help-13

[olive heart]

this is pre calc?

aint no way

[crimson sedge]

I mean, it is expanded a lot more

[olive heart]

im in ALegbra 2

[crimson sedge]

Oh you guys take that in algebra too? Never knew

[olive heart]

ye

[crimson sedge]

Interesting

[olive heart]

lol

i know how to do it

just forgot

i was focused on other subjects more

need a fresher

[crimson sedge]

Anyways since you are in algebra I suppose it's understandable

[olive heart]

yea

[crimson sedge]

You need to make the denominator of 1 equal to the denominator of the fraction

[olive heart]

ohh

ok i get it now

but what would u do with x?

[crimson sedge]

Try multiplying by the common denominator

[crimson sedge]

Just... Leave it there

So you basically have x/2 - 2/2

[olive heart]

so x/2 - 1/2

ye i meant 2/2

[crimson sedge]

Nono remember I multiply both top and bottom

[olive heart]

yea

typo

[crimson sedge]

It becomes x-2/2

[olive heart]

ohh ok

there i get it now

so that would be my answer?

[crimson sedge]

Yep good job

I mean yes

You can't go anywhere else

[olive heart]

oh lol

thats simple

[crimson sedge]

Yep

And it is fun

[olive heart]

yea

[crimson sedge]

Because you can do a lot with parametric curves

[olive heart]

ye

is alegbra 2 hard

[crimson sedge]

Uh give me a rundown of your curriculum

[olive heart]

wdym

[crimson sedge]

Because I honestly don't remember what algebra 2 was all about

[olive heart]

oh

i dont got the book on me rn

[crimson sedge]

I don't remember the topics, so I am asking if you could give the topics you study in it

[olive heart]

is calc difficult?

[crimson sedge]

Calculus?

[olive heart]

ye i dont got the book on me rn

[olive heart]

yea

[crimson sedge]

Mmm it definitely is challenging and fast paced. You have a lot of topics you would be learning about

[olive heart]

oh

[crimson sedge]

But if you have a solid foundation in pre calculus, you will definitely do good in calculus

[olive heart]

oh ok sounds good

thanks for the help

[crimson sedge]

Ofc

[olive heart]

everyone yesterday

didnt know how to do it

lol

finally found someone

[crimson sedge]

Who is "everyone"

[olive heart]

like 3 different helpers

[crimson sedge]

From this server? You probably misinterpreted what they said... Most helpers here are way above my knowledge base

[olive heart]

yea from this server

no

they told me

they forgot how to do parethmetic equations

[crimson sedge]

Okay

[olive heart]

ok gotta go

thanks

.close

[cedar kiln]

Channel closed

Closed by @olive heart

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[blissful sparrow]

Could someone explain how????

[crimson sedge]

Um an even powered term is never going to give you a negative result

[blissful sparrow]

Ohh that was supposed to be minus not plus

My bad

My Phone read this wrobiły

Wrongly

[native flint]

So what is it solving for?

the x values that make the inequality true?

[cedar kiln]

@blissful sparrow Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[scarlet schooner]

The hamsters wheel is 16 cm in diameter and the base of the wheel is 2cm off the ground. If Harry can spin the wheel 4 times each second, what is a cosine function that describes the movement of the wheel if it starts at its lowest point?

[scarlet schooner]

Any help is appreciated Im not sure where to start

[cedar kiln]

@scarlet schooner Has your question been resolved?

[scarlet schooner]

Does anyone know how to answer, if not it’s fine.

[cedar kiln]

@scarlet schooner Has your question been resolved?

[crimson sedge]

DADDY

I AM GOOD AT MATH

PLEASE

HELP MEEE

If you divide x Square by 789 then whats the answer Pinky

Oh sorry TINKY

OH NO SORRY ALOO TIKKY

[cedar kiln]

@scarlet schooner Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[abstract locust]

Help 😦

[cedar kiln]

@abstract locust Has your question been resolved?

[cedar kiln]

@abstract locust Has your question been resolved?

[abstract locust]

<@&286206848099549185> 😄

[abstract locust]

.close

[cedar kiln]

Channel closed

Closed by @abstract locust

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[strange fulcrum]

Can someone help me solve this please I have tried 10 times

[strange fulcrum]

Someone who is really good at math please

[south tundra]

I told you it's ln5 + 2arctan(4/3)/3 - ln3

[strange fulcrum]

No it’s wrong

It’s 2+2ln(3)

[coral imp]

Yeah

[strange fulcrum]

I know it’s so hard

[south tundra]

,w integrate (x+3)/(x^2+2x+10) from -1 to 3

[coral imp]

I used calculus calculator and got its answer as well

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by A Lonely Bean#7998

[south tundra]

,w 2 + 2ln(3)

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by A Lonely Bean#7998

[south tundra]

They are nowhere close

Ahh wait do you have a square root there?

