#help-13

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long arrow
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,w factor (4x^4-25x^3+16x^2-9)

weak python
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oh

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oh

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ty

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:)

long arrow
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finding it witout Wolfram

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takes some time

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but it's possible obv

weak python
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yeah im master the ^2

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ty

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have a great day

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cedar kilnBOT
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zenith warren
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I need help with some BODMAS or PEDMAS for some people
202 + 4 × 9 - 8 - 16 + 9 - 4 =?
I'm really confused, could someone explain how to get the final answer?
BODMAS I understand but I got

202 + 4 × 9 - 8 - 16 + 9 - 4
=202 + 36 - 8 - 16 + 9 - 4
202 + 36 - 8 - 15 - 4
=238 - 8 - 15 - 4
=230 -15 - 4
= 215 - 4
= 21

dusk finch
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The problem was in this step:
=202 + 36 - 8 - 16 + 9 - 4
=202 + 36 - 8 - 15 - 4

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You combined -16+9 to -15

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which is incorrect

zenith warren
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oh? so it takes a away the minus sign?

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dont i leave the sign since it was infront if the 16

dusk finch
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Can you work with negative numbers?

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If not start doing it from left to right

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so do 202+36 then -8 then -16 then +9 then -4

zenith warren
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i can work with negative but doesnt if i do it that way wont it not use bodmas?

dusk finch
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Subtraction is same level as addition

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it doesnt matter what you do first

tropic oxide
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it's not P>E>M>D>A>S, it's P>E>(M=D)>(A=S)

zenith warren
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oh sorry i havent learnt that part of bodmas then mb

tropic oxide
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it is most likely a consequence of it being taught badly rather than you not having learned it properly.

zenith warren
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It might be that im in grade 8 so thats probably it

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steel flare
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can anyone help me in understanding preturbation here in this article, (in the section Backpropagation through a weighted sum) how this equation came, I have given the article as well as the link below

steel flare
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ds[0]=w[0]⋅dz
https://atcold.github.io/pytorch-Deep-Learning/en/week02/02-1/
cedar kilnBOT
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@steel flare Has your question been resolved?

steel flare
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No

cedar kilnBOT
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@steel flare Has your question been resolved?

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@steel flare Has your question been resolved?

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flat haven
cedar kilnBOT
flat haven
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i cant use u v integration

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the question is,

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integrate this using reverse chain rule

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and ive been staring at this for quite a while now

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the answer is tan^3(x)/3 +c

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but like

inland roost
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what is uv integration?

flat haven
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i meant

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u substitution

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mb

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eitherway

inland roost
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oh i see

flat haven
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WAIT

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NVM I GOT IT

inland roost
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try with f(x)=tanx

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lol

flat haven
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f(x) is tanx not tan^x and n is 2

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yes

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thanks

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fierce mason
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The Commutative property doesn't apply to subtraction, but 6 - 3 = -3 + 6

copper crest
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6-3 ≠3-6

copper crest
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This what they meant

gleaming cloud
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Of 6 and -3

copper crest
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Or maybe -3--6≠-6--3

cosmic steppe
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You had to change the operation from - to +

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Commutative's whole purpose is to preserve the operation

fierce mason
copper crest
fierce mason
cosmic steppe
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Well the property austerely states that:

a + b = b + a

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Only for addition (and multiplication) as far as I'm concerned with basic operations

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Because:

a - b = -(b-a)

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But that isn't commutative

fierce mason
cosmic steppe
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Commutative requires no other operation

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a-b = -(b-a) introduces multiplication

fierce mason
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Basically I mean a + (-b) = - b + a

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Because subtraction is based on addition it works?

cosmic steppe
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Well a and b can be any real number

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So like it works

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With manipulation

fierce mason
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I know it's sort of a manipulation, it's indeed not what it basically wants to explain

cosmic steppe
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well here

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2 - 3

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We can manipulate that so a = 2 and b = -3

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And both 2 and -3 are real numbers so we can easily apply communicative

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You're arguing that a-b can be communicative because a + -b, but then you're introducing the -b which complicates things

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You can think of that as -1 • b

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A nonunit multiplier

fierce mason
fierce mason
cosmic steppe
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And it fails to persevere the operation

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What you COULD say though

fierce mason
fierce mason
cosmic steppe
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Is that if $(a,b) \in \bR$, then $a+b = b+a$ and you can go from subtraction to addition since it satisfies that condition

wraith daggerBOT
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Umbraleviathan

fierce mason
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That's the question, yeah

cosmic steppe
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Well then it's taken care of with the statement:

$$(a, b) \in \bR$$

wraith daggerBOT
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Umbraleviathan

fierce mason
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Thanks for your help, I'll will do some more reasearch, I'm open to find some completly different answer 🙂

cosmic steppe
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You don't need to do a + -b = -b + a with that condition

fierce mason
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I'll be back later

cosmic steppe
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So yes

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But it works for all numbers in R

cedar kilnBOT
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@fierce mason Has your question been resolved?

cedar kilnBOT
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cunning bronze
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Can i get some help on my math homework? Its Interpret Linear Function Equations

cunning bronze
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whats this

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?

