help-13

[surreal cave]

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[night finch]

k^2 - 10k+25

[night finch]

i need to solve this by completing the square

how do I do that?

[upper abyss]

If you don't know anything at all about completing the square, YouTube is a better first stop. But, if you have any particular questions about the method, we'd be happy to answer!

[night finch]

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[burnt falcon]

I under stand everything up until question three. Can anyone help me solve that question

[nova snow]

No one can help you if you leave it in a PDF

[burnt falcon]

k

gimme a sec

sorry for the delay

something came up

and i apologize the image is in low resolution

<@&286206848099549185>

[cedar kiln]

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[surreal cave]

for absolute values there are two cases

[mossy shard]

ye

idk what to do tho

[mossy shard]

what do u do to the |x+2|

[mossy shard]

?

<@&286206848099549185>

[obsidian coral]

Please don't abuse the helper ping, you pinged twice in a 3 minute span. It's ping once after 15 minutes if your question has not been answered

[mossy shard]

no one has helped yet tho

[obsidian coral]

Then just wait patiently

[mossy shard]

i have

..

[obsidian coral]

You just ping once and wait

[mossy shard]

everytime i wait it takes like 30 mins and still no one

[cedar kiln]

Helpers are just people volunteering their time to help you. Be polite.

[mossy shard]

can u help with the question then

💀 more concerned with how many times someone pings u than actually helping

<@&286206848099549185>

<@&286206848099549185>

<@&286206848099549185>

<@&286206848099549185>

[torpid shard]

<@&268886789983436800>

Ping spam

[finite atlas]

this isn't our job we are volunteers, chill out

[cedar kiln]

@mossy shard Has your question been resolved?

[slim hearth]

they left ig

.close

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[crimson sedge]

At the underlined point, do I need to get rid of the fraction by multiplying everhing by 2 so I can factor it?

[short blade]

you don't need to

but it might help you

[crimson sedge]

Hello

What is the initial question '

?*

[crimson sedge]

What is the question pls

I mean , the thing needed to be solved

[vague rapids]

We multiply by a constant to reduce the calculations. If multiplying by 2 makes the calculation easy for you, then sure do it

[cedar kiln]

@crimson sedge Has your question been resolved?

[crimson sedge]

Wait

Am solving it

[crimson sedge]

Gotcha

Yea cuz that is easier to solve for me

[crimson sedge]

The original question

Hhhm , wait bro/sis

I got it already

[crimson sedge]

This was all i wanted to confirm

.close thanks!

[cedar kiln]

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[crimson sedge]

Sorry if I couldn't help

I was going to solve it by complex

I mean , i

[cedar kiln]

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[crimson sedge]

No that’s okay I already had it solved I jsut wanted to confirm that

[crimson sedge]

Thanks tho

I’ve gotten to here, but idk how to answer the question .

When are the production costs of the two sites equal?

How do I figure that out?

[vague rapids]

(x-3)(2x+2)=0
Until here everything is right

[crimson sedge]

2(3)^2 is me finding the y val

[vague rapids]

No

[crimson sedge]

So is (-1)^2

[vague rapids]

No

Just find values of x

[crimson sedge]

why tho?

[vague rapids]

That is required answer

[crimson sedge]

Cause isn’t that what you do when solving a quadratic ??..

[vague rapids]

Noo

You just need values of x

[crimson sedge]

Don’t I need to find coordinates ..?

[vague rapids]

No

[crimson sedge]

Ok then

[vague rapids]

(x-3)=0 and (2x+2)=0

[crimson sedge]

The questioned asked you when the production costs are equal

[vague rapids]

Find values of x and one will be rejected

[crimson sedge]

X=3 and x =-1 I’ll reject -1 cuz it don’t make sense for the production cost to be = at -1

But now what…?

when x = -1 it doesn't mean costs are at -1

when x = -1 it means the factories are producing -100 units misread

[crimson sedge]

You're done

…????

[crimson sedge]

X=3 is not my answer.

[crimson sedge]

why not?

The answr is 300

Who wrote these questions

It’s in the workbook, bro is the wording not odd ???

The questions are super poorly worded. so it make sense for the answer to be just as bad

I guess

wait how is the answer 300

Idk

can you show the answer sheet?

Question 8

Ask your parents to talk to the teacher

The questions and answers are bad

But was my work right?

Yeah it was up to when you found the x values

you didn't have to find the y values

Are you sure?

Yeah, i'm sure. go talk to your parents and tell them about how bad your math problems are

Nowhere in the question does it say x is hundreds of units built

Okay but just to recap,for this kind of question. As soon as I find the x values, I’ll reject the one that doesn’t make sense, and then I’ll just plug in the remaining x value into the word problem. And get an answer ?

and nowhere in the question did it tell you what costs were

I hope that the question on the test make sense.

[crimson sedge]

Talk to your parents and tell them to do something about the work your teacher is giving you

[crimson sedge]

But generally, is this the procedure?

