#help-13

1 messages · Page 89 of 1

zenith sail
#

Notice that x is the radius of the smaller red circle

lusty marlin
#

I see

zenith sail
#

Do you see why that is helpful?

#

For learning about the second triangle?

lusty marlin
#

so I can find out the radius of the larger circle

zenith sail
#

right, that's what you're after

vagrant elbow
#

you can get the length of the base of the second triangle

zenith sail
#

right, it's also the radius of the smaller circle

lusty marlin
#

yh, but I need the base for the larger triangle

zenith sail
lusty marlin
#

oh yh

#

so I get the hypotenuse of the larger triangle as 3^1/2

#

which equals the radius of the larger circle

zenith sail
#

right yeah

lusty marlin
#

what length does the "y" represent

zenith sail
#

it's just that x-value on the x-axis

#

But if the center of the circle is at (0,0)

#

and it passes through (y,0) on the x-axis

#

then the radius is y

#

the distance from (0,0) to (y,0)

lusty marlin
#

Now I get it

zenith sail
#

🎉

lusty marlin
#

thx

zenith sail
#

no problem

lusty marlin
#

.close

cedar kilnBOT
#
Channel closed

Closed by @lusty marlin

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

terse tartan
#

Hello

cedar kilnBOT
terse tartan
#

Can I get some help

#

?

#

.close

cedar kilnBOT
#
Channel closed

Closed by @terse tartan

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

bronze pivot
#

how to know the best test to use on this?

bronze pivot
#

the best series test

radiant topaz
#

p

bronze pivot
#

what?

radiant topaz
#

p

bronze pivot
#

??????

tropic oxide
#

i'd go with cauchy condensation

#

or integral

#

reducing this to a p series would take a bit of work would it not? @radiant topaz

bronze pivot
#

oh i mean absolute convergence test

#

my bad

tropic oxide
#

both of these tests i suggested require the terms of your series to be positive

#

so convergence and absolute convergence are one and the same unless you blind yourself to that sort of thing

#

ah wait, you can also compare with a p series...

bronze pivot
#

yeah

#

how do i prove this

bronze pivot
#

without graphing

tropic oxide
#

$\log(n) < n^{p}$ for any positive $p$

wraith daggerBOT
tropic oxide
#

so n^(1/2) log(n) < n^(1/2) * n^(1/2)

tropic oxide
# wraith dagger **Ann**

it must be said of course that this inequality holds eventually rather than outright for all n.

bronze pivot
#

why

tropic oxide
#

for example if you take p = 1/5, log(n) is actually greater than n^(1/5) for quite a while, but n^(1/5) takes over at n somewhere around n=330,000

#

so the inequality ln(n) < n^(1/5) taken in full literality is only true for n greater than that value

bronze pivot
#

damnn this is so hard

#

series is so hard for me 😦

tropic oxide
#

well, ln(n)<n^(1/2) actually does happen to hold for all n

#

so there's that

radiant topaz
#

Ye

tropic oxide
#

but my idea was that you should not be afraid of a series violating some property on a finite number of terms

bronze pivot
bronze pivot
#

am i doing this right so far

#

is this right?

#

can someone tell me please

bronze pivot
radiant topaz
#

Yes it is wrong

bronze pivot
bronze pivot
radiant topaz
#

Yes

wraith daggerBOT
bronze pivot
#

why did you put two sqrt(n)'s

radiant topaz
#

I multiplied both sides by 1/sqrt(n)

bronze pivot
#

why?

radiant topaz
bronze pivot
#

ohhh

#

okay

bronze pivot
radiant topaz
#

It depends on question

#

That's why there are a lot of methods

bronze pivot
#

also i am just bad at proving

#

and picking what to compare it o

radiant topaz
bronze pivot
#

integrals were easier than this

#

how do I get better?

radiant topaz
#

Just solve questions and try to be comfortable tackling different types of problems

bronze pivot
#

im trying

#

but I keep failing

radiant topaz
#

Keep on trying

bronze pivot
#

and also I get stuck

radiant topaz
#

Then you can ask here

bronze pivot
bronze pivot
bronze pivot
radiant topaz
bronze pivot
bronze pivot
radiant topaz
#

No

bronze pivot
#

it's correct now?

#

nothing missing?

tropic oxide
#

four pings opencry

bronze pivot
#

is it wrong 😦

#

ohh

#

its wrong

radiant topaz
bronze pivot
#

I should've said

radiant topaz
#

No

bronze pivot
#

p = 1

#

not p = 1/2

#

so this one is right

#

?

bronze pivot
radiant topaz
#

Yes

bronze pivot
#

but we are comparing it with 1/n

#

and p is not = 1/2

radiant topaz
#

Who said p=1/2

bronze pivot
#

me

#

awhile ago

radiant topaz
#

p=1

bronze pivot
#

yeah

#

we are comparing it with 1/n

#

.close

cedar kilnBOT
#
Channel closed

Closed by @bronze pivot

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

long mauve
#

How to do this

cedar kilnBOT
long mauve
#

.close

cedar kilnBOT
#
Channel closed

Closed by @long mauve

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

worn frigate
cedar kilnBOT
worn frigate
#

why did they do 5m-x

#

they have already said its 5m

tough carbon
#

therefore the remaining metres would be 5 take away whatever x metres was for the base

cedar kilnBOT
#

@worn frigate Has your question been resolved?

