#help-13 | Mathematics | Page 72

steady wing Feb 28, 2023, 8:46 AM

#

I am wondering when negating the convergence of a sequence

cedar kilnBOT Feb 28, 2023, 8:46 AM

#

steady wing I am wondering when negating the convergence of a sequence

steady wing Feb 28, 2023, 8:46 AM

#

First, when negating an implication a=>b, its "a and not b"

#

So when we have a sequence converging, is it for all e, there is an n such that n>N => |un-l|<e

#

Or is it for all e, theres an N, such that n>N, |un-l|<e

#

Idk the statements seem equivalent to me

#

But their negations will differ

#

In the first one i get there's an e, for all N, n>N and un-l>e

#

.close

cedar kilnBOT Feb 28, 2023, 8:50 AM

#

Channel closed

Closed by @steady wing

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

peak ether Feb 28, 2023, 9:06 AM

#

Hi

cedar kilnBOT Feb 28, 2023, 9:06 AM

#

peak ether Hi

peak ether Feb 28, 2023, 9:07 AM

#

#

Can anybody help me with this question

tropic oxide Feb 28, 2023, 9:07 AM

#

what's troubling you

peak ether Feb 28, 2023, 9:08 AM

#

The question

#

I dont know the process and how to start solving

tropic oxide Feb 28, 2023, 9:10 AM

#

Z is the number of bad chips in the tech's sample

#

how many chips does the tech pick in total?

peak ether Feb 28, 2023, 9:11 AM

#

2?

tropic oxide Feb 28, 2023, 9:11 AM

#

he picks 2 chips?

#

are you sure about that?

peak ether Feb 28, 2023, 9:12 AM

#

No im not

tropic oxide Feb 28, 2023, 9:12 AM

#

it says in the problem, at the beginning:

A technician has to choose three chips at random...

peak ether Feb 28, 2023, 9:13 AM

#

Oh

#

3 it is

tropic oxide Feb 28, 2023, 9:13 AM

#

right

#

so if you knew nothing else about the problem,

#

what would you say the range of values for "number of bad chips in the sample" would be?

#

this is not something you have to think too hard about or even do any calculations.

peak ether Feb 28, 2023, 9:18 AM

#

4 chips in which two are defective yet he has to choose three randomly.
{W, W, NW}?

#

<@&286206848099549185>

tropic oxide Feb 28, 2023, 9:25 AM

#

@peak ether you're overthinking it.

#

massively so

#

when all you know about the tech's selection is that it consists of 3 chips, how many bad ones could he possibly have picked up?

#

anywhere between 0 and 3 bad chips, of course.

#

does this specific point make sense to you?

#

we cannot continue if you do not confirm or deny that this point makes sense to you.

peak ether Feb 28, 2023, 9:29 AM

#

tropic oxide <@1023236968240394321> you're overthinking it.

I think i really am

tropic oxide Feb 28, 2023, 9:32 AM

#

when all you know about the tech's selection is that it consists of 3 chips, how many bad ones could he possibly have picked up?
anywhere between 0 and 3 chips, of course.

#

does this make sense to you?

#

like really forget anything else and don't try to think of it until i tell you to. simple shit.

#

if the tech picks up 3 chips the number of bad ones is between 0 and 3

cedar kilnBOT Feb 28, 2023, 9:44 AM

#

@peak ether Has your question been resolved?

cedar kilnBOT Feb 28, 2023, 9:59 AM

#

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

balmy shard Feb 28, 2023, 10:03 AM

#

Can someone pls double check to see if this is right

cedar kilnBOT Feb 28, 2023, 10:03 AM

#

balmy shard Can someone pls double check to see if this is right

#

@balmy shard Has your question been resolved?

balmy shard Feb 28, 2023, 10:19 AM

#

<@&286206848099549185>

#

Hello anyone pls?

#

Ive been waiting for ages

#

<@&286206848099549185>

lethal jackal Feb 28, 2023, 10:27 AM

#

I've been waiting for ages for her to text me a goodbye

balmy shard Feb 28, 2023, 10:28 AM

#

Can u help me?

#

Just make sure i got it right

lethal jackal Feb 28, 2023, 10:29 AM

#

how did you conclude that the radius of the cone is 10 cm

balmy shard Feb 28, 2023, 10:29 AM

#

I amde the radius 10

lethal jackal Feb 28, 2023, 10:29 AM

#

so you're allowed to pick?

balmy shard Feb 28, 2023, 10:29 AM

#

We just need dimensions that fit

lethal jackal Feb 28, 2023, 10:30 AM

#

wasn't obvious from the question how you were supposed to find a unique answer

#

but yes if you just need that

balmy shard Feb 28, 2023, 10:30 AM

#

So we pick the radius/height and then figure out the other

lethal jackal Feb 28, 2023, 10:30 AM

#

well

balmy shard Feb 28, 2023, 10:31 AM

#

So its all good?

lethal jackal Feb 28, 2023, 10:32 AM

#

yes, but are you aware that you could've done all of the checking yourself

#

there are calculators on the internet

balmy shard Feb 28, 2023, 10:32 AM

#

Oh yea...

#

Sorry for the disturbance.. thank you

lethal jackal Feb 28, 2023, 10:32 AM

#

np

balmy shard Feb 28, 2023, 10:33 AM

#

.close

cedar kilnBOT Feb 28, 2023, 10:33 AM

#

Channel closed

Closed by @balmy shard

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

humble oracle Feb 28, 2023, 10:37 AM

#

cedar kilnBOT Feb 28, 2023, 10:37 AM

#

humble oracle

lyric leaf Feb 28, 2023, 10:41 AM

#

which part of the question are you confused about?

lethal jackal Feb 28, 2023, 10:41 AM

#

literally awful question though

#

these should all be called "sample mean" "sample variance" "sample standard deviation"

#

or estimated mean, estimated variance, estimated standard deviation

#

people get so confused because of it

lyric leaf Feb 28, 2023, 10:41 AM

#

those distinctions werent ever made to me until my third year of university 💀

lethal jackal Feb 28, 2023, 10:42 AM

#

yeah it's actually horrifying how they expect you to calculate the variance of the sample mean

#

when you're literally told the mean is just add all of the numbers and divide by something

humble oracle Feb 28, 2023, 10:43 AM

#

I dont get any of it as its in a weird format

lyric leaf Feb 28, 2023, 10:43 AM

#

do you mean the notation?

humble oracle Feb 28, 2023, 10:44 AM

#

yeah

lyric leaf Feb 28, 2023, 10:44 AM

#

this, specifically?

humble oracle Feb 28, 2023, 10:45 AM

#

Both I havent rly studied this topic at all

lyric leaf Feb 28, 2023, 10:45 AM

#

Σ means 'to sum up'

#

say we have xi where i=1,2,3,4,5 (any one of those values)

#

Σxi means x1+x2+x3+x4+x5

humble oracle Feb 28, 2023, 10:46 AM

#

How do I know what to divide it by tho for the mean

lyric leaf Feb 28, 2023, 10:46 AM

#

here you are told you have 5 data observations, x1, x2, x3, x4, x5

humble oracle Feb 28, 2023, 10:46 AM

#

Oh god

#

youre right

lyric leaf Feb 28, 2023, 10:46 AM

#

well with the definitions you are familiar with

humble oracle Feb 28, 2023, 10:46 AM

#

thanks lol

lyric leaf Feb 28, 2023, 10:46 AM

#

mean = [SUM of everything]/number of things

#

so yea

#

Σxi would just be that top part

#

'the sum' of each squared data observations is something you should see in Variance and Standard Deviation, too

humble oracle Feb 28, 2023, 10:48 AM

#

thanks a lot i completely skipped past the 5 lol

#

im blind

lyric leaf Feb 28, 2023, 10:48 AM

#

no worries, it happens

cedar kilnBOT Feb 28, 2023, 11:03 AM

#

@humble oracle Has your question been resolved?

cedar kilnBOT Feb 28, 2023, 11:18 AM

#

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

silent finch Feb 28, 2023, 11:37 AM

#

What are directed lengths? Context:

cedar kilnBOT Feb 28, 2023, 11:37 AM

#

silent finch What are directed lengths? Context:

crystal raptor Feb 28, 2023, 11:39 AM

#

https://math.stackexchange.com/questions/4031833/use-of-directed-lengths

Mathematics Stack Exchange

Use of directed lengths

I was studying Menelaus' Theorem which can be found here https://en.wikipedia.org/wiki/Menelaus's_theorem.
I noticed they use directed lengths which specifies that points $E,D,F$(in reference to...

#

I'd never heard of them, seem to just make sure you label/draw things correctly

#

Or rather that it doesn't matter what labels you use

cedar kilnBOT Feb 28, 2023, 11:52 AM

#

@silent finch Has your question been resolved?

cedar kilnBOT Feb 28, 2023, 12:07 PM

#

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

orchid oriole Feb 28, 2023, 12:14 PM

#

cedar kilnBOT Feb 28, 2023, 12:14 PM

#

orchid oriole

orchid oriole Feb 28, 2023, 12:14 PM

#

Someone pls help, idk how I’m getting it wrong

hardy island Feb 28, 2023, 12:16 PM

#

I’d use the AC method

#

Multiply AC and find factors that add up to B

orchid oriole Feb 28, 2023, 12:17 PM

#

What will be AC and B in this case ?

quartz frost Feb 28, 2023, 12:17 PM

#

i would do complete the square, that is always nice

hardy island Feb 28, 2023, 12:18 PM

#

CTS is a waste

quartz frost Feb 28, 2023, 12:18 PM

#

😦

distant cedar Feb 28, 2023, 12:18 PM

#

😅

hardy island Feb 28, 2023, 12:19 PM

#

If you do AC you can re write it using the factors, so 10x^2 - factor 1 - factor 2 + 4 then continue from there

#

Or you can do CTS

orchid oriole Feb 28, 2023, 12:20 PM

#

#

Is this ur method ?

