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livid hound
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but why isnt the solution start from - 3
wdym

steel thistle
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like

jaunty mural
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it might make sense if u plot it on desmos

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what they r doing

steel thistle
#

???

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why isnt the max possible valueof x is - 3

livid hound
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why do you think that would be -3

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how are you reaching that conclusion

steel thistle
#

idkkkk

livid hound
#

a basic approach would be to consider what's happening before, between and after the critical locations

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as they've done described in their steps and on that number line

steel thistle
#

but where does the line between 1 and - 3 comes from

livid hound
#

well 1 is also a critical location

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for values less than 1, x-1 is less than 0
for values more than 1, x-1 is more than 0

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they're just checking the signs for each interval

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but where does the line
what line are you talking about

steel thistle
#

???

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where does the line between 1 and - 3 comes from

livid hound
#

what line

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i don't know what line you're referring to

steel thistle
livid hound
#

ok, well as indicated

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the sign there is negative

steel thistle
#

oh yes

livid hound
#

for values in that interval,
(x-3)^2 is greater or equal to 0
x-1 is negative,

(x-3)^2/(x-1) is negative or 0

steel thistle
#

but

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why cant it be

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(-inf, inf) excluding 1

livid hound
#

well check what happens for values greater than 1

#

and again as indicated by the work,
the expression is + there

#

for values greater than 1,
x-1 is positive
and hence
(x-3)^2/(x-1) will be positive for such values

#

those values don't satisfy the given inequality

steel thistle
#

ohhhhhh

#

.close

cedar kilnBOT
#
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tight cove
#

how does one go about solving this

cedar kilnBOT
livid hound
#

have you made an attempt?

#

not you

tight cove
#

I have made an attempt

#

i got 5

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it was wrong

tropic oxide
#

show your work

dense socket
#

Well if k is a square, you just need to find one side, look at what side has most... info

tight cove
#

i see it now

#

thanks

#

.close

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fallow sedge
#

Can anyone help me solve this question? im not sure how to

livid hound
#

have you tried anything at all?

fallow sedge
#

i tried 72* 2/3 and 80*2/3

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which i got 48 and 53.334

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but now idk what to do

livid hound
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tell me what your calculations were intended to achieve

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i.e. what does doing

72* 2/3
get you

fallow sedge
#

distance = speed * time

livid hound
#

ok

fallow sedge
#

thats what i tried to achieve

livid hound
#

that would be the total distance, yes

fallow sedge
#

ok but idk how to find the time that it took

livid hound
#

with the 80 there, it seems that you identified the new speed would be 80km/h
however you shouldn't be multiplying that by 2/3 hours

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you should again apply the relation between distance speed and time

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you know the distance and the speed

fallow sedge
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mhm

livid hound
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because that would tell you how far they can travel in 40minutes going at 80km/h

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which is pretty much useless to you

fallow sedge
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oh

livid hound
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when you are more interested in finding out how long it'd take to travel the required distance at the new speed

fallow sedge
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idk what to do to change the 2/3 tho

livid hound
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you don't need it anymore

fallow sedge
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ok now you're just confusing me

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im not as wise as you

livid hound
#

you did simplify the

72 (km/hours) * 2/3 (hours)
right?

fallow sedge
#

yea

livid hound
#

and what was the result

fallow sedge
#

48 km

livid hound
#

you should again apply the relation between distance speed and time
you know the distance
48km
and the speed
80km/h

#

t = ?

fallow sedge
#

ohhh ok

#

time is distance divided by the speed

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which is 0.6

livid hound
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0.6 hours,

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do you know how to continue from here?

fallow sedge
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yea

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so that should be 36 minutes

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and 48-36=12

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so 12 minutes earlier

livid hound
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not quite

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why are you use 48

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the original time wasn't 48minutes

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48 was the number of km

fallow sedge
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oh yea

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40-36 then

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@livid hound i have another question, i got 0.1667 hours, that should be correct right

livid hound
#

yeh

fallow sedge
#

alright

fallow sedge
livid hound
#

show the question
and what you've done and clearly explain your issue

fallow sedge
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nvm actually, i think i got this

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after im finished do u mind checking it for me?

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ok i got 12:06 pm

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i think thats correct

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@livid hound

livid hound
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yeh

fallow sedge
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oh my i feel so much more confident after i get a question correct

#

thank you for explaining to me before

cedar kilnBOT
#

@fallow sedge Has your question been resolved?

