help-13

[cerulean sail]

Oh nvm me - do you know some properties of matrix exponentials?

[tiny dome]

i thought i did but im not quite sure. is this what you mean?

[cerulean sail]

Yea that's what I meant, that's one of the properties

Well, almost...

[tropic oxide]

no, e^Λt is still a matrix

$e^{\Lambda t} = \bmqty{e^{at} & 0 \ 0 & e^{bt}}$

[wraith dagger]

Ann

[cerulean sail]

What I was looking for is that $B \cdot \exp(A) \cdot B^{-1} = \exp(BAB^{-1})$

[wraith dagger]

chartbit

[tiny dome]

thanks a lot! i think i got it now

.close

[cedar kiln]

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[cedar kiln]

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[crimson sedge]

Could someone help me do b(ii) linear regression, Ive done the other two qauestion up to there just not sure how to perform linear regression on ln y = ln a + b*ln x

[cedar kiln]

@crimson sedge Has your question been resolved?

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[indigo berry]

is my answer correct?

[cedar kiln]

@indigo berry Has your question been resolved?

[cedar kiln]

@indigo berry Has your question been resolved?

[cedar kiln]

@indigo berry Has your question been resolved?

[cedar kiln]

@indigo berry Has your question been resolved?

[cedar kiln]

@indigo berry Has your question been resolved?

[patent cairn]

I need help with this I've been stuck on it for quite a long time and it's coming up in an exam soon

[clever lintel]

get your own channel #❓how-to-get-help

[gritty viper]

probably not

you have the length of the interval part right

but you need to give x a definition

in terms of i

[indigo berry]

do i replace the second expression in paranthesis with i's instead of x's?

[gritty viper]

you cant just replace

you have to find the i'th right endpoint and use that

[cedar kiln]

@indigo berry Has your question been resolved?

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[winged hare]

factorize

[violet night]

have you tried anything?

[winged hare]

Yes mi result is 3x+4x-x

[desert zephyr]

x is common in all parcels

[buoyant latch]

Those aren’t the same

That’s like saying 6 = 3

[winged hare]

I'm in the first year of high school, it's another prisoner

[desert zephyr]

when you say factorize you mean factorizing the polynomial

[cedar kiln]

@winged hare Has your question been resolved?

[cedar kiln]

@winged hare Has your question been resolved?

[crisp quartz]

factor out 5x you get3x^2+4x-1 which is a quadratic equation go ahead and factorise it the quadratic way

[cedar kiln]

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[languid pine]

sin(180-@)/sin(90-@)

[languid pine]

simplify

can anyone help me pls

[rain drift]

it's just using identities:
sin(180 - a) = sin(a), cos(180 - a) = -cos(a), sin(90 - a) = cos(a), and cos(90 - a) = sin(a)

so just plug in appropriately and solve

[languid pine]

ohh

ty

.close

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[marble ermine]

hi

[zealous compass]

whats the question?

[marble ermine]

I found that both transformations are not $\mathbb{C}$ - linear but R-linear

is that correct?

[zealous compass]

me thinking this was math i knew

what math is this?

[wraith dagger]

lilisworld

[zealous compass]

aren't they maps?

whatever i cant help sorry

[marble ermine]

i dpnt understand

its linear algebra

[fast sundial]

Is there a graph given?

[marble ermine]

no

<@&286206848099549185>

well the question is "Are they C-linear? R-linear?"

[elfin hemlock]

Yes its correct

[marble ermine]

C-linear and R-linear means that scalar should be either from C or R set right?

[marble ermine]

ok thx

.close

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[woven tapir]

This last question has me stuck. I know all the basics of trig, but I just don’t know how to do everything in this 😦

[ember siren]

Bro what grade you in

[woven tapir]

I knew someone was gonna say that

11 💀

[ember siren]

Broooo

[woven tapir]

But it’s split with 10

[ember siren]

I dont wanna go to highschool

[woven tapir]

So you can’t help I’m guessing 😁

[ember siren]

Im just a 8th grader

[woven tapir]

8th grade is highscool for me because Canada

[ember siren]

Im just looking at these helps to see whats up

[ember siren]

DUDE WHAT

Dam

[woven tapir]

Do you need help? 😁

[ember siren]

Yes

[gusty jasper]

you can use SOHCAHTOA for that

[ember siren]

da hell is that

[gusty jasper]

because you know that 78 degree angle, and you know B is a right angle with the top, you can find CBD

[ember siren]

Oh you mean @woven tapir mb

[woven tapir]

I’m still confused 😄

[gusty jasper]

do you see how you can find angle CBD?

