z+conj(z) = 2 Re(z)
#help-13
opal ravine
wait so for complex vectors its (|u+v|² - |u+iv|²)/2
and for real vectors it would be 4<u,v>
right?
crimson delta
what is "it"
opal ravine
scalar product solution?
Idk I might be confusing you beacuse Im myself pretty confused about this lmao
crimson delta
$\langle u+v, u+v \rangle = \norm{u}^2 + 2 Re\langle u, v\rangle + \norm{v}^2$
yes?
wraith daggerBOT
Denascite
crimson delta
yes
opal ravine
yeah
crimson delta
now what about <u+iv, u+iv> ?
crimson delta
no
<u+iv,u+iv> = <u,u> + <u, iv> + <iv, u> + <iv, iv>
same as before but just now with the vector iv instead of v
what next
what can we do with the terms <u,iv> and <iv, u>
opal ravine
i<v,u>?
crimson delta
yes and then next?
opal ravine
2i*(<u,v>+<v,u>)
opal ravine
thats its equal to <u,v>-<v,u>?
crimson delta
I mean as a general identity for complex numbers
crimson delta
what is (a+bi)-(a-bi)
opal ravine
2bi?
crimson delta
imaginary part of z
crimson delta
so now putting the pieces together, what is <u,iv>+<iv, u> ?
opal ravine
2i*lm(z)?
crimson delta
and what is z
crimson delta
z=<u,v>
opal ravine
oh wait yeah
crimson delta
no
opal ravine
which is -2i| |v| |^2
crimson delta
where are you getting the 2 from
crimson delta
$\langle iv, iv\rangle = i \overline{i} \langle v, v\rangle$. where the $i$ is from the second argument and the $\overline{i}$ is from the first. now what
wraith daggerBOT
Denascite
opal ravine
But why is it conjugate(i)
crimson delta
do you know the axioms for scalar products
opal ravine
first time I hear that
crimson delta
what is a scalar product
what properties does <u,v> have to fulfill to be called a scalar product/dot product/inner product
crimson delta
$\langle \lambda x,y\rangle = \overline\lambda \langle x,y\rangle$ and $\langle x,\lambda y \rangle = \lambda \langle x,y\rangle$
wraith daggerBOT
Denascite
opal ravine
seems familiar
crimson delta
here lambda=i
opal ravine
aight
opal ravine
**Denascite**
so back to this
what is the conjugate of i?
doesnt i=sqrt(-1)
but what is the conjugate of that?
crimson delta
just -i
opal ravine
so its i-i? which is just 0
crimson delta
which is?
opal ravine
which is (-i^2)*| |v| |^2
crimson delta
what is i^2
opal ravine
1
crimson delta
no
crimson delta
yes
opal ravine
so its (-1)*| |v| |^2
crimson delta
so what is -i^2 ?
opal ravine
its 1
crimson delta
yes
opal ravine
so its just | |v| |^2
crimson delta
yes
and now lets put those things together
$\langle u+iv, u+iv \rangle = \norm{u}^2 - 2i Im \langle u, v\rangle + \norm{v}^2$
crimson delta
**Denascite**
and we got this earlier
so what do we now get if we combine them
$\norm{u+v}^2-\norm{u+iv}^2 = $ ?
wraith daggerBOT
Denascite
opal ravine
so what do we now get if we combine them
wait what
combine what
oh wait nvm
yeah
crimson delta
whoops didnt send $\norm{u+v}^2-\norm{u+iv}^2 =?$
opal ravine
wraith daggerBOT
Denascite
opal ravine
this? except this is for real vectors
what we just solved was the same but for complex ones
right?
oh wait
so we get this?
crimson delta
and now subtract those
opal ravine
and we get -2iIm(<u,v>)-2Re(<u,v>)
crimson delta
well in the other order
crimson delta
and now divide by 2
opal ravine
why do we divide it by two?
crimson delta
what formula do we want to prove?
opal ravine
scalar product of <u,v> can be computed via norms
chat isnt loading up far enough for some reason
.
