help-13

[hot cloak]

how do i approach this

ive tried a few different substitutions

but they dont seem to work

[short blade]

this looks like trig sub

[hot cloak]

yh thats what i tried

i tried subbing sinhx

[short blade]

have you tried x = (tan theta)^1/4

[hot cloak]

no

[short blade]

hm the outside is only squared

that probably won’t work then

oh sorry

x = sqrt(tan theta)

i think that might get you somewhere but i haven’t worked it all out

[hot cloak]

i tried

but its not getting me anywhere

lol

i get some awkward integral to solve

sqrt(sec)/tan^3

is what i end up with

[short blade]

the bottom should become tan * sec^(3/2)

then when you do dx -> dtheta

ah i see i thought the secant would go away

[cedar kiln]

@hot cloak Has your question been resolved?

[hot cloak]

it apparenltly gives a nice answer actually

still ns how to solve it tho

<@&286206848099549185>

[crimson sedge]

Yes?

[hot cloak]

hi

trying to solve this integral

[hot cloak]

made a substitution for x^2 = tan(u)

ended up with this integral but not sure how i can solve it

[cedar kiln]

@hot cloak Has your question been resolved?

[hot cloak]

/close

.close

[cedar kiln]

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[astral thicket]

You distribute 25 oranges over 10 boxes at random.
(a) Identify the distribution of the number of oranges in box #1.
(b) What is the probability that box #1 receives more than 3 oranges?
(c) What is the expected number of boxes that contain more than 3 oranges?

[astral thicket]

can someone help me with part b

i assume part a is just the numbers from 0 to 25 as he asked for distribution not probability distribution

[crimson sedge]

I think in a) they mean the probability distribution for the number oranges in box 1

[astral thicket]

wouldnt that take so much time

[crimson sedge]

You know binomial distributions?

[astral thicket]

yeah

[crimson sedge]

then it takes one line

[astral thicket]

25 choose 1?

or wait no

[crimson sedge]

let's call the number of oranges in box 1 by the letter k

then you need to calculate a probability that depends on k

[astral thicket]

25Ck/25C10?

[crimson sedge]

ask yourself what the probability is to pick box 1 in a single pick

[astral thicket]

1/10

[crimson sedge]

right

so if you have k oranges in box 1 you have for each configuration a probability of $0.1^k \cdot 0.9^{25-k}$; now think about how many ways there are to pick k things from 25 ones

[wraith dagger]

Landau08

[astral thicket]

25CK?

[crimson sedge]

right, now put both things together.

[astral thicket]

25CK 0.1^k 0.9^25-k

oh i know this

thanks alot man

[crimson sedge]

right

$P(X=k) = {25\choose k}0.1^k\cdot 0.9^{25-k}$

[wraith dagger]

Landau08

[crimson sedge]

You can use that result to answer b and c.

[astral thicket]

and for part b i just do 1-P(box <= 3)

[crimson sedge]

That's a simple way to do b.

[astral thicket]

which is 1-P(0)-P(1)-P(2)-P(3)

[crimson sedge]

right

[astral thicket]

give me please a minute to think about c

[crimson sedge]

I need to think about it first, too 😉

(I misread c first)

c is more complicated

[astral thicket]

we can do it summation ( P(X=K).k) for k from 4 to 25

but bruh it takes so much time

though i dont think professor will mind me using a calculator

[crimson sedge]

The problem is that when one box has many oranges in it that will change the probability for another box to have more than 3 oranges in them, so those probabilities are correlated

[astral thicket]

what do you suggest we do

[astral thicket]

lol i read question wrong as well

[crimson sedge]

I haven't had a clever idea yet

My intuition is that one can and needs to show that the answer to c is 10*result from b).

[astral thicket]

how?

the answer of b is 0.23

so thats basically 2.3 boxes

too low

unless i did a calc mistake

[crimson sedge]

I would guess that.

I'll quickly write a simulation in python

[astral thicket]

its a perfect number?

[astral thicket]

while you are at it plz write one for b cuz i believe i chocked it

[crimson sedge]

I think your answer to b is correct.

[astral thicket]

yeah correct

you are fast lmao

[crimson sedge]

(that wasn't a simulation though)

it's not close enough to 10*answer of b

[astral thicket]

wow

nice one

whats your major?

[crimson sedge]

I am a physicist

[astral thicket]

wow good luck

so any idea on how can we prove c?

[crimson sedge]

I am bit confused why this simulation is so different from our result b

[astral thicket]

this is the exact value i got

honestly i dont know much about python so i cant understand what you are writing

[crimson sedge]

didn't you get 0.236...

[astral thicket]

yes

[crimson sedge]

that's a bit away from 0.3

[astral thicket]

wdym

anyway it isnt a big deal i can make sure of it tmrw

[crimson sedge]

it's off by 20% too big discrepancy

[astral thicket]

i think you did a mistake in the last code

[crimson sedge]

I now see

[astral thicket]

because the previous one is exact to mine

[crimson sedge]

It was an error in my python: rnd.randint(1,high=10,size=25) gives you random numbers from 1 to 9

I should have written rnd.randint(1,high=11,size=25) because the upper bound is excluded

[astral thicket]

F

[astral thicket]

W

[crimson sedge]

for the expected number of boxes with more than 3 oranges I get the following simulated value

which is slightly less than 10*result from b

[astral thicket]

so its good?

