help-13

[unique ravine]

over the y axis?

but how does that make sense with our domain?

for original function

[crimson sedge]

Because here

,w graph log(2x)

[wraith dagger]

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[crimson sedge]

Do you see how it is asymptomatic to y = 0 and is extending to infinity? That's just a normal log function

[unique ravine]

yeah

[crimson sedge]

Also here is the cool thing, you know how when u multiply x in an f(ax) situation it's a compression right?

[unique ravine]

yes

[crimson sedge]

With logs that compression results in a i-forgot-what-it-is-called transformation because
[
\log(ax) = \log(a) + \log(x)
]

[wraith dagger]

♡LexQa♡

[crimson sedge]

It's x intercept will be different

[unique ravine]

i think i understand that

[crimson sedge]

But anyways, to graph a function and its inverse, they are going to be symmetrical about the y = x line

[unique ravine]

mhm

i think ive got it for now

ima practice some more

to get the hang of it

[lusty grotto]

hello

so admira u got it solved?

[unique ravine]

yeah i did

thank you so much to the both of you

for helping me

:)

[lusty grotto]

dm if u have any more doubts

[unique ravine]

i was genuinely stressing out over it but ima practice on it

i will!

[lusty grotto]

lexqa probably did a better job of explainig

[crimson sedge]

Anyways to graph -log(-2x) +1 there are a lot of stuff going on there but u can start with finding out what log(2x) looks like

[unique ravine]

you taught me the steps which i rly needed 😅

[unique ravine]

ok perf!

[lusty grotto]

😄 sometimes i feel i sound strict when i explain

lexqa sounds very friendlier 😁

[crimson sedge]

Dude I have been struggling to walk to this restaurant so it's not like I'm being the best teacher right now ahaha

[unique ravine]

you both were great :') tysm

ima close the channel so others can use now

.close

[cedar kiln]

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[whole radish]

could someone walk me through the step for factoring $27x^{2}-30x+3$

[wraith dagger]

Astassa

[coral imp]

Just

[worn wave]

Do you know what is this

Like do you know what type of equation is this

[coral imp]

Split the coeff of x

[coral imp]

Bro sounded like a mafia for a sec

[worn wave]

what

[whole radish]

its a quadratic right?

[coral imp]

"Do u know what is this"

"This is brown sugar"

Mafia boss

[coral imp]

Just split the coeff bro

Coeff of x

[worn wave]

yes

[worn wave]

coefficient doesn’t work

and this is not how you are supposed to approach these types of questions

because these involve quadratic

[coral imp]

Bro literally said factoring

Ya gonna apply quadratic eqn formula here or what?

Smh

[worn wave]

Isn’t that count as factoring a quadratic equation?

I don’t get it, this is essentially how you’re supposed to factor a quadratic

[coral imp]

Ya gonna tell him to apply quad formula here?

[worn wave]

If that doesn’t help, there’s other ways.

[whole radish]

so when splitting x do I just choose any two numbers that sum to -30?

[worn wave]

That is not how you’re supposed to solve quadratics

[coral imp]

First take 3 as common from the whole exp n make it simpler

[worn wave]

Then identify the b and c of the equation

[coral imp]

Who said factoring isn't allowed?

[worn wave]

At least that’s not how I was taught?

[coral imp]

Smh

That will be long asf

@whole radish choose factoring or quad eqn

[worn wave]

Will you stop being so judgemental?

[coral imp]

..

[whole radish]

so $3(9x^{2}-10x+3)$

[wraith dagger]

Astassa

[worn wave]

I have my own ways on solving quadratics

[worn wave]

Now from here identify the b and c

From the general form of a quadratic formula it’s

ax^2 + bx + c

Find the constant b and c here

[whole radish]

factoring is just simplifing the equation, its not solving it

[worn wave]

Then I don’t understand what’s your meaning of “factoring”

[coral imp]

Nvm then ig I should take over?

[worn wave]

I’ll still help

[coral imp]

Umm

[coral imp]

Ye split it as -9x-x

[whole radish]

ok $3(9x^{2}-9x)-(x+1)$ right?

[wraith dagger]

Astassa

[coral imp]

Yee

Take 9x common from the left one

And I think u can do the rest

[whole radish]

ok so this is were im getting confused, i can take 9 out of the first one

[coral imp]

Take 9x

[whole radish]

$3 * 9x(x-1)-(x+1)$?

[coral imp]

Umm

I'll prefer to make this exp

[wraith dagger]

Astassa

[coral imp]

$$3[9x(x-1)-1(x-1)]$$

[wraith dagger]

anand

[coral imp]

Coz the 3 was taken whole from the whole eqn(shit I said it eqn)

Not just 9x one

[worn wave]

Isn’t || (9x-1)(x-1) || the factor of this equation

[coral imp]

its 3(9x-1)(x-1)

[whole radish]

its a x+1 on the right side right?

