help-13

[crimson sedge]

Cannot get wolfram to show me the steps

[upper abyss]

That should not be true, as it would imply the complex number is equal to its conjugate

True for real numbers!

[dire geode]

Not even true for z=i

[crimson sedge]

Hmm.. feeding wolfram $\frac{z}{z^{*}}$ returns 1

[wraith dagger]

SillyRaccoon

[crimson sedge]

My thought exactly!

Don't know.. I am confused tbh

Original question mentions: is it possible to find a z where z / z* = 2

And then proceeds to answer it with the help of absolute values

[dire geode]

This is only true for real numbers

Which is what wolfie defaults to

[dire geode]

Try calculating this yourself for any complex number

[cedar kiln]

@crimson sedge Has your question been resolved?

[flint plinth]

it's true that |z / z*| = 1

questions like this are easy to solve using polar coordinates

[crimson sedge]

Should've done that instead tbh!

[crimson sedge]

The answer is $\frac{a^2 +2abi + b^2}{a^2 + b^2}$ and therefore never real afaik

[wraith dagger]

SillyRaccoon

[crimson sedge]

Where $z = a + bi$

[wraith dagger]

SillyRaccoon

[cedar kiln]

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[acoustic bear]

mb

[brazen bolt]

I need help with part b

let me send a picture real quick

[rough lynx]

what have you done so far?

[copper crest]

Use eqns of motion

S=ut + half at^2

[brazen bolt]

thats like part a

the problem is I cannot solve that equation

[brazen bolt]

just posted my bad for delay

<@&286206848099549185>

[brazen bolt]

can you help?

[copper crest]

a(2)

[brazen bolt]

?

[copper crest]

Is the acceration after first 2 seconds

[brazen bolt]

ok

[copper crest]

Use this

[brazen bolt]

i want to know the time it takes for the object to travel the first two meters tho

[copper crest]

Ok

[brazen bolt]

can you do the way im doing

cause i wanna do the way my teacher did

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@crimson sedge Has your question been resolved?

[cedar kiln]

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[toxic moat]

,rccw

[crimson sedge]

5/8 of the attendees were female... This means ---- were not female @crimson sedge

fill in the blank for ----

[undone halo]

whats the fraction for everybody who visited

so 5/8 of that entire crowd is 105 correct

if you add the unknown amount of 3/8 people you get everybody

so i dont know what you would do but what id do is find what is 1/8 of the total amount

[crimson sedge]

You actually don't need to do any of that since they are just asking u for the total

So @crimson sedge

Let's say 'x' is the total amount of people in the thing

When we want to describe the amount of female attendees in terms of x, what do we write?

We already know whatever that is also equal to 105

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

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[wild quail]

just need help starting it

[foggy merlin]

you check the differentiability on the left and on the right

[crimson sedge]

You just need it to be continuous at $1$ then. Equate $x^4-4x^2+3=ax^2+b$, solve for b.

[wraith dagger]

3317

[wild quail]

i got b = 2

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[crimson sedge]

tan^-1(tan(x))=x, then what about tan(tan^-1(x))???is it also x??

[crimson sedge]

yes

tan^-1(tan(x)) isnt x tho

its only x from -pi/2 to pi/2

k thx for info

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[crimson sedge]

.close

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.reopen

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✅

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[native mango]

If you wanted to choose an X so that the probability of you choosing an X that is greater than or equal to lets say 20 is 1/20, how would you do it?

So more formally Probability of choosing an X >= k is 1/k

[crimson delta]

Seems like you can explicitly write down a density function

f has value 1/2 between 1 and 2, value 1/2-1/3=1/6 between 2 and 3, value 1/12 between 3 and 4 and so on

[native mango]

Could you dumb it down for me hehe, not exactly following. Just me being slow, takes some time for things to click for me.

.solve

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[merry heath]

can someone guide me through how to solve this using factorisation method?

[tropic oxide]

well the first step would surely be to multiply both sides by 3 to get rid of the fractions

[crimson sedge]

Wait, is that a mixed fraction first?

[tropic oxide]

surely it is

[gusty vine]

who uses mixed fraction

[crimson sedge]

26 whole parts and 2/3?

