#help-13

1 messages · Page 194 of 1

azure citrus
#

i’m not sure at all how to start or even what i’m determining!!

#

say 1a

#

do i just pick some r?? and determine an interval?

native heath
#

hold on lemem see

#

Okay this is interesting lmao

#

uhh do you have an answer key?

#

1a might be (-inf, inf)

#

the second part is def more interesting

#

okay i believe i have to get my hands a little dirty here

#

is it (0,1) 😭

#

im probably doing something wrong here sigh

azure citrus
#

yes the domain for 1a is (-inf to inf)

#

but apparently i have to be able to prove it :zcc

wet fossil
native heath
#

are we sure about that

#

im not sigh

#

@azure citrus what's the answer sigh

azure citrus
#

i’m not sure. i tried getting help from professor

#

i don’t have an answer key

#

lol

royal finch
#

The upperbound is a non-zero natural and the lower bound is its negative reciprocal, of course 0 is in there.

native heath
#

yeah is zero included though?

azure citrus
#

but the lower bound is interesting when r is small

native heath
#

i mean it says greater

#

not greater or equal

royal finch
#

If you're not convinced you can prove it using an intermediate value theorem argument. x is a continuous function and -1/r and r are far enough away from zero that you can construct an compact interval.

native heath
#

yeah nvm zero is included

#

im tired sorry

native heath
#

like draw a few intervals and extrapolate

azure citrus
#

hmm

cedar kilnBOT
#

@azure citrus Has your question been resolved?

#
Channel closed

Closed by @azure citrus

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

cinder venture
#

A particle is projected on a straight line from the point O with an initial velocity of
25m/s. Its acceleration after t(s) is given as (6t2 – 4t) m/s. Find the velocity and distance
from O after 3s.

cinder venture
#

First half good?

#

<@&286206848099549185>

copper talon
cinder venture
#

Isn’t the antiderivative of acceleration velocity?

#

Second part I got 97.5

#

Good?

copper talon
cinder venture
copper talon
cinder venture
#

@copper talon

copper talon
#

didn't study most of these yet

cinder venture
#

no problem

#

.close

cedar kilnBOT
#
Channel closed

Closed by @cinder venture

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

ashen field
#

I used Kuratowskis theorem to prove it’s non planar by finding k3,3 as a subgraph but I’m not sure how I would prove part c

ashen field
#

here’s part c a bit clearer

solemn harbor
ashen field
#

yes sure

solemn harbor
#

and is this university level?

ashen field
#

graph theory and it’s A level further maths which is just before university in the uk

cedar kilnBOT
#

@ashen field Has your question been resolved?

ashen field
#

I can see that if we choose any 3 adjacent vertices we won’t be able to choose another one that’s connected to all 3 but I’m not sure how to put it down in a way that’ll lead to a proof

#

because i’m thinking if the subgraph is isomorphic to K4 it’ll need to have 4 nodes that are all connected

#

but we can only choose a maximum of 3 nodes that are all connected

#

<@&286206848099549185>

cedar kilnBOT
#

@ashen field Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

wise verge
#

We want to build a channel that has an isosceles trapezoid as a section in such a way as to widen it the upper part of the channel is twice the lower width and that the non-parallel sides are 8 meters.
Below is a diagram of the channel section.

wise verge
#

Find the value of the L segment of the graph as a function of the variable x.

#

<@&286206848099549185>

cedar kilnBOT
#

@wise verge Has your question been resolved?

cedar kilnBOT
#

@wise verge Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

quasi patrol
#

I don’t get how this is competing the square ?

quasi patrol
#

I’m struggling to see how

cedar kilnBOT
#

@quasi patrol Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

cedar kilnBOT
flint plinth
#

do you agree with the last (typeset) line?

#

ah ok

#

so you just need to make a few observations:

#

f and g are positive

#

so f(x) > 0and g(x) > 0

#

f and g are increasing

#

so what does that tell you about f'(x) and g'(x)

#

no..

#

increasing doesn't imply concave

#

what can you say about the first derivative of an increasing function?

#

numerically what you can you say

#

if a function is increasing, can its derivative be negative?

#

ok

#

so f'(x) and g'(x) are both >= 0

#

finally, you also have that f and g are concave upward

#

which tells you something about f''(x) and g''(x)

#

(assuming they have second derivatives)

#

right

#

so what can you conclude about your last expression (the typeset expression)

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

#
Channel closed

Closed by @scarlet wyvern

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

pseudo grove
#

for (x+a)(x+b), where a and b are any number,
is it possible that one of the roots could possibly not be a solution?

digital cliff
#

solution to what

pseudo grove
#

i just mean in general

#

to a and b

#

if i find a and b

digital cliff
#

so (x+a)(x+b)=0?

pseudo grove
#

yes

#

is it possible if i found the roots

#

a and b, one of them could not be a solution

#

or would they always be a solution

digital cliff
#

if you were able to factorise into that form, then x=-a and x=-b must be solutions

pseudo grove
#

got it

#

thank you

#

.close

cedar kilnBOT
#
Channel closed

Closed by @pseudo grove

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

orchid widget
#

For linear algebra, if a vector space is 1 dimensional, does that mean that it only consist of one vector?