[crimson sedge]

so things are probably more complicated than just calculating 10 * result b because of correlations

[astral thicket]

ill check it out tmrw because honestly its 12 am here and i get to wake up at 6

[crimson sedge]

I see, where do you live?

[astral thicket]

unless you have something in mind we can try

lebanon

[crimson sedge]

No clue yet, so have a good sleep!

[astral thicket]

thanks for you attention man

appreciate it

[crimson sedge]

no problem!

[cedar kiln]

@astral thicket Has your question been resolved?

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[crystal idol]

Is that correct?

[crystal idol]

hello

lol

wtf

im sorry lol

[sinful hound]

you made a factoring error for log(x^3 - xy^2)

[crystal idol]

which one

[sinful hound]

log(x^3 - xy^2) ≠ log(x(x-y))

[crystal idol]

$log(x^3 - xy^2) ≠ log(x(x-y))$

[wraith dagger]

Lupin

[sinful hound]

wow latex hates me :’)

[crystal idol]

no you are not allowed to make space between the $ and the written thing.

$jj$

[wraith dagger]

Lupin

[sinful hound]

oh

[crystal idol]

$ jj $

[sinful hound]

woops

[crystal idol]

comes nothing

[sinful hound]

$ jj$

[crystal idol]

$jj$

[wraith dagger]

Lupin

[crystal idol]

anyways log(x(x^2 -y)?

[sinful hound]

no

if you’re only factoring out x you don’t factor out y too

[crystal idol]

I did

y^2 => y

or not

[sinful hound]

no

[crystal idol]

show me then

[sinful hound]

$x^3 - xy^2 = x(x^2 - y^2)$

[wraith dagger]

Syafiq

[sinful hound]

that

[crystal idol]

dont we have to take out from everything one of them like y^2 => y and x^4 =>x^3 for example

(my english is not the best im sorry)

[crystal idol]

Now if we do it with x(x^2 -y^2) how would it be look like?

[sinful hound]

in the case of the factorization i did no cause i only took out x and i didn’t take out y

[sinful hound]

so for x^2 - y^2 you factor out by difference of squares

$x^2 - y^2 = (x+y)(x-y)$

[wraith dagger]

Syafiq

[crystal idol]

from both

But How do I get x(x-y)

[wraith dagger]

Lupin

[sinful hound]

make use of log properties

[crystal idol]

why its not (x+y)^2 here

solution says only x+y

[sinful hound]

so after you fully factor out x^3 - xy^2 you get x(x-y)(x+y)
then when you do log(x(x-y)(x+y)) - log((x+y)^2) and make use of log properties the x+y term gets cancelled out once

[crystal idol]

okey thanks

.close

[cedar kiln]

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[neat wave]

ANS 12

Is choice a correct for 12th

[muted bear]

Show us the other choices

[neat wave]

Here

Pls anyone, help daddy

[muted bear]

Wtf

[neat wave]

Ohh, u back mah dude

[muted bear]

Can b be negative?

[neat wave]

I assume z is complex number

It could be a+bi or a-bi

Or same with a

I am not looking to solve, just want to ej

Check

Anyone there?

[muted bear]

Oh its imaginary

[neat wave]

Complex

B is imaginary

So which choice is correct

[muted bear]

think about Z as a point on the complex plane

What formula do you use to find the length between two points

[neat wave]

Yes

Pythogrean thorm

I choice obtion b

[muted bear]

Indeed

[neat wave]

Okay here is where the problem cimes

Comes*

The answer key says the correct ans is a

Which doesn't make any sense even if z is a complex or real umber

[muted bear]

It doss if a and b are both positive reals

But thats it

[neat wave]

But they haven't specified

So I am assuming they could be negative

Alright my worksheet is r worded

[muted bear]

Can you show the original directions?

Like the whole worksheet

Or at least the directions

[neat wave]

You want a copy of the whole worksheet?

Directions?

[muted bear]

Nah just the directions

[neat wave]

Ohh, to download it?

Well, it is

[muted bear]

No i dont download anything

[neat wave]

You want the PDF link?

[cyan breach]

what is Z

[neat wave]

It's a whole book sorta

Not a single workshet

For entry test preparation

[muted bear]

Did you read

I dont download

Take a screenshot

[neat wave]

Hrre

Yo big papi

Here is the whole bundle, 55gs in there

[neat wave]

Hair

Should I close this chanel or so to want to say something else?

. close

.close

[cedar kiln]

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[cedar kiln]

@dense gate Has your question been resolved?

[cedar kiln]

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[crimson sedge]

.

[zealous spear]

Claim 😈

[zealous spear]

LOL

So hey guys, just wondering if you guys can help me solve for (Co), I tried treating it as if it is the variable x, but no success even on photomath, I know Co is supposed to equal to 30.28 but I want to know how to get it

[lusty grotto]

U can factor out a C_O⁴ from the denomimator

[zealous spear]

Can you show me how, when it comes to this type of algebra of factoring out it was never my strong suit

So like (pi/2)*C_O^4(1-(0.9)^4) ?