[gusty vine]

[crimson sedge]

Yes, just wanted to make sure it is not a multiplication. Since if it is a mixed fraction, could lead to the error of thinking $26\frac{2}{3} \cdot 3 = 26(2)$ or something

[crimson sedge]

Literally true

[merry heath]

wow I'm dumb asf, I never thought about that

[wraith dagger]

♡LexQa♡

[crimson sedge]

$\frac{78}{3}$

[wraith dagger]

Mathematician? probably

[crimson sedge]

so after multiplying by 3 you get $12x = -2x^{2} + 80$ and once you rearrange you get $2x^{2} + 12x - 80 = 0$ divide by 2 $x^{2} + 6x - 40 = 0$ solve

I have an inkling it could be a typing error and they meant multiplication

nah

the multiplication sign only disappears with variables

its a mixed frac

I just never see mixed fractions around the time factorisation gets discussed

But fair enough

[merry heath]

I'm going to try it brb

[crimson sedge]

$x = 4\sqrt{3} \pm 3$

[wraith dagger]

Mathematician? probably

[crimson sedge]

if youre factoring i guess you can do it now

[merry heath]

why is it 78?

@crimson sedge

[crimson sedge]

parts * numerator + denominator

wait wait

its 80

mb

i forgot to add the 2

[merry heath]

ahh it makes sense now

[wraith dagger]

Mathematician? probably

[crimson sedge]

this shld be fixed

10 and -4 for sum and product

$(x-10)(x+4)$

[wraith dagger]

Mathematician? probably

[crimson sedge]

thats your factored eq

[merry heath]

I figured it out. Thanks for the help!

.close

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[crimson sedge]

if this is true ^

why is there an n-1 attached to the (-1) here? shouldnt it just be (-1)^n ?

[grand forge]

(-1)^n

when n = 1, u get -1

when n = 2 u get 1

when n = 2 u get -1

but for (-1)*n - 1

when n = 1 u get 1

when n = 2 u get -1

its just started posiitve

instead of negative

thats it

[crimson sedge]

why though? for what reason?

like why would i choose that instead of just n?

[grand forge]

well

it depends

if u want ur first value

neg or positive

[crimson sedge]

this is what the question was

i dont think it stated that

[grand forge]

well what is the first

value

if u were to take the summation

[crimson sedge]

of which series? the one with n-1 or n?

n-1 is = 1 as u said

n is -1

[grand forge]

no

figiure it out

how would u put x^6ln(1+x)

into a power series

[crimson sedge]

yeah i got (-1)^n * x^(n+6)/n

i just didnt get the n-1 attached to the (-1)

simply n

and im wondering why they made me include that in the answer

[grand forge]

lemme see if i get that

:O

btw i only learnt this this year so maybe im just wrong

[crimson sedge]

oh alright

i have finals next week and they JUST threw this at us yesterday

[crimson sedge]

those are two different power series

everything up to this point has been ez as balls so im like what

one has +x and the other -x

[crimson sedge]

i am aware. my question is why is there an n-1 attached to the (-1)

because the signs are alternating

with the frist term being postivie

why cant you just keep it as n though

why does the first term have to be positive

[grand forge]

Because that is the power series

u must've worked it out wrojg

[crimson sedge]

maybe i just have the idea wrong

so im trying to match these values?

[grand forge]

Yea

so when n = 0

the first value is positive

which what u should have

[crimson sedge]

and im trying to match them based on the power series for ln(1-x)

?

[grand forge]

no

the Power series for that is all negative

[crimson sedge]

ok ok so why do i need to make this positive

[grand forge]

u just did ur maclaurin series wrong

thats it

[crimson sedge]

see idek what that is lol i havent gotten that far

[grand forge]

???

so how did u work that out

what

[crimson sedge]

8 hours

thats how

[grand forge]

bro

what

[crimson sedge]

what am i doing

i dont get this

[grand forge]

U need to do maclaurin to do power series

[crimson sedge]

what is that

[grand forge]

u know taylor series?

[crimson sedge]

bro whta

no

[grand forge]

WHAT

HOW IS UR TEACHER

EXPECT U TO DO THISA

[crimson sedge]

thats our friday topic

lol

bro maybe this is why im not getting it right

[grand forge]

did he give u like a base idnetity

that u use to figure it out

[crimson sedge]

no

[grand forge]

Than

idk how to help

[crimson sedge]

oh ok

[grand forge]

unless u teach ur self maclaurin and taylor

[crimson sedge]

i shall go watch some professor leonard

[grand forge]

LOL

khan academy is good

so is organic chem teacher

[crimson sedge]

🫡 good day

[grand forge]

he's my go to

[crimson sedge]

yeah i tried org chem tutor for this

but i had no idea what he was doing

he pulled integrals out of thin air

and confused the shit out of me

oh well

ty

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[crimson sedge]

I was watching a video by the channel: Mind your decisions (https://youtu.be/LWPOlZBXtD8)
Pls, anyone tell the proper reasoning of this.