silver parcel
#

no, it's span(one non 0 vector)

#

for example, R is a R vector space of dim 1

#

which can be written as span{1}

#

a vector space that consists of only one vector is {null vector} by def of vector space

#

and would be of dim 0

#

intuitively, a vector is a point, and a 1 dimensional space can be visualised as a line

#

a 2 dimension as a plane

#

etc

orchid widget
#

I see

#

.close

cedar kilnBOT
#
Channel closed

Closed by @orchid widget

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

buoyant mirage
#

My brother is doing a problem that requires him to solve an equation for x by distributing the wrong way. Any idea how you would get x=-19/20 from
"-24 - (4x - 6) = -2(-8x-11)"

cedar kilnBOT
#

@buoyant mirage Has your question been resolved?

buoyant mirage
#

<@&286206848099549185>

buoyant mirage
#

.close

cedar kilnBOT
#
Channel closed

Closed by @buoyant mirage

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

quaint scarab
#

How can I use the limit comparison test with this?

quaint scarab
#

idk how to get a bk with a sin

#

sin(n)?

solid juniper
#

some intuition here is that sin(1/n) and 1/n are very close in value when n is large

#

so that should suggest something to use for comparison

quaint scarab
#

oohhhhh

#

thank you!

#

.close

cedar kilnBOT
#
Channel closed

Closed by @quaint scarab

Use .reopen if this was a mistake.

quaint scarab
#

.reopen

cedar kilnBOT
#

quaint scarab
#

I closed this too early

#

that would suggest a divergent p series then, no?

solid juniper
#

yes the series diverges

quaint scarab
#

why? it seems to go to 0...

solid juniper
#

it's very similar to $\sum_{n=1}^\infty \frac{1}{n}$

wraith daggerBOT
solid juniper
quaint scarab
#

looking at the graph of sin(1/n)

#

as x -> infinity

solid juniper
#

yea but so what

#

same thing for 1/n as n goes to infinity

quaint scarab
#

hm. must just be getting my limits and such mixed up. series are hard....

solid juniper
#

true

cedar kilnBOT
#

@quaint scarab Has your question been resolved?

#
Channel closed

Closed by @quaint scarab

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

rotund stream
#

2x + x
3 4

cedar kilnBOT
rotund stream
#

.close

cedar kilnBOT
#
Channel closed

Closed by @rotund stream

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

real burrow
#

need some help with these 2

cedar kilnBOT
cosmic steppe
#

Do you know the definition of a function

real burrow
#

kinda

crimson sedge
real burrow
#

for a function or the problem

crimson sedge
#

the defintion of function - whats the general meaning?

real burrow
#

an expression that has 1 or more variables?

grand crystal
#

nope

#

An input can only have one output

#

^

#

Main rule of a function

crimson sedge
#

apply that to what is given to you

grand crystal
#

So basically one x can only have one y value corresponding to it

real burrow
#

well all i got is that 2,3, and 4 are x and y is 5

grand crystal
#

Yeah

#

Each input has one output in it

#

So is it a function?

real burrow
#

yeah

grand crystal
#

Yeah it is

#

And for 5

#

look whether an x has 2 y values

#

And decide

real burrow
#

since it has 2 y values

#

it is not

crimson sedge
#

yep

real burrow
#

gotcha

#

thanks

#

.close

cedar kilnBOT
#
Channel closed

Closed by @real burrow

Use .reopen if this was a mistake.

grand crystal
#

welcome

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

inner ruin
cedar kilnBOT
inner ruin
#

Is this correct?

crimson sedge
#

,rccw

wraith daggerBOT
cedar kilnBOT
#

@inner ruin Has your question been resolved?

crimson sedge
#

whats the symbol between angle hrs and hts?

#

i cant tell

#

in the top line

inner ruin
#

It is the congruency symbol

cedar kilnBOT
#

@inner ruin Has your question been resolved?

cedar kilnBOT
#

@inner ruin Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

fickle imp
#

how do I solve this integral?

cedar kilnBOT
fickle imp
#

.close

cedar kilnBOT
#
Channel closed

Closed by @fickle imp

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

real burrow
#

need some help with this one:
since its h of f with 1 i believe I just put 1 into the other functions and multiply them but since the "of" symbol is there I am not sure what to do

tropic oxide
#

this is function composition

spice kraken
#

you don't multiply function composition

tropic oxide
#

$(h \circ f)(1)$ means $h(f(1))$

wraith daggerBOT
tropic oxide
#

it does not mean $h(1) \cdot f(1)$

wraith daggerBOT
real burrow
#

gotcha

#

i think

#

so it would be that i plug in the 1 for f

#

and then i put that equation i get out of it into h

#

right?

tropic oxide
#

misuse of the word "equation", also you'd get a number

real burrow
#

i got -3

#

since f(x)=x-4

#

it would be f(1)=1-4

#

so f(1)=-3

#

right?

tropic oxide
#

yes f(1) = -3

real burrow
#

so then i would put -3 into x from h right?

#

so it would be h(x)=sqrt-3-5

tropic oxide
#

missing parentheses

#

sqrt(-3-5)

#

and it's not h(x) but h(-3)

real burrow
#

so then i get sqrt -8

#

would that be the answer?