[lusty grotto]

Yes

That is right

So that becomes ur denomimator

And now u see that there is also a C_O in the numerator

[zealous spear]

So something like this right?

I rewrote C_O^4 as x to make it easier to read

[lusty grotto]

Yeah I'm guessing ur numerical values are correct

So now u can cancel an x

Assuming x is not 0

[zealous spear]

The x in the numerator right

because an x / x^4 is basically like taking the x in the numerator away and the denom x being x^3 now

[lusty grotto]

Yes

Now move everything other than the x³ to one side of the equation , and just take the cube root of both sides to find x

[zealous spear]

Wow thank you Silver Soldier

[lusty grotto]

👍

[zealous spear]

I feel smart as hell now

Cheers, have a good night / day, ill close the channel

[lusty grotto]

😄

[zealous spear]

.close

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[bronze phoenix]

this right?

[ember geode]

yeah

although that first minus sign should be a plus, i assume thats just a typo

[bronze phoenix]

also when it says find the exact value does it want me to punch cos(30) in the calc or does it want the unit circle value?

[bronze phoenix]

it is srry on that part

[cedar kiln]

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[spark perch]

need help to solve this

[zenith sail]

,rotate

[cedar kiln]

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[jade stag]

is this the same as, (cbrt(x) )^2

[jade stag]

https://tenor.com/view/ratatouille-rat-ratjam-catjam-ratjammers-gif-21929051

[tropic oxide]

we don't say "3rd sqrt"

we say cube root, or third root

[jade stag]

how would u type that

certainly not (3sqrt(x))^2 right

[tropic oxide]

x^(2/3), honestly.

[jade stag]

im aware this is x^(2/3)

[cosmic steppe]

cbrt

[tropic oxide]

cbrt(x^2) if you insist

[jade stag]

ok

[tropic oxide]

but i would not bother with plaintexting roots of higher degrees as distinct from fractional exponents

[jade stag]

gotchu

so going back to the original question

is that writing incorrect

besides the first part

(cbrt(x))^2?

or cbrt(x^2)

are they both the same?

[crimson sedge]

they're quite different

try substituting x as 8 in both

in (cbrt(x))^2

we'll have 2^2

which will be 4

in cbrt(x^2)

[tropic oxide]

they are the same

[crimson sedge]

we'll have cbrt(64)

4

oh shi they're same

lmao my bad

[jade stag]

im not even capping

both r 4

l0l

soooooooooo

[crimson sedge]

they're the same

[jade stag]

https://tenor.com/view/ratatouille-rat-ratjam-catjam-ratjammers-gif-21929051

which (ann)otation is correct

[jade stag]

here

[half forge]

cbrt(x^2) and (cbrt(x))^2 are the same

They're both x^(2/3)

[jade stag]

which is formal writing

though

[half forge]

Both

[crimson sedge]

both are correct

[jade stag]

so in a textbook

if one feels like doin one

over they other

theyll do it that way

[crimson sedge]

you can do it

[jade stag]

if they have chocolate, theyll do first way, but if theyre feeling vanilla then latter

[crimson sedge]

yea it's cool

[jade stag]

flip a coin then

isee

thanks guys

.close

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[flint plinth]

cool pic bro

!status

[cedar kiln]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[dire geode]

Sneaky photo in class while taking a test?

[cedar kiln]

@worthy shell Has your question been resolved?

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[rich radish]

how is this incorrect lol

[crimson sedge]

Why plus sign

It's quotient rule

Negative in between

[rich radish]

oh yea

lol

[cedar kiln]

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[signal vault]

for b why cant i just plug the formula

[crimson sedge]

did you look at the solution

[signal vault]

yeah

[crimson sedge]

which part do you not understand exactly?

[signal vault]

i plugged in the formula but it still gave me the wrong answer

[crimson sedge]

What was your answer?

[signal vault]

wait let me just show you my working out

[crimson sedge]

,rotate

[crimson sedge]

Are you trying to use the formula for the sum of the first terms of an Arithmetico-geometric sequence?

I'm not familiar with this formula but obviously you didn't apply it correctly

[signal vault]

Yes

How do

So

[crimson sedge]

I think what you're supposed to do is simply add a1+a2+a3+a4 since they asked you a2 and a3 it's the quickest and simplest you just need a4 and it's a simple sum

[signal vault]

So no formula just add up

This is a geometric sequence right ?

[crimson sedge]

no

It's arithmetico-geometric

I think the formula would look like that

$\left( k-\dfrac{3}{1-5}\right) \left( \dfrac{1-5^{4}}{1-5}\right) +4\times \dfrac{3}{1-5}$

But i could be very wrong

The best is definitely to add a1+a2+a3+a4

[wraith dagger]

Zamarus

[crimson sedge]

Ho i see you used the formula for a geometric sequence

But because of the +3 it's an arithmetico-geometric sequence so it doesn't work

" un+1= a * un " is not the same as "a * un+b" so it doesn't work

Here because of the +3 can you see it's not geometric?

