np
#help-10
main cedar
spare sphinx
how do we prove it, cuz isnt it already obvious cuz we cant make one out of the other?
main cedar
we have to show that if we set this linear combination equal to the zero matrix, then a=b=c=0
(which is just the definition of linear independence)
pseudo willow
Stuck on this trig identity
obtuse pebbleBOT
Stuck on this trig identity
warm canopy
Try cross multiplying the two fraction and using some identities
cerulean tulip
Stuck on this trig identity
try evaluating the difference of the two fractions
oh the LHS
hello! try not to post in a channel thats already taken though
patent marten
Sorry I had the channel open and was typing
pseudo willow
try evaluating the difference of the two fractions
Wait is it just -2sinx
cerulean tulip
Wait is it just -2sinx
??
make a common denominator for the fractions in the LHS
and add them
pseudo willow
make a common denominator for the fractions in the LHS
oh like from the secx and tanx fractions
cerulean tulip
yep
pseudo willow
Do I continue by changing the denominator to 1?
junior granite
hey guys
junior granite
can anyone help me with this question : If 24 m of fencing are required to enclose a rectangular garden, what is the area, A, of the garden as a function of the length of one side?
im a dumb highschool student 😦
obtuse pebbleBOT
@junior granite Has your question been resolved?
cerulean tulip
can anyone help me with this question : If 24 m of fencing are required to enclo...
A = length x width
do you see any way to express the width in terms of the length?
plain grove
to show that ABCD for instance is a parallelogram, i only need to show the AB is parallel to CD right
obtuse pebbleBOT
to show that ABCD for instance is a parallelogram, i only need to show the AB is...
plain grove
i feel like i have to show smth else too but its been so long i forgotr
merry whale
You have to show ab = cd as well
plain grove
would it be half of AC
merry whale
Yup
plain grove
how would i show that though?
merry whale
Do you know how to show two triangles are similar
Similarity tests.. SAS in particular
merry whale
Ratio of corresponding sides is equal to each other
And the angle between the two sides is the same
Then the two triangles will have all the same angles
And the corresponding ratio of the third side will be the same too
So DZ/DA = DY/DC and angle zdy = angle adc
Does that help?
plain grove
So DZ/DA = DY/DC and angle zdy = angle adc
still confused how this would work with YZ and WX
merry whale
So DZ/DA = DY/DC and angle zdy = angle adc
Because y and z are midpoints and they have a common angle, the two triangles are similar. So think of it as just being able to expand the smaller triangle by twice the size to get the bigger triangle
In that case, how would YZ and AC be related?
Apply the same logic to wx and ac
To show that in addition to being parallel, they are equal too
plain grove
To show that in addition to being parallel, they are equal too
so would it be enough to show that WX is parallel to YZ using the midpt. thm
and then with that you could see that WX = ZY = AC/2
using similar triangles
merry whale
You can mark it as closed then by typing .close
plain grove
.close
feral sentinel
hi, can someone explain the difference between reflexive and irreflexive and why not reflexive != irreflexive
obtuse pebbleBOT
hi, can someone explain the difference between reflexive and irreflexive and why...
brave bramble
,w irreflexive
warm shaleBOT
brave bramble
"Not reflexive" means there exists an element x, such that x is not related to x
"irreflexive" means EVERY element x is not related to itself
feral sentinel
oh so the element is not related to any element
brave bramble
You can have relations that are not reflexive, but also not irreflexive
feral sentinel
like element p is irreflexive, it doesnt have a relation with any other element
feral sentinel
You can have relations that are not reflexive, but also not irreflexive
would this mean that element x is related to every other element other than itself
brave bramble
"irreflexive" is a property of a relation, not an element
A relation is irreflexive if no element is related to itself
feral sentinel
oh wait
brave bramble
A relation is not reflexive if some element is not related to itself
feral sentinel
ohhhhhh
so irreflexive is for all
eh no i meant
not reflexive is for all
wait
so irreflexive is for all
but reflexive is there exists
is that correct haha
brave bramble
Well, "not reflexive" is a "there exists"
A relation is reflexive if all elements are related to themselves
feral sentinel
oh right
brave bramble
Therefore, a relation is not reflexive if there's a single element that isn't related to itself
fierce lagoon
What the heck it can pull up definitions?
