#help-13

1 messages · Page 182 of 1

surreal ember
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ok thanks bro

dense relic
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I’ll help you out there

surreal ember
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🙂

cedar kilnBOT
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turbid isle
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So I copied the question and made a scenario. I checked the answer and it says true but I got false. Can someone explain what I did wrong

idle sonnet
turbid isle
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Yes I am aware

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Thanks

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surreal ember
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hi

cedar kilnBOT
surreal ember
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I need help

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does anyone know a bit of chemistry? haha

idle sonnet
surreal ember
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the third question

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do I divide by the total?

idle sonnet
cedar kilnBOT
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@surreal ember Has your question been resolved?

surreal ember
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How

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Do u know how to do it

idle sonnet
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Do you know how to compute molar mass

surreal ember
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no but bro I wanted the third questino!!!

idle sonnet
idle sonnet
cedar kilnBOT
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idle sonnet
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.reopen

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not helpful yet angerysad

idle sonnet
cedar kilnBOT
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open crest
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Hi! I'm really confused as to why finding the inverse function with 2 different methods results in two answers with completely different signs, but I can't seem to find any mistakes that I've made. I'd really appreciate an explanation for what I possibly did wrong, or if this is normal, why?

grave ether
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yeah wait they are the same thing

open crest
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wouldn't one of them have to be -y though? for the answers to be the same

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oh wait, the denominators would not be affected by a sign change

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i think?

grave ether
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I actually have no idea what an inverse function is but the two final answers are the same are they not

open crest
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i'm having trouble wrapping my head around that

grave ether
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for the first one, factorise out -1 for the numerator

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then for the second one, factorise out -1 in the denominator

open crest
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sorry fhsjf i still don't understand

grave ether
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,rotate

wraith daggerBOT
open crest
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ohhh that makes more sense!

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my friend told me to multiply by -1 in earlier step to see and this is what i got too

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thank you for the explanation!!

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so they really are the same

grave ether
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ur welcome

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yeah

open crest
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thank you again!

#

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alpine cloak
cedar kilnBOT
alpine cloak
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.rotate

median holly
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take 2^x common

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youll see it

alpine cloak
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how is it common

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cuz

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doesnt addition make exponent rules die

median holly
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3 x 2^x +1 x 2^x

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when do you take common

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when its in addition or subtraction lol

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converse of distributive law

alpine cloak
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where is the 1 from

median holly
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multiplying 1 by any number

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does nothing

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so i just wrote 2^x as

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1 x 2^x

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for better understanding

obsidian coral
alpine cloak
median holly
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you take 2^x common

alpine cloak
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whay do i do with it

median holly
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you take it common you will get the asnwer

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take common and tell me what u get

alpine cloak
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how do u take it common

median holly
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ahem

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if theres

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3x+5x

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you can write as

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x(3+5)

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yes?

alpine cloak
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yes

median holly
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same way here

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its 3 x 2^x +1 x 2^x

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so

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2^x(1+3)

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so 4 x 2^x

alpine cloak
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WAIT i get it

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3 is the co efficient of x^2

median holly
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yes

alpine cloak
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snd 1 is rhe co efficient of the other

median holly
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not x^2

alpine cloak
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snd u add the co efficients

median holly
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yes

alpine cloak
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i mean 2^x

median holly
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2^x

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ye

alpine cloak
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ohh ok thx

latent shell
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and then............

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u can write as 2^2 * 2^x

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and combine to 2^(2+x)

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!

alpine cloak
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yes ty

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vivid sundial
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Hello

cedar kilnBOT
drifting matrix
vivid sundial
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one thing i know its not parallel thats for sure

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<1, -1, 1> = <2,-1,1>

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does not equal

idle sonnet
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it might be useful to replace the parameter in one of them by k instead of t

vivid sundial
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then i set them equal to each other

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so i get 1 + t = 1 + 2t2 | 2 - t1 = 1 - t2 | 1 + t1 = t2

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now here im stuck i dont know what to do

idle sonnet
vivid sundial
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what do you mean by that

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like do you mean

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i take the first equation and solve for t2

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ill get t2 = 0 is that right

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1 + t1 = 1 + 2t \\ 1 = 1+t2 \\ t2 = 0

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so it dosent intersct

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intersect *

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<@&286206848099549185>

idle sonnet
idle sonnet
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probably means I forgot

vivid sundial
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Oh sorry mb I thought I couldn’t ping members

idle sonnet
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I’ll let you ping me

vivid sundial
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Ty

idle sonnet
vivid sundial
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I can do that right because technically it’s t

idle sonnet
vivid sundial
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Oooh

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So how do I solve them

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Wait is it

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The x + y = let’s say c and then 2x + 2y = c

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I forgot what’s it called

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You mean I have to systems of equations

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@idle sonnet

cedar kilnBOT
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@vivid sundial Has your question been resolved?

cedar kilnBOT
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keen plover
cedar kilnBOT
keen plover
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Why is this wrong

tropic oxide
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try DNE? maybe they want you to say DNE...

