this ?
#help-13
dawn junco
wraith daggerBOT
_aplatypus
flint plinth
it's fine if you consolidate the +-[scribble] into just -
dawn junco
then yea it works
obsidian coral
Who said it's wrong?
brittle wasp
But the answer model says: (-3x^2-4x-1)e^-3x but i dont know how to get that
flint plinth
or just multiply out the (x+1)^2 in the second term, and then combine the terms involving x^2, and the terms involving x, and the other terms
brittle wasp
or just multiply out the (x+1)^2 in the second term, and then combine the terms ...
What do you mean?
flint plinth
your answer is perfectly fine though.. it's equal to the one in the answer model
flint plinth
What do you mean?
start like this:
$2(x+1)e^{-3x} - 3(x+1)^2e^{-3x} = \left(2(x+1) - 3(x+1)^2\right) e^{-3x}$
wraith daggerBOT
Bungo
flint plinth
now simplify the stuff in the brackets in that last expression
brittle wasp
Yeah i'm working it out
flint plinth
yep, if the product of two things is zero, then at least one of the things must be zero
wraith daggerBOT
brittle wasp
which denominator
brittle wasp
? but 2*-3 = -6 right
wraith daggerBOT
_aplatypus
pseudo merlin
hi
tame owl
logically x can't be the same length as the side
tame owl
so i have to sub it in?
your formula is right but you need to consider the constraints
pseudo merlin
pardon
o thought i just put 10 into 20-2x and get 20-20
and thats 0
wait.......
theyre both 0
tame owl
...
pseudo merlin
what im confused
tame owl
LOL
pseudo merlin
...
tame owl
ok so basically your x can't be 10 right?
dim willow
Hello?
pseudo merlin
hi
pseudo merlin
ok so basically your x can't be 10 right?
yes
tame owl
So, the maximum value of x is half the width or length:
Maximum x = 10 cm / 2 = 5 cm
pseudo merlin
ohh cause it means
10 or 5
x = 10 or x = 5
ok lets try now
20 - 2x becomes 20-10 which is 10 and 10-2x becomes 10-10 which is 0
woooooaooaoaoaahhh
tame owl
woahh
tame owl
goodnight
pseudo merlin
WISH ME LUCK
tame owl
goodluck!
versed fjord
help
south tundra
You are given that h = 0 and k = 4, so the f(x) should be of the form ax^2 + 4, where a is to be found
And in finding a the point (1, 5) will help us
Generally, some point (x0, y0) lying on the graph of y = f(x) implies that y0 = f(x0)
In our case that means that f(1) = 5
versed fjord
so whats the answer?
south tundra
I (and any helper you may meet here) am not here to give you the answer, but rather guide you through the question
So, is the hint that I gave you enough for you to solve it or do you want me to explain a bit more?
versed fjord
yes please
south tundra
Before I do that, everything I said so far have said makes sense to you, right?
versed fjord
explain one more time
south tundra
Okay, we are given the standard form of a quadratic function, namely f(x) = a(x - h)^2 + k where h and k are the coordinates of its vertex
In this particular case, they are saying (h, k) = (0, 4), so h = 0 and k = 4 for our function f(x)
Meaning that f(x) = a(x - h)^2 + k = a(x - 0)^2 + 4 = ax^2 + 4, right?
versed fjord
yes
south tundra
It is also implied that the point (1, 5) lies on the graph
Which means that if we were to substitute those values (x = 1 and y = 5) into what we have so far, we would get a equation that is true
So, 5 = a * 1^2 + 4 is what we get
Meaning that 5 = a + 4
I think the solution to a should be obvious now
versed fjord
nope
south tundra
Meaning that 5 = a + 4
Can you move the 4 to the other side in this equation?
south tundra
Right, and 5 - 4 is just 1
versed fjord
yeah
south tundra
So a = 1
But don't forget that our main goal was not to find the value of a
We need to write down the standard form, it's just that we needed to know the value of a in order to do that
So, the final answer is f(x) = x^2 + 4
south tundra
You can do analogous steps here, try doing things similar to what I did previously
south tundra
Yes
south tundra
Correct, keep it up
south tundra
Right, so what's a?
versed fjord
a=2
south tundra
Are you sure? You should have gotten a = 4 - 1
versed fjord
?
