help-10

[wraith lion]

you would get sin2theta = 1/4

[timid silo]

sin²x+cos²x-2sinxcosx=1/4

i would do that

both ways are ok

imo

[tranquil arch]

$$\begin{aligned}\sin x -\cos x &=\sqrt{2}( \frac{1}{\sqrt{2}} \sin x - \frac{1}{\sqrt{2}} \cos x)\
& = \sqrt{2} (\sin x \cos 45^\circ - \cos x \sin 45 ^\circ)\
&= \sqrt{2} \sin(x-45^\circ )
\end{aligned}$$

[warm shale]

秋水

[wraith lion]

hmm so you force took out sqrt2 and then how do the cos/sin 45s appear?

.close

[obtuse pebble]

Channel closed

Closed by @wraith lion

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wraith lion]

What do I do with the +4x in transformations?

[wraith lion]

this is f(x) btw

I already made a complete the square form

2(x-1)^2 + 5

[frosty river]

Complete-square both of them

not only one. That way you can compare

[wraith lion]

How do you complete-square g(x)

There is no x^2

Should we multiply out again and try?

[radiant mauve]

CALCULATE THE VOLUME OF THE SKETCHED workpiece (dimensions in centimeters) help pls

[frosty river]

Expand (x-1)² then you gave x², x and 1 and you can complete square

[wraith lion]

D: try #help-17

.close

[obtuse pebble]

Channel closed

Closed by @wraith lion

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[acoustic pawn]

is the sum of 2 subspaces U and W of the vectorspace V always a subspace of V?

[kind hawk]

yes

[acoustic pawn]

thanks alot!

.closze

.close

[obtuse pebble]

Channel closed

Closed by @acoustic pawn

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[exotic herald]

is this correct

[nocturne minnow]

Yes

[exotic herald]

ty for verifying : D

.close

[obtuse pebble]

Channel closed

Closed by @exotic herald

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[zenith sky]

hi, i have this limit but i found 2 ways of solving it which give 2 different values and the teachers answer is yet another value

[zenith sky]

this is the first way i tried solving it

and the second is by doing the same but multiplying with (1+ln(x))/(1+ln(x))

[kind hawk]

(x^2-e^2)(x^2+e^2)=x^4-e^4

[zenith sky]

oh

yes

bruh

thanks

.close

[obtuse pebble]

Channel closed

Closed by @zenith sky

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[white spade]

For what s does the integral converge?

The problem I have is that if I want to use the criteria, i will need x to the power of a number bigger than 1, but then s needs to be more than bigger than 2

[obtuse pebble]

@white spade Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[warm shale]

Rœmer
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[obtuse pebble]

Channel closed

Closed due to the original message being deleted

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[half light]

How was equation 9 derived ?

[half light]

I have redrawn this figure on the right to get a better picture of the terms b and theta

Let's just say that I have no problem in equation 8
φ = 4π/λ . bll

And , bll = - b sin (θ – α)

How come did bll = - b [sin(θo – α) + cos(θo – α)(θ - θo)]

[obtuse pebble]

@half light Has your question been resolved?

Channel closed

Closed by @half light

Use .reopen if this was a mistake.

[half light]

.reopen

[obtuse pebble]

✅

[obtuse pebble]

@half light Has your question been resolved?

[obtuse pebble]

@half light Has your question been resolved?

[obtuse pebble]

@half light Has your question been resolved?

[obtuse pebble]

@half light Has your question been resolved?

[obtuse pebble]

Channel closed

Closed by @half light

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[undone hinge]

Hello

[undone hinge]

Hello?

[haughty coyote]

#❓how-to-get-help

[undone hinge]

HEELOOO?

[undone hinge]

Ok

[nocturne minnow]

,rotate

[undone hinge]

Is this correct and also I’m stuck on question B

[undone hinge]

Hello?

Taking a bit long

[obtuse pebble]

@undone hinge Has your question been resolved?

[brave bramble]

Yes that's correct

[undone hinge]

.end

[obtuse pebble]

Channel closed

Closed by @undone hinge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

Any help pls

[grizzled shore]

,rotate

[grizzled shore]

when looking at these "at least x happening" kind of questions

you want to do 1 - P(opposite)

it usually results in less calculations and simpler thinking required

so first you want to consider the chance there is no defects at all

[timid silo]

Ahhhh

Wdym by p(opposite)?