#

Is it the same as rhis

hardy island Feb 28, 2023, 12:20 PM

#

Yes

orchid oriole Feb 28, 2023, 12:20 PM

#

I’m confused on how they fit 5 and 8

#

Bc they multiply to give 40

distant cedar Feb 28, 2023, 12:20 PM

#

It's 0.5 and 0.8

orchid oriole Feb 28, 2023, 12:20 PM

#

Or does that not matter

distant cedar Feb 28, 2023, 12:20 PM

#

Not 5 and 8

hardy island Feb 28, 2023, 12:21 PM

#

They multiply to give 40

orchid oriole Feb 28, 2023, 12:21 PM

#

Where did 40 come from is what I’m confused about

hardy island Feb 28, 2023, 12:21 PM

#

Multiply A and C

orchid oriole Feb 28, 2023, 12:21 PM

#

Ohhh

hardy island Feb 28, 2023, 12:21 PM

#

If it’s in quadratic form

hardy island Feb 28, 2023, 12:21 PM

#

distant cedar It's 0.5 and 0.8

?

orchid oriole Feb 28, 2023, 12:21 PM

#

I forgot the formula, what is it again

acoustic vale Feb 28, 2023, 12:21 PM

#

hello

hardy island Feb 28, 2023, 12:21 PM

#

no formula really

#

Just multiply a and c

orchid oriole Feb 28, 2023, 12:22 PM

#

Oh

hardy island Feb 28, 2023, 12:22 PM

#

Factor it so the terms add to b

acoustic vale Feb 28, 2023, 12:22 PM

#

( -b+-v/b2 - 4ac ) / 2a

distant cedar Feb 28, 2023, 12:22 PM

#

hardy island ?

Reply was w.r.t the image shared above by the OP

acoustic vale Feb 28, 2023, 12:22 PM

#

just do a second grade ecuation

#

@orchid oriole you know how to do that+

orchid oriole Feb 28, 2023, 12:23 PM

#

#

Also for the 6x (6x-3) equals 0 question

#

Why do I divide only 6x

acoustic vale Feb 28, 2023, 12:23 PM

#

Second grade equation bro its so easy

hardy island Feb 28, 2023, 12:24 PM

#

I mean what else would you divide by

livid hound Feb 28, 2023, 12:24 PM

#

orchid oriole

x(10x-13) + 4 = 0
is NOT in the form ab = 0 where a = 10x-13 and b = x+4
you can't apply zero product property like this

distant cedar Feb 28, 2023, 12:24 PM

#

orchid oriole Where did 40 come from is what I’m confused about

It won't be 40 btw

#

Yes as Ramonov pointed out ,please understand when certain operations are valid

hardy island Feb 28, 2023, 12:24 PM

#

8 x 5 is 40

orchid oriole Feb 28, 2023, 12:25 PM

#

livid hound x(10x-13) + 4 = 0 is NOT in the form ab = 0 where a = 10x-13 and b = x+4 you can...

Oh, so writing it like that is wrong ? How should I write it

livid hound Feb 28, 2023, 12:25 PM

#

writing x(10x-13) + 4 = 0 itself is fine, (it just doesn't really help you here)
the conclusion you reached from that is wrong

distant cedar Feb 28, 2023, 12:25 PM

#

hardy island 8 x 5 is 40

That's not how multiplication of roots work

#

We are supposed to write the equation such that the coefficient of x^2 is in the correct form

#

Only then can we use the method

livid hound Feb 28, 2023, 12:26 PM

#

what?

orchid oriole Feb 28, 2023, 12:26 PM

#

hardy island I mean what else would you divide by

Idk I thought If I divide one thing I have to deivide eveyrbtung

livid hound Feb 28, 2023, 12:26 PM

#

who said anything about multiplication of roots

distant cedar Feb 28, 2023, 12:27 PM

#

Not you Ramonov, I am replying to the method suggested by Meep

hardy island Feb 28, 2023, 12:27 PM

#

Still don’t get what you’re saying

livid hound Feb 28, 2023, 12:27 PM

#

the method they're referring to seems fine

#

the ac method for factorising non-monic quadratics

orchid oriole Feb 28, 2023, 12:28 PM

#

#

For the first question why do i only divide 5a

#

Like why does only 5a change

#

Why not a-2

livid hound Feb 28, 2023, 12:28 PM

#

divide by 5 not 5a

#

its just general clean up and simplification of the equation

#

you don't need to if you don't want to

orchid oriole Feb 28, 2023, 12:29 PM

#

Ok, what’s the other way?

hardy island Feb 28, 2023, 12:29 PM

#

Also where or how did a change to x

livid hound Feb 28, 2023, 12:29 PM

#

apply zero product property directly

hardy island Feb 28, 2023, 12:30 PM

#

Or did the coefficient change

orchid oriole Feb 28, 2023, 12:30 PM

#

hardy island Also where or how did a change to x

Thats a multiplication sign

hardy island Feb 28, 2023, 12:30 PM

#

Oh

west zenith Feb 28, 2023, 12:30 PM

#

orchid oriole

I don't know if someone solved it below or not

orchid oriole Feb 28, 2023, 12:30 PM

#

west zenith I don't know if someone solved it below or not

Thank you

livid hound Feb 28, 2023, 12:31 PM

#

5a(a-2) = 0
is in the form pq = 0
applying zero product property directly to taht
5a = 0 or a-2 = 0

orchid oriole Feb 28, 2023, 12:31 PM

#

Ohh

livid hound Feb 28, 2023, 12:31 PM

#

5a = 0 leads to a = 0

orchid oriole Feb 28, 2023, 12:31 PM

#

I understand now

livid hound Feb 28, 2023, 12:31 PM

#

you can also first divide both sides by 5 to simplify the equation to
a(a-2) = 0

#

and applying zpp there leads to the same end result

orchid oriole Feb 28, 2023, 12:32 PM

#

Ok thank you

distant cedar Feb 28, 2023, 12:32 PM

#

hardy island Still don’t get what you’re saying

It's fine Meep, was looking at the wrong picture

orchid oriole Feb 28, 2023, 12:33 PM

#

.close

cedar kilnBOT Feb 28, 2023, 12:33 PM

#

Channel closed

Closed by @orchid oriole

Use .reopen if this was a mistake.

quartz frost Feb 28, 2023, 12:33 PM

#

just for good measure im gonna leave the completed square here @orchid oriole

cedar kilnBOT Feb 28, 2023, 12:34 PM

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

orchid oriole Feb 28, 2023, 12:34 PM

#

Thank you

cedar kilnBOT Feb 28, 2023, 12:34 PM

#

orchid oriole Thank you

quartz frost Feb 28, 2023, 12:37 PM

#

.close

cedar kilnBOT Feb 28, 2023, 12:37 PM

#

Channel closed

Closed by @quartz frost

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

#

Channel closed

Closed due to the original message being deleted

long mauve Feb 28, 2023, 12:53 PM

#

.reopen

#

How to know the resistance is 9ohm

quartz frost Feb 28, 2023, 12:54 PM

#

we know that the resistance of the whole plate is 3 ohm

long mauve Feb 28, 2023, 12:55 PM

#

why ammeter reading is not 3/9 instead of 3/4.5

quartz frost Feb 28, 2023, 12:55 PM

#

wait, in the picture they are connected parallel, not in series or am i wrong lol

#

i think they mean parallel, no?

long mauve Feb 28, 2023, 12:56 PM

#

quartz frost i think they mean parallel, no?

idk what do u think

quartz frost Feb 28, 2023, 12:57 PM

#

#

in your task, they are in parallel i would say

#

but the task says they are in series

long mauve Feb 28, 2023, 12:58 PM

#

quartz frost

Oh I see if but parallel ammeter reading is what, how do you calculate it

cedar kilnBOT Feb 28, 2023, 1:00 PM

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

quartz frost Feb 28, 2023, 1:01 PM

#

.

#

this is how i would do it

cedar kilnBOT Feb 28, 2023, 1:02 PM

#

quartz frost this is how i would do it

quartz frost Feb 28, 2023, 1:02 PM

#

@long mauve

long mauve Feb 28, 2023, 1:02 PM

#

quartz frost this is how i would do it

I see

#

Ty

quartz frost Feb 28, 2023, 1:06 PM

#

.close

cedar kilnBOT Feb 28, 2023, 1:06 PM

#

Channel closed

Closed by @quartz frost

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

zealous tapir Feb 28, 2023, 1:13 PM

#

How do I find x?

cedar kilnBOT Feb 28, 2023, 1:13 PM

#

zealous tapir How do I find x?

tropic oxide Feb 28, 2023, 1:20 PM

#

!status

cedar kilnBOT Feb 28, 2023, 1:20 PM

#

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

#

@zealous tapir Has your question been resolved?

zealous tapir Feb 28, 2023, 1:28 PM

#

1

clear berry Feb 28, 2023, 1:29 PM

#

try expanding using cos(a+b) formula

#

@zealous tapir

cedar kilnBOT Feb 28, 2023, 1:58 PM

#

@zealous tapir Has your question been resolved?

distant cedar Feb 28, 2023, 2:09 PM

#

@zealous tapir Use this identity: cos(a+b) = cosacosb + sinasinb

#

,, cos(a+b) = cosacosb + sinasinb

wraith daggerBOT Feb 28, 2023, 2:10 PM

#

RaphaelZZZ

distant cedar Feb 28, 2023, 2:10 PM

#

Once you simplify using this , you will be closer to getting x

cedar kilnBOT Feb 28, 2023, 2:28 PM

#

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

green jungle Feb 28, 2023, 2:30 PM

#

cedar kilnBOT Feb 28, 2023, 2:30 PM

#

green jungle

green jungle Feb 28, 2023, 2:31 PM

#

how do i continue?

timber mauve Feb 28, 2023, 2:33 PM

#

Do it graphically

leaden ledge Feb 28, 2023, 2:33 PM

#

Graph can only help in the no. Of solutions..

