#help-13

1 messages · Page 191 of 1

subtle yew
#

You can get the side lengths of the base of the prism

golden thicket
#

tan30=CB/BB1?

subtle yew
#

no

golden thicket
#

then I don’t understand how to apply this in my task

subtle yew
#

Well, this is basic trigonometry

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The most basicest of the basicest

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💀

golden thicket
#

and in the formula for the area of ​​the base you need the height

subtle yew
#

Because you didn't show how you got to that part

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I have a method of solving it in my head

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It likely doesn't allign with how you're doing it

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That's why I said it was wrong, but really I meant to say "I don't know"

golden thicket
#

I need to know your method to understand if we do this

subtle yew
#

Do you get it?

golden thicket
subtle yew
#

so far so good?

golden thicket
subtle yew
#

If you increase the 30 degree angle... the width of the base of the prism would change, right?

#

So would the height or something, probably

golden thicket
#

right

subtle yew
#

Meaning there's a relation between the 30 degree angle, and angle at point c

#

Find that relationship, and you'll be able to solve the question.

golden thicket
#

I know that a leg opposite an angle of 30 is equal to half the hypotenuse, but that doesn't fit, does it?

subtle yew
#

I'm not sure myself to be honest.

#

Assuming the height is static, which it is

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The angle at C is dependent on the angle at B1, probably by some factor of the static height given, which is 2 * sqrt(3)

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I'm thinking it might be possible using similar triangles.

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At this point, I'm giving ideas lol

golden thicket
#

what is cubert(3)? 3^2?

subtle yew
#

cube root.

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so 3 ^ (1/3)

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OH

golden thicket
subtle yew
#

sqrt, square root

#

My bad

golden thicket
subtle yew
#

If AB is double of b

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Then would AB1 be double the length of CB? 🤔

#

I'm not sure... I feel like there's way too little fiven info in the question

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Alright, man... I tried.

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I'm sorry ;----;

golden thicket
subtle yew
#

See, I'd spend more time on it, but it's 3 32 am and I have maths of my own to study too. I'm sorry I couldn't help much lol

cedar kilnBOT
#

@golden thicket Has your question been resolved?

golden thicket
#

.close

cedar kilnBOT
#
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cedar kilnBOT
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worthy grove
cedar kilnBOT
worthy grove
#

how do find the zeros without a calculator

#

like the easy method

#

.close

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flat sparrow
#

Does this look good?

cedar kilnBOT
flat sparrow
#

sorry if its hard to read

surreal cave
wraith daggerBOT
#

FancyBredFries

surreal cave
#

that 2a goes to both -b and the radical

flat sparrow
#

did i mis input

flat sparrow
surreal cave
#

the first line

flat sparrow
#

oh

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i was suppoesd to divide 16 by 2

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at the start

#

so in the end it would actually end up being {-4 +/- square root 79}

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?

flat sparrow
surreal cave
#

pretty much all ur calculations are wrong 😅

flat sparrow
#

so what do i do different?

#

divide 6 by 256 and 60?

#

.close

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#
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severe estuary
#

Factor by grouping 2x^4+3x^3-32x^2-48x

severe estuary
#

(Click the image) This is what I got but idk how to do it

rain drift
#

good start! Is there anything out of x^3-16x we can factor out?

severe estuary
#

The 16x

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(x+4) (x-4)

rain drift
#

we have to factor out an x

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in order to do that

severe estuary
#

Oh yeah

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I was wondering where the other x went

rain drift
#

So then you have x(x+4)(x-4)(2x+3)

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that's about as far as you can factor

#

so there's your answer 🙂

severe estuary
#

Thanks I have a question tho how do we know to factor the x outside the box?

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Like how does x^3-16x factor to x

#

Nvm I got it

#

.close

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#
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reef robin
#

This is part of a chemistry problem, so the ask seems a little weird out of context. I have 3 positive constants $a, b, c$ where $a < b$. I want to prove that $2a < a + b + 2c - \sqrt{(a-b)^2 + 4c^2} < 2b$
Where would I start

reef robin
neat dune
#

I would start by adding both sides of the two inequalities by the square root, then subtracting both sides by 2a or 2b respectively to isolate the square root, and then squaring

#

After that it's probs just a bunch of expanding and rearranging but I'm not 100% sure

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The fact that $a <b$ is useful for the latter portion of the inequality chain cus otherwise after taking those steps, u can't necessarily justify that squaring both sides preserves the inequality

wraith daggerBOT
#

992qqoloy

reef robin
neat dune
#

bleh I wanted to avoid that cus I'm on my phone tbh bleakkekw

reef robin
#

oh nw

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When we prove this sort of thing, we need to start with a true statement right?