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like as written the sequence does approach infinity...

keen plover
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But isn’t the right answer infinity?

cold briar
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Yes, it is infinity.

royal loom
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sort of

keen plover
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I only have 3 attempts

neat dune
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The instructions say to write DNE

royal loom
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infinity isn't a number so technically the limit DNE

cold briar
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,w Limit[(n^4 - 4)/(n^2 + n), n -> Infinity]

keen plover
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Bruh

cold briar
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maybe they want you to write DNE

royal loom
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the limit does not exist however because it grows without bound

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you can think of this as approaching infinity

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yet infinity still is not a number so the limit DNE

tropic oxide
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try DNE

cold briar
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When you say the limit does not exist, it means that the limit is either infinity, or not defined.
-Quora (idk)

keen plover
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Idk man

tropic oxide
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try DNE !!!

royal loom
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DNE

neat dune
keen plover
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Nah we good

royal loom
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isn't a real number*

keen plover
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DNE is what they wanted lol

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It’s stupid

royal loom
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it's not

neat dune
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the instructions say to write DNE :p

tropic oxide
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it's a difference in convention

keen plover
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Can y’all show me a way to work this one out

tropic oxide
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they want to lump all non finite/existent limits into DNE

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ig

tropic oxide
keen plover
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Yes

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But the thing is

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This one is in a square root

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With another number

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So idk what to do in this scenario

royal loom
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if u want to pull a n^2 through a square root

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what does it have to be on the inside

keen plover
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?

royal loom
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if you want to rewrite sqrt(n^a) into n^2sqrt(n^(x))

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what is x

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in terms of a

keen plover
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My bad I have no idea what those codes mean

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I’m on a phone

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So uhh

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@royal loom

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What’s the rule that allows me to take it out

cedar kilnBOT
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@keen plover Has your question been resolved?

cedar kilnBOT
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slender quartz
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Can someone please for the love of god explain this stupid rule Ive been losing it since physics

slender quartz
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I know mathematically how to calculate cross product but I cannot figure out the direction of it if just given a picture and asked for it

tropic oxide
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with the handshape that's shown there, the rule is to curl your 4 fingers in the direction of rotation from a to b, and then the thumb will point in the direction of a×b

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i dont like that rule because it is kind of confusing specifically in this instance

slender quartz
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Ok let me give a better version

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to help me understand

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is this better to use to explain?

tropic oxide
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uh hold on i think i took a picture of it myself at some point let me look for it

slender quartz
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Alr, just ping me whenever 🙏 I appreciate your time and effort

tropic oxide
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thumb = a, index = b, middle = a×b

slender quartz
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so for this scenario, axb would point into the page?

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i don get it ;-;

tropic oxide
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are a and b both meant to be parallel to the page?

slender quartz
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uh unsure i was just providing an example, here's something solid that's better

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Ignore math, just at the bottom it tells the direction

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so i'd have to twist my arm to get the thumb down right
thumb - u
v - index

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omg

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it's out

tropic oxide
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yeah

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it points towards us

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admittedly, my handshape sometimes requires putting your hand in somewhat of an awkward position.

slender quartz
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okok

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could you provide me an example see if i get it right myself?

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y'know nvm, you're probably busy helping other people out.
I'll google some questions and practice it, ty for the trick!

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cedar kilnBOT
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tropic oxide
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oh.

slender quartz
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it's alright 😂 tysm

cedar kilnBOT
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harsh zephyr
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hell

cedar kilnBOT
harsh zephyr
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hello

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how do we know that cos(30°) = √3/2?

tropic oxide
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30-60-90 triangle

vestal bear
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cause thats it's value of the function

south tundra
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Draw an equilateral triangle and a height from any point, you will have formed a right triangle where the acute angles are 30 and 60 degrees. You can solve for the length of the height using Pythagorean theorem and the fact that the height is also the median, hence you will know every trig-ratio of 30 and 60 degrees

tropic oxide
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which itself can be obtained from cutting an equilateral triangle in half

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^

harsh zephyr
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i was confusing as to how we knew a 30-60-90 had those exact side lengths

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.close

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civic coral
#

given event A and B, why does A*B represents the
intersection of these two events

civic coral
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why it is called "product event"?

