#help-13
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missing a square on the (y^2 - x^2) term
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Is there any nice mathematical notation I can use to denote a 3x3 "block" of a 9x9 matrix? Same idea as a sudoku board, just need to define it mathematically.
Here's what it currently is.
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can someon explain how this is answer A and not B
<@&268886789983436800> obvious troll
Ok and?
Alright but have you considered the whole expression?
The sum is not over i/n
We take sum over f(x_i)
ya ik
So what actually is f(x_i) here
Alright if the x_i = ln(1 + (i/n)) then?
is it because they have ln(1 + x) in the definite integral that makes it so xi = i/n making a = 0
Yeah x_i = i/n
ok
also
how would i do this
ive done this so far
but i dont know if its even right
fäf
i understand that
fäf
yes i know
can u help with this
fäf
Alright this
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did you get 51 as your answer
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cuz if not then my answer key is just wrong
i used calculators online and it gave me 81.75
which is what i got
but thats not what my answer key says
if a function is continous on [a,b] then Ln = Rn
and i found Rn
and Rn = 81.75
bro 124 isnt even an answer
just wasting my tim
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Wth
I'm not here to give out answers, I gave you explaination
,w sum (n)³+2(n)+1 from n=1 to 4
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The options may be wrong
,w integrate (x³+2x+1) from 1 to 4
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Yo
Help
@hardy isle type .close in this one
.close
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@bronze briar Has your question been resolved?
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Hi!
I need some help using Wolfram Mathematica
when plotting a piecewise function there is a "true" statement in there, could that be avoided?
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In the accompanying figure of triangle ABC, a =10 b=10 and the measure of angle A is 75 degrees. find the area of triangle ABC
MS Paint?
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
1
what im thinking is since there are 2 conguruent sides and since of them is already 75 degrees
im thinking angle B is also 75 degrees
that sounds more like status 2 to me.
yes, triangle ABC is isosceles. yes, angle B is 75°.
i dont know what to do after that tho
lol sorry
draw the altitude from C onto AB
wonky
hahaha
call the other end of that H
ok
look at triangles ACH and BCH
ok
im looking at it
but not getting anywhere
@crimson sedge Has your question been resolved?
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A cylindrical tank with the radius of 5m is being filled with water at of 3 m^3/min. How fast is the height of the water increasing?
you want dh/dt
you know that
V = pi * r^2 h
use chain rule
dh/dt = dh/dV * dV/dt
we use chain rule on the Volume equation?
yh perfectly fine
if anything you should, because if it were a
pyrimid
youd need to use chain rule
@loud forum what are you doing
if youre differentiating both sides by t
which also works
v turns into dV/dt
you still need to use product rule
for
r^2 h
dr/dt is 0 anyway
since cylinder has a constant radius
Am I using chain rule for the product rule?
yh you still use chain rule
but its irrelevant here
since r is a constant
you dont even need to use product rule
just differentiate the V and h
Ignore the highlighted parts, that’s for different problem
But we do need to plug in r no?
just because you need to plug in r, doesnt mean its not constant
also you didnt do prduct rule right to begin with
should be r^2 dh/dt
what is dr/dt then.
yes
but i mean
literally
what is dr/dt
dV/dt is 3 m^3/min
what do you think dr/dt is
that’s dr/dt
oH wait it doesn’t
If you use product rule, I assume it’s 2r(dr/dt)h + (dh/dt)r^2
accidentally deleted it-
So I plugged my numbers
what is dr/dt
Again, the radius doesn’t increase
so what number do I put as my dr/dt
we also don’t get a specific height
so then it’s remains as h
@loud forum didnt we literally establish
that the radius doesnt increase
so dr/dt = 0
@loud forum you forgot the pi
Didn’t the Pi cancel
no
cuz of derivative-
oHhHhH because pi multiplies to the other two
I just forgot to add it-
thanks a lot
figured it out thanks to you

You're welcome
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I am stuck in obtaining the three pythagorean identities using pythogorean theorem. Any help is appreciated
What have you tried
I have no idea what to do really
have you atleast wrote out the pythagorean theorem
yeah i did
and drawn the triangle it relates to
alright
And from that, use SOHCAHTOA. Relating to an angle inside the unit circle, what is cos(theta) and what is sin(theta)
oh ok
let me know what you think cos(theta) and sin(theta) are
i think i got how to solve this question. thank u tho
oh nice! no problem
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How to approach problem 19?
