help-13

[slow thicket]

😔

if for every dog I have you have two dogs

if I have four dogs

how many dogs do you have

[plush lagoon]

2

[slow thicket]

no

[plush lagoon]

0

the question doesn’t make sense tho

:((

[slow thicket]

howwww

1:2 is a ratio

for every dog I have you have two dogs

if I have 4 dogs you have 8 dogs

if I have 100 dogs you have 200 dogs

[plush lagoon]

ok

i think ik?

soo

[slow thicket]

@plush lagoonok so

ho wmany triangles

[plush lagoon]

idk what this means

[slow thicket]

read this

[plush lagoon]

8 triangles

?

[slow thicket]

yes

okay finally

so how many rectangles

area: rectangle = 765, triangle = 131.75

[plush lagoon]

4..

[slow thicket]

okay

so what is the total area

[plush lagoon]

idk

[slow thicket]

you have the area for each shape

and you have the amount of each shape

just multipliy the two

[plush lagoon]

of what

8 and 4

[slow thicket]

area of all rectangles = area for one rectangle * number of rectangles

same for triangles

[plush lagoon]

idk what you said but i agree

idk what to do now

[slow thicket]

i just told you

[slow thicket]

^

[plush lagoon]

and this is not 6?

[slow thicket]

that is 6

[plush lagoon]

ok soo

[slow thicket]

sooooo

area of all rectangles = area for one rectangle * number of rectangles

area of all triangles = area for one triangle * number of triangles

total area = area of all rectangles + area of all triangles

[plush lagoon]

i add them

[slow thicket]

yes

[plush lagoon]

what do i add

[slow thicket]

i'm telling you

please read what I am saying

you have 4 numbers

which is all you need

[plush lagoon]

i did

6 times

[slow thicket]

i dont understand what you dont understand

you already calcualated 4 values

area: rectangle = 765, triangle = 131.75

number of rect = 4, number of triangle = 8

[plush lagoon]

ok

[slow thicket]

now just plug them in

[plush lagoon]

how

[slow thicket]

what do you mean how

area of all rectangles = area for one rectangle * number of rectangles

lets do this one

area of all rectangles = 765 * 4 = 3060

do the rest

[plush lagoon]

16.46875

right

[slow thicket]

what

where did that come from

how can the area be just 16

[plush lagoon]

131.75 divided by 8

[slow thicket]

why are you dividing

[plush lagoon]

idk

[slow thicket]

i said here that you multiply

[plush lagoon]

idk what that means

[slow thicket]

do you not understand multiplication

if bricks are $10 each and I want 10 bricks

the total cost is $10 * 10 = $100

same thing here

[plush lagoon]

it’s 1,054

[slow thicket]

yes

now what is the area for the entire 3d shape

[plush lagoon]

3060 and 1054

[slow thicket]

and..

thats two seperate areas

[plush lagoon]

idk what to do

4,114

[slow thicket]

yes

[plush lagoon]

YAY

[slow thicket]

That’s it!

We are done

[plush lagoon]

i have a mother question

don’t mind the writing

how do i find the volume

[slow thicket]

area of triangle * length of shape

[plush lagoon]

so i have to find the area of it

[slow thicket]

area of just the triangle

[plush lagoon]

so first it’s 55.00x63.50

wait

right

[slow thicket]

so

[plush lagoon]

i do them 2 times?

[slow thicket]

What

This is volume not area

Figure out the area of the triangle

So that you can find the volume

[plush lagoon]

ok it’s 3,492.5

then um

[slow thicket]

No

You forgot something

A = bh/2

[plush lagoon]

divide by 2

[slow thicket]

Yes

[plush lagoon]

ok now what

for the volume

[slow thicket]

volume = area of base * length

[plush lagoon]

1746.25x85.00?

[slow thicket]

Ye

[plush lagoon]

ok now what

[slow thicket]

That’s it

[plush lagoon]

i add them

[slow thicket]

No

[slow thicket]

It’s just this

[plush lagoon]

wait

how do i do a 2 one

for volume

[slow thicket]

Same thing

Area of base * length

[plush lagoon]

where is the base

it’s 25

and the length is 230

there’s no w?

nvm thx

.close

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[tidal frost]

Hey I'm struggling with this question

[tidal frost]

I'm not sure where p

to start

[cosmic steppe]

Prove that angle CAB is congruent to EFB, ABC to FBE, and BCA to BEF

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[strange musk]

Can someone help me with 15 please

[digital cliff]

perhaps let y=x^(-2) if that helps

[strange musk]

36y^2-5y-1=0 (9y+1)(4y-1)=0 y= -1/9 and 1/4

[digital cliff]

yup

[strange musk]

Im not getting the answers from the book

[digital cliff]

have you said that 1/x^2=-1/9 or 1/x^2=1/4?

[strange musk]

it says its ±3i, ±2

[strange musk]

yes

[digital cliff]

then how did you solve for x?, you should, following the above, get x^2=-9 or x^2=4

which then arrives at the answers after sqrt both sides

[strange musk]

O wait

U right

i see it now

Thanks for the help

[digital cliff]

np

[strange musk]

.close

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[neat widget]

I know I just need two vertical asymptotes to make it have two extrema, but how do i ensure one is at x = -3

[cedar kiln]

@neat widget Has your question been resolved?