I can't say yes or no because of the problem* making no sense

[crimson sedge]

Does this one make sense?

@crimson sedge

Yeah looks great

But how do I find my answr

How did they decide on 30$

[crimson sedge]

one way is to look at the leading term

$$-50p^2$$

[wraith dagger]

Brandon H

[crimson sedge]

You know the leading term will have the shape of an upside down parabola

Yes

so as p increases

y gets smaller

but honestly

the way they asked both could be answers to the question

however they first start to break even at 30

then they break even at 40 then start to lose money again

Hm

@crimson sedge

How do I find how many items to break even

[crimson sedge]

<@&286206848099549185>

[umbral hull]

Breaking even is when your net profits is 0

profits is calculated as you would in any business, revenue-costs

you solve for the zeros of that equation

your profit function is P(x)=R(x)-C(x)

the questions they are asking are equivalent to asking, when is P(x)=0? When is P(x) positive?

[crimson sedge]

When is y=0 and when is y=positive?

[umbral hull]

what're you calling y here

so they gave you two functions C= something and R=0

[crimson sedge]

#10

[umbral hull]

subtract R - C

you get a new function which is your profit function P

[umbral hull]

they want to know when that is equal to 0 or when it is positive

[crimson sedge]

That’s what the key says

[umbral hull]

yeah it's the same thing as what I said

if C=R then R-C=0

same thing as solving for when the function R-C is 0

[gray obsidian]

if you make between 2 units to 100 units, it will be profitable. i guess

[umbral hull]

yes basically it's a polynomial so

[crimson sedge]

If you read their work they already did that

[umbral hull]

it only changes sign potentially after crossing a 0

right but they asked how do they find it I'm answering how

solve for the zeros of R-C

use whatever method you want to for this, factoring of any kind that can be used if you want, or just the quadratic formula

all roads to the same thing

[crimson sedge]

You should've solved the equation the other way around

The other person kinda talked about It I guess

But you didn't do Profit - Costs = 0

You did Costs - Profit = 0

You kinda get the same answer for the x intercepts(break even value)

but the range where they're making a profit would be different with the equation you have.

[umbral hull]

the points where R-C = 0 should be exactly the points where C-R=0, both equations are exactly where C=R

[crimson sedge]

😭 Why are you still asking this question

[umbral hull]

but yes the profit region will be different potentially

Just remember Profit = Revenue - Costs

not just a math equation but an IRL one

[gray obsidian]

yes, make the profit above x-axis

[crimson sedge]

Wdym

It asks me

The question asks me

[crimson sedge]

yeah but you were told the answer the last five times you asked the exact same thing

the break even values are the x intercepts of the polynomial

Okay, so when asked the break even value set y = 0 and solve?

[gray obsidian]

yes. when R-C = 0, solve the equation. and ignore the negative roots if pops up

[crimson sedge]

But I’ve got my P vals already

So what do I set = to 0?

[crimson sedge]

That has been what you've been doing for the past two days

so yes

I don’t understand what do u set = to 0

look at the image you just shared

what is is equal to zero in the picture

(P-40)(1500-50p)

yeah you set that to zero

So I’ve got now 40 and 30 as P values

and the P values are the x intercepts

I see.

But now what is my break even value?

the p values

[crimson sedge]

So what is the price per book ? Tho?

the p values

But I have 2 values ?

are you confused what break even means?

break even means 0

No

Yes

[crimson sedge]

Yes they are both break evens

Ok.

Thank you

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[ocean python]

Can someone tell me how to solve the first problem?

[tropic oxide]

you want the system

{ x + 2y = k
{ xy = 6

to have exactly two solutions

have you solved problems like this before?

[cedar kiln]

@ocean python Has your question been resolved?

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[scarlet hearth]

Need help

[tropic oxide]

,rccw

[cedar kiln]

@scarlet hearth Has your question been resolved?

[scarlet hearth]

<@&286206848099549185>

[gray obsidian]

whats the question again? what does S_ENT stand for?

[scarlet hearth]

Area of E N T triangle

[cedar kiln]

@scarlet hearth Has your question been resolved?

[crimson sedge]

help

[gray obsidian]

sry i tried, need bigger brain here.

[fading summit]

I think ENT is 1/4 of KLM

Area wise

[scarlet hearth]

nah

its not right triangle

[fading summit]

is this problem for precalc or geometry?

Are we supposed to use trig?

[scarlet hearth]

geometry

[scarlet hearth]

no

[fading summit]

ok

so I think the first thing to start with is the similar triangles

do you see how LEN is similar to LKM ?

[scarlet hearth]

yes

[fading summit]

so can you find the lengths of EN, NT, and ET?

[scarlet hearth]

i tried but i cant find it

[fading summit]

So we know LM is 15, what is LN ?

