#help-13

1 messages · Page 189 of 1

rustic siren
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you didnt divide the 32, only the first part

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but the main problem was before that, you didnt factor the top part ideally, it should be (x-8)(x+4)

dreamy lava
rustic siren
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find 2 numbers that add up to -4, and multiply to -32

cedar kilnBOT
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@dreamy lava Has your question been resolved?

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dreamy lava
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.reopen

cedar kilnBOT
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dreamy lava
rustic siren
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the coefficient is -4

cedar kilnBOT
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uneven siren
cedar kilnBOT
uneven siren
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spent almost 1hr by now

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can anyone explain this?

dreamy lava
uneven siren
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....

foggy tendon
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Whenever a vector component is inclined to an angle you should resolve it into x and y

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But it’s only moving in x direction right?

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If you ask me I would solve for the A there, then find the velocity for the B from A

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So it’s given that A is moving in x with v0

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And how fast the string is moving on the left side = to how fast the string is moving on the right side

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v0 is in the x direction, using the definition of trigonometry, you will find the velocity component in the direction of the string, and that should be equal to the velocity of the string falling

foggy tendon
cedar kilnBOT
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@uneven siren Has your question been resolved?

cedar kilnBOT
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cold briar
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In an arithmetic progression where the common difference is 1/2, given S_100 = 145, find S_99.

cold briar
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So what I first thought of doing was.

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wait nvm

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i wasovercomplicating everything

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.close

cedar kilnBOT
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stiff totem
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it doesn't look like it's S_99 by the way

cold briar
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oh wait

stiff totem
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it's just the odd terms, a_1, a_3, ...

cold briar
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.reopen

cedar kilnBOT
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cold briar
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odd terms

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haha

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okay

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i definitely didn't misread that...

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so...

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just make the common difference 1 and the number of terms is 50

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okay

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.close

cedar kilnBOT
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cold briar
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just find a_1 and i'm done

cedar kilnBOT
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median mason
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Greetings can someone help on this system equation have been stuck for 30 minute

median mason
cold briar
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why not find xy first?

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x^2 + y^2 + xy = 75
x^2 + y^2 - xy = 25


2 xy = 50
xy = 25

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@median mason

median mason
cold briar
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but you still don't have any progress tho

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you'll end up with
x^2 + y^2 = 50 on both equation

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wait... is x and y integers?

median mason
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No

cold briar
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are you supposed to find x and y?

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or some other expression?

median mason
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Yes

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4 answers

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I need to find x and y

median mason
cold briar
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it's xy - (-xy) = 50

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2xy = 50

median mason
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Oh

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So did u find any solution

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<@&286206848099549185>

muted timber
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you start by getting two different equations.
The first one is the sum of both equations:
2x^2 + 2y^2 = 100, which means that x^2 + y^2 = 50
The second one is the difference of both equations:
2xy = 50, which means that xy=25; That means that y=25/x
You substitute that in the previous equation:
x^2 + (25/x)^2 = 50
When solving these you will get a biquadratic equation, which means 4 solutions of x.
Each solution of x will get a unique solution of y.
Each (x,y) pair will give you one of the four solutions of the problem

median mason
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So like x1 = 5 x2 = -5, y1=5 , y2=-5

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.close

cedar kilnBOT
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junior hollow
cedar kilnBOT
junior hollow
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how do u find the innequality for this?

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thanks!

dim tiger
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alright for part a

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$x^2\geq 3x\implies x^2-3x\geq 0\implies x(x-3)\geq 0$

wraith daggerBOT
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calculus is fun

dim tiger
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do you know table of sign ?

junior hollow
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ohh

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so we put it in like

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the format

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and then what?

dim tiger
junior hollow
dim tiger
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ok no problem

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we got x(x-3)>=0

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now we have 2 cases

junior hollow
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mhm

dim tiger
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for a product of 2 factors to be positive we need either both factors to be positive or both be negative right

junior hollow
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yeah

dim tiger
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ok so first case we have x>=0 or x-3>=0

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what will this give ?

junior hollow
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OHHH

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so we sub in values that make sure that its greater than zero?

junior hollow
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wait what

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idk?

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x= -3

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positive*

dim tiger
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do you know how to solve inequalities

junior hollow
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3

junior hollow
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since i mean usually we need to bring all values to one side

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solve it as normal

dim tiger
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ok if i have x-3>0 then where does x lie

junior hollow
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get 2 values

dim tiger
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in which interval

junior hollow
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plot it on a number line

junior hollow
dim tiger
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3 is a number not an interval

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do you know what is an interva

junior hollow
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nope

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confused

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cant we just find the values, put them on a sign diagram, and find out the answer?

dim tiger
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what is a sign diagram

junior hollow
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oh-

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like, usually, we plot the values after factorising the equation

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on a numberline

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we sub in a value greater than the positive value, smaller than the negative value, or somewhere in between the two values

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to find out which applies to the signs : < or > or equal and > <

dim tiger
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something like this

junior hollow
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YeAHH

dim tiger
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ohh ok so you just plug numbers

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ok then lets do that

junior hollow
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uh huh

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tyy

dim tiger
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x(x-3)>=0

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this is factorized form

junior hollow
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oh

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yeah-

dim tiger
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what are the roots

junior hollow
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3?

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i think?

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im not so sure

dim tiger
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and ?

junior hollow
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since theres a x infront- of the brackets

dim tiger
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roots are the zeros of the equation

junior hollow
dim tiger
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the values of x where the expression becomes 0

junior hollow
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Oh

dim tiger
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$x(x-3)\geq 0$

wraith daggerBOT
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calculus is fun

junior hollow
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so sqrt 3?

dim tiger
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when does x(x-3) become 0

junior hollow
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when?

dim tiger
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at which values of x

junior hollow
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idk

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do i just sub in random values?

dim tiger
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no

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follow me

junior hollow
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or like a value greater than 3 and smaller than 3?

dim tiger
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we have a product of 2 factors

junior hollow
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yes

dim tiger
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if one of them is 0 what happens to their product

junior hollow
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oh so equate x to 0?

dim tiger
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nice

junior hollow
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it would be -3x

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wait

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WAIT

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nono

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sorry

dim tiger
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and equate x-3 to 0

junior hollow
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0

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it would be 0

junior hollow
dim tiger
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ok so the roots are 0 and 3

junior hollow
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wait what

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they are seperate roots?