[sleek condor]

the reasoning is: you cant do what you want with limits and infinity

lim(length(curve)) = / = length(limit(curve))

in calculus terms what we are doing is computing the arc length of the stair curve

this involves the "derivative" of the curve

which itself doesnt converge to 0

[crimson sedge]

ooh, I see

thanks a lot for clearing

[sleek condor]

basically it would work

if the curve approximations flattens out

as you approach the curve

but this one doesnt

[crimson sedge]

Hm Hm, I'm getting it, right!

Thanks 🙂

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[sleek condor]

whatr have you tried?

[valid harbor]

i dont really understand this topics

[sleek condor]

proof by induction?

[valid harbor]

yes

[sleek condor]

ok so a proof by induction is a kind of reasoning thats used to prove a statement Pn that depends on an integer n

and we want to prove the statement Pn for any integer n bigger than some starting integer n_0

usually n_0 is 0 or 1

like in this case

the smallest n that makes sense is 1

so to do so

we need to prove 2 things

that the statement holds for the first integer

and that if the statement holds for one particular integer then it holds for the next one

if those 2 things are true

then Pn is true for the first one

[sleek condor]

but because of this its also true for the second one

but if its true for the second one

[sleek condor]

then its true for the third one

and so on

and so on

all in all this is the same as probing it for all integers

does this make some sense?

[valid harbor]

yes i got it

so how to do the first step for calculation?

[sleek condor]

so we must prove that your statement

holds for the first integer so n=1

,w (1/4)1^2(1+1)²

[wraith dagger]

Results provided by WolframAlpha

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Requested by Benjamin#3570

[sleek condor]

so its indeed equal to 1^3

so the statement holds for n=1

now onto the induction thing

lets suppose that for some integer n

the statement holds

meaning that

$\sum_{k=1}^{n} k ^3 = \frac{1}{4} n^2 (n+1)^2$

[wraith dagger]

Benjamin

[sleek condor]

now we must prove it

for n+1

right?

[valid harbor]

yes

[sleek condor]

so lets study $\sum_{k=1}^{n+1} k^3$

[wraith dagger]

Benjamin

[sleek condor]

do you have an idea of how to use this which we know is true to calculate the sum i just wrote?

[valid harbor]

i think n+1

[sleek condor]

wdym?

$\sum_{k=1}^{n+1} k^3 = (n+1)^3 + \sum_{k=1}^{n} k^3$

thats what i was thinking

[wraith dagger]

Benjamin

[valid harbor]

okay after that we need to proove

[sleek condor]

we are not done

like do you understand why i wrote this?

[cedar kiln]

@valid harbor Has your question been resolved?

[cedar kiln]

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[spring sluice]

Consider the following cuboid whose square base has a side length 13 and whose height is 3cm.
What is the surface area of the largest sphere that can fit inside the cuboid?

[spring sluice]

I tried using the lenght and the width but im not sure which would be correct

i believe it is= 4 * pi * 1.5^2 = 28.3

would that be correct

[tropic oxide]

well, the diameter of the largest fitting sphere is 3cm, so...

,calc 4pi * 1.5^2

oh, the bot is down.

yeah you're good to go

(assuming no rounding nonsense at play)

[spring sluice]

Oh

OK

Thanks

how do i close the bot

[tropic oxide]

.close

[spring sluice]

.close

[cedar kiln]

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[spring sluice]

sorry

i mea

like how do i stop with the occupied space

so someone else can use it

[cedar kiln]

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[lapis wharf]

How do I derive an expression for d[B]/dt ?

My brain is starting to crumble

[dull oxide]

Are you familiar with derivatives at all?

[lapis wharf]

Yes

It’s just i don’t understand this format

[dull oxide]

So you're taking a derivative of [B] with respect to the variable t

Ah you may be more comfortable reading it as [B]'(t)

[lapis wharf]

Yes That looks better than the other way haha

[dull oxide]

You'll need to be familiar with both notations.

