#help-13
1 messages · Page 174 of 1
You just need to cancel out the sqrts and get to your answers
Now, for g, make 1 into y/y and cancel.
I can explain further if needed
ohhhh that makes sense for g, thanks. Let me try them all again I will send again in channel either that I completed them or if I am still confused
Gotcha
where would I go from here
Okay lets backtrack to your initial substitution.
alright
Let us multiply by complex fraction by y/y (as to make it a simpler fraction, however, it is possible to do it without this step)
Correct
It's better to leave the denominator as a factored form, but do you see where we might be able to cancel a factor on the numerator and denominator?
is there a way you can make it y-2?
the coefficients of both the constant and the y are the same
But it's just one thing that's different...
if we flip it it will be -y+2
correct.
should i multiply by -1 or something
Yup
ok
is this correct
Yep
so the answer would just be 0?
Mhmm
oh so it would be 1/2
that's right.
thank you so much that was helpful
No problem!
/solved
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im confused on what are the first steps
ooh i loved these types of questions
thats good
so are you aware of the ASTC rule?
no ive never heard of it
in Quadrant II only sine and cosec are positive, which means the other 4 trigonometric function will be negative
are you able to calculate what sin(t) will be, knowing that csc(t) = 3 ?
yes but it's value
oh no i dont know how to
will be 1/3
sin(t) = 1/3
are you aware sin(t) = 1/csc(t)
no
you will be working with the reciprocal and pythagoream identities
to find all six trig functions
first step was to know which are postive and negative. (we now know by the ASTC rule that only sin and csc are positive)
next....
we apply the first identity to find sin(t)
which is simply the reciprocal of csc(t)
yeah
and csc(t) = 3 according to the question. so sin(t) = 1/3
oh okay
next we will find cos(t)
we will use the first pythagoran identity
we now know that sin(t) = 1/3 so we will use this info to find cos(t)
gotchu
sqrt(2)?
oh okay yeah
the second pythagorean equation
But for that you need the value of tan(t)
You will use the second reciprocal identity
Because you already know cos(t)
You will use it to get sec(t)
oh
And then use the second Pythagorean equation to get tan(t) using sec(t)
Then the last step: use tan(t) to get cot(t) using the final reciprocal identity
okay thank you unfortunately i had to leave my homework to drop somone off but i will keep a picture of the convo
I have a sample question somewhere let me get that
I will DM you the sample/example question
@lofty granite
okay thank you
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Hi. Best learning apps.
For math.
13-15 year old math.
Especially algebra
And creating algebra equation
Example like this
The price of a theater ticket is 64$ more than a cinema ticket. A total of 400$ was paid for 4 theater tickets and 5 cinema tickets
Calculate the price of one theater ticket. Save calculations.
I wanna learn how to do these
I suck at these
x = 64 + y
400 = 4x + 5y
Simplify
Yk how to do this?
@glad dagger
substitute the x in 4x with “64+y”
400 = 4(64+y) + y
400 = 256 + 4y + y
400 = 256 + 5y
I think I have made a mistake
Anyway this is pretty much the process
Have you heard of khan academy?
This book is a good for pre-algebra.
https://batch.libretexts.org/print/Letter/Finished/math-22458/Full.pdf
This book is good for basic algebra
https://batch.libretexts.org/print/Letter/Finished/math-19848/Full.pdf
No
What’s this
click on it and see
@glad dagger Has your question been resolved?
@glad dagger Has your question been resolved?
i watched a lot of black pen red pen on youtube he does stuff like that
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how do i do this? where do i start? am trying to simplify
i would replace the bases with their prime factorizations
after that this is what i got: (8)^12 x (3)^30 / 1^46
what do i do from here? plz ping me next time so i get a notif
doesn't seem right, did you skip some steps?
ok well first of all you misread a 5 as a 6 but beyond that
you can't cancel factors like that when they're inside a power
$(2.2.2.2)^{12} = 2^{12}.2^{12}.2^{12}.2^{12} = 2^{48}$
hayley!
hayley!
the 45 in the denominator became 46 somehow
do something like this to the factors
oh whoops its my handwriting sry
yep
so the answers 8?
i haven't done the math myself but what did you do with the 18^45 on the bottom?
yeah i split it up to 3x3x2
oh ok cool
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I have a small question
for part a how do I know what to differentiate with respect to?
when it says if k is a constant does that mean I differentiate with respect to k?
