You're not usually up at this time
#help-13
dull oxide
dull oxide
Are you familiar with the general idea of exponentiation?
Like, $a^b$ makes sense to you, yeah?
wraith daggerBOT
SWR
frosty ocean
$b^{\log_{b}(a)}=a$ and $b^{k \log_{b}(a)} = b^{\log_{b}(a^k)}=a^k$
wraith daggerBOT
marsh pond
$b^{\log_{b}(a)}=a$ and $b^{k \log_{b}(a)} = b^{\log_{b}(a^k)}=a^k$
Yeah I get that impression
Just trying to understand why
wraith daggerBOT
SWR
marsh pond
Like the examples I gave above are exactly what you wrote again in Latex
frosty ocean
You can verify them by taking log_a both the sides
marsh pond
Okay. So if I gave you $a^b=c$, how would you solve for b?
log_a(a^b) = log_a(c)
b = log_a(c)
since log_a(a) = 1
and I can move b in front
dull oxide
You're using properties of logs while omitting the most important part
marsh pond
What’s that?
dull oxide
By definition, $b=\log_a c$ is the solution to $a^b=c$
wraith daggerBOT
SWR
dull oxide
That is the definition of log
you don't need those properties
In fact, those properties come from the definition
tropic oxide
You're using properties of logs while omitting the most important part
dont you know definitions are for nerds? the hip new thing is to memorize and use symbolic properties without understanding them
dull oxide
So I believe you're getting confused because you've been applying circular logic, not knowing the root of the properties of logarithms
marsh pond
I normally have it the other way,
log_a(b) = c
rather than c = log_(b)
It’s just a habit so I can use a right arrow on the bottom from log base to the exponent
dull oxide
I normally have it the other way,
log_a(b) = c
This would be the solution to $a^c=b$ then. Same thing
wraith daggerBOT
SWR
marsh pond
Right
marsh pond
And I don’t mind if it’s memorization
I’m trying to understand now
Why things are the way they are
buoyant latch
Better than not trying at all, I salute you for you dedication!
marsh pond
This log inverse really trips me up for some reason
marsh pond
This log inverse really trips me up for some reason
When I see logs included in exponents
Ty
wraith daggerBOT
SWR
marsh pond
Yeah I was gonna say
Maybe that would be way easier for me
At least for now
I wish Symbolab (and all online calculators) would offer more examples than just 1 for solving
Maybe WA does?
buoyant latch
You could pay for wolfram alpha
dull oxide
Example
buoyant latch
It’ll give you the steps
marsh pond
I paid for Symbolab it gives all steps but in this case only for the exponential method which I’m having trouble with
If they showed ln on both sides as another solution I think I would get it
marsh pond
Example
Yeah like this
WA shows ALL possible ways to solve? Or picks one
With all steps for that one method
Kind of like Russian Roulette with whatever method they pull the trigger on
Imo so far as I have seen
buoyant latch
It usually picks the more algorithmic way to solve it from my experience
(Likely due to it being a computer)
cedar kilnBOT
@marsh pond Has your question been resolved?
upper flame
Why do we use function notation to denote y why can't we just use y=x+2 instead of f(x)=x+2 ?
mighty drift
y = x+2 defines a graph, the set of all (x, y) verify this equality. It doesn't define a function.
f(x) defines a function, because it's a notation that gives you an actual input to interact with (remember that a function takes an input and gives an output, the notation must represent that).
Now you can talk about (simplifying the notations a bit) f(x+2), f(2x), f(x^2) as being transformations of your function f, which create a new graph.
the y= notation doesn't allow for that well. It generally prevents doing function arithmetic, like sums and products (f+g and fg) because it doesn't denote a function, but a graph
upper flame
Wait i understand everything but do you mean the f(x)
Does not mean y
Means y is not same as f(x)
mighty drift
It doesn't have to be
if you look closely at whatever math book you probably have, they should say
"The graph y = f(x)" (or y = x^2 + 2 or whatever)
And "the function defined by f(x) = x^2 + 2"
upper flame
Okay so function is just a notation which allows us to do arithmetic and other stuff like that as you mentioned while if we have just y we can't do that using it .
mighty drift
But here's the thing.
y(x) = x+2 is a function
upper flame
This will be confusing when we will state y(x) = y
mighty drift
Not a function
Because y(x) must be defined as a function of x
Right now you've defined the function y as returning itself (a function) for every value of x.