[woven tapir]

180 rule?

I’m feeling dumb today

[gusty jasper]

so you know that top line forms a right angle with line B

and you know that big curve is 78 degrees

so the rest of it would be 90 degrees - 78 degrees

once you know that little angle, you can calculate angle ABD

[woven tapir]

Oh I see

[gusty jasper]

once you know ABD, you can calculate DAB

and once you have DAB, you can use SOHCAHTOA to find the length of AD

then, because you have CBD, you can use SOHCAHTOA to find the legnth of CD

then subtract CD from AD to find AC

[woven tapir]

Okie

I would do 78 - 36 to get 42 degrees in the abc triangle right ?

Almost done

Ignore the picture

[gusty jasper]

yeah

but you also know ABD because you know CBD and ABC

then you can use SOHCAHTOA on ABD to find the length of AD

[woven tapir]

Thank you for helping

@ember siren did you get help?

[ember siren]

Ye

[cedar kiln]

@woven tapir Has your question been resolved?

[cedar kiln]

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[agile widget]

for question C (ii) do i multiply the acceleration of gravity with the height it was dropped from in order to find the velocity?

[agile widget]

so 9.8m/s x 4m?

[craggy oriole]

Not really a maths question, but what would be the units of acceleration × distance?

[obsidian coral]

Technically it is math related, what you mean is, it's more physics related than the usual math topics

[agile widget]

velocity?

[craggy oriole]

Units as in m and s, acceleration is m/s² and distance is m, so their product is m²/s²

[agile widget]

im totally lost, it's my first time doing physics

[craggy oriole]

Ultimately ever question is a math question

[agile widget]

.close

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[celest otter]

if A and B are sets, Is A ×B = B ×A?

[craggy oriole]

They are not equal but they are isomorphic

[celest otter]

Ok so the order of an element in a set matters

set {(1,a)} is not equal to {(a,1)}

and (1,a) is not an element of set {(a,1)}

[craggy oriole]

Unless a=1 they are different sets

[celest otter]

ok

[celest otter]

and (1,a) is not an element of set {(a,1)}
^ this is correct right

[scarlet garnet]

yes

[craggy oriole]

Same, unless a=1

[scarlet garnet]

point points are defined such that (a,b) = {a,{a,b}}

[celest otter]

ok thanks @craggy oriole and @scarlet garnet

.close

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[heady echo]

how do i approach this question ?

[cedar kiln]

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[red pumice]

n^2 - m^2 = 27

n, m integers

[summer charm]

hmm.

which one is greater?

im not relaly sure..

[red pumice]

i think the question is kinda weird

[summer charm]

same..

[red pumice]

but theres multiple possibilities i guess

36 - 9 = 27

6^2 - 3^2 = 27

and i guess another solution

[summer charm]

soo...

which one is bigger?

so what would be my answer

im kinda confused

[red pumice]

theres another solution

you need to find it

[summer charm]

hmm.

uhhhhhhh lets see.

[red pumice]

write it as (n-m)(n+m) = 27

then 27 = 3 * 3 * 3

so 27 = 3 * 9

but we already have that solution

[summer charm]

ummmm im thinking lets see

[red pumice]

27 = 27 * 1

[summer charm]

OOHHHh yeah

that.

we can do that

[red pumice]

yes

(n-m)(n+m) = 1 * 27

[summer charm]

ok

soo what would be the answer im still kinda lost

[red pumice]

alright so we know that n + m > n - m since n and m are whole positive numbers

[red pumice]

so from this we can setup 2 equations

namely

n+m = 27

n - m = 1

[summer charm]

now solve by system of equations?

[red pumice]

exactly

[summer charm]

,w n+m = 27
n - m = 1

[wraith dagger]

Results provided by WolframAlpha

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Requested by Spetsnaz_Comrade#1591

[summer charm]

is that correct?

[red pumice]

thats not quite right

i think wolframalpha interpreted it wrong

point is

the answer is

n = 14

m = 13

then

,w 14^2 - 13^2

[wraith dagger]

Results provided by WolframAlpha

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[summer charm]

hmm that means the answer is 14?

[red pumice]

13

they ask for the side of the smaller square

[summer charm]

oh mb

i read it wrong

🤣

[red pumice]

haha yeah happens to me all the time 💀

[summer charm]

u mind helping me on this too?

i'm kinda confused..

[red pumice]

N must be a prime

well

not really

it must not have any common factors with 3 or 5

[summer charm]

yeah not really..

yeah.

so that means ummmm.. hmmm

[red pumice]

so all the numbers between 10 and 100 that arent divisible by 3 or 5

but i should go

perhaps open a new channel

[summer charm]

u need to go?