Think about binary numbers
In each wallet i will place 2^0 2^1 2^2 ...... 2^7
Yes
Thanks for helping
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$\frac{d^2}{dt^2}X(t)=\frac{kX_2-kX(t)}{[(X_2-X(t))^2+(Y_2-Y(t))^2][|X_2-X(t)|+|Y_2-Y(t)|]}$
! R4MP4G3
Not sure where to start with the above equation and the absolutes throw me off
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Domains and Ranges of composite functions
channel's taken bruv
means?

😶
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if V is a finite dimensional vector space and T: V -> V is onto, then T is one to one.
I know if T is linear, T is onto <=> T is one to one
but the problem doesn't give T is linear. I have no idea pls give some hints
What is t? Only T was given
no it is True/false example
But what is t? The same as T?
f(x)=x^3-x
f has roots x=0, x=1, x=-1
f is definetely onto
But not one to one as the kernel is not empty
if T isn't known to be linear then it can't be known to be one to one from being onto
@tropic oxide Why?
I gave a counter example
oh i got it
Let V be the natural numbers
f(1)=f(2)=0, for other x: f(x)=x-1
f is onto but not one to one
yes Thank you I really understand
natural numbers isn't a fd vector space usually 
thanks for counter example
True
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Find an equation of the tangent to the curve at the point corresponding to the given value of the parameter.
x = t^4 + 2
y = t^3 + t
t = 1
y(x) =
@uncut veldt I NEED HEELP
We should first get dy/dx
If we get dy/dt and dx/dt we can do one of the following:
Rewrite to get dy and dx and then get dy/dx
Or do dy/dt / dx/dt
Both works
so now would i plug in 1
dy/dt / dx/dt = dy/dx * dt/dt = dy/dx
Because dt/dt=1
Alternatively we can do:
dy/dt=3t^2+1
Therefore
dy=(3t^2+1)dt
For dy we get dx=4t^3dt
dy/dt=(3t^2+1)dt/4t^3dt=(3t^2+1)/(4t^3) * dt/dt
And here again dt/dt=1
-3(t^2+1)/4t^4
(3t^2+1)/(4t^3)
i did the quiotent rule to that
Quotient rule?
We are not really differentiating here
ahhh ok
we already have dy/dx via rearraging
ok, so what next
it is 4/4 so 1
ok
y=mx+b
Now we need b
y=x+b
To do that we have to get a pair of x and y
We can get them by putting t=1 into y(t) and x(t)
so the equation we started with?
Yes
x=3 y = 3
2
y=2
x= (1)^4+2=3
y=(1)^3+(1)
=2
@quartz frost ?? is that correct??
so -1
Yes
Yes
have a great daty
👍
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Hi there, I am a student trying to tweak the physics equation for moment of rotational inertia (MOI) such that I can calculate it for my object. As my object is a complex rigid body, I am attempting to use the MOI formula for a cuboid to derive the MOI for my object. Normally you would convert dV into the volume of the cuboid, but here I am manipulating it such that dV is the [Volume of cuboid - Volume unoccupied by object]. This way I would not need to figure out the algebraic equation of my object.
My current problem is that I'm not sure if I am integrating it correctly or if there is a better way as this is beyond my level. To anyone that replies thank you!
This is my reference pic
if it helps this is how one of my objects look like, it's a waterwheel
<@&286206848099549185> sorry for the ping guys!
