#help-13

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maiden garnet
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  1. Write a Matlab function that gives the value of S100 where limn→+∞ Sn = S
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  1. Create a Matlab function that uses Newton's method to evaluate S, taking
    |S100 − Sn| as test stop
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anyone good at numeric analyse can help me in the second Q

cedar kilnBOT
#

@maiden garnet Has your question been resolved?

maiden garnet
#
  1. Write a Matlab function that gives the value of S100 where limn→+∞ Sn = S
  2. Create a Matlab function that uses Newton's method to evaluate S, taking
    |S100 − Sn| as test stop
    anyone good at numeric analyse can help me in the second Q
cedar kilnBOT
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@maiden garnet Has your question been resolved?

maiden garnet
#

ccc

cedar kilnBOT
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@maiden garnet Has your question been resolved?

cedar kilnBOT
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@maiden garnet Has your question been resolved?

cedar kilnBOT
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crimson sedge
cedar kilnBOT
crimson sedge
#

So my proposed solution to b) is that the coefficient matrix defines a linear map that takes the solution vector to the 0 vector

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and there is a property of linear transformations s.t. if there is a linear transformation T, a solution vector v and a scalar multiple c then T(cv) = cT(v) = c * 0 = 0

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is this correct?

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<@&286206848099549185>

cedar kilnBOT
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@crimson sedge Has your question been resolved?

crimson sedge
#

<@&286206848099549185>

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<@&286206848099549185>

cedar kilnBOT
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@crimson sedge Has your question been resolved?

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old salmon
cedar kilnBOT
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still tartan
cedar kilnBOT
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limpid brook
cedar kilnBOT
limpid brook
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Im doing this rn but i dont understand how google got 36 for one of it

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where did they get -36x

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i got 3(36x^2 - 18x + 2x)
= 108x^2 -54 + 6x

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(not including the other side)

cedar kilnBOT
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@limpid brook Has your question been resolved?

limpid brook
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yes super

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thnks

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bhAHAH

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I get it

rain drift
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lol

cedar kilnBOT
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rain drift
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I was just reading it

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you got it?

limpid brook
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yeah

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i was right

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i didnt do any mistakes

cedar kilnBOT
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slender warren
#

At where the arrow pointed, I'm wondering can I perform integration at this state cuz I still see e^2x? Or I can just do integration like what I've written

solid juniper
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wellll

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no, not quite :c

slender warren
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aww

solid juniper
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but e^(2x) = 1 - u

slender warren
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oooo

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lemme redo this -

solid juniper
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but i think it's like

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still kinda complicated

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also umm

slender warren
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yea integration is a hard topic for me

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yea?

solid juniper
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never mind haha

slender warren
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Man

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I still have e^(2x)

solid juniper
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how not $-\frac{1}{2}\int\frac{u^{-1/2}}{1-u}du$?

wraith daggerBOT
#

💜𝓁𝒶𝓎𝓁𝒶💜

slender warren
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what's this?

solid juniper
slender warren
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OHH

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ok I was dumb

solid juniper
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nooo 😭

slender warren
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yea I swapped the numerator instead of the denominator after u hinted HAHA

solid juniper
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the integral is still ☠️

slender warren
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I think this time I got it right?

solid juniper
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idt that's right bearlain

slender warren
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nani

solid juniper
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explain?

slender warren
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I separate them?

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nvm

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I noticed something

slender warren
cedar kilnBOT
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@slender warren Has your question been resolved?

solid juniper
slender warren
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I just press calculator

solid juniper
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idt this is right?

slender warren
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oh ya now u remind me, I couldn't just separate

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man idk how to continue with this

cedar kilnBOT
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@slender warren Has your question been resolved?

cedar kilnBOT
#

@slender warren Has your question been resolved?

pulsar pulsar
pulsar pulsar
# slender warren

if you're unsure whether your solution is correct, a way to verify it is by just differentiating your solution and checking whether it matches the given integrand

slender warren
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im kinda a slow learner, can u explain a bit on the denominator part?

pulsar pulsar
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let me get more paper

pulsar pulsar
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just some exponent laws

slender warren
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wowww understood the denominator part

pulsar pulsar
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👍

slender warren
pulsar pulsar
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because we want to bring it into a form such that the denominator's derivative is in the numerator

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because ∫ f'(x)dx/f(x) is something we can integrate to log| f(x) | + C.

slender warren
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U mean like this formula?

pulsar pulsar
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mhm

slender warren
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They are same right?

pulsar pulsar
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yep, just θ as the variable instead of x

slender warren
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ok I understood the rest, but this part is so hard, I dont think I can think of it when it comes to exam 🗿

