#help-13

1 messages · Page 200 of 1

merry nacelle
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No

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<@&286206848099549185>

cedar kilnBOT
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@merry nacelle Has your question been resolved?

merry nacelle
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no.

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marble ermine
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Let ( V ) be a real vector space. Every subspace of ( V ) is a subgroup of ( (V, +) ).

wraith daggerBOT
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lilisworld

marble ermine
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is that true or false?

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ok thanks

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and

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Every subgroup of ( (V, +) ) is a subspace of ( V ).

wraith daggerBOT
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lilisworld

marble ermine
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is that true or not?

south tundra
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E.g., consider R as an R-vectorspace and its subset Z

marble ermine
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ok

south tundra
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Z is a subgroup of (R, +) but not a subspace

marble ermine
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yes thanks

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stone gate
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Hi guys! Can someone please tell me where I made mistake in this???

mortal wagon
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the arctan formula only applies if a is constant

stone gate
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ohh I see I see

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thanks for the help!

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coarse rock
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Mae Carol Jemison, the first black woman to travel into space, writes books about space for children. Her agent is selling copies of her latest book, Mae Among the Stars, on an online marketplace. She currently charges $13.30 per book and sells 824 books every yearWhile experimenting with the price, the agent estimated that for each $0.05 increase in book price, the number of books sold decreases by 4
How do i find the revenue for that
I need to write a function for the revenue where x is the number of books

steel cloak
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Are you sure that you are not asked to find the revenue as a function of the price?

coarse rock
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revenue as a function of BOOK price

steel cloak
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Okay

coarse rock
steel cloak
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I would start to find an equation relating the number of books to the price

coarse rock
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book * price

steel cloak
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That is one equation we need, but we need another one.

coarse rock
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Its alright i am done working on that

steel cloak
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If the author sets the price to 13.30+0.05x, what is the number of books sold? [edited]

coarse rock
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824

steel cloak
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Oh

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13.30+0.05x

coarse rock
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Oh

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x

steel cloak
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Perhaps you used x as the number of books. I meant like, x could represent how many notches of 0.05$ we have increased the price.

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So like, if x=20, we increase the price by 0.05*20 dollars

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We can write the price as 13.30+0.5x. Using the information in the text, how can you express the number of books in a similar fashion?

cedar kilnBOT
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@coarse rock Has your question been resolved?

steel cloak
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fantastic! Now you just have to combine price=13.30+0.05x and books=824-4x to express the number of books in terms of the price

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Here is how you can start:

price = 13.30 + 0.05x

price - 13.30 = 0.05x = x / 20

20(price - 13.30) = x

cedar kilnBOT
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@coarse rock Has your question been resolved?

coarse rock
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20(price-13.3= [books-824]/4

steel cloak
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Great!

coarse rock
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🙂

steel cloak
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🙂

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Now, there is only a few steps left

coarse rock
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Ohh

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Solve for price?

steel cloak
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Remember, we want to write books * price in terms of only the price

coarse rock
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Hmm

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How do we do that

steel cloak
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Well, just like we sovled for x previously, we can solve for books.

coarse rock
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Why didn’t we do 13+0.05x*[824-4x]

steel cloak
coarse rock
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20*4(price-23.3)+824= books

steel cloak
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Oh, great

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That works too

coarse rock
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That is all?

steel cloak
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except minus

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Yeah

coarse rock
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Minus?

steel cloak
coarse rock
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Right

steel cloak
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It should be 824 - 20*4(price-23.3) = books

coarse rock
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Where did we get the - from

steel cloak
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books = 824 MINUS 4x

coarse rock
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Ah

coarse rock
steel cloak
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np, great work!

coarse rock
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.close

cedar kilnBOT
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oak anchor
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does anyone know what's wrong with my program?

oak anchor
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I have to compute that

cunning drift
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I dont now sorry

oak anchor
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no, why?

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yup

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yes

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économie mais c pas le sujet

cunning drift
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de quoi

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économie

oak anchor
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prepa économie

cunning drift
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à force

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je suis en 4eme

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tu aime les math ou pas

oak anchor
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si je suis sur ce serv c'est que c'est le cas jpp

cunning drift
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ok

dull oxide
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your method names could use some work, for starters

cunning drift
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Quels sont les principaux facteurs économiques qui influencent les décisions de politique monétaire d'un pays, et comment ces décisions peuvent-elles avoir un impact sur l'économie nationale et internationale ?

oak anchor
dull oxide
cunning drift
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de quoi

oak anchor
oak anchor
cunning drift
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En utilisant le modèle d'équilibre général, explorez en profondeur les implications de l'ouverture des marchés internationaux sur la spécialisation, la croissance économique et la distribution des revenus dans un pays en développement. Discutez des avantages et des inconvénients de cette ouverture pour l'économie nationale et les divers acteurs sociaux?

cunning drift
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tinquiéte

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alors?

oak anchor
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mes dissertations de 12 pages sont pas aussi exigeantes stp

crimson sedge
cunning drift
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a dsl

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@oak anchor Comment l'offre et la demande de travail influencent-elles les fluctuations du taux de chômage dans une économie et quel rôle joue la politique gouvernementale dans ce contexte ?

crimson sedge
cunning drift
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@oak anchor alors

crimson sedge
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Welp I'm out

oak anchor
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but there's still an error

mighty drift
mighty drift
oak anchor
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ok I've solved it, I changed a y = np.zeros(n) to a y = np.zeros(n+1)