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oh

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my bad

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can someone help me understand how to do this homework please?

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:/

cunning bronze
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do i add them together?

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or?~

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i was sick so i had to miss some classes this week and the power points the teacher gave me arent really making sense tbh

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actually.. give me a minute i got an idea-

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sly canopy
cedar kilnBOT
runic garnet
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Show ur work

sly canopy
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i tried simplying by (x2+6x+h- x2 + 6x)h

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i got rid of the x`"

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x^2

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then 6x+6x = 12x

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and u cant get rid of the h right?

runic garnet
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It’s not easy to understand when typed liked that, could u send a picture or use latex

sly canopy
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okay

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ill send picture

runic garnet
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No that’s not how u do it

sly canopy
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okay

runic garnet
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Lemme give u an example

sly canopy
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how would I do it?

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okay

runic garnet
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Without simplifying anything, what would f(5) be equal to

sly canopy
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5^2 + 6(5)

runic garnet
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Perfect

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How about f(20)

sly canopy
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20^2+6(20)

runic garnet
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Good, now

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How about f(s)

sly canopy
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s^2+6(s)

runic garnet
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Nice

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How about f(s+2)

sly canopy
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(s+2)^2+6(s+2)

runic garnet
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Yes!!!!

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How about f(x+h)

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Don’t let the x+h confuse u, it’s just like everything else

sly canopy
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ooh

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i think i get it

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OOHH

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okaz

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okay

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so it would be

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(x+h)^2 + 6(x+h)

runic garnet
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Xd

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Ok

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So now we have f(x+h)

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Now trying setting up the difference quotient with that in mind

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Also when it’s -f(x) in the numerator, keep parentheses around the f(x)

sly canopy
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okok

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ill try

runic garnet
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Close

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But not quite

runic garnet
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Just plug that it in there without simplifying anything and we can take it from there together

sly canopy
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ohh okok

runic garnet
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Good

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Now let’s start simplifying step by step

wraith daggerBOT
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Stephen

sly canopy
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expand (x+h)(x+h)

runic garnet
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Yes

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Try that and lmk what u get

sly canopy
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x^2 + hx + hx + h^2

runic garnet
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Good

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And simplify that

sly canopy
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2hx

runic garnet
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Good so now let me write it out

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Now we have

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$\frac{x^2 + 2hx + h^2 + 6x+6h -x^2 - 6x}{h}$ do u agree?

sly canopy
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we expand the 6(x+h) to 6x+6h?

runic garnet
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Sure

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So now we have

sly canopy
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yeah

runic garnet
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Now how do we simplify -(x^2 + 6x)

sly canopy
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-x^2 -6x

runic garnet
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Good

wraith daggerBOT
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Stephen

runic garnet
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Now, simplify the entire numerator by combining like terms

sly canopy
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yes ill try that

runic garnet
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Good

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Try simplifying from there

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Hint, take out the common term from the numerator

sly canopy
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im not sure how

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will h^2 become h?

obtuse sable
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yes

sly canopy
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so the answer will be 2hx + h + 6h

obtuse sable
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No

sly canopy
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2hx + 7h

obtuse sable
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The entire numerator is divided by h

sly canopy
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ooh

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so we get rid of all the h?

obtuse sable
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Do you know how to common factor

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$ax+bx = x(a+b)$

wraith daggerBOT
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Whatever🎄

sly canopy
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that equation I know

runic garnet
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Ok so see how each term has an ‘h’ in the numerator

obtuse sable
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You dont have to do this step, but essentially each term is divided by that h

sly canopy
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so we divide all h and get 2x+h+6

runic garnet
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Yes

obtuse sable
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Yep

sly canopy
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ahh yes

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i understand now

runic garnet
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Cool

obtuse sable
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And thats simplified

sly canopy
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thank you so much!

runic garnet
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Np

sly canopy
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i think ill improve my functions more

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.close

cedar kilnBOT
#
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crimson sedge
cedar kilnBOT
crimson sedge
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Can you find what E is?

crimson sedge
obtuse sable
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Not exactly

crimson sedge
crimson sedge
obtuse sable
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Oh wait

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Thought it was the angle adjacent to that

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My bas

crimson sedge
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it is 75

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now that you know that the line AB would be making an angle of 180 totally

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Wait so y should be 50? @crimson sedge

crimson sedge
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So you have 20 + 75 + z = 180 with z being the third angle in that triangle

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recover what z is

crimson sedge
crimson sedge
crimson sedge
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wait a sec, im in class rn

cedar kilnBOT
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@crimson sedge Has your question been resolved?