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is there multiplication involves?

crimson sedge
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product $\approx$ multiplication

wraith daggerBOT
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Replaced by new brandon H

crimson sedge
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Are you given two events or the probability of two events?

civic coral
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just two events

cedar kilnBOT
#

@civic coral Has your question been resolved?

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sullen raft
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Hello, can someone help me find the angle(AMC)

sullen raft
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abc right triangle, ab = 12, bc = 24, m is the mid point of bc, so, BM=MC

neat dune
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One quick way is to find AM first

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Do u know about the circumradius?

sullen raft
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No, I don't really know

neat dune
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Hmm ngl that was the only way I've come up with so far bleakkekw

sullen raft
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does it have another name, or, is a specific formula, maybe the english name is not familiar with me

neat dune
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What about law of cosines

sullen raft
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a^2 = b^2 + c^2 - 2bc cos a?

neat dune
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yeah but actually I came up with a way to do it without that

sullen raft
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hmm

neat dune
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Drop a perpendicular from M to AC first

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did u do it

sullen raft
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so

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MN perpendicular AC

neat dune
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No

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Oh

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Ye

sullen raft
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aight

neat dune
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OK now looking only at the lengths of triangle ABC you should be able to find the angle of C

sullen raft
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umm

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I don't really know where to look at

neat dune
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Do u know about 30-60-90 and 45-45-90 triangles?

sullen raft
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ooh

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not really

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Actually

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I think

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180 is the sum

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So I think I know what u mean

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we have N 90

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I'm a bit confused

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:))

neat dune
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lyeah but like they have certain memorable ratios to their sides

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So like for instance 45-45-90 triangles have 1:1:sqrt(2) ratios

sullen raft
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Um, I never heard of this

neat dune
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Sigh gotta come up with a new way brb

sullen raft
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:)))

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I'm so sorry :))

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it should be something easy... It's a book with not difficult problems, I know all the theory I did in school, I think it should be something different by that, since I don't know about circumradius use here or 45 45 90 ratio

neat dune
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hm kinda surprised u know law of cosines but not these cus that's usually more advanced hmmCat

sullen raft
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I know law of cosines bc I searched on internet like a week ago

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and I memorized it

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I have a pretty good memory, ngl

neat dune
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Do you know trig?

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Like for instance what cos(30) is?

sullen raft
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yea, until 60*

neat dune
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Bet

sullen raft
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sin of 30 is 1/2

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I'm saying that only till 60

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cuz in highschool is studied

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90, 120

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things like that

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in our country

neat dune
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OK so back to what we were doing previously which we can now do cus u know trig 😄

sullen raft
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:)

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we know Ab and BC or BM / MC

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hmm

neat dune
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Notice that 12/24 = 1/2.remind u of anything?

sullen raft
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hmm

neat dune
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Think of a trig value

sullen raft
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adjacent on hyp

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so, cos

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is that what u talking about

neat dune
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Could also be sin, and that would be preferable tbh since we're looking for the angle of C rn

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so sinC =? In terms of the known lengths of ABC?

sullen raft
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Oh

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AB/BC

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12/24

neat dune
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Ye

sullen raft
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that s what u've told earlier

neat dune
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🙂

sullen raft
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so

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C would be 30

neat dune
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Yup!

sullen raft
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ooh

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good

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I love math

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when someone explains it

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good

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we have c

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and we were looking for

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m

neat dune
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Now the perpendicular we dropped comes in handy

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Then what's <NMC?

sullen raft
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M would be 60

neat dune
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Well just <NMC

sullen raft
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in NMC

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yes

neat dune
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Ye so now we have part of <AMC. Now we gotta find <AMN

sullen raft
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good

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now

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hmm

neat dune
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Oh right lol I was tryna figure out a thing I forgot

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OK so next up what's NC?

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U have the hypoteneuse and <C

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So set up some more trig

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And solve for NC this time

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Hypoteneuse is MC

sullen raft
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um

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wait

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for what do we need NC

neat dune
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Because eventually it helps us find <AMN

sullen raft
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hmm

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aight

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how do we find NC

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:))

neat dune
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Triiiiig

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Set up a ratio equal to some trig function that takes in <C as input

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Like opposite/Hypoteneuse or adjacent/hypoteneuse

sullen raft
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um

neat dune
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Oh wait actually we can do this without trig

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u know similar triangles right?

sullen raft
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I'm eyes and ears

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of fuck

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I hate this

neat dune
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lol

sullen raft
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I know, yes

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AMB with NMC?