#

or should i simplify it more

tropic oxide
#

missing parentheses for the square root again, but i guess yes?

#

or maybe

#

you're expected to not yet know about complex numbers and so this should just be "undefined"

real burrow
#

so in total

#

i get 1

#

and put it in the equation of f where x is

#

then get the answer from that equation which is a singular number (-3)

#

then put -3 into h where x is

#

then get answer

tropic oxide
#

this wording is extremely clunky, but yes.

real burrow
#

gotcha

#

so how would undefined as answer go like

#

as in how do i show my work to get undefined if there is already an answer

#

which was sqrt 8

crimson sedge
real burrow
#

yeah i got that

#

but in my work would i just put sqrt-8=undefined?

crimson sedge
#

Yes.

real burrow
#

thanks

#

also

#

i got a couple more things that are very similar

#

if thats ok with you daniel

#

or ann

crimson sedge
#

No problem, ¿how can I help you?

real burrow
#

and thats it

#

and im done with EVERTHING

#

and 24-26 is using the pics from above

#

this one

crimson sedge
#

Give me a second, I'll turn on the laptop, I'm on my cell phone and I have a good brain but terrible eyesight.

real burrow
#

gotcha

crimson sedge
real burrow
#

in 24 to 26 i need to state the domain and interval notation

#

and for 27 i need to write 2 functions f and g that h(x)=(f of g)(x)

#

all in the pics above

crimson sedge
real burrow
#

wasn't expecting a full answer, but thank you. But if you could walk me through the rest at least so I know how to do it exactly that would be amazing

crimson sedge
#

Sure

real burrow
#

damn

#

thank you I guess?

crimson sedge
#
  1. (g/f) (x)

g(x) = 1/(x-3)
f(x) = (x-4)

g/f = (1/(x-3))/(x-4))

g/f = 1/ (x-4) (x-3)

Here at x = 4, 3 the function would be undefined. So the domain is R - {3, 4}

crimson sedge
crimson sedge
# crimson sedge

In this g(h(x) there lies an discontinuity at x = 14. Remove that

crimson sedge
real burrow
#

Jefe?

#

damn

#

nice

crimson sedge
#

jajajaja

#

Im from Colombia.

#

Jefe = boss

real burrow
#

nice

#

i know

#

ill get this one down and then i can finally do 27

crimson sedge
real burrow
#

ok

crimson sedge
real burrow
#

wait is this one 26 or 27?

crimson sedge
real burrow
#

ok

#

and how would i do the last one?

crimson sedge
real burrow
#

oh

real burrow
real burrow
crimson sedge
crimson sedge
real burrow
#

but didnt the other guy say that the third one was incorrect in that picture?

crimson sedge
real burrow
#

ah

#

perfect

crimson sedge
#

It's after dawn in my country, I guess sleep is playing tricks on me. Sorry for the mistake.

real burrow
#

thank you anyway

#

very much

#

for your amazing math skills

#

its 11:33 here

#

pm

#

.close

cedar kilnBOT
#
Channel closed

Closed by @real burrow

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

native shuttle
cedar kilnBOT
native shuttle
#

how could i do the problem on the left

cedar kilnBOT
#

@native shuttle Has your question been resolved?

native shuttle
#

.close

cedar kilnBOT
#
Channel closed

Closed by @native shuttle

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

civic eagle
#

what subspace is Nul A a part of? R^4?

cedar kilnBOT
tropic oxide
#

you did not actually need to do any of these calculations!!!

#

you were not asked for the nullspace itself but rather what R^p it lives in

#

and it should be plain as day that Nul(A) ⊆ R^4 without even doing any calculations, bc A is a 3 by 4 matrix.

civic eagle
#

so it's R^4 just by virtue of column count, got it. thank you.

#

.close

cedar kilnBOT
#
Channel closed

Closed by @civic eagle

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

feral citrus
cedar kilnBOT
feral citrus
#

A quadratic equation is any equation of the form: y=ax2+bx+c
, where a
, b
, and c
are integers. The solutions to a quadratic equation are values that when substituted into the quadratic equation, yield a true statement.

One method for solving a quadratic equation is by factoring the equation and setting each of the factors equal to 0. Not all quadratic equations can be solved by factoring, and in such cases, it is necessary to use the quadratic formula to find the factors.

To simplify the quadratic equation given, two factors that multiply to 15 and add to 8 are necessary. The only valid pair of factors is 3 and 5. The equation can then be rewritten as:

(x+3)(x+5)=0
Recall that if ab=0
, then either a=0
, or b=0
. So, the values of x
can be found by setting each parenthesis equal to 0
and solving for x
:

(x+3)=0
or
(x+5)=0

x=−3
or
x=−5

#

explain this

#

x2+8x+15=0

#

!help

cedar kilnBOT
#

To ask for mathematics help on this server, please open your own help channel or help thread. See #❓how-to-get-help for instructions.

elfin otter
#

What do you not understand?

silver gust
#

hi

feral citrus
#

theres the answer and solution but i cant understand it

#

the questions is x2+8x+15=0

#

and the options are

#

idk how to get the answer

elfin otter
#

Do you know how to factorise the equation?