[coral imp]

Nope

[worn wave]

Aren’t you supposed to simplify it?

[coral imp]

Ya can't ignore the 3

[worn wave]

???? That doesn’t make sense

[whole radish]

hmm, why did the sign flip?

[coral imp]

So you're trynna tell that ya can just throw off a value from exp?

[worn wave]

Isn’t that’s the point of simplifying?

Because I could take the original equation and simplify it

From 27x^2 - 30x + 3

[coral imp]

Coz when ya took - common from (-x+1)

Ya made it -(x+1)

Ya had to make it -(x-1)

[worn wave]

Never mind I understand this now, it’s an expression and not an equation

[coral imp]

Smh

[coral imp]

Ofc

Where did ya see = ?

[whole radish]

oh ok, yeah i forgot to flip the sign

[coral imp]

Hehe

[whole radish]

can i ask another question in here?

[coral imp]

Ofc

Why not

[whole radish]

ok, so im dividing two functions $\frac {h(x)}{g(x)}$ and i needed to factor the top part which we just did, $\frac {3(9x-1)(x-1)}{6x}$, now it need to get simplified further to $9x-1$, im wondering, do i multiply the top half by its reciprocal?

[wraith dagger]

Astassa

[whole radish]

nvm, i just realized i used the wrong equation for g(x)

🙂

[coral imp]

💀

[whole radish]

thank you for the help

[cedar kiln]

@whole radish Has your question been resolved?

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[cedar kiln]

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[crimson sedge]

What does this symbol mean?

[crimson sedge]

I know it is union

[copper crest]

Chi?

Like susceptibility

[crimson sedge]

But I don't understand that numbers

[crimson sedge]

Should I sent the question?

[gusty forum]

the union of 50 sets $x_1, x_2, ..., x_{49}, x_{50}$

[wraith dagger]

IV

[crimson sedge]

Ok

.close

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[coral imp]

²√ is called sq rt

[coral imp]

³√ is called cube root

What is then

⁴√ and... Called?

[sacred grail]

hypercube root

[solid juniper]

fourth root, nth root

[sacred grail]

go with layla

[coral imp]

Oki

Ty then

💀

[solid juniper]

[coral imp]

.close

[cedar kiln]

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[coral imp]

I was actually worried abt someone replying quadruple root

[crimson sedge]

quad root

Quadruple root

[coral imp]

https://tenor.com/view/shoe-throw-target-shooting-gif-15305887

[coarse canyon]

bruh we have the same name

[solid juniper]

water bottle?

[coarse canyon]

no "anand"

[coral imp]

Another indian

[solid juniper]

oh lol

[coarse canyon]

nah

[coral imp]

What else can ya comment

[coral imp]

Then weird

[coarse canyon]

bruh u are from india?

[coral imp]

How ya pronounce anand without hindi accent wtf?

💀

Ya gonna pronounce it as (an) +(and)

💀

[coarse canyon]

burh

[coral imp]

Then take an common

an(1+d)

Now it feels like a weird style type Android

[coral imp]

Yeh

[cedar kiln]

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[shy drift]

Hello to all, I forgot all my maths skills and vocabulary.
How does one find the "common link", the formula between a set of number (via excel)?
Of course I know that it's +2, +3, +4, +5 here, it's X+(X-1)

[gusty forum]

tools - data analysis - regression

[shy drift]

Ok got it thanks!

.close

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[lapis hare]

made this proof for a->0, sin(a)/a = 1
but it's so absurdly simple compared to the one i'm seeing that i have to imagine something in it is wrong. Is solving the indeterminate form at the end legal? did i do something else wrong?

[south tundra]

This proof is inconsistent, you need to prove that the derivative of sin is cos

Which is done by proving the limit that you're trying to solve rn

So that's circular reasoning

[lapis hare]

ah i did not know that

thank you

.close

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[crimson sedge]

does anyone know the rule for natural logs? I know there is one for logs, which is log(base a) [u] is equal to u'/uln(a), but I swear there was one for ln[U] as well

[tranquil oracle]

what rule?

it seems like this is calculus

[crimson sedge]

yes it is calculus @tranquil oracle

like i literally had this rule in my notes but i cant find it anymore. its something like ln[U] = U'/U or U/U' i just dont know

[tranquil oracle]

ln is just base e

[crimson sedge]

maybe im overthinking it

so like ln(8x+4) would be 1/8x+4 times 8?

isnt that the rule being applied

cries

[chilly mesa]

Yes, when you differentiate ln(8x+4) you get 8/(8x+4)

In general when you differentiate ln( f(x) ) you get f’(x) / f(x)

[crimson sedge]

okay thank you

while im here

when they ask for NO extrema is there a guaranteed way I can draw the line so its always no extrema

like if i just level out the no extrema line with another line will that work 100% of the time