Well i doubt you have the formula for arithmetico-geometric sequence so yep just add them by hand

[signal vault]

ah ok i got it

tysm

.close

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[waxen kestrel]

Find the new coordinates for vector b = (1,3,7,7)^T in base h=cols(H).

[waxen kestrel]

Where do I start? I have proved that the "Hadamard Matrice" is orthogonal. But when it comes to base change I'm a little lost

[cedar kiln]

@waxen kestrel Has your question been resolved?

[crimson delta]

so you need to find coefficients c1, c2, c3, c4 so that b=c1h1+c2h2+c3h3+c4h4 where h_i are the columns of H

can you write that as a system of linear equations?

can you solve it using H orthogonal?

[waxen kestrel]

I'm having a hard time visualizing how e.g c1h1 looks like, is it just c1(1/2, 1/2, -1/2, 1/2)?

[crimson delta]

why the minus

h1 is the column

the first row of the system will be 1/2 c1 + 1/2 c2 - 1/2 c3 + 1/2 c4 = 1

[cedar kiln]

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[noble yarrow]

.cliam

.claim

Claim

[upper garnet]

.claim

[sage forge]

.unclaim

[upper garnet]

Rude

.claim spiffier

It's yours again now!

Do .claim stop for people unable to unclaim it

[noble yarrow]

Prove (x+1)/(x-2)=1 as x approaches infinity

[noble yarrow]

Oh

[lusty grotto]

Divide the numerator and denominator by x

[sage forge]

Outstanding move. There is nothing I can do against

[upper garnet]

Real

[noble yarrow]

Delta epsilon

[lusty grotto]

Oh

[upper garnet]

Ph god

Oh

Delta epsilon 💀

[lusty grotto]

Have u tried anything

[noble yarrow]

Um I have gotten 3/epsilon +2

Idk

I wanna make sure

[sage forge]

How did you get that?

[noble yarrow]

Lemme send a document

[sage forge]

A picture would be better. I don't download documents of people I don't know

[noble yarrow]

Oh no it’s an image

[upper garnet]

That's good

[noble yarrow]

I don’t do limits with infinity so this might be incorrect

.close

[cedar kiln]

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Channel closed

Closed due to the original message being deleted

[prime sparrow]

From where should i learn how to graph composite functions

Like i know some basics like what happens when you divide or multiply or add by some number (say) K and all of that

[rugged palm]

#❓how-to-get-help

[prime sparrow]

Wdym

It says channel closed so i asked my question

[rugged palm]

You have to pick a channel from these (the available section)

[cedar kiln]

Available help channel!

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[prime sparrow]

Oh alr, got you

[hushed spoke]

You got this one now

You can ask your question here

[prime sparrow]

Yes lemme copy paste it

From where should i learn how to graph composite functions

Like i know some basics like what happens when you divide or multiply or add by some number (say) K and all of that

[cedar kiln]

@prime sparrow Has your question been resolved?

[hushed spoke]

you are going to have to elaborate more

and you should also probably post a related problem

that you are having trouble with

so that we know what you are trying to get

[cedar kiln]

@prime sparrow Has your question been resolved?

[prime sparrow]

Like i can graph functions like sin4x or stuff but cant sketch the graphs for functions like sinx+cosx

Or sin(cosx)

And so on

[cedar kiln]

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[calm laurel]

I got a question about chemistry can someone help

[reef crown]

Well this is not the correct server, but try asking?

[calm laurel]

.close

[cedar kiln]

Channel closed

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Use .reopen if this was a mistake.

[shrewd blaze]

.

[calm laurel]

Question d

.reopen

[cedar kiln]

✅

[shrewd blaze]

N

[cedar kiln]

@calm laurel Has your question been resolved?

[cedar kiln]

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[hardy verge]

ABC is a triangle with BC = 15cm, AC = 18cm, and AB = 12cm. Let I and G be the center of the incircle and the incenter of triangle ABC, respectively.

a) Prove that IG is parallel to BC.

b) Calculate the length of the line segment IG.

[desert cosmos]

wait me 5 min

i will try

iy

it

[hardy verge]

okay

[desert cosmos]

a)

i was sloved

i think :))

[hardy verge]

anyway are you vietnamese?

[desert cosmos]

u

i from vietnamese

[hardy verge]

i'm vietnamese

[desert cosmos]

vc

[hardy verge]

yea

[desert cosmos]

vai l

noi tieng viet me di

:)))

[hardy verge]

so we can talk in vietnamese to understand each other better

[hardy verge]

ừ

rồi chỉ đi

[desert cosmos]

cau a

no tiep cũ

xúc

vc bc

nó tiếp xúc với BC

tututu

cho xiu

[hardy verge]

ừ

[desert cosmos]

xam l me r

:))

lop may vay

[hardy verge]

cấp hai. _.

[desert cosmos]

t cap 3

:))

the cu em thi hsg chua

[hardy verge]

kết bạn discord đi có gì tiện hỏi

[hardy verge]

em thi hsg tiếng anh cơ

[desert cosmos]

chi a hoc TA di e

:))

anh ngu TA vc

t hsg gioi toan

[hardy verge]

em cùng lắm chỉ làm đưuọc đến lớp chín

.close

[cedar kiln]

Channel closed

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[cedar kiln]

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[signal comet]

Hello, I'm doing my maths homework and I'm stuck at the questions c1/c2. I tried for an 1h but I'm still stuck. Thanks for your help

[signal comet]

If you want my responses at the previous questions I could send them to you.