feral sentinel
not reflexive -> there exists
reflexive -> for all
irreflexive -> for all
brave bramble
I know right
feral sentinel
fierce lagoon
So you're telling me I did not need to screenshot a Google page, crop it, and send it
feral sentinel
fierce lagoon
I hate everything
brave bramble
I was like "I'm not going to pretend I know what irreflexive is off hand" haha
feral sentinel
I hate everything
itsokay now you know
better late than never
oh also i get the meaning
brave bramble
not reflexive -> there exists
reflexive -> for all
irreflexive -> for all
Pretty good summary
feral sentinel
brave bramble
Most obvious relations are reflexive
You'd need to make a weird one to get irreflexive
brave bramble
I don't dm questions sorry, haha. But, feel free to send it here!
brave bramble
Worth asking, do you understand the relation? Like, if I handed you two different jobs, could you tell me if they're <?
feral sentinel
erm not really, can i try explaining to see whether my understanding makes sense?
brave bramble
Sure!
feral sentinel
set J = {set of jobs represented by J1 J2...Jn}
each J can be represented as {sk, ek}, where sk is the start time and ek is the end time so sk < ek, k in {1,2,...,n}
so the example shows us 8 jobs and each of their timings are depicted in the number line
the relation < denotes that two jobs have a relation if and only if job 1's ending time is less than or equal to the starting time of job 2
woah wat
brave bramble
So if I told you that I1 < I7, you'd say true/false?
brave bramble
Yeah it seems like you get it!
brave bramble
Okay. So none of the jobs can possibly end before they start
feral sentinel
so ill have to show that ALL elements' ending time is > starting time
so none of them could possibly be reflexive
brave bramble
Sure sure
feral sentinel
Sure sure
Irreflexive:
Irreflexive denotes that ALL elements are not reflexive.
Let x $\in$ J, then x: {$s_1, e_1$}
Proof by contradiction:
Assume x $\prec$ x.
Then, e1 ≤ s1.
This would mean that the time that job x ends is the same as the time when job x starts.
This implies a contradiction as such an instance would never occur.
Thus, x $\nprec$ x.
Hence, no element $\in$ J is reflexive, thus $\prec$ is irreflexive.
feral sentinel
wtf
@brave bramble i dont get the anti-symmetric one
anti-symmetric means that if two elements have a relation then both elements are the same right? but its not the case in this scenario
meager canyon
why not?
feral sentinel
erm because an element cant have the relation on itself
or i mean an element cant be $$\prec$$ to itself
so it doesnt make sense
i think
warm shaleBOT
HellO
meager canyon
yes because it's irreflexive, but why does that mean not anti-symmetric?
feral sentinel
erm wait
anti-symmetric denotes that $$x_1 R x_2 \land x_2Rx_1\implies x_ 1 = x_ 2$$
uh wait
warm shaleBOT
HellO
brave bramble
Hello I am back
feral sentinel
helloo
brave bramble
You can't call an element reflexive. That's not something an element can be. But, you can say an element is "related to itself"
feral sentinel
ohh
brave bramble
That is, xRx or x < x here
brave bramble
Otherwise that's great, yeah!