#
Channel closed

Closed by @worn frigate

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

grand raft
#

In a circular square there are stands of 100 merchants, each of which has a certain amount of coins. all
A merchant sells fish at his own fixed price. Each merchant has an unlimited supply of fish. on the first day one
of the merchants had assembled a golden rod. Each day thereafter the merchant holding the gold rod goes to the merchant's booth
The next in the circle, hands him the rod and then buys from him as many fish as possible according to the money he has.
If the merchant fails to buy fish at all on any day, that day will be called a sad day.
They proved that if the day 2022 is a sad day then the day 2023 will also be a sad day

grand raft
#

I know the answer but I have a question

#

Doesnt it mean all days are sad?

#

pls smart people

cedar kilnBOT
#

@grand raft Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lime crystal
cedar kilnBOT
lime crystal
#

How would you solve this?

devout prairie
#

What is the relation between two consicutive terms in arithmetic sequence

lime crystal
#

the difference?

devout prairie
#

Un + r = Un+1

crimson sedge
lime crystal
crimson sedge
#

b)maxm sum will be possible till last term becomes zero so till n=31 use sn = n(a+l)/2

lime crystal
#

ohhhhhhhhhh

#

oh my god

#

thank youu

crimson sedge
#

it will give 697.5

crimson sedge
devout prairie
#

First and last term

lime crystal
#

oh alr

#

.cloose

#

.close

cedar kilnBOT
#
Channel closed

Closed by @lime crystal

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

wide scaffold
#

if (A\B) ∩ C = ∅ then .A ∩ C ⊆ B

cedar kilnBOT
wide scaffold
#

That statement is wrong right?

#

I did some things and got to the point where x is element of A ∩ C but not in B

#

just making sure I am corret

cedar kilnBOT
#

@wide scaffold Has your question been resolved?

wide scaffold
#

if (A\B) ∩ C = ∅ then A ∩ C ⊆ B

earnest fiber
#

Yeah, the statement is wrong

#

You can see it just by assigning some nums to it.
Let's say A is {1, 2} B is 3, 4 and C is 5, 6
Here the first one would hold true but the second one would not

wide scaffold
#

so the empty set is not considered

#

like can we not say that A intersect C = {} and {} is in B?

earnest fiber
#

Hmmm, yeah, now that you say that, we can

wide scaffold
#

That's why im confused

#

Sorry for the language, I tried this
not sure if the process is correct though

earnest fiber
# wide scaffold

Well, after the step (B complement) intersection with (A intersection C)
It's clear if you visualise it. If the value of it is a null set that means the B complement has nothing in common with A intersection C. This means that whatever exists in A intersection C must exist in B also

#

Not sure how to write it tho

cedar kilnBOT
#

@wide scaffold Has your question been resolved?

wide scaffold
#

Maybe I can use contrapositive if NOT(A ∩ C ⊆ B) then NOT((A\B) ∩ C = ∅)

#

So here's my final proof to if NOT(A ∩ C ⊆ B) then NOT((A\B) ∩ C = ∅):
"We assume the x is an element in AnC => (x element in C and A)(x not element in B)
From here, we check if (A\B)nC≠∅
Since x is element in A and x is not element in B then we can say that x is an Element in (A\B)
Plus, according to our assumption x is element in C
Therefore, x is an element in (A\B)nC
SO IT CANT BE (A\B)nC=∅"

#

That's a clearer way to put it since my terminology sucks in English

wide scaffold
#

.close

cedar kilnBOT
#
Channel closed

Closed by @wide scaffold

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

turbid spoke
#

somoene can explain me this ?

cedar kilnBOT
turbid spoke
cedar kilnBOT
#

@turbid spoke Has your question been resolved?

#
Channel closed

Closed by @turbid spoke

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

cedar kilnBOT
#

@cinder stratus Has your question been resolved?

cinder stratus
#

.close

cedar kilnBOT
#
Channel closed

Closed by @cinder stratus

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

terse tartan
#

Hello

cedar kilnBOT
terse tartan
#

Can i get

#

Your help on my hw

#

Cool thank you

#

Ok

#

So that’s the problem

#

This is my attempted solution

mental trail
#

The point is to bring every thing to the same denominator

#

Start back from the 3rd line

#

Actually even the 2nd line is good

mental trail
terse tartan
#

Ok so from the third line?

mental trail
#

How did you bring sin(t) inside the fraction?

terse tartan
#

(Cos(t)Cot(t))/sin(t) x Sin(t)/1

#

Ah wait i think i made a mistake

#

I am a little lost

mental trail
#

Alright

#

I will give you a small example

#

If i have a number, let's say 5, but I want to write it with a denominator of 6, i write 5 = 5×6/6 = 30/6

#

If I have a quantity x, but I want this under a denominator of y, I write : x = xy/y

#

So if I want sin(t) written with a denominator of sin(t), what do I write?

terse tartan
#

Sin(t)sin(t)/sin(t)

#

?