I'd say d[B]/dt is a lot more common once you get into higher level stuff.

[lapis wharf]

I get you, finally understand that notation haha , how would I go about this question

[dull oxide]

d[B]/dt basically says "What is the differential change of [B] with respect to a differential change of t?"

[lapis wharf]

Would I be right in saying it wants me to differentiate in respect to B and then divide that by dt?

Or am I lost

[dull oxide]

It wants you to take the derivative of the function [B] with the variable t

This function:

[lapis wharf]

How would I do that, wouldn’t the left hand side of the question just cancel out when u differentiate it ?

Then i just have to derive (e^etc …) by power rule

[dull oxide]

Not sure you what mean

The left hand side is kind of irrelevant

[lapis wharf]

That’s what I meant sorry 🤣

[dull oxide]

To find d[B]/dt is just taking the derivative of this:

Also, cancel out how?

[lapis wharf]

As in When i differentiate left hand side it’ll become 0?

Im very confused idk where to start with taking derivative of this

[dull oxide]

No it won't be zero

How're you getting zero?

[lapis wharf]

I don’t quite know sorry

What would be first step to doing this ?

[dull oxide]

How about just trying to do the derivative then show me what you get

I can help you from there

[lapis wharf]

Oke sure thing

[dull oxide]

looks good

[lapis wharf]

How would I derive for 1/k2-k1 ?

[dull oxide]

don't need to

It's a constant

(with respect to t)

[cedar kiln]

@lapis wharf Has your question been resolved?

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[lapis wharf]

Ur a life saver

Thank you

[dull oxide]

np

[cedar kiln]

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[fathom mural]

how do i do part b and c

[cedar kiln]

@fathom mural Has your question been resolved?

[cedar kiln]

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[loud moon]

i need help

[scarlet garnet]

where exactly are you stuck on?

[loud moon]

im stuck on how to start even tbh

[scarlet garnet]

if its the start, try to come up with the formula for the mass in relation to the decay

I do not know what course you currently attend, but this can be a series, a function or a group

Also very importantly, are you allowed to use a calculator for this?

[cedar kiln]

@loud moon Has your question been resolved?

[loud moon]

yes

[scarlet garnet]

well, then do what I wrote above

[loud moon]

okayy

.close

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[loud moon]

thanks

[cedar kiln]

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[cursive swift]

sisters work spent over an hour doing it

had over 5 different answers please help

yhyh nvm

finally got it

Read it wrong 😭😭

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[idle oyster]

is this an appropriate way to multiply radicals

[cedar kiln]

Please don't occupy multiple help channels.

[idle oyster]

if not, lmk the rules

[toxic moat]

kinda radical

but yes

considering the stuff in the sqrt are positive numbers

so no weird stuff like

sqrt(-1) * sqrt(-1) = sqrt(1)

thats just sus

so take note of that

in this case um

they said r<0

so

its sus

u cant

[idle oyster]

so how am i supposed

to

multiply it out then

cause i still have to simplify it

in order to get my answer

[short pier]

i need help

[idle oyster]

use a help forum #1021175428326633542

or channel

plz ty

[cedar kiln]

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[merry heath]

can someone guide me through all 4 questions?

[merry heath]

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[restive vigil]

Is this vector unique ?

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[fringe ore]

I just need to know if 4.55 + πk is an actual solution to this problem. My homework app is very inconsistent and my textbook is awful.

[fringe ore]

This problem doesn't have a second solution like the first problem.

It marks it wrong when I include the second solution

Again, my homework app is inconsistent. I just need to know if the problem should have two solutions. Theoretically speaking, it should, but both the second problem and Mathway disagree.

<@&286206848099549185>

[cedar kiln]

@fringe ore Has your question been resolved?

[stable talon]

yeah it's got LOADSSS of solutions "d"awg

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[low ice]

How do I find a equation for a perpendicular bisector

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[brazen umbra]

Yo, how do I factor "5x^4 -5"

[brazen umbra]

Kinda dumb question but idk, hard

Oh wait mb

Pull out 5 and diff of squares

Never mind

.close

[obsidian coral]

Yes

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[crimson sedge]

help pls i donu understand this question

[long arrow]

hint: turn it upside down

,rccw

[crimson sedge]

what

[long arrow]

Don't you see the pattern?

it's 86, ?, 88, 89, 90, 91

[crimson sedge]

oh 87

💀 _ _

⚰️ _ _

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[tawny kettle]

guys?