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So what statement do I start with? $a<b$?

wraith daggerBOT
#

Methylfluorophosphonylcholine

neat dune
#

Well with inequalities like this

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What you generally do is work backwards

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That only works if all the steps you do are reversible tho

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So for instance if $x^2 < y^2$ you can't generally conclude that $x < y$

wraith daggerBOT
#

992qqoloy

neat dune
#

Buuuut if say, you know that $0 < x$ and $0 <y$ then you can.

wraith daggerBOT
#

992qqoloy

neat dune
#

So for simplicity's sake imma call the whole expression under and including the square root $\sqrt{n}$ devastation

wraith daggerBOT
#

992qqoloy

reef robin
neat dune
#

U split up those inequalities u want to prove into $2a < a + b +2c - \sqrt{n}$ and $ a + b +2c - \sqrt{n} < 2b$

wraith daggerBOT
#

992qqoloy

neat dune
#

I was thinking first, for each of those inequalities, you add $\sqrt{n}$ to both sides

wraith daggerBOT
#

992qqoloy

neat dune
#

Then for the first subtract $2a$, and for the second subtract $2b$

wraith daggerBOT
#

992qqoloy

neat dune
#

And then square both sides so u can get rid of the square root

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The tricky part here is that u gotta make sure $x^2 < y^2$ implies $x <y$, i. E. That the step is reversible

wraith daggerBOT
#

992qqoloy

reef robin
#

mmmm

neat dune
#

for the first inequality, since $\sqrt{n}$ is always nonnegative, and u'll have something like $\sqrt{n} < stuff$ after the rearranging we just did, then you also know "stuff" is positive, so that justifies the squaring step

wraith daggerBOT
#

992qqoloy

neat dune
#

But for the second inequality you'll have something like $stuff2 < \sqrt{n}$

wraith daggerBOT
#

992qqoloy

neat dune
#

So you gotta justify why "stuff2" is positive

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Oh wait hmm I just realized I misread

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Is it $a < b$ or $b< a$ ? Cus the former means squaring both sides won't necessarily work as you'll have $a - b + 2c$ be "stuff2", so since then $a - b$ is negative, depending on the value of $c$ it could be positive or negative

reef robin
#

I've got it now I think!

wraith daggerBOT
#

992qqoloy

neat dune
#

alright

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Wait

reef robin
#

so the issue is to go backwards from the result to a known true statement, we have to square the inequality. But that step isn't always reversible right and thats the issue

neat dune
#

Yeah

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Oh wait I think I know how to fix this

#

U have two cases: one where $a - b + 2c$ is negative and one where it's nonnegative

wraith daggerBOT
#

992qqoloy

reef robin
#

right

neat dune
#

In the negative case, clearly $a - b + 2c < \sqrt{n}$

wraith daggerBOT
#

992qqoloy

neat dune
#

So u can assume it's nonnegative when u square

reef robin
#

valid. Thank you bro!

neat dune
#

np

cedar kilnBOT
#

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unborn pond
#

hello, can you help me understand the approach to this problem

unborn pond
dire geode
unborn pond
#

Ok so i just understoof the first and second line

#

in this is where the equation came from

#

now im trying to understand the mathematical process after the second line

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like how did we get this

cedar kilnBOT
#

@unborn pond Has your question been resolved?

cedar kilnBOT
#

@unborn pond Has your question been resolved?

unborn pond
#

.close

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crimson sedge
#

To be clear is Vy at the first second 9.81m/s?

crimson sedge
cedar kilnBOT
#

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crimson sedge
#

And initial velocity for Vy is 0

azure shadow
#

yes that is correct

cedar kilnBOT
#

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marble sluice
#

How to do this problem?

cedar kilnBOT
crimson sedge
#

whats the question?

marble sluice
#

$$ \text{ if } \lvert x - 1 \rvert < \delta \text{ Then } \lvert x^2 - 1 \rvert < \frac{1}{2} \text{ f(x) = x^2 find delta so that epsilon = 1/2} $$