#

Or 1/sin(t)?

#

Can i get your help?

#

.close

cedar kilnBOT
#
Channel closed

Closed by @terse tartan

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

crimson sedge
#

This is confusing

cedar kilnBOT
#

Please don't occupy multiple help channels.

crimson sedge
#

.close

cedar kilnBOT
#
Channel closed

Closed by @dapper lantern

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

upbeat loom
#

I have forgot how I am supposed to evaluate this

cedar kilnBOT
#

@upbeat loom Has your question been resolved?

west gazelle
#

you’re integrating the y variable

#

so x is like a constant

#

and you only need to integrate the cos(y)

upbeat loom
west gazelle
#

sin(3pi/2) - sin(pi)

upbeat loom
#

i literally just realized as you where typing. = -x. lol

#

thx

#

.close

cedar kilnBOT
#
Channel closed

Closed by @upbeat loom

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

torpid urchin
cedar kilnBOT
torpid urchin
#

could someone explain why my coefficients are wrong?

#

i think it must have to do with having the wrong series?

silk thistle
#

The function is +8x not -8x

torpid urchin
#

right i ended up noticing that

#

and flipped that 8 to -8 inside the bracket

#

but i feel like there is more wrong as the c1 term would still be 8

#

which is wrong

#

have i done something wrong?

dire geode
torpid urchin
#

oh yeah i need cnx^n

dire geode
#

what is the first term?

torpid urchin
#

c_0

#

right

#

cn

#

so i need to change my series to fit that form?

#

wait.

#

its a taylor series?

dire geode
#

doesn't matter what you call it

torpid urchin
#

hm

#

so how could i put it into that form

dire geode
#

google how to shift power series

torpid urchin
#

ok

#

so is what i have up to now fine though?

dire geode
#

probably

torpid urchin
#

ok

#

would the x^n here atleast imply a=0?

dire geode
torpid urchin
#

alright

#

i tried working with it as a taylor series but cant figure out this last part of it

#

also missed a -1^n in front

dire geode
#

that's definitely the wrong way to do the problem

dire geode
dire geode
torpid urchin
cedar kilnBOT
#

@torpid urchin Has your question been resolved?

#
Channel closed

Closed by @torpid urchin

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

frosty sphinx
#

Is it possible to turn indefinite integral into definite integral? (turn the generalized form of the integration integral f(x) at y to integral f(x) from a to b, that a and b are some real numbers with respect to the function f and the real number y)
It'd be useful to calculate the indefinite integral programmitically, and approximate it as we could do in definite integrals (using Riemann's sum)

cedar kilnBOT
#

@frosty sphinx Has your question been resolved?

lethal jackal
#

not sure what you mean by approximate an indefinite integral

#

indefinite integrals don't have numerical values

frosty sphinx
lethal jackal
#

huh?

#

suppose I write that the indefinite integral of 2x dx is x^2 + C

frosty sphinx
#

Assuming that integral f(x) = g(x), I want to get the numberical value of the the function f at a point, like y

lethal jackal
#

what value does that have

frosty sphinx
lethal jackal
#

huh? no it's not

frosty sphinx
lethal jackal
#

okay so you get 25 + C

#

that could literally be any number

frosty sphinx
lethal jackal
#

then that's not an indefinite integrla

#

that's a definite integral

frosty sphinx
#

:/

lethal jackal
#

$\int_0^x 2t , dt = x^2$

wraith daggerBOT
#

Saccharine

frosty sphinx
# wraith dagger **Saccharine**

For this example, this statement is true. But not necessarily
That's true, if and only if the indefinite integral of it at 0 is 0

lethal jackal
#

no you're not making any sense whatsoever

frosty sphinx
#

Assuming the integral of the function f is F, this statement is true, only when F(0) = 0

lethal jackal
#

the indefinite integral doesn't have a defined value at a point

frosty sphinx
lethal jackal
#

suppose you say that an indefinite integral of a Riemann-integrable function f is F such that F' = f

lethal jackal
frosty sphinx
lethal jackal
#

if you assume that integral of something on a certain interval = 0

frosty sphinx
#

The indefinite integral is being defined by F(b) - F(a)

lethal jackal
#

no, that's a definite integral

frosty sphinx
lethal jackal
#

$\int_a^b f(t) , dt = F(b) - F(a)$

wraith daggerBOT
#

Saccharine

frosty sphinx
lethal jackal
frosty sphinx
#

..how am I supposed to calculate F^-1(0)?

lethal jackal
#

what are you even saying

#

suppose you say that an indefinite integral of a Riemann-integrable function f is F such that F' = f
do you agree with this definition of indefinite integral?

lethal jackal
#

then how are you supposed to figure out a unique value for F(1), for example?

