I don't know
#help-13
digital shell
lusty grotto
shud u make 4 bigger or smaller?
digital shell
g(4) = 2
lusty grotto
do u realize g is just a function that takes in a number as input, does something to that number, and gives it as input to f, and then outputs whatever f outputs at that number?
lusty grotto
do u realize that when u input 4 to g, it must output what f outputs at 1?
digital shell
how can I figure out the horizontal scaling 4factvor
digital shell
do u realize that when u input 4 to g, it must output what f outputs at 1?
yes
lusty grotto
so what must g do to the number 4, before inputting it into f, to get the same output that f outputs at 1
digital shell
I have no idea
digital shell
I don't know
lusty grotto
okay if u put 4 into g, and g made the number 4 bigger and then inputs it to f
lusty grotto
okay if u put 4 into g, and g made the number 4 bigger and then inputs it to f
what kinda number wud f output
digital shell
6
lusty grotto
okay if u put 4 into g, and g made the number 4 bigger and then inputs it to f
if u put 4 into g, and g made the number 4 smaller, and then input it to f, then what kinda number wud f output?
lusty grotto
if you put 4 into g you get 2
this is because g turns the number 4 into whatever number u need to input into f, to get 2 as output
is that clear?
digital shell
no I don't understand
digital shell
oh okay
well thank you for the help
<@&286206848099549185> could someone help me with this problem please
cedar kilnBOT
@digital shell Has your question been resolved?
nimble veldt
$f(x) = 4\sqrt[3]{x}-2$
wraith daggerBOT
ThM
nimble veldt
since g(x) should be horizontally scaled is has to look like:
$g(x) = 4\sqrt[3]{ax}-2$
wraith daggerBOT
ThM
nimble veldt
and we know f(1) = g(4).
digital shell
yeah
nimble veldt
you need to transform 4 -> 1 to get this last equation.
digital shell
you need to transform 4 -> 1 to get this last equation.
I don't follow
digital shell
yeah
nimble veldt
f(1) = 1, right?
digital shell
f(1) = 2
nimble veldt
$2 = 4\sqrt[3]{ax}-2$
wraith daggerBOT
ThM
wraith daggerBOT
ThM
nimble veldt
we have g(4), so it is:
$4 = 4\sqrt[3]{a4}$
wraith daggerBOT
ThM
digital shell
does that not change the vertical value?
nimble veldt
does that not change the vertical value?
which step do you mean?
digital shell
when you add 2 to the equation
nimble veldt
no. we have g(4) = f(1) = 2 which gives us
$2 = 4\sqrt[3]{4a}-2$
wraith daggerBOT
ThM
digital shell
I don't understand it
nimble veldt
which point?
digital shell
how to solve for a
nimble veldt
what value has a?
digital shell
I don't know
nimble veldt
so we try to calculate a.
nimble veldt
again asking. do you agree with this? we have g(4) = f(1) = 2 which gives us
$2 = 4\sqrt[3]{4a}-2$
wraith daggerBOT
ThM
nimble veldt
but couldn't you plug in x = 1 for f(1)
we did this, to calculate f(1) = 2.
digital shell
I didn't see that
digital shell
I don't see the correlation
nimble veldt
which correlation? who is talking about correlations?
nimble veldt
we know f(1) = 2, do we?
digital shell
yes
nimble veldt
we know g(4) = f(1) = 2, do we?
digital shell
yes
nimble veldt
we know g is horizontally scaled, do we?
digital shell
yes
nimble veldt
what does horizontally scaled mean?
digital shell
that the x value has been scaled by some factor
nimble veldt
$g(y) = 4\sqrt[3]{ay}-2$
wraith daggerBOT
ThM
nimble veldt
with the scale factor a, right?
digital shell
yes
nimble veldt
ok, g(4) = 2, right?
digital shell
right
nimble veldt
just slowly. write 4 instead of y in this equation.
digital shell
$g(4) = 4\sqrt[3]{4a}-2$
nimble veldt
we get $g(4) = 4\sqrt[3]{4a}-2$
digital shell
$2 = 4\sqrt[3]{4a}-2$
wraith daggerBOT
Norahc
nimble veldt
add 2 on both sides.
digital shell
$4 = 4\sqrt[3]{4a}$
wraith daggerBOT
Norahc
nimble veldt
divide both sides by 4.
digital shell
$1 = \sqrt[3]{4a}$
wraith daggerBOT
Norahc
nimble veldt
power both sides by 3.