[cedar kiln]

@signal comet Has your question been resolved?

[cedar kiln]

@signal comet Has your question been resolved?

[cedar kiln]

@signal comet Has your question been resolved?

[cedar kiln]

@signal comet Has your question been resolved?

[cedar kiln]

@signal comet Has your question been resolved?

[gentle yacht]

bro has been staying up since 5 pm and still hasn’t gotten his question answered

<@&286206848099549185>

[dire geode]

don't ping for other people

you don't know if they're here or not

[crimson sedge]

.

[regal bridge]

It's in Spanish

Not everyone can answer

[crimson sedge]

im loving this discord server

[gentle yacht]

It’s great to have an explanation ready for him when he returns, in case someone has the knowledge

[dire geode]

and if someone wanted to work on it, they would have done so by now

without your unnecessary ping

[gentle yacht]

‘

[crimson sedge]

translate it into english and were gonna answer it

[small dust]

french lol

[regal bridge]

I couldn't tell. Just new it was another language

[cedar kiln]

@signal comet Has your question been resolved?

[signal comet]

Okay ill do it for you guys

[fickle trellis]

I've turned off Helper pings for the same reason that people abuse the ping.

[soft owl]

1. Prove that for each $n \in \N$, $a_{2n+2} = (2n+2) \int^{\frac{\pi}{2}}_{0} t\sin(t)\cos(t)^{2n+1} \dd t$ \
2. deduce that for each $n \in \N$, $\frac{a_{2n+2}}{n+1} = (2n+1)b_n - (2n+2)b_{2n+1}$

[wraith dagger]

Mehdi_Moulati

[soft owl]

@signal comet you can solve the (C1) by integration By part

hint : ||(2n+2) sin(t) cos(t)^(2n+1) = ( - cos(t))^(2n+2) )'||

replace it first then integrate

[crimson sedge]

<@&286206848099549185>

[cedar kiln]

@signal comet Has your question been resolved?

[shrewd blaze]

I need help

[soft owl]

#❓how-to-get-help

open your own channel to get help

[cedar kiln]

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[plain badge]

We have 65 students and want to divide them into two classes in the same room

[plain badge]

however the room has a maximum capacity of 34

how would you find the number of possible outcomes

[cedar kiln]

@plain badge Has your question been resolved?

[plain badge]

Classes are assigned as A and B

both classes held in the same room at different times

[cedar kiln]

@plain badge Has your question been resolved?

[cedar kiln]

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• Show your work, and if possible, explain where you are stuck.
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[crimson quarry]

How to do 2.c

[crimson quarry]

2.a is true i just did dot product

2.b I got 2i,3j, 12k

Idk how to do c

<@&286206848099549185>

[old pewter]

Hmmm

Let's see here

[crimson quarry]

Did u see?

.close

[cedar kiln]

Channel closed

Closed by @crimson quarry

Use .reopen if this was a mistake.

[old pewter]

.reopen

[cedar kiln]

✅

[old pewter]

I'm working it out

[mild arrow]

Bros impatient

[old pewter]

It's taking me a minute haven't done vectors in a while

[cedar kiln]

@crimson quarry Has your question been resolved?

[cedar kiln]

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• Show your work, and if possible, explain where you are stuck.
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[ruby yew]

need help finding y

[lusty grotto]

can you find those angles inside the triangle in terms of y

[ruby yew]

they arent given

[lusty grotto]

can you find them in terms of y i ask, i dont mean an exact value for them

[ocean linden]

If two lines bisect, there must be similar angles yes?

[ruby yew]

sorry but I cant

[lusty grotto]

what do you know about angles on a straight line

[ruby yew]

they are 180?

[lusty grotto]

yes

you can use that here

[ruby yew]

so?

they are both 180?

[lusty grotto]

well

what did you mean when you said "they are 180"

[ruby yew]

cuz the angles are all on a straight line

so they can equal to 180?

[ruby yew]

ok?

[lusty grotto]

look over here

that entire thing, that angle inside the triangle + the angle 3y form a straight angle

[ruby yew]

okayy

[lusty grotto]

what can you say about their sum; angle inside the triangle + 3y = ?

[ruby yew]

idk

[lusty grotto]

what did we just talk abt

[ruby yew]

about forming a straight angle

[lusty grotto]

what can you say about the sum of angles that form a straight angle

[lusty grotto]

look at this

[ruby yew]

it is 180

[lusty grotto]

yes

[ruby yew]

yes

[lusty grotto]

so angle inside the triangle + 3y = ?

[ruby yew]

180?

[lusty grotto]

yes

coz those two angles are on a straight line right

[ruby yew]

yes

[lusty grotto]

if you have any number of angles like this that lie on a straight line

then their sum is 180

[ruby yew]

so the both angles will equal to 180?