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

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hushed yarrow
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How do I answer these

cedar kilnBOT
hushed yarrow
clear berry
hushed yarrow
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i have to solve all of them, I'm starting calc soon and this a practice quiz. I am literally super low level math

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So i have like no idea what im doing, not even joking

clear berry
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okay, let's go one-by-one

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Let's start by 2nd one, seems the easiest

hushed yarrow
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okay

clear berry
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Do you know what slope of a line means?

hushed yarrow
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y = mx +b?

clear berry
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no, that's the slope intercept form

hushed yarrow
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oh

clear berry
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The slope of the line kinda means the steepness of the line

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Like thing about how steep mountains are harder to climb

hushed yarrow
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yea

clear berry
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Or steep roads are harder to drive upwards

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That steepness can be measured using slope

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Mathematically, it is the amount the by which the value changes which input is changed linearly

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so, say you go from (x1, y1) to (x2, y2)

hushed yarrow
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okay

clear berry
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The slope is (y2 - y1)/(x2 - x1)

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Try using this formula to get the slope of the line mentioned in question 2

hushed yarrow
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ok just a sec

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i got 10/6

clear berry
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How did you get 10/6?

hushed yarrow
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13 - 3 / 8 - (-2)

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simplified is 5/3

clear berry
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13 - 3 is 10 and so is 8 - (-2) right?

hushed yarrow
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oh oops

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yes

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two neg equals pos

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so 8 plus 2

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10/10

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=1

clear berry
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yep

hushed yarrow
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answer is a

clear berry
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Next question 1 asks to rationalise fraction

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$\frac{8 \sqrt{x} + 27}{3x}$

wraith daggerBOT
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numbpy

clear berry
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notice here, in the numerator we have x inside a square root

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To remove this square root we multiply by it's conjugate, this is called rationalisation

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Do you understand what a square root is?

hushed yarrow
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yea its the symbol after the 8

clear berry
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As in, what does it do and its properties

hushed yarrow
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its like the square root of a number would equal what 2 numbers multiplied by eachother equal it

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so for example square root of 36 is 6

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because 6 times itself is 36

clear berry
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yes, in particular it is the inverse of a square

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Which means square of root and root of a square gives back what we started with

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$\sqrt{x^2} = x$ and ${(\sqrt{x})}^2 = x$

hushed yarrow
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makes sense yep

wraith daggerBOT
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numbpy

clear berry
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and do you know that (a + b)(a - b) = a^2 - b^2

hushed yarrow
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ive seen that formula before yea

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and it makes sense

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if you expand

clear berry
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Then everything is set

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You multiply but the conjuate of the numerator

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it's like the numerator just with 1 sign reverse

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For the numerator 8root(x) + 27, you multiply with 8root(x) - 27

hushed yarrow
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so then the answer would be a right?

clear berry
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answer would be a right meaning?

hushed yarrow
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its 8root(x) - 27

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which is the conjugate

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of the numerator

clear berry
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yes

hushed yarrow
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ah i see

clear berry
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generally we rationalise the denominator but it's the same principle with numerator

hushed yarrow
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for question 3 do i need to plug a value in as "t"?

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because it says 3 minutes, and t represents minutes

clear berry
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clearly not cause t is in minutes and s is in m so it would be wrong

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Let's do 4 and 5 first

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For 4, we need to find $\lim_{x \rightarrow 4} 5$

wraith daggerBOT
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numbpy

clear berry
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Notice something weird here?

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Oh btw, do you know limits?

hushed yarrow
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i havent learned limits

clear berry
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alright, so, limit is the concept of how a function behaves close the the limit point

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easiest example is 1/x

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for x=0, this is not defined

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cause that would be 1/0

hushed yarrow
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and 0 cant be a denomenator

clear berry
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BUT what would happen if we can go very very very close to zero but not exactly 0

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,w plot 1/x

upbeat lotus
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<@&268886789983436800>

clear berry
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thanks

upbeat lotus
#

Continue

clear berry
# wraith dagger

So, as you can see when you go close to 0, 1/x becomes larger and larger

hushed yarrow
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yea

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ive seen these graphs before

clear berry
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in the limit we say that it goes to infinity, written as

hushed yarrow
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arrow positive infinity?

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something like that, i remember slightly

clear berry
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$\lim_{x \rightarrow 0} \frac{1}{x} = \infty$

wraith daggerBOT
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numbpy

hushed yarrow
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oh nvm lol.. didnt look like that

clear berry
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alright, notice the question is a bit weird it doesn't have the variable

hushed yarrow
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what does the number below the "lim" represent

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is it like what you cant cross but are approaching in the graph

clear berry
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That's the variable, in general x->a symbol means that the variable x approaches a

hushed yarrow
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got it

clear berry
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alright, notice the question is a bit weird it doesn't have the variable

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Did you see it

hushed yarrow
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yea there is no x in the denom

clear berry
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$\lim_{x \rightarrow 4} 5$

wraith daggerBOT
#

numbpy

clear berry
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Take a guess as to what the answer would be

hushed yarrow
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uhh

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4?

