#help-10

1 messages · Page 591 of 1

royal basin
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from nothing?

timid silo
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yes?

royal basin
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the lengths of some of the arcs pictured here might help

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that's the only thing i can think of other than the angle itself

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or maybe the areas of some of these regions

timid silo
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hmmm

solar trellis
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just use a protractor lol

royal basin
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if this diagram came from nothing then this angle is of no relevance to anything

royal basin
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there is nothing in my message to "hmmm" about.

timid silo
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how do you calculate an angle regularly? like do you have an example?

royal basin
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it depends heavily on what else is known and what the diagram is like

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there are numerous theorems that relate angles in certain configurations to each other or to lengths. there are too many to give an exhaustive list.

obtuse pebbleBOT
#
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plucky patio
#

how do I do b?

obtuse pebbleBOT
plucky patio
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( btw this is a past paper )

knotty crow
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you can use the sketch from (a) to show that or just find inverse and then do that

knotty crow
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oh

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sr

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you can also use a graph to determine solution to the b)

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imagine function y = k (line parallel to the x-axis) for some k's

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determine 'k' such that line y = k crosses your f(x) in two point whose x-coords are negative

grizzled shore
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you could just do -(x+1)^2+4-k where the you check the sign of this

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so u know a is negative and the top has -b±∆

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so for it to be negative the top cant also be negative

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so -b±∆ > 0

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±∆ > b and u just see what kind of k's give u this inequality

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at least that's how i'd think about this question algebraically

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this is actually similar to thinking about it as, look at your vertex point, ∆/(2a) as how far this is from the vertex and saying the + of this from the vertex is negative

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cos if the vertex + |∆/(2a)| is negative then the vertex - |∆/(2a)| is definitely also gonna be negative

plucky patio
obtuse pebbleBOT
#

@plucky patio Has your question been resolved?

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feral island
#

How do I write a equation for this graph?

obtuse pebbleBOT
cerulean tulip
#

what

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wheres the origin

royal basin
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do these measurements say 19^2 m and 1ab m?

grizzled shore
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is that supposed to be a parabola?

obtuse pebbleBOT
#

@feral island Has your question been resolved?

obtuse pebbleBOT
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obtuse pebbleBOT
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slender fjord
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This is just a hypothetical to help me understand something.

slender fjord
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But assume I was given sin(theta) = 2/4

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how would I find cos(2theta)

urban patrol
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No way is that technoblade

slender fjord
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lol

urban patrol
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ok so sin(theta)=1/2

slender fjord
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yeah

urban patrol
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the expanded double angle formula for cosine can be 3 things if I remember correctly

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You can just plug in the 1/2 into any of them

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then solve for cosine(theta)

slender fjord
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oh I see

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ok thats all I needed to know

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thanks for the name

urban patrol
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Or maybe you can use the value of arcsin 1/2

slender fjord
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yeah the expanded double angle formula is right

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I just remembered

urban patrol
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okay cool

slender fjord
urban patrol
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no problem

slender fjord
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I just remembered how to do it

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thanks

#

.close

obtuse pebbleBOT
#
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azure hollow
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Hello, I need help with finding 75% of 110. I tried what my teachers try to teach me is to make 75 into 0.75 and then multiply it with 110. But I still do not understand why we make 75% into 0.75.

gleaming burrow
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75% is another way of saying 75/100

azure hollow
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Oh

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why?

gleaming burrow
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And 75/100 when expressed using decimal notation is 0.75

azure hollow
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oh bec ause .75 means 75 hundreths

gleaming burrow
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% percent -> per one hundred

azure hollow
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oh ok

gleaming burrow
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per -> / (division)

azure hollow
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Oh ok i think my teacher said that before

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thanks eeveeKawaii

obtuse pebbleBOT
#

@azure hollow Has your question been resolved?

wooden cipher
#

They left :l

obtuse pebbleBOT
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spring frost
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In this problem how do i find the vertical stretch

spring frost
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I initially thought it was 8 but it doesnt seem to be that way

haughty coyote
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What do you call vertical stretch ? The length of the interval of value reached ? If so remember sin has a stretch of 2, not 1

spring frost
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oh sorry it was 2

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I accidently changed it to 3 when I typed it the new one is below

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ok so it is that

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that also doesn't have a vertical stretch of 8 thought as well

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how do I find it again?

haughty coyote
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Because I actually don't know how you've defined that

spring frost
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in a function that is af(x)

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its the a

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so its the amount you multiply the y-coordinates by

haughty coyote
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And what is f here ? The stretch is relative to something

spring frost
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idk but I think d is the vertical shift in this function

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srry

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I was using notes from a different chapter on accident

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alr thanks for the help

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I think I just figured it out

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.close

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long phoenix
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How would I take the function from this graph?

long phoenix
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i dont know if i should take sin or cos

brave bramble
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Either can work. cos looks easier, though

wanton violet
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if it passes through (0, 0) then sin otherwise use cos (but technically both will work)

long phoenix
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so i got 3cos(x)

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but i still need to 3cos(x-d)

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and solve for d

brave bramble
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Do you?

long phoenix
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or 3cos[b(x-d)]

wanton violet
long phoenix
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yea so i could do 3cos(1/2x)

wanton violet
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2x not 1/2 x
for horizontal stretches you do 1/the factor you want to stretch by so in this case 1/(1/2) = 2

long phoenix
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ahh

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so its 3cos(2x)

wanton violet
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yep

long phoenix
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tytyty!

wanton violet
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np

long phoenix
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i see it now thanks!