Which I doubt is legal
upper flame
Right now you've defined the function y as returning itself (a function) for eve...
Yeah think so
.close
left moss
the first 3 terms in the expansion of (a + x)^3(1-(x/3))^5, in ascending powers of x, can be written in the form 27 + bx + cx^2, where a,b and c are intergers. Find the value of a,b and c
left moss
vagrant elbow
Just put x = 0 and you'll get the value of a
To get b and c individually well we could use a bit of calculus if you're comfortable with it
left moss
i haven't covered that yet
left moss
yeah
vagrant elbow
Did the powers higher than 2 all cancel out or something
vagrant elbow
Alright give me a sec
Wolfram seems to tell me that the powers don't cancel out which is odd
vagrant elbow
i prolly stopped midway
So what you're gonna have to do is group together all the terms that can make up x^2 and x
Did you understand how x = 0 gives us a?
vagrant elbow
$(a + x)^3(1 - \frac x3)^5 = 27 + bx + cx^2$
left moss
(a+0)^3(1-(0/3))^5?
wraith daggerBOT
NEONPerseus
vagrant elbow
Put x = 0 into both sides of the equation here
left moss
oh
vagrant elbow
(a+0)^3(1-(0/3))^5?
Yeah
left moss
and then expand?
vagrant elbow
If you put x = 0 there will be no need to expand
vagrant elbow
What do you have after putting in x = 0
vagrant elbow
**NEONPerseus**
Can you tell me what would the highest power in the expansion on the left here be
left moss
5?
vagrant elbow
vagrant elbow
What would the highest power be in (a - x)^3
vagrant elbow
And in (1 - x/3)^5?
vagrant elbow
So if you multiply those two expressions what would the highest power be
vagrant elbow
Well if the highest power from the first expansion was multiplied with the highest power in the second expansion what would the power be?
left moss
15?
wraith daggerBOT
NEONPerseus
left moss
yeah
vagrant elbow
I hope you understand that
Because we're gonna be using a similar concept to get b and c
left moss
👍
vagrant elbow
So can you tell me in how many ways can you get a power of 1
left moss
for both expansions?
vagrant elbow
The total power needs to be 1
left moss
oh
vagrant elbow
From multiplying both expansions
left moss
two ways
vagrant elbow
What would those be?
left moss
3ax from the expansion of (a + x)^3, -5/3 x from the expansion of (1 - x/3)^5
vagrant elbow
I meant how would you express them as a product of powers from both expansions
For example if I wanted power 8 I would do 3 + 5
left moss
oh man
that's
idk
this is confusing
help
pls
<@&286206848099549185>
.close
crimson sedge
is it okay if you add zeroes too compare?
cedar kilnBOT
is it okay if you add zeroes too compare?
crimson sedge
if i dont write zeroes
i can not seem to figure out which one would be smaller
is that okay to do
drowsy veldt
write all as powers of 10
crimson sedge
i did
the last two were to be written
as i wrote
will it still be considered the right way if i add zeroes?
drowsy veldt
yes
crimson sedge
so can you mark my question
drowsy veldt
adding zero after decimal makes no effect
drowsy veldt
so can you mark my question
yes
crimson sedge
so my answer is right?
crimson sedge
adding zero after decimal makes no effect
it does not it is that it helps compare
drowsy veldt
it does not it is that it helps compare
yes
tall sand
hello i dont understand how my professor went from π∫ to 2π∫ after the {even part
tall sand
and why/how did the bounds change f rom [-1,1] to [0,1]
violet night
I believe it's because since f(x) = f(-x) , the volume generated from -1 -> 0 is the same as 0->1 , hence instead of doing an extra annoying substitution (that we would need to do with bounds of -1 -> 1) , we can just multiply our answer 0->1 by 2.
and just for a sanity check, you can even compute the bounds -1 -> 1 with just " 1 pi " and it will work out the same
tall sand
i see so it's optional 😭
violet night
yes
tall sand
this whole time i thought it was mandatory
violet night
but a nice time saver
tall sand
i see i see thank you!
im sure you explained it well but i cant wrap my head around it 💀 so ill stick to working it out completely
i appreciate it!
violet night
,w plot x^4-2x^2+1 from x -2 to 2
wraith daggerBOT
violet night
symmetry is cool
tall sand
so say if the function was odd would there be another way to work it out or does this only apply to even functions
violet night
not entirely sure if that its odd it means it wouldn't work at all, there are still some instances were it would still work I think but would be better to ask your prof so he can visualise it in person
hard to describe moving all the parts around I guess
tall sand
gotcha gotcha
sorry i have 1 more question regarding the even part
regardless of how its written as long as it's even itll always become 2pi?
