#help-13

1 messages · Page 103 of 1

lethal bison
#

,rotate

wraith daggerBOT
dire geode
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missing a square on the (y^2 - x^2) term

lethal bison
#

that's true

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I see it now thanks

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.close

cedar kilnBOT
#
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amber willow
#

Is there any nice mathematical notation I can use to denote a 3x3 "block" of a 9x9 matrix? Same idea as a sudoku board, just need to define it mathematically.

amber willow
#

Here's what it currently is.

cedar kilnBOT
#

@amber willow Has your question been resolved?

cedar kilnBOT
#

@amber willow Has your question been resolved?

cedar kilnBOT
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@amber willow Has your question been resolved?

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royal light
#

can someon explain how this is answer A and not B

royal light
#

because i thought f(xi) = f(a + i(deltax))

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and is a not = 1 here?

granite knoll
#

<@&268886789983436800> obvious troll

radiant topaz
#

Google that shit

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Troll

royal light
#

cuz isnt (b-a)/n = 1

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1/n

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so b-a = 1

radiant topaz
#

Ok and?

royal light
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and xi = a + i(deltax)

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and it says 1 + i/n

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so is a = 1?

radiant topaz
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Alright but have you considered the whole expression?

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The sum is not over i/n

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We take sum over f(x_i)

royal light
#

ya ik

radiant topaz
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So what actually is f(x_i) here

royal light
#

sqrt(ln(xi))

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am i wrong?

radiant topaz
#

Alright if the x_i = ln(1 + (i/n)) then?

royal light
#

is it because they have ln(1 + x) in the definite integral that makes it so xi = i/n making a = 0

radiant topaz
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Yeah x_i = i/n

royal light
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ok

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also

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how would i do this

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ive done this so far

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but i dont know if its even right

wraith daggerBOT
royal light
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i understand that

radiant topaz
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Taking i=0

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i=n gives i/i=1

wraith daggerBOT
royal light
#

yes i know

royal light
radiant topaz
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Sure

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Ok wait lemme writ it properly

royal light
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i messed up

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it should be this

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what

wraith daggerBOT
radiant topaz
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Alright this

royal light
#

what even is that

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ok nvm i think the answer they gave is just wrong

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.close

cedar kilnBOT
#
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radiant topaz
royal light
#

did you get 51 as your answer

cedar kilnBOT
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royal light
#

.open

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@radiant topaz did u get 51 as your answer

royal light
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cuz if not then my answer key is just wrong

radiant topaz
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Wait then

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,w sum (1 + xn)³ + 2(1+xn) + 1 from 0 to 3

royal light
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i used calculators online and it gave me 81.75

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which is what i got

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but thats not what my answer key says

radiant topaz
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Don't

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x0 = 1 , x1=2 , x2=3

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x3=3

royal light
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bro

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did u get 51 as your answer?

radiant topaz
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Just wait akash

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,w sum (1+n)³+2(1+n)+1 from n=0 to 3

wraith daggerBOT
royal light
#

if a function is continous on [a,b] then Ln = Rn

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and i found Rn

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and Rn = 81.75

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bro 124 isnt even an answer

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just wasting my tim

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.close

cedar kilnBOT
#
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radiant topaz
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I'm not here to give out answers, I gave you explaination

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,w sum (n)³+2(n)+1 from n=1 to 4

royal light
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bro this still dont even equal 51

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and its over the wrong inteval

radiant topaz
#

Atleast give me some time to figure out

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You are on my ass the whole time

wraith daggerBOT
cedar kilnBOT
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radiant topaz
#

The options may be wrong

cedar kilnBOT
radiant topaz
#

,w integrate (x³+2x+1) from 1 to 4

wraith daggerBOT
cedar kilnBOT
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@radiant topaz Has your question been resolved?

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hardy isle
#

Yo

cedar kilnBOT
hardy isle
#

Help

north wyvern
#

@hardy isle type .close in this one

crimson sedge
#

.close

cedar kilnBOT
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bronze briar
cedar kilnBOT
bronze briar
#

not to sure on this

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i did (10C2)(10C3)(10C5)

cedar kilnBOT
#

@bronze briar Has your question been resolved?

bronze briar
#

<@&286206848099549185>

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dreamy zealot
#

Hi!

cedar kilnBOT
dreamy zealot
#

I need some help using Wolfram Mathematica

#

when plotting a piecewise function there is a "true" statement in there, could that be avoided?

cedar kilnBOT
#

@dreamy zealot Has your question been resolved?

cedar kilnBOT
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@dreamy zealot Has your question been resolved?

cedar kilnBOT
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crimson sedge
#

In the accompanying figure of triangle ABC, a =10 b=10 and the measure of angle A is 75 degrees. find the area of triangle ABC

crimson sedge
tropic oxide
#

MS Paint?

crimson sedge
#

nope

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lol

tropic oxide
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ok nvm

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!status

cedar kilnBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
crimson sedge
#

1

crimson sedge
# tropic oxide ok nvm

what im thinking is since there are 2 conguruent sides and since of them is already 75 degrees

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im thinking angle B is also 75 degrees

tropic oxide
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that sounds more like status 2 to me.