#

.close

obtuse pebbleBOT
#
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timid junco
#

migght be a stupid question but I was wondering why he didn't solve for f''(x) on this problem

knotty crow
timid junco
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So it seems like all we have to do is solve when f'(x)=0 and plug it back into the original equation

timid junco
knotty crow
timid junco
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Well first derivative only shows if it's going up or down right?

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Only rate of change of f(x)

knotty crow
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yeah, it's about monotonicity of f(x)

timid junco
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I don't follow

knotty crow
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if you want to use f''(x) to determine them, then u should try this:
f'(x) = 0 and f''(x) < 0 --> max
f'(x) = 0 and f''(x) > 0 --> min

timid junco
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Yeah that's what I've been doing

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How do we determine only using f'(x) like you said

knotty crow
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for example

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for max

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it follows

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If the function $f$ has a derivative on the interval $(a,b)$ and $f'(x)>0$ for $x \in (a,x_{0})$ and $f'(x)<0$ for $x \in (x_{0},b)$, then $f$ has a maximum at $x_{0}$.

timid junco
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Oh I think I understand now

warm shaleBOT
knotty crow
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like in other words

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if function increases to some point

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and then decreases from this point

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on some interval

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then it's maximum

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shortcut is to determine change of the sign of f'(x) at the point we investigate

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if it changes from "+" into "-" then it's max
if it changes from "-" into "+" then it's min

timid junco
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For example f'(4)=-2 then this is max

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f'(-4)=2 then min

knotty crow
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not really

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it's not about the only one value

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let's say you investigate x = 4

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for some function

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you can take for example f'(-3.9) and f'(4.1), if f'(-3.9) < 0 and f'(4.1) > 0 then it's max
but this method rather works with graph of f'(x), because we can't be always sure that we take interval which is small enough

knotty crow
obtuse pebbleBOT
#

@timid junco Has your question been resolved?

timid junco
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seems a bit complicated

slim cove
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Because it's possible that the derivative is not zero there, but they could still be the absolute min/max

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That's why they plug 0 and pi in

timid junco
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I thought they plug 0 and pi because the question asks for the value at those points

slim cove
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no the question doesn't ask for the value at those points, it asks for the maximum and minimum value of f

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when 0 ≤ x ≤ pi

timid junco
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yeah the max and min in that interval of f(x)

slim cove
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right

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lemme give an example

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so let's say we're trying to find the max and min of this function in the interval [0, pi]

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you could set the derivative equal to zero

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and try to find maxes/mins that way

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but that doesn't give you all the possibilities

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it only gives you these two points

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because you need to check the endpoints at all

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aka these purple points

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does that make sense?

timid junco
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setting to 0 doesn't find all endpoints got it

obtuse pebbleBOT
#

@timid junco Has your question been resolved?

obtuse pebbleBOT
#
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jagged edge
obtuse pebbleBOT
jagged edge
#

i kind of dont understand this one

white urchin
jagged edge
#

i do understand the givern information

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but like i dont quite get what the question is

white urchin
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it is like :

A={1,2,3,4}
B={2,3}

then {1,4} = A-B

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You have to create an equation involving the sets A, B, and C that gives {-7,-7,-5,-3,-1,1,3,5,7,9}

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you can add a '-', '+', '∩', '∪', etc in your equation

obtuse pebbleBOT
#

@jagged edge Has your question been resolved?

obtuse pebbleBOT
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sleek cosmos
obtuse pebbleBOT
sleek cosmos
#

I don’t know how to do this equation

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What I mean is that I don’t know what to do on how to plot the four points other than vertex

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On 4x

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4c*

high lily
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to get additional points, choose some values of x, plug into the equation to get the respective y values to get your points

sleek cosmos
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Am I doing it right

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like plugging the equation

high lily
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yes

sleek cosmos
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What does ax^2+bx+c have to equal as seen in my thing which equals 3

high lily
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your question is unclear

sleek cosmos
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In the thing it says this

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idk how the person got ax^2+bx+c=3/-3

high lily
#

where exactly

sleek cosmos
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on the parabola equation

high lily
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they're all about parabolas

sleek cosmos
#

like the section where it says plot 4 points other than vertex you see -3

high lily
#

circle what you're referring to

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example 3? the table?

sleek cosmos
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yes why is f(x) equal 3 or negative 3

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basically similar

high lily
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consider the full table

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when x=0, f(x) = -3
etc

sleek cosmos
#

oh ok

high lily
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thats what you get from plugging in those values

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f(0) = f(4) and f(1) =f(3)
since x=2 is the axis of symmetry

sleek cosmos
#

ohhhhhhh

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I get it now. I will try another question

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on the page and check if I did it right

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@coral groveov#0921 did I do it right?