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thanks for teaching me patiently btw

pulsar pulsar
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I did it just to show you

slender warren
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ohhhh

pulsar pulsar
slender warren
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yeah

slender warren
pulsar pulsar
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I see

slender warren
pulsar pulsar
#

There are more 'standard form' integrals which you might learn later on

slender warren
#

oooo okie thanks

#

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cedar kilnBOT
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bold hazel
cedar kilnBOT
bold hazel
#

is this the right approach?

cedar kilnBOT
#

@bold hazel Has your question been resolved?

cedar kilnBOT
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supple mortar
#

Anyone know what tally means

cedar kilnBOT
supple mortar
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So just tally like

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So the first one would have no tally

tame zodiac
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yes but over 5 is different

supple mortar
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But the third one will have I

tame zodiac
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yes

supple mortar
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When it’s 5 don’t you put a cross into it

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Then start again

tame zodiac
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yrs

supple mortar
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Thank you for your help

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Was just a little confused

cedar kilnBOT
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fickle ermine
cedar kilnBOT
fickle ermine
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i forget the algorithm to solve this

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pls help me how to solve

crimson sedge
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100=2^2*5^2, so you could use crt

fickle ermine
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yep then

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y^3= 3 mod 4

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y^3= 7 mod 25 right?

crimson sedge
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no, the right is still 21 in both lines

fickle ermine
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and what is crt?

dry heart
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chinese remainder theorem

fickle ermine
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oh got it

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then

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y^3 =21 (mod 4), y^3= 21 (mod 25)

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=> y^3= 1 (mod4) , y^3 = 21 (mod 25) right?

crimson sedge
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yea

fickle ermine
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then how could i get a y^3= 21( mod 25) ?

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Just put natural numbers?

crimson sedge
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we know y^3=1 mod 5, so we only have to check 5 things

fickle ermine
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wait where it is come from y^3=1 mod 5

crimson sedge
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well if y^3=21 mod 25, then we definitely have y^3=1mod5

fickle ermine
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how does it work?

crimson sedge
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25=5^2

fickle ermine
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yep

crimson sedge
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so anything that holds mod 25 must hold mod 5

fickle ermine
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i see

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then the answer is 1..?

crimson sedge
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its 1 mod 5, but we need to check 1,6,11,16,21 mod 25 (because crt only works if its coprime)

fickle ermine
#

.close

cedar kilnBOT
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cedar kilnBOT
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patent bone
#

does anybody know the answer to this?

cedar kilnBOT
patent bone
#

I’ve already solved it but it doesn’t give me the correct answer

opal basin
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what answers did you get?

patent bone
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2(x-2)(x-1/2)

opal basin
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yes

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that's correct

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but do they want you to find the roots?

patent bone
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they gave me these options

opal basin
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one of them is correct, but it's written in another way

patent bone
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which one?

opal basin
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notice how you can distribute the 2 to get (x - 2)(2x - 1), which is closer to the answer

patent bone
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yeah but the signs change

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x has to be positive

opal basin
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how do you mean, x can be any real number

patent bone
opal basin
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if you distribute 2(x - 2)(x - 1/2) you get 2x^2 - 5x + 2

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why can't x be negative?

patent bone
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But won’t it be (2x-1)(x-2)

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There’s no option with those numbers

opal basin
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that's the same as (x - 2)(2x - 1)

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but (x - 2) = -(2 - x) and (2x - 1) = -(1 - 2x)

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so (x - 2)(2x - 1) = -1 * (2 - x) * -1 * (1 - 2x)

patent bone
#

Oh ok that makes sense thank you

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wintry wasp
#

How do i write the following sum in closed form: $$\sum_{i=1}^{100} i*x^{i-1} $$

south tundra
#

100 instead of \100

wraith daggerBOT
#

نعمان

wintry wasp
crystal raptor
#

The inside looks suspiciously like a derivative..

wintry wasp
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yeah you're right

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Weve never really been thought about evaluating sums, this was a problem from the chapter on integration so idk how to go about this.

crystal raptor
wintry wasp
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Okey thank you

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OHH

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oh okey i get it, thanks alot!

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crimson sedge
cedar kilnBOT
crimson sedge
#

I had those questions and a document attached, those are just my answers

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I have no way to know if that's how to do it and was lost on q4 especially

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Skipped a for q4 for now

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

crimson sedge
#

<@&286206848099549185>

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

crimson sedge
#

<@&286206848099549185>

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

crimson sedge
#

No

#

<@&286206848099549185>

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

short blade
#

@crimson sedge what do you need help with exactly

short blade
# crimson sedge

part a should be fairly clear. the function is even and they provide you what it looks like from x=0 to x=2pi, so for x=-2pi to x=0 it's just the mirror image of that

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then the function repeats since it is periodic with period 4pi