Not necessarily "the same time", but also could be "before"
That's a nitpick though. It's clear you know what's going on with that proof.
brave bramble
XD
brave bramble
Similar idea. There is no single x and y such that, given xRy, then yRx
It's "no elements follow symmetry at all"
feral sentinel
oh wait
OH
because the "if" part doesnt succeed at all
so the right side wont be reached
ohhhh
thanks alot hah
brave bramble
But that never works here, yeah
brave bramble
Feel free to ask if you have anything else!
hybrid frost
How is the standard deviation of the means related to the standard deviation of the population and the standard error?
obtuse pebbleBOT
How is the standard deviation of the means related to the standard deviation of ...
hybrid frost
<@&286206848099549185>
obtuse pebbleBOT
@hybrid frost Has your question been resolved?
obtuse pebbleBOT
Question 5
kindred oasis
What did you try to do?
scarlet relic
I differenated and subbed in 8
royal basin
that sounds like exactly the right thing to do, modulo the typo in the word "differentiated"
royal basin
you can disregard the second half of my last message
anyway
what is the issue here?
does your answer not match that of the answer key?
scarlet relic
i got 165 and the asnwers say 181
kindred oasis
That looks right to me, maybe there's a mistake in the textbook you're using
royal basin
bad notation
it's not S = 3t^2 - 4t + 5, it's dS/dt = 3t^2 - 4t + 5
also let's check
,calc 3 * 8^2 - 4 * 8 + 5
warm shaleBOT
Result:
165
proper forum
Is my approach in/correct?
obtuse pebbleBOT
Is my approach in/correct?
royal basin
your handwriting is nigh unreadable
proper forum
Wrote it with my mouse.. but yes used the mouse with my hand so handwriting. Will wait for a translator I suppose.. will rewrite it if no one can decipher it.
royal basin
just rewrite it anyway
proper forum
royal basin
hmm
no, this is not correct as stated
it can be fixed by adding 3P(A ∩ B ∩ C) however
proper forum
Isn't P(A ∩ B ∩ C) the scenario in which all three hit their target which is not what we need?
pine sail
It's not about that, Set theory, inclusion exclusion. You removed that part an extra number of times.
royal basin
let me make a diagram
proper forum
Will try to confirm it via venn diagrams.
royal basin
here you go
P(A) - P(A&B) - P(A&C) counts P(A only) with a coefficient of 1 but it also counts P(A&B&C) with a coefficient of -1
so when you do this for B and for C too and add it all up
you end up with this
proper forum
P(A) - P(A&B) - P(A&C) counts P(A only) with a coefficient of 1 but it also coun...
The arithmetic operations are occurring one-by-one correct? Because if we were to subtract P(A&B) and P(A&C) from the original P(A) that would give us -2 for P(A&B&C)..
royal basin
no
look at the diagram
A&B&C is a subset of A
and as you can see i've put a red +1 in every region contained in the A circle
to reflect the addition of P(A)
so the A&B&C region ends up with +1-1-1 = -1 as its coefficient
proper forum
I see it now; it was +1 initially and after subtracting two it becomes -1.
royal basin
yes
proper forum
That was certainly an enlightening experience. Thank you for your time and assistance.
.close
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
forest cove
can I have help with this ques
obtuse pebbleBOT
can I have help with this ques
timid silo
replace y with 2x in the first equation
in simultaneous equations your aim should be to represent an equation in terms of 1 variable
y = 2x
timid silo
yes
forest cove
?
timid silo
as I said your aim should be to represent an equation in terms of 1 variable
https://www.youtube.com/watch?v=d6vyYvx8URw&t=24s
watch this video
this will help u
no see this one
hidden bluff
is anyone awake
obtuse pebbleBOT
is anyone awake
kind hawk
hidden bluff
okay
could someone walk me through how to solve this question
omg wait i think the reason im getting it wrong is because im rounding
this is pain
.closed
.close
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
hybrid thicket
How can I expand this $(a+bi)^m$ where $m\in\mathbb{Z}^+$
obtuse pebbleBOT
How can I expand this $(a+bi)^m$ where $m\in\mathbb{Z}^+$
warm shaleBOT
wil
restive ridge
Or convert to polar and use demoivre's theorem
this is the better option
obtuse pebbleBOT
@hybrid thicket Has your question been resolved?