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or

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wait

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we don't have another triangle

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to know length and an angle

neat dune
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Two triangles share <C

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And also have right angles

sullen raft
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oh, abc and nmc

neat dune
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Ye

sullen raft
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hmm

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I don't really know to write the ratios

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lets se

neat dune
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Actually the nice thing here is that unlike what I was thinking of earlier we don't have to find any numerical values

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I mean u still gotta write out ratios tho

sullen raft
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AB/NM = BC / MC = AC / NC

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?

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I have no idea how the ratios work here

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lol

neat dune
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Well we know BC/MC

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I guess you do have to calculate that numerical value :p

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Soo uh calculate that

sullen raft
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um

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I am so confused now

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I feel like an idiot

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I think I'm an idiot

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why there isn't a simple way

neat dune
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lol

sullen raft
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maybe we should pass this geometry prob :)) ?

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it is a bit 2 hard

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for my level

neat dune
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We can do it

sullen raft
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and I don't want to take your time

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I have an algebra equation

neat dune
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Eh if u want I can just tell u the rest real quick

sullen raft
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if u can guide me a bit

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:))

neat dune
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BC/MC = 24/12 = 2 so AC = 2NC so AN = AC - NC = 2NC - NC = NC

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Theeeen

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Congruent triangles

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AN = NC, MN = MN, right angle in between. SAS congruency

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Finally <AMN = <NMC cus congruent triangles

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So all of angle <BMC is 60 + 60 = 120

sullen raft
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I think I'll deal with it a bit later, thank you so much!

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do you have 'nother 5 mins

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for an equation ?

neat dune
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Ok

sullen raft
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thank you

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:))

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how can I

neat dune
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Is it asking to evaluate a and then evaluate b separately?

sullen raft
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yes

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I have to find both

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and do a geometric lean

neat dune
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Kool

sullen raft
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but I don't really know

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how to find

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them

neat dune
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Hmmm

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Well as long as u know algebra the first set of para theses on a isn't too hard

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Just add them like u would with fractions

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Find common denominator and stuff

sullen raft
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um

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The radicals are making be to stuck

neat dune
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For the second set of parentheses

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It helps to factor

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The values inside first

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So 75 = 5^2*3 for instance

sullen raft
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hmm

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Aight, I will see

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thank you so much, hope you'll have a nice day ! :)

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.close

cedar kilnBOT
#
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lapis totem
#

How do I solve for Y? I need this for a graded assignment.

tropic oxide
#

do you know trig

lapis totem
#

yeah

#

kinda

#

ive been learning for a week now but its still unclear to me

#

heres a better pic of the diagram

proven thistle
#

Wassup

lapis totem
#

yo

proven thistle
#

What do you need help with

lapis totem
#

i need to solve for Y

proven thistle
#

Try to eliminate p and o

#

Find value of p and o

lapis totem
#

O = 93.34
P = 71.5

#

the problem is that i did a similar version to this problem and both have different valued outcomes of Y

#

hello?

#

you there?

#

guh

cedar kilnBOT
#

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main herald
cedar kilnBOT
main herald
#

For this question am I doing 7 +7+x

#

Which then equals 14x

#

Could someone help me please

cedar kilnBOT
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@main herald Has your question been resolved?

cedar kilnBOT
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@main herald Has your question been resolved?

main herald
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.close

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crimson sedge
#

In how many different ways can eleven people be seated at a circular table with eight seats, if three are left waiting?

crimson sedge
#

I think it is (8-1)! (11)

crimson sedge
# crimson sedge

This is a simplified version I did: (k-1)! (n) gave me the answer

#

or C(11,8)(8-1)!
(11!/8!3!) x 7!

#

The logic seems correct. Choose 8 people out of 11 people to occupy 8 seats. Then apply circular permutation on those people seated on those 8 seats.