versed fjord
but you have -1 to the power of 2 which makes another 1
south tundra
Yeah, but that 1 is multiplied by a
And 1 * a is just 1
The "+ 1" stays uneffected
versed fjord
yeah so 1+1
south tundra
$a\cdot1 + 1 \ne a\cdot(1 + 1)$
wraith daggerBOT
alonelybean
south tundra
First you multiply and then add
versed fjord
f(x)=3(x+2)*2+1
south tundra
versed fjord
k ty
cedar kilnBOT
Available help channel!
fringe tree
cedar kilnBOT
fringe tree
Help with this would be greatly appreciated. I have an idea of what to do but want help as I don't want to get it wrong.
granite eagle
so u need to understand the symmetry about the vertex
at x=400 here
then u can intuitively deduce what percent of ppl lie between x=450and x=550
fringe tree
at x 400 is 68%
granite eagle
huh
fringe tree
uh
granite eagle
thats incorrect
fringe tree
idk
fringe tree
yes between 350 and 450
dreamy cloud
find 450 and 550 on that graph
granite eagle
so try making a guess of what percent lie between 400 and 450
dreamy cloud
what are the percentages of the two red lines at those two points
fringe tree
68%?
dreamy cloud
thats one of them
granite eagle
so try making a guess of what percent lie between 400 and 450
answer this again
granite eagle
so now
fringe tree
ya
fringe tree
34
granite eagle
nice
granite eagle
now try solving ur og question
granite eagle
huh thats ur solution to the original qquestion?
fringe tree
im stupid 😭
granite eagle
percentage remmeber?
dreamy cloud
if you mean (50% - 34%) is the answer you arent right, 550 isnt at the end of the tail
granite eagle
<100
granite eagle
if you mean (50% - 34%) is the answer you arent right, 550 isnt at the end of th...
what?
fringe tree
i just did 34 x 3
granite eagle
y tho
granite eagle
ok do u know whats symmetry
granite eagle
if you mean (50% - 34%) is the answer you arent right, 550 isnt at the end of th...
dont ghost elaborate urself; else ur just confusing everyone
granite eagle
google it yt it understand it; im not gonna explain
fringe tree
ok...
dreamy cloud
99.7% is where 550 is (from the right)
68% is where 450 is (from the right)
take the difference of the two and then halve that difference
that gives you the answer
dreamy cloud
the reason you halve is because those percentages still take account of the left side (you dont want that side)
fringe tree
ah
granite eagle
ur new to the server right? did u go thru the rules?
no giving out the answer
help them goddamit
fringe tree
It's not giving out the answer..
dreamy cloud
google it yt it understand it; im not gonna explain
and this isnt helping either
granite eagle
you were giving a wrong answer
i asked a different question to explain symmetry; if u think ur helping them w/o them even knowing whats symmetry nice job
imma just quit
fringe tree
i asked a different question to explain symmetry; if u think ur helping them w/o...
its not helping if u assume i know as much as u do thats just frustrating
dreamy cloud
the normal distribution (that curve you see) is symmetric about its mean (which we are told is 400) @fringe tree
hope that helps
granite eagle
its not helping if u assume i know as much as u do thats just frustrating
ummm when? its hard to explain so i asked u to google 
now u just trying to piss me
fringe tree
if someone comes here
chances are they already tried google
so they want someone else to explain it to them in a way they will understand
thats all im saying
granite eagle
good sir please understand i tried to explain a long way before asking u to do that; but believe me its really basic and hard to explain just google it u'll understand it
fringe tree
ok.
granite eagle
dreamy cloud
theres a method of doing this without the graph as well, im not too sure if youll always be given a graph like this
dreamy cloud
270 to 330
fringe tree
that is 68
dreamy cloud
yes
granite eagle
theres a method of doing this without the graph as well, im not too sure if youl...
and its...
dreamy cloud
its something ill tell if they want to know
fringe tree
but if it were 270 to 300, it'd be 34?
dreamy cloud
thats right
fringe tree
ok
granite eagle
its something ill tell if they want to know
we r supposed to help each other u know... its not a job to maintain this lvl of rigidity
fringe tree
Can you stop trying to help me please? You are not helping me. @granite eagle
granite eagle
im no longer doing so. trying to understand this method
fringe tree
in other words your help is not helpful
granite eagle
ok
fringe tree
ok 😄
fringe tree
im no longer doing so. trying to understand this method
yes but its distracting my learning experience
kindly not distract anymore, thanks
granite eagle
cedar kilnBOT
Available help channel!