Im pretty sure we dont have to divide by 2 do we?
crimson delta
.
but something is fishy here. I think we made a sign error somewhere. or the formula is wrong
opal ravine
wait did I not mention thats the answer someone else said it was when I asked them?
maybe they misunderstood my question or something
crimson delta
or maybe they did a small sign error. it's easy to mess this stuff up
opal ravine
Cant belive you stayed with me for like
holy shit 2 hours
You have my gratitude
really appriciate it
thanks a bunch
crimson delta
this is the one on wikipedia
I don't find the one you have somewhere atm
just gets messier but the idea still stays the same
crimson sedge
Is there an efficient way to calculate 10¹²⁴ mod 271?
cedar kilnBOT
Is there an efficient way to calculate 10¹²⁴ mod 271?
crimson delta
square-and-multiply
crimson sedge
Sorry, I didn't get you
crimson delta
thats the name of the algorithm
crimson sedge
Oh
crimson delta
10^124 = (10^62)^2
so if you can calculate 10^62 you can easily get 10^124
but then 10^62 = (10^31)^2
and next 10^31 = 10*10^30
and 10^30=(10^15)^2
and so on
crimson delta
(and of course take remainder after every step)
crimson sedge
.close
crimson delta
17
gaunt hamlet
Don't troll in help channels
sage forge
You're not the first one to make this "joke"
upper garnet
ahaha roasted
cedar kilnBOT
@crimson sedge Has your question been resolved?
gaunt hamlet
<@&268886789983436800>
calm sierra
.close
cyan fractal
<@&286206848099549185>
cedar kilnBOT
@cyan fractal Has your question been resolved?
high spruce
hm yeah that doesn't make sense
think the question is wrong
unless you miswrote the question or something
heavy star
Can some one help me with this?
cedar kilnBOT
Can some one help me with this?
heavy star
Im working on the question below I need to convert it into interval notation but I m stuck as this point I m not sure what to do.
its section h
Solve the inequalities below, stating your answer in interval notation. Thats what the question is asking
wintry wagon
Can someone help me with linear translations
cedar kilnBOT
Can someone help me with linear translations
wintry wagon
This is the question I'm getting asked "What kind of transformation converts the graph of f(x)=8x–9 into the graph of g(x)=8x–1?"
wintry wagon
what's confusing about the table
I don't understand it
dire geode
I don't understand it
which part
wintry wagon
All of it 
dire geode
All of it <:IMDEAD:891531826865270815>
read specifically the 1st and 2nd rows
wintry wagon
Still don't get it
dire geode
i don't get why you don't get it
dire geode
This is the question I'm getting asked "What kind of transformation converts the...
maybe read the given functions here and compare it to the table
wintry wagon
This is the question I'm getting asked "What kind of transformation converts the...
The only answers I had for this was translations 1 unit up down left and right
dire geode
oh rows 3 and 4 also work
wintry wagon
How do I know if it's left or right or up or down
How do I know if it's a vertical or horizontal translation
How can I tell if it's down or right, or up and left. There aren't parenthesis in the questions they're giving me.
dire geode
there are multiple ways to translate f to get g
dire geode
The only answers I had for this was translations 1 unit up down left and right
if you're given multiple choices, pick the one that works
wintry wagon
if you're given multiple choices, pick the one that works
I don't know to check if it works
dire geode
https://www.onlinemathlearning.com/image-files/transformation-rules-graphs.png
using a combination of the first four rows
wintry wagon
How do I use the first four rows
dire geode
try different c/d values
dire geode
https://www.onlinemathlearning.com/image-files/transformation-rules-graphs.png
plug in c / d = -1, 1, etc.
wintry wagon
How am I supposed to know if it's right (x-c) or down (x)-d
wintry wagon
plug in c / d = -1, 1, etc.
How
wintry wagon
you just try
Bro how do I try I don't know how to
dire geode
don't know how to what? plug in variables into funcitons?
cedar kilnBOT
@wintry wagon Has your question been resolved?
mental lotus
i need help
cedar kilnBOT
i need help
mental lotus
how do i do this
anyone
pls
idk gradients
hello
anyone
i am alone
in saddness
😦
@lusty birch
<@&286206848099549185>
anyone
zenith sail
Gradient in this sense is another word for slope. maybe you know it by that name
zenith sail
Pick two points on the line $(x_1,y_1)$ and $(x_2,y_2)$. Then the gradient is $\frac{y_2-y_1}{x_2-x_1}$
wraith daggerBOT
tatpoj
zenith sail
Any two points will work. Pick ones that are at whole numbers, they're easier to see
honest saddle
what does it mean by "generated by given element"
cedar kilnBOT
what does it mean by "generated by given element"
crimson delta
<g> or (g) or whatever your notation may be
the smallest subgroup of G containing g
<g> = {g^k: k in Z}
cedar kilnBOT
@honest saddle Has your question been resolved?
honest saddle
<g> or (g) or whatever your notation may be
so for a would there be multiple cyclic subgroups?
honest saddle
wtf
why are there spaniards here
solo is actually english so u can speak english
since u guys are here can u help me with that question
hermano pls help me
vamanos vamanos
a donde estas
crimson delta
<@&268886789983436800>
celest seal
👍
crimson delta
so for a would there be multiple cyclic subgroups?
