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hold on lemem see
Okay this is interesting lmao
uhh do you have an answer key?
1a might be (-inf, inf)
the second part is def more interesting
okay i believe i have to get my hands a little dirty here
is it (0,1) 😭
im probably doing something wrong here sigh
yes the domain for 1a is (-inf to inf)
but apparently i have to be able to prove it :zcc
[0,1), 0 is also common in all intervals
squints his eyes
are we sure about that
im not sigh
@azure citrus what's the answer sigh
The upperbound is a non-zero natural and the lower bound is its negative reciprocal, of course 0 is in there.
yeah is zero included though?
but the lower bound is interesting when r is small
If you're not convinced you can prove it using an intermediate value theorem argument. x is a continuous function and -1/r and r are far enough away from zero that you can construct an compact interval.
you could just try it graphically
like draw a few intervals and extrapolate
hmm
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A particle is projected on a straight line from the point O with an initial velocity of
25m/s. Its acceleration after t(s) is given as (6t2 – 4t) m/s. Find the velocity and distance
from O after 3s.
not sure about " v=∫a dt " but the rest is correct
Isn’t the antiderivative of acceleration velocity?
Second part I got 97.5
Good?
ok yeah that's correct i just checked
What about the distance bit?
can you show how you got it?
i don't know how to help you sorry
didn't study most of these yet
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I used Kuratowskis theorem to prove it’s non planar by finding k3,3 as a subgraph but I’m not sure how I would prove part c
can’t help u but can i ask a few questions
yes sure
graph theory and it’s A level further maths which is just before university in the uk
ah oki interesting
@ashen field Has your question been resolved?
I can see that if we choose any 3 adjacent vertices we won’t be able to choose another one that’s connected to all 3 but I’m not sure how to put it down in a way that’ll lead to a proof
because i’m thinking if the subgraph is isomorphic to K4 it’ll need to have 4 nodes that are all connected
but we can only choose a maximum of 3 nodes that are all connected
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We want to build a channel that has an isosceles trapezoid as a section in such a way as to widen it the upper part of the channel is twice the lower width and that the non-parallel sides are 8 meters.
Below is a diagram of the channel section.
Find the value of the L segment of the graph as a function of the variable x.
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I don’t get how this is competing the square ?
I’m struggling to see how
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do you agree with the last (typeset) line?
ah ok
so you just need to make a few observations:
f and g are positive
so f(x) > 0and g(x) > 0
f and g are increasing
so what does that tell you about f'(x) and g'(x)
no..
increasing doesn't imply concave
what can you say about the first derivative of an increasing function?
numerically what you can you say
if a function is increasing, can its derivative be negative?
ok
so f'(x) and g'(x) are both >= 0
finally, you also have that f and g are concave upward
which tells you something about f''(x) and g''(x)
(assuming they have second derivatives)
right
so what can you conclude about your last expression (the typeset expression)
@crimson sedge Has your question been resolved?
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for (x+a)(x+b), where a and b are any number,
is it possible that one of the roots could possibly not be a solution?
solution to what
so (x+a)(x+b)=0?
yes
is it possible if i found the roots
a and b, one of them could not be a solution
or would they always be a solution
if you were able to factorise into that form, then x=-a and x=-b must be solutions
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For linear algebra, if a vector space is 1 dimensional, does that mean that it only consist of one vector?
no, it's span(one non 0 vector)
for example, R is a R vector space of dim 1
which can be written as span{1}
a vector space that consists of only one vector is {null vector} by def of vector space
and would be of dim 0
intuitively, a vector is a point, and a 1 dimensional space can be visualised as a line
a 2 dimension as a plane
etc
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My brother is doing a problem that requires him to solve an equation for x by distributing the wrong way. Any idea how you would get x=-19/20 from
"-24 - (4x - 6) = -2(-8x-11)"
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How can I use the limit comparison test with this?