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for b, recall that the fourier series for $f(x)$ with period $2p$ is expressed as $$f(x)=\frac{a_0}{2}+ \sum_{n=1}^\infty a_n\cos(\frac{n\pi x}{p}) + b_n\sin(\frac{n\pi x}{p})$$ where $$a_n=\frac{1}{p}\int_{-\infty}^\infty f(x)\cos(\frac{n\pi x}{p}), dx$$ and $$b_n=\frac{1}{p}\int_{-\infty}^\infty f(x)\sin(\frac{n\pi x}{p}), dx$$

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since f(x) is even, it should be clear that b_n is 0 for all n

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so your task is to find the first 5 a_n such that a_n=/=0

wraith daggerBOT
#

maximo

crimson sedge
#

Thx for the reply mate

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I'm prolly in a different timezone to u

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The a_n I found includes like a sin(npi/2) and I don't know how to simplify that

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@short blade

granite peak
#

a level math right there

open plover
#

help

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@cedar kiln

short blade
short blade
crimson sedge
short blade
#

and also, i didn’t mention this but your $a_0$ can be found with $$\frac{1}{p}\int_{-p}^p f(x), dx$$

wraith daggerBOT
#

maximo

crimson sedge
crimson sedge
crimson sedge
short blade
#

oh

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so

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sin(npi/2) can be 0 as well

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and cos(npi/2) can be nonzero

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it’s a little more nuanced than that i guess 😂

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i think it should be fine to leave them as they are

crimson sedge
#

Lol😂

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Aight g 🙌

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I looked through it earlier and picked out my miscalculations too

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Thanks

#

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crimson sedge
cedar kilnBOT
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crimson sedge
#

Anyone know how to find θ?

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slim crown
#

I end up getting an awful looking cubic, how am I meant to do this?

slim crown
#

I have (2(n+1)(n+2)(2n+1))/6 + (n(n+1))/2 - n = 454n

cedar kilnBOT
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@slim crown Has your question been resolved?

dire geode
fair geyser
#

i was going to explain how you have (2(n+1)(n+2)(2n+1))/6 + (n(n+1))/2 - n = 454n

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then i read that you already do

slim crown
#

and I dont feel I can factorise something with that

dire geode
#

Something like 2 * sum r^2 + sum r - sum 1

slim crown
#

the sum of r^2 is (n+1)(n+2)(2n+1)/6 right?

#

oh

#

right

#

its n(n+1)(2n+1)/6

dire geode
slim crown
#

thanks

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crimson sedge
#

Finding z1 and z2?

cedar kilnBOT
crimson sedge
#

Let $z_1 = x + iy$ and $z_2 = u + iw$

wraith daggerBOT
crimson sedge
#

Hmm okay and then?

#

$z_1 + z_2 = (x + u) + i(y + w)$

wraith daggerBOT
crimson sedge
#

$(x + u) + i(y + w) = 4 + 4i \implies x + u = 4, y + w = 4$

wraith daggerBOT
crimson sedge
#

now do the same for the second equation

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keeping in mind that $\overline{z_2}$ is the conjugate of $z_2$, i.e. the complex number whose imaginary component is $-iw$

wraith daggerBOT
crimson sedge
#

Oooooh thank youuuuu

#

You da best

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@formal geyser Has your question been resolved?

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@formal geyser Has your question been resolved?

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ivory finch
#

$ Compute\ \frac{dy}{dx}\ if\ xe^{y}\ =\ 2xy$

wraith daggerBOT
#

cookie2

ivory finch
#

Can anyone tell me step by step what I do?

runic garnet
#

Product rule on both sides

cedar kilnBOT
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@ivory finch Has your question been resolved?

dire geode
cedar kilnBOT
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mossy spruce
#

are these the same

cedar kilnBOT
zenith sail
#

No, $\sqrt{a+b}$ is not the same as $\sqrt{a}+\sqrt{b}$ in general

wraith daggerBOT
#

tatpoj

mossy spruce
#

okay that makes sense thank you!

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plush solstice
#

Hi :)) Small question, how do I develop a power series (?) of a given function like this one? I know already the formula of the power series but cant seem to be able to apply it efficiently. I need to develop this power series given a development point "a" and further give its convergence radius

plush solstice
#

so 1/c-x for c != "a" and with "a" part of R

#

As a help tip we know that the geometric series is of help in this case

cedar kilnBOT
#

@plush solstice Has your question been resolved?

plush solstice
#

<@&286206848099549185> Do you have any idea? If not I can just leave it, no problem

dire geode
#

c-x = c(1-(x/c))

plush solstice
#

this is supposed to be a function f(x) and we are supposed to look for the correspondent power series

#

ok no worries

#

ill figure it out somehow

#

.close

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ivory finch
cedar kilnBOT
#

Please don't occupy multiple help channels.

ivory finch
#

How do I simplify if it's 0/0?

dire geode
dire geode
#

.close

cedar kilnBOT
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cedar kilnBOT
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bold hazel
#

trying to understand what this problem is asking

bold hazel
#

"For the following exercises, draw an outline of the solid and find the volume using the slicing method."