[tranquil oracle]

what is the question?

because usually there would be context

they wouldn't ask you to draw a function on [0, 1] with no extrema

(unless the paper has a mistake)

[crimson sedge]

uhh

yes yes haha one second

@tranquil oracle

I always get the "no local extrema" question incorrect when I draw the graphs

that pic is the solution btw

but im jut curious how i should approach drawing the no local extrema.. should I just level it out with another part of the graph

sorry i dont mean to spam u with images but here is another thing i got wrong regarding that

[tranquil oracle]

it's like the x^3 or -x^3 shape

[crimson sedge]

like that is correct. no local extrema. but for mine i got marked wrong

for that

[tranquil oracle]

yeah the graph "changed directions"

was going down, then going up

[crimson sedge]

OHH

so its supposed to maintain the same direction?

while not being a max/min

[tranquil oracle]

yeah, like x^3 and -x^3 shape

[crimson sedge]

ohh

[tranquil oracle]

,w plot y=x^3

[wraith dagger]

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Requested by Element118#2437

[crimson sedge]

how come it wouldnt be considered a local minimum

[crimson sedge]

because of the abs min next to it?

[tranquil oracle]

do you remember the definition for local minimum?

[crimson sedge]

not exactly. just that its the lowest point in the vicinity

something like that

[tranquil oracle]

yeah, on a small open interval containing the point x, all points in the open interval satisfy f(y)>=f(x)

so near x=0, for that graph, you see that x=-0.0001 has a smaller value

[crimson sedge]

I see

would this work then?

if it went down like that

[tranquil oracle]

yeah that should be fine although labelling the points can help I guess

[crimson sedge]

of course

thanks a bunch for the help/images

i appreciate it

.close

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[topaz imp]

Can anyone help me out with this

[crimson sedge]

Wow this question is...wild

[topaz imp]

yea lmao, I am not able to understand the gist of the problem

[neon spruce]

do you know baye's theorem?

[topaz imp]

yes

[neon spruce]

well then just apply that

that's just off the top of my mind , i didn't really work it out yet

[topaz imp]

I tried too, but I feel I need to make a tree for that

will the assumption probability be just 1/2 ?

[cedar kiln]

@topaz imp Has your question been resolved?

[topaz imp]

@neon spruce can this be a valid answer?

[neon spruce]

i think so

[topaz imp]

okk

.close

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[bold pond]

how do they switch the normal vector to direction vector? is it just pick one and make it negative and switch?

[bold pond]

would a normal vector of (2,0,1) be turned into a direction vector if (-1,0,2)

[unborn pike]

yes

[bold pond]

so its just simply pick vector, make negative, and switch?

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[crimson sedge]

Hello, today we've done exponential equations in school and we had something like (a+√b)^x+(a-√b)^x=4
The math problem is not the issue, I just want to understand how (a+√b)^x = y and (a-√b)^x = 1/y

[patent cape]

roman observ

frumos

[crimson sedge]

Dap 🙂

[patent cape]

astea se fac in a 9 a nu

[crimson sedge]

Nu

Sunt a 10 a științe ale naturii

[patent cape]

aa

pai da ca cred ca ai nevoie de logaritmi ca sa demonstrezi

2 sec

[crimson sedge]

Am vrut sa fac o sinteza la modul si substitutia asta ma lasa pe ganduri

[patent cape]

hai ca am inteles eu ceva din aia

[crimson sedge]

Super

Ei bine, dovedi macar ca x=0 întotdeauna

Sorry for the romanian.

[patent cape]

nush man ca eu am incercat niste fonfoneli cu logaritmi naturali da nu am prea ajuns in mare loc

right english would be better

[crimson sedge]

Thoughts?

Proving that for every (a+√b)^x+(a-√b)^x=n, x=0

[crimson sedge]

I forgot the x power and some radical at b

[patent cape]

yeah i saw

[crimson sedge]

But I appreciate the effort nevertheless, I guess I should follow the rule, but I will not forget it

[patent cape]

ill look up a proof

[crimson sedge]

Sure, I'll close the tab for the free place, but you can DM me anytime

Good chat.

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[split crest]

transfer

her money

into pesos

and if the item costs less then she can buy it

@iron gate

[iron gate]

i need the answers

[split crest]

well we do not give answers in here

[cedar kiln]

@iron gate Has your question been resolved?

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@iron gate Has your question been resolved?

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[lean solstice]

isnt the answer y = -6sin(x) ?

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[scarlet garnet]

1. I don't know where to begin 2. I have begun but got stuck midway 3. I got an answer but I'm told it's wrong 4. I got an answer and would like my work checked 5. I have a question about someone else's worked solution 6. None of the above
what number describes your status the best?