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yes, triangle ABC is isosceles. yes, angle B is 75°.

crimson sedge
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i dont know what to do after that tho

crimson sedge
tropic oxide
#

draw the altitude from C onto AB

crimson sedge
tropic oxide
#

wonky

crimson sedge
#

hahaha

tropic oxide
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call the other end of that H

crimson sedge
#

ok

tropic oxide
#

look at triangles ACH and BCH

crimson sedge
#

ok

crimson sedge
#

but not getting anywhere

tropic oxide
#

heres a neater reproduction of your diagram

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triangle ACH is a right triangle

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

cedar kilnBOT
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loud forum
#

A cylindrical tank with the radius of 5m is being filled with water at of 3 m^3/min. How fast is the height of the water increasing?

tame wraith
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you know that

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V = pi * r^2 h

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use chain rule

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dh/dt = dh/dV * dV/dt

loud forum
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we use chain rule on the Volume equation?

tame wraith
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if anything you should, because if it were a

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pyrimid

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youd need to use chain rule

loud forum
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Then how do I find V

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Because we don’t get a value for V

tame wraith
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@loud forum what are you doing

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if youre differentiating both sides by t

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which also works

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v turns into dV/dt

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you still need to use product rule

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for

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r^2 h

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dr/dt is 0 anyway

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since cylinder has a constant radius

loud forum
#

Am I using chain rule for the product rule?

tame wraith
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yh you still use chain rule

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but its irrelevant here

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since r is a constant

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you dont even need to use product rule

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just differentiate the V and h

loud forum
#

Ignore the highlighted parts, that’s for different problem

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But we do need to plug in r no?

tame wraith
#

just because you need to plug in r, doesnt mean its not constant

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also you didnt do prduct rule right to begin with

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should be r^2 dh/dt

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what is dr/dt then.

loud forum
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Derivative of r?

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sorry professor was really “skim” about this chapter

tame wraith
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but i mean

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literally

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what is dr/dt

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dV/dt is 3 m^3/min

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what do you think dr/dt is

loud forum
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that’s dr/dt

tame wraith
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no

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thats not

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do you think

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the radius of the cylinder

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is changing

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over time

loud forum
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oH wait it doesn’t

loud forum
tame wraith
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?

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where did your dr/dt go

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should be 2r dr/dt h + r^2 dh/dt

loud forum
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accidentally deleted it-

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So I plugged my numbers

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what is dr/dt

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Again, the radius doesn’t increase

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so what number do I put as my dr/dt

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we also don’t get a specific height

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so then it’s remains as h

tame wraith
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@loud forum didnt we literally establish

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that the radius doesnt increase

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so dr/dt = 0

loud forum
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oh shit mb bro

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oh so that cancels out

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dh/dt = 3/25

tame wraith
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@loud forum you forgot the pi

loud forum
#

Didn’t the Pi cancel

tame wraith
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no

loud forum
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cuz of derivative-

tame wraith
#

the actual product rule was

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2 pi r dr/dt h + pi r^2 dh/dt

loud forum
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oHhHhH because pi multiplies to the other two

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I just forgot to add it-

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thanks a lot

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figured it out thanks to you bleakkekw KEK

radiant topaz
#

You're welcome

cedar kilnBOT
#

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sudden robin
#

I am stuck in obtaining the three pythagorean identities using pythogorean theorem. Any help is appreciated

royal loom
#

What have you tried

sudden robin
#

I have no idea what to do really

royal loom
#

have you atleast wrote out the pythagorean theorem

sudden robin
#

yeah i did

royal loom
#

and drawn the triangle it relates to

sudden robin
#

yeah

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but don’t know how to derive pythogrean identities from it

royal loom
#

hmmm

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Try drawing out the unit circle

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where x^2+y^2=1

sudden robin
#

alright

royal loom
#

And from that, use SOHCAHTOA. Relating to an angle inside the unit circle, what is cos(theta) and what is sin(theta)

sudden robin
#

oh ok

royal loom
#

let me know what you think cos(theta) and sin(theta) are

sudden robin
#

i think i got how to solve this question. thank u tho

royal loom
#

oh nice! no problem

cedar kilnBOT
#

@sudden robin Has your question been resolved?

