#help-13

1 messages · Page 174 of 1

pliant wedge
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So for both c and f, you are on the right track, by using conjugates

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You just need to cancel out the sqrts and get to your answers

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Now, for g, make 1 into y/y and cancel.

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I can explain further if needed

swift fossil
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ohhhh that makes sense for g, thanks. Let me try them all again I will send again in channel either that I completed them or if I am still confused

pliant wedge
#

Gotcha

swift fossil
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where would I go from here

pliant wedge
#

Okay lets backtrack to your initial substitution.

swift fossil
#

alright

pliant wedge
#

Let us multiply by complex fraction by y/y (as to make it a simpler fraction, however, it is possible to do it without this step)

swift fossil
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oh the full fraction by y/y

pliant wedge
#

Correct

swift fossil
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one sec

pliant wedge
#

It's better to leave the denominator as a factored form, but do you see where we might be able to cancel a factor on the numerator and denominator?

swift fossil
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oh i see

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one sec

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but the top is 2-y and the bottom is y-2

pliant wedge
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is there a way you can make it y-2?

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the coefficients of both the constant and the y are the same

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But it's just one thing that's different...

swift fossil
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if we flip it it will be -y+2

pliant wedge
#

correct.

swift fossil
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should i multiply by -1 or something

pliant wedge
#

Yup

swift fossil
#

ok

pliant wedge
#

Technically, it's distributing a negative out

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But it's the same effect

swift fossil
#

is this correct

pliant wedge
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Yep

swift fossil
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so the answer would just be 0?

pliant wedge
#

Oh wait

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I didn't read that part

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When you cancel something it doesn't become 0...

swift fossil
#

oh

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it becomes 1

pliant wedge
#

Mhmm

swift fossil
#

oh so it would be 1/2

pliant wedge
#

that's right.

swift fossil
#

thank you so much that was helpful

pliant wedge
#

No problem!

swift fossil
#

/solved

pliant wedge
#

use .close

slate lintel
#

.close

cedar kilnBOT
#
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lofty granite
cedar kilnBOT
lofty granite
#

im confused on what are the first steps

tight garden
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ooh i loved these types of questions

lofty granite
#

thats good

tight garden
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so are you aware of the ASTC rule?

lofty granite
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no ive never heard of it

tight garden
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in Quadrant II only sine and cosec are positive, which means the other 4 trigonometric function will be negative

lofty granite
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okay

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got that

tight garden
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are you able to calculate what sin(t) will be, knowing that csc(t) = 3 ?

lofty granite
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it will be positive

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?

tight garden
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yes but it's value

lofty granite
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oh no i dont know how to

tight garden
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will be 1/3
sin(t) = 1/3

are you aware sin(t) = 1/csc(t)

lofty granite
#

no

tight garden
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you will be working with the reciprocal and pythagoream identities

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to find all six trig functions

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first step was to know which are postive and negative. (we now know by the ASTC rule that only sin and csc are positive)

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next....

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we apply the first identity to find sin(t)

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which is simply the reciprocal of csc(t)

lofty granite
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yeah

tight garden
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and csc(t) = 3 according to the question. so sin(t) = 1/3

lofty granite
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oh okay

tight garden
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next we will find cos(t)

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we will use the first pythagoran identity

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we now know that sin(t) = 1/3 so we will use this info to find cos(t)

lofty granite
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gotchu

tight garden
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you will get (1/3)^2 + cos(t)^2 = 1

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solve for cos(t)

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tell me what you get

lofty granite
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sqrt(2)?

tight garden
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got it so far?

lofty granite
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oh okay yeah

tight garden
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Okay so now you have the value of sin, csc, cos

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How will you find sec(t)

lofty granite
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the second pythagorean equation

tight garden
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But for that you need the value of tan(t)

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You will use the second reciprocal identity

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Because you already know cos(t)

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You will use it to get sec(t)

lofty granite
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oh

tight garden
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And then use the second Pythagorean equation to get tan(t) using sec(t)

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Then the last step: use tan(t) to get cot(t) using the final reciprocal identity

lofty granite
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okay thank you unfortunately i had to leave my homework to drop somone off but i will keep a picture of the convo

tight garden
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I have a sample question somewhere let me get that

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I will DM you the sample/example question

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@lofty granite

lofty granite
#

okay thank you

cedar kilnBOT
#

@lofty granite Has your question been resolved?

cedar kilnBOT
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glad dagger
#

Hi. Best learning apps.
For math.
13-15 year old math.
Especially algebra
And creating algebra equation
Example like this
The price of a theater ticket is 64$ more than a cinema ticket. A total of 400$ was paid for 4 theater tickets and 5 cinema tickets
Calculate the price of one theater ticket. Save calculations.
I wanna learn how to do these
I suck at these

cinder venture
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x = 64 + y

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400 = 4x + 5y

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Simplify

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Yk how to do this?

