help-13

[dusty hazel]

Why are you subtracting that from 240x then?

[haughty vapor]

idk lmao

240x = 4560 but we are trying to find how many months it will take so

how

[dusty hazel]

Divide both sides by an obvious number...

You essentially need x by itself

Because that is the number of months.

[haughty vapor]

4560/240

= 19

[dusty hazel]

yeah

[haughty vapor]

oh ok so thats all

.close

[cedar kiln]

Channel closed

Closed by @haughty vapor

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[worldly walrus]

tell me any and all info need be

[worldly walrus]

just wondering; for help. ive tried inputting things into variables and im stuck p much everywhere

[obsidian tinsel]

Let’s represent their rate of doing houses per day

[worldly walrus]

a+b=10, a+c=12, b+c=20

[obsidian tinsel]

For the first sentence, let’s represent the number of houses Avi can do per 1 day as A houses/1 day

BUTT BUT BUT, with the ratio/rate at which Avi does houses per day, we multiply it by days to get out houses

So A’s house per day rate, over 10 days, and B’s house per day rate, also over 10 days, creates 1 house

Or 10A + 10B = 1 houses

[wintry prism]

ratio

[worldly walrus]

lmao im so stupid

[worldly walrus]

OHH i c

and now what do we do?

[obsidian tinsel]

Do the same thing with the next 2 parts

Build a similar equation with A and C

And B and C

[worldly walrus]

so 12a+12c=1 house?

[obsidian tinsel]

YUSSSS

[worldly walrus]

20b+20c=1 house

Omlll

Look at me

[obsidian tinsel]

YUSSSSSSSSSS

[worldly walrus]

Btw what lvl math is this

like universally

what grade lvl

[obsidian tinsel]

Hmm

I fully understood it at grade 11 but got it at around middle school

[worldly walrus]

This is grade 10 so ..

[obsidian tinsel]

U are already 1 year ahead of me!

[worldly walrus]

... Not rlly

anyways

what do we do next?

should i substitute and find a variable alone

[obsidian tinsel]

Yes

[worldly walrus]

Ok which one

[obsidian tinsel]

Umm let’s isolate what a in the first equation. And after we know what a is equal to, we can put that into the a in the second equation.

You’ll end up with an equation relating B and C

[worldly walrus]

Dont we have that tho---

Wtgh

[obsidian tinsel]

?

[worldly walrus]

Nvm.

[worldly walrus]

so 10a=1 house-10b

[obsidian tinsel]

And then isolate B and put that into the B from third equation

Close

[worldly walrus]

a=1h-b?

[obsidian tinsel]

That’s what 10a is equal to, but what about a

[worldly walrus]

Girl idk

WAT

WAIT

[obsidian tinsel]

Soooo sooo close

[worldly walrus]

i got this

[obsidian tinsel]

Do it

I believe in u

[worldly walrus]

a=1h/b

[obsidian tinsel]

Ehmmmm

U were closer the first time

A = 1/10 - B

Or A = 1 house per day minus B

[worldly walrus]

WHAT

How

One sec

Dont say another msg

[obsidian tinsel]

Divide both sides by tan

[worldly walrus]

ohhhhh

[obsidian tinsel]

My bad

[worldly walrus]

Why r u a nerd Gn

GIVE ME A SEC

Omg

if we divide BOTH sides by 10

then its a+b

=1/10h

Ummm

[worldly walrus]

Wait why r u smart

OOMG

THAT MAKES SENSE

[obsidian tinsel]

Because I’m not

[worldly walrus]

DIVIDE BY 10 AND THEN SUBTRACT

[obsidian tinsel]

Or subtract and then divide. The order don’t really matter

A+B = 1/10 >> a = 1/10 - b is one way

[worldly walrus]

ok

[obsidian tinsel]

10a = 1-10 b >> a = 1/10 -b is another way

[worldly walrus]

anyways we have a = 1/10-b

NOWW

plug into 2

12(1/10-b)+12c

and it becomes

1.2-12b+12c=1h???

@obsidian tinsel

[obsidian tinsel]

Yup! Isolate b

And then the value u get for b, plug that into the b of the THIRD equation

[worldly walrus]

r u in college rn?

b=1/12h-.1-c? @obsidian tinsel

[obsidian tinsel]

Um not quite

[worldly walrus]

Baiii what did i do

Let me run down my mouth One sec

[obsidian tinsel]

-12 b = 1 - 1.2 - 12c
= -0.2 -12c
b = 0.2+12.c

[worldly walrus]

when i moved the 1.2 i removed the negative sign

does it stay

how do we get -12b to b

@obsidian tinsel

[obsidian tinsel]

Divide everything by-12

[worldly walrus]

Bai

LMF

thats so easy

Like i couldve learned that in 5th grade

[obsidian tinsel]

Good for you 👍

[worldly walrus]

My dumbass 🤝

[obsidian tinsel]

But we got all our dumbasses past the finish line together

[worldly walrus]

Fake it till u make it 😍

-.2/-12??