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steep umbra
#

How to approach problem 19?

cedar kilnBOT
stray drift
steep umbra
#

In each wallet i will place 2^0 2^1 2^2 ...... 2^7

stray drift
#

Yes

steep umbra
#

Thanks for helping

tropic oxide
#

up to 2^6 though

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2^7 is 128. you don't have that much.

steep umbra
#

Oh yea

#

I miss counted didnt take 0 into acc

#

Thanks

#

.close

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crimson sedge
#

$\frac{d^2}{dt^2}X(t)=\frac{kX_2-kX(t)}{[(X_2-X(t))^2+(Y_2-Y(t))^2][|X_2-X(t)|+|Y_2-Y(t)|]}$

wraith daggerBOT
#

! R4MP4G3

crimson sedge
#

Not sure where to start with the above equation and the absolutes throw me off

cedar kilnBOT
#
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crimson sedge
#

.reopen

cedar kilnBOT
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spiral orbit
#

Domains and Ranges of composite functions

cedar kilnBOT
spiral orbit
#

what's e asking?

#

im confused

river nexus
#

hello i need help

#

in this sum

spiral orbit
#

channel's taken bruv

river nexus
#

means?

spiral orbit
river nexus
#

😶

spiral orbit
#

lmao

#

anyway

cedar kilnBOT
#

@spiral orbit Has your question been resolved?

spiral orbit
#

<@&286206848099549185> hi

#

: )

#

i dont get F

cedar kilnBOT
#

@spiral orbit Has your question been resolved?

cedar kilnBOT
#

@spiral orbit Has your question been resolved?

spiral orbit
#

.close

cedar kilnBOT
#
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fickle ermine
#

if V is a finite dimensional vector space and T: V -> V is onto, then T is one to one.

fickle ermine
#

I know if T is linear, T is onto <=> T is one to one

#

but the problem doesn't give T is linear. I have no idea pls give some hints

quartz frost
#

What is t? Only T was given

fickle ermine
#

no it is True/false example

quartz frost
#

But what is t? The same as T?

fickle ermine
#

yes

#

it was typo

quartz frost
#

f(x)=x^3-x
f has roots x=0, x=1, x=-1

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f is definetely onto

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But not one to one as the kernel is not empty

tropic oxide
fickle ermine
#

@tropic oxide Why?

quartz frost
#

I gave a counter example

fickle ermine
#

oh i got it

quartz frost
#

Let V be the natural numbers
f(1)=f(2)=0, for other x: f(x)=x-1
f is onto but not one to one

fickle ermine
#

yes Thank you I really understand

sacred grail
#

natural numbers isn't a fd vector space usually thonk

fickle ermine
#

thanks for counter example

quartz frost
#

True

fickle ermine
#

.close

cedar kilnBOT
#
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fickle ermine
#

.reopen

cedar kilnBOT
#

fickle ermine
#

.close

cedar kilnBOT
#
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summer sandal
#

Find an equation of the tangent to the curve at the point corresponding to the given value of the parameter.
x = t^4 + 2
y = t^3 + t
t = 1
y(x) =

summer sandal
#

@uncut veldt I NEED HEELP

quartz frost
#

y=mx+b

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Lets start by getting m

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m=dy/dx at t=1

summer sandal
#

yes

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so would i plug in 1

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in t

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or would i first do the deritive

quartz frost
#

We should first get dy/dx

#

If we get dy/dt and dx/dt we can do one of the following:
Rewrite to get dy and dx and then get dy/dx
Or do dy/dt / dx/dt

#

Both works

summer sandal
#

so it owuld be 4t^3

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3t^2+1

quartz frost
#

dy/dt = 3t^2+1
dx/dt = 4t^3
Yes

#

That way we get dy/dx

summer sandal
#

so now would i plug in 1

quartz frost
#

Once you have dy/dx, ye0s

#

<@&268886789983436800>

#

Thx

summer sandal
#

can you show me dy/dx

#

how to get it

quartz frost
#

dy/dt / dx/dt = dy/dx * dt/dt = dy/dx

#

Because dt/dt=1

#

Alternatively we can do:
dy/dt=3t^2+1
Therefore
dy=(3t^2+1)dt
For dy we get dx=4t^3dt
dy/dt=(3t^2+1)dt/4t^3dt=(3t^2+1)/(4t^3) * dt/dt
And here again dt/dt=1

summer sandal
#

-3(t^2+1)/4t^4

quartz frost
#

(3t^2+1)/(4t^3)

summer sandal
#

i did the quiotent rule to that

quartz frost
#

Quotient rule?

summer sandal
#

yea

#

to find the deritice of that

quartz frost
#

We are not really differentiating here

summer sandal
#

ahhh ok

quartz frost
#

we already have dy/dx via rearraging

summer sandal
#

ok, so what next

quartz frost
#

We only needed to differentiate y and x with frespect to t

#

Now we put in t=1

summer sandal
#

it is 4/4 so 1

quartz frost
#

Yes

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m=1

summer sandal
#

ok

quartz frost
#

y=mx+b

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Now we need b

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y=x+b

#

To do that we have to get a pair of x and y

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We can get them by putting t=1 into y(t) and x(t)

summer sandal
#

so the equation we started with?

quartz frost
#

Yes

summer sandal
#

x=3 y = 3

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2

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y=2

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x= (1)^4+2=3

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y=(1)^3+(1)

#

=2

#

@quartz frost ?? is that correct??