[tawny kettle]

whats 1 +1 i forgot

[haughty wraith]

hilarious

[tawny kettle]

no im serious'

i forgot

whats 1 +1

[craggy oriole]

,calc 1 +1

[wraith dagger]

Result:

2

[tawny kettle]

yay

ty

[cedar kiln]

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[junior timber]

Amelia travelled 2 hours more by train than she did by bus. the train trevelled at 70km/h and the bus at 50km/h. her total trip was a distance of 740 km. what distance did she travel by bus

[junior timber]

x = time of train

y = time of bus

y+2=x

i made an equation but idk if its right

70(y+2)+50y=740

y=5

[craggy oriole]

Looks alright

[junior timber]

okay so now would i just multiply 5 by 50?

cuz distance = speed * time

[craggy oriole]

Yes

[junior timber]

ok ty

[craggy oriole]

[junior timber]

could u help me with one more?

[craggy oriole]

Sure

[craggy oriole]

You'll get two equations and two variables

[junior timber]

yea

so

distance = speed * time

x = time for major road

y= time for secondary road

so

im stuck

[craggy oriole]

x+y=9
70x+60y=580

[junior timber]

ohh ok

so

9-x=y

70x+60(9-x)=580

then solve

[craggy oriole]

That's right

[junior timber]

tysm

[craggy oriole]

[junior timber]

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[drifting solar]

how can I show that the curve with parametric equations x=tcost y=tsint and z=t lies on the cone z^2=x^2+y^2

[drifting solar]

I get that I eventually get like 1=cos^2t+sin^2t

[upper abyss]

Compute x² + y² in terms of t. Turn that into z².

[drifting solar]

right so it would be t^2cos^2t+t^2sin^2t=t^2

[upper abyss]

The algebra behind the conversion is pretty quick

[drifting solar]

right

but what does doing that really do for me

^(this wasn't meant to be rude just like straight up do not know where to go from here)

[upper abyss]

"Lies on the cone x² + y² = z²" means that for every point on your curve obeys x² + y² = z²

[drifting solar]

oh oh

which I proved bc it's true

[upper abyss]

You're using the parametric equations to prove, yeah

[drifting solar]

gotcha

maaaaaaan

I hate when it's there but like a piece of my brain just isn't lol

I appreciate it!

.close

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[light cliff]

Can someone walk me through this question so i can do others like it. Thank you

[light cliff]

.close

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[sterile sierra]

could someone help me with this

[brisk dirge]

just need to integrate and find C,k with the 2 given points

[sterile sierra]

how do u find c

when k is unknown

and vice versa

[long arrow]

2x2 system

and 1st point is (0,1) so then some variable will disapper in the equation

[sterile sierra]

well yes

but the constant will still remain

[long arrow]

and that's the point

solve for the constant

[sterile sierra]

but theres two

and to simultaneously solve it

[long arrow]

can't you solve it

[sterile sierra]

i would have to expand a linear expression to the power of 6

[sterile sierra]

thats why im asking

[sterile sierra]

which seems unlikely

[sterile sierra]

what do u mean by this

[long arrow]

ok so what's your antiderivative

[sterile sierra]

i dont know what that means sorry

[long arrow]

what's your y

[sterile sierra]

y=((kx-1)^6)/3k + c

when x = 0

1/3k + c = 1

[long arrow]

and for x = 1

[sterile sierra]

((k-1)^6)/3k + c = 8

its my working right so far

[long arrow]

let's see

integral is (kx-1)^6/3k + c
for x = 0:
1/3k + c = 1
for x = 1:
(k-1)^6/3k + c = 8

ok

now

[sterile sierra]

where do i go from here

[long arrow]

we can subtract both sides then:
1/(3k) - (k-1)^6/(3k) = -7
1 - (k-1)^6 = -21k
(k-1)^6 - 21k - 1 = 0
let u = k-1 ---> k = u + 1
u^6 - 21(u+1) - 1 = 0
u^6 - 21u - 22 = 0

[sterile sierra]

its u^6

i dont know how to solve with variable of that power

[sterile sierra]

how do i solve from the last line

<@&286206848099549185>

[cedar kiln]

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[sterile sierra]

<@&286206848099549185>

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[cedar kiln]

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[crimson sedge]

Domains:

Is it correctly understood that, in general, the domain of real-valued functions is always (- infinity, infinity)

[crimson sedge]

UNLESS we are dividing or there's a square root involved?

