson sedge
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Yes

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$\sqrt{u^2}$

wraith daggerBOT
#

jan Lapiwin

crimson sedge
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Simplify this

high goblet
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Is it just u again?

crimson sedge
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$\sqrt{2u^2}$

wraith daggerBOT
#

jan Lapiwin

crimson sedge
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Now, pull the u out of the square root

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@high goblet Struggling?

high goblet
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Yeah to be honest

crimson sedge
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$\sqrt{u^2}=u$

wraith daggerBOT
#

jan Lapiwin

crimson sedge
#

This can be written equivalently as:

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$\sqrt{1u^2}=\sqrt{1}u$

wraith daggerBOT
#

jan Lapiwin

crimson sedge
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Makes sense?

high goblet
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That makes sense yes

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I just don’t get how I can “pull it out”

crimson sedge
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That's what I mean

high goblet
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But how do we get the u^4 then

crimson sedge
#

First I wnat to confirm you can do this:

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$\sqrt{2u^2}=?$

wraith daggerBOT
#

jan Lapiwin

crimson sedge
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How do you "pull the u out"?

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Sorry for the slow response times by the way

cedar kilnBOT
#

@high goblet Has your question been resolved?

crimson sedge
#

You know what, maybe I am keeping you guessing a bit too much

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$\sqrt{2u^2}=\sqrt{2}u$

wraith daggerBOT
#

jan Lapiwin

crimson sedge
#

Well actually we nearly always put the u at the front for aesthetic reasons but you get the point

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And similarily:

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$\sqrt{2u^4}=\sqrt{2}u^2$

wraith daggerBOT
#

jan Lapiwin

crimson sedge
#

(If you have trouble understanding that one, just realise u^4=(u^2)^2)

cedar kilnBOT
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latent hazel
#

Hi, do you know how to solve this integral?

dim tiger
#

!status

cedar kilnBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
latent hazel
#

I would say number 2

#

Basically I know the result will be arctg

dim tiger
#

ok can you show your work

latent hazel
#

But I do not know how to work out that 7/4

dim tiger
#

ok so do you know that $\int{\frac{dx}{x^2+a^2}}=\frac{tan^{-1}(\frac{x}{a})}{a}$?

wraith daggerBOT
#

calculus is fun

sly granite
latent hazel
#

Is there some prove

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Because I might be asked

dim tiger
#

then what integral do you know that results in arctan

latent hazel
#

1/(x^2+1)

dim tiger
#

ok so from $\int{\frac{dx}{x^2+a^2}}$ take $a^2$ as a common factor in the denom what do you get

wraith daggerBOT
#

calculus is fun

latent hazel
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so in the denom I would get x^2/a^2 + 1

dim tiger
#

ok now

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you are missing something

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a^2

dim tiger
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so overall you have 1/[a^2[(x/a)^2+1]]

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this is under the integral sign

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wrt x

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so now 1/a^2 is a constant

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you can "drag" it outside the integral sign since it is a constant multiplied by the integrated function

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this gives$\frac{1}{a^2}\int{\frac{dx}{(\frac{x}{a})^2+1}}$

wraith daggerBOT
#

calculus is fun

dim tiger
#

now from here what can you do

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try this

#

@latent hazel

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are you there

#

sorry for the ping but i need to go sleep soon

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thats why

latent hazel
#

yes I think I managed to calculate it so thank you very much for help

dim tiger
#

it is an easy u-sub

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this leads to $\frac{1}{a}tan^{-1}(\frac{x}{a})+C$

wraith daggerBOT
#

calculus is fun

dim tiger
#

is this what you got ?

latent hazel
#

yeah exactly

#

so again thanks for help

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.close

cedar kilnBOT
#
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dim tiger
#

np you did the whole work

cedar kilnBOT
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void sand
cedar kilnBOT
void sand
#

!status

cedar kilnBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
void sand
#

1

#

trying a) right now, but I can't really seem to get anything

vast pike
#

do you know the definition of uniform continuous ? if yes, can you please write it up

void sand
vast pike
#

nice

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so lets take $x_1,...,x_n\in(a,b)$ such that $(a,b)\subset \bigcup (x_i-\delta/2, x_i+\delta/2)$

wraith daggerBOT
void sand
#

why?