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because its approaching 4

clear berry
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but notice there is no x on the right

upbeat lotus
# hushed yarrow what does the number below the "lim" represent

Like it's the same as plotting the x value to a function and getting the y value but sometimes there are not "well defined" y values for a function like as you have seen lim x to 0 (1/x) is not defined but still it is infinity cause it approaches the value of infinity but it is not exactly infinity also if I say that what's lim x to 5 (x²) gives us we will just plot 5 in x² and that will give 25 it's just like f(5)=x² where f(x)=x² but it's just a way to imagine it

hushed yarrow
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or 5 because thats the limit

upbeat lotus
wraith daggerBOT
upbeat lotus
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Now can you imagine it?

hushed yarrow
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uhhh not gonna lie im not sure

clear berry
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There is NO x in the right hand side

upbeat lotus
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Well when you have a constant given in a limit then you assume there is a variable and the power of that variable is 0 it will ultimately give you the constant

clear berry
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if instead it was $\lim_{x \to 4} 5x$

wraith daggerBOT
#

numbpy

clear berry
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Then it would give 5*4 = 20

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But there was NO x in the function (the right hand side)

hushed yarrow
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yea

clear berry
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Did you understand

hushed yarrow
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oh

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if there was an x next to the 5, then its 5 x 4

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because x is 4

clear berry
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yes, if instead it was $\lim_{x \to 4} 5x^2$

wraith daggerBOT
#

numbpy

hushed yarrow
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20 ^ 2 then no?

clear berry
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it would be 5 * 4^2

hushed yarrow
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oh wait

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5 x 16 then?

clear berry
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yes

hushed yarrow
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i gotcha

clear berry
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think about it in this way, the 5 part is CONSTANT

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it simply can't be changed, IT IS WHAT IT IS

hushed yarrow
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okay

clear berry
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should we move to question 5

hushed yarrow
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yea

clear berry
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Maybe try it on your own and think would be the answer

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It's simple enough just looks weird

upbeat lotus
#

In short
$\lim_{x \to c} (a×f(x))=a×\lim_{x\to c}(f(x))$where c and a are constant

wraith daggerBOT
hushed yarrow
#

okay ill try 5 on my own, can you help me with 3

clear berry
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3 is slightly more difficult

hushed yarrow
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for 5 im plugging in the 5 as x

clear berry
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you're given s(t) = 4t^2 and s is the distance is metres

upbeat lotus
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"Rate of moving"

hushed yarrow
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just got 5, its 4/40 which simplifies to 1/10

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damn that wasnt so bad

clear berry
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that looks correct

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anyway, what is asked in Q 3 is the rate of at which avalanche is moving

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basically velocity

upbeat lotus
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Oh velocity

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Find the derivative then

clear berry
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for that you need to find the derivative of s(t) wrt t

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yeah

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But I am guessing you're not familiar with it are you?

hushed yarrow
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no im not

ionic sorrel
clear berry
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well, the derivative of a function f at a is this thing -

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$f'(a) = \lim_{h \to 0} \frac{f(a + h) - f(a)}{h}$

wraith daggerBOT
#

numbpy

clear berry
#

There's a lot to unpack but first thing to notice is that this is literally the definition of slope

#

let y1 = f(x) and y2 = f(x+h), then

#

$f'(a) = \lim_{h \to 0} \frac{f(a + h) - f(a)}{h} = \lim_{h \to 0} \frac{y2 - y1}{(a + h) - h} = \lim_{h \to 0} \frac{y2 - y1}{x2- x1}$

wraith daggerBOT
#

numbpy

clear berry
#

The most important difference is that the difference between x1 and x2 approaches 0

#

Geometrically, this thing goes from a secant between 2 points to a tangent at a point

hushed yarrow
#

okay

clear berry
#

and this derivative gives the instantaneous slope of any given function

#

In practice you just need to remember some of the rules of the derivative

#

first is that the constant is always constant and can be taken out

#

$\frac{d}{dx} a f(x) = a \frac{d}{dx} f(x)$

wraith daggerBOT
#

numbpy

clear berry
#

second is that of the derivative of a power

#

$\frac{d}{dx} x^n = n x^{n - 1}$

wraith daggerBOT
#

numbpy

clear berry
#

The question essentially boils down to finding this derivative wrt to t

#

ie $\frac{d}{dt} 4t^2$

wraith daggerBOT
#

numbpy

clear berry
#

Use the above rules to find the answer

hushed yarrow
#

okokok

#

i got 24

#

4(2t) = 8(t) = 8(3)

#

=24

clear berry
#

yess

#

congratulations!