wraith daggerBOT
#

Nerdy_Coder

$$ \text{ if } \lvert x - 1 \rvert < \delta \text{ Then } \lvert x^2 - 1 \rvert < \frac{1}{2} \text{ f(x) = x^2 find delta so that epsilon = 1/2} $$
```Compilation error:```! Missing $ inserted.
<inserted text> 
                $
l.57 ...x) = x^2 find delta so that epsilon = 1/2}
                                                   $$
I've inserted a begin-math/end-math symbol since I think
you left one out. Proceed, with fingers crossed.```
valid yacht
#

If $\lvert x - 1 \rvert < \delta$ then $\lvert x^2 - 1 \rvert < \frac{1}{2} \text{ f(x) = x^2$. Find $\delta$ so that $\epsilon = 1/2$.

#

lmao

crimson sedge
#

∀ϵ>0,∃δ>0
s.t. if 0<|x−1|<δ
, then |x2x+2−13|<ϵ
.

|3x2−x−23(x+2)|=|(3x+2)(x−1)3x+6|<ϵ
Let δ=13
. Then, |x−1|<13⇒|x|<43,|3x+2|<6
..

Then, |(3x+2)(x−1)3x+6|<|6(x−1)6|<ϵ
|x−1|<ϵ
, so δ
=min{1/3, ϵ
}

i think this feels correct, but to be sure... i thank in advance!

#

ig

#

its correct

marble sluice
#

I can’t figure this out, so here is the work i’ve done

#

I tried working out what delta is, but no method worked

tulip stream
#

Need more readable text and tell what is part of the question and what is not instead of everything being written as white

marble sluice
#

$$ \text{ if } \lvert x - 1 \rvert < \delta \text{ Then } $$ $$ \lvert x^2 - 1 \rvert < \frac{1}{2} \text{ $f(x) = x^2 find delta so that epsilon = 1/2} $$

wraith daggerBOT
#

Nerdy_Coder
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

cedar kilnBOT
#

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fading forum
#

hi can someone help? i tried drawing a diagram

fading forum
snow locust
#

probably 140?

#

💀 IDK man I just did 360-220 and I got so-

fading forum
#

according to the answer scheme

snow locust
#

mbmb sry 💀 I just made a wild guess

#

sry if it was a test

violet brook
cedar kilnBOT
#

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polar ermine
#

determine the vertex form for the function with x-intercepts of (-5, 0) and (-3, 0) that goes throuhj point (-2, -9)'

cedar kilnBOT
#

Please don't occupy multiple help channels.

zenith sail
#

I'm assuming you're looking for a quadratic

polar ermine
#

i also found the axis of symmetry which is -4

zenith sail
#

ahh okay, you found most of the equation

#

but you're missing the amplitude, a

#

$y=a(x+5)(x+3)$

wraith daggerBOT
#

tatpoj

zenith sail
#

do you see where you could go from here? @polar ermine

polar ermine
zenith sail
#

no, I think that'll just make it harder to find a

zenith sail
#

so if you have something you can plug in for x and y, you can solve for a

polar ermine
#

ohhh

#

so i would do
-9 = a(-2+5)(-2+3)?

zenith sail
#

yep

polar ermine
#

-9=a(3)(1)
-9=3a
a=-3

#

i would plug it into vertex form and find q?

zenith sail
#

you want it specifically in vertex form, right?

polar ermine
#

yep

zenith sail
#

what does your vertex form look like? I don't know of a parameter called q in vertex form

polar ermine
#

y=a(x-p)^2+q

zenith sail
#

ahh ok

#

plug what in to find q?

polar ermine
#

-9=-3(-2+4)^2+q

zenith sail
#

yes, that'll work

polar ermine
#

k

#

-9=-3(4)+q
-9=-12q
q=3/4

#

is this right?

zenith sail
#

no, be careful

#

-12+q

#

not -12q

#

in the middle step

#

-9 = -12 + q

polar ermine
#

ohh right

#

3 = q?

zenith sail
#

yep

polar ermine
#

so y=-3(x+4)^2+3

zenith sail
#

yep

#

just don't forget the square 😉

polar ermine
#

ye lol

polar ermine
#

thx man

#

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#
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tropic goblet
#

quick question

cedar kilnBOT
tropic goblet
#

I can't divide 0/0 right? so the second part is wrong

#

and the answer should be y' = 1 or y' = -1 and any T thats not t = 0 or t = -2?

#

is a solution?

#

This is a question about existence and uniqueness btw

#

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trim crescent
#

Could anyone help with this ?

cedar kilnBOT
tropic oxide
#

$|2i \cos(2t) - 2 \sin(t)| = 2 \sqrt{\cos^2(2t) + \sin^2(t)} = 2 \sqrt{1 - 2 \sin^2(t) + \sin^2(t)} = 2 |\cos(t)|$

wraith daggerBOT
trim crescent
tropic oxide
#

$|x + iy| = \sqrt{x^2 + y^2}$?

wraith daggerBOT
tropic oxide
#

and i also factored the 2 out for convenience.

trim crescent
#

Ohhh wow yes of course

#

Thank you so much @tropic oxide, take care ❤️

#

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lilac flame
#

23 + x = 69 what's x

cedar kilnBOT
tropic oxide
#

!status

cedar kilnBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
lilac flame
#

1

fickle trellis
#

How old're you?

tropic oxide
#

do you know basic algebra?

lilac flame
lilac flame
fickle trellis
tropic oxide
#

ok so then do you know such basic moves as "subtract ___ from both sides"?

lilac flame
#

Why would we do that

tropic oxide
#

to get x on its own? cause that's our goal, isn't it?

#

what should we subtract from both sides so that the 23 that's being added to x disappears?

lilac flame
#

Oh yes

#

Ooooooooh

#

x = 69 - 23

tropic oxide
#

yes

#

muhammad asked the question to see if you were under 13 or not

lilac flame
#

Ooooh

#

But what if

#

We took squares on both sides

tropic oxide
#

(23+x)^2 = 69^2?

lilac flame
#

And then used thr quadratic formula

#

Yes

tropic oxide
#

hold on

#

let me think of an analogy for how stupid that is

lilac flame
#

Yes?

#

Ouch

tropic oxide
#

this is like seeing a small pothole in a road, and saying "What if we blew it up with TNT and then put 200 truckloads of concrete into it?"

lilac flame
#

are you saying we shoulda took cubes on bs