quartz frost
#

Yes,y=2 and x=3

#

We had
y=x+b

#

Therefore b=y-x

summer sandal
#

so -1

quartz frost
#

Yes

summer sandal
#

so it is y=(1)x-1

#

thanks

quartz frost
#

Yes

summer sandal
#

have a great daty

quartz frost
#

👍

summer sandal
#

.close

cedar kilnBOT
#
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#
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austere widget
#

Hi there, I am a student trying to tweak the physics equation for moment of rotational inertia (MOI) such that I can calculate it for my object. As my object is a complex rigid body, I am attempting to use the MOI formula for a cuboid to derive the MOI for my object. Normally you would convert dV into the volume of the cuboid, but here I am manipulating it such that dV is the [Volume of cuboid - Volume unoccupied by object]. This way I would not need to figure out the algebraic equation of my object.

My current problem is that I'm not sure if I am integrating it correctly or if there is a better way as this is beyond my level. To anyone that replies thank you!

austere widget
#

This is my reference pic

#

if it helps this is how one of my objects look like, it's a waterwheel

#

<@&286206848099549185> sorry for the ping guys!

cedar kilnBOT
#

@austere widget Has your question been resolved?

austere widget
#

<@&286206848099549185>

mental trail
#

I'll repost my message here. @austere widget You need more variables than r. The radius of the semi circles is required at least

austere widget
#

Here are its dimensions

#

they arent exactly semicircles, more like ellipses tho,

#

the depths that I have are 0.00cm, 0.25cm, 0.50cm, 0.75cm, 1.00cm, 1.25cm, 1.50cm, 1.75cm

#

Here's how i created the blades (ellipses)

cedar kilnBOT
#

@austere widget Has your question been resolved?

crimson sedge
#

pi(ab) - pi(a' b')

austere widget
#

the problem is im not sure how to take into account the portion that overlaps with the circle at the center

#

lemme make another diagram

crimson sedge
austere widget
austere widget
#

this is for a physics report

#

and somehow i got to math

#

💀

crimson sedge
#

im not sure how to account for the overlapped portions but as far as i can see

#

i cant really draw it and send but if you can notice then assuming that the ellipse is a perfect semi-ellipse the circle cuts out an approximately triangle shaped component

#

if you want accuracy to some degree you can use this approximation, im not sure how would we be precise about it tho

austere widget
#

yeah i did consider finding the overlapping component with arc area hmmm maybe ill try again

cedar kilnBOT
#

@austere widget Has your question been resolved?

cedar kilnBOT
#
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cedar kilnBOT
#
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lament yoke
#

hi!i have got a question:how do u calculate the sine in a non-right triangle?

crimson sedge
#

do you have an example?

#

perhaps you are talking about the sine law?

lament yoke
#

yeah,that's where this question comes from

#

i noticed that when took solely the sine ,calculating it independently

#

that could be any sine in a non-right triangle

humble marsh
#

the sine is a property of an angle, not the triangle

#

you can use right triangles to calculate it

lament yoke
humble marsh
#

can you give the example that prompted the question?

lament yoke
#

there's an exercise,don't know where it is ,but basically

#

there was a given line and an angle

#

i don't remember if the sine or some other angle was required

#

but since it's the sine law

#

i get it

#

but the second one ,I was just wondering how could u calculate it on its own?

gleaming cloud
#

Power series

lament yoke
#

and how do u do that?

gleaming cloud
#

sinx = x -x^3/3! + x^5/5! - ...

lament yoke
#

where does that come from?

gleaming cloud
#

Calculus

lament yoke
#

I have never encountered that form

gleaming cloud
#

Yes it's quite surprising the first time you see it

#

It's quite nice

lament yoke
#

I'm in high school,plenty of things r unseen by my eyes

#

what theorem was that over there?

gleaming cloud
#

Not really a theorem but it's called power series

#

That's the way we normally define sin

#

And there's a way to relate this to the geometric picture

lament yoke
#

interesting

#

perhaps,when i get to this form,Math will be taught as more than just formulas

#

thanks

#

.close

cedar kilnBOT
#
Channel closed

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cedar kilnBOT
#
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marsh pond
cedar kilnBOT
marsh pond
#

I want to identify the location and maximum value

#

any reason for doing f'(0)?

tropic oxide
#

no

marsh pond
#

f'(0) is where the slope is 0, i thought?

tropic oxide
#

no

#

f'(0) is the slope at x=0

marsh pond
#

oh

tropic oxide
#

confusing input with output

marsh pond
#

that makes sense

#

yeah, it's the input of the derivative

#

so it would refer to the x value only

#

x=0

#

but here I wanna set it y itself EQUAL to 0

#

of the derivative

#

not sure if i worded that correctly

#

I wanna set the derivative equal to 0? or y equal to 0?

#

i think if I set the derivative equal to 0 it would be f'(x) = 0

tropic oxide
#

you yourself do not know what you want to do

marsh pond
#

lol

#

ya pretty much..