stiff cradle
Hello
stiff cradle
.close
scarlet laurel
How would I approach this problem?
cedar kilnBOT
How would I approach this problem?
silent finch
Find the area under the graph by splitting into easily computable shapes
scarlet laurel
Thanks
balmy jewel
cedar kilnBOT
balmy jewel
Thomas Calculus 16.5: Surfaces and Area. Subtopic: Parametric Surfaces/Surfaces of Revolution. Super confused on why it was done this way
couldn't they have just done $\begin{cases} x = 3\cos(\theta) \ y - 3 = 3\sin(\theta) \implies y = 3\sin(\theta) + 3 \ z = z \end{cases}$?
then $0 \le \theta \le 2\pi$
I know there are infinitely many parameterizations but is it really just a matter of style in this case? or is there really a specific reason
cedar kilnBOT
@balmy jewel Has your question been resolved?
balmy jewel
.close
crimson sedge
how can i search videos in youtube about this?
"Consider that sin(A) = -7/25 in the fourth quadrant and sin(B) = 4/5 in the second quadrant."
crimson sedge
it would be easier if it were without especifying the quadrants
cedar kilnBOT
@crimson sedge Has your question been resolved?
cedar kilnBOT
Available help channel!
warm python
i didnt get it how to do
cedar kilnBOT
i didnt get it how to do
smoky idol
!status
cedar kilnBOT
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
hold on there
warm python
alright
smoky idol
you do realize that tan(43deg) is just a number right?
warm python
yes.
smoky idol
,w tan(43deg)
wraith daggerBOT
smoky idol
approximately this number
warm python
so x = 0.93
warm python
with the 0.93
smoky idol
yes
warm python
0.93 = x/10
warm python
alright
smoky idol
Do you see it now?
warm python
so i do cross multiply or no?
warm python
x = 9.30?
warm python
alright
cedar kilnBOT
Available help channel!
pallid frigate
cedar kilnBOT
pallid frigate
how do i prove that its not a square?
regal oak
Isn't a square a special type of rhombus?
pallid frigate
yea
but its more specific than rhombus
and you have to prove that rhombus is the most specific
regal oak
So it's asking to prove it's a rhombus but not a square?
pallid frigate
So it's asking to prove it's a rhombus but not a square?
yea
well kind of
its asking to prove that rhombus is the most specific you can get
so like, not parallelogram because thats too vague but not square cause thats too specific
regal oak
Oh I get it
We just have to take a random corner and prove it's not 90 degrees
This should be simple if you know about slopes (aka gradient)
pallid frigate
This should be simple if you know about slopes (aka gradient)
huh
regal oak
Do you know?
pallid frigate
no
regal oak
Ok, plan B
pallid frigate
huh
south wedge
what concepts with angles do you know. The only difference between a rhombus and square is the angles\
if you dont have angles
regal oak
I just had an idea
south wedge
use diagonals
pallid frigate
what concepts with angles do you know. The only difference between a rhombus and...
yea but how do we prove that the rhombus doesnt have 90 degree angles with only coordinates
oh
south wedge
yea but how do we prove that the rhombus doesnt have 90 degree angles with only ...
use diagonals then
pallid frigate
ohhhhh
south wedge
the diagonals will be different
south wedge
no problem!
pallid frigate
.close
dry cargo
cedar kilnBOT
dry cargo
Hi I'm still stuck on this question
bold hinge
let's try solving for the points of intersection (this will give us integral bounds)
x+1 = 3
solve for x
dry cargo
2
regal oak
The answer $9\frac{1}{3}\pi$ is correct
wraith daggerBOT
math_is_fun
dry cargo
The answer $9\frac{1}{3}\pi$ is correct
I want the working steps
regal oak
Ok
bold hinge
do you agree?
dry cargo
Yup
bold hinge
what's the equation of the y axis
dry cargo
y = x + 1
bold hinge
no
the y axis has an equation. every point on the y axis satisfies this equation
can you give me an example of a point on the y axis
dry cargo
3 ?
bold hinge
what does a point on the plane look like?
points in 2D space are described by 2 numbers, aren't they?