some intuition here is that sin(1/n) and 1/n are very close in value when n is large
so that should suggest something to use for comparison
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✅
yes the series diverges
why? it seems to go to 0...
it's very similar to $\sum_{n=1}^\infty \frac{1}{n}$
layla
what does?
hm. must just be getting my limits and such mixed up. series are hard....
true
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2x + x
3 4
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need some help with these 2
Do you know the definition of a function
kinda
what do you understand the meaning to be?
for a function or the problem
the defintion of function - whats the general meaning?
an expression that has 1 or more variables?
apply that to what is given to you
So basically one x can only have one y value corresponding to it
well all i got is that 2,3, and 4 are x and y is 5
yeah
yep
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welcome
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Is this correct?
,rccw
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It is the congruency symbol
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how do I solve this integral?
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need some help with this one:
since its h of f with 1 i believe I just put 1 into the other functions and multiply them but since the "of" symbol is there I am not sure what to do
this is function composition
you don't multiply function composition
$(h \circ f)(1)$ means $h(f(1))$
Ann
it does not mean $h(1) \cdot f(1)$
Ann
gotcha
i think
so it would be that i plug in the 1 for f
and then i put that equation i get out of it into h
right?
misuse of the word "equation", also you'd get a number
yes f(1) = -3
missing parentheses for the square root again, but i guess yes?
or maybe
you're expected to not yet know about complex numbers and so this should just be "undefined"
so in total
i get 1
and put it in the equation of f where x is
then get the answer from that equation which is a singular number (-3)
then put -3 into h where x is
then get answer
this wording is extremely clunky, but yes.
gotcha
so how would undefined as answer go like
as in how do i show my work to get undefined if there is already an answer
which was sqrt 8
Yes.
thanks
also
i got a couple more things that are very similar
if thats ok with you daniel
or ann
No problem, ¿how can I help you?
and thats it
and im done with EVERTHING
and 24-26 is using the pics from above
this one
Give me a second, I'll turn on the laptop, I'm on my cell phone and I have a good brain but terrible eyesight.
gotcha
These are pretty easy. What do you need help with? Find domain, range or what?
in 24 to 26 i need to state the domain and interval notation
and for 27 i need to write 2 functions f and g that h(x)=(f of g)(x)
all in the pics above
This is the answer of 23. At x=3 the function would be undefined because it would be in 1/0 form. Otherwise at any value of x it's defined.
The domain is R - {3}
You could write it as (-∞, 3) U (3, ∞)
wasn't expecting a full answer, but thank you. But if you could walk me through the rest at least so I know how to do it exactly that would be amazing
- (g/f) (x)
g(x) = 1/(x-3)
f(x) = (x-4)
g/f = (1/(x-3))/(x-4))
g/f = 1/ (x-4) (x-3)
Here at x = 4, 3 the function would be undefined. So the domain is R - {3, 4}
This is sufficient
In this g(h(x) there lies an discontinuity at x = 14. Remove that
Pete the 3rd one is incorrect
ok
wait is this one 26 or 27?
3
......
oh
wait so this one is 26
and this is 27
24, 25, 26
27
but didnt the other guy say that the third one was incorrect in that picture?
The correction of the 26 answer.
It's after dawn in my country, I guess sleep is playing tricks on me. Sorry for the mistake.
thank you anyway
very much
for your amazing math skills
its 11:33 here
pm
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how could i do the problem on the left
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what subspace is Nul A a part of? R^4?
you did not actually need to do any of these calculations!!!
you were not asked for the nullspace itself but rather what R^p it lives in
and it should be plain as day that Nul(A) ⊆ R^4 without even doing any calculations, bc A is a 3 by 4 matrix.
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A quadratic equation is any equation of the form: y=ax2+bx+c
, where a
, b
, and c
are integers. The solutions to a quadratic equation are values that when substituted into the quadratic equation, yield a true statement.