[grizzled shore]

opposite of what you're finding

what you want to find is P(at least 1 defect)

opposite is P(no defects)

P(at least 1 defect) = 1 - P(no defects)

[timid silo]

And what if it said at least 2 defects how would we do that here?

Or we dont have enough info

[grizzled shore]

then we do P(at least 2 defects) = 1 - P(no defects) - P(only 1 defect)

[timid silo]

Ohhh

So how would we calculate no defects?

Kinda confused on that part

[grizzled shore]

ok so fail rate is 0.02 per mm^2

so it's 2% chance for fail per mm^2

so success rate is 98%

98% success rate for 6.4 mm^2 is what?

[timid silo]

The probably it wont have a defect?

But wouldn't that be for 0.02 per mm^2

[grizzled shore]

if there's a 98% chance to succeed for 6.4 tries

the probability it succeeds always is...?

[timid silo]

6.272?

[grizzled shore]

the probability is greater than 1?

[timid silo]

Ohh mb I meant 0.06272

[grizzled shore]

there's a 98% chance for it to work once

there's a 6% chance for it to work 6 times?

you flip a coin, 50% heads

you flip a coin 6 times, how do you calculate the chance of it all being heads

[timid silo]

6×50% right?

[grizzled shore]

so 300% chance to flip 6 heads in a row?

[timid silo]

Wait no

Its just half of 6

So 3 times

[grizzled shore]

what 3 times

[timid silo]

Of getting heads

Out of 6

[grizzled shore]

im asking for a probability here, that means i want either a number from 0 to 1 or 0% to 100%

[timid silo]

Ohhh yeh

[brave ravine]

probablitiy 50 percent

[timid silo]

50%?

[grizzled shore]

what's the probability of flipping 2 heads in a row

[timid silo]

Ohhh I've seen it

0.5^2?

[grizzled shore]

yes

what's the probability of flipping 6 heads in a row

[timid silo]

0.5^6

[grizzled shore]

what's the probability of flipping 6.4 heads in a row

[timid silo]

0.015625

[timid silo]

0.5^6.4

[grizzled shore]

what if flipping heads as a 98% chance instead of 50%

[timid silo]

0.98^6.4

[grizzled shore]

.

there u go

[timid silo]

Ahhhh

Damn that makes sense

So that's the probability of no defects right?

[grizzled shore]

yes

[grizzled shore]

now use this

btw have u learned binomial theorem

[timid silo]

That equation right?

[grizzled shore]

which equation

[timid silo]

For binomial distribution?

[grizzled shore]

yeah

[timid silo]

I dont think they're the same though

[grizzled shore]

oh

not distribution sorry

binomial theorem

[timid silo]

The binomial theorem is that yr1 or 2?

Nah probably not, what is it

[timid silo]

Yeah deffo not learned that 💀

I haven't even done series yet lol

[grizzled shore]

if u had to calculate "at least n defects"

you'd need to use this

[timid silo]

I'll keep it, when I learn it you mind if I come back?

[grizzled shore]

but without learning binomial theorem it's basically impossible to do past "at least 3 defects" or "at most 3 defects"

[timid silo]

Which part of maths is it in, further or yr 2 stats?

[grizzled shore]

u can just open a new channel and ask im sure there will be people to help you

[timid silo]

True yeah

[grizzled shore]

i dont know, it's in combinatorics

[timid silo]

Probably further

Thanks though, really helped

[grizzled shore]

my school called it "counting techniques, probability, combinatorics and permutations"

[hidden remnant]

Hi guys, can i have a quick question?

[grizzled shore]

#❓how-to-get-help

[timid silo]

Yeah I havent seen those in stats, probably further stats

[grizzled shore]

it's not stats

it's probability

[hidden remnant]

It will be quick just question where u can say only yes or no

[grizzled shore]

still use a new channel please

[hidden remnant]

Okay sorry

[timid silo]

Isn't probabilty in stats though?

It's a sub topic I'm pretty sure

[grizzled shore]

they're kinda related

either way it's a very fundamental understanding needed to do a lot of these basic probability stuff

[timid silo]

Yeah I'll have to do the same, thanks

Does anyone know if this is correct?