feral citrus
#

no

#

maybe i fo but idk what things are called

#

but can u explain

elfin otter
onyx dove
#

completing the square if you're good at it

feral citrus
elfin otter
feral citrus
#

so like the

#

4 x 2 is 8

#

and

#

3 x 1 is 3

#

then u cross multiply

fast relic
#

No

elfin otter
feral citrus
feral citrus
fast relic
#

You have to find multiples of the c term

feral citrus
#

icic

elfin otter
#

U break down the A and C term
Then it's all trial and error when cross multiplying

feral citrus
#

to match the b right

elfin otter
#

Yes

feral citrus
#

aight

#

thanks

#

ill try it

elfin otter
#

In the end, it must satisfy A B C terms

feral citrus
#

and if i have questuons ill come back

#

how do i end channel

onyx dove
#

.close

feral citrus
#

.close

cedar kilnBOT
#
Channel closed

Closed by @feral citrus

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

fervent merlin
cedar kilnBOT
fervent merlin
#

Here I'm getting the answer 4h^2 = 9ab

#

But that's not in options

#

.close

cedar kilnBOT
#
Channel closed

Closed by @fervent merlin

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

frank idol
#

Help please

cedar kilnBOT
hot rampart
#

I’ve no idea how to do this

cedar kilnBOT
#

@frank idol Has your question been resolved?

frank idol
#

<@&286206848099549185>

cedar kilnBOT
#

@frank idol Has your question been resolved?

cedar kilnBOT
#

@frank idol Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

keen nova
#

can anyone understand what was done from step 2 to 3?

livid hound
#

are you referring to

wary hamlet
#

they simply factorise

#

my bad

keen nova
#

yeah

#

but how

#

which rule

livid hound
#

distributive property

#

ab + ac = a(b+c)

#

definition of squaring
a^2 = a * a

cedar kilnBOT
#

@keen nova Has your question been resolved?

#
Channel closed

Closed by @keen nova

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

crimson sedge
cedar kilnBOT
crimson sedge
#

!status

cedar kilnBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
granite knoll
#

If x < 10, what can you say about x - 10

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

crimson sedge
#

Sorry i was busy

#

Yeah i figured it out

#

x - 10 = -b

#

x = 10 - b

#

b - x = b - 10 + b = 2b - 10

#

It's correct right?

granite knoll
#

no

crimson sedge
#

???

crimson sedge
granite knoll
#

sry let me double-check, I mis-read

crimson sedge
#

We found x then subtracted from b

muted timber
crimson sedge
#

Wait oh sorry

#

Typo

#

Meant to write = instead of >

muted timber
#

that line is still not correct

crimson sedge
#

Dude

#

I solved it correctly didn't i?

muted timber
#

if you had, it would be correct.
It isnt, so you havent

crimson sedge
#

x - 10 = b
x = 10 - b

#

We found x

muted timber
crimson sedge
#

So to find b - x it the same as

b - (10 - b)

crimson sedge
#

Not x

muted timber
#

i am aware

granite knoll
#

I think your edit above is correct

crimson sedge
#

Are yall high

#

It's fucking correct

granite knoll
#

don't be rude, what you had first written before the edit was not correct

crimson sedge
#

C is the correct option

smoky harness
#

in MCQs will it be better to put some values and see the relations? it will save some time in exam?

crimson sedge
granite knoll
#

if x < 10, then x - 10 < 0, so |x - 10| = 10 - x = b. Rewrite as -x = b - 10 --> b - x = 2b - 10

crimson sedge
#

Yeah exactly

crimson sedge
#

.close

cedar kilnBOT
#
Channel closed

Closed by @wooden lily

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

keen basin
#

is the least squares regression line of Y on X the same as the least squares regression line of X on Y?

cedar kilnBOT
#

@keen basin Has your question been resolved?

keen basin
#

<@&286206848099549185>

cedar kilnBOT
#

@keen basin Has your question been resolved?

cedar kilnBOT
#

@keen basin Has your question been resolved?

keen basin
#

.close

cedar kilnBOT
#
Channel closed

Closed by @keen basin

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

dire geode
#

take your grievances elsewhere. help channels are for math problems

#

.close

cedar kilnBOT
#
Channel closed

Closed by @dire geode

Use .reopen if this was a mistake.

dire geode
#

hundreds of people get help everyday

crimson sedge
dire geode
crimson sedge
dire geode
#

or lazy idk

crimson sedge
crimson sedge
dire geode
#

i help plenty of people who want to do work

crimson sedge
#

Did someone ping me here?

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

cold briar
#

How many ways can you order n identical balls in a circle with n + m places?

My original answer was: (n + m)!/n!m!(n+m)

The number of arrangements of n + m distinct objects in a circle will be (n + m)! / n+m
And there are n identical balls and m identical empty spots.

So... I divide by n! and m!
thus
(n + m)! / n! m! (n + m)

cold briar
#

But,

muted bear
#

this is only true when n and m are coprime

cold briar
#

Yeah, but why?

muted bear
#

the dividing factor of n+m assumes that each rotation is unique

cold briar
#

ah. I see

#

Okay

#

thanks...