One method for solving a quadratic equation is by factoring the equation and setting each of the factors equal to 0. Not all quadratic equations can be solved by factoring, and in such cases, it is necessary to use the quadratic formula to find the factors.
To simplify the quadratic equation given, two factors that multiply to 15 and add to 8 are necessary. The only valid pair of factors is 3 and 5. The equation can then be rewritten as:
(x+3)(x+5)=0
Recall that if ab=0
, then either a=0
, or b=0
. So, the values of x
can be found by setting each parenthesis equal to 0
and solving for x
:
(x+3)=0
or
(x+5)=0
x=−3
or
x=−5
explain this
x2+8x+15=0
!help
To ask for mathematics help on this server, please open your own help channel or help thread. See #❓how-to-get-help for instructions.
What do you not understand?
hi
theres the answer and solution but i cant understand it
the questions is x2+8x+15=0
and the options are
idk how to get the answer
Do you know how to factorise the equation?
Sth like this
completing the square if you're good at it
i see no i dont
What abt this?
Familiar?
@feral citrus
ye i smeone what get it
so like the
4 x 2 is 8
and
3 x 1 is 3
then u cross multiply
No
U talking abt this?
oh ok
ye
You have to find multiples of the c term
icic
U break down the A and C term
Then it's all trial and error when cross multiplying
to match the b right
Yes
In the end, it must satisfy A B C terms
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Help please
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can anyone understand what was done from step 2 to 3?
are you referring to
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!status
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
If x < 10, what can you say about x - 10
@crimson sedge Has your question been resolved?
Sorry i was busy
Yeah i figured it out
x - 10 = -b
x = 10 - b
b - x = b - 10 + b = 2b - 10
It's correct right?
no
???
Why not
sry let me double-check, I mis-read
We found x then subtracted from b
this line is not correct
that line is still not correct
if you had, it would be correct.
It isnt, so you havent
you should very easily realize that this is not correct, since it's not one of the valid options and the actual answer is one of them
So to find b - x it the same as
b - (10 - b)
It's looking for b - x💀
Not x
i am aware
I think your edit above is correct
b - 10 + b
2b - 10
Are yall high
It's fucking correct
don't be rude, what you had first written before the edit was not correct
C is the correct option
in MCQs will it be better to put some values and see the relations? it will save some time in exam?
Yeah it was a typo mesnt to write = instead of >
if x < 10, then x - 10 < 0, so |x - 10| = 10 - x = b. Rewrite as -x = b - 10 --> b - x = 2b - 10
Yeah exactly
Are you blind because it clearly is
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is the least squares regression line of Y on X the same as the least squares regression line of X on Y?
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hundreds of people get help everyday
Yup. Wish I found one of those hundred people like I found yesterday.
you got help. you just didn't want to do the work
That's not help. Humble yourself dude.
plotting is a good start that you were too proud to do
or lazy idk
There's an easy approach there than plotting that too itn variable since it wouldn't help at all
good luck with that helping.
i help plenty of people who want to do work
yup tell them to put values n=1
Did someone ping me here?
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How many ways can you order n identical balls in a circle with n + m places?
My original answer was: (n + m)!/n!m!(n+m)
The number of arrangements of n + m distinct objects in a circle will be (n + m)! / n+m
And there are n identical balls and m identical empty spots.
So... I divide by n! and m!
thus
(n + m)! / n! m! (n + m)
But,
this is only true when n and m are coprime
Yeah, but why?
the dividing factor of n+m assumes that each rotation is unique
for example, if you have 7 spots,
X O X O O X O will cycle through all 7 spots and create a unique arrangement
in this case, you have 4 balls
the number of ways to arrange them is (7C4)
if you have 6 spots and 4 balls, you will hit the same arrangement after half a cycle for some arrangements
like O X O O X O

Wait I thought of something...
nvm
What if I...