[lusty grotto]

in this case A + B + C = 180

[lusty grotto]

no that is not possible and why would you think that

[ruby yew]

ok

[lusty grotto]

i have a certain number of marbles, and you have a certain number of marbles, lets say the total number of marbles that we have is 180. that does not mean you and i both have 180 marbles

[ruby yew]

okayy

[lusty grotto]

it maybe that i have 90 marbles and you have 90 marbles

or it may even be that i have 100 and u have 80 etc

anyway

now that you know angle inside the triangle + 3y = 180

can you rearrange this equation so it looks like angle inside the triangle = ?

[ruby yew]

no i cant

[lusty grotto]

like move everything else to the other side

if you have x + y = 2, can you move everything to one side and make it look like x = something?

[ruby yew]

No i cant since the work is online I cant move anything

[lusty grotto]

just send me a msg i mean

you don have to do this in ur work but can you just do that and type it here?

[ruby yew]

wait i have to go

[cedar kiln]

@ruby yew Has your question been resolved?

[cedar kiln]

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[cedar kiln]

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• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

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[rugged pewter]

What have you tried

What does X represent?

So then what time would it be?

if x = 1

if its one minute past noon

what time is it

So what time is it if x = 1?

If x is the number of minutes past noon?

I trust that you can figure it out from here, good luck!

Perhaps

What have you tried?

[random bison]

Hi

[rugged pewter]

Well I can't help you without knowing what you have attempted so far, I don't know what it is that you need help on

[random bison]

Read the question carefully

[rugged pewter]

Read it thoroughly and try to understand what it is asking

[random bison]

And take your time

[rugged pewter]

The answer is in the question

What was your thought process

Not exactly

when you use an oven, does it instantly get to its temperature to bake, or do you have to wait time for it to preheat?

and does it instantly get to 450 degrees?

Right

it increases by a little bit as time goes on

So y is the final temperature

79 is just a constant

the 45 is being multiplied by x

So we'll say 79 is the starting temperature of the oven

what has to happen for the 79 degrees to get up to like 450 degrees?

What has to happen for an oven to get to a higher temperature

and waiting takes ...

what passes when you wait

hint: it starts with a t

Right

and what does X represent in this problem

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

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[cedar kiln]

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• Show your work, and if possible, explain where you are stuck.
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• Be polite and have a nice day!

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[leaden lintel]

Assume there is a parametric function (x(t), y(t)). We are given dx/dt and dy/dt

[leaden lintel]

if dx/dt -> infinity or -infinity, can we make any conclusions about the original x(t)?

as in, can we conclude that x(t) exists or not

[cedar kiln]

@leaden lintel Has your question been resolved?

[dire geode]

What does parametric have anything to do with the question

[flint plinth]

how can you even define dx/dt if x(t) does not exist

[dire geode]

Also a good point

[cedar kiln]

@leaden lintel Has your question been resolved?

[leaden lintel]

essentially, if dx/dt at a certain point tends towards an infinity, does that mean we can make conclusions about the existence of x(t) at that point

[leaden lintel]

i think the original q had a portion abt calculating dy/dx, but i didn't include that bit here

[dire geode]

Can you think of a function x(t) that exists at a point t=a when the derivative is infinite at t=a

[leaden lintel]

i can't to be honest

but that could be because im not expanding my scope in terms of thinking enough; would there be any rigorous proofs going with an idea of nonexistence when the derivative tends towards infinity at x=a

[dire geode]

Rigorous would involve the definition of x'(a) using the limit

lim t goes to a ...

For simplicity take a = 0

[leaden lintel]

like starting with this

[dire geode]

Yes

But the right side has all the wrong variables

[cedar kiln]

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[dry dirge]

i still can not get this :

[dry dirge]

and then:

oh no no

in Q it is not true

but Q is subset of R

what type of theorem is that ?

[cedar kiln]

@dry dirge Has your question been resolved?

[dire geode]

What answer are you looking for

Theorems don't have classifications

Except maybe basic ones like existence and uniqueness

[cedar kiln]

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[crimson sedge]

anyoonneee?

<@&286206848099549185>

[royal loom]

!15mins

[cedar kiln]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[crimson sedge]

lets start with angle CAR

since we know that this is a square, what is true about every angle in a square?

yeaa

How many degrees is each of the 4 corner angles in the square?

90

oh wait

45

90

oh sorry sorry

dw

for future reference, squares and rectangles will have 90 degree angles

so CAR is 90 degrees

yess sirr!

does that make sense

yess

cool

I don't know how to solve the givenn

i’m assuming you get 2 as well

i’ll go on to 3 and 4

So what makes squares and rhombuses unique from other parallelograms is that their 4 sides are all equal length

every corners are 90° Mhmm

it gives us AE, CR, CA and ER’s lengths

can you see that AE and CR are equal in length?

yess

so, since AE = 7x + 13
and
CR = 3x + 21

yeaa?

we can set them equal to each other and find x

$7x + 13 = 3x + 21$

[wraith dagger]

pulse

[crimson sedge]

ohh what is that

since AE and CR are equal in length, you can set the two equal to each other to find x

and from here you would solve for x with algebra

WHAT

ALGEBRAA??