cedar kilnBOT Feb 28, 2023, 2:46 PM

#

@green jungle Has your question been resolved?

cedar kilnBOT Feb 28, 2023, 3:01 PM

#

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

#

Channel closed

Closed due to the original message being deleted

keen estuary Feb 28, 2023, 3:05 PM

#

$$tg({2x + π})$$

my solution is:
$$\frac{1}{cos^{2}(2x + π)} * 2$$

wraith daggerBOT Feb 28, 2023, 3:05 PM

#

sla-ppy

keen estuary Feb 28, 2023, 3:05 PM

#

wolfram is telling me i done messed up

#

i believe there is a common rule where you are usually supposed to switch most tg() into sin()/cos()

cerulean sail Feb 28, 2023, 3:06 PM

#

cedar kiln

[get a new channel btw as this one will close and may get hidden]

keen estuary Feb 28, 2023, 3:06 PM

#

cerulean sail [get a new channel btw as this one will close and may get hidden]

appreciate it

cedar kilnBOT Feb 28, 2023, 3:14 PM

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

drifting solar Feb 28, 2023, 3:24 PM

#

I need to prove for all real numbers n, if n is greater than 3, then $n^{2}>9$

cedar kilnBOT Feb 28, 2023, 3:24 PM

#

drifting solar I need to prove for all real numbers n, if n is greater than 3, then $n^{2}>9$

drifting solar Feb 28, 2023, 3:24 PM

#

I let $n=3+k$, such that $n^{2}=(3+k)^{2}$

wraith daggerBOT Feb 28, 2023, 3:24 PM

#

Matt.Rey

versed kayak Feb 28, 2023, 3:25 PM

#

drifting solar I need to prove for all real numbers n, if n is greater than 3, then $n^{2}>9$

Ur qn is incomplete

drifting solar Feb 28, 2023, 3:25 PM

#

my bad lol

wraith daggerBOT Feb 28, 2023, 3:25 PM

#

Matt.Rey

versed kayak Feb 28, 2023, 3:25 PM

#

Bro n^2 = 9+k^2+6k

#

Obv this is > 9

red pumice Feb 28, 2023, 3:26 PM

#

induction doesnt work on the reals

drifting solar Feb 28, 2023, 3:26 PM

#

versed kayak Bro n^2 = 9+k^2+6k

that's literally where I was going

#

I'm not doing induction

#

I was going to get there and I showed my work like $k(k+6)+94$, but that would be fine to show since the +9 is there anyways

wraith daggerBOT Feb 28, 2023, 3:27 PM

#

Matt.Rey

drifting solar Feb 28, 2023, 3:28 PM

#

.close

cedar kilnBOT Feb 28, 2023, 3:28 PM

#

Channel closed

Closed by @drifting solar

Use .reopen if this was a mistake.

cedar kilnBOT Feb 28, 2023, 3:52 PM

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

#

hollow garnet Feb 28, 2023, 3:59 PM

#

I'm having trouble finding my b variable here

#

This is integration with partial fractions

#

The problem is the thing on the top left

cedar kilnBOT Feb 28, 2023, 4:12 PM

#

Channel closed

Closed due to the original message being deleted

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

normal thorn Feb 28, 2023, 4:27 PM

#

Anyone here good with computers

cedar kilnBOT Feb 28, 2023, 4:27 PM

#

normal thorn Anyone here good with computers

normal thorn Feb 28, 2023, 4:27 PM

#

I know its not maths but i cant find anywhere to get tech help

viral cloak Feb 28, 2023, 4:32 PM

#

This is for maths - I suggest trying a different server.

normal thorn Feb 28, 2023, 4:35 PM

#

They kinda overlap

#

Im in dire need of help and noone else is replying

crimson delta Feb 28, 2023, 4:41 PM

#

you didnt even ask a proper question

#

how are people supposed to help you if they dont even know if they can help you because you didnt say anything specific

cedar kilnBOT Feb 28, 2023, 4:51 PM

#

@normal thorn Has your question been resolved?

normal thorn Feb 28, 2023, 4:52 PM

#

crimson delta how are people supposed to help you if they dont even know if they can help you ...

My computer is on but there isnt any response from the keyboard and mouse or monitors

crimson delta Feb 28, 2023, 4:53 PM

#

for that type of question this really is the wrong server

#

something something turn off and on again

#

plug everything in and out again

cedar kilnBOT Feb 28, 2023, 5:06 PM

#

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

vagrant condor Feb 28, 2023, 5:13 PM

#

how can i determine wether a given vector a is a scalar multiple of a given vector b in R^N?

cedar kilnBOT Feb 28, 2023, 5:13 PM

#

vagrant condor how can i determine wether a given vector a is a scalar multiple of a given vect...

#

@vagrant condor Has your question been resolved?

cedar kilnBOT Feb 28, 2023, 5:43 PM

#

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

plain badge Feb 28, 2023, 5:47 PM

#

cedar kilnBOT Feb 28, 2023, 5:47 PM

#

plain badge

plain badge Feb 28, 2023, 5:48 PM

#

I know we have to use the
Cauchy criterion to begin this problem

#

it's what comes after that i'm not sure

cedar kilnBOT Feb 28, 2023, 6:03 PM

#

@plain badge Has your question been resolved?

cedar kilnBOT Feb 28, 2023, 6:35 PM

#

@plain badge Has your question been resolved?

plain badge Feb 28, 2023, 7:02 PM

#

anyone, anyone

#

bueller?

cedar kilnBOT Feb 28, 2023, 8:02 PM

#

@plain badge Has your question been resolved?

wind glade Feb 28, 2023, 8:35 PM

#

$a_1 + a_2 + \cdots + a_n \ge na_n$

wraith daggerBOT Feb 28, 2023, 8:35 PM

#

please request a new nickname

plain badge Feb 28, 2023, 8:36 PM

#

wind glade $a_1 + a_2 + \cdots + a_n \ge na_n$

why is it >= na_n?

#

shouldn't it be epsilon not na_n

ripe siren Feb 28, 2023, 9:02 PM

#

plain badge why is it >= na_n?

decreasing sequence

#

a_i>=a_n for all i<=n

plain badge Feb 28, 2023, 9:06 PM

#

i had written down that cauchy's convergence criterion yields for every epsilon >0 there exists N, such that a_n+ a_n+1 + a_n+p < epsilon

cedar kilnBOT Feb 28, 2023, 11:06 PM

#

@plain badge Has your question been resolved?

cedar kilnBOT Feb 28, 2023, 11:25 PM

#

Channel closed

Closed by @plain badge

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

idle elm Feb 28, 2023, 11:31 PM

#

Does anyone have any advice on how to solve this? I get what its asking but I don't have any idea how I would find fk. I dont really understand math with factorials

cedar kilnBOT Feb 28, 2023, 11:31 PM

#

idle elm Does anyone have any advice on how to solve this? I get what its asking but I do...

proud torrent Feb 28, 2023, 11:32 PM

#

determine what C_1 is

idle elm Feb 28, 2023, 11:33 PM

#

-x^3/3!

#

assuming it wants the bottom series to be similar to the top one

proud torrent Feb 28, 2023, 11:33 PM

#

that's not C_1, that's the term from mclaurin series

idle elm Feb 28, 2023, 11:33 PM

#

Is C_1 not a term in the mclaurin series?

proud torrent Feb 28, 2023, 11:34 PM

#

the only things you know about C_j are that C_0 = x and that further C's can be obtained by using the recursive formula

idle elm Feb 28, 2023, 11:35 PM

#

But we are also told that the recursive formula can compute the maclaurin series

proud torrent Feb 28, 2023, 11:36 PM

#

if you know what coefficients f_k to put in, sure

#

but you said that you have a problem with that

idle elm Feb 28, 2023, 11:42 PM

#

I dont understand what you mean

proud torrent Feb 28, 2023, 11:43 PM

#

can you compute C_1 using the recursive formula?

idle elm Feb 28, 2023, 11:48 PM

#

If I replaced f_k with -3! then it would give me C_1

#

But that only works for C_1

proud torrent Feb 28, 2023, 11:50 PM

#

well you figured out what f_0 is equal to

#

what if you repeat the same process for C_2

proud torrent Feb 28, 2023, 11:51 PM

#

idle elm If I replaced f_k with -3! then it would give me C_1

and that's not the reasoning you should be approaching it with, you're trying to choose f_k such that the sum matches that of a mclaurin, not the other way around

cedar kilnBOT Mar 1, 2023, 12:04 AM

#

@idle elm Has your question been resolved?

cedar kilnBOT Mar 1, 2023, 12:19 AM

#

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

heady osprey Mar 1, 2023, 12:25 AM

#

cedar kilnBOT Mar 1, 2023, 12:25 AM

#

heady osprey

muted bear Mar 1, 2023, 12:26 AM

#

find the number of ways to not choose C

#

then subtract that

cedar kilnBOT Mar 1, 2023, 12:40 AM

#

@heady osprey Has your question been resolved?

cedar kilnBOT Mar 1, 2023, 12:55 AM

#

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

cedar kilnBOT Mar 1, 2023, 1:14 AM

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

vernal shoal Mar 1, 2023, 1:20 AM

#

cedar kilnBOT Mar 1, 2023, 1:20 AM

#

vernal shoal

vernal shoal Mar 1, 2023, 1:20 AM

#

help pls i dont know where to start

lethal jackal Mar 1, 2023, 1:22 AM

#

what's the increment method?

vernal shoal Mar 1, 2023, 1:22 AM

#

#

apparently this one

lethal jackal Mar 1, 2023, 1:24 AM

#

oh interesting

#

always thought of this as just using the definition of the derivative

vernal shoal Mar 1, 2023, 1:36 AM

#

pls help on how to start

#

im really confused

#

bcs its a fraction

latent bloom Mar 1, 2023, 1:39 AM

#

Hmm

#

Okay first write y = f(x)

#

@vernal shoal

vernal shoal Mar 1, 2023, 1:41 AM

#

yeaaa

latent bloom Mar 1, 2023, 1:43 AM

#

Okay

#

Now write f(x+h)

vernal shoal Mar 1, 2023, 1:43 AM

#

okk

latent bloom Mar 1, 2023, 1:47 AM

#

Did you get there yet?

vernal shoal Mar 1, 2023, 1:50 AM

#

yes

latent bloom Mar 1, 2023, 1:51 AM

#

Okay what did you get so far?

cedar kilnBOT Mar 1, 2023, 2:05 AM

#

@vernal shoal Has your question been resolved?

cedar kilnBOT Mar 1, 2023, 2:20 AM

#

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

crimson sedge Mar 1, 2023, 2:29 AM

#

hi - if you had to do r = 2cos4theta, can you multiply the 4 by theta?

cedar kilnBOT Mar 1, 2023, 2:29 AM

#

crimson sedge hi - if you had to do r = 2cos4theta, can you multiply the 4 by theta?

crimson sedge Mar 1, 2023, 2:29 AM

#

wait that doesnt make sense sorry

#

i have to graph points on polar coordinates by taking angles not on the unit circle like 16 degrees or 27 degrees and plugging them into the equation to find r so i can get a point (r, theta)

#

so if I had to do r = 2cos4theta where theta is 16 degrees, would it be r = 2cos(64 degrees) or r = 2cos(4(16 degrees)) ?

gilded elm Mar 1, 2023, 2:30 AM

#

ooh a plot?