@austere widget Has your question been resolved?
<@&286206848099549185>
I'll repost my message here. @austere widget You need more variables than r. The radius of the semi circles is required at least
Here are its dimensions
they arent exactly semicircles, more like ellipses tho,
the depths that I have are 0.00cm, 0.25cm, 0.50cm, 0.75cm, 1.00cm, 1.25cm, 1.50cm, 1.75cm
Here's how i created the blades (ellipses)
@austere widget Has your question been resolved?
calculate areas of the semi ellipse shaped things then just add them?
pi(ab) - pi(a' b')
the problem is im not sure how to take into account the portion that overlaps with the circle at the center
lemme make another diagram
be a physicist like me and assume it to be neglibile 😌
my teacher's so gonna kill me over the accuracy hahahah
this is for a physics report
and somehow i got to math
💀
im not sure how to account for the overlapped portions but as far as i can see
i cant really draw it and send but if you can notice then assuming that the ellipse is a perfect semi-ellipse the circle cuts out an approximately triangle shaped component
if you want accuracy to some degree you can use this approximation, im not sure how would we be precise about it tho
yeah i did consider finding the overlapping component with arc area hmmm maybe ill try again
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hi!i have got a question:how do u calculate the sine in a non-right triangle?
yeah,that's where this question comes from
i noticed that when took solely the sine ,calculating it independently
that could be any sine in a non-right triangle
the sine is a property of an angle, not the triangle
you can use right triangles to calculate it
can i do that without those?
sin(x) is defined as the y-coordinate of the point at an angle of x around the unit circle
can you give the example that prompted the question?
there's an exercise,don't know where it is ,but basically
there was a given line and an angle
i don't remember if the sine or some other angle was required
but since it's the sine law
i get it
but the second one ,I was just wondering how could u calculate it on its own?
Power series
and how do u do that?
sinx = x -x^3/3! + x^5/5! - ...
where does that come from?
Calculus
I have never encountered that form
I'm in high school,plenty of things r unseen by my eyes
what theorem was that over there?
Not really a theorem but it's called power series
That's the way we normally define sin
And there's a way to relate this to the geometric picture
interesting
perhaps,when i get to this form,Math will be taught as more than just formulas
thanks
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no
f'(0) is where the slope is 0, i thought?
oh
confusing input with output
that makes sense
yeah, it's the input of the derivative
so it would refer to the x value only
x=0
but here I wanna set it y itself EQUAL to 0
of the derivative
not sure if i worded that correctly
I wanna set the derivative equal to 0? or y equal to 0?
i think if I set the derivative equal to 0 it would be f'(x) = 0
you yourself do not know what you want to do
lol
ya pretty much..
i need to identify the location and maximum value of the function
so first i find the derivative
then i set the derivative equal to 0 to find the x=something value, which is the local max or min
haven't you already done that?
just cross out the last line, everything else is ok
(you should probably explain why x=8 corresponds to a local max and not a local min)
then i set the derivative equal to 0
i think my wording is incorrect here
i replace f'(x) with 0?
this wording is fine.
oh OK
which is a critical point. It could be neither max nor min (y=x³)
you've set the derivative equal to 0 and you have found the x coordinate at which it equals 0
you wanna find fx s max value right
that makes sense. whenever f'(x) is 0, it's neither increasing nor decreasing
so therefor it must be a max or min
or another word, can't remember
like x^3 at origin
inflection point?
is only local
and it may not even be local max
there could be multiple curves
so i gotta test them all to see which one is higher/lower
if it's a really long polynomial
I heard we needed more helpers
Assemble
If i understood what you wanna find thats the answer
ppl will get upset for answers, just warning you
!nosols
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
I don't even understand what your problem is, you found the what x corresponds to the stationary point , you understand the relation between f(x) and f'(x)
Oh i didnt know that
Should i delete it?
just couldn't remember if it's f'(0) or 0 that i wanna solve for
but now it makes sense
f(x)=y=0
If its f'(0) then just put 0 on x-s you will find it
Yea thats it
compare answers and you will 'remember' which is correct again
Hmm if you meant f'(0) yep ur right
typo, f'(x) = 0
i'm replacing the derivative with 0
and finding the value of x that causes it to be true
Then f(0)=x
I got it
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Hello
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C
@worthy ferry because I can't be checking discord 24/7
!show
Show your work, and if possible, explain where you are stuck.