vast pike
#

i ll draw a quick picture to show the geoemtric idea

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in the picture, the dots's height are values f(x1) f(x2) f(x3)

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because every interval has diameter equal to delta

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we know that the function restricted e.g. in the red interval is near to the red dot (at most it moves away espilon from the red dot)

void sand
#

ok...

vast pike
#

so lets make it rigorous

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let $M=max f(x_i)$

wraith daggerBOT
vast pike
#

now for every $x$ in $(a,b)$ there is an $x_i$ such that $|x_1-x|<\delta$

wraith daggerBOT
vast pike
#

hence $|f(x)-f(x_i)|<\epsilon\implies |f(x)|<|f(x_i)|+\epsilon$

wraith daggerBOT
vast pike
#

implies $f(x)<M+\epsilon\implies \sup f(x)< M+\epsilon<\infty$

wraith daggerBOT
void sand
#

but don't we want to show that f is bounded on R, not (a,b)?

polar goblet
vast pike
#

wdym with lingo ?

polar goblet
#

that language you speak to generate the math synboks

#

symbols

#

it truly appears as if it is divine

fair geyser
#

you don't want to master it, like with anything else, it becomes not worth the effort much earlier

vast pike
#

that is latex, i am a university so i know by my onw

polar goblet
#

ok

vast pike
#

striker try this

#

(a) talks about (a,b)

void sand
#

ah, so it does

#

mb

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what about part b)..?

vast pike
#

ok any ideas ?

void sand
vast pike
#

lets see

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if $x\in(0,\delta)$ then $|f(x)|<|f(0)|+\epsilon$

wraith daggerBOT
vast pike
#

if $x\in (\delta,2\delta)$ then $|f(x)|<|f(\delta)|+\epsilon<|f(0)|+\epsilon+\epsilon$

wraith daggerBOT
vast pike
#

which part you don t follow

#

?

void sand
#

starting with 1, tbh

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if 0 < x < delta, why does |f(x)| < |f(0)| + eps?

vast pike
#

by unifotm cont

void sand
#

isnt it then |f(x) - f(y)| < eps?

vast pike
#

$|f(x)|-|f(0)|<|f(x)-f(0)|<\epsilon$

wraith daggerBOT
vast pike
#

are you ok with (1) then ?

void sand
#

give me a moment

vast pike
#

is it passed that moment ?

void sand
#

how are we getting these inequalities?

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it's non-obvious to me, even though i feel like it shouldnt be

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I suppose I should start with the right-side inequality

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why is |f(x)| < eps

vast pike
#

oh sorry

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$|f(x)|-|f(0)|<|f(x)-f(0)|<\epsilon$

wraith daggerBOT
vast pike
#

now is it better ?

void sand
#

ok so 0 < |x - 0| < delta => |f(x) - f(0)| < eps sure

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what about the other inequality

vast pike
#

because

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triangular inequality

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$|a+b|<|a|+|b|$

wraith daggerBOT
vast pike
#

implies

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$|a+b|-|a|<|b|$

wraith daggerBOT
void sand
#

but the reverse triangle inequality is | |x| - |y| | <= |x-y| no?

vast pike
#

the use b=f(x)-f(0) and a=-f(0)

void sand
#

ok im good with this one

void sand
vast pike
#

(2) is just like (1) but in (delta, 2delta) instead of (0,delta)

void sand
#

ok, got it

vast pike
#

(3) is just (2)+(1) ok ?

cedar kilnBOT
#

@void sand Has your question been resolved?

cedar kilnBOT
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void sand
#

.reopen

cedar kilnBOT
#

cedar kilnBOT
#

@void sand Has your question been resolved?