digital shell
$1 = {4a}$
wraith daggerBOT
Norahc
nimble veldt
divide both sides by 4.
nimble veldt
you are asked for g. just plugin this a in the previous function equation.
nimble veldt
you need to transform 4 -> 1 to get this last equation.
you could have done this in a shorter way. since f(1) = g(4). which factor makes 1 from 4?
nimble veldt
exactly.
nimble veldt
ok, lets stop this. you have your g:
$g(y) = 4\sqrt[3]{\frac{y}{4}}-2$
wraith daggerBOT
ThM
digital shell
ok, lets stop this. you have your g:
$g(y) = 4\sqrt[3]{\frac{y}{4}}-2$
yes thank you
but is there a way to apply this method more generally?
for other problems like this
nimble veldt
but is there a way to apply this method more generally?
if you have a f and horizontally scaled g, write the function equation with such an a. and then you need 2 points (as we had here with 1 and 4) and then sovlve for a. This is an general method.
digital shell
if you have a f and horizontally scaled g, write the function equation with such...
so if I had the points f(2) = g(8). how could I apply it?
nimble veldt
if you mean f(2) = g(8): calculate f(2), then use this value for g(8) and write 8 instead of y in your function equation of g.
digital shell
if you mean f(2) = g(8): calculate f(2), then use this value for g(8) and write ...
alright, thank you very much for your help
have a great rest of your day
.close
lunar thunder
i need help on this equation
cedar kilnBOT
i need help on this equation
lunar thunder
lunar thunder
i know
cosmic steppe
Would you like a gold medal for your comedy
soft owl
cosmic steppe
How about a <@&268886789983436800> ping
hollow nebula
Yes
cosmic steppe
This is like the 5th collatz Shitpost I've seen this month
celest seal
.close
cedar kilnBOT
celest seal
please dont misuse help channels for a joke
cedar kilnBOT
Available help channel!
kindred hornet
can i get a hint for where to start?
cedar kilnBOT
can i get a hint for where to start?
kindred hornet
anyone?
cedar kilnBOT
@kindred hornet Has your question been resolved?
tropic oxide
@kindred hornet which direction is troubling you?
kindred hornet
<@996044212158083084> which direction is troubling you?
well i dont know how to exactly prove this
should i prove that a parrelelogram with 4 equal sides has perpendicular diagonals
even if i do that, where would i go from there
u there?
tropic oxide
sorry, was showering
you are proving an if-and-only-if statement
this means that you are to prove two implications
- if a parallelogram is a rhombus, then its diagonals intersect at right angles.
- if a parallelogram's diagonals intersect at right angles, then it is a rhombus.
what you described is (1)
you will still need to have (2) to go
tropic oxide
do you think i need a diagram for this proof
99% of geometric proofs require diagrams.
cedar kilnBOT
@kindred hornet Has your question been resolved?
kindred hornet
ah ok then
cedar kilnBOT
@kindred hornet Has your question been resolved?
umbral adder
can someone help me figure out how to set up this equation?
cedar kilnBOT
can someone help me figure out how to set up this equation?
@umbral adder Has your question been resolved?
flint plinth
can someone help me figure out how to set up this equation?