[obsidian tinsel]

Oh that’s 1/60

[worldly walrus]

oh..

what abt -12 divided by -12

thats 1

not 12

[worldly walrus]

idk how u got this, the last expression

it should be

b=1/60+1c

[obsidian tinsel]

Oop I did it wrong

[worldly walrus]

is mine right

[obsidian tinsel]

Yes

[worldly walrus]

Ok i slayed

[obsidian tinsel]

See u r smarter than I. Yes slayyy

[worldly walrus]

💀

1/3+40c=1h

wht now

40c=2/3h?

is the answer just c=1/60h

so 60 hours?

NO WAY BRO

SO 2.5 DAYS

OMG

@obsidian tinsel

(is this right)

[cedar kiln]

@worldly walrus Has your question been resolved?

[cedar kiln]

@worldly walrus Has your question been resolved?

[cedar kiln]

@worldly walrus Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

can someone assist me?

[cedar kiln]

Please don't occupy multiple help channels.

[cedar kiln]

@crimson sedge Has your question been resolved?

[crimson sedge]

.close

[cedar kiln]

Channel closed

Closed by @jaunty cape

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lucid grove]

Im sick today so im not coming to school but we are finishing a math chapter and having a test on it tomorrow.
Could someone help me figure out how to use this formula to find stationary points?

[livid hound]

you don't

[lucid grove]

What?

[livid hound]

you don't use the second derivative to find stationary points

(also why you posted isn't a formula)

to find location of stationary points you'd solve
$$\dv{y}{x} =0$$

[wraith dagger]

ℝamonov

[lucid grove]

Yes if dy/dx = o and that is ... Then thr point is a maximum of minimum

How do i put values into that

Into this

What do i do next

[livid hound]

differentiate $\dv{y}{x}$ to get $\dv[2]{y}{x}$

[wraith dagger]

ℝamonov

[livid hound]

plug in the value(s) you obtained from solving dy/dx = 0

[lucid grove]

So d^2

Means i need to do differentiate again?

So it was f'(x)=6x^2-30x+26

Then its f(x)=6x -30

And then i plug in my X's

@livid hound thank you for your hospitality, unfortunately i have to go

.close

[cedar kiln]

Channel closed

Closed by @lucid grove

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[livid hound]

fdouble dash
f''(x)

[livid hound]

.close

[cedar kiln]

Channel closed

Closed by @livid hound

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cedar kiln]

Channel closed

Closed by @high gust

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dreamy jetty]

In the second equation

We get a^3b = 64

64= 2⁶

3b= 6 , b= 2

a=2

a^b = 4

64

Is 2⁶

[coarse ore]

how did u solve for b?

[dreamy jetty]

We get a^3b = 64

Bruh

64= 2⁶

a^3b = 2^6

Equate the base and exponent

a= 2

3b = 6 i.e. b=2

[coarse ore]

ye ok

[dreamy jetty]

So a^b = 2^2 = 4

[coarse ore]

so x=4?

[dreamy jetty]

Yes

80= d.m³

[cedar kiln]

@coarse ore Has your question been resolved?

Channel closed

Closed by @coarse ore

Use .reopen if this was a mistake.

[coarse ore]

.close

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[quaint thunder]

Hi! so i need some one to point me into an direction. I have two treatments and i want to see how the 3 variables effect each other: program size, development time and total number of errors

[quaint thunder]

they are all continuous and normally distributed

[cedar kiln]

@quaint thunder Has your question been resolved?

[quaint thunder]

.close

[cedar kiln]

Channel closed

Closed by @quaint thunder

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[civic solstice]

Hello, could anyone help me figure these out, the shape is very confusing and I'm having a hard time finding the angles. I haven't found any of them yet

[opal basin]

okay, so for i we have this

[civic solstice]

Yes, I can see that

[opal basin]

so what is angle vpu?

[civic solstice]

is it 38?

[opal basin]

yes

V and U are the D and B in the diagram

[civic solstice]

Ok

[opal basin]

we also have this identity

[civic solstice]

where

[opal basin]

which means we know angle TPR

[opal basin]

this is true for any quadrilateral in a circle

in this case it's RSTP

[civic solstice]

this one?

[opal basin]

yes

[civic solstice]

Ohh so 180-106

74

[opal basin]

yes

[civic solstice]

nice

[opal basin]

you can combine this with VPU to find TPU

because VPR is a straight line

[civic solstice]

OOOO

got it

thanks

.close

[cedar kiln]

Channel closed

Closed by @civic solstice

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

How do i start to simplyfy this?