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crimson sedge
#

How do I fall in 'love' with maths as a subject and be #1 in it? im currently not the best 😭
Im year 10 gcse

cedar kilnBOT
#

Please don't occupy multiple help channels.

crimson sedge
#

?!

crystal raptor
crimson sedge
#

oh ok

#

.close

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proven abyss
#

hello! i know how to use law of cosines, however i was wondering (if even possible) how i’d go about using law of cosines to solve two triangles. here is the problem:

proven abyss
cedar kilnBOT
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proven abyss
#

.reopen

cedar kilnBOT
#

βœ…

proven abyss
#

<@&286206848099549185>

crimson sedge
#

What

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I was trying to do stuff

cerulean sail
crimson sedge
#

Oh

crimson sedge
#

is is another triangle with same length for d,e,f?

cedar kilnBOT
#

@proven abyss Has your question been resolved?

proven abyss
proven abyss
#

see i was wondering if this problem could even be solved

cedar kilnBOT
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proven abyss
#

.reopen

cedar kilnBOT
#

βœ…

proven abyss
crimson sedge
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lethal reef
#

can someone explain whats wrong?

cedar kilnBOT
lethal reef
#

this is the answer

#

oh wait nvm i found it

#

.close

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hearty plinth
#

Hi

cedar kilnBOT
hearty plinth
#

idk how to solve this problem

#

ik I'm using the dish method but idk what is wrong with it

#

rn i have the problem as pi int(0,3) [4-3/1+x]^2dx

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oh wait nvbm i have to use the washer method

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i still got the problem wrong

#

what else am i doing wrong?

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!15m

cedar kilnBOT
#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

hearty plinth
#

<@&286206848099549185>

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oh wait nvm i completed it i did the formula wrong and messed up my pi placement

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but i alos

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have another problem that i cannot solve

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i need help with this

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all ik is that i have to use the dish method

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and its in terms of y now

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this is what i have currently but it isnt right

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nvm i solved

#

It

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but im now confused on this now

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this is what i have so faR

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<@&286206848099549185>

cedar kilnBOT
#

@hearty plinth Has your question been resolved?

hearty plinth
#

.close

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foggy mason
#

I am confused on how (n+1)! is (n+1)(n)(n-1)!

foggy mason
#

I do not know where that came from

buoyant latch
#

Which one

#

Oh

velvet mortar
#

5! Can be written as 5 * 4 * 3! For example

buoyant latch
#

Write the expanded form of n!

foggy mason
foggy mason
velvet mortar
#

If 5 is n+1 then 4 is n

buoyant latch
#

What is n!

velvet mortar
#

And 3 n-1

buoyant latch
#

What does ! mean

foggy mason
#

oooooooh

#

I see I get it now

#

oops

#

thanks

#

.close

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low birch
#

sorry to get away from doing maths, but what is a masters level thesis in math like? i am a grad student who doesnt have to complete one.. im curious about length etc

crimson delta
#

well there are some of them online

#

but really it always depends

low birch
#

its hard to imagine what lies between a dissertation and undergrad project

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besides comp exam, my school requires a project but not a thesis

crimson delta
#

well you might get a paper from your prof and get told to look into a particular theorem which the prof thinks could be improved

low birch
#

sounds cool

#

.close

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slow thicket
#

so what two values it is between

#

-2 and -1

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look at the dot again

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its not -1.5

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its halfway between what two values

tough karma
#

-1.25 looks like

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Between -1 and -1.5

slow thicket
#

they're never going to give you a trick like that

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its exactly -1.25

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otherwise you couldnt solve it

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youd have to guess

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so how do you represent -1.25 as a fraction

tough karma
#

There's a six in the denominator tho

slow thicket
#

they could have put that there

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also you can do a 6 thats fine

tough karma
#

Is the six put there or did u put it @split nimbus

#

Oh

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It's -1.25

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Looks like it

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No

#

In the decimal it is -1.25

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Now convert this into improper fraction

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Ofc np take your time

cedar kilnBOT
#

@split nimbus Has your question been resolved?

slow thicket
#

yes

#

that will be true because the value > 1

#

dont do that

#

youre supposed to do it by hand

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well yeah

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but you relied on the calculator

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thats the whole point of the question

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do you know how to turn 1.25 into 5/4

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ok so

#

break it down

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what two fractions sum to 5/4

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yes but something simpler

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something you know the values of

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not quite

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they have to equal 5/4

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what I was looking for was 4/4 and 1/4

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what is 4/4

#

what is 1/4

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in decimal

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so what is 5/4

#

okay now the other way

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we know the value is 1.25

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we need to convert

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so 1.25 is 1.25/1 right

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what number do we need to multiply both sides of the fraction with so that we remove the decimals

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yep

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so (1.25x4)/(1x4)

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what does that equal

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5/4, but yes

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thats all there is to it

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yea

#

yeah

#

like if it was 1.2

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what is the fraction for that