.done

.close

[cedar kiln]

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[tame granite]

alright so

to start

whats the formula for cone volume

[meager plinth]

pi(rsquare)(h) divided by 3

[tame granite]

pi * r^2 * h/3?

ok

so

ur gonna set the equation equal to 55

[meager plinth]

yeah

[tame granite]

and set 5 as the height

[kindred elk]

Ok So

[tame granite]

pi(r^2) * 5/3 = 55

now solve that

[kindred elk]

I need help this is rreally har

[tame granite]

luc this isnt how the server works

go to math help (available) category

and select a help channel

rn help-32 and help-48 r open

[kindred elk]

This one

[meager plinth]

bro

[tame granite]

you're

[kindred elk]

HArd

[meager plinth]

stop trolling

[tame granite]

in third grade

ok

[kindred elk]

No i got held back

[tame granite]

mm

[kindred elk]

Im special

[meager plinth]

...

[kindred elk]

But i wanna graduate

[tame granite]

<@&268886789983436800>

[kindred elk]

Im serious

Wait so how does it work

How i geyt help

[meager plinth]

use a channel thats not occupied

[tame granite]

i already explained if ur serious which u r not

[meager plinth]

#❓how-to-get-help

read that channel

[kindred elk]

oKAY THABNKS

Thanks

[meager plinth]

np

[tame granite]

🤨

ok so

youve got

pi * r^2 * 5/3 = 55

how r u gonna solve

[meager plinth]

isolate r square??

[tame granite]

id start w making it simpler

if i see 2 numbers

i can j divide both sides by 5/3

so ur getting rid of it on the left side to make there be less terms in the equation

[meager plinth]

so 5 divided by 3?

[tame granite]

nah

ill draw it out gimme asec

[meager plinth]

👍

[tame granite]

@meager plinth

[meager plinth]

o

[tame granite]

Since ur dividing a fraction ur multiplying by reciprocal right

so you'll have

[meager plinth]

165 over 5

[tame granite]

Which is 33

Alternatively if u wanna learn smth rq

Do u know how like

U have a 55 and a 5 there

[meager plinth]

yes

[tame granite]

So u can factor out a 5

U can do one of these

And it becomes 11 * 3

[meager plinth]

yeahh cross multiplication

[tame granite]

Which is a much easier equation yk

[meager plinth]

i learned that before

[tame granite]

Ok anyway

So

You now have

πr² = 33

r u guys j using 3.14 as pi or do u get calculators or what

[meager plinth]

my teacher said you can use either

i just use 3.14

[tame granite]

Ok so

Now we'll isolate r

By dividing both sides by π right

[meager plinth]

wait holdup

so

yk how you did 5 over 3

[tame granite]

Ye

[meager plinth]

and you put it under the 55

[tame granite]

Ye

[meager plinth]

what do you do there

[tame granite]

Ok so

It's not incredibly intuitive like if u were dividing smth like 4 ÷ 2

When ur dividing smth by a fraction

U instead r gonna multiply by the reciprocal of it

For example

1 divided by ½

Equals

2

Because the reciprocal of ½ is 2 over 1

[meager plinth]

OH YEAH

[tame granite]

So it ends up being 1 * 2

[meager plinth]

so then we got 33

[tame granite]

Ye ye

[meager plinth]

know i get it

[tame granite]

So ur dividing it by pi right

[meager plinth]

yeah

[tame granite]

So it'll be r² = 33/π

[meager plinth]

10.50

[tame granite]

Alright so

r² = 10.5

do u know how to get rid of the ²

[meager plinth]

not sure

do we square 10.5?

[tame granite]

nop

you square root both sides

[meager plinth]

ohh

[tame granite]

u do that w a calculator

ye

its the same thing w being raised to like a 3

[tame granite]

u j do the cube root

thats ur answer yup yup

remember to round it

[meager plinth]

👍

[tame granite]

have u learned how cube roots work

[meager plinth]

3.3

[tame granite]

No

it would be 3.2

[meager plinth]

ohh

[tame granite]

have u learned how cube roots work btw

[meager plinth]

yeah i think so

i remember doing this

[tame granite]

do u know how to raise things to a fraction power

[meager plinth]

nope

im in gr 9

do i learn that in gr 9

[tame granite]

im in grade 10

U will yeah

[meager plinth]

ohh

[tame granite]

Ur taking trig right

Or r u in geometry

[meager plinth]

yeah

[tame granite]

