help-13

[limpid jasper]

.close

[cedar kiln]

Channel closed

Closed by @limpid jasper

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[oak wagon]

15

I don’t even know where to start

[golden raven]

write the slope in terms of k

@oak wagon

[oak wagon]

What

[golden raven]

do you know what the slope of a line is

[oak wagon]

Yes

What do you mean in terms of k

[golden raven]

well slope is rise over run right

[oak wagon]

Yes

[golden raven]

so what are the rise and run?

for the line through the points

[oak wagon]

(Y2 - y1)/ (x2 -x1)

[golden raven]

well can you plug in the coordinates for the two points

[oak wagon]

I don’t have y2

[golden raven]

you do

its k

[oak wagon]

Oh yeah

[golden raven]

so now you have the slope in terms of k

[oak wagon]

I got -5k/ -12

[golden raven]

im assuming you mean (-5-k)/(-12)

which just simplifies to (5+k)/12

and we know that the slopes of two perpendicular lines mulitply to -1

therefore, if one line has slope 4, the other line has slope -1/4

so we now have (5+k)/12=-1/4

and we solve that

sorry i need to go rn

[oak wagon]

5 + k?

K is not -

[golden raven]

well (-5-k)/(-12)=(5+k)/12

you can just leave it like (-5-k)/(-12) if you like thats fine

[golden raven]

you cant just combine the -5 and -k like that

its -5 minus k

not -5 times -k

[oak wagon]

Oh yeah

What do we do now?

[cedar kiln]

@oak wagon Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

For standard deviation can it be determined by the gap of numbers

for example in data set a

it goes from 20,000-120,000

while in b

it goes from 20,000 - 600,000

so is that the reason why b is greater?

<@&286206848099549185>

[cedar kiln]

@crimson sedge Has your question been resolved?

[crimson sedge]

<@&286206848099549185>

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lyric cairn]

ok so the problem is this function, and i want to find the tangent line at x=0.8

[lyric cairn]

its kinda hard to see but this is honesrlt the farthest ive gone

i was wondering if there was a way to like get rid of the e with the ln in the 2ln(x+h) and 2ln(x)

[cedar kiln]

@lyric cairn Has your question been resolved?

Channel closed

Closed by @lyric cairn

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lyric cairn]

oops

[lyric cairn]

i meant to say

could i cancel out the e and ln in anyway?

[short blade]

do you know how to find derivatives with the quotient, power, and chain rules?

[tropic oxide]

not as it currently stands, no

also

[lyric cairn]

we technically didnt learn those yet...

[tropic oxide]

... what

[short blade]

yikes

[tropic oxide]

you are expected to do this straight from the defn??????

what the fuck?

[lyric cairn]

uhm

[tropic oxide]

hold up

can you show the entire problem exactly as it was given to you?

[lyric cairn]

we can use a calculator to estimate the slope...

[tropic oxide]

ok so you are expected to use a calculator.

can you show the calculator you're working with

[tropic oxide]

okay

are you able to use this calculator to evaluate your function at, say, x=0.8 and x=0.80001?

[lyric cairn]

lemme try

and i put this in the graph

oh wait is that it-

[tropic oxide]

hm

might not be working out so great

are you able to subtract two of the graphed y-values from each other

[lyric cairn]

uhm, not sure what that means

i can have two graphs going at the same time

[short blade]

there’s a derivative function in the ti-84

[lyric cairn]

ehh where

[short blade]

it should be able to evaluate the derivative of your function at the specified value

select MATH

[lyric cairn]

ohh

i see it

[short blade]

for future reference, you can just look up “ti-84 derivative” or what have you, and you’ll probably find something useful

[lyric cairn]

omg ty

yall are lifesavers

.close

[cedar kiln]

Channel closed

Closed by @lyric cairn

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[toxic sequoia]

Hi can someone help me? Im in geometry. I know how to get the side lengths of the 30-60-90 triangle but I cant figure out how to get to the area

[toxic sequoia]

And i need help with these types of problems. “Find the area using 30-60-90 triangles”

[uneven crater]

Ok, what is the area of a triangle you have learned in general

[cedar kiln]

@toxic sequoia Has your question been resolved?

[toxic sequoia]

what do you mean

[uneven crater]

Area of a triangle what is the formula for that

[toxic sequoia]

1/2 (bh)

Umm i figured out how to find the area of polygons using special right triangles after going through my previous notes for 15 mins. Thanks for your help tho, much appreciated

.close

[cedar kiln]

Channel closed

Closed by @toxic sequoia

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cyan pelican]

how to graph and equation

[cyan pelican]

and its first and second

derivative

without using graphing

calculators

/sites

behavior around critical points

need a sketch

do i just need behaviour

[cedar kiln]

@cyan pelican Has your question been resolved?

[cyan pelican]

<@&286206848099549185>

[slow crow]

Well a good exercise to be able to do that is to graph a random function, and try to graph one of its anti derivative

Knowing that your current function represents the variation of the one you're graphing

So highly negative means deeply falling down, near 0 means pretty stable, highly positive mean escalating up

Then you take your new graph and do it again

That's for the part function to derivatives

What do you mean by "equation?"? Something like f(x) =ax+b Or y² + x² = 1?

It just came to me that you may not know anti derivatives if it is the case let me know

[cyan pelican]

i dont

need rough sketch

its 4:30 am and im still doing this long assignment damn

[slow crow]

Ok so therefore we'll do otherwise because it is a little bit advanced

[cyan pelican]

critical points

[slow crow]

The first step will then be to graph f(t)

[cyan pelican]

are

[slow crow]

yup

[cyan pelican]

1.4 and .2

rounded

i just need ROUGH sketch

[slow crow]

Ok so you can put your critical points on your graph

Then try to see where the function is under and below

Maybe calculate some other far points if you want

And try to just graph something smooth

If you need rough sketch it'll be plenty enough

[cyan pelican]

do i need to find max/min for a rough sketch

[slow crow]

Well those are critical points aren't they ?