tropic oxide
#

fuck no that's nuking it

lilac flame
#

Regardless there's one more question

tropic oxide
#

why are you trying to make this equation more complicated than it needs to be lmao

lilac flame
#

So the question i aksed was q1 part 1

#

Heres the 2nd part

tropic oxide
#

!original

cedar kilnBOT
#

Please show the original problem, exactly as it was stated to you. A picture or screenshot is best.

If the original problem is not in English, then post it anyway! The additional context might still help helpers help you. Do your best to translate.

dim tiger
#

if you want you can raise it to the power of n

lilac flame
#

x^x^3 = 36

lilac flame
tropic oxide
#

$x^{x^3} = 36$?

wraith daggerBOT
tropic oxide
#

also uh

lilac flame
#

Yes

tropic oxide
#

can you take a screenshot

#

seeing these two side by side is mega sus

lilac flame
#

Of myself?

#

Oh of the question

#

Wait

#

Oh shit no my textbook is burnt silly ol me

fickle trellis
#

Are you essentially trying to troll @lilac flame ?

lilac flame
#

Anyways

#

Please solve that question

tropic oxide
#

bruh

lilac flame
regal steeple
#

Nah this dude trolling

dim tiger
#

ok then can you please take a screenshot of the question

lilac flame
tropic oxide
#

you would not

lilac flame
lilac flame
bleak gazelle
lilac flame
#

I have only today

tropic oxide
#

this equation is impossible to solve with simple algebra

bleak gazelle
#

or some enumerator

lilac flame
tropic oxide
#

also how do we know you did not misremember the question

bleak gazelle
#

or microsoft math

lilac flame
#

Can i show my procedure?

tropic oxide
#

sure why not

#

you are really sounding more and more like a troll rn tho

bleak gazelle
#

or something starts with G, with a P in middle and T at the end

tropic oxide
#

off*

#

not that

#

NEVER USE CHATGPT FOR MATH.

lilac flame
bleak gazelle
tropic oxide
#

hm

fickle trellis
#

fakeryc please move elsewhere with your AI advertisement

dim tiger
tropic oxide
#

happy coincidence, i guess?

lilac flame
thorn furnace
#

fun little status u got there too

tropic oxide
#

you could not solve x^x^3 = 37 this way.

tropic oxide
lilac flame
bleak gazelle
#

I'd just grab python

lilac flame
#

Well lovely talk wasn't it fellows

dim tiger
bleak gazelle
#

make a enumerator

lilac flame
livid hound
lilac flame
#

Ann senpai im sorry

tropic oxide
#

yeah it was not lovely at all

fickle trellis
#

Thankyou for the trolling you did.

orchid summit
livid hound
#

if you already had the solution, that you knew was right you didn't really need to come here for that

lilac flame
#

Why tf is the entire server here

tropic oxide
#

@lilac flame are you over or under 13 btw

lilac flame
lilac flame
tropic oxide
#

it matters for the purposes of discord terms of service

#

you're fine

thorn furnace
#

We are gathered here today to let you know mista V that You Suck

tropic oxide
#

we get underage people in here sometimes

livid hound
#

and the difference in level of math compared to your original question
makes people queestion whether your intentions are genuine

tropic oxide
#

^

tropic oxide
#

why open with the most elementary equation possible

fickle trellis
orchid summit
tropic oxide
#

why the bait and switch

#

there's no point in it other than to waste people's time and troll

lilac flame
livid hound
#

of whether you're genuinely here to get proper help
or just troll/waste peoples time

nova snow
#

ok

orchid summit
#

bro what

lilac flame
#

Can i go now?

orchid summit
#

sure

lilac flame
#

I believe i found the my answer

fickle trellis
#

Do you have any other questions that are genuine and not troll messages?

livid hound
#

go whenever, you don't need our permission to leave

regal steeple
fickle trellis
#

Actually yes you can go now

lilac flame
#

Huh

#

Thought you wanted questions

fickle trellis
#

I don't want questions, I meant if you needed any help with more questions

lilac flame
#

{a} what kind of matrix is this is it a scalar, diagonal, square, rectangular

fickle trellis
#

Where is the matrix?

dim tiger
lilac flame
tropic oxide
#

mistav you are trolling

orchid summit
#

fs

lilac flame
#

[a]

dim tiger
#

the guy is a troll

lilac flame
#

Alright now better

dim tiger
#

high level troll

lilac flame
#

NO I AM NOT ISTG

thorn furnace
#

1x1 matrix is all of the above lololo

lilac flame
dim tiger
#

ohh wait

fickle trellis
#

Its a scalar matrix first of all.

lilac flame
thorn furnace
#

it kinda is

#

but its also diagonal

lilac flame
#

Brb

thorn furnace
#

its only nonzero entriesareon the diagonal

orchid summit
#

it's diag as well?

thorn furnace
#

its also square because 1=1

fickle trellis
#

It's also a square matrix

thorn furnace
#

its also rectangular because every matrix is rectangular

orchid summit
#

it's a quadruple matrix opencry

fickle trellis
lilac flame
#

The correct answer was diagonal btw

fickle trellis
#

But anyway this is a help channel

fickle trellis
lilac flame
#

Am i in general chat?

lilac flame
thorn furnace
#

you're in your own help channel

orchid summit
#

how is it diagonal cuh

lilac flame
fickle trellis
#

Okay I'm done here

#

Should we ping the mods

orchid summit
orchid summit
lilac flame
orchid summit
dim tiger
#

you are in general troll my friend

fickle trellis
#

I hate people who are all about their sir.

orchid summit
#

jk

#

jk

lilac flame
#

Wdym

fickle trellis
lilac flame
#

Why

#

Can i go now

fickle trellis
#

Whats a scalar matrix, Mistav?

orchid summit
#

mostav can u tell what a scalar matrix is