[solar scarab]

$$f'(x)=\lim_{h\to 0}\frac{f(x+h)-f(x)}{h}$$

[wraith dagger]

minerals

[brave oar]

3

[solar scarab]

So f'x = lim(h->0) of 0/h

=0

[scarlet garnet]

well no matter, minerals 'helped' you by doing it for you

[brave oar]

I got h/h =1 after simplifying but then I get h->0 1-> 8 (not sure where i went wrong)

[solar scarab]

if we take the expression inside the limit, 0/h, it is basically 0 for all h and undefined at h=0

so lim(h->0) 0/h = 0, i hope that helps?

[brave oar]

The expression is just h/h ?So since h -> 0 ; the division is 0/0 = 0 ?

[cedar kiln]

@brave oar Has your question been resolved?

[cedar kiln]

@brave oar Has your question been resolved?

[brave oar]

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[light pine]

for iii

[light pine]

before i graph it would this be correct?

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[wintry cargo]

i figured it out

.close

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[light pine]

nice

[cedar kiln]

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[atomic granite]

use a known Taylor series to conjecture the value of the given limit.

shouldnt the answer be -1/9?

[tropic oxide]

what makes you think that?

[atomic granite]

comparing to this

[tropic oxide]

nyeh?

but you've got x^9 in the denominator this time.

not x^6.

[atomic granite]

Oh I got it, ty 🤦‍♂️

[atomic granite]

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[random moon]

Hello

[random moon]

Can anyone help me to solve this please

$x<\frac{-1}{exp(x)}$

[wraith dagger]

Sama様

[olive lance]

wdym solve?

[random moon]

I want to know when the member on the right is higher than the one in the left

[dull oxide]

Have you tried graphing both equations?

[random moon]

No

I am supposed to find it by calculus

It was a test that my school has done last year

[dull oxide]

Is this right?

[random moon]

Wdym by is this right ?

You think there's no way to find it by calculs ?

[dull oxide]

I mean are you trying to write this?

[random moon]

Yes !

Mb

[dull oxide]

Ah. Are you trying to prove that it's true for all x?

[random moon]

Something Like that

I am trying to find all the solutions of this inequation

[olive lance]

it's definitely not true for all x

[dull oxide]

It isn't?

[olive lance]

if x is positive then the rhs is negative

[dull oxide]

Oh

I have it bakcwards

You're right

[random moon]

So there is not a way to find it ?

[dull oxide]

No. It's that it's not true

Are you reading the problem correctly?

[random moon]

I need to write the variation table of f(x)

I naturally used f'(x)

Since $(exp(x)-1)² > 0$

[wraith dagger]

Sama様

[random moon]

I just need to find when the upper member is superior to 0

$-1 -x × exp(x) > 0$ is the same thing than that

[wraith dagger]

Sama様

[random moon]

@dull oxide if I made a mistake i genuinely don't know where it was

[dull oxide]

what's a variation table

[random moon]

Table of variation if you prefer

[dull oxide]

I still don't know what that is

Oh just where it's increasing or decreasing?

[random moon]

Yes !

[dull oxide]

Looks like it never is

Here's the graph

Always decreasing

except at 0

[random moon]

You are right

It looks like it was a question needing intuition

I was so focused on the calculus that I did'nt even think about that

Thank you

.close

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[hollow moat]

hellk

[hollow moat]

hello

<@&286206848099549185>

[hollow moat]

message to help

i saw that after

[dull oxide]

Anyway

What is your question

[hollow moat]

i sent a photo

[dull oxide]

yeah but what is your question

[hollow moat]

whats the answer

i wanna see if mine is right

[dull oxide]

What did you put and why

[hollow moat]

u dont need all that

[dull oxide]

then you don't need help

[hollow moat]

to give me an answer

i put c because i think its right

@dull oxide ru here

[dull oxide]

Looks right to me. What was your intuition?

[hollow moat]

i eanted to make sure its rigft

[dull oxide]

Yeah but what makes you think it's c?

If you're unsure, it would be helpful to become sure

[hollow moat]

because my brain said it

[dull oxide]

So just a guess?

[hollow moat]

no

.close

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[bitter nacelle]

how do you write this in interval notation (-9, 16)

[bitter nacelle]

and how do you write things in interval notation as a whole

[tropic oxide]

(-9, 16) already is interval notation...?

[bitter nacelle]

oh...

then can u help me on a problem

[violet night]

what is the lowest possible value of x ?

[cedar kiln]

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[jade sable]

When i derive f(x), I keep getting stuck at (7x^(4/3) - 7) / 3x^(2/3)

[jade sable]

how did they get that numerator?

