A, no necesitas usar potencia
#help-13
vivid shoal
es que tengo x a la 2
vivid shoal
:VVVVVV
te digo que tengo una x
no esta definido el valor
es una X a la 2
x^2 +
runic garnet
Sí, esta bien
vivid shoal
xd
runic garnet
Taba confudido
Ahora entiendo
escribe x^2
Sip
Centro: (0,2) así el primero terminó es (x-0)^2 = (x)^2 = x^2
vivid shoal
:v como se pone?
vivid shoal
Centro: (0,2) así el primero terminó es (x-0)^2 = (x)^2 = x^2
pues si
el segundo quedo en 4- i*i
runic garnet
es lo q tienes ahora? o has hecho mas
cedar kilnBOT
@vivid shoal Has your question been resolved?
cedar kilnBOT
cedar kilnBOT
Available help channel!
river rapids
Ok so basically the question goes a little like this: You got a plane company that sells ticket for 1000$ each, and the plane has a maximum capacity of 200 people. It's legal for the company to sell more tickets than they have seats, but if someone with a ticket is refused access to the flight, they have to be refunded the 1000$ for the ticket, plus 1000$ for compensation. We know that there is a 7% chance that a person with a ticket won't show to the flight. If the company decided to sell 202 tickets, what should be their average profit? (profit being the money from the tickets minus the refunds).
I haven't even figured out where to start. This is what I was told I should start with?? Ill send a picture
river rapids
tropic oxide
,rccw
wraith daggerBOT
river rapids
Oh sorry revenue, thats a translation error on my part
tropic oxide
okay
river rapids
Also I think the binomial law needs to be used, or so my teammate told me
tropic oxide
so we have 202 tickets each sold for $1k
for 200 seats
the number of no-shows follows a Bin(202, 0.07) distribution
we need to pay if and only if there are 0 no-shows (in which case we're on the hook for 4k) or exactly 1 no-show (in which case we're on the hook for 2k)
if there are 2 or more no-shows everyone can fit on the plane and we don't need to do any refunds
and we have a constant $202k in our pockets before any refunds
does that make sense to you
river rapids
yes
tropic oxide
whats the probability of there being exactly 0 no-shows
river rapids
0.93^201 x 0.07
tropic oxide
that times 202.
river rapids
wha
tropic oxide
202 * 0.07 * 0.93^201
there are 202 choices for who among the 202 passengers is the no-show
river rapids
ooooh okay
tropic oxide
yeah anyway like
the average refund amount is 4000 * 0.93^202 + 2000 * 202 * 0.07 * 0.93^201
tropic oxide
yes that'll be expected revenue
river rapids
Thank you. You are a savior
Oh yeah if there's another part to the question is that something you can also help me with?
bright sky
Calculate the length of the arc corresponding to the central angle 𝛼. The radius of the circle is 4.0 cm, and the distance between points O and P is 10.0 cm.
I need help with getting started.
crimson sedge
look at the right angle triangle and use trig
remote tulip
cos(x) = adjacent / hypotenuse
bright sky
I was trying to solve with sin(x).
I still don't get why I should calculate it with cos(x).
crimson sedge
,tex .sohcahtoa
wraith daggerBOT
Toby
bright sky
Sigh, I had drawn the alpha to a wrong corner🤦♀️ Than you and apologies for my stupidity.
.close
prisma garden
I am working on my stats review (I don't know how to do any of it lol) and after getting a friend to help neither of us can figure this one out:
Fifty rounds of a new type of ammunition were fired from a test weapon, and the muzzle velocity of the projectile was measured. The sample had a mean muzzle velocity of 863 meters per second and a standard deviation of 2.7 meters per second. Construct and interpret a 99% confidence interval for the mean muzzle velocity.
After looking at the key and the question I don't know how to get anything I'm really struggling 😭
prisma garden
I'd show work but idk what to do I've just been trying to search up what everything means but I can't piece it together
dire geode
I am working on my stats review (I don't know how to do any of it lol) and after...
look in your textbook for this formula
prisma garden
How do you get the z score
dire geode
How do you get the z score
it's just a number you memorize that corresponds to 99% two-sided CI
dire geode
show your work
prisma garden
z = 2.575
sample mean = 863
s = 2.7
n = 50
cedar kilnBOT
@prisma garden Has your question been resolved?
cedar kilnBOT
@prisma garden Has your question been resolved?
kindred bridge
How do you get the z score
should be in the t-table as well
kindred bridge
z = 2.575
sample mean = 863
s = 2.7
n = 50
looks right to me
now construct and interpret
cedar kilnBOT
@prisma garden Has your question been resolved?