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this is the example it gives

cedar kilnBOT
#

@bold hazel Has your question been resolved?

bold hazel
#

this is such a stupid problem

#

my textbook is stupid lol

cedar kilnBOT
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@bold hazel Has your question been resolved?

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hardy island
#

How could I find the Minimum distance between two functions, for optimization

tough aurora
#

You can make a function of distance

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Then find the minimum of that one

wraith daggerBOT
hardy island
#

Yea I got the distance formula

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Also I’m specifically trying to find the minimum vertical distance

cedar kilnBOT
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cedar kilnBOT
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@uncut crow Has your question been resolved?

cedar kilnBOT
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@uncut crow Has your question been resolved?

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vestal bear
cedar kilnBOT
vestal bear
#

I put it into photomaths and i got some bizzare answer

gaunt hamlet
#

I can see why

vestal bear
#

I have no clue how to do this and I think its kind of embarrassing for me

gaunt hamlet
#

Nvm

#

Try u sub

vestal bear
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I did

gaunt hamlet
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What did you get

crimson sedge
#

You can take u = x+2 and then x^2 = (u-2)^2 lol

vestal bear
#

Wait shit

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I thought of that but rejected it because it didnt work another time

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Because it was on the bottom of the fraction

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I'm stupid

#

Ty

#

.close

cedar kilnBOT
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keen furnace
cedar kilnBOT
#

Please don't occupy multiple help channels.

gaunt hamlet
#

Bro

#

Open ONE CHANNEL

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And wait

crimson sedge
#

Bruh <@&268886789983436800>

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This person spammed literally every channel

calm sierra
#

@keen furnace pls use only 1 channel

cedar kilnBOT
#

@keen furnace Has your question been resolved?

obsidian tinsel
#

The formula for distance between two points is sqrt((x1-x2)^2 + (y1-y2)^2)), and we are comparing the points on a line and the point at the origin, so we plug in 0 and 0 for x2 and y2, and we plug in x and y(which is 3x-10) into x1 and y1.

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We get Distance = sqrt(x^2 + (3x-10)^2)

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But we want to find the least distance, an x that makes the distance the smallest, a minimum. Thus we want the derivative. Take the derivative of Distance. Find it’s critical point where derivative is zero. Find the minimum. BOOM, u found the x that makes a minimum

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We know the x that gives the shortest distance between one of the points on a line and the origin. In order to find the value of that distance, we plug in this x back into our equation for the distance between points on a line and the origin.

#

@keen furnace

cedar kilnBOT
#

@keen furnace Has your question been resolved?

cloud lily
cedar kilnBOT
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turbid portal
#

Does anyone know how to do the Empirical Rule part? I am confused since we hardly covered this part in class

cedar kilnBOT
#

@turbid portal Has your question been resolved?

rain drift
#

The empirical rule, also known as the three-sigma rule or the 68-95-99.7 rule, is a statistical rule that states that almost all observed data for a normal distribution will fall within three standard deviations (denoted by σ) of the mean or average (denoted by µ).

#

so it looks like 68%

turbid portal
#

Oh I see. I knew it had those three numbers but didn't know if I could use it in my answer

lyric nymph
#

Yall could anyone help with this problem: A street light is at the top of a 18 ft pole. A 5 ft tall girl walks along a straight path away from the pole with a speed of 7 ft/sec.

At what rate is the tip of her shadow moving away from the light (away from the top of the pole) when the girl is 28 ft away from the pole?

I got 126/13 but it's not the right answer.

turbid portal
#

It's not 68

rain drift
lyric nymph
#

(Don’t mind the questions everyone)

rain drift
#

uhh

cedar kilnBOT
#
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turbid portal
#

.reopen

cedar kilnBOT
#

rain drift
#

ooooh

#

right

#

okay

#

so one std deviation below the mean is $\mu - \sigma$ right?

wraith daggerBOT
#

MellowDramaLlama

rain drift
#

so you've already figured out that $\mu - \sigma = -28$

wraith daggerBOT
#

MellowDramaLlama

turbid portal
#

yes

rain drift
#

wait no

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sorry

#

stats is not my strong suit lol

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bare with me

turbid portal
#

its okay

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its not mine either lol

#

well I'm currently in probability

rain drift
#

uhhhhh. Okay so like just a stretch but like if you did 100 - 68, you get 32%. So then we have for anything past 68% (aka 1 std deviation), then at least 1 would exclude the middle section

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so then we get 32%

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however since we're only dealing with 1 std deviation away, then we only need to worry about 1 side of the bell curve

#

so uhh

#

I'm gonna say 16%?

#

I have no idea if that's right or not lol but try it out

#

so like this is the idea

#

the dark yellow box is what we care about here

rain drift
turbid portal
#

16%?

#

Yes it was correct

#

i was literally in between

#

i was either putting 15.5 or 16.5 lol

rain drift
#

haha!