#

it could literally be anything

#

suppose you have an F that works

#

what privileges that over something like G = F + 25

frosty sphinx
lethal jackal
#

obviously C isn't known

frosty sphinx
#

We can say it with respect to C, or well, assume that C = 0

lethal jackal
#

that's the indefinite part of the indefinite integral

#

that still doesn't make any sense

#

I can write something like $\int 2t ,dt = t^2 + 4 + C$

wraith daggerBOT
#

Saccharine

frosty sphinx
frosty sphinx
lethal jackal
#

that still doesn't make any sense

#

a function is just something that takes in a value and spits out a value

#

how I choose to write it has no bearing on what it does

frosty sphinx
lethal jackal
#

no you can't limit it like that

#

that "limit" makes no sense

#

there is nothing that makes t^2 more "pure" than t^2 + 4

#

I can keep giving worse and worse examples

frosty sphinx
lethal jackal
#

you need to state an actual mathematical way you're going to define the value of an indefinite integral

lethal jackal
#

how do you define whether a function contains an integer or not?

frosty sphinx
#

You can turn t^2 + 6 - 6 to t^2, with no integer after
"exists a function equavaliant to that, being added by no integer"

lethal jackal
#

that's not a mathematical definition

#

you need to define what a function is based on the behaviour of its inputs and outputs

#

because functions are literally just the list of inputs and the list of outputs

frosty sphinx
lethal jackal
#

how do you define "has an integer" if it's just {(0, 5), (1, 6), (2, 9), (3, 14), ...}

#

I'm just going to straight up tell you that there's probably no definition along this approach that makes any sense at all

lethal jackal
frosty sphinx
#

...

lethal jackal
#

you can keep trying to patch what you think are loopholes

#

but the problem here is your definitions don't make any mathematical sense

frosty sphinx
lethal jackal
#

let me ask you

#

what's the value of the indefinite integral of 2x + 2 at 0?

#

your supposed defined value

frosty sphinx
lethal jackal
#

why isn't it 1

frosty sphinx
lethal jackal
#

it's x^2 + 2x

#

okay but why can't I say that x^2 + 2x + 1 is

#

why can't I say that C = 0 for x^2 + 2x + 1 + C

frosty sphinx
# frosty sphinx cuz I assumed that C = 0..

And when you say like, "I can do it like 4 + C", now you defined another constant C' = 4 + C = 4 - as the assumation, the constant (that became C' now) should be equal to 0, but here it isn't

lethal jackal
#

why can't I say that an indefinite integral of 2x + 2 is x^2 + 2x + 1

#

and therefore the general indefinite integral is x^2 + 2x + 1 + C?

frosty sphinx
lethal jackal
#

yeah C = 0

#

so the value is 1

#

do you see how little sense that makes?

frosty sphinx
#

I did that, to make me being able to solve the problem

lethal jackal
#

huh?

#

why isn't the value 1

#

I set C = 0

frosty sphinx
lethal jackal
#

no I'm not

#

I can say that it's (x+1)^2 + C

#

I'm not adding anything now!!!!

frosty sphinx
lethal jackal
#

huh?

frosty sphinx
#

The constant == the value that if you change it in the function, the derivative of it wouldn't be changed

frosty sphinx
lethal jackal
#

why is THE of indefinite integral of 2x+2 supposedly defined as x^2 + 2x

#

instead of (x+1)^2

frosty sphinx
frosty sphinx
lethal jackal
lethal jackal
frosty sphinx
lethal jackal
#

no it made absolutely no sense

frosty sphinx
lethal jackal
#

what is "value that if you change it in the function"

#

a function is defined by its outputs and inputs

#

let that sink into your head

frosty sphinx
frosty sphinx
lethal jackal
#

it is quite literally the set of ordered pairs {(input1, output1), (input2, output2), ...} (well, it's not countable, but whatever)

#

no you don't

frosty sphinx
#

Let's leave the previous things that I defined

lethal jackal
#

you clearly don't

#

because your definitions don't make any sense in that context

frosty sphinx
lethal jackal
#

wtf does "the value that if you change it in the function" even mean

frosty sphinx
lethal jackal
#

how do you get 4 from {(0, 4), (1, 5), (2, 8), ...}

lethal jackal
frosty sphinx
lethal jackal
#

that definition makes no sense

#

if you add ANY number to a function

#

it doesn't change the derivative

#

how are you going to claim that's unique

#

yknow what

frosty sphinx
lethal jackal
#

adding ANY of those numbers doesn't change the derivative

frosty sphinx
#

We actually cannot

lethal jackal
#

I'm not asking you to FIND it

#

I'm asking you to DEFINE it

lethal jackal
#

you still haven't explained why "the" indefinite integral of 2x + 2 is x^2 + 2x instead of (x+1)^2

frosty sphinx
lethal jackal
#

stop

frosty sphinx
#

:/

lethal jackal
#

just answer my question

#

you still haven't explained why "the" indefinite integral of 2x + 2 is x^2 + 2x instead of (x+1)^2