[dire geode]

put everything over a common denominator

[jade sable]

which is 3 right

and since x^(-2/3) you move that down to the denominator

ok the first step I got was 7/3x^(4/3) - 7/3x^(-2/3)

so the common denominator is 3 in this case

[dire geode]

$x^{-2/3} = \frac{1}{x^{2/3}}$

[wraith dagger]

riemann

[jade sable]

ye

[dire geode]

that's a denominator

so your least common denominator so you should include it

[jade sable]

$\frac{7x^{4/3}-7}{3x^{2/3}}$

[wraith dagger]

rice

[jade sable]

oh i made a mistake

i didnt multiply the 7x^4/3 by x^2/3

.close

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[mild eagle]

I’m not sure how to solve this if I would get help for t would be amazing

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[shrewd monolith]

x^2+6x=0 complete the square can someone help me please

[obsidian coral]

One, you don't need to close your channel and open a new one if people stop helping you. Just wait for help you come

Two, you have (x+3) (x+3) = 0

Solve for x

[shrewd monolith]

i dont know how to do that

and people keep leaving at that part

it happend like 3 times today

[obsidian coral]

Have you ever solved something like (x - 1)(x + 1) = 0 before?

[shrewd monolith]

do i need to cross multiply?

if not then no

[obsidian coral]

No

Have you ever factored a quadratic and found the roots/zeros of the equation before?

[shrewd monolith]

yes

[obsidian coral]

How would you find the roots?

[shrewd monolith]

well it usually has 4 different numbers and is in the format x^2+x -x+x

or something like that'

[obsidian coral]

That's the process of factoring. After you factor, it should look something like this, (x - 1)(x + 1) = 0

[shrewd monolith]

ok so (x+3) (x+3) is the final answer?

[obsidian coral]

No you need to find the roots of that

[shrewd monolith]

?

how do i do that

[obsidian coral]

@mild eagle

[obsidian coral]

(x+3) (x+3) = 0, solve for x

Zero product property

[shrewd monolith]

whats that?

[nova snow]

do x + 3 = 0

[shrewd monolith]

oh duh

x would be -3

complete the square

[nova snow]

Do you know the form

a(x + b)^2 + c

[shrewd monolith]

no

so what is that

[cedar kiln]

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[umbral silo]

I need help starting this integral. I know it involves with trigonometric substitution, but the $x^2$ in front is throwing me off

[wraith dagger]

eyevan

[cedar kiln]

@umbral silo Has your question been resolved?

[carmine bronze]

Substitute x = 2sin(u).

[cedar kiln]

@umbral silo Has your question been resolved?

[umbral silo]

@carmine bronze Thank you, but what is the reasoning? I'm not sure how to apply this in the future

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[arctic oracle]

Hiiii I need help on how to solve this I tried to do the graph by finding the vertex and roots of the equation

[arctic oracle]

Heres my answers so far

[cedar kiln]

@arctic oracle Has your question been resolved?

[arctic oracle]

<@&286206848099549185>

[crimson sedge]

Hold on

[arctic oracle]

for b and c Im confuse on how to get the values, ik that the answer for b must be greater than 0 and for c it should be less than 0 I just dont know how get the values

[cedar kiln]

@arctic oracle Has your question been resolved?

[autumn cape]

Can someone help me with this question pls?

So far what I’ve done was this but idk wat it means from 7 to 8 how much the constraint changes

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[daring shadow]

hello

[daring shadow]

i need help on problem 2

<@&286206848099549185>

[cedar kiln]

@daring shadow Has your question been resolved?

[coral imp]

https://youtu.be/-xWJwTQcgjk

@daring shadow

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[crystal mason]

Let $f \ : \ [a,b] \longrightarrow \mathbb{R}$ be monotonically increasing (i.e. $x \leq y \Longrightarrow f(x) \leq f(y)$). Show that the set of all discontinuities of $f$ is countable.\
\
I have no idea how I can start this.. any help?

[wraith dagger]

Levens

[dull oxide]

Do you know what monotonically increasing is? Do you know what countable means? Do you know what a discontinuity is?

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[austere plume]

How to answer 5c

[foggy merlin]

find the expression of both AC and AB and make them equal and solve for t

knowing that AC and AB are both distances

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[tacit bolt]

Hi

[tacit bolt]

For the 1) a)

its express MN with DB and DH

Im at MN = 1/2AB + DH -1/4 DB

[cedar kiln]

@tacit bolt Has your question been resolved?

[drifting furnace]

Try to make a drawing from the top.

I think it could help

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@tacit bolt Has your question been resolved?

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[robust swallow]

is
1/2 x (-4/8)
4?

[valid yacht]

I don't think so

[coral imp]

Nope

[valid yacht]

You mean $\frac12 \cross \frac{-4}{8}$, right?