So there are n identical balls and m identical empty spots.
put 1 ball in between the empty spots
(m - 1)C1
put 2 ball in between the empty spots
(m - 1)C2 + (m - 1)C1
put 3 ball in between the empty spots
(m - 1)C3 + (m - 1)C2 + (m - 1)C1
...
put n ball in between the empty spots
(m - 1)Cn + (m - 1)C(n-1) + (m - 1)C(n-2) ... + (m - 1)C1
But... only works when m - 1 >= n
...
and idk how to write sums
ima just sleep
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i can just do it the other way around if n - 1 >= m
but for n = m idk
i go sleep
brrrr
and i think i wrong
i
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How to find LCM(24823,26854,21452)
My approach was trying to find LCM(24823,26854) then find the LCM of the number i got with 21452 but my calculator said math error so i got into a dead end xD
Umm... they are big numbers...
Please help in the question 3 and
huh?
i dont know but my teacher said it doable by calculator so i gotta figure out how now 
I tried to do prime factorisation but the sol i got is too big
24823 is 103x241
26854 is 2x29x463
21452 is 2^2x3x173
so LCM should be 2^2x3x29x103x173x241x463 but the answer is too big
it's too small actually
that 3 should be 31
i'm not sure how i would do it with a calculator 🤔
oh ye it 31, i forgot to add a 1, still numbers too big for the display 😔
how did you even do prime factorization
there a button on calc for that
I just realized the sol itself is too big for the calculator to display .,.
welp ty , ima ask my teacher about this tmr
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The equation or the graph
The equation you wrote is right, but usually when writing graphing equations, y is on the left side.
Y = 25(x) + 100
Your x axis is your independent and your y is your dependent. When solving a problem like this, think about “what variable cannot change no matter what?”
That’s your X axis
25 pounds per week
You can’t change time, days , or weeks but you can change money, pounds etc
Weeks
Your y axis units are good, and so is your x axis
I personally would’ve spaced them differently since you have so much space but I don’t think the teacher would take odd points just for that
Ok
Do u need help with a?
Yes
The y intercept is when x is zero. So during week zero,how many pounds of aluminum cans does he have
100
Your slope in any graph represents the change over your independent variable.
So what happens as time passes, in your case, as weeks passes
So the slope represents his plans to collect additional 24 pounds per week
Perfect.
25
Yes
Ok so let’s re write the equation as
Y = 25 x + 100
Ok
What does y represent on the graph and in the equation
Yup. So we need to find when y equals 800.
On your paper you put 400 in for x. X is your time. So you calculated how many cans he would get in 400 weeks lol
Oh
Since your graph is small, you could draw your graph and when y equals 800, what your x coordinate is is the answer, but as you go on in school they want you to find x in the equation
Oh no
Yup
Ok thank you
Np
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the first part is obviously fine but idk abt the last bit
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I think the equation is wrong but I want to check with you all.
If I plug in the given values into the equation:
Rate = 1
N = 36
It doesn't give the values that I'm supposed to get.
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why do you keep opening help channels
<@&268886789983436800>
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can someone help me understand this rq
i know that if a point has a veritcal tangent line then it isnt differentiable but how come the answer is telling me that x=2 is differentiable?
how is f(x) differentiable at x=2 if there is a vertical tangent line at x=2
The tangent at x=2 is horizontal, not vertical
it says it has a vertical and horizontal tangent at x=2
Oh what, I didn't notice the sentence at the bottom.
The wording is awkward
It does have a vertical tangent somewhere
And it does have a horizontal tangent at x=2
do you think the answer is a mistake
No, look at the graph
It didnt mean it has both a horizontal and vertical tangent at x=2
The way they phrased the sentence was just weird
There are vertical tangents, but not at 2
so they forgot to put something after the vertical tangent part
I guess
Or they're just saying
There are vertical tangents, period.
And also
A horizontal tangent at x=2
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They did forget to put something after the vertical tangent part actually. It says "there's a vertical tangent at" and then nothing
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Help with proving every convergent sequence is a cauchy sequence
Give me a hint?