[crimson sedge]

,, \lim_{h \to 0} \frac{\frac{1}{\sqrt{2+h}} - \frac{1}{\sqrt{2}}}{h}

[wraith dagger]

Rwy

[crimson sedge]

after simplyfying next step is to find the limit :)

[sacred stone]

$\frac{1}{\sqrt{2+h}} - \frac{1}{\sqrt{2}}=\frac{\sqrt{2}-\sqrt{2+h}}{\sqrt{2(2+h)}}
=\frac{-h}{\sqrt{2(2+h)}(\sqrt{2}+\sqrt{2+h})}$

[wraith dagger]

秋水

[crimson sedge]

i understand to here

[sacred stone]

$$\frac{\sqrt{2}-\sqrt{2+h}}{\sqrt{2(2+h)}} = \frac{\sqrt{2}-\sqrt{2+h}}{\sqrt{2(2+h)}}\times \frac{(\sqrt{2}+\sqrt{2+h})}{(\sqrt{2}+\sqrt{2+h})}$$

[kind patio]

He multiplied num and den by conjugate

[wraith dagger]

秋水

[crimson sedge]

yes

so isnt it

,, \frac{\frac{\sqrt{2}-\sqrt{2+h}}{\sqrt{2(2+h)}}}{h}

[wraith dagger]

Rwy

[kind patio]

Yes

[crimson sedge]

What now?

how did he turn that into

[kind patio]

This

Do the multiplication

[kind patio]

This is just for the numerator part

The h in denominator is still there

[crimson sedge]

yeah

[crimson sedge]

so

,, \frac{2-2+h}{\sqrt{2(2+h)}(\sqrt{2}+\sqrt{2+h})}

[wraith dagger]

Rwy

[crimson sedge]

simplifies to just h?

[sacred stone]

$2-(2+h)=2-2-h=-h$

[wraith dagger]

秋水

[crimson sedge]

oh yeah

,, \frac{-h}{\sqrt{2(2+h)}(\sqrt{2}+\sqrt{2+h})}

[wraith dagger]

Rwy

[crimson sedge]

and all that over h?

[kind patio]

Yes

[crimson sedge]

,, \frac{\frac{2-2+h}{\sqrt{2(2+h)}(\sqrt{2}+\sqrt{2+h})}}{h}

[kind patio]

Then the hs cancel

[crimson sedge]

,, \frac{\frac{-h}{\sqrt{2(2+h)}(\sqrt{2}+\sqrt{2+h})}}{h}

[wraith dagger]

Rwy

[crimson sedge]

the -h and h?

[kind patio]

Yes leaving -1 in numerator

[crimson sedge]

,, \frac{-1}{\sqrt{2(2+h)}(\sqrt{2}+\sqrt{2+h})}

[kind patio]

Then put in 0 for h

[wraith dagger]

Rwy

[kind patio]

Yea

[crimson sedge]

okay
,, \frac{-h}{\sqrt{2(2+0)}(\sqrt{2}+\sqrt{2+0})}

,, \frac{-h}{\sqrt{4}(\sqrt{2}+\sqrt{2})}

[wraith dagger]

Rwy

[kind patio]

No -h

[crimson sedge]

ohh yeah -1

that i know sorry typo

,, \frac{-h}{\sqrt{4}(\sqrt{2+2})}

[wraith dagger]

Rwy

[crimson sedge]

damn -1 ontop

[kind patio]

The roots don't combine

[crimson sedge]

They dont?

[kind patio]

Ans is -1/4√2

[crimson sedge]

wait so here

,, \frac{1}{\sqrt{4}(\sqrt{2}+\sqrt{2})}

[wraith dagger]

Rwy

[kind patio]

√2+√2 make 2√2

[crimson sedge]

ohh okey wait

and - ontop

[kind patio]

And√4 is 2

Yes now it's done

[crimson sedge]

,, \frac{-1}{2(2\sqrt{2})}

[wraith dagger]

Rwy

[crimson sedge]

like that?

[kind patio]

Yes that's ans

[crimson sedge]

Wow

Thank you wide putin!

.close

[cedar kiln]

Channel closed

Closed by @glad pike

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

,calc 587-1

[wraith dagger]

Result:

279

[crimson sedge]

It's because of the multiply symbol here in discord:

Yes thats the solution for a

yep

a) There are 279 ways of making a snack with at least a threat.

[cedar kiln]

Channel closed

Closed by @still tinsel

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed due to the original message being deleted

[junior ocean]

@pseudo current

[pseudo current]

abe not now

have to eat

dinnah

bui

[crimson delta]

use dms if you wanna chat. dont open and close help channels

[pseudo current]

[kind patio]

Huh do i know you?

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[static crag]

<@&286206848099549185>

I need to solve these three lims

And I have no clue how

[velvet mortar]

!15m

[cedar kiln]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[static crag]

ημ = the trigonometric function sine

[velvet mortar]

sin (1/x)?

[static crag]

Yep

[random osprey]

ii) lhopital

[cedar kiln]

@static crag Has your question been resolved?

Channel closed

Closed by @static crag

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mint niche]

solve the rational equation

[rugged palm]

What did you try?

[cedar kiln]

@mint niche Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[languid swallow]

these are the laws

and this is what i have tried so far

any help is appreciated

[cedar kiln]

@languid swallow Has your question been resolved?