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@glad dagger

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substitute the x in 4x with “64+y”

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400 = 4(64+y) + y

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400 = 256 + 4y + y

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400 = 256 + 5y

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I think I have made a mistake

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Anyway this is pretty much the process

crimson sedge
glad dagger
crimson sedge
glad dagger
#

What’s this

crimson sedge
#

click on it and see

cedar kilnBOT
#

@glad dagger Has your question been resolved?

cedar kilnBOT
#

@glad dagger Has your question been resolved?

crimson sedge
cedar kilnBOT
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unreal spear
#

how do i do this? where do i start? am trying to simplify

slate lintel
#

i would replace the bases with their prime factorizations

unreal spear
#

after that this is what i got: (8)^12 x (3)^30 / 1^46

unreal spear
slate lintel
unreal spear
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that's my work

slate lintel
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ok well first of all you misread a 5 as a 6 but beyond that

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you can't cancel factors like that when they're inside a power

slate lintel
wraith daggerBOT
#

hayley!

slate lintel
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and it's similar for the others

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,tex .exp rules

wraith daggerBOT
#

hayley!

slate lintel
slate lintel
unreal spear
slate lintel
#

you question marked the rules i sent

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do you not understand them?

unreal spear
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yeah i got it now sry

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wait nvm could u walk me through it

slate lintel
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i showed you the example with the 2s

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do the same thing for the 3s

unreal spear
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yeah right i did that too

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so 3^30 three times right

slate lintel
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yep

unreal spear
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so that leaves us with (2x2x2x2)^12 / 2^45

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right?

unreal spear
slate lintel
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i haven't done the math myself but what did you do with the 18^45 on the bottom?

unreal spear
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yeah i split it up to 3x3x2

slate lintel
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oh ok cool

unreal spear
#

then i just simplified like normally tytytsmmm

#

.close

cedar kilnBOT
#
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ocean garnet
cedar kilnBOT
ocean garnet
#

I have a small question

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for part a how do I know what to differentiate with respect to?

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when it says if k is a constant does that mean I differentiate with respect to k?

cedar kilnBOT
#

@ocean garnet Has your question been resolved?

cedar kilnBOT
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stark kiln
#

hey so there is this game on a discord bot where it's essentially a sort of gambling. basically you can "buy a chicken" for 100 coins and send it to fight and bet that it will win for however much money as long as it's >= 100 coins. in the first round, it has a 50% chance of winning. each time you win, you gain 1% chance (so 51%, 52%, etc). if it dies, you have to buy a new chicken for 100 coins.

I find this game very interesting because it feels like there's a decent amt of probability and decision making
SO, I'm trying to make a program that can play in the most "accurate" way and gain money. i know this sounds dumb, it's virtual money after all, but I am more interested in the math behind it and how (or if) this can even be done?

finite lion
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winpercentage = min(0.5+0.01*wincount, 100)

flint plinth
#

virtual chickenfighting, what will they think of next

finite lion
slate lintel
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lootBWAKses

stark kiln
#

wha?

finite lion
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that’s the code

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wait why did i write rand

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i did not write that

slate lintel
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how much do you get if you win?

stark kiln
#

random?

stark kiln
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and you lose that same amount too

finite lion
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can you just bet very little every time, until the percentage goes higher then you roll in the big bucks

stark kiln
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yeah but you often lose by like round 2 or 3

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but yeah i was actually trying that

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coding some weird exponential function where it begins to spend more in later rounds

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it seemed like it just performed worse

slate lintel
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so the first round is always 100 and then after that you get to pick?

stark kiln
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no you get to pick in every round

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100 coins is to play a game in the first place

slate lintel
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confused

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you buy it for 100 coins - exactly?

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and then what you send it in with some amount of coins stuffed up its butt? that also has to be at least 100?

finite lion
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wait until you’re pretty confident it aint gonna die

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wait is it theroeiteically possible for the chicken to hit 100%

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cuz if that’s the case then ya could just keep doin it until a chick

stark kiln
# slate lintel you buy it for 100 coins - exactly?

yeah, so like for example

  1. you start a game (buy a chicken) for 100
  2. you play round 1 by betting any amount you want
  3. if you win, you go to round 2 with a higher chance, still betting how much u want.
    If you lose, you go back to step 1
stark kiln
slate lintel
stark kiln
#

but I don't think I've seen it reach round 20 even (prob the chance is so low)

wraith daggerBOT
slate lintel
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good luck hitting 100%

stark kiln
#

LOL

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wow

finite lion
#

oh

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my bad

slate lintel
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feels like the first actual bet you do should be a large amount

finite lion
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i think if you bet a constant amount, the expected value will go up

stark kiln
#

i was thinking, is there a bigger chance of winning after you lose a lot of games?

finite lion
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because the chance you win is >50% overall

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no it’s probably independent

stark kiln
#

oh

finite lion
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but even if so, because of the winning percentage going up, the expected value should be a profit

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could we be a bit more greedy and bet more on the higher percentages to abuse it

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how much money in the game do you have

slate lintel
stark kiln
finite lion
#

is it dank memer

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what game

stark kiln
#

unbelievaboat

finite lion
#

unbelievably

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nice

stark kiln
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like i lost a lot of money 💀

finite lion
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rip

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wait what can your program do

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can it automatically play the games for you

stark kiln
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i mean i just recreated the game yeah

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and made it play it thousands of times

slate lintel
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even if the chance were always 70% there would be some minimum bet that you need to use or you lose money on chickens

finite lion
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try telling it to bet 100 every time