#

i need to identify the location and maximum value of the function

#

so first i find the derivative

#

then i set the derivative equal to 0 to find the x=something value, which is the local max or min

flint plinth
#

haven't you already done that?

#

just cross out the last line, everything else is ok

#

(you should probably explain why x=8 corresponds to a local max and not a local min)

marsh pond
#

then i set the derivative equal to 0

#

i think my wording is incorrect here

#

i replace f'(x) with 0?

tropic oxide
marsh pond
#

oh OK

dull oxide
tropic oxide
#

you've set the derivative equal to 0 and you have found the x coordinate at which it equals 0

mental tide
#

you wanna find fx s max value right

marsh pond
#

so therefor it must be a max or min

#

or another word, can't remember

#

like x^3 at origin

#

inflection point?

halcyon marlin
#

is only local

marsh pond
#

and it may not even be local max

#

there could be multiple curves

#

so i gotta test them all to see which one is higher/lower

#

if it's a really long polynomial

royal loom
#

I heard we needed more helpers

crystal raptor
#

Assemble

mental tide
mental tide
#

If i understood what you wanna find thats the answer

marsh pond
#

ppl will get upset for answers, just warning you

tropic oxide
cedar kilnBOT
# mental tide

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

violet night
#

I don't even understand what your problem is, you found the what x corresponds to the stationary point , you understand the relation between f(x) and f'(x)

mental tide
#

Oh i didnt know that

mental tide
#

Should i delete it?

marsh pond
#

but now it makes sense

mental tide
#

f(x)=y=0

halcyon marlin
#

its pretty easy to do control for this stuff

#

,w 16x-x^2+5 local max

mental tide
#

If its f'(0) then just put 0 on x-s you will find it

mental tide
#

Yea thats it

marsh pond
#

not y=0

halcyon marlin
#

compare answers and you will 'remember' which is correct again

mental tide
marsh pond
#

i'm replacing the derivative with 0

#

and finding the value of x that causes it to be true

mental tide
#

Then f(0)=x

mental tide
marsh pond
#

.close

cedar kilnBOT
#
Channel closed

Closed by @marsh pond

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#
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smoky trench
#

Hello

cedar kilnBOT
smoky trench
cedar kilnBOT
#

@smoky trench Has your question been resolved?

cedar kilnBOT
#
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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

crimson sedge
#

C

cedar kilnBOT
crimson sedge
#

@worthy ferry because I can't be checking discord 24/7

granite knoll
#

!show

cedar kilnBOT
#

Show your work, and if possible, explain where you are stuck.

west gazelle
#

@crimson sedge how old are you ?

crimson sedge
#

14

crimson sedge
granite knoll
#

combine like terms

crimson sedge
#

So just remove parentheses

#

And combine like terms

granite knoll
#

yes

crimson sedge
#

And sort by highest to lowest degree

granite knoll
#

you don't need to sort anything

crimson sedge
#

Ok

#

What would y²+y² be

#

Both negative

granite knoll
#

what do you think it would be?

#

so "-y^2 - y^2"

crimson sedge
#

-2y²

granite knoll
#

yes

crimson sedge
#

Why is this wrong

granite knoll
#

you didn't do your arithmetic correctly. the minus sign in front of the second parentheses applies to all those terms

#

not just the first one

crimson sedge
#

Ohhhhhhhhhh

#

So it would make 5 positive right?

#

And 2

granite knoll
#

yes

crimson sedge
#

Thanks

#

I double checked my work and I still don't know what I did wrong

granite knoll
#

where did the "a^2" come from?

crimson sedge
#

3a times a

#

Oh crap I'm doing it wrong

granite knoll
#

you aren't multiplying those two

crimson sedge
#

So I remove parentheses

#

And add up like terms

#

?

granite knoll
#

yes

crimson sedge
#

Ohh

#

Would x²+2x² = 3x²?

granite knoll
#

yes

crimson sedge
#

Here would I just distribute both numbers into both other numbers?

granite knoll
#

you would use "FOIL", if you've learned that

#

but yea, it's distributivity

crimson sedge
#

Ah I see

#

What would I do here

granite knoll
#

what would be your guess?

crimson sedge
#

I don't know but I'd say remove parentheses

granite knoll
#

no, there's an exponent there

crimson sedge
#

Distribute to 13 and b?

granite knoll
#

what do you mean? do you know what the exponent "2" means there?

crimson sedge
#

No

granite knoll
#

$x^2 = x \cdot x$

wraith daggerBOT
#

cwatson

crimson sedge
#

Uh?

#

So (b+13)x•x

granite knoll
#

no, the "x" was just an example. the "2" means "squared" and it means you multiply something by itself

#

so $(b + 13)^2 = $ what

crimson sedge
#

I'm lost

granite knoll
#

you have to multiply (b + 13) by itself. does that make it more clear?

crimson sedge
#

So (b+13)(b+13) ?

granite knoll
#

yes

crimson sedge
#

So b²+169?