violet night
hmm not sure, the 2 comes from the reasoning that we are taking the entire area and splitting it up into 2 equal parts
violet night
for example it could be even but not around the x=0 line
,w plot (x-2)^2 from x 1 to 3
wraith daggerBOT
violet night
so that isn't 'an even function' nor an odd one but if we had bounds 1->3 we could still split it from 1->2 + 2->3 as they would be equal
or just 2 * 1->2 (as 1->2 and 2->3 are equal)
tall sand
gotcha i think im slowly getting it
thanks again @violet night ! much appreciated :D
take care friend :) have a nice day
.close
timid cloak
.close
cedar kilnBOT
Available help channel!
wraith heath
can someone help me understand how to solve this :3
cedar kilnBOT
can someone help me understand how to solve this :3
cosmic steppe
There's a lotta ways
south tundra
You could pretty much make use of any trigonometric functions
cosmic steppe
Identify the relationship angle A has with any two of the sides
south tundra
Which one would you pick?
wraith heath
jus give me one :l
south tundra
There are sine, cosine, tangent, cotangent, secant and cosecant
cosmic steppe
sin(A) = ?
wraith heath
sin is the one we're learning abt
south tundra
Okay then go with sine yeah
south tundra
Can you identify what sin(A) is?
wraith heath
uhm
is it
wait no i forgot them all
my teacher speaks really fast and doesnt explain anything so we're supposed to figure it out
south tundra
Soh cah toa, do you at least remember this?
wraith heath
yes
i think
holup i have an image somewhewre
thius
houlp
thsi
sin a is A/c
i think
@south tundra
wraith heath
hypotenuse is a->b
the c line right
wait
yes
then opposite is B->c
the a lone
line
holup
south tundra
can someone help me understand how to solve this :3
Yeah, what values do they have here though
south tundra
Okay, so what's sin(A) in that case?
wraith heath
that would be
one moment
.6327212
but isnt there a special thing you're supposed to do with a calculator
like sin # then get a specific decimal
south tundra
We are getting there
wraith heath
okie
wraith heath
mhm
south tundra
Now we can isolate A by using the arcsin function
The inverse* function of sin
On your calculator it may also be denoted as sin^-1
south tundra
So sin(A) = that
Anyways, this implies that A = arcsin(.6327212)
south tundra
y = sin(x) -> arcsin(y) = x
south tundra
It works just like any other inverse function for some values of x
wraith heath
kinda
what are the other inverse functions
are there ones which are easier to remember
south tundra
sqrt(x) is the inverse function to x^2 for nonnegative x
ln(x) is the inverse function of e^x
Inverse of f(x) is usually denoted as f^-1(x)
wraith heath
oh i think i remember something like that
if theres a negative which results in something like sin# = #/x which is switched around to be x= 15/sin = .#
unless im mixing that up
south tundra
Seems irrelevant
wraith heath
idk im just looking at the notes i took
he just solves it and makes us write it down hoping to learn from watching what he does
but says it like
"ok looking at this we can isolate # # # # and number
but doesnt tell us how to do it
which has started to get really annoying
so im just going off bits and pieces i have written down
cedar kilnBOT
@wraith heath Has your question been resolved?
opaque root
!status
cedar kilnBOT
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
autumn fox
We know a few things from the sketch. Both vertical lines are perpendicular to the horizontal line, and they are both on each their side of the origin.
The second thing isn't explicitely stated, but I think it's a fair assumption.
Now: imagine the situation where y and x are minimized
Yes. Can you argue why?
What happens to the lines with length x and y
Yes. The length y will be minimized when the line with y length is as far to the right as possible (almost 0). The length x will be minimized as the line with length x goes as far to the left as possible, while still touching the horizontal line.
The side with length x should be easily determined to be less than the diameter when it is minimized, and with y practically being 0 when it is minimized we should be able to conclude that the sum of x and y halfed will be less than the radius
Now let's look at the scenario where x and y are maximized
autumn fox
On the drawing they are on either side of the origin, so this is a fair assumption to start from
autumn fox
sorry i missread
I formulated it weirdly in retrospect
opaque root
yeah but it's ok anyways
autumn fox
On the drawing they are on either side of the origin, so this is a fair assumpti...