Keep in mind that KN bisects the angle K

take a guess

[scarlet hearth]

LN is 225/23

the point where 3 bisector meet is middle point of the circle thats inside triangle

So OE = ON = OT

[fading summit]

ok yeah I made some wrong assumptions about this problem

let me think about this

[scarlet hearth]

I know there is one formula for this but cant remember the name 💀

[fading summit]

Heron's Formula?

[scarlet hearth]

No

Im writing gimme sec

Idk it is correct but i believe this is formula

[fading summit]

,rccw

[scarlet hearth]

Its solved using this formula

Yep

[fading summit]

yeah I believe that is a correct formula

[scarlet hearth]

,close

.close

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[crude needle]

For number 4, how would I calculate the basis matrix A?

[crude needle]

Would I just take 1(B1) + 2(B2) etc.?

[fading summit]

I think you have to write A in terms of B1 through B4

[crude needle]

How would I do that?

[fading summit]

so you could set up a system of equations

[crude needle]

What would I take as the constants though?

Just a,b,c and D?

[fading summit]

sure

so a + b + c =1

[crude needle]

And then solve for a,b,c,d?

[fading summit]

c+d =1 , etc.

[crude needle]

Ohhh I see

For 1

I know T: R4->R3

But how would you compute TA(x)

[fading summit]

idk I'm guessing you just write the formula for the result of the transformation, when applied to vector {x1,x2,x3,x4}

It's been a while since I've done linear algebra

[crude needle]

Can you maybe give an example if you can?

[fading summit]

https://math.stackexchange.com/questions/3919210/determine-the-domain-codomain-and-image-of-a-linear-map

[cedar kiln]

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[warped hound]

If I have $5000, and a cookie costs $3.6, however after each purchase it goes up buy $0.05, how many cookies can I buy with $5000.

I need the formula to find the amount of cookies I can purchase

[uneven crater]

Do you know what is an arithmetic progression

!status

[cedar kiln]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[warped hound]

I don't, I just need to know the formula to calculate it for a game I'm making

[tropic oxide]

the price of n cookies in dollars is 3.60 + 3.65 + 3.70 + ... + (3.6+0.05(n-1))

which works out to 3.60n + 0.05 * (0+1+2+...+(n-1)), or 3.60n + 0.05*n(n-1)/2

[warped hound]

I would use that, but in the code that would require the need for a while loop, which is very inefficient. I just need the formula to calculate it in just maths

[tropic oxide]

you need to solve the equation 3.6n + 0.025n(n-1)=5000 for n

which can be done with the quadratic formula, as this is a quadratic equation

[warped hound]

So I HAVE to do it with trial and error? Or is there a formula that I can use to get the number of cookies I can purchase?

?

@ me if someone responds

[uneven crater]

@warped hound $0.025n^2 + (3.6 - 0.025)n -5000 = 0$ You can then use the quadratic formula

[wraith dagger]

Encrpyt

[warped hound]

I'm not plugging it into a scientific calculator or anything though, I need to put in into a python script. (python doesn't have a solving method for the quadratic formula)

[granite knoll]

Python should have no trouble, it is just arithmetic

[warped hound]

This is what ChatGPT told me to do, but it always gives me the wrong answer:

budget = 5000
initial_cost = 3.6
increase_per_cookie = 0.05

# Calculate the discriminant
discriminant = (increase_per_cookie ** 2) + (4 * increase_per_cookie * initial_cost) * budget

# Calculate the positive root of the quadratic equation
positive_root = (-increase_per_cookie + math.sqrt(discriminant)) / (2 * increase_per_cookie)

# Calculate the maximum number of cookies by rounding down the positive root
max_cookies = math.floor(positive_root)

print("Maximum number of cookies you can buy within the budget:", max_cookies)```

[cedar kiln]

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[slow thorn]

how do you simplify ((D.B)+(A.C))+((D+B)+D)

[slow thorn]

the answer is AC + D + B

but i don't know the steps to get to it

[clear berry]

Is this boolean algebra?

[slow thorn]

yeah

[clear berry]

alright, we can simplify from the right

(D+B)+D = ?

[slow thorn]

uhhh D+B?

[clear berry]

in fact we can remove brackets cause the sum is associative

yes

let's remove all brackets

[slow thorn]

oh ok so the Extra D outside the brackets doesn't do anything

[clear berry]

then we have B.D + A.C + B + D

[slow thorn]

is there a rule here?

[clear berry]

yep I think you can reduce B + B.D to something

[slow thorn]

i see a single B would be the same as that?

and same can be done with D

thanks a lot

[clear berry]

I think so

[slow thorn]

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[mortal ether]

what is the symbol that looks like an E?

[granite knoll]

"is an element of"

[hollow geyser]

that

[mortal ether]

thank you

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[rough kindle]

not sure wtf is going on here, i would think youd do like (1/0.065(12))450e^0.065(12) - (1/0.065(3))450e^0.065(3) and then divide by 9 to get the average but according to the marking scheme (second picture) ig not

[rough kindle]

lemme try to figure out how to put my initial idea into latex

[violet night]

very difficult to know what you mean with your initial idea due to the notation, but you shouldn't be taking a factor of t to the denominator after you integrate

[rough kindle]

says this this the integral of e^ax in my booklet

also yeah

[violet night]

and do you see a x on the denominator?