#

this one

#

if you're going to try to construct some other dumb rule

#

stop

#

I have MORE examples where your patching up will fail

#

you just fundamentally misunderstand what x^2 + C means

frosty sphinx
lethal jackal
#

and say that x^2 + 2x is the one with the constant

#

yknow what

#

just sotp

#

stop arguing

#

it's very obvious that whatever approach you're using to define the value of the indefinite integral of something

#

is completely baloney

#

the standard definition of the indefinite integral does not admit talking about its "value" at something -- it's nonsense

frosty sphinx
#

Or maybe define it like that: "if doesn't exist a function equavaliant to the function f that by changing a literal value of it the derivative of it would change, the function has the constant 0"

lethal jackal
#

stop

#

that's just a word salad at this point

frosty sphinx
lethal jackal
#

do you know what $\int 2t , dt = t^2 + C$ means?

wraith daggerBOT
#

Saccharine

frosty sphinx
lethal jackal
#

what does it mean

frosty sphinx
#

The derivative of t^2 + C, whatever C is, becomes 2t

lethal jackal
#

it means that ANY function that can be written in the form t^2 + C has derivative 2t

#

that is LOGICALLY EQUIVALENT to saying any function that can be written in the form t^2 + 4 + C has derivative 2t

frosty sphinx
#

Ok

lethal jackal
#

one way of writing it is not any more "correct" than the other

#

so your idea of somehow "setting C = 0" makes no mathematical sense

#

and stop trying to insist it does

frosty sphinx
#

That's right. But I'm trying to filter some results of the function, so I can solve the actual problem, by changing what we assume
And I'm too sleepy now, and my brain doesn't work

#

So, maybe, bye for now

lethal jackal
#

you can't filter that stuff

#

you need to reconsider wtf you mean by approximate an indefinite integral

#

there are a ton of other examples

#

one that comes to the top of my mind is something like 1/(4x)

lethal jackal
#

no you weren't

#

you were just trying to assert that an indefinite integral has a value

frosty sphinx
lethal jackal
#

when under the standard definition, that makes absolutely no sense

#

your definitions are just word salads

#

they make no sense

#

how about instead of saying indefinite integral

#

you state exactly what you want

#

just state some properties

frosty sphinx
#

Don't expect my brain to be perfect after 18 hours of being awake, and the moment before I sleep..

#

I don't even know what I'm doing

lethal jackal
#

are you trying to find any function F such that the integral of f is F(b) -F(a)?

frosty sphinx
lethal jackal
#

no it's not

frosty sphinx
#

..anyway, I prefer to sleep now

lethal jackal
#

the indefinite integral describes an entire class of functions

frosty sphinx
lethal jackal
#

no it's not

#

it's asking to find an antiderivative of f

#

an

cedar kilnBOT
#

@frosty sphinx Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

bronze briar
#

if anyone is familiar with the ti-nspire CX II calculator, is it possible to copy a .py file from my pc to the calculator? I found a reddit post about this but there were no distinct answers

cedar kilnBOT
#

@bronze briar Has your question been resolved?

bronze briar
#

.close

cedar kilnBOT
#
Channel closed

Closed by @bronze briar

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

flint plinth
#

this isn't really suitable for a help channel, see guideline 3:

#

nah that dude was wrong to suggest that

cedar kilnBOT
#

@fossil ridge Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

twilit lagoon
#

how do this

cedar kilnBOT
solid thorn
#

Do you know how sine and cosine work?

#

@twilit lagoon

twilit lagoon
#

i know how to press it on a calculator that is the limit of my understanding

solid thorn
#

I’ll just send a video to explain then

#

Goes into depth but if you don’t have time skip to 11 minute mark

#

It actually talks about relevant stuff there

#

For you

cedar kilnBOT
#

@twilit lagoon Has your question been resolved?

#
Channel closed

Closed by @twilit lagoon

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

small willow
#

hi guys i need help with how to find the range of values for Δc_j for which the solution remains optimal. i know how to do it for variables with are non basic, but im not sure how to get it for basic variables. heres the tableau and the obj functions. i already found the ranges for x2 and x3, but again, im not sure how to obtain the ranges for x1 and x4

small willow
#

looking at the textbook i understasnd that i need to use the formula below, but im not sure how to find and plug the numbers into it

cedar kilnBOT
#

@small willow Has your question been resolved?

small willow
#

no bro no one said anything

cedar kilnBOT
#

@small willow Has your question been resolved?