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and try running it for 1000 games or however many your pc can handle within a second

stark kiln
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yeah i did that and it lost so much lol

finite lion
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woah what the hell;

finite lion
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why would it happen tho

stark kiln
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probably because you are buying chickens in the first place

finite lion
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OH

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WAIT WAIT WAIT

stark kiln
#

😭

finite lion
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SO IF I LOSE, I NEEDA BUY ANOTHER CHICKEN AGAIN

stark kiln
#

yes

finite lion
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so when you lose you’re not only losing your bet, but losing another 100 on top of that

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well fuck dont play this game it’s guarantee lose

stark kiln
#

BRUH

slate lintel
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i feel like the max EV here is going to be bet nothing on the 50 then bet everything on the 51% chance

stark kiln
#

yeah..

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it's even more scammy that you must bet at least 100 each round so you can't bet nothing

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im starting to think there is no solution

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it's just pure luck

slate lintel
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so i mean

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it shouldn't be

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the entry fee doesn't really matter

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if you have a big enough bank

finite lion
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wait i agree with hayley

slate lintel
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and the game is otherwise positive EV

finite lion
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buy 100, bet 200 on the 51%

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yeah

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so bet as little as possible on the 50%

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and bet 200 for everything >50%

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can ya try running a 1000 games or sth on tht

stark kiln
#

hmm okay i will try

slate lintel
#

i think with a finite bank you're probably guaranteed to go bust at some point? not sure

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some kind of martingale otherwise

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but yeah like without the entry fee it's positive EV

stark kiln
finite lion
#

ok that was not the best run

stark kiln
#

each one of these is 1000 games

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lol

slate lintel
#

-100,000
did it lose every game???

stark kiln
stark kiln
#

yeah this is kinda alarming

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let me look into it

slate lintel
#

sometimes you can analyze these problems from absurdism

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imagine you had a bank of 101 coins

cedar kilnBOT
#

@stark kiln Has your question been resolved?

stark kiln
#

so this is the winrates of one test of 1000 games

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very strange

stark kiln
#

but what is your point? i am curious

slate lintel
stark kiln
#

yeah

slate lintel
#

ohhhh okay

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a good test for a method like this is to do it over and over with some starting bank

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and see whether you go bust first or double your starting cash first

stark kiln
#

ah thats a good idea

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so i started with around 10k and it busts first, anywhere from game 60 to 200

stark kiln
#

im gonna head out, i honestly dont think there's really a way to play this game accurately lol

#

thank you everyone for the help

#

.close

cedar kilnBOT
#
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deft trench
#

Been stuck on number 4 for a while. I have an inkling idea of what it means but no idea how to actually rewrite it

celest ledge
#

x is in at least one of P(A), meaning x is a subset of A, where A is a member of F

deft trench
#

That makes sense

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So there exists an x that is a subset of A?

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Where A is in F

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Is that how I’d write it?

celest ledge
#

I simply explained what it means. I don’t know what form of answer it requires since it’s your assignment.

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What you sent looks perfectly correct to me, I just don’t know whether it’s the form your assignment requires

deft trench
#

Yeah the wording of what it’s asking for is kinda vague sry

#

Thank you 😁

celest ledge
#

Np

deft trench
#

.close

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crimson sedge
#

hello

cedar kilnBOT
crimson sedge
#

can anyone help me

gaunt trench
#

what am i doing wrong here?

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oh oops

crimson sedge
#

sorry its a lot

#

^

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yes

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these are all new attempts

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second to last question, i put :

[-7,-7] U [7,7]

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but it was wrong

wraith daggerBOT
cedar kilnBOT
#

@crimson sedge Has your question been resolved?

crimson sedge
#

oops

hearty arch
#

have you tried just [-7,7]? the only values y can hold lie in that interval, even though y is only either -7 or 7

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since it's only asking for one set, that's what my first thought would be

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

crimson sedge
#

ohh

#

maybe you’re right

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

cosmic steppe
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hybrid light
cedar kilnBOT
hybrid light
#

why was sinxdx set to dv and not v?

celest ledge
#

(-cos(x))’=sin(x)

hybrid light
#

so when solving integrals by parts, you set u to the first part and derive it and then set the next part to dv instead of v?

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and then derive it?

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also according to the formula for integration by parts, don't you subtract

celest ledge
#

It’s simply d(f(x))=f’(x)dx

cedar kilnBOT
#

@hybrid light Has your question been resolved?

cedar kilnBOT
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regal peak
#

If one performs a singular value decomposition on some demeaned data, (n,m) matrix X where n and m are the number of features and observations accordingly, we will get USV = X. From here we can recover the covariance matrix $V^{T}SV$. This will be the equivalent of a maximum likelihood estimator for the covariance under a Gaussian distribution. How is the Gaussian distribution related to the SVD? Is there a normality assumption here somewhere?

wraith daggerBOT
#

LetečiDebjule

cedar kilnBOT
#

@regal peak Has your question been resolved?

cedar kilnBOT
#

@regal peak Has your question been resolved?