Alright ready

[meager plinth]

learning surface area volume perimeter area and stuff

[tame granite]

So

Yk how when a coefficient is 1 u don't write it

Like instead of saying 1x u j say x

[meager plinth]

yeah

[tame granite]

Roots r like that too

Where there's a little number there saying what kind of root it is

[meager plinth]

wait hold up

i dont think im gonna learn this

bc

tmrw i have a unit test

[tame granite]

eventually u will

[meager plinth]

and after the unit test we are gonna learn about lines

[tame granite]

here ill get u a head start it'll take like 5 min

[meager plinth]

kk

[tame granite]

you'll learn it next year then

It's also this

Rifht

[meager plinth]

yeah

[tame granite]

I'm boutta blow ur mind

[meager plinth]

ok lol

[tame granite]

same thing as x to the ½ power

U j transfer the things

[meager plinth]

ohh

[tame granite]

it works w any fraction see

[meager plinth]

so 3 then square root of x and 1 on top

would be x1/3

[tame granite]

yessir

[meager plinth]

W

[tame granite]

cube root x is x to the ⅓

wanna learn how negative powers work

it's super simple

[meager plinth]

sure

[tame granite]

When there's a negative

U j put a 1 over it

[meager plinth]

YEAH I REMEMBER LEARNING THIS

[tame granite]

whoo

I'm gonna go grab microwave popcorn see ya

[meager plinth]

bye

thanks for helping

[tame granite]

i gotchu

[meager plinth]

.close

[cedar kiln]

Channel closed

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[tame granite]

ping me if u need anything else

ever

i gotchu

[meager plinth]

👍

BET

can i add you on discord?

[tame granite]

i gotchu

[meager plinth]

thanks

W mans

[cedar kiln]

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• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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[crimson sedge]

How do i find the area under a downward facing parabola?

[craggy oriole]

That's the integral

[crimson sedge]

how use

[obsidian coral]

Do you know what an integral is?

[crimson sedge]

kinda

its like that s thing right

[obsidian coral]

$\int$

[wraith dagger]

dldh06

[crimson sedge]

and it tells you to integrate infinitesimally thin rectangles for a function

right

[craggy oriole]

Precisely

[crimson sedge]

so how would i use that for a quadratic function?

lets say f(x) = x^2 + 2

[craggy oriole]

,w integrate x^2+2 from 0 to 1

[wraith dagger]

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[craggy oriole]

For example

[crimson sedge]

:0

@obsidian coral why leave me

.close

[cedar kiln]

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[toxic quartz]

have i set up the integral correctly

[flint plinth]

there should be a difference somewhere, since it's the area between two curves

[toxic quartz]

so im supposed to do x^2 - x?

i thought that was only when it was bound :/

[flint plinth]

not quite right

you want g - f where g is the bigger one

but

x is bigger than x^2 on [0,1]

and x^2 is bigger than x on [1,2]

[toxic quartz]

right ok i get that

[flint plinth]

so you should break it into two intervals

[toxic quartz]

so i should make it

one sec

like this ?

[flint plinth]

yep that's what you want

[toxic quartz]

ah okay 😄

thank you so much

[flint plinth]

sure

[toxic quartz]

.close

[cedar kiln]

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[bronze pivot]

can someone check please

am I wrong 😦

[gusty jasper]

chceks out to me

[bronze pivot]

fr?

[cedar kiln]

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[versed kayak]

bruh lmao

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[glossy vale]

Hello, just wanna know if I did this the right way 'cause it's been a while since I last factored a polynomial.
6w^4 - 10w^3 + 2w, GCF=2w
6w^4 / 2w=3w^3, 10w^3 / 2w=5w^2, 2w / 2w=1
Therefore, 2w(3w^3 - 5w^2 + 1)

[versed kayak]

yea its right

[glossy vale]

Great! Thank you so much!

[versed kayak]

npnpnnp

[glossy vale]

Uhh, how do I let the bot know that the question has been resolved?

[versed kayak]

.close

@glossy vale

[glossy vale]

Oh, a'ight. Thanks again.