spare sphinx
obtuse pebbleBOT
spare sphinx
How to do B hmm
wary vigil
in a you found a way to write (1, 0) as a combination of (1, 2) and (3, 5)
what b asks
i think
is to do the same thing with the "vectors" p1 p2 and p3
using the given B
so using
1
x
x(x-1)
and x(x-1)(x-2)
spare sphinx
ohh
wary vigil
that's how i read it
spare sphinx
okaii
wary vigil
does that make sense?
wary vigil
in A you have
spare sphinx
[1 3 ] [1]
[2 5 ] [0]
[1]
[2]?
wary vigil
$\lambda \begin{pmatrix} 1 \ 2 \end{pmatrix} + \mu \begin{pmatrix} 3 \ 5 \end{pmatrix} = \begin{pmatrix} 1 \ 0 \end{pmatrix}$
warm shaleBOT
Katharine
spare sphinx
Ohh
wary vigil
and you have to find lambda and mu
wary vigil
i could be wrong though
it could be the case that v1 is already in terms of the basis
and you need to find the x and y components
spare sphinx
it could be the case that v1 is already in terms of the basis
oo i dont think so? They say i have to give in terms of basis
wary vigil
i think i'm right though because for b the first way makes sense
wary vigil
so p1
spare sphinx
do i do it by row reduction
wary vigil
our basis is {1, x , x(x - 1), x(x - 1)(x - 2)}
and we want to use this to create x^2
by only adding multiples of the basis
spare sphinx
Ohhh
spare sphinx
I see
wary vigil
which one of our basis has x^2
spare sphinx
**Katharine**
sorry, but how do i find lambda and mu?
wary vigil
by splitting that equation into 2 equations
spare sphinx
Oh wait
spare sphinx
Okk
spare sphinx
our basis is {1, x , x(x - 1), x(x - 1)(x - 2)}
I understand what is going on but idk how to apply 
wary vigil
b is actually a bit different in the way to solve
because in b you have a 1d "vector" made from the basis
so the whole 2 variables 2 equations thing won't work
but what we do have in our bag
is the fact that using linear combinations
aka
adding and subtracting only
we cannot change the degree of the polynomials
spare sphinx
Ohhh
wary vigil
so if in our answer
we want x^2
that means in our basis we have to find the one that gives us a term x^2
or a multiple of x^2
and we can then later try to get rid of any numbers
spare sphinx
Only x^2 so no other variable?
wary vigil
or x terms
spare sphinx
ooo
we can just add and subtract and get x^2 but how to find the basis for it, do we write it in matrix?
wary vigil
let me say it this way
we want to get x^2
we have
{1, x , x(x - 1), x(x - 1)(x - 2)}
so what we want is
$\lambda + \mu x + \zeta x(x - 1) + \eta x(x - 1)(x - 2) = x^2$
warm shaleBOT
Katharine
wary vigil
i hope this is clear
to me it looks a bit cluttered
but my point is that we have to find all those letters
lambda mu zeta and eta
and to do that is normally very difficult with 4 unknowns
but what we know is that the maximum degree is x^2
so eta
the last term
is 0
because if you get rid of those parenthesis you will get x^3 term
i hope that makes sense
spare sphinx
Ohh got it
wary vigil
ye
wary vigil
you can ask
tardy stratus
Remind me, what does it mean for something to be a basis?
spare sphinx
Umm vectors that cannot represent each other, and is the simplest way to describe span?
tardy stratus
Okay, this is an interesting definition
Perhaps there is a more precise definition? What does it mean that they cannot represent each other?