Or am I confusing vocabulary ?

[cyan pelican]

oh

they are

y points

do i need to find those

i thought u just find

behaviour around

critical points

negative positive

and just make those lines

[slow crow]

Behavior around x coordinates, therefore x coordinates of your critical points, and also y coordinates yeah

[cyan pelican]

ok so what do i need to find for a rough sketch

im confused

[slow crow]

You need to know the variation table of your function

The x where you have a min or a max

[cyan pelican]

critical points
behaviour around critical points
and what

[slow crow]

And f(x), the value of the min / max

that's all

pretty much

But you can help yourself by calculating other x value at midpoints between your max min or whatever you want

The more you know the better it get right ?

[cyan pelican]

i did behavioir around criticsl points and its

[slow crow]

I mean now i guess you're ready to graph it ?
If you're not confident show me the work and i'll try to help you

[cyan pelican]

-inf,0.2 test value 0 you get positive
0.2,1.14 test value 1 you get negative
1.14,+inf test value 2 you get positive

critical points .2 and 1.14

[cyan pelican]

meant to say +-+

[slow crow]

Try to graph it and then let me know

[cyan pelican]

wait no what

ok it is + - +

idk how to make a rough graph of this

critical points
(.195,0)
(0.138,0)

i pit this on rough grsph

now i gotta make lines that go + - +

shittt

something like this?

@slow crow

[slow crow]

It depends what you +-+ is for

Are you saying f is positive negative positive

Or f' is positive negative positive

[cyan pelican]

im trying to graph second derivstive rn

of a finction

this is second derivative

wanna graph this

,w roots 9t^2 - 12t + 2

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by cjfjfjfkfi#7363

[cyan pelican]

here r the critical points

man

hate this question

wanna sleep its 5am but need to finish

[cyan pelican]

@slow crow

i give up i need to sleep ill just hand in whatever i have tomorrow

im sorry thanks alot for the help tho

got school in 4 hours i need sleep

.close

[cedar kiln]

Channel closed

Closed by @cyan pelican

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[onyx grail]

hello! Does anyone know how to find the volume and total surface area of a quarter pipe?

[crimson sedge]

These are just a quarter of the volume and surface area of a regular pipe

[onyx grail]

what’s a regular pipe?

[crimson sedge]

Like, full pipe?

Not just a quarter pipe

[onyx grail]

a half pipe?

[crimson sedge]

No

A full pipe

In all its glory

[onyx grail]

Sorry this is for a math designing assignment, I have not worked with full pipes 🥲🥲🥲

Only half pipes

[crimson sedge]

What have you worked with?

[onyx grail]

Only half pipes

[crimson sedge]

Oh okay that'll do

Well a quarter pipe is just half of a half pipe

So do the calculations for a half pipe then divide surface area and volume by 2

[onyx grail]

Oh ok! 😄 that’s doe the volume?

For*

[crimson sedge]

Both the volume and surface area

[onyx grail]

Oh! Thank you ! It was really that easy ? 😭😭😭

[crimson sedge]

Yep, a quarter is half a half, it's as simple as that

If that's all you need, you can now .close this channel

[onyx grail]

I’m not sure if I have done my calculations right for the half pipe tho tbh

[crimson sedge]

You can send them here

[onyx grail]

ok

please.. if I did it all wrong Ima cry 😭😭

[crimson sedge]

I am gonna be honest, I expected something else and I am a little baffled

[onyx grail]

💀

is it really that bad

where did I go wrong 🥲🥲🥲

[crimson sedge]

Nah I just have no idea what the frick I'm looking at

.close

[cedar kiln]

Channel closed

Closed by @long cosmos

Use .reopen if this was a mistake.

[crimson sedge]

.reopen

[cedar kiln]

✅

[onyx grail]

💀😭

Is it really that bad?

[crimson sedge]

If anyone understands what is going on feel free to take over

[cedar kiln]

@onyx grail Has your question been resolved?

[onyx grail]

😭😭😭😭

[bronze echo]

I have a ques pipe and cylinders are not same?

[crimson sedge]

Idk how this works

[onyx grail]

.close

[cedar kiln]

Channel closed

Closed by @onyx grail

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[drifting ledge]

what are pi/2 pi/4 pi/6 pi/8 pi/10 pi/12

[dusk finch]

numbers?

[nova glacier]

piece of cake 😉

[cedar kiln]

@drifting ledge Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[spiral path]

Hello

[spiral path]

How to solve this equation

What are the steps?

What does it mean that the log is squares, the x is always positive?

[tropic oxide]

the numerator is $(\log_{2/3}|3-x|)^2$

[wraith dagger]

Ann

[spiral path]

That means the value is always positive, right?

[tropic oxide]

no, the value is always nonnegative

but you cannot say that it is always positive

[spiral path]

So it can be also 0

@tropic oxide I got the value |3-x| >= 1

Should there be a system

[tropic oxide]

... ?? how did you get that |3-x| should be >= 1?

[spiral path]

From log

Base is 2/3

Exponent is 0

And it equals abs( 3-x)

Isn't it correct?

Hm?

[tropic oxide]

you confused yourself or didn't do this properly...

i sure am confused as to what you did

[spiral path]

How to solve then?