cedar kilnBOT
#
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signal vault
cedar kilnBOT
signal vault
#

can someone explain a

dreamy sleet
signal vault
#

i triedf expanding lhs

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so i got

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$\frac{1}{\cos(\theta)} + \frac{1}{\sin(\theta)} \times \frac{\cos(\theta)}{\sin(\theta)}

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how does this work

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\frac{1}{\cos(\theta)} + \frac{1}{\sin(\theta)} \times \frac{\cos(\theta)}{\sin(\theta)}

dreamy sleet
#

$\frac{1}{\cos(\theta)} + \frac{1}{\sin(\theta)} \times \frac{\cos(\theta)}{\sin(\theta)}$

wraith daggerBOT
#

rysrobrgldvoelroep>vneae=u

signal vault
#

yep

dreamy sleet
#

you missed a dollar sign on the end

signal vault
#

woops

#

yeah

#

so i got there

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and now idk where to go

dreamy sleet
#

You could try expanding the right side as well

signal vault
#

i did

dreamy sleet
#

so that the right and left become the same thing

#

what did you get ?

signal vault
#

$\frac{1}{\cos(\theta)} \times \frac{1}{\sin^2(\theta)}$

wraith daggerBOT
dreamy sleet
#

And then you could multiply both expressions for the left and right sides by (cos theta)(sin theta)^2

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so that it’s easier to identify them

signal vault
#

ohhhh

#

right yeah

#

yep

#

that works

#

thanks

#

.close

cedar kilnBOT
#
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crimson estuary
#

how should i do this?

cedar kilnBOT
tropic oxide
#

a, b or c?

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if more than one, which first?

crimson estuary
#

just a first

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then the rest after

tropic oxide
#

ok

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can you write out what a generic polynomial of degree 2 looks like

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no other information known about it yet

crimson estuary
#

ax^2 + bx + c?

tropic oxide
#

yes of course. what room is there for second guessing?

crimson estuary
#

wait

tropic oxide
#

now make it monic. do you know what it means for a polynomial to be monic?

crimson estuary
#

so a = 1

tropic oxide
#

yes

#

so what does it look like now

crimson estuary
#

2 + bx

tropic oxide
#

crimson estuary
#

ah

#

x^2 + bx + c?

tropic oxide
#

yes of course

#

again this is all simple if you put some thought in it

#

now make the constant term 1

crimson estuary
#

so x^2 + bx +1

tropic oxide
#

yes

#

now make b such that P(-1)=7

crimson estuary
#

if i subbed in p(-1) just 2 -b = 7

tropic oxide
#

crimson estuary
#

my bad

#

is that correct

tropic oxide
#

yes now it's correct, 2 - b = 7

#

so b is what

crimson estuary
#

-5

tropic oxide
#

ok great

#

do you have any more questions about part a specifically

crimson estuary
#

not really

tropic oxide
#

ok

#

anything else you would like to ask?

crimson estuary
#

how to do b and c

tropic oxide
#

well

#

analyze them piece by piece like i had you do for a

crimson estuary
#

what does quartic mean?

tropic oxide
#

degree 4.

crimson estuary
#

so it the first term would be 2ax^4

tropic oxide
#

don't try to kill two birds with one stone unless you know exactly what you are doing.

crimson estuary
#

oh i thought that was correct

#

im a bit confused then

tropic oxide
#

ok then let's go through it slowly again

#

one moment

crimson estuary
#

ok

tropic oxide
#

write me a generic 4th-degree polynomial

#

do nothing else with it until i say otherwise

crimson estuary
#

ax^4+ bx^3 + cx^2 + dx + e

tropic oxide
#

now make its leading coefficient 2.

crimson estuary
#

2x^4+bx^3+cx^2+dx+e

tropic oxide
#

the other terms do not vanish

crimson estuary
#

oh right

#

thats better

tropic oxide
#

yes

#

now make its constant term 0

crimson estuary
#

2x^4 + bx^3+cx^2+dx+0

tropic oxide
#

great

#

you can erase that zero unless you are a bureaucrat

crimson estuary
#

i think ill just keep it there to make sure i do everythig=ng

tropic oxide
#

anyway, now write what it means that Q(-2) = 12

crimson estuary
#

32 -8b + 4c -2d + 0 = 12?

#

do i need to keep the b and stuff?

tropic oxide
#

why would you not keep "the b and stuff"

#

why's your default to throw them away like they are junk to rid yourself of

crimson estuary
#

oh

#

is that better?

tropic oxide
#

better would have been to put it in a new message.

#

but yes, the equation is 32 - 8b + 4c - 2d = 12

crimson estuary
#

oh

#

sorry about that

tropic oxide
#

do you see how to proceed?

crimson estuary
#

-8b +4c - 2d = -20

tropic oxide
#

great

#

again, do you see how to proceed?

crimson estuary
#

Not relaly

#

should i factor out 2?

tropic oxide
#

i think you are overthinking it.

#

observe that all of the information from the problem has already been incorporated

#

and the problem asks only for an example of a polynomial with the properties it gives you

#

you have 3 variables and 1 equation relating them

#

pick two of your three variables (b, c, d) and set them to any values you want.