#

no

cedar kilnBOT
#
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#

βœ…

slow thicket
#

what number do we need to multiply both sides of the fraction with so that we remove the decimals

#

no

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remember 1.2 = 1.2/1

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how did we get rid of 1.25

#

we multiplied by 4

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because 0.25 is 1/4

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so 4*1/4 = 1

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same thing here

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what is 0.2

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how did you get 20

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why x100

tough karma
#

dont use a calculator it doesnt help

slow thicket
#

what is 0.2 in fraction form

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if you multiply by 100 you need to do on both sides

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0.2 = 0.2x100/(1x100)

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0.2 = 20/100

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what is 5

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ok so

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back to 1.2

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what is that fraction equal to

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??

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5 is not a fraction

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and 5 is not 1.2

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is 1/5 more than 1

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cause 1.2 is more than 1

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stop guessing

#

do you know how fractions work

#

i think you should watch some videos

#

about how fractions work

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happy to help

#

good luck

cedar kilnBOT
#

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limber sentinel
#

Hello

cedar kilnBOT
#

Please don't occupy multiple help channels.

zenith sail
#

Please stop opening channels. Post your question in one and wait

limber sentinel
#

It was an accident

#

Can you please help me

#

Five cards are drawn randomly from a standard deck of 52 cards.

Determine the probability that exactly 3 of these cards are Aces. Write your answer in decimal form, rounded to 5 decimal places.

#

@zenith sail

long swan
#

how many aces are in a standard deck?

cedar kilnBOT
#

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gloomy crater
#

π’th root of -1

cedar kilnBOT
gloomy crater
#

how does it equal e^i

tame wraith
#

e^(ipi) + 1 = 0

cedar kilnBOT
#

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turbid spoke
#

why is x + y = 0

cedar kilnBOT
dull oxide
#

First of all, it's not x+y

tame wraith
turbid spoke
#

?

tame wraith
#

this doesnt say x + y = 0

cerulean sail
#

[nor does it imply that x + y = 0]

turbid spoke
#

why did the 2 leave?

dull oxide
#

Division by 2 on both sides of the equation

turbid spoke
#

aaa I don't understand why they divide?

obsidian coral
#

Because 2 is a common factor

#

So you would factor out a 2

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Then divide by 2 on both sides

#

0/2 is still 0

turbid spoke
#

oh 2(x+y)/2 = x+y?

obsidian coral
#

You understand that dx/dt and and dy/dt are important too, right?

turbid spoke
#

yes

#

thx

#

.close

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β€’ Ask your math question in a clear, concise manner.
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crimson sedge
cedar kilnBOT
crimson sedge
#

im not sure how to do this

obsidian coral
cedar kilnBOT
#

@crimson sedge Has your question been resolved?

cosmic steppe
#

Your y intercept doesn't make sense

#

Do you know what a y intercept even is

crimson sedge
#

no

cosmic steppe
#

It's when the function hits the y axis

#

That means it's when x = 0

#

What you have is the x-intercept

crimson sedge
#

so would it be (0,-2)

cosmic steppe
#

No

#

Look at your table

crimson sedge
#

ohh

#

10

cosmic steppe
#

Mmhm

#

Therefore your equation is y = 5x + 10

crimson sedge
#

lol i didn’t even see that oops

#

i see thank you

crimson sedge
#

im lost now

#

how i find the y intercept?

#

<@&286206848099549185>

ancient valley
#

y intercept is when x=0

crimson sedge
#

Use slope intercept form

#

For the equation

patent ingot
#

Hello Can some1 help me to understand this. I'm starting to learn set theory. How can it be trie that A is not a subset of B.

That makes no sense to me. If A, {A}, are elements of B and {A}, and {{A}} are subsets of B. Then, A should be a subset of B as well? right?

crimson sedge
ancient valley
ancient valley
#

wait no mb

crimson sedge
#

what would it be?

ancient valley
#

wait yes jeez im have a stroke

#

yeah you should be correct

crimson sedge
#

ah okay lol

#

thanks

ancient valley
#

np πŸ™‚

crimson sedge
#

could u help me figure out how to do this one

#

i divided the changes in x and y and all of them were equal to -1 (3/-3= -1) (2/-2= -1) but idk where to go from there to find the y intercept

ancient valley
#

first you would se up an equation for finding the y-intercept

#

to do this, we could plug in 1 for x

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and set the value we add to x, equal to c