dry cargo
A triangle
dry cargo
that tells you that x=1, and y=2
Wait I'm kinda blur rn 😭
dry cargo
The point that I solve just now ?
dry cargo
(2,3) ?
bold hinge
sure, that's an example of a point
it is a set of numbers that describes a position in space
let's use your example. what position does the point (2,3) describe?
dry cargo
a rectangle ?
dry cargo
trapezium tho ?
bold hinge
what?
dry cargo
bcz i did some similar qustion as those
cedar kilnBOT
@dry cargo Has your question been resolved?
sinful summit
The volume of a solid of revolution generated by rotating a region bounded by $y = f(x)$ and $y = g(x)$ (where $f(x) \geq g(x)$) about the $x$-axis from $x = a$ to $x = b$ can be found using the disk method. The formula for the volume $V$ is given by:
$$
V = \pi \int_{a}^{b} [f(x)]^2 - [g(x)]^2 dx
$$
In this case, the region is bounded by the lines $y = x + 1$, $y = 3$, and the $y$-axis. The $y$-axis is the line $x = 0$. Can you find the limits of integration?
wraith daggerBOT
adzetto
dry cargo
The volume of a solid of revolution generated by rotating a region bounded by $y...
0 to 2 ?
i mean the limit of integral
sinful summit
i mean the limit of integral
Yes. Can you explain?
dry cargo
bcz of the equation of straight line cut on the y-axis
sinful summit
bcz of the equation of straight line cut on the y-axis
According to the definition I gave, we have to determine the range of change x of the integration region.
Solving system of equation y=3, y=x+1 gives a point (2,3). This means that the maximum limits of the integration region are x=0 and x=2.
rigid gulch
cedar kilnBOT
dire geode
dire geode
Well that's because you didn't ask a question
stable reef
What do you need to do to solve 32b?
cedar kilnBOT
@rigid gulch Has your question been resolved?
rigid gulch
I’m trying to graph it
stable reef
i don't sure, buy a think you need to get the intersection of the plane XY and the function
and the do the same
with the plane XZ
if the function have 2 variables and you intersec you get a function of 1 variable
In this case if the function is z = f(x,y)
the intersection with the plane XY is 0 = f(x,y) so exists (i don't sure if for all cases but for simple function work) y = g(x)
and with the plane XZ make the same
z = f(x, 0) so z = h(x)
using geogebra3D you will able to see the function and intersections for each case
cedar kilnBOT
Available help channel!
bronze pivot
\text{Recall the Fundamental Theorem of Calculus for the following.}\\
$f(x,y) = \int_{2}^{x^2y} e^{t^{2}} dt; f_{x}, f_{y}$
casiofx991exz
bronze pivot
how does FTC part 1 work for multivariable calc?
I understand how to use it for Single Variable Calc
not in here though
tropic oxide
why do you capitalize Single Variable Calc but not Multi Variable Calc
why is mvc inferior
why do you treat the two so disparately
bronze pivot
huh
tropic oxide
anyway to find f_x you pretend y is a constant and differentiate wrt x as you normally would
bronze pivot
lol
\text{Recall the Fundamental Theorem of Calculus for the following.}\\
$f(x) = \int_{2}^{x^2} e^{t^{2}} dt$
casiofx991exz
bronze pivot
if it was like this then f'(x) is $e^{x^{4}}$
wraith daggerBOT
casiofx991exz
bronze pivot
anyway to find f_x you pretend y is a constant and differentiate wrt x as you no...
\text{Recall the Fundamental Theorem of Calculus for the following.}\\
$f(x,y) = \int_{2}^{x^2y} e^{t^{2}} dt; f_{x}, f_{y}$
Umm is it like this:
$f_{x} = e^{x^4y^2}$
casiofx991exz
inland fossil
you need the chain rule
wraith daggerBOT
casiofx991exz
bronze pivot
\text{Recall the Fundamental Theorem of Calculus for the following.}\
$f(x) = \int_{2}^{x^2} e^{t^{2}} dt$
wraith daggerBOT
casiofx991exz
bronze pivot
$f'(x) = e^{(x^2)^2} 2x$
casiofx991exz
bronze pivot
you didnt use the chain rule though
is this correct
inland fossil
if its just x^2 yeah
bronze pivot
for singlevariablecalc
okay
\text{Recall the Fundamental Theorem of Calculus for the following.}\\
$f(x,y) = \int_{2}^{x^2y} e^{t^{2}} dt; f_{x}, f_{y}$
casiofx991exz
bronze pivot
$f_{x} = e^{(x^2y)^2} 2xy$
casiofx991exz
bronze pivot
if its just x^2 yeah
hwo about now
inland fossil
looks good
cedar kilnBOT
cedar kilnBOT
Available help channel!
crimson sedge
If an $n \by n$ matrix $A$ has $n-2$ pivots, then $\trans A y = 0$ always has the trivial solution only
wraith daggerBOT
crimson sedge
Basically trying to verify if this statement is true or not
But I am pretty uh, stuck?