[languid swallow]

<@&286206848099549185>

[languid swallow]

Hi, the layout in which we need to answer the question is in my example I gave

@earnest sentinel

[cedar kiln]

@languid swallow Has your question been resolved?

[cedar kiln]

@languid swallow Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hollow minnow]

Integral?

Well you integrate it.

$\int (x-1)^2 dx$

[wraith dagger]

Pure

[hollow minnow]

Either expand it and integrate term by term

[quartz frost]

(x-1)^2=x^2-2x+1

[hollow minnow]

Or use substitution u=x-1 (you should be able to do this by inspection.)

[cedar kiln]

Channel closed

Closed by @fathom hound

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[opaque arch]

I've completed figure (A) and Quadrant 1 and 3 of figure (B) but I'm not sure how to find quadrant 2 and 4. Any help on where to start would be great, Thank you.

[south juniper]

For B quadrant 2, notice that you have the same angle as quadrant 1

[opaque arch]

The green lines mean they're the same?

[south juniper]

Yes

[opaque arch]

man I thought it meant they were different hahahaha, thank you for the help

.close

[cedar kiln]

Channel closed

Closed by @opaque arch

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fallen owl]

$|BE|^2 = 4DC^2/9 + 4DC * BC/3 + |BC|^2$

[fallen owl]

$So we have |BE|^2 = 4DC^2/9 + 4DC * BC/3 + |BC|^2
And |BF|^2 = 9|DA|^2/4 - 3DA * AE + |AE|^2$

[wraith dagger]

*-_~T~.~W~.~I~.~S~.~T~_-*

[hollow minnow]

[fallen owl]

Bruh

Wont work

.close

[cedar kiln]

Channel closed

Closed by @fallen owl

Use .reopen if this was a mistake.

[crimson sedge]

Please help 😭😭😭😭

I can fill in the formula but how do I calculate

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[north pulsar]

i cant find my mistake

[high spruce]

,rotate

[north pulsar]

‘rotate

[high spruce]

,rotate

[north pulsar]

sorry about that

[high spruce]

oh oops idk how this thing works

[north pulsar]

there

[high spruce]

nvm was just bugging

what's the question?

[north pulsar]

its google translate lmk if its not accurate

the beach is around the pool with the same width

[high spruce]

ye seems good lemme try get the formula

eqation

i mean

[north pulsar]

usually i get it, idk where the mistake is, i tried a few times and still doesnt work

[high spruce]

oh is it non calc?

cus ur method looks like you weren't alowed to use a calculator

I got 2.5

with just quad formula

you went wrong somewhere here

-12.25 x 4 = -49 not -50 @north pulsar

[north pulsar]

ohhhh tysm!!

ill try it

[high spruce]

👍

[north pulsar]

wait even then the x is still -3.5

[high spruce]

no

[north pulsar]

its just the y that changes

?

[high spruce]

I just did it using your method

and I got 2.5

[north pulsar]

wait im dumb i didnt pick the write number to put at that spot

[high spruce]

4(x+3.5)^2 = 144

[high spruce]

oh ahah it's ok

[north pulsar]

tysm man 👍👍

.close

[cedar kiln]

Channel closed

Closed by @north pulsar

Use .reopen if this was a mistake.

[north pulsar]

.reopen

[cedar kiln]

✅

[north pulsar]

@high spruce sorry im confused cus here it says 3.5 in the parenthesis and thats the value of x, and x is supposed to be 2.5, am i missing something?

[high spruce]

what do you mean?

just solve this equation

divide by 4

[north pulsar]

oh wait ur right

im sorry

thanks :$

[high spruce]

so (x+3.5)^2 = 36

[north pulsar]

:)*

[high spruce]

no worries :)

[north pulsar]

.close

[cedar kiln]

Channel closed

Closed by @north pulsar

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[muted chasm]

aaah

[smoky anvil]

Can you take u as what’s under the radical? I don’t really know how to start. Thanks

[manic acorn]

Substitution

[smoky anvil]

For what

[muted chasm]

whats the derivative of arcsecx

[manic acorn]

Well yes u can technically do that however thats not the most optimal route

[smoky anvil]

Haven’t learned that yet

[manic acorn]

Learn it, its just a formula

[smoky anvil]

Then what is the formula

[eternal comet]

for the interest of expedience

,w derivative of arcsec(x)

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Remavas#3737

[eternal comet]

not going to lie wolfram, but that's a pretty terrible way to write that

[velvet mortar]

Wolfram doesn't care about us mortals

[smoky anvil]

So it equals the bottom value. So it’s just the integral of u du?

.close

[muted chasm]

.close

[cedar kiln]

Channel closed

Closed by @muted chasm

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pure oxide]

question

[pure oxide]

when u bring stuff over

the +3 became - 3 because when u bring stuff over from the = sign it switches from + to negative?

[sonic thistle]

yes

whenever you move terms form one side to another you change the sign

[pure oxide]

so anytime u bring something over from the = sign

it changes right?