hushed yarrow
#

lets GOO

#

thankyouu

#

this is the whole other half of the quiz 🥲

clear berry
#

nah, I don't have any more energy. I have to do my own homework also

hushed yarrow
#

hahah no problem, you've already helped so much

#

i appreciate it

clear berry
#

lemme tag other helpers

#

<@&286206848099549185>

upbeat lotus
#

@hushed yarrow I could help you in this three questions

hushed yarrow
#

yea please

upbeat lotus
#

In which part you need help in

hushed yarrow
#

all 3 loll

upbeat lotus
#

Are you familiar with rationalisation

hushed yarrow
#

not until today

#

like i just learned an idea of it

#

but im no master

upbeat lotus
#

It's like
$√2/√3=(√2×√3)/(√3×√3)$

wraith daggerBOT
hushed yarrow
#

okay

upbeat lotus
#

Especially when we find square roots in it

#

Also sometimes we could find the exact value of the square root fraction

#

Are you familiar with complex numbers?

hushed yarrow
#

uhh no i dont think so

upbeat lotus
#

We can sometimes find the real part of complex numbers by using rationalization but not in all cases

upbeat lotus
#

In the second question I don't think so you would have a problem to graph

#

,w plot (x-6)/(2+x)

wraith daggerBOT
upbeat lotus
upbeat lotus
#

Are you talking about rationalisation

hushed yarrow
#

yea

#

question 1

upbeat lotus
#

You can watch this video for understanding

#

I have to sleep now sorry

#

,ti

wraith daggerBOT
#

The current time for 𝓐𝓡𝓝𝓐𝓑 𝓟𝓐𝓛 is 12:17 AM (IST) on Sat, 04/02/2023.

upbeat lotus
#

I have school tomorrow

#

🥲

hushed yarrow
#

its okay dont worry

#

thanks for trying to help

cedar kilnBOT
#

@hushed yarrow Has your question been resolved?

cedar kilnBOT
#

@hushed yarrow Has your question been resolved?

sonic thistle
hushed yarrow
#

lol

sonic thistle
#

i think you should open another help channel with your exact question

#

and only 1 question

cedar kilnBOT
#

@hushed yarrow Has your question been resolved?

cedar kilnBOT
#

@hushed yarrow Has your question been resolved?

hushed yarrow
#

.close

cedar kilnBOT
#
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ebon solstice
#

what’s the problem

obsidian coral
#

Wdym by this?

cedar kilnBOT
#
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faint stag
#

For this,

Can I make u= 9x + 5?

cedar kilnBOT
faint stag
#

Then Du/9 = dx?

#

Then simply power rule for (U)^(-7/3)

short blade
#

yes

#

dont forget the +C

cedar kilnBOT
#

@faint stag Has your question been resolved?

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whole portal
#

suppose that there are 4 boys and 2 girls sitting in a row

whole portal
#

how many possible combinations are there such that the girls are exactly one seat apart from each other?

#

case 1:
~(B)~(B)~(B)~(B)~
5 possible slots
5 entities existing (4 boys & [2 girls])
take 5C2 to find the number of ways to pick 2 slots out of 5, then permute the girls by taking 2!, then rearrange the boys by taking 4!

whole portal
muted bear
#

I think it would be easier if you start with _ _ _ _ _ _ and placing the girls first

whole portal
#

there are many ways to placing the girls though

muted bear
#

You sure?

whole portal
#

never mind not a lot I guess

#

_ _ _ _ _ _

G _ G _ _ _ _

_ G _ G _ _

_ _ G _ G _

_ _ _ G _ G

muted bear
#

The first one has an extra seat

#

But yeah only 4 cases, all relatively the same, so the math works in our favor

#

How many ways can the girls be arranged in the seats?

#

Just pick one case for now

whole portal
#

okay

#

I choose thee 3rd case

#

okay so hmm

#

there are 4 seats left

#

and 4 guys left

#

so erm

#

4C4?

#

then I multiply it by 4?

whole portal
whole portal
#

and 2! to permutate the girls?

muted bear
#

Yup

whole portal
# muted bear Yup

and for such that the girls are exactly two seat apart from each other

so either
G~-G~-
or ~-G~-G
or ~G~~G~
so, 4C4 * 3 * 4! * 2! ?

#

oops the lines

muted bear
#

sounds right

whole portal
#

alright tysm!

#

imma try q1v now

whole portal
gilded elm
#

draw a diagram

#

let b1 and b2 be fixed

whole portal
cedar kilnBOT
#

@whole portal Has your question been resolved?

cedar kilnBOT
#

@whole portal Has your question been resolved?

cedar kilnBOT
#

@whole portal Has your question been resolved?

wheat pagoda
#

and you do the permutation of the boys too

#

4!

cedar kilnBOT
#

@whole portal Has your question been resolved?

cedar kilnBOT
#
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whole portal
#

oh okay thx

cedar kilnBOT
#
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split briar
#