[crimson sedge]

To move a line along the x axis you can add the number so, in the case of x = -3, you would add a + 3 to the end of your function

Given a function 𝑓 , a new function 𝑔(𝑥)=𝑓(𝑥−ℎ) , where ℎ is a constant, is a horizontal shift of the function 𝑓 . If ℎ is positive, the graph will shift right. If ℎ is negative, the graph will shift left.

[cedar kiln]

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[neat widget]

if im solving b^2 > +/- sqrt(36)

[neat widget]

why does the inequality flip for the positive?

b < 6 and b > -6

why is that the answer?

[lethal jackal]

1. b < 6 and b > -6 is never true.
2. neither of those individual statements are solutions to this

can you paste the original question?

[neat widget]

Sorry I meant

B^2 > 36

@lethal jackal

[lethal jackal]

I see

I think the correct inequality here is actually b^2 >= 36

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[quasi bear]

\

[quasi bear]

i'm confused on what dx should be

[radiant topaz]

why?

it's not asking for valuue of dx

it's asking for value of whole integration

[quasi bear]

oh

oopsies

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[onyx fjord]

Hey

[onyx fjord]

I am not sure how to find the following limit using L'Hopital's rule

[brisk dirge]

Do you know how to find derivatives

[onyx fjord]

yes

but I am not sure how to find the first derivative of the numerator

[brisk dirge]

Then just differentiate the numerator and denominator with respect to u

So denominator becomes 1

[onyx fjord]

yes

[brisk dirge]

And standard derivative of a^x

[onyx fjord]

but what about the numerator?

[brisk dirge]

We'll need to consider x and y are constants

[onyx fjord]

how does that change things?

[brisk dirge]

So u can say numerator will be x^u.lnx - y^u.lny

[onyx fjord]

would it be different if they weren't constants?

[brisk dirge]

Yeah

Then you'd have an extra factor of dy/du

And DX/du

[brisk dirge]

If they're constants you can just do this

[onyx fjord]

but we don't have to do that here since they are both constants?

okay

[brisk dirge]

Then put u=0

So lnx-lny

Ln(x/y)

[onyx fjord]

x and y disappear

[onyx fjord]

so that will be my final answer?

[brisk dirge]

Yes

[onyx fjord]

awesome, thank you!

.close

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[thorny swallow]

can someone help me for these 2 questions?

here is the question information

[flat harbor]

hey mate

another aussie here

[thorny swallow]

hey there

[flat harbor]

do ya know the compound interest formula

[thorny swallow]

yup

An = P(1+r)^n

[flat harbor]

good

so if the amount is 1 mil

rate is 6%

[thorny swallow]

oh wait

[flat harbor]

n is 30

you are only looking for p

[thorny swallow]

but isnt it compounded monthly?

[flat harbor]

i reckon ya can do this

true

[thorny swallow]

so n would be 360 right?

[flat harbor]

amaing

z

just sub into formula and ur sweet mate

[thorny swallow]

oh alright then

thanks

[flat harbor]

if u have questions

im still happy to help ya

but ya should be fine

[thorny swallow]

alright then

[thorny swallow]

wait so i subbed everything into the formula

An = 1000000(1+0.005)^360

and got $6022575.21

do i just divide that by 360?

and the total interest part is just $6022575.21 - 1000000 right?

[flat harbor]

hey mate

so 1 mil is ur amount not ur principal

you are finding the principal

if you swap those two around

ur probably right

[thorny swallow]

so 1 mil is An?

[flat harbor]

yes

[thorny swallow]

ohh ic

[flat harbor]

well done on dividing the rate by 12

[thorny swallow]

lmao

[flat harbor]

almost did that myself

[thorny swallow]

is the answer 166042?

also can you explain why the 1 mil is the an and not the principal please @flat harbor

[flat harbor]

he borrowed 1 mil

which means it is the amount

you are finding the monthly repayment

thats the principal

[thorny swallow]

for d, do i make 1mil the prinicpal?

@flat harbor

i dont see any other way that the interest would be higher than the principal

[cedar kiln]

@thorny swallow Has your question been resolved?

[thorny swallow]

.close

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[visual mirage]

Help plz

[dull oxide]

What have you considered so far?

[visual mirage]

7 is not equal to 7-1

@dull oxide

[nimble veldt]

so what do you need?

[visual mirage]

im just wondering if im correct

[nimble veldt]

the "proof" starts with a wrong statement, so the result is wrong even if the transformations are all correct.

[visual mirage]

alr

[dull oxide]

This is a very common fallacy proof

Always watch out for division by zero

[nimble veldt]

this version has second error in it.

[dull oxide]

Idkwym

[crystal raptor]

Line 8

Although it would follow from line 7 with a "line 7.5"

[visual mirage]

so step 5 is incorrect?

[dull oxide]

If x=y, then what is x-y?

[visual mirage]

0?