[sonic thistle]

yes

[pure oxide]

TY so much sir/ms

I appreciate that

[sonic thistle]

np

[pure oxide]

im doing one more question

dont leave yet

one more confirmation question

[plain burrow]

you should try to think about this as doing an operation to both sides, instead of moving stuff from one side to the other

if you were to bring a +3 to the other side you would subtract 3 from both sides

[pure oxide]

again sorry im not smart as you guys but

again...the +12 became negative because it was brought over?

sorry

[sonic thistle]

yes

[pure oxide]

wow makes so much sense

lol

gonna practice

[sonic thistle]

😄

[pure oxide]

can u give me some practice questions?

actually nvm

but thanks for the help

[sonic thistle]

np

[pure oxide]

.close

[cedar kiln]

Channel closed

Closed by @pure oxide

Use .reopen if this was a mistake.

[pure oxide]

ty again @sonic thistle

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wintry steeple]

What is a relation that is transitive and symmetric but not reflexive. Does $ X={a,b,c}, ~ is {(a,b),(b,c)}$ satisfy this

[crimson delta]

no

(a,b) is in the relation but not (b,a)

[wintry steeple]

Oh SORRY

i meant {(a,b),(b,a)}

[crimson delta]

thats not transitive

[wintry steeple]

Right so the reason we need (a,a) and (b,b) is so that

Since a,b, c are in X, and (a,b) and (b,c) then (a,c)

So if we choose c as a, or b

Then (a,b) and (b,a) are in the set so (a,a) must be

Is that the idea

[crimson delta]

yes

[wintry steeple]

Relations are really confusing me

Is there a way to write relations as functions

[crimson delta]

it doesn't help that you use the same letters for the "rules" of what transitive mean and for the elements of the set X

no

some relations are functions

anyway, now you have {(a,a), (a,b), (b,a), (b,b)}

this is symmetric and transitive

but not reflexive

[wintry steeple]

Why do we need (a,a) and (b,b) though?

[crimson delta]

like you said, cause it's supposed to be transitive

[wintry steeple]

Okay kinda makes sense thank you

Btw what is the formal way of writing a relation?

[crimson delta]

$R\subseteq X\times X$

[wraith dagger]

Denascite

[crimson delta]

do you see why this is not reflexive?

[wintry steeple]

Yes because we dont have c~c

[crimson delta]

yes

exactly

[wintry steeple]

But im so confused at what ~ is

Like a function i get, u put something in u get something out

But x~y is what?

[crimson delta]

it just says that x and y relate in some way

[wintry steeple]

Like how is x related to y

[crimson delta]

a classical example is for example "x <= y"

that is a relation

[wintry steeple]

Okay sure

So if you took any set

With some real numbers

Then that is an equivalence relation

[crimson delta]

no

[wintry steeple]

What is the counter example?

[crimson delta]

every set with two elements

[wintry steeple]

a<=a is always true

[crimson delta]

yes

[wintry steeple]

Where does that fail?

If u have {a,b}

[crimson delta]

what are the three properties for an equivalence relation

[wintry steeple]

Transitive, reflexive, symmetric

So a~b, b~c then a~c

[crimson delta]

ok. we showed that it is reflexive

what about transitive

[wintry steeple]

There are only two elements

So wlog x<=y

Wait

[crimson delta]

every set with at least two elements is a counterexample

[wintry steeple]

Ohhhhhh

If a,b then b is not related to a

So a~b does not imply b~a

But that just means symmetry is not satisfied

Not sure why transitivity isnt

[crimson delta]

I didn't say transitivity isn't

[wintry steeple]

Ah

[crimson delta]

but yes you are right, it's not symmetric

[wintry steeple]

Okay so its just symmetry

[crimson delta]

on the other hand it is anti-symmetric

[wintry steeple]

Since a~b actually imples b!~a

[crimson delta]

assuming a!=b, yes

any relation with the properties reflexive, transitive and anti-symmetric is in fact called an order

cause those are the properties we want from something that "orders" a set

[wintry steeple]

As in anti symmetric means that if a relates to b, then b must not relate to a?

[crimson delta]

yes

[wintry steeple]

Okay cool

Thank you!

How do i give u points do i need to tag you when i say thank you?

[crimson delta]

technically this is a non-strict ordering. you can also do the same for x<y but then you want that it is not reflexive

anyway, orders, equivalence classes and functions are the three most important cases of relations

[wintry steeple]

Right okay fine. Im not sure why i dont know this since im in third year of undergrad

[crimson delta]

better late than never

[wintry steeple]

True true

[crimson delta]

dw about that, just close

[wintry steeple]

When did u learn this?

[crimson delta]

well first semester

[wintry steeple]

Hahaha okay

I must have missed the lecture

Thank you tho, rlly appreciate your time

[crimson delta]

youre welcome

[wintry steeple]

.close

[cedar kiln]

Channel closed

Closed by @wintry steeple

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[light cliff]

Can anyone help me with this

[light cliff]

.close

[cedar kiln]

Channel closed

Closed by @light cliff

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson olive]

Let f: R^2 -> R^2 be the linear transformation that sends (1,0) -> (3,3) and (0,1)-> (2,3). What does f(2,3) =?