#

,w (11 choose 8)*(7!)

crimson sedge
#

Yes, thanks (:

#

.close

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cloud fiber
#

Could someone explain to me how definite integrals work with substitution example: x/x^2*8 dy/dx

crimson sedge
#

Could you please try to typeset the expression on latex bot?

cloud fiber
#

what is latex bot

crimson sedge
#

$\frac{x}{x^{2×8}} \frac{dy}{dx}$

wraith daggerBOT
#

- Miles12345

crimson sedge
#

Is this your expression?

cloud fiber
#

no 8 in the exponent

crimson sedge
#

$\left(\frac{x}{x^{2}}\right)^8 \frac{dy}{dx}$

cloud fiber
#

yes

wraith daggerBOT
#

- Miles12345

dim tiger
#

what is the meaning of this expression

#

i mean what do you want to do with this

cloud fiber
#

definite integral from 0 to 5

dim tiger
#

there is no meaning for dy/dx here

cloud fiber
#

im sorry. I'm not very good at calculus

dim tiger
#

so there is no meaning to this $\int_{0}^{5}{(\frac{x}{x^2})^8}{\frac{dy}{dx}}$

wraith daggerBOT
#

calculus is fun

dim tiger
#

do you mean to type this $\int_{0}^{5}{(\frac{x}{x^2})^8}{dx}$

wraith daggerBOT
#

calculus is fun

dim tiger
#

now this makes sense

#

this doesnt require substitution

#

$\int_{0}^{5}{(\frac{x}{x^2})^8}{dx}=\int_{0}^{5}{(\frac{1}{x})^8}{dx}=\int_{0}^{5}{x^{-8}}{dx}$

wraith daggerBOT
#

calculus is fun

crimson sedge
dim tiger
#

now use what you know about $\int{x^n}dx$ $\forall x \in \mathbb{R}$

wraith daggerBOT
#

calculus is fun

crimson sedge
#

I don't intend to complicate things, but you can assume 1/x⁸ and dy/dx as two seperate functions and apply integration by parts:
(assuming you are integrating w.r.t. dx):

$\int\left(\frac{x}{x^{2}}\right)^8 \frac{dy}{dx}dx$

$ = \frac{1}{x^8}\int\frac{dy}{dx}dx - \int y \left(\frac{x^{-7}}{-7}\right) dx$

$ = \frac{y}{x^8} + \frac{1}{7} \int\frac{y}{x⁷} dx$

#

For that, you need to know what y is as a function of x. This is not substitution.

dim tiger
#

you forgot a dx in the first integral

crimson sedge
#

Oh yes thanks for pointing out

wraith daggerBOT
#

- Miles12345

dim tiger
#

yea

#

i didnt consider dy/dx bc we dont know abt y

#

and we dont have an integral or a differential equation to get y(if an explicit solution can be found even if there is a diff or int eq)

crimson sedge
#

To the OP
https://math.stackexchange.com/a/2396916

This comment shows how the integrating by substitution is derived (for indefinite integration, you can apply this for definite integration further by changing the integrating limits when substituting then using FTC1 in the end). This could clear up your concept about this

cedar kilnBOT
#

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crimson sedge
cedar kilnBOT
#

Please don't occupy multiple help channels.

dire geode
cedar kilnBOT
dire geode
#

.close

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austere plume
#

What type of integration would I use for this

foggy merlin
#

which one

austere plume
#

M

foggy merlin
#

hmm

#

maybe partial fraction decomposition

#

since x²-4 = (x-2)(x+2)

austere plume
#

Ok

#

How do I know I would use that

#

Instead of substitution by parts?

#

Since I can’t really tell when to use which

foggy merlin
foggy merlin
austere plume
foggy merlin
#

its called integration by parts

austere plume
austere plume
#

My school calls it the other way

#

.closs

#

.close

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shrewd gale
#

I need help, arithmetic

cedar kilnBOT
orchid summit
#

!status

cedar kilnBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
shrewd gale
orchid summit
#

Do u know arithmetic progressions?

shrewd gale
#

This is my current progress

shrewd gale
orchid summit
#

Woah that was not ehat I was thinking

shrewd gale
#

okay

#

it's my first time coming across with arithmetic square roots

#

So I don't have an earthly idea how to solve this

orchid summit
#

I was thinking like difference between 36√3 and 8√3 is 28√3 (36√3 - 8√3 = 28√3).

dense socket
#

Why wouldnt d be an irrational number? Whats so scary about that

#

Finish your work

orchid summit
#

im not sure if im correct and dont wanna give the answer out by mistake :(

orchid summit
#

i thought that was a reverse 6 and got confused 😭

shrewd gale
#

💀

orchid summit
#

yeah go on and find "d"

shrewd gale
#

Ik but idk what's the next step

#

solve the square roots?

dense socket
#

Well you have an equation with one unknowm

#

How do you solve that

#

So...