#

also hello spideygirl

crimson sedge Mar 1, 2023, 2:31 AM

#

gilded elm also hello spideygirl

wow its derpz

#

i feel better about being dumb now

gilded elm Mar 1, 2023, 2:31 AM

#

lol yes i frequent these help channels

#

idk why

#

lol ur not dumb

crimson sedge Mar 1, 2023, 2:31 AM

#

but yea a plot

#

true, but regardless familiarity tends to be a plus

gilded elm Mar 1, 2023, 2:31 AM

#

crimson sedge so if I had to do r = 2cos4theta where theta is 16 degrees, would it be r = 2cos...

2cos 64 deg and 2cos 4(16) deg is the same you know

crimson sedge Mar 1, 2023, 2:31 AM

#

it evaluated differently when i plugged it into the calculator

gilded elm Mar 1, 2023, 2:32 AM

#

can you take a pic of the calculator

crimson sedge Mar 1, 2023, 2:32 AM

#

wait

#

now it did smh

#

i am dumb. my apologies

gilded elm Mar 1, 2023, 2:33 AM

#

no worries lol

crimson sedge Mar 1, 2023, 2:33 AM

#

.close

cedar kilnBOT Mar 1, 2023, 2:33 AM

#

Channel closed

Closed by @blissful mesa

Use .reopen if this was a mistake.

crimson sedge Mar 1, 2023, 2:33 AM

#

i appreciate the help re: stating the obvious

gilded elm Mar 1, 2023, 2:37 AM

#

lol nw

cedar kilnBOT Mar 1, 2023, 2:39 AM

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

crude scroll Mar 1, 2023, 2:48 AM

#

what would be the contradiction assuming $\alpha^2 > 2$?

Screen_Shot_2023-02-28_at_9.47.39_PM.png

cedar kilnBOT Mar 1, 2023, 2:48 AM

#

crude scroll what would be the contradiction assuming $\alpha^2 > 2$?

wraith daggerBOT Mar 1, 2023, 2:48 AM

#

KN

cedar kilnBOT Mar 1, 2023, 3:03 AM

#

@crude scroll Has your question been resolved?

#

Channel closed

Closed by @crude scroll

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

crimson sedge Mar 1, 2023, 3:08 AM

#

How do I go about solving this?

cedar kilnBOT Mar 1, 2023, 3:08 AM

#

crimson sedge How do I go about solving this?

long swan Mar 1, 2023, 3:09 AM

#

Pythag

#

Be careful with sign

lyric leaf Mar 1, 2023, 3:12 AM

#

cos(x) = sin(pi/2 - x)
sin(x) = cos(pi/2 - x)

cos(pi/2 - x) = 0.707
arccos(0.707) = 0.785549163

pi/2 - x = 0.785549163

x = 0.785549163

#

so do cos(0.786)

crimson sedge Mar 1, 2023, 3:13 AM

#

Sweet thank you

lyric leaf Mar 1, 2023, 3:14 AM

#

feel a little weird about my sol. though, wouldnt mind being double checked

crimson sedge Mar 1, 2023, 3:14 AM

#

Alright, not sure if I should round it or not

cedar kilnBOT Mar 1, 2023, 3:29 AM

#

@crimson sedge Has your question been resolved?

cedar kilnBOT Mar 1, 2023, 3:44 AM

#

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

crimson sedge Mar 1, 2023, 3:55 AM

#

cedar kilnBOT Mar 1, 2023, 3:55 AM

#

crimson sedge

crimson sedge Mar 1, 2023, 3:57 AM

#

@uncut veldt

cosmic steppe Mar 1, 2023, 3:58 AM

#

!15m

cedar kilnBOT Mar 1, 2023, 3:58 AM

#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

#

@crimson sedge Has your question been resolved?

cedar kilnBOT Mar 1, 2023, 4:27 AM

#

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

near trout Mar 1, 2023, 4:36 AM

#

how to do this quadratic graph?

cedar kilnBOT Mar 1, 2023, 4:36 AM

#

near trout how to do this quadratic graph?

crimson sedge Mar 1, 2023, 4:38 AM

#

what class is this for

#

@crimson sedge do you know about transformations

#

?

crimson sedge Mar 1, 2023, 4:39 AM

#

near trout how to do this quadratic graph?

@near trout is this calculus or like an algebra class

near trout Mar 1, 2023, 4:40 AM

#

the teacher introduced a new topic to us but didnt explain it. he just gave the worksheet right away.

#

so i dont know- most likely algebra

crimson sedge Mar 1, 2023, 4:40 AM

#

what class is this for though?

near trout Mar 1, 2023, 4:40 AM

#

10

crimson sedge Mar 1, 2023, 4:40 AM

#

alr

#

you havent done derivatives right?

near trout Mar 1, 2023, 4:40 AM

#

i have

crimson sedge Mar 1, 2023, 4:40 AM

#

oh

near trout Mar 1, 2023, 4:40 AM

#

derivative function?

crimson sedge Mar 1, 2023, 4:40 AM

#

so its a calculus class ?

near trout Mar 1, 2023, 4:40 AM

#

dy/dx?

crimson sedge Mar 1, 2023, 4:40 AM

#

yeah

#

find the derivative of f(x) and plug in 0.5

#

that will be the gradient of the tangent line

near trout Mar 1, 2023, 4:41 AM

#

oh alright thanks

#

❤️

cedar kilnBOT Mar 1, 2023, 4:56 AM

#

@near trout Has your question been resolved?

cedar kilnBOT Mar 1, 2023, 5:11 AM

#

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

#

worldly vault Mar 1, 2023, 5:34 AM

#

need help proving this

cedar kilnBOT Mar 1, 2023, 5:35 AM

#

Channel closed

Closed due to the original message being deleted

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

dusky marsh Mar 1, 2023, 5:58 AM

#

cedar kilnBOT Mar 1, 2023, 5:58 AM

#

dusky marsh

dusky marsh Mar 1, 2023, 5:58 AM

#

dusky marsh

just need help on understanding 1/7 of the GST inclusive price

#

this question is basically asking which one i should rather take to get a better deal of the shoes. so either take 1/7 of the GST inclusive price or refund the GST which at this moment would be 158.50 x 0.85= 134.725

cedar kilnBOT Mar 1, 2023, 6:15 AM

#

@dusky marsh Has your question been resolved?

cedar kilnBOT Mar 1, 2023, 6:45 AM

#

@dusky marsh Has your question been resolved?

dusky marsh Mar 1, 2023, 7:15 AM

#

.close

cedar kilnBOT Mar 1, 2023, 7:15 AM

#

Channel closed

Closed by @dusky marsh

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

gilded oracle Mar 1, 2023, 7:19 AM

#

hello

cedar kilnBOT Mar 1, 2023, 7:19 AM

#

gilded oracle hello

gilded oracle Mar 1, 2023, 7:20 AM

#

i had like 20 questions in statistics to solve and i did solve all except 4 questions, can you guys help me out with answer for the remaining 4, the due is in 15 minutes

#

The relationship between two data series, with 38 data points per series, is investigated. Calculated correlation coefficients are Rs = 0.87 and R= 0.82.

Which of the following question statements is/are correct?

There is a monotonic relationship between the data series.
When one variable increases, the other variable can be expected to increase.
There is a linear relationship between the data series.
There is a causal relationship between the data series.
There is a statistical relationship between the data series.

#

.close

cedar kilnBOT Mar 1, 2023, 7:33 AM

#

Channel closed

Closed by @gilded oracle

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

steady wing Mar 1, 2023, 7:37 AM

#

Nature of the series defined by $a_{n+1}=1-e^{-(a_n)}$

cedar kilnBOT Mar 1, 2023, 7:37 AM

#

steady wing Nature of the series defined by $a_{n+1}=1-e^{-(a_n)}$

steady wing Mar 1, 2023, 7:37 AM

#

With an >0

wraith daggerBOT Mar 1, 2023, 7:38 AM

#

dabble

steady wing Mar 1, 2023, 7:47 AM

#

.close

cedar kilnBOT Mar 1, 2023, 7:47 AM

#

Channel closed

Closed by @steady wing

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

sturdy barn Mar 1, 2023, 7:51 AM

#

PLEASe HELP

cedar kilnBOT Mar 1, 2023, 7:51 AM

#

sturdy barn PLEASe HELP

sturdy barn Mar 1, 2023, 7:54 AM

#

<@&286206848099549185>

devout galleon Mar 1, 2023, 7:54 AM

#

expand it

crimson sedge Mar 1, 2023, 7:54 AM

#

sturdy barn <@&286206848099549185>

!15m

cedar kilnBOT Mar 1, 2023, 7:54 AM

#

sturdy barn <@&286206848099549185>

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

sturdy barn Mar 1, 2023, 7:55 AM

#

alr

#

i did and now i have 2xcubed +2pxsquare+1xsquared+8X+pX+4

devout galleon Mar 1, 2023, 7:56 AM

#

coefficients of x = 2 * coefficients x^2

#

solve it

sturdy barn Mar 1, 2023, 7:57 AM

#

p=2?