[crimson olive]

i tried doing 2(1,0)+3(0,1) = (2,3)

but that doesnt seem right

[quartz frost]

since it is linear we can do the following:
f((2,3))=f((2,0))+f((0,3))
=2f((1,0))+3f((0,1))
=2(3,3)+3(2,3)
=(6,6)+(6,9)
=(12,15)

we used the fact that
f(x+y)=f(x)+f(y)
and
f(ax)=af(x)

in fact, from this we can conclude that a linear transformation is uniquely defined by the image of the basis, meaning what the basis vectors are plotted to, in this case (1,0) and (0,1)

[crimson olive]

ah i see now

but why do you use the transformed values like (3,3) and (2,3)?

is it just the formula?

[quartz frost]

well

we have f((2,3))

so i split it up into f((1,0)) and f((0,1))

which we know

are (3,3) and (2,3)

so

we pretty much have to use the transformed values

that is how we do it

[crimson olive]

ah ok

[quartz frost]

or we build a matrix that describes f

and apply it to the vector

[crimson olive]

that makes more sense now

ty

.close

[cedar kiln]

Channel closed

Closed by @crimson olive

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[grand heath]

hi i would like to know how to find the range of 7b

i understand that f(x) is a member of real number but i don't understand that f(x) is greater than 3

i mean the range of part b

[leaden snow]

e^x is > 0 for every x and approaches 0 as x goes to -inf

so the minimum you can achieve is $\lim_{x \to -\infty} (2e^x - 3) = -3$

[wraith dagger]

nvx

[grand heath]

does that means -3 (shift 3 units downward) the minimum I can go is -3 therefore all f(x) is greater than -3?

[leaden snow]

f(x) > -3, yes

[grand heath]

thanks

.close

[cedar kiln]

Channel closed

Closed by @grand heath

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[strange mortar]

Need help with #1

I can't seem to understand how to work this out. Physics **

[eternal comet]

"Mars is 2.28e11 meters"

,w 1.5 AU to meters

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Remavas#3737

[eternal comet]

Ah, so that's the orbital radius of Mars

[strange mortar]

How do you find au ?

Do we need to convert it?

[eternal comet]

That doesn't matter, I just know that the distance of Mars to the Sun is about 1.5 AU

I wanted to check what the actual hell you are given here

Because "Mars is 2.28e11 meters" makes no sense

[strange mortar]

omg I KNOW RIGHT ! What the fuck is "mars is 2.28 hdksbdkdnskddj" Mars is what? Doesn't make sense

[eternal comet]

Anyways, now that we know that the radius of Mars' orbit is 2.28e11 meters

[strange mortar]

Should I complain to the professor lol like what? Should I assume it's bagels? Donuts

Yeah radius

[eternal comet]

What kind of motion describes Mars' movement around the Sun?

[strange mortar]

Are you asking me for a FORMULA?

I have no clue

[eternal comet]

No, just the type of motion. The formulae come later.

[strange mortar]

Circle

Circular

[eternal comet]

Circular motion, but also a special type of it

[strange mortar]

I am not familiar

[eternal comet]

uniform circular motion

Well then, now that we know what we are dealing with.

What do we know about it that could help us solve the problem?

[strange mortar]

Yesssss that

We know radius

And the time it takes to orbit once

[eternal comet]

Well, and we want the acceleration of Mars

So do you know some kind of formula that could help us?

[strange mortar]

a=v^2/R

?

[eternal comet]

yes, that is the formula for centripetal acceleration when an object is in uniform circular motion

We have R

but we don't have v

How could we get the velocity of Mars?

[strange mortar]

Right

Ummmm

[eternal comet]

Remember, we still have the period of Mars' orbit available

Let's call it T

[strange mortar]

Yes

Okay

[eternal comet]

so, what formula do you know for velocity that we could possibly apply here?

[strange mortar]

I know d/t?

Displacement over time

[eternal comet]

yes!

just since we want to find the linear speed, we'll use distance covered / time taken

Well, during one orbit, what distance does Mars cover?

[strange mortar]

2pi?

Right?

2pi/687 days

Or 59,356,800 seconds

[eternal comet]

Well, the circumference of Mars' orbit is definitely not 2pi

I mean, Mars covers way more than 6.28 meters per 2 years

[strange mortar]

How do you calculate distance covered by mars

[eternal comet]

what is the circumference of this circle?

[strange mortar]

Oh fuck

That's umm

2r

[eternal comet]

[strange mortar]

Times pi

[eternal comet]

yes

[strange mortar]

lmao

I botted

No fucking way I forgot that

My b g

https://tenor.com/view/nervous-gif-18906606

[eternal comet]

$v = \frac{2\pi R}{T};, a = \frac{v^2}{R}$

[wraith dagger]

Remavas

[eternal comet]

well then, I don't know how you've been taught.