#

It wasnt rly supposed to be a rethorical question

floral terrace
#

Ah hello there @shrewd gale haha

shrewd gale
#

Yo

#

It's you

#

Wsg

#

I'm struggling quite once again 💀

floral terrace
#

Ohh i see what's going on

#

yeah don't be afriad of square roots here

shrewd gale
#

Yep

#

Okay

floral terrace
#

Square roots are basically like constants. you can treat them like "x" in some way.

shrewd gale
#

Hmm

#

They have the same 3 the same applies in fraction right copy it?

floral terrace
#

So if you had something like $2\sqrt{3} + 3\sqrt{3}$, you can treat this as \ $2x + 3x$.

wraith daggerBOT
#

HqppyFeet

shrewd gale
#

AHH I get it

floral terrace
shrewd gale
#

Okayy you explain it so good

orchid summit
#

is thr a document which explains how to use TeXit 🤣

#

I wanna see so I can help explain a better way

floral terrace
#

https://atomurl.net/math/ this website taught me everything with Tex xD

orchid summit
#

alr thx xD

floral terrace
#

anyway- ye u got the idea fundora?

orchid summit
#

I knew how to explain it but saying root 3 = x sounds stupid 💀

dense socket
#

Nah its a good idea

floral terrace
#

yeah I know how that feels, I just call it sqrt(3), at least you understand that sqrt is square root

dense socket
#

I give that advice too

shrewd gale
floral terrace
#

.rotate

#

(wait how does this work again?)

dense socket
#

Cuz 2x + 3x Works the same way as 2 *sqrt(3) + 3 sqrt(3) but People get afraid of the sqrt part

#

Youre on right track fundora

#

Almost done

shrewd gale
#

Thanks

floral terrace
#

yess fundora! continue

shrewd gale
#

wait I don't have to copy sqrt (3) right

orchid summit
#

Ur almost done 👀 nice

shrewd gale
#

I think it's done I was finding the common difference, Im gonna find a2 a3 a4

floral terrace
#

There ya go! 7sqrt(3) is your d.

shrewd gale
#

7 is the common difference I tried it out and it worked and got all the way up to 36

floral terrace
#

yess!!! I knew u could do it 🥹

shrewd gale
cedar kilnBOT
#

@shrewd gale Has your question been resolved?

cedar kilnBOT
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verbal pawn
#

How do you solve this

cedar kilnBOT
verbal pawn
#

I just took a quiz and I had literally no idea how to solve that

#

I’m in my car bombarded

orchid summit
#

Do u know what a square root is?

floral terrace
#

hmm, let's see.
what can 75 be factored to? Or what numbers multiply together to get 75?

verbal pawn
#

yes

#

15 and 5

orchid summit
orchid summit
verbal pawn
#

yes

#

3 and 5

orchid summit
#

What will it be

orchid summit
#

Ok

#

Now put together all the factors of 75

#

What are they

verbal pawn
#

Like add 15+5+3+5?

#

28

orchid summit
verbal pawn
#

hahaha

orchid summit
orchid summit
verbal pawn
#

okay

orchid summit
#

so 75 = 3 * 5 * 5

verbal pawn
#

yea

orchid summit
#

root we know that √75 = √ 3 * 5 *5

#

right?

verbal pawn
#

right

#

I got to that point now what

#

what after

orchid summit
#

Now you know what a square is right?

verbal pawn
#

yes

#

Square

orchid summit
#

😭

verbal pawn
#

what do u mean

#

square

#

square root?

orchid summit
#

like square power

#

2^3

verbal pawn
#

oh yea

#

yea yea yea

orchid summit
#

yeah that 😭

#

Ok so now thinking about that we can say that √75 = √ 3* (5^2)

#

right?

proven radish
#

I need help asap what’s the name of the topics in these questions

orchid summit
#

whr did u go man

verbal pawn
#

Ohhhhhh

#

hahahah

#

omg

orchid summit
#

yessss

#

do u know what to do after ?

verbal pawn
#

Take out the 5^2 and keep the 3 inside

#

I think it would just be 5 cuz

orchid summit
#

YES

verbal pawn
#

5 the symbol 3

orchid summit
#

2/2 = 1

#

Yep

verbal pawn
#

dang

#

that’s a weird problem we didn’t even get it in homework or anything and it was on the quiz

#

thanks

#

U can close

orchid summit
#

Don’t u dare close

verbal pawn
#

Wtf

orchid summit
#

lol

verbal pawn
#

what do u mean I’m not done

orchid summit
#

The question was - 4 sqrt (75)

#

If u take out 5

verbal pawn
#

Omg

#

that stupid -4

#

We multiply it right

orchid summit
#

And tell me what u get

verbal pawn
#

-25 symbol 3

orchid summit
#

@floral terrace || ngl when I saw the square shape I felt happy for the first time today ||

orchid summit
verbal pawn
#

thank you

#

u can close

orchid summit
#

Use .close

verbal pawn
#

U do it

orchid summit
#

I can’t catBruh

#

.close

#

See

cedar kilnBOT
#

@verbal pawn Has your question been resolved?