lilac flame
sudden pivot
#

wth is happening here

regal steeple
fickle trellis
orchid summit
thorn furnace
#

multiple of identity

lilac flame
fickle trellis
#

Actually we need a modping tbh

sudden pivot
#

do .close

lilac flame
#

Well bye

#

.close

cedar kilnBOT
#
Channel closed

Closed by @lilac flame

Use .reopen if this was a mistake.

fickle trellis
#

<@&268886789983436800> read the help channel please.

orchid summit
thorn furnace
#

its so intuitive if thats notan actual term then it ought to be

fickle trellis
#

Let them decide

thorn furnace
#

why ping mods lmao

dim tiger
orchid summit
#

yo mods we probably got a under 13 year old here

fickle trellis
orchid summit
thorn furnace
#

hes just having his fun at the expense of others

dim tiger
thorn furnace
#

hes kindachillin

orchid summit
#

i was like this when i was 12 👀

cedar kilnBOT
#
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fickle trellis
cedar kilnBOT
sudden pivot
#

close

orchid summit
#

lmao

fickle trellis
#

Seriously

#

.close

cedar kilnBOT
#
Channel closed

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dim tiger
sudden pivot
#

stop talking

fickle trellis
#

Ive never ever created a help channel

nova snow
dim tiger
fickle trellis
#

This is a bug

fickle trellis
#

My message is before the available message

#

anyway vacate

dim tiger
#

my internet is trash images are taking forever to load

slim jasper
thorn furnace
lilac flame
#

Btw i am 16

fickle trellis
fickle trellis
#

Except for the x^x^3 one.

#

.close

dim tiger
#

.close

#

lets end this

#

oh forgot

#

it is already closed

cedar kilnBOT
#
Available help channel!

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agile trellis
cedar kilnBOT
agile trellis
#

.reopen

#

.close

cedar kilnBOT
#
Channel closed

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#
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nimble ibex
cedar kilnBOT
random pivot
#

How can the question be simplified to only sqrt of 5

nimble ibex
#

can someone explain what this means

random pivot
#

oh

#

you did before mb

nimble ibex
#

yh sos

random pivot
#

np

nimble ibex
#

Can someone explain what the question is asking for?

#

surely all integrals go to something

random pivot
#

lol i dont even know what all 3 is

nimble ibex
#

how does that answer my question? slightly confused

random pivot
#

it dont

nimble ibex
#

oh

#

Could someone help me then? Im confused what the question is asking for

random pivot
#

i cant sorry, but someone will eventually help you

cedar kilnBOT
#

@nimble ibex Has your question been resolved?

nimble ibex
#

<@&286206848099549185>

nimble ibex
#

thanks

wicked relic
#

It's saying, is the area finite

nimble ibex
wicked relic
#

Yes

nimble ibex
#

.close

cedar kilnBOT
#
Channel closed

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#
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formal gate
#

Could someone help me with 2 b ? This is what I got for 2 a

prisma gull
#

Haven’t you got help earlier?

formal gate
#

Wbat?

#

Yeh you helped me with 2 a

prisma gull
#

Oh i see

#

do you see, x being a variable can result in different area based on the input for x from part a?

#

4x+4 is rather an equation for finding area when you have a varying length x

#

do you see that ?

formal gate
#

Ye

prisma gull
#

So for different values of x you get different area right?

#

or for a specific area you have the corresponding length specific value for x.

#

now the area of the figure being 18

#

what does that tell you?

#

you have to set the length accordingly so the the total sum becomes 18 right?

#

or 4x+4= 18

formal gate
#

Ye

#

So is it just 4x + 4 = 18

#

Then you switch this sides of 18

#

4x - 14= 0

prisma gull
#

not really switching sides

#

rather subtract 18 from both sides

formal gate
#

Ye

prisma gull
#

better to subtract 4

#

first

#

your goal is make x alone in the right, by undoing the process

#

your x is being multiplied by 4 and added 4 leaving you 18

#

now you undo adding 4 by subtracting 4

formal gate
#

4x = 14

prisma gull
#

yes, now undo multiplication

formal gate
#

X = 7/2 ?

prisma gull
#

sure

formal gate
#

Is that the final answer of the question ?

prisma gull
#

What is the question asking you to find?

formal gate
#

X

prisma gull
#

and what have you found?

formal gate
#

X !!

prisma gull
#

Good job

formal gate
#

Cheers 👍

prisma gull
#

hf

formal gate
#

Do you mind helping with another question ?

prisma gull
#

Claim a new channel and post

formal gate
#

Okay 👍

#

.close

cedar kilnBOT
#
Channel closed

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#
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crude lark
#

Find all angles and sides of a right triangle, knowing angle B and the sum of the cathetus (AB + AC)

crude lark
#

so far I have used pythagora's theorem, this way:

wraith daggerBOT
#

beautiful man

crude lark
#

i am stuck from this point

#

i thought maybe i can write b^2+c^2 as (b+c)^2 - 2bc

#

but sadly the product is not given

crude lark
#

$a^2 = b^2+c^2 = \frac{b^2}{sin^2B}$

wraith daggerBOT
#

beautiful man

crude lark
#

<@&286206848099549185>

cedar kilnBOT
#

@crude lark Has your question been resolved?

cedar kilnBOT
#

@crude lark Has your question been resolved?

#
Channel closed

Closed by @crude lark

Use .reopen if this was a mistake.

crude lark
#

i solved it

verbal compass
#

oh nvm

crude lark
#

yeah

#

thanks tho

cedar kilnBOT
#
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ember geyser