[rough kindle]

didnt mean the t there

[violet night]

well then you essentially agree with the marking scheme

[rough kindle]

why is it only one 450 there tho

[violet night]

because they factored the constants out

ax - ay = a(x-y)

[rough kindle]

ok yeah im dumb nvm

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[flat lance]

2x+5y-10=0.

[violet flume]

whats the goal?

[flat lance]

So uhm

the the

direction

equation

right

[violet flume]

the direction?

[flat lance]

Line

[violet flume]

right, its a line

[flat lance]

Yes a line.

So.

There is also

a Cirle

That has a

center dot

[violet flume]

can you post the entire question

[flat lance]

on that line

XD

OKAY

Determine the equation of the circle that passes through the points A(-1,2) and (-3,0), and the center of the circle lies on the line
2x+5y-10=0.

i thought about

getting the

radius by knowing those two points

but

it only get me the right part of the equation

Not sure how to get the P and Q

[south tundra]

Note that the distance from the center to A and to B should be equal

[flat lance]

Yes

i know that :D

[south tundra]

The coordinates of the point should be of the form (x, 2 - 2x/5)

Because 2x + 5y - 10 = 0 implies y = 2 - 2x/5

[flat lance]

The center u mean ?

[south tundra]

Yes

The center's coordinate has that form

[flat lance]

yes.

but

does that mean

that

[south tundra]

The distance from the center to A hence is sqrt((x + 1)^2 + (2x/5)^2)

[flat lance]

(x, 2 - 2x/5) = (p,q)

?

[south tundra]

If by p and q you mean the coordinates of the center

[flat lance]

No

[south tundra]

What's p and q then?

[flat lance]

wait

lemme fill u in

The equation

has the radius

and the p and q

which is the

coordinates of the center

[south tundra]

p and q are the coordinates of the center here

Why did you say no then

[flat lance]

Lol

i

uhm

yeahh...

lets not talk about that

[south tundra]

Anyway, the distance from the center to A is hence sqrt((x + 1)^2 + (2x/5)^2)

[flat lance]

Well

i got thatr

distance

but

does that mean

that in the end

the equation should be (x-x)^2 + (y+2x/5)^2 = r2 ?

[south tundra]

No

[flat lance]

uhh

[south tundra]

And the distance from the center to B is sqrt((x + 3)^2 + (2 - 2x/5)^2)

These two distances must be equal, right?

[flat lance]

yes the r is all the way around the same

yes

any dot on the circle

[south tundra]

So we set (x + 1)^2 + (2x/5)^2 = (x + 3)^2 + (2 - 2x/5)^2

Can you solve this?

[flat lance]

Oh so at the end we get a quadratic equation ?

and thats the p and q

[south tundra]

Yes, this is a quadratic equation with p as its unknown

[flat lance]

what about q

[south tundra]

You will find it using the equation y = 2 - 2x/5

Well, you could also use the equation of the circle, but that is gonna be way harder, so just stick with y = 2 - 2x/5

[flat lance]

Can u stop mixing up x ,y and p,q

its not the same lol

ur messing with my head

[south tundra]

I defined x and y to be the same as p and q respectively

[flat lance]

My brain does not work like that

t _ t

[south tundra]

Okay, so solve for p in (p + 1)^2 + (2p/5)^2 = (p + 3)^2 + (2 - 2p/5)^2

And then find q using q = 2 - 2p/5 once you know the value of p

[flat lance]

-5 ?

beanie

[south tundra]

Yes, p = -5

What's q then?

[flat lance]

uhhhh

so

2-2*-5/5

that meansss

uhhhh

[south tundra]

Right, which is just 2 + 2 * 5/5

5's cancel

2 + 2

[flat lance]

5

XD

4

sorry

so

[south tundra]

So q = 4

[flat lance]

p is -5 and q is 4

yes but

i still kinda dont get how

did u equal those two equations above

those are for both r's ?

r^2 = r^2 ?

[south tundra]

Yes, what we started with is the system of equations
2p + 5q - 10 = 0
(p + 1)^2 + (q - 2)^2 = (p + 3)^2 + (q - 0)^2

From the first equation we got q = 2 - 2p/5 and plugged that into the second equation

And solved for p

[flat lance]

Wait so the first equation is just the line ?

but the second is

the two r's equaling for

[south tundra]

Yes

[flat lance]

a to center and b to center ?

[south tundra]

Right

[flat lance]

Ok ok ok.

Last one beanie

can i ?

[south tundra]

Of course

[flat lance]

Determine how many common points have the line 4x + y − 4 = 0 and circle x^2 + (y + 3)^2 = 34.