@crimson sedge how old are you ?
14
combine like terms
yes
And sort by highest to lowest degree
you don't need to sort anything
-2y²
yes
you didn't do your arithmetic correctly. the minus sign in front of the second parentheses applies to all those terms
not just the first one
yes
where did the "a^2" come from?
you aren't multiplying those two
yes
yes
Here would I just distribute both numbers into both other numbers?
what would be your guess?
I don't know but I'd say remove parentheses
no, there's an exponent there
Distribute to 13 and b?
what do you mean? do you know what the exponent "2" means there?
No
$x^2 = x \cdot x$
cwatson
no, the "x" was just an example. the "2" means "squared" and it means you multiply something by itself
so $(b + 13)^2 = $ what
I'm lost
you have to multiply (b + 13) by itself. does that make it more clear?
So (b+13)(b+13) ?
yes
no, use "FOIL", the same as your previous problem
yes
What does the =0 at the problem represent
oh actually I hadn't noticed before
Oh
B and -b?
cwatson
how can you get 0 from multiplying two numbers
If one is 0
yes
So how would that help
-13 both side
yes
So where would I use that
what do you mean?
Like where would I -13 both sides
what do you mean "-13 both sides"?
Wait
look at the original equation. Plug in b = -13. what do you get?
...you just found the answer...
no
it's kinda similar
you have 3 numbers multiplied together. how can you get 0 from that?
If 1 = 0?
no... 1 does not equal 0
If one of the numbers = 0?
So I would make 3 different equation?
yes
Without parentheses right?
it won't matter
guess if you have to
2y= 0
yes
so? there are 3 terms, so 3 equations to solve for "y"
you have the first one already
Y=0?
from the first equation, yes
What about second one
what do you think the second one is?
Y-9=0
yes
you need to solve for y
+9 both sides?
you should know how to solve "y - 9 = 0" by now, you've done a similar problem already
-9y?
no
Idk
,tex .alg lesson
??
cwatson
read that
Y=9
yes
yes
How would I do this
do you have a textbook? or course notes or something? this is harder to teach
Yes let me grab it
Ok I'll watch
I'll do that later wow that's hard to understand
What do I do here
it's the same type of problem. it'd be helpful if you watched the video or checked out your book/notes
well y, but ye
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Either close ur last channel or close this one
idk how to close it man
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wdym
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I don't know where to start
n(n^2 -9)
whats a common term that both n^3 and 9n have
N
thats the awnser
wait nvm
@crimson sedge whats something that you can do to both x^2 and 9
you can square root both
$$\text{you can factor out n from both: }\$$
$$n^3-9n = n(n^2-9)$$
now what do we do
Talent Unlimited
I'm struggling
n(n+3)(n-3)
Where did u get that from
when you multiply by the conjugate and its in the form x^1+-a
$$\text{using this identity: }\$$
$$a^2-b^2 = (a+b)(a-b)$$
Talent Unlimited
@crimson sedge you have n^2 - 9 in the form of a^2 - b^2, so you can expand that out into (n+3)(n-3)
(x-3)(x+3) xtimesx is x^2 -3timesx is -3x 3timesx is 3x so -3x and 3x cancel and -3times3 is 9
n^3-9n
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why is the height of the rectangle (h) equal to exactly the y value? 1-x^2
that's what "inscribed" means
the -x^2 itself has a maximum y value of 1
the upper corners of the rectangle just touch the function
this is a math term?
i have never heard of it before
yep
it comes from geometry: https://en.wikipedia.org/wiki/Inscribed_figure
In geometry, an inscribed planar shape or solid is one that is enclosed by and "fits snugly" inside another geometric shape or solid. To say that "figure F is inscribed in figure G" means precisely the same thing as "figure G is circumscribed about figure F". A circle or ellipse inscribed in a convex polygon (or a sphere or ellipsoid inscribed i...