#

does that logic make sense though?

turbid portal
#

yes it does

#

thank you very much for your help

#

.close

cedar kilnBOT
#
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crimson sedge
#

what does 5 units and ten square means on a graph

crimson sedge
#

like 25 - 30

#

5 units and how is this 10 squares

echo veldt
#

I guess the graph's "boxes" just represent 1/2 or 0.5. So 2 "boxes" means 1 unit. Just how the graph was designed

crimson sedge
#

right - ty

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

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winged pewter
#

I don’t get the 1/2

cedar kilnBOT
winged pewter
#

How is it 1/2

dire geode
#

What they mean is each term in parentheses is greater than 1/2

#

n/n > 1/2, (n-1)/n > 1/2, etc

rain drift
#

ooooh yeah totally

#

it's the convergence comparison

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but yeah that's super confusing

dire geode
#

Should have > next to each of the 1/2

cedar kilnBOT
#

@winged pewter Has your question been resolved?

winged pewter
#

Thanks

#

.close

cedar kilnBOT
#
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rocky wave
#

$x^\log(x) = \log_x(\frac{x^3}{100})$

cedar kilnBOT
wraith daggerBOT
#

WhyWouldYouKap

$x^\log(x) = \log_x(\frac{x^3}{100})$
```Compilation error:```! Missing { inserted.
<to be read again> 
                   \tex_let:D 
l.57 $x^\log
            (x) = \log_x(\frac{x^3}{100})$
A left brace was mandatory here, so I've put one in.
You might want to delete and/or insert some corrections
so that I will find a matching right brace soon.
(If you're confused by all this, try typing `I}' now.)```
rocky wave
#

$x^{\log(x)} = \log_x(\frac{x^3}{100})$

wraith daggerBOT
#

WhyWouldYouKap

rain drift
#

so just to double check, the LHS is $x^{log_{10}(x)}$?

wraith daggerBOT
#

MellowDramaLlama

rocky wave
#

yes

rain drift
#

okay cool

#

welp

rocky wave
#

i assumed i didnt need the base

rain drift
#

hmm

rocky wave
#

with base 10

rain drift
#

nah you don't

#

it's implied

rocky wave
#

ok chill

rain drift
#

but it's good to double check

#

okay so the first thing I can see that we can do is simplify the RHS

#

$log_x\left(\frac{x^3}{100}\right) = log_x(x^3) - log_x(100) = 3 - log_x(100)$

wraith daggerBOT
#

MellowDramaLlama

rocky wave
#

ok fair

rain drift
#

not sure if that will help

#

just trying stuff out lol

#

dang

#

I know I'm just barely missing something lol

#

so there's a log rule that states $log_a(b) = \frac{1}{log_b(a)}$. So we could transform $x^{log(x)}$ into $x^{\frac{1}{log_x(10)}$

rocky wave
#

u need the slash before the logs

wraith daggerBOT
#

MellowDramaLlama
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

rocky wave
#

oh fair

#

thats so smart

rain drift
#

So then $\frac{1}{log_x(10)} = log_x(10)^{-1}$, so $x^{(log_x(10)^{-1}}$

wraith daggerBOT
#

MellowDramaLlama

rain drift
#

I dont think that'll help though

rocky wave
#

nah i dont think that will help

rain drift
#

boo

#

BOO

#

umm

rocky wave
#

idk

rain drift
#

and you're not allowed to just graph it and look? lol

#

it looks like the answer is x = 0.14

#

I think

#

aaaand just to confirm the goal is to find x right? Lmao

rocky wave
#

yep

#

there has to be a way to get to that

rain drift
#

yeah there is

#

I normally am pretty good at log stuff

#

but this has me stumped

#

hmm

rocky wave
#

this was in my maths test earlier

#

is there any way to remove the power

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bc that would help to isolate the x

rain drift
#

oh my

#

I feel silly (I think lol)

#

$a^{log(b)} = b^{log(a)}$

wraith daggerBOT
#

MellowDramaLlama

rain drift
#

nope nvm

#

that does nothing haha

rocky wave
#

yeah was about to say

rain drift
#

and we're sure that the RHS has log_x? and it's not just x^3/100?

rocky wave
#

100%

#

was in my maths test this morning

#

i cant give proof

rain drift
#

yeah no problem

#

I'm just looking for holes lmao

#

see it's such a weird problem because like if it was x^3/1000, then we could do (x/10)^3 and pull out that 3

#

all of my normal tools are not working! D:

rocky wave
#

sorry

rain drift
#

no worries

#

honestly I gotta go to bed, I was trying to solve this before bed. If I come up with a solution I'll DM yeah

rocky wave
#

all good mate

#

thanks for ur help

#

ur a legend

rain drift
#

in the meantime it might be good to see if @Helpers can help or just .close the thread and reopen to get pushed on the stack

#

lol thank you

#

g'night!

rocky wave
#

yeah ill close

#

thanks mate

#

.close

cedar kilnBOT
#
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rich sandal
#

If you tried to evaluate this from left to right, would it be the same as taking two double integrals? One for the region above the x axis and the one below.

rich sandal
#

So it's easier to just go from -x to sqrt of x

#

and 0 to 3

#

More like I'm wondering if these are both the same