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if that makes sense

#

we know if we plug in 1 for x, we get 3

#

so lets set it up

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$-1\left(1\right)+c=3$

wraith daggerBOT
#

Judgemental Snail

timber mauve
#

You got the slope so take any point for example (-2,6) so the line equation becomes y-6=-1(x+2)

ancient valley
#

now, just solve for c

timber mauve
#

For y intercept plug in x=0 in line equation

crimson sedge
ancient valley
#

yep

crimson sedge
#

wait no

ancient valley
#

why no

#

?

crimson sedge
#

idk im lost again wew

ancient valley
#

if you do his method or mine, you get the exact same answer

crimson sedge
#

so (0,4) is correct for either method?

ancient valley
#

here, we know standard form for a liner expression is y=mx+c right?

crimson sedge
#

yeah

ancient valley
#

so you got the slope already

#

so we can plug that in for m

#

getting y=-1x+c

timber mauve
ancient valley
#

we know if we plug in 1 for x, we get an output (y) of 3 right?

crimson sedge
#

yes

ancient valley
#

so, if we plug in 1 for x, and 3 for y, all we have to do is solve for c

#

so, 3=-1(1)+c

#

3=c+1

#

c=4

crimson sedge
#

ohh okay i see now

#

is that equation right

#

forgot to add the x on -1

#

how’s that

ancient valley
#

they look right

crimson sedge
#

alr thanks for the help

ancient valley
#

np πŸ™‚

cedar kilnBOT
#

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#

Please don't occupy multiple help channels.

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proud spindle
#

How do i do these 3 questions? :)

cedar kilnBOT
lean spindle
#

hint: if two vectors are perpendicular to each other their dot product is zero

dire palm
#

sqrt(x^2+y^2) = 4
x + y = 0

lean spindle
#

if two vectors are parallel, then they are just scalar multiples

dire palm
#

thats for k

#

actually oops

#

i thought its perpendicular

dire palm
#

let p be a vector with a magnitude of 4

#

and its parallel to c

#

so sqrt(x^2 + y^2) = 4
and p = n c where n is a scalar

(x, y) = n(1, 1)
x = n && y = n <==> x = y

so sqrt(x^2 + x^2) = 4
sqrt(2 x^2) = 4
sqrt(2) x = 4
x = +- 4/sqrt(2) = +- 2sqrt(2)

for x = 2sqrt(2), y = 2sqrt(2)
for x = -2sqrt(2), y = -2sqrt(2)

#

for i, let p be a vector with a magnitude of 10, and its perpendicular to b, so

p.b = 0
sqrt(x^2 + y^2) = 10

p.b = 0
(x, y).(3, -4) = 0
3x - 4y = 0

x = 4/3 y

sqrt((4/3 y)^2 + y^2) = 10
y = +- 6

for y = 6, x = 8
for y = -6, x = -8

#

for question j im not sure what the question means

lean spindle
#

i dont think feeding them the answer would be helpful. they should try to work it out on their own first

#

anyway, kudos to you

dire palm
#

im just sending the answers incase theyre in an urgent mater, its their choice to read the steps one by one later when they have the time or not, thats out of my reach

cedar kilnBOT
#

@proud spindle Has your question been resolved?

proud spindle
#

thanks so much guys

cedar kilnBOT
#
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quasi plover
cedar kilnBOT
quasi plover
#

ΰΈ‡

#

;-;

mellow cairn
quasi plover
#

but when i actually got the question

#

i tends to forget, infact somehow felt like dont understand

#

plus the answer sheet make it even worst

mellow cairn
#

The explanations seem clumsy

#

Try putting each statement given with English

quasi plover
#

doesnt thats mean 1-10 is in the A intercept B?

#

and 11-13 is in the B

mellow cairn
#

I don't understand what you're saying, but I worked (a) out like this

3 in {not A and not B}
Therefore 20-3=17 in {A union B}
Therefore 10+13-17=6 in {A intercept B}

#

The answer is already given I'll just give a better explanation then, mods don't kill me

quasi plover
#

my brains lagging i think

#

i dont understand that either

mellow cairn
#

Quite normal with Venn diagrams

quasi plover
#

ik cuz its a basic one and im boutta have an exam on it

mellow cairn
#

With the info given, you know that there's 17 members in {A union B}

#

But there's 10 and 13 members in A and B respectively

#

So there must be 10+13-17=6 members overlapping

quasi plover
#

yes

#

why add A and B together

#

and why does - 17

mellow cairn
#

I don't know how to explain, but I'd say forcing in the concept of overlapping into your doubts would help

quasi plover
#

forcing in the concept of overlapping into your doubts

#

and how we do thta\

mellow cairn
#

Idk it's literally pure reason already

quasi plover
#

my ADHD aint ready for this

mellow cairn
#

The facts are that A has 10 members, B has 13 members, but A and B combined has 17 members

#

For that to work there must be 6 members that are in both sets

#

Is that better

quasi plover
#

but

#

isnt that should mean 10 +13 = 17?