With this in mind, how will the scenario look where x and y are the greatest?
opaque root
you can also see by drawing the diameter
autumn fox
Did you come to a conclusion?
For x + y to be equal to the diameter we need that both vertical lines are extensions of eachother, that is that they both go through the origin. We know they the length of the lines can get very very close to being the diameter, but since they are both in either side if the origin, they will actually never be in this scenario.
We can also imagine this to be the case where x + y is maximized. But if we know that x + y maximized never can be the diameter (very very close, but no actually that value) then the half of that must always be less than the diameter
Correct!
Nono, just happy to be helpful
It is. I had to think a while before I could give any coherent advice
cedar kilnBOT
@crimson sedge Has your question been resolved?
cedar kilnBOT
cedar kilnBOT
Available help channel!
lucid warren
Help, I got 4, -4 the answers but it says incorrect
cedar kilnBOT
Help, I got 4, -4 the answers but it says incorrect
silent cedar
Can someone help me pls
scenic heath
Can someone help me pls
lucid warren
it's great
Oh so c=4 only?
gritty viper
yeah
lucid warren
Oh no wonder y I got it wrong, didn’t pay attention to the words open interval
Thx for pointing that out
gritty viper
np
granite knoll
<@&268886789983436800> no test help, no payments
raw bobcat
cedar kilnBOT
cedar kilnBOT
Available help channel!
hardy vortex
who tryna get help because they have been absent for 2 weeks
mighty mortar
Determine the smallest positive root of the following equation:
f(x) = 2x4–3x3+5x –7 =0
The root should be correct up to two decimal places, usingRegula-falsi method.
when I put f(1) I'm getting-3 and when I put f(2) I'm getting 11
mighty mortar
Does this mean that the root exist between f(1) and f(2) ?
south tundra
Between 1 and 2*
mighty mortar
yeah, So I need to check when the value turns positive?
for example, if I get a negative value on f(5) but positive on f(6), the root will exist between 5 and 6?
@south tundra
south tundra
for example, if I get a negative value on f(5) but positive on f(6), the root wi...
Yes
mortal marten
cedar kilnBOT
cedar kilnBOT
@mortal marten Has your question been resolved?
mortal marten
@toxic thistle
cedar kilnBOT
@mortal marten Has your question been resolved?
cedar kilnBOT
@mortal marten Has your question been resolved?
cedar kilnBOT
cedar kilnBOT
Available help channel!
opal willow
im able to use pythagoras to work out the length BC using the sides OC and OB right?
opal willow
so i need to use a^2 = b^2 + c^2 - 2bcCos(A)?
zenith sail
That sounds good yeah
opal willow
i wrote it exactly the same onto my calc
but didnt get that answer
i tried in radians and degrees
<@&286206848099549185>
obsidian coral
but didnt get that answer
What did you get
zenith sail
That's what I get
obsidian coral
Did you get 174.7006136958175?
opal willow
i got that when i use radians
obsidian coral
Because notice how it says BC^2
opal willow
and degrees i get 1.043...
obsidian coral
You have BC^2 = 174.7006136958175
opal willow
Because notice how it says BC^2
o do i have to root it
obsidian coral
Yes
pulsar zephyr
Working on a practice worksheet with regular polygons and im having issues solving these
cedar kilnBOT
Working on a practice worksheet with regular polygons and im having issues solv...
@pulsar zephyr Has your question been resolved?
torpid ore
Working on a practice worksheet with regular polygons and im having issues solv...
for 13 find the area of the circle - area of 6 triangles
cedar kilnBOT
@pulsar zephyr Has your question been resolved?
kindred hornet
@silver parcel
three consecutive numbers will be like this: k, k+1, k+2
how you can choose k such that the 3 are composite ?
again, no need to find the smallest k, just the simplest idea that will come to your mind
i cant find a k that works. especially for k+1
silver parcel
k = 8
8, 9, 10 are composite
hint: think about how a factorial has many divisors, it will be of great help for the case n = 100
kindred hornet
hint: think about how a factorial has many divisors, it will be of great help fo...
do we need numbers with lots of divisors?
silver parcel
we want the following number to have proper divisors too
so it's more about a trick in choosing k
kindred hornet
so it's more about a trick in choosing k
do you have a hint on how to choose k? im really confused tbh
silver parcel
try the case 4 consecutive number with the hint to go near a factorial
if k is somewhere near a factorial it will go well for reasons you'll see
kindred hornet
try the case 4 consecutive number with the hint to go near a factorial
24 works
120 works for 5 consecutive
silver parcel
yes, what's happening here ?