#
Channel closed

Closed by @small willow

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

civic elk
#

How do I find the actual value? It wasn’t given by my teacher

dire geode
#

Go back and read the previous information and figure it out

civic elk
#

It’s a titration lab where we have to find the percentage of vinegar

civic elk
inland ocean
#

Can you show the whole

#

Question

civic elk
#

I can try and get the whole lab

inland ocean
#

Sure that'd be nice

#

The actual value is the mean of all the readings of your experiment

civic elk
inland ocean
#

The final absolute value or the absolute mean value is the mean of the difference in your true value and the respective readings

#

When you divide that by the actual value and mulitply it by 100 you get the percentage error

civic elk
#

Well the problem is I don’t have the actual value

#

And idk where to find it, the teacher never talked abt it

inland ocean
#

I just mentioned what the actual value was

civic elk
#

Ohh, didn’t see that sorry

#

So basically the average

#

Still not getting it

#

I got 1% error?

inland ocean
#

I dont know, i havent read the question.

#

Maybe you are right

civic elk
#

Idk ig I’ll just have to ask tmr

inland ocean
#

Lets start with 3

#

It says to calculate the amount of 0.1M NaOH required to neutralize 50mL of 0.6M acetic acid sol

#

If that is correct

#

$CH_3COOH + NaOH => CH_3COONa + H_2O$

wraith daggerBOT
#

ColdTee

civic elk
#

#3 is correct, just checked it

#

It’s 300ml

inland ocean
#

Looks balanced

#

Okay

#

Lets move on to 5

#

Then

#

I mean 4

civic elk
#

Well 4 should also be correct that’s the one I asked my teacher abt

inland ocean
#

$Molarity = \frac{n}{V}$

wraith daggerBOT
#

ColdTee

inland ocean
#

Its not visible can you tell me what you did in 4

civic elk
#

0.35 (V) = (M)(10ml)
0.35 * 19 = 6.65
6.65 / 10 = 0.665 M

inland ocean
#

Oh

#

It used M1V1 = M2V2

#

Alr

#

How about 5 now

civic elk
#

Duno abt that one

#

Idk what molarity to use

#

The one in 4?

inland ocean
#

Not very visible they multiplied molarity of vinegar with ?

civic elk
#

It seems correct reading it

inland ocean
#

Yeah makes sense

#

Now the final one

#

7

civic elk
#

Number 6 actually

#

The percent error one

inland ocean
#

Yeah 6

#

Alr so

#

The different volume readings for both the compound are given and the molarity have also been given, i think you have to take the mean of the readings of molarity for actual value.

civic elk
#

And what abt the experimental value then?

inland ocean
#

My head hurts

#

Can you wait a min

civic elk
#

Ye, nw

inland ocean
#

Wasnt the one that we calculated the experimental value, wont the actual value be given to us.

civic elk
#

That’s what I was thinking

#

But my teacher never gave us anything

#

For rn, im just Gona put this and turn it in, I’ll ask my teacher tmr

#

Tnx for the help

#

Hope ur head also gets better

#

.close

cedar kilnBOT
#
Channel closed

Closed by @civic elk

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

spare geyser
#

hello <@&286206848099549185>

cedar kilnBOT
cedar kilnBOT
obsidian coral
#

Do not open a channel by pinging helpers as the first message

spare geyser
#

im sorry

#

i was having network challenges. please my question is

#

how do i sketch a pipeline diagram of 6 operational cycles of a typical 8086 microprocessor

#

<@&286206848099549185>

cedar kilnBOT
# spare geyser <@&286206848099549185>

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

halcyon eagle
#

boy what the hell

#

sorry but what in the name of god

spare geyser
#

ikr!

#

😭 😭 😭

cedar kilnBOT
#

@spare geyser Has your question been resolved?

slow thicket
#

this is engineering

cedar kilnBOT
#

@spare geyser Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

pseudo merlin
#

hello

cedar kilnBOT
pseudo merlin
#

why is this wrong

#

.close

cedar kilnBOT
#
Channel closed

Closed by @pseudo merlin

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

wraith daggerBOT
#

LeftySam

#

LeftySam

cedar kilnBOT
#

@unkempt steeple Has your question been resolved?

cedar kilnBOT
#

@unkempt steeple Has your question been resolved?

cedar kilnBOT
#

@unkempt steeple Has your question been resolved?

cedar kilnBOT
#

@unkempt steeple Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

tough plinth
#

could some explain to me why 1/x diverges?

tough plinth
#

was doing the convergence/divergence test for the n/n^2 + 1 infinite series

#

and did the limit comparison

#

where an = n/n^2+1

#

bn = 1/n

scenic fable
#

can you hel me with AMGA

tough plinth
#

amga?

scenic fable
#

algebra matricial y geometría analítica

#

matrix algebra and analytic geometry

craggy perch
#

that's spanish, I don't know who else speaks it

#

and get another channel

tough plinth
#

.close

cedar kilnBOT
#
Channel closed

Closed by @tough plinth

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

molten kernel
#

hello

cedar kilnBOT
molten kernel
#

can someone explain why this is

cedar kilnBOT
#

@molten kernel Has your question been resolved?

modern compass
#

which one?

molten kernel
#

all if possible

#

is that alright @modern compass

modern compass
#

|AxB| = |A| * |B|
|P(B)| = 2^|B|
{2} is an element of A, not a subset
2 is not {2} so 2 is not an element of A

cedar kilnBOT
#

@molten kernel Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

languid fjord
#

What does the bracket(?) mean?

cedar kilnBOT
crimson delta
#

ceiling probably

#

the next largest integer

#

rounding up

languid fjord
#

ah THANKY OU!