[cedar kiln]

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[uncut lodge]

please help with question ive solved it but the answer is completely different and i just need someone else to solve it to confirm the answer

[uncut lodge]

<@&286206848099549185>

<@&286206848099549185>

[crystal raptor]

Show your work

[crimson sedge]

completely different?
there are only a handful of transformations

you couldn't have been that off

[uncut lodge]

my work was reflection in the y-axis
dilation 4 in the y axis
translation left 3

[crimson sedge]

you reflect/scale after translating

dilation meaning compression?

[uncut lodge]

i guess its the same word diffrerent teachers

[crimson sedge]

try factorizing the -1/4 from the argument in the root

it should be made clear

[crimson sedge]

stretch, squeeze, idk

[uncut lodge]

same ting

[crimson sedge]

oh right

[uncut lodge]

but the answer says Reflection in the 𝑦-axis, dilation of factor 4 from the 𝑦𝑦-axis, followed by horizontal translation 12 units to the
right

how could it be 12 units to the right

[crimson sedge]

it should be a flatenning of the curve horizontally

[steady anchor]

thats wrong

[steady anchor]

seems right

[uncut lodge]

thats what i was trying to find out

if the answer was wrong

thank you

[steady anchor]

just do double check do that translation to the original graph

(x, y) -> ... (x', y')

using this

[uncut lodge]

yep

[steady anchor]

answer is def wrong tho

[uncut lodge]

thank gosh

.close

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[crimson sedge]

-x -> -1/4 x -> -1/4 (x - 12)

[cedar kiln]

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[wide scaffold]

https://cdn.discordapp.com/attachments/903486479064522752/1090325292519804979/image.png

[wide scaffold]

How do I go about solving such limit

[crimson sedge]

write the cube root n^4 using ratio of powers

[wide scaffold]

I did that

which becomes 8*n^(4/3) ?

[crimson sedge]

did you factorize?

yeah

[wide scaffold]

where

on each side or on the whole thing

[crimson sedge]

each side

[wide scaffold]

so I take n^2

from each

[crimson sedge]

just an n

[wide scaffold]

arent u supposed to divide by the biggest factor when calculating limits?

[crimson sedge]

hold on

[crimson sedge]

you're right

[wide scaffold]

so I factor out n^2

[crimson sedge]

i think you can write it as a difference of squares

[wide scaffold]

how so

u mean x^2-y^2=(x-y)(x+y)?

[crimson sedge]

no, they're cubes

gimme a sec sorry

[wide scaffold]

all good take your time

[crimson sedge]

thinking to do something like that

difference of cubes

[wide scaffold]

I see but how would I apply it here]

I would apply it on the original limit or the "simplified one"?

[crimson sedge]

just trying to spot a way to turn it into a simplifyible form

[wide scaffold]

in our case we have 1/3 not 3

Isee

[crimson sedge]

but using things like n^1/3 as a way of fitting it

quite tired, so algebra and mental maths isn't the greatest

[wide scaffold]

Hahhaa

all good

[crimson sedge]

$n^{\frac{2}{3}}(n^{\frac{1}{3}} + 2^{\frac{3}{2}})(n^{\frac{1}{3}} - 2^{\frac{3}{2}})$

[wraith dagger]

hannibal

[crimson sedge]

for the RHS

you can factorize the argument as a difference of squares

[wide scaffold]

can I not say x=9th root of ... and then x^3 is the 3rd root of...

and then use diff of cubes

or would that be super long

[crimson sedge]

give it a go

can't help this time. looks doable with some clever factoring though

[wide scaffold]

they did say we could use this formula to help us out

[crimson sedge]

oh ok

[wide scaffold]

which is basically diff of cubes "extended"

[crimson sedge]

like a generalized difference?

[wide scaffold]

yea

[crimson sedge]

i'll give it a go later on

roots get too clusterfucked to do neatly

[wide scaffold]

no worries thanks anyways<3

[wide scaffold]

real

[crimson sedge]

good luck

no good notation

stuck with big squiggly houses or weird fractions in the air

[wide scaffold]

😅

[cedar kiln]

@wide scaffold Has your question been resolved?

[cedar kiln]

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[crimson sedge]

might be a dumb question, but i have a 3 year cost which i am trying to break down into a quarterly cost

[crimson sedge]

it is $450,000 for 3 years for example

[hidden osprey]

LIXERA

remember me

i helped you yesterday

[autumn fox]

How many quarters of a year, are there in 3 years?

[upper garnet]

Help him again

[crimson sedge]

that would be 36 months, so on a monthly basis you can just divide by 36 and then multiply by 4 to make it quarterly, right?

oh im dumb thank you mikkel

i just realised

[hidden osprey]

in case you didnt see

[crimson sedge]

why did i multiply by 4

[crimson sedge]

yeah i got the idea later on thanks

[hidden osprey]

ye

[autumn fox]

This is also a correct approach.

[crimson sedge]

but wait its not

because 4 would make it it...thirdly?

whatever that is called

shouldnt it be 3

[autumn fox]

You are correct

Yes

Brain fart

[crimson sedge]

great!

yeah i also wrote 4 and i was so confused why i was wrong haha

ty

.close

.close

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[gilded elm]

lixera caught.