#

how do i do this?

cedar kilnBOT
strange mauve
#

!status

cedar kilnBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
ember geyser
#

2

strange mauve
#

!show

cedar kilnBOT
#

Show your work, and if possible, explain where you are stuck.

ember geyser
#

wait no 3 i mean sorry

strange mauve
#

Still show your work if you have

#

Or what answer did you get

ember geyser
#

-3x+18≥6
18≥6+3x
12≥3x
4≥x

strange mauve
#

Its correct

ember geyser
#

ah

#

i must have typed -4 on accident as thats what a help source had used an example of, sorry for the inconvenience

cedar kilnBOT
#

@ember geyser Has your question been resolved?

#
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#
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hollow garnet
#

Can someone help me get from the thing I underlined in blue to the one I drew the arrow to

cedar kilnBOT
hollow garnet
#

I think I'd have to group them somehow but I'm lost

cedar kilnBOT
#
Channel closed

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hollow garnet
#

.reopen

cedar kilnBOT
#
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karmic vortex
#

Hello, excuse me

cedar kilnBOT
karmic vortex
#

may i ask a question?

#

close

worldly iron
#

.close

worldly iron
karmic vortex
#

.close

cedar kilnBOT
#
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frigid quartz
#

V = span{(1, 1, 2), (1, 0, −1), (2, 3, 1)} What is the base and the dimention?

I can't understand something. For those 3 vectors to be the base, they all have to be linear independent.
How can i check that in a trivial way?
Shouldnt it be like this?
(Uploading pic)

frigid quartz
#

Ignore that B = 1 at the end

proven thistle
#

Add equation 1 and 3

tropic oxide
#

can add equations #1 and #3 and get 3α + 3γ = 0

frigid quartz
#

it becomes alpha = gamma, right?

tropic oxide
#

no

frigid quartz
#

oh

#

Ah, alpha = -gamma?

tropic oxide
#

yes

frigid quartz
#

Doesn't that make them dependent?

tropic oxide
#

who are "they"

#

also you arent done solving the system yet

frigid quartz
#

Let me draft something in a clean paper to show you

tropic oxide
#

put α = -γ into α + 3γ = 0 and you will get γ = 0 and from this the other two letters will also turn out as 0

frigid quartz
#

Yeah I was getting into that

#

Please give me a minute to show my result

#

I jumped a few steps since, I suppose that, knowing that alpha and gamma are 0, using the first equation with that information, beta will be 0 aswell

cedar kilnBOT
#

@frigid quartz Has your question been resolved?

#
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#
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random veldt
cedar kilnBOT
random veldt
#

help

#

online math competition and my team has no remote idea

primal socket
#

I'd feel the same had I been given just this photo

#

Oh hang on, I was

random veldt
#

also

#

any updates?

cedar kilnBOT
#

@random veldt Has your question been resolved?

random veldt
#

Not yet

cedar kilnBOT
#

@random veldt Has your question been resolved?

cedar kilnBOT
#
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violet flume
#

I need to ask about using the fourier transform to solve the heat equation

violet flume
#

I'm working with $$\phi _t = \kappa \phi _{xx}$$

wraith daggerBOT
#

jan Niku

violet flume
#

I'm able to get this with forward transforms and integrating factor to $$\pdv \qty( \hat \phi e^{\kappa n^2 t} )$$ providing $$\hat \phi (t,n) = \hat \phi _0 (k) e^{-\kappa n^2 t}$$

wraith daggerBOT
#

jan Niku

violet flume
#

now I'm confused about the reverse. The thing I'm following says that we want some $S(x,t)$ such that $\mathscr F ^{-1} { \hat S(n,t) } = S$

wraith daggerBOT
#

jan Niku

violet flume
#

this by the definition of the fourier transform im using should mean $$S(x,t) = \frac{1}{2\pi} \int _{\bR} e^{-\kappa n^2 t}e^{-inx} \dd n$$

wraith daggerBOT
#

jan Niku

violet flume
#

I'm having a hard time with this integral is the hard part. Mainly, getting the same thing the guide says

#

we would just be able to complete the square, right?

#

so $\frac{1}{2 \pi} \int _{\bR} e^{ \qty(\sqrt{\kappa t} n + \frac{ix}{2\sqrt{\kappa t}} )^2 + \frac{x^2}{4\kappa t}} \dd n$

wraith daggerBOT
#

jan Niku

violet flume
#

using $\int _{\bR} e^{a(x+b)^2} \dd x = \sqrt{ \frac{\pi}{a} }$, shouldnt this be $$\frac{1}{2\pi} e^{ \frac{x^2}{4\kappa t} } \sqrt{ \frac{\pi}{\sqrt{\kappa t}}$$?

wraith daggerBOT
#

jan Niku
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

cedar kilnBOT
#

@violet flume Has your question been resolved?

violet flume
#

.cclose

#

.close-

#

.close

cedar kilnBOT
#
Channel closed

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#
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pastel surge
cedar kilnBOT
pastel surge
#

could someone help me wit hthis

#

i dont know what im doing wrong

#

i did

sly abyss
#

send your work

pastel surge
#

ok

#

100000 X 1.4 to the power of 3 - 100000 X 1.4

sly abyss
#

you could just do

#

100000 X 1.4 to the power of 5 - 100000 X 1.4 to the power of 3

pastel surge
#

ill try that

#

i got 263424

#

?

sly abyss
#

ye

#

that should be right

pastel surge
#

thanks

#

it workeD

#

could u explain if u have time?

cedar kilnBOT
#

@pastel surge Has your question been resolved?

#
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merry drift
#

Help

cedar kilnBOT
#
Channel closed

Closed due to the original message being deleted

merry drift
#

<@&286206848099549185>

cedar kilnBOT