Would A^T also have n-2 pivots? That's the thing I cannot verify
tropic oxide
why not take A = identity matrix but two of the 1's deleted 
crimson sedge
cedar kilnBOT
@crimson sedge Has your question been resolved?
south tundra
Would A^T also have n-2 pivots? That's the thing I cannot verify
Btw yeah it will have n-2 pivots too
south tundra
Yeah, so A^T is not injective
Might be wrong though, I recently started LA too
But at least I remember the book saying that rank of A is the same as rank of A^T
A is not full rank in this case, so nor is A^T
Meaning its nullspace is not trivial
cedar kilnBOT
@crimson sedge Has your question been resolved?
cedar kilnBOT
cedar kilnBOT
Available help channel!
finite glacier
can somebody explain to me why the geometric series converges to the value it, well, converges to?
livid hound
dire geode
can somebody explain to me why the geometric series converges to the value it, w...
Give an example or problem
finite glacier
im sorry i will be freestyling the translation so i do apologize if something is incorrect, but i have a problem where i am supposed to a series display of the function f := 1/((1-x)^2) for all x in (0, 1), where ( and ) exclude those numbers. the solution split the function into 1/(1-x) * 1/(1-x), and then transformed those into the geometric series
what i dont understand is, WHY 1/(1-x) is the value the geometric series converges to
ive tried to look it up, both in the script and online, but was left as confused as before
tranquil drift
ok so you want to know why $\sum_{k=1}^{\infty} x^k = \frac{1}{1-x}$?
wraith daggerBOT
226phil
finite glacier
yes
tranquil drift
ok, lets look at the partial sum first $\sum_{k=1}^{n} x^k$
wraith daggerBOT
226phil
tranquil drift
Try calculating $\sum_{k=1}^{n} x^k- x\cdot\sum_{k=1}^{n} x^k=$
wraith daggerBOT
226phil
tranquil drift
correct now isolate $\sum_{k=1}^{n} x^k$ in the equation
$\sum_{k=1}^{n} x^k- x\cdot\sum_{k=1}^{n} x^k=1 -x^{n+1}$
tranquil drift
$\sum_{k=1}^{n} x^k = ?$
wraith daggerBOT
226phil
finite glacier
but thats just x^1 + x^2 + x^3 + .... + x^n
tranquil drift
**226phil**
well yes but use that equation
finite glacier
then i have what you got, 1 - x^{n+1}
because its just (x^1 + x^2 + x^3 + .... + x^n) - x(x^1 + x^2 + x^3 + .... + x^n)
wait actually no
the 1 is missing
doesnt k have to be equal to 0 in the beginning?
tranquil drift
**226phil**
you can transform this equation into the one below
finite glacier
all good, my question is way too stupid for you to have to feel sorrow for a mistake
tranquil drift
$\sum_{k=1}^{n} x^k -x\cdot\sum_{k=1}^{n} x^k = (1-x)\sum_{k=1}^{n} x^k$
wraith daggerBOT
226phil
tranquil drift
**226phil**
so with this
tranquil drift
**226phil**
and this
tranquil drift
**226phil**
what do you have here?
finite glacier
ah aight
$\sum^\infty_{n = 0} x^n = (1-x)\cdot\sum^\infty_{n = 0} x^n + x\cdot \sum^\infty_{n= 0} x^n$
tranquil drift
you also need $ at the end
finite glacier
not finished, thought i had autocomplete on from sharetex xD
wraith daggerBOT
alvirus
tranquil drift
no thats not correct: you have
$1-x^n=\sum_{k=0}^{n} x^k -x\cdot\sum_{k=0}^{n} x^k = (1-x)\sum_{k=1}^{n} x^k$
wraith daggerBOT
226phil
tranquil drift
devide this by 1-x and just look at the first and last term
finite glacier
aaaaaaaaaaaaaaaaah now i see it i think
the last sum with k = 1 is also meant to be k = 0, or did i miss anything?