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cedar kilnBOT
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mighty drift
oak anchor
mighty drift
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généralement une Q de maths c'est pas de la programmer

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c'est trouver la limite, un DL, une forme explicite, des choses comme ça

cedar kilnBOT
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crimson sedge
cedar kilnBOT
crimson sedge
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im 99.9% sure im correct but my paranoia is not letting me go forward without double checking

mighty drift
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that's why we invented calculators

crimson sedge
mighty drift
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well it's not why, but it's still usable for that purpose

crimson sedge
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.close

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mighty drift
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because that's also wolfram alpha-able

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though at your level, any computation is

crimson sedge
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.close

mighty drift
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you can't double close

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and you don't need to unless you reopen

crimson sedge
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oh ok

mighty drift
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it just auto closes after a random amount of time

crimson sedge
crimson sedge
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the exponet is -2 right

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so i just write -2

mighty drift
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you can do these. You don't need to ask for all of them

cedar kilnBOT
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vivid fog
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Hi there, I am studying proofs myself to prepare for my later courses, in the textbook they left the exercise of proving the attached proposition. I am stuck with the case that x is negative and was wondering what is my next best step.

Thank you for taking the time to help 🙂

vivid fog
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Wait actually, can we just say that root x^2 will always be positive because any number squared is positive and we can't square root a negative number, which in turn makes the absolute value of x = x instead of -x?

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<@&286206848099549185>

cedar kilnBOT
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@vivid fog Has your question been resolved?

vivid fog
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<@&268886789983436800> can I ping again

floral sinew
vivid fog
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😄

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<@&286206848099549185>

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thx :3

floral sinew
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Np - please have a look next time before pinging eveyrone though lol (seems funny pinging lots of people to see if you can ping lots of people xd)

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raw star
cedar kilnBOT
raw star
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Hi can I get some help on this question

exotic furnace
cedar kilnBOT
# raw star
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
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@raw star Has your question been resolved?

raw star
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@exotic furnace I am at 1

exotic furnace
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well, 0<a<1, right?

raw star
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Yes

exotic furnace
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What’s the range of a^2 then?

raw star
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Between that

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0 and 1 also?

exotic furnace
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So what’s -a^2’s range?

raw star
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It would be negative

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Perhaps between 0 and -1?

exotic furnace
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Yes

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So which of the three pieces will it fall under?

raw star
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The first piece

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Less than 0

exotic furnace
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Yes

raw star
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But what would I plug into the function

exotic furnace
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What’s your x

raw star
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Negative # between 0 and -1?

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Can I put like any negative number in the range there?

exotic furnace
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So just put it in terms of a

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In other words you’re plugging in -a^2 everywhere x is

raw star
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So

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Would I only do that for the first one?

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U get like -a^6-2

exotic furnace
raw star
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So is that all I have to do? Sorry for late reply

exotic furnace
cedar kilnBOT
#

@raw star Has your question been resolved?

cedar kilnBOT
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raw star
#

Thank for the help

cedar kilnBOT
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lime citrus
#

Why is this answer wrong?

cedar kilnBOT
void sand
#

I believe you have holes at x = 3 and x = 4

lime citrus
#

How do I find that?

carmine whale
sterile wharf
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When combining functions (+, -, *, /) - You can never get rid of domain restrictions, only add them

lime citrus
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OHH

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so my answer should look like this?

carmine whale
sterile wharf
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I believe it's an operation of functions, slightly different

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@lime citrus was that the correct answer?

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If it's asking for composition it's something different

lime citrus
sterile wharf
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How did your professor explain it?

lime citrus
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Actually looking at my notes, maybe that is what the was telling us I think I just confused, we only did one example in class

sterile wharf
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Gotcha

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In that example it works

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Because g(x) has no domain restrictions

lime citrus
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Yeah I wish we did more examples

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I think we're going to cover it more in depth next unit, he just wanted to touch on it in case its on our exam for Thursday

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Thanks for the help

sterile wharf
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Can I send you a piece of reference?

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My favorite math YouTuber

lime citrus
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Sure

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Anything helps lol

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I took alegebra 10 years ago so it's been hard to remember things

sterile wharf
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I feel that

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I skipped math for 3 years at the end of high school and restarting in college was a pain

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Can I close this ticket?

lime citrus
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yes

sterile wharf
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.close

cedar kilnBOT
#

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unreal bolt
cedar kilnBOT
unreal bolt
#

i dont even know where to start with this problem

balmy zenith
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a percent is part/total

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so the first step would be to find the total amount of money spent

unreal bolt
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so add all the values together?

balmy zenith
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yes

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to start

unreal bolt
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i got 425000

balmy zenith
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how much was spent on appliance department?

unreal bolt
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10000

balmy zenith
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so what percent was spent on applicance department?

unreal bolt
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2.35%

balmy zenith
#

exactly

unreal bolt
#

OHHHHHHHH

balmy zenith
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the percent is part/ total

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step 1 calculate the total

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then for each part, divide it by the total

unreal bolt
#

bro tysm

balmy zenith
#

you got this

unreal bolt
#

.close

cedar kilnBOT
#
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crimson sedge
cedar kilnBOT
crimson sedge
#

How would I solve #22

unique thunder
#

what's a six letter word and it is a type of a real vector space ? <@&286206848099549185>

cedar kilnBOT
unique thunder
#

this a password for a zoom meeting , I did not find anything

dire thorn
unique thunder
#

ow sorry

crimson sedge
dire thorn
cedar kilnBOT
#

@crimson sedge Has your question been resolved?