.close

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[drifting isle]

Trying subtracting method why is this wrong

[runic garnet]

At the start

-6y - (-3y) = 12

It’s not 12

[drifting isle]

Ahhh yep I see

12+-6

[runic garnet]

No

-6-12

Because u subtracted eqn2 from eqn1

[drifting isle]

Wait whaaat

[runic garnet]

What are u confused abt

[drifting isle]

The 6x subtracted from the 6x and then I thought it’s -6y - (-3y) = -6+12

[runic garnet]

Why -6+ 12

[drifting isle]

Because the first two equations don’t they have to be added together

[runic garnet]

U subtracted them

Which is fine

But u gotta do it to the whole equations

Not just the part before the equals sign

[drifting isle]

That’s why I tried minusing -6 from 12

I thought that was how you join them

[runic garnet]

U subtracted the second equation from the first

So we have to minus 12 from -6

[drifting isle]

Ahhhhh

12 - (-6)

[runic garnet]

No

-6-12

Subtracting 12 from -6

[drifting isle]

Ok I see

Geez idk why it’s confusing im tempted to use substitution on this sob, but I need to learn this method aswell

so why are subtracting the bottom equation from the top equation

[runic garnet]

U subtracted the bottom from the top to get rid of the x term

We coulda also done bottom-top

[drifting isle]

Well didn’t I go -6y -(-3y) isn’t that subtracting top from bottom

[runic garnet]

No u subtracted the bottom from the top

That’s what -6y -(-3y) is

Just some tricky English ig

[drifting isle]

But 6 minus 3? Isn’t that subtracting 6 from 3 top from bottom

[runic garnet]

Top minus bottom isn’t the same as subtracting top from bottom

Top minus bottom = bottom subtracted from top

[drifting isle]

My heads going to explode..

So the ?-? Always the one on the left is what is being like attacked and subtracted from?

I need an easy way to remember

[runic garnet]

Yea ig

[drifting isle]

Ok I thiiiink Mayby I got it

[runic garnet]

For ur problem above, u coulda done top-bottom or bottom-top, doesn’t matter same answer

[drifting isle]

Yeaah I just need to remember to stick to one way because I guess I’m having trouble telling the difference when subtracting

Thanks for the patience and help

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[fleet wedge]

How do I solve this. I tried to solve it but i can't get the solution

[muted bear]

do you know the angle bisector theorem

[fleet wedge]

oh

thanks

[muted bear]

hope that worked!

[fleet wedge]

.close

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[fast stag]

a

[fast stag]

why is the limits of g(x) 1 to x and not y to 0

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@crimson sedge Has your question been resolved?

[long swan]

What

,w 12a + 24b = 10, 25a+18b = 18, 13a + 34b = 15

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Mr. Gamer#6658

[long swan]

Welp

We know its not a linear combination

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[misty berry]

I dont know what im missing

[misty berry]

ty

.close

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[crimson sedge]

Glad to help.

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[misty berry]

this question is giving me a stroke can someone help me?

[crimson sedge]

What have you tried

[misty berry]

i got 35

[crimson sedge]

That's right

Good job

[misty berry]

ok thank you

[sacred grail]

what if its 21

[misty berry]

https://tenor.com/view/indignation-jump-window-done-gif-3443826

alr ty

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[short blade]

me when 21-7 = 28

[sacred grail]

-21

[misty berry]

no more

please

i cant take it

[short blade]

32

57

[crimson sedge]

It just is dw
[
\abs{x-28} = 7
]

[short blade]

88

[wraith dagger]

♡LexQa♡

[misty berry]

extra credit is done 😍

[floral forge]

No because the difference of 21 and -28 is not 7

Oh waot i think im being retatded now lol

[misty berry]

happens to the best of us

[sacred grail]

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[wild belfry]

https://gyazo.com/e8ffaa657dde4e0e2a2d684dff9e4d5d.png

[short blade]

recall that $a^{\log_a(b)}=b$

[wraith dagger]

maximo

[tropic oxide]

recall also that log_1(x) is undefined

[short blade]

so do x^both sides

[wild belfry]

I got the right answer but only putting sqrt4(0.0001) in my calculator, I'm not allowed a calculator in my exam, is there any way to do this without a calculator?

[short blade]

.0001 = 1/10000

then $\sqrt[4]{\frac{1}{10000}}=\frac{1}{\sqrt[4]{10000}}$

[wraith dagger]

maximo

[wild belfry]

aaaaaaaah I see

Thank you thats a nice way of doing it!

Thanks everyone for the help ❤️

[short blade]

yeah, also notice that if you did 1^4, you’d be back to 1, not .0001

so you can also sus it out a little if you can’t do the fourth root

[wild belfry]

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[heavy lark]

So I'm fairy certain the equation would be 96= (9A) - B

But I'm just confused on where to go from there

[tropic oxide]

are A and B the numbers you're asked to find?

[heavy lark]

Yes

[tropic oxide]

then your equation is incorrect

[heavy lark]

How should I put it?

[tropic oxide]

and it's also incomplete, because there really should be two equations

A - B = 96 and A = 9B

[heavy lark]

How would I go about finding A?