finite glacier
its basically $1^n = \sum^n_{k = 0}x^k$
wait
no
its not
its $\frac{1 - x^n}{1-x} = \sum^n_{k = 0}x^k$
wraith daggerBOT
alvirus
wraith daggerBOT
226phil
finite glacier
$\frac{1-0}{1-x}$
wraith daggerBOT
alvirus
finite glacier
aaaaaaaaaaaaaah
tranquil drift
and thats your solution (;
tranquil drift
np
finite glacier
alright, with this i will head back into the fields of series etc, have a good day!
.close
cedar kilnBOT
tranquil drift
thx you too (;
cedar kilnBOT
Available help channel!
cedar dune
cedar kilnBOT
cedar dune
can this be solved using partial differentiation
flint plinth
that looks kinda nasty, have you tried implicit differentiation?
or possibly some variable substitution would make it nicer
crimson sedge
should be fairly quick with implicit differentiation
you can do [
\dv[y]x = -\f{F_x}{F_y}
]
if you want to be really quick lmfao
wraith daggerBOT
cedar kilnBOT
@cedar dune Has your question been resolved?
cedar dune
should be fairly quick with implicit differentiation
yup i used that first but the equation was pretty nasty
super long
slate lintel
I wonder if u = x-y would help
whole lance
cedar kilnBOT
whole lance
ALRIGHT, so this is what I have came up with so far…
slate lintel
whole lance
slate lintel
(from the purple thing, simplify your constants a bit and then do another IBP)
whole lance
OOOH
Yes, that part I knew.
Not even going to lie, I danf near fell out of my chair when you sent that
I just wanted to double check that I was at least headed in the right direction prior so simplifying and pulling out all the constants
slate lintel
yeah it's right 
you can probably shortcut a lot of the working out of the e^{-x/2} integral on the next pass since you already did that
whole lance
Well, and I feel showing everything will help with my practice and understanding. We get to use our notes on the test, so I am over simplifying anything I can
slate lintel
that's fair!! if you don't mind writing it out by all means
whole lance
Thank you for the reassurance and heart attack. Now that I have the confidence and understanding, I will post again when I feel I have the correct answer! Y'all are the best and truly are appreciated! ❤️
.close
cedar kilnBOT
wraith daggerBOT
1shero1
flat oracle
for a=constant=a0 we have u'=a0 => u=a0t+c
for t=0 u=c but for t=0 u=u0
so u=a0t+u0
this is the equation when a is constant
yeah antideriv/integrate
f'(x)=c => f(x)=cx+a
yes
integrate again
wraith daggerBOT
1shero1
flat oracle
would be a nice exercise...integrate our previous answer
and x(0)=x0
integrate x''=a0 twice
or integrate u=a0t.... once
flat oracle
integrate x''=a0 twice
well if u go and do that u ll end up with u=a0t... so
flat oracle
you gotta find c and c2
when you asked for the first answer i showed how to get c
so c=u0 , c2=x0
you are asking the same question
it is the same c as the first question
cedar kilnBOT
cedar kilnBOT
Available help channel!
spare carbon
cedar kilnBOT
spare carbon
regarding the definit intagral
it says the correct answer is 1.3
can someone point out what ive done wrong?
crimson sedge
Why are the denominators 12 and 6 for the terms x^2 and x
crimson sedge
Yes that's fine but it's because you used a sub in here
You didn't for the one at the bottom
crimson sedge
For $\ds \int (2x-3)^3 \dd x$ your procedure was akin to the following:[
\int (2x-3)^3 \dd x \implies \int \f{(u)^3}2 \dd u = \f{u^4}8 =\f{(2x-3)^4}8
]
wraith daggerBOT
crimson sedge
This is by means of a substitution u = 2x-3
spare carbon
hmm
ok
and we DO NOT use the u substitution for the 1st question?
ugh
there is a command to fix this
spare carbon
This is by means of a substitution u = 2x-3
do you know how to fix this sorry?
cedar kilnBOT
@spare carbon Has your question been resolved?
spare carbon
<@&286206848099549185>
flint sapphire
Which question?