If you're working from a textbook, the definition should be in there somewhere. Why not have a look back and remind yourself.
spare sphinx
ahh okay
tardy stratus
I'd like a precise description of what it means for three vectors to be a basis for R^3
tardy stratus
OK, where are these questions coming from? A course?
spare sphinx
yes a summer coursw
tardy stratus
Has your teacher at any point given you a definition of what a basis is?
spare sphinx
i think i have the notes
tardy stratus
OK, you should check these notes because the definition of a basis is one you should be able to recall immediately
spare sphinx
ahh my question is b, i think
tardy stratus
So you can definitely do 3(a)?
OK
Now you'll have to excuse me, because your course uses notation that I don't know
What is $P_{B_1 \leftarrow B_2}$? I don't know what this means.
warm shaleBOT
Boytjie
tardy stratus
Feel free to ping me once you have this information
tardy stratus
OK, so it is a matrix that takes a vector in the basis B_2, and expresses it as a vector in the basis B_1?
Great.
So a vector in basis B_2 is like this:
$\begin{bmatrix} a \ b \ c \end{bmatrix}_{B_2} = a\begin{bmatrix} 1 \ 0 \ 0\end{bmatrix} + b\begin{bmatrix} 1 \ 1 \ 0\end{bmatrix} + c\begin{bmatrix} 1 \ 1 \ 1\end{bmatrix}$
warm shaleBOT
Boytjie
tardy stratus
Do you think you can try to do that?
Express this vector above in the basis B_1
In fact, apologies, I made a small mistake above
I used the basis B_1 already, when I meant to use the basis B_2
I'm going to quickly rewrite it
This is correct: $\begin{bmatrix} a \ b \ c \end{bmatrix}_{B_2} = a\begin{bmatrix} 1 \ 1 \ 1\end{bmatrix} + b\begin{bmatrix} 0 \ 1 \ 1\end{bmatrix} + c\begin{bmatrix} 0 \ 0 \ 1\end{bmatrix}$
spare sphinx
Okk no worries
tardy stratus
Oh my goodness sometimes I hate latex
spare sphinx
😆
warm shaleBOT
Boytjie
tardy stratus
There we go
tardy stratus
Please write this out in full. What you've written doesn't make sense to me.
tardy stratus
So what is this meant to be?
It'd be great if you could write this out on paper, though I can read this fine
tardy stratus
OK
spare sphinx
.close
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
turbid wing
obtuse pebbleBOT
turbid wing
I need help with question 15
ik this function x + 1/x decreases from [-1, 0) and increases from (0, 1]
so how can I prove that it is strictly increasing in [-1, 1]
cerulean tulip
You could use derivatives
turbid wing
I don't understand what 'interval disjoint' means
turbid wing
So can you prove it will always be positive
its not
nocturne minnow
Is that image upside-down?
turbid wing
it will be 0 for 1 and -1
nocturne minnow
,rotate
turbid wing
Is that image upside-down?
wait sorry
warm shaleBOT
cerulean tulip
Nice u finished almost everything
turbid wing
for (-1,1) the derivative comes out to be -ve
nocturne minnow
Threw me off for a second because it looked like actual numbers and stuff when it was upside down
cerulean tulip
Recall that that if its continuous it cant changr signs between critical points
cerulean tulip
Recall that that if its continuous it cant changr signs between critical points
This
Also disjoint means everything not in that interval lmao
turbid wing
I don't understand what the question means by 'interval disjoint from [-1, 1]
turbid wing
Also disjoint means everything not in that interval lmao
ohhh
bruh
like
okay
then this question is tooo easy 😭
I literally thought that I need to prove that this function is increasing in this particular interval
thanks
.close
mental portal
obtuse pebbleBOT
nocturne minnow
Get same base
cerulean tulip
Where r u having a problem
mental portal
How to solve
pine sail
Get same base
...
cerulean tulip
Lmao
proven zephyr
show work
nocturne minnow
Post work
mental portal
cerulean tulip
Bruh
cerulean tulip
Make the base 2
mental portal
Can u give me step by step?