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i thought it was just one whole thing

dim tiger
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these are values of x when the product is 0

junior hollow
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and if we equate it to 0 its o

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0*

dim tiger
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this is an inequality

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but to solve it we need to solve the equation $x(x-3)=0$

wraith daggerBOT
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calculus is fun

dim tiger
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now x(x-3) is a product of x and x-3

junior hollow
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yeah-

dim tiger
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if x=0 then x(x-3)=0(0-3)=0

junior hollow
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yeah

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so its 0

dim tiger
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and if x=3 then x(x-3)=3(3-3)=3(0)=0

junior hollow
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yeah

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but where r u getting these x values?

dim tiger
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so x(x-3) is 0 when x=0 or x=3

junior hollow
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oh

dim tiger
junior hollow
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thats the answer

dim tiger
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$x(x-3)=0\implies x=0$ or $x-3=0\implies x=0$ or $x=3$

junior hollow
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so we r right

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where did x=3 come from

wraith daggerBOT
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calculus is fun

junior hollow
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do we just takr the answer from the brackets only

dim tiger
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look

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the concept is like this

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we have z=xy ok

junior hollow
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ok

dim tiger
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we want z=0

junior hollow
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ok

dim tiger
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now xy is a product of x and y

junior hollow
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ye

dim tiger
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a product is 0 when at least one of its factors is 0

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isnt this right

junior hollow
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yeah

dim tiger
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the factors of z are x and y

junior hollow
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uh huh

dim tiger
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so z=xy is 0 when at least one of its factors is 0 so x=0 or y=0

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did you get the concept

junior hollow
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ok

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but where did the 3 come from

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like i get that theres a 0

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but

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why did u take out the (x-3)

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and equate it to 0

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oh wait

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nvm

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ok

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i got it

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i understand now

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so the x outside of the brackets is individual

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correct?

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so its -0

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=*

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and (x-3)=0 is positive 3

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and then we have the values for the

dim tiger
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exactly

junior hollow
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okok

dim tiger
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the factors here are x and x-3

junior hollow
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yah

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got it

dim tiger
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niceee

junior hollow
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i was confused at first since i thought they were a whole one

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ok what abt the second one tho

dim tiger
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np

junior hollow
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x^2<4

dim tiger
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we didnt solve the inequality yet

junior hollow
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oh do we just do the same?

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OH

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rigth

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so

dim tiger
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we still need to solve the inequality

junior hollow
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sub in a value greater than 3

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smaller than 3

dim tiger
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now plot 0 and 3 on the number line

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sub value less than 0 a value between 0 and 3 and a value greater than 3

junior hollow
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yup

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the answer is

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x is greater or equal to 3

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and x is smaller or equal to 0

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yayy

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ok

dim tiger
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great

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now for the second one

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x^2<4

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so x^2-4<0

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now factor x^2-4 into product of 2 factors

junior hollow
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u cant rly factor it tho

dim tiger
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why cant you

junior hollow
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o wait

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squareroot 4

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so x<2

dim tiger
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what is sqrt(4)

junior hollow
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squareoot

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brb, tysm for the help so far tho

cedar kilnBOT
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@junior hollow Has your question been resolved?

cedar kilnBOT
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hearty vector
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Any idea how to solve this

cedar kilnBOT
hearty vector
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<@&286206848099549185>

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This is the original equation

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<@&286206848099549185>

spice folio
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Solution does not exist in real numbers

cerulean harness
hearty vector
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Wtf

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It says 0 in the answers

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Ok thx

cerulean harness
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U do it by urself first

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Letting 3^x as a

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Then applying the quadratic equation

hearty vector
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What?

cerulean harness
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?

hearty vector
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U said there is no answer

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I the real numbers

cerulean harness
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Wdym?

hearty vector
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Rational

spice folio
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it is actually 0 if you go trial and error

hearty vector
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How do i get to that

spice folio
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wait, mb

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forgot the log

hearty vector
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Zero is a rational number

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No

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Im stupid

cerulean harness
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Also,
0 can't be the ans

spice folio
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yes

hearty vector
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Ok thx

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I checked myself

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Mistake

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In the book

cerulean harness
hearty vector
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.close

cedar kilnBOT
#
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keen nova
#

i am struggling to see how this can be right

keen nova
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basically the last step states this:

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,rotate

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,rotate

wraith daggerBOT
keen nova
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yet, here they are treating MP as if it was the hypotenuse

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taking MP^2 - r^2

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TP will always be larger as long as TMP is 90 degrees

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i don't get it

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more context :

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THIS HAS TO BE WRONG

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YET THEY MAKE ME SPEND HOURS ON THIS BUT THE QUESTION HAS TO BE WRONG

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oh my god i am so mad

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please someone tell me i'm wrong

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okay i realized my mistake

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.close

cedar kilnBOT
#
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cedar shale
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Only got the center correct other two are wrong, even tho a site says I'm right

cedar shale
cedar kilnBOT
#

@cedar shale Has your question been resolved?

cedar kilnBOT
#

@cedar shale Has your question been resolved?

cedar kilnBOT
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worn forge
#

Hi there! I'm trying to figure out how to build a formula that explains a bunch of variables, but I'm very new to math... I'm passionate about video games and always get "lazy" about math.. I figure it's time to fix this problem... I never got a proper education in mathematics, but since I'm finding myself doing wiki pages for games I love, I'm now finding I can't run from this any more. is anyone willing to help me figure out how to write down a "Chance to hit" formula?

I know how it works logically, I just don't know how to explain it using mathematical symbols... it's the notation that's the problem here. Should be easy to answer for someone who's involved in this. 🙂

narrow wagon
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A chance to hit is a percentage often like 84% this means it's a ratio. You could think of it as 84 hits / (84 hits + 16 misses), or 84 hits out of 100 tries.