flint sapphire
<@&286206848099549185>
Hi
spare carbon
ah sorry
flint sapphire
Which question is it?
spare carbon
so i corrected in a corrdance to what he said
flint sapphire
Are you trying to find the derivative or the integral
I cant Tell what you’re trying to solve for
sweet gazelle
primitive of x^n is x ^(n+1) / (n+1)
spare carbon
i am doing definitive integral
flint sapphire
From
spare carbon
ill get a better pic...
sweet gazelle
did you read my answer @spare carbon ?
spare carbon
solar peak
speak spanish?
spare carbon
did you read my answer <@270678085983141899> ?
i did i just dont understand it
solar peak
no se ve muy bien
spare carbon
did you read my answer <@270678085983141899> ?
ok re-reading it no i get it
its just not relevent
flint sapphire
It’s 8/3
sweet gazelle
you didnt understand why denominator is not 12 , but 3
it is about primivite formulas
sweet gazelle
primitive from (4 x^2 + 3 x - 2 ) is
F(x) = 4 / 3 x^3 + 3 / 2 x^2 - 2 x
then just calculate F(1) - F (-1)
spare carbon
The answer is 8/3
im not getting that
flint sapphire
Solve it again
spare carbon
i did
sweet gazelle
F ( 1 ) = 4/3 + 3/2 -2 = 5 / 6
F(-1) = 13 / 6
then F(1) - F(-1) = 5 / 6 - 13 / 6 = -4/3
fluid phoenix
oops nvm
spare carbon
all good
spare carbon
F ( 1 ) = 4/3 + 3/2 -2 = 5 / 6
F(-1) = 13 / 6
then F(1) - F(-1) = 5 / 6 - ...
so i was right and this is the correct meathod?
sweet gazelle
yes, you only have to know that primitive of x ^n is
1 / (n+1 ) * x^(n+1)
spare carbon
yes, you only have to know that primitive of x ^n is
1 / (n+1 ) * x^(n+1)
why is the first one different?
it seems like the same question but it has different meathods
median maple
Why this step?
cedar kilnBOT
Why this step?
median maple
to be more specific, wouldn’t you add 2*row2 to row3 to get rid of the y variable, or am I missing something?
crimson delta
they typo'ed
1/2
instead of 3/2
like they also typo'ed the second row in the new version with 1 instead of z
and the RHS of the third row
someone didnt check this properly
median maple
haha i guess not
it’s the fourth edition of linear algebra by jim hefferon
would you happen to know any decent sources for self studying linear algebra?
crimson delta
khan academy?
median maple
khan academy is good yea, i got through a lot of the introductory vids but it just felt slow
thanks for the help!
.close
cedar kilnBOT
crimson delta
well everyone has a different speed
cedar kilnBOT
Available help channel!
crude lagoon
cedar kilnBOT
iron saffron
that factoring is wrong
royal loom
yea
iron saffron
-4 * -3 = 12, not 3
royal loom
factored incorrectl
crude lagoon
o
got it
idk how i mseed up that
whats the extra thing you do when one of the factors is irreducible
a quadratic in my case
dim tiger
Do you know the quadratic formula ??
keen raven
cedar kilnBOT
@crude lagoon Has your question been resolved?
mortal jewel
cedar kilnBOT
cedar kilnBOT
@mortal jewel Has your question been resolved?
cedar kilnBOT
cedar kilnBOT
Available help channel!
sacred sorrel
sacred sorrel
Can someone please double check this for me? Thank you!
cedar kilnBOT
@sacred sorrel Has your question been resolved?
open nacelle
looks good to me!
sacred sorrel
looks good to me!
Great, thank you!
crude lagoon
yo
rain drift
howdy
crude lagoon
i found the x values
tried plugging 1 and 3 to 2x+y=5
...
wait a minute
nvm
.close
cedar kilnBOT
cedar kilnBOT
✅
wraith daggerBOT
dios
crude lagoon
$x^2-9x+18=0$
wraith daggerBOT
dios
open nacelle
what did you input exactly?
open nacelle
and the y values?
crude lagoon
$6*8=24$
wraith daggerBOT
dios
open nacelle
😭😭😭
crude lagoon
ill try another one
open nacelle
it was supposd to be (6,19)
crude lagoon
victory
open nacelle
🔥
cedar kilnBOT
open nacelle
ofc
cedar kilnBOT
Available help channel!