# merry drift <@&286206848099549185>

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

obsidian coral
#

And not your channel

pastel surge
#

.

merry drift
#

Ok

pastel surge
merry drift
#

Sorry

cedar kilnBOT
# pastel surge

The original post of this help channel has been deleted, and it will abruptly close and possibly lock. (This is irreversible.) Please claim a new channel, and don't delete the first message of any future channel you claim.

obsidian coral
#

You're going to have to wait for this channel to fully close

pastel surge
#

ight

surreal cave
obsidian coral
pastel surge
#

Can i take anotehr one

#

one just opened

surreal cave
#

there's no channels avaliable, damn funny asf ngl

surreal cave
cedar kilnBOT
#
Available help channel!

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echo shuttle
#

Hello, would someone be able to explain this to me:

echo shuttle
#

You buy a stove for​ $1500 on February 20. The store gives you 4 months​ “interest free”, after which you must pay the​ $1500. ​ However, the store charges an administration fee of​ $50, to be paid today. What rate of simple​ interest, r, are you being charged for this​ “interest free”​ plan?

#

I know the answer but I dont know how it arrived at that. The answer is 10.49%

cedar kilnBOT
#

@echo shuttle Has your question been resolved?

cedar kilnBOT
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fickle imp
#

how are these integrals solved differently?

fickle imp
#

i never knew the placement of dx mattered

flint plinth
#

wdym solved differently

#

in the second one, only 6x^5 is being integrated

#

the dx among other things is indicating "end of the integrand"

fickle imp
#

so everything before the dx is what we integrate?

flint plinth
#

yea generally

#

unless you're a physicist weirdo who writes the dx first haha

#

don't be that

fickle imp
#

so the first integral would be x^6 - 6x^3 + 7x + C

and the second integral would be
x^6 - 18x^2 + C ?

#

i lumped the constant 7 into C

#

or maybe we can just leave it as x^6 - 18x^2 + 7

gritty viper
#

Yeah looks right

#

Nothing wrong with lumping the C into a constant

flint plinth
fickle imp
#

thank you guys

#

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cedar kilnBOT
#
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obsidian coral
cedar kilnBOT
#
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inner quest
#

I can not use MCT or LDC

flint plinth
#

what's up with the limit in the first line, there's no n

inner quest
#

yeah its not correct let me reformat it 1 sec (FIXED QUESTION HERE*)

flint plinth
#

ah that's better

#

are there any hypotheses for X, like is it a finite measure space for example

inner quest
#

no

#

Only thing I have shown is that u is also positive measurable and I have shown that \int_X u d\mu \leq 2023

#

and that \int_X u d\mu = 2023 if the sequence is increasing using Beppo levi

inner quest
inner quest
flint plinth
#

hmm, offhand maybe first show that it's true if X has finite measure, then see if you can somehow extend that to the general case. If X were sigma-finite you could use a sequence X_1, X_2, ... of measurable sets with finite measure whose union is X, but in the general case that won't work

cedar kilnBOT
#
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upbeat basin
cedar kilnBOT
upbeat basin
#

why is roc at minor axis b/a^2 ... if a circle is lying below the curce then isnt roc -ve? and even by formula its coming out to be -ve

cedar kilnBOT
#

@upbeat basin Has your question been resolved?

upbeat basin
#

<@&286206848099549185>

#

pls help someone

cedar kilnBOT
#

@upbeat basin Has your question been resolved?

upbeat basin
#

<@&286206848099549185>

restive ibex
#

Yes

#

What's your question

upbeat basin
#

<@&286206848099549185>

upbeat basin
#

<@&286206848099549185>

cedar kilnBOT
#

@upbeat basin Has your question been resolved?

upbeat basin
#

<@&286206848099549185>

upbeat basin
#

...

#

<@&286206848099549185> s

cedar kilnBOT
#

@upbeat basin Has your question been resolved?

cedar kilnBOT
#
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cedar kilnBOT
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wheat silo
#

Let's say I have

Ax=B, is it true that A^-1*Ax = A^-1*B => x = A^-1*B

In general, is A^-1*A = I?

wheat silo
#

nvm, just tried it in matlab, it's true

#

.close

cedar kilnBOT
#
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visual basin
#

how do i solve this question?

cedar kilnBOT
tropic oxide
#

image on its way?

visual basin
#

yeah

tropic oxide
#

!status

cedar kilnBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
visual basin
#

1

#

i think i might need a kinematic equation

tropic oxide
#

yes you do

visual basin
#

but i'm not sure which one

tropic oxide
#

well you might as well start by writing out the equation for its position wrt time

#

like

#

$x(t) = x_0 + v_0t - \frac{1}{2}at^2$

wraith daggerBOT
tropic oxide
#

and also $v(t) = v_0 - at$ while we're at it?

wraith daggerBOT
tropic oxide
#

like ok there is probably a pre-derived one

#

but i don't remember it off the top of my head

visual basin
#

v_0 is initial velocity, and x_0 is initial distance, right?

#

v(f)²=v(i)²+2ad
24²=2ad
a=576/38.4

#

a=-15ms⁻²

#

thanks

#

what about this one?

#

i think i might need simultaneous equations

#

but i'm not sure how to implement it

#

@tropic oxide

tropic oxide
#

you don't really need simultaneous equations here

#

you can find the rate at which A catches up to B

visual basin
#

you mean something like 340/280?

tropic oxide
#

no