Do two epsilons
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as in e1, e2?
Yes
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i’m not sure if i did this right im getting a different answer when I put into a derivative calculator
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@long veldt Has your question been resolved?
could u take a better picture
yes
@long veldt what are u gettin on derivative calculator?
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😭 why is this wrong
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a, b, c, d ∈ {0,1,2,3,4,5,6,7,8,9}
a! +b! +c!=d!What is the sum of a+b+c+d?
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perimeter of a polygon = 158cm. The measures of their sides creates an arithmetic progression with common difference d = 3cm. Knowing the largest side = 44cm. How many sides of the polygon are there?
so I tried to analyse the problem and got
P of the Polygon = Sn of the AP
d = 3cm
the
44 = a1 + (n-1).3
Idk what to do next
Yea
Mb
Solve those two equations and get the value of n
We get 44=a+3n-3, so a= 3-3n+44, so u substitute this in sn formula
316=2(44+3-3n)n +3n^2-3n
@slender geyser
@slender geyser Has your question been resolved?
Ohhh ty
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im trying to understand the standard deviation equation
so if the top part is to get the sum of values of the difference between values from the mean, and it has to be squared so that the negative wont cancel out with the positive
then why isnt n squared as well
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Hello sorry if this is a dumb question, but how can you simplify this
the solution in my book says this is the solution but i have no idea how to do that
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@clever cedar Has your question been resolved?
@clever cedar Has your question been resolved?
@clever cedar that solution doesn't look correct
yea im also starting to think its a mistake, it wouldnt be the first time the book was wrong
what level of math is this?
what are the x boundaries in the sol.
2nd year of high school
@clever cedar Yea im stumped, maybe someone else (smarter) can help, sorry!
oh yea, didn't know of that propety tbh, makes question very simple
yea me neither, i just learned that the formula exista
ah also lol you can do it like this $\sqrt{x+y+2*\sqrt{x-y}*\sqrt{x+y}+x-y$ which gives $\sqrt{(\sqrt{x+y}+\sqrt{x-y})^{2}}$
lolk
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write .close
Also tho if u wanna know how to do this w/o knowing the formula
Say $u = \sqrt{expression}$
992qqoloy
Then $u^2 = expression$
992qqoloy
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What is math?
what kind of answer do you want
Simple definition
good luck with that
let math = x
so math is x
Real ( Idk math ) 
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How do I solve these type of questions?
translation: Find a linear ODE with solutions ...
How can I get to the possibility for 1,2 and 3 right answers?thx for any help!
A test consists of four questions. There are three possible answers for each question. Exactly one answer is correct. A candidate who has not learned anything randomly checks one answer. The random variable A indicates the number of correctly checked answers. a) What values can the random variable A take? b) Calculate the values of the probability distribution and represent them using a dot diagram
calculate the first couple of derivatives, see if you notice something
there isnt a general process (I think), the point here is to notice something
derivative of what?
of the four functions
alr I try
well actually for functions of the form e^(lambda x) there is a general process. think about when you use those functions to solve an ODE
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<@&286206848099549185>
translation:
roughly sketch the graph of y
i dont get it
what are they saying here
like
how do they know x^3 is where it is
and why is it there and all
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@glacial crane Has your question been resolved?
It's just an estimate of the parent function, which is $y=x^3$
Kai Funaba
U can draw it anywhere on the 1st & 3rd quadrant ngl, but don't make it too absurd ofc
In a nut shell, it doesn't hv to be specific
⬇️ (if u want to feel better)
||Since it's on a book it can't explain itself, and writing what I wrote above in the book wld just be deemed 'redundant' ||
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Omg 😂😳😂
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Hey so I need a mathmatical formula where the higher 'X' is the lower the constant value is
For example
Lets say the constant is 25, if X = 5 then 25 can equal 20 (doesnt have to be exactly that just so long as its smaller than the constant)
and if X is 25 then 25 can equal 10
Something like that
I tried doing something like |25 * (15*(-.025))|
that doesnt really work though
is it like y=k/x something like that?