#
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crimson sedge
#

help with lagranges multipliers

cedar kilnBOT
crimson sedge
#

would this be right

runic garnet
#

dont think so

#

@crimson sedge

#

i got a diff answer

crimson sedge
#

yh i did it wrong

#

@runic garnet have you done this the same

#

thus far

#

oh its root of 2/5**

runic garnet
#

no need to solve a numerical answer for lambda, but lemme see

#

no its still wrong

#

those two equations right under "solve for x and y"

crimson sedge
#

yh

runic garnet
#

what do u get when solving for x

#

do it again

crimson sedge
#

well -3/2 lamda?

runic garnet
#

with lambda in numerator or denominator?

crimson sedge
#

oh

#

god

#

tragic

runic garnet
#

lol

crimson sedge
#

i've dont the same in y have i not

runic garnet
#

yea y is wrong too

#

but this isnt even how i would do it

crimson sedge
#

how do u do it then

runic garnet
#

$-3 = 2x\lambda \newline \newline 4 = 2y \lambda \newline \newline \frac {-3}{2x} = \frac 2y$

wraith daggerBOT
#

Stephen

runic garnet
#

now id just solve for x or y, and plug into x^2 + y^2 = 1

#

and there you have it

crimson sedge
#

ok let me try

#

give me 2 min

#

but

#

why is lambda not in the equation

#

oh nvm

runic garnet
#

yea this is how i do it

#

just get rid of lambda immediately

crimson sedge
#

what now

runic garnet
#

what

#

ok so u have x = -3y/4

#

and x^2 + y^2 = 1

#

plug in the first into the second

#

then just solve

crimson sedge
#

i have plugged it in

#

do i not need to solve for both

runic garnet
#

u plugged in both x and y, whats the point

runic garnet
crimson sedge
#

xd

#

then ill get the most cursed number

runic garnet
#

x = -3y/4
x^2 + y^2 = 1

crimson sedge
#

ok

#

i get y to be 4/5 or -4/5

runic garnet
#

yea

#

now find x

crimson sedge
#

3/5

#

-3/5

runic garnet
#

ok now find the points: (x,y,z) and (x,y,z)

crimson sedge
#

how do i find z

runic garnet
#

ur given f(x,y) are you not?

crimson sedge
#

yh

#

do i insert every combo of x and y in?

#

since thye can be plus or minus

runic garnet
#

why every combo? u found y = 4/5 and y = -4/5, find which value of x goes with y = 4/5 and y = -4/5

crimson sedge
#

ok, i am bit lost

#

first ever question on this

runic garnet
#

y = 4/5 and we have x = -3y/4

#

find x

crimson sedge
#

why isnt it the negative one

runic garnet
#

u have to do the negative one too

#

im just showing u whats going on

crimson sedge
#

how do i find x from equation with no x in them?

runic garnet
#

y = 4/5 and we have x = -3y/4

#

plug in y into that equation

#

to solve for x

#

idk, am i not being clear or smth lol

crimson sedge
#

you're probably being clear, i am just missing something

#

if y=4/5 and x=-3y/4
how can i solve for this equation:
4/5 = -3y/4 and find x?

runic garnet
#

how did u set them equal like that

#

4/5 = -3y/4 howd u get that

#

@crimson sedge

crimson sedge
#

well

#

i just dont understand how to solve for x if x is given by y

runic garnet
#

nono

#

just tell me how u got that

#

$y = \frac 45 \newline \newline x = \frac {-3y}{4}$

wraith daggerBOT
#

Stephen

crimson sedge
#

yes, i agree

runic garnet
#

so if y = 4/5, what would u do to find the value of x here

#

ik im just repeating but maybe the latex makes it more obvious

#

like we are given the value of y

#

if u put that value of y into the equation x = -3y/4 , what do u get

crimson sedge
#

oh

#

you meant it like so

#

lets see

#

Can i write in latex here or is it only you?

runic garnet
#

anyone can do it

crimson sedge
#

at any rate

#

so we know that 4/5 and -3/5 go together

runic garnet
#

yea we have our two sets of (x,y)

#

now find (x,y,z) for both

crimson sedge
#

ok

#

so i get -24/5

#

and 24/5

runic garnet
#

think u got ur addition wrong

#

try agian

crimson sedge
#

5

#

and -5

runic garnet
#

👍

crimson sedge
#

put x=y and y=x

#

hence the answer

#

so lambda = 5?

runic garnet
#

lambda?