So

this i could just

draw and figure out

but

im not allowed to do that

[south tundra]

That is basically the same as asking for how many solutions does the system of equations
y = 4 - 4x
x^2 + (y + 3)^2 = 34
has

Like we did previously, just plug in y = 4 - 4x into the second equation

[flat lance]

but

then ill just get

[south tundra]

But this time you need to check how many solutions does x have there

[flat lance]

Yeah how do i do that

[south tundra]

What quadratic equation are you getting this time?

[flat lance]

well i still didnt get it but

what will the result of

the system be

thats what i wanna know

[south tundra]

Alright

After plugging y = 4 - 4x into x^2 + (y + 3)^2 = 34 we get x^2 + (4 - 4x + 3)^2 = 34 or x^2 + (7 - 4x)^2 = 34

Expanding the brackets yields x^2 + 49 - 56x + 16x^2 = 34

Which is the same as 17x^2 - 56x + 15 = 0

[flat lance]

istg

i cant follow this text converted math equations

i have dyslexia

uhhh

can we vc and u draw in paint

lol

[worldly lava]

guys i need help

[south tundra]

$\begin{cases} y = 4 - 4x \ x^2 + (y + 3)^2 = 34\end{cases}$

[worldly lava]

x3+y3+z3=k??

[wraith dagger]

A Lonely Bean

[south tundra]

Is this better?

[flat lance]

YEWS

YES

YES

okay

okay

[south tundra]

Post your question in an available help channel

[flat lance]

im following

[south tundra]

After plugging the first equation into the other should get you $x^2 + (4 - 4x + 3)^2 = 34$ or $x^2 + (7 - 4x)^2 = 34$

[wraith dagger]

A Lonely Bean

[flat lance]

okay yeah

[south tundra]

And expanding the brackets yields $x^2 + 49 - 56x + 16x^2 = 34$, right?

[wraith dagger]

A Lonely Bean

[flat lance]

meaning doing the

uhm

x^2+2timesXtimesY+y^2

in this case

minus

on the first one

part

[south tundra]

$(7 - 4x)^2 = 7^2 - 2\cdot7\cdot4x + (4x)^2 = 49 - 56x + 16x^2$

[wraith dagger]

A Lonely Bean

[flat lance]

Okay

yes

im following

[south tundra]

$$17x^2 - 56x + 49 = 34$$
$$17x^2 - 56x + 49 - 34 = 0$$
$$17x^2 - 56x + 15 = 0$$

[wraith dagger]

A Lonely Bean

[flat lance]

and then we get the

quadratic

yes

[south tundra]

In order to determine the amount of solutions to a quadratic equation, we need to consider its discriminant

[flat lance]

Its D ?

[south tundra]

Yes

[flat lance]

the uhm

2x

something

forgot

[south tundra]

$D = b^2 - 4ac$

[wraith dagger]

A Lonely Bean

[flat lance]

yes

Oh

Oh

so

D<0 , D=0 , D>0

meanine uhmmm

if

uhh

[south tundra]

If it's positive, then there are two solutions
If it's zero, then there is just one solution
If it's negative, then there are no solutions

[flat lance]

Solutions meaning

points of

[south tundra]

In this case $D = 56^2 - 4\cdot15\cdot17$

[flat lance]

contact ?

[wraith dagger]

A Lonely Bean

[south tundra]

Yes

[flat lance]

Okay phew

Thank you again beanie <3

Ur always here for me

[south tundra]

You are welcome

[flat lance]

Now give me

uhm

5 mins to screenshot what i need

and ill try

doing one task again

and ill come back

https://tenor.com/view/anime-cheeks-hugs-clingy-naotsugu-gif-14106855

Okay

figured it out

thank you

[cedar kiln]

@flat lance Has your question been resolved?

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[deep rivet]

I'm getting x as negative

My working:
Since 110 is an exterior angle, the FULL interiro angle is 250 deg

hence 2x + 50 + 250 = 360

so 60/2

x = 30

wait nvm i think i made this unnesecerily

I made a mistake in initial calc before posting

soz

.close

[cedar kiln]

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• Show your work, and if possible, explain where you are stuck.
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[white fable]

Hi, just want to know if this is correct.

[tropic oxide]

angles A and B are definitely not 45°

[white fable]

I was told its not an acute triangle so I figured its a 90-45-45 triangle

[tropic oxide]

well it's not an acute triangle, it's a right triangle

but not all right triangles are 90-45-45...

do you have in writing exactly what you were told? it sounds like there might have been some misunderstanding.

[white fable]

Yes, I will send it here

[tropic oxide]

A and B are definitely not 89.36° and not 0.64° either.

,calc 5/sqrt(61)

[wraith dagger]

Result:

0.64018439966448

[tropic oxide]

sin(B) = 0.64, this is NOT the same as saying B itself is 0.64 of a degree.

[white fable]

How so?