But I always like to create a "final" formula, linking the physical quantity you are searching for with known parameters

And only then calculate the numerical result

After some algebra, you'd get

$a = \frac{4\pi^2 R^2}{T^2 R} = \frac{4\pi^2 R}{T^2}$

[wraith dagger]

Remavas

[eternal comet]

Verifying units, we see that we divide Radius (m) by period ^2 (s^2) and we get m/s^2

so everything seems in order

[strange mortar]

One sec I'm working it out now with this info

[eternal comet]

,w 4*pi^2 * (2.28e11 meters) / (687 days)^2

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Remavas#3737

[strange mortar]

Days need to be converted to seconds

[eternal comet]

Wolfram does that

[strange mortar]

Ohhhhh

I got a different answer

1.059 m/s^2

[eternal comet]

,w G * (mass of sun) / (1.5 AU)^2

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Remavas#3737

[eternal comet]

Yeah nope, wolfram is definitely correct here.

[strange mortar]

But

Where did it all go wrong

Wait

I didn't square

I think

No

[eternal comet]

,w (24134)^2 / 2.28e11

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Remavas#3737

[eternal comet]

well you made a mistake here

[strange mortar]

I didn't square

Lol fuck

There I found the issue

Is this the visual representation on what's happening?

[eternal comet]

yes

[strange mortar]

Thanks 😊

. Close

Forgot how to close

[eternal comet]

.close

[cedar kiln]

Channel closed

Closed by @eternal comet

Use .reopen if this was a mistake.

[eternal comet]

didn't know I had perms to do that

huh

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

.rotate

[eternal comet]

,rotate ccw

[crimson sedge]

How do I verify do I do f(g(x))?

[hollow minnow]

Yes $f^{-1}(f(x)) = x$

[wraith dagger]

Pure

[crimson sedge]

F-¹?

What does that do

@hollow minnow can you show me steps or no

[hollow minnow]

My point is if you apply f to g or g to f in whatever order and get that it’s equal to x then they are inverses of each other.

[crimson sedge]

F(g(x)) then g(f(x))?

@hollow minnow

[hollow minnow]

Well yeah they should be the same

Best thing to do is fg(x)

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

help please

[crimson sedge]

im so dumb i literallyt odnt know

havent dont work yet

[lofty ridge]

we can write it out as a x y table

x being the figure and y being the number of red tiles

go ahead!

[crimson sedge]

oh okay

ty

lemme try

wait x + 2(y)

i th ink thats it ty

.close

[cedar kiln]

Channel closed

Closed by @cobalt grove

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[haughty wraith]

this is math help not cs help

and i cant program either

[radiant mountain]

but it truth table tho

they are intertwined

[haughty wraith]

just plug in 00 01 10 11 and then see the results and put in a truth table

[radiant mountain]

do u know logic gates?

[haughty wraith]

yeah been a while though

the triangle one is a not operator

the rest i've forgot but its not a hard problem

[fair geyser]

they are all not something

the circle is the not

nand specifically

so D is simply A and B

[cedar kiln]

@radiant mountain Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gentle field]

damn it I have to go

.close

[cedar kiln]

Channel closed

Closed by @gentle field

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[kind magnet]

Hey I am trying to solve this exponents problem

I followed the formula being A = P (1+r/m)^m * t

so if I plug everything in

A = 3000 ( 1 + 0.07/1)^9*1

which gives 3434.7 on my calculator

Is there something that I did not understand when plugging in my numbers or is it a concept of the exponents that I made a mistake in?

[livid hound]

show what you're pluigging into your calculator

[kind magnet]

nvm i made the error lol

I wrote to the power of 2 instead of 9

it's being compounded for 9 years not 2

.close

[cedar kiln]

Channel closed

Closed by @kind magnet

Use .reopen if this was a mistake.

[kind magnet]

.reopen

[cedar kiln]

✅

[kind magnet]

Quick question in my lecture

it says that the population is growing by a factor of 8 every hour

how did he come to that conclusion?

I 4000/60 and it gave me like 66

[zenith sail]

Started with 500 bacteria. After an hour there are 4000 bacteria

That's an increase by a factor of 8 in one hour

4000/500 = 8

[kind magnet]

ohhhh

ok thanks a lot

[zenith sail]

Sure thing 👍

[kind magnet]

so in the old example the bacteria doubles every 40 mins

how would I go about finding the factor for this problem?

since it is every 4 hours

would it be 300 * 2^t/4?

2 because it is doubling

.close

[cedar kiln]

Channel closed

Closed by @kind magnet

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

@crimson sedge Has your question been resolved?

[crimson sedge]

One message removed from a suspended account.

[cedar kiln]

Channel closed

Closed by @wild pelican

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[bronze rune]

can a limit be determined from this data? or does the 7.05 make it so that you cannot determine the limit

[zenith sail]

You can't prove the limit from that. But the table definitely suggests that a limit exists

[bronze rune]

riiiight

alright ill just say it cant be definitively determined

thx

.close

[cedar kiln]

Channel closed

Closed by @bronze rune

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[shell topaz]

Let X denote a random variable with X ∼ Exponential(2).
Calculate E[sin(X)] using simulation

can someone explain to me how i can calculate E[sin(X)] without simulating it?