#

why lambda?

crimson sedge
#

z sorry

runic garnet
#

yea, z = 5 for (-.6,0.8)

crimson sedge
#

-6?

runic garnet
#

-.6

#

-3/5

crimson sedge
#

oh yh

#

what now

runic garnet
#

wdym

#

isnt that what u wanted?

#

what is ur assignmnet asking for

crimson sedge
#

i had to use lagrange multipliers to find the max and min

#

under some condition

#

which was x^2+y^2=1

runic garnet
#

yea so u got the values of the max and min

crimson sedge
#

5 and -5

#

niceeee

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

cedar kilnBOT
#
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After 15 minutes, feel free to ping <@&286206848099549185>.
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sage vine
#

A cylinder has a radius of x+4 units and a height of 6 units greater. Express the volume of the cylinder as a polynomial function.

civic coral
sage vine
#

It's asking for a whole polynomial

civic coral
#

Then it is done

sage vine
#

I don't understand how do to that, that's why I'm asking

civic coral
#

Ok

#

Do you know how to find the volume of cylinder with its radius and height given to you

civic coral
sage vine
#

no

#

that's why I'm asking for help

civic coral
#

Then let me teach you how to calculate the volume

#

It should be very intuitive, that you will never forget once you learnt it

sage vine
#

okay thank you

civic coral
#

Given the radius of the cylinder is x+4

#

Could you tell me the bottom area of the cylinder?

cedar kilnBOT
#
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bold pond
#

Why is the answer not -9?

cedar kilnBOT
civic coral
#

Is has an minimum

zealous compass
#

-2+4-3=-1

bold pond
#

No it doesn’t

#

It has a maximum

civic coral
#

My bad

bold pond
#

I got -1 tho for b/-2a

#

What am I doing wrong

civic coral
#

Let me see

bold pond
bold pond
civic coral
#

I got -1 as the maximum too

bold pond
#

Can u show me

civic coral
bold pond
#

You need to use a formula b/-2a

civic coral
#

I used the derivative to find it

#

But it’s fine tho

bold pond
#

Oh damn

civic coral
#

Let me try your method

bold pond
#

That’s y I figured it

#

It’s bc -2a would be positive 4

#

So it’s 4/4 not 4/-4

civic coral
#

Terrific

bold pond
#

.close

cedar kilnBOT
#
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crimson sedge
#

can i have help

cedar kilnBOT
crimson sedge
#

im doing linear inequalities with two variables and i plugged in all the multi choice ordered number pairs they gave me and none were true

#

and i just cant figure out what to do

#

it says "Which of the following points lies in the solution set of the inequality y ≥ 3x + 10

(1) (1, 10)
(2) (-1, 3)
(3) (4, 20)
(4) (2, 18)

#

i plugged 1, in for 1, -1 in for 2, 4 in for 3, and 2 in for 4 and none of them were true

#

because 1 is 13, and 10 is not ≥ 13

#

because 2 is 7 and 3 is not ≥ 7

#

because 3 is 22 and 20 is not ≥ 22

#

OHHH WAIT

#

i switched up 4 i think

#

i put 16≥18 and its supposed to be 18≥16

#

nice lol

#

thanks @crimson sedge

crimson sedge
#

.close

cedar kilnBOT
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ancient vector
cedar kilnBOT
ancient vector
#

Not sure if I set it up correctly.

dire geode
#

Looks like you wrote down the same answer 3 times

#

You didn't actually plug in k=0,1,2

#

Do that

ancient vector
#

yea im working on it

#

yea when doing this problem i don't think it ever took this long thats why im curious if i did anything wrong so far

lavish wedge
#

,rotate

wraith daggerBOT
ancient vector
cedar kilnBOT
#

@ancient vector Has your question been resolved?

cedar kilnBOT
#

@ancient vector Has your question been resolved?

cedar kilnBOT
#
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dull spoke
cedar kilnBOT
dull spoke
#

im confused

opal schooner
#

christ that has awful wording

#

so what I'm getting from it is that this graph is of the derivative function

#

and so when you find the area underneath the curve and all that you should be able to apply 2FTC to find F(1) and F(7)

dull spoke
#

what is 2FTC?