cedar kilnBOT
#

@rich sandal Has your question been resolved?

cedar kilnBOT
#

@rich sandal Has your question been resolved?

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cedar kilnBOT
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void marsh
cedar kilnBOT
void marsh
#

please hel

upbeat lotus
#

This is an English exam

#

Could you extract the length of any line by this data

cedar kilnBOT
#

@void marsh Has your question been resolved?

zenith sail
# void marsh x

You're provided a diagram, it just isn't completely labeled.

#

Which segments can you label from the given information?

cedar kilnBOT
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crimson sedge
#

I Need help with a question about probability

crimson sedge
#

I’m finding the wording of the question very odd

#

Like what’s X

celest maple
#

Try using that

#

Like a random number other and greater than 6

crimson sedge
#

But there’s only 1 die

#

Which means there’s only 6 sides

celest maple
#

Start a new one

crimson sedge
#

A new what

celest maple
#

Nvm

#

I just reread it

#

X is like the number that appears the most when you roll the dice

crimson sedge
#

So it would be 1 or 2

#

Since they have .25

celest maple
#

I think they are asking on what’s the number after 1 roll

celest maple
crimson sedge
#

Yeah so I’d write down 25%

celest maple
#

Your answer could be like 1 or 2

#

Or maybe 3 and 4

#

Depends on the roll

crimson sedge
#

This question is bugging me greatly it’s so weird the way they structured it

celest maple
#

It’s hard to understand

#

But I hope you get an point

crimson sedge
#

Exactly yeah I get a point but it has to be right it’s worth like 10% of the test

#

That were doing tomorrow

celest maple
#

Oh

#

That’s sad

crimson sedge
#

Exactly

#

Why does this happen to people man

#

10% for a question that doesn’t make sense

celest maple
#

Yeah

#

But you understand it now?

crimson sedge
#

I think so

celest maple
#

Ok

#

You sure?

#

I can explain it deeper if you want me to

crimson sedge
#

Yes please I reread the question

celest maple
#

Ok

#

You have a chart

#

6 numbers in a dice

crimson sedge
#

Yes

celest maple
#

There are different chances of getting that number

#

The highest one is 1 and 2 and mostly the chances of landing that are 1 in 3

#

The variable X

#

Asks you to find the number that has the highest chance of pulling it

#

Then to the lowest number

#

Alright?

crimson sedge
#

How would it be 1 in 3 wouldn’t it be in one in six or two in six since that’s how many chances you have

#

No it’s how many options they’re are

celest maple
#

So there’s a chance on landing it and not

crimson sedge
#

Yes so it would be 2 chances instead of 3 wouldn’t it

#

?

celest maple
#

That’s optional

crimson sedge
#

So the answer is 1/2 or 1/3

#

Or would it be 2 over 6

#

Since those are two highest

celest maple
#

Yeah

#

Sr my if I am responding lately, I am currently outside in the cold

#

💀

crimson sedge
#

💀

#

Why

celest maple
#

Yk

#

Average day for a 13 yr old

crimson sedge
#

Your 13?

celest maple
#

Yes going to school

crimson sedge
#

And your good at math?

celest maple
celest maple
crimson sedge
#

How?

celest maple
#

Don’t ask

crimson sedge
#

Alright thanks for your help

celest maple
#

Np

crimson sedge
#

Appreciate your time

celest maple
#

Thanks, you too

#

.close to close the channel

crimson sedge
#

.close

cedar kilnBOT
#
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halcyon jacinth
cedar kilnBOT
halcyon jacinth
#

Can anyone help me to solve 4 and 5?

crimson sedge
#

just think of it as f(g(h(x)))

#

for the first one

#

and work from inside out

#

the h(x) will be considered as the input to function g

#

so you would substitute the h(x) into g(h(x)) as you would for say, g(2), g(x+1), g(z)

#

For your second question, a one to one function basically denotes the mapping of two sets. A function g is one-to-one if every element of the range of g corresponds to exactly one

crimson sedge
#

Well, there is a lot of methods

halcyon jacinth
#

Can u show one pls?

crimson sedge
#

most commonly is the horizontal line test. But that isn't available right now

#

So instead, if you can show that $f(x) = f(y) \to x = y$ then a function is one-to one

wraith daggerBOT
#

♡LexQa♡

halcyon jacinth
#

Can I solve it and show it to you in your dms?

crimson sedge
#

the converse is also true, if you can show that $x \neq y \to f(x) \neq f(y)$ then the function is one-to-one

wraith daggerBOT
#

♡LexQa♡

crimson sedge
halcyon jacinth
#

Dming u

cedar kilnBOT
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autumn oxide
#

Have you been given a formula for the volume of a sphere?

#

If you're given a reference/formula sheet of any kind it's typically on there

cedar kilnBOT
#

@slow mirage Has your question been resolved?

autumn oxide
#

sorry I was called away