What do you mean with multiple cyclic subgroups
One element generates a unique cyclic subgroup of G
That subgroup is denoted by <g>
crimson delta
Well you could write down every element in the subgroup
raw star
cedar kilnBOT
long arrow
yes
raw star
Ok thanks
cedar kilnBOT
@raw star Has your question been resolved?
crimson sedge
Hey, really struggling breaking this down, don't need you to solve for me but just need some help :)
cosmic steppe
Whatvtge fuckb
Uh
well
The second clause
"The first number is four more than the product of six and the second number"
What does this mean lol
crimson sedge
0 idea.
cosmic steppe
That makes literally no sense
OH
I see
It's worded weirdly
a + b + c = 40
a = 6b + 4
c = 2b - 9
The product of (6 and the second number) is 6b
deep wind
are they all integers?
no right
well b isnt an integer lol
actually it is
i had sum as 45 but its 40
34,5,1 lol
deep wind
Hey, really struggling breaking this down, don't need you to solve for me but ju...
u can solve it with systems of equations
with the way the problem is worded, it is convient for u to plug them all into the first equation you get from reading it
deep wind
a + b + c = 40
a = 6b + 4
c = 2b - 9
plug a and c into the first equation and solve for b
then plug b into 2nd and 3rd equation
@crimson sedge
crimson sedge
why does putting these vectors in a matrix
cedar kilnBOT
why does putting these vectors in a matrix
cedar kilnBOT
@crimson sedge Has your question been resolved?
crimson sedge
<@&286206848099549185>
cedar kilnBOT
@crimson sedge Has your question been resolved?
cedar kilnBOT
low holly
I have that $|\widetilde{f}(k)|^2 = \int_{-\infty}^\infty \int_{-\infty}^\infty f(x)e^{-ikx} f^*(y) e^{iky} \,\dd x \dd y$
wraith daggerBOT
π=√g
low holly
Multiplied by 2pi maybe
cedar kilnBOT
@low holly Has your question been resolved?
low holly
<@&286206848099549185> Anyone likes doing fourier transforms lol?
low holly
Ayo i think i got it
mighty minnow
Could someone help me understand this?
It's from my exercise book about proof by induction.
Step1:
LHS = 1
RHS = 1
Step2:
assume 1+3+5+...+(2n-1) = n^2
Step3:
LHS = 1+3+5+...+(2n-1) + (2(n+1)-1)
= 1+3+5+...+(2n-1) + (2n + 1)
= n^2 + 2n + 1
RHS = (n+1)^2
= n^2 + 2n + 1
=> Statement has been proved by induction
Could someone explain what this is saying and how?
Any help would be appreciated. I don't really understand this at all.
Thanks
sleek condor
do you get proofs by induction in general?
sleek condor
ima use the classic analogy of dominos for it
lets say you want to build a row of dominos and be sure that every domino will fall
you have to check two things:
that you make fall the first domino of the row
and that for each domino, making it fall will make the next one fall right?
do you get this?
mighty minnow
Yes makes sense
sleek condor
so the logic is the same with induction
if you want to prove a property for all integers
if you manage to prove it for a starting integer
and if you manage to prove that for any integer
if the property holds
then that means it also holds for the next one
then you have proved it for all possible integers after the starting one
mighty minnow
Alright makes sense
sleek condor
so now it seems that your property is some formula
P(n) = " the sum of the first n odd integers is equal to n^2"
right?
and we want to prove this for any n
so lets do it by induction
first, is it true for our starting integer?
n=1
the sum of the first 1 odd integer is just 1
and 1^2 is also just 1
this is what they meant by LHS=1 and RHS=1
ok?