[cedar kiln]

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[ripe agate]

i need help with this question, i honestly don't get anything or what they mean by "fg", or how im meant to know the new functions period from that. What are they asking, and what should I do?

[mental trail]

ah

Yeah if they're saying "state the period" it must mean f o g (composition)

[ripe agate]

what does composition mean?

[mental trail]

for x in the domain of g, fg(x) = f(g(x))

[ripe agate]

ok, then how do I know what the period would be like?

And how does a graph look like if its domain is based on another function?

[mental trail]

you might not need the graph for this

[ripe agate]

ok, then how do I find the period?

[mental trail]

let's try to forget about f, and focus on g of period q

if I add a constant C, is g+C still periodic?

[ripe agate]

yes? would it be a translation?

[mental trail]

correct

now, if I multiply by a constant C, is C*g still periodic?

[ripe agate]

I think so, instead of a translation, it would make the graph stretch or compress?

[mental trail]

kind of, yes!

now, what about g*g ? is it still periodic?

[ripe agate]

it should be? what would make a periodic function not periodic?

[mental trail]

we'll see in a minute, but right now g*g is periodic!

So it seems that any transformation we directly apply to g keeps its periodicity

[ripe agate]

got it

[mental trail]

So, if we take any function f

[mental trail]

would f o g keep its periodicity ? (composition notation)

[ripe agate]

yeah

[mental trail]

alright, well try to prove it!

[ripe agate]

as in... how?

and how is the period of f affected by g?

[mental trail]

since g is applied before f, which one of the periods is going to matter more?

when we compose both functions f o g ?

[ripe agate]

g? because its x and y depends on x?

[mental trail]

Kind of, yeah

so maybe f o g has the same period as g

how do we verify it?

[ripe agate]

im not sure, could we use like a placeholder function?

[mental trail]

well, knowing the period of g is "q"

we know a function H is of period q if H(x+q) = H(x)

So, how do we apply this here?

[ripe agate]

f(g(x+q) = g(x)?

[mental trail]

you forgot an f

f(g(x+q)) = f(g(x))

[ripe agate]

oh, because its still going to be the same f(x), got it

[mental trail]

so, we proved it!

[ripe agate]

what does this mean though?

[mental trail]

that no matter if f is periodic or not, f o g will have g's periodicity

[ripe agate]

so whats the difference between function g and f(g(x+q)) = f(g(x))?

[mental trail]

for example, if f(y) = y^2

then g and f o g = g^2 are not the same thing

[ripe agate]

ohhhh got it

thank you so much!!

[mental trail]

np

[ripe agate]

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[silent wraith]

hello i no understand first degree functions

[lyric narwhal]

?

any context?

[silent wraith]

hello

i dont undestand first degree functions

can you help me

[lyric narwhal]

what do you mean by first degree functions

[upper garnet]

lol

[lyric leaf]

a function of form ax^1 + c??

[silent wraith]

ax + b

[lyric leaf]

what don't you understand about them?

[silent wraith]

everything

i failed every test

[lyric leaf]

[silent wraith]

i got bad teache

teacher

[livid hound]

be more specific,
don't over exaggerate

[wanton isle]

First degree like linear equation?

[lyric leaf]

do you know how to solve the equation 5x + 2 = 3

[silent wraith]

yes

[upper garnet]

what do u need help with

[lyric leaf]

can you be more specific as to the type of problems you're having trouble with

[livid hound]

give a specific math problem you had an issue with
and the issues you encountered when solving

[silent wraith]

f(x)= 5x + 4

[upper garnet]

what about it

[silent wraith]

i need to get the slope

i dont know how

[upper garnet]

do u know what a slope is

[wanton isle]

The slope is 5

[silent wraith]

no

[upper garnet]

then google what it is

[silent wraith]

ok

[wanton isle]

y=mx + b
Where m is the slope

So, m=5

Slope is 5

[wanton isle]

That's for 5x+2=3

[silent wraith]

oh thank you

i got another question

how can i find the zero value

[upper garnet]

watch a youtube video

[wanton isle]

what zero value?

[silent wraith]

yes

[wanton isle]

what about zero value?

[silent wraith]

how can i find it

[upper garnet]

.

[silent wraith]

it is written in the exercise

calculate the zero value

[wanton isle]

5x + 2= 3
5x + 2 - 3=0
5x-1=0

So, y=5x -1
Let x = 0
y=5(0)-1
y= 0-1
y= -1

[silent wraith]

oh thank you

thats it

thank you very much

[wanton isle]

You can do the same for y to find the value of X. Just let y =0 then solve the equation

[silent wraith]

okay i will remember that

.close

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[crimson sedge]

if you have a matrix a

[crimson sedge]

and uve to find its inverse

i have to do subtraction

so this equation ( 4 * 1 ) - (- 2 * - 1 )

it should not be 4 + 2?

how is it 4 - 2?

so confused

[crimson delta]

-2*-1=2

minus*minus=plus

[crimson sedge]

do you have to look inside the bracket?