For ii

[grizzled shore]

,rotate

[grizzled shore]

in terms of exam technique

this is what i would write

v = u + at, u = 5.12m/s, a = -9.81m/s^2, when the water is at its highest point, v = 0.00m/s
0 = 5.12 - 9.81t
9.81t = 5.12
t = 0.52s

with equations being used, value of the variables, clear steps and units everywhere that's needed

you arent wrong but if i was the marker you'd get 1 out of 3 marks

1 loss mark for lack of working out, 1 loss mark for missing units

[timid silo]

What would you do with the 5 seconds though?

[grizzled shore]

also wrong sig figs but you got the answer so you get 1 mark

[timid silo]

Oh yh tru

[grizzled shore]

u dont do anything it says find the time taken

when u are in an exam you dont care about being right, you care about ticking the marker's boxes

so he gives u marks

[timid silo]

So you dont add it onto the time you get?

[grizzled shore]

no

if u needed to the question would when does the water reach its highest point

then you would be counting from t = 0

but this asks how long it takes to reach the top so from when it first starts going up

is there part 3?

[timid silo]

Ahhhh that makes sense

[timid silo]

Nope

[obtuse pebble]

@timid silo Has your question been resolved?

Channel closed

Closed by @ripe heron

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[subtle whale]

Translation
Description: With the graph of a function belongs the following tabel

Question 4: calculate f(1) in the instance f(0)=4
Question 5: take f(2) = 6 and express f(5) in "a".
Question 6: For what value of "a" applies f(2) = f(5)

I've tried doing this myself but with no luck everything else on the practice test was doable but i truly don't understand this set of problems.

[thick oracle]

This looks so much like german

[subtle whale]

Haha it's dutch actually

[thick oracle]

Maybe translate it for us?

[subtle whale]

I have

[thick oracle]

Oh

Yeah

[subtle whale]

I've translated the description and the questions

Above it

[vocal portal]

Hey are you guys active 24/7?

I need someone to help me with multiple choice but at a later date

if anyone can please dm me

[thick oracle]

Yeah we are

[thick oracle]

You can ask the questio here #help-28

Ok?

[vocal portal]

yes that’s perfectly alright.

i think it will be sometime next week

[thick oracle]

Just so you know

[subtle whale]

Mike do you think you understand the set of problems?

[thick oracle]

We cant help you with tests

[vocal portal]

^ yeah that I know it’s homework for a new unit next week

[thick oracle]

Ok

You can ask your question anytime

Read this

#❓how-to-get-help

[thick oracle]

Idk what "in the instance" means

[subtle whale]

in the case of

[vocal portal]

#help

[subtle whale]

why are you doing this here

?

[thick oracle]

I told you to read #❓how-to-get-help

[vocal portal]

sorry

[thick oracle]

Yeah idk how to do it

Sry

But you can ping helpers now, since 15 min have passed

[subtle whale]

<@&286206848099549185> Does anyone know how to do this set of problems?

[summer spire]

oof sorry cant help you, ive never encountered this before

[obtuse pebble]

@subtle whale Has your question been resolved?

[obtuse pebble]

@subtle whale Has your question been resolved?

[thick oracle]

Bro noone understand your problem

Maybe you should google it

[obtuse pebble]

@subtle whale Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[warped cape]

How do you find the quadratic formula for this

[warped cape]

This is the answer but how do you get from the table to the equation

[sacred oak]

the quadratic formula is ax^2+bx+c

[sacred oak]

here is telling you

[warped cape]

Sorry I didn’t mean the quadratic formula I meant exponential

Sorry about that

Exponential Formula

[timid silo]

that's not an exponential

that's a quad

tho

[warped cape]

Oh

[sacred oak]

the values that h(x) gets when x its a certain value

[sacred oak]

if its a quad formula then what i would do its just using this form and just putting the values of x and youll get a system of equations

[timid silo]

or a lagrange interpolation

[sacred oak]

and then just find the values of a b and c

[sacred oak]

yea

[timid silo]

@warped cape what topic exactly is that? Exponential modelling?