dire thorn
# crimson sedge No

Exactly, same thing applies for addition/subtraction. That means changing the value of y will not affect the real part of the complex number on either side. It also means changing the value of x will not affect the imaginary part of the complex number on either side. This means we can set the real parts equal to each other, and the imaginary parts equal to each other and from there its easy to find x and y

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7x=14 and -2yi=6i

crimson sedge
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Ohh

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Oh my god

dire thorn
crimson sedge
#

Me when I realize what I did wrong

#

.closr

#

.close

cedar kilnBOT
#
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somber snow
#

how do i fill the zeros and the multiplicity

upper abyss
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Why did you take the negatives of all the zeros

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Multiplicity is what the zero "looks like". x = -4 is "like a parabola" so it has multiplicity 2.

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#

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slate thistle
#

How should I prove this proof using the laws of logic
Only laws we learned: Detachment(Modus Pollens), Syllogism, Simplifcation, Contrapositive, Disjuinctive and Demorgans)

cedar kilnBOT
#

@slate thistle Has your question been resolved?

slate thistle
#

<@&286206848099549185>

cedar kilnBOT
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@slate thistle Has your question been resolved?

cedar kilnBOT
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obtuse sparrow
#

ive mana

cedar kilnBOT
obtuse sparrow
#

ive managed to reduce this integral to the following:

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1/r^2 * 1/sqrt(1+r^2/x^2)

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however, when I plugin my bounds, I get 0, not 2/R

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r^2/x^2 reduces to just 0

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so its just 1/r^2 - 1/r^2

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What am I doing wrong here?

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because r^2/x^2 goes to 0 when x = infinity

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i see part of the issue. originally, it's ( x/r^2) * x/sqrt(x^2 + r^2)

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and so when i try to do the simplification pulling out x from the square root i lose informatoin carried in the sign of x

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but when i leave x in the numerator, I just get infinities in the numerator, and I'm having trouble reconciling that with the expected 2/r answer

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<@&286206848099549185>

#

i believe ive figured it out, youve got 2 separate the integral into two pieces and sum them

#

.close

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undone star
cedar kilnBOT
undone star
#

I’m not really sure how to do this question

opal basin
#

Triangle inequality

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|a + b| <= |a| + |b|

cedar kilnBOT
#

@undone star Has your question been resolved?

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crimson sedge
cedar kilnBOT
crimson sedge
#

,rotate

wraith daggerBOT
crimson sedge
#

How do I do number 2?

hollow trail
#

a scale measures the normal force you exert on it, which by newton's third law is equal to the normal force it exerts on you. Set up Newton's second law (Fnet = ma), using the two forces (mg pulling down, given normal force), and solve for the acceleration

crimson sedge
#

So A is just 644/73?

hollow trail
#

you need to account for the force of gravity. Remember, newton's second law only applies to the net force.

crimson sedge
#

I’m not sure what to add sorry

hollow trail
#

Let's start with a free body diagram of the forces at play here. The two that are relevant here are the force of gravity and the normal force

crimson sedge
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Yes from the ground

hollow trail
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The force of gravity always points down, and the normal force from the elevator floor points up since the floor is below us

crimson sedge
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Ok

hollow trail
#

Based on that free body diagram, we can set up an equation for the net force

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our net force should add up all of our forces, but forces pointing in opposite directions should have opposite signs (i.e., if a force pointing up is positive, then a force pointing down is negative).

crimson sedge
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I was falling asleep yo

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Hm

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Okay

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What do I do with this info

hollow trail
#

you need to add up the forces to get the net force on your object

crimson sedge
#

Is weight a force?

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Not sure what forces or shown except gravity

hollow trail
#

whenever you are on the ground, you are being pulled down by gravity. Considering that you are not falling into the center of the earth, the ground must be pushing you up. we call this a reaction force, specifically the normal force

#

because of newton's third law, this normal force is equal and opposite to the force you exert on the ground from gravity (a.k.a. weight)

crimson sedge
#

Would weight be positive ?

#

Because it’s mg

#

Absolute value?

hollow trail
#

depends on what you're talking about. weight is the force due to gravity. but when we measure weight, what we actually measure is the normal force you exert on a scale (which is equal and opposite to the normal force the scale exerts on you)

crimson sedge
#

Ok

#

What can I do with the given force on the elevator and mass on ground

hollow trail
#

so we have two forces: one that is the force of gravity (mg, down) and one that is the normal force (apparent weight), up

#

so we set Fnet = sum of both forces, with upwards forces positive and downwards forces negative

#

this is important because of newton's second law Fnet = ma. so if we find the net force we can solve for acceleration

crimson sedge
hollow trail
#

in this case, yes

crimson sedge
#

What’s gravity in newtons

hollow trail
#

1 newton = 1 kg * 1 m/s². so mg is in newtons

crimson sedge
#

Cause idk any other force besides gravity acting on it

hollow trail
#

no, that's the "apparent weight" a.k.a measured normal force

crimson sedge
#

Oh ok

crimson sedge
#

73 I mean*

hollow trail
#

We have two forces at play

  1. gravity = mg
  2. normal - given as "apparent weight = 644 N
crimson sedge
#

I mean subtract

hollow trail
#

if your class gives g = 10, then yes

crimson sedge
#

730-644 = 86

#

F=ma
A=F/m
A= 86/73

#

?

hollow trail
#

ok, that gives us the acceleration. which direction is that acceleration in?