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Sorry for the ping of wrong person

#

@high lily

obtuse pebbleBOT
#

@sleek cosmos Has your question been resolved?

obtuse pebbleBOT
#
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gray hill
obtuse pebbleBOT
gray hill
#

I need help solving this. I found the point of intersection, but not really sure how to integrate this

hybrid gull
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Given that you’re integrating about the y-axis, you’ll be integrating with respect to y

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So you’ll need bounds in terms of y

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This may help you get started

gray hill
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so my bounds are 8 & 0 for limits?

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I'm not really sure what steps to take except just knowing how the formula is

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because what to plug in for r (radius)

hybrid gull
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If you have the formula, then you’re good to go. You just need the setup

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You’re trying to make the integral describe the volume

gray hill
hybrid gull
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Which number? The limits? The radius?

gray hill
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like this example:

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i'm sure I have to do the same thing with this problem

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oh wait

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I see it now

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so basically make x=y

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so y^3/2=8

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so y=4

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so my limit is 4 0 and I just plug in my x, which is pi(y^3/2)^2 dy right?

hybrid gull
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It helps to draw a picture

gray hill
hybrid gull
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I think you integrate from 0 to 8

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y = 8 is where the solid/revolution stops

gray hill
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how come then in that example they used what y was as the limit then?

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so i just change it to 8 0 pi(y^3/2)^2 dy then?

hybrid gull
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I’m gonna look at a picture

gray hill
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im stuck lol

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tried to follow what was in the example above but not sure if im doing that step right

hybrid gull
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I think what they’ve done is wrong

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Get a picture of specifically the region you’re revolving

gray hill
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not sure if that's correct

gray hill
hybrid gull
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The region you’re revolving

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That is bounded by what the problem tells yo

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*you

gray hill
#

not sure if I did this right

gray hill
hybrid gull
#

You can use a graphing calculator to get a picture

grizzled shore
#

why dont i see any cylinders

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in a rotating question

hybrid gull
# gray hill

This, but a picture that includes the bounded region

wooden cipher
#

They have the rotate arrow

gray hill
grizzled shore
#

oh

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ok nvm didnt see

gray hill
#

assuming I shade till 8

hybrid gull
#

Right

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So revolving this about x = 0 means the horizontal layers of your solid will start at y = 0, end at y = 8, and radius will be equal to x = y^(3/2)

gray hill
#

something like this?

gleaming burrow
#

That isn't the bounded region

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For your desmos graph, there is a bounded region

gray hill
#

oh the green line?

gleaming burrow
#

Between blue, green, red curves

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By the way, do you have desmos link?

gray hill
gleaming burrow
#

I thought you used it to make the graph

gray hill
gray hill
#

just the regular website

gleaming burrow
#

Anyway, the bounded region is between them all

gray hill
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so shade all of it in the space within all 3

gleaming burrow
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Yes

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Shading below the red curve doesn't work, since it has no lower bound

gleaming burrow
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Yes

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Now can you draw on this which axis it will rotate around?

gray hill
gleaming burrow
#

Kind of ambiguous the way you draw it, but it's rotating around the vertical y axis

gray hill
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my bad

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so 45 degrees clockwise?

gleaming burrow
#

So consider drawing a single cylinder / disk on the line for an example

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Based on the question, it revolves all the way around.

gray hill
#

so draw a cylinder from 0?

gleaming burrow
#

I will draw it

gray hill
#

@next reef I see you lurkin' SobbingCry im so bad at this CB_kermit_lmao

next reef
#

ohh

#

hewo

gray hill
#

nice reactions XD

gleaming burrow
gray hill
#

oh the middle

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between 0 and 1

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so 0.5

gleaming burrow
gray hill
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so what do I do now?

gleaming burrow
#

Now you need to start with the volume of a single cylinder

gray hill
#

so...I plug it in here

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so pi with the limit 8 and 0 with not sure about y^2 dx

gleaming burrow
#

The problem is that is around the x-axis

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But we're around the y axis

gray hill
#

but same formula right

gleaming burrow
#

For our sample cylinder, we would do pi * dx^2 * dy since the height is dy and the radius is dx

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Yeah, you will use same formula

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The only problem is it is easy to get confused on this type of problem

gray hill
#

so what'd I plug in for dx?