brittle field
cedar kilnBOT
brittle field
so we know the rate the volume increases
and we are looking for the rate of increase of the radius when diameter is 50cm
do we start with setting up 100 = 4/3 * pi * r^3 ?
finite lion
would it be ok to take derivative
brittle field
probably, I'm not too sure how to do this kind of problem but my teacher most likely used derivatives
finite lion
do we start with setting up 100 = 4/3 * pi * r^3 ?
yes i think this, then derive with respect to r
bold vine
ye
brittle field
what
finite lion
what what
brittle field
4/3 is different than 4 * pi * r^3 over 3 or no?
bold vine
4/3 is different than 4 * pi * r^3 over 3 or no?
nope
finite lion
$\frac{4\pi r^3}{3} =\frac{4}{3}\pi r^3$
bold vine
^^
wraith daggerBOT
candies
brittle field
ok i'll believe you
finite lion
rn whats in mind is find a function for r and derive and sub 50 in
finite lion
what is this
wraith daggerBOT
candies
brittle field
ok
now should I multiply both sides by 3?
im not sure where I need to go from here to somehow incorporate diameter=50
runic garnet
**candies**
Why 100t
brittle field
time is relevant I think
runic garnet
I don’t think that’s how u do this problem
wraith daggerBOT
Stephen
runic garnet
No, that’s incorrect
runic garnet
it says volume increases at 100cm/s
That means that $\frac {dV}{dt} = 100$
wraith daggerBOT
Stephen
runic garnet
**Stephen**
First you need to differentiate both sides of this
brittle field
0 = 0 * 0 * 3r^2
runic garnet
Wat
brittle field
First you need to differentiate both sides of this
.
runic garnet
Have u done problems like these before?
runic garnet
0 = 0 * 0 * 3r^2
That’s incorrect
brittle field
1 or 2 times like a month ago
runic garnet
You should probably watch a video on related rates then
brittle field
differentiate in terms of what?
runic garnet
Wrt time
wraith daggerBOT
Stephen
runic garnet
We are trying to solve for dr/dt
runic garnet
Yea, but we differentiate with respect to time, that’s what 100 cm^3 / s means
brittle field
ok so its
runic garnet
No, I already stated that’s incorrect
Watch this video: https://youtu.be/Ua0YZMo1N78
There’s no point trying to attempt this if knowledge of the concept isn’t there
brittle field
yes
runic garnet
We’re solving for dr/dt
brittle field
so I divide by 100?
runic garnet
Show me what u get upon differentiating both sides
runic garnet
so I divide by 100?
No
runic garnet
Because in the video, he’s solving for dV/dt
Ur not
U alrdy have dV/dt
U want dr/dt
brittle field
ok so 100cm^3/s = dV/dt because its volume over time. I need dr/dt because we need radius over time
runic garnet
cm^3 /s yes
brittle field
ok so somehow I need to use radius = 25
brittle field
theres is no both sides
runic garnet
brittle field
maybe you gave me wrong video. he is given dr/dt already
runic garnet
maybe you gave me wrong video. he is given dr/dt already
I am aware. It’s the same derivation.
That is the correct video
It’s literally plugging in now that both sides have been differentiated
runic garnet
Just rewrite this and solve for dr/dt
brittle field
im confused. what about the 100
runic garnet
100 = dV/dt
.
brittle field
runic garnet
What about the dr/dt….
What are u gonna solve for if there’s no unknown in the equation
brittle field
thats the 25^2
runic garnet
As shown here
brittle field
runic garnet
Ok.. keep going, why just stop there
brittle field
idk what happens next
brittle field
Ur still solving for dr/dt
or is this wrong?
cedar kilnBOT
@brittle field Has your question been resolved?
granite knoll
go back to here
brittle field
ok
brittle field
and then what
granite knoll
just solve for dr/dt
brittle field
thats what gave me
granite knoll
that is wrong
you have, on the right side, a number times the "variable" you want to solve for. so what operation would you do to isolate that variable?
brittle field
divide
brittle field
thats how I got to
granite knoll
no, you took a square root
brittle field
i cant do that?
granite knoll
because you would have to apply it to all terms on both sides of the equation
that would include dr/dt
and it's just a number, 25^2 = 625. there is no reason to take a square root
cedar kilnBOT
@brittle field Has your question been resolved?
brittle field
brittle field
and it's just a number, 25^2 = 625. there is no reason to take a square root
what comes next?