no worries

so

yesyes

I BRB

20 MINS

I'm so sorry 😭😭😭😭

no worries

heyy. an u accept

can*

just dm me and i’ll reply lol

I'll unfriend u afterr

i might be asleep tho

ohh okokk

[crimson sedge]

algebra is simply rearranging the equation by isolating the variables so we can find x

in other words

we start with this:

$7x + 13 = 3x + 21$

[wraith dagger]

pulse

[crimson sedge]

My goal here will be to make it so that the left side has only variables and the right side has only numbers. We can start by removing the +13 on the left side by subtracting 13. However, every change made to one side must be made to the other, so I will also subtract 13 from the right side:
\vspace{0.5cm}

$7x + 13 = 3x + 21$

\hspace{0.7cm} -13 \hspace{1cm} -13

$7x = 3x + 8$

\vspace{0.5cm}
Next, we need to move the 3x to the left side of the equation, which we can do by subtracting 3x from both sides.

\vspace{0.5cm}

$7x = 3x + 8$

-3x \hspace{0.5cm} -3x

$4x = 8$

Now, we have that 4x = 8. Let’s solve for x by dividing both sides by 4:
\vspace{0.5cm}

$4x = 8$
$÷4 \hspace{0.3cm} ÷4$
$x = 4$

[golden thistle]

@crimson sedge take the values associated with x on one side and other values on the other side you`ll know how to find x

[wraith dagger]

pulse

[crimson sedge]

My goal here will be to make it so that the left side has only variables and the right side has only numbers. We can start by removing the +13 on the left side by subtracting 13. However, every change made to one side must be made to the other, so I will also subtract 13 from the right side:
\vspace{0.5cm}

$7x + 13 = 3x + 21$

\hspace{0.7cm} -13 \hspace{1cm} -13

$7x = 3x + 8$

\vspace{0.5cm}
Next, we need to move the 3x to the left side of the equation, which we can do by subtracting 3x from both sides.

\vspace{0.5cm}

$7x = 3x + 8$

-3x \hspace{0.5cm} -3x

$4x = 8$

\vspace{0.5cm}

Now, we have that 4x = 8. Let’s solve for x by dividing both sides by 4:
\vspace{0.5cm}

$4x = 8$

÷4 \hspace{0.12cm} ÷4

$x = 4$

[jaunty mural]

this aint your channel is it?

[wraith dagger]

pulse

[jaunty mural]

or is this help?

[crimson sedge]

I am teaching algebra 💀

[jaunty mural]

bruh

what

i mean go for it if you want, but that really isnt what this server/channels r for

[crimson sedge]

the person who needed help is afk for 20 mins and does not know algebra

[jaunty mural]

usually better to direct to resource

[jaunty mural]

then theyre likely not going to see this... gl anwyays

[crimson sedge]

ty

i feel like this latex image could be a good example for many people who dont know algebra though

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

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• Show your work, and if possible, explain where you are stuck.
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• Be polite and have a nice day!

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[wind violet]

how can I use this richardson extrapolation formula to derive a better euler method?

[wind violet]

@lusty birch

oops

<@&286206848099549185>

[cedar kiln]

@wind violet Has your question been resolved?

[cedar kiln]

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[wanton granite]

Hey im trying to find a graph for some degree of Calculus in our chapter about Models, specifically when it comes to anything relevant to how to make a customized graph so that i can properly show how the income/cost function works in combination with eachother thus creating the equilibrium point, prefrebally trying to make a graph with x^2 so that it becomes a graph starting from Origin to wherever it may be, generally i'm trying to get help on how to write a specific graph that suits my perfectionist habit because ive been struggling at this task for maybe 2 or 3 weeks, any help and explanation would be greatly appreciated especially if there is tips on how to get a specifically customised graph (apologies for the typos i didnt sleep that well)

[wanton granite]

ive so far just been like brain sstorming on things so like so far all i have is this :
Brainstorming:
• Use one of the last tasks most relevant to what we want to find out to use as an example. This may enable us to understand the task properly.
•
• Do a task from the book, then do more and more of what is on target throughout the task. Possibly: 3.22 or 3.23

idk its a bit hard im just trying to to make a graph that isnt a parabola but is similar to a second degree graph, atm i dont have my book with me but am able to use geogebra and am using one note for my notes

• Anything that applies to the following
||
• Functional relationship between the graphs representing cost, income and tangent to the graph
• Should write what the y and x axis are worth with text in the graph
• Also write down things like what the vectors mean in this set and what the equilibrium means
''

thesea re just general thoughts from what i have as far as i remmeber, i will be home around 4pm (GMT+1) so if ye need an example from my book on what im working on let me know so im prepared ^^

[cedar kiln]

@wanton granite Has your question been resolved?

[wanton granite]

<@&286206848099549185> any help?

no help yet :c

[wanton granite]

<@&286206848099549185> anyone?

[neon ridge]

What's your question?

[wanton granite]

oh

my question would be how do i make a customized graph

prefrebally osmething that can allow me to make a perfect example

of uhh

idk the word lemme google translate

equillibrium, deficit, and profit

and i also somewhat need help to understand it so i can properly explain it xD

[wanton granite]

any idea?