i would start by defining a reference point (such as the general store or the roadside eatery) that you're going to call "position 0"
and then write two equations describing the positions of the two people as a function of time
vagrant spindle
cedar kilnBOT
flint plinth
if f(x) has a domain of |x-7| <= 5, then f(x/3) has a domain of |x/3 - 7| <= 5
vagrant spindle
what is range tho
flint plinth
well the x/3 won't change the range - that's just scaling the x axis
so focus on the -1/2 and the +8
vagrant spindle
ok
hot kayak
how can I simplify
$\frac{x^{3}}{\sqrt[3]{x^2+1}}
cedar kilnBOT
how can I simplify
$\frac{x^{3}}{\sqrt[3]{x^2+1}}
cosmic steppe
how can I simplify
$$\frac{x^{3}}{\sqrt[3]{x^2+1}}$$
wraith daggerBOT
Umbraleviathan
hot kayak
I want to take the integral of the function and I think I need to use partial fractions since that's the chapter that the problem is in
$$\int{\frac{x^{3}}{\sqrt[3]{x^2+1}}}$$
hot kayak
$$\int{\frac{x^{3}}{\sqrt[3]{x^2+1}}dx}$$
wraith daggerBOT
What
cosmic steppe
Yeah I guess do a trig sub of some sort
stable osprey
the result looked weird
cosmic steppe
,w integrate x^3 / (x^2 + 1)^(1/3)
wraith daggerBOT
stable osprey
ew
cosmic steppe
Yeah it looks like a result of a trig sub
cosmic steppe
ew
Also can you DM me the Fiddy sticker imma steal it
Although symboblab did a u-sub
Doesn't specify what they subbed in
Oh actually
hot kayak
so $$\int{\frac{u^{2}-1}{2\sqrt[3]{u}}du}$$
wraith daggerBOT
What
hot kayak
,w integrate 1/(u^(1/3))
wraith daggerBOT
hot kayak
,w (u^2) * (u^(-1/3))
wraith daggerBOT
hot kayak
**What**
so after the u-sub I split what I replied to into 1/2 the integral of u^2 / u^(1/3) and 1/2 the integral of -1 / u^(1/3)
which turns into $$(\frac{3(x^2 + 1)^{11/6}}{16}) + \frac{3(x^2 + 1)^{2/3}}{4} + C$$
wraith daggerBOT
What
hot kayak
which isn't the right answer
$$\int{\frac{u^{2}-1}{2\sqrt[3]{u}}du} = (1/2)\int{\frac{u^{2}}{\sqrt[3]{u}}du} + (-1/2)\int{\frac{1}{\sqrt[3]{u}}dx}$$
wraith daggerBOT
What
hot kayak
is this true? I must be missing something because I have the two integrals on the right side of the equality correct
hot kayak
**What**
this is wrong
should be so $$\int{\frac{u^{2}/sqrt(u-1)-u}{2\sqrt[3]{u}}du}$$
wraith daggerBOT
What
hot kayak
.close
nova warren
How would I find these measurements with the info I have already written down?
warm bone
Have you used CAD software before?
But anyway, like all geometrical problems, using geometry
cedar kilnBOT
@nova warren Has your question been resolved?
cedar kilnBOT
@nova warren Has your question been resolved?
nova warren
.close
obtuse coral
I need help w #12, plz
cedar kilnBOT
I need help w #12, plz
ancient lodge
Consider ||shared angles||
obtuse coral
Consider ||shared angles||
Right, but there’s only 1 set of congruent angles
I need 2
ancient lodge
'Shared angles' means angles shared between the triangles
ancient lodge
Well you know what to look for
It's kind of a common sense thing
look at it again
obtuse coral
Ok
It angle C congruent to itself by the reflexive property of congruence?
Ah, that makes sense
Could u also rq check what I did for #14? @ancient lodge
ancient lodge
sure
obtuse coral
Here it is
Are the congruence marks correct, as well as the similarity statement?
ancient lodge
,rotate
wraith daggerBOT
ancient lodge
Looks good to me 👍
ancient lodge
Yes, the statement is correct \ \ And you could've also used the shared $\angle N$, though you don't have to since two angles are sufficient to prove similarity
wraith daggerBOT
Civil Service Pigeon
ancient lodge
Bc I think the answer key has smth different
There's $3!=6$ ways to order the letters so that's fine
wraith daggerBOT
Civil Service Pigeon
ancient lodge
👍
obtuse coral
Ty @ancient lodge
O
Oh, and, here for example
How do I know that the side that’s 12 units long corresponds with the side that’s 24 units long?
ancient lodge
Alternate interior angles
obtuse coral
Got it, ty
cedar kilnBOT
@obtuse coral Has your question been resolved?
cedar kilnBOT
cedar kilnBOT
Available help channel!
severe edge
cedar kilnBOT
severe edge
In the proof of this theorem
How do we know that anything less than N is bounded
Can elements of a sequence not be infinity?
I guess that would make sense
Because the proof clearly makes sense for the sequence elements greater than N
But I guess I don’t get why if we can just write off the elements before N Why can’t we do the same for the elements after N
.close
foggy berry
cedar kilnBOT
foggy berry
can someone help me with arithmatic and geometric sequences
tame stream
A or b
foggy berry
both
foggy berry
3
tame stream
Okay and what is d
half forge
an=a1+d(n-1) for arithmetic sequence
tame stream
N-1 tells us how far away we are from n1
When it’s 1 1-1 is 0 since we’re at n1
N2 is 1 away from n1 so 2-1 = 1
Since it is +5 for every n away from n1 we need to multiply n-1 by 5
foggy berry
An=3+(n-1)times5
tame stream
Yup
foggy berry
is that it
tame stream
Yes
half forge
(b) is just a25
tame stream
Can you send a clearer pic
foggy berry
tame stream
Still can’t read it ha
foggy berry
find the 25th term
tame stream
I meant the equation
tame stream
Oh
First you get the equation we just calculated and then plug in a25
The 3 was not in the bracket
It’s 3 + (25-1) * 5
tame stream
Yeah
foggy berry
i think i have it
the next question is
12,10,8,6
write an explicit formula
i got An=12+(n-1)*-2
is it -2 or 2
...