[crimson delta]

thats how brackets work. you look at whats inside them

[crimson sedge]

okay so because previously there was no signs with the number inside, i mean to to say is that with one digit

it was like (4 * 1 ) - (-2 * 1)

here this was 4 + 2

[crimson sedge]

@crimson delta why do we say -2?

how is it -2? / 4-2?

[crimson delta]

you have an extra minus compared to that one so why should it still be +2

[crimson sedge]

4 + 2?

you might be thinking what i am doing

i have got it, there is an extra minus sign

the thing that was confusing me there is

that why it should not be positive - - = +

there is an extra

it would be negtive

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[idle storm]

Hi, im confused about this question, for part a, apparently I cant just differentiate v(s), i dont understand why

[mental trail]

Hi, have you thought about our lord and saviour?

⛓️

(Bad joke taste sorry)

[short blade]

the reason why is that acceleration is the derivative of velocity

[idle storm]

yh, but the mark scheme is wierd

it says i cant just do that

[mental trail]

Why not?

[idle storm]

is does v(dv/ds)

[mental trail]

v is in m/s

dv/ds is in s^-1

[idle storm]

but, ive got an expression for the velocity with displacement

[mental trail]

Though there is a relationship between the acceleration an the derivative of velocity w respect to position

Since a = dv/dt = ...

And now, we call our lord and saviour

⛓️

Do you see how?

[cedar kiln]

@idle storm Has your question been resolved?

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[lofty oasis]

Is this formula correct

[lofty oasis]

I got 1920 but my friend got this

[sleek swift]

What is the geometric object?

[lofty oasis]

Unknown

That is full question

[sleek swift]

Yeah it's right

[cedar kiln]

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[tepid otter]

How many ways are there for four men and five women to stand in a line so that either
a) all men stand together, or
b) all women stand together?

[tepid otter]

pls help

on exercise a) I found the answer 6 * 5! * 4! is this correct?

[flint plinth]

offhand it looks right, what was your rationale?

[dusk finch]

it is correct I guess

four man together + 5 women form 6 groups that can be rearranged, that's 6! or 5!*6, then the four man can be rearranged in 4! ways so the res is 6! 4!

[tepid otter]

if you put all the men first and the women after yo get 4! ways to place the men and 5! ways to place the women. Now if you put a woman in front and the men after you have 5 women to choose from on the start and then 4! ways to put the men and then 4! ways to put the rest of the women which will be 5! * 4!. And since there are 6 scenarios the answer will be 6 * 5! * 4! ?

[flint plinth]

yea

basically you have six choices for how many women are standing behind the group of men: 0,1,2,3,4,5

and for each of those choices you have 5! 4! ways to sort the two groups

[tepid otter]

yes ok, thank you! 🙂

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[whole pecan]

hello , what is sin of 5degrees,5seconds and 5 minutes. and how+

[whole pecan]

its 5+ 5/60+ 5/3600 yes?

[tropic oxide]

that's the angle 5°5'5'' converted into degrees, yes

one must of course not conflate an angle with its sine

as for how to calculate sin(5°5'5'')? use a calculator.

[whole pecan]

and what is the difference between cos and sin

l.

[tropic oxide]

wdym?

in terms of ratios in a triangle, sin = opp/hyp while cos = adj/hyp.

is that what you're looking for?

[whole pecan]

ignore the text but i just have to find the value by the hundreth

[whole pecan]

@tropic oxide

[tropic oxide]

,rccw

[tropic oxide]

and are you expected to do this BY HAND?

[whole pecan]

no, i am allowed a calculator

but on a calculator is there a difference between cos and sin

[tropic oxide]

why WOULDN'T there be...

[whole pecan]

well thats what i am asking

[tropic oxide]

cos and sin are different functions, why would they somehow not be different on a calculator

[whole pecan]

whats the formula or algorithm the calculator is using to find the sin /cos

[tropic oxide]

https://en.wikipedia.org/wiki/CORDIC or https://en.wikipedia.org/wiki/Taylor_series

would need to look into technical documentation to figure out exactly how any particular calculator/computer program does it

[whole pecan]

i need to find the cos and sin of a what looks to be a 90degree angled triangle, and what i have been given is numbers on the sides, hypothenus and cover

hypo is 10, and covers are 8 and 6

[tropic oxide]

are you just throwing questions out in rapid succession??

[whole pecan]

rapid succession as in fast? well i am trying to make sense of this cos and sin thing

since i already got past the other question

[tropic oxide]

you jump from "how does the calculator compute sin and cos" to "how do i find the sin and cos of an angle from a right triangle"

[whole pecan]

well, they are labeled 476 and 478

[tropic oxide]

discord chat isn't the best place to learn basics of trigonometry unfortunately

[whole pecan]

its just sin(a)= a/c tho right

and cos(a)= b/c

[tropic oxide]

without a diagram these equations are meaningless

[whole pecan]

the first one

[cedar kiln]

@whole pecan Has your question been resolved?