nocturne minnow
No
Use what we told you
Make the bases the same
And only manipulate the base
warm shaleBOT
Boytjie
tardy stratus
So do you think you can use this to infer something?
light niche
how do i simplify the expression sin(60)cos(30)+sin(30)cos(60)
obtuse pebbleBOT
how do i simplify the expression sin(60)cos(30)+sin(30)cos(60)
light niche
sin = opposite/hypotheneuse
wanton violet
$$\sin(a+b) = \sin(a)\cos(b) + \sin(b)\cos(a)$$
warm shaleBOT
Nathan_
light niche
oh
wanton violet
Have you seen that one before?
If not there is another way to do it but this is the quicker way
light niche
whats the other way to do it
high lily
these are all special angles
evaluate directly
wanton violet
To remember the exact values for sin cos and tan ( tan not needed in this case ) for 0, 30, 45, 60 and 90 degrees
wanton violet
Not sure what that is but if its a way to remember exact trig values then yes
light niche
so how do i use this to solve it
wanton violet
Find the angle you want
The x coordinate is the cos of the angle and the y coordinate is the sin of the angle
light niche
so sin60 = sin 1/2
wanton violet
Sin60 = sqrt(3)/2
wanton violet
Yep
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
hasty linden
obtuse pebbleBOT
hasty linden
From L idk what happened
sage geode
Do you know what L is in this case?
hasty linden
Length of curve
sage geode
Yeah, an generally for f(x) it is equal to this
Here they used this formula
And then evaluated the integral
tardy epoch
Yes algebraically i dont know how they went from l to the next line
$sin^2(t) + cos^2(t)=1$
warm shaleBOT
riemann
hasty linden
The prior image
tardy epoch
What line exactly
hasty linden
Therefore L statement to the line below
I just dont know how they got what they did
warm shaleBOT
riemann
hasty linden
e^4t -2e^2te^-2t+e^-4t
warm shaleBOT
riemann
hasty linden
Should be -2 right
weary delta
That is such a horrible way to write your steps wtf. It’s not obvious at all
hasty linden
I didnt write it
weary delta
Did you figure out what they did there btw?
hasty linden
Kinda, they expanded it and put it back in factored form
And then the next step goes
weary delta
You get a -8 in the middle when you expand it, group by 4, you get a +2, then you can put it back together
Whoever wrote that needs to go to algebra jail for showing off
hasty linden
Showing off?
obtuse pebbleBOT
Available help channel!
elfin vapor
Hiya , should be a quick one.
obtuse pebbleBOT
Hiya , should be a quick one.
warm shaleBOT
Max..
timid silo
(a+b)²=a²+2ab+b
(a+b)²-2ab=a²+b²
slim lake
But moved the 2ab to the other side
elfin vapor
slim lake
You've shown that $(a+b)^2=a^2+b^2+2ab$ so $(a+b)^2-2ab= (a^2+b^2+2ab)-2ab=a^2+b^2$
warm shaleBOT
Max..
slim lake
Np bro, u were basically there!
elfin vapor
.close
obtuse pebbleBOT
high lily
!= means not equal to
in some coding languages
obtuse pebbleBOT
Available help channel!
elfin tangle
obtuse pebbleBOT
elfin tangle
how would i find y
heavy beacon
wat
elfin tangle
cos= x/r right
heavy beacon
i dont know what you mean but yh sure
but the 3 things i told u
if u play around with it
u will find the answer
heavy beacon
cosD=2/5
draw triangle
SOHCAHTOA
why u graphing when the 2nd step says draw a triangle
draw a triangle bro
then maybe u ll see what to do
solar trellis
let me ask you. what does it mean to find the cos of an angle?
solar trellis
what does cos mean?
solar trellis
how would you find the cosine of this angle
heavy beacon
galactica bro watch a video on right angle triangles
elfin tangle
i have omg
heavy beacon
clearly havent
solar trellis
radius of what
heavy beacon
ok
solar trellis
what circle
heavy beacon
ok where is the circle in a right angle traingle by itself
solar trellis
unit circle
how is the unit circle defined?
heavy beacon
what if theres no circle
elfin tangle
okay not in a right triangle
heavy beacon
what is the radius
elfin tangle
what is the radius
5
heavy beacon
oh kurwa
elfin tangle
and ofc i heard that word lol
heavy beacon
watch a video
solar trellis
how is the unit circle defined?
