help-13

[crimson sedge]

idk how to read the triangle

[buoyant latch]

What is tan

On a triangle how is tan defined

[crimson sedge]

uh

im not really sure

its a new concept for me

[crimson obsidian]

Triangle is 3 lines connected with each other. There is no words on it so how can you read triangle

[crimson sedge]

idk about tan or sin

i know trig tho

[crimson obsidian]

Atmost you can see triangle

[buoyant latch]

Ok what do you know about sin cos and tan

[cosmic steppe]

You wrote down "sohcahtoa" and still don't know what tan is?

[crimson sedge]

that aint me

[buoyant latch]

What do you know about trig

[crimson sedge]

Write in a triangle to solve for x

[crimson obsidian]

What does that mean

[buoyant latch]

How would you do this

[crimson sedge]

i know how to do trig

so

u find the hypotenuse

adjacent

and opposite

the opp is 4

adj is 2

no

wait

the hyp is 4

[crimson obsidian]

It's not right triangle

[buoyant latch]

Nowhere does it say 4 is the hypotenuse

[crimson sedge]

u wrote it wrong

[crimson obsidian]

Hypotenuse exist only in right angled triangle

[crimson sedge]

thats hyp

[buoyant latch]

Of what

There’s no right angle triangle on this diagram

[crimson sedge]

^^^^^^^^^^^^^^^^^^^^^^

Your doing everything but answering my question

[crimson obsidian]

Concept required is necessary

[buoyant latch]

Well you’re missing a lot of foundational knowledge

[obsidian coral]

Because you have a lack of understanding of the concepts that leads into it

[buoyant latch]

I’m trying to see where you’ve gone wrong

[buoyant latch]

Do you understand that trig works on right angled triangles

[crimson sedge]

i only know trig in a right angle triangle

[crimson obsidian]

You also have English problem like you can't read a triangle, and surely you can't do a triangle since it's not verb

[buoyant latch]

Not the point, he’s saying he doesn’t understand the diagram

[crimson obsidian]

I see

[crimson sedge]

Clearly you must have missed the point. By "read" i mean interpret. Stop talking here if you wont help.

[buoyant latch]

Anyway

So do you know that tan = sin/cos

[crimson sedge]

Yeah ik this

[buoyant latch]

Or have you heard of soh cah toa outside of this one question?

[buoyant latch]

What does that mean

[crimson sedge]

i have never seen a q like that

[buoyant latch]

Can you explain what this means

[crimson sedge]

ILL JUST SKIP THE Q

damn

[buoyant latch]

What’s the star

[crimson sedge]

.close

[cedar kiln]

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[obsidian coral]

.reopen

[cedar kiln]

✅

[crimson sedge]

do not reopen

.close

[cedar kiln]

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[obsidian coral]

So you don't want help?

[crimson sedge]

no because ppl do not understand how to answer my q

they are doing everything except answering the q

[obsidian coral]

People are trying to help you. You are failing to understand the concepts that leads intothe question are are asking

[crimson obsidian]

If you want answer then it's not place. We help you understand how to find answer yourself so we don't give you answer

[obsidian coral]

So people are trying to see where the disconnect is

.reopen

[cedar kiln]

✅

[crimson sedge]

is this notbasic knowledge tho

[crimson sedge]

I did not say i want the answer i said how do i read the triangle

to find sin60 etc.

[buoyant latch]

The definition of sin cos and tan is very basic

[crimson obsidian]

I see

[buoyant latch]

It is the first thing you learn about sim cos and tan

[obsidian coral]

And understanding how trig works leads into how to read that triangle

[crimson sedge]

i meant is it not basic knowledge

[buoyant latch]

It should be

[crimson sedge]

i dont have time for that

my exam is in 4 hours.

[crimson obsidian]

Reading a triangle is also a basic knowledge

[crystal raptor]

bro just go to sleep

[buoyant latch]

You should’ve started studying months ago then

It is not our problem you decide to ask now

[crimson sedge]

you clearly didnt even know what i meant by read.

[crimson obsidian]

Yeah but now I know, you meant interpret

[crimson sedge]

I agree. but your doing everything but answering the question

You dont need to know trig to learn how to read that triangle.

[buoyant latch]

You can’t read the triangle because you don’t understand what you’re reading

[crimson sedge]

I am trying to find out how to find sin 60 and tan 30 on that triangle

[crimson sedge]

Why am i here then

[buoyant latch]

This requires understanding what sin and tan means

Which is what I asked you at the beginning if you knew

[buoyant latch]

We were up to here which is close to the answer before you decided to quit

[crimson sedge]

Wdym what does sin and tan mean?

[crimson obsidian]

If you study with calm and patience mind you will learn a lot sooner

[buoyant latch]

exactly, what does it represent on a triangle

That’s the missing piece you need to know

[obsidian coral]

I 100% agree with this. Because tbh, all the questions I've seen you ask are basic concepts that people explained well and you were still confused on what people meant

[buoyant latch]

Which will allow you to read the triangle to do the question

[buoyant latch]

So can you further elaborate on what the stars mean on this picture

If you can’t I can explain what it’s supposed to mean

[buoyant latch]

I’m just trying to push you to think about the topic a bit before giving you the answer

[crimson sedge]

I agree too.

The star obviously means times

???????????????????????????????????????///

[buoyant latch]

So for something like this how would you find x?

[crimson sedge]

Why would i put a random x there.