#

but its not either

mellow cairn
#

No because you're counting the 6 overlapping members TWICE with 10+13

#

There's only 4 in A only, 7 in B only, and 6 in both A and B

#

Therefore there's still only 17 members in {A union B}

quasi plover
#

theres 10 in A and 13 in B

mellow cairn
#

Yes

#

But there's 6 in both A and B

quasi plover
#

so according to what you trying to say, basicaly there should be 17 members in A U B

mellow cairn
#

Yes

quasi plover
#

so what you do

#

is you trying to find the numbers that also been counted in the intercept A and B

#

or whatever that thing called

#

right?

mellow cairn
#

Yes

quasi plover
#

i undersatnd the process of what you do to find 17, but not understand the process on why you do 10 + 13

mellow cairn
#

Try reversing that process

quasi plover
#

wheres 6 come from now

mellow cairn
quasi plover
#

i thought there're 17

#

what the

mellow cairn
mellow cairn
quasi plover
#

yes

#

what I wrote down on my paper is 10+13-x = 17

#

it seems make sense

mellow cairn
#

Yes and that's 6

quasi plover
#

when i try to said it out, i dont understand

mellow cairn
#

Make it out in language ig

#

What about (b)

quasi plover
#

ohhhhhhh

#

ohhhhhhhhhhhhhhhhhhhh

#

ohhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

#

f------------------

#

i get it

#

i get the scratch

mellow cairn
#

Lol

quasi plover
#

but i wont remember it in the exam

#

what i do

#

i tried to focus too much on the diagram

mellow cairn
#

Yep that's Venn diagrams

quasi plover
mellow cairn
#

Not sure

#

Do more questions

quasi plover
#

my exam have like tons of other topics, what you do to remember it when you see it in first sight @mellow cairn

quasi plover
mellow cairn
#

Prob just Venn diagrams

#

The topic

quasi plover
#

just normal ordinary venn diagram question?

quasi plover
#

now only 2 months left

#

im getting panicked

mellow cairn
#

Which exam are you preparing for?

quasi plover
mellow cairn
#

Oh well.

#

If you're not familiar with Venn diagrams just do Venn diagrams

#

Are there by topic past papers?

quasi plover
#

srry im not 1st languang english, i might not understand alot

mellow cairn
#

As in there might be past papers sorted by topic

quasi plover
#

for like opening my eyes or smth

mellow cairn
mellow cairn
quasi plover
quasi plover
mellow cairn
mellow cairn
quasi plover
#

im scared abit too

#

srry

mellow cairn
cedar kilnBOT
#

@quasi plover Has your question been resolved?

#
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hoary spoke
#

Sorry, I know this is off topic but can someone give me discord links where people help you in subjects other than maths and are as dedicated to help as here?

slow thicket
#

links should be in announcments

hoary spoke
#

Okay

cedar kilnBOT
#

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hoary spoke
#

.close

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sudden blade
#

help pls

cedar kilnBOT
slow thicket
#

!status

cedar kilnBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
sudden blade
slow thicket
#

find the probability first

#

do you know how

cedar kilnBOT
#

@sudden blade Has your question been resolved?

cedar kilnBOT
#
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quiet pine
#

All matrixes are invertible. I'm asked to simplify for X, but not sure if I'm anywhere near the right answer as this gets very confusing quickly.
First equation is the given equation.

quiet pine
#

I arrived to the conclusion that there's no solution for X. Which doesnt sit right with me

silk thistle
#

What did you do from lign 2 to 3

#

@quiet pine

#

Here is what I'd do :

(ABtX-1)t = B

#

A. Bt. X-1 = Bt

#

A. Bt = BtX

quiet pine
#

so take the transpose of both sides, multiply by x and rearrange? Does seem more reasonable
Thank you!

lethal jackal
#

yeah I see a lot of steps here that are unjustifiable

#

these two as byshadowz pointed out

#

these two

#

these two

quiet pine
#

.close

cedar kilnBOT
#
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β€’ Show your work, and if possible, explain where you are stuck.
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warm turret
#

Hello, I need help with a question regarding trigonometry

warm turret
#

The question was

#

Are the walls of the room perpendicular?