[modern compass]

no

and yet you keep talking

[crimson sedge]

Let me rephrase my question... if we have real-value functions where we only use finding sum, product, difference, or raising a real number by exponents, or taking absolute values of real numbers, then the domain is (- infinity, infinity), right?

[modern compass]

yes, then the domain can be all real values

quit spamming someone elses channel

[crimson sedge]

Thanks! Then if we have functions that include division, those domains are (- infinity, -) u ( 0, infinity), right?

[solid juniper]

raising a real number by exponents
might run into trouble there

[crimson sedge]

I blocked fernandez, no idea that that troll is saying

[solid juniper]

for example, the domain of $x\mapsto x^\pi$ is not implicitly $\bR$

[wraith dagger]

💜𝓁𝒶𝓎𝓁𝒶💜

[crimson sedge]

Hmmm I see. Thank you guys

Fernandez stop fucking sending me friend requests and spamming me

[modern compass]

<@&268886789983436800>

[crimson sedge]

To tell you to stop this shit, what are you even doing here? Someone ban this clown..

Thanks guys

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[crimson sedge]

I need help with trigonometry

[crimson sedge]

I just don't have it lol

question I need some help with rn

[cedar kiln]

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[crimson sedge]

show attempt

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[abstract stirrup]

Hello! Could someone help me, please? Using Abel-Dirichlet criterion, prove that the series sigma (n=1 to infinity) sin(n)cos(n^2)/sqrt(n) converges. This is what I tried. And I don't know how to prove that Sn is bordered (hope I said it right in English).

[cedar kiln]

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[abstract stirrup]

<@&286206848099549185>

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[sour hare]

A school started in the year 1999. After 5 years (2004) the amount of students had increased by 55%. After another 5 Years (2009) the amount of students increased by another 30%. In the year 2014, the total amount of students was 270% of what it was in 1999. With how many percent had the amount of students increased in between 2009-2014?

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[crimson sedge]

is it always necessary to remember the quadratic formula

[crimson sedge]

ive practiced enough of the questions i still forgets it

[amber seal]

yes its quite useful

[crimson sedge]

so is there anyway i can keep that in mind and not to forges it

[amber seal]

um isnt it kinda simple...just remeber d..

thats it

[hushed spoke]

you could derive it

[amber seal]

id suggest u to once derive it yourself

if you havent still

[hushed spoke]

using complete the square method

[amber seal]

using completing the square

[hushed spoke]

it gets easier cause

[crimson sedge]

i have not derived it

[hushed spoke]

you know what everything is for

[amber seal]

https://www.khanacademy.org/math/algebra/x2f8bb11595b61c86:quadratic-functions-equations/x2f8bb11595b61c86:completing-square-quadratics/v/solving-quadratic-equations-by-completing-the-square

refer to this

[hushed spoke]

lol i will stop we are saying the same things at the same time

[amber seal]

the formula becomes quite clear and makes sense after this..

[crimson sedge]

that’s okay - thank you for the help on this one

[crimson sedge]

okay ✅

.close the channel

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[plucky dagger]

Is it correct??

anyone please??

[crimson sedge]

this isn't "by inspection"

but yes that's correct

[plucky dagger]

Then what I have to do?

[crimson sedge]

by inspection means you do it without writing anything

[plucky dagger]

Ohh alright

Okay !!

Thnkoo

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[weak fable]

I have a few different samples from a large data set the smallest sample size is 800 the largest about 3500, if I want to test the means would it be best to use a t test or a z test?

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[quiet hazel]

If we have a die and we roll it four times, and the final three rolls are at least as large as the preceding one, does that mean the last three rolls have to at least be the same or more?

[drifting marlin]

"At least as large" means greater or equal yes

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[fading jasper]

Mb i was afk since i was taking a test

[fading jasper]

I need help with the phone packet

[hushed spoke]

i answered when you posted ealier

for the first one

and the second pic is blurry

[fading jasper]

Mb

The 2nd one says

[hushed spoke]

also is this supposed to be a test?

[fading jasper]

Prove yx bisects ol

[fading jasper]

Nope its a worksheet

I have things that refeil my personal info

So thats why i cencored stuff

[hushed spoke]

ye i understand that but try to send in a clear pic with the full question

[fading jasper]

U want mw to just read it out

In using a damsung so all pics look like that

Samsung

*sometimes

Hello?