well, 5! is divisible by 5, 5! + 1 by 11, 5! + 2 by 2, 5! + 3 by 3, 5! + 4 by 4
but it's not perfect yet: we had to use that 5! + 1 is divisible by 11 so it cannot be "generalised" to the case 100 consecutive
can you make a choice near 120 that gives something nicer ?
kindred hornet
yes, what's happening here ?
well, 5! is divisible by 5, 5! + 1 by 11, 5! + 2 by...
im not sure why it works though
121 works
silver parcel
im not sure why it works though
because n! is divisible by all integers before n, n! + 2 is divisible by 2, n! + 3 by 3, ..., n! + n-1 by n-1, n! + n by n
can you see how near n!, we can always find n-1 consecutive integers easily ?
kindred hornet
can you see how near n!, we can always find n-1 consecutive integers easily ?
Right. So, would 100! Work for k in the 100 consecutive number case?
silver parcel
be careful, from 100! + 2 to 100! + 100, it's only 99 integers
we don't know a lot of things about 100! + 1 or 100! + 101, which is annoying
how can we choose the factorial a bit better ?
kindred hornet
Use a larger one?
silver parcel
yeah
kindred hornet
Like 101!
alpine acorn
cedar kilnBOT
alpine acorn
i dont know how to put the equation in standard in standard form
cedar kilnBOT
@alpine acorn Has your question been resolved?
static fern
in general, the equation of a line with slope $m$ and $y-$intercept $b$ is $y=mx+b$
wraith daggerBOT
FireBlazer
cedar kilnBOT
cedar kilnBOT
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atomic hazel
Need some help regarding empirical rule, and a questionable choice of a word problem.
atomic hazel
Obviously pretty easy to understand
but the problem is that when subtracting towards the left marks, you eventually go into the negative.
My issue is how exactly would credit card debt go into the negative?
Here are my markings.
Now I tested it by getting the mean between (-38) and 6562, which is 3262. But I still feel kind of uncomfortable with this answer
Like.. negative debt? I don't know.
The math makes sense so I suppose I'll leave the negative number.
formal egret
My issue is how exactly would credit card debt go into the negative?
It can’t
atomic hazel
But shouldn't each symmetrical marking on both sides provide the mean when combined and divided by 2?
If the marking was typed as a 0 instead of -38, then I wouldn't be able to reverse engineer it if the question was "find the mean"
It seems wrong either way
formal egret
Yeah you’re right
atomic hazel
🤨
formal egret
All your math checks out
atomic hazel
I think I'll mention my confusion in my answer, but the negative answer seems more truthful to how empirical rule works, even if it conflicts with the word problem, which ultimately should only exist to provide a real-world application of the math.
Kind of ironic when understanding the word problem is more difficult than the actual math
bronze briar
x^5 can't appear in this when an expanded ,right?
cedar kilnBOT
x^5 can't appear in this when an expanded ,right?
bronze briar
i don't see how it possible can. The highest power will be x^12, and then the will decrease by increments of 3
still barn
If that’s the case then the term is 0x^5
cedar kilnBOT
@bronze briar Has your question been resolved?
marsh pond
cedar kilnBOT
marsh pond
Solve for x
Did I mess up somewhere?
4 needs to be multiplied with the both terms in numerator?
runic garnet
when u got to $\frac 14 = \frac {x-2}{x+2}$ why didnt u just cross multiply?
wraith daggerBOT
Stephen
tropic oxide
cedar kilnBOT
runic garnet
didnt even notice...time to sleep
cedar kilnBOT
Available help channel!
onyx sparrow
cedar kilnBOT
onyx sparrow
I know for A its about how many routes from city A to city B that take 2 flights, while for C its how many routes from city A to city B take no more than 2 flights
but im very stuck with D
cedar kilnBOT
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onyx sparrow
<@&286206848099549185>
cedar kilnBOT
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vast yacht
how do I find the limit definition of the derivative?
cedar kilnBOT
how do I find the limit definition of the derivative?
livid hound
you are given the definition
vast yacht
yes but I'm having trouble simplifying
I'll send my work in a sec
what do i do from here
livid hound
scribble bottom line
you didn't multiply properly/ didn't use sufficient parentheses
-((x+h)-1) isn't
-x+h-1
vast yacht
wouldn't it give me the same thing?