half forge
Yeah your good
half forge
is it -2 or 2
-2, since the common difference is -2
foggy berry
ok thanks
cedar kilnBOT
@foggy berry Has your question been resolved?
short sierra
Can someone please help me understand how I can solve #49
cedar kilnBOT
Can someone please help me understand how I can solve #49
buoyant latch
Do you know what topic this is under
short sierra
I can't even find a video to help me. The videos I find are doing very simple questions
I am trying so hard to understand what to do but I can't find a video to help me
buoyant latch
Fantastic this is under differentiation
What does the derivative of a function tell you?
short sierra
The slope
buoyant latch
Of?
buoyant latch
The important thing is it tells you the slope of f(x) at its corresponding x value
short sierra
Okay so, I have x value, I sub x into f(x) to get y value
buoyant latch
So f’(2) tells you the slope of the tangent at x=2 for the function f(x)
short sierra
Then to get m I just derive
Then I sub everything into y-y1 = m(x-x1)
Would this be the goal?
buoyant latch
Yes
buoyant latch
Then I sub everything into y-y1 = m(x-x1)
This is a the formula to find the equation of a line that passes through a known point and the slope
By differentiating you can find the slope at the point (“where x = ???” Part of the question)
And by subbing in that x value into f(x) you can find that point
buoyant latch
Doing these 2 steps give you a slope and a point
buoyant latch
Then I sub everything into y-y1 = m(x-x1)
Then use this formula to find the equation of said line
short sierra
Ok I am going to try and do 49, I will probably have mistakes, and it would be nice if you can tell me if something is wrong
Please
buoyant latch
Of course, send your working out through
short sierra
2x
short sierra
Ohh oops
The top seem to cancel out
So would f'(x) = 0
The slope = 0?
Oh I made a mistake
Should be 2x^2(e^(2x))
buoyant latch
Look again
short sierra
Im gonna try to derive it again
short sierra
Yeah mb
short sierra
Yeah
buoyant latch
Now look at x=1
Find the slope of F(x) at x=1
It also passes through the point (x, F(x))
short sierra
I sub in x=1 into f'(x) now
buoyant latch
Yes
short sierra
I simplified the f'(x)
So im trying again
My final answer
According to the textbook this is the correct answer. I just want to make sure I did not skip any steps or break any rules
grave turret
idk how to do this question can someone pls help
cedar kilnBOT
idk how to do this question can someone pls help
short blade
what's giving you trouble with the question?
grave turret
i dont understnad how to find the domain and range
gilded elm
first thing: do you know what a domain and range is
grave turret
yes domain is like the x value and range is like the y value of the function isnt it
half forge
The domain of f^-1 is the range of f, and the other way around for the range of f^-1, because f and f^-1 are y=x symmetry
grave turret
ok so i have to find the domain and range of f(x) to solver this?
ok thanks
and question b what does it mean find an expression for f-1(x)
is it just to find out what f-1(x) is?
gilded elm
yep
spark perch
Which is the expanded form of (x + 1)3?
cedar kilnBOT
Which is the expanded form of (x + 1)3?
winged bay
you mean (x+1)^3?
spark perch
yes
winged bay
expand to (x+1)(x+1)(x+1), then distribute
if you are learning binomial theorem, then use it
cedar kilnBOT
@spark perch Has your question been resolved?
latent bloom
short sierra
How can I do part b for this question?
cedar kilnBOT
How can I do part b for this question?
plucky carbon
cedar kilnBOT
plucky carbon
How can this be simplified?
runic garnet
Try doing a substitution, let k=arcsin(x), then try using a double angle identity to solve
Hint: u want a double angle identity that’s entirely in terms of sin
(To get rid of the arcsin)
cedar kilnBOT
@plucky carbon Has your question been resolved?
runic garnet
Yea that looks good
tame blade
I Need help in maths
cedar kilnBOT
I Need help in maths
flint plinth
which question?
crimson sedge
all of them
tame blade
@flint plinth
flint plinth
i'll let @crimson sedge take over, obviously he's itching to solve these
crimson sedge
NO
tame blade
I smell a troller!