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thick portal
cedar kilnBOT
thick portal
#

so would x^2 cancel you the sqr from x-4

#

since your plugging in g(x) function for f(x)?

#

so it'll be f(x)=(sqrx-4)^2-5

#

hello?

#

.close

cedar kilnBOT
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lime gyro
#

Help I dont know why my answer was incorrect

digital cliff
#

could you show your working?

#

oh wait

#

just saw it

#

sos

#

one moment

lime gyro
#

i was about to say lol

royal loom
#

!noclopen

cedar kilnBOT
#

Please don't repeatedly close and claim a new channel with the exact same question. This erases all previous progress made towards your problem, and is confusing for helpers, making it more difficult for them to answer your question. We ask you to please be patient, even if your channel has not received much attention. If you are having a problem with a helper, please report it to <@&833154869451292722> rather than closing the channel and attempting to seek out another helper.

digital cliff
#

were you asked to do it by first principles? seems like a random way to do it

lime gyro
digital cliff
#

so you had [9h/(h-1)]/h

#

the issue is the next step

#

when you cancel that h it should become 9/(h-1) rather than 8h/(h-1)

#

if you carry on from there with that correction you should be fine

lime gyro
#

oh

#

okay thank you

#

that fixed it, thank you

#

.close

cedar kilnBOT
#
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Closed due to the original message being deleted

jade creek
#

@cosmic quiver

#

hey i can help here!

cosmic quiver
#

oh you opened a channel too

#

sure

#

thank you

jade creek
#

ok

royal loom
#

they have their own open channel already. this channel is going to close, if you read the message sent by the bot

#

there is no reason to make this so difficult

cedar kilnBOT
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safe gate
#

Am I crazy, or would I need the mass of the block to be able to solve this?

safe gate
#

This is the only info provided.

#

<@&286206848099549185>

#

I tried combining F=ma with the equation for static friction, but that still brings up the problem that mass is not given.

muted bear
#

It would be n8ce if we can see the figure

digital cliff
#

its possible the mass, m, can be cancelled once you set everything up

muted bear
#

Oh true

#

But still

broken ferry
#

hello

muted bear
#

What is fig 6.3.1

safe gate
muted bear
#

Have you drawn free body diagrams?

safe gate
digital cliff
#

there would be 4 but only 2 that really matter

safe gate
#

mass did indeed cancel, cool. Thanks guys.

#

.close

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#
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crimson sedge
cedar kilnBOT
crimson sedge
#

i need help with this, idk how to do piecewise functions

wraith daggerBOT
#

quadrangle

crimson sedge
#

not sure

#

-4 to -1

#

oh wait would it be -4 to 3

#

filled out 1 of them

#

5/3

#

2

#

3

#

got it

#

problem is idk how ud get the 4 from

#

how

wraith daggerBOT
#

quadrangle

#

quadrangle

crimson sedge
#

wait so how did u get the 4

#

yeah

#

-1?

#

3

#

there

#

final 2

#

3

#

4

#

figured it out

#

also

#

how do i do this version

#

-1?

wraith daggerBOT
#

quadrangle

crimson sedge
#

opposite right

#

oh

wraith daggerBOT
#

quadrangle

crimson sedge
#

-4

#

next -3

#

2x-3

#

idk where f(2) goes

wraith daggerBOT
#

quadrangle

crimson sedge
#

first

#

1

#

got the last one

#

1

#

thanks bri

#

bro

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

crimson sedge
#

can someone help me with this?

crimson sedge
#

.close

cedar kilnBOT
#
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shrewd violet
cedar kilnBOT
shrewd violet
#

can someone help me for b30 for span

buoyant latch
#

Consider a vector (x, y) ∈ ℝ²

#

Show that there exists an a, b ∈ ℝ such that a(2, 1) + b(1, 3) = (x, y)