[tropic oxide]

sin(B) is not equal to B.

sin(B) is a trig ratio corresponding to angle B.
sin(B) is not itself an angle

[white fable]

Oh

How would I find CosB?

[tropic oxide]

which part of SOH-CAH-TOA deals with cosine?

[white fable]

CAH

[tropic oxide]

spell it out

[white fable]

Adjacent over Hypotenuse

[tropic oxide]

as an equation, in full

[white fable]

I dont know the equation actually

[tropic oxide]

you don't know "Cosine equals Adjacent over Hypotenuse"?

[white fable]

Oh, yeah

[tropic oxide]

cos(B) = adjacent/hypotenuse

which side is adjacent to angle B?

[white fable]

Wouldnt the adjacent be 5 though?

[tropic oxide]

would it?

is the side with length 5 adjacent to angle B?

[white fable]

Ohh, no

I thought it was the adjacent of the entire triangle, i will show you

[tropic oxide]

"adjacent of the entire triangle" makes no sense.

[tropic oxide]

Side adjacent to angle A

adjacency is relative to an angle

it is not absolute like you were trying to say

[white fable]

Makes sense now

And for finding tan its opposite over adjacent. I know now that the opposite for 90 degree for C is square root of 61. But how would I distinguish whether the adjacent of C is 6 or 5?

[tropic oxide]

it's neither

C is the right angle

the concepts of opposite and adjacent are undefined for it

for the purposes of trig ratios, 90° is a special case

as your teacher says,

You know the trig values of 90° through your familiarity with the unit circle.

[white fable]

I dont think so

Would it be the “Complementary Relationships”?

[tropic oxide]

idk what that's supposed to mean

but i do not think so

[autumn yew]

yes it is

[tropic oxide]

no that is not what i was talking about.

sin(90°) = 1, cos(90°) = 0, and tan(90°) is undefined.

that's what i was talking about.

[white fable]

Oh, okay. Yeah I never knew that fact.

So tanC would be Undefined? Since its 90 degrees

[tropic oxide]

yes, exactly.

[white fable]

Thank you! I really appreciate your help. 😊

[tropic oxide]

for a moment that felt like a bot was saying it. but you're welcome

[white fable]

XD

.close

[cedar kiln]

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[fallow helm]

I have a doubt in question 9, I am getting stuck in finding the nature of the roots, i can find the intervals where the roots are, I think that could get me something

[crimson sedge]

intermediate value theorem is helpful here

!show

[cedar kiln]

Show your work, and if possible, explain where you are stuck.

[fallow helm]

I am going home now, I’ll repost later with my work to free this chat

.close

[cedar kiln]

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[cedar kiln]

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[drowsy osprey]

Am I right?

[cedar kiln]

@drowsy osprey Has your question been resolved?

[drowsy osprey]

<@&286206848099549185>

What is the right answer?

Why is that?

[celest seal]

[mod ping dealt with]

[drowsy osprey]

I got 1.2232. Is that correct?

[drowsy osprey]

Can you help with my math 😂

[cedar kiln]

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[cedar kiln]

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• Show your work, and if possible, explain where you are stuck.
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[light flame]

how can I create a blocked letters on desmos

[rain drift]

for future ref I would head to #latex-help for any latex questions since these help channels are mainly used for specific problems and questions that you're stuck on

but you can use the \mathbb{} command

like so

$\mathbb{R}, \mathbb{C}, \mathbb{Z}, \mathbb{LOL}$

[wraith dagger]

MellowDramaLlama

[rain drift]

etc

[light flame]

ok thx

[cedar kiln]

@light flame Has your question been resolved?

[cedar kiln]

@light flame Has your question been resolved?

[cedar kiln]

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[gaunt trench]

28.309 - 4.9

[gaunt trench]

when we write it in normal notation with correct number of decimal places

wouldnt it be 23?

since the lowest number only has 2 sig figs

[obsidian coral]

Not exactly

Sig figs with addition/subtraction is based on the least amount of decimal places

So the numbers before the decimal, don't get "affected" by addition/subtraction sig fig rules

[gaunt trench]

ohh

i get it

[cedar kiln]

@gaunt trench Has your question been resolved?

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[steel thistle]

bcus the ans is 7050g but i calculated 7480g

[steel thistle]

can anyone help me find what did i do wrong

[cedar kiln]

@steel thistle Has your question been resolved?

[silent viper]

Yea, ok @steel thistle I figured it out

You aren't counting for the fact that because each board is 1cm thick that it cuts into the other sides dimensions

You should have 2 50x50 boards, 2 50x48 and 2 48x48 boards

[steel thistle]

how

[silent viper]

if the top is 50 x 50 then it cuts off a cm of the sides surrounding it

does that make sense?

[steel thistle]

doesnt

[silent viper]

Sry, bad drawing but does that communicate what I mean?

[steel thistle]

but can they just put the 1 cm outside

[silent viper]

for the cube to be a perfect 50x50x50 that cm will need to be accounted for

Does that make any sense at all?