Since you mentioned about exponential

[warped cape]

We’re supposed to write an explicit equation for the table

[timid silo]

Well then

Given that it's quadratic and 0 is a root of that

Then it can be represented like h(x) = (x-a)x = x^2 - ax

Now you have only one unknown variable. Put whatever value you want from that table other than 0 and solve it

[warped cape]

But my question is how can I find the equation to plug in the points from the table

[warped cape]

This is the answer to it but I just want to know HOW I get there with just the information on the table

[obtuse pebble]

@warped cape Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sly grotto]

i'm not sure how and where to start solving this :// i'd appreciate some help a lot

[sly grotto]

Topic: Angles Formed by Tangents and Secants

<@&286206848099549185>

help pls huhu

<@&286206848099549185>

[obtuse pebble]

@sly grotto Has your question been resolved?

[sly grotto]

<@&286206848099549185>

[devout solar]

Tf is m

[sly grotto]

ohh m refers to measurement pretty sure

[devout solar]

cool

[sly grotto]

u know how to answer this?

[devout solar]

Ive slept a whole 90min and its a new subject

but seems we use radians yes?

[sly grotto]

nah i think we use degrees

[devout solar]

well

good luck

[sly grotto]

so uh you can't help me? :/

[devout solar]

Nope

But BOC=POA so APD=180-BOC-90

So if you can figure out that angle

Wait

[sly grotto]

hmm

[devout solar]

nvm

my dumbass was trying to change the radius

[sly grotto]

mhm

<@&286206848099549185>

still need help

.close

[obtuse pebble]

Channel closed

Closed by @sly grotto

Use .reopen if this was a mistake.

[sly grotto]

.reopen

[obtuse pebble]

✅

[sly grotto]

<@&286206848099549185>

https://cdn.discordapp.com/attachments/779602052619173898/983570419124666398/Document_79_2.jpg

[timid silo]

told anything about the radius?

[sly grotto]

no i don't think so

[timid silo]

oh ok

[sly grotto]

you got any idea how to solve this?

[timid silo]

I am trying to see

[sly grotto]

aight cool man, appreciate it

anything? @timid silo

[obtuse pebble]

@sly grotto Has your question been resolved?

[crimson horizon]

Since arc BC is 40, you know the measure of angle BOC.
Do you know the relationship between angle BOC and AOD?
After this we'll focus on triangle AOP to find angle APB

Also we know line PA is tangent at the endpoint of the diameter segment AC, so you would know that angle as well

[sly grotto]

ahhh sorry for the late reply, i'm currently in a meeting

[sly grotto]

i understand

i'll get back to you

[crimson horizon]

Gotcha

[obtuse pebble]

@sly grotto Has your question been resolved?

[glossy basalt]

Hello @sly grotto
Do you still need help with your question?

[sly grotto]

oh yes, I still do

I appreciate it a lot!

[glossy basalt]

Okay, so

First 13)

mBC is 40 is it degrees?

[sly grotto]

yep it's in degrees

[glossy basalt]

Okay, and we have to find M∠APB

I would suggest you to take a look that the triangle AOP

Recall, angle sum of triangle = 180°

Got anything nice?

[sly grotto]

uhh sorry, what do you mean?

[sly grotto]

mhm I understand

[glossy basalt]

I mean, I can go through step by step, but I also wanna know did you think of anything

Like in triangle AOP

Got any idea on how to find the 3 angles?

[sly grotto]

some sort of formula or multiplication? i'm not entirely sure

[glossy basalt]

Okay, no problem, let's go through step by step then 😁

[sly grotto]

sure thanks man! I really appreciate this

[glossy basalt]

To find angle APB, the easiest way I think is to consider the angles inside triangle APO

We have 3 (interior)angles in this triangle APO, let's name it A, P and O

P is what we are finding, so let's leave it at the end

A looks good, and recall, PA is a tangent to the circle and AO and a radius of the circle

Ring any bells on what to use now?

Hint: relationship between radius and it's corresponding tangent

[sly grotto]

hmm, is it PO?

I'm not sure, sorry if I get things wrong—I missed a lot of lessons on this topic

wait, it just said that m∠APB is 30°

[glossy basalt]

Oh, it's because it's an "IF"

[sly grotto]

oh, right

[glossy basalt]

For a question, if there are subquestions with if, that means, each subquestion has it own measurement

[sly grotto]

I see, understood

[glossy basalt]

I think rather than tell you the relationship one by one, I would tell you what keywords to search

[glossy basalt]

Google "tangent radius"

[sly grotto]

Okay

This is what showed up

So, what's the next step in solving for m∠APB?