#

For all (x, y)

buoyant latch
#

Not solve

shrewd violet
#

this is what i did

buoyant latch
#

And not just for a

shrewd violet
#

a and b

#

there is an x and y

#

that you can get an a

#

and b from

#

so this would be R^2

buoyant latch
#

There you go

shrewd violet
#

or can i write it like

buoyant latch
#

You have shown that given any point in ℝ²

#

You can write it in a linear combination of the elements in B

#

You haven’t shown they are linearly independent though

#

But you know for sure they span ℝ²

#

(There’s another theorem that instantly gets you independence as well)

shrewd violet
#

this is correct?

buoyant latch
#

You don’t need to do that

buoyant latch
shrewd violet
#

i get confused tho

#

like

#

this quesiton

buoyant latch
#

We just need to show A and B exist

#

For span

shrewd violet
#

for example in this question

#

trying to find the span

#

it is different than the one i did and its confusing to what the span is

#

since x = z , z = x and b is the only coeff in which there exists an x and y

#

how do you tell teh span of this

buoyant latch
#

Clearly this doesn’t span ℝ³

#

By inspection of the elements of B it is obvious

shrewd violet
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how can you tell

buoyant latch
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The first element is just 2 of the second + 1 of the third

shrewd violet
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its not a scalar multiple

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this is a plane

buoyant latch
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It’s a linear combination of the other ones

shrewd violet
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the 2nd vector has coeff of 2 and third coeff of 1?

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to equal the first?

buoyant latch
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It’s also obviously a plane by the 2nd and 3rd elements being independent by inspection

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Yeah

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v₁ = 2v₂ + v₃

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So the v’s aren’t linearly independent

shrewd violet
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so how can you tell the span isnt R^3 algebraically

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sometimes i dont notice that

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like i solved for a b and c

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b is the only independent coeff

buoyant latch
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You see how X fixes A and B

shrewd violet
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wdym by fixes

buoyant latch
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Well it also fixes the A and B for Z

shrewd violet
buoyant latch
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But in ℝ³ we have for all (x, y, z)

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But actually you find that this is not true

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You can’t actually find A B C’s that make it true for all (x, y, z)

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Namely because x and z are expressed by the same linear combination of A and B

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So when x ≠ z, there doesn’t exist an A and B in ℝ such that they express x and z at the same time

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So for example say I want to express (1, 2, 0) in a linear combination of elements in B

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I get 2A + B = 1

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I get 2A + B = 0

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There does not exist an A, B in ℝ that make those 2 true at the same time

shrewd violet
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wait

buoyant latch
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<@&268886789983436800>

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Thanks

shrewd violet
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wtf

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@verbal rivet

buoyant latch
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<@&268886789983436800>

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Thank you

shrewd violet
buoyant latch
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Ok anyway

buoyant latch
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We choose some arbitrary x y z then we find the a b c’s

shrewd violet
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sorry i didnt understand what you were implying

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yea

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we find a b c to see if they equal some combination of x y and z

buoyant latch
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We don’t need to find them

shrewd violet
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to see if it spans in R^3

buoyant latch
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We need to show if they exist

shrewd violet
buoyant latch
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Well you can solve the system of linear equations

shrewd violet
buoyant latch
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But you will end up with 2 different expressions for the A and B

shrewd violet
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i see how that is not possible

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from your example

buoyant latch
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I see oh x and z are represented the same way

shrewd violet
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oh i seee

buoyant latch
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So if I chose x ≠ z then it won’t work

shrewd violet
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so its only r^2

buoyant latch
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Nope

shrewd violet
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how

buoyant latch
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None of ℝ² lives in ℝ³

shrewd violet
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so if its not r^3 then what is it??

buoyant latch
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Elements of ℝ² have only 2 components

shrewd violet
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y axis in r^3?

buoyant latch
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And every element of ℝ³ has 3 components

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So it’s not that the span is ℝ²

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But rather it spans a subspace of ℝ³ of dimension 2

shrewd violet
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ahh

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So x and y axis

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or just y

buoyant latch
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Or it spans a 2 dimensional subspace of ℝ³

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What

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What axis

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No one said anything about axis

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Axis are arbitrary

shrewd violet
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spans in x or y plane of suspace of r^3

buoyant latch
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That makes no sense

shrewd violet
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x and y plane

buoyant latch
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That still makes no sense

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A plane is a plane

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There’s no x y plane

shrewd violet
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span of [1,0],[-1,0]

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my prof said the span is

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x-axis in r^2

buoyant latch
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Sure you can say that spans the x-y plane

shrewd violet
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so in this cacse