#

Or would I use FOIL

granite knoll
#

no, use "FOIL", the same as your previous problem

crimson sedge
#

Ok

#

B²+26b+169

granite knoll
#

yes

crimson sedge
#

What does the =0 at the problem represent

granite knoll
#

oh actually I hadn't noticed before

crimson sedge
#

Oh

granite knoll
#

you need to solve for "b"

#

so for what value(s) of "b" will that equation equal 0

crimson sedge
#

B and -b?

granite knoll
#

no, you need to find a number

#

$(b + 13)^2 = 0$. or $(b + 13)(b + 13) = 0$

wraith daggerBOT
#

cwatson

crimson sedge
#

How would I find a number

#

?

granite knoll
#

how can you get 0 from multiplying two numbers

crimson sedge
#

If one is 0

granite knoll
#

yes

crimson sedge
#

So how would that help

granite knoll
#

think about it

#

how can you get 0 from that equation?

crimson sedge
#

Ok

#

I honestly don't know

granite knoll
#

you don't know how to solve b + 13 = 0

#

?

crimson sedge
#

-13 both side

granite knoll
#

yes

crimson sedge
#

So where would I use that

granite knoll
#

what do you mean?

crimson sedge
#

Like where would I -13 both sides

granite knoll
#

what do you mean "-13 both sides"?

crimson sedge
#

Wait

granite knoll
#

look at the original equation. Plug in b = -13. what do you get?

crimson sedge
#

Oh

#

0

#

So what would the answer be

granite knoll
#

...you just found the answer...

crimson sedge
#

Oh

#

How would I do this because I'm stuck

#

So I distribute the 2y first

granite knoll
#

no

#

it's kinda similar

#

you have 3 numbers multiplied together. how can you get 0 from that?

crimson sedge
#

If 1 = 0?

granite knoll
#

no... 1 does not equal 0

crimson sedge
#

If one of the numbers = 0?

granite knoll
#

yes

#

so you set each of them equal to 0, and solve for "y"

crimson sedge
#

So I would make 3 different equation?

granite knoll
#

yes

crimson sedge
#

Without parentheses right?

granite knoll
#

it won't matter

crimson sedge
#

Ok

#

Can you write the first equation to help

granite knoll
#

guess if you have to

crimson sedge
#

2y= 0

granite knoll
#

yes

crimson sedge
#

What about the second one

#

Because there's a constant

granite knoll
#

so? there are 3 terms, so 3 equations to solve for "y"

#

you have the first one already

crimson sedge
#

Y=0?

granite knoll
#

from the first equation, yes

crimson sedge
#

What about second one

granite knoll
#

what do you think the second one is?

crimson sedge
#

Y-9=0

granite knoll
#

yes

crimson sedge
#

I cant type y-9=0

granite knoll
#

you need to solve for y

crimson sedge
#

+9 both sides?

granite knoll
#

you should know how to solve "y - 9 = 0" by now, you've done a similar problem already

crimson sedge
#

-9y?

granite knoll
#

no

crimson sedge
#

Idk

granite knoll
#

,tex .alg lesson

crimson sedge
#

??

wraith daggerBOT
#

cwatson

granite knoll
#

read that

crimson sedge
#

Y=9

granite knoll
#

yes

crimson sedge
#

How did I not know that

#

Y=-4

granite knoll
#

yes

crimson sedge
#

How would I do this

granite knoll
#

do you have a textbook? or course notes or something? this is harder to teach

crimson sedge
#

Yes let me grab it

crimson sedge
#

Ok I'll watch

#

I'll do that later wow that's hard to understand

#

What do I do here

granite knoll
#

it's the same type of problem. it'd be helpful if you watched the video or checked out your book/notes

crimson sedge
#

(x+10)(x-10)

#

Would that be it?

#

It not I'ma go take a very long break

granite knoll
#

well y, but ye

crimson sedge
#

Alright I'ma close it u were a great helper

#

.close

cedar kilnBOT
#
Channel closed

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#
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acoustic plinth
#

pls*

#

can someone help me pla

cedar kilnBOT
#

Please don't occupy multiple help channels.

acoustic plinth
#

pls

#

like how did we add 1- 1/1+x^2. ?

runic garnet
#

Either close ur last channel or close this one

acoustic plinth
#

idk how to close it man

cedar kilnBOT
#

@acoustic plinth Has your question been resolved?

cedar kilnBOT
#

@acoustic plinth Has your question been resolved?

slow thicket
#

@acoustic plinth.close

slow thicket
cedar kilnBOT
#
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After 15 minutes, feel free to ping <@&286206848099549185>.
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crimson sedge
cedar kilnBOT
crimson sedge
#

I don't know where to start

languid bobcat
#

n(n^2 -9)

kindred violet
#

whats a common term that both n^3 and 9n have

crimson sedge
#

N

kindred violet
#

so then take out n from both terms

#

you get n(n^2-9)

crimson sedge
#

Ok now what??