I'm not sure if you're asking how to design a more interesting formulation using more variables (attack level, evasion of enemy etc), if so you could mention them here

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Ah ok I think I misread your question, you're asking for symbols so you can write a wiki page?

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I think as long as the ratio is clear (It should have a numerator and denumerator) I think it makes sense

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I don't think you need anything fancy symbols

worn forge
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Sure, so, here's the way this works.

the game is Final Fantasy XII: The Zodiac Age (The remaster)

Evasion comes from shields and weapons in this game, and if you're playing the original on PS2, there's an accessory that conditionally adds chance to avoid.
the game does a series of checks.

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The game assumes from a starting point that chance to hit is 100.

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there are 4 variables (I think that's what they're called? oop) that go against this
Mechanics of Damage Avoidance

Damage Avoidance has 4 checks as to whether the defender successfully avoids damage, in order:

  1. Shield Block
  2. Weapon Block
  3. Parry
  4. Miss
narrow wagon
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Yeah so you can represent conditional variables by setting some function that evaluates to 1 when true and 0 otherwise

so

20 + I_shield * 40 will give 60 if I_shield is true, 20 otherwise

worn forge
#

Here's where it gets nasty... this engine doesn't behave like that does.

narrow wagon
worn forge
#

So, say it's between you and I, you're the attacker using a magic spell.

narrow wagon
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need to attend class will try to check later

worn forge
#

Sure, I'll type it out and you can look when you can. 🙂

cedar kilnBOT
#

@worn forge Has your question been resolved?

worn forge
#

The game has augments which are passive skills, and technicks and magicks which are actives (Abilities for shorthand), you have to DO those.

Game has two types of attacks, physical and magickal. (Spelling is old timey)

The attacker has 100% chance to hit unless:

  • Windy/Heavy Rain/Snowstorm/Sandstorm and using a bow (x0.5) or crossbow (x0.8)
  • Blinded (x0.5)

so, worst case, we're walking in with 25% accuracy, but not always.
the formula needs to reflect these as potential variables.

Outside of this, it's on the defender's side.
This is done in a series as follows:

  1. defender's shield block
  2. weapon block
  3. parry chance
  4. miss chance (unknown variable, honestly, always been a mystery, miss is pretty rare, though.)

Before the game does any math, though, it asks itself 3 conditionals

  1. Does the attacker have the Ignore Evade augment (Yes/No?) [if yes, skip shield block, weapon block and parry.]
  2. [If No] Can the ability be evaded? (abilities can be blocked or evaded, but they cannot miss. this is how you get around bad weather as a blind bowyer, but some abilities like the spell "dark/darkness" have an innate "Ignore Evasion" property as well, so it'll entirely ignore any chance to avoid. [so, it will ignore the defender's shield block, weapon block, parry, and it cannot miss.]
  3. [If Yes] What type of damage is the defender taking? (Physical or Magickal)
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So say after all this, attacker doesn't have ignore evade, the ability doesn't have ignore evade, and we're taking magickal damage.

Conditionals:

  • "Shield Block" augment for Defender. (can have up to 3) "adds a flat 5% chance to evade to a shield per stack" but ONLY in categories your shield has.

so if you have 3 SB Augments (+15/+15) and your shield has 15 Physical and 15 Magickal evasion, you'll have 30 of both evasion types from your shield.

  • if it has 15 magick evade and 0 physical evade, you'll have 30 magick evade and 0 physical evade.
  • if you have 15 and 1, you'll have 30 and 16... it only applies where the shield is positive.

so if we have a magickal attack (Always 100% accurate) and we have 10 Magick Evasion on the shield, and 2 Shield Block Augments, I have 20% chance to evade. which is 80% chance to hit.

THEN
If my weapon has 10% magickal evasion, it takes 10% off of OF 80%

THEN
You can't normally parry, it requires a specific item to be worn as your accessory, if you're wearing it, parry is always 30% chance.

THEN it rolls for a miss. (We don't know the chance of this to occur exactly)

So it then runs a probability chain, Accuracy - Shield's Chance to Avoid = 80%
did that hit? yes.

okay, 80 - Weapon's chance to avoid = 72%

Did that hit? yes

Okay 72 - Parry = 50.4

Did that hit? yes

Cannot Miss
HIT!

worn forge
# cedar kiln <@106637056335216640> Has your question been resolved?

For clarity:
Evasion and Block are the same thing, evading is blocking, blocking is evading according to this game, so that's the same variable. (I think that's the name for it)

so, you can't "block" per se, you evade.

So you evade (block), parry, or the attack misses.
"Miss" is a random outlier, you can't modify the chance of it occurring. it basically only occurs as a last ditch before deciding whether you got hit or not.

#

If anyone has any questions regarding how this works, just ask! 😄

I'm just trying to come up with a formula I can put on the wiki, lmao.

cedar kilnBOT
#

@worn forge Has your question been resolved?

cedar kilnBOT
#

@worn forge Has your question been resolved?

worn forge
#

No

cedar kilnBOT
#

@worn forge Has your question been resolved?

narrow wagon
#

so assuming you want to write a wiki page for this game you could write it two ways. The first is very similar to how you wrote it here where you just explain the effects of each conditional, this is honestly probably preferred if you want the people to fully understand what's happening

#

if you want to write it in a single line of math it will be ugly. However, you can abuse the indicator functions that I mentioned earlier.

Ill just make an example here:

The attacker has 100% chance to hit unless:
Windy/Heavy Rain/Snowstorm/Sandstorm and using a bow (x0.5) or crossbow (x0.8) Blinded (x0.5)

Let the function Weather(X) = 1 when X = Windy, Heavy Rain, Snowstorm or Sandstorm and 0 otherwise. You can defined these function as piecewise (https://wikimedia.org/api/rest_v1/media/math/render/svg/e3977eccbf90d95798f9d4c30f04a8ad7ac45974)
Let the function Bow(Y) = 1 if a bow is used, 0 otherwise, same logic from crossbow and blinded.

Just to make sure I interpret this correctly its if the weather is BAD and you are using a bow OR crossbow you get a penalty, and you get blinded penalty regardless of weather.