.
elfin tangle
https://www.youtube.com/watch?v=a5WQlcFTXyk&ab_channel=NancyPi
i literally watched this exact video
the hypotenuse isnt the radius
because x=2
heavy beacon
oh kurwa
solar trellis
well it's rather tricky to define the word "define"
heavy beacon
giannis u got this one
solar trellis
wdym by unit circle
solar trellis
ok so it's a circle
elfin tangle
solar trellis
what makes it a unit circle tho
solar trellis
all circles have a radius
solar trellis
right so unit circles have radius 1
let's say you wanted to find cos40
how would you do that?
elfin tangle
just converting it into a decimal? wdym
heavy beacon
bro u went straight to cos 40
heavy beacon
just converting it into a decimal? wdym
listen
the question says hint:draw a diagram
if u drew a triangle
where is the radius
?
solar trellis
just converting it into a decimal? wdym
how would you find the value of cos40
heavy beacon
ok what is the longest side called?
heavy beacon
man forget the circle
elfin tangle
dear god
heavy beacon
throw the circle in the bin
heavy beacon
what measurements u given?
yes
and where is there a circle mentioned there
u can draw a circle
elfin tangle
yes
elfin tangle
yes
heavy beacon
ok so draw a right angle triangle
with the angle and the sides u know
and label them
solar trellis
lemme take this
elfin tangle
let me show you
solar trellis
how would you find the value of cos40
.
heavy beacon
bro forget the damn circle
heavy beacon
just draw the triangle with hyp 5 and 2
solar trellis
bruh
elfin tangle
saying bruh isnt helping me understand at all
elfin tangle
kk
heavy beacon
solar trellis
is x a side of a triangle?
elfin tangle
yes
solar trellis
which side
solar trellis
adjacent, opposite or hypotenuse?
elfin tangle
adj
elfin tangle
first finding the angle of d
solar trellis
you already know 2 side lengths
solar trellis
first finding the angle of d
how would you do that
you want a numerical value for the opposite side length, remember
elfin tangle
= sin-1 (opp/hyp)
nocturne minnow
FYI, these are right triangles, you are dealing with and when you drew hyp = 5, that's the length of the hypotenuse, not the coordinates of it
elfin tangle
looking from the other
elfin tangle
FYI, these are right triangles, you are dealing with and when you drew hyp = 5, ...
kk
solar trellis
you would like to get a number for the opposite side
without a calculator
except for standard operations
elfin tangle
24deg, then adj=5cos66
solar trellis
is D = 24 degrees?
solar trellis
ok try to not to use your calculator
elfin tangle
why
solar trellis
do you pythagoreas' theorem?
elfin tangle
2
solar trellis
it's not 2
elfin tangle
how
solar trellis
try to use pythagoreas' theorem
nocturne minnow
You're finding the missing side of that triangle
elfin tangle
jesus christ this is going nowhere
elfin tangle
wait
heavy beacon
Mandem he needs to learn the basics
elfin tangle
i know the basics
nocturne minnow
What is Pythagorean theorem?
.
elfin tangle
a^2 + b^2 = c^2
solar trellis
what's a,b,c
elfin tangle
c is hyp
solar trellis
yes
nocturne minnow
What value is the hypotenuse in that triangle?
elfin tangle
a and b can be either sides
elfin tangle
What value is the hypotenuse in that triangle?