I really need your help, are you still there? @glossy basalt

[glossy basalt]

Okay, I'm back

[glossy basalt]

Do you know what is perpendicular?

[sly grotto]

Lines that intersect which form right angles?

[glossy basalt]

Bingo!

[sly grotto]

Alright cool!

[glossy basalt]

Right angle = 90°

[sly grotto]

AO = 90° from what I've searched

[glossy basalt]

Lemme draw something

[sly grotto]

Aight sure thing

[glossy basalt]

So, from our previous notation,
Angle A=90° (tangent perpendicular to radius)
Angle P (this is what we have to find)
Angle O (we will do it now)

All good till now?

[sly grotto]

Mhm I'm following

[glossy basalt]

Okay, for O
Search "vertically opposite angles"

[sly grotto]

Vertically opposite angles are angles that are opposite one another at a specific vertex and are created by two straight intersecting lines. Vertically opposite angles are equal to each other. These are sometimes called vertical angles.

[glossy basalt]

Yey!

[sly grotto]

Yeah! So what I get from this is that Angle O is also 90°

[glossy basalt]

Nope

[sly grotto]

Oh

Could you guide me as to what's next?

[glossy basalt]

https://www.chilimath.com/wp-content/uploads/2021/11/illustration-of-vertical-angles-v2.png

When there's a cross

The opposite angles will be equal

For angle O, what which angle does it equal to?

[sly grotto]

So angle O is 40° then?

[glossy basalt]

Yep

[sly grotto]

Ah I knew it

[glossy basalt]

So finally, angle P

[sly grotto]

Right

[glossy basalt]

This

[sly grotto]

So, angle P would be 50°

Yessss

[glossy basalt]

Yesssss

Correct!

I think I don't have time to go through all others
But I will give you tips on the questions
14. Use angle A in 13, find O and search (angle on a straight line)
15. Reversed thinking of 14.
16. Use angle A in 13, and angle sum of triangle

Good luck!
@sly grotto

[sly grotto]

Thank you so much man! @glossy basalt Appreciate it very much!

.close

[obtuse pebble]

Channel closed

Closed by @sly grotto

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[leaden shoal]

help

[leaden shoal]

oh im meant to answer it without using desmos

im stuck on deciding which solution i should use

[royal basin]

my screenshot was not intended as giving away the answer anyway

but you may find that you can use it to inform yourself as to which solution you want

also you would have done better to not convert 9/40 into a decimal

but that's just a style thing

[leaden shoal]

why do u mean?

[royal basin]

did you mean why or what

[leaden shoal]

yes what do u mean

[royal basin]

i mean that you would've done better to keep 9/40 as 9/40 as opposed to converting it into a decimal like you did

unless you're deathly allergic to fractions

[leaden shoal]

why?

[royal basin]

fractions are cleaner

[leaden shoal]

i need decimal to plot it on the unit circle

[royal basin]

no you don't

[royal basin]

and what stopped you from labeling that as -9/40?

[leaden shoal]

ok

ill do fractions

[leaden shoal]

but i dont get this

use what to inform myself to use which solution i want

[royal basin]

use my graph

and observe that you want the second positive solution

which corresponds to the lower point on your circle graph

[leaden shoal]

whats a second positive solution?

[royal basin]

do you know what the words "second" and "positive" mean

[leaden shoal]

-1.798 on the graph?

[royal basin]

thank you for not answering my question

i now assume you don't know what the words "second" and "positive" mean

[leaden shoal]

basically the second angle on the graph

[leaden shoal]

yes

tell me

what is a "second positive solution" mean?

[royal basin]

https://en.m.wiktionary.org/wiki/second

https://en.m.wiktionary.org/wiki/positive

[leaden shoal]

so its just the second point of the unit circle

[royal basin]

yes that's what i said

2pi - 1.798 radians

[leaden shoal]

ok

what should i do with 2pi - 1.798

do i isolate t from here?

im stuck

what should i do with 2pi - 1.798?

hey Ann

im curious on why we need the second positive solution and not the first one

<@&286206848099549185>

[obtuse pebble]

@leaden shoal Has your question been resolved?