crude lagoon
cedar kilnBOT
crude lagoon
$x^2=3$
wraith daggerBOT
dios
crude lagoon
where did imess up
or can x be a sqrt
nvm it can
but then theres this
$-sqrt(3)^2+y=7$
wraith daggerBOT
dios
crude lagoon
$-3+y=7$
wraith daggerBOT
dios
crude lagoon
$y=10$
wraith daggerBOT
dios
crude lagoon
am i wrong here
crude lagoon
imaginaries?
hearty arch
no
crude lagoon
$(sqrt(-3))^2$
wraith daggerBOT
dios
crude lagoon
uhhh
hearty arch
the x values are plus minus sqrt(3)
just plug both of them into one equation one at a time
crude lagoon
$+or-sqrt(3)^2+y=7$?
wraith daggerBOT
dios
wraith daggerBOT
wumbo_.
crude lagoon
i dont see what the point is
hearty arch
it changes the sign
keeping the plus and minus on the outside keeps it plus or minus, if it's moved inside the parentheses it will always be positive
crude lagoon
oh
crude lagoon
.close
cedar kilnBOT
@crimson sedge Has your question been resolved?
magic bloom
bro
rain drift
wat do you mean?
rain drift
sorry I'm not sure what you mean by "decorate". that's where I'm having some issue understanding the question 😦
ancient valley
I'm pretty sure he is asking how to fill out a multiplication chart
magic bloom
I'm pretty sure he is asking how to fill out a multiplication chart
YES
magic bloom
tyy
crimson sedge
how can i find $b^-2$ being b that matrix
cedar kilnBOT
how can i find $b^-2$ being b that matrix
wraith daggerBOT
donkn0w
crimson sedge
invert b then square it?
you mean this
lime bone
yea
cedar kilnBOT
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Available help channel!
balmy yoke
given that the vector v has a magnitude of 6, and a directional angle of 160 degrees, how can I find the components of v, I tried first to find the angles of the triangle formed but I think its wrong
lunar lynx
You have done that correctly.
Just make sure to assign magnitude the proper sign by seeing their direction in plane.
balmy yoke
Just make sure to assign magnitude the proper sign by seeing their direction in ...
oh, I don't have a plane the question literally just says
balmy yoke
You have done that correctly.
oh nice
lunar lynx
oh, I don't have a plane the question literally just says
Okay. Well, then draw the component vectors in the answer at least. Without orientation being shown with respect to other component, vectors can be misleading.
balmy yoke
Okay. Well, then draw the component vectors in the answer at least. Without orie...
alright, doing that right now
balmy yoke
Okay. Well, then draw the component vectors in the answer at least. Without orie...
hm trying to find the magnitude of the components now but I think I did something wrong
lunar lynx
No. No. you can't use the 90° angle for breaking into components.
Basically, you often use the angle which vector makes with the x-axis. Here, that is 20°.
lunar lynx
No. No. you can't use the 90° angle for breaking into components.
Trigonometric ratios are defined for the acute angles in a right-angled triangle. Of course, extrapolation of those acute angles are done up to 90° but those are not realisable in a figure as Hypotenuse will meet one of the other two sides at infinity.
balmy yoke
ahh okay I get it now, thanks 👍 will fix that now
balmy yoke
Trigonometric ratios are defined for the acute angles in a right-angled triangle...
are the components right now?
lunar lynx
are the components right now?
Yes. They are fine.
cedar kilnBOT
@balmy yoke Has your question been resolved?
nocturne compass
[ \int^{\pi}_0 |\sin(\alpha x)| \dd{x} ]
cedar kilnBOT
\[ \int^{\pi}_0 |\sin(\alpha x)| \dd{x} \]
dawn junco
\[ \int^{\pi}_0 |\sin(\alpha x)| \dd{x} \]
nocturne compass
Right
wraith daggerBOT
bigpufik
dawn junco
you have an absolute value here
you should prolly try and see when sin(ax) is positive
nocturne compass
Yeah on pi/alpha
so what i did is took out the alpha
And then i can remove the abs value
Now i Got positive alpha
Still seems wrong asf but okay
dawn junco
Now i Got positive alpha
that's prolly alright if your alpha is an integer
it might not be one though
nocturne compass
we assume alpha is an integer yes
dawn junco
ah ok