#

is my answer

#

correct?

devout galleon Mar 1, 2023, 7:58 AM

#

show your equation

#

coefs of x: 8 + p

#

coefs of x^2: 2p + 1

#

8 + p = 2 (2p + 1)

#

solve

sturdy barn Mar 1, 2023, 8:01 AM

#

yes thats it

#

did you get 2

devout galleon Mar 1, 2023, 8:02 AM

#

thats it

sturdy barn Mar 1, 2023, 8:04 AM

#

how do you do this

devout galleon Mar 1, 2023, 8:05 AM

#

divide to (y-3)

sturdy barn Mar 1, 2023, 8:06 AM

#

how

#

oh ok

devout galleon Mar 1, 2023, 8:06 AM

#

you know column division?

sturdy barn Mar 1, 2023, 8:07 AM

#

no

devout galleon Mar 1, 2023, 8:08 AM

#

hey are you sure?

sturdy barn Mar 1, 2023, 8:08 AM

#

no

#

is column division dividing everythig by 3?

#

also why y-3?

#

OH I GOT IT

devout galleon Mar 1, 2023, 8:10 AM

#

see
3xy-9x+4y-12
3x(y-3)+4(y-3)
(y-3)(3x+4)

sturdy barn Mar 1, 2023, 8:10 AM

#

you can use long divison too

devout galleon Mar 1, 2023, 8:10 AM

#

not me you

sturdy barn Mar 1, 2023, 8:11 AM

#

also how to do this

#

lets work out together

devout galleon Mar 1, 2023, 8:11 AM

#

try yourself first

sturdy barn Mar 1, 2023, 8:11 AM

#

alr

#

factorise but stuck on the inverse part

devout galleon Mar 1, 2023, 8:13 AM

#

factorisation is already done

sturdy barn Mar 1, 2023, 8:17 AM

#

alr i got x=e cubed

#

and x=-4/3

devout galleon Mar 1, 2023, 8:19 AM

#

show your solution

#

right

sturdy barn Mar 1, 2023, 8:21 AM

#

yeah

#

alr thanks boss

#

seriously

#

have a good day

#

.close

cedar kilnBOT Mar 1, 2023, 8:21 AM

#

Channel closed

Closed by @sturdy barn

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

shell beacon Mar 1, 2023, 8:36 AM

#

cedar kilnBOT Mar 1, 2023, 8:36 AM

#

shell beacon

shell beacon Mar 1, 2023, 8:38 AM

#

for part (ii), i wrote that due to y = 1 being a line of symmetry for C1 and C2, the only way to have one intersection point is for the point to be at the left vertex of the ellipse. i can solve for k (k = 6), but i then i tried to approach it differently by setting up a quadratic equation and setting discriminant = 0, but i cant seem to get the same answer.

#

Is the discriminant approach not possible in this question? If so, why not?

tribal sparrow Mar 1, 2023, 8:44 AM

#

discriminant approach should work, maybe some calculation mistake?

shell beacon Mar 1, 2023, 8:50 AM

#

#

wait my first step is already wrong fml

#

tribal sparrow Mar 1, 2023, 9:01 AM

#

well, tried it myself, but it doesn't seem to work lol

shell beacon Mar 1, 2023, 9:02 AM

#

Is there a reason why it shouldn’t?

tribal sparrow Mar 1, 2023, 9:02 AM

#

I can't think of any reason to say so

shell beacon Mar 1, 2023, 9:03 AM

#

did you get the same equation as i did

tribal sparrow Mar 1, 2023, 9:04 AM

#

nope

#

I mean almost same, just difference of a sign

shell beacon Mar 1, 2023, 9:08 AM

#

oh oops yeah the last equation should be -1 not +1

tribal sparrow Mar 1, 2023, 9:09 AM

#

I mean, I got, 36k^4 + 4(1296 + k^2)(1296k^2) = 0

shell beacon Mar 1, 2023, 9:09 AM

#

but ultimately the discriminant is still never 0

tribal sparrow Mar 1, 2023, 9:09 AM

#

tribal sparrow I mean, I got, 36k^4 + 4(1296 + k^2)(1296k^2) = 0

which simply implies that there are no real solutions

#

apart from k = 0

shell beacon Mar 1, 2023, 9:10 AM

#

rip

#

would it matter if the equation was in terms of y?

tribal sparrow Mar 1, 2023, 9:11 AM

#

nope, D would still have to be 0

#

since you only want one x, and one y

shell beacon Mar 1, 2023, 9:13 AM

#

Is the discriminant approach impossible?

tribal sparrow Mar 1, 2023, 9:15 AM

#

that's what I am trying to think, that if it's really not possible, then why not

cedar kilnBOT Mar 1, 2023, 9:28 AM

#

@shell beacon Has your question been resolved?

cedar kilnBOT Mar 1, 2023, 9:59 AM

#

@shell beacon Has your question been resolved?

cedar kilnBOT Mar 1, 2023, 10:59 AM

#

@shell beacon Has your question been resolved?

cedar kilnBOT Mar 1, 2023, 12:59 PM

#

@shell beacon Has your question been resolved?

cyan wren Mar 1, 2023, 2:49 PM

#

shell beacon Is the discriminant approach not possible in this question? If so, why not?

I know it's related to extraneous roots, I just am not sure why

#

gimme a sec

#

ye it should be just about how (-x)^2 = x^2 aka extraneous root shenanigans

cedar kilnBOT Mar 1, 2023, 5:36 PM

#

@shell beacon Has your question been resolved?

cedar kilnBOT Mar 1, 2023, 9:36 PM

#

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

upper root Mar 1, 2023, 9:52 PM

#

#chill

cedar kilnBOT Mar 1, 2023, 9:52 PM

#

upper root #chill

#

@upper root Has your question been resolved?

cedar kilnBOT Mar 1, 2023, 10:22 PM

#

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

balmy raft Mar 1, 2023, 10:31 PM

#

Hello guys my camera is dookie so I'll send pictures instead written on an app

cedar kilnBOT Mar 1, 2023, 10:31 PM

#

balmy raft Hello guys my camera is dookie so I'll send pictures instead written on an app

balmy raft Mar 1, 2023, 10:31 PM

#

#

I need to verify this identity

fallen moat Mar 1, 2023, 10:32 PM

#

i guess it's in degrees

balmy raft Mar 1, 2023, 10:32 PM

#

I've tried changing tan and cot to their formule which is cos/sin and sin/cos and then work it out by canceling etc but I can get nowhere near 1

#

And yes the identity is true

balmy raft Mar 1, 2023, 10:33 PM

#

balmy raft I've tried changing tan and cot to their formule which is cos/sin and sin/cos an...

I was hoping someone could help me from here on

burnt pumice Mar 1, 2023, 10:33 PM

#

Working on it

fallen moat Mar 1, 2023, 10:33 PM

#

did you try things like
sin(90°-a)=cos(a)

balmy raft Mar 1, 2023, 10:33 PM

#

U can't use those here

#

I think...

burnt pumice Mar 1, 2023, 10:36 PM

#

Have you tried using these?

balmy raft Mar 1, 2023, 10:37 PM

#

I can't use those here cuz my math teacher will ask me to prove these formulas and she'll count them wrong

burnt pumice Mar 1, 2023, 10:37 PM

#

I'm pretty sure you can't do this without these formulas

Why not just learn the proofs?

#

And what do you mean, "she'll count them wrong"?

balmy raft Mar 1, 2023, 10:38 PM

#

burnt pumice Have you tried using these?

If I use the things you sent here she will ask me this on my paper "proof this" and I wont prove it cuz I don't know the proof of it so it will be counted as wrong

burnt pumice Mar 1, 2023, 10:39 PM

#

Oh

#

Okay

balmy raft Mar 1, 2023, 10:39 PM

#

It's pure math like fractions etc but it's just that I'm stuck and can't do a thing

burnt pumice Mar 1, 2023, 10:42 PM

#

Yeah man, you cant solve it without those formulas

#

I'll send u the solution in a minute

balmy raft Mar 1, 2023, 10:43 PM

#

Thanks a lot I'll try explaining it to hzr

cedar kilnBOT Mar 1, 2023, 10:58 PM

#

@balmy raft Has your question been resolved?

balmy raft Mar 1, 2023, 11:01 PM

#

cedar kiln <@668512189245685790> Has your question been resolved?

Someone is working on it

burnt pumice Mar 1, 2023, 11:02 PM

#

Hmmm

cedar kilnBOT Mar 1, 2023, 11:13 PM

#

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

green grove Mar 1, 2023, 11:15 PM

#

2 independent quality tests are applied to a product, the probability of the project passing the first successfully is 0.3, the probability that a product doesnt pass any quality test is 0.1, given that a product has passed the first test what is the probability that it has passed both tests

cedar kilnBOT Mar 1, 2023, 11:15 PM

#

green grove 2 independent quality tests are applied to a product, the probability of the pro...

green grove Mar 1, 2023, 11:15 PM

#

A - passes first check - P(A)=0.3\
B - passes second check\
$P(A \cup B)=0.9$\
$P(A \cup B) = P(A)+P(B)-P(A \cap B) \implies P(A \cup B)=P(A)+P(B)-P(A)P(B)$\
$P(B \mid A)=P(B)$

wraith daggerBOT Mar 1, 2023, 11:15 PM

#

metnal

green grove Mar 1, 2023, 11:15 PM

#

did i solve this correctly?