#

Help

kindred violet
#

thats the awnser

#

wait nvm

#

@crimson sedge whats something that you can do to both x^2 and 9

crimson sedge
#

Umm

#

Add them?

kindred violet
#

you can square root both

crimson sedge
#

Ok

#

Square root of 9 is 3 square root of 2 is idk

wintry vault
#

$$\text{you can factor out n from both: }\$$
$$n^3-9n = n(n^2-9)$$

kindred violet
wraith daggerBOT
#

Talent Unlimited

kindred violet
#

if we have sqrt n^2-9

#

what is that

crimson sedge
#

I'm struggling

kindred violet
#

n(n+3)(n-3)

crimson sedge
#

Where did u get that from

kindred violet
#

when you multiply by the conjugate and its in the form x^1+-a

wintry vault
wraith daggerBOT
#

Talent Unlimited

kindred violet
#

(x-5)*(x+5)=x^2-25

#

same thing with x^2-9

wintry vault
kindred violet
#

(x-3)(x+3) xtimesx is x^2 -3timesx is -3x 3timesx is 3x so -3x and 3x cancel and -3times3 is 9

crimson sedge
#

Ok

#

Now what

kindred violet
#

if you multiply them together what do you get

#

n(n+3)(n-3)

crimson sedge
#

N9

#

9n

#

9n²

kindred violet
#

n^3-9n

crimson sedge
#

Oo

#

K

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

#
Channel closed

Closed by @stray marten

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#
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marsh pond
cedar kilnBOT
marsh pond
#

why is the height of the rectangle (h) equal to exactly the y value? 1-x^2

flint plinth
#

that's what "inscribed" means

marsh pond
#

the -x^2 itself has a maximum y value of 1

flint plinth
#

the upper corners of the rectangle just touch the function

marsh pond
#

i have never heard of it before

flint plinth
#

In geometry, an inscribed planar shape or solid is one that is enclosed by and "fits snugly" inside another geometric shape or solid. To say that "figure F is inscribed in figure G" means precisely the same thing as "figure G is circumscribed about figure F". A circle or ellipse inscribed in a convex polygon (or a sphere or ellipsoid inscribed i...

marsh pond
#

what about odd power polynomials?

#

x^3 + 1

dull oxide
flint plinth
#

well for that particular odd polynomial i don't think you could inscribe anything because it only crosses the x axis once

marsh pond
#

well, i guess it's hard to put a rectangle inside of that

#

yeah

flint plinth
#

but other cubics have three roots in which case you could

marsh pond
#

what about x^4 + 431

#

the height of max rectangle within that is x^4 + 431?

flint plinth
#

that one is always above the x axis

marsh pond
#

that is the exact value for height?

#

of the inscribed rectangle

#

interesting..

#

oh of course

#

that's when y = x

#

so it's where y and x meet, right?

#

at exactly the same point

#

so therefor, it must be a point on the graph

#

touching the line of the parabola

#

inscribed rectangle with maximum volume will always be using the point y=x

#

or maybe -y=x

#

if it's positive or negative parabola

#

.close

cedar kilnBOT
#
Channel closed

Closed by @marsh pond

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nimble relic
cedar kilnBOT
nimble relic
#

i get stuck after i move 3x

#

i did A but i got a question on the factoring out 5x-ax. For part B i need help

granite knoll
#

what are you stuck on for B

nimble relic
#

i get up to -8y=6-3x

granite knoll
#

how can you get y on its own

cedar kilnBOT
#

@nimble relic Has your question been resolved?

nimble relic
#

sorry for the long wait

#

i divide the -8

granite knoll
#

yes

nimble relic
#

now tho idk what to do next

#

ik you cant have a - denom

livid hound
#

ik you cant have a - denom
where are you getting that idea

nimble relic
#

my friend said you cant have a - denom so you multiply it

livid hound
#

its legal to have stuff like that in the denominator

#

though you should ultimately simplify/manipulate so that it doesn't

nimble relic
#

oh i got confused with square root

#

i tried getting help from photo math but it put the 8 twice

#

6/8 and 3/8

#

i dont get why its two separate fractions

cedar kilnBOT
#
Channel closed

Closed due to timeout

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nimble relic
#

.reopen

cedar kilnBOT
#

cosmic steppe
wraith daggerBOT
#

Umbraleviathan

cosmic steppe
#

I hope you know how fraction addition/subtraction works if you're doing linear equations

nimble relic
#

ohhhhhhhhhhh

#

forgot about that ngl

#

how do i close it

cold knoll
#

type .close

nimble relic
#

.close

cedar kilnBOT
#
Channel closed

Closed by @nimble relic

Use .reopen if this was a mistake.