#

ima just... try something else ig

muted bear
#

for example, if you have 7 spots,
X O X O O X O will cycle through all 7 spots and create a unique arrangement

#

in this case, you have 4 balls

#

the number of ways to arrange them is (7C4)

#

if you have 6 spots and 4 balls, you will hit the same arrangement after half a cycle for some arrangements

#

like O X O O X O

cold briar
#

Wait I thought of something...

#

nvm

#

What if I...

#

So there are n identical balls and m identical empty spots.

#

put 1 ball in between the empty spots

(m - 1)C1
put 2 ball in between the empty spots
(m - 1)C2 + (m - 1)C1
put 3 ball in between the empty spots
(m - 1)C3 + (m - 1)C2 + (m - 1)C1
...
put n ball in between the empty spots
(m - 1)Cn + (m - 1)C(n-1) + (m - 1)C(n-2) ... + (m - 1)C1

#

But... only works when m - 1 >= n

#

...

#

and idk how to write sums

#

ima just sleep

#

.close

cedar kilnBOT
#
Channel closed

Closed by @cold briar

Use .reopen if this was a mistake.

cold briar
#

i can just do it the other way around if n - 1 >= m

#

but for n = m idk

#

i go sleep

#

brrrr

#

and i think i wrong

#

i

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

crimson sedge
#

How to find LCM(24823,26854,21452)
My approach was trying to find LCM(24823,26854) then find the LCM of the number i got with 21452 but my calculator said math error so i got into a dead end xD

fickle trellis
#

Umm... they are big numbers...

crimson sedge
#

Please help in the question 3 and

fickle trellis
crimson sedge
#

I tried to do prime factorisation but the sol i got is too big

#

24823 is 103x241
26854 is 2x29x463
21452 is 2^2x3x173
so LCM should be 2^2x3x29x103x173x241x463 but the answer is too big

fair geyser
#

it's too small actually

#

that 3 should be 31

#

i'm not sure how i would do it with a calculator 🤔

crimson sedge
#

oh ye it 31, i forgot to add a 1, still numbers too big for the display 😔

fair geyser
#

how did you even do prime factorization

crimson sedge
#

there a button on calc for that

#

I just realized the sol itself is too big for the calculator to display .,.

#

welp ty , ima ask my teacher about this tmr

#

.close

cedar kilnBOT
#
Channel closed

Closed by @tawny moth

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

narrow junco
cedar kilnBOT
narrow junco
#

I don’t know what to do

#

I’m not sure how to reach the answer

desert cedar
#

The equation or the graph

narrow junco
#

Both

#

?

desert cedar
#

The equation you wrote is right, but usually when writing graphing equations, y is on the left side.

Y = 25(x) + 100

narrow junco
#

Oh

#

Ok

desert cedar
#

Your x axis is your independent and your y is your dependent. When solving a problem like this, think about “what variable cannot change no matter what?”

That’s your X axis

narrow junco
#

25 pounds per week

desert cedar
#

You can’t change time, days , or weeks but you can change money, pounds etc

narrow junco
#

Weeks

desert cedar
#

Your y axis units are good, and so is your x axis

#

I personally would’ve spaced them differently since you have so much space but I don’t think the teacher would take odd points just for that

narrow junco
#

Ok

desert cedar
#

Do u need help with a?

narrow junco
#

Yes

desert cedar
#

The y intercept is when x is zero. So during week zero,how many pounds of aluminum cans does he have

narrow junco
#

100

desert cedar
#

Your slope in any graph represents the change over your independent variable.

#

So what happens as time passes, in your case, as weeks passes

narrow junco
#

So the slope represents his plans to collect additional 24 pounds per week

desert cedar
#

Perfect.

narrow junco
#

25

desert cedar
#

Need help with b?

#

Also yes

narrow junco
#

Yes

desert cedar
#

Ok so let’s re write the equation as

Y = 25 x + 100

narrow junco
#

Ok

desert cedar
#

What does y represent on the graph and in the equation

narrow junco
#

Y represents the amount of aluminum cans

#

X represents weeks

desert cedar
#

Yup. So we need to find when y equals 800.

On your paper you put 400 in for x. X is your time. So you calculated how many cans he would get in 400 weeks lol

narrow junco
#

Oh

desert cedar
#

Since your graph is small, you could draw your graph and when y equals 800, what your x coordinate is is the answer, but as you go on in school they want you to find x in the equation

narrow junco
#

Oh no

desert cedar
#

800 = 25x + 100

#

Where did you get 10100 from

narrow junco
#

Nm

#

So would you get 28 for x?

desert cedar
#

Yup

narrow junco
#

Ok thank you

desert cedar
#

Np

narrow junco
#

.close

cedar kilnBOT
#
Channel closed

Closed by @narrow junco

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

pale badger
cedar kilnBOT
pale badger
#

the first part is obviously fine but idk abt the last bit

cedar kilnBOT
#

@pale badger Has your question been resolved?

cedar kilnBOT
#

@pale badger Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

pliant juniper
cedar kilnBOT
pliant juniper
#

I think the equation is wrong but I want to check with you all.

#

If I plug in the given values into the equation:

Rate = 1
N = 36

It doesn't give the values that I'm supposed to get.

cedar kilnBOT
#

@pliant juniper Has your question been resolved?