limber stag
wouldn't it give me the same thing?
no, not at all
vast yacht
limber stag
how on earth did you get there?
real flame
find the fourier half range even expansion of the function f(x) = (-x/l +1), 0<=x<=1?
limber stag
step 1 is to convert it all into a single fraction
limber stag
please help with this question
ask in an open channel
limber stag
step 1 is to convert it all into a single fraction
@vast yacht
real flame
ask in an open channel
where is that?
vast yacht
convert the thing I started with to a single fraction?
real flame
i dont have much time left
vast yacht
that's what I did by multiplying both the numerator and denominator with the factor of the denominators of the fractions in the numerator
and then I wanted to simplify from there but got stuck
limber stag
well, something went wrong in step 1, bc it should look like this:
then just multiply it out and things cancel convineiently
limber stag
-((x+h)-1) = -x-h+1
vast yacht
ohh i see what you mean
limber stag
once you get the top canceled, you should just have h on top, which cancels with the bottom
limber stag
great, you can replace h now
vast yacht
replacing h with the numbers given like -2 in f'(-2)?
limber stag
replacing h with the numbers given like -2 in f'(-2)?
h is the value the limit is approaching
vast yacht
0
limber stag
exactly
vast yacht
so i would just have -1/(x-1) and i would replace x with the number given
I think i get it
limber stag
so i would just have -1/(x-1) and i would replace x with the number given
correct
wait no
vast yacht
or -1/(x-1)^2 sorry
limber stag
yeah that
vast yacht
ok thank you
limber stag
you can check it by using desmos like this:
since f'(x) - ur function is 0, it's correct
cedar kilnBOT
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nova snow
I'm trying to graph the above function so I'm using desmos as a reference. How do I find the minimum value though?
nova snow
I have these values after finding f'(x)=0 from differentiating the polynomial
not sure what comes next
slate current
if you put that x value back into the original equation you should get the y values of where the slope is zero and then the smallest y value would indicate the absolute minimum no?
so now you have x where the slope changes, and then for any function you can find the y from just plugging it back in
kind of a tedious process with such a complicated number though but thats what calculators are for right 😅
nova snow
when I plug it in it equals 0 which supports the f’(x) = 0 thing unless I’m plugging it into the wrong thing
slate current
plugging in the x value to the first derivative gives you the slope at that point, where as plugging in to the original equation will give you the corresponding y value
does that make sense?
and then (where you are probably headed) plugging in any x value to the second derivative will give you a negative or positive value for negative or positive concavity
but basically itll always come back to the first equation if it asks you for a important point on the graph
nova snow
I get 5.6688… when I plug it back into x^2(x+3)(x-1) and -0.79 which doesn’t sound right to me
slate current
this is what I was able to get, are you sure you are plugging the value into the calculator correctly?
and then in this scenario the -12.39 would be absolute minimum and the -.5446 would be local minimum
gentle flower
I'm trying to graph the above function so I'm using desmos as a reference. How d...
desmos supports functions, you can write it as f(x) = .. then just use the x you want on another line, like f(2), it supports derivatives as well, you can use f’(x)
you can plot the slope function as well
slate current
and then in this scenario the -12.39 would be absolute minimum and the -.5446 wo...
these would then be set as points in your answer (-2.18, -12.39), (.68, -.54) these are obviously approximate
nova snow
Hm I must have inputted something wrong then.
nova snow
It’s a Casio model I believe
nova snow
this is what I was able to get, are you sure you are plugging the value into the...
But that result makes more sense then
slate current
there should be a way to do fractions like i did it which should clean up your calculator when dealing with weird ratios and such id try looking it up?