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hey so there is this game on a discord bot where it's essentially a sort of gambling. basically you can "buy a chicken" for 100 coins and send it to fight and bet that it will win for however much money as long as it's >= 100 coins. in the first round, it has a 50% chance of winning. each time you win, you gain 1% chance (so 51%, 52%, etc). if it dies, you have to buy a new chicken for 100 coins.
I find this game very interesting because it feels like there's a decent amt of probability and decision making
SO, I'm trying to make a program that can play in the most "accurate" way and gain money. i know this sounds dumb, it's virtual money after all, but I am more interested in the math behind it and how (or if) this can even be done?
winpercentage = min(0.5+0.01*wincount, 100)
virtual chickenfighting, what will they think of next
have you seen that problem where 2019 penguins waddle to their favourite rewstaurant
lootBWAKses
how much do you get if you win?
random?
however much you betted
and you lose that same amount too
can you just bet very little every time, until the percentage goes higher then you roll in the big bucks
yeah but you often lose by like round 2 or 3
but yeah i was actually trying that
coding some weird exponential function where it begins to spend more in later rounds
it seemed like it just performed worse
so the first round is always 100 and then after that you get to pick?
confused
you buy it for 100 coins - exactly?
and then what you send it in with some amount of coins stuffed up its butt? that also has to be at least 100?
yeah which is why dont bet in the early percents
wait until you’re pretty confident it aint gonna die
wait is it theroeiteically possible for the chicken to hit 100%
cuz if that’s the case then ya could just keep doin it until a chick
yeah, so like for example
- you start a game (buy a chicken) for 100
- you play round 1 by betting any amount you want
- if you win, you go to round 2 with a higher chance, still betting how much u want.
If you lose, you go back to step 1
well unfortunately the devs were smart and capped it at 70% xd
,w 100!/(100^50*50!)
but I don't think I've seen it reach round 20 even (prob the chance is so low)
good luck hitting 100%
ah fuck
feels like the first actual bet you do should be a large amount
i think if you bet a constant amount, the expected value will go up
i was thinking, is there a bigger chance of winning after you lose a lot of games?
oh
but even if so, because of the winning percentage going up, the expected value should be a profit
could we be a bit more greedy and bet more on the higher percentages to abuse it
how much money in the game do you have
actually that 50% chance of losing 100 coins (at least) right away seems like a lot
technically like 5000 rn but if you gamble right with other games it won't take long to reach like 50000
depends on what the game
are there any better games
is it dank memer
what game
unbelievaboat
constant amount failed according to my program
like i lost a lot of money 💀
even if the chance were always 70% there would be some minimum bet that you need to use or you lose money on chickens
try telling it to bet 100 every time
and try running it for 1000 games or however many your pc can handle within a second
yeah i did that and it lost so much lol
woah what the hell;
right
why would it happen tho
probably because you are buying chickens in the first place
😭
SO IF I LOSE, I NEEDA BUY ANOTHER CHICKEN AGAIN
yes
so when you lose you’re not only losing your bet, but losing another 100 on top of that
well fuck dont play this game it’s guarantee lose
BRUH
i feel like the max EV here is going to be bet nothing on the 50 then bet everything on the 51% chance
yeah..
it's even more scammy that you must bet at least 100 each round so you can't bet nothing
im starting to think there is no solution
it's just pure luck
so i mean
it shouldn't be
the entry fee doesn't really matter
if you have a big enough bank
wait i agree with hayley
and the game is otherwise positive EV
buy 100, bet 200 on the 51%
yeah
so bet as little as possible on the 50%
and bet 200 for everything >50%
can ya try running a 1000 games or sth on tht
hmm okay i will try
i think with a finite bank you're probably guaranteed to go bust at some point? not sure
some kind of martingale otherwise
but yeah like without the entry fee it's positive EV
ok that was not the best run
-100,000
did it lose every game???
very true i just tested it
uhh
yeah this is kinda alarming
let me look into it
sometimes you can analyze these problems from absurdism
imagine you had a bank of 101 coins
@stark kiln Has your question been resolved?