[timid silo]

cos(x) is an even function, where cos(x) = cos(-x).
So cos(1.79773) = cos(-1.79773) = -0.225 or -9/40

Now it has asked time.
So think which solution will fit here. 1.79773 or -1.79773

[leaden shoal]

yep

hmm so which one

[timid silo]

[leaden shoal]

the negative one

[timid silo]

Interesting that time can be negative

[leaden shoal]

hmm i dont get it

[timid silo]

Like length, time can never be negative

It's just like solving a quadratic formula to find length of something, then you exclude the negative solution because length can never be negative

[leaden shoal]

hmm i dont understand it

this is confusing

[timid silo]

When you take -1.79773 as the answer to calculate the time, it will result negative time. Negative time would essentially mean going backwards in time, which nothing in existence has ever done this (it breaks causality, that is why).
What I'm saying is that there are some things that cannot be negative at all, or else it would break the logic, or is not experimentally observed at all. Have you ever seen something having negative length? It's not possible at all in reality. Same goes for time.

[leaden shoal]

oh ok

[leaden shoal]

but we can rewrite it

[timid silo]

As 2π-1.79773 right

[leaden shoal]

yes

[timid silo]

Check both of them

[leaden shoal]

6.28+1.79

[timid silo]

And see which one of them is right

And once again

[leaden shoal]

yes i have checked it

we checking to see which one is the solution right?

[timid silo]

Please do not change the values like 2π or 9/40 to decimals in calculations
It can give errors

[timid silo]

Yes

You got time

[leaden shoal]

yes

[timid silo]

Two positive solutions

Check which when inputting in the function parameters gives -80

Why is the distance given in "-80cm"

[leaden shoal]

wait

[timid silo]

Displacement can be negative

Distance can never be

[timid silo]

Just check

[leaden shoal]

yes

im double checking

[timid silo]

👍

[leaden shoal]

thanks for assisting btw

[timid silo]

Wlcm

Now

,w calc 40 cos(1.797793) - 71

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Pencil#9129

[timid silo]

There

[leaden shoal]

wait what

[timid silo]

,w calc 40 cos(2π - 1.797793) - 71

[leaden shoal]

why

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Pencil#9129

[timid silo]

Checking

Okay so look

[leaden shoal]

oh this is how u check

i check like this

[timid silo]

Yeah

Well u can keep t as 3/2π × 1.79773

It makes calculations easier

For rechecking purposes

[leaden shoal]

ok im gonna redo the question

from step one

[timid silo]

It's correct

The answers are correct dw

If you look closely

[leaden shoal]

oh its just that its been a while since i did the question and i just wanna do it for recall

if u dont mind

i mean its fine if u dont want me to do it

[timid silo]

It's alright

U can

[leaden shoal]

ok

[timid silo]

👍

[leaden shoal]

:)

[timid silo]

So uh here's how this goes. To frame your answer, use the principal value 1.79773 seconds

Positive because all the stuff I explained earlier ^

Within the cos(2π/3 t) function, t can take any 2nπ±t values

[leaden shoal]

ok

[timid silo]

See this as an example

Wait NVM

See this

,w calc cos(π/6)

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Pencil#9129

[timid silo]

,w calc cos(2π + π/6)

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Pencil#9129

[leaden shoal]

oo

[timid silo]

,w calc cos(4π + π/6)

And so on

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Pencil#9129

[timid silo]

Same for negative

So generalized answer is (2nπ ± theta)

Which is same

For any n

[leaden shoal]

hmm i dont understand

[timid silo]

Cosine is a periodic function

Like sine

So at every interval of 2nπ

It repeats itself

U can check it on a graph

,w graph cos(x)

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Pencil#9129

[timid silo]

See

[leaden shoal]

ow

[timid silo]

Yes

So t = 2π ± 9/40

But

In the box

Write the positive principal value

[leaden shoal]

is it 2πn ± 9/40?

[timid silo]

I just wanted to make you clear the distinction between principal and arbitrary values, and that cosine is periodic

[timid silo]

Yes sorry mb

But

[leaden shoal]

oh ok

[timid silo]

In the answer box

Write only the positive principal value

[leaden shoal]

hmm im not clear

[timid silo]

It's the first answer you get

Okay see

1.79773 is your first answer

[leaden shoal]

yes!