cedar kilnBOT
#

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atomic steppe
cedar kilnBOT
atomic steppe
#

need help with 23

dire thorn
#

!status

cedar kilnBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
atomic steppe
#

but the answer key says it’s wrong

#

this is supposed to be the answer

dire thorn
# atomic steppe

The equation of a line is y=mx+b. I believe you forgot to find b (your m is good)

cedar kilnBOT
#

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onyx wing
#

Hello, so basically i have a sum of a transport fee (1260) which i have to spread to different goods (they come with the same transport) in the left yellow column there's the quantity in KG while in the right yellow the total. "Price" column is the price for each good, i wanted to spread it considering both quantity and price cause I don't want to put 0,86 cents on the 3,8€ good for example (sorry im dumb and thank you)

cedar kilnBOT
#

@onyx wing Has your question been resolved?

cedar kilnBOT
#

@onyx wing Has your question been resolved?

cedar kilnBOT
#

@onyx wing Has your question been resolved?

crimson sedge
cedar kilnBOT
#

@onyx wing Has your question been resolved?

crimson sedge
onyx wing
#

Oh uh

#

In my phone if i zoomed in i could see pretty well, lemme get a decent one

cedar kilnBOT
#

@onyx wing Has your question been resolved?

cedar kilnBOT
#

@onyx wing Has your question been resolved?

onyx wing
#

<@&286206848099549185> sorry for the ping in advance

cedar kilnBOT
#

@onyx wing Has your question been resolved?

cedar kilnBOT
#

@onyx wing Has your question been resolved?

dire geode
onyx wing
#

I can try, i have six products which i want to add a transport fee to, they all come with the same transport and each time i pay 70€, so to make something more precise(hopefully) i chose a period of time and summed the quantities (kgs) for each product and i did 70€ x (times the transport came) = 1260€. In the Excel you can see i spread the transport fee to all the products but i only used quantity as a variable so i would like to involve the price of each product as well so I don't put the transport fee of 1€(for example) on both a product priced 30€ and one priced 2€ cause that would be kinda weird i think

amber ridge
#

like, base it off of “goods total”

onyx wing
#

Hmm i tried but it's too high

amber ridge
onyx wing
#

Hmm they're kinda skewed

#

The first three are kinda okay, the others are soo low

#

Like 0,00--

#

Fun thing is i did it last year on my own but i forgot how

#

Fml im growing dumber

#

I remember i used the two columns on the right and divided by 10 once

#

But yeah idk, numbers kinda weird

amber ridge
onyx wing
#

Well actually tried another and i think it should be good

#

Using the total and quantity column

crimson sedge
#

.open

amber ridge
#

@onyx wing Has your question been resolved?

onyx wing
#

Ur a weird bot

amber ridge
#

xd

#

do .close

#

like literally type in
.close

onyx wing
#

Oh i was gonna ask about that, thought i had to wait for the bot again

#

.close

cedar kilnBOT
#
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scarlet heron
#

Anyone help with this ?

cedar kilnBOT
amber ridge
#

use product rule

#

ez

scarlet heron
#

How, idk how to

#

Not sure how to start

tawdry atlas
#

Substitute the two terms in your right-hand expression with functions. So let $f(t) = t^5 + 3t$ and $g(t)=1-e^{-5t}$. Then you have $$ w(t) = f(t)\cdot g(t)$$ Now use the product rule to continue after you differentiate w with respect to t.

wraith daggerBOT
tawdry atlas
#

Differentiating w with respect to t, is akin to evaluating dw / dt.

scarlet heron
#

I’m a bit confused on how to differentiate this

floral arrow
#

Do you know how to differentiate each part?

tawdry atlas
#

you can apply the same logic where x is t instead.

#

and w is [f(t)g(t)]

#

(if you mean you don't know how to differentiate using the product rule. if you are having trouble differentiating each part, then it's an another thing. srry)

scarlet heron
#

Oh I get it

#

Omg thanks a lot

cedar kilnBOT
#

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marsh pond
cedar kilnBOT
marsh pond
#

I followed the instructions here but didn't get it correct

#

a = (4,-4)
b = (3,-5)

cos(Θ)=[a•b]/[|a| |b|]

#

any ideas?

clear umbra
#

maybe try drawing it in a xy plane

lusty grotto
#

,calc acos((12+20)/(sqrt(4^2+4^2)*sqrt(3^2+5^2)))

wraith daggerBOT
#

Result:

0.24497866312686
marsh pond
#

ty

#

,calc acos((20+12+4)/(sqrt(5^2+3^2+2^2)*sqrt(4^2+4^2+2^2)))

wraith daggerBOT
#

Result:

0.23147736397018
marsh pond
#

,calc acos((-20+12-4)/(sqrt(5^2+3^2+2^2)*sqrt(4^2+4^2+2^2)))

wraith daggerBOT
#

Result:

1.9012189747064
marsh pond
#

got my signs mixed up but figured it out

cedar kilnBOT
#

@marsh pond Has your question been resolved?

cedar kilnBOT
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stoic void
#

If you have two functions that are strictly increasing, is it safe to say they intersect at MOST one time?

prisma granite
#

no

stoic void
#

Can i get an example?

prisma granite
#

one sec

#

x=y

#

x=y +1

turbid mesa
#

They never intersect

prisma granite
#

yup

turbid mesa
#

You can also have infinitely many intesections

prisma granite
#

if its the same function

#

scaled by a constant

#

2x=2y + 2 and x=y+1 are equal

turbid mesa
#

Even when they are not the same functions

#

Now floor(x) is not strictly increasing, but one should be able to see that you can modify floor(x) such that the purple lines have some non zero slope and still intersect y=x, making it strictly increasing

prisma granite
#

how will you make floor x tilted tho?