opal schooner
#

2nd fundamental theorem of calculus

dull spoke
#

oh

opal schooner
#

or first I cant remember which it is

#

$\int_{a}^{b} f'(x) dx = f(b) - f(a)$

wraith daggerBOT
#

Triaxyz

dull spoke
#

so its the area or whatever

opal schooner
#

yes

dull spoke
#

of F(0) - minus the ones i find

opal schooner
#

so for example integral from 0 to 1 is the area of that triangle

dull spoke
#

or the other way around

#

1 - 0

opal schooner
dull spoke
#

okay

opal schooner
#

then you solve for F(1)

dull spoke
#

so -1.5-5

opal schooner
#

+5 because you're adding

#

-1.5 = F(1) - 5

dull spoke
#

ohh

#

i see

#

so its 3.5

#

for the first

opal schooner
#

I'd imagine it is

dull spoke
#

okay yeah its right

#

thanks

#

.close

cedar kilnBOT
#
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outer pelican
#

So I have a function f(x,y,z)=ax^2 - by^2 - 3zx+yz where a and b are parameters. I found the Hessian matrix but the question I am trying to answer is, "Determine if there are conditions on a,b that would make f concave in some region of R3. If so, what conditions and what region?" Any guidance or help on this would be great!

outer pelican
#

I originally found the leading principal minors and was going to create the conditions off of that but thinking of it, i dont believe that would work(?)

cedar kilnBOT
#

@outer pelican Has your question been resolved?

cedar kilnBOT
#

@outer pelican Has your question been resolved?

cedar kilnBOT
#
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rocky harness
#

How is $\frac{1}{\mid x \mid \sqrt{1-x^{2}}}$ the derivative of arcsec(x)? The domain of this function is (-1,1) while the domain for arcsec is $(-\infty,-1) \cup (1, \infty)$. How would I find the derivative of arcsec at, say x=85?

wraith daggerBOT
#

smidgin

crimson delta
#

its x^2-1 in the sqrt

rocky harness
#

Yeah, I just realised, the first answer on google being wrong doesn't help

#

Thanks!

#

.close

cedar kilnBOT
#
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modern glen
#

This is calculus 3.

I need help on 38.

cedar kilnBOT
modern glen
#

I know I have to use this equation

#

using polar coordinates because this is a circle

I know
r(t) = <x,y,z> = <rcost, rsint, z> = <4cost, 4sint, 5>

and I found r'(t)

#

i don't understand how

F(r(t)) = <20sint, 40 cost, e^16sintcost>

from my teacher's solution below

#

<@&286206848099549185>

#

.close

cedar kilnBOT
#
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umbral tapir
#

hey can someone help me with this? i already started it but im a bit lost of what to do enxt (antidifferentiation)

umbral tapir
paper vigil
wraith daggerBOT
#

Combustion

umbral tapir
#

hey im bit confused

#

a bit confused*

#

i mean ive done that part already

paper vigil
#

no

#

you didn't

#

if you did, these x's would be gone and this whole thing would be negative

umbral tapir
#

th Let u part

#

the*

paper vigil
#

yeah you did do that

umbral tapir
#

im so confused cuz my other classmates also did the same beginning process as shown on the right and our teacher said it was right

paper vigil
#

what you did is right

paper vigil
umbral tapir
#

ohhh ok ok

#

so i add the du part right

#

at the end

paper vigil
#

yep

#

doing this $-1\cdot du=\frac{dx}{x}$

wraith daggerBOT
#

Combustion

umbral tapir
#

so i take out the negative one from the integral sign

paper vigil
umbral tapir
#

what i have so far is

#

idk if that thing will work for me too

#

$2∫{2}\frac{x(u)^2}-1 ∫{(1-u)^2}\frac{x(u)^2}\cdot du

#

helpp

#

ill just take a picture

#

wait thats 1/x(u)^2 cuz i moved the 2 out

#

is this right

#

what do i do next

paper vigil
#

well

#

it should've been $-1\cdot\int_{ }^{ }\frac{2+\left(1-u\right)^{2}}{u^{2}}du$

wraith daggerBOT
#

Combustion

paper vigil
#

remember that dx/x = -du, so there should be no x left

umbral tapir
#

ohhhh

paper vigil
#

and this should also have a negative one

umbral tapir
#

ohhhh i see

#

so its just u^2 left

paper vigil
#

yep

umbral tapir
paper vigil
#

yeah

umbral tapir
#

what happens next

#

im really sorry

paper vigil
#

it's okay dude lol

#

you basically split them up like you did

umbral tapir
#

our teacher didnt discuss it and just gave us a seatwork right away assuming we read in advanance