Or, B, I guess, because we need B to find A

[tropic oxide]

it is easier in this case to start by finding B

you can substitute the second equation into the first

[heavy lark]

So would it be "(9B) - B = 96"?

[split crest]

x-y=96
x=9y

9y-y=96

8y=96

/8

[livid hound]

...

[split crest]

y= 12

[livid hound]

don't give out answers

[split crest]

oh

im sorry

[livid hound]

and/or effectively repeat what's already been said

[tropic oxide]

yes, exactly. though those parentheses are redundant.

[tropic oxide]

well, you know how it is. people deem things i say to be worthless unless somebody else repeats them.

[cedar kiln]

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[spice sonnet]

Please show me the work to do this

[copper crest]

Multiple numberator

And denominator

By √6

And √p for second one

[spice sonnet]

Hmmm

Could you write out and send a pic to me instead?

As if your showing your work?

[short blade]

$\frac{1}{\sqrt{x}}=\frac{1}{\sqrt{x}}\cdot \frac{\sqrt{x}}{\sqrt{x}} = \frac{\sqrt{x}}{x}$

[wraith dagger]

maximo

[short blade]

just replace x with whatever number is in the denominator

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[digital bloom]

What does ‘ the solutions for general p are not elementary’ mean?

[foggy merlin]

context ?

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[boreal epoch]

Hello I'm trying to type an algorithm that basically finds the number of different ways square shapes can fill a random given XY Grid

For example there is only 1 way to fill 1x1 grid and that's by putting a 1x1 square, there are 2 ways to fill a 2x2 grid first is 4 1x1 squares and second is 1 2x2 square, how can I approach this problem without brute force?\

[boreal epoch]

from gathering data (with small grids) i could guess it could be done with some sort of combinations formula but in 2D im kinda lost

[cedar kiln]

@boreal epoch Has your question been resolved?

[boreal epoch]

<@&286206848099549185>

[inland fossil]

do they all have to be the same shape

or are you allowed to mix and match them

i.e. for 3x3, one 2x2 in the middle and 5 1x1's on the outside

[cedar kiln]

@boreal epoch Has your question been resolved?

[boreal epoch]

3x3 has no middle for 2x2

4x4 has a middle for 2x2

but all i want is the number of combinations

these are all the combinations for 3x3 grid

[inland fossil]

i meant middle to bottom right or whatever

you can fill in a 3x3 with 1 2x2 with 5 1x1's

[boreal epoch]

4*

[inland fossil]

no its 5 lol

[boreal epoch]

i don't need the number

of squares

i need the number of total combinations

that the squares can be put

[inland fossil]

sure

[boreal epoch]

for example my algorithm should output number 6

[boreal epoch]

for this 3x3 grid

[fair geyser]

even with just square grids you have to bruteforce

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[wispy meadow]

please help im stuck here idk what to do

<@&286206848099549185>

[cedar kiln]

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[wispy meadow]

<@&286206848099549185> plz

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[jagged obsidian]

Hiii

[cedar kiln]

Please don't occupy multiple help channels.

[dire geode]

[jagged obsidian]

Hi @dire geode

I m having trouble solving a problem

Do you mind helping me

[dire geode]

this means just post your question

right now i have nothing to help with

so you pinged me but i have nothing to do

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[odd needle]

can someone help me with these its laplace transform

[odd needle]

can someone help me?

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@odd needle Has your question been resolved?

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[shrewd monolith]

how do i solve -16x^2 + 20 + 75=0

[cedar kiln]

Please don't occupy multiple help channels.

[tame granite]

Have u tried quadratic formula

[cosmic steppe]

Quadratic formula goes crazy

[shrewd monolith]

it does go crazy

lemme solve it and can you tell me if its right

[tame granite]

quadratic formula my beloved

[tame granite]

Wait so it's + 95?

Or 20x

[shrewd monolith]

my bad 20x+75

=0

[silk laurel]

Oh

15 and 5?

[tame granite]

I don't think that works bc of the -16

[silk laurel]

Oh wait

I forgot bout the -

And 16

[shrewd monolith]

this is the whole thing

[silk laurel]

Did you tried the abc formula?

[tame granite]

I think quadratic formula doesn't work

Bc I think u end up square rooting a negative

Wait nvm

don't talk to me im dumb

[silk laurel]

Everyone can be dumb sometimes in math

[shrewd monolith]

here is the whole problem

[tame granite]

That's

A diff equation than the one you sent

[dire geode]

lol

[silk laurel]

Um...