well you couldn't quite afford a round with that
but what is your point? i am curious
oh wait yeah you need to bet at least 100 on top of the chicken?
yeah
ohhhh okay
a good test for a method like this is to do it over and over with some starting bank
and see whether you go bust first or double your starting cash first
ah thats a good idea
so i started with around 10k and it busts first, anywhere from game 60 to 200
im gonna head out, i honestly dont think there's really a way to play this game accurately lol
thank you everyone for the help
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Been stuck on number 4 for a while. I have an inkling idea of what it means but no idea how to actually rewrite it
x is in at least one of P(A), meaning x is a subset of A, where A is a member of F
That makes sense
So there exists an x that is a subset of A?
Where A is in F
Is that how I’d write it?
This?
I simply explained what it means. I don’t know what form of answer it requires since it’s your assignment.
What you sent looks perfectly correct to me, I just don’t know whether it’s the form your assignment requires
Np
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hello
can anyone help me
sorry its a lot
^
yes
these are all new attempts
second to last question, i put :
[-7,-7] U [7,7]
but it was wrong
@crimson sedge Has your question been resolved?
have you tried just [-7,7]? the only values y can hold lie in that interval, even though y is only either -7 or 7
since it's only asking for one set, that's what my first thought would be
@crimson sedge Has your question been resolved?
@crimson sedge Has your question been resolved?
Well no because f doesn't take all values between -7 and 7 between x in [-5, 5]
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why was sinxdx set to dv and not v?
(-cos(x))’=sin(x)
so when solving integrals by parts, you set u to the first part and derive it and then set the next part to dv instead of v?
and then derive it?
also according to the formula for integration by parts, don't you subtract
It’s simply d(f(x))=f’(x)dx
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If one performs a singular value decomposition on some demeaned data, (n,m) matrix X where n and m are the number of features and observations accordingly, we will get USV = X. From here we can recover the covariance matrix $V^{T}SV$. This will be the equivalent of a maximum likelihood estimator for the covariance under a Gaussian distribution. How is the Gaussian distribution related to the SVD? Is there a normality assumption here somewhere?
LetečiDebjule
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can someone explain a
What are you confused about?
i triedf expanding lhs
so i got
$\frac{1}{\cos(\theta)} + \frac{1}{\sin(\theta)} \times \frac{\cos(\theta)}{\sin(\theta)}
how does this work
\frac{1}{\cos(\theta)} + \frac{1}{\sin(\theta)} \times \frac{\cos(\theta)}{\sin(\theta)}
$\frac{1}{\cos(\theta)} + \frac{1}{\sin(\theta)} \times \frac{\cos(\theta)}{\sin(\theta)}$
rysrobrgldvoelroep>vneae=u
yep
you missed a dollar sign on the end
You could try expanding the right side as well
i did
$\frac{1}{\cos(\theta)} \times \frac{1}{\sin^2(\theta)}$
kevvv
And then you could multiply both expressions for the left and right sides by (cos theta)(sin theta)^2
so that it’s easier to identify them
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how should i do this?
ok
can you write out what a generic polynomial of degree 2 looks like
no other information known about it yet
ax^2 + bx + c?
yes of course. what room is there for second guessing?
wait
now make it monic. do you know what it means for a polynomial to be monic?
so a = 1
2 + bx
❌
yes of course
again this is all simple if you put some thought in it
now make the constant term 1
so x^2 + bx +1
if i subbed in p(-1) just 2 -b = 7
❌
-5
not really
how to do b and c
what does quartic mean?
degree 4.
so it the first term would be 2ax^4
don't try to kill two birds with one stone unless you know exactly what you are doing.
ok
write me a generic 4th-degree polynomial
do nothing else with it until i say otherwise
ax^4+ bx^3 + cx^2 + dx + e
now make its leading coefficient 2.
2x^4+bx^3+cx^2+dx+e
the other terms do not vanish
2x^4 + bx^3+cx^2+dx+0
i think ill just keep it there to make sure i do everythig=ng
anyway, now write what it means that Q(-2) = 12
why would you not keep "the b and stuff"
why's your default to throw them away like they are junk to rid yourself of
better would have been to put it in a new message.
but yes, the equation is 32 - 8b + 4c - 2d = 12
do you see how to proceed?