We can also drop the X and Y for convenience

Chance to hit = (1 - Blinded * 0.5) * (1 - (Weather * ((Bow * 0.5) + (Crossbow * 0.3)))

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assuming you cannot use both a bow and a crossbow at the same time

worn forge
narrow wagon
#

might have messed up some numbers but does this help

worn forge
#

kind of? because I'm not even sure how indicators work, may I DM you for the purposes of this question and call this room closed?

#

It's okay if you say no! I'm trying to learn mathematics and I'm a bit of a scrub.

narrow wagon
#

I'm a bit busy rn, but I wish some other person would check this

worn forge
#

Poke em? kekw

narrow wagon
#

ideally someone who actually does probability lol

#

let me check

#

Idk anyone I can ping but perhaps you could use the help forum (because those post stay up for longer) and copy paste what you wrote

#

alternatively you could post on reddit maybe

worn forge
#

This doesn't mean anything to me, btw.

#

It references itself it so many places that it can't do anything.

#

how can X = -itself if it's less than zero

how can X= +itself if it's greater than or equal to zero?

#

I don't know what these symbols mean lmao.

woeful flame
#

|x| means the absolute value of x

#

if a number is less than 0, multiply it with -1, which give us an ans as the abs value
and if a number is greater than 0, the abs value is itself

#

-x which means to the ans of the duplication (x*-1), -x mustn't be considered as a negative integer

woeful flame
#

actually, it is meaningful if 'x*-1' is written instead of '-x', and 'x' instead of '+x'

dapper raven
#

The vertical line means absolute value which is just how big the number is, not caring about if it is positive or negative

woeful flame
#

yes

#

I forgot to tell that

dapper raven
#

The curly bracket thing { is the notation for a function with two(or more) different conditions. This is known as a piecewise function

#

The reason it is -x is because when you have |X| if X is negative that means you have a number like '-a' and in order to find the size of the number you add another - in order to just get a

#

The commas and text after that indicates that for any number X , if X is less than 0 aka negative then use -x

#

and the same for the bigger than or equal to 0

#

Where instead of adding a - in front you just take the number as it is

cedar kilnBOT
#

@worn forge Has your question been resolved?

cedar kilnBOT
#
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winter rose
#

is there any "steps to follow" to find the boundaries of a convex real function of single variable?

winter rose
#

my notes just have all kinds of proof, but nothing on how to use them and such

#

given a function f(x) of the form ax^k, bx^(k-1) ... where a, b, ... are constant coefficients, and k is the an integer (that is the order? of the function, if i am using the term right), and no "funny" stuff like trigo for the moment,

i am told f(x) is convex in some interval [a,b] (unrelated to the a and b above), where a < b.

to find a+b

#

my thoughts are to twice differentiate it?

#

and then it must be greater than 0

crimson delta
#

yes

winter rose
#

that's it?

#

then i gues, the issue is just me and my algebra skills then

#

.close

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livid tundra
#

can someone explain

cedar kilnBOT
livid tundra
#

I want to know how we got ln (1)

tropic oxide
#

$\lim_{b \to -\infty} \frac{b-1}{b+1}=1$

wraith daggerBOT
livid tundra
#

I take the highest degree?

tropic oxide
#

sure...

livid tundra
#

-infinity/-infinity = 1?

tropic oxide
#

yes but you should never write it this way

livid tundra
#

Okay thanks

#

How did we get to this?

tropic oxide
#

u = sqrt(x) => x = u^2, and dx = 2u du = 2 sqrt(x) du

livid tundra
#

and then I replace the value of x in 2 sqrt(x)

#

2sqrt(u^2) ?

tropic oxide
#

overthinking it

livid tundra
#

sorry?

tropic oxide
#

ok let me write it in full

#

$\int_0^{\infty} \frac{\dd{x}}{(1+x)\sqrt{x}} \overset{x=u^2}{=} \int_0^{\infty} \frac{2u \dd{u}}{(1+u^2)u}$

wraith daggerBOT
tropic oxide
#

agree or disagree?

livid tundra
#

yes

tropic oxide
#

this was not a yes/no question

livid tundra
#

Are you mentally okay?

#

One of the definitions of exactly is “a reply used to confirm or agree with what someone has just said.” Like absolutely and definitely, you can also add “yes” to this I agree synonym.

tropic oxide
#

"agree" is only two characters longer

livid tundra
#

I'm not here for english I'm here for math

tropic oxide
#

well i've already told you the math you asked about, save for one (1) cancellation

livid tundra
#

wdym save for one(1) cancellation

tropic oxide
#

i did not cancel out the u's from the top and bottom.

cedar kilnBOT
#

@livid tundra Has your question been resolved?

cedar kilnBOT
#
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chilly spade
#

stuck on this calculus question

cedar kilnBOT
chilly spade
#

diff calc

#

not sure how to approach

spice kraken
#

calculate the total profit in terms of x

chilly spade
#

so like total profit =

#

this one is better:

celest sentinel
#

be careful; the cost is "per x blankets", while the market value is "per 1 blanket"

chilly spade
#

oh

#

so i multiply the selling price by x?

celest sentinel
#

Yeah, that should work

chilly spade
#

alr swt

#

cheers

#

.close

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ripe cliff
#

need to find det(2B^(−1))

cedar kilnBOT
ripe cliff
#

i don't understand how to turn A matrix into B or something like that

#

that's what i got and don't know what to do next

earnest socket
#

probably better to try transforming B into A

#

rearrange columns of B, and then transpose

#

(modifying the sign of the determinant correspondingly)

ripe cliff
#

okay

#

em... i can't just multiply the rows can i?

cedar kilnBOT
#

@ripe cliff Has your question been resolved?

ripe cliff
#

.close

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strange bronze
cedar kilnBOT
strange bronze
#

How do you simplify the denominator?

#

I can't make (tan^2(x)+1) to get to sec^2(x)

#

Or idk how

#

Oh wait a minute

#

.close

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crimson sedge
#

Let A be a 3×3 matrix. Let B be a column vector such that $B^TAB$ is 0.
If I take transpose both sides, then $B^TA^TB$ is 0. I don't know what information I can extract from this. Does this imply A is symmetric?

wraith daggerBOT
#

- Miles12345

crimson sedge
#

<@&286206848099549185>

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

crimson sedge
#

<@&286206848099549185>

spice spoke
#

without giving any more infos on B, then not necesarily. Take B zero vector. then B^TAB = 0 is true, but A can be anything.