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y^3/2?

gleaming burrow
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It is between x = y^(3/2) and x = 0,

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So yeah, it is y^(3/2)

gray hill
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so I do pi*y^(3/2)dy?

gleaming burrow
#

That gives you the value of a single cylinder, and to add them all up you turn it to an integral

gray hill
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oh wait

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supposed to add the integration

gleaming burrow
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The dy becomes part of the integral

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It will go away when you integrate

gray hill
gleaming burrow
#

Is that wolfram?

gray hill
#

nah, symbolab

#

this correct though?

gleaming burrow
#

Wait, did we remember to square it?

gray hill
#

just the y^3/2 part yeah?

gleaming burrow
#

since y^(3/2) is radius and it needs to be squared

gray hill
#

got it

#

1024pi

gray hill
#

.close

obtuse pebbleBOT
#
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feral island
#

I am given a question to determine a quadratic equation with these characteristics

Minimum value is 12
X=-4
Y intercept of 60

feral island
#

will I be using y=a(x-p)^2+q?

#

but than where would the minimum value go?

quaint glen
#

When you write "x=-4" what does that mean? Is that its axis of symmetry? It's x-axis intercepts? Something else?

royal basin
#

@feral island do you have the exact problem statement?

feral island
#

Determine a quadratic function step by step:
minimum value of 12 at x=-4 and y intercept of 60

royal basin
#

ah

#

minimum value of 12 at x=-4

feral island
#

Does it make a difference?

royal basin
#

i think this answers your question of "where is the minimum"

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and tells you exactly what the coords of the vertex are

feral island
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Ooh

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So the vertex will be -4,12?

royal basin
#

(-4,12), yes

#

don't drop the parentheses when specifying the coordinates of a point

feral island
#

Thanks

feral island
#

since Y-int=(0,60)
Vertex=(-4,12)

royal basin
#

when you say "the equation" do you mean "the equation of the curve" or "the equation that gives the value of a"

feral island
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The equation that give the value of a

#

Sorry

royal basin
#

then yes

feral island
#

But I kept on getting the wrong answer for some reason

royal basin
#

were you putting your answer into your homework system that kept rejecting it?

#

show the work that led to your wrong answer.

feral island
#

A is suppose to be 3

#

According to the answer

devout solar
#

It would be if you didnt fuck up

#

try again

royal basin
#

how did a(0+4)^2 + 12 become 28a?

feral island
#

Oops

#

16

devout solar
#

no

royal basin
#

no, 4^2 is not 12

feral island
#

+12

#

Than it’s 28

devout solar
#

ig you did some 16a+12 bullshiy

#

you dont add 16a and 12

feral island
#

Oooh

devout solar
#

smh

#

16a+12 isnt 28a

royal basin
#

16a + 12 ≠ (16+12)a

devout solar
#

16a+12a is 28a

feral island
#

Thanks I got it now

obtuse pebbleBOT
#

@feral island Has your question been resolved?

#
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obtuse pebbleBOT
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zenith dagger
#

I forgot all the percentage stuff, some one help me

devout solar
#

pretty low chance

#

1/8192

zenith dagger
#

oh wait, is this the answer? 0.0001220703125%

#

also including the before values

devout solar
#

no

royal basin
#

you havent yet converted that into a percentage

#

the wording "2% out of 100" is kinda sus tho

devout solar
#

it is

zenith dagger
zenith dagger
#

any help?

gleaming burrow
#

So just 2% of 1/8192?

obtuse pebbleBOT
#

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flat apex
#

Please help. Why it says that R\(closure of Q) is an open set? I'm sure that I've read before that R\Q isn't open set.

warm canopy
#

The closure of Q is closed

#

The complement of a closed set is open

flat apex
#

that makes sense

#

thank you

#

.close

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timid silo
#

So for n = 123, i got either p = 9, 3. p = 3, 10, however I don't understand how 2n = 66, wouldn't 2n = 246 if its multipied by 2?

high lily
#

consider rounding
e.g take 5 as an example

#

sum of its digit is 5,
but 2*5 = 10
which has a digit sum of 1+0 = 1

timid silo
#

so 5 have a digit sum of 5 and 10 has a digit sum of 1?

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

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vestal rose
#

Is there a difference between the two statements? Or is the first one a more compact way of saying the other one?

royal basin
#

there is no difference

vestal rose
#

Yeah I figured, just making sure, I'm learning about math notation

#

Thank you :)

#

.close

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narrow brook
#

Is a tangency point also a point of intersection?
I've always thought of a tangent line as one that 'touches but does not intersect' a curve (or circle, etc.) because for me, 'intersect' seems to imply 'cutting through' or 'crossing'.
But some looking around suggests that tangent lines are said to intersect at one point (the tangency point). Something about that seems very unsatisfying.

severe dune
#

A point of intersection that intersects a circle only once is known as a tangent

#

So all tangents must be intersection

narrow brook
severe dune
#

Yes

#

But the point where it's tangent at is still an intersection

#

As a definition intersection is just the points where 2 functions are equal

narrow brook
#

So I'm wondering, how best to define the tangent line at a point in the case of the curve of a function?

severe dune
#

If you visualise it like this the tangent is cutting through the curve and then cutting back out between a and b as a-> b

#

Point of intersection

#

Because it is

#

Just infinitly small

narrow brook
#

sure, but it seems we can't define the tangent line of a curve at a point as one that intersects the curve at that point (and only that point)