[buoyant latch]

(It’s wrong if it means multiply)

[crimson sedge]

haha

[buoyant latch]

This is wrong

[crimson sedge]

anyways ty for ur help

.close

[cedar kiln]

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[obsidian coral]

Why are you being rude to people who are trying to teach you?

[crimson sedge]

^^^^^^^^^

I do not have time I appreciate the help

4 hours till an exam

[buoyant latch]

Come back after the exam when you have time then

[crimson sedge]

I would rather lose 4 marks then spend 4 hours on it to gain 4 marks

Its not even guaranteed to come up too

[obsidian coral]

Losing marks adds up

Btw you being rude to people, makes people want to help you less and less

[crimson sedge]

No one was rude.

I thanked the person.

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[crimson obsidian]

Is the range of y=x^12-x^9, [0, infty)

[crimson obsidian]

Nvm this question I seem to be confused with something else..I can't remember the exact question

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[crimson obsidian]

.reopen

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[crimson obsidian]

Is the range of y=x^12-x^9, [0, infty)

This is the question I want to ask I'm sure

Because polynomial function is always continuous and this functions minimum value seems to be 0, can I say that range is [0, infty)?

Just want to make sure

[fresh quarry]

Is the domain given?

[crimson obsidian]

No domain is not given

x belongs to R

You could say

[fresh quarry]

Okay

[crimson obsidian]

Teacher told that if minimum value and maximum value is given and function is continuous then the range is [min, max]

Just want to be sure if this concept is applicable here or not

[fresh quarry]

For what value of x, you can have y = 0?

[crimson obsidian]

0

[fresh quarry]

No my bad, 1

Yeah and 0

[crimson obsidian]

And 1

[fresh quarry]

Yeah you're correct then
Range is [0,infinity)

[crimson obsidian]

Ohh

Thank you for confirming it!

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[cosmic basalt]

I feel so dumb but for future reference, how do I go about solving equations like this?

[cosmic basalt]

No matter what I do or how I interpret it on earlier questions, I fail.

[dire geode]

Work inside out

|6-14| ignore the vertical bars first

What's 6-14

[cosmic basalt]

That would be -8

[dire geode]

Since 6-14 = -8, you can substitute that

|-8|

Do you know how absolute value works

[cosmic basalt]

I forgot, hence why I ask

Sorry if that's rude

[dire geode]

It's a very simple function

You can be more specific next time if you don't want to be told stuff you already knew

[cosmic basalt]

I genuinely forgot how to do equations like this in general

So absolute value is just restorative to positive right?

So like no matter what, anything in absolute value is positive?

If I recall correctly

Got it, thanks for forcing me to remember lol

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[ionic thistle]

<@&286206848099549185> any ideas?

[vague kelp]

A

Repeating patterns or maybe like repeating additions

No sorry

Answe is E

[ionic thistle]

yes

[vague kelp]

Get it now?

You can close the post

[ionic thistle]

no wait

i mean yes when u ask about the answer

[vague kelp]

Ok see

Upper boxes are 5, 1 and 4

Which add up to make 10

[ionic thistle]

to make it more easy i draw the numbers

[vague kelp]

Yeah so

To make the LHS = Rhs

Repeat the addition pattern

That's it

Get it?

[ionic thistle]

i dont think u have to make them "="

[vague kelp]

Like to solve the question

These are easy questions

[cedar kiln]

@ionic thistle Has your question been resolved?

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[quick flume]

What did I do wrong

[vague rapids]

4-16=-12

@quick flume

Step 3

[quick flume]

I figured it out

Is the answer x= 3/4?

[vague rapids]

gud

[vague rapids]

no

[quick flume]

X=3

@vague rapids

[vague rapids]

yes

[cedar kiln]

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[crimson sedge]

Ik it should be simple but my brain is shutting down and i cant understand why its equal to a^3

[vague rapids]

,rccw

[vague rapids]

same power of r is in numerator as well as denominator, so they get cencelled

cancelled

[crimson sedge]

OH

Tysm

.close

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[crimson sedge]

delta infinity - < Limit -delta H(being anti derivative) - 0
is this A way to solve for an intagral that inevitably divides by 0?

[cedar kiln]

@crimson sedge Has your question been resolved?

[jaunty thunder]

which specific integral are you facing? @crimson sedge

[crimson sedge]

i’m just wondering in general

[jaunty thunder]

because I don't quite get the notation...could you handwrite your notation or use LaTeX? Sorry for it!

[cedar kiln]

@crimson sedge Has your question been resolved?

[crimson sedge]

here

@jaunty thunder

{h>x}

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[simple bane]

There are 3 questions, you can only answer yes and no. What is the cance to answer 2 yes and 1 no, if the order doesn't matter?

[radiant topaz]

think about arrangements of yyn

[simple bane]

so i know there are eight combinations

[radiant topaz]

that are the total ways yes

[simple bane]

but i dont know how to approach this task

[radiant topaz]

think about how many ways can you arrange yyn

[simple bane]

yyn?

how come there are 3?

[radiant topaz]

yes yes no

[simple bane]

oh

[radiant topaz]

yes no yes

what more?

[simple bane]

3?

[radiant topaz]

yes that's it

[simple bane]

so 3/8 chance?

[radiant topaz]

yes

[simple bane]

damn, thanks!

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[half urchin]

1+1=?

[simple bane]

do you know how to approach this question?

[cedar kiln]

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[cedar kiln]

@crimson sedge Has your question been resolved?