[strange fulcrum]

Yessss

That’s why u get wrong answer

[south tundra]

I'd do trig sub

[coral imp]

See now it matches

[south tundra]

Let x+1 = tan(theta)

[strange fulcrum]

This is my solution

[coral imp]

Is the log fn and 26/9 in addition?

[strange fulcrum]

Yeah it’s plus sign between them

But I think I did something wrong in the end

[coral imp]

I can tell u its incorrect 💀

[strange fulcrum]

Ohhhhhh

What should I do guys

[strange fulcrum]

Thanks for checking my answer

[coral imp]

Here's the question

[strange fulcrum]

<@&286206848099549185>

[cedar kiln]

@strange fulcrum Has your question been resolved?

[cedar kiln]

@strange fulcrum Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[steep grove]

this should be really easy i dont know why im messing it up

[short blade]

can we see your work

[toxic moat]

yes

really easy

[steep grove]

i dont get what to do

i haven't really done anything

[short blade]

solve for x in u=2x-1, then plug whatever you get into the original equation for x

[steep grove]

ohhh

thanks 🙂

.close

[cedar kiln]

Channel closed

Closed by @steep grove

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ripe meadow]

<@&286206848099549185>

[nova snow]

Dude you haven’t even posted your question

[ripe meadow]

Oh bruh

Uh

A pyramid is standing on a table, the base of the triangle is a square with sides of 9 cm, L is the middle of side BC of the base of the triangle, the length of TL is 12cm.
How high is TM in cms?

I dont understand at all

[wary scaffold]

I believe pythagoras is supposed to be used

[ripe meadow]

Thank you but i dont really know how

[patent cape]

you can compute MT in the triangle ABC to be half of AB (ABCD is a square therefore M is the midpoint of AC, T is the midpoint gor BC meaning TM id a middle line in the triangle)

then pythagoras in TML

if you want proof TM is perpendicular on ML i can write it

[ripe meadow]

Sorry but could you explain that again but dumber

[patent cape]

basically ML is half of AB cause its a middle line

or an axis of simmetry in the square but half

which means its half of AB

or 4 cm

ML = 4 cm

ml

sorry

god therse side notations kinda bug me

anyways

then pythagoras in TML

[wary scaffold]

Why would it be 4 and not 4.5?

[patent cape]

oh wait its 9

[wary scaffold]

yh

[patent cape]

sorry i thoght AB was 8

yeah its 4.5

[wary scaffold]

So you form this triangle

I should've marked it's right angled

but...

[ripe meadow]

So do i now do 12² plus 4.5² and then root of the outcome?

[wary scaffold]

Well the Pythagorean theorem states that in a right angles triangle a^2 + b^2 = c^2 where c is the longest side also called the hypotenuse. So our longest side will be 12. So instead we get 4.5^2 + b^2 = 12^2

So you have to do some rearranging

[ripe meadow]

I still dont really understand

What would you enter into a calculator?

[soft owl]

b = 12² - 4.5²

[ripe meadow]

Wait so 12²-4.5²=123.75
Root of 123.75=11.1, so then tm is 11.1?

[wary scaffold]

Yeah

[ripe meadow]

Thanks

.close

[cedar kiln]

Channel closed

Closed by @ripe meadow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[graceful vigil]

how do i find dh/dt?

[crimson sedge]

h(t) is given in the question

[graceful vigil]

but thats not dh/dt, is it? thats just h

[crimson sedge]

you can differentiate it

[graceful vigil]

oh i see

thanks

.close

[cedar kiln]

Channel closed

Closed by @graceful vigil

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cinder zealot]

Proposition True or False or Open:
If factoring is an element of P, then P does not equal NP.

[fair geyser]

did u see my answer?

essentially you go by implication rules, then it's clearly not true and not false

[crimson sedge]

(#help-3 message)

[fair geyser]

ty

[crimson sedge]

isn't P\subseteq NP?

[fair geyser]

yes

even without "implication rules", factoring is not NP-complete, so it could be that factoring is in P, but other things aren't, which means the proposition is not false

(rather it's not shown to be NP-complete, for extra brain torture)

[cinder zealot]

So if if the proposition is open —> open then it would be open

[fair geyser]

yeah

[cinder zealot]

Also It just hasn’t been proven that if factoring is in p then p != np

But if we said satisfiavilty is in p then p = NP

Even though it’s open —> open

It’s true because it’s been proven true

[fair geyser]

hm

yeah true

ok this is kinda fun

"If SAT is an element of P, then P does not equal NP"

[cinder zealot]

Oh okay because it’s confusing because with these implication rules wouldn’t these np hard problems technically be open?