granite knoll
it should be 25/pi, and you can simplify
brittle field
.close
brazen wigeon
A wagon is pulled along level ground by exerting a force of 40 pounds on a handle that makes an angle of 40 degrees with the horizontal. How much work is done pulling the wagon 60 feet?
wraith daggerBOT
@brazen wigeon
uneven crater
Can you expand on the dot product in terms of the magnitude of the vectors
brazen wigeon
Can you expand on the dot product in terms of the magnitude of the vectors
idk what u mean
tame wraith
honestly, no point in doing that
brazen wigeon
like ik what dot product/magnitude are
tame wraith
what is your F vector
sage badge
It might be better to draw a diagram first
brazen wigeon
tame wraith
damn imperial units
who thought it was a good idea
to have the same units
for mass and force
brazen wigeon
who thought it was a good idea
my teacher 😂
uneven crater
Now, there can be two components of the force, one of which is perpendicular to the distance moved and the other one which is parallel to the displacement.
brazen wigeon
Now, there can be two components of the force, one of which is perpendicular to ...
so do i almost have to "split" the force into horiz/vertic using trig
tame wraith
yh
uneven crater
yes,
brazen wigeon
yh
ok hold on
am i making it more complicated than it has to be?
(btw im still keeping the exact value of tan(40) in my calculator)
sage badge
We need the kilogram component
Not the pound component
Also feet needs to be in meters
brazen wigeon
We need the kilogram component
im not supposed to convert to metric (or any other unit) because wE LiVe iN AmErIcA
uneven crater
Don't worry that much about the units, we can fix them later,
find the components of the forces
tame wraith
am i making it more complicated than it has to be?
yh
you have the hypotenuse
so use sin
and cos
wraith daggerBOT
@brazen wigeon
tame wraith
yh
uneven crater
yeah, you have to find the opposite and adjacent of the angles
brazen wigeon
brazen wigeon
just used pythagorean theorem to verify, and my numbers seem to be correct
so
now what do i do
brazen wigeon
you have your F vector
still idk 😭
uneven crater
Tell me if you know that when, the force is perpendicular to displacement, then the work done will be 0 for the vertical component only
brazen wigeon
Tell me if you know that when, the force is perpendicular to displacement, then ...
perpendicular or parallel? cause if youre pulling perfectly straight, no force is being "wasted" so no vertical force
uneven crater
perpendicular or parallel? cause if youre pulling perfectly straight, no force i...
perpendicular forces to the displacement result in 0 work done for the vertical component
tame wraith
while your method is perfectly valid, its less general @uneven crater. if the person were to encounter a situation like what i have drawn
it would be far better to just learn how to use the dot product
correctly
brazen wigeon
ik how to get product
brazen wigeon
ik how to get product
*get
uneven crater
it would be far better to just learn how to use the dot product
Yes, I too would use the dot product, but, @brazen wigeon has not learned it yet, hence I was trying to explain the answer in a way he could understand it.
Also perpendicular and parallel components in this case are defined with respect to the displacement.
brazen wigeon
Also perpendicular and parallel components in this case are defined with respect to the displacement.
👍 understood
cedar kilnBOT
quasi hinge
cedar kilnBOT
@gleaming sequoia Has your question been resolved?
cedar kilnBOT
cedar kilnBOT
Available help channel!
tacit phoenix
How?
cedar kilnBOT
cedar kilnBOT
Available help channel!
shell abyss
would the answer be 42
royal loom
.close
cedar kilnBOT
royal loom
Read this
You have #help-12 open, stay there and read #❓how-to-get-help and #rules while you wait
shell abyss
look at the side
royal loom
it will show you the channels without any new messages
once you click it
right now you have it only on channels with new messages
royal loom
you're still in the wrong channel
royal loom
I closed already, just leave it and it will close down soon
cedar kilnBOT
Available help channel!
ionic thistle
cedar kilnBOT
ionic thistle
<@&286206848099549185>
tropic oxide
!15m
cedar kilnBOT
Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.
tropic oxide
!status
cedar kilnBOT
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
do you have your work in writing...? "break down the roots and abbreviations" doesn't make much sense to me
might be a language thing
ionic thistle
might be a language thing
yes cuz sometimes i use translater
ionic thistle
do you have your work in writing...? "break down the roots and abbreviations" do...
i write it on pdf page
i ont have the work
can u give a hints to start
tropic oxide
$\sqrt[4]{x-4}$ only exists if $x-4 \geq 0$, and $\sqrt{4-x}$ only exists if $4-x\geq 0$
wraith daggerBOT
Ann
tropic oxide
typos fixed
tropic oxide
okay so x =4
exactly
tropic oxide
12-4 is not 9
ionic thistle
i mean 8
but thats the deal
8 will remove the root
okay stop talking im going to solve it and show u
so up we have 2
and down we have 8
if my calculates are right
@tropic oxide
no wait i mean down we will have 2
n 2 on 2 = 1
ohhhhhhhhhhh
is it right?