#

there are no wrong answers here, but if you are having trouble deciding, then say "I am Buridan's ass!" and i will pick some for you.

crimson estuary
#

so if i set b = 1 and c = 2

#

i get -8 + 8 -2d = -20

#

then 2d = 20
then d = 10?

tropic oxide
#

indeed.

crimson estuary
#

so is it just 2x^4 + 10x?

tropic oxide
#

you yourself set b to 1 and c to 2

#

but now you have struck them down entirely

#

as if they were trash to rid yourself of

crimson estuary
#

fhoauisfj

tropic oxide
#

you need to not forget things that you yourself have done

crimson estuary
#

ok ive kinda confused myself now

#

so 2x^4 + x^3 + 2x^2 + 10x + 0?

tropic oxide
#

yes

#

you do not need to keep that zero around

crimson estuary
#

oh ok

tropic oxide
#

are you able to do part c?

crimson estuary
#

let me try

#

ok i think ill be fine

cedar kilnBOT
#

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still raft
#

Hello how do I solve this?

cedar kilnBOT
still raft
#

do I just 0=x-cos(x) and then solve for x?

untold torrent
#

No, there's no good way of isolating x.

#

You just need to show a solution exists somewhere.

jaunty mural
#

I mean - what's your idea to try if u wanna do this

still raft
#

or something

still raft
gleaming cloud
#

yes

jaunty mural
#

No - I was saying if you wanted to solve the equation

#

what did you wanna do

#

(im just checking - because nothing should really work)

gleaming cloud
#

ivt should work?

#

oh wait nvm

still raft
jaunty mural
#

yeah no, you cant

gleaming cloud
jaunty mural
#

All you have is a theorem that can show the existence of solutions given certain conditions

still raft
#

I think I figured something out, let me try it. thanks all

#

.close

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twilit nest
#

Hey, i am unsure if this is correct. Could someone have a look?

cedar kilnBOT
#

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hollow beacon
#

can someone help me understand: https://www.geeksforgeeks.org/find-the-largest-possible-value-of-k-such-that-k-modulo-x-is-y/
namely this observation: to maximize the answer, we need to consider only two integers:
n−nmodx+y
n−nmodx−(x−y)
.

cedar kilnBOT
#

@hollow beacon Has your question been resolved?

cedar kilnBOT
#

@hollow beacon Has your question been resolved?

cedar kilnBOT
#

@hollow beacon Has your question been resolved?

cedar kilnBOT
#

@hollow beacon Has your question been resolved?

cedar kilnBOT
#

@hollow beacon Has your question been resolved?

cedar kilnBOT
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sacred stone
#

hwo do i find m<IJK

cedar kilnBOT
crimson sedge
#

Well we know that IJL is 92°

sacred stone
#

yess

crimson sedge
#

And LJK is 65°

#

Is there any relationship between these two angles and the angle we want to get?

sacred stone
#

nope

crimson sedge
#

There isn’t?

sacred stone
#

no because

crimson sedge
#

There is.

sacred stone
#

oh

#

i dont see it 😭

crimson sedge
#

What angles does the angle IJK consist of?

sacred stone
#

isnt a relationship like when theyre intersecting

crimson sedge
#

So

#

*no

sacred stone
crimson sedge
#

IJK consists of angles IJL + LJK

#

So you add.

sacred stone
sacred stone
#

157

surreal cave
#

m∠IJK = m∠IJL + m∠LJK

sacred stone
#

how

#

wait but its 157 right

#

.close

cedar kilnBOT
#
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surreal cave
sacred stone
#

.reopen

cedar kilnBOT
#

sacred stone
#

like

#

ykw nvm

#

.close

cedar kilnBOT
#
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cedar kilnBOT
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fervent depot
cedar kilnBOT
fervent depot
#

help pls

surreal cave
#

use $a_{n}=a_{1}+(n-1)d$ to solve for $a_{1}$ :)

wraith daggerBOT
#

MrFancy

fervent depot
#

i see

#

can you explain more in detail?

cedar kilnBOT
#

@fervent depot Has your question been resolved?

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warm bone
#

hello, i would like some help in solving this limit

warm bone
#

i need to determine the limit as x approaches inf and -inf

#

however i'm not sure what exactly i should do. i'd like to first divide every term by x^2/3

celest ledge
#

Divide by x^(4/3) both above and below

warm bone
#

oh yeah squared

#

why isn't it 4/9?

celest ledge
#

1/4^2

#

1/16

#

Above 1+…, 1 left, below (4+..)^2, 16 left

warm bone
#

why am i dividing by x^4/3

#

where did that number come from

celest ledge
#

#

Highest power is 4/3 for both above and below

warm bone
#

says to divide every term by the highest power of x that appears in the denominator, so how did we get x^4/3 from 4x^2/3

vestal bear
#

highest power in the denominator

celest ledge
#

vestal bear
#

youre trying to get rid of x in the denominator

celest ledge
#

Let him

warm bone
#

oh

#

alright good point

#

i see my mistake, ty

#

.close

cedar kilnBOT
#
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scarlet star
#

Hello I need help with all four questions. I do not understand anything in this question.

nimble mulch
#

Are you familiar with integrals

scarlet star
#

No

nimble mulch
#

but you were introduced to calculating area under a curve

scarlet star
#

Not really

nimble mulch
#

even if not, here you only need to calculate the area of triangles and rectangles