[neon ridge]

What language do you speak natively?

[cedar kiln]

@wanton granite Has your question been resolved?

[wanton granite]

Norwegian

and my mother tongue is English

sorry for the late reply im in chem xD

[cedar kiln]

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[stray jasper]

why cant i do \frac{1}{2n}

[stray jasper]

oh

wait try again: why cant i do sum of 1/2n

its undefined

[tropic oxide]

wdym by "do"?

[stray jasper]

OH IM SUPID

i had the bottom as 0 so it does 1/0

[tropic oxide]

are you trying to calculate the sum of 1/(2n) for n from 1 to infinity?

[stray jasper]

i need to set it to 1

[tropic oxide]

ah, so it's a division by zero error.

[stray jasper]

ye

i forgot

ye it looks better now

so how do i calculate this

i need to find x

guess it should be like this

[cedar kiln]

@stray jasper Has your question been resolved?

[stray jasper]

what

x!?

what would that look like

[cedar kiln]

@stray jasper Has your question been resolved?

[cedar kiln]

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[cedar kiln]

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[stoic cove]

Not sure what to do

[crimson sedge]

what do the red x's mean?

[stoic cove]

They just mean a variable

[crimson sedge]

ah ok

so $28x^3+126x^2-24x^2-40x=68x$

[wraith dagger]

Toby

[crimson sedge]

note that in your last step, you can take a common factor of x out

[stoic cove]

Sorry, let me show the whole picture

[crimson sedge]

looks fine

where are you stuck/confused?

[stoic cove]

Not sure, the teacher just mark this wrong but he didn’t tell me anything

[crimson sedge]

,w 28x^3+126x^2-24x^2-40x=68x

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Toby#2275

[crimson sedge]

sign error

[stoic cove]

Ahhh, ok

I see it now

[cedar kiln]

@stoic cove Has your question been resolved?

[cedar kiln]

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[cedar kiln]

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[fallow sedge]

can anyone help me? idk how to do this question

[fallow sedge]

im not sure what equation to use

[crimson sedge]

1.1x=220

x= the original length

just solve for x

[fallow sedge]

damn

i tried to think about what the equation would be but i ended up with nothing

my teacher taught me the very very minimum knowledge to do this question 😭

[crimson sedge]

Yea for these types of questions you're basically just doing the multiplier and then x and then it equals the length they tell you in the problem

since its increasing by 10% thats 1.1

because 1 would be the original value

and if it asked for like 25% decreasing then it would be 0.75

[fallow sedge]

ohh ok i get what you mean

[crimson sedge]

So if its like for example saying it increased 40%

then you would do 1.4x

[fallow sedge]

so like for example this question, i do 0.75x=72 because the questions states that Mary spent 25%

and it would be 96

[crimson sedge]

Yeah thats right

Good job

[fallow sedge]

thanks

and tysm for explaining to me

🙂

[crimson sedge]

Np

[fallow sedge]

.close

[cedar kiln]

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[hard parrot]

Write an equation in slope-intercept form: slope is undefined and (-3,5) is on the line.

[runic garnet]

What type of line has an undefined slope

[hard parrot]

Vertical

Which if im not wrong it means its a 0

Idk

[runic garnet]

Yes it’s a vertical line, but wdym by “means it’s a 0”?

[hard parrot]

Actually no im tripping

i just know its vertical

Idk how to solve it though

[runic garnet]

So we have a vertical line that passes thru (-3,5)

Try drawing to understand it

[crimson sedge]

slope = 0 is defined, but horizontal

[runic garnet]

Perhaps that may help

[hard parrot]

Ohhh

[hard parrot]

Okkk

So x intercept would be -3

[runic garnet]

Yes

[hard parrot]

Wab y intercpet

(0,5)?

[runic garnet]

Try graphing it

U will see

[hard parrot]

Okkk

I dont get it 🧍

[cedar kiln]

@hard parrot Has your question been resolved?

[hard parrot]

No

[ornate hearth]

So you know its a vertical line

this means every x coordinate is the same on the line

[cedar kiln]

@hard parrot Has your question been resolved?

[cedar kiln]

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[silver sphinx]

i need a bit help

[silver sphinx]

Differentiate w.r.t. x

[lusty grotto]

You must use the chain rule

What have you tried

[silver sphinx]

i did y= 2sin 3x

[lusty grotto]

this is (sin3x)²

[silver sphinx]

oh okay

so

[lusty grotto]

Okay that multiplied by

What

[silver sphinx]

nvm

multiplied by what

can i just differ it

[lusty grotto]

What you wrote is part of the answer

[silver sphinx]

humm

[lusty grotto]

When you have a function of a function, it's derivative is the derivative of the outer function evaluated on the inner function, multiplied by the derivative of the inner one

In ur case, you got sin²3x=(sin3x)², so your outer function is the squaring function

And inner function is sin3x

[silver sphinx]

oh okay

[lusty grotto]

So you differentiate the outer function and evaluate it on the inner function to get 2(sin3x)

But now you must multiply this by the derivative of the inner function as well

[silver sphinx]

wdym

like how?

[lusty grotto]

What is the derivative of sin3x