#
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#
Channel closed

Closed due to the original message being deleted

cedar kilnBOT
#
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foggy quartz
#

<@&286206848099549185>

cedar kilnBOT
upbeat dune
foggy quartz
#

hi

upbeat dune
#

Is there anything you need help with?

foggy quartz
#

Confidence intervals

#

I have a packet of questions that is due at 9:20 am and it's 12:24 am right now

crimson sedge
#

@foggy quartz send questions

foggy quartz
#

On here?

#

Or DM's

upbeat dune
#

Here

foggy quartz
#

Okay.

crimson sedge
#

Here I’ll try them out

#

Try my best to help you

foggy quartz
#

Thank you

crimson sedge
#

No worries

foggy quartz
crimson sedge
#

This is statistics?

foggy quartz
#

Yea

#

Elementary

crimson sedge
#

Okay what grade? @foggy quartz

foggy quartz
#

Freshman in college

crimson sedge
#

Yeah I didn’t know it was statistics lol

foggy quartz
#

It's okay

#

It's hard asf

crimson sedge
#

If it was pre calc/calc

#

I Can help

foggy quartz
#

2nd time taking this class

crimson sedge
#

In my high school we have statistics and AP stats, but I never was interested

foggy quartz
#

Do you think you could help at all?

#

If not it's okay

#

I just need to boost my grade

crimson sedge
#

I’m not in college I’m really sorry

foggy quartz
#

Yikes

crimson sedge
#

I’m only in senior year final year

#

I’m grade 12 basically

foggy quartz
#

I've been struggling for 6 hours aha

crimson sedge
#

Damn

#

I’m sorry to hear that

cedar kilnBOT
#

@foggy quartz Has your question been resolved?

wise prairie
#

ew stats

dire geode
# foggy quartz

no point in sending your entire assignment. close and reopen a channel with one problem at a time

wise prairie
#

#4 should be 131

#

also all ur questions are like on chegg

#

check on there

#

@foggy quartz

cedar kilnBOT
#

@foggy quartz Has your question been resolved?

foggy quartz
#

I just used CHAT GPT

#

.close

cedar kilnBOT
#
Channel closed

Closed by @foggy quartz

Use .reopen if this was a mistake.

wise prairie
#

gets u the questions for free

cedar kilnBOT
#
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foggy quartz
cedar kilnBOT
wise prairie
cedar kilnBOT
#

@foggy quartz Has your question been resolved?

royal loom
cedar kilnBOT
#
Channel closed

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foggy quartz
#

so no

cedar kilnBOT
#
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marsh pond
cedar kilnBOT
marsh pond
#

Why is this true?

tropic oxide
#

a = e^ln(a)

#

and exponent laws

marsh pond
#

I’m fine with b

#

When it’s in front of ln

tropic oxide
#

exponential and logarithmic functions are inverse to each other...

marsh pond
#

Right but is there any more info to see behind the scenes?

tropic oxide
#

no

marsh pond
#

With ln(2^x) it becomes xln(2)

#

So I’m’ fine with that

tropic oxide
#

you say "becomes" as if that transformation is obligatory and unique

marsh pond
#

But with e^ln(x) I don’t follow

marsh pond
tropic oxide
#

idk what to tell you

marsh pond
#

but e^ln(x)

tropic oxide
#

ln(x) is the answer to "e raised to what power gives x?"

#

that's what it means for ln to be the inverse of exp

#

when you raise e to the power to which e must be raised to give x, what could you possibly get if not x?

marsh pond
#

2^log_2(100) is 100?

tropic oxide
#

yes of course!!

marsh pond
#

Ya I don’t see it lol

#

It’s the argument to the log

tropic oxide
#

????

#

how did you learn about logarithmic functions?

quartz frost
#

Lets say f and g are inverse to each other. Then f(g(x))=x, no?

marsh pond
tropic oxide
#

then HOW???

#

you are literally telling me that you don't know the definition of log_a(x)

marsh pond
storm mural
#

maybe they learned it as the integral from 1 to

#

/joke

marsh pond
storm mural
marsh pond
#

Right

quartz frost
#

Think about the wording maybe.
ln(a)=b means e to the power of b equals a. Or: to what power must e be taken that it equals a

tropic oxide
marsh pond
#

No I do know that log arguments must be positive

tropic oxide
#

do you have anywhere in your notes the first class in which you were introduced to logarithms

#

the first, the very beginning

quartz frost
marsh pond
#

No

#

Brain exploding

#

That log argument is negative

#

I don’t even know what that is

tropic oxide
#

do not.

marsh pond
#

It’s not legal

quartz frost
#

Think about the wording

#

Log_a(b)=c
is equivalent to
a^c=b
a to what power equals b? Answer: c

marsh pond
#

Log_69(x) = 2 means that 69 is the base, 2 is the exponent, x is the argument

#

69^2 = x

#

So why don’t I understand the inverse of that

#

If that’s what this is

#

2^(xlog_2(69))

#

that’s the same thing as 69^2 = x?

#

= e^(xln(69))

dull oxide
#

your test must be tomorrow