#

I did a calculation but I’m not sure it’s actually correct so I just wanted help to confirm it

crisp lodge
#

If you calculation is using pythagoras theorem then I guess its correct because its only true if the the sides measured 80 and 60 cm are perpendicular to each other

#

*your calculation

#

You could also use the cosine rule to show that both walls are perpendicular too

cedar kilnBOT
#

@warm turret Has your question been resolved?

warm turret
#

Thanks then for helping

crisp lodge
#

No problem πŸ‘

warm turret
#

Oh just a question, the 100 CM is at 1M but I converted it to 100cm just so it was easier

#

Does that change anything

crisp lodge
#

No it shouldn't change anything

warm turret
#

Alright thank you

crisp lodge
#

It's better that you converted

#

If you are using multiple units at the same when you're calculating your answer could be wrong

warm turret
#

I calculated mostly by hand, I only used calculator for the exponent part,

crisp lodge
#

Yh that should be good then πŸ‘

warm turret
#

Thanks a lot for helping then

#

.close

cedar kilnBOT
#
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crisp lodge
#

No worries! πŸ˜€

cedar kilnBOT
#
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rich haven
#

Can someone tell me what I’m doing wrong. Can’t wrap my head around it. Red is what mark scheme says

rich haven
#

Also if my whole approach is wrong please tell me

cedar kilnBOT
#

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stray plover
#

Hi

cedar kilnBOT
stray plover
#

Need help with thud

#

unit solving equations w pronumerals on both side

ripe fog
#

what have you tried so far?

stray plover
#

4x-x-20=-x-x

#

But im confused now

ripe fog
#

close but that doesn't quite group all the x's together

stray plover
#

Oh

ripe fog
#

how would you get rid of the -x on the right side

stray plover
#

-x

#

No

#

Omg

#

-4

#

To leave x on its own

#

NO

#

STOP

#

IM SO DUMB

#

To get rid of -x youll have to add x

ripe fog
#

yepppp

stray plover
#

So I’ll have to add x to the right?

crimson sedge
#

yep that would work, but tbh I'd recommend to remove the 4x on the right side

ripe fog
#

either way works

crimson sedge
#

so it would isolate the term with x in it

stray plover
#

Which wld be done by 4x-x?

ripe fog
#

4x-x gets you 3x right

stray plover
#

To leave 4 on UTS own

#

Oh

ripe fog
#

but you want all the x's together

stray plover
#

So what do I do

#

Im stuck

#

πŸ’€

#

I know to remove the negative β€˜x’ I had to add an β€˜x’ but how do I get 4 on its own - if thats what we’re trying to find

ripe fog
#

lets get rid of the -x on the right side

stray plover
#

Suew

ripe fog
#

so to do that we +x to both sides of the equation

#

whats left over?

stray plover
#

Plus x to 4x?

ripe fog
stray plover
ripe fog
#

so whats that get you

upbeat lotus
stray plover
#

Wait what

upbeat lotus
#

,w 4x-20=-x

stray plover
#

4x+x= would be 4x^2?

wraith daggerBOT
upbeat lotus
#

5x

ripe fog
stray plover
#

OHH YEA

upbeat lotus
#

4xΓ—x=4xΒ²

stray plover
#

SORRY ITS MIDNIGHT HERE AND IM HALF ASLEEP

ripe fog
#

no worries lmao

stray plover
#

Now I have 5x

upbeat lotus
ripe fog
#

yep

#

whats the full equation

stray plover
#

5x-20=x

ripe fog
#

well

#

be careful

#

whats on the right side

stray plover
#

0

ripe fog
#

lmao yep

stray plover
#

Its 5x-20=0

ripe fog
#

so its 5x-20=0

stray plover
#

Its 1:29am here I am so sorry

ripe fog
#

but you want to isolate x

#

so how do you isolate the x's

#

you have 5x-20 on the left side

stray plover
#

Yes

#

So

ripe fog
#

how do you get to 5x only

stray plover
#

We’ll have to take 5 away

#

From 5 and 20

ripe fog
#

well

stray plover
#

Or divide

#

Def divide

ripe fog
#

lets do ur first idea

#

lets -5x from both sides

#

whats left

stray plover
#

X-15=0

ripe fog
#

wait so we we 5x-20=0 right

stray plover
#

Yes

ripe fog
#

subtract 5x from both sides, what's left?