[wraith dagger]

n11

[robust swallow]

https://i.gyazo.com/1a34c62074724b87280fa57f4052686b.png

[coral imp]

Same thing

[valid yacht]

Right, yeah

its not 4

[robust swallow]

I did 4/8 x 8/8

4x8 = 32/8

[hushed spoke]

That’s incorrect

[vagrant elbow]

It's the slope of a line who's parallel to a line who's slope is 4 🧠

[coral imp]

"You didn't have to cut me off-"

[vagrant elbow]

Wait were you gonna say the same thing

[coral imp]

Naa its a meme

[robust swallow]

is it -4?

[valid yacht]

no

do you know the rules for multiplying or operating on fractions?

in particular for this question, that $\frac ab \cross \frac cd = \frac{ac}{bd}$

[wraith dagger]

n11

[robust swallow]

is it -3?

-3/16

[coral imp]

How is the numerator 3?

[robust swallow]

1 x -4

[coral imp]

1 x -4 is -3?

How?

[hallow widget]

That will make it -4

Anything times one is itself...

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[hallow token]

What is the nth term of 12,8,4,0?

[obtuse belfry]

the difference between each term is -4

so we have a -4n

and the starting point is 12 -(-4 * 1) = 16

=> An = 16 - 4n

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[cerulean herald]

how do i solve it

what steps

[scarlet garnet]

what have you tried?
you can just shorten one term for example

[cerulean herald]

i just dont know where to start

and i dont know wht u mean by shorten one term :/

[scarlet garnet]

you know how you can turn $\frac{10}{10}$ to just 1?

[wraith dagger]

Jigglyproff

[cerulean herald]

where is 10/10

[scarlet garnet]

it was an example.

[cerulean herald]

oh

well i know 10/10 is 1 yes

[scarlet garnet]

so do the same here

[stiff heron]

that step was already done btw

[scarlet garnet]

no its not

[stiff heron]

it says the expression was simplified

[scarlet garnet]

yes, but both expressions as functions are NOT equal

so to say, it wasn't a algebraically correct simplification

the task is to find out why

[wraith dagger]

Mehdi_Moulati

[cerulean herald]

am i supposed to find an x value to plug in or am i supposed to figure out what the x value is by doing something to the rational expression

[scarlet garnet]

you have to find out what the difference between the right and left is
as its provided above, most x values behave the same in both

but the (x+1) makes it a little more complicated

[cerulean herald]

ok one sec

ok is it d

because both -1 and 5 made a zero on the numerator

[scarlet garnet]

well, the (x-5) is also on the right side....

[cerulean herald]

does that mean its c

i mean

b

ok b i think its b

[scarlet garnet]

I do too

[cerulean herald]

hooray

[scarlet garnet]

so you understand why right?

on the left, -1 makes it undefinied because you cannot divide by 0, on the right its fine, so thats the value thats different

[cerulean herald]

yes because that one doesnt make both sides equal

[scarlet garnet]

alright

good job

[cerulean herald]

ty

.close

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[tacit ermine]

if this means x is a real number

[tacit ermine]

what does this mean?

[tranquil cobalt]

It means the domain.

[tacit ermine]

Thank you

.close

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[loud pumice]

,, A = \begin{bmatrix}
r_x & u_x & -f_x & 0\
r_y & u_y & -f_y & 0\
r_z & u_z & -f_z & 0\
-(r\cdot e) & -(u\cdot e) & f \cdot e & 1
\end{bmatrix}

[wraith dagger]

finn

[loud pumice]

and

,, B = A^{-1}

[wraith dagger]

finn

[loud pumice]

how do i calculate B directly?

where r, u, f, e are 3-dimensional vectors

[cedar kiln]

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@loud pumice Has your question been resolved?

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@loud pumice Has your question been resolved?

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[clear grail]

how do i simplify this?

[thorn ruin]

Not sure what left one's problem is, maybe formatting. Right one missing a 6

[cedar kiln]

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[clear grail]

hrmm

[cedar kiln]

@clear grail Has your question been resolved?

[worthy cairn]

You should only be factoring a c out from terms that have a c inthem

Same for the d

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[opal imp]

is (r-p)(r-p*) = (r-p)^2? where r is a variable and p is a complex number while p* is its complex conjugate?

[opal imp]

if yes what is this called?

[dire geode]

,calc (3-(1+i))(3-(1-i))

[wraith dagger]

Result:

5

[dire geode]

,calc (3-(1+i))^2

[wraith dagger]

Result:

3 - 4i

[dire geode]

soooo no?

[cedar kiln]

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[cinder dagger]

how do I solve this?

[violet flume]

cursed notation

i think this is

$\qty( \log \qty( \log (20))^5)^4$

[wraith dagger]

jan Niku

[violet flume]

there is no solve, only simplify

[dreamy fern]

solve what i mean what value do you wanna find

[turbid anvil]

Whats the base ?

Is it natural?

[cedar kiln]

@cinder dagger Has your question been resolved?