<@&286206848099549185>

[hushed spoke]

for the second one there

notice that Triangle ACD and BED are congruent

can you take it away from here?

the third one again

HWO is congruent to DWO

[fading jasper]

Um
I think u do def of angle bisector

And then do hl on adc

And do ctptc

[hushed spoke]

wheres the angle bisector?

[fading jasper]

Bd

[hushed spoke]

where does it say it is the angle bisector?

[fading jasper]

Oh shoot its given

[fading jasper]

Isnt it a bisector for ac

[hushed spoke]

...

no?

"D bisects CE"

[fading jasper]

OH

MB

THATS QUESTIONS 5

I WAS TALKING ABOUT 2 LOL

whoops

[hushed spoke]

LOL

okay so

do you know how to do this one?

[fading jasper]

Nope lol

I was hoping u cpuld teach it

[hushed spoke]

prove the congrience of ACD and BED

once you do, you will find that by cpct

AD=BD

voila

(ADB is isosceles)

[fading jasper]

Mk

[hushed spoke]

so the angles opposite to equal sides have to be equal

[cedar kiln]

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[buoyant tinsel]

i need help

[hushed spoke]

isolate x

[buoyant tinsel]

what

[hushed spoke]

try to get rid of the -5.4

[buoyant tinsel]

5.4- 5.4

5.4 - 7

give me - 1.6

[hushed spoke]

yes, but you have -5.4, so will you add 5.4 on both sides or subtract to get rid of it?

[hushed spoke]

no

[buoyant tinsel]

subtract it

[hushed spoke]

so you are saying that -5.4 - 5.4 = 0?

[buoyant tinsel]

nvm

add it

[hushed spoke]

yessir

[buoyant tinsel]

12.4

[hushed spoke]

yes

[buoyant tinsel]

okay thank you\

.close

[cedar kiln]

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[crimson sedge]

Yo

[crimson sedge]

can someone briefly tell me why

theta = theta?

like a proof or something

[crimson sedge]

Like this I think

[crimson sedge]

youre the best

sincere appreciation ♥️

.close

[cedar kiln]

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[tropic moat]

im not sure how to get started here any help?

[cedar kiln]

@tropic moat Has your question been resolved?

[tropic moat]

no

<@&286206848099549185>

[cedar kiln]

@tropic moat Has your question been resolved?

[tropic moat]

NO

<@&286206848099549185>

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@tropic moat Has your question been resolved?

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[west lagoon]

hi

[west lagoon]

i need help

k

[obsidian coral]

• Show your work, and if possible, explain where you are stuck.```

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[gaunt yacht]

Hi

[gaunt yacht]

If i want to find center of mass,

on a graph

inside of the equation for M

is the Density INSIDE or OUTSIDE of the Integral?

[cedar kiln]

@gaunt yacht Has your question been resolved?

[crimson sedge]

What dimension is it @gaunt yacht

[cedar kiln]

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@mental mural Has your question been resolved?

[cedar kiln]

@mental mural Has your question been resolved?

[zenith sail]

Are you sure these match? The work looks like it's for a completely different integral than the one you posted

[cedar kiln]

@mental mural Has your question been resolved?

[mental mural]

oh I so sorry I will repost

[cedar kiln]

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[crimson sedge]

can i get help on this one

[crimson sedge]

i made an equation 6 - 15x = 9x + 30

You multiplied the numerator by 3?

Keep it as 2-5x = 9x + 30

i multiplied numerator and denominator

it was due to equals to sign and then = 3

[rare schooner]

linear equation

[crimson sedge]

Well if you are going to do that, then you have to also do that for the right hand side, but it is just more work for you for nothing

[rare schooner]

its easier to just get rid of the denominatot

[crimson sedge]

merely bcz i learnt it that wai

[rare schooner]

denominator*

just multiply both sides by 3x + 10

[cold briar]

he did that, but wrongly

[crimson sedge]

you can also say 1/3

[rare schooner]

ah

[crimson sedge]

like

[rare schooner]

heres how you should do it

multiply 3x + 10

so on the right hand side they just cancel or simplify out

and for the left hand side multiply 3 by the entire thing

hence we distribute the 3 across

[crimson sedge]

there are so many ways for this kind of a question

[rare schooner]

yes this is one way

[crimson sedge]

so the one you have done seems entirely new to me

[crimson sedge]

there is only this one way?