5
nocturne minnow
You have a side, what value is that side.
elfin tangle
2
nocturne minnow
Plug that into for a or b, whatever you want
Then solve for the other variable
What value do you get?
solar trellis
no calculator
elfin tangle
can you give me like 5 seconds to think
nocturne minnow
no calculator
You can't enforce that. It's pointless
solar trellis
can you give me like 5 seconds to think
take your time
solar trellis
You can't enforce that. It's pointless
wdym
heavy beacon
You can't enforce that. It's pointless
Bro spoon feeding him the answer is not helping either
It just means he has no understanding of what hes doing
elfin tangle
Bro spoon feeding him the answer is not helping either
you literally havent helped at all either
nocturne minnow
It's pointless to try to enforce no calculators
heavy beacon
Like i said watch a video and acc try to understand what its saying
nocturne minnow
Bro spoon feeding him the answer is not helping either
I'm not feeding the answer. I'm stating what should be done next, not filling in the blanks
elfin tangle
i literally have been watching videos
thats why i came here lol
to be taught
its math help for a reason
anyways
heavy beacon
Help not answer
elfin tangle
its not answer lol
nocturne minnow
When you filled in the values into Pythagorean theorem, what is the equation you have?
elfin tangle
ive been sitting here for 2 hours trying to undertsand this
solar trellis
p sure D (not the angle) has tried a fair amount to help
nocturne minnow
When you filled in the values into Pythagorean theorem, what is the equation you...
.
elfin tangle
When you filled in the values into Pythagorean theorem, what is the equation you...
5^2= 2^2 + b^2
which then i need to rearrange
solar trellis
yes
solar trellis
which then i need to rearrange
do it
nocturne minnow
Rearrange to what exactly?
solar trellis
should be obvious from context
elfin tangle
to solve for b
nocturne minnow
Good
nocturne minnow
should be obvious from context
Someone who is low leveled could have said, set equal to 2^2
heavy beacon
Someone who is low leveled could have said, set equal to 2^2
Bro he is learning sec
nocturne minnow
No one asked for your input
elfin tangle
Bro he is learning sec
pls stop lurking here and go answer somebody else
solar trellis
Someone who is low leveled could have said, set equal to 2^2
i don't think they're that "low-leveled"
nocturne minnow
You never know, unless you ask
solar trellis
well they were going to rearrange it however they thought they should anyways
ok but moving on
elfin tangle
b=sqrt21
solar trellis
the question asks for sinD
elfin tangle
would sinD= sqrt21/5 ?
solar trellis
why
solar trellis
y as in adjacent, opposite, or hypotenuse?
elfin tangle
opp
solar trellis
would sinD= sqrt21/5 ?
yes
elfin tangle
wait
solar trellis
well actually not quite
solar trellis
this triangle definition of sin, cos, tan is only for angles between 0 and pi/2 but it extends quite naturally to more angles using the unit circle
with the unit circle, we allow for negative values for sin cos tan as well, which is not possible in just a triangle
solar trellis
sinD= -sqrt21/5
this is correct; D is in the 4th quadrant
elfin tangle
yayayyyyy
solar trellis
elfin tangle
i have another question tho from my work that i skipped over earlier, could you help? cuz clearly you helped me quickly lol
solar trellis
maybe or someone else might help. you can just post ur question
solar trellis
calculator
solar trellis
what did you type in ur calculator
elfin tangle
nothing lol
elfin tangle
359.212?
slim cove
would the other one be 218?
yup
obtuse pebbleBOT
Available help channel!
acoustic siren
Helppp!
acoustic siren
<@&286206848099549185>
acoustic siren
Sorry I thought I had to do that
versed cave
after 15 minutes
devout solar
obtuse pebbleBOT
@acoustic siren Has your question been resolved?
vagrant nacelle
could someone help me with this?
obtuse pebbleBOT
could someone help me with this?
tardy epoch
put over a common denominator
vagrant nacelle
so something like this?