[dire geode]

you weren't the dumb one after all

[shrewd monolith]

the second paragraph

[silk laurel]

Doesnt thst become -16x^²+20x

[shrewd monolith]

has -16x^2 +20x + ___=0

[tame granite]

Well #1 is -5

[shrewd monolith]

wait how

[tame granite]

u subtract 75 from both sides

[silk laurel]

I mean

[tame granite]

75 - 75 = 0

[silk laurel]

-5

[tame granite]

70 - 75 = -5

[silk laurel]

Mb

Ye

[shrewd monolith]

its telling me to rewrite the equation

[tame granite]

Yeah

[silk laurel]

You remove 75 from both sides

[tame granite]

It rewrites it by setting it equal to zero

[silk laurel]

Remove 75 to make it 0

[tame granite]

You rewrite it by filling in the blank w -5

[shrewd monolith]

what goes in the blank bruh

oh

[silk laurel]

-5

[agile moat]

quadratic giving sqr 5200 my gosh

[silk laurel]

70-75=-5

[shrewd monolith]

im not seeing where 75 can be subtracted to get -5

in this -16x^2 +20x + ___=0

[tame granite]

70 - 75

[silk laurel]

The 75 becomes 0

So you do 75-75

[shrewd monolith]

theres no 70 there

[silk laurel]

=0

[tame granite]

Y

Yeah

Because

It's being subtracted

The 70 is becoming a -5

that is why there is not a 70

it becomes a -5 after subtracting 75

[shrewd monolith]

i dont get it but whatever

[silk laurel]

Like this

[shrewd monolith]

ok -16x^2 +20x + -5 =0

[tame granite]

it isn't whatever ur here to learn

let's stop and show u how it works

[silk laurel]

Forgot to put x

[tame granite]

ye

[shrewd monolith]

ok well i didnt get that cuz its telling me to fill the blank and not to solve and fill in the blank

[silk laurel]

Because 75 turned into 0 you have to subtract 75 from 75 to mske 0

[tame granite]

It's transforming it from the previous equation

If u see smth that first says 75

And then it's 0

[silk laurel]

What you did on the right you have to do it on the left too

[shrewd monolith]

i see it now

[tame granite]

then I think it's p reasonable to assume u took away 75

[shrewd monolith]

ok moving on, do i do the quadratic formula now?

[silk laurel]

Ye

[tame granite]

-16x² + 20x - 5

[silk laurel]

You can use abc formula

Right?

[shrewd monolith]

what is that

[silk laurel]

Or you didnt get it yet?

[shrewd monolith]

get what yet the formula?

[silk laurel]

Ye

[shrewd monolith]

im not sure if we learned that yet

but maybe we did it doesnt sound familiar

[tame granite]

i actually dk the abc formula

im googling it and it's j bringing up quadratic formula

[silk laurel]

This

[shrewd monolith]

it looks like the diet version of the quadratic formula

[silk laurel]

I thought you would learn this with the quadratic formula if you cant find x

[shrewd monolith]

what is the square root of 5

i forgot how to find square roots on calculators

[agile moat]

couldnt he use ruffini?

[shrewd monolith]

whats that

[craggy oriole]

,w sqrt(5)

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by ralvrz#3477

[silk laurel]

@shrewd monolith

[shrewd monolith]

yes

[silk laurel]

Thats what it came up

[shrewd monolith]

-5 is the b value?

[silk laurel]

No

Ax^2+bx+C=0

B is 20

C is -5

[shrewd monolith]

then why did you put 5+-

at the end

[silk laurel]

There is 2 x answers

[shrewd monolith]

how did you get 8 from 2 (-16)

[silk laurel]

No

Those 2

Are the x value

Aka the answer to the formula

[dire geode]

halt is gonna be a quadratic formula pro now

[shrewd monolith]

lol

[shrewd monolith]

so this is the answer to the problem?

[silk laurel]

Yes

If you type that in calculator

You can see the decimals too

[agile moat]

did you guys got the roots?

[shrewd monolith]

it just gave me the same thing

[silk laurel]

Wdym same thing

[shrewd monolith]

it didnt give me the decimal

[silk laurel]

Did you press s=d

The S<->D

[shrewd monolith]

I don't have that

[silk laurel]

What calculator are you using

[shrewd monolith]

Ti-36x pro

[silk laurel]

@shrewd monolith

See if x is correct

Try both x

[agile moat]

i tried ruffini but doesn't help in this case sadly

[cedar kiln]

@shrewd monolith Has your question been resolved?