[fair geyser]

that's not false

[cinder zealot]

Yeah but I’m assuming just because it’s been proven true, so it is true

[fair geyser]

there's no loading emoji

right,
"If SAT is an element of P, then P = NP" is true, we can exclude T → F, which is enough

"the opposite" is not false, we can exclude T → T, and F → F, but F → T is possible

so it's open

(and not "opposite")

[cedar kiln]

@cinder zealot Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[velvet mason]

Can someone walk me through number 4 here

[cedar kiln]

@velvet mason Has your question been resolved?

[cedar kiln]

@velvet mason Has your question been resolved?

[cedar kiln]

@velvet mason Has your question been resolved?

Channel closed

Closed by @velvet mason

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[floral vale]

is this the final answer or am i missing something? i used the power rule.

[modern compass]

what about the +4?

[floral vale]

do i just add it as a constant to the answer or should i add the antiderivative of 4 to the answer

[modern compass]

yep, that's it

[floral vale]

ok thanks

was doubting myself

have a good day/night

.close

[cedar kiln]

Channel closed

Closed by @floral vale

Use .reopen if this was a mistake.

[floral vale]

.reopen

[cedar kiln]

✅

[floral vale]

.close

[cedar kiln]

Channel closed

Closed by @floral vale

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tidal prism]

.reopen

.close

Hi i need help

[cedar kiln]

Please don't occupy multiple help channels.

[tidal prism]

sorry

idk where my other channel went

but can i get help

.open

.reopen

.close

[cedar kiln]

Channel closed

Closed by @tidal prism

Use .reopen if this was a mistake.

[tidal prism]

.reopen

[cedar kiln]

✅

[tidal prism]

https://artofproblemsolving.com/wiki/index.php/2021_Fall_AMC_10B_Problems/Problem_13

need help with this

i'd like an explanation because it doesn't tell me that clearly

or i might be dumb idk

whatever it's fine

.close

[cedar kiln]

Channel closed

Closed by @tidal prism

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[half garden]

X=-49

Wait never mind that it so wrong

[violet night]

x^2 + x^2 -14x + 49 = x^2+2x+1

[half garden]

X=-48*

Right?

Idk how to do lol

[violet night]

I got two solutions

you know $a^2+b^2=c^2$

[wraith dagger]

Clarkie

[violet night]

just apply that here

[half garden]

I did that lol

[violet night]

how tf did you get -48

[half garden]

And got -48

[violet night]

working?

[half garden]

x^2 + 1 (this is A) + x^(this is B) = x^2 + 49 (and finally C)

[violet night]

I dont understand

[half garden]

Wait it is positive x = 47 lol

[violet night]

no it is not

I got x^2 + x^2 -14x + 49 = x^2+2x+1

[half garden]

Idk I plugged the three sides into Pythagorean

[violet night]

after expanding

(x)^2 + (x-7)^2 = (x+1)^2

x^2 + x^2 -14x + 49 = x^2+2x+1

x = 4 or 12

so a 3,4,5 triangle or a 5,12,13 triangle

[half garden]

Oh shoot

[violet night]

helps to know Pythagorean triples as well

[half garden]

I got 6.9282

[violet night]

no

no I have no idea

what you're doing

post your working

[half garden]

Where did 14x come from

[violet night]

$(x-7)^2 = x^2-14x+49$

[wraith dagger]

Clarkie

[violet night]

no

$(x-7)^2 DOES NOT MEAN x^2 - 49$

[wraith dagger]

Clarkie

[violet night]

gotta foil it

https://www.youtube.com/watch?v=nyk3UGwCAms

[half garden]

Oh your right lmao

[violet night]

you gotta learn to reason your answer as well

get it and plug it in

see if it works

[half garden]

What the I went through it all my calculator doesn’t get 4 or eight

Also @violet night

I don’t know how to find the side lengths

[violet night]

wait someone asked this earlier

[half garden]

Lol

[violet night]

[half garden]

That was me

I think

[violet night]

ah

ratio

[half garden]

But it didn’t work

[violet night]

so add up all your 'ratio' parts

and thats how much '1' ratio part has

then multiply by each thing

[half garden]

But like the sum has to be 200.6

[violet night]

yep

,calc 200.7 / (4+4+9)

[wraith dagger]

Result:

11.805882352941

[violet night]

,calc 11.8 * 4

[wraith dagger]

Result:

47.2

[violet night]

,calc (11.8*4)2 + (911.8)

[wraith dagger]

Result:

200.6

[violet night]

see

200.6

[half garden]

Wow

How do I do #5 lmao

[violet night]

whats the total perim

or is it the same?

[half garden]

This is like a pre test thingy and I wanna do well we have only learned a basic overview

Before the ratio was sides and now this is angles

Oh wait 2 + 3 + 7 = 180

@violet night this is the final boss

Never mind 10.8166

Clarkie thanks for all the help your a really nice guy lmao

You gave me so much of your time

So thanks

@violet night

[violet night]

no problem bro

[half garden]

.close

[cedar kiln]

Channel closed

Closed by @half garden

Use .reopen if this was a mistake.