Please help
I don’t want mayo
Mayo is bad at maths
I Need Bingo
.clothesfirst
tame blade
.close
quiet iris
hey
clear berry
,rotate
wraith daggerBOT
clear berry
i dont understand what im supposed to do at all
Weird question but it basically wants to start with an answer and create a question
quiet iris
how do i do that
clear berry
In other words create a question that when solved ends with x=2
clear berry
Shouldn't be hard, just add/subtract and divide/multiply some stuff from both sides. For example
x = 2, (add 3 both sides), x + 3 = 5 (divide both sides by say 5) then (x + 3)/5 = 1
quiet iris
mk so
clear berry
Then solve it by reversing the steps and you'll be able to get x=2
quiet iris
x = 2, x + 3 = 5, (x + 3)/5=1
clear berry
You can make it more complex by adding some x-terms also but this should suffice
quiet iris
im sorry math isnt my strong suit ☠️
solar vector
You should try to come up with your own similar answer to numbpy's answer.
clear berry
Just solve it normally
quiet iris
2 + 5 / 4 - 9 x 6
clear berry
Also, I'd suggest you make your own question to get a better idea of what's hapenning
clear berry
2 + 5 / 4 - 9 x 6
what is this?
quiet iris
ill do it then show u
quiet iris
what is this?
my equation
clear berry
How is this an equation when there's no equal "="
clear berry
okay, lemme guide you
write down x=2
add or subtract some number from both sides
Then divide or multiply some non-zero number from both sides
Ta-da you have an equation
clear berry
I don't think that evaluates to 2
clear berry
I tried it in the calculator and it gives 36.4
clear berry
I mean 5 divides neither 3 nor 5 so it will give a decimal number
clear berry
ah, you misplaced the brackets then
quiet iris
Did I?
clear berry
It should be (- 9 x 4 + 7 - ( - 3 x 4))/5 - 9
clear berry
Yes after you correct the placement of bracket
quiet iris
So copy and paste what u sent?
(- 9 x 4 + 7 - ( - 3 x 4))/5 - 9
Correct?
Bottom one
clear berry
Shouldn't it be 9 not -9?
clear berry
Just solve it normally
quiet iris
What I do first
clear berry
Use the pemdas rule
quiet iris
Okok
clear berry
but evaluate the brackets first
quiet iris
Good?
clear berry
You were supposed to do the innermost bracket first
clear berry
As in, (-3 x 4)
clear berry
Just a small error, you perform all multiplications first
clear berry
Just a small error, you perform all multiplications first
So, you should have "(36 + 7 + 12)/5 - 9"
quiet iris
In the second stage?
clear berry
yeah or you can add more stages
quiet iris
I’ll slide it in the middle of the both
clear berry
Like -> (36 + 7 - (-12))/5 - 9, then (36 + 7 + 12)/5 - 9
clear berry
yep
clear berry
Why did you reverse it again?
quiet iris
Wym
clear berry
you wrote 12 in third step
quiet iris
Yeah
clear berry
Then again wrote -(-12) in forth step
clear berry
yep
clear berry
yep
clear berry
yes, five part first
clear berry
After you're done evaluating the bracket, the bracket is automatically removed
clear berry
So, in the previous step itself you'd have 55/9 instead of (55)/9
clear berry
correct, maybe finally write x=2
clear berry
I meant writing x=2 after 2=x but it's good anyway
clear berry
Do you have time helping me with two other ones?
show the questions
clear berry
That's a rectangle right?
quiet iris
That's a rectangle right?
Ya
clear berry
Thiis one first
quiet iris
Mk
clear berry
What's the area of rectangle
quiet iris
120 cm2
clear berry
no, no as in what's the formula for area of a rectangle?
quiet iris
L x W??
clear berry
L, W?
clear berry
what is L, what is W?
clear berry
yeah so write is properly
clear berry
area = length x width
quiet iris
Okay
clear berry
now, what's the length and the width?
clear berry
yes, solve it
clear berry
You don't know how to solve linear equation?
clear berry
hmm... you have to isolate the x
quiet iris
how do i do that
clear berry
first thing you do is remove anything outside
So, there's a 6 as product
to remove it you do reverse of product, ie divide
So, divide both sides by 6
quiet iris
How do I do so
clear berry
6 x (4x +8) = 120 cm
write this
clear berry
yeah, now you have 6(4x + 8) = 120
clear berry
6 is multiplied by (4x + 8)
quiet iris
Mhm
clear berry
so, to remove it you divide by 6 on both sides
quiet iris
ohh
clear berry
I hope you remember how to perform 120/6
quiet iris
quiet iris
I hope you remember how to perform 120/6
= 20
clear berry
what is that weird thing?