Can you show your way

[tropic oxide]

$\frac{(\log_{2/3}|3-x|)^2}{x^2-5x} \leq 0$

[wraith dagger]

Ann

[tropic oxide]

numerator is undefined when x=3, zero when |3-x|=1 (thus when x=4 and when x=2), and positive elsewhere.

the denominator is undefined at x=0 and at x=5.

thus, disregarding these special cases, we may divide out by the numerator and be left with 1/(x^2 - 5x) < 0 [and now equality cannot happen]

which is equivalent to x^2 - 5x < 0

[spiral path]

Wait, why are we allowed to divide

With an unknown

[tropic oxide]

it is known to be positive everywhere that we care about

[spiral path]

I still can't understand this step

Wait let me draw

[tropic oxide]

$(\log_{2/3}|3-x|)^2$ is positive for $x \neq 2, 3, 4$

[wraith dagger]

Ann

[tropic oxide]

yeah sure

[spiral path]

I don't get why we must do this😭

What are the general steps

[tropic oxide]

you want a one size fits all strategy that will work on every single ineq you will come across...?

it's not that we "must" do this

if you dont want to do what i suggest, then dont

[spiral path]

I accept anything as long as there is a good reason (and explanation as to why)

[tropic oxide]

why as in "why is this allowed" or "why do we do this"

[spiral path]

Why we do this

[tropic oxide]

makes the equation simpler

gets the logarithmic shit out of our hair now that we've properly accounted for it

[spiral path]

Hmm

Then the logarithmic would be positive for R besides 2,3,4

[tropic oxide]

yes i said this here

[spiral path]

I understand why it's 3
But 2 and 4?

If it's in an abs, then any number would be positive

|3-4|>0

No?

[tropic oxide]

what is $\log_{2/3}|3-4|$?

[wraith dagger]

Ann

[spiral path]

Oh

It would be 0

This stuff would happen when there is abs, right?

3 undefineds

[cedar kiln]

@spiral path Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[keen estuary]

can someone check if i messed this one up, please

im unsure because wolfram is going crazy

homogén = homogeneous
általános megoldás = general solution

is my approach completely wrong here?

i think you need to go for the homogeneous equation, or im not sure what to do here

[cedar kiln]

@keen estuary Has your question been resolved?

[worthy cairn]

I used integrating factor and got the same solution as wolfram

It seems hard to guess a particular solution t9 the problem

[worthy cairn]

Specifically you can show that a polynomial is NOT a particular solution

[cedar kiln]

@keen estuary Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[void star]

i started learning about rational equations a few days ago and need to get the LCM of 9x^2 - 1 and 1 - 3x
i was taught that i need to factor the equations as much as possible and then add the elements without anything repeating, and if something repeats i grab the thing that repeats with the highest exponent
ive got 9x^2 - 1 to (3x - 1)(3x + 1) but i dont know where to go from there

[obsidian coral]

Hint: factor -1 from 1 - 3x

[void star]

how do you factor -1 from 1 - 3x

do i just flip the operations?

[obsidian coral]

Sorta

Take (2 - x^2), factoring out a -1, that becomes -1 * (x^2 -1)

[void star]

i got it to -(3x - 1)

oh wait, i can take it from here now i think

[obsidian coral]

Yes like this

I was saying sorta because you don't just only flip the signs, you need the negative outside too

[void star]

yea, i've forgotten that

[void star]

anyways i do not think this is true anymore

i got the lcm of -(3x-1)(3x+1)

[obsidian coral]

Yes exactly

[void star]

but how do i apply it now

[obsidian coral]

Now you need to multiply each fraction to get the proper common denominator

[void star]

i have to multiply the first one with -1 to get the - in the denominator

and the second with 3x + 1?

[obsidian coral]

Yep

[void star]

so i tried going as far as i can with this but i managed to get to $\frac{-6x-1}{9x^2+1}$ which is a bit different from the correct $\frac{6x+1}{9x^2-1}$ in my book

[wraith dagger]

qweasdzxc

[cedar kiln]

Show your work, and if possible, explain where you are stuck.

[delicate patrol]

x = {1,2,3} ;A = {1,{1,2},{{1,2,3}}}
is X subset of A?
can u answere this guys?
and what are the power set?

[void star]

#❓how-to-get-help

$\frac{3x}{(3x-1)(3x+1)}-\frac{1}{-(3x-1)}$
this is when i factorize them as far as i can, then after getting the LCM
$\frac{-3x}{-(3x-1)(3x+1)}-\frac{3x+1}{-(3x-1)(3x+1)}$ i multiplied the first fraction with $-1$ and the second one with $(3x+1)$
after i do the operations:
$\frac{-3x-(3x+1)}{-(3x-1)(3x+1)}$
$\frac{-3x-3x-1}{-(3x-1)(3x+1)}$
$\frac{-6x-1}{9x^2+1}$

$\frac{3x}{(3x-1)(3x+1)}-\frac{1}{-(3x-1)}$
this is when i factorize them as far as i can, then after getting the LCM
$\frac{-3x}{-(3x-1)(3x+1)}-\frac{3x+1}{-(3x-1)(3x+1)}$ i multiplied the first fraction with $-1$ and the second one with $(3x+1)$

after i do the operations:
$\frac{-3x-(3x+1)}{-(3x-1)(3x+1)}$
$\frac{-3x-3x-1}{-(3x-1)(3x+1)}$
$\frac{-6x-1}{9x^2+1}$

[wraith dagger]

qweasdzxc

[void star]

anyone?

[keen estuary]

im out of place, and will prolly have to retake this exam but thanks for answering man!