nova snow
Yeah had to have been a misinput on my end or something, but that all makes sense now
Thanks
slate current
Amazing, I’m off to bed but if you need any more help ill be back up in like 7 hours so just lmk
nova snow
Alright cheers
crimson sedge
hi
livid hound
since you're doing stuff AP/GP
try to determine whether you have an arithmetic or geometric series
livid hound
what did you try doing
livid hound
show work
tropic oxide
,calc 0.29088*5.05/1.212^2
wraith daggerBOT
Result:
1
hm interesting
crimson sedge
,calc 0.29088*5.05/1.212^2
what's this
crimson sedge
show work
i was unable to calculate formally but we are not allowed to use calculators in exams
i just used it to find the common ratio
livid hound
cruel to make you do tedious calculations like this
i was unable to calculate formally
wdym
crimson sedge
i am good with algebraic calculations but not those basic ones
crimson sedge
> i was unable to calculate formally
wdym
i mean to find the common ratio , its tedious with such numbers
livid hound
if you were allowed access to a calculator, would you be able to do it
livid hound
and confirm the type of series you have
crimson sedge
yeah its a geometric progression
livid hound
but not those basic ones
that's something you'll need to work on
crimson sedge
hey i need some advice
livid hound
if you don't like doing long division, long multiplication is nicer to work with
crimson sedge
what according to you is pre requisites to learn calculus and possibly master it
livid hound
5.05/1.212 = 1.212/0.29088 iff
0.29088 * 5.05 = 1.212^2
showing whether these two products are equal should be easier than the alternative
crimson sedge
5.05/1.212 = 1.212/0.29088 iff
0.29088 * 5.05 = 1.212^2
showing whether these tw...
yeah
true
livid hound
pre-req would be
basic algebra
functions
exponents/logs
geometry
trigonometry
crimson sedge
functions at what level ?
livid hound
polynomials
crimson sedge
pre-req would be
basic algebra
functions
exponents/logs
geometry
trigonometry
conic sections ?
livid hound
familiarity with function notation
crimson sedge
polynomials
would they be enough to solve physics problems which require familiarity with calculus 3
livid hound
you'd need to know calc 2 before calc 3
crimson sedge
like differential equations
crimson sedge
you'd need to know calc 2 before calc 3
ofcourse but i have recorded lectures in this sequence , functions 》limits 》 continuity , differentiability 》 then application of derivatives and definite indefinite integration and then application of integrals and finally differential equations
drowsy veldt
what grade y all iinn?
crimson sedge
so if i watch lectures in this sequence would it be easy to learn have a good grasp on calc ,i really need it for physics
crimson sedge
yeah ive had enough practice of aljebra and trig
@livid hound do you think learning complex numbers deeply before starting with calculus is a good idea
livid hound
can be learned concurrently
crimson sedge
i don't get much time to do math all day , I've to do tedious syllabus of chemistry and physics along with math :(
that's why learning one thing at a time suits my current situation
wary hamlet
cedar kilnBOT
wary hamlet
how do i do this
tropic oxide
do you know what a geometric series is in general
wary hamlet
ive did the working out
im getting a =1
but i think i did soemhting wrong on the way
ok nvm
i got it
.close
cedar kilnBOT
cedar kilnBOT
Available help channel!
fervent notch
need help trying to derive a quadrature rule for this
cedar kilnBOT
need help trying to derive a quadrature rule for this
@fervent notch Has your question been resolved?
grizzled hamlet
can someone help me in this sum
cedar kilnBOT
can someone help me in this sum
steel heart
grizzled hamlet
X+X=4
grizzled hamlet
THEN WATS X+Y=9
round nexus
bro
steel heart
!nosols
cedar kilnBOT
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
round nexus
ok
i can't tell the solution
i got it
so
X+X=4
you know that both X are the same number
yeah
so something + something = 2 (turning around)
surreal cave
@grizzled hamlet (sorry for ping)
grizzled hamlet
thank u@gaut
round nexus
you got it ?
proud root
hi im new here
steel heart
surreal cave
hi im new here
hello, please go to #discussion to talk or go to #❓how-to-get-help if you have a question
steel heart
come talk there
proud root
ok thx
cedar kilnBOT
@grizzled hamlet Has your question been resolved?
steel heart
.close
solid latch
Hey, I’m confused on how to complete this differentiation by first principle
digital cliff
just evaluate the limit and simplify and you should get what you want
wild stone
im a bit confused on the last line, because it had been stated that there is also a case where no there isn't any f(a) = b
wild stone
.close
bitter pollen
cedar kilnBOT
bitter pollen
Have i done it corretly?
the question is find the general solution for 10d^2y/dx^2-3dy/dx-y=0
woeful abyss
Does anyone know how to solve this, Im really lost as to what to even do
cedar kilnBOT
Does anyone know how to solve this, Im really lost as to what to even do
@woeful abyss Has your question been resolved?
cedar kilnBOT
@woeful abyss Has your question been resolved?
lean sable
Does anyone know how to solve this, Im really lost as to what to even do
as the body is in equilibrium
net force on it should be zero
and net torque also should be zero
untold locust
cedar kilnBOT
lean sable
ahh
lean sable
momentum before collision = momentum after collision
untold locust
what
lean sable
you know what is momentum?