[cedar kiln]

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[half grail]

help

[cedar kiln]

Channel closed

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[half grail]

help

ik it looks easy but i don’t understand

[cedar kiln]

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[cosmic siren]

https://cdn.discordapp.com/attachments/773347629785677825/1090729516583891004/image.png

[cosmic siren]

i know ab is b-a

and ak is 3b-3a

but i don't know what to do next

[crimson sedge]

Use the property that $\vec{AB} + \vec{BC} = \vec{AC}$

[wraith dagger]

Nika

[cosmic siren]

idk how to do thta

<@&286206848099549185>

[cedar kiln]

@cosmic siren Has your question been resolved?

[cosmic siren]

Help pls

[cosmic siren]

<@&286206848099549185>

[cedar kiln]

@cosmic siren Has your question been resolved?

[cedar kiln]

@cosmic siren Has your question been resolved?

[cedar kiln]

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[kindred orbit]

Sigma notation
(-1/6+5/3k)
12 above, k = 1

[kindred orbit]

is there any specific formula for this

[jade sonnet]

Do you have the original question

[kindred orbit]

uhhh nope the teacher gave me that question

i think i should use
$S_n=\frac{n}{2}{2a+(n-1)d}$

[wraith dagger]

JA.

[jade sonnet]

$\sum_{k=0}^{12}\frac{5}{3} k - \frac{1}{6}$

[wraith dagger]

lewis_f04

[jade sonnet]

Yeh that formulas not quite correct but Ik what you mean, it’s sun to n arithmetic series

[kindred orbit]

yep yep

alr thanks for the help

.close

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[prisma yew]

the following conversion was done correctly: 3miles/1hour * 1hour/60minutes * 5280feet/1mile*12inches/1foot, what were the final units for this conversion.

1. minutes per foot
2. minutes per inches
3. feet per minute
4. inches per minute.

I think answer is 4 cuz I use AI but I do not get how it is this answer even after AI explained, can someone explain better.

[crimson sedge]

cancel like terms

[prisma yew]

Wdym

Like miles, feet and inches?

[crimson sedge]

any same unit on opposite sides cancel each other

whatever is left over is the final conversion

[prisma yew]

So same units, on denominator and numerator cancels each other out

[crimson sedge]

yeah

this also goes for any other term

[prisma yew]

Ok what about 3miles/hours tho

How I cancel 3 miles

[crimson sedge]

just leave it there

you cancel it in the next fraction

[prisma yew]

Ok

After canceling I get 3 miles times 60 min times 5280 feet times 12 inches

Oh wait

5280 times 3 times 12

Ohhhh that makes sense

Thx

Smallest units will be the final units of the conversion right, like if there is hours and minutes it will always be minutes

Wait me need help again on another question

Peyton is a sprinter who can run the 40 yard dash in 4.5 seconds. He converts his speed into miles per hour as shown below.

Which ratio is incorrectly written to convert his speed

1. 3ft/1yd
   2)5280ft/1mile
2. 60 sec/1min
3. 60min/hour

So far I got 40 yd * 3 ft * 5280 ft * 60 sec * 60 min

But I think I did something wrong

Wait it prob 3

I don’t think I needa solve it

Ok this I need actual help

olivia entered a baking contest. as part of the contest, she needs to demonstrate how to measure a galloon of milk if she only has a teaspoon measure. she converts the measurement using ratios below: which ratio is incorrectly written in olivia's conversion?

4 quarts/1 galloon * 2 pints/1 quart * 2 cups/1 pint *1/4/4tablespoons * 3 teaspoons/1tablespoon.

1. 4quarts/1gallon
2. 2 pints/1quart
3. 1/4 cups /4tablespoons
4. 3 teaspoons/1 tablespoon

I asked ai but ai keeps saying 1/4 cups is 8 tablespoons even when it said 1/4 cups is 4 tablespoons

[obsidian coral]

And that is why you don't trust ai

[prisma yew]

“So am I. The conversion factor of 1/4 cups to 8 tablespoons is the same for US tablespoons and cups. There are 16 US tablespoons in 1 US cup, so there are 8 US tablespoons in 1/4 US cup. This is a standard measurement that is used in most recipes and cooking instructions. You can check this by using a US measuring cup and a US measuring spoon. Do you have those tools?”

Bro I’m mad confused

I think I just lost 1 million of my brain cells

Am i wrong or is this AI got 0 brain cells

[obsidian coral]

And that is why you don't trust ai

[prisma yew]

Also help pls

I think number 1 is right

All of them seem right

I think it 3

Maybe

[obsidian coral]

Do you remember this part?

any same unit on opposite sides cancel each other
whatever is left over is the final conversion

on denominator and numerator cancels each other out

[prisma yew]

Ye

[obsidian coral]

4 quarts/1 galloon * 2 pints/1 quart * 2 cups/1 pint * 1/4/4tablespoons * 3 teaspoons/1tablespoon.

Start cancel things out

[prisma yew]

Ok

Hold I I needa watch chemistry guy math man video cuz it still confuse

Ok

So

Wait

Nvm

[obsidian coral]

4 quarts/1 galloon * 2 pints/1 quart * 2 cups/1 pint * 1/4/4tablespoons * 3 teaspoons/1tablespoon.
Can you cancel quarts?