#

left side is 5x-20-5x=what

#

right side is 0-5x=what

stray plover
#

X=15=0

#

Is it not

ripe fog
#

well

stray plover
#

0-15x=0

ripe fog
#

you cant do 20-5x directly since 20 doesnt have an x

stray plover
#

Yup

#

Correct

ripe fog
#

instead you can rearrange to make it a bit clearer

#

5x-5x-20

#

whats that leave you?

stray plover
#

X=20

ripe fog
#

but 5x-5x=0 right

stray plover
#

Yes

#

So I was right before

#

My days

#

0=20

ripe fog
#

-20=0-5x

#

-20=-5x

#

5x=20

stray plover
#

Yes

#

Im confused

#

Can I j type 4 since I know the answer

#

And sleep fr

ripe fog
#

haha

#

i guess

#

go to sleep

stray plover
#

One more question after this then I can sleep

#

Its a school day too bro

#

Had a family party yesterday so cldnt do anything yesterday

#

,w 2h-11=7h-41

wraith daggerBOT
stray plover
#

LOVE

#

THANK YOU SO MUCH GUYS

#

MERRY CHRISTMAS

#

AB TO SLEEP NOW YAYY

ripe fog
#

lmao gl

stray plover
# ripe fog go to sleep

Na but man thanks a lot i j couldnt comprehend maths rn coz of the time but u explained it good

#

Thanks for being patient

ripe fog
#

appreciate ur patience

stray plover
#

All u bro

#

Now goodnight πŸ’€πŸ’€

#

.close

cedar kilnBOT
#
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#
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Remember:
β€’ Ask your math question in a clear, concise manner.
β€’ Show your work, and if possible, explain where you are stuck.
β€’ After 15 minutes, feel free to ping <@&286206848099549185>.
β€’ Type the command .close to free the channel when you're done.
β€’ Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

fossil thorn
cedar kilnBOT
fossil thorn
#

What is the correct way to graph a logarithmic function?

#

I'm not sure if what I'm doing is right, and if it is which method is better?

crisp lodge
#

The way I would do it is: we know that the logarithmic function is the inverse (opposite) of the exponential function. I.e. log2(x) is the inverse of 2^x. The way of graphing an inverse is by reflecting the graph at the the line y=x...the visual below may help

fossil thorn
crisp lodge
#

Np!

#

you would not need to convert log2(x) to 2^x as such you would use the graph of y=2^x as a reference to be able to draw the log function.

#

Basically, you would have needed to remember what 2^x would look like in the first place

#

remember that all exponential graphs pretty much look similar: they slope upwards and always go through 0 on the x-axis

#

I apologise if my explanation is not clear!

fossil thorn
#

tysmm!! it makes much more sense now!

crisp lodge
#

That's great to hear!!

fossil thorn
#

.close

cedar kilnBOT
#
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honest shore
#

hello,how many Lebesgue non-measurable sets are in R?

red pumice
#

i would guess infinitely many

cedar kilnBOT
#

@honest shore Has your question been resolved?

honest shore
#

In general?

cedar kilnBOT
#

@honest shore Has your question been resolved?

dense socket
#

Still infinite imo

cedar kilnBOT
#

@honest shore Has your question been resolved?

crimson delta
#

there are uncountably many vitali sets

#

just pick one vitali set, take one element of it and take a different representant of its equivalence class

#

(and obviously vitali sets have uncountably many elements)

cedar kilnBOT
#
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long arrow
#

is this reccurence relation or? no wider context?

#

what's t_n

#

I mean what's t1 and t2, what's the point of calculating them?

#

is kind of method?

#

can't you just solve f(x) = 21?

#

sin(pi/12(x-10)) = 3/8
from here:
pi/12(x-10) = arcsin(3/8) + 2pin or pi/12(x-10) = pi - arcsin(3/8) + 2pin

#

now you can get your solutions plugging different n's

cedar kilnBOT
#
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cedar kilnBOT
#
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bright sorrel
cedar kilnBOT
bright sorrel
#

Help pls

cosmic steppe
#

!status

cedar kilnBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
cosmic steppe
#

And which questions

bright sorrel
#

All

cosmic steppe
#

,rotate

bright sorrel
wraith daggerBOT
cosmic steppe
#

3x + 39 = 90

#

What did you do from here

#

The hand writing is messy

bright sorrel
#

I did 3x+39=90

#

Then subtract 39 by 90

#

Then x= 48

cosmic steppe
#

You subtracted 39 from 90?

#

so 3x = 51

bright sorrel
#

Yeah and added it by 3

cosmic steppe
#

You can't add 3

bright sorrel
#

Oh

cosmic steppe
#

You then have to divide by 3 because 3 is the coefficient of x

bright sorrel
#

So 90- 49

#

39

upbeat lotus
#

Where did the 3x go?