Something like that but it cant be lower than 1 so I assume id just make k a larger number?
So for example if I did y = 550/1
1 being X and Y being the constant of 25
550/25 would be 22 which is fine but 550/1 obv is 550 which is too high of a starting number
So my starting number would be 25
That probably doesnt make sense so heres a table
I dont care about the numbers between 25 and 10 they can be whatever so long as they decrease
I need a formula where if I put in 1 for X I get 25 and if I put in 50 for X I get 10
actually nevermind I think this would work
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when i factored by grouping
i have 4x^2(2x+1)-1(2x+1)
what do i do from there now
how would you factor pq+rq?
wdym
ayo youre not sposed to tell the answers straight away
let the one who asked work for it, mate
that isnt the answer tho
soory
allg

its (2x-1)(2x+1)^2
yup
yea but idk how to get there
okay so did you get till (2x-1)(4x^2-1)?
i got 4x^2(2x+1)-1(2x+1)
alright so lets say you have an expression
px+qx, how would you factorise it?
x^2(p+q)?
its not factorable
it is
or u cud say the reverse that
ab+ac can be redistributed to a(b+c)
if you were to apply this to what i asked
yes good
so now in your expression
4x^2(2x+1)-1(2x+1)
yes
can you reapply the same thing
if tp+tr= t(p+r)
then can you identify what works as 't', 'p' and 'r' in
4x^2(2x-1) -1(2x-1)
yes exactly
and then u can break 4x^2-1
to 2x+1 and 2x-1
and there you have your answer
ye :>
np
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maximum possible value of xy where
(12x + 1)(12y + 1)=24193
@lunar radish Has your question been resolved?
<@&286206848099549185>
no
the original equation was x^2 + y^2 + 12xy = 2016
after dividing by 12 i used simon's bla bla bla
(x+1/12)(y+ 1/12)=168 + 1/444
multiplied both sides by 144
(12x+1)(12y+1)=24193
and here we are
oh so i did it wrong?
x^2 + y^2 + 12xy = 2016
x^2 - 2xy + y^2 + 14xy = 2016
(x - y)^2 + 14xy = 2016
from here
xy = (2016 - (x - y)^2) / 14
= 144 - (x-y)^2/14
now notice that it's enough to minimize (x-y)^2 because (x-y)^2 >= 0
how did you get this
2016/14 = 144
so why's the other denominator 12
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Hello!
I’m looking for someone to look over the work I have so far and make sure it’s correct, then help me solve the remaining three parts of the problem.
Here are the photos;
@ripe coyote Has your question been resolved?
In the previous question, part b, what variables were required to find the distance between the house and the tower?
So far the workings out have been very clear and easy to revise from!
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Did I get these right?
@crimson sedge Has your question been resolved?
And why does 2 work
<@&286206848099549185>
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<@&286206848099549185>
<@&286206848099549185>
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A triangle has sides of length cos(20 degrees), cos(30 degrees), cos(40 degrees). What is the degree measure of its largest angle?
why is it not 50
how are you getting 50
i used law of cosine
show work
,rotate
cos(20°) is the longest side
the largest angle will be opposite that
wait isnt it cos(40)
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Any ideas how to proof?
<@&286206848099549185>
@distant kite You need to use the Rational Zeros Theorem
What can you say about the zeros of ax^2 + bx + c?
I don't really know about Rational Zeros Theorem
I know how to use but idk what it says
I just know the theorem can solve cubic or higher power equation
Ok. Basically, if the polynomial has rational zeros, it tells you the possible values for them
And the possible values are c' / a' , where c' is a factor of c, and where a' is a factor of a
rational zeros means equal to zero?
Do you know what is a rational number?
yes
What is it?