#

the answer is just P(B) right?

cedar kilnBOT Mar 1, 2023, 11:31 PM

#

@green grove Has your question been resolved?

cedar kilnBOT Mar 1, 2023, 11:46 PM

#

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

buoyant latch Mar 1, 2023, 11:51 PM

#

cedar kilnBOT Mar 1, 2023, 11:51 PM

#

buoyant latch

buoyant latch Mar 1, 2023, 11:51 PM

#

,rotate

wraith daggerBOT Mar 1, 2023, 11:51 PM

#

buoyant latch Mar 1, 2023, 11:51 PM

#

#

,rcw

wraith daggerBOT Mar 1, 2023, 11:51 PM

#

buoyant latch Mar 1, 2023, 11:52 PM

#

wraith dagger

Shouldn’t this one be linear combinations of (1, 2, 3) and (2, 2, 4)?

buoyant latch Mar 1, 2023, 11:52 PM

#

wraith dagger

Since here we say the vector z is a linear combinations of its vectors x and y

buoyant latch Mar 1, 2023, 11:53 PM

#

wraith dagger

But in here c1 c2 is just some real number, not a vector

#

(Well now that I think about it, R is a vector space so each element would be a vector, but I don’t think that’s the point here)

lethal jackal Mar 1, 2023, 11:54 PM

#

what's z

#

oh

#

wait what's your question

#

oh

#

yeah c(A) is the set of vectors that are linear combinations of the columns of A

buoyant latch Mar 1, 2023, 11:55 PM

#

Did I/lecturer write down the wrong thing

lethal jackal Mar 1, 2023, 11:55 PM

#

c is the column space yeah

buoyant latch Mar 1, 2023, 11:56 PM

#

So it should say C(A) is the set of vectors that are a linear combination of (1, 2, 3), (2, 2, 4)

lethal jackal Mar 1, 2023, 11:57 PM

#

what does C(A) mean though

#

like the notation

buoyant latch Mar 1, 2023, 11:57 PM

#

Oh is it supposed to be small c

#

Column space of A

lethal jackal Mar 1, 2023, 11:58 PM

#

is it the column space of the matrix A

buoyant latch Mar 1, 2023, 11:58 PM

#

Oh it doesn’t say

#

Fuck I missed the first part

#

Yes

lethal jackal Mar 1, 2023, 11:58 PM

#

like I'm just assuming that it is

#

then yes it is the set of all linear combinations of the columns of A

#

otherwise known as the span of the columns of A

buoyant latch Mar 1, 2023, 11:58 PM

#

Yeah yeah

#

lethal jackal Mar 1, 2023, 11:59 PM

#

or maybe you could call it Im(A) if you think about the associated linear transformation

buoyant latch Mar 2, 2023, 12:03 AM

#

I don’t know what Im(A) is

lethal jackal Mar 2, 2023, 12:03 AM

#

like the set of all vectors that Ax can produce

buoyant latch Mar 2, 2023, 12:03 AM

#

Anyway I either wrote down the wrong thing or the lecturer did

lethal jackal Mar 2, 2023, 12:03 AM

#

yeah

buoyant latch Mar 2, 2023, 12:14 AM

#

Would it be correct to say that the column space of matrix A, denoted as C(A) is the set of all possible linear combinations of the column vectors of A, and is a vector space

#

Do we know it’s a vector space or should I try and prove that to further my understanding

cedar kilnBOT Mar 2, 2023, 12:30 AM

#

@buoyant latch Has your question been resolved?

royal loom Mar 2, 2023, 12:38 AM

#

buoyant latch Do we know it’s a vector space or should I try and prove that to further my unde...

it is most definitely a vector space

buoyant latch Mar 2, 2023, 12:42 AM

#

Is this a good start

buoyant latch Mar 2, 2023, 12:44 AM

#

royal loom it is most definitely a vector space

Yeah that’s what it says on Wikipedia but I don’t know for certain that it is

#

Hmm is it for some or for any

#

And do I have to say that at least 1 of the c’s have to be non zero?

lethal jackal Mar 2, 2023, 1:06 AM

#

no

#

a vector space has to contain the zero vector

buoyant latch Mar 2, 2023, 1:12 AM

#

Oh true

#

Hmm I’m kinda stuck on showing the sum of 2 column spaces is another column space

#

#

Not sure how to get a ci out

buoyant latch Mar 2, 2023, 1:45 AM

#

.close

cedar kilnBOT Mar 2, 2023, 1:45 AM

#

Channel closed

Closed by @buoyant latch

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

misty tinsel Mar 2, 2023, 1:47 AM

#

This chem but

cedar kilnBOT Mar 2, 2023, 1:47 AM

#

misty tinsel This chem but

misty tinsel Mar 2, 2023, 1:48 AM

#

How he divide 0.010/15.0 x 1000000

#

And get 670?

#

I got a decimal

obsidian coral Mar 2, 2023, 1:48 AM

#

What did you type in your calculator?

cedar kilnBOT Mar 2, 2023, 2:03 AM

#

@misty tinsel Has your question been resolved?

misty tinsel Mar 2, 2023, 2:09 AM

#

obsidian coral What did you type in your calculator?

#

<@&286206848099549185>

obsidian coral Mar 2, 2023, 2:10 AM

#

misty tinsel

670 is rounded to the nearest tens

misty tinsel Mar 2, 2023, 2:12 AM

#

Isn’t rounding to the nearest tenths

#

666.7

#

(Just to show)

#

@obsidian coral

#

Nearest whole number is just 667

obsidian coral Mar 2, 2023, 2:13 AM

#

Not tenth

#

Tens

#

The tens place

misty tinsel Mar 2, 2023, 2:13 AM

#

Oh

#

.close

cedar kilnBOT Mar 2, 2023, 2:14 AM

#

Channel closed

Closed by @misty tinsel

Use .reopen if this was a mistake.

misty tinsel Mar 2, 2023, 2:14 AM

#

,close

#

Ok

#

Thx

#

,close

#

.close

cedar kilnBOT Mar 2, 2023, 2:15 AM

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

echo osprey Mar 2, 2023, 2:15 AM

#

cedar kilnBOT Mar 2, 2023, 2:15 AM

#

echo osprey

echo osprey Mar 2, 2023, 2:15 AM

#

i have to find a polynomial that factors into these

#

but i don't know how

cedar kilnBOT Mar 2, 2023, 2:30 AM

#

@echo osprey Has your question been resolved?

echo osprey Mar 2, 2023, 2:32 AM

#

i got it

#

.close

cedar kilnBOT Mar 2, 2023, 2:32 AM

#

Channel closed

Closed by @echo osprey

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

weak mountain Mar 2, 2023, 2:33 AM

#

Let X be a topological space

cedar kilnBOT Mar 2, 2023, 2:33 AM

#

weak mountain Let X be a topological space

weak mountain Mar 2, 2023, 2:34 AM

#

Can the closure of $X\setminus{x}$ be X if no sequence in $X\setminus{x}$ can converge to x

wraith daggerBOT Mar 2, 2023, 2:34 AM

#

Kitty

cedar kilnBOT Mar 2, 2023, 2:49 AM

#

@weak mountain Has your question been resolved?

#

Channel closed

Closed by @weak mountain

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

wind whale Mar 2, 2023, 3:03 AM

#

How do i do this? i have no idea where to even start

cedar kilnBOT Mar 2, 2023, 3:03 AM

#

wind whale How do i do this? i have no idea where to even start

wind whale Mar 2, 2023, 3:05 AM

#

#

along with these i have no idea where to even begin

forest sparrow Mar 2, 2023, 3:12 AM

#

wind whale How do i do this? i have no idea where to even start

keep up w the good work bud 👍

fallen moat Mar 2, 2023, 3:15 AM

#

,rotate

wraith daggerBOT Mar 2, 2023, 3:15 AM

#

fallen moat Mar 2, 2023, 3:17 AM

#

wind whale How do i do this? i have no idea where to even start

how did you do Q3 in the first place?
that one is correct, and Q4 is similar

cedar kilnBOT Mar 2, 2023, 3:22 AM

#

@wind whale Has your question been resolved?

cedar kilnBOT Mar 2, 2023, 3:37 AM

#

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

crimson sedge Mar 2, 2023, 3:42 AM

#

I got that I need 27 steps to calculate the cube root correctly w/ bisection method but it doesn’t sound right. Can I have a second opinion?

cedar kilnBOT Mar 2, 2023, 3:42 AM

#

crimson sedge I got that I need 27 steps to calculate the cube root correctly w/ bisection met...