#

@slow mirage in the formula r stands for radius

#

and V for volume

#

$pi$ is a number on your calculator

wraith daggerBOT
#

neptune-a-fish

autumn oxide
#

?

#

sorry i was only trying to help

#

no need to be rude

#

.close

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smoky terrace
#

Hannah finds two dice in the attic with a rather peculiar feature: they are not standard dice (which have every natural number between 1 and 6 exactly once), but both have six
certain (not necessarily different) non-zero natural numbers. Hannah notes that the probability distribution
the sum of the eyes of both dice is exactly the same as that of two standard dice.
For example, the probability of rolling a sum of 12 pips is equal to 1 . in both cases
36 .
What are all the possible pairs of dice that match the above

smoky terrace
#

but idk

fallow steppe
#

well, maybe start by writing down the probabilities of standard dice then

smoky terrace
#

i dont have time

#

and thats not the solution at all

#

so you wont help me with that

fallow steppe
#

its part of the (or at least a) solution

#

but if you dont have time to put in work, this server cannot help you

cedar kilnBOT
#

@smoky terrace Has your question been resolved?

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@smoky terrace Has your question been resolved?

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@smoky terrace Has your question been resolved?

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@smoky terrace Has your question been resolved?

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fresh summit
#

How do I find out the exponential function just by using these graphs?

wraith daggerBOT
humble sleet
#

idk if u have a point cant you substitute it to get the answer?

#

for a

#

the y intercept is (0,4)

#

so

#

f(x) = a b^x + 4

#

then

#

actually idk

#

i dont do exponentials

cedar kilnBOT
#

@fresh summit Has your question been resolved?

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late vector
#

This might be a different question. But is there an online calculator or anything that can find the equation for a polynomial from a graph?

dire geode
#

how do you expect to input a graph

#

without an equation

late vector
#

Possibly data points or image?

patent belfry
#

i mean with data points

crimson delta
#

plenty of interpolation calcs on the internet I would assume

patent belfry
#

there can be an infinite amount of polynomials that pass through a set of points

crimson delta
#

wolframalpha can do it

#

I would assume desmos can also do it

dire geode
#
late vector
#

Ok sweet, i’ll try some of these out and see what I can do! Thanks!

#

.close

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sonic bramble
#

hi

cedar kilnBOT
sonic bramble
#

is this integral setup correct?

cedar kilnBOT
#

@sonic bramble Has your question been resolved?

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.close

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tacit crescent
#

Help

cedar kilnBOT
tacit crescent
toxic moat
#

hi

#

its all

tacit crescent
#

Can I get help on this

toxic moat
#

yes

#

all

#

R

tacit crescent
#

?

toxic moat
#

the range

#

is R

tacit crescent
#

What’s the range

toxic moat
#

ok

#

so thats ur q

#

um

#

well

#

a function f takes in some inputs and maps it to some outputs

#

inputs it can take in is the domain

#

outputs it spits is called range

tacit crescent
#

I think the range is [-5, 5]

toxic moat
#

oh

#

crap

#

thrs black dots

#

im so dumb

#

yes u r right

#

hahaha

tacit crescent
#

You sure

toxic moat
#

yea

#

pretty sure

tacit crescent
#

You know what range means what’s the lowest and what’s the highest

toxic moat
#

at least 1% sure

#

err

#

no it isnt

tacit crescent
#

Yes it is

#

It’s not based off the dots

toxic moat
#

no its

#

the values it can spit out

#

consider

tacit crescent
#

So what do you think the range is and why

toxic moat
#

f(x) = 1/x

#

in the domain

#

[-1,1]\{0}

toxic moat
#

i was sayin i got it wrong previously

tacit crescent
#

What about this?

#

I think it’s (-1,7)

toxic moat
#

ye

tacit crescent
#

Can you write it in [

#

*[,]

#

[-5,5]

#

Am I correct because if I get it wrong I can’t go back

#

@toxic moat you there?

toxic moat
#

sounds like a test

tacit crescent
#

No it’s an assignment

#

Delta math

#

So what do you think the range is?

#

Hello? @toxic moat

#

.close

cedar kilnBOT
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desert zinc
#

I forgot what to do when 3b...

cedar kilnBOT
desert zinc
#

<@&286206848099549185>

eager sparrow
wraith daggerBOT
desert zinc
#

How do I also do B, C and D

weak lake
#

can you find the center of the circle?

desert zinc
desert zinc
#

Idk

eager sparrow
wraith daggerBOT
desert zinc
#

Isn't it the values in the circle equation

weak lake
#

the equation of circle is (x – h)^2 + (y – k)^2 = r^2

eager sparrow
desert zinc
#

18 and 2