[patent cape]

if its not written its assumed to be 10

[turbid anvil]

Well it's maths..so it may be a natural log

[patent cape]

well log(20) = log(10)+log(2) = 1 + log(2)

that would be ln

[turbid anvil]

Not saying it has to be but it can be

[turbid anvil]

My book refers to natural logs as log so

¯_(ツ)_/¯

[cinder dagger]

this is hard

[patent cape]

yeah goofy book

[turbid anvil]

Yes xD

[patent cape]

maybe they write the base of the log at the top

[turbid anvil]

Do u know the basics of logs ?

[patent cape]

for some fuckin reason

[turbid anvil]

Is that a thing ?

This is the right time to question humanity

[patent cape]

idk its the first time i saw someone refer to ln as log

[turbid anvil]

Well lemme share something with you

[patent cape]

i would love to have some standard notation for math that follows all countries

then teach that to students

it would be so simple

[turbid anvil]

+1

Look at 24 for eg
Its ln but it's written as log

[patent cape]

i hate humanity

even we have ln(x)

[cinder dagger]

nope

[turbid anvil]

Then how would u be able to solve the ques 💀

[cinder dagger]

ohh f

alr thx

.close

[cedar kiln]

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[dense laurel]

Hello, I have this problem and I have no idea where to start.

m mass bullet is fired verticaly with initial speed v0 and height h0. Air resistance is propotional to speed square and propotional coefficient is equal to k1 when bullet is going up and k2 when bullet is going down. What maximum height and when the bullet will reach? When bullet will reach the ground?

m, kg = 0.5
v0, m/s = 50
h0, m = 30
k1, kg/m = 0.015
k2, mg/m = 0.05

The problem is that I need to make a ordinary differential equations, but I have no idea where to start or what to do. Is anyone here who can help me understand this task?

[cedar kiln]

@dense laurel Has your question been resolved?

[cedar kiln]

@dense laurel Has your question been resolved?

[crimson sedge]

draw a force diagram

[cedar kiln]

@dense laurel Has your question been resolved?

[surreal stratus]

this would be better suited in a physics server, as they can help you with forming the equations

but as a start, you can find forces and use eqqns of motion

[cedar kiln]

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[cedar kiln]

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[red patio]

I've done this

But

a+b= -5
c= -17
a+b+c = -22

and the answer is -23

[random bison]

@slender palm write the equation as normal and solve it and then write it as -(3x-1)≥2 and solve it

[cedar kiln]

@red patio Has your question been resolved?

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[red patio]

Bruh i didnt notice

Ty

Solved

[cedar kiln]

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[tacit ermine]

can someone give me a hint? im going in circles currently

[tacit ermine]

(im doing part a )

ive got this far

,rotate

[cosmic steppe]

Just compare the positions of the vertex

You remember how to do translations right

[tacit ermine]

like y=y?

ohh you mean the triangle inside, making the points, (6,0) (7,6) (8,0) ?

,rotate

[tacit ermine]

they have the same gradient and shape?

wait so

b=3 as its 3 higher up

and a=-5 as its -5 places

.close

[cedar kiln]

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[cedar kiln]

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[crimson sedge]

This is really interesting, but how can I represent this to find a Hamilton circuit?

[cedar kiln]

@crimson sedge Has your question been resolved?

[sacred grail]

are mazes meant to be solved with hamiltonian circuits?

[crimson sedge]

I mean

Yeah

[sacred grail]

you dont traverse every cell in the maze tho

[crimson sedge]

I say that because like

The previous question before this one was quite literally

"Explain why backtracking can be used to find a Hamilton circuit" Or something along those lines, so I'm supposing there is some link

[sacred grail]

modelling a maze solution as a hamiltonian path just doesnt seem right

[crimson sedge]

Then what would?

[sacred grail]

well you're just trying to find a path

not necessarily one which visits every cell

and like in the pic you sent i dont think you can even find a hamiltonian path

because like the top left corner if you walk in you cant walk back out without going over yourself

[crimson sedge]

Hmm

Is this good enough

I mean, I technically answered the question sooo

[sacred grail]

"how did you solve it"

"i just eyeballed it"

[crimson sedge]

Yeah I'm a true mathematician

[sacred grail]

i mean certainly backtracking is helpful for solving mazes

for a larger maze id imagine that what you might do

as a human that is

[crimson sedge]

Yeah

But let's pretend we are robots

[sacred grail]

beep boop

ah im locked out of my account cant solve the captcha

[crimson sedge]

,w robot sounds

[wraith dagger]

Wolfram Alpha doesn't understand your query!
Perhaps try rephrasing your question?
Click here to refine your query online

Requested by ♡LexQa♡#5050

[crimson sedge]

Damn bro

Disappointed

[sacred grail]

i guess the point is backtracking isnt limited to hamiltonian circuit finding

[crimson sedge]