well for that particular odd polynomial i don't think you could inscribe anything because it only crosses the x axis once
but other cubics have three roots in which case you could
that one is always above the x axis
that is the exact value for height?
of the inscribed rectangle
interesting..
oh of course
that's when y = x
so it's where y and x meet, right?
at exactly the same point
so therefor, it must be a point on the graph
touching the line of the parabola
inscribed rectangle with maximum volume will always be using the point y=x
or maybe -y=x
if it's positive or negative parabola
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i get stuck after i move 3x
i did A but i got a question on the factoring out 5x-ax. For part B i need help
what are you stuck on for B
i get up to -8y=6-3x
how can you get y on its own
@nimble relic Has your question been resolved?
yes
ik you cant have a - denom
where are you getting that idea
my friend said you cant have a - denom so you multiply it
its legal to have stuff like that in the denominator
though you should ultimately simplify/manipulate so that it doesn't
oh i got confused with square root
i tried getting help from photo math but it put the 8 twice
6/8 and 3/8
i dont get why its two separate fractions
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✅
$\frac{a \pm b}c = \frac ac \pm \frac bc$
Umbraleviathan
I hope you know how fraction addition/subtraction works if you're doing linear equations
type .close
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<@&286206848099549185>

hi
Is there anything you need help with?
Confidence intervals
I have a packet of questions that is due at 9:20 am and it's 12:24 am right now
@foggy quartz send questions
Here
Okay.
Thank you
No worries
This is statistics?
Okay what grade? @foggy quartz
Freshman in college
Yeah I didn’t know it was statistics lol
2nd time taking this class
In my high school we have statistics and AP stats, but I never was interested
Do you think you could help at all?
If not it's okay
I just need to boost my grade
I’m not in college I’m really sorry
Yikes
I've been struggling for 6 hours aha
@foggy quartz Has your question been resolved?
ew stats
no point in sending your entire assignment. close and reopen a channel with one problem at a time
#4 should be 131
also all ur questions are like on chegg
check on there
@foggy quartz
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they told me to
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thank you, I’ll try this
fs
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is this a test
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Why is this true?
This part I don’t get
I’m fine with b
When it’s in front of ln
exponential and logarithmic functions are inverse to each other...
Right but is there any more info to see behind the scenes?
no
you say "becomes" as if that transformation is obligatory and unique
But with e^ln(x) I don’t follow
I’m not gonna go into wording just that I understand it
idk what to tell you
but e^ln(x)
ln(x) is the answer to "e raised to what power gives x?"
that's what it means for ln to be the inverse of exp
when you raise e to the power to which e must be raised to give x, what could you possibly get if not x?
2^log_2(100) is 100?
yes of course!!
Lets say f and g are inverse to each other. Then f(g(x))=x, no?
Not this way
then HOW???
you are literally telling me that you don't know the definition of log_a(x)
I’m not sure.. I do know inverse functions must be one to one
Domain and range swap
to be fair assuming a real valued ln
e^ln(x) = x only for x > 0
Right
Think about the wording maybe.
ln(a)=b means e to the power of b equals a. Or: to what power must e be taken that it equals a
you're going to confuse her even more.
No I do know that log arguments must be positive
do you have anywhere in your notes the first class in which you were introduced to logarithms
the first, the very beginning
That makes sense to me
log_(-1)(-1)=1 hehe
do not.
It’s not legal
Think about the wording
Log_a(b)=c
is equivalent to
a^c=b
a to what power equals b? Answer: c