#
Channel closed

Closed by @pliant juniper

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

untold onyx
cedar kilnBOT
#

@untold onyx Has your question been resolved?

cedar kilnBOT
#

@untold onyx Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

cedar kilnBOT
#

Please don't occupy multiple help channels.

dire geode
#

why do you keep opening help channels

grand forge
#

he has proble,s

#

hess just stuck on a geometry dash level

dire geode
#

<@&268886789983436800>

celest seal
#

.close

cedar kilnBOT
#
Channel closed

Closed by @celest seal

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

warped marsh
#

can someone help me understand this rq

cedar kilnBOT
warped marsh
#

i know that if a point has a veritcal tangent line then it isnt differentiable but how come the answer is telling me that x=2 is differentiable?

#

how is f(x) differentiable at x=2 if there is a vertical tangent line at x=2

zenith sail
#

The tangent at x=2 is horizontal, not vertical

warped marsh
#

it says it has a vertical and horizontal tangent at x=2

zenith sail
#

Oh what, I didn't notice the sentence at the bottom.

#

The wording is awkward

#

It does have a vertical tangent somewhere

#

And it does have a horizontal tangent at x=2

warped marsh
#

do you think the answer is a mistake

zenith sail
#

No, look at the graph

#

It didnt mean it has both a horizontal and vertical tangent at x=2

#

The way they phrased the sentence was just weird

#

There are vertical tangents, but not at 2

warped marsh
#

so they forgot to put something after the vertical tangent part

zenith sail
#

I guess

#

Or they're just saying

#

There are vertical tangents, period.

#

And also

#

A horizontal tangent at x=2

warped marsh
#

yea

#

alr ty

#

.close

cedar kilnBOT
#
Channel closed

Closed by @warped marsh

Use .reopen if this was a mistake.

zenith sail
cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

prisma gull
#

Help with proving every convergent sequence is a cauchy sequence

prisma gull
#

Give me a hint?

dire geode
#

Do two epsilons

cedar kilnBOT
#

@prisma gull Has your question been resolved?

prisma gull
dire geode
#

Yes

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

long veldt
#

i’m not sure if i did this right im getting a different answer when I put into a derivative calculator

cedar kilnBOT
#

@long veldt Has your question been resolved?

cedar kilnBOT
#

@long veldt Has your question been resolved?

cedar kilnBOT
#

@long veldt Has your question been resolved?

wanton mountain
long veldt
#

is this better

wanton mountain
wanton mountain
#

@long veldt what are u gettin on derivative calculator?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

nocturne nexus
#

😭 why is this wrong

cedar kilnBOT
nocturne nexus
#

it makes no sense

#

even the graph says its at 2.72

cedar kilnBOT
#

@nocturne nexus Has your question been resolved?

cedar kilnBOT
#

@nocturne nexus Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

frozen cloud
#

a, b, c, d ∈ {0,1,2,3,4,5,6,7,8,9}
a! +b! +c!=d!What is the sum of a+b+c+d?

celest abyss
#

.open

celest abyss
#

5x+7x=180 What is the value of x?

#

5x+7x=180
What is the value of x?

cedar kilnBOT
#

@frozen cloud Has your question been resolved?

tawny drum
cedar kilnBOT
cedar kilnBOT
#

@frozen cloud Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

slender geyser
#

perimeter of a polygon = 158cm. The measures of their sides creates an arithmetic progression with common difference d = 3cm. Knowing the largest side = 44cm. How many sides of the polygon are there?

slender geyser
#

so I tried to analyse the problem and got
P of the Polygon = Sn of the AP
d = 3cm
the
44 = a1 + (n-1).3

#

Idk what to do next

crimson sedge
#

Oh

slender geyser
#

Yea

crimson sedge
#

Mb

#

Solve those two equations and get the value of n

#

We get 44=a+3n-3, so a= 3-3n+44, so u substitute this in sn formula

#

316=2(44+3-3n)n +3n^2-3n

#

@slender geyser

cedar kilnBOT
#

@slender geyser Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed by @slender geyser

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

obtuse pelican
cedar kilnBOT
obtuse pelican
#

im trying to understand the standard deviation equation

#

so if the top part is to get the sum of values of the difference between values from the mean, and it has to be squared so that the negative wont cancel out with the positive

#

then why isnt n squared as well

cedar kilnBOT
#

@obtuse pelican Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

clever cedar
#

Hello sorry if this is a dumb question, but how can you simplify this

clever cedar
#

the solution in my book says this is the solution but i have no idea how to do that

tropic oxide
#

!occupied

cedar kilnBOT
#

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

#

@clever cedar Has your question been resolved?

cedar kilnBOT
#

@clever cedar Has your question been resolved?

clever cedar
#

Im starting to think this stuff is impossible

#

and its a mistake in the book

summer nova
#

@clever cedar that solution doesn't look correct

clever cedar
summer nova
#

what level of math is this?

summer nova
clever cedar
summer nova
#

@clever cedar Yea im stumped, maybe someone else (smarter) can help, sorry!