#

eg consider the first graph

scarlet star
#

Ok

nimble mulch
#

it goes from (0|0) to (0.09|3)

#

so you know the change in x and in y

scarlet star
#

Ok

nimble mulch
#

meaning you know the length and the height of the triangle which forms the shape under the graph relative to the x-axis

#

can you thereby calculate that area?

scarlet star
#

I don’t know how to calculate it

scarlet star
nimble mulch
#

well if I tell you a right triangle

#

has length 0.09

#

and height 3

#

can you tell me the area of that right triangle

scarlet star
#

Ok one second

#

0.27

nimble mulch
#

nop

#

the area of a triangle is 0.5 * length * height

scarlet star
#

0.135

nimble mulch
#

0.5 * 0.09 * 3 = 0.135

#

ys

scarlet star
#

Ok

nimble mulch
#

that's the area for A

#

once you see the relation between the area under the graphs and the according triangles/rectangles it's easy

#

you can apply the same for the other tasks

#

just keep in mind that area under the x-axis is considered negative

scarlet star
#

Can I try them and tell you the answer to tell me if it’s correct

nimble mulch
#

sure I may not be here but others can check as well :)

scarlet star
#

Ok

#

For the first one I got 0.135

#

Not to doubt you or anything but when I searched it up they all used a itegrals formula starting with an s symbol

#

I that the same thing on the paper I am doing or something completely different?

nimble mulch
#

generally you solve them with integrals

#

Eg if I gave you a sine curve

#

And you want to know the area

#

you can't use triangles

scarlet star
#

so what i am doing right now is correct?

#

do you want me to show you the previous pages i worked on?

#

for b i got 20

#

and a i got 0.135

nimble mulch
#

I think you may have gotten the rectangle wrongly

#

which is just length * height

#

8 for the left triangle

scarlet star
#

so just 40?

nimble mulch
#

8 for the right triangle

#

8 for the rectangle

#

= 24

scarlet star
#

i am confused what triangles?

nimble mulch
#

Task b)

#

it starts with a slope upwards

#

then a constant value

scarlet star
#

oh the drawing makes 2 triangles

nimble mulch
#

then a slope downwards

#

consider the three regions there shapes yes

scarlet star
#

i honostly think this may be wanting the definite integral formula

#

would that be possible?

nimble mulch
#

Sure but I thought you didn't have intwgrals

scarlet star
#

yea i didnt learn them yet its my summer packet so it may want me to do it for the first time

#

i am going into physics this year

#

lets do it using that

#

the page before it was talking about best fit lines and scatter plots, and slope intercept form

nimble mulch
scarlet star
#

ok

nimble mulch
#

are you fully unfamiliar with the integral notation

scarlet star
#

yes

nimble mulch
#

because if so I may have trouble writing it out on phone, would be better if someone else may take over as I'm not on my setup

#

but the interpretation of the symbol is fairly straightforward

#

you have two values at the top and bottom of the S

scarlet star
#

ok

nimble mulch
#

and then a function inside

#

the values describe the interval for the integral

#

eg in your first image a)

#

you'd take the integral for the interval 0 to 0.09

#

and the function would be 100x/3 which you get by retrieving the linear function for the line

#

so you actually calculate the integral from 0 to 0.09 of 100x/3

#

which is the same as the area under curve

scarlet star
#

can u get me a picture of this formula

nimble mulch
#

the key aspect is that the value of the integral always refers to the signed area

nimble mulch
scarlet star
#

is it this?

#

ok, thanks for you help i guess i will wait for someone else

nimble mulch
#

yes

#

bottom a for the lower interval bound

#

upper a for the higher interval bound

#

usually

#

in case no one comes along I'll be able to write to you tomorrow as well

scarlet star
#

ok, thank u

dire geode
#

.close

cedar kilnBOT
#
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serene badge
#

I'm stuck on number 20, I'm having problem starting the problem and haven't continued after that.

weary vessel
#

Draw roughly, it makes it easier

#

Use vectors sum to find H

cedar kilnBOT
#

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spare dome
#

how do you find the oblique asymptotes to this?

cedar kilnBOT
#

@spare dome Has your question been resolved?

south tundra
#

Do you know how to find oblique asymptotes for a function in general?

spare dome
south tundra
#

thonk You need to find a and b s.t. lim (f(x) - (ax + b)) = 0 as x -> inf or x -> -inf

#

So here you can make the denominators common for x^4/sqrt(x^6 + 1) - ax and then use the conjugate

cosmic steppe
#

So you can just omit the 1

spare dome
#

oh okay

#

thanks

cedar kilnBOT
#

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meager sonnet
#

Hi anybody here

cedar kilnBOT
meager sonnet
#

for rho 2 there is definitely an error here right?

#

<@&286206848099549185>

cedar kilnBOT
#

@meager sonnet Has your question been resolved?

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@meager sonnet Has your question been resolved?

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@meager sonnet Has your question been resolved?