#

We could specify that the gradient of the tangent line and the curve at the tangency point are equal, but then I'm trying to define the derivative in terms of the tangent line. And at the moment the definitions seem circular.

obtuse pebbleBOT
#

@narrow brook Has your question been resolved?

flint sundial
#

because 100/100 x 2=2

obtuse pebbleBOT
#

@narrow brook Has your question been resolved?

high lily
#

I mean that's more or less the limit definition of the derivative

steep harness
#

i.e. if the function is ccu at a particular point, then the tangent line will be less than the value of the function (at least locally) around that point of tangency

narrow brook
#

Thanks, that helps

steep harness
#

this is important especially for things like the tangent line to f(x)=x^3 at x=0, the tangent line graphically is above the function on the left side, but below the function on the right, and so it "crosses" the function, but it stays on the outside of the concavity at all times.

obtuse pebbleBOT
#

@narrow brook Has your question been resolved?

obtuse pebbleBOT
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trail haven
obtuse pebbleBOT
trail haven
#

how would i find x and y

harsh remnant
#

English

trail haven
#

sure

#

The box diagram shows the result from a sample. The sample indicates the number
hours one person slept per night for a period of 15 nights

#

the values ​​in the sample below are given in order of magnitude. Two values ​​have
replaced by x and y, respectively.

harsh remnant
#

Is it related to mean, median, and mode?

trail haven
#

yh think so

harsh remnant
#

So what's the question?

trail haven
#

what is x and y

#

What are the values ​​of x and y? Motivate your answer

harsh remnant
#

x should be 3

#

Do you know why?

trail haven
#

no

#

how did u arrive at that

harsh remnant
#

The numbers listed are the possible/recorded values

trail haven
#

oh nvm yh that makes sense

harsh remnant
#

Yes, nice

trail haven
#

and the y?

trail haven
harsh remnant
#

Not...sure...

trail haven
#

alrighty

obtuse pebbleBOT
#

@trail haven Has your question been resolved?

obtuse pebbleBOT
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obtuse pebbleBOT
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hearty thunder
#

Hey

obtuse pebbleBOT
hearty thunder
#

Im working on long division of polynomials

#

How do i approach a problem like

#

(x^5+1)/x+1

kind hawk
#

well like you would approach any other division of polynomials

#

it may help to write x^5+1 = x^5+0x^4+0x^3+0x^2+0x+1

#

but apart from that just your usual algorithm

hearty thunder
#

This is the first time im dealing with these kinds of problems

#

Can you solve it

#

And maybe a step by step process if you wouldnt mind

#

I just learn better that way

#

Oh my

#

Nvm

obtuse pebbleBOT
#

@hearty thunder Has your question been resolved?

obtuse pebbleBOT
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timid silo
#

Determine where the given function is a linear transformation. If it is, find it’s standard matrix A.

timid silo
#

I’m not sure how to start the problem.

kind hawk
#

what is the definition of a linear transformation?

#

does T satisfy that definition?

timid silo
kind hawk
#

look up the definition in your book/class notes

#

or on the internet

timid silo
kind hawk
#

that is true but not very specific

#

does it get more specific?

timid silo
kind hawk
#

what a shitty book

#

a map $T:\bR^3 \to \bR^3$ is called linear if for all constants $a,b\in\bR$ and all vectors $x,y\in\bR^3$ we have $T(ax+by)=aT(x)+bT(y)$

warm shaleBOT
#

Denascite

kind hawk
#

there is nothing specific about R^3 here, this also works for R^n or in general any vector space

#

sometimes this definition is also seperated into the two conditions that T(x+y)=T(x)+T(y) and T(ax)=aT(x)

timid silo
kind hawk
#

that's included in the vector space axioms

timid silo
kind hawk
#

do you know what a vector space is?

timid silo
# kind hawk do you know what a vector space is?

It’s a space consisting vectors, together with the associative and commutative operation of addition of vectors, and the associative and distributive operation of multiplication of vectors by scalars.

kind hawk
#

and scalar multiplication is also commutative

timid silo
kind hawk
#

well how about you first determine whether T is actually linear

timid silo
kind hawk
#

and why do you think that

timid silo
kind hawk
#

which distributive property

#

R^3 is a vector space

timid silo
kind hawk
#

let $x=(x_1, x_2, x_3), y=(y_1, y_2, y_3)\in\bR^3$ be two vectors. can you calculate $T(x+y)$ and $T(x)+T(y)$ ?

warm shaleBOT
#

Denascite

timid silo
kind hawk
#

no

#

can you tell me what $T(x)=T(x_1, x_2, x_3)$ is?

warm shaleBOT
#

Denascite

timid silo
kind hawk
#

what? I don't understand what you mean

kind hawk
#

I want you to apply this definition to T(x_1, x_2, x_3)

kind hawk
#

that is T(x,y,z).