[jaunty thunder]

you just need to use int(x)=ln|x|+C

integration by parts is only applicable when all terms are well-def.

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[crimson sedge]

what do you mean

also can you explain that?

[surreal cave]

domain of logarithm

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[lone forum]

For 2e, would the minimum just be the zero vector, as you add an opposite vector?

[crimson obsidian]

What is 2 in first place though

[lone forum]

That’s the question number my bad

I was just stating which question I’m asking on

[crimson obsidian]

I know, I asked what is question 2 though

Because e is sub part of 2

So knowing the actual question could help

[lone forum]

My bad, a and b don’t represent a numerical value in this question, so I didn’t bother adding it in when I should’ve to provide you with context

[crimson obsidian]

I see. My bad I misunderstood the question then

Do you know the formula that if A and B are two vector then the magnitude of their sum, |A+B|= √(|A|^2 + |B|^2 + 2|A||B|costheta)?

Also sorry for late response

[lone forum]

Yes I do know that and no worries

[crimson obsidian]

So basically you can prove that e using that formula

Just see at what theta e comes to existence

And that theta will give your answer

[lone forum]

What do you mean by theta e?

[crimson obsidian]

Angle

The angle in that formula

By adjusting its value so that you get minimum value of the given vector

[lone forum]

Would theta be 180 then, because of cos180=-1?

[crimson obsidian]

Yeah

Just put it

You told right at beginning

That opposite vector is minimum

No you didn't tell that nvm

[lone forum]

I’m confused, are you saying that the addition of a vector plus it’s opposite, gives the minimum of zero vector? Or is it also angle related?

[crimson obsidian]

There is no zero vector

Because only if both vectors are equal, the sum is 0 vector

Here they may not be equal

a may not be equal to b

[crimson obsidian]

magnitude is minimum, yes

That's evident by formula

If a is opposite vector of b, I suppose you mean their direction is opposite

[lone forum]

Yes

[crimson obsidian]

Opposite vector is not equivalent to negative vector

If a and b are negative vector their sum is zero vector

By zero vector I suppose you're telling about a vector whose magnitude is 0

[lone forum]

Yes

[crimson obsidian]

So if a and b are opposite vector their sum may not be a zero vector

[lone forum]

True

[crimson obsidian]

But one thing is sure that their sum will form a vector with minimum magnitude possible

And that's what the question is asking

So only if a is opposite vector of b

Can minimum value be achieved

Does that help you getting answer?

[lone forum]

Is “their sum” referring to b vector summed with its opposite (a in this case)?

[crimson obsidian]

Yeah

We made a and b opposite vector by adjusting their angle with each other to "180 degree"

[lone forum]

Oh, so the 180 degrees minimizes the sum of the vectors and it can’t be guaranteed that the vectors with cancel each other out. So therefore the 180 is the main factor in minimizing the magnitude of the addition of the vectors

[crimson obsidian]

Yeah angle 180 degree is

|A+B|= √(|A|^2 + |B|^2 + 2|A||B|*cosQ) so if you put theta, Q 180 degree here.. you will get answer

Similarly if you want to maximize the sum of two vector, angle 0 degree is the main factor in maximizing the magnitude of the addition of the vector which can be analysed from formula as well

[lone forum]

The thing is though, is that the question asks what is the minimum value of the magnitude, so isn’t the minimum the zero vector if conditions are met? Because it seems it’s asking for what’s the smallest rather than how to minimize it. I understand what you’re saying but is that what the question is asking?

[cedar kiln]

@lone forum Has your question been resolved?

[cedar kiln]

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[hidden osprey]

How do we go from r𝜔^2(-cos(𝜔t)î-sin(𝜔t)ĵ)
to -𝜔^2r

[crystal raptor]

You were not differentiating between the two different r last time FYI

[hidden osprey]

?

[crystal raptor]

Anyway pull out a minus and see that it's -ω²(bold r)

[hidden osprey]

different r?

[crystal raptor]

There is a bold r and a normal r

Those are different things

[hidden osprey]

r is simply the magnitude

of bold r

[hidden osprey]

what happens to the cos and sin

wait a minute

[crystal raptor]

Remind yourself the definition of bold r

[hidden osprey]

does it have something to do with root(2)

[hidden osprey]

a vector

oh wait a minuet

ohhh

.close

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[worn hazel]

Does anyone know how to solve this?

[cedar kiln]

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[cedar kiln]

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[low holly]

How does one actually remember or derive these?

[low holly]

This one i can find by differentiating r = r sin cos x ex + r sin sin ey + r cos ez wrt to r, theta and phi. But how about cartesian in terms of spherical?

[dire geode]

yea there aren't great resources online

i could only find physics notes
https://ocw.mit.edu/courses/16-07-dynamics-fall-2009/57081b546fff23e6b88dbac0ab859c7d_MIT16_07F09_Lec05.pdf

but maybe that's good enough for your purposes

this one... is detailed
https://derive-it.com/2022/02/22/unit-vectors-for-a-spherical-coordinate-system/

[low holly]

Cool thanks

Just gotta remember it well for my exams

[still barn]

Do you actually need to know the derivation for an exam? That above link has some broken links in it, but the roadmap in my head for how I would approach this derivation is longer than my attention span would allow to see it through to the end.