[half garden]

😊

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fringe vortex]

I have no clue how to do this

can someone explain

[obsidian tinsel]

What math course even is this??????

[fringe vortex]

discrete math

[obsidian tinsel]

College?

[fringe vortex]

yes

[gleaming cloud]

Hey, do you do physics at uni?

[gleaming cloud]

What's a_n

[obsidian tinsel]

No. Physics at high

Wait how do you know I do physics?

[fringe vortex]

wym

[violet night]

the physics scouter

[gleaming cloud]

I could tell ur name is a reference to the pauli exclusion principle

Also ur in the physics server 🙂

[obsidian tinsel]

I don’t take any class in quantum physics

[gleaming cloud]

How is a_n defined

[fringe vortex]

what does that even mean

[gleaming cloud]

$a_n$

[wraith dagger]

giannis_money

[solid juniper]

"prove that (sequence)"

[fringe vortex]

how do i prove that

[solid juniper]

if that's the whole question it makes no sense

[fringe vortex]

its proof by strong induction

[cedar kiln]

@fringe vortex Has your question been resolved?

Channel closed

Closed by @fringe vortex

Use .reopen if this was a mistake.

[fringe vortex]

Sure it has

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[shrewd monolith]

Converting quadratics vertex form to standard then graphing them

[haughty wraith]

whats the question exactly

[shrewd monolith]

i have almost zero clue on how i do that

[haughty wraith]

just expand parenthesis

[shrewd monolith]

??

[haughty wraith]

and add like terms

like expand (x-2)^2

for the first equation

add like terms and then its in standard form

[shrewd monolith]

how do i expand parenthesis

[obsidian coral]

Distribution

[shrewd monolith]

the 3?

[haughty wraith]

do you know how to expand like (x+1)^2

[shrewd monolith]

i dont

[haughty wraith]

urm

what about like

if it was written as (x+1)(x+1)

[shrewd monolith]

oh thats what u mean

[obsidian coral]

Yes that's how you expand

[shrewd monolith]

ahhh yes i did that and missed a step

thats why i got it wrong

ok now how would i graph it

[haughty wraith]

how accurately do they want you to graph it

you could solve for roots

[shrewd monolith]

hang on before we move on to graphing

[haughty wraith]

and you have y intercept from standard form and vertex coords from vertex form

[shrewd monolith]

is y=x^2-4x+7

that is the standard form right?

[haughty wraith]

for which equation

[shrewd monolith]

the first one

[haughty wraith]

yes

are you graphing by hand

[shrewd monolith]

yes

[haughty wraith]

how accurate does it need to be

like what requirements

[shrewd monolith]

very accurate

[haughty wraith]

im assuming roots, vertex, y intercept?

ok so whats our vertex coord firstly

[shrewd monolith]

hang on

um

the vertex is 3 i believe

[obsidian coral]

Vertex is a coordinate point not a value, at this that was what was being asked

[shrewd monolith]

oh right

vertex is (h,k) so it woud be (2,3)

[haughty wraith]

yeah

whats our y intercept

[shrewd monolith]

um

[haughty wraith]

what is y when x=0

[shrewd monolith]

C is the y intercept?

[haughty wraith]

yeah

[shrewd monolith]

7

[haughty wraith]

ok so (0, 7)

is y intercept

(2, 3) is our vertex

now u need to solve for roots

[shrewd monolith]

if one of the vertex numbers are negative does it make the coord negative?

or only for the k value

[haughty wraith]

only for the bit inside the parenthesis yeah

wait

like

its (x-k)^2+h

so if its (x-5)^2

k = 5

if it was (x+5)^2 then k=-5

is that what u mean?

[shrewd monolith]

ok so in the parenthesis if its - then the coord is + and vice versa?

[haughty wraith]

yes

[shrewd monolith]

so what about the other coord value

does it matter?

[haughty wraith]

huh

[shrewd monolith]

(x-2)^2 + 3

the 3 part

does that matter?

[haughty wraith]

yes thats the y value

so the vertex is

(2, 3)

because the -2 becomes a +2

[shrewd monolith]

but if it was -3 it would be -3

[haughty wraith]

yes

[shrewd monolith]

alr thanks

ok now back to graphing

so the vertext is 2,3

and intercept is 0,7

[haughty wraith]

yes and is it concave up or concave down

[shrewd monolith]

um it opens up?

[haughty wraith]

like is it a smile or a frown

[shrewd monolith]

smile

[haughty wraith]

yup

because its x^2 and not -x^2

ok thats 3 pieces of info

[shrewd monolith]

gotcha

[haughty wraith]

now we just need to find roots

and then just draw it

[shrewd monolith]

how would i ffind the roots

[haughty wraith]

urm whatever method you want

i guess because you have in vertex form its not that bad

just like subtract constant and sqrt then subtract the other constant

actually that wont work because u get a complex number

idk factor or use quadratic

[shrewd monolith]

ok

yeah im lost

idk where to start to find the roots

[haughty wraith]

just plug into quadratic formula

it might not have real roots

actually yeah it doesnt have real roots because our vertex is above the x axis and its concave up

so u can just graph it

[shrewd monolith]

we only have 2 points

[haughty wraith]

thats all u need

[shrewd monolith]

so its just a diagonal line?