sleek condor
so now the tricky part
we take any integer n
and we assume our property P(n) is true
we then want to prove P(n+1) is true
so lets calculate the sum of the first n+1 odd integers
its equal to 1 +3 +5 +.... + 2n-1 + 2n+1
which is the same as the sum up to the nth odd integer (2n-1)
2n+1
the next one
but since we know P(n) is true
the sum up to the nth odd integer
is just n^2
so we have
1 +3 +5 +.... + 2n-1 + 2n+1 = n^2 +2n + 1
right?
mighty minnow
ahhh not following
calculate the sum of the first n+1 odd integers?
its equal to 1 +3 +5 +.... + 2n-1 + 2n+1
not sure what you mean here
mighty minnow
3 ?
sleek condor
dont be sorry
i just want to understand what you are thinking
so that i can help you
sleek condor
P(n) recall is a property on number n
sleek condor
P(n) = " the sum of the first n odd integers is equal to n^2"
.
as with the domino example
we want to prove that if P(n) is true
then P(n+1) is also true
ok?
mighty minnow
Sure
mighty minnow
Wait so does "n+1" mean the next odd number or just adding one to the current n?
mighty minnow
what does P(n+1) say?
I'm not sure what you mean by say
sleek condor
what is P(n+1)
sleek condor
Wait so does "n+1" mean the next odd number or just adding one to the current n?
n+1 is the number that comes after n
P(n) is a property on the number n
a statement that depends ona number n
sleek condor
no
P(n+1) is not a number
its a statement
the statement: " the sum of the first (n+1) odd integers is equal to (n+1)^2"
and we want to prove this statement
given the statement P(n)
which is " the sum of the first n odd integers is equal to n^2"
mighty minnow
Sure okay makes sense
sleek condor
so lets prove P(n+1)
we need to calculate the sum of the first (n+1) odd integers
which is 1 + 3 +... +2n -1 + 2n+1
we can group it like this
( 1 + 3 +... +2n -1) + 2n+1
where whats in bracket
is just the sum of the first n odd numbers
and since P(n) is true
we know thats equal
to n^2
is that clear?
so 1 + 3 +... +2n -1 + 2n+1 = ( 1 + 3 +... +2n -1) + 2n+1 = n^2 +2n +1
sleek condor
what step seems weird?
try to explain what you dont understand
and why it doesnt make sense
mighty minnow
(1+3..+2n+1) + 2n+1
I dont understand why there is the 2n+1 inside of the brackets
I understand the sum is 4
sleek condor
4?
sleek condor
1 + 3 +... +2n -1 + 2n+1 do you get what this notation means?
with the .... in the middle?
mighty minnow
Yes it means the numbers up to n, correct?
because it can keep going
first n = 1
second n = 3
and so on
but after the ... i am confused
sleek condor
yeah
here is the rigorous notation on the left
it means sum for k =1 to k=n
of 2k-1
like add all of them
and the dotted notation
is on the right
the ....
is representing all the terms of the sum
mighty minnow
sure
sleek condor
so now we are interested
in the sum up to n+1
because thats what P(n+1) talks about
and what i did is this
the sum up to n+1
is the sum up to n
- the last term
mighty minnow
yes makes sense
sleek condor
and this last term simplifies
to 2n +1
if you expand the bracket
now we have this
since we assumed P(n)
that means the sum up to n
is equal to n^2
is that ok?
mighty minnow
yes okay
sleek condor
ok so in the end we have
which is what was said here
do you see how those are the same thing?
mighty minnow
yes
sleek condor
okay so now they talk about the right hand side
which should be (n+1)²
but if you expand (n+1)²
you get
n²+2n+1
so
which is exactly P(n+1)
P(n+1) was "the sum of the first n+1 odd numbers is equal to (n+1)²"
so now we have P(n+1) is true
if we assume P(n) is
so we have all we need for our proof by induction
we just proved every domino is well set up and will indeed make the next one fall
mighty minnow
hmmmmm
sleek condor
what part do you find shady?
mighty minnow
but if you expand (n+1)²
you get
n²+2n+1
you dont know how to expand (a+b)²?
mighty minnow
a*a + b*b ?
sleek condor
yeah no
mighty minnow
lmao
sleek condor
(a+b)² = (a+b)*(a+b) right?
thats the definition of a square
so now can you expand this form?
mighty minnow
which one? (n+1)^2?
sleek condor
(a+b)² = (a+b)*(a+b) right?