[obsidian coral]

First thing is the denominator, you started with 9x^2 - 1 then factored to (3x - 1)(3x + 1), then somehow made it 9x^2 + 1

[void star]

oh.

[obsidian coral]

Second is the negative sign that was with the LCM, if it's -(3x - 1)(3x + 1) then expanding gets -(9x^2 - 1)

And the numerator is -6x - 1, factor out a -1

And you should see what happens

[void star]

yeah but factoring 1 - 3x gives -(3x-1)

which is where the negative sign comes in the lcm

[obsidian coral]

$$\frac{-3x-(3x+1)}{-(3x-1)(3x+1)}$$
$$\frac{-3x-3x-1}{-(3x-1)(3x+1)}$$
$$\frac{-6x-1}{9x^2+1}$$

[wraith dagger]

dldh06

[obsidian coral]

Those steps

How does the denominator go from -(3x - 1)(3x + 1) to (9x^2 + 1)?

[void star]

i mustve miscalculated something then

oh i have

doing the a^2 - b^2 formula and then flipping the signs will give you 9x^2 + 1

oh wiat

wait

i dont get it

[obsidian coral]

You expanded (3x - 1)(3x + 1) using a^2 - b^2, correct?

[void star]

yes

[obsidian coral]

What do you get when you do that?

[void star]

i represent 9x^2 as (3x)^2

and 1 can be put on whtaever exponent so i put it on the 2nd power

you get (3x - 1)(3x + 1)

[obsidian coral]

I mean expanding (3x - 1)(3x + 1), what do you get?

[void star]

9x^2 - 1^2

[obsidian coral]

Yes

Now don't forget the -1 that was on the outside so it's -(9x^2 - 1^2)

Do you agree?

[void star]

wait where on the outside is -1

where are we right now

[obsidian coral]

-(3x - 1)(3x + 1)
Expanding this

[void star]

ah

[void star]

yes

[obsidian coral]

So this is what you should have, right?
-(9x^2 - 1^2)

[void star]

oh yeah

so the lcm is indeed the problem

[obsidian coral]

$$\frac{-6x-1}{9x^2+1}$$

[wraith dagger]

dldh06

[obsidian coral]

That is what you showed

[obsidian coral]

after i do the operations:
$\frac{-3x-(3x+1)}{-(3x-1)(3x+1)}$
$\frac{-3x-3x-1}{-(3x-1)(3x+1)}$
$\frac{-6x-1}{9x^2+1}$

[wraith dagger]

dldh06

[obsidian coral]

The very last line

[void star]

thats where the problem is

[obsidian coral]

Yes

[void star]

so it should be 1 - 9x^2?

[obsidian coral]

Now you can keep it like this
-(9x^2 - 1^2)

[void star]

oh

[obsidian coral]

Because as I mentioned before, factor out -1 from the numerator

Factor out -1 from -6x - 1

What do you get?

[void star]

uh

-(6x+1)

[obsidian coral]

So you should have $\frac{-(6x+1)}{-(9x^2 - 1)}$

[wraith dagger]

dldh06

[void star]

okay

[obsidian coral]

Do you see how there is something that cancels out?

[void star]

the -1

[obsidian coral]

Yes

[void star]

and then thats the result

oh wow this was way simpler than i thought

[obsidian coral]

And that matches the book now, right?

[void star]

yeah

alright hang on im going to write this down and figure out how to close this

[obsidian coral]

.close to close the channel

But do it when you're done

[void star]

and also quick question

its possible to simplify this further right

by using a^2 - b^2 on the denominator after cancelling -1

[obsidian coral]

You can factor but there's no point to it

[void star]

alright

[obsidian coral]

Because you just end up with $\frac{(6x+1)}{(3x - 1)(3x + 1)}$

[wraith dagger]

dldh06

[obsidian coral]

And there's nothing you can cancel out

[void star]

i see okay

.close

[cedar kiln]

Channel closed

Closed by @void star

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[split crest]

Idk how to start

[dull oxide]

Did chatgpt give you this integral?

[cosmic steppe]

LAUGHING OUT LOUD (lol)

[dusk finch]

doesnt seem to be easy

I cant even factor the denominator

,w calc int_1^2 (x^3+x)/(x^4+4x-1) dx

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by MathIsAlwaysRight#4079

[lyric narwhal]

😭

[vagrant elbow]

Are those-

Cube roots of unity

[crimson sedge]

no it says w is all solutions for w^4 + 4w -1 = 0

[vagrant elbow]

Interesting I've never seen sigma notation used like that

[split crest]

No

I just asked to write it in latex

To post it here

[dull oxide]

Who gave you this integral, because there is no pretty solution

[cedar kiln]

@split crest Has your question been resolved?

[split crest]

Its a test

At school

[dire geode]

show the test question

[dull oxide]

We are missing context

[split crest]

Its literally left like this

Calculate following integral

[dire geode]

screenshot or picture is best

[split crest]

Bro what 😂 i just told you

[split crest]

This is the test question

[dire geode]

yea i get that you think you typed it correctly

can't be sure so just screenshot or take a picture

[astral bay]

that's not the test question, it's the output from chatgpt when you asked it to write the question in latex

[split crest]

Identical

[dull oxide]

We are missing context still

You are leaving something out because there is something wrong with this integral

[dire geode]

Again, that's your handwriting. If you're gonna keep evading helpers' requests to help you, just close the channel and stop wasting everyone's time

[cedar kiln]

@split crest Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ionic thistle]

i just want to know the idea of the q

[dull oxide]

which one

[ionic thistle]

two of them

i guess its the same idea right?