<@&286206848099549185> can anyone just check if its right?
cedar kilnBOT
@ionic thistle Has your question been resolved?
tropic oxide
and down we have 8
no, on the bottom you have sqrt(9)+4-5. that's not 8.
sqrt(9) is not 9, it's 3
ionic thistle
yes dont look at that
ionic thistle
look at this
pearl tide
any help with this?(z=1+2i)
cedar kilnBOT
any help with this?(z=1+2i)
pearl tide
crimson sedge
write everything in polar form
pearl tide
ive tried that but finding some angles isnt very pleasant
crimson sedge
!show
cedar kilnBOT
Show your work, and if possible, explain where you are stuck.
pearl tide
hold on lemme try one more time
eg: 2+i: |r| = sqrt(5)
so cosθ = 2sqrt(5)/5
@crimson sedge
.close
halcyon ferry
cedar kilnBOT
cedar kilnBOT
@halcyon ferry Has your question been resolved?
cedar kilnBOT
@halcyon ferry Has your question been resolved?
halcyon ferry
.close
ivory flare
cedar kilnBOT
ivory flare
What angle in a) are they talking abt
Can someone like
Draw it for me or something
Cos PAQ is an arc I thought
Not an angle
livid hound
draw the segments PA and AQ
ivory flare
Oooh
ok
I did this
But how should I explain why it’s 120
I mean
How do I lrove
Prove
unborn pike
Draw triangle PAB
PA and PB are radii of the circles
But both circles have the same radius
So PA=PB
AB is the distance between the centres which is equal to the radius
So PA=PB=AB
PAB is an equilateral triangle, so all its angles are 60 degrees
cedar kilnBOT
@ivory flare Has your question been resolved?
cerulean harness
no, add PA and AQ then u will get PAQ angle
cerulean harness
sry I'm not good at probablity stuffs
ivory flare
Oh wait
Oops
How do I solve this question
I have working out abt it’s rlly messy
uneven crater
Could you please send your working
crimson sedge
How do I solve this question
First find the area of circle with the center of B. Since the circle with the center of B is two times bigger than A divide 10/2 to find A. Then find the area of A. This should get you somewhat started on the problem.
cedar kilnBOT
@ivory flare Has your question been resolved?
spring coyote
cedar kilnBOT
spring coyote
This true?
livid hound
no
cedar kilnBOT
@spring coyote Has your question been resolved?
livid hound
is that supposed to be $\frac{L^1}{3}$ or $L^{\frac 13}$
wraith daggerBOT
ℝamonov
livid hound
and what's the end goal
livid hound
consider what operation you could apply to L^(1/3) that'll result in just L
spring coyote
Square rooting?
i mean
cube rooting
hmm no
I thought multiply everything with ()^2/3
so that 1/3 + 2/3 = 1
and L becomes L^1
Yo
Has I been wrong
when you use like Function / ()^2/3, it doesnt sum with the function's exponents but actually multiply?
I thought rule was summing exponents
cedar kilnBOT
@spring coyote Has your question been resolved?
livid hound
I thought multiply everything with ()^2/3
that's not a thing
you "could" multiply both sides by L^(2/3) and L^(1/3) * L^(2/3) = l
however that doesn't really help you as that'll introduce L to the right side of the equation
consider what undoes the cube root
consider an example with square roots
how would you solve
sqrt(x) = 2
or x^(1/2) = 2
cedar kilnBOT
spring coyote
Oh
cedar kilnBOT
Available help channel!
summer idol
Questions is show that only solution is x=4 , I’ve got 4 solutions, im confused as to where I have gone wrong
summer idol
cedar kilnBOT
@summer idol Has your question been resolved?
wicked vortex
What do you need help with?
summer idol
I don’t understand how x=4 can be the ONLY solution
dire geode
Questions is show that only solution is x=4 , I’ve got 4 solutions, im confused ...
the domain of the inverse is only defined for certain values of x. you have to make the function one-to-one
Read Example 1.7.9
https://math.libretexts.org/Bookshelves/Precalculus/Precalculus_1e_(OpenStax)/01%3A_Functions/1.07%3A_Inverse_Functions
the domain of $f^{-1}(x) = (x-2)^2$ is the range of $f(x) = 2 + \sqrt{x}$
wraith daggerBOT
riemann
cedar kilnBOT
@summer idol Has your question been resolved?