#

.close

cedar kilnBOT
#
Channel closed

Closed by @languid fjord

Use .reopen if this was a mistake.

crimson delta
#

otherway around is floor

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

hot iron
#

is it possible

cedar kilnBOT
hot iron
#

to integrate

#

e^(x^3)

#

pretty please

crimson sedge
#

there is no elementary antiderivative

#

you'll have to use the fact that $e^x = \sum_{n=0}^\infty} \frac{x^n}{n!}$

wraith daggerBOT
#

Nika
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

mortal yarrow
#

? it's not just e^(x^3)/3x^2

crimson sedge
#

No

violet rapids
#

nooope

hot iron
#

why would it be that?

mortal yarrow
#

if you derivate you get your first result

hot iron
#

@mortal yarrow explain your though logic

violet rapids
#

because the secret background math equations dont let us

muted bear
#

oh yeah i guess you can use maclaurin

muted bear
#

pepega whats the original problem?

hot iron
#

we can't do that unless there is no x multiplier though righ @mortal yarrow

#

integral of e^(x^3)

dull oxide
muted bear
#

send us a picture or screenshot of the orignal problem pleaes

hot iron
#

uh

dull oxide
#

,w integral e^(x^3)

hot iron
#

i don't own

hot iron
#

gamma rule?

#

again

muted bear
#

it is inevitable

dull oxide
#

Incomplete gamma function

hot iron
#

i do a level maths

#

i'm tripping

dull oxide
#

This is why we keep saying it can't be solved (analytically)

hot iron
#

my bad

dull oxide
#

You either need to do series, or incomplete gamma function

hot iron
#

that's the other rule i forgot

#

series one

dull oxide
#

You're allowed to use series?

hot iron
#

i was trying to tell someone the other way to do it but i forgot the name of it

#

no..

dull oxide
#

Then there is no solution for you

hot iron
#

i was thinking

#

maybe

#

okay

#

idk how to write it so you can visualise it but

#

imagine

#

we integrate by parts an expression

#

and you get the like loop when you do the u'v part of the equation. so uv-integral of u'v

#

Ignore me ong

#

.close

cedar kilnBOT
#
Channel closed

Closed by @hot iron

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

#
Channel closed

Closed due to the original message being deleted

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

plush lagoon
#

how do i do the first one

cedar kilnBOT
plush lagoon
#

help

#

i do 45.0x15.5 = 697.5 cm3 is the answer?

#

nvm

#

help

cedar kilnBOT
#

@plush lagoon Has your question been resolved?

plush lagoon
#

do i do 63.50x1000

#

@cold briar

#

OOPS

#

<@&286206848099549185>

slow thicket
#

@plush lagoonthere are only 2 unique shapes

#

figure out the area for each

plush lagoon
slow thicket
#

I'm not doing the question

#

you didnt even mention which shape

plush lagoon
#

what yes i did

slow thicket
#

which shape

#

there are two

plush lagoon
#

the first shape

slow thicket
#

???

#

im thinking of two numbers

#

which is the first one

#

thats what youre telling me

plush lagoon
#

idk wym

slow thicket
#

which shape are you talking about

#

there are two shapes

#

there is a triangle and rectangle

plush lagoon
#

idk how to get the answer

#

umm both?

slow thicket
#

you gave me a single number

#

there is a different number for each shape

#

how did you calculate 170

plush lagoon
#

i did 17.0x10

#

to mm

slow thicket
#

where did you get 10 from

plush lagoon
#

1cm= 10mm

slow thicket
#

so your first step to calculate the area was to turn a side length from cm to mm?

#

do you know how to calculate area

plush lagoon
#

no

#

what do i do

slow thicket
#

uh

#

what is the area of a square with side length 5

plush lagoon
#

25

#

cus you square it

#

hi?

slow thicket
#

okay

#

what about a triangle with base 15 and height 12

plush lagoon
#

idk how

slow thicket
#

look itup

plush lagoon
#

i don’t understand it

#

can you tell me

slow thicket
plush lagoon
#

oh nah i’m not using fractions how do i do it without that?

slow thicket
#

do you mean (1/2)

plush lagoon
#

yup

#

nvm

#

now what

slow thicket
#

whats the area for the triangle in your hw

dull oxide
plush lagoon
slow thicket
#

nope

plush lagoon
#

1/2 is 2 divided ?

dull oxide
plush lagoon
#

2 divided by 17?