Can someone explain this symbol in cs? There's litererally no explaination for it and is just used

split briar
#

and the definition they use in the text makes it look like it does nothing

fair geyser
#

that's the intention yes

#

for any x, ◇(x) keeps it x

#

unless () means something

#

so it's (x) instead

split briar
#

No clue what you mean man

#

so it does nothing?

fair geyser
#

if the parentheses around (x) mean something it does the wrapping of x in ()

#

i can't see if they talked about the ()

#

or it does nothing

#

i can't decide which is more likely

#

50/50

split briar
#

welp

#

thanks man

#

.close

cedar kilnBOT
#
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hollow sleet
#

A cup of ice cream was sold at ₹26 find the original cost of the ice cream if the cost includes 15% GST and ₹3 other expenses.

hollow sleet
#

anyone

earnest pollen
#

let X be the cost of the ice cream try and write this as an equation and solve for X

earnest pollen
#

what did you get

hollow sleet
#

<@&286206848099549185>

hollow sleet
half forge
cedar kilnBOT
# hollow sleet <@&286206848099549185>

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

nimble veldt
hollow sleet
#

p

#

15% of x = 26

#

x = 26*100/15

#

I don't understand pls gimme solution

nimble veldt
#

where are the "3 other expanses"?

hollow sleet
cedar kilnBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

jaunty mural
#

We do not give answers.

nimble veldt
hollow sleet
jaunty mural
#

???

#

Doesn't matter

#

Helpers are here to help you learn

hollow sleet
jaunty mural
#

Dishing out answers does not achieve this.

#

Demanding solutions is rude.

hollow sleet
#

is the answer 20?

weak python
nimble veldt
hollow sleet
weak python
#

so

#

let the original price be x

hollow sleet
#

yes i know it

nimble veldt
weak python
#

and what make the price up to 26?

#

the orignals price

#

and

#

the 15% of the original

#

and

#

the $3

#

so try to sum it up

hollow sleet
weak python
#

make an equation

#

OK

hollow sleet
weak python
#

I DONT HAVE THET EMOJI

weak python
hollow sleet
jaunty mural
#

The equation you wrote doesn't include the $3 mentioned

hollow sleet
#

19.1

weak python
#

( original price ) + ( 15% of original price ) + ( expense ) = 26

#

try to replace those word with

#

number

hollow sleet
weak python
#

what is this

hollow sleet
#

but the answer given by teacher is 20

hollow sleet
weak python
#

i think so

#

what is this tho

#

15% of 26 ?

hollow sleet
#

so how to make it right

weak python
hollow sleet
#

@jaunty murali have the equation now help me rude

hollow sleet
weak python
#

so what does the tax affect on?

hollow sleet
#

Goods service tax

hollow sleet
weak python
#

exactly

#

so it is not 15% of 26

hollow sleet
#

and 3 other expenses

weak python
#

but

#

15% of ???

hollow sleet
weak python
#

correct

hollow sleet
#

but it say 1/80 now

weak python
#

no

weak python
#

replace 26 with x

#

and solve the equation

hollow sleet
#

he is sitting next to me

weak python
#

💀 bro just finish your work

hollow sleet
weak python
#

wtf

#

no

hollow sleet
#

u can off ur camera

#

i'll on mine

weak python
#

JUST FINISH YOUR WORK

odd snow
#

what is the question

hollow sleet
hollow sleet
# odd snow what is the question

A cup of ice cream was sold at ₹26 find the original cost of the ice cream if the cost includes 15% GST and ₹3 other expenses.

#

Answer : ₹20

odd snow
#

okay

#

then, the price with only %15 taxes will be 23 right?

#

26-3

hollow sleet
odd snow
#

so we can think like this:
there is a cup of ice cream that costs x originally

#

without anything

hollow sleet
#

yeah

odd snow
#

if you add %15 taxes, x*15/100 right?

#

that is the tax

#

x*15/100

#

15/100=%15

#

you know this i assume

hollow sleet
#

hm

odd snow
#

tax is calculated from its original price

#

we found the tax now

#

x*15/100

hollow sleet
#

already know it

hollow sleet
odd snow
#

okay any problem finding the tax?

hollow sleet
odd snow
#

now we add the tax to the original price

hollow sleet
#

calculation problem

odd snow
hollow sleet
odd snow
#

okay

#

can you understand what im saying

#

we found the tax

#

x*15/100

#

any problem here?

#

did you get it

#

x is the original price

hollow sleet
#

fine

odd snow
#

everything good by here?,

hollow sleet
#

yes thanks

odd snow
#

okay then, we add the tax into the price now

hollow sleet
#

.close

cedar kilnBOT
#
Channel closed

Closed by @hollow sleet

Use .reopen if this was a mistake.

odd snow
#

x+x*15/100

#

bro💀

hollow sleet
#

what

#

my friend also solved it

#

right now

odd snow
#

can you do the rest?