Or am I not explaining this right?

[steel thistle]

idk

[silent viper]

Ok, give me a sec I'm going to make a diagram

Here ya go

Does this make more sense @steel thistle?

So you should have 2 of each board like this:

[steel thistle]

ohhh

[silent viper]

Are we now on the same page?

So the areas should be 50x50x2 + 50x48x2 + 48x48x2 - 100pi

so (14408 - 100pi) cm cubed x .5 g/cm cubed

Which comes out to 7046.92036732

which in 3 significant figures is 7050g

[silent viper]

@steel thistle are we good?

[steel thistle]

oh

then how about the side of the 50x48 cm

cube

isnt it suppost to be 48x48

[silent viper]

if you look here you can see that the right and left side of the cube are 48x50

Hmm, well I gotta run @steel thistle hopefully you understand. If not maybe somebody else can explain better

[cedar kiln]

@steel thistle Has your question been resolved?

[cedar kiln]

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• Show your work, and if possible, explain where you are stuck.
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[zinc lagoon]

Does anyone know where I can take a class over the summer to accelerate my math learning

[zinc lagoon]

?

[obsidian coral]

Look up resources yourself

Find a tutor

See if your local school offers summer classes

[zinc lagoon]

Is there a site?

[obsidian coral]

For what?

if your local school offers summer classes
?

Ask your school

Find a tutor
Ask around in your area

[zinc lagoon]

I kinda wanna do online classes but I forgot the website name it was in here somewhere but I can’t find it

[cedar kiln]

@zinc lagoon Has your question been resolved?

[cedar kiln]

@zinc lagoon Has your question been resolved?

[cedar kiln]

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[crimson sedge]

hi i need help

[crimson sedge]

i need help with question 5

can someone help me

[fallen moat]

,rotate

[fallen moat]

!status

[cedar kiln]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[crimson sedge]

2

[fallen moat]

!show

[cedar kiln]

Show your work, and if possible, explain where you are stuck.

[crimson sedge]

i have done question 1

and im aware on how to do it

[fallen moat]

can i have a look?

[crimson sedge]

but idk how to do the rest

ok give me a min

[fallen moat]

i see

[crimson sedge]

this is how my teacher had taugth me to do

[fallen moat]

nice!

you understand what's happening on this question, right?

if yes, let's start with (b)

[crimson sedge]

i dont understand one thing

[fallen moat]

oh

[crimson sedge]

how to determine the equation

is it based on the number given whether its positive or not

[fallen moat]

lemme explain further on this question (a) then

[crimson sedge]

ok

[fallen moat]

your teacher did skipped some steps

[crimson sedge]

ok

[fallen moat]

pq-qr-pw+rw

1st: rearrange to this pattern

pq-pw-qr+rw

this is your teacher's first hidden step

[crimson sedge]

ok

[fallen moat]

yes?

[crimson sedge]

nvm pls continue

[fallen moat]

oh typo, just corrected

[crimson sedge]

ok

[fallen moat]

2nd group them into 2 pairs
(pq-pw) + (-qr+rw)

the brackets are mainly for clear expression

[crimson sedge]

ok

[fallen moat]

3rd: find common factors for each group

+pq and -pw, we have a common factor p

[crimson sedge]

yes

[fallen moat]

so, we can factor it out and become
p(q-w)

[crimson sedge]

ohhh ook

[fallen moat]

-qr and +rw, we have a common factor r

so we can factor out and become
r(-q+w)

[crimson sedge]

so its r(-Q+W)

sorry ca[s

[fallen moat]

np!

now write it down and become
p(q-w) + r(-q+w)

[crimson sedge]

done

[fallen moat]

and we notice that (q-w) is very similar to (-q+w)

[crimson sedge]

yes however the equation is diff

[fallen moat]

but in what sense?

[crimson sedge]

so we change it

[crimson sedge]

one bracket is minus while the other iis plus

[fallen moat]

we need to do something to make (-q+w) become (q-w)

so we factor out a -1

[crimson sedge]

yes

[fallen moat]

(-q+w) = ( (-1)q + (-1)(-1)w )

get it?

[crimson sedge]

yes

[fallen moat]

next it will become
(-1)(q-w)

which is -(q-w)

[crimson sedge]

sum (-)+(+)) is (_)

[fallen moat]

hmmm?

[crimson sedge]

ok

[fallen moat]

product of (-) and (-) is (+)

[fallen moat]

now plug back in

[crimson sedge]

ok

[fallen moat]

p(q-w) + ( r ( -(q+w) ) )

[crimson sedge]

r turn to negative

[fallen moat]

yes

which becomes
p(q-w)-r(q-w)

which is your teacher's first step

[crimson sedge]

ok i understand

[fallen moat]

now

find common factor(s) of this 2 terms

+p(q-w)
-r(q-w)

[crimson sedge]

(p-r)(q-w)

[fallen moat]

very good

[crimson sedge]

ok i understand now

[fallen moat]

let's start with (b)

[crimson sedge]

ok

[fallen moat]

tbf, usually with 4 terms, you dont really need to rearrange

so

(b) x²+xy+6x+6y

[crimson sedge]

just skip to the 2 step

and save time during exam*

[fallen moat]

good

whats the common factor of +x² and +xy

[crimson sedge]

x

[fallen moat]

so

they will become?