#

@crimson sedge Has your question been resolved?

cedar kilnBOT Mar 2, 2023, 4:12 AM

#

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

silent plover Mar 2, 2023, 4:17 AM

#

cedar kilnBOT Mar 2, 2023, 4:17 AM

#

silent plover

silent plover Mar 2, 2023, 4:17 AM

#

hi can someone help with the last part

cedar kilnBOT Mar 2, 2023, 4:32 AM

#

@silent plover Has your question been resolved?

silent plover Mar 2, 2023, 4:32 AM

#

<@&286206848099549185>

wind pewter Mar 2, 2023, 4:36 AM

#

silent plover hi can someone help with the last part

[0,1]

#

if p and q are 90 degrees from each other r=1, if they are 0 degrees from each each other then r=0

silent plover Mar 2, 2023, 4:37 AM

#

yeah i did that but it says its wrong

wind pewter Mar 2, 2023, 4:38 AM

#

hm

wind pewter Mar 2, 2023, 4:39 AM

#

silent plover yeah i did that but it says its wrong

have you tried [-1,1]

silent plover Mar 2, 2023, 4:39 AM

#

ah

wind pewter Mar 2, 2023, 4:39 AM

#

that should be correct, since you can get negative values

silent plover Mar 2, 2023, 4:40 AM

#

forgot about negative

#

yep its correct

#

@wind pewter ty

wind pewter Mar 2, 2023, 4:40 AM

#

np

#

.close

wind pewter Mar 2, 2023, 4:45 AM

#

silent plover yep its correct

you should type ,close my dude

silent plover Mar 2, 2023, 4:46 AM

#

sorry i forgot

#

.close

cedar kilnBOT Mar 2, 2023, 4:46 AM

#

Channel closed

Closed by @silent plover

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

cinder bluff Mar 2, 2023, 4:54 AM

#

how to i’(x) = ((4x+6)^4(2x-5)^2))’

cedar kilnBOT Mar 2, 2023, 4:54 AM

#

cinder bluff how to i’(x) = ((4x+6)^4(2x-5)^2))’

vagrant elbow Mar 2, 2023, 5:03 AM

#

$i(x) = (4x + 6)^4(2x - 5)^3$

wraith daggerBOT Mar 2, 2023, 5:03 AM

#

NEONPerseus

vagrant elbow Mar 2, 2023, 5:03 AM

#

If you're meant to differentiate this, use the product rule

cinder bluff Mar 2, 2023, 5:05 AM

#

i honestly don’t know how to arrive to the solution

vagrant elbow Mar 2, 2023, 5:05 AM

#

$(uv)' = u'v + v'u$

wraith daggerBOT Mar 2, 2023, 5:05 AM

#

NEONPerseus

cinder bluff Mar 2, 2023, 5:05 AM

#

4(4x+6)^3 X 3(2x-5)^2 ?

vagrant elbow Mar 2, 2023, 5:06 AM

#

Not quite

cinder bluff Mar 2, 2023, 5:06 AM

#

but there’s no + in the solution

#

so I’m lost

vagrant elbow Mar 2, 2023, 5:06 AM

#

They probably did some factoring maybe

#

4(4x + 6)^3(2x - 5)^3 + 3(2x - 5)^2(4x + 6)^4

#

You should have this

cinder bluff Mar 2, 2023, 5:07 AM

#

ok

#

but from this to 32(2x+3)^3(2x-5)^2(14x-11) I’m lost

#

shit makes no sense to me

cedar kilnBOT Mar 2, 2023, 5:26 AM

#

@cinder bluff Has your question been resolved?

cedar kilnBOT Mar 2, 2023, 6:03 AM

#

@cinder bluff Has your question been resolved?

cedar kilnBOT Mar 2, 2023, 7:03 AM

#

@cinder bluff Has your question been resolved?

cedar kilnBOT Mar 2, 2023, 8:03 AM

#

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

tidal wasp Mar 2, 2023, 8:37 AM

#

can someone explain to my why the graph of -2^x looks like this?

cedar kilnBOT Mar 2, 2023, 8:37 AM

#

tidal wasp can someone explain to my why the graph of -2^x looks like this?

tidal wasp Mar 2, 2023, 8:37 AM

#

isnt -2^2 = 4 not -4?

leaden ledge Mar 2, 2023, 8:38 AM

#

You have to out -2 in a bracket

#

(-2)^x

#

Like that

#

It drew the graph of y = - 2^x

tidal wasp Mar 2, 2023, 8:38 AM

#

it just shows this then...

#

leaden ledge Mar 2, 2023, 8:40 AM

#

Its actually kind of ungraphable as it will be undefined onn the real axis at infinitely many points between any two even powers

#

Is what I think kind of

tidal wasp Mar 2, 2023, 8:41 AM

#

hmm

#

i kinda get it

#

i guess

#

so when i graph -2^x it actually graphs -1 * 2^x?

leaden ledge Mar 2, 2023, 8:45 AM

#

Yeah

tidal wasp Mar 2, 2023, 8:52 AM

#

i see

#

thx

#

.close

cedar kilnBOT Mar 2, 2023, 8:52 AM

#

Channel closed

Closed by @tidal wasp

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

tidal wasp Mar 2, 2023, 8:55 AM

#

cedar kilnBOT Mar 2, 2023, 8:55 AM

#

tidal wasp

tidal wasp Mar 2, 2023, 8:57 AM

#

by doing it manually i got the value to be 1102.5

#

but the formula given is giving me 36000

#

nvm im supposed to take r as 0.05 instead of 5

wary hamlet Mar 2, 2023, 8:59 AM

#

The answer is d?

#

Yes

tidal wasp Mar 2, 2023, 8:59 AM

#

wary hamlet The answer is d?

yes it is

tidal wasp Mar 2, 2023, 8:59 AM

#

wary hamlet Yes

mhm

#

thx

#

.close

cedar kilnBOT Mar 2, 2023, 8:59 AM

#

Channel closed

Closed by @tidal wasp

Use .reopen if this was a mistake.

cedar kilnBOT Mar 2, 2023, 9:22 AM

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

chilly bolt Mar 2, 2023, 9:43 AM

#

does the negation of a statement reverse its quantifier

cedar kilnBOT Mar 2, 2023, 9:43 AM

#

chilly bolt does the negation of a statement reverse its quantifier

chilly bolt Mar 2, 2023, 9:43 AM

#

like negation of a for all statement changes to there exists ...

crimson delta Mar 2, 2023, 9:43 AM

#

Yes

chilly bolt Mar 2, 2023, 9:44 AM

#

would that also be a counterexample

crimson delta Mar 2, 2023, 9:44 AM

#

"For all numbers something holds" gets turned to "there exists a number for which it doesn't hold"

#

And that number is then precisely a counterexample

#

If that's what you are asking

chilly bolt Mar 2, 2023, 9:44 AM

#

ok thanks

cedar kilnBOT Mar 2, 2023, 9:59 AM

#

@chilly bolt Has your question been resolved?

#

Channel closed

Closed by @chilly bolt

Use .reopen if this was a mistake.

cedar kilnBOT Mar 2, 2023, 12:21 PM

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

shrewd blaze Mar 2, 2023, 12:23 PM

#

.

#

How do you solve/calculate the percentile?

cedar kilnBOT Mar 2, 2023, 12:25 PM

#

shrewd blaze How do you solve/calculate the percentile?

shrewd blaze Mar 2, 2023, 12:26 PM

#

I know how to solve that but i forgot one step

quartz frost Mar 2, 2023, 12:27 PM

#

can you post an example of what you are doing/where you are stuck?

shrewd blaze Mar 2, 2023, 12:28 PM

#

Wait let me make a problem

#

I dont have a problem yet but i need it for exam tomorrow

#

So i need to review

#

#

There i made a small problem

#

I just want to know on where to place / where the percentile located

#

#

Here i added the cf

#

Can you find the percentile of 23?

#

. Close

#

.close

cedar kilnBOT Mar 2, 2023, 12:39 PM

#

Channel closed

Closed by @shrewd blaze

Use .reopen if this was a mistake.

shrewd blaze Mar 2, 2023, 12:39 PM

#

Ill just study my self

cedar kilnBOT Mar 2, 2023, 12:40 PM

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

peak dome Mar 2, 2023, 12:48 PM

#

how did he factorized it ?

cedar kilnBOT Mar 2, 2023, 12:48 PM

#

peak dome how did he factorized it ?

#

@peak dome Has your question been resolved?

cerulean gyro Mar 2, 2023, 1:15 PM

#

u can do it with your calculator

#

or if your fractions is really good, use any method you want

cedar kilnBOT Mar 2, 2023, 1:18 PM

#

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

#

Channel closed

Closed due to the original message being deleted

waxen agate Mar 2, 2023, 1:23 PM

#

#

so in question #4 how did they get 2x?

cerulean gyro Mar 2, 2023, 1:29 PM

#

probably by isoceles triangle property

waxen agate Mar 2, 2023, 1:30 PM

#

whats that

cerulean gyro Mar 2, 2023, 1:30 PM

#

it's a circle, so all the lengths from the centre to the side of the circle are the same lengths

#

when u join the edges, they form isoceles triangles

#

the 2 non-centre angles in the triangle are the same

#

using that, u can calculate the centre angle

#

the 2 triangles' centre angles are related, as when u add them up you get 180 degrees

#

do the reverse to get 2x

waxen agate Mar 2, 2023, 1:32 PM

#

sorry if im being dumb

#

but wdym by

#

do the reverse

cerulean gyro Mar 2, 2023, 1:32 PM

#

isoceles triangles' angles in this case are " 2 side angles + 1 centre angle = 180 degrees"

cedar kilnBOT Mar 2, 2023, 1:32 PM

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

cerulean gyro Mar 2, 2023, 1:32 PM

#

if u know the centre angles, u can solve for both side angles

cedar kilnBOT Mar 2, 2023, 1:32 PM

#

cerulean gyro if u know the centre angles, u can solve for both side angles

#

Please don't occupy multiple help channels.

waxen agate Mar 2, 2023, 1:33 PM

#

ok thanks

#

.close

cedar kilnBOT Mar 2, 2023, 1:47 PM

#

@cerulean gyro Has your question been resolved?

#

Channel closed

Closed by @cerulean gyro

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

crimson sedge Mar 2, 2023, 1:54 PM

#

math help in polygons uve all those sides that r basically equal to each other like a pentagon shape having five sides so how do i know or i can prove that all sides are equal to each other?

#

can you help me understand with an image of a shape that how are those sides actually equal is i dont get?

cedar kilnBOT Mar 2, 2023, 1:54 PM

#

crimson sedge math help in polygons uve all those sides that r basically equal to each other l...

cosmic steppe Mar 2, 2023, 1:56 PM

#

What

#

You need to state your problem clearer

#

Are you asking how to prove a polygon is regular?

crimson sedge Mar 2, 2023, 1:58 PM

#

yes that

#

how do one proves that the polygons all sides are equal to each other or like angels thing

cosmic steppe Mar 2, 2023, 1:59 PM

#

Send me a photo

#

You most likely have to use SAS and then CPCTC

crimson sedge Mar 2, 2023, 2:00 PM

#

what is sas and cpctc

cosmic steppe Mar 2, 2023, 2:01 PM

#

"Side-angle-side" and "corresponding parts of congruent triangles are congruent"

#

But like

#

I need to see the full problem

#

Send a photo

crimson sedge Mar 2, 2023, 2:01 PM

#

#

it has said the pentagon has five sides and all those sides are equal to each other as in a polygon

#

so how do one knows that they are equal in a polygon shape?