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civic meteor
cedar kilnBOT
civic meteor
#

x'=3x+5y
y'=x+2y
x=(x'-5y)/3
y=(y'-x)/2
i plugin these expressions into y=2-3x
(y-x)/2=2-3((x-5y)/3)
y-x=2(2-(x-5y))
y-x=4-2x+10y
9y=x-4
y=(x-4)/9

#

did i do it it right?

tropic oxide
#

you are mixing old and new together

#

so your work is unsalvageable unfortunately

civic meteor
#

wdym?

#

the x' and y' are only to indicate that the old equation will be used to plugged into

#

as they are the new x and y after the tranformation has taken place

wraith daggerBOT
cedar kilnBOT
#

@civic meteor Has your question been resolved?

civic meteor
#

<@&286206848099549185>

cedar kilnBOT
#

@civic meteor Has your question been resolved?

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#
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dim tiger
wraith daggerBOT
#

calculus is fun
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

celest ledge
#

A in your text

#

Your original basis is x_α: α from A

dim tiger
#

so A is indexing set

#

but then what does this set have to do with what we were talking about

celest ledge
#

It’s just that p-1 elements of x is replaced

#

|A|-(p-1) many x remaining

#

I just didn’t see any reason I express the number |A|-(p-1) differently

dim tiger
#

ohh yea i get your idea now

celest ledge
#

Okay

dim tiger
#

tysm for your time sorry if you dont like to get pinged i wont do that again

#

i just pinged this time because it was something you wrote so you are the best to clarify what you wrote

#

.close

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#
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azure citrus
#

Hi guys! just started abstract math. i definitely didnt do this right i think..

My understandings is that true implies true, false implies false, and false implies true. but not sure i did this right, or even understand what the question was asking.

tropic oxide
#

your column for $\neg Q$ looks wrong.

azure citrus
#

like im not sure if the column is saying "This statement is true" and i plug it in

wraith daggerBOT
azure citrus
#

or would it be then like:
F
F
T
T
F
F
T
T

#

cause i feel like it wants me to plug -q into the truth table statement

tropic oxide
#

idk what "plug -q into the truth table statement" means

azure citrus
#

yeah sorry okay lemme try again

tropic oxide
azure citrus
#

oh okay. i get it then

#

i think i just didn’t understand the instructions :p

tropic oxide
#

that is the most likely cause of your confusion, yes.

azure citrus
#

can you help me with this one then? i’m not sure at all how to start.

tropic oxide
#

construct one big truth table with columns for !P, !Q, P=>Q, !Q=>!P and !P OR Q.

azure citrus
#

! being not right?

cedar kilnBOT
#

@azure citrus Has your question been resolved?

cedar kilnBOT
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onyx owl
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Hello, how can I get dot product out of the degrees between the two vectors?

nimble mulch
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therefore if you have the angle, you get the dot product via

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cos(angle)*(|A|*|B|)

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where A, B are the vectors

onyx owl
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Oh, yeah, forgot about that formula, yeah, sounds brilliant, thank you 😄

nimble mulch
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and |...| would be the magnitude

nimble mulch
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the same applies for sin btw

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sin(angle) = det(A,B)/(|A|*|B|)

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really neat equations for linear algebra

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as they're quite fundamental

onyx owl
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but there is not actual reason to use sin instead of cos I suppose?

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I mean, they give the same result

nimble mulch
onyx owl
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oh, initially I thought that you mistyped dot 😄

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nvm

nimble mulch
onyx owl
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alright, thank you so much 🙏

nimble mulch
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seh jz erst das München, selten dass hier Deutsche sind :3

onyx owl
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I'm not actually German

nimble mulch
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oops

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😄

onyx owl
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hehe, it's just a local meme 😛

nimble mulch
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kk cya

cedar kilnBOT
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@onyx owl Has your question been resolved?

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limpid bane
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Is a liter = dm^3 for both solids, liquids and gases? Or only for water?

tropic oxide
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it's a unit of volume

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it doesn't matter what it measures the volume of

limpid bane
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Oki

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Oh nevermind i just remembered that a liter of water weights 1kg

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I confused the things

tropic oxide
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yes, that's one of the original defining features of metric.

limpid bane
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Also if I’m doing some operations in chemistry should I use liters or dm^3?

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I know I should use pascals instead of bars

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Or kelvins instead of celsius

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But with the volume?

vagrant elbow
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litres are pretty standard

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but it depends on what the question you're working on uses

limpid bane
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Sometimes they give me the wrong measuring unit to confuse me

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But idk if I should use liters or dm^3 (the question uses dm^3 but idk if it’s accepted in the standard National measuring thing)

slate lintel
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both of them are SI units

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i'd probably use liters most of the time

limpid bane
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Thanks 🙏

cedar kilnBOT
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cedar kilnBOT
dire geode
cedar kilnBOT
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graceful island
cedar kilnBOT
graceful island
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i’m kinda confused with this bc i did everything to not solve it
but all i could do is process of elimination to determine that it’s the first two that aren’t crossed out

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ik it’s these two bc i accidentally solved them lol, but can’t seem to figure out how to do it without solving

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<@&286206848099549185> ?

fallow steppe
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sorry if something important got purged, but autodelete on ban failed

graceful island
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nw

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repost?