[shell topaz]

trying to understand the difference between say finding the expected value of a random variable vs the arithmetic mean

[cedar kiln]

@shell topaz Has your question been resolved?

[shell topaz]

<@&286206848099549185>

[cedar kiln]

@shell topaz Has your question been resolved?

[cedar kiln]

@shell topaz Has your question been resolved?

[cedar kiln]

@shell topaz Has your question been resolved?

[cedar kiln]

@shell topaz Has your question been resolved?

[gritty viper]

expected value is a similar concept to arithmetic mean

I don't think arithmetic mean applies to random variables so that's the difference

[warm bone]

https://en.wikipedia.org/wiki/Law_of_the_unconscious_statistician

[shell topaz]

how would I calculate the expected value in my example?

[warm bone]

This tells you how

[shell topaz]

i tried using lotus

but im not getting the result

[warm bone]

Show some working

[shell topaz]

thats the thing im not sure how to define the integral

my guess is g(x) is sin(x)?

[warm bone]

Yes.

[shell topaz]

so \int sin(x)fX(x)dx?

[warm bone]

Yes.

[shell topaz]

but

what are the limits?

0 to inf?

[warm bone]

How do you define f_X(x)?

[shell topaz]

the exp function

[warm bone]

Not just that...

[shell topaz]

where lambda is 2

[warm bone]

$$f(x, \lambda) = \begin{cases}\lambda e^{-\lambda x} & x\geq 0\0 & x<0\end{cases}$$

[wraith dagger]

草w

[warm bone]

Directly from Wikipedia

[shell topaz]

f(x, \lambda) never seen this notation

[warm bone]

Integrate on whole real line as desired.

well wikipedia does $f(x; \lambda)$ but why does it matter

[wraith dagger]

草w

[shell topaz]

hmm

same as fX(x)?

[warm bone]

What happens when you use it to integrate on the whole real line?

it should be obvious...

[shell topaz]

not sur

not a random var anymore?

[warm bone]

............

[shell topaz]

dont know

[warm bone]

How do you find the mean of any random variable

[shell topaz]

find the expected value

wait

it gives me the correct answer

when i do the integral

but I did the same integral yesterday

and i couldnt get the answer

hmmm

[warm bone]

That is correct

[shell topaz]

but

I tried for like 20 mins yesterday

same integral

dont get it

[warm bone]

then you were wrong yesterday

and correct today

[shell topaz]

weird

ooh

i remember

[warm bone]

it's fine

[shell topaz]

i said sin(fX(x))

xd

wow

what was i thinking

okay so the difference between the arithmetic mean and the expected value is that the arithmetic mean deals with frequency while expected value deals with probability?

[warm bone]

I don't know if that's a meaningful difference

[shell topaz]

just what i gathered looking at the formula for both

since expected value you multiply with probability while arithmetic mean u just add the occurrences together and divide by n

or is it wrong to think about it like that

[gritty viper]

expected value just has an additional complication of probability

they don't apply to the same things

[shell topaz]

it's bcs you can also simulate the expected value of this

x <- rexp(10000000,2)

sum(sin(x))/10000000

and you get 0.4

this is the arithmetic mean

but I have a hard time understanding why the exp function goes into sin(x)

[warm bone]

the rexp are random draws

don't mix up r p d q

[shell topaz]

yea I take a lot of samples from the exp distribution

[gritty viper]

ah so you're taking the arithmetic mean of a bunch of samples yes

That's the motivation behind expected value

the arithmetic mean of n samples will probabilistically converge to it as n goes to infinity

[shell topaz]

yea so the expected value is the real mean

well

only if you integrate to inf i guess

so they are kind of the same thing just written differently

[gritty viper]

well you can't talk about the arithmetic mean of a distribution

there's nothing to add up and divide by n

[shell topaz]

really

but if you have lots of samples

[gritty viper]

if you have lots of samples and you take the mean you will probably get close to the expected value

[shell topaz]

yea so wouldnt that be the arithmetic mean of the distribution?

[gritty viper]

distributions don't have arithmetic means

arithmetic mean is when you have a finite set of elements

and you add then all up and divide by the total number of elements

[shell topaz]

ah yea

[gritty viper]

that's not happening here though

[shell topaz]

thats true

simulating to infinity is impossible I guess?

[gritty viper]

yeah

and if you did, then what

infinity/infinity?

[shell topaz]

heh

uuuh my brain stopped working thinking about infinity

thanks for help this is a good time to end it

.close

[cedar kiln]

Channel closed

Closed by @shell topaz

Use .reopen if this was a mistake.

[gritty viper]

np

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

,w solve x^2+(4x^2)/(x-2)^2=12

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by 3317#7956

[crimson sedge]

There.

[sacred grail]