#

it returns an integral output right?

turbid mesa
prisma granite
#

i guess

#

yeah

cedar kilnBOT
#

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wild grove
cedar kilnBOT
wild grove
#

Anyone can explain to me how we moved from the forth to the fifth step

royal finch
#

You can multiply the inside of an absolute value by -1 without changing the value

wild grove
#

Yes yes I get it

#

Thank you

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#

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lyric narwhal
#

Hi, I was solving a question and I generated a functional equation, I was just wondering if it is solvable

lyric narwhal
#

The equation is $f^2(x)=1+xf(x+1)$

wraith daggerBOT
#

kheerii

lyric narwhal
#

f(x) only takes positive integer values

#

and it's output must also be positive (since it arises from a square root)

cedar kilnBOT
#

@lyric narwhal Has your question been resolved?

gritty viper
#

Is the ^2 iteration?

cedar kilnBOT
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granite crystal
cedar kilnBOT
granite crystal
#

could i get some help with this continuity question please

#

im confused to as which part is the area

#

so A1U1=A2U2=A3U3

#

isnt u1 = 0 since its streamline is at the surface?

#

so surely q=0

peak minnow
#

cant u just use torcellis theorm to solve that?

#

to have h constant , the flowrate of the hole of container must be equal to the flowrate of the bottle

#

so calculate the flowrate of hole of container using torcellis theorm

granite crystal
#

oh ok

#

bernoulli's

#

thats what i thought as well

peak minnow
#

yeah modified bernoullis

granite crystal
#

but wasnt sure it was equal to flow that

#

roate*

#

rate*

#

thats why i didnt try

peak minnow
#

im pretty sure they both are equal

#

like other wise the height h would vary

granite crystal
#

yea they are

#

should be

#

by the way for bernoulli's equation

#

for the static pressure p1

#

is that the same pgh?

#

rgh

#

which has a reference point from the atmospheric pressure so up to downwards on the container

peak minnow
#

use torcelli's thoerm , its modified bernoulli's and its v = sqrt(2gh)

#

v is the flow rate
g is gravity
h is height above the hole

granite crystal
#

yh im looking at it rn on wikipedia

peak minnow
#

and ik why they have given diameters , its so that u use
A1V1 = A2V2 = constant
but flowrate would be equal so its ok

granite crystal
#

yh

#

but im asking for bernoulli's equation

#

p1+rv^2/2+rgz = constant

#

is the p1

#

equal to rgh where h is the reference point as the atmospheric pressure

#

so in this case h would be from top to bototm

peak minnow
#

why use bernoulli's?

granite crystal
#

no im asking question

#

a different one

peak minnow
#

oh ok

granite crystal
#

for bernoulli's equation

#

p1 - static pressure

#

is that equivalent to rgh

#

where h has a reference point of atmospheric pressure

peak minnow
#

r is rho?

granite crystal
#

yea

peak minnow
#

yeah thats valid

granite crystal
#

oh ok nice

#

thank you for answering both

peak minnow
#

np

granite crystal
#

.close

cedar kilnBOT
#
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floral badger
cedar kilnBOT
floral badger
#

Greetings, how do I prove what's written in the picture?

#

Do I use the determinant formula or is there another way?

dusty hazel
#

You'd have to evaluate the determinant eventually.

#

Though you can make the determinant easier.

#

By performing a few row operations and such.

floral badger
#

How?

dusty hazel
#

But ultimately, it's the determinant.

dusty hazel
crimson sedge
#

yea u can erase a bunch of those 1's

floral badger
#

Ah fair enough

crimson sedge
#

then u can do leibniz expansion

floral badger
#

Still don't know leibniz unfortunately

#

But I'll try the row operations and then use the determinant

#

Thanks a lot for the advice though!

crimson sedge
#

oh sorry i meant laplace expansion

floral badger
#

I don't know that either kekwcry

#

I'll look it up though

crimson sedge
#

its like

#

co factor expansion

floral badger
#

Fair enough

#

I'll check it out

#

Thanks again

#

.close

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#
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torn talon
#

Hello i need a help in french please

cedar kilnBOT
torn talon
#

Ahahaha t’es à l’affût

dawn junco
#

é oui

#

alors c'était bien les vidéos?

torn talon
dawn junco
#

si t'as check

torn talon
#

Vrm un maître nageur 😂

#

Oui franchement c’était bien

dawn junco
#

le gars de la rochelle, maître maître nageur

torn talon
#

Juste vers la fin je comprenais plus rien il allait trop vite

#

😂😂

dawn junco
#

oui c'est pas mal dense

torn talon
#

En gros tu vois ce que j’ai envoyé

#

J’ai fait la question 1

#

J’ai dit qu’il n’était pas vide

#

Qu’il était stable par addition et multiplication

#

Du Coup jen ai conclut que c’est un sev

#

Voilà je te montre tous ça

#

Mais à la question 2 je bloque je vois pas comment m’y prendre je voulais exprimer des trucs selon t mais vu que c’est pas égal à 0 bah j’arrive pas

dawn junco
#

d'où tu le sors x=y=t=0 ?

#

c'était un truc qu'ils ont oublié de marquer ?

torn talon
#

Non..