cedar kilnBOT
cedar kilnBOT
Available help channel!
crimson sedge
Can someone help me solve this equation 7/x-6 - x/(x+6)(x-7)
rugged raven
okay umm can you type in the full equation?
crimson sedge
sur
(7/x-6)-(x/x^2+x-42)
i Factor out the x^2 which is (x+6)(x-7)
but idk where to go form there so
if anyone can help let me know or something
its just subtracting rational expressions
just solve
balmy lily
is it to simplify or to solve?
crimson sedge
simplify
balmy lily
ok
balmy lily
x - 6 is a common factor for the both fractions
so 7/x-6 can be expressed as (7(x+7) + x) / (x-6)(x+7)
= 7x + 49 - x / (x-6)(x+7)
= 6x + 49 / x^2 + x - 42
cedar kilnBOT
@crimson sedge Has your question been resolved?
rugged raven
=(6x²+13x-294) / (x-6)(x+6)(x-7)
=(6x+49)(x-6) / (x+6)(x-6)(x-7)
=(6x+49)/(x²-x-42)
crimson sedge
Dang
cedar kilnBOT
@crimson sedge Has your question been resolved?
cedar kilnBOT
@crimson sedge Has your question been resolved?
fiery ivy
i'm not getting how i should calculate that "2a"...i got i have to write it like that, but what do i do? i just multiply that 2 with that 5? which operation?
fiery ivy
i believe so it's wrong? it should be -2/7?
bright bridge
wait solving for x is not the axis of symmetry
fiery ivy
so the whole formula is incorret?
upper abyss
x = -1/5 is the equation for the axis of symmetry.
x = -1/5 is not the root of the quadratic
I think that's the confusion
fiery ivy
thanks
so it should be right for the axis of simmetry? ignoring that "x" that is probably wrong for what i'm indicating
bright bridge
looks right
fiery ivy
I'm not sure if the delta of this one is 6 (summing up those 5 and 1) or 0 (solving it in line)
modern compass
Does that say $\Delta = 2^2-4(5)(1)$?
fiery ivy
the last number is not 3 it's 1
wraith daggerBOT
Zybikron
modern compass
then neither of your answer are correct. You should be following the order of operations.
deal with the 2^2 and 4 * 5 * 1, then subtract them.
real smelt
cedar kilnBOT
real smelt
so far i have (2-2/3)+(1-2/4)+(2/3-2/5)+...+(2/n-2/n+2)
sleek condor
separate it into two sums, k even and odd then you'll have two telescopic series i think
upper abyss
I can see a -2/3 ... +2/3 already
sleek condor
like $\sum (\frac{2}{2i} - \frac{2}{2(i+1)}) + \sum (\frac{2}{2i+1} - \frac{2}{2(i+1)+1})$
wraith daggerBOT
Benjamin
sleek condor
left summ is even and right sum is odd
real smelt
this is so confusing dang
modern compass
the series is already telescoping, it just doesn't start for a few terms.
write out more terms and you'll see the cancelations
dire geode
so far i have (2-2/3)+(1-2/4)+(2/3-2/5)+...+(2/n-2/n+2)
if you just write out a few more initial terms, you'll see the telescope
real smelt
ah okay
sleek condor
the series is already telescoping, it just doesn't start for a few terms.
write...
it is but 2 by 2, i said to decompose to see easily the cancelations
cedar kilnBOT
@real smelt Has your question been resolved?
cedar kilnBOT
cedar kilnBOT
Available help channel!
bronze phoenix
cedar kilnBOT
bronze phoenix
guys is this right?
cedar kilnBOT
@bronze phoenix Has your question been resolved?
bronze phoenix
<@&286206848099549185> ?
cedar kilnBOT
@bronze phoenix Has your question been resolved?
cedar kilnBOT
cedar kilnBOT
Available help channel!
cedar kilnBOT
tropic oxide
do you have confirmation from your teacher that this is what's meant
if not then you have to return the problem to your teacher saying that it is corrupted beyond comprehension
shell pasture
My friend asked the teacher and said that it was a typo
radiant topaz
I seems like eight yes
shell pasture
It is eight
radiant topaz
eight gives a good answer too
shell pasture
Yep it is five out of eight attendees
tropic oxide
right
so 5/8 of the attendees are women, and 80% of those invited attend the party.
shell pasture
Yep
tropic oxide
and invitations were sent out to fill 25 tables of 6 people each.
shell pasture
Yep
tropic oxide
!status
cedar kilnBOT
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
I don’t know where to begin
tropic oxide
you think, but you doubt yourself?