#

okay

hollow sleet
cedar kilnBOT
#
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jagged charm
#

How to Prove that if $p$ and $p^2+8$ are prime, then so is $p^3+8p+2$?

wraith daggerBOT
#

Pierre de Fermat

jagged charm
#

I think we use Wilson's theorem

#

(p-1)!\equiv{-1}[p]

#

But I can't conclude

crimson delta
#

mod 3

cedar kilnBOT
#

@jagged charm Has your question been resolved?

jagged charm
crimson delta
#

look at p^2+8 mod 3

jagged charm
#

p^2\equiv{-8}(mod 3)

#

So it's congruent to -1

#

Okay it's prime

crimson delta
#

if p=0,1,2 mod 3, what is p^2+8 mod 3

jagged charm
#

If p=0 than p²+8\equiv{-1}(mod 3)

#

Cause 8=3×3-1

#

If p=1
We've 9\equiv{0}(mod 3)

#

If p=2
We've 12\equiv{0}(mod 3)

#

Is that correct?

crimson delta
#

yes

#

and now think about what 0 mod 3 means

cedar kilnBOT
#

@jagged charm Has your question been resolved?

jagged charm
#

Okay thanks

#

.close

cedar kilnBOT
#
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wild belfry
#

I know that e) isnt valid but they want me to find the appropriate assignment of truth values to make it valid

#

Is there any way to do this other than trial and error? Cause theres 4 truth values so this would take up a lot of time in an exam just testing them all

#

like I would need to test every combination of positive and negative for each truth value...

gilded elm
#

get rid of everything that doesnt involve p and s

#

oh theres nothing to get rid of

#

whoops

wild belfry
#

haha

#

why would that have helped?

#

like I dont really understand the method

cedar kilnBOT
#

@wild belfry Has your question been resolved?

wild belfry
#

.close

cedar kilnBOT
#
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abstract vapor
#

what do i do if i calculated slope and i got m=12.5/0?

crimson sedge
#

that means the slope is vertical at that point

#

which is not a function

crimson delta
#

or you made a mistake

#

show your work

abstract vapor
#

sure

half forge
abstract vapor
#

, rotate

wraith daggerBOT
abstract vapor
#

second section

#

i was asked to find slope of BD

#

D middle of AC

half forge
#

there's no slope tho, is there?

abstract vapor
#

maybe my drawing is a little off

#

here is the original

crimson delta
#

checks out

#

vertical line

#

well assuming you have all the coordinates of the points correctly

abstract vapor
#

yea

#

i got it

#

it would like this

half forge
#

yeah

abstract vapor
#

okay

#

thanks

#

.close

cedar kilnBOT
#
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cedar kilnBOT
#
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crimson sedge
cedar kilnBOT
latent bloom
#

Okay

#

?

long arrow
#

solve each one, then take an intersection

crimson sedge
#

Done it

latent bloom
#

What is the issue with the question?

crimson sedge
#

I'm getting a different answer=I'm doing something wrong and I can't tell what it is

long arrow
#

don't mind showing work?

crimson sedge
#

Here

long arrow
#

well, x > -1/5 for the 1st one is ok

crimson sedge
#

Aight

long arrow
#

thing is

crimson sedge
#

?

#

second 1 it should factorize to (x-1)(x-4)

long arrow
#

you factored trinomial incorrectly

crimson sedge
#

Really, I'm going to do it agaim then

#

I see

#

Got it

#

Thanks guys

#

.close

cedar kilnBOT
#
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crimson sedge
cedar kilnBOT
crimson sedge
#

I'm in a pinch here, i can not figure this out

runic garnet
#

Wat u tryna do

crimson sedge
#

Get the ?

runic garnet
#

O I thought that was a 2

#

Hmm

crimson sedge
runic garnet
#

Is that all that was given?

#

Could u send a pic of the original problem

crimson sedge
#

Ok

#

I need to get the MK

crimson sedge
#

Oh yeah and the square sides are 4

runic garnet
#

How does the image above relate to ur first image?

crimson sedge
#

Well it's the same thing it's a trapezoid

#

Right angle trapeziod

runic garnet
#

Oh I see it now

#

Do u know about angle bisectors of squares

#

ABCD is a square, so the lines that connect opposite corners bisect the angles as well

#

meaning the angle of 90 degrees is split into two 45 degree angles

crimson sedge
#

Ah well

#

That makes a difference

#

Ok thx i think i can do it now

runic garnet
#

sure np

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

cedar kilnBOT
#
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woven zephyr
#

i have this question for homework and am stuck at the first part of b. how would you approximate required work with a riemann sum here?