[timid silo]

Likewise -1.79773

[leaden shoal]

mhm

[timid silo]

2π + 1.79773 is your another answer

[leaden shoal]

both is cos(-9/40)

[timid silo]

Likewise 2π - 1.79773

[leaden shoal]

mhm

its either

[timid silo]

At every period of 2π

Cosine like

Repeats itself

Same like sine

[leaden shoal]

one full rotation

[timid silo]

Kind of

Due to that

cos(theta) = cos(2nπ ± theta)

theta is ur principal value here

[leaden shoal]

mhm

[timid silo]

And ± here is only for cosine function since it's an even function

I hope you've understood

In your actual answer in the box

[leaden shoal]

what does even function mean?

[timid silo]

Well

[leaden shoal]

does it mean same amplitude?

[timid silo]

It's a function that satisfies f(-x) = f(x)

No

[leaden shoal]

oh okay i get it

[timid silo]

See this

[leaden shoal]

both has the same value

[timid silo]

,w cos(30°)

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Pencil#9129

[timid silo]

,w cos(-30°)

Yes

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Pencil#9129

[leaden shoal]

mhm

but the sine wont be the same

[timid silo]

Sine is an odd function

Yes

[leaden shoal]

one will be negative and another positive

[timid silo]

f(-x) = -f(x) for any odd function

Like sine

[leaden shoal]

ok

[timid silo]

Keep the properties of sine, cosine and tangent functions clear in mind

They help a lot

[leaden shoal]

yep i have it

[timid silo]

👍

So after all this

What is your final answer of t?

In the box

What will u write

[leaden shoal]

hmm i still dont know how this will help me to distinguish if i should use either -1.7 or 1.7

[timid silo]

Okay see

This is related to Physics actually

You see

Time always moves forward

It can never move backwards

[leaden shoal]

yep i think its positive

[timid silo]

Yes

Negative time

Will actually mean

Moving backwards in time

[leaden shoal]

what if the x variable isnt time and its something else instead

[timid silo]

Which breaks causality

[leaden shoal]

ye breaks the timeline

[timid silo]

Pardon?

[leaden shoal]

hmm ill show you

[timid silo]

Sure

[leaden shoal]

what happens to the second one?

how can we distinguish if negative or positive

[timid silo]

Distance, time, length are always positive

And never negative

Height, distance fall under length

[leaden shoal]

oo

[timid silo]

Which can never be negative

[leaden shoal]

so it never reverses

[timid silo]

Because it doesn't have direction

It's a scalar quantity

[leaden shoal]

negative as in never goes to the left

[timid silo]

It's just not defined

[leaden shoal]

ok

[timid silo]

You distance is x input

So for negative x

It's not defined at all

[leaden shoal]

which output gives positive

gives u the x coordinate of that angle

ok

[timid silo]

So

[leaden shoal]

hmm so i use 1.7 as a solution?

[timid silo]

Yes

[leaden shoal]

but u see

we can write -1.7 as positive

[timid silo]

Absolute value, which results in 1.7 only

[leaden shoal]

-1.7 is going clockwise but we can just write it in anticlockwise

[timid silo]

That would be 2π-1.7

Which is not the principal value

[leaden shoal]

yes

oh yea

it has negative

[timid silo]

Nono

2π-1.7 is positive

But

It's not the principal value

You only consider the principal value

Which is 1.7 seconds

[leaden shoal]

principal value as in orginal value right?

[timid silo]

Yes

[leaden shoal]

ok

[timid silo]

Basically "your first answer" in informal terms

[leaden shoal]

ok

hmm so what should i do with 1.7 now?

[timid silo]

arccos(-9/40) has solutions -1.7 and 1.7 too

Regarding to your question asked

It will be 1.7 only (you discard -1.7)

Just want to make clear

[leaden shoal]

ok

[timid silo]

Yes

Just calculate t

[leaden shoal]

ok

[timid silo]

Yes now

What was asked again

Nearest to tenth of a second right

[leaden shoal]

yes

0.9?

[timid silo]

Yes

[leaden shoal]

0.9 time after

hmm its wrong

why?

[timid silo]

Weird

[leaden shoal]

the answer is this

i just dont understand why they wanted the second positive solution

help me

i've been stuck on this question for hours

[timid silo]

I apologise for not correctly helping you out...
I also don't really know why, I suspect it must be due to the derivative, but I'm also not really sure.
Derivative (of this function) at 0.9 is negative, while at 2.1 is positive and so on
But I suggest you to clarify this with someone else...