#

@crimson sedge

crimson sedge
#

What if B is non-zero

spice spoke
#

take any A with A11 = 0, take B=e1. Then again u have the equality but A can be anything up to the A11 entry

#

and B is not zero

#

Maybe give more context, is it a part of proof?

crimson sedge
#

,rotate

wraith daggerBOT
#

Couldn't find an attached image in the last 10 messages.

crimson sedge
#

,rotate

wraith daggerBOT
crimson sedge
#

Question 2

spice spoke
#

it literally says for EVERY vector B u have the equation AWOOKEN

crimson sedge
#

Yea

#

But like

#

I don't even know how to proceed or what information to extract if I consider general case. So I thought to consider special cases and get to the answer

spice spoke
#

if B is a column vector aint a B^TAB just a number?

crimson sedge
#

Here's my rough work. It may seem weird due to the assumptions I'm making

spice spoke
#

then why it says BTAB is a zero matrix

crimson sedge
#

That's what confused me initially but I thought it's taking 0 as [0] (a 1×1 matrix) lol

spice spoke
#

ye technicaly correct but still weird. Anyway take B=ej for j=1,2,3 plug in into equation B^TAB = 0

#

what it says about A?

crimson sedge
#

Well nothing except it's a 3×3 matrix, and some values of its elements

#

Oh wait

#

Lemme plug

spice spoke
#

ye u know the diagonal entries of A

crimson sedge
crimson sedge
#

Wait wait

#

I did a big mistake

spice spoke
#

nonono

#

B = e1 = [1,0,0]

crimson sedge
#

Ohh

spice spoke
#

B = e2 = [0,1,0]

crimson sedge
#

My bad

spice spoke
#

a13 a23 a21 are given aswell for free

crimson sedge
#

Yes

#

Oh I see

#

I have to form something like a system of equations and solve it?

spice spoke
#

probably for the rest of unknowns entries, but atleast u know diagonal entries immediately if u plug e1,e2,e3 in

crimson sedge
#

Perfect

spice spoke
#

oh ye try plugin [1,1,1] u will find a12 that way

crimson sedge
#

Thanks a lot!

spice spoke
#

no problems

crimson sedge
#

.close

cedar kilnBOT
#
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crimson sedge
#

If......, calculate

cedar kilnBOT
crimson sedge
#

I have done this, but I don't know if it's correct

wintry pier
#

!noclopen

cedar kilnBOT
#

Please don't repeatedly close and claim a new channel with the exact same question. This erases all previous progress made towards your problem and is confusing for helpers, making it more difficult to help you. Please be patient, even if your channel has not received much attention.

crimson sedge
#

oh okay, I wanted to pin the question and put then my answer

#

this is why I opened another one

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

#
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turbid spoke
#

Someone can help me

cedar kilnBOT
turbid spoke
#

with mathemathic discrate

mild coral
#

ok im going to read your mind and help you

crimson sedge
crimson sedge
turbid spoke
#

wait let me find

#

how i can make venn diagram

turbid spoke
turbid spoke
crimson sedge
turbid spoke
#

Okay thx

crimson sedge
#

A universal set as a big box

#

And then three intertwining circles, name them set A B C

#

Then like
Keep the commons of set A and B between the common area of circle A and Circle B

#

Similarly for all

#

Thinsg that dont come in A B C circles, will be inside the box outside of all the circles

#

And things that come in all three sets A B C , will be in the commonplace of all the three circles

#

Whichever you understand the best 👍

#

@turbid spoke

turbid spoke
#

oh i see

#

If they are not in any set, it is u

#

?

crimson sedge
#

Yep

turbid spoke
#

Ohhh thx bro

#

hey

#

where i can solve venn diagram word problem?

crimson sedge
#

What

#

You uave a question?

turbid spoke
crimson sedge
#

Ummm idk

turbid spoke
#

yes i need solve word problem

crimson sedge
#

Khan academy prolly

#

Wait

turbid spoke
#

with set theory

crimson sedge
#

What grade are you in

turbid spoke
#

university

crimson sedge
turbid spoke
#

oh

#

but

turbid spoke
crimson sedge
#

And i cant find specific site for word problems on solvjng sets using venn diagrams

turbid spoke
#

sow |A| + |B| - | A(intersect) B|

#

you can remember?

crimson sedge
#

Wait

#

Yeah

#

Ik

turbid spoke
#

Does it always start with the intercept or are there exceptions?

crimson sedge
#

The words you use go over my head but
Yes
Like youre given n sets
(Add all singletons) - (all intersection pairs) + (3 intersetions ones) - (4intersection ones) .... ±(n intersections)

crimson sedge
#

@turbid spoke

turbid spoke
#

ow

#

thx for help me

cedar kilnBOT
#

@turbid spoke Has your question been resolved?

cedar kilnBOT
#
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gusty rune
#

can someone help me with this

cedar kilnBOT
digital cliff
#

do you know soh cah toa

gusty rune
#

a little

digital cliff
#

o=opposite, h=hypotenuse, a=adjacent
sin=o/h
cos=a/h
tan=o/a

gusty rune
#

okay

digital cliff
#

what would sin(A) be

gusty rune
#

5/13

digital cliff
#

yup

#

are you aware of what csc, sec and cot are?

gusty rune
#

no not at all

digital cliff
#

its not too bad really:
cosec=csc=1/sin
sec=1/cos
cot=1/tan

#

just the reciprocals

gusty rune
#

so 13/5

#

is csc a

digital cliff
#

it is indeed

gusty rune
#

thank you

#

so is this correct

digital cliff
#

looks good to me

gusty rune
#

okay and now what do i do for sin b

#

the same thing

digital cliff
#

yup, just from B rather than from A

gusty rune
#

so where would the adjacent and opposite be

digital cliff
#

with respect to B, 5 is adjacent

#

12 is opposite

gusty rune
#

so 13 is still the hyptonuse

#

.close

cedar kilnBOT
#
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strange bronze
cedar kilnBOT
strange bronze
#