the RHS of this
mighty minnow
I'm not sure
mighty minnow
(a*c)+(b*c) ?
mighty minnow
c = (a+b)^2 ?
mighty minnow
im not sure what you mean
mighty minnow
alright
mighty minnow
no
sleek condor
.
mighty minnow
ahhh not sure
sleek condor
you should really clear this up
math WONT be easy if you dont know how to do this kind of calculations
mighty minnow
yeah i hear you
sleek condor
like this is supposed to be the easy part
i'm just going to do it all
but be sure
to get better at this kind of thing
mighty minnow
okay
mighty minnow
true i hear you
sleek condor
okay
sleek condor
mighty minnow
ah okay
it makes sense
so with a(a+b) you just multiply each term inside the brackets with a ?
sleek condor
so now
mighty minnow
the rest of it makes sense
mighty minnow
I'm not sure how you did it
Can you show me the steps of how you went from
n²+2*n*1 +1²
to
n²+2n+1
mighty minnow
sure i get that
sleek condor
so whats the issue
mighty minnow
nothing makes sense now
sleek condor
its not really helpful
mighty minnow
okay wait
n²+(2*n*1)+1²
in the brackets is just 2n
1^2 = 1
so you get
n²+2n+1
Sorry maybe i was unclear, i meant nothing is the issue, it makes sense now
not nothing at all makes sense lol
sleek condor
you seemd to understand the complicated concept
which was induciton
but you are struggling with the do basic calculations part
which is not something i can really teach you
mighty minnow
Its fine, I know I need to get better. I've been thrown in the deep end with this induction stuff, my understanding of math isn't that great for some of what is required for the course I'm taking
I'll keep working at it don't worry
sleek condor
its something quite common actually
people comming here struggling with a "hard lesson"
and in fact their main issue
is that they lack fundamentals
and often fundamentals from a few years back
so either they got the time to fix it
or they are kind of fcked
like people at university
or in college
asking for help before exams and they cant realistically succeed not because the current lesson is too hard
but because of what came before
but you should be hopeful
because you understood induction
the hard part quickly
just practice basic calculations more
dont be scared to ask your teacher about your lackluster areas
so they can give you advice on how to catch up
mighty minnow
because you understood induction
I don't really feel like I understand it. I get the general concept, but when I'm doing these exercises I'm not really sure what I'm doing
sleek condor
yeah but this is normal
you can understand poetic structures, if you struggle reading words, poems will be hard to understand
mighty minnow
For sure. I'm doing a bachelor degree in IT. I'm fine with most of it but I took the optional math classes and most of it goes over my head. Some of it is easy but when it comes to things like induction I just feel lost. You're right though, I need to spend more time learning the fundamentals
I feel like i've just been thrown in the deep end lol
sleek condor
yeah if you are in uni this will be harder
most likely your teacher wont be able to dedicate much time
mighty minnow
He's a pretty decent teacher but i'm just one of many students. He replies to my 1am messages asking for help though which is good. But even when he explains it to me i still struggle lol
sleek condor
but yeah expanding brackets and basic algebra is 7-8-9 grade stuff i would say
sleek condor
this should feel very easy after highschool
mighty minnow
Just been a while since i've done any math
sleek condor
good luck
mighty minnow
Lmao thank you
sleek condor
this stuff just improves through practice
but i recommend you to go through everything you should know with someone
to identify what you need to work on
w/e gotta sleep
sleek condor
yeah ok
wintry violet
cedar kilnBOT
wintry violet
I'm not sure how this is wrong
vernal shell
c0 is not -5 with that formula
vernal shell
Use the same eq. you found before
3n+5
Mutiply by (-1)^something such that it's -1 when n=0
There are many possible answers
vernal shell
Why do you put that parentheses at the end
You should have (-1)
Also (-1)⁰ = 1
not -1
wintry violet
oh
vernal shell
You need to have -5 when n=0
wintry violet
I did n + 1
I'm stupid
didn't realize -1^0 was = 1
that was my mistake
.close
cedar kilnBOT
cedar kilnBOT
Available help channel!
small wave
I need to find the derivative of ln(xe^-2x). Where do I start?
high spruce
do you know derivative of ln f(x)?
small wave
do you know derivative of ln f(x)?
u'/u?
small wave
now just find u'
so e^(-2x) -2xe^(-2x) / xe^(-2x) ?
high spruce
so e^(-2x) -2xe^(-2x) / xe^(-2x) ?
yep looks good
small wave
yep looks good
ok, how do i simplify from here?
small wave
e^-2x?
high spruce
ye
high spruce
is 1-2x/x correct?