Just write it normally
6 x (4x + 8) = 120
4x + 8 = 120/6 = 20
quiet iris
I okay
clear berry
4x + 8 = 120/6 = 20
Then subtract 8 from both sides, after this
clear berry
you have 4x + 8 = 20 right
quiet iris
Yes.
clear berry
4x + 8 - 8 = 20 - 8
I hope you performed the subtraction and didn't leave it as 20 - 8
clear berry
ok, good
quiet iris
Division?
clear berry
yes
clear berry
no, you have to remove 4
So, you divide both sides by 4
on the lhs the 4/4 would cancel
quiet iris
4 / x
clear berry
on the rhs you'd get ___
clear berry
yep
quiet iris
3?
clear berry
yess
clear berry
This is also a linear equation that shouldn't be too hard to solve
quiet iris
clear berry
write the question first
quiet iris
LMAO
clear berry
then that
clear berry
by mistake did you miss the - sign before 18?
clear berry
then perform the bracket
remember that number next to bracket means that they are multiplied
quiet iris
clear berry
take note of the - sign
quiet iris
clear berry
just write 36
quiet iris
?
clear berry
-(-36) is the same as (-1) x (-36) = 36
quiet iris
So what do I write
quiet iris
How did we get that tho
I thought it was gonna be negative
Cause neg and pos equal nrg
Neg
clear berry
I'd be 3y + 36 - 18 = 0
clear berry
yeah, I think you should be fine noe
quiet iris
It’s answered?
clear berry
Just get the value of y
clear berry
WHY DID YOU AGAIN WRITE -36
quiet iris
WYM?
clear berry
Look at the 3rd line you've written
quiet iris
Yea??
wraith daggerBOT
numbpy
quiet iris
OH
clear berry
You need to pay attention smh
clear berry
3y + 6 = 0
subtract 6 from both sidesw
clear berry
how'd you get -3y?
quiet iris
3-6
clear berry
why did you do that?
clear berry
I think I did it cause u said subtract it from both sides
I meant both sides of the equal sign
clear berry
So, 3y = -6
Do you know how to proceed from here?
quiet iris
quiet iris
Do you know how to proceed from here?
There’s more?
clear berry
Nah, how do still not understand
You can't just remove 3 directly on only one side
You HAVE TO DIVIDE both sides by 3
clear berry
Wait a damn minute
clear berry
how did you go from 3y + 18 = 0 to 3y +6 = 0
clear berry
by what?
clear berry
Then why didn't you also divide the 3 in 3y
quiet iris
oh.
clear berry
The division happens everywhere
clear berry
$3y + 18 = 0 \implies \frac{3y + 18}{3} = \frac03 = \frac{3y}{3} + \frac{18}{3} = 0$
wraith daggerBOT
numbpy
clear berry
yep, correct
quiet iris
can I dm you if i ever hit a roadblock w my homework again?
quiet iris
Then finally y = -6
how we go from positive to -
clear berry
Yeah, we all are here to help but you'll really need to work more
clear berry
how we go from positive to -
we had y + 6 = 0
quiet iris
yea
quiet iris
-6
OHH
WTFG
WWTF
OHH
OK
I GET IT NOW
OKKK
TY
that was awfully horrid learnign experience for u
mb
quiet iris
Okay.
clear berry
And see what exactly is happening
quiet iris
yeah
clear berry
Like why does each step happen etc.
clear berry
alright then
quiet iris
bye bye
cedar kilnBOT
cedar kilnBOT
Available help channel!
steel mural
hey if there is no p outside an event is the question just asking for the sample space
cedar kilnBOT
@steel mural Has your question been resolved?
digital cliff
I think i would need more context on where it is being used, If this is for a venn diagram then its just the sample space yeah (all natural and integer values)
waxen crater
cedar kilnBOT
waxen crater
I was given this example by my teacher but I think I copied sth wrong
frosty ocean
,w 6x^2-13x+6
wraith daggerBOT