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[rugged shadow]

Let A be a set of logical evaluations with an odd number of elements (i.e., A contains an odd number of evaluations). Let D be the set of propositional formulas that are satisfied by a majority of evaluations (at least half plus one) in A. Prove or explain why the following statements do not hold:

1. If φ is a formula, then either φ or ¬φ belongs to D.
2. If φ belongs to D and (φ → ψ) is a tautology, then ψ belongs to D.
3. If φ and (φ → ψ) belong to D, then ψ belongs to D.

[cedar kiln]

@rugged shadow Has your question been resolved?

[rugged shadow]

<@&286206848099549185>

[cedar kiln]

@rugged shadow Has your question been resolved?

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@rugged shadow Has your question been resolved?

[rugged shadow]

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[oblique mauve]

hi can someone point me to a resource where I can read up spatial integration? my google search keeps giving me stuff about policies and what not.

[royal loom]

Ask this in #book-recommendations

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[trim quail]

identify the verticies and direction of opening

how would i do it for this particular prob

[cedar kiln]

@trim quail Has your question been resolved?

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[surreal cave]

are you trying to find the height of the tree?

[azure violet]

yep

i know its 1,8m + AC

[surreal cave]

what do you know about 30-60-90 special right triangles? especially relating to their sides

[azure violet]

i ended up with 10,8 but it was wrong

[azure violet]

the shortest side is half of the hyptoneus

[surreal cave]

that is true and what about the other leg?

[azure violet]

idk

[surreal cave]

think of the pythagorean theorem $x^2+b^2=(2x)^2$ i got this because $b$ is the missing side and $x$ is the shortest side, the hypotenuse is two times the length

[wraith dagger]

XxMrFancyu2xX

[surreal cave]

do you think you can solve b?

[azure violet]

i know that a^2+b^2=c^2

[surreal cave]

yes

and c, the hypotenuse is two times the shortest length a

so what can you therefore infer?

[azure violet]

CB is 18m'

i think

18-9 is 9

9+1,8 is what i end up with

wait

eh

idk

[surreal cave]

sqrt(18^2-9^2) my friend

the pythagorean theorem relates the squares of the sides

not the sides themselves

[azure violet]

oh wait yeah

9x9

81

81*2

is the hypo

[surreal cave]

no, 81 is the shortest side

18^2 is the hypotenuse

[azure violet]

es i know

yes

[surreal cave]

Pythag says: a^2+b^2=c^2 ==> b^2=c^2-a^2 in your triangle a=9 and b=2*9=18 hence b is the missing side—the remaining height of the tree: b^2=18^2-9^2

can you do the rest?

[azure violet]

i did it

[surreal cave]

what did you get as your answer?

[azure violet]

'

the tree is 17.3

in height

[surreal cave]

congrats! 🎉

[azure violet]

thank you

thanks for the help

.close

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[timber turtle]

A car can hold 3 people in the front seat and 4 in the back seat. in how many ways can 7 people be seated if 2 people must sit in the back seat and 1 in the driver seat?

[timber turtle]

wouldn't it just be 7!

since the 7 people will always fill the car

thus filling the condition of 2 in the back and 1 driver

mhm

right

mhm

so its 3 * 4P2 * 4!

wait nvm

yeah im tripping balls

ohh right

4p2 * 4!

is that correct

[rain drift]

fwiw I think the question is not worded very well, hence the confusion.

[timber turtle]

true

.close

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[smoky idol]

!status

[cedar kiln]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[iron cave]

1

[smoky idol]

Do you know about the law of cosine?

[iron cave]

Yes but i figured it wouldn;t make sense with x

[smoky idol]

Ah you're right, I read too fast. Stand by

[iron cave]

👍

[iron cave]

yea

[smoky idol]

you could find angle C which would be $180^{\circ} - \alpha$

[bold vine]

Law of Sines?

idk

[wraith dagger]

imTyp0

[smoky idol]

and then do law of cosine with that

[bold vine]

minus 3 alpha

[iron cave]

but there;s still the x

[smoky idol]

cosine law only takes angle and the two sides next to it

if you take angle C you should be fine

[iron cave]

hmm

[smoky idol]

and yeah -3 alpha my bad

but er, that might not lead somewhere unless there's an identity for cos(pi-alpha) let me check

[iron cave]

now i have $x^{2}=25+9-30\sin\left(180-3a\right)$

[wraith dagger]

TheWiseDragon

[iron cave]

and like i said, the x is in the way

[smoky idol]

am dumb bleh

[bold vine]

You could do Law of Sines with angles A and B

[iron cave]

If it helps, this unit is about simplification of trig and double angles

[iron cave]

ill try

[smoky idol]

oh wow yea

sorry Shen you said that above but I skipped it -.-

[bold vine]

Is ok ❤️

[iron cave]

$3\sin\left(2a\right)=5\sin\left(a\right)$

[wraith dagger]

TheWiseDragon

[iron cave]

now what

[smoky idol]

$sin(2\theta) = 2sin(\theta)cos(\theta)$

[wraith dagger]

imTyp0

[iron cave]

oh yeah

[smoky idol]

divide by sin

and solve

[iron cave]

ok i got it

now what to do for b?

[smoky idol]

hm. Find the value of x with law of sine / cosine

and then plug in polynomial I guess?

to be frank I don't get the question that well

[iron cave]

same

[smoky idol]

but I think it wants you to show that the x in the triangle is a solution to that in the polynomial

[iron cave]

yeah

orrrrrrrrrrr

Use the law of cos but try "to find" 3?

since we have cos(a)?