shell pasture
120
tropic oxide
can you share how you calculated this?
little crane
aw man i thought the question would've been a super interesting combinatorics question
shell pasture
(25*6)*0.8
little crane
got excited when reading it
tropic oxide
(25*6)*0.8
this does not answer my question of "how many invitations were sent out"
shell pasture
25 times 6 times 0.8
tropic oxide
you jumped ahead.
you should have said
the number of invitations sent out is 25 * 6
and the number of ATTENDEES is 25 * 6 * 0.8
tropic oxide
okay, so now we know there are 120 attendees
given that five-eighths of this amount were women,
how many women came?
cedar kilnBOT
shell pasture
Oh got it
tropic oxide
you could have also typed .close
cedar kilnBOT
Available help channel!
somber tiger
cedar kilnBOT
somber tiger
No the derivative is correct I double checked
marsh wren
o that was plus sign sorry
somber tiger
Also if you take a derivative of a constant it goes awa
marsh wren
the picture isnt clear thats why .. sorry
marsh wren
i figured out likely
you had to do integration in the 2nd last step
before putting limits
you messed up the integration after root(1) dt
somber tiger
Ya but we don’t have I derive 2 + cosT because that is Y
somber tiger
Ok let me see what you get
Root of 1 would be 1
And anti derv of 1 would be T
But let me see what you do
marsh wren
check
if you remove dt before
then with respect to which you will integrate the integrand ?
somber tiger
Hold on let me look at your pic for a sec
narrow sail
if you have a starting amount P that is growing at a compounding R every x, but a fixed amount F is being removed from it every x, how do you determine this new cummulative rate of change?
narrow sail
for example, lets say P=100, R=0.05,F=5, then the new rate of change is actually 0. but this is easy to know in this case because the fixed amount is the same as the growth of the first x, so it effectively constantly resets back to the 100.
but how would you determine the rate of change if F=4or F=6 in the above case?
P(1+R)^x + -F(((1+R)^x - 1) / R) is the equation, but can this actually now be represented as some alternative R value?
such that i can just do P(1+R)^x with a new R value.
newR = R + (-F/P) is obviously wrong, over larger period of x.
cedar kilnBOT
@narrow sail Has your question been resolved?
little crane
how is ur rate of change defined? is it ur effective interest
narrow sail
R is the interest basically. But the rate of change is for the entire account.
And there are two things at play. The interest rate and the withdrawal rate. That’s pretty much it..
narrow sail
how is ur rate of change defined? is it ur effective interest
☝️
little crane
can't u use annuity formula
for the withdrawl
since it is constant
@narrow sail
i see u dont know x
let me pull out my old econ formula sheet lol
@narrow sail are u given x?
if ur given x then this question is simple linear interpolation or smth
but if not then
it doesnt make sense
since the R_new changes depending on what x is
cedar kilnBOT
@narrow sail Has your question been resolved?
eager sedge
cedar kilnBOT
eager sedge
Why doesn’t this work?
cedar kilnBOT
@eager sedge Has your question been resolved?
shell pasture
can i aks how to do this
gritty galleon
To have 5$/l
U must have total amount/total cost =5
So first find cost of 44l at 5.5$/l
gritty galleon
So first find cost of 44l at 5.5$/l
Can u do this?
gritty galleon
Yes
crimson sedge
In How many ways the letters of the word TUESDAY be arranged in which vowels are never together?
crimson sedge
I permuted the consonants and had 4! and then attempted to put vowels in between the consonants which is 5!/3!
so my answer was 4! * 5!/3!, am i wrong or missing something basic?
uneven crater
Ok,
Hint: Total Permutation - (Permutation when all vowels are together)(Internal Permutation within the vowel) = Permuation in which vowels are not together
crimson sedge
Ok,
Hint: Total Permutation - (Permutation when all vowels are together)(Intern...
okay but for a different problem i used this approach and it worked?
I'm aware i can use inclusion exclusion
5! * 6!/3! = 14400
TSDYUEA so permuting consonants = 4! and to distribute vowels into 5 spaces i'd have 5!/3!
so 4! * 5!/3!
uneven crater
okay but for a different problem i used this approach and it worked?
Yes, but you will have to be careful in cases where 2 or more of the same letter is used and you must take that into consideration
crimson sedge
Yes, but you will have to be careful in cases where 2 or more of the same letter...
yes but every letter is unique here and in the other question lol
uneven crater
Ok,
Hint: Total Permutation - (Permutation when all vowels are together)(Intern...