#

how are five sides equal

cosmic steppe Mar 2, 2023, 2:18 PM

#

If you're given that it's a regular polygon then by definition the five sides are congruent

#

But

#

If you were to take all the radii of the polygon

#

They should all sector the polygon into 5 congruent isosceles triangle whose vertex angle is 360/5

cedar kilnBOT Mar 2, 2023, 2:23 PM

#

@crimson sedge Has your question been resolved?

crimson sedge Mar 2, 2023, 2:25 PM

#

thanks so much @cosmic steppe

cedar kilnBOT Mar 2, 2023, 2:25 PM

#

Channel closed

Closed by @tender sundial

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

quasi plover Mar 2, 2023, 2:33 PM

#

cedar kilnBOT Mar 2, 2023, 2:33 PM

#

quasi plover

quasi plover Mar 2, 2023, 2:33 PM

#

mark scheme

south juniper Mar 2, 2023, 2:34 PM

#

can u find the gradient of the given line first?

quasi plover Mar 2, 2023, 2:34 PM

#

south juniper can u find the gradient of the given line first?

it mseems like 5

#

im not sure

south juniper Mar 2, 2023, 2:35 PM

#

5/2 because you need to isolate y first

#

that is done by dividing both sides by 2

quasi plover Mar 2, 2023, 2:35 PM

#

how do we do that

south juniper Mar 2, 2023, 2:35 PM

#

for a line y=mx+c, the gradient/slope is always m

quasi plover Mar 2, 2023, 2:35 PM

#

y = (3+5x)/2

south juniper Mar 2, 2023, 2:35 PM

#

Yes, so the slope is 5/2

cosmic steppe Mar 2, 2023, 2:35 PM

#

Well there's a nicer way of doing it

quasi plover Mar 2, 2023, 2:35 PM

#

what about the 3

cosmic steppe Mar 2, 2023, 2:35 PM

#

I can show you a little trick

south juniper Mar 2, 2023, 2:35 PM

#

its the y-intercept you dont need it

#

sure!

quasi plover Mar 2, 2023, 2:36 PM

#

cosmic steppe I can show you a little trick

yes please

cosmic steppe Mar 2, 2023, 2:36 PM

#

For the linear equation $Ax + By = C$, the perpendicular gradient is $\frac BA$

wraith daggerBOT Mar 2, 2023, 2:36 PM

#

Umbraleviathan

quasi plover Mar 2, 2023, 2:36 PM

#

what about the C?

cosmic steppe Mar 2, 2023, 2:36 PM

#

Don't care

quasi plover Mar 2, 2023, 2:36 PM

#

we just ignore it?

#

oh

#

graet

cedar cypress Mar 2, 2023, 2:37 PM

#

The constant just controls the intercepts and shifts the line while keeping the slope same

quasi plover Mar 2, 2023, 2:37 PM

#

sounds unreasonable but i like it

quasi plover Mar 2, 2023, 2:37 PM

#

cedar cypress The constant just controls the intercepts and shifts the line while keeping the ...

C is constant?

cedar cypress Mar 2, 2023, 2:37 PM

#

quasi plover C is constant?

I mean the constant term without any x or y degrees in it

cosmic steppe Mar 2, 2023, 2:37 PM

#

Well yeah. The constant just shifts the line up or down but has nothing to do with slope

floral forge Mar 2, 2023, 2:37 PM

#

the inverse of a line will have slope perpendicular to the initial line, hence why this works

#

so its like solving for x=my+c

quasi plover Mar 2, 2023, 2:38 PM

#

should I understand this, or i should just remember the equation up there and use it

cedar cypress Mar 2, 2023, 2:38 PM

#

Another thing I'd like to add, product of slopes of two perpendicular lines is always -1

floral forge Mar 2, 2023, 2:38 PM

#

def should understand it

#

as always in math

quasi plover Mar 2, 2023, 2:38 PM

#

cedar cypress Another thing I'd like to add, product of slopes of two perpendicular lines is a...

?

quasi plover Mar 2, 2023, 2:38 PM

#

floral forge as always in math

well i dont understand the process of thinking to solve the equation it self ;-;

cedar cypress Mar 2, 2023, 2:39 PM

#

quasi plover ?

Let's say i have two perpendicular lines with slopes M1 and M2, then M1 times M2 is always -1

#

Comes handy

quasi plover Mar 2, 2023, 2:39 PM

#

cedar cypress Let's say i have two perpendicular lines with slopes M1 and M2, then M1 times M2...

to make sure, perpendicular lines is the line that intercept with each other right?

quasi plover Mar 2, 2023, 2:40 PM

#

cedar cypress Let's say i have two perpendicular lines with slopes M1 and M2, then M1 times M2...

gradient of both line times each other always -1

cedar cypress Mar 2, 2023, 2:40 PM

#

quasi plover to make sure, perpendicular lines is the line that intercept with each other rig...

Perpendicular lines are those lines that which intersect at right angles

cedar cypress Mar 2, 2023, 2:40 PM

#

quasi plover gradient of both line times each other always -1

Yep

#

If the lines are perpendicular

quasi plover Mar 2, 2023, 2:41 PM

#

cedar cypress Perpendicular lines are those lines that which intersect at right angles

oh, so does the -1 only works with perpendicular lines or any lines that intercept with each other at any angles

#

oh oh sorry my bad

cedar cypress Mar 2, 2023, 2:41 PM

#

Only with perpendicular

#

It's converse is also true

#

If product of gradients of two lines is -1, then they are perpendicular

cosmic steppe Mar 2, 2023, 2:42 PM

#

cedar cypress If product of gradients of two lines is -1, then they are perpendicular

(As fractions)

quasi plover Mar 2, 2023, 2:42 PM

#

oh wait, the question is asking me to find the gradient of the other (opposite) lines of the equation right?

#

which so gradient A times gradient B is always -1

#

so why i cannot just do -1/5

cedar cypress Mar 2, 2023, 2:43 PM

#

Why -1/5?

quasi plover Mar 2, 2023, 2:44 PM

#

cedar cypress Why -1/5?

i thought the equation is the y=mx+b?

cedar cypress Mar 2, 2023, 2:44 PM

#

The gradient of the first line is 5/2

#

Not 5

cedar cypress Mar 2, 2023, 2:44 PM

#

quasi plover i thought the equation is the y=mx+b?

Yes, but there's a 2 in your equation with that y

#

Need to get rid of that first

quasi plover Mar 2, 2023, 2:44 PM

#

cedar cypress The gradient of the first line is 5/2

cedar cypress Mar 2, 2023, 2:45 PM

#

Yes get it in the form y=mx+c

#

M is 5/2

quasi plover Mar 2, 2023, 2:45 PM

#

2y = 5x + 3?

#

now its in the form

cedar cypress Mar 2, 2023, 2:45 PM

#

No

#

The 2

#

Isn't there in the mx+c form

#

you need to divide it

#

Both sides by 2

#

The form is y=MX+c, not 2y=MX+c

quasi plover Mar 2, 2023, 2:46 PM

#

but the it would be (5x+3)/2

cedar cypress Mar 2, 2023, 2:47 PM

#

Yes and take the 2 inside

#

5x/2+3/2

#

So m is 5/2

#

And c is 3/2

quasi plover Mar 2, 2023, 2:47 PM

#

?

#

whats C in the y=mx+c again?

#

i think i forgot

#

and is this the way to find the gradient of the another line right?

#

;-;

cedar cypress Mar 2, 2023, 2:50 PM

#

quasi plover whats C in the y=mx+c again?

The y intercept

quasi plover Mar 2, 2023, 2:50 PM

#

cedar cypress The y intercept

but y interccept is mx+c isnt it?

#

i rememebr the M is gradient

cedar cypress Mar 2, 2023, 2:50 PM

#

What do you understand by the y intercept?

quasi plover Mar 2, 2023, 2:51 PM

#

the point where the line pass the Y axis

cedar cypress Mar 2, 2023, 2:51 PM

#

Yes so logically shouldn't it the point (0,c), where c is the value of y at x=0?

#

So the y intercept is c

quasi plover Mar 2, 2023, 2:52 PM

#

cedar cypress Yes so logically shouldn't it the point (0,c), where c is the value of y at x=0?

sorry can you expand that? im not sure did i understand it correctly

#

#

whats 0,c

#

0 and c

#

y=mx+b

cedar cypress Mar 2, 2023, 2:52 PM

#

quasi plover whats 0,c

The coordinates

#

Of the y intercept

quasi plover Mar 2, 2023, 2:53 PM

#

what???

#

im not sure did i understand you

cedar cypress Mar 2, 2023, 2:54 PM

#

Can you plot this line? That way you can understand yourself

#

What I mean by 0,c

quasi plover Mar 2, 2023, 2:54 PM

#

its the middle

#

the-positive-solutions-of-the-equation-ax-by-c-0-always-lie-in-the-1644991092.png

#

#

the point where y and X interceppt

cedar kilnBOT Mar 2, 2023, 3:10 PM

#

@quasi plover Has your question been resolved?

cedar kilnBOT Mar 2, 2023, 3:25 PM

#

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

knotty wagon Mar 2, 2023, 3:41 PM

#

(Q.25) Had this question for an exam, is the answer 72m? (7200 cm)

cedar kilnBOT Mar 2, 2023, 3:41 PM

#

knotty wagon (Q.25) Had this question for an exam, is the answer 72m? (7200 cm)

gritty galleon Mar 2, 2023, 3:42 PM

#

knotty wagon (Q.25) Had this question for an exam, is the answer 72m? (7200 cm)

Depends, in a MCQ you would tick all the opinions which means 72m/7200cm
In a subjective manner, then yes, 72m would be better