#help-13
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I’ll help you out there
🙂
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So I copied the question and made a scenario. I checked the answer and it says true but I got false. Can someone explain what I did wrong
the trace is when you sum the diagonal entries
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hi

here
the third question
do I divide by the total?
can you show your work
@surreal ember Has your question been resolved?
Oh sorry, that’s the one about percent natural abundance right?
yesss]
bro
Notice that the peaks look like 1:2:1 ratio
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so from that, you can get that the isotopes are in roughly equal abundance
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Hi! I'm really confused as to why finding the inverse function with 2 different methods results in two answers with completely different signs, but I can't seem to find any mistakes that I've made. I'd really appreciate an explanation for what I possibly did wrong, or if this is normal, why?
yeah wait they are the same thing
wouldn't one of them have to be -y though? for the answers to be the same
oh wait, the denominators would not be affected by a sign change
i think?
I actually have no idea what an inverse function is but the two final answers are the same are they not
i'm having trouble wrapping my head around that
for the first one, factorise out -1 for the numerator
then for the second one, factorise out -1 in the denominator
sorry fhsjf i still don't understand
ohhh that makes more sense!
my friend told me to multiply by -1 in earlier step to see and this is what i got too
thank you for the explanation!!
so they really are the same
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.rotate
3 x 2^x +1 x 2^x
when do you take common
when its in addition or subtraction lol
converse of distributive law
where is the 1 from
multiplying 1 by any number
does nothing
so i just wrote 2^x as
1 x 2^x
for better understanding
It's ,rotate btw
so then after that i
you take 2^x common
whay do i do with it
how do u take it common
yes
yes
snd 1 is rhe co efficient of the other
not x^2
snd u add the co efficients
yes
i mean 2^x
ohh ok thx
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Hello

one thing i know its not parallel thats for sure
<1, -1, 1> = <2,-1,1>
does not equal
it might be useful to replace the parameter in one of them by k instead of t
yea i did that i called the first one t1 the other t2
then i set them equal to each other
so i get 1 + t = 1 + 2t2 | 2 - t1 = 1 - t2 | 1 + t1 = t2
now here im stuck i dont know what to do
then you can solve them simultaneously and see if they lead to a contradiction
what do you mean by that
like do you mean
i take the first equation and solve for t2
ill get t2 = 0 is that right
1 + t1 = 1 + 2t \\ 1 = 1+t2 \\ t2 = 0
so it dosent intersct
intersect *
<@&286206848099549185>
how
you could ping me if I don’t respond
probably means I forgot
Oh sorry mb I thought I couldn’t ping members
I’ll let you ping me
Ty
how did you get this
.
I can do that right because technically it’s t
No, they are different
Oooh
So how do I solve them
Wait is it
The x + y = let’s say c and then 2x + 2y = c
I forgot what’s it called
You mean I have to systems of equations
@idle sonnet
@vivid sundial Has your question been resolved?
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Why is this wrong
try DNE? maybe they want you to say DNE...
like as written the sequence does approach infinity...
But isn’t the right answer infinity?
Yes, it is infinity.
sort of
I only have 3 attempts
The instructions say to write DNE
infinity isn't a number so technically the limit DNE
,w Limit[(n^4 - 4)/(n^2 + n), n -> Infinity]
Bruh
maybe they want you to write DNE
the limit does not exist however because it grows without bound
you can think of this as approaching infinity
yet infinity still is not a number so the limit DNE
try DNE
When you say the limit does not exist, it means that the limit is either infinity, or not defined.
-Quora (idk)
Idk man
try DNE !!!
DNE
AkShUaLlY infinity is a number in the extended real number line but I seriously doubt they're being taught about it here :p
Nah we good
isn't a real number*
it's not
the instructions say to write DNE :p
it's a difference in convention
do you know the method of dividing out by the highest power
Yes
But the thing is
This one is in a square root
With another number
So idk what to do in this scenario
?
My bad I have no idea what those codes mean
I’m on a phone
So uhh
@royal loom
What’s the rule that allows me to take it out
@keen plover Has your question been resolved?