Wait, I suggested the complement method where, double counting is taking place, here we must use inclusion exclusion principle. I am sorry if any confusion was caused
crimson sedge
Okay sure lol, but still i don't see why what i did was wrong
I saw a similar solution in an intro to prob book as well for a very similar problem
<@&286206848099549185>
waxen shadow
<@&286206848099549185>
uneven crater
What is the answer given in the source? Also, I checked out a similar problem, and they have solved it with the same method as you have detailed.
crimson sedge
What is the answer given in the source? Also, I checked out a similar problem, a...
Idk the answer lol, could it be 1440?
One of the teachers say it's 1440
uneven crater
Yes, It is 1440
wraith daggerBOT
crimson sedge
uneven crater
Ok, we have to permute, 5 space for 3 vovels, that is 5P3 = 5!/2! not 5!/3!
The formula for permutation is nPr = n!/(n-r)!
crimson sedge
The formula for permutation is nPr = n!/(n-r)!
Ah okay you're right
Thanks~
.close
tulip thunder
At what value of the parameter p is the plane a : px+2y+3z-8= parallel to the straight line I: y-z=0, x+y = 0
tulip thunder
hey, im quite bad at geometry in space, and would love some help
uneven crater
ok, do you know what the coefficient in the equation of the plane represent
tulip thunder
not really
uneven crater
well, the coefficients of the equation of the plane represent the direction ratios of the normal to the plane i.e. the direction ratios of a line perpendicular to the plane
For a line parallel, to the plane, it must also be perpendicular to the normal of the plane
cedar kilnBOT
@tulip thunder Has your question been resolved?
tulip thunder
@uneven craterare you here?
uneven crater
Sorry was busy with another
uneven crater
so how do i start the exercice ?
Yeah, now do you know what are the direction ratios of the line given
tulip thunder
not at all, if you can guide me as if i never did an exercise like that, i will get the full on explaination
.close
cedar kilnBOT
cedar kilnBOT
Available help channel!
quartz frost
Hey
quartz frost
Is a klein bottle a manifold?
My prof introduced something as an example for a manifold without saying what a manifold is by definition
Just that it has to locally be euclidian
tropic oxide
a manifold is a topological space that locally looks like R^n for some n
quartz frost
But a klein bottle intersects itself, is that a problem?
tropic oxide
do not confuse the klein bottle for an immersion thereof into R^3
tropic oxide
there is no intersection
intersections are only an artifact of how it is immersed in R^3
the klein bottle itself is a 2-manifold and it does not have any self intersections
dusk finch
Where did I go wrong? The last line already tells me that either b=0 or cos(a)=0 which is both false
peak nymph
seven times a two digit number is equal to four times the number obtained by reversing the order of the distance sum of the digits is 3 find 6the no :
dusk finch
b cant be equal to 0 since it would mean that the equation has real solution
cerulean sail
The expansion of the second last line to the last one I think
cedar kilnBOT
dusk finch
.reopen
cedar kilnBOT
✅
muted tendon
cerulean sail
The real part of the LHS is already zero
dusk finch
,w calc arcsin(2)
wraith daggerBOT
sacred grail
,w pi/2
wraith daggerBOT
cedar kilnBOT
wraith daggerBOT
signal cave
,w integral from 0 to pi/2 of cos^2(x) dx
wraith daggerBOT
signal cave
This is correct.
The pic is right. It got pi/4.
You have to begin by using the half angle identity
So far so good
Indeed
My friend, the upper limit is pi/2, not pi/4.
Ah shit indeed
crimson sedge
Tragic
signal cave
Please close the channel with .close if your question has been resolved.
crimson sedge
you're right. You can do this way
marsh granite
cedar kilnBOT
marsh granite
Hi, I have quite a simple question but I want to avoid making mistakes in my exam coming up
When trying to show that this operation is closed
Do you have to do anything more than ``Let $x,y \in G$. Then by definition of $*, x * y = xgy \in G$. Therefore it is closed."
wraith daggerBOT
trayan_b
granite knoll
what is "g"
radiant topaz
an element of g i guess
marsh granite
yes, g in G
radiant topaz
Do you have to do anything more than ``Let $x,y \in G$. Then by definition of $*...
no need
this is enough
marsh granite
But how do we know for sure that xgy is in G
radiant topaz
G is a group no?
marsh granite
radiant topaz
yes so it is multiplicatively closed
so xgy will be in G because G is group under multiplication
marsh granite
"multiplicatively written" means that for convenience we write x * y as xy
I don't think it means it's closed under multiplication
radiant topaz
"multiplicatively written" means that for convenience we write x * y as xy
- is not same as xy?
radiant topaz
I don't think it means it's closed under multiplication
well they did say it's a group that does mean if x,y in G then xy in G
let alone how * is defined later
radiant topaz
you're welcome dear 
marsh granite
.close
cedar kilnBOT
cedar kilnBOT
Available help channel!
hidden osprey
If I use my phone continuously, its battery will last for 6 hours. If I do not use my phone, its battery will last for 60 hours.