#

Jsp c’est faux ? 😭

dawn junco
#

on te dit rien sur x, y, z, t, à part que c'est des nombres

torn talon
#

Jetait censé montrer comment alors

#

J’ai trop la haine 🥲

dawn junco
#

en vrai ta preuve est plutot ok

#

t'enlèves les x=y=z=t=0, que t'as mis un peu partout et c'est bon plus ou moins

torn talon
#

Mais tu vois quand j’ai dit que tout est égal à 0 si je dit ça c’est faux ?

dawn junco
#

bha oui

torn talon
#

Ah ok

dawn junco
#

il y a rien qui dit que x=y=z=t=0 dans G

torn talon
#

Commet on saura que c’est vide alors

dawn junco
#

pas vide tu veux dire

#

oui 0 est dedans

torn talon
#

Oui voilà

dawn junco
#

pour montrer que le vecteur 0 est dedans, oui tu mentionnes que pour x=y=z=t=0 t'obtiens bien le vecteur 0

#

pour le reste non

torn talon
#

C’est ce que j’avais fait non ?

#

J’ai mentionner

dawn junco
#

pour stable par addition ça a rien à voir

#

c'est ça que j'essaie de dire

torn talon
#

Hmm ok donne moi la démarche alors stp

#

Pour montrer que c’est un sev

dawn junco
#

t'as montré que 0 était dedans ok

#

la seule condition qui importe pour qu'un vecteur soit dans G c'est qu'il soit de la forme (x+z, x+t, y+t, y+z)

#

c'est tout

torn talon
#

Ah mais c’était plus simple alors

#

Je me suis casser la tête à faire des op bizarre la orgh

#

Si pas possible

dawn junco
#

et pour la multiplication par un scalaire c'est pareil

#

tu t'arrêtes avant d'introduire des op bizarre

#

et t'as déjà montré que si f est dans G, alors lambda*f est dans G

#

gagné

torn talon
#

Je le fait et tu le corrige encore ?

dawn junco
#

oui

torn talon
#

C’est mieux ?

dawn junco
#

mieux mais j'ai du mal à comprendre la fin encore

#

pour l'addition on voit mieux où tu veux en venir, parce que tu regroupes les x, y, z, t des deux vecteurs ensemble

torn talon
#

Pourquoi

dawn junco
#

donc on imagine bien que le "x" de f+g c'est x1+x2

#

que le "y" de f+g c'est y1+y2

#

etc...

torn talon
#

Oui

#

J’aurai du utiliser la mm méthode pour la multiplication c’est ça ?

dawn junco
#

ça pourrait être mieux affiché mais on voit bien l'idée déjà

torn talon
#

Je remplace les x y z et t par x1

#

Ça marche ou pas

dawn junco
#

si tu veux faire ça clean

torn talon
#

Fin par x1 y1 z1 et t1

dawn junco
#

tu peux définir de nouvelles variables X = x1+x2, Y=y1+y2, Z=z1+z2, T=t1+t2

#

et dans ce cas-là f+g = (X+Z, X+T, Y+Z, Y+T)

#

là c'est vraiment apparent que f+g a la forme souhaités

torn talon
#

Ah mais la somme non plus c’était pas bon du coup ?

dawn junco
#

c'était compréhensible

#

mais pas impeccable

dawn junco
torn talon
#

Attend je vais d’abord faire l’addition à la perfection àlors avant de faire la multiplication

dawn junco
#

et tu peux faire un truc similaire pour la multiplication

torn talon
#

Vas-y je comprend plus rien

#

La f et g ça correspond à quoi mtn

dawn junco
#

ça change pas, c'est toujours des vecteurs de G

torn talon
#

Mais quel vecteur

#

On a déjà défini des variable

#

T’aurai mis quoi pour f ?

dawn junco
#

le début est très bien, introduire f et g, puis regarder f+g il y a aucun souci

torn talon
#

Ah c’est après genre on dit

dawn junco
#

ma suggestion c'est juste de rendre la conclusion plus lisible, plus percutante

torn talon
#

Qu’on pose les variables

#

A la fin

#

Ok attend je crois j’ai capter

dawn junco
#

oui voilà

torn talon
#

Enfinn

dawn junco
#

là on voit très explicitement que f+g est dans G

torn talon
#

Mtn on attaque la multiplication

dawn junco
#

pour des preuves de routine comme ça (montrer que tralala est un s.e.v.), faut vraiment être carré

#

donc si tu peux simplifier la vie de la personne qui lit ton truc, et qu'elle ait pas de détails de preuve à remplir elle-même, c'est tout à ton avantage

torn talon
#

Okay merci chef

#

Là le prof s’il voit pas ce que je veux faire je lui crève les yeux

dawn junco
#

si tu veux vraiment rester dans l'esprit de la preuve pour l'addition

#

faudrait plutôt poser X = lambda*x1, Y = lambda*y1, ...

#

comme ça t'as littéralement lambda*f = (X+Z, X+T, ...)

torn talon
dawn junco
#

et là boom

#

maintenant tout crève les yeux

torn talon
#

Hahaha je crève déjà des yeux sans les maths tkt

#

Bon la question 1 c’est bon alors ?

dawn junco
#

yep

torn talon
#

La question 2 du coup explique moi comment faire pcq vu que c’est pas égal à 0 à chaque fois j’arrive pas à exprimer des choses en fonctions de qlq chose mmdrr

dawn junco
#

bha l'idée c'est qu'il faut que tu trouves un ensemble de vecteurs {v1, ..., vk} qui génère G, et qui soit libre/linéairement indépendant

#

c'est ça les deux conditions pour être une base d'un e.v.