[lapis maple]

not really

have you seen the pattern in the first one

or the difference

[ionic thistle]

i did

[dull oxide]

These are series

And you can solve them as such

For problem 70: $\newline r_{1, n}=n\newline r_{2, 1}=1 \newline r_{2,n}=r_{1,n-1} + r_{2,n-1}=n-1+r_{2,n-1}$

[wraith dagger]

SWR

[dull oxide]

So you need to know how to solve the arithmetic series $\newline r_{2,n}=n-1+r_{2,n-1}$

[wraith dagger]

SWR

[ionic thistle]

okayy thank u

.close

[cedar kiln]

Channel closed

Closed by @ionic thistle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ocean hinge]

What does it mean that I'm supposed to solve linear equations? It gives me an equation and then tells me to write the solution?

[tropic stone]

can you send a pic

[ocean hinge]

its in swedish but sure

removed the text

but first quesiton is write an equation for the blue line, which is y=2x + 1

and then the second question is write the equations solution

[livid hound]

the solution will be the intersection point of the two lines

[ocean hinge]

alright so x=3 y=7?

okay so if it's the other way around that i've got the solution and they tell me to write an equation I just make up an equation that goes thru that specific point?

or do I need to make two equations that goes thru that point?

[crimson sedge]

Or you can do
y-y1=m(x-x1)

Just change the m

And x1 , y1 are solutions

It will make 2 random line with that solution

[ocean hinge]

A linear equation system has the solution=
The equation system has two different equations that both got X and Y.
Give an example:

I may have just misunderstood the question

.close

[cedar kiln]

Channel closed

Closed by @ocean hinge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[inland canopy]

.

[empty umbra]

Help on this q

[cedar kiln]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[empty umbra]

4

I have begun and got stuck mid way

[lapis maple]

!show

[cedar kiln]

Show your work, and if possible, explain where you are stuck.

@empty umbra Has your question been resolved?

[empty umbra]

No

[cedar kiln]

@empty umbra Has your question been resolved?

[silent bobcat]

First of all, a better image would be nice for people helping, so that we don't feel like skipping ahead @empty umbra
Also, if you have begun and are stuck midway, that means you have some work you did originally that you're not showing us. We are waiting for you to show it

If you don't, then nobody is going to help you

Good luck

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[spiral badge]

A rectangular plot of land with an area of ​​3,750 m² is divided into three rectangular plots of equal size as shown in the figure

What were the dimensions of the plot before the division? Save calculations

[spiral badge]

Idk how to begin with

[crimson obsidian]

Does doing 3750/3 count as calculation

[lapis maple]

that does not give dimensions

can you see that length is 2* width

[spiral badge]

3750:2? @lapis maple

1250

,w 3750:2

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by choco#7206

[spiral badge]

1875

,calc 1875:2

[wraith dagger]

Result:

[]

[lapis maple]

no

[spiral badge]

,calc 1875 : 2

[wraith dagger]

Result:

[]

[spiral badge]

Stupid bot

Trash

[lapis maple]

,w 6w^2 = 3750

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by [code{RED}]#8104

[lapis maple]

it’s 50 by 75

[spiral badge]

How did you do that

@lapis maple <@&286206848099549185>

[south narwhal]

#❓how-to-get-help

not here

[spiral badge]

<@&268886789983436800>

[calm sierra]

@azure drum use an unoccupied channel, see #❓how-to-get-help

[cedar kiln]

@spiral badge Has your question been resolved?

[cedar kiln]

@spiral badge Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

If a=12 and h = 25, then the volume a triangular pyramid is?

[dull oxide]

[rain drift]

please stop closing and reopening channels

[crimson sedge]

im not getting any help

[grand forge]

he closed the channel

you left

[crimson sedge]

also sorry

[grand forge]

1 minute

its was 1 minute

[rain drift]

dude you closed it after 1 min

[grand forge]

and u closed the channel

[crimson sedge]

sorry

[grand forge]

no you're not

[crimson sedge]

but i am

[rain drift]

anywho, what is the formula for the volume of a triangular pyramid?

[dull oxide]

You mean A, not a.

[crimson sedge]

oh

[grand forge]

probably should crop out name if its your pic

[crystal raptor]

SWr 7th grade lol

hang on, 7th grade.. (nvm too non american)

[crimson sedge]

well its not mine its from a friend

[violet night]

are you 12

[crimson sedge]

no 14

[violet night]

(UK citizen moment)

[grand forge]

whats 7th grade uk equiv?

year 8?

[crimson sedge]

im am american

[grand forge]

i figured

[dull oxide]

It's darkboy's pic

[crimson sedge]

https://tenor.com/view/emoji-smiley-whistling-off-topic-gif-8328609

[grand forge]

you have the formula

plug in the numbersd

[crimson sedge]

ok next

[grand forge]

???

there is no next

[crimson sedge]

oh

well then

[violet night]

have you actually tried writing down and playing around with what people have suggested ?

[crimson sedge]

yes i have

[grand forge]

no you havent

[violet night]

show it

[crimson sedge]

hold up

i needed somewhere to noted it

[grand forge]

you dont have a pen?

[crimson sedge]

not at the moment

[grand forge]

so you havnet done this than have u

so you just lied

[crimson sedge]

bruh why do yall think im lieing

[upper abyss]

Aggressive

[crimson sedge]

.close

[cedar kiln]

Channel closed

Closed by @gentle isle

Use .reopen if this was a mistake.

[grand forge]

you cannot write down numbers if u do not have a pen

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

can someone explain how the difference of the sums results in that?

nvm

.close

[cedar kiln]

Channel closed

Closed by @finite reef

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[oblique prawn]

Five cards are marked with the numbers 1,2,3,4,5, shuffled and 2 cards are drawn. How many different 2-card combinations are there?