[smoky idol]

maybe. let's see, $3^{2} = x^2 + 5^2 - 2 \cdot 5 \cdot x \cdot \frac{5}{6}$

[wraith dagger]

imTyp0

[smoky idol]

is that what you meant?

[iron cave]

yea

[smoky idol]

well, that'd certainly give you x.

[iron cave]

yes but see it's trying to make you prove a polynomial i think

[smoky idol]

I think I see what you mean, but I don't know where that x^3 would come from

[iron cave]

x^3?

it's to the power of 2

[smoky idol]

em blind

[livid hound]

applying the cos law there gives you the quadratic equation above. Just rearrange to the desired form

[smoky idol]

yeah this

[smoky idol]

this

[iron cave]

something is wrong thou

I got x^2-25x+98=0

not 48

[livid hound]

show work

[iron cave]

ok

[iron cave]

I literally just simplifed this

oh wait

never mind

Ok thank you all so much!!!

I think i can do c

.close

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[light cliff]

Help is appreciated

[drifting marlin]

!status

[cedar kiln]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[light cliff]

1

[drifting marlin]

start by filling in the totals on the edges

[light cliff]

30, 35, 35, 100 top to bottom i think

[drifting marlin]

and the bottom row?

[light cliff]

65, 25, 10

[drifting marlin]

alright

now using the table, what is P(junior and drama)?

[light cliff]

like the totals of the two?

[drifting marlin]

no

what does each number (excluding the totals) in that table represent?

like what does the 20 in the top-left box represent?

[light cliff]

oh i see so 13?

[drifting marlin]

13 isn't a probability

[light cliff]

oh

[drifting marlin]

13 students are indeed juniors that do drama. However, how many students are there?

[light cliff]

100?

[drifting marlin]

so if 13 students are juniors that do drama, and there are 100 students total, then the probability that a randomly chosen student is a junior that does drama is...?

[light cliff]

i did 13/10 and got 0.13

dont think thats right

so 13%?

[drifting marlin]

13% yes

[light cliff]

oh it is right

[drifting marlin]

now how about drama?

[light cliff]

what do you mean? is 13% not the answer

oh

i see nvm

but how do i get the percent of drama, is it just 7%?

[drifting marlin]

it is not

how many students total do drama?

[light cliff]

25

28%?

[drifting marlin]

why 28%?

[light cliff]

i divided 7/25 and got 0.28 and converted to percent which is 28%

[drifting marlin]

where is the 7 coming from?

[light cliff]

sahit

shit

is it 52%

i was looking at the sophomore drama not junior

[drifting marlin]

it's not 52%

25 total students do drama, and there are 100 total students

[light cliff]

oh

25%?

[drifting marlin]

better

[light cliff]

lmao i hate this

[drifting marlin]

well the hard part is done

[light cliff]

idk how people remember this

[blazing zephyr]

can say a sophomore be both in sports and drama?

[light cliff]

?

is the final answer 52%?

[blazing zephyr]

like can a person be counted in sports and drama?

[drifting marlin]

,calc 13/25

[wraith dagger]

Result:

0.52

[drifting marlin]

seems good

[light cliff]

thank you 🙏

[light cliff]

not sure

[drifting marlin]

the way the table is presented implies no

[blazing zephyr]

is it saying if you pick a person that is in drama what is the probability of it being a junior or what

[drifting marlin]

yes

[light cliff]

pretty sure

[drifting marlin]

<@&268886789983436800>

[light cliff]

can you help with 1 more question its basically the same type i just wanna make sure i do it right

[blazing zephyr]

sure

[drifting marlin]

the channel is yours until you close it

[light cliff]

its this sorry i was not looking

i got 2% for junior and male

how do i get the male part

is it 14% for final answer

[blazing zephyr]

i think so

[light cliff]

yeah i put it in its right

k im good now

thanks for the help

.close

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[wintry owl]

How do I know if there is V.A or H.A in a graph

[south tundra]

If the limit of f(x) as x -> inf or x -> -inf exists, then there is a horizontal asymptote

[heavy mulch]

A V.A appears when the numerator and denominator does not share a factor while the denominator approaches zero (or something like that)
A horizontal asymptote appears if the numerator biggest ^x is less than or equal to the denominators biggest ^x

[south tundra]

If there is a point where the value of f(x) diverges to either of infinities, then that's where the vertical asymptote lies

[wintry owl]

Ok

thanks

.close

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[somber tiger]

$\int sin^4(x)} dx$

[wraith dagger]

Kry
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[somber tiger]

whats the best way to tackle this would it be just to make it 1/2(1-cos2x) times 1/2(1-cos2x) and just do by parts?

[smoky idol]

maybe with $1-2sin^{2}x = cos(2x)$, then isolate sin^2x and square both sides?

[wraith dagger]

imTyp0
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[somber tiger]

i have no clue what you mean

[smoky idol]

take the identity that I just gave, namely 1-sin^2(x) = cos(2x), and isolate sin^2(x)

[somber tiger]

how would you get 1-2sin^2(x) from sin^4(x)

oh ok i see

[smoky idol]

that should give you -(cos(2x)-1)/2

or something like that. Then you square both sides and you have sin^4(x) in terms of cos(2x). Easier to integrate

[somber tiger]

wait can you right it out step by step cause im a little reetarded

[smoky idol]

$cos(2x) = 1 - 2sin^{2}x \newline cos(2x) - 1 = -2sin^{2}x \newline -\frac{1}{2}(cos(2x)-1) = sin^{2}x$

[wraith dagger]

imTyp0

[bold vine]

You can look up a list of trig identities too

[smoky idol]

the identity for sin^4 must be monstruous though, wouldn't it?