#

I asked for T(x_1, x_2, x_3)

#

different symbols, same idea

timid silo
kind hawk
#

instead of x you now have x_1, instead of y you now have x_2 and instead of z you now have x_3. that's just renamed. nothing else changed

kind hawk
#

you haven't yet done what I asked for

timid silo
#

X,y,Z

kind hawk
#

no

timid silo
kind hawk
#

T(x_1, x_2, x_3) is not equal to X,y,Z

#

also I don't know why you wrote X and Z in capital letters

timid silo
#

Sorry

timid silo
kind hawk
#

T(x,y,z)=(x,0, -y)
T(x_1, x_2, x_3) = (x_1, 0, -x_2)

#

it's just renaming

timid silo
kind hawk
obtuse pebbleBOT
#

@timid silo Has your question been resolved?

obtuse pebbleBOT
#
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obtuse pebbleBOT
#
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dreamy forge
obtuse pebbleBOT
dreamy forge
#

How do I find the traces of these?

obtuse pebbleBOT
#

@dreamy forge Has your question been resolved?

dreamy forge
#

<@&286206848099549185>

obtuse pebbleBOT
#

@dreamy forge Has your question been resolved?

obtuse pebbleBOT
#

@dreamy forge Has your question been resolved?

slim cove
obtuse pebbleBOT
#

@dreamy forge Has your question been resolved?

dreamy forge
slim cove
#

I looked it up and it seems to just mean the shape of the cross section in this context

#

can you describe what shape z = 2x^2 + y^2 is?

rugged bobcat
#

hello

#

i need help

slim cove
rugged bobcat
#

ok

dreamy forge
#

How would I find the trace

#

I set y=0

#

Then I got z = 2x^2

slim cove
#

yes

#

so what shape is thay

#

that

#

@dreamy forge

dreamy forge
#

Quadratic

dreamy forge
slim cove
#

isn't that just what the answer is

#

quadratic

dreamy forge
#

I got z = 2x^2

slim cove
#

yea

dreamy forge
#

But it’s asking for coordination

#

So I’m confused on that part

slim cove
#

where

dreamy forge
#

Let me send full screen shot

#

Of the problem

dreamy forge
slim cove
#

try z = 2x^2 maybe

dreamy forge
#

got it

#

thanks

slim cove
#

also the yz-plane one is not right

#

awesome 👍

dreamy forge
#

z = y^2

#

.close

obtuse pebbleBOT
#
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timid silo
obtuse pebbleBOT
timid silo
#

Answer is B right?

restive ridge
#

no, why?

timid silo
#

wait

#

it is tho

#

i really think it is

restive ridge
#

ah

timid silo
#

cuz look

restive ridge
#

I didn't read the every seven years part lol

timid silo
#

.92 cuz it goes down 8 percent

#

yea

restive ridge
#

yes B is correct

timid silo
#

so once it fills up to 1

#

okay

#

thank you

#

❤️

#

.close

obtuse pebbleBOT
#
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somber sierra
#

How does g(t+h) = 3(t+h)

obtuse pebbleBOT
main cedar
#

its hard to tell without the full context

#

can you post the original question as well?

#

(also, i think you are asking why g(t+h) = 3(t+h)+6)

somber sierra
#

That’s the question

main cedar
#

i think its a given that g(x)=3x+6

#

like thats just an arbitrary function

fierce lagoon
#

^

#

It states that g(t+h) = 3(t+h)+6

#

That easily means that g(t) = 3t+6

#

And it even states that

somber sierra
#

Oh yeah it does shit.

#

sorry, Im thinking Of other stuff not paying attention looks like

#

Thanks .close

#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
#
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graceful quail
#

Is the period in -3sinx+4 equal to 2pi?

obtuse pebbleBOT
compact shadow
#

Minimal period, yeah

graceful quail
#

Thank you!

#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
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timid silo
#

How do i find the roots

obtuse pebbleBOT
timid silo
#

Of

#

.close

obtuse pebbleBOT
#
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timid silo
#

nah all good

#

.reopen

obtuse pebbleBOT
#

timid silo
#

How do i find the roots of

#

-3x³ - 2x² - 6x - 4

royal basin
#

rational root theorem sounds like it might help

timid silo
#

factorize

#

group first

#

it will be (-3x³ - 2x²)+ (- 6x - 4)

#

find the common factor in each group

#

Ohh okay

#

then factorize again

#

How do i factor again?

compact shadow
#

Factorize the remaining quadratic of it if it can be factorized

timid silo
#

Okay

royal basin
#

may i suggest

#

multiplying the whole thing by -1

#

just to get rid of all the minus signs

obtuse pebbleBOT
#

@timid silo Has your question been resolved?

obtuse pebbleBOT
#
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leaden shoal
#

idk what to do

obtuse pebbleBOT
leaden shoal
royal basin
#

you are wrong about the events' mutual exclusivity and also your abbreviation of the events to "true" and "false" made you mislead yourself

#

these events are NOT mutually exclusive, as the problem clearly states

leaden shoal
#

but

#

90% isnt 80%

royal basin
#

90% ≠ 80% so what?

leaden shoal
#

it doesnt match

#

so its not mutually exclusive

royal basin
#

whether or not the probabilities of two events are equal has NOTHING to do with their mutual exclusivity

leaden shoal
#

ok lets make this clear

#

mutually exclusive means that both events happen simultaneously right?

royal basin
#

no

leaden shoal
#

what?

royal basin
#

mutually exclusive means the events exclude each other

#

mutually exclusive means that if one event happens then the other cannot

leaden shoal
#

oh yes ur right

royal basin
#

mutually exclusive means that the events CANNOT happen simultaneously

leaden shoal
#

i mean non mutually exclusive

royal basin
#

so when you say A you can sometimes mean not-A?