#

Don't leave the 3x alone like she left me

bright sorrel
#

Idk how to do this

upbeat lotus
#

3x+39=90

#

3x=90-39

#

Now do it

#

You have 1 minute πŸ”ͺ

bright sorrel
cosmic steppe
#

90-39 = 51

upbeat lotus
#

Then

cosmic steppe
#

So 3x = 51

cosmic steppe
#

I already told you how to do it

bright sorrel
#

I get it now

#

Lemme do

#

It and show it

#

If I’m right

#

I’m right

upbeat lotus
#

We already told you about than

#

You're right till now

#

Then

#

πŸ”ͺπŸ”ͺπŸ”ͺπŸ”ͺπŸ”ͺπŸ”ͺπŸ”ͺ

bright sorrel
#

What should I do next

#

Cause I can’t add 3x by 51

upbeat lotus
#

Divide it by 3

bright sorrel
#

The answer is yes 17

#

I got it

upbeat lotus
#

Yes very good

bright sorrel
#

There is more

upbeat lotus
bright sorrel
#

Yeah

#

No

#

Is su something

#

Angles

upbeat lotus
#

Linear pain

#

Pair*

bright sorrel
#

Wdy@

#

Wydm

cosmic steppe
#

A linear pair add up to 180Β°

upbeat lotus
#

All angles in a straight line adds up to 180Β°

bright sorrel
#

Oh

upbeat lotus
#

Yupp

bright sorrel
#

I did 6x+3x

#

=9x

upbeat lotus
#

Why 3x

#

It's 2x

#

πŸ”ͺ

bright sorrel
#

Oh my bad

upbeat lotus
#

Yes

#

You are doing math in the morning I am doing at a broken midnight

#

,ti

wraith daggerBOT
#

The current time for 𝓐𝓑𝓝𝓐𝓑 π“Ÿπ“π“› is 01:39 AM (IST) on Mon, 06/03/2023.

bright sorrel
#

So it’s gonna be 6x

#

No 8c

#

8x

upbeat lotus
#

Yes

#

And there's another 8 don't forget

bright sorrel
#

Then 8+180

upbeat lotus
#

Ughhhh

#

No

bright sorrel
#

Then divide it by 7

#

8x

upbeat lotus
#

$8x+8=180$

wraith daggerBOT
#

Offline due to exams

upbeat lotus
#

Look the equation closely

bright sorrel
#

Oh

upbeat lotus
#

There's only substracting and dividing

bright sorrel
#

But we can’t subtract 8x and 8

#

Cause there is no x on the other 8

upbeat lotus
#

So shift it to right hand side

bright sorrel
#

Wdym

upbeat lotus
#

Shift +8 to other side of the equation

#

Or just add -8 in both sides

bright sorrel
#

If I shit it

#

Is gonna be 8x=8+180

upbeat lotus
#

Why +8

#

πŸ’€ sully

#

-8

#

πŸ”ͺπŸ”ͺπŸ”ͺ

bright sorrel
#

So 8-180

upbeat lotus
#

That minus sign is important

#

180-8

#

πŸ”ͺ

#

Don't be broke don't worry you don't have to resist days that I'm resisting

bright sorrel
#

Lemme calculate

#

Thanks for helping

#

I’m really need help in math

upbeat lotus
#

Welcome but what did you get

bright sorrel
#

Hold on

#

172

upbeat lotus
#

Good

bright sorrel
#

Now we divide

#

Right

upbeat lotus
#

Yes

#

Divide it by 8

bright sorrel
#

I got 21.5

#

So x=21.5

upbeat lotus
#

,w 172/8

wraith daggerBOT
upbeat lotus
#

Yes

bright sorrel
#

We did ittt

#

Did u add me back

upbeat lotus
#

Good

upbeat lotus
bright sorrel
#

On discord

#

I added u

upbeat lotus
#

I already added in you my friend list

bright sorrel
#

Can I call

#

It will be easier

#

To do the work

#

It’s due in 2 days

upbeat lotus
#

,ti

wraith daggerBOT
#

The current time for 𝓐𝓑𝓝𝓐𝓑 π“Ÿπ“π“› is 01:48 AM (IST) on Mon, 06/03/2023.

upbeat lotus
#

Can you see the time bro

#

πŸ₯²

bright sorrel
#

It’s 3:18pm

#

Here

upbeat lotus
#

1:48 am here

bright sorrel
#

Oops

upbeat lotus
#

Yupp

#

Post it here

bright sorrel
#

That the next one

upbeat lotus
#

Vertically opposite angles

bright sorrel
#

Yeah

upbeat lotus
#

Two angles are equal

bright sorrel
#

Idk

upbeat lotus
#

Just 3x+1=112

bright sorrel
#

Do I subtract

#

112 by 1

upbeat lotus
#

Yes

bright sorrel
#

Then divide the answer by 3

upbeat lotus
#

Yes

bright sorrel
#

I got 37

upbeat lotus
#

,w 111/3

wraith daggerBOT
upbeat lotus
#

Yes

#

Ok so good night bro

bright sorrel
#

There is more😭

#

One more

#

Then tomorrow we’ll do the others

#

When I get home