#

if you run at 5 km/h and i run at 8 km/h at what rate would i be catching up to you

visual basin
#

3km/h

#

oh

#

so it would be 60kts

tropic oxide
#

yes

#

so how long does it take to close the 210 NM gap at 60 kt

visual basin
#

3.5 hours

#

at the speed of aircraft b, 3.5 hours covers 980 NM

#

ok

#

thanks

#

i have 1 more

#

@tropic oxide

tropic oxide
#

too tired for this shit sry

visual basin
#

okay

#

i'll look online

#

thanks for all the help

onyx dove
#

ideal gas law yes?

visual basin
#

uh

#

yeah

#

i'd imagine

onyx dove
#

then what's the problem

visual basin
#

i haven't studied it

#

not that i was too lazy to study or anything, i was just never taught it to begin with

onyx dove
#

but you're supposed to know it for whatever this is for?

visual basin
#

yeah

#

that, and a whole bunch of other things

onyx dove
#

a great teacher

#

so the law states $PV=nRT$, R=8.314

wraith daggerBOT
#

chlamydia

visual basin
#

i'd imagine p is pressure and v is volume

onyx dove
#

yes

visual basin
#

r seems like a constant

onyx dove
#

T in kelvin

visual basin
#

temperature, okay

#

and that's n?

onyx dove
#

for mols

visual basin
#

mols are a measure of the amount of a substance, right?

#

sorry, i don't do chemistry

onyx dove
#

oh

#

well yeah

visual basin
#

does the equation work without n?

#

@onyx dove

onyx dove
#

yeah constant n and V

visual basin
#

wait
i don't need to know n, do i?

onyx dove
#

so they're not needed

visual basin
#

yeah

#

so oneside changes exactly as much as the other side

#

i know that 22c in kelvin would be 295.15

stark ocean
#

any1 know linear interpolation?? #help-19

visual basin
#

p increases by a factor of 2/3
so T would also increase by the same amount, right?

onyx dove
#

yeah

visual basin
#

so it's about 494k?

#

huh
492

#

close enough

#

especially since i can't even use a calculator for this exam

#

on the bright side, it's only MCQs

cedar kilnBOT
#

@visual basin Has your question been resolved?

cedar kilnBOT
#
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prisma gull
cedar kilnBOT
prisma gull
#

Can you check if the proof is correct

#

as well as help me with proper way to write it

tropic oxide
#

you didn't write your epsilons correctly

#

$\ep$ should not look identical to $\in$

wraith daggerBOT
tropic oxide
#

other than that it seems fine.

prisma gull
#

Is the scrarch work written in proof side?

#

I feel like we do scratch work backwards in proof

crimson delta
#

I would make it more explicit where you are using the triangle inequality

#

you should get used to writing a chain of inequalities, instead of inequality implies inequality implies inequality

#

and the proof should start with "let epsilon>0 be given"

crimson delta
#

|an+bn-a-b|<=|an-a|+|bn-b|<eps/2+eps/2=eps

prisma gull
#

I see

prisma gull
crimson delta
#

yes

prisma gull
#

I’m making use of things I’m guaranteed from other two convergence

crimson delta
#

in general, any symbol you use in the proof also has to be introduced somewhere

prisma gull
#

right

#

my epsilon came out of the blue

#

Thanks for pointing it out

#

Essentially the choice we take from the definition of convergence of (bn) is after we fix epsilion for (an+bn) right?

#

i think that’s what you mean

crimson delta
#

yes

#

for an+bn you have to show it for any epsilon

#

for bn you can use it for any epsilon

#

which you do for epsilon/2

prisma gull
#

makes sense now

#

Thanks again, have a great day!

crimson delta
#

u2

prisma gull
#

.close

cedar kilnBOT
#
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olive olive
cedar kilnBOT
olive olive
#

i did part (a) and (b) but need help on (c). i feel like its true but im not sure how to explain it

crimson delta
#

still try explaining

olive olive
#

like for any bounded function where n exists, it is strictly bounded under k = n + 1
similarly, for any strictly bounded function where k exists, it is also bounded under n = k

#

i dont feel like this is "valid"

crimson delta
#

it is

olive olive
#

alright thanks

#

.close

cedar kilnBOT
#
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civic coral
# wraith dagger **Ann**

Given there’s 9 balls in a bag, in which 2 of these 9 balls are named number 2, 3 of them are number 3, and 4 of them are number 4. Now we pick 3 balls from the bag, what is the expected value of the number sum?

civic coral
#

This question is quite time-consuming.
If you list out all of the possibilities for the numbers of these 3 chosen balls.

However,

My textbook mentiond that the EV would equal to the EV with just one pick from the bag multiplied by 3
And that sounds like a cap to me

#

I wonder how the clever trick works

muted bear
#

Do you put the ball you picked back?

#

Because if so, the textbook is right

civic coral
muted bear
#

The book is wrong

civic coral
muted bear
#

Oh it is?

civic coral
#

it is

muted bear
#

Instinct told me otherwise

#

Lemme think about it more then

civic coral
muted bear
#

!original please

cedar kilnBOT
#

Please show the original problem, exactly as it was stated to you. A picture or screenshot is best.

If the original problem is not in English, then post it anyway! The additional context might still help helpers help you. Do your best to translate.

muted bear
#

Still thinking about it, but i just want to be sure

civic coral
#

it is not being written in English, but i will send it tho

sacred grail
#

the book is right

civic coral
muted bear
#

Yooo hi snow

#

Im curious to see why it is right too