#

is that what you are saying?

leaden shoal
#

no?

#

mutually exclusive means both cannot happen simultaneously

#

non mutually exclusive means both can happen simualtaneously

royal basin
#

mutually exclusive means both cannot happen simultaneously
non mutually exclusive means both can happen simualtaneously

#

yes sure

leaden shoal
#

is that sarcasm

#

i cant tell!

#

so for this its mutually exclusive?

#

u cant pick true and false at the same time

#

actually i think its non mutually exclusive

#

how about the second part

royal basin
#

were it sarcasm i would've marked it as such

#

and also your abbreviation of the events to "true" and "false" made you mislead yourself

leaden shoal
#

ok

#

just to clarify

#

the answer is non mutually exclusive

#

both can happen the same time

#

idk what to do

royal basin
leaden shoal
#

?

#

my attempt

#

i dont understand

#

i need help

#

ok i get it

#

.close

obtuse pebbleBOT
#
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#
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languid vapor
#

Hey

obtuse pebbleBOT
languid vapor
#

If i had an exponential in the form of $a\cdot b^x$

warm shaleBOT
#

PixelWolf

languid vapor
#

What was the name of b and x?

tranquil heart
#

B is base and x is power are u asking this?

obtuse pebbleBOT
#

@languid vapor Has your question been resolved?

obtuse pebbleBOT
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elfin tangle
obtuse pebbleBOT
elfin tangle
#

Im having trouble with this one,

clever nacelle
#

you just do

elfin tangle
#

I did (300,000(1.07))(12)

clever nacelle
#

its 1.07^12

#

compound interest

#

since every year it appreciates 7% so it will be based on the new appreciated value every year

#

so after 1 year it will be 300,000*1.07

elfin tangle
#

so its the 2nd one right

clever nacelle
#

2nd year

timid silo
#

u don't even have to calculate

#

the only one that makes sense is the second one

elfin tangle
clever nacelle
#

2nd year (300,000)*1.07*1.07

elfin tangle
#

just to make sure

clever nacelle
#

use a calculator

elfin tangle
#

i did

#

thank you

#

!

#

.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
#
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spring frost
obtuse pebbleBOT
spring frost
#

is what I did at the bottom correct?

tardy epoch
#

call this w. do you know how to find the equation for w?

spring frost
#

so

#

is it 3, -3

#

or something?

#

I know I need to get one of these as the final answers

tardy epoch
spring frost
tardy epoch
#

vector points to the right/up -> positive sign

#

vector points left/down -> negative sign

spring frost
#

ok

#

so -3. -3?

tardy epoch
#

right

#

you also have to fix your u and v vectors

spring frost
#

yeah so v is 1, 2

#

and u is -1, 1?

tardy epoch
#

nah

#

u points up AND right, so both coordinates should be positive

spring frost
#

yeah

tardy epoch
#

v points left and up so the first coordinate should be negative and second coordinate positive

spring frost
#

sorry I confused v and u

#

yeah so u is 1, 2

#

and v is -1, 1?

tardy epoch
#

right

spring frost
#

ok can you come back in like 5 minutes or something, I think I can figure the rest out

tardy epoch
#

maybe. ping helpers if not

spring frost
#

ok

#

thanks for the help

#

Thanks riemann, I figured it out

#

.close

obtuse pebbleBOT
#
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elfin tangle
obtuse pebbleBOT
elfin tangle
#

How would I do this?

proven zephyr
#

expand first and then simplify 🙂

cerulean tulip
#

use distributive property

#

you can also notice that this is a difference of squares

elfin tangle
#

expanded getsb me 22

#

well like

#

expanded and simplified

cerulean tulip
#

yep

#

thats correct

elfin tangle
#

thank you!

#

.close

obtuse pebbleBOT
#
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kindred oasis
#

@timid silo come here you closed the channel

kindred oasis
#

Basically we know that the sum of their ages is 45

#

And Jim's age is twice Jane's age right?

#

@timid silo

#

Ok. Knowing that you can already find both of their ages. Do you have any ideas on how to do that or I should give you a hint?