clever cedar
#

I think i figured it out

#

with this formula

wraith daggerBOT
summer nova
#

oh yea, didn't know of that propety tbh, makes question very simple

clever cedar
summer nova
#

ah also lol you can do it like this $\sqrt{x+y+2*\sqrt{x-y}*\sqrt{x+y}+x-y$ which gives $\sqrt{(\sqrt{x+y}+\sqrt{x-y})^{2}}$

wraith daggerBOT
#

lolk
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

clever cedar
#

This channel can be closed now

neat dune
#

Also tho if u wanna know how to do this w/o knowing the formula

#

Say $u = \sqrt{expression}$

wraith daggerBOT
#

992qqoloy

neat dune
#

Then $u^2 = expression$

wraith daggerBOT
#

992qqoloy

clever cedar
#

.close

cedar kilnBOT
#
Channel closed

Closed by @clever cedar

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

willow seal
#

What is math?

cedar kilnBOT
crimson delta
#

what kind of answer do you want

willow seal
#

Simple definition

crimson delta
#

good luck with that

cerulean harness
cedar kilnBOT
#

@willow seal Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

#
Channel closed

Closed due to the original message being deleted

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

crimson sedge
cedar kilnBOT
crimson sedge
#

How do I solve these type of questions?

#

translation: Find a linear ODE with solutions ...

glacial crane
#

How can I get to the possibility for 1,2 and 3 right answers?thx for any help!

A test consists of four questions. There are three possible answers for each question. Exactly one answer is correct. A candidate who has not learned anything randomly checks one answer. The random variable A indicates the number of correctly checked answers. a) What values ​​can the random variable A take? b) Calculate the values ​​of the probability distribution and represent them using a dot diagram

crimson delta
#

there isnt a general process (I think), the point here is to notice something

crimson delta
#

of the four functions

crimson sedge
#

alr I try

crimson delta
#

well actually for functions of the form e^(lambda x) there is a general process. think about when you use those functions to solve an ODE

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

#
Channel closed

Closed by @rain oxide

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

cedar kilnBOT
white wadi
#

translation:

#

roughly sketch the graph of y

#

i dont get it

#

what are they saying here

#

like

#

how do they know x^3 is where it is

#

and why is it there and all

cedar kilnBOT
# white wadi

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

cedar kilnBOT
# glacial crane <@&286206848099549185>

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

#

@glacial crane Has your question been resolved?

elfin otter
wraith daggerBOT
#

Kai Funaba

white wadi
#

yes but

#

why do they specifically start drawing it at that one point

elfin otter
#

In a nut shell, it doesn't hv to be specific

⬇️ (if u want to feel better)
||Since it's on a book it can't explain itself, and writing what I wrote above in the book wld just be deemed 'redundant' ||

white wadi
#

bruh i see

#

thank you very much :D

cedar kilnBOT
#

@glacial crane Has your question been resolved?

cedar kilnBOT
#

@glacial crane Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

median hedge
#

Hey so I need a mathmatical formula where the higher 'X' is the lower the constant value is

median hedge
#

For example

Lets say the constant is 25, if X = 5 then 25 can equal 20 (doesnt have to be exactly that just so long as its smaller than the constant)

and if X is 25 then 25 can equal 10

#

Something like that

#

I tried doing something like |25 * (15*(-.025))|

#

that doesnt really work though

fallen moat
#

is it like y=k/x something like that?

median hedge
#

Something like that but it cant be lower than 1 so I assume id just make k a larger number?

#

So for example if I did y = 550/1

1 being X and Y being the constant of 25

550/25 would be 22 which is fine but 550/1 obv is 550 which is too high of a starting number

#

So my starting number would be 25

#

That probably doesnt make sense so heres a table

I dont care about the numbers between 25 and 10 they can be whatever so long as they decrease

I need a formula where if I put in 1 for X I get 25 and if I put in 50 for X I get 10

#

actually nevermind I think this would work

#

.close

cedar kilnBOT
#
Channel closed

Closed by @median hedge

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

scarlet prism
cedar kilnBOT
scarlet prism
#

when i factored by grouping

#

i have 4x^2(2x+1)-1(2x+1)

#

what do i do from there now

zinc mist
#

how would you factor pq+rq?

scarlet prism
#

wdym

zinc mist
#

say you have an expression

#

pq+rq

#

you wanna factorise it, so what'll be your result?

devout nexus
zinc mist
#

let the one who asked work for it, mate

scarlet prism
#

that isnt the answer tho

devout nexus
zinc mist
#

allg

devout nexus
scarlet prism
#

its (2x-1)(2x+1)^2

zinc mist
scarlet prism
#

yea but idk how to get there

zinc mist
#

okay so did you get till (2x-1)(4x^2-1)?

scarlet prism
#

i got 4x^2(2x+1)-1(2x+1)

zinc mist
#

alright so lets say you have an expression
px+qx, how would you factorise it?

scarlet prism
#

x^2(p+q)?

zinc mist
#

nope nope

#

try again

scarlet prism
#

its not factorable

zinc mist
#

it is

scarlet prism
#

oh

#

idk then

zinc mist
#

to factor is to use the distributive property

#

a(b+c) can be 'distributed' as ab+ac

scarlet prism
#

oh yea

#

i wrote it incorrectly

zinc mist
#

or u cud say the reverse that
ab+ac can be redistributed to a(b+c)

scarlet prism
#

so it would be x(p+q)