Why are these not equal

#

Ax^2-16Ax+64A+Bx-8B+C

#

1=A, 0=-16A+B, 64A+C=0 so A=1, B=16, C=-64

muted bear
#

You forgot the -8B for the fonstants

#

@strange bronze

#

constants*

strange bronze
#

I just fingured it out a moment before you sent that

#

But you're right

#

I hate that little mistakes like that take up so much time

#

I'm going to write it differently and put it into the formulas while I expand it so that doesn't happen again

#

Thanks

#

.close

cedar kilnBOT
#
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muted bear
#

Youre welcome!

cedar kilnBOT
#
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hazy depot
#

I need to find the co-ordinates of the point of intersection of CM (y + 3x = 14) and AD (x - 2y = -2)

hazy depot
#

<@&286206848099549185> it is such a simple part of the question, but i still just don't know how to do 😭

cedar kilnBOT
#

@hazy depot Has your question been resolved?

hazy depot
#

<@&286206848099549185> just to alert again

sweet crest
#

solve the system to get your point

hazy depot
#

but how

sweet crest
#

for example you could solve one of them for y

#

then substitute

hazy depot
#

ok thank you :))

#

i got it now

#

.close

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#
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floral condor
#

find n

cedar kilnBOT
wintry pier
#

,rotate -90°

wraith daggerBOT
cedar kilnBOT
#

@floral condor Has your question been resolved?

crimson sedge
floral condor
floral condor
#

<@&286206848099549185>

floral condor
#

.close

cedar kilnBOT
#
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buoyant hill
#

Hi guys, I'm French btw

i want to make an equation of this text

International standards define the danger threshold as : 85 dB for 8 hours. This threshold increases by 3dB each time the exposure time is divided by 2.

It means u can resist 8hours hearing a 85dB sound without ur ears getting hurt.
it s like 85+n3 = ...

buoyant hill
#

it s a basic thing, plz i need help

cedar kilnBOT
#

@buoyant hill Has your question been resolved?

buoyant hill
#

<@&286206848099549185>

onyx dove
#

$85+3(3-log_2(t))$

wraith daggerBOT
#

chlamydia

buoyant hill
#

how to put in calculate

onyx dove
buoyant hill
#

thank u brah i understand ;)

#

.close

cedar kilnBOT
#
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random shore
#

Hey I dont need help with anything but I wanted to give a big shout out to all the helpers. Im pretty sure I got a solid mark on my calc test and I wouldnt have been able to if it wasnt for you guys and gals. Thank you all so much.

random shore
#

.close

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#
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winter cairn
cedar kilnBOT
winter cairn
#

Can someone please help be with this?

#

I’m really confused

onyx dove
#

!status

cedar kilnBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
winter cairn
#

1

onyx dove
#

$x\to{\frac{\pi}2}^-$ know what this means?

wraith daggerBOT
#

chlamydia

winter cairn
#

No I know when it’s simpler numbers

#

I’m really confused

#

@onyx dove do you think you can help me?

cedar kilnBOT
#

@winter cairn Has your question been resolved?

winter cairn
#

No

#

I need help

#

Still

neat dune
winter cairn
#

I got it now

neat dune
#

Noice

cedar kilnBOT
#

@winter cairn Has your question been resolved?

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upper elm
#

I am solving something for my company and was wondering if anyone could help.

Basically, I need to write an algorithm to accurately get from an initial % composition by mass, to a desired % composition by mass. For example, if sample A was 100kg initially, and it was made up of 40% carbon and 60% iron, and I wanted it to become 45% carbon and 55% iron, how would I determine suitable amounts of either to obtain that composition. I CANNOT subtract anything that was initially in the sample, nor take away anything that I add. I can only add enough to dilute the sample to its desired % compositions respectively.

If I can get an algorithm for this, I will need to extrapolate a formula to work with, let's say, 12 different materials within the composition.

upper elm
#

Here is an example of what a final wants list could look like, but I would like to start with a simpler example so I can understand the math behind it.

upper elm
#

Typo, sorry.

#

Obviously, there are an infinite number of answers so what I'm finding difficult is finding the most efficient or first one.

#

If anyone is interested in doing a voice call for further clarifications that may be helpful

cedar kilnBOT
#

@upper elm Has your question been resolved?

cedar kilnBOT
#

@upper elm Has your question been resolved?

cedar kilnBOT
#

@upper elm Has your question been resolved?

lethal jackal
#

this seems like a linear programming problem

#

set x to be the amount you add of each element

#

minimize c^T x, where c is the cost of each element

#

your constraint is a little harder, but you can actually write it as A(x_0 + x) = 0

#

for a suitable A

cedar kilnBOT
#

@upper elm Has your question been resolved?

upper elm
#

I don't understand that exactly

cedar kilnBOT
#

@upper elm Has your question been resolved?

fair geyser
#

take any amount of final composition e.g. 1 kg
divide every part of the orginal by every part of final
if you take the largest quotient and multiply by
that 1kg every part becomes at least as large as the orginal so you can just add the difference
@upper elm

#

maybe that's nonsense somehow

#

can't see the problem if so

lethal jackal
#

yeah I wonder if some greedy algorithm works here

#

the thing I'm worried about is if the elements cost different amounts

cedar kilnBOT
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broken mist
#

What are typical good techniques of determining reasonable domain and range?

broken mist
#

Other than the obvious figuring out what fits “reasonably”

#

Like if your range is distance a ball can be thrown, hundreds of miles are obviously out of the picture, but I have no idea what outliers could be at. Is there a certain number of standard deviations from a mean that is generally used?

buoyant latch
#

What does standard deviation has to do with range

broken mist
#

I don’t know that’s why I’m asking

#

Like are there any general conventions that are followed when determining “reasonable” domain and range?