desert zinc
#

Idk how to find it

weak lake
#

which question are you on?

desert zinc
#

5b

eager sparrow
#

Find the slope first

#

And sub either values between two points

#

Either way they both work

desert zinc
#

Do I do -6+2=m(-7-18)

eager sparrow
#

Nooo

#

Find the slope first using the two points

#

Do you also know how to find the slope of a line?

desert zinc
#

No

eager sparrow
#

Bruh

desert zinc
#

Isn't it the gradient

eager sparrow
#

This is much better

desert zinc
#

I then found an equation to the line by applying the gradient to the coordinates I already have?

eager sparrow
#

Yes that's how you do it

#

Wait, so your school calls slope gradient?

desert zinc
#

Yes

eager sparrow
#

Ok, so find the gradient

eager sparrow
#

Then use either the two set of points for y_1 and x_1

#

Either way, both points will work

#

Then find the perpendicular

#

Then you will have the equation of the perpendicular line for the equation

#

I got something like this @desert zinc

#

If you want to do checking or to show that this perpendicular line is correct, sub something for your equation of a circle

#

you will get a point there

desert zinc
#

Ugh

#

I got the gradient of the center of the circle and the tangent

#

But its all coming out wrong

eager sparrow
desert zinc
#

I mean point on the tangent that touches the circle

#

(-7,-6)

eager sparrow
desert zinc
#

Ty

#

I got it now

#

.close

cedar kilnBOT
#
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lapis sleet
#

could somebody please help with part B

cedar kilnBOT
#

Please don't occupy multiple help channels.

#

@lapis sleet Has your question been resolved?

cedar kilnBOT
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@lapis sleet Has your question been resolved?

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crimson sedge
#

could someone explain why I get 675.88

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

crimson sedge
#

<@&286206848099549185>

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

eager sparrow
crimson sedge
#

Yes

eager sparrow
#

If the calculator isn't set correctly, then it might be that you used degrees instead of radians.

#

You need to set your calculator first from degrees to radians

eager sparrow
#

I tried to answer the question but I set it to degrees. I also got 675.86

#

Just set it to radians and you're good to go

#

Can you take a picture of your calculator @crimson sedge ?

cedar kilnBOT
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dull stratus
#

Hello everyone, if a sequence of simple functions converges point wise to a function f, does f have to necessarily be a simple function?

dull stratus
#

I know the answer is no but not why

cedar kilnBOT
#

@dull stratus Has your question been resolved?

solid juniper
#

there are also some more overkill theorems that would tell you this

#

like every measurable function is the limit of a sequence of simple functions

#

provided you believe not every measurable function is simple

solid juniper
#

alternatively, you don’t need to start with a function and try to build a sequence of simple functions that converges to it

#

but instead just try to think of a sequence of simple functions, where each has an image larger than the previous, that converges to something

cedar kilnBOT
#

@dull stratus Has your question been resolved?

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grim fulcrum
#

hey what does this mean?

cedar kilnBOT
grim fulcrum
#

.close

cedar kilnBOT
#
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celest ibex
#

Hi, I have this exercice :

cedar kilnBOT
celest ibex
#

With this definition for the lim sup and inf :

#

I don't know how to solve that... Please help

#

I think is ? b) lim inf = N
c) lim inf A_2p = [-1,2] = lim sup A_2p and
lim inf A_2p+1 = ]-2, 1] = lim sup A_2p+1 ?

cedar kilnBOT
#

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olive heart
#

{xt=2t

cedar kilnBOT
olive heart
#

{xt=2t
{y(t)=t-1

#

write each pair of parethmetic equation as a single equation in x and y

crimson sedge
#

I assume u mean x(t) with that

olive heart
#

i forgot how to do it

#

ye my bad

crimson sedge
#

But anyways, solve for t for one of them and sub it in in the other

olive heart
#

hm ok

#

whats next?

#

thats all?

crimson sedge
#

That's it

#

Lmao

olive heart
#

nah

#

ik theres more to it

#

lmao

#

theres no way its that simple

crimson sedge
#

Well uh it is

olive heart
#

so what woud be the answer

#

like how would u write it out

crimson sedge
#

t= x(t)/2

olive heart
#

ye

crimson sedge
#

y(t) = x(t)/2 -1

#

You can simplify the fraction ig?

olive heart
#

hm

#

how would

#

u do x/2 - 1

crimson sedge
#

Uhh

#

Are u asking me how to subtract the fraction?

olive heart
#

ye

crimson sedge
#

I think you should look that up

#

Pretty dangerous to not know how to add with fractions while taking a pre calculus topic

olive heart
#

bro