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so i narrowed it down to the first two that aren’t crossed out mainly bc i accidentally solved the integral. Going back, i kinda bs’ed it using process of elimination, but i’m still unsure if there’s another way of going about this. Any clue how to go about solving it?

tranquil drift
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I think method of elimination works fine. You correctly deduced that it cannot be bottom left because the integral would be negative.

graceful island
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yeap

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what about bottom right?

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would that reasoning work?

tranquil drift
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I am not so sure myself what they want for the other one but i assume its because of the large values on the y axis

graceful island
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gotcha

stiff totem
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fwiw, it asks about the area of the shaded regions, so I think you'd take the absolute value of the lower left integral anyway

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the area is still too small in this case, but just because the integral spits out a negative doesn't mean the shaded area is necessarily different

graceful island
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Ahh i see

tranquil drift
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ah true

graceful island
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how could i justify the bottom left?

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i mean tbf, i don’t think i even did the bottom right justification correctly

stiff totem
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the curve doesn't go below -1 I guess

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so it's constrained within a really small box, so you know the area will be small

graceful island
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what about the lower bound being too big?

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when absolute?

stiff totem
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oh, I just read the title; it says "using the substitution rule"

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there's probably a neater way of doing this

graceful island
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definitely
that’s where i’m kinda confused lol

stiff totem
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try transform them all into the form ae^x or something using u-substitution

graceful island
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alr alr

tranquil drift
graceful island
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for the first graph
using u=-x^2
i would also have to adjust the bounds accordingly
correct?

stiff totem
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yes, always adjust the bounds

tranquil drift
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i would do u=x^2 without the -

graceful island
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smart

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uh

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itd be the same thing lol

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when u integrate
the negative will come down regardless

stiff totem
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no, but you get it into the same form as the other integral

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if you use u = x^2

graceful island
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oh i see what u mean

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matching the integral

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bro i ended up solving it again 🤦🏽‍♂️😭

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i think i got it! tysm 🙂

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.close

cedar kilnBOT
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crimson sedge
cedar kilnBOT
crimson sedge
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So when I try this on

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“Find hcf of 120, 36, and 84”

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I

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Lemme show u

tropic oxide
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image incoming?

crimson sedge
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Yee

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Wait

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Nvm

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.close

cedar kilnBOT
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crimson sedge
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.reopen

cedar kilnBOT
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crimson sedge
crimson sedge
crimson sedge
tropic oxide
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ok so

crimson sedge
tropic oxide
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36 = 2 * 2 * 3 * 7?

crimson sedge
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Which is wrong

tropic oxide
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where did 7 come from in the factorization of 36?

crimson sedge
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O:

tropic oxide
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for that matter, why is 84 written as 2 * 2 * 3 * 3...

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did you switch 84 and 36 around, or what

crimson sedge
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I think so

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Lemme fiz that

tropic oxide
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120 = 2 * 2 * 2 * 3 * 5
84 = 2 * 2 * 3 * 7
36 = 2 * 2 * 3 * 3

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your answer curiously doesn't include any fives even though 120 has one.

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how come?

crimson sedge
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O:

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Lemme fix that too

tropic oxide
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wait hold on

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we are finding the least common multiple, yes?

crimson sedge
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Yes

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Okay

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I got it right this time

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Thank you BLESS U BYE ;***

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.close

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cedar kilnBOT
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tawdry thunder
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how do I solve this?

cedar kilnBOT
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@tawdry thunder Has your question been resolved?

crimson sedge
tawdry thunder
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yup

crimson sedge
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the domain is rappresented in the x axes and the range in the y axes

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so in this case the function is between 2 and 6 in the x right?

tawdry thunder
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I think ye

crimson sedge
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while in the y axes what is the interval?

tawdry thunder
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?

crimson sedge
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in the y axes what are the point where there is th funcion?

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the funcion is between -2 and -6

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so domain [2;6] and range [-6;-2]

tawdry thunder
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ohhh makes sense what about this one?

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This one looks completely different to me

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Then how I was taught a bit

cedar kilnBOT
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@tawdry thunder Has your question been resolved?

tawdry thunder
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.close

cedar kilnBOT
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shrewd blaze
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..

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Can someone tell me what i did wrong to 3 and 4

shrewd blaze
crimson sedge
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what are your steps for 3 first

shrewd blaze
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I swear im right, But i cant Make square root

crimson sedge
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no number 3 not number 4 we'll do number 4 second

shrewd blaze
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Oh okay

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Basically i did the parentisis first, So 2y will be 4y² since it is squared, then 3x3=9, then i transfer it to -49 and change its sign, Then it would be -49 - -9=40

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Then i find the root square

crimson sedge
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Well

shrewd blaze
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I Divided with 2 first to cancel it

crimson sedge
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theres no reason to foil it out

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because 49 is a perfect square

shrewd blaze
crimson sedge
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so you can just find the square root of both sides at the start

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and get 2y-3=+-7

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then

2y-3=7

2y-3=-7

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you should be able to solve from there

shrewd blaze
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Where did the -7 came from?

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Square root of 7?

crimson sedge
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squarte root of 49

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square

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is + or - 7

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because (-7) squared and 7 squared are both 49

shrewd blaze
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So y=+-7?

crimson sedge
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No

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2y-3=+-7

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you need to solve for both equations

shrewd blaze
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I got it