Elaborate the method you are used to

[rare schooner]

no

[crimson sedge]

2 - 5x / 3x + 10 = 3

2 - 5x = 9x + 30

this is how i have been doin’

[rare schooner]

how did you get this then

[rare schooner]

thats correct

[crimson sedge]

that one

[rare schooner]

okay its fine

[rare schooner]

you know hiw to get this?

[crimson sedge]

earlier i made a mistake i multiplied the numerator too with three had to multiply it with the denominator onli

[crimson sedge]

after multiplying three with the denominator

[rare schooner]

ah okay

[crimson sedge]

so

this has to be

2 - 5x = 9x + 30

2 - 30 = 9x + 5x

[rare schooner]

yes good

now simplify it

[crimson sedge]

i get is seven

ill check my answers

[rare schooner]

not quite

[crimson sedge]

the answer is - 2

[rare schooner]

yep

[crimson sedge]

im simplifying it

[cold briar]

it's 9x + 5x btw

[rare schooner]

he got it correct wym

[crimson sedge]

oh no

[cold briar]

no, he probably got 7 because he mixed up the signs when calculating

[rare schooner]

his final answer

[crimson sedge]

it was a minor mistake

[cold briar]

he get 7 but the answer is -2, so im just reminding him

so yeah

that's why i said that

[rare schooner]

yea he got -2 after the second try

but thanks yea good advice

[crimson sedge]

I was subtracting

that was my fault

[rare schooner]

np

as long as you understand

[crimson sedge]

well thank you very much

thank you.

.close

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[cinder lake]

.

.close

[cedar kiln]

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[cursive pumice]

Can someone help me do q11

[cedar kiln]

@cursive pumice Has your question been resolved?

[cedar kiln]

@cursive pumice Has your question been resolved?

[livid needle]

I can try

But I'm unsure of the exact physics

[cedar kiln]

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[marsh wagon]

Do anyone know how to use economical analytics on excel?

[scarlet garnet]

https://dontasktoask.com/

[marsh wagon]

What?

I need to know for my math assignment

[scarlet garnet]

please read what the link says

just ask what you want to know

not ask to have someone ask you what you want to know

thats annoyting

[marsh wagon]

Ok I'll send my assingment so you can help if that's needed

[scarlet garnet]

you can send it here

in case I cannot help

the others can

[marsh wagon]

In this assingment I am working with personal economics topics. In this I will need to make an savings account and my goal is to know when I have saved up to 6 600 000 kr

I know something about I need to use target analystics to find it out

I do not know how to change language on excel, but what I wrote in it I have translated

[scarlet garnet]

so you have to find the closest match to 6 600 000 kr within the money columns?

[marsh wagon]

Yes

[scarlet garnet]

i wouldn't know how to do it myself, but google gives a bunch of results

[marsh wagon]

I have tried to find target search analystics, but I do not find a video that gives me the information I need

[scarlet garnet]

what you want to do is

1. get the differences between the target number and the numbers to check
2. get the lowest value of those
3. print that number

[marsh wagon]

I am not completely following what you want me to do

[scarlet garnet]

actually no, print whatever row you got, but the first column, so you get the year

[scarlet garnet]

well, since we are looking for the number CLOSEST to 6600 000, the target is the number with the smallest difference

[crimson delta]

in google sheets there is a function vlookup which does essentially this. excel should have an equivalent function

[marsh wagon]

They do got a function for it, but I am not sure how to use it

[crimson delta]

well presumably there is a documentation with some examples

[cedar kiln]

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[cursive pumice]

Soo?

[cursive pumice]

Q11

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[random gale]

Parameterization question:

How do you parameterize the intersection of y^2 + z^2 = 4 and x = 2?

[cedar kiln]

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[obtuse frigate]

anyone knows what this organic compound is named?

sorry this is a math server but I’ve asked the chemistry server and I got ignored multiple times

the discussions there are also very advanced

[copper crest]

You're still not allowed to ask

[obtuse frigate]

But I’ve gotten help here before

[copper crest]

Ask at jee pro

[tall hare]

wait this is possible?

[copper crest]

Jee pro server

[copper crest]

There are rules.

[tall hare]

i wiuld say AlFClBr