#

Or is it just a situation of if I fits I sits

buoyant latch
#

You can do like rough approximations to bound your results

#

Like let’s say you probably can’t throw harder than a bat swing

broken mist
#

What if a datum somehow does surpass that

buoyant latch
#

And a bat swing hits a ball around a baseball court

broken mist
#

I guess you’d just increase the reasonable range

buoyant latch
#

So the size of a baseball court is probably a good upper limit on how far you can throw a ball

broken mist
#

So essentially just what makes sense

#

I don’t like that lol math isn’t supposed to be subjective in my mind

buoyant latch
#

Nothing about this has to do with math

#

I can’t even tell what topic you’re talking about

broken mist
#

Determining “reasonable” domain and range of a function

buoyant latch
#

The domain and range of a function has nothing to do with reasonability

broken mist
#

I’m supposed to teach it with function domain and range and can’t wrap my head around how to effectively determine a “reasonable” domain or range

buoyant latch
#

They are defined alongside the function with the notation f: A -> B

broken mist
#

Then why is it in this curriculum lol

buoyant latch
#

Well I don’t know the context you know

broken mist
#

So like take a word problem that’s optimizing the area of a fence

#

classic problem

#

Obviously your area can’t be negative, so even if the area is modeled by a parabola then you’re not going to include negative intervals of the domain in a “reasonable” domain

#

It makes sense with cases where you can’t have negative area but I can’t figure out how one would consistently determine a reasonable range for something like throwing a ball

#

Like the length of a baseball field makes sense, but I’m sure there some outlying person who could yeet a home run

#

Would they be included in a “reasonable” range?

lethal jackal
#

the concept of signed area is a pretty useful one

broken mist
#

For high school sophomores?

lethal jackal
#

yeah in some matters of practicality it is

broken mist
#

What’s the point in ever bringing this up in a class then?

lethal jackal
#

as an example, suppose you have two parcels of land that are currently separated by a property curve

#

there's a proposed redrawing of the property line

#

compute the amount of land you stand to lose/gain from this redrawing of the property line

#

you compute signed areas and add them up

broken mist
#

I’m not trying to condemn “reasonable” domain and range though I’m trying to justify it

lethal jackal
#

I'm not actually sure what you mean by domain and range here

#

like domain and range of a function?

broken mist
#

A word problem that allows for signed area defeats the purpose of it in the first place

#

Yes

lethal jackal
#

seems several things are getting conflated here

broken mist
#

Domain and range of a function

lethal jackal
#

functions are defined on whatever domain you wish them to be

broken mist
#

A function that models typically a word problem where signed or extreme values would be, for lack of a better word, “unreasonable” to include in the domain or range

lethal jackal
#

I think that's a little bit of a rigid way of looking at things

#

one is generally free to pick whatever mathematical tools they please to solve a real-life problem

#

for example, even though voltage and current are physically related to the flow of charges, and as such take on real values, people use complex numbers for them all the time

#

the same goes for things like complex frequencies, even though frequency is just counting the number of times something happens

broken mist
#

.close

cedar kilnBOT
#
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viral plover
#

hello

cedar kilnBOT
viral plover
#

kan someone calculate this equation?

#

x3+y3+z3=k

lusty grotto
#

what do u mean by calculate it?

viral plover
#

like solve it

lusty grotto
#

it is not possible to solve it, there are too many unknowns

dusky peak
#

maybe you want this?

viral plover
#

thx

lusty grotto
#

u can plot it

#

and u can use geogebra for it too

cedar kilnBOT
#

@viral plover Has your question been resolved?

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crimson pike
cedar kilnBOT
crimson pike
#

is this the right way to proceed with this question or is there another way to do the integration

tropic oxide
#

missing dx but yes this is correct so far

crimson pike
#

oh yea forgot about that thanks

#

.close

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mint raft
#

Is this the correct inverse function of the problem?

primal socket
#

It is, yes

mint raft
cerulean harness
#

I don't think it's correct

#

Isn't it should be h^-1(x) = (2-3x)/(x-1)

primal socket
#

Yeah, replace y with $h^{-1}(x)$

#

Because y= isn't a function

#

But you can use commutativity to rearrange $2-3x$ to $-3x + 2$

wraith daggerBOT
#

USS-Enterprise

#

USS-Enterprise

primal socket
#

x+1 is correct though

cerulean harness
#

Oh right my bad

cedar kilnBOT
#

@mint raft Has your question been resolved?

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sterile grove
cedar kilnBOT
sterile grove
#

for d.

#

how was I supposed to know what T is?

opal basin
#

B^T means the transpose of B

sterile grove
opal basin
#

It's swapping the rows for the columns

sterile grove
opal basin
#

So the rows become the columns and vice versa

sterile grove
#

is the determinant of a transposition of a square matrix always the same as the original?

opal basin
#

Yes

sterile grove
#

but a non-square matrix would have to be calculated right?

opal basin
#

Non-square matrices don't have determinants

sterile grove
opal basin
#

No, it's impossible for some of the properties of determinants to hold in that case

sterile grove
#

I guess that makes sense

#

strange that I haven't run into that question up until now

opal basin
#

det(AB) = det(A)*det(B) = det(BA) wouldn't always be true

sterile grove
#

right

#

thanks

#

.close

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#
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stiff gyro
#
  1. A particle moves to the right along the curve y = x^3/3 with a constant speed of 4 feet per second. Find a_t and │a_n │as it passes through the point (1, 1/3).

  2. A particle moves along the given curve r = 1 + sin^2 Ɵ with a constant angular velocity of 2 radians per second. Find the speed and acceleration at Ɵ = π/2.

  3. A particle moves in accordance with the equations r = t^2 + t and Ɵ = t^3 /6 where t denotes the time. Find its position and speed when t = 2.

i really need help....it wasnt discussed yet but the teacher already gave us this math problems...

blazing dune
#

Can you picture them as there are some numbers that aren't understandable

#

Like
The first question
Is it

#

$$y = \frac{x^3}{3}$$

stiff gyro
#

wait lemme fix it

wraith daggerBOT
#

Sherif Player

blazing dune
#

Or $$y = \frac{3x}{3}$$

wraith daggerBOT
#

Sherif Player

stiff gyro
blazing dune
#

Also what is $a_n$ and $a_t$?

wraith daggerBOT
#

Sherif Player

blazing dune
#

@stiff gyro ?

stiff gyro
#

hold on i do not know about it maybe it is normal acceleration and tangential accelaration...

blazing dune
#

Normal acceleration mean you want the acceleration to the right or what ?