[crimson sedge]

x(x+y)

[fallen moat]

very good

whats the common factor of +6x and +6y

[crimson sedge]

6

[fallen moat]

and they will become

[crimson sedge]

6(x+Y)

[fallen moat]

now we have x(x+y) + 6(x+y)

[crimson sedge]

YEA

[fallen moat]

they will become?

[crimson sedge]

(x+6)(x+Y)

[fallen moat]

done, remember it's y and not Y

[crimson sedge]

sorry this isnt my com

[fallen moat]

in maths, they are usually representing different things

[crimson sedge]

its glicthig

[fallen moat]

np!

now it's your turn for the rest

you can write them out instead of typing

if that's better for you

[crimson sedge]

ok

before we go to the others can i write it down

[fallen moat]

of course

[crimson sedge]

ok done

[fallen moat]

for 4 terms questions

1. group them into groups of 2
   (be careful with the negatives)
2. get common factor(s) out of each group
3. get common factor(s) out of the resulted 2 terms

[crimson sedge]

alrigth

let me write it down

[fallen moat]

now is your turn, take your time

if i am not respondin, ping me

[crimson sedge]

how to ping exactly

[fallen moat]

type @ and it will show

[crimson sedge]

ok

sure

@fallen moat i understand a and b

[fallen moat]

yea？

[crimson sedge]

but c is a different equation

can u help me out

[fallen moat]

lemme check

[crimson sedge]

ok

[fallen moat]

well, (c) is not that different, lemme type it out first

[crimson sedge]

ok

[fallen moat]

(c) 3ab-9ad+bc-3cd

let's look at the first 2 terms

[crimson sedge]

3 and 9

[fallen moat]

what common factor(s) do they have

[crimson sedge]

a

[fallen moat]

and ?

[crimson sedge]

c

[fallen moat]

nah, i mean the first 2 terms

i see you've noticed the 3 and 9

[crimson sedge]

a and 3 ?

[fallen moat]

correct

now it will become?

[crimson sedge]

3a

[fallen moat]

3a(?????)

[crimson sedge]

3a(b-3d)

[fallen moat]

correct

i bet you can continue from here

(note that always get ALL common factors out before next step)

[crimson sedge]

ok let me try

got it\

@fallen moat

[fallen moat]

yey

[crimson sedge]

its (3a+c)(b-3d)

[fallen moat]

correct!

[crimson sedge]

i think i can do the rest

[fallen moat]

(d) ah+aj-bh+bj
(e) jm-jn+ym-yn
(f) 9xy-3xz+12py-4pz

okay!

good luck!

[crimson sedge]

yes im confident

thank you for ur time

[fallen moat]

[crimson sedge]

i thougth i was dumb

anyways byeee

https://tenor.com/view/cat-sticker-line-sticker-bye-sticker-goodbye-sticker-hand-wave-gif-26479344

[fallen moat]

nah~

you did good!

[crimson sedge]

ty

[fallen moat]

bye~

[crimson sedge]

close the sever

[fallen moat]

you can type .close

[crimson sedge]

.close

[cedar kiln]

Channel closed

Closed by @loud tinsel

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

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Remember:
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[viscid perch]

if the first permutation has p inversions

how many will the second one have

say in general

we don't know values of n1, n2, nk....

[cedar kiln]

@viscid perch Has your question been resolved?

[dreamy sleet]

,rotate

[dreamy sleet]

can you define “inversions”?

a permutation has only one inverse( f * f^(-1) = f^(-1) * f = e)

[viscid perch]

when number of bigger value is before number of smaller value

(3 2 1) has 3 inversions

3>2

3 >1

2>1

[dreamy sleet]

Does this mean an inversion is a permutation

[viscid perch]

inversions are in permutation

and we want to know how many there are in lower row of the second one

[cedar kiln]

@viscid perch Has your question been resolved?

[cedar kiln]

@viscid perch Has your question been resolved?

[dreamy sleet]

is this group theory?

[viscid perch]

not really, we can leave that out

[cedar kiln]

@viscid perch Has your question been resolved?

[viscid perch]

<@&286206848099549185>

[tranquil oracle]

consider two numbers ni, nj in the permutation, show that A iff B, where

A: They form an inversion in the first permutation
B: They do not form an inversion in the second permutation

[viscid perch]

i understand that

[tranquil oracle]

once you notice that, it shouldn't be too hard to count

inversions in the first permutation become non-inversions in the second

and vice versa