paper vigil
#

and then expand (1-u)^2

umbral tapir
#

oh okok hold on

umbral tapir
# umbral tapir

ohh like what i did on the top right except it shouldve been just (u)^2 left and theres -1 on the outside

paper vigil
umbral tapir
#

i already split them up

#

can i use the ln thing with this format now

#

or do i still haev to do further anipulations

#

manipulations*

#

since its u^2

paper vigil
#

1/u^2 can be easily integrated using the power rule

umbral tapir
#

oh so i bring out 2 as well?

#

so it becomes 1/u^2

#

then i do the power rule?

paper vigil
#

yep

umbral tapir
#

wait how do i do that, do i recriprocate it so u is on numerator?

#

or do i keep it on donminator

#

since the power rule for integration is the u^n+1 over n+1?

#

or am i mistaken

paper vigil
#

1/u^2 is the same as u^(-2)

#

if that's what you meant to ask?

umbral tapir
#

yeahh

#

do i do that?

#

hold on let me just write it on paper

paper vigil
#

yeah sure you can do that

umbral tapir
#

then ill ask u to verify if thats okay

#

did i do it right?

#

sorry its quite long and i didnt do the other one yet i did the first one first

paper vigil
#

you have to remove the integration sign

#

but yeah that's right

#

for the second one you expand (1-u)^2

umbral tapir
#

ohh yeah im sorry i always do this mistake

#

ohh okok hold on

#

thank you so much btw this really means alot

paper vigil
umbral tapir
#

did i expand it right? also is it right what i did on the left side or do i have to wait until i do the right side

paper vigil
#

we already integrated u^-2, you can't integrate 1/-u again

umbral tapir
#

ohhh oh my god right

#

so does it become 2/u?

paper vigil
#

yes

umbral tapir
#

ohh i see i see thank youu

#

after expanding the left side what do i do

paper vigil
#

we split them up again

umbral tapir
#

into three?

paper vigil
#

yes

umbral tapir
#

then i do the same process?

paper vigil
#

yep

umbral tapir
#

okok

#

when i split them one becomes u^2/u^2 will that just be equal to one?

paper vigil
#

yep

umbral tapir
#

and so i take it out?

paper vigil
#

no we still have to integrate it

umbral tapir
#

ohh okok

#

what happens to 2u/u^2 if i take 2 out its still gonna be u/u^1 right not 1/u^2?

paper vigil
#

u/u^2 is 1/u

#

$\frac{u}{u^{2}}=\frac{u}{u\cdot u}=\frac{1}{u}$

wraith daggerBOT
#

Combustion

umbral tapir
#

ohhhhhh thank you so much

#

ahh im not sure if this is right

paper vigil
#

don't forget the negative 1 applies to everything, not just the first 2/u^2

#

also

#

integral of -1/u is -ln(|u|)

umbral tapir
#

ohh yeah i forgot the -1 from the beginning

umbral tapir
#

from 1/u^2 i did the product rule and so it became -1/u

paper vigil
#

oh i see

#

it should've been 1/u not 1/u^2

umbral tapir
umbral tapir
#

so for that one i do the ln thing

paper vigil
#

yep

umbral tapir
#

oki oki hold on

#

hold on

#

what did u mean again by the -1 applies on everything

#

like i switch all their signs at the end?

#

or just for the -2 part

paper vigil
#

yeah because we had this $-1\int_{ }^{ }\frac{u^{2}-2u+1}{u^{2}}du$

wraith daggerBOT
#

Combustion

umbral tapir
# umbral tapir

ohh so i should have multiplied it here? i did -1 x 2 making it -2

#

i shouldnt have had*

paper vigil
#

multiplying it by two is right

#

it doesn't change the integral

umbral tapir
#

so the -2 part is right

#

but i should also multiple the -1 on the others as well?

paper vigil
#

yes

umbral tapir
#

is what i did right?