south tundra
Conservation of energy?
lean sable
nah
untold locust
aaaaaaa
crimson sedge
momentum is mass * velocity
untold locust
please teach it to me
untold locust
momentum is mass * velocity
oh
south tundra
You shouldn’t be doing this without knowing any conservation laws though
untold locust
im a stay at home student
lean sable
go watch some yt then, many tutors available there
untold locust
i cant go to school because of broken bone on feet
untold locust
Your teacher’s fault again?
it is though
untold locust
can you guys just teach it to me ?
lean sable
or physics wallah
untold locust
cause i feel like you guys can teach it better
lean sable
just know that momentum is mass x velocity
untold locust
ok so what do we do tho
lean sable
total momentum before collision is same as after collision
untold locust
.
lean sable
balance it
crimson sedge
untold locust
total momentum before collision is same as after collision
what's total momentum
lean sable
momentum of both bodies together :/
untold locust
but they arent touching
lean sable
untold locust
if they're not touching or touching they're still considered as one and i ned to get the sum of their momentum?
lean sable
ys
untold locust
do i mulply or add
untold locust
dam
i'll just have to fail
i have no choice
i mean the answers are on google
but when the exam comes i wont have access to google
.close
untold locust
nahhh bruh
cedar kilnBOT
nahhh bruh
untold locust
@lean sable
i was learning from yt and it said something needs to have mass and velocity
it needs to weigh something and it needs to be moving also
how do i calculate the momentum if they aint moving
crimson sedge
if it is not moving it has no momentum
crimson sedge
no, you can for the first question but cannot for others
crimson sedge
because in the first question even after the explosion the bodies does not move, but it does in the rest of the questions
untold locust
wait i have a guess for number for
4
i guess 20
is that right?
i just used 5 braincells for that
crimson sedge
no it is -20 m/s since it is velocity
untold locust
whattttttttt
crimson sedge
cm/s*
crimson sedge
they denote the direction
crimson sedge
both the bodies after explosion moves in the opposite direction
untold locust
why is that
cause it exploded?
right here correct me if im wrong but i believe the truck has 20m/s?
crimson sedge
yes you can assume like that, but mathematically the momentum of the both bodies should be equal and opposite so the total is zero which is the sum of initial momentum of the bodies
untold locust
but t the same time idk cause like it seems slower than the car
untold locust
yes you can assume like that, but mathematically the momentum of the both bodies...
ahhh
15
wait
crimson sedge
the readymade formula is M1u1 + m2u2 = m1v1 + m2v2
crimson sedge
one sec will type it
untold locust
ok
crimson sedge
i am slow in typing
untold locust
i see
crimson sedge
M1= mass of first object, u1 = the initial velocity of the first object ,m2= mass of second object, u2 = the initial velocity of the second object
untold locust
oooooooooo
untold locust
right here correct me if im wrong but i believe the truck has 20m/s?
right here
m1 is 3000kg
u1 is 10m/s
and m2 is 1000kg and u2 is 0m/s
correct?
crimson sedge
v1= is the velocity of the first object after collision or explosion , v2= is the velocity of the second object after collision or explosion
untold locust
ooh
crimson sedge
yes that's it !
untold locust
collision?
crimson sedge
after
crimson sedge
yes
untold locust
right here correct me if im wrong but i believe the truck has 20m/s?
this as an example
untold locust
the readymade formula is M1u1 + m2u2 = m1v1 + m2v2
how do i apply this
crimson sedge
just substitute the give values in their place and find the unknown
crimson sedge
yes now find the missing value
untold locust
ok i'll try
i do
3000 x 10
30000
then + 1000
31000
then on the other side
crimson sedge
no
untold locust
what
crimson sedge
1000*0 = 0 right?
crimson sedge
dont forget to use bodmas
crimson sedge
yes
crimson sedge
no
untold locust
what
crimson sedge
(30000-15000)/3000
untold locust
ohhhh we minus
crimson sedge
yes
crimson sedge
yes thats it !!
cedar kilnBOT
@untold locust Has your question been resolved?
flat kayak
My class is Precalculus and we are doing Average Rate of Change. I need help trying to solve this one equation i'm stuck on with a variable
flat kayak
Find the ARC of F(x)=8x^2-7 from the intervals [1,t]
dire geode
Find the ARC of F(x)=8x^2-7 from the intervals [1,t]
t is a variable?
flat kayak
yes
flat kayak
yeah I'm at that part