[somber tiger]

mmm ok is that the best way to solve it

[bold vine]

Just square what you typed up

[somber tiger]

cause its in the chapter where we usual have an odd and even cos/sin so you can u sub

[smoky idol]

yeah. But that'd give something quite big and weird to memorize

[bold vine]

Kinda true

[smoky idol]

hm, well, there I don't think you can do it because if u=sinx, du = cosx and you don't have cosx in your expression

[somber tiger]

i know thats why i asked for help I meant is that the identity the best route to go

[smoky idol]

that's pretty much the only thing I see there

[dire geode]

,w int sin^4(x)

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by riemann#2529

[dire geode]

Yes double angle formulas

[dire geode]

.

[somber tiger]

ok but if i square it I would still have a cos^2

so should I then make that into 1/2(1+cos2x) and then int that whole thing

[bold vine]

Double angles twice for cos^4 and sin^4

[dire geode]

Repeat for cos^2(2x)

[somber tiger]

ok ill try that thxs guys

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[ebon drift]

I have no idea how to do part c of the question

[humble marsh]

for domain, g(x) is defined whenever f(x + 1) is defined

[ebon drift]

How do you know that

what does the -3 mean then

[humble marsh]

g(x) = -3 × f(x + 1)

if f(x + 1) exists then so does -3 × f(x + 1)

[ebon drift]

right

[humble marsh]

the -3 will affect the range

[ebon drift]

why not the domain though

[humble marsh]

the domain is wherever g(x) is defined

correct?

[ebon drift]

yeah

[humble marsh]

and g(x) = -3 f(x + 1)

[ebon drift]

right

[humble marsh]

when is -3 f(x + 1) defined?

[ebon drift]

in g(x)

?

[humble marsh]

for what values of x is -3 f(x + 1) defined

[ebon drift]

is it any value in the graph

from -4 to 5

[humble marsh]

that's when f(x) is defined

[ebon drift]

oh

[humble marsh]

what we want is -3 f(x + 1)

[ebon drift]

I guess I'm unsure about that then

[humble marsh]

it's defined whenever f(x + 1) exists

[ebon drift]

ohhhh wait

is it like

-3(f(x+1)

like that

[humble marsh]

I'm not sure what you mean

maybe this plot will help

[ebon drift]

-3 of f of x+1

[humble marsh]

f(x) is defined when 1 ≤ x ≤ 2

0.5 f(x) is f(x) but squashed by a factor of 2

0.5 f(x - 2) is that translated over to the right by 2 units

[ebon drift]

right

and the 0.5 affects the curve?

making it less steeper

[humble marsh]

yeah

so f(x) is defined when 1 ≤ x ≤ 2

and g(x) is defined when f(x - 2) is defined

[ebon drift]

yeah, right

[humble marsh]

which is when 1 ≤ x - 2 ≤ 2

or 3 ≤ x ≤ 4

so the blue curve (g) is between x = 3 and x = 4

[ebon drift]

Yeah

[ebon drift]

so would it be between 6 and -3

no wait

it's between -5 and 4

[humble marsh]

yep!

the -3 part means it's flipped and stretched out by a factor of 3

what does that mean for the range?

[ebon drift]

oh so i multiply it

so its -15 and 12?

[humble marsh]

correct!

[ebon drift]

ok, thank u

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[storm abyss]

Hey, could someone help me in solving this?

[storm abyss]

I tried taking the sin*cos to the other side and squaring, trying to convert all the cos terms into sin but it got too long

[silver parcel]

Squaring directly seems to be useful

(sin(theta)+cos(theta))^2 * (sin(2theta)/2)^2 = (1+sin(2theta))sin^2(2theta)/4

And now it's a polynomial in sin(2theta)

[storm abyss]

oh, didn't think of converting it into 2theta

[silver parcel]

Be careful of extraneous solutions tho, since we squared the eq

[storm abyss]

what do you mean?

[silver parcel]

Once you square, you make the right hand side always positive
But maybe the value of RHS was -1/sqrt(2) which was squared into 1/2

[storm abyss]

oh ic

thanks

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[earnest cloak]

how do icomplete the quare

[earnest cloak]

square

[autumn current]

ok so do you know what completing the square method is?

[earnest cloak]

halve and square the second term right

[autumn current]

yea

so do that

but this quadratic doesnt have simple roots, just letting you know

it has decimal values

[earnest cloak]

yeah

ik fractions

just tell me what to essetnially do from there

i did x^2+5x+(5/2 x)^2-5-(5/2 x)^2

oh wait

no

x^2+5x+(5/2)^2-5-(5/2)^2

[autumn current]

ok so from here you just do x^2+5x+(5/2)^2 - (5/2)^2-5=0

[earnest cloak]

yeah then after

[autumn current]

then you just take (x+5/2)^2 = (5/2)^2+5

then you simplify the RHS

then root it and you have an answer

plug answer into desmos to check answer

[earnest cloak]

why though

[autumn current]

you have a squared term on one side

you can just root it and you'll have isolated an individual x term

[earnest cloak]

alr fs

ty

[cedar kiln]

@earnest cloak Has your question been resolved?