-8b +4c - 2d = -20
i think you are overthinking it.
observe that all of the information from the problem has already been incorporated
and the problem asks only for an example of a polynomial with the properties it gives you
you have 3 variables and 1 equation relating them
pick two of your three variables (b, c, d) and set them to any values you want.
there are no wrong answers here, but if you are having trouble deciding, then say "I am Buridan's ass!" and i will pick some for you.
indeed.
so is it just 2x^4 + 10x?
you yourself set b to 1 and c to 2
but now you have struck them down entirely
as if they were trash to rid yourself of
fhoauisfj
you need to not forget things that you yourself have done
oh ok
are you able to do part c?
@crimson estuary Has your question been resolved?
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Hello how do I solve this?
do I just 0=x-cos(x) and then solve for x?
No, there's no good way of isolating x.
You just need to show a solution exists somewhere.
you don't have the tools to do it this way?
I mean - what's your idea to try if u wanna do this
like the intemediate value theorem?
or something
something to do with continuity is what I think I should be doing
yes
No - I was saying if you wanted to solve the equation
what did you wanna do
(im just checking - because nothing should really work)
put it in wolframalpha lol, I dont really know
yeah no, you cant
kid named wolf:
All you have is a theorem that can show the existence of solutions given certain conditions
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Hey, i am unsure if this is correct. Could someone have a look?
@twilit nest Has your question been resolved?
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can someone help me understand: https://www.geeksforgeeks.org/find-the-largest-possible-value-of-k-such-that-k-modulo-x-is-y/
namely this observation: to maximize the answer, we need to consider only two integers:
n−nmodx+y
n−nmodx−(x−y)
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@hollow beacon Has your question been resolved?
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@hollow beacon Has your question been resolved?
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hwo do i find m<IJK
Well we know that IJL is 92°
yess
And LJK is 65°
Is there any relationship between these two angles and the angle we want to get?
nope
There isn’t?
no because
There is.
What angles does the angle IJK consist of?
isnt a relationship like when theyre intersecting
I j k
?
m∠IJK = m∠IJL + m∠LJK
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look at the angles
.reopen
✅
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help pls
use $a_{n}=a_{1}+(n-1)d$ to solve for $a_{1}$ :)
MrFancy
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hello, i would like some help in solving this limit
i need to determine the limit as x approaches inf and -inf
however i'm not sure what exactly i should do. i'd like to first divide every term by x^2/3
Divide by x^(4/3) both above and below
says to divide every term by the highest power of x that appears in the denominator, so how did we get x^4/3 from 4x^2/3
highest power in the denominator
…
youre trying to get rid of x in the denominator
Let him
bro
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Hello I need help with all four questions. I do not understand anything in this question.
Are you familiar with integrals
No
but you were introduced to calculating area under a curve
Not really
even if not, here you only need to calculate the area of triangles and rectangles
eg consider the first graph
Ok
Ok
meaning you know the length and the height of the triangle which forms the shape under the graph relative to the x-axis
can you thereby calculate that area?
I don’t know how to calculate it
Yes, but I am not sure how to do it
well if I tell you a right triangle
has length 0.09
and height 3
can you tell me the area of that right triangle
0.135
Ok
that's the area for A
once you see the relation between the area under the graphs and the according triangles/rectangles it's easy
you can apply the same for the other tasks
just keep in mind that area under the x-axis is considered negative
Can I try them and tell you the answer to tell me if it’s correct
sure I may not be here but others can check as well :)
Ok
For the first one I got 0.135
Not to doubt you or anything but when I searched it up they all used a itegrals formula starting with an s symbol
I that the same thing on the paper I am doing or something completely different?
Given that you mentioned you haven't yet done integrals you can ignore that for now
generally you solve them with integrals
Eg if I gave you a sine curve
And you want to know the area
you can't use triangles
so what i am doing right now is correct?
do you want me to show you the previous pages i worked on?
for b i got 20
and a i got 0.135
How is it 20
I think you may have gotten the rectangle wrongly
which is just length * height
8 for the left triangle
so just 40?
i am confused what triangles?
oh the drawing makes 2 triangles
i honostly think this may be wanting the definite integral formula
would that be possible?