mighty drift
#

basically from 30 to 60

#

instead of 0 to 60

woven zephyr
#

the part that i'm having a problem with is the lim(n->inf) part. i understand why the top is .3x_i*dx because of the .3 lb/ft, but i don't understand how i'm supposed to get that part of the question for half the rope to the top

mighty drift
#

you're pulling half the length

#

the notation xi is weird to me because they're defined nowhere

woven zephyr
#

it's visualized like this for a similar problem, x_i is a point within the change of x

mighty drift
#

I know

#

what formula

#

xi should depend on n (as well as delta_x), which makes this notation very bad imo

woven zephyr
#

well this is how it explained to get the lim(n->inf) part earlier, this was for a 200-lb cable that's 100 ft long

mighty drift
#

still doesn't define xi

woven zephyr
#

all it says is divide the cable into small parts with length delta_x and that x_i is a point in the ith such interval

mighty drift
#

so you never saw an actual definition of xi with a formula ?

woven zephyr
#

this is what's given, equation 2 is just W = Fd

mighty drift
#

so xi is simply the number that works

mighty drift
#

because it works

woven zephyr
#

i don't know what you mean

#

this is all the book has given me up to this point to solve this problem

mighty drift
#

if it was reusing the xi from the previous question, I'd say it's 0.3 * (30 + xi/2)

#

but since they didn't specify whether xi changes between questions because they never defined it, I can't know

#

and that's why you always define things in math rather than handwaving it. Otherwise you get crap questions like this

woven zephyr
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if it helps at all they want the integral you find from the limit in part b to be from 0 to 30

mighty drift
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oh right

#

but still

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I don't know what xi is

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so I can only guess what the expected answer is

mighty drift
cedar kilnBOT
#

@woven zephyr Has your question been resolved?

cedar kilnBOT
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#
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crimson sedge
#

.show

cedar kilnBOT
crimson sedge
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how do i get a graph of the curved sides exeact position

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or an angle of the curved sides exeact position

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on both

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<@&286206848099549185>

nimble veldt
#

can you explain a little bit more, what you need?

crimson sedge
#

well i want to draw the angle but in scale

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the curved side

#

and for that i for me to accuratly do that i'd need to know how it bends

nimble veldt
#

i am not sure, which angle you mean.

#

do you mean this?

crimson sedge
#

345

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sorry im not good at english

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i want to know its positon

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

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orchid jewel
#

A box contains 3 different formats of shaped elastics
circular.
The perimeters of each format are 12 cm, 20 cm and 25 cm. THE
weight of rubber bands are proportional to their perimeters.
In the box, the total weight of the rubber bands of each format is
27g. Each rubber band weighs less than 1g, but more than 0.3g.
How many 12 cm rubber bands are there in this box knowing that there are more than 100 rubber bands in total? How can I find the weight by the peremeter?

cedar kilnBOT
#

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crimson sedge
#

Need help

cedar kilnBOT
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true spindle
cedar kilnBOT
true spindle
#

a: there are two distinct students who have asked all faculty members a question

#

is that right?

wicked brook
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shouldnt it have something to do with: if one has asked a staff member, so has the other?

true spindle
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wait

crimson sedge
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yeah nvm

true spindle
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the biconditional is kinda confusing me

wicked brook
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how was the biconditional defined for you

true spindle
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so its: there are two distinct students who if one has asked asked a faculty member a question then the other has also

wicked brook
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i think that is the correct answer

#

Cause its like

Staff member implies (A(x,y) if and only if A(y,z))

true spindle
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yes yes

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this feels right

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aight i think i have the second one translated to logic but i need to figure how to use the latex boy

#

bot*

#

,help

wraith daggerBOT
#

A brief description and guide on how to use me was sent to your DMs!
Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!

wicked brook
#

i this has all the operators youll need

true spindle
#

,list

wraith daggerBOT
#
My commands!

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true spindle
#

yah fuck this i havent learned the quantifiers yet ima use paint

crimson sedge
#

yeah i got same

true spindle
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aight thanks

crimson sedge
#

$\forall z \exists x \exists y :(S(x) \land S(y) \land x \neq y \land (F(z) \implies (A(z, x) \land A(z, y))))$

true spindle
#

aight i gotta go eat but i will have more questions for yall in like 30

#

thanks again

#

.close

cedar kilnBOT
#
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wraith daggerBOT
#

Jester

wary estuary
#

Not really a "help" question, but I just realized I'm having trouble doing basic arithmetic with exponents in algebra, where can I improve this?

cedar kilnBOT
#

@wary estuary Has your question been resolved?

gilded elm
#

,tex \factoid original

wraith daggerBOT
cedar kilnBOT
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@wary estuary Has your question been resolved?

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After 15 minutes, feel free to ping <@&286206848099549185>.
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native shuttle
cedar kilnBOT
native shuttle
#

how can i approach this question

grand forge
livid hound
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use the given info and set up a system of equations

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the first step would be to first find f'(x)

native shuttle
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i have that

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and i plugged in the values for f'(-1) and equated the derivative to 12

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and got a+b =4

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maybe i can try a = 4-b

livid hound
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and got a+b =4
how are you getting that

native shuttle
livid hound
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you didn't manipulate your equation properly

native shuttle
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yeah half of it is right

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one momment i think ik my mistake

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what part is wrong tho?