👍
small wave
how do i simplify it further?
small wave
you could split it up as 1/x - 2 if you wish
could you explain how we would do that?
high spruce
(1-2x)/x = 1/x - 2x/x
small wave
solution for this one was 1/x - 2
high spruce
could you explain how we would do that?
you just split up the fractoin
small wave
don't see the point though
i got points taken from my last exam cause i didn't simplify
small wave
you just split up the fractoin
alright, tysm
high spruce
alright, tysm
np
small wave
.close
cedar kilnBOT
cedar kilnBOT
Available help channel!
crimson sedge
these correct?
crimson sedge
<@&286206848099549185>
livid atlas
can we solve this without calculating the area using hero's formula
cedar kilnBOT
can we solve this without calculating the area using hero's formula
@livid atlas Has your question been resolved?
cedar kilnBOT
livid atlas
.reopen
cedar kilnBOT
✅
livid atlas
<@&286206848099549185>
inner glacier
use heron's formula then equate it with 1/2ab
livid atlas
Yeah ik we can do that way but this is a GRE question and we don't have that formula in GRE
So j wanted to know a method without using that formula
inner glacier
i am not sure about that
inner glacier
sure
livid atlas
Thanks for the help anyways 😃
ashen magnet
hey
ashen magnet
what do i slot in for my particular solution?
sullen saffron
,w 2y'' + 3y' -2y = 0
wraith daggerBOT
sullen saffron
Your complementary function is wrong.
ashen magnet
Your complementary function is wrong.
?
sullen saffron
For (2m + 1)(m - 2) = 2m^2 -3m + 2.
sullen saffron
Since Q(x) contains a term which is x^0 of a term in y_c(x), y_p(x) = Axe^(x/2) + (Be^(x/2)) but we need not bother with the term in brackets since it's included in y_c(x).
sullen saffron
Yeah. Something like that but you need to differentiate it twice and as you can see it does get messy.
ashen magnet
an i following along the right path ?
ashen magnet
Yeah. Something like that but you need to differentiate it twice and as you can ...
true yeah
sullen saffron
I looks like it. I didn't check your calculations but you need to differentiate y_p(x) twice.
ashen magnet
oh yes ik
it’s rlly messy tho but i’ll give it a shot
@sullen saffron can u double check if i’ve done the product rule correctly on the side for the second derivative?
ashen magnet
ashen magnet
ah, thanks!
cedar kilnBOT
@ashen magnet Has your question been resolved?
boreal trail
cedar kilnBOT
boreal trail
why is pheta 2.3 if one of them is 10
what did i do wrong
for these values
i probably drew the triangle incorrect
if so can someone draw it correectly
i have to find the time it takes, to go from 1 point to another (as in picture) with the following bearings (PER being the bottom left one and PBO being top right one)
regarding wind speed of 15, distance of 987 and plane speed of 300
cedar kilnBOT
@boreal trail Has your question been resolved?
boreal trail
.reopen
cedar kilnBOT
✅
cedar kilnBOT
@boreal trail Has your question been resolved?
boreal trail
im going to sleep very late but PLEASE, if anyone can do this question fully, or draw a traingle graph that is correct, or tell me why its wrong @ reply to me so i come back
otherwise im gone
cedar kilnBOT
@boreal trail Has your question been resolved?
slate solstice
a
slate solstice
In these types of questions i should do asq-bsq right?
Like so it becomes that in demon
Denom
crimson sedge
what is asq-bsq
cedar kilnBOT
@slate solstice Has your question been resolved?
cedar kilnBOT
@slate solstice Has your question been resolved?
crimson sedge
cedar kilnBOT
crimson sedge
Here in task 4e
How can I tell if the graph is symetrical or mot
Nvm theres an example lol sorry for bothering
.close
cedar kilnBOT
crimson sedge
I need help again
Okay so
I have f(x) = 5/x⁴ + x²
And I need to tell if it's symetrical
And I have no clue how
The example shows something with negating and stuff but I'm stuck
cedar kilnBOT
Available help channel!
livid atlas
cedar kilnBOT
livid atlas
I worked out like this but i am getting wrong answer
crimson sedge
The example shows something with negating and stuff but I'm stuck
What the
My question just got ignored by the bot
livid atlas
Damn
Bro are you German?