#

que tu puisses générer G, ça veut dire que n'importe quel vecteur g de G peut être écrit comme une combinaison linéaire g = a1*v1 + a2*v2 +... + ak*vk de v1, ..., vk

#

et être libre/linéairement indépendant ça veut dire qu'il y a une unique manière d'écrire g comme combinaison linéaire de v1, ..., vk

#

ça c'est le résumé en 2 minutes, pour avoir une idée rapide

#

mais je te conseille de check les vidéos du gars de la rochelle sur le sujet

#

il y aura plus d'exemples et ça sera mieux expliqué

#

@torn talon

cedar kilnBOT
#

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torn talon
#

Dsl ma tablette a buger

cedar kilnBOT
torn talon
#

.close

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dawn junco
#

.reopen

cedar kilnBOT
#

dawn junco
#

re @torn talon si jamais t'as d'autres questions

#

sinon je peux juste reclose

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jagged wave
#

Is the same AxA^-1 and (A^-1)xA being A a matrix of order n???

jagged wave
#

I know that a matrix might not be conmutable, but does it still happens even when one matrix is the inverse of the other one?

digital cliff
#

its the same here yeah, they both give I_n

dusty hazel
#

Inverse of a Matrix commutes that Matrix.

#

Because yeah, it gives identity Matrix of that order as the product.

jagged wave
#

okay thank you so much

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lapis laurel
#

a crab wants to build a house with an area of 490m^2. The house has to have a distance of 5 meters from to edges of the property except from the front of the house where the distance is 9 meters. What is the smallest area property the crab can build his house on

muted timber
#

!show

cedar kilnBOT
#

Show your work, and if possible, explain where you are stuck.

lapis laurel
#

ok well ive come to the conclusion because the house is built in the shape of a rectangle it will have the most area when its square

#

im stuck because im unable to form equations from the given information

muted timber
#

did you try to draw it?

lapis laurel
#

something like thos

muted timber
#

good

#

now, the area of your house is xy=490 (im gonna ommit the units, assume everything in m or m^2 as appropriate)

#

so y=490/x

lapis laurel
#

yes

muted timber
#

but you dont care about the area of the house, you care about the area of the property

lapis laurel
#

yes thats also true

muted timber
#

the area of the property is (x+10) (y+14)

#

Replace y for the value we got before. Simplify as much as possible. Gimme the equation with only x.

lapis laurel
#

well thats not the final

muted timber
#

keep going

lapis laurel
muted timber
#

okay so that's the area of your property, according to whatever x you choose

#

now they ask for the minimum area

lapis laurel
#

now i assume i am supposed to differentiate it

muted timber
#

you know that the minimum area is obtained at the point where the derivative is 0

#

so derive that, and solve for A'(x) = 0

#

and you should get a crappy number with radicand

lapis laurel
#

what is a radicand?

astral arrow
#

help ]

#

help

#

grade 10 quetsion

#

help me please

lapis laurel
#

i got something like this for the x

#

so the width of the house is approximately 6 meters

cedar kilnBOT
#

@lapis laurel Has your question been resolved?

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gray oyster
#

Can someone help me explain how do we find the correct answer? I’m not sure about this one

gray oyster
#

I just guessed cuz there were only few seconds

dull oxide
#

Consider $\lim_{x\rightarrow a} g(x)=0$

wraith daggerBOT
gray oyster
#

Hm?

dull oxide
gray oyster
dull oxide
gray oyster
#

Uhhhhhh

#

We divide by 0 there?

#

I don’t get it

jaunty mural
#

Let g(x) = 0

#

observe this is a continuous function.

dull oxide
#

could be discontinuous

gray oyster
#

Yeah ik, we have to choose the ones that could be discontinuing

#

But how we find which one by dividing by 0?

dull oxide
gray oyster
#

After?

jaunty mural
#

The question is phrased very specifically

gray oyster
#

Oh

#

So if the answer was 0, is it discontinued?

#

Sorry if I didn’t understand yet

#

Like we have in the question:
1+0=1
1-0=1
1/0= undefined
1*0=0

#

I replaced the f(x) by 1 and g(x) by 0

#

So what’s next?

#

What is the answer to the question, and how to explain?

native egret
#

Mommy

gray oyster
dire geode
#

1/0 is undefined

#

Oh I guess that's enough

gray oyster
#

I’m asking to just keep in mind @dire geode

cedar kilnBOT
#

@gray oyster Has your question been resolved?

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gray oyster
#

.reopen

cedar kilnBOT
#

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grizzled jetty
#

Hey

cedar kilnBOT
grizzled jetty
#

I need help with this summation

dapper cairn
#

did u try?

grizzled jetty
#

I did

dapper cairn
#

show me

grizzled jetty
#

I simplified it but I forgot how to do summations 💀

#

Should I make groups of 2?

dapper cairn
#

use this

#

did u study this?

grizzled jetty
#

So this ?