#

before substituting u again

paper vigil
#

nice!

umbral tapir
#

omggg really

paper vigil
#

yep good job

umbral tapir
#

thank you!!!

#

also when i substitute the 1-lnx

#

on "-u"

#

does it became 1+lnx?

paper vigil
#

close

#

it becomes ln(x)-1

umbral tapir
#

ooo thank you!!!

paper vigil
#

have a good day

umbral tapir
#

and does it

#

become + ln(x)-1

paper vigil
#

?

umbral tapir
#

just a clarification hold on

paper vigil
#

that's right

umbral tapir
#

thank u so so so much!!!!! have a nice day bless you!!!!

cedar kilnBOT
#

@umbral tapir Has your question been resolved?

cedar kilnBOT
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summer panther
#

I'll denote theta by @ here for convenience.

To find the Z-transform of sin(n@) or cos(n@), the common strategy that everybody uses seems to be to equate the real and imaginary parts of the Z-transform of (e^i@)^n.

But I think this is just not valid because how do we know that Z{cos(n@} and Z{sin(n@)} are real?
Moreover, we also need to be sure that the corresponding expressions that occur on the right (when finding Z{(e^i@)^n}) are also real.

We can equate Re. and Im. parts of two complex numbers a+ib and c+id but don't we need to be sure that a, b, c, and d are all real in the first place?

My question is whether or not I'm right in raising this question?

I have seen an alternate way to just compute using the exponential expression of cosine and sine, with which I don't see any problem.

astral bay
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i don't really know what a z-transform is, but as a guess: is it generally true that the z transform of a real number is a real number?

summer panther
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No.

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The Z-transform of a function f(n) defined for integers n is, sum over all n of f(n)/z^n.

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Where z is a non-zero complex number.

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So in most cases the Z-transform is actually not real.

astral bay
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hmmm

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ok maybe a slight variant of this strategy works: you can also compute the z-transform of (e^-i@)^n, and then e^i@ + e^-i@ = 2cos(@) and e^i@ - e^-i@ = 2isin(@)

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but yeah it sounds like just splitting it into real and imaginary parts doesn't make much sense if you don't already know that the result is going to be a real number

summer panther
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hmm..

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I still want a more expertise answer but I thank you nevertheless for your help.

cedar kilnBOT
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@summer panther Has your question been resolved?

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crimson sedge
cedar kilnBOT
crimson sedge
#

This is from the bluebook sat practice test, it's not homework

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I just don't understand this

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@crimson sedge Has your question been resolved?

verbal gust
#

does that ring a bell

crimson sedge
verbal gust
crimson sedge
#

Ohh i see

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I solved it in another way already but that seems much easier

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It's 48pi right?

verbal gust
#

The only information you're given here is PS arc and PQ arc
Which if you combine both of them it makes the arc of half a circle

verbal gust
crimson sedge
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I'll solv eit that way too

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Ty for the help

verbal gust
verbal gust
crimson sedge
#

Ty

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thick mauve
#

Hello

cedar kilnBOT
thick mauve
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How could I find the derivative of e^(2*(x-1))?

thick tiger
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chain rule

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derivative of function with input unmodified, times the derivative of the input

thick mauve
#

Oo

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thank youu

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brave loom
#

Hey guys, I am just curious about this trivia I found. Does anyone have any idea whats going on?

muted timber
#

first one is a question about logic

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the truth table that you're asked for is that of:
q AND (NOT p)

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if p is true, then NOT p is false

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the same way, if p is false, NOT p is true

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for the whole proposition to be true, q needs to be true, and (NOT p) needs to be also true

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the second is a question about operations with sets, specifically union of sets.
The union of two sets is another set, which contains the elements of both sets

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So A U C contains every element in A and every element in C

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brave loom
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vestal hedge
#

So I checked and its diff-able at 0

cedar kilnBOT
vestal hedge
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but for 4 I check by the limit definition of derivative from left and right cause |x^2-4x|

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is it -4sin4 from left and 4sin4 from right?

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im not sure how to delete the | | sign when its limit from the left

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@vestal hedge Has your question been resolved?