[shrewd monolith]

Yes

[cedar kiln]

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[upbeat pond]

What does bearing mean ? Does anyone know

[upbeat pond]

this is what its supposed to look like but . i dont get it

[livid hound]

(true) bearing would be the angle measured clockwise from north

[upbeat pond]

OHH

that makes sense

Whats he doing with the 10 degrees and 350 degrees stuff

[snow grail]

The 10 degrees is in the other direction

[upbeat pond]

ohhh

what does vertical triangle mean?

or horizontal

[snow grail]

When they’re talking about angles of depression and elevation, imagine you are standing on a ladder looking at a tree

You can look directly at the tree with a straight line, the base of the tree has some angle of depression that points down and creates another line from you to the base of the tree, which the trunk of the tree connects to make a vertically oriented triangle

You can use the same reasoning for the top of the tree, with an angle of elevation making a line to the top of the tree and the trunk connecting the level line to the top line to create another vertically oriented triangle

In this case, you have two trees and are standing on a 30m tall ladder and need to find the distance on a flat plane between two bases of trees

[upbeat pond]

Can you draw what this looks like so I can get a better understanding ?

[snow grail]

One second

I’m no artist so I’m just going to draw a triangle and label things

[upbeat pond]

thats fine no worries

[snow grail]

It’s a modern masterpiece

[upbeat pond]

Ohh that makes more sense

[snow grail]

The point on the left is the observer

So you’ll just need to use sin or cos with the angles of depression

Wait no, tan

[upbeat pond]

like this stuff?

[snow grail]

If you use tan you can get right to where you need to be, since it’s $\frac{opposite}{adjacent}$

[wraith dagger]

Helmfirth

[upbeat pond]

Oh true true

[snow grail]

Once you find the level distance from observer to person, you can use sin and cos to find coordinate values of their locations and then use distance between two points

[upbeat pond]

I will write that down ✍🏻

can i ask u another question

[snow grail]

If you go that route I recommend rethinking the angles by orienting it counterclockwise with respect to the positive x-axis

And go ahead, ask away

[upbeat pond]

Oh okay

[upbeat pond]

How would one approach the diagram of this question

[snow grail]

First, recall that bearing is degrees clockwise with respect to north, so start by orienting the angles of the boat

[upbeat pond]

Okay

Wait does this look right cause im confused

[snow grail]

That skips to step 3

Find out what the angles are

[upbeat pond]

How do i find out the angles ?

[snow grail]

Do you know your parallel angle theorem?

[upbeat pond]

Yes i sort of remember it

[snow grail]

Do you think you can get it on your own with just that or do you need a refresher on exactly what it is?

[upbeat pond]

I need help

Idk how to apply it to that triangle

[snow grail]

Imagine that the x and y axes are still present at the sailor and red lighthouse, and extend each line if necessary

[upbeat pond]

Oh okay

hold on i need to draw it

[snow grail]

The diagram with axes and extended lines should look like this

After this, use the parallel angle theorem and complementary angles to solve for the angle values

[upbeat pond]

I drew it before i looked at ur diagram

Does this look right?

[snow grail]

Exactly

So now use parallel axis theorem and complementary angles to solve for the interior angles of the triangle

[upbeat pond]

im gonna be honest idk how to do that can u help

I Swear i know the transverse thing but my brain is blanking right now

Idk where to start

[snow grail]

Start with the vertical lines and the line from sailor to red lighthouse

Ignore the horizontal lines for now, if needed erase them entirely

[upbeat pond]

Okay

nvm Im ser iously lost can u show me ur process

[snow grail]

This is the parallel angle theorem

Each single angle is equivalent and each double angle is equivalent

[upbeat pond]

?

[snow grail]

Looking at only the vertical lines and the one from sailor to red, what is the bearing from red to sailor?

[upbeat pond]

Im gonna guess like 30 degrees

[snow grail]

Do you recall the numbers from the beginning?

[snow grail]

The bearing from sailor to red is 200 degrees, or 20 degrees west of south

[upbeat pond]

Yes

Wait so the answers 20 degrees?

R u subtracting 200 - 180

[snow grail]

Yeah, the angle between the negative y axis and the line from sailor to red is 20 degrees

[upbeat pond]

Ohhhhh

so u'd put it like this ?

[snow grail]

Exactly

Now we move on to the horizontal lines

What’s the bearing from red to blue

[upbeat pond]

340

OH

So the other angle would be 20

?

[snow grail]

Yes

[upbeat pond]

omgoshhh

thank you sm

[snow grail]

No problem

Do you know how to get the base angles?

[upbeat pond]

Hold on let me think about it

uhh no

[snow grail]

Let’s start with complementary angles