slow thicket
#

no

#

1/2 is one divided by 2

#

if there are two people who are sharing a cookie

#

each person gets 1 cookie divided by 2 people

#

which is half (1/2) a cookie

plush lagoon
#

so what do i do

slow thicket
#

use the formula

#

A = bh/2

#

find the area of triangle

plush lagoon
#

17x45 then what is the /2?

slow thicket
#

thats the rectangle

#

17*45 is the area of the rectangle

plush lagoon
#

what is *

#

oh k

#

the answer is long tho? 0.3777778

plush lagoon
slow thicket
#

b = base, h = height

plush lagoon
#

how do i do 1/2 x 45x17

slow thicket
#

this is what you are dealing with

#

would you happen to be able to call

plush lagoon
#

no

slow thicket
#

ok

#

well

#

45*17 is not a triangle

#

so there is no multiplying by half

plush lagoon
#

ok

#

so it’s lxw

#

what do i do

slow thicket
#

well you have all the numbers

#

just plug them in

plush lagoon
#

WDYM

slow thicket
#

what is l

plush lagoon
#

it’s the 45

#

and 15 .5

slow thicket
#

no

#

how is that possible

#

no shape that you are given has those dimensions

#

draw it out

#

and label l, w, b, h

#

without the numbers

#

just the letters

plush lagoon
#

no can you show it

slow thicket
#

no

plush lagoon
#

the bottom one is l

slow thicket
#

are you on mobile

plush lagoon
#

yes

slow thicket
#

ah

#

draw it out on your paper and send a photo

plush lagoon
#

what do i draw

#

a rectangle

#

i can do a triangle

slow thicket
#

Keep it flat

#

Just draw the rectangle and triangle

plush lagoon
#

so there’s no w anymore

slow thicket
#

There is

plush lagoon
#

i can’t do it i’m gonna kms help pls

slow thicket
#

Gimme a min

plush lagoon
#

how do i do the question thoooo

slow thicket
#

@plush lagoon

#

since they are connected we know that W = B

#

does this make sense

plush lagoon
#

yup

slow thicket
#

okay now you have all the numbers you need

#

plug in

plush lagoon
#

what? 17x 45

slow thicket
#

which area is that

plush lagoon
#

it’s 765

slow thicket
#

which shape

plush lagoon
#

rectangle

slow thicket
#

okay now the triangle

plush lagoon
#

17x15.5?

slow thicket
#

almost

#

this isnt a rectangle so you have a different equation

plush lagoon
#

then divide it by 2

slow thicket
#

yes

plush lagoon
#

now what

#

it’s 131.75

#

then i add them ?

slow thicket
#

not quite

#

count how many of each shape you have

#

cause its not just one of each

plush lagoon
#

4

#

3

#

2

slow thicket
#

there are only two shapes

#

you gave me three numbers

#

and you didnt label which one is which

plush lagoon
#

the rectangle is 765 and the triangle is 131.75

slow thicket
#

yes

plush lagoon
#

???

slow thicket
#

but how many of each are there

plush lagoon
#

wdym

#

2 shapes

slow thicket
#

wel no

#

look back at your paper

plush lagoon
#

ok

#

just what is it

#

what are you sayin

slow thicket
#

each side is a square

#

say it has side length 5

#

the total area of the cube is not just 5*5

#

since there are 6 squares

plush lagoon
#

ok

slow thicket
#

same thing here

plush lagoon
#

so i x all them

slow thicket
#

by how many there are

#

which is...

plush lagoon
#

2 numbers

slow thicket
#

no

#

look at this again

#

this shape is 3D

plush lagoon
#

ok

slow thicket
#

count the rectangles

plush lagoon
#

2

slow thicket
#

not quite

plush lagoon
#

o4

slow thicket
#

yes

#

how many triangles

plush lagoon
#

4

#

i meant 3

slow thicket
#

no

#

also no

#

this is a solid shape

#

like if I give you this

#

its not just 3 squqres

#

theres 6

#

so how many triangles

plush lagoon
#

6

#

5

#

ITS 6

plush lagoon
#

ALL OF THE SHAPE SIDES?

slow thicket
#

it is not 6

slow thicket
slow thicket
#

every rectangle has two triangles at the end

#

how many rectangles are there

plush lagoon
#

2

#

umm

slow thicket
#

no

plush lagoon
#

what is it

slow thicket
#

4

#

you said it before

#

@plush lagoon

#

we almost done

#

how many triangles

plush lagoon
plush lagoon
slow thicket
#

how many triangles are there

plush lagoon
plush lagoon
#

idk

slow thicket
#

There are 4 rectangles

plush lagoon
#

i said 4 and 4

slow thicket
#

No

slow thicket
#

Read it

plush lagoon
#

ok

plush lagoon
slow thicket
#

Read it slowly

#

every rectangle

plush lagoon
#

i did

slow thicket
#

So for every rectangle there are 2 triangles

#

How many triangles

plush lagoon
#

oh the rectangle has 2 triangles

slow thicket
#

Each

plush lagoon
#

yes

slow thicket
#

So how many total

plush lagoon
#

idk

#

4