#

i wrote x^2

#

mb

zinc mist
#

if you were to apply this to what i asked

#

yes good

#

so now in your expression

#

4x^2(2x+1)-1(2x+1)

scarlet prism
#

yes

zinc mist
#

can you reapply the same thing

#

if tp+tr= t(p+r)
then can you identify what works as 't', 'p' and 'r' in
4x^2(2x-1) -1(2x-1)

scarlet prism
#

wait isnt it 2x+1

#

and it would be (2x+1)(4x^2-1)

#

ohh

zinc mist
#

yes exactly

scarlet prism
#

and then u can break 4x^2-1

zinc mist
#

i didnt see that too

#

yup

scarlet prism
#

to 2x+1 and 2x-1

zinc mist
#

and there you have your answer

scarlet prism
#

so you'll have (2x+1)^2(2x-1)

#

isee

#

i see

zinc mist
#

ye :>

scarlet prism
#

ohh okok

#

ty

zinc mist
#

np

cedar kilnBOT
#

@scarlet prism Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lunar radish
#

maximum possible value of xy where
(12x + 1)(12y + 1)=24193

cedar kilnBOT
#

@lunar radish Has your question been resolved?

lunar radish
#

<@&286206848099549185>

long arrow
#

Do you have the answer?

#

or are there any restrictions about x, y?

lunar radish
#

the original equation was x^2 + y^2 + 12xy = 2016

#

after dividing by 12 i used simon's bla bla bla

#

(x+1/12)(y+ 1/12)=168 + 1/444

#

multiplied both sides by 144

#

(12x+1)(12y+1)=24193

#

and here we are

long arrow
#

huh

#

this is why it was impossible

#

hehe

lunar radish
long arrow
#

x^2 + y^2 + 12xy = 2016
x^2 - 2xy + y^2 + 14xy = 2016
(x - y)^2 + 14xy = 2016

#

from here

#

xy = (2016 - (x - y)^2) / 14

#

= 144 - (x-y)^2/14

#

now notice that it's enough to minimize (x-y)^2 because (x-y)^2 >= 0

lunar radish
long arrow
#

2016/14 = 144

lunar radish
#

so why's the other denominator 12

long arrow
#

mb, typo

#

it should be 14 indeed

lunar radish
#

alr thx

#

.close

cedar kilnBOT
#
Channel closed

Closed by @lunar radish

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

ripe coyote
#

Hello!
I’m looking for someone to look over the work I have so far and make sure it’s correct, then help me solve the remaining three parts of the problem.
Here are the photos;

cedar kilnBOT
#

@ripe coyote Has your question been resolved?

limpid sigil
#

So far the workings out have been very clear and easy to revise from!

ripe coyote
#

Thank you! I think i have solved this question!

#

.Close

cedar kilnBOT
#

@ripe coyote Has your question been resolved?

#
Channel closed

Closed by @ripe coyote

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

crimson sedge
#

Did I get these right?

cedar kilnBOT
crimson sedge
#

1-4

#

unreadable

#

the part in the shadow

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

crimson sedge
#

yes its right

crimson sedge
#

What abt 5

#

How do I do the limit stuff

crimson sedge
crimson sedge
#

<@&286206848099549185>

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

crimson sedge
#

<@&286206848099549185>

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

crimson sedge
#

<@&286206848099549185>

crimson sedge
#

<@&286206848099549185>

crimson sedge
#

<@&286206848099549185>

#

.close

cedar kilnBOT
#
Channel closed

Closed by @crude crane

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

oblique prawn
#

A triangle has sides of length cos(20 degrees), cos(30 degrees), cos(40 degrees). What is the degree measure of its largest angle?

oblique prawn
#

why is it not 50

livid hound
#

how are you getting 50

oblique prawn
livid hound
#

show work

oblique prawn
#

this is the triangle i used

livid hound
#

,rotate

wraith daggerBOT
livid hound
#

cos(20°) is the longest side
the largest angle will be opposite that

oblique prawn
livid hound
#

no

#

consider cos(0) = 1
and cos(90°) = 0

oblique prawn
#

oh

#

OMG cosine is a decreasing function

#

atleast on [0,90]

#

.clsoe

#

.close

cedar kilnBOT
#
Channel closed

Closed by @oblique prawn

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

distant kite
#

Any ideas how to proof?

cedar kilnBOT
distant kite
#

<@&286206848099549185>

zinc crown
#

@distant kite You need to use the Rational Zeros Theorem

distant kite
#

O

#

c/a?

zinc crown
#

What can you say about the zeros of ax^2 + bx + c?

distant kite
#

I don't really know about Rational Zeros Theorem

#

I know how to use but idk what it says

#

I just know the theorem can solve cubic or higher power equation

zinc crown
#

Ok. Basically, if the polynomial has rational zeros, it tells you the possible values for them

#

And the possible values are c' / a' , where c' is a factor of c, and where a' is a factor of a

distant kite
#

rational zeros means equal to zero?

zinc crown
#

Do you know what is a rational number?

distant kite
#

yes

zinc crown
#

What is it?