#

Correct

#

Yw

#

.close

obtuse pebbleBOT
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elfin tangle
obtuse pebbleBOT
cedar lichen
#

What have you tried?

elfin tangle
#

i tried solving for x and it didnt make any sense

#

and i truly don't know where to start lol

cedar lichen
#

What is a horizontal asymptote?

elfin tangle
#

no clue LOL

cedar lichen
#

You don't know what a horizontal asymptote is? Because that's kind've a prerequisite

elfin tangle
#

it like guides the graph right?

#

like shows where it is on the x axis

#

?

cedar lichen
#

A horizontal asymotote is what the y value approaches when you go infinitely far to the left or right

#

1/x has a horizontal asymptote at 0, for instance, because the function approaches 0 as you go infinitely far in one of the directions

elfin tangle
#

so how would i find the horizontal asymptote for this equation?

#

function*

cedar lichen
#

Well, what does the function approach, if anything, as x gets more and more positive?

elfin tangle
#

i dunno 😭

cedar lichen
#

Plug in values

#

Plug in 10, 100, 1000

#

What does the function look like it does?

#

Does it approach a value?

#

Does it blow up?

elfin tangle
#

when i plug in 1000 i get a math error lol

cedar lichen
#

Is the math error overflow?

elfin tangle
#

wdym?

cedar lichen
#

The number is really fuckin big when you put in 1000, right?

#

You should be able to see that without a calculator

elfin tangle
#

i dont even get a number lol

cedar lichen
#

Because it's too big for the calc to handle

elfin tangle
#

but yes

cedar lichen
#

So clearly, there's no asymptote to the right. It just gets bigger

#

What about to the left?

#

-10, -100, -1000?

elfin tangle
#

im still so confused LOl

oblique sage
#

What number does the graph approach as x app - infinity?

elfin tangle
cedar lichen
#

Maybe we can try something else

oblique sage
#

Plug it into Desmos my guy and see

cedar lichen
#

Whats the asymptote of 3^x

#

3^x by itself

#

Think about the graph of an exponential

elfin tangle
#

idkk 😭

#

what steps

#

do i need to do to get an answer

#

bc these examples arent working for me

heavy beacon
#

@elfin tangle ok look at the graph of e^x-1

#

what part of that graph shows that the graph is approaching a certain value

elfin tangle
#

the like

#

idk how to explain it

heavy beacon
elfin tangle
#

yes its approaching 1,-1

heavy beacon
#

no its approaching the line y=-1

#

not a coordinate

elfin tangle
#

ok wtf im rlly confused now

cedar lichen
#

I would highly suggest reviewing asymptotes. I'm sure you can find plenty of sources online

elfin tangle
#

wait

#

is the answer -7

heavy beacon
#

u see the part of the function where its flat lining but not ever reaching that y value

#

yh y=-7

elfin tangle
#

slay

#

tysm

#

.close

obtuse pebbleBOT
#
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#
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Ask your math question in a clear, concise manner.
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After 15 minutes, feel free to ping <@&286206848099549185>.
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autumn atlas
#

what is the growth rate of V(t) = 50(1.006)^t in percent?

warm shaleBOT
#

The following error occured while calculating:
Error: Undefined function ln

proven zephyr
#

is this exponential growth?

autumn atlas
#

yes

#

would it just be 0.006?

proven zephyr
#

no

hexed agate
#

I mean technically yes?

heavy beacon
#

.6%

hexed agate
#

0.006 is just 0.6%

#

Cos 0.006 * 100% = 0.6%

autumn atlas
#

ok so its 0.6%?

hexed agate
#

Yes

autumn atlas
#

ty

#

if it was exponential decay would it be -%?

#

like 0.950 would be -5%?

proven zephyr
proven zephyr
autumn atlas
#

well its an exponential function

proven zephyr
#

ok idk what's the difference, i give up

autumn atlas
#

.close

obtuse pebbleBOT
#
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Ask your math question in a clear, concise manner.
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static cargo
#

How woudlI go about this problem?

obtuse pebbleBOT
static cargo
#

I found the slope of the line PQ, which is -8/pi

#

so then i did like d/dx 4cosx

thick trail
#

hello

static cargo
#

and i got -4sinx

thick trail
#

can anyone help me

static cargo
#

meaning that -4sinx = -8pi

static cargo
#

But then i got like x = sin^-1(2/pi)

thick trail
#

if x-y=7, xy=39, find x^3-y^3

static cargo
#

whipped

#

go to help 12

thick trail
#

ok

static cargo
#

and ask it

main cedar
static cargo
static cargo
main cedar
#

Do you have access to a calculator?

static cargo
#

I do

#

yes

knotty crow
#

That's it basically, you've found x-coord

static cargo
#

so plug it into the original equation

#

to find the y?

main cedar
#

arcsin(2/pi) is ur x coord

#

The question asks for the x coord

static cargo
#

oh

#

so i had everything?

main cedar
#

Yes

#

FYI csc is not the same as arcsin

static cargo
#

oh what

main cedar
#

Csc is 1/sin while arcsin is the inverse of sin

obtuse pebbleBOT
#

@static cargo Has your question been resolved?

obtuse pebbleBOT
#
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