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[near wing]

Can someone please explain to me step for step how to solve this problem

[livid hound]

the question requires you to know the definitions of
acute angle
obtuse angle
complementary angles
supplementary angles

if you don't know them, the first thing you should do is look them up

[near wing]

i know what they mean i’m just not understanding what i put for the supplement and the complement

[livid hound]

are you sticking with your choice for the first question?

[near wing]

oh no i know it’s acute

[livid hound]

in your own words, what are complementary angles

[near wing]

two angles that adds to 180

[livid hound]

no

complementary angles to not add up to 180°

[near wing]

oh wait

i meant 90

[livid hound]

yes, the measures a pair of complementary angles add up to 90°

$c + \red{\text{it's complement}} = 90\deg \
\red{\text{it's complement}} = , ?$

[wraith dagger]

ℝamonov

[near wing]

the complement is 90 right?

[livid hound]

no

c + x = 90°

c and x are complementary as they add to 90°

x is the complement of c

can you solve that equation for x

x = ?

[near wing]

okay i’m confused. how exactly would i find x

[livid hound]

have you solved equations before?

would you be able to solve something like
p + 3.1415 = 90

(for p)

[near wing]

no i haven’t even learned that yet

[livid hound]

$\algebruh$

[wraith dagger]

ℝamonov

[near wing]

yeah i know how to do that

[livid hound]

what's stopping you from doing that here

and you would also have been able to solve

p + 3.1415 = 90
(for p)

[cedar kiln]

@near wing Has your question been resolved?

[cedar kiln]

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[cedar kiln]

@raw wren Has your question been resolved?

[cedar kiln]

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[outer canopy]

be specific

[cedar kiln]

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[crimson sedge]

\emph{QUESTION PERTAINING TO CONVERGENT GEOMETRIC SEQUENCES}\par\par\par

Prove that:
$$\sum_{n=1}^{\infty} [\frac{3^{n-0.5} \times (\frac{x}{n})^2}{4}] = 2\sqrt{3}x^2$$

[wraith dagger]

LordFoogThe2st

[tropic oxide]

this looks strange

are you sure you copied the question correctly

it feels like an infinite power series like this cannot just be equal to a polynomial everywhere lol

[crimson sedge]

This must be diverging

Idk

Isn't x^k/k^2 some sort of special weird sum

[tropic oxide]

REPLY TO QUESTION PURPORTEDLY PERTAINING TO CONVERGENT GEOMETRIC SERIES (OR SEQUENCES? I DON'T KNOW WHAT OP MEANT)

@crimson sedge do you have a picture/screenshot of the question?

[crimson sedge]

Nope :(

It’s handwritten

[tropic oxide]

can you take a pic

[crimson sedge]

But it’s the exact same question

Okay

My tutor wrote it for me in my notebook

Just hold up

2 seconds

[tropic oxide]

ok

[crimson sedge]

Thanks for waiting

[tropic oxide]

hm.

oh right it's (x/n)^2 not (x/n)^n

this looks like a constant times the sum of 1/n^2

or... wait

does this even converge???

no, it doesn't... 3^n overpowers n^2

so not even the terms approach zero

so your tutor is asking you to prove a false statement.

[cedar kiln]

@crimson sedge Has your question been resolved?

[crimson sedge]

https://tenor.com/view/crying-meme-black-guy-cries-sad-man-thank-god-for-my-reefer-hood-news-gif-24902056

I will check with them then

Tysm for your time @tropic oxide

.close

[cedar kiln]

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[cedar kiln]

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[fading forum]

can someone please guide me?

[stray otter]

p series?

[fading forum]

havent learnt this yet

[stray otter]

ah shit

wait

[tropic oxide]

nor do you need to.

[stray otter]

not p series

[tropic oxide]

have you learned the power rule for integration

[stray otter]

just saw that as sigma notation

[fading forum]

yes

[tropic oxide]

have you also learned the definition of an improper integral

[fading forum]

i did find the integral to be (x^-a+1)/(-a+1)

[fading forum]

yeah

[tropic oxide]

missing parentheses!!!

two pairs of them

you found that the antiderivative is x^(1-a)/(1-a)

[fading forum]

yeah

[tropic oxide]

now you need to evaluate it at x=t and at x=1, subtract the two, and let t approach infinity

and tell which values of a result in a finite limit and which do not

also note your antiderivative only works when a ≠ 1 so the case a = 1 will need to get separate treatment entirely

[fading forum]

got (t^(1-a)-1 )/(1-a)

[fading forum]

oh right

[fading forum]

so the values which result in a finite limit are when a > 1 right?

[tropic oxide]

quite the opposite

[fading forum]

yea just realised

[tropic oxide]

a>1 yes

[fading forum]

and now i consider a new limit for when a = 1

right?

[tropic oxide]

you integrate 1/x dx

[fading forum]

okay cool. tysm

[cedar kiln]

@fading forum Has your question been resolved?

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[rain vine]

!status

[cedar kiln]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[rain vine]

4. I got 22.5

[tropic oxide]

show how you got there

I got an answer and would like my work checked
does not post work

also your answer doesnt match mine, so.

right now all that can be said is your answer appears wrong!

[rain vine]

like i said i don't have phone but here is the solution

on left side

[tropic oxide]

why did you convert H from feet to inches?

[rain vine]

i just put it in the online conevrter

[tropic oxide]

i said why not how

you dont need an online converter unless you happen not to know a foot equals twelve inches

the question is, why did you choose to stray from the formula's specifications?