[minor pasture]

if you pick one card how many ways would you have to do that?

[oblique prawn]

is this a permutation or combination

[minor pasture]

does the order matter?

[oblique prawn]

i dont understand what order matters in permutation and order doesnt matter in combinations mean

like idk what order its talking about

[minor pasture]

if i have 1,2 is it the same as 2,1?, ask yourself that everytime you get a comb. problem like this and you're stuck ig

[dull oxide]

It asked for 2-card combinations, right?

[oblique prawn]

ye

oh

xd lol i got confused cuz my teacher was talking about how like a school locker combination is technically a permutation

[dull oxide]

yes

It is

It's very confusing

[rain drift]

yeah sometimes it's hard to distinguish which one you want to use. happens to me all the time depending on how the problem was asked

[minor pasture]

exactly

[gritty viper]

ye one of many examples where things have a precise meaning in math and a different, much less precise meaning to most people

[dull oxide]

This should be called a permutation lock, not a combination lock, because the order in which you put in the numbers matters.

It's confused many a-student

[oblique prawn]

How many different 7-digit telephone numbers can be written if the digit 0 cannot appear among the first 3 digits?

[rain drift]

dang I never thought about that but you're totally right. BRB I'm writing a petition to Joe Biden to get that fixed

[gritty viper]

This one is at least probably an example of mathematicians taking an established English word and giving it some very specific meaning

[rain drift]

Did you get the correct answer for the first problem before we move onto this one?

[oblique prawn]

so i figured out there is 9 possible digits for each of the first 3 digits of the phone number and the rest of the digits have 10 possible digits

[oblique prawn]

i think

[gritty viper]

the opposite is so infuriating lol

[rain drift]

what did you get?

[gritty viper]

I've seen people call linear growth "exponential"

[oblique prawn]

i did 5 choose 2 and got 10

[rain drift]

bingo

if you ever need to double check yourself and the problem is small enough just write out the possibilities

in this case we get

12 = 21
13 = 31
14 = 41
15 = 51
23 = 32
24 = 42
25 = 52
34 = 43
35 = 53
45 = 54

10 total 🙂

[oblique prawn]

what about 41

[gritty viper]

14

[rain drift]

it's the same as 14

[oblique prawn]

so in combinations swapped orders dont create a different possibility

[gritty viper]

Right

[rain drift]

yeah exactly

a combination is a way to "divide out" the duplicates from a permutation

[gritty viper]

Combination is like how many ways can you choose a subset

[rain drift]

that's a more accurate way to say that

[gritty viper]

It also doesn't allow you to choose something like 11

permutations wouldn't either

[oblique prawn]

wait really

[gritty viper]

yeah so the telephone example isn't a permutation

[oblique prawn]

From a group of 6 people, how many different ways can you select a president, vice-president & secretary?

i did 6!/3!

[gritty viper]

that works yeah

[rain drift]

yep that works because in this case order does matter

[gritty viper]

since 3 is the number of people not being chosen for positions

(and order matters)

[dull oxide]

💯 🥇

[oblique prawn]

How many ways can Mrs. Sullivan choose two students from 27 to help put away calculators at the end of class?

[rain drift]

so this one would be a combo since order shouldn't matter here

[oblique prawn]

oh wait nvm i keep forgetting which one the order matters and which one it doesnt

You have enough tickets to play 6 different games at the amusement park. If there are 14 games, how many ways can you choose six?

so this one you would do 14 choose 6

[rain drift]

yep exactly

order of the games does not matter

[oblique prawn]

How many different 12-letter arrangements can be made using the letters in the word INDIANAPOLIS?

ok how is this a permutation

[dull oxide]

NO and ON are different words

order of the letters matters

But, my sweet child, you gotta watch those repeated letters

[rain drift]

oooooh right I hated these haha

[oblique prawn]

ok ty

.close

[cedar kiln]

Channel closed

Closed by @oblique prawn

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[old viper]

i tried a lot of different methods on trying to find OAD but keep finding different answers, can someone help?

[obsidian coral]

tried a lot of different methods on trying to find OAD but keep finding different answers
What methods did you use?

[old viper]

hold on i was in the middle of typing the method i tried to solve it and caught my mistake

what i used was

180-29 = x and then 180 x

180 - x

(originally)

then im gonna try 90 - 29

= 61

but the angle looks acute, not obtuse

180 - 61 = 119

okay nevermind, i'm stuck again

would BCO=OAB ?

i tried doing 2(ABC)

Then adding thatto 131

then i subtracted the sum from 360

360 - 229 = 131

but i don't know if i should split it

or not because i don't know it it'll be correct

is anyone there?

<@&286206848099549185> can you help me solve the angle of OAD, i'd like to know how to solve an angle like this in case it comes up on my paper 2 exam on wednesday

[cerulean harness]

Inscribed Quadrilateral Theorem: A quadrilateral can be inscribed in a circle if and only if the opposite angles are supplementary. If A B C D is inscribed in , then m ∠ A + m ∠ C = 180 ∘ and m ∠ B + m ∠ D = 180 ∘ .

In short: The opposite angles sum to 180 degrees in an inscribed quadileteral

Note 2: Angle OCT = 90 degrees

so OCD is ?

and hence since OCD+OAD = 180
So OAD= ?

@old viper

[old viper]

hold on i gotta write down what im supposed to do to get ocd

ok so 180-131 = 49

hold on i think im looking at it wrong

bco = oac?