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@vestal hedge Has your question been resolved?

vestal hedge
#

Oh well

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.close

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crimson sedge
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wet flume
cedar kilnBOT
dire thorn
wet flume
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okay

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i feel like im not getting the explanation that i need :/

livid hound
#

what did you find when you started that up

wet flume
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Im finding tutorials on how to solve it if it has an equation like f(x)=x^3−5x^2+17^x−13

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but i dont have that so i dont necissarily know what to do still

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this says that its 4-51=0 i presume but i dont know what i need to do to see what else is also 0

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i just need some help explaining it :[

livid hound
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that doesn't sound like you're looking up what was recommended

wet flume
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i mean, i copy and pasted it

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and im looking at what shows up

livid hound
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show me

wet flume
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this is one of the ones i looked at

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another one

livid hound
#

what you want is mentioned multiple times

wet flume
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is it? okay, ill have to reread it. i was just hoping to recieve one on one help i guess

livid hound
#

for a polynomial with real coefficients,
if a complex number is a zero, so is its complex conjugate

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@wet flume Has your question been resolved?

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opal anvil
#

If I encounter a difficult math question, how should I begin to solve it. Let's say I know all math behind the topic of it, let's say deriviate. How do I start solving it?

thick tiger
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that's very broad

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i would say split the task into subproblems and/or visualize it with a graphing calculator, if applicable

opal anvil
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hmm ok

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I'll try that next time

subtle harbor
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and your objective

opal anvil
hollow valve
#

Sadly, there is no true one task-solving method. If there were, there wouldn't be all these 100 Million USD open questions. But, if you are able to specify more, you can begin to tread beaten paths in the particular branch you exist on. Look at similiar problems, maybe their easier version, a generalized example to unravel some sort of pattern. There always is going to be a degree of specificity, which will dictate your approach somewhat, and sometimes, that is good to break.

subtle harbor
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like for a related rates problem, it'd be useful to list off the formulas related to the problem (i.e. if you got a sphere and something with volume mentioned, probably good to write down formula for volume of a sphere)

hollow valve
#

It is also good to know your theory, and, at any point, if you feel totally lost, it's ok to ✨ ask ✨

subtle harbor
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and if you know the radius, know the rate of change of volume or radius, basically just write down all of your knowns and givens from the problem. :)

opal anvil
hollow valve
opal anvil
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Is undergraduate lower level of education than pre university?

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I'm not familiar with that term, hence the question

dawn junco
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undergraduate is beginning university

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@opal anvil

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unkempt crater
#

Pls help me solve this quick

cedar kilnBOT
unkempt crater
#

pls

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<@&286206848099549185>

cedar kilnBOT
#

@unkempt crater Has your question been resolved?

hollow valve
#

i can't read what you need to find

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do you need to express RS in terms of OQ?

unkempt crater
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yes

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I managed to get something along the terms where OP = RS yet idk if thats true

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tbh I am so lost

swift sorrel
unkempt crater
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I need to calculate RS

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THis is what I have so far but I need to find the value and idk if this is even corect

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it is not a prism

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wait

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then that doesn't make any sence

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.close

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minor acorn
cedar kilnBOT
minor acorn
#

i am not sure exactly how to begin this but i sketched thr triangle so far

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<@&286206848099549185>

cedar kilnBOT
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@minor acorn Has your question been resolved?

minor acorn
#

@gleaming path

elfin hollow
#

what does average value of 9 means?

minor acorn
#

i am not sure, its just given in the problem

minor acorn
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@gleaming path

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ionic wolf
cedar kilnBOT
#

Please don't occupy multiple help channels.

ionic wolf
#

I don't rlly get 1/3 of the bacteria duplicates

crimson sedge
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I think that each minute there are 1/3 more bacteria

ionic wolf
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So times 1.3

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To the t power

crimson sedge
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So each minute the total number of bacteria is multiplied by 4/3

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Yes

ionic wolf
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Is less than 100000

crimson sedge
#

Exactly

ionic wolf
#

50,000(4/3)^t < 100,000

crimson sedge
#

👍👍

ionic wolf
#

Thank you

#

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