[rain vine]

I am not american but i got 120inch for 10 feet

[tropic oxide]

H is supposed to be measured in feet!!!

A civil engineer relates the thickness T, in inches, and the height H, in feet ...

[rain vine]

yeah T = 4 inch
H = 10 feet = 120inch

[tropic oxide]

YOU SHOULDNT CONVERT H AT ALL!!!

[rain vine]

okay,

[tropic oxide]

the formula description says H is supposed to be in feet and it already IS in feet!!!!

[rain vine]

but from what i learn doesn't all the unit should be same while doing calculation

[tropic oxide]

all the units should be consistent if you want to avoid conversion-factor mistakes.

but this formula is given to us as-is with strict specifications for what unit each thing is measured in

even if it is inconsistent

from a dimensional analysis standpoint that 25 is pulling a lot of weight given that it includes all of the constants of proportionality that would need to go into the formula

also disregarding this: there's a fuckup at the last line -- 6,400 = 144,000L does not lead to L = 144,000/6,400

[rain vine]

oh I made mistake there i didn't see that

[tropic oxide]

your entire work is going to need to be thrown out anyway.

also i would recommend first solving for L symbolically (i.e. keeping T and H as T and H) and only then plugging the numbers in.

it'll be easier this way.

[rain vine]

okay, thanks for the help. The only think for me to click in my brain that unit shouldn't be converted. As from the childhood i was taught that way to always convert in the same unit

.close

[cedar kiln]

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[tropic oxide]

.ropen

.reopen

[cedar kiln]

✅

[tropic oxide]

@rain vine one last remark -- making sure all inputs of the same kind are measured in the same units is good practice when making a formula, generally

[rain vine]

@tropic oxide I am currently self-learning a book called "Algebra and Trigonometry by Micheal Sullivan" it's a great book and big book containing 1010 pages of content. Out of 1010pages I have only finished 120pages so far and it's been a month + a week i have started this book. Is not that I want to go any faster since this last 120pages has me teaches me so much. Is that I am losing my motivation since it has going too slowly. I got 3 month of vacation. So I am just staying inside doing nothing. I really want to complete this book as efficient I could. I am just looking for some advice. I really don't have any goal set up apart after finishing this i would read pre-calculus book and calculus. Can you just give a word that would insipire me to read/practice all day. I know it all depend on myself but can you speak out some word.

-this took a damn long time to write

[tropic oxide]

so... you're learning a lot, but also think the book is going too slow?

[rain vine]

the chapter are 15 to 20 page long but exercise takes a lot of time since every chapter have 100+ exercise.
going through one chapter also takes me more than a hour sometime even three hour. and all exercise essentially took me days to finish it

which is also kinda good since it help me to digest the chapter is that i am losing motivation

[tropic oxide]

so you're going through every single exercise?

[rain vine]

yup, trust me when i say every question is unique their are answer to only odd number question and all odd number question are unique and even number question are just like follow up but i am doing every single one

[tropic oxide]

i think maybe you would do well from lowering your question load

i can't say i have a foolproof technique for doing that

[rain vine]

uhh now i think of that I could do only odd number question and when I finish the book i can do even number question as a revise.
but the thing i am trying to say is my self-learning is not going well day by day i am loosing my interest/motivation what to do about that have u ever felt like that?

[tropic oxide]

i have, but i don't have any remedies for it

i do have an idea though

feel free to follow it or not

[rain vine]

what's the idea

i will try

[tropic oxide]

before you start every question, roll a pair of dice. if they come up 11 or 12, skip the question. otherwise do it as normal

[rain vine]

what's the probablity of that lol

[tropic oxide]

1/12

[rain vine]

hmm, feel like pokemon accuracy stat.

that's the absurd idea i have heard so far have u tried it?

[tropic oxide]

no

[rain vine]

ok ay

yeah i am closing this channel this was maybe helpful

.close

[cedar kiln]

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[cedar kiln]

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[last hedge]

I need help with that

[cedar kiln]

@last hedge Has your question been resolved?

[cedar kiln]

@last hedge Has your question been resolved?

[cedar kiln]

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[wraith basin]

Hi, I got a question regarding graph theory

[granite eagle]

[wraith basin]

Given a tournament with odd number of vertices, and with a property that all vertices have equal number of outgoing edges, show that for each vertex deg_in = deg_out

[crimson sedge]

!status

[cedar kiln]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[wraith basin]

I don't really know what to do

[crimson sedge]

start with a small example to build up intuition (eg 3 vertices)

[wraith basin]

Okay I did that already

[strange summit]

I can see that it's the case, I just can't proof it

[crimson sedge]

maybe use induction?

[strange summit]

You mean you know there is a nice induction proof or you just guess?

[crimson sedge]

oh wait

theres a nice proof without induction

@wraith basin consider A+A^T where A is the adjacency matrix

consider the vector of ones, using the above, you can show that 1 is an eigenvector of A^T

[strange summit]

Dear God

[crimson sedge]

?

[strange summit]

I was hoping I left linear algebra behind me

[crimson sedge]

are you the op?

linear algebra is a very big part of graph theory

[strange summit]

I am, guess we are though differently, it's just an intro

[crimson sedge]

what do you know about graphs then, any theorems that might be useful?

I guess you havent looked at adjacency matrices at all?

[strange summit]

I mean I know what they are, but we never once used them to solve exercises