[haughty wraith]

no…

its gonna be a quadratic

so curved

its just got no real roots

[shrewd monolith]

ok so i can just curve it randomly

[haughty wraith]

yea as long as it goes through those 2 coordinates and is concave up

[shrewd monolith]

ok lemme do that

how long are u able to help me for?

[haughty wraith]

like this

idk im probably going to go soon but u can just make a new thread

and someone else can help

[shrewd monolith]

ah ok

thanks for the help imma make a new thread

actually one last quick thing

what is the formula i would use to find the roots for another problem

[haughty wraith]

quadratic formula?

id just google it

[shrewd monolith]

so i would do that formula once and im done?

[haughty wraith]

its x= -b +- sqrt(-b-4ac) all divided by 2a

[haughty wraith]

yeah

or just factor if its easier

[haughty wraith]

or this if its in vertex form

theres lots of methods just do whatever

[shrewd monolith]

what arethe constants?

[haughty wraith]

if all else fails use quadratic formula

so like

y = (x+1)^2 - 1
0 = (x+1)^2 - 1
1 = (x+1)^2
positive and negative sqrt(1) = x+1

x = sqrt(1)-1
x = -sqrt(1)-1

[shrewd monolith]

this isnt the problem we just did right?

just an example?

[haughty wraith]

no i just made it up

[shrewd monolith]

ok

ok i got it thanks alot for the help

[cedar kiln]

@shrewd monolith Has your question been resolved?

Channel closed

Closed by @shrewd monolith

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[glacial birch]

im confused on why the answer is B for this one

[cosmic steppe]

ln(a/b) = ln(a) - ln(b)

[glacial birch]

so why isnt it C?

[cosmic steppe]

You can simplify it further

[limpid bane]

ln e^x = x

[glacial birch]

oh

i see

thanks

wait are there different preperties for log and ln?

[limpid bane]

Well yes, ln is the natural logarithm and is in base e, log is a logarithm in base 10

[glacial birch]

ok

thanks

so essentially is the whole topic of logs and ln just simplifying and rewriting these things mostly

?

[solemn torrent]

ehh

using the rules yeah

[glacial birch]

ok

thanks

idk how to do this one

[crimson sedge]

Rewrite the square root in exponential form

That's a good start

[cedar kiln]

@glacial birch Has your question been resolved?

[glacial birch]

ohh i get it now

how is the answer to this one not A?

the correct answer is C

oh wait they just simplified the log 5 625 more

[rain drift]

$log_5\left(\frac{625}{\sqrt{x - 1}}\right) \= log_5(625) - log_5(\sqrt{x-1}) \= log_5(5^4) - log_5((x-1)^{\frac{1}{2}}) \ = 4 - \frac{1}{2} log_5 (x - 1)$

looks like the bot isn't working right now

[rain drift]

looks like you got it

[cedar kiln]

@glacial birch Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tranquil glen]

Have you made any steps yet?

What could be the starting point

well you could write equations by substiting variables for fruits

[cedar kiln]

@crimson sedge Has your question been resolved?

[crimson delta]

https://www.quora.com/How-do-you-find-the-positive-integer-solutions-to-frac-x-y+z-+-frac-y-z+x-+-frac-z-x+y-4

althought the RHS is different (4 in the link) it gives you an overview about ways to solve equations like this

TLDR: it's hard

very hard

maybe because the RHS is 10 here it's easier, dunno

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

Channel closed

Closed by @stuck lichen

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gloomy swift]

hi! i have genuinely have no idea how to work this out

[gloomy swift]

pls help

[livid hound]

what have you tried

[gloomy swift]

Dividing the perimeter into 4

since it has 4 sides

but the 3x dont make sense :(

[livid hound]

3x is 3 times x

do you know the definition of perimeter

[gloomy swift]

The outside?

[livid hound]

be more specific

[gloomy swift]

like the edges of the shape

[livid hound]

the perimeter is the length of the border of a shape

[gloomy swift]

yep

[livid hound]

a diagram has been conveniently provided to you

apply the definition of perimeter to set up an equation

[gloomy swift]

so it would be

x+x+3x+3x= 192

?

[livid hound]

yes

[gloomy swift]

OH

they asking for equation?