#

I checked it

stiff gyro
#

i dont really know to be honest....

blazing dune
#

Oh so you didn't get it in class
Or you didn't study well to know it ?

stiff gyro
#

huh?

#

i really need help....it wasnt discussed yet but the teacher already gave us this math problem - earlier message

#

kinda like i didnt know how to solve this yet because it wasnt discussed yet

cedar kilnBOT
#

@stiff gyro Has your question been resolved?

cedar kilnBOT
#
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slender dew
#

hey, sorry for bothering. can someone help me with this question?

scarlet garnet
slender dew
#

this step right here, am i on the right track?

#

i conversed 1/x = a for example, so it changes from lim x to lim a->0

#

i have tried separating cot a/(1/a) and (2-3a)/(5-2a) but the result is still 0

scarlet garnet
slender dew
#

oop, my bad

scarlet garnet
#

tbh I would simplify the function first by deleting irrelevant parts

#

in the nominator you have something like $2x\cdot a - 3 a$, so you know that towards infinity the left term escalates, meaning the right one is irrelevant

wraith daggerBOT
#

Jigglyproff

scarlet garnet
#

the same goes for the denominator, you have $5x^2-2x$, which basically is $5x^2$

wraith daggerBOT
#

Jigglyproff

scarlet garnet
#

there is a formal way, either big O notation or a play with division by x, whatever your prof/teacher used

slender dew
#

oh wait okay, so the limit dont change first, but rather simplified it to algebra

scarlet garnet
#

then you end with\
$\frac{2x\cot{\frac{2}{x}}}{5x^2}$, where you can push out the $\frac{2}{5}$ in front of the limit to get\
$\frac{2}{5}\cdot$ limit of $\frac{\cot{\frac{2}{x}}}{x^2}$

wraith daggerBOT
#

Jigglyproff

scarlet garnet
#

limit as x approaches inf, forgor how to do that in LaTex

slender dew
#

oooo okay

#

thank you

#

hold on let me try it first

scarlet garnet
#

as a hint:
|| cot(x)=cos(x)/sin(x) ||

slender dew
#

soo
lim $\frac{1\frac{cos\frac{2}{x}}{sin\frac{sin\frac{2}{x}}{x^2}$

#

mmmkay got it. thank youu

#

.close

cedar kilnBOT
#
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patent pond
#

Help me pls,I haven't found a solution to this exercise.

patent pond
#

help meee

night kite
patent pond
#

Help pls

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#

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errant wasp
#

projection matrix for
the projection onto its column space, im actually confused what this means

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errant wasp
#

is every vector in R^3 orthogonal to the zero vector

barren forum
#

can you recall the definition of orthogonal? two vectors v and w are orthogonal when ...?

errant wasp
#

they are perpendicular

#

their dot product is 0

barren forum
#

and do you know how a dot product is computed?

errant wasp
#

in R^3 (1,0,0),(0,1,0),(0,0,1) these are the vectors where if you take the dot product of any, their result will be 0

barren forum
errant wasp
#

v1w1 + v2w2 + v3w3

barren forum
#

yep, now what is the zero vector?

errant wasp
#

v1w1 + v2w2 + v3w3 = 0

barren forum
#

🤨

#

the zero vector is just (0, 0, 0)

errant wasp
#

(1,0,0),(0,1,0),(0,0,1) is this not the span where the dp = 0

errant wasp
barren forum
# errant wasp gotcha

so to better phrase your question, if we have some vector w = (w1, w2, w3), is it perpendicular to the zero vector (0, 0, 0)?

errant wasp
#

is it not just a dot at origin?

#

then any line that goes through the origin will be perpendicular

#

right

barren forum
#

I would say at this point it's just by the definition, w1 x 0 + w2 x 0 + w3 x 0 = 0, so yes, they are orthogonal

#

the intuition of perpendicular arrows breaks down here

errant wasp
#

i hate linear algebra

barren forum
errant wasp
#

fuck being a cs major

#

this shit suck

#

anyways

#

Describe S⊥ by finding a basis for it if --> S is the subspace of R3 containing only the zero vector --> all of R^3

#

since w1 x 0 + w2 x 0 + w3 x 0 = 0 holds for any vector

#

in r^3

errant wasp
#

what if S is the subspace of R3 spanned by (1, 1, 1), how do i think about this

#

like is this meaning that 1, 1, 1 is the only linear combination?

barren forum
errant wasp
#

1 (-1) + 1 (1) + 1(0) = 0

#

-1, 1, 0..?

barren forum
#

S⊥ (usually called S complement) is a 2-D plane perpendicular to the line (also through the origin)

barren forum
errant wasp
#

probably 1, -1, 0 too

#

and then like ... 1, 0, -1

#

and then -1, 0, 1

#

i need to find the entire basis ig

barren forum
#

you just need two linearly independent ones

errant wasp
#

why two

#

why just two

barren forum
#

recall the definition of basis?

#

(hint: there are two conditions)

errant wasp
#

must be linearly independent

#

oh it should be a minimal set?

south tundra
#

S is one dimensional, its complement will be two dimensional since we are working in R^3

errant wasp
#

i just looked up basis defn but in my notes there is nothing about being minimal

barren forum
south tundra
#

Alternatively you can say basis is the minimal set that spans the entire vector space, yes

errant wasp
#

but if spanning means all the possibilities, why are their just two?

#

because i just listed like more than 2

south tundra
#

And 2 pairs of them are linearly dependent

barren forum
#

The point is, you couldn't find a set of 3 vectors in a plane that is linearly independent

south tundra
barren forum
#

Let's imagine R^2 as a vector space a bit. Sure, B = {(1,0), (0,1)} is a basis, but adding any extra vector in it would break the linear independence.

#

you can prove it by recalling the definition for linear independence

errant wasp
#

like if you added 2, 0

#

you could just divide by 2

#

or 1/2(2, 0) right

#

which makes it 1, 0 not linearly dependent