[prisma yew]

Yep

I Cancel pints also

That’s all I could cancel I think

[obsidian coral]

4 quarts/1 galloon * 2 pints/1 quart * 2 cups/1 pint * 1/4 cups/4tablespoons * 3 teaspoons/1tablespoon.
That's the more exact way

Can cups cancel out?

[prisma yew]

They both on numerator

Oh wait

Wait yeah they both on numerator

[obsidian coral]

Do you see what ratio is wrong now?

[prisma yew]

I think it’s cups but idk how

[obsidian coral]

Can cups cancel out?

[prisma yew]

No

[obsidian coral]

The goal is to convert from your starting unit to the end goal unit, leading up to the last fraction you should end up with your end goal unit

In that case teaspoon

[prisma yew]

My brain hurting rn

What about teaspoon

[obsidian coral]

That's the end goal unit

[prisma yew]

Yea cuz it’s smallest

[obsidian coral]

No, it's not because of that

[prisma yew]

Oh

[obsidian coral]

It's because Olivia, only has teaspoons

[prisma yew]

Ohhhh

[obsidian coral]

4 quarts/1 galloon * 2 pints/1 quart * 2 cups/1 pint * 1/4 cups/4tablespoons * 3 teaspoons/1tablespoon.
Would you end up with teaspoons?

[prisma yew]

Yea

[obsidian coral]

Start cancel things out

Can you cancel quarts?
Can you cancel pints?
Can cups cancel out?

[prisma yew]

Quarts yeah

Pints yeah

Cups no

[obsidian coral]

Do you see what the answer to your question is now?

[prisma yew]

3?

[obsidian coral]

Do you understand why?

[prisma yew]

not really

Wait

[obsidian coral]

It all goes back to this

Start cancel things out
Can you cancel quarts?
Can you cancel pints?
Can cups cancel out?

[prisma yew]

The tablespoons don’t matter cuz one is 4 table spoons and the other is just 1 right

[obsidian coral]

4 quarts/1 galloon * 2 pints/1 quart * 2 cups/1 pint * 1/4 cups/4tablespoons * 3 teaspoons/1tablespoon.
Would you end up with teaspoons?

[prisma yew]

Yea

But why did u not ask can we cancel out tablespoons

[obsidian coral]

The unit you need to end up with is suppose to be in the numerator

[prisma yew]

Oh

I get it now

Thx

.close

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[ruby sundial]

I have trigonometry questions

[runic garnet]

[ruby sundial]

Oh hi! So I’m doing homework and it’s due in like 2 hours and I have no idea what I’m doing🥲

[teal nest]

Send the questions and let's see if we can get u help

[ruby sundial]

Thank you! Just a sec!

It’s only 2 questions but each got multiple parts

So do you think you can help me 🥲

[royal loom]

!status

[cedar kiln]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[ruby sundial]

1

[flint wren]

so for the first one(like the first picture u posted), I would suggest u use the defenetion of cos to solve for x

since u have lenght of the hypotnuse and the angle near x(90 degree one)

[cedar kiln]

@ruby sundial Has your question been resolved?

[cedar kiln]

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[pale iris]

can someone help me solve this

please and thanks my mmidterm is tom

[obsidian coral]

You really don't need to keep opening a new channel, especially when you ping helpers then immediately close it

[pale iris]

to be honest i dont think the helpers ping does anything

[obsidian coral]

It pings anyone who's a helper

[pale iris]

also how come u respond but then not help 💀

[obsidian coral]

Because I see you trying to bump your question to the top and I needed to say something about it

[pale iris]

there isnt a rule about it

so its allowed

.close

[cedar kiln]

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[upbeat frigate]

How can I complete this simple integral

[cedar kiln]

@upbeat frigate Has your question been resolved?

[cedar kiln]

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[tranquil plank]

Having trouble with part a here, just not sure how to approach it.

[tranquil plank]

I'm going to keep working on it, ping me if you can help please!

I'm getting that after using Leibniz rule and plugging in something, that:
E'(t)=u_t(x,0)^2+c^2u_x(x,0)^2-u_t(x,L)^2-c^2u_x(x,L)^2+2c^2*integral from 0 to L of (u_t(x,t)u_xx(x,t) + u_x(x,t)u_xt(x,t))dx

Sorry for the cluttered notation there

[cedar kiln]

@tranquil plank Has your question been resolved?

[tranquil plank]

<@&286206848099549185>

[tranquil plank]

No i think I did smthin wrong here

Yeah I did

[tranquil plank]

I figured it out on my own!

.close

[cedar kiln]

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[kind gale]

I need help with this problem I’ve gotten to the point of finding the common denominator which is 4 and the fractions become 2/4 - 3/4 = 1/4 and I subtracted the whole numbers but idk what to do now

[teal nest]

what's the question

[nova snow]

I assume 4(1/2) - 2(3/4)

[kind gale]

What do I do after getting to the point of subtracting the new fractions?