[livid hound]

no

[gloomy swift]

oh

[livid hound]

an equation is what you'd set up and use to determine the value of x

[gloomy swift]

yep

[livid hound]

they want the values of x and 3x

[gloomy swift]

im not sure how to find that out :(

[livid hound]

you have your equation

x+x+3x+3x= 192

solve that equation (for x)

[gloomy swift]

ermm

oh SO WE add all x's

OHH

i get it now

it would be 8x

thank you so much

[cedar kiln]

@gloomy swift Has your question been resolved?

Channel closed

Closed by @gloomy swift

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[simple bobcat]

3g + 5b = p

[simple bobcat]

Pls help

[bitter reef]

3 variables but 1 equation

[limpid bane]

There either has to be more equations with the same variables or a given relationship between them for that to be solvable.

[wary scaffold]

Yeah there are just about infinite g,b and p that satisfy this equation.

[cedar kiln]

@simple bobcat Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

What is 0-(-7) and what is -1-(-2)? Sorry, im confused at integers

[haughty wraith]

0 - (-7)

is the same as

0+7

and -1 - (-2) is the same as -1 + 2

[crimson sedge]

So it's 7 and 1?

[safe agate]

Yup

[cedar kiln]

@crimson sedge Has your question been resolved?

Channel closed

Closed by @fierce atlas

Use .reopen if this was a mistake.

[crimson sedge]

.reopen

[cedar kiln]

✅

[crimson sedge]

But my classmates told me it was wrong

[tropic oxide]

your classmates told you that you were wrong to say 0 - (-7) = 7 and (-1) - (-2) = 1?

[crimson sedge]

Yes

Wait

Can you check this if it's correct?

[tropic oxide]

well your classmates are wrong re: the question you came here with first

is this worksheet just "here's two points, find the slope of the line going through them"?

[crimson sedge]

Yeah, we determine the slope of a line

[tropic oxide]

right, everything appears to be in order here

except that you wrote 7/1 and not 7, for whatever reason. but that's not a serious mistake

[crimson sedge]

What i remember... The answer is "-7/3" or idk if it's "7/-3"

[covert chasm]

1

[crimson sedge]

That's the answer my classmates had

[tropic oxide]

-7/3 and 7/-3 are the same thing

[covert chasm]

For the second one

[crimson sedge]

Ohh

[covert chasm]

7

For the first one

Because

I think

Positive numbers minus negative numbers equals the positive number plus the negative number

I’m not sure but like

x-(-x)=2x

I think

Kind of like that

[crimson sedge]

yes, i never actually learned about the slopes being not a fraction, so idk about it

[tropic oxide]

??

they're numbers

[crimson sedge]

ohh

[tropic oxide]

a slope is a number

[crimson sedge]

but i never actually had an answer that is not a fraction

[tropic oxide]

it's just a little odd that you insist on writing 7/1 when you could just write 7 and have it be the same thing, you know?

[covert chasm]

I forgot how to subtract negative from negative

[crimson sedge]

yes but my classmates answer about "7/3" something like that

[tropic oxide]

your answer is correct!

[crimson sedge]

but the teacher also told me that my answer was wrong

[covert chasm]

Then the teacher dumb

Put it into a calculator

Legit

[tropic oxide]

,calc (0-(-7))/((-1)-(-2))

[wraith dagger]

Result:

7

[tropic oxide]

did your teacher say anything more specific or just "your answer is wrong and i refuse to elaborate"

[crimson sedge]

well she told me something about "negative minus positive will be turnrd into addition, so it will be -3"

turned*

something like that

[tropic oxide]

...??

does she claim that (-1) - (-2) = -3??

are we talking about the same problem?

[crimson sedge]

yes T-T

im just really confused as to why it's like that

cuz, i double checked my answer and it was literally the same as the calcu

the only correct answer i had was number 1

the 3/4 one

[tropic oxide]

weird

[crimson sedge]

yeah ikkk

[tropic oxide]

maybe you copied some data incorrectly

[haughty wraith]

did u write down the questions correctly

[crimson sedge]

yes, i did exactly the formula correctly

[haughty wraith]

I mean like the actual questions themselves not the formula for slope

[crimson sedge]

yes i did

[crimson sedge]

i double checked multiple times

[cedar kiln]

@crimson sedge Has your question been resolved?

[crimson sedge]

<@&286206848099549185> can someone help me on what to do with my activity?

i'll just copy my previous answers, idec anymore if i just get 1

.close

[cedar kiln]

Channel closed

Closed by @fierce atlas

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[keen estuary]

$4^{\log_2(7)} = 49$

[wraith dagger]

sla-ppy

[keen estuary]

oh damn my latex skills on point

my initial thought is that for some reason we end up with 7^2

is that because we divid 4 with the log's base or something?

im not sure whats happening here

or maybe this is a better way to look at it?

yea alright, i think the alternative representation makes it very clear

is it best to just re-order problems like this?

so its more clear

ig

.close

[cedar kiln]

Channel closed

Closed by @keen estuary

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

i don't know if this is the right place to ask but im desperate

is return on equity calculated using total equity or contributed equity??