= 37 ?

nd then

oh no the session expired

the page refreshed 😦

hold on lemme get back on tht question

okay here we go

OCD = 90-20 = 70

OAD = 180 - 70 = 110?

no that's BAD

OAD = BAD - OAB

[cerulean harness]

that's it

think it inside the small quadiletral not the bigger one

OACD

OCD and OAD are opposite angles

well there're many other ways to solve it

u do wahtever suits u the most

[old viper]

can you show me an alternative way

that took me like 2 hours to grab

(literally)

but doesn't the lines have to be meeting the circumference for that rule to be valid?

OAD is an acute angle how couild it be 110 degrees?

BAD looks more like the angle I solved for

i'm going to punch the 110 in though

[cedar kiln]

@old viper Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[violet flume]

find 2 solutions then describe how they repeat

[cosmic spindle]

Use unit circle

[violet flume]

maybe more clear to write it distributed but yea

[cosmic spindle]

Isn’t it 4n+1?

[violet flume]

its $\frac{\pi}{2} + n\pi$

[wraith dagger]

jan Niku

[cosmic spindle]

It’s 2k pi +- pi/2

[cosmic spindle]

Oh nvm they same

[cedar kiln]

Channel closed

Closed by @last sapphire

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[floral tapir]

I understand that statement b is wrong since c = 0 would lead to a zero vector as an eigenvector which is wrong by definition. But what about statement A, how would i go about proving/disproving. Maybe because eigenvalues are unique?

[short blade]

how many eigenvalues can a 2x2 matrix have?

[floral tapir]

Well im assuming 2

[short blade]

yes, at most 2

[floral tapir]

Oh awesome

So thats it

Thanks

[short blade]

yes, the sum of the eigenvalues couldn’t be a third eigenvalue. you can also just give a counterexample by constructing any matrix with 2 distinct eigenvalues

[cedar kiln]

@floral tapir Has your question been resolved?

Channel closed

Closed by @floral tapir

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[primal ginkgo]

My current data:
sample mean= 42
sample standard deviation = ???
n = 337
alpha=0.05
alpha/2=0.025
df = 336

I have no idea how to calculate for the sample standard deviation for this question

[drifting marlin]

what is the question?

[deep plover]

gm

[primal ginkgo]

i have to calculate for confidence interval

im using the t-score

[drifting marlin]

ok so the statistic you're observing is the sample proportion

[primal ginkgo]

but im missing standard deviation

[drifting marlin]

now does it make sense for the sample proportion to have a mean of 42?

[primal ginkgo]

well i guess not

[drifting marlin]

indeed not

[primal ginkgo]

so would that be the standard deviation?

[drifting marlin]

the standard deviation is not 42 either, no

[primal ginkgo]

welp im not sure what the use of the 42 is

[drifting marlin]

the 42 is used in computing a proportion

[primal ginkgo]

ahhh

[drifting marlin]

what is the sample proportion?

[primal ginkgo]

uh

im not gonna lie i havent studied proportion too much

I just have the CI formula for it

[drifting marlin]

show me whatever you have

[primal ginkgo]

I only have this and the data i have above

sample mean= ???
sample standard deviation = ???
n = 337
alpha=0.05
alpha/2=0.025
df = 336

[drifting marlin]

well again, sample mean = 42 is complete nonsense

you need to compute $\hat p$

[wraith dagger]

Steakanator

[primal ginkgo]

I was a little bit confused with the proportion formula because I wasn't too sure how to calculate for p hat

[drifting marlin]

do you know what a proportion is in general?

[primal ginkgo]

uh

no...

yea sorry, proportion is completely foreign to me

[drifting marlin]

well you should probably familiarize yourself with the word

it's not a probability-specific word, it's just general English

once you know what it means, then it's just a matter of understanding that $\hat p$ is the sample proportion, ie the proportion that is present in your sample

[wraith dagger]

Steakanator

[primal ginkgo]

I mean i guess i do lowkey have an understanding of proportion in general. Like 1/4 a pie

but im still confused as to how p-hat is calculated for in stats

[drifting marlin]

the second screenshot you posted explains how the proportion is calculated

[primal ginkgo]

yup, but i mean the p-hat specifically

since you said it wasn't the 42 either

its used to calculate p-hat

The only other way I can make sense of it is the 42/337, but i dont know if thats correct

[drifting marlin]

the sample proportion, ie the proportion that is present in your sample
if you understand what proportion means, and you understand that these 337 individuals make up your sample, then the connection should be apparent

[primal ginkgo]

im sorry, im really dense when it comes to mathematical explanations

so p-hat would be the 42/337?

[drifting marlin]

yes

[primal ginkgo]

okay i see, thank you so much

.close

[cedar kiln]

Channel closed

Closed by @primal ginkgo

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hollow grotto]

The integral of 4e^2x is 4e^2x/2?

[tropic oxide]

+C but yes

[hollow grotto]

Ty

.close

[cedar kiln]

Channel closed

Closed by @hollow grotto

Use .reopen if this was a mistake.

[chilly fractal]

gm

[tropic oxide]

@chilly fractal casual chat goes in #discussion or #chill

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[untold rampart]

Can someone explain to me what I'm doing wrong here?

[untold rampart]

The absolute value of z is a scalar quantity, right? It's just the distance from the origin. So no imaginary parts. Which is why I set sqrt(z)=-1

Correct answer is E btw

[short blade]

why did the 1 and sqrt(a^2 + b^2) disappear

[lapis maple]

yeah lol

[untold rampart]

Cuz I set sqrt(a^2+b^2) equal to -i and tried to solve that

[short blade]

sqrt(a^2 + b^2) is a real value

[untold rampart]

I mean a+bi

[lapis maple]

but how do you know that

i would do some squaring

[untold rampart]

Doesn't the absolute value of any complex numbers have to be real?