Sure but I thought you didn't have intwgrals
yea i didnt learn them yet its my summer packet so it may want me to do it for the first time
i am going into physics this year
lets do it using that
the page before it was talking about best fit lines and scatter plots, and slope intercept form
k a sec
ok
are you fully unfamiliar with the integral notation
yes
because if so I may have trouble writing it out on phone, would be better if someone else may take over as I'm not on my setup
but the interpretation of the symbol is fairly straightforward
you have two values at the top and bottom of the S
ok
and then a function inside
the values describe the interval for the integral
eg in your first image a)
you'd take the integral for the interval 0 to 0.09
and the function would be 100x/3 which you get by retrieving the linear function for the line
so you actually calculate the integral from 0 to 0.09 of 100x/3
which is the same as the area under curve
can u get me a picture of this formula
the key aspect is that the value of the integral always refers to the signed area
I would but on phone it becomes quite annoying, I'll hope someone else comes by though :)
yes
bottom a for the lower interval bound
upper a for the higher interval bound
usually
in case no one comes along I'll be able to write to you tomorrow as well
ok, thank u
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I'm stuck on number 20, I'm having problem starting the problem and haven't continued after that.
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how do you find the oblique asymptotes to this?
@spare dome Has your question been resolved?
Do you know how to find oblique asymptotes for a function in general?
yeah, top divided by bottom. how would you divide a square root in this case?
You need to find a and b s.t. lim (f(x) - (ax + b)) = 0 as x -> inf or x -> -inf
So here you can make the denominators common for x^4/sqrt(x^6 + 1) - ax and then use the conjugate
Think about this in terms of end behavior. In other words, focus only on the leading terms
So you can just omit the 1
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Hi anybody here
@meager sonnet Has your question been resolved?
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x'=3x+5y
y'=x+2y
x=(x'-5y)/3
y=(y'-x)/2
i plugin these expressions into y=2-3x
(y-x)/2=2-3((x-5y)/3)
y-x=2(2-(x-5y))
y-x=4-2x+10y
9y=x-4
y=(x-4)/9
did i do it it right?
wdym?
the x' and y' are only to indicate that the old equation will be used to plugged into
as they are the new x and y after the tranformation has taken place
jstn.
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<@&286206848099549185>
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@celest ledge dw you can respond when you want in #help-21|아리스킨충1 you said that A is index of $\alpha$ wdym by that
calculus is fun
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so A is indexing set
but then what does this set have to do with what we were talking about
It’s just that p-1 elements of x is replaced
|A|-(p-1) many x remaining
I just didn’t see any reason I express the number |A|-(p-1) differently
ohh yea i get your idea now
Okay
tysm for your time sorry if you dont like to get pinged i wont do that again
i just pinged this time because it was something you wrote so you are the best to clarify what you wrote
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Hi guys! just started abstract math. i definitely didnt do this right i think..
My understandings is that true implies true, false implies false, and false implies true. but not sure i did this right, or even understand what the question was asking.
your column for $\neg Q$ looks wrong.
like im not sure if the column is saying "This statement is true" and i plug it in
Ann
or would it be then like:
F
F
T
T
F
F
T
T
cause i feel like it wants me to plug -q into the truth table statement
idk what "plug -q into the truth table statement" means
yeah sorry okay lemme try again
yes that is exactly what it would be
that is the most likely cause of your confusion, yes.
can you help me with this one then? i’m not sure at all how to start.
construct one big truth table with columns for !P, !Q, P=>Q, !Q=>!P and !P OR Q.
! being not right?
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Hello, how can I get dot product out of the degrees between the two vectors?
cos(angle) = dot(A,B)/(|A|*|B|)
therefore if you have the angle, you get the dot product via
cos(angle)*(|A|*|B|)
where A, B are the vectors
Oh, yeah, forgot about that formula, yeah, sounds brilliant, thank you 😄
and |...| would be the magnitude
np 🦇
the same applies for sin btw
sin(angle) = det(A,B)/(|A|*|B|)
really neat equations for linear algebra
as they're quite fundamental
but there is not actual reason to use sin instead of cos I suppose?
I mean, they give the same result
for sin you have the determinant instead of the dot product
so if you had the angle but instead wanted the determinant, then you'd get it this way :)
alright, thank you so much 🙏
seh jz erst das München, selten dass hier Deutsche sind :3
I'm not actually German
hehe, it's just a local meme 😛
kk cya
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Is a liter = dm^3 for both solids, liquids and gases? Or only for water?