[nova snow]

You know you can do this an easier way

By converting the mixed fractions into an improper fraction

And going from there

[teal nest]

Yup

turn 4 1/2 into 9/2

and for the other fraction too

[kind gale]

Okay I will try that.

[nova snow]

This will only confuse you more

[kind gale]

Okay so after I change it into a improper fraction do I subtract them?

[nova snow]

Are the denominators the same?

[kind gale]

I’m doing it now give me a sec

The denominators aren’t the same 9/2 and 11/4

Do I find the common factor between denominators?

[vague kelp]

Yeah

[nova snow]

Lowest common factor yes

[vague kelp]

Do a lcm

To make it same

[kind gale]

Okay this is what I got so far should I be doing multiplication or division?

[nova snow]

what’s with the bottom fraction of 11/4

where’d you get that

[kind gale]

From 2 3/4 I multiplied 2x4=8 then I added the numerator 3 and got 11. Then I kept the denominator the same .

[nova snow]

You did it wrong

wait

never mind

ignore that

Actually no you still did it wrong

[kind gale]

This is the original question for the problem.

[nova snow]

I don’t know why you’re multiplying 11/4 by 4/4

[kind gale]

Wait your right I did it wrong

It should be 11/4 right?

[nova snow]

Yes

make 11/4 and 9/2 have common denominators

[kind gale]

Okay give me a sec

I should be finding multiples of 4 and 2 right?

[nova snow]

what number can you multiply the denominator of 9/2 to make it the same as 11/4

[kind gale]

2

[nova snow]

Then do that

after that then you can subtract the fractions

[kind gale]

Okay I got 2/4 or 1/2 but I still need to work in the whole numbers

[nova snow]

Did you do 18/4 - 11/4?

[kind gale]

I just did and got 7/4

[nova snow]

Yeah that’s correct

If you need it in a mixed fraction just convert it back to one using the opposite process of turning a fraction improper

[kind gale]

The book says the answer to 4 1/2 - 2 3/4 = 1 3/4

I’m still so confused but I’ll eventually figure it out

.close

[cedar kiln]

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[random urchin]

bit confused on how to solve this

the answer is supposed to be 3

i know first step is to flip the right side and make it multiplication

so

after this im not 100% sure

[nova snow]

you can put it into one big fraction and multiply it together

For example the denominator would be (x^2-7x+6)(2x)

[random urchin]

(x^2-7x+6)(2x)

sp

so

2x^3-14x^2+12x

top becomes

6x^3-42x^3+36x

and

if you multiply the bottom by 3

they match

so the answer is 3?

[nova snow]

Hold on lemme do it

Yep

[random urchin]

ty

[nova snow]

That’s correct

[random urchin]

.close

[cedar kiln]

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[tough plinth]

can someone explain how i should setup my an bn and a0 for a piecewise function with more than 2 conditions?

do i just have to combine the integral from -pi to +pi as a combination of the following?

-pi to 0

0 to pi/2

pi/2 to pi

[radiant topaz]

what are an,bn

[tough plinth]

nvm i think i got it

.close

[cedar kiln]

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[plush ravine]

I'm turbo sleep deprived and need to estimate a number with 6 decimal places of accuracy. Where E is the error which of these requirements would be correct:
(1) E <= 5*10^-7
(2) E < 10^-6

[slow thicket]

so

write them out

E <= 0.0000005

and E < 0.000001

@plush ravine

[plush ravine]

uhhhhh yeah I think I should do the top one

But I'm borderline dumb irl from 30 hour no sleep which is why im asking for help

Needs to be turned in

@slow thicket

[slow thicket]

bro why

go sleep

[plush ravine]

yeah yeah I need to finish it man

[slow thicket]

why do you think its the first one

[plush ravine]

u round up from 5 right

so u do 1 10^-7 instead of 10^-6

makes sense or no?

makes sense in my head

but im asking help since might be complete brainfart

oh wait

not

=

fucking

[crimson sedge]

why have you been up for 30 hours?

[plush ravine]

dog died

:(

[crimson sedge]

sorry

[plush ravine]

its ok

[crimson sedge]

he's in dog heaven

[plush ravine]

true and real

[crimson sedge]

100%

athiesms got nothing on it

[plush ravine]

fuck it ig im going with >5*10^-7

🙏

[cedar kiln]

@plush ravine Has your question been resolved?

[slow thicket]

that is correct

.close

[cedar kiln]

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[crimson sedge]

how to solve this ?? we have to find the range of x in the question

[frozen rock]

log can't have anything that is 0 and below so find the range of x for log_2(2x^3+5x^2-14x) then log_3(log_2(2x^3+5x^2-14x)) and keep doing that.

[crimson sedge]

sorry to say but i didnt get it

can you explain it again ?

[frozen rock]

this is how log_2(x) looks, there are no values for x <= 0

[crimson sedge]

ok

[frozen rock]

pretend 2x^3+5x^2-14x is just one variable like log_2(z) where z = 2x^3+5x^2-14x so find what values make log_2(z) > 0 and then keep doing that for every log