Sorry once again

[leaden shoal]

ok i got it

https://youtu.be/kpvYVICDQAw

this video helps alot

[leaden shoal]

its fine

[timid silo]

Ah I see it asked what's the time taken when it goes all the way down from its peak and rises back up to 80 cm from her hand

Hence the second positive solution

[leaden shoal]

yep

[summer spire]

@leaden shoal do you still need a question answered?

[leaden shoal]

sure

actually nvm its fine

but thanks for asking

.close

[obtuse pebble]

Channel closed

Closed by @leaden shoal

Use .reopen if this was a mistake.

[leaden shoal]

sorry for the ping

[summer spire]

no worries

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[polar socket]

If I'm finding the average value using integration and the integration requires substitution do I still need to recalculate the bounds like I would in a normal substitution problem? none of my practice questions had us redo the bounds so I just wanna confirm

[summer spire]

you dont have to recalculate the bounds

if you use the original equation again

[polar socket]

ah okay, thank you!

.close

[obtuse pebble]

Channel closed

Closed by @polar socket

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[devout lark]

.open

[devout lark]

can someone help me with this

I got a final today and smoked through the review

but this one stumped me

ping if u respond cause this servers deep in my folders

[fierce lagoon]

Use power theorem

Tangent-secant one

$$9(9+2r) = 16^2$$

[warm shale]

Umbraleviathan

[fierce lagoon]

@devout lark

[devout lark]

ok

so 16 squared is equal to 9 squared plus 2r?

ok

i got it

.close

[obtuse pebble]

Channel closed

Closed by @devout lark

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[reef loom]

The figure shows three circles of centers O, P, and Q, each tangent to the others at points A, B and C, as indicated. The diameter AD of the circle of center O touches the circle of center Q at E. The radii of the circles of center O and center P measure 1 and 2/3, respectively. What is the radius of the circle of center Q? (A) 1/5 (B) 6/25 (C) 7/25 (D) 8/25 (E) 9/25

[reef loom]

i tried many things

but i cant progress here

does someone have any idea of what path should i try to use? (preferably, don't write the answer, I still want to try)

(sorry for my english btw, im not an american)

[steep harness]

this is interesting. here's a question that might help: what is the largest circle you could make in the space outside circle P but inside circle O?

[reef loom]

hmmmmmm

would be the circle Q

or

an another circle

like Q

[steep harness]

Q has an extra restriction on it, making it smaller

right now we're solving an easier problem to then modify into the desired problem

[reef loom]

whats Q restriction?

theres a bigger circle than Q?

[steep harness]

It is tangent to AD at point E

[reef loom]

OOHHH

true

[steep harness]

if we think logically, the biggest possible circle will have a center somewhere on AD, right?

[reef loom]

yes

[steep harness]

because any shift off will squeeze it smaller

[reef loom]

yeah

ok, makes sense until now

[steep harness]

if we can find that biggest possible circle, then start shifting it until it becomes tangent with AD, we'll have found our answer. I have no idea if that's easy to do, but it might give you some ideas

[reef loom]

hmmmmmmm

[reef loom]

but how could i know the size it might get after shifting?

theres like, a formula for it?

[reef loom]

by eye, i would guess 7/25

[steep harness]

there might be, I don't have any idea, We would have to build it ourselves

[reef loom]

but i have no proof of it

[reef loom]

thinking

[steep harness]

that's the fun part of math: formulas aren't just already invented things to memorize, sometimes we have to make our own to do what we want

I seem to remember some facts about angles of lines that pass through the center of a circle and some other point within it. I'm not sure if this is the right direction at all

[obtuse pebble]

@reef loom Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[warm frigate]

Hey ive been struggling a lot with this question

so what i did was

this is what i got up to so far

can someone check if this is even right

=close

.close

[obtuse pebble]

Channel closed

Closed by @warm frigate

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[heady zenith]

My physics professor just wrote this in the recorded video and I don't know why, I do understand the integral of a conservative vector field, however, I do not know what steps did he take to reach this part

[heady zenith]

$-df = \vec{F}.d\vec{r}$

[warm shale]

Sir Isaac

[heady zenith]

f is the potential
F vector is the force vector

I especially don't get the - sign

I'll be gone working on other problems in the meantime

[sage iron]

dot product