Oki
Oh nevermind i just remembered that a liter of water weights 1kg
I confused the things
yes, that's one of the original defining features of metric.
Also if I’m doing some operations in chemistry should I use liters or dm^3?
I know I should use pascals instead of bars
Or kelvins instead of celsius
But with the volume?
litres are pretty standard
but it depends on what the question you're working on uses
Sometimes they give me the wrong measuring unit to confuse me
But idk if I should use liters or dm^3 (the question uses dm^3 but idk if it’s accepted in the standard National measuring thing)
Thanks 🙏
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better suited for#discussion
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i’m kinda confused with this bc i did everything to not solve it
but all i could do is process of elimination to determine that it’s the first two that aren’t crossed out
ik it’s these two bc i accidentally solved them lol, but can’t seem to figure out how to do it without solving
<@&286206848099549185> ?
sorry if something important got purged, but autodelete on ban failed
nw
repost?
so i narrowed it down to the first two that aren’t crossed out mainly bc i accidentally solved the integral. Going back, i kinda bs’ed it using process of elimination, but i’m still unsure if there’s another way of going about this. Any clue how to go about solving it?
I think method of elimination works fine. You correctly deduced that it cannot be bottom left because the integral would be negative.
I am not so sure myself what they want for the other one but i assume its because of the large values on the y axis
gotcha
fwiw, it asks about the area of the shaded regions, so I think you'd take the absolute value of the lower left integral anyway
the area is still too small in this case, but just because the integral spits out a negative doesn't mean the shaded area is necessarily different
Ahh i see
ah true
how could i justify the bottom left?
i mean tbf, i don’t think i even did the bottom right justification correctly
the curve doesn't go below -1 I guess
so it's constrained within a really small box, so you know the area will be small
ahh i see
oh, I just read the title; it says "using the substitution rule"
there's probably a neater way of doing this
definitely
that’s where i’m kinda confused lol
try transform them all into the form ae^x or something using u-substitution
alr alr
ah yeah reading helps 😅
for the first graph
using u=-x^2
i would also have to adjust the bounds accordingly
correct?
yes, always adjust the bounds
i would do u=x^2 without the -
smart
uh
itd be the same thing lol
when u integrate
the negative will come down regardless
oh i see what u mean
matching the integral
bro i ended up solving it again 🤦🏽♂️😭
i think i got it! tysm 🙂
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image incoming?
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✅
This is the method i used
look^
ok so
My ans is 1512
36 = 2 * 2 * 3 * 7?
Which is wrong
where did 7 come from in the factorization of 36?
O:
for that matter, why is 84 written as 2 * 2 * 3 * 3...
did you switch 84 and 36 around, or what
120 = 2 * 2 * 2 * 3 * 5
84 = 2 * 2 * 3 * 7
36 = 2 * 2 * 3 * 3
your answer curiously doesn't include any fives even though 120 has one.
how come?
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how do I solve this?
@tawdry thunder Has your question been resolved?
need help?
yup
the domain is rappresented in the x axes and the range in the y axes
so in this case the function is between 2 and 6 in the x right?
I think ye
while in the y axes what is the interval?
?
in the y axes what are the point where there is th funcion?
the funcion is between -2 and -6
so domain [2;6] and range [-6;-2]
ohhh makes sense what about this one?
This one looks completely different to me
Then how I was taught a bit
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I cant get the square roott
what are your steps for 3 first
I put 80 to 0,Then change it's sign, Then i divided 4,to cancel it, and make it to y²
I swear im right, But i cant Make square root
no number 3 not number 4 we'll do number 4 second
Oh okay
Basically i did the parentisis first, So 2y will be 4y² since it is squared, then 3x3=9, then i transfer it to -49 and change its sign, Then it would be -49 - -9=40
Then i find the root square
Well
I Divided with 2 first to cancel it
Ahh, so what do ido😭😭😭
so you can just find the square root of both sides at the start
and get 2y-3=+-7
then
2y-3=7
2y-3=-7
you should be able to solve from there
squarte root of 49
square
is + or - 7
because (-7) squared and 7 squared are both 49
So y=+-7?