[lapis maple]

so we get rid of sqrts

[short blade]

yes but you’re still making too many jumps

nothing would suggest sqrt(a+bi) = -i

[wraith dagger]

[code{RED}]

[untold rampart]

But I feel like squaring too sides would make it too messy. There's too many terms so I feel like it wouldn't be the correct way

I'll try it

[short blade]

your assumption is not correct anyhow

my gut says that squaring is actually a good idea here

[untold rampart]

alright

[lapis maple]

$a^2 + b^2 = 9a + 9bi + (18i+6)\sqrt{a+bi} -8 + 6i$

[wraith dagger]

[code{RED}]

[lapis maple]

i got this

[short blade]

maybe there’s an easier way

[lapis maple]

then rearrange

[short blade]

let w = sqrt{z}

[lapis maple]

$-(18i+6)\sqrt{a+bi}= 9a + 9bi -8 + 6i-(a^2 + b^2)$

[wraith dagger]

[code{RED}]

[lapis maple]

oh

that’s an awful lot of terms

[short blade]

then (w + i)3 + 1 = |w|^2
so
3(a + bi + i) + 1 = a^2 + b^2

[lapis maple]

,w (6+18i)^2

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by [code{RED}]#8104

[lapis maple]

that

[short blade]

then b = -1, and a = 3
so w = 3 - i, and z = w^2 = 8 - 6i

[lapis maple]

nice

[short blade]

did what i did make sense saif

[lapis maple]

( 9a + 9bi -8 + 6i-(a^2 + b^2))^2

[untold rampart]

ok hold on I'll try that. So you set sqrt(z) as another complex number

[lapis maple]

,w ( 9a + 9bi -8 + 6i-(a^2 + b^2))^2

[short blade]

we let w = sqrt{z} yes

[lapis maple]

yeah

[untold rampart]

OK I just solved like you did. I understand now

thanks!

.close

[cedar kiln]

Channel closed

Closed by @untold rampart

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[scarlet plaza]

hello i need some help on this whole page 😅

[cedar kiln]

@scarlet plaza Has your question been resolved?

[cedar kiln]

@scarlet plaza Has your question been resolved?

[scarlet plaza]

<@&286206848099549185>

[cedar kiln]

@scarlet plaza Has your question been resolved?

[scarlet plaza]

<@&286206848099549185>

[scarlet plaza]

.close

[cedar kiln]

Channel closed

Closed by @scarlet plaza

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[past wigeon]

how do i find the volume with x?

[cedar kiln]

@past wigeon Has your question been resolved?

[cedar kiln]

@past wigeon Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[upper narwhal]

help pls. this question asks me to write the equation to find the vertex of this equation;
y = x^2 + 7

[vague rapids]

You mean co-ordinates?

[upper narwhal]

yep

[vague rapids]

Vertex is given by -b/2a,f(-b/2a)

[upper narwhal]

what is f in the equation?

[iron saffron]

y = ax^2 + bx + c

f(x) = x^2 + 7

f(1) = 1^2+7

f(-b/2a), you can do it

[upper narwhal]

yeah but what does the variable f represent in the equation?

[iron saffron]

f is not a variable

is the function

[crimson obsidian]

f(x)=x+1 is a function whose input is x and output is x+1

Here also f(x)=x^2+7 is a function whose input is x and output is x^2+7

[glossy shoal]

Im wondering why we dont directly find the vertex? Its already vertex form

[iron saffron]

because he doesn't know what is a function so it doesn't make too much sense to make this exercise in the first place

[glossy shoal]

oh ok

[crimson obsidian]

If you put input which is x as 1, the way to write it is f(1)=1^2 + 7

[radiant topaz]

why does this need function knowledge?

[iron saffron]

He represented the equation as y = x^2 + 7

f(x) = x^2 +7

it's like I say: what's the capital of USA

[crimson obsidian]

y and f(x) is same thing

[iron saffron]

but I don't know what USA means

Before solving an exercise you must know every word that is in the question

[radiant topaz]

well but do we really need to introduce functions to tackle this problem?

[iron saffron]

eitherway you're just using "pre-fabricated" formulas to solve something without knowing what are u doing

i'm quiet sure

[crimson obsidian]

Or putting variable as number also would do the work

[radiant topaz]

I think we learnt about vertex of quadratic equation even before functions was taught to us

[iron saffron]

To me, you need the knowledge of what is a function earlier.

The context is important

[crimson obsidian]

I've yet to study what is vertex

[radiant topaz]

well probably link wasn't introduced to it yet

[iron saffron]

anyways, no more answers until the person who asked say something, tbh xd

[radiant topaz]

xd

[cedar kiln]

@upper narwhal Has your question been resolved?

Channel closed

Closed by @upper narwhal

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dusk gate]

After I figured out the first answer (a), I couldn't find the rest

[cedar kiln]

@dusk gate Has your question been resolved?

[dusk gate]

No

[stoic quarry]

u r not supposed to put quiz questions here

[dusk gate]

Wait what?

What's the difference tho💀

[dusk gate]

No this quiz is done in paper in class

But I still don't get it when the teacher gave us the pdf version to think out the answer

[cedar kiln]

@dusk gate Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[quick atlas]

Hi i need help with probabilities i don't know what to do

[cedar kiln]

@quick atlas Has your question been resolved?

[cedar kiln]

@quick atlas Has your question been resolved?

[cedar kiln]

@quick atlas Has your question been resolved?

[quick atlas]

No

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[prisma bluff]

When we are making x s

[prisma bluff]

When we make x the subject, can there be multiple solutions?

[dire geode]

yes