On a plane trip, I use my phone for only half of the trip.
The phone is completely drained the exact moment the trip ended.
how long was the plane trip?
dull oxide
!status
cedar kilnBOT
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
1
nova glacier
Let's say you have 100% battery. It drains (100/6)% per hour that you use it, and (100/60)% per hour that its idle
nova glacier
Let's call the total trip time T
hidden osprey
ye
hidden osprey
ye
nova glacier
So, the usage takes T/2 * (100/6)% of the battery, and the idle takes T/2 * (100/60)% of the battery
Together it should be 100%
So you have an equation
hidden osprey
so the function is T/2 * (100/6)% +T/2 * (100/60)%
nova glacier
T/2 * (100/6)% + T/2 * (100/60)% = 100%
hidden osprey
T/2 * (100/6)% + T/2 * (100/60)% = 100%
T/2 * (100/6)% + T/2 * (100/60)% = battery percent?
nova glacier
You don't really need the % 🙂
hidden osprey
ye
nova glacier
It begins with full battery right?
nova glacier
So you know that when the trip ended it was 0% and when the trip started it was 100%
hidden osprey
ye
nova glacier
So together all the usage sum up to 100% battery
So, T/2 * (100/6) + T/2 * (100/60) = 100
hidden osprey
so when t = 0 it should be 100 no
nova glacier
It's a function of how much the battery was used at time T
So at T =0 it should be 0
and at T = (travel time) it should be 100
and you should find the travel time
So make an equation and find when the function gets a value of 100
Like so: T/2 * (100/6) + T/2 * (100/60) = 100
(Sorry had a typo before, read it again) @hidden osprey
So it's not what you wrote, but: T/2 * (100/6) + T/2 * (100/60) = battery usage
You can try to write a function battery percentage if you like it better 🙂
(just take 100- battery-usage)
hidden osprey
.close
pearl tide
any help with proving that?
cedar kilnBOT
any help with proving that?
red musk
try using $2 Re(w)=w+\overline w$
wraith daggerBOT
Lemma
red musk
yeah, since it's real
red musk
right
pearl tide
ok thanks
red musk
$\lambda = \lambda +0i = \lambda -0i = \overline\lambda$
wraith daggerBOT
Lemma
sonic sand
if a surface for an object A, has a tangent line to the surface, t
and a normal vector n perpendicular to that tangent line all being transformed by a linear transform matrix M , then the new t will also be a tangent line to the transformed surface, but the new normal may not be perpendicular anymore.
Why is that? what is special about a normal vector that makes not perpendicular anymore but the tangential line stays tangential?
cedar kilnBOT
if a surface for an object A, has a tangent line to the surface, `t`
and a norm...
@sonic sand Has your question been resolved?
cedar kilnBOT
@sonic sand Has your question been resolved?
crimson sedge
Guys help him
<@&286206848099549185> I think he needs help
Sorry bro you ain’t getting help
sonic sand
Sorry bro you ain’t getting help
Thank you, for your kind message,
I am not in a rush.
I understand people have their own lives and their own things to do, so no rush at all.
cedar kilnBOT
@sonic sand Has your question been resolved?
crimson sedge
<@&286206848099549185>
cedar kilnBOT
@sonic sand Has your question been resolved?
royal loom
cedar kilnBOT
royal loom
I wanted to confirm that this was written incorrectly. It's defining a field and this says that for a field there must be an element 0 in the field such that for all elements in the field + 0 it equals 0....
It is meant to say equals x right?
cerulean sail
royal loom
how
sleek condor
yeah unless they are messing
royal loom
how did you have that ready so fast
sleek condor
up + and *
cerulean sail
how did you have that ready so fast
still had the video open haha
crystal raptor
chartbit omniscient
royal loom
^
chartbit the instant I post the screenshot
Okay thanks guys, seemed obvious enough
.close
earnest socket
literally not true for any field lol
cedar kilnBOT
crystal raptor
the field with one element 
cedar kilnBOT
Available help channel!
stuck gazelle
cedar kilnBOT
stuck gazelle
does anyone know how to get the 2nd point that shapes the vertex?
violet flume
hrm? second point?