#

We did

dapper cairn
#

thats trye

#

true

#

u did it right

grizzled jetty
#

No

#

Wait last value of n

#

Is 20

dapper cairn
#

why i wrote i^20

grizzled jetty
#

Not i^20

#

Sorry

dapper cairn
#

write 20

grizzled jetty
#

Yes

#

I saw it

dapper cairn
#

u know why right?

grizzled jetty
#

Yes thank you and now I’ll use the formulas that we learned in grade 9

grizzled jetty
#

Nope?

dapper cairn
#

no problem

grizzled jetty
#

Oh wait

#

It’s actually simple

#

We form groups of 4

#

That will evaluate to 0

#

So it’s 0

#

Isn’t it?

cedar kilnBOT
#

@grizzled jetty Has your question been resolved?

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mild narwhal
cedar kilnBOT
mild narwhal
#

i dont understand how this equals to 3

#

i worked it out to be 0

#

or rather 4h

digital cliff
#

4+4h+h^2-2-h-2=3h+h^2

#

divide by h you have 3+h

#

h tends to 0

#

just leaves 3

mild narwhal
#

i missed one h

digital cliff
#

ah i see

mild narwhal
#

thanks

#

.close

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stoic garnet
#

so I know B and C are the answers but I dont know how to find them with the known angles

brisk apex
#

try and find "g" first

#

you can do this by noticing that there is a "180" degree angle that already has the values "61" and "54"

#

using this you can finding the missing angle, you can then use the corresponding angle theorem to find "g"

#

sorry if I'm a bit unclear

#

not rly the best at explaining

cedar kilnBOT
#

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stoic garnet
#

alright thank you!!

cedar kilnBOT
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tight cove
#

Why is it that when rationalizing a denominator with one square root only one of them is affected by multiplication but when it’s more than just a square root it affects all the numbers

dull oxide
#

wdym

tight cove
#

So in the image on the right

#

When rationalizing the denominator say multiplying it by 4 root 2, the 3 and the root 3 are not affected, only the two is

#

But on the image on the left everything is affected

#

Why

rustic siren
#

wdym affected

tight cove
#

It doesn’t get multiplied by root 2

rustic siren
#

u multiply both the denom and the nom in both case, so everything is affected by it

#

it is affected in the first case too, thats where u get the 2 in the denom

tight cove
#

But the 3 and root 3 don’t get changed

rustic siren
#

ofc

#

(3 * 5 * 7 * 9) * 2 is not (6 * 10 * 14 * 18) only one "part" gets doubled

#

in our case its the 2^(3/4) part that gets multiplied

#

were you referring to this?

tight cove
#

Yeah

#

So why does it all get multiplied in the left image

rustic siren
#

can you circle it?

tight cove
rustic siren
#

its + not * there

#

and (a+b) * c is indeed ac+bc

#

(distributivity)

tight cove
#

I’m in a pre Calculus class and I’m being killed by basic arithmetic

#

damn

rustic siren
#

the previous thing was the (associativity)

tight cove
#

Thanks

rustic siren
#

you will learn these properties name in algebra, if you have not seen them already

tight cove
#

I have

#

I’m just dumb

#

.close

cedar kilnBOT
#
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elfin bluff
#

can someone please help me figure this out...

elfin bluff
#

I do not even know where to begin

#

I'm supposed to solve it using excel

#

If you can help me figure out the first one, I can do the rest myself

cedar kilnBOT
#

@elfin bluff Has your question been resolved?

crimson sedge
#

so each confidence interval should be centered around 0.44

#

do you understand that?

elfin bluff
#

yea I guess

crimson sedge
#

wdym I guess

#

say someone asks you to give me a guess about how many ounces of water you drink per day

#

the inital guestimate would be the point estimate

elfin bluff
#

Ohhh so 0.44 is the middle right?

crimson sedge
#

now if I said

#

give me a (balanced) interval estimate

#

that you are 99% confident

#

would capture the true amount of water you drink per day

crimson sedge
#

forget the problem for a second

#

@elfin bluff

elfin bluff
crimson sedge
#

ok

#

so now we get to more formally defining what a confidecen interval is

#

confidence interval $=$ point estimate $\pm$ possible error

wraith daggerBOT
#

! matthewzz

crimson sedge
#

the higher % the confidence interval is

#

the greater the "possible error is"

#

since you are going to be 99% CONFIDENT that the true parameter is in the interval

#

if we specifically assume that the parameter is normally distributed and we know the standard deviation we can define it even more formally

#

confidence interval $=$ point estimate $\pm$ standard deviation * z score corrosponding to your X% confidence interval

wraith daggerBOT
#

! matthewzz

crimson sedge
#

in variable terms:
$X% CI = \mu \pm \sigma * z_{(100-X)}$

wraith daggerBOT
#

! matthewzz

crimson sedge
elfin bluff
crimson sedge
#

the higher % the confidence interval is
the greater the "possible error" is, which means your confidence interval will be larger

intuitively it makes sense,
since you are going to be 99% CONFIDENT that the true parameter is in the interval, the intervala better be pretty wide, to make sure youll capture the true value

elfin bluff
#

I notice now....I didn't understand the concept at first that's why I was confused

#

thanks bro!

crimson sedge
cedar kilnBOT
#

@elfin bluff Has your question been resolved?

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feral basalt
#

Help please?

cedar kilnBOT
feral basalt
#

Idk how to do problem 2

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#

@feral basalt Has your question been resolved?

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proven condor
#

how do i solve this problem?

cedar kilnBOT
#

@proven condor Has your question been resolved?

proven condor
#

<@&286206848099549185>

pastel vault
#

after that the line has direction vector (2, -2, 1) as x = 2t + 1 etc.

#

so you just need to find the angle between those vectors and subtract 90 degrees

cedar kilnBOT
#

@proven condor Has your question been resolved?