Ich komme nach Deutschland nächstes Jahr für meine master's
crimson sedge
Bro are you German?
Ich komme nach Deutschland nächstes Jahr für meine master's
Yeah
That's cool, what you be studying
livid atlas
I am not able to understand your question though
livid atlas
Automotive engineering
crimson sedge
I need to prove if the graphs to these equations are symetrical or not
And I struggle with 4f
livid atlas
Hmn lemme see
crimson sedge
here
livid atlas
Okk
crimson sedge
You understand it?
livid atlas
Bro it's a website for mathematics
livid atlas
U can do anything maths related
Just put in the function and it will show u the graph
Or u can use Desmos another website just for graphs
livid atlas
I'm in 10th grade : ) I don't know these super complicated things
Ohh nvr mind
livid atlas
Wait I'll send
crimson sedge
Just put in the function and it will show u the graph
No I can't visualize it
I can do that on calculator
I need to do in some crazy way stuff
Lemme show you
livid atlas
crimson sedge
This is the first task
livid atlas
So we basically put in the values of x and make a table right
That is what I remember
floral forge
i worked it out but im also getting the wrong answer. not sure if im doing something wrong or there is something wrong with the problem. what answer are you getting?
@livid atlas
livid atlas
16.66
floral forge
well thats different from me. what i did was write $B=l\cdot y^2$ where $y$ is the width and height (as it is a square and $l$ is the length. with this then we can find that $$A=1.2l(y-x\cdot10^{-2})^2$$ as we have that the length $l$ of $A$ is $20%$ longer and the width and height are $x$ percent less than in $B$. solving this i get 9.22 which is not a solution
wraith daggerBOT
Duh Hello
livid atlas
Nvr mind i got it bro
Bro see the phot i sent before of my working
I was doing calculation mistake
I am getting 8.71
Which is the answer
floral forge
i try and solve them myself to see where people go wrong. but yeah i just typoed when putting it into a calculator 
so yeah i get 8.71 as well now
chrome marsh
the number of orderings of 2 3's and 10 1's is just $$\frac{12!}{2!10!}$$
wraith daggerBOT
ryan_
cedar kilnBOT
chrome marsh
right?
umbral lotus
well
you have 2 3's and 10 1's that you have to order
so in total you have 12 elements
that would be 12! orderings
howerver that would also included doubles
not sure if division is the way to go for getting rid of them tho
grim flower
cedar kilnBOT
@chrome marsh Has your question been resolved?
mortal marten
x^2-11x-2/x^2-4
cedar kilnBOT
x^2-11x-2/x^2-4
turbid anvil
show your work
+1
turbid anvil
-(-3)
silk thistle
- (4x-2) * (-2) +8x
mortal marten
ok lemme show my working hang on
turbid anvil
+ (4x-2) * (-2) +8x
e^(-ln(1/5))
violet rapids
guys stop being silly we need to be serious
silk thistle
Well we are just waiting
violet rapids
,rotate
turbid anvil
Well we are just waiting
+1
wraith daggerBOT
mortal marten
Thanks
mortal marten
what next
mortal marten
factorise it?
silk thistle
I think you forgot -1
mortal marten
yes forgot that
silk thistle
To begin
mortal marten
what to do now
turbid anvil
And u opened the brackets wrong
silk thistle
no here its correct i think
silk thistle
I think you forgot -1
Just do that bro and you'll be good
indigo berry
-6x+5x=-11x?
silk thistle
Add the -1
indigo berry
oh, i didn't see that earlier
mortal marten
Add the -1
wdym idk how to tbh
indigo berry
i'd honestly include parenthesis to make it clear
silk thistle
i'd honestly include parenthesis to make it clear
I agree
turbid anvil
no here its correct i think
5x is wrong i think
silk thistle
Yes mb
turbid anvil
@mortal marten don't multiply the minus sign so fast
First open the brackets and then do it
mortal marten
still confused
any chance u guys could do it on paper and show? @turbid anvil @silk thistle
silk thistle
I do it
mortal marten
amd then what @turbid anvil
turbid anvil
amd then what <@739482154425122819>
Solve the equation which i have written
silk thistle
ivory finch
how to git gud @ derivatives fast?
mystic plover
Hmm guyz