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

@crimson sedge Has your question been resolved?

[solemn torrent]

Damn might as well ask a finance server but maybe just read the wiki article

You might find your answer in the DuPont Analysis

https://en.wikipedia.org/wiki/DuPont_analysis

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[worn heart]

Hello there, I don't understand this problem and don't exactly know how to do it.
(edit: i know what it's asking, i just don't know how to solve it)

[safe agate]

Try to multiply (one of) the equations so that that you can cancel out a variable

[cedar kiln]

@worn heart Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jovial prism]

here is my work for this question

but i couldn't seem to find where i made a mistake

I was trying to use Variation of Parameters (Wronskian) method thingy

<@&286206848099549185>

anyhelp is appreciated i just could find where i make a mistake is probably some basic math

[cedar kiln]

@jovial prism Has your question been resolved?

[jovial prism]

<@&286206848099549185>

Problem solved me big brain

I did my Integraul erong

[cedar kiln]

@jovial prism Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[exotic hamlet]

I have to determine if this vectors span R3, but I don't know how to continue

[crimson sedge]

aren't you already done here? If I remember correctly every row needs to have a pivot and is linearly independent

[exotic hamlet]

Can linearly dependent vectors not span?

[crimson sedge]

i mean sure, but i would assume a dependent vector would not be making an additional dimension possible

im rusty with my linear algebra tho so might as well wait for someone else

two linearly independent vectors span R^2, three span R^3

https://en.wikipedia.org/wiki/Rank_(linear_algebra)

[crimson sedge]

tobyyy

saves it again 🙏🏻

kind of funny how i was doubtful of such a basic fact, too

[cedar kiln]

@exotic hamlet Has your question been resolved?

Channel closed

Closed by @exotic hamlet

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[long stag]

I am given this power series which converges when -13 < x < -5

[long stag]

The estimated sum is

when -13 < x < -5

Question is. How do I determine c1, c2 and c3?

[jovial smelt]

is the estimated sum just the value of the power series?

[long stag]

I think it's meant as the sum from n=1 to N

[jovial smelt]

but it doesn't depend on N?

[long stag]

It hasn't been specified so clearly, so i am not sure

It could also be the exact value

[jovial smelt]

I think it might be that S is the function associated to the power series

[long stag]

It's probable

[jovial smelt]

what have you tried so far to find c1, c2 and c3?

[long stag]

Nothing, I am blank right now. I have the answers, but I am unsure of the methodology

Those are c1,c2 and c3

[jovial smelt]

huh

ok, well how I'd do it is probably try to evaluate my power series in certain well chosen values

since I could in theory exactly calculate the value of the power series for any x, I could get a system of equations that let me solve for the unkowns

the difficulty here is choosing which x to evaluate the power series at

[long stag]

Yea. We know that -13 < x < -5

[long stag]

How would you get this system?

[jovial smelt]

what I mean is say I pick x = -9

then that gives me S(-9) = [something that involves c1, c2 and c3]

but since S is the function associated to the power series, I also get that if I replace x by -9 in the power series, I get S(-9)

[long stag]

This happens to be 0

[jovial smelt]

in this case, -9 cancels the 9, and I get 0^n, which is 0

yeah

and if I evaluate S at -9 I get (c1 - 9)/(-9c2 + c3)

[long stag]

so (c1 - 9)/(-9c2 + c3)=0?

[jovial smelt]

yep!

[long stag]

Is one equation

AHA

I see u

[jovial smelt]

what does that tell you about c1?

[long stag]

That it's 9

[jovial smelt]

exactly

[long stag]

omg u are a genius

[jovial smelt]

one down

that was the easy one

now you have to choose another x, but you have to choose is so that you can still calculate the power series relatively easily

[long stag]

I see

So rn S(x)=

[jovial smelt]

yeah

[long stag]

I'm thinking x=-8 would make it "easy", so it just becomes an alternating series

[jovial smelt]

good idea

I think it is possible to explicitly calculate that

but not the easiest

is there a way to make it a non alternating series?

[long stag]

Hm...

Well absolute value, but wouldn't that make it divergent?

[jovial smelt]

wait actually nevermind, alternating is fine

taking the absolute value wouldn't give you S(x) anymore

ok so if you plug in x = -8 as you did, what is the sum?

[jovial smelt]

yeah

sum of those

now

have you seen 1 + x + x^2 + x^3 + ....

the power series of x^n

[long stag]

Yea x/(1-x)

Right?

The sum of x^n

[jovial smelt]

well sanity check, if you plug in x = 0, you should get 1

its 1/(1-x), that one is good to just know by heart (not that you can't re derive it if you really want to)

and so that power series converges for -1 < x < 1, right?