Captcha got nothing on us 😎

[sacred grail]

[crimson sedge]

How can I write this in

Fancy math terms

[sacred grail]

i have no idea

[crimson sedge]

Okay back to using

"It just is bro" Answers

My favourite

[sacred grail]

i mean

you could like

say the cells of the maze are uh

vertices

and the open walls are edges

then like

to find a path between the start and end

you use like backtracking alg

[crimson sedge]

[sacred grail]

or just dijkstras lmao

[crimson sedge]

I'm never touching math after this semester

It has gone too far

[sacred grail]

... and thus lex was never heard on the maths server again

[crimson sedge]

You will see me camping #probability-statistics next semester, which is my last math course

[sacred grail]

or you could just ask here and ill solve all your qs for you

[crimson sedge]

Ah yes snow my saviour 🙏🏻

I actually have not asked a single non-calculus homework question here, so I feel a bit better

[sacred grail]

[crimson sedge]

But that's the confidence

I wonder what question you will not be able to solve one day

Gonna drop some uh

Oh FUCK I just remembered

[sacred grail]

[crimson sedge]

I still have to take differential equations noooo

[sacred grail]

get ready for the eigenfunction expansions

your question earlier btw

about the series

[crimson sedge]

Will calculus 3 like ever help me with diff eqs actually

[sacred grail]

was busy so i couldnt reply but

[crimson sedge]

Oh that yes

[sacred grail]

you should've used one of my favourite tricks when theres logs

cauchy condensation

[crimson sedge]

Oh what

Teach

[crimson sedge]

I'm guessing brackets up top? But alright

[sacred grail]

called cauchy condensation

[crimson sedge]

Cauchy condensation...

[sacred grail]

but the trick basically turns the log into a linear term

its like a substitution but for sums

[sacred grail]

which obviously converges because n^2

[crimson sedge]

Holy shit

[sacred grail]

wait i think i missed a ln2

but its constant so whatever

[crimson sedge]

Okay I actually never heard of that test, but it seems hella interesting, I will study it and then come back to this

[sacred grail]

https://en.wikipedia.org/wiki/Cauchy_condensation_test

anyway so now if anyone ever asks you if something like

[sacred grail]

converges

[crimson sedge]

Always use Cauchy condensation?

[sacred grail]

use cauchy condensation to turn log term into linear term

then its easy af

[crimson sedge]

Why did nobody mention that haha

[sacred grail]

[crimson sedge]

But noted! Also I really appreciate your constant help, it is so insightful since you give such intuitive and unique solutions that really break away from the usual formulaic methods we get taught

I wonder if I can exercise such fluency in those subjects eventually

[sacred grail]

[sacred grail]

maybe just a little bit

for calculating laplacians in polar coordinates

[crimson sedge]

Pain

I feel like I'm learning so much shit just to barely apply them

I guess this is where the engineering comes in

But thanks anyways time to die again

.close

[cedar kiln]

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[red grove]

once again i am here

[red grove]

at the end of his 3-year borrowing period, skye owed 4635.55

his interest rate was 3.9% what was the original amount of the loan

i only can use these 2 formulas.
i = prt
and
a = p + i

i was told to "work backwards" but not given any direction of how to or where to start

[livid hound]

I gave you the instructions twice already

[red grove]

no

u said work backwards

u also used a formula not of the two i am allowed to use

[livid hound]

I said more lines after that

[red grove]

i can only use those 2 formulas

[livid hound]

I know

[red grove]

i cant use compound interest formula

[livid hound]

I know

my comments had nothing about compound interest formula

[red grove]

ok can you please repeat the process

[livid hound]

determine the interest gained during the third year

which can then be used to determine the amount owed at the end of the second year

[red grove]

how would i do that without knowing the principal

[livid hound]

amount at end of 2nd year + 3.9% applied to that gives amount at end of 3rd year

[red grove]

i dont know the amount at the end of the 2nd year

[livid hound]

you can determine that

which is what I'm telling you to do

[red grove]

what formula are you using to determine this

?

[livid hound]

a combination of the given formulas,

[red grove]

yea in what combination

[livid hound]

use can use substitution

[red grove]

can u type the formula example

[livid hound]

isolate i in the second equation and substitute it into the first equation

[red grove]

again, you arent typing out formula examples

[livid hound]

I'm providing you with simple instructions that you should be able to follow that will lead to you getting it yourself

[red grove]

and im telling you im a visual learner who requires a different method

i appreciate your help but you teaching method doesnt work for me

please dont answer my future help requests

.close

[cedar kiln]

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[livid hound]

ok I wont

[cedar kiln]

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[misty talon]

need help on how to simplify this to x^2+xy/2y

[latent bloom]

Ok take a close look at this property

[wraith dagger]

VulcanOne

[latent bloom]

Should help you out