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Can someone please for the love of god explain this stupid rule Ive been losing it since physics
I know mathematically how to calculate cross product but I cannot figure out the direction of it if just given a picture and asked for it
with the handshape that's shown there, the rule is to curl your 4 fingers in the direction of rotation from a to b, and then the thumb will point in the direction of a×b
i dont like that rule because it is kind of confusing specifically in this instance
Ok let me give a better version
to help me understand
is this better to use to explain?
uh hold on i think i took a picture of it myself at some point let me look for it
Alr, just ping me whenever 🙏 I appreciate your time and effort
are a and b both meant to be parallel to the page?
uh unsure i was just providing an example, here's something solid that's better
Ignore math, just at the bottom it tells the direction
so i'd have to twist my arm to get the thumb down right
thumb - u
v - index
omg
it's out
yeah
it points towards us
admittedly, my handshape sometimes requires putting your hand in somewhat of an awkward position.
okok
could you provide me an example see if i get it right myself?
y'know nvm, you're probably busy helping other people out.
I'll google some questions and practice it, ty for the trick!
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it's alright 😂 tysm
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hell
30-60-90 triangle
cause thats it's value of the function
Draw an equilateral triangle and a height from any point, you will have formed a right triangle where the acute angles are 30 and 60 degrees. You can solve for the length of the height using Pythagorean theorem and the fact that the height is also the median, hence you will know every trig-ratio of 30 and 60 degrees
ah thanks
i was confusing as to how we knew a 30-60-90 had those exact side lengths
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given event A and B, why does A*B represents the
intersection of these two events
product $\approx$ multiplication
Replaced by new brandon H
Are you given two events or the probability of two events?
just two events
@civic coral Has your question been resolved?
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Hello, can someone help me find the angle(AMC)
abc right triangle, ab = 12, bc = 24, m is the mid point of bc, so, BM=MC
No, I don't really know
Hmm ngl that was the only way I've come up with so far 
does it have another name, or, is a specific formula, maybe the english name is not familiar with me
What about law of cosines
a^2 = b^2 + c^2 - 2bc cos a?
yeah but actually I came up with a way to do it without that
hmm
OK now looking only at the lengths of triangle ABC you should be able to find the angle of C
Do u know about 30-60-90 and 45-45-90 triangles?
ooh
not really
Actually
I think
180 is the sum
So I think I know what u mean
we have N 90
I'm a bit confused
:))
lyeah but like they have certain memorable ratios to their sides
So like for instance 45-45-90 triangles have 1:1:sqrt(2) ratios
Um, I never heard of this
Sigh gotta come up with a new way brb
:)))
I'm so sorry :))
it should be something easy... It's a book with not difficult problems, I know all the theory I did in school, I think it should be something different by that, since I don't know about circumradius use here or 45 45 90 ratio
hm kinda surprised u know law of cosines but not these cus that's usually more advanced 
I know law of cosines bc I searched on internet like a week ago
and I memorized it
I have a pretty good memory, ngl
yea, until 60*
Bet
sin of 30 is 1/2
I'm saying that only till 60
cuz in highschool is studied
90, 120
things like that
in our country
OK so back to what we were doing previously which we can now do cus u know trig 😄
Notice that 12/24 = 1/2.remind u of anything?
hmm
Think of a trig value
Could also be sin, and that would be preferable tbh since we're looking for the angle of C rn
so sinC =? In terms of the known lengths of ABC?
Ye
that s what u've told earlier
🙂
Yup!
ooh
good
I love math
when someone explains it
good
we have c
and we were looking for
m
M would be 60
Well just <NMC
Ye so now we have part of <AMC. Now we gotta find <AMN
Oh right lol I was tryna figure out a thing I forgot
OK so next up what's NC?
U have the hypoteneuse and <C
So set up some more trig
And solve for NC this time
Hypoteneuse is MC
Because eventually it helps us find <AMN
Triiiiig
Set up a ratio equal to some trig function that takes in <C as input
Like opposite/Hypoteneuse or adjacent/hypoteneuse
um
lol
I know, yes
AMB with NMC?
or
wait
we don't have another triangle
to know length and an angle
oh, abc and nmc
Ye
Actually the nice thing here is that unlike what I was thinking of earlier we don't have to find any numerical values
I mean u still gotta write out ratios tho
Well we know BC/MC
I guess you do have to calculate that numerical value :p
Soo uh calculate that

um
I am so confused now
I feel like an idiot
I think I'm an idiot
why there isn't a simple way
lol
We can do it
Eh if u want I can just tell u the rest real quick
BC/MC = 24/12 = 2 so AC = 2NC so AN = AC - NC = 2NC - NC = NC
Theeeen
Congruent triangles
AN = NC, MN = MN, right angle in between. SAS congruency
Finally <AMN = <NMC cus congruent triangles
So all of angle <BMC is 60 + 60 = 120
I think I'll deal with it a bit later, thank you so much!
do you have 'nother 5 mins
for an equation ?
Ok
Is it asking to evaluate a and then evaluate b separately?
Kool
Hmmm
Well as long as u know algebra the first set of para theses on a isn't too hard
Just add them like u would with fractions
Find common denominator and stuff
For the second set of parentheses
It helps to factor
The values inside first
So 75 = 5^2*3 for instance
hmm
Aight, I will see
thank you so much, hope you'll have a nice day ! :)
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How do I solve for Y? I need this for a graded assignment.
do you know trig
yeah
kinda
ive been learning for a week now but its still unclear to me
heres a better pic of the diagram
Wassup
yo
What do you need help with
i need to solve for Y
O = 93.34
P = 71.5
the problem is that i did a similar version to this problem and both have different valued outcomes of Y
hello?
you there?
guh
@lapis totem Has your question been resolved?
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For this question am I doing 7 +7+x
Which then equals 14x
Could someone help me please
@main herald Has your question been resolved?
@main herald Has your question been resolved?
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In how many different ways can eleven people be seated at a circular table with eight seats, if three are left waiting?
This is a simplified version I did: (k-1)! (n) gave me the answer
or C(11,8)(8-1)!
(11!/8!3!) x 7!
The logic seems correct. Choose 8 people out of 11 people to occupy 8 seats. Then apply circular permutation on those people seated on those 8 seats.
,w (11 choose 8)*(7!)
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Could someone explain to me how definite integrals work with substitution example: x/x^2*8 dy/dx
Could you please try to typeset the expression on latex bot?
what is latex bot
$\frac{x}{x^{2×8}} \frac{dy}{dx}$
- Miles12345
Is this your expression?
no 8 in the exponent
$\left(\frac{x}{x^{2}}\right)^8 \frac{dy}{dx}$
yes
- Miles12345
definite integral from 0 to 5
there is no meaning for dy/dx here
im sorry. I'm not very good at calculus
so there is no meaning to this $\int_{0}^{5}{(\frac{x}{x^2})^8}{\frac{dy}{dx}}$
calculus is fun
do you mean to type this $\int_{0}^{5}{(\frac{x}{x^2})^8}{dx}$
calculus is fun
now this makes sense
this doesnt require substitution
$\int_{0}^{5}{(\frac{x}{x^2})^8}{dx}=\int_{0}^{5}{(\frac{1}{x})^8}{dx}=\int_{0}^{5}{x^{-8}}{dx}$
calculus is fun

now use what you know about $\int{x^n}dx$ $\forall x \in \mathbb{R}$
calculus is fun
I don't intend to complicate things, but you can assume 1/x⁸ and dy/dx as two seperate functions and apply integration by parts:
(assuming you are integrating w.r.t. dx):
$\int\left(\frac{x}{x^{2}}\right)^8 \frac{dy}{dx}dx$
$ = \frac{1}{x^8}\int\frac{dy}{dx}dx - \int y \left(\frac{x^{-7}}{-7}\right) dx$
$ = \frac{y}{x^8} + \frac{1}{7} \int\frac{y}{x⁷} dx$
For that, you need to know what y is as a function of x. This is not substitution.
you forgot a dx in the first integral
Oh yes thanks for pointing out
- Miles12345
yea
i didnt consider dy/dx bc we dont know abt y
and we dont have an integral or a differential equation to get y(if an explicit solution can be found even if there is a diff or int eq)
To the OP
https://math.stackexchange.com/a/2396916
This comment shows how the integrating by substitution is derived (for indefinite integration, you can apply this for definite integration further by changing the integrating limits when substituting then using FTC1 in the end). This could clear up your concept about this
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!onechannel
Please stick to your channel.
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What type of integration would I use for this
which one
M
Ok
How do I know I would use that
Instead of substitution by parts?
Since I can’t really tell when to use which
substitution by parts ? what is this ?
Intuition
When u use the formula uv-intergral sign V dy/dx
its called integration by parts
Hopefully I get that eventually
Yea that
My school calls it the other way
.closs
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I need help, arithmetic
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
Do u know arithmetic progressions?
This is my current progress
Yes
Woah that was not ehat I was thinking
okay
it's my first time coming across with arithmetic square roots
So I don't have an earthly idea how to solve this
I was thinking like difference between 36√3 and 8√3 is 28√3 (36√3 - 8√3 = 28√3).
im not sure if im correct and dont wanna give the answer out by mistake :(
oh thats a d 💀
i thought that was a reverse 6 and got confused 😭
💀
yeah go on and find "d"
Well you have an equation with one unknowm
How do you solve that
So...
It wasnt rly supposed to be a rethorical question
Ah hello there @shrewd gale haha
Square roots are basically like constants. you can treat them like "x" in some way.
So if you had something like $2\sqrt{3} + 3\sqrt{3}$, you can treat this as \ $2x + 3x$.
HqppyFeet
AHH I get it
exactly. They can be added/subtracted together because they have the same square root of 3
Okayy you explain it so good
is thr a document which explains how to use TeXit 🤣
I wanna see so I can help explain a better way
https://atomurl.net/math/ this website taught me everything with Tex xD
alr thx xD
anyway- ye u got the idea fundora?
I knew how to explain it but saying root 3 = x sounds stupid 💀
Nah its a good idea
yeah I know how that feels, I just call it sqrt(3), at least you understand that sqrt is square root
I give that advice too
Cuz 2x + 3x Works the same way as 2 *sqrt(3) + 3 sqrt(3) but People get afraid of the sqrt part
Youre on right track fundora
Almost done
Thanks
yess fundora! continue
Ur almost done 👀 nice
I think it's done I was finding the common difference, Im gonna find a2 a3 a4
There ya go! 7sqrt(3) is your d.
7 is the common difference I tried it out and it worked and got all the way up to 36
yess!!! I knew u could do it 🥹

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How do you solve this
I just took a quiz and I had literally no idea how to solve that
I’m in my car bombarded
Do u know what a square root is?
hmm, let's see.
what can 75 be factored to? Or what numbers multiply together to get 75?
Stop stealing my channel, ugh, I’m going u do it on ur own now 
Can u factor 15 more?
What will it be
xDDD im sorzy

hahaha
75 = this
and this
okay
so 75 = 3 * 5 * 5
yea
Now you know what a square is right?
yeah that 😭
Ok so now thinking about that we can say that √75 = √ 3* (5^2)
right?
I need help asap what’s the name of the topics in these questions
!help
Please read #❓how-to-get-help
whr did u go man
YES
5 the symbol 3
dang
that’s a weird problem we didn’t even get it in homework or anything and it was on the quiz
thanks
U can close
Ur not done
Don’t u dare close
Wtf
lol
what do u mean I’m not done
-25 symbol 3
@floral terrace || ngl when I saw the square shape I felt happy for the first time today ||
Yep ur done
U do it
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so would x^2 cancel you the sqr from x-4
since your plugging in g(x) function for f(x)?
so it'll be f(x)=(sqrx-4)^2-5
hello?
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Help I dont know why my answer was incorrect
i was about to say lol
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were you asked to do it by first principles? seems like a random way to do it
im assuming, its my first introduction to derivatives so i assume thats a yes
so you had [9h/(h-1)]/h
the issue is the next step
when you cancel that h it should become 9/(h-1) rather than 8h/(h-1)
if you carry on from there with that correction you should be fine
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Closed due to the original message being deleted
ok
they have their own open channel already. this channel is going to close, if you read the message sent by the bot
use #help-8
there is no reason to make this so difficult
ur good
you can go back now
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Am I crazy, or would I need the mass of the block to be able to solve this?
This is the only info provided.
<@&286206848099549185>
I tried combining F=ma with the equation for static friction, but that still brings up the problem that mass is not given.
It would be n8ce if we can see the figure
its possible the mass, m, can be cancelled once you set everything up
hello
What is fig 6.3.1
Have you drawn free body diagrams?
with one force? I think the correct answer is to cancel M, this is a brand new problem type for me.
there would be 4 but only 2 that really matter
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i need help with this, idk how to do piecewise functions
quadrangle
not sure
-4 to -1
oh wait would it be -4 to 3
filled out 1 of them
5/3
2
3
got it
problem is idk how ud get the 4 from
how
wait so how did u get the 4
yeah
-1?
3
there
final 2
3
4
figured it out
also
how do i do this version
-1?
quadrangle
quadrangle
quadrangle
@crimson sedge Has your question been resolved?
can someone help me with this?
.close
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can someone help me for b30 for span
Consider a vector (x, y) ∈ ℝ²
Show that there exists an a, b ∈ ℝ such that a(2, 1) + b(1, 3) = (x, y)
For all (x, y)
so solve for a?
Not solve
Show there exists
And not just for a
a and b
there is an x and y
that you can get an a
and b from
so this would be R^2
There you go
or can i write it like
You have shown that given any point in ℝ²
You can write it in a linear combination of the elements in B
You haven’t shown they are linearly independent though
But you know for sure they span ℝ²
(There’s another theorem that instantly gets you independence as well)
yea ik
You don’t need to do that
This is enough
for example in this question
trying to find the span
it is different than the one i did and its confusing to what the span is
since x = z , z = x and b is the only coeff in which there exists an x and y
how do you tell teh span of this
wdym
how can you tell
The first element is just 2 of the second + 1 of the third
no?
its not a scalar multiple
this is a plane
It’s a linear combination of the other ones
hm?
the 2nd vector has coeff of 2 and third coeff of 1?
to equal the first?
It’s also obviously a plane by the 2nd and 3rd elements being independent by inspection
Yeah
v₁ = 2v₂ + v₃
So the v’s aren’t linearly independent
so how can you tell the span isnt R^3 algebraically
sometimes i dont notice that
like i solved for a b and c
b is the only independent coeff
You see how X fixes A and B
wdym by fixes
Well it also fixes the A and B for Z
wdym by fixes 💀
This part
But in ℝ³ we have for all (x, y, z)
But actually you find that this is not true
You can’t actually find A B C’s that make it true for all (x, y, z)
Namely because x and z are expressed by the same linear combination of A and B
So when x ≠ z, there doesn’t exist an A and B in ℝ such that they express x and z at the same time
So for example say I want to express (1, 2, 0) in a linear combination of elements in B
I get 2A + B = 1
I get 2A + B = 0
There does not exist an A, B in ℝ that make those 2 true at the same time
so you cant find something like a = x+2y-z
wait
im cofnsued 💀
????

Ok anyway
You’re a bit mistaken
We choose some arbitrary x y z then we find the a b c’s
sorry i didnt understand what you were implying
yea
we find a b c to see if they equal some combination of x y and z
We don’t need to find them
to see if it spans in R^3
We need to show if they exist
yeah i meant doing what i did here for R^2
Clearly you can see here they can’t exist
Well you can solve the system of linear equations
but how would I know what vector to choose
But you will end up with 2 different expressions for the A and B
Well I looked at your first 3 equations
I see oh x and z are represented the same way
oh i seee
So if I chose x ≠ z then it won’t work
so its only r^2
Nope
how
None of ℝ² lives in ℝ³
so if its not r^3 then what is it??
Elements of ℝ² have only 2 components
y axis in r^3?
And every element of ℝ³ has 3 components
So it’s not that the span is ℝ²
But rather it spans a subspace of ℝ³ of dimension 2
Or it spans a 2 dimensional subspace of ℝ³
What
What axis
No one said anything about axis
Axis are arbitrary
spans in x or y plane of suspace of r^3
That makes no sense
x and y plane
like for example
span of [1,0],[-1,0]
my prof said the span is
x-axis in r^2
Sure you can say that spans the x-y plane
so in this cacse