[long stag]

Oh yea thats from n=0

[long stag]

yes

[jovial smelt]

ah, yeah

I'm used to power series starting at 0, my bad

you're right, x/(1-x)

[jovial smelt]

I don't mean the sum from 1 to N though, I mean the infinite power series

[long stag]

xDD

[jovial smelt]

ok so you want to calculate the power series of (-1)^n/4^(n+2)

[jovial smelt]

is there a way to make that look like this?

[long stag]

Time to think

Yes, but i am messing it up rn

My mind is fried from doing fourier series

[jovial smelt]

I have to go very soon so I'll give you a hint if you want

[long stag]

Oh okay, yes please c:

[jovial smelt]

since 1/4^(n+2) = 1/4^n * 1/2^2, you can factor out 1/2^2 = 1/4 from each term of your sum

so you get 1/4 * sum of (-1/4)^n

since -1/4 is less than 1 in absolute value, you can use the fact that the power series converges to x/(1-x)

with x = -1/4

[long stag]

OY

[jovial smelt]

so you get the value of the power series

[long stag]

Yeaaa i see

Omg you are a life saver

Thank you so much

[jovial smelt]

haha np

[long stag]

You made it rlly easy to understand

[jovial smelt]

for other values of x, maybe try setting x such that (9+x)^n "plays nicely" with 1/4^(n+2)

but yeah, really using x + x^2 + x^3 + .... = x/(1-x) is the main idea here

[long stag]

I think I'll be able to do the rest from here

Thanks a ton

[jovial smelt]

great, good luck

seeya

[long stag]

Take care!

[cedar kiln]

@long stag Has your question been resolved?

Channel closed

Closed by @long stag

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wispy ridge]

Hey guys how to get 12 % of 250 ?

[weak lake]

250*0.12

to convert percentage to decimal you move it two decimals to the right

[wispy ridge]

thx

[cedar kiln]

@wispy ridge Has your question been resolved?

Channel closed

Closed by @wispy ridge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sick orbit]

What is the length of the hypotenuse

[cedar kiln]

@crimson sedge Has your question been resolved?

[crimson sedge]

just tell me the answer mf

[sick orbit]

nah g never

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[bold hazel]

my textbook doesn't really explain how this works

[sick orbit]

the highest degree of power in the numerator is 2

yes?

[bold hazel]

yes

[sick orbit]

and the highest degree of power in the denominator is also 2

[bold hazel]

yup

[sick orbit]

therefore u can divide using long division or comparing coefficients

[bold hazel]

interesting

so the remainder is 3x+5

after doing long division just on the x^2

I see a little minus sign

so it looks like you're actually doing a subtraction

subtracting x^2-4 from the polynomial above it

[sick orbit]

i mean that is how long division works

[bold hazel]

oh, sheit

totally forgot

[sick orbit]

cuz 1 multiplied by x^2-4 is x^2-4

[bold hazel]

sheit

ok

kinda confused about that part

well, no, I think I get it

so this one for example

x^2 - x

= x

[sick orbit]

?

[bold hazel]

idk

I might have to draw this

don't have a pencil/paper rn

uhhh

hm

[sick orbit]

watchu get

[cedar kiln]

@bold hazel Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[marble ermine]

Hello, can you explain me what infinitesimals are?

[gaunt hamlet]

I'm not sure a question like this is suited for a help channel. One of the discussion channels might be better imo

[dire geode]

https://en.wikipedia.org/wiki/Infinitesimal

[marble ermine]

uhm ok

[marble ermine]

and why is that for?

.close

[cedar kiln]

Channel closed

Closed by @marble ermine

Use .reopen if this was a mistake.

[marble ermine]

.reopen

[cedar kiln]

✅

[marble ermine]

.close

[cedar kiln]

Channel closed

Closed by @marble ermine

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

Hi

[crimson sedge]

I don't like algebra

ALGEBRA

ALGEBRA

[woven linden]

uhh why?

also is this really a problem?

[crimson sedge]

It's confusing

Yes

I need to send it

Wait

[woven linden]

explain whats confusing and i could help depending on what it is

is this alg 2 or 1?

are you even still here?

.close

[cedar kiln]

Channel closed

Closed by @woven linden

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tame coyote]

Hello! I hope that you are doing well. I have a question regarding Rolle's Theorem. I solved this question but am unsure of the answer. May you please check if i made the right steps and got the correct answer? Thank you and here are the 3 pictures that show my work. Let me know if my handwriting is unclear for any reason...

[tame coyote]

<@&286206848099549185> may you help me know whether my steps and answer is correct?

Hello?

nevermind i got the answer

.close

[cedar kiln]

Channel closed

Closed by @tame coyote

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[bold hazel]

wondering if I did this right

[haughty wraith]

9--36

= 9+36

[tall wraith]

You're confused in this step.
Its: (-6x + 9) - (-6x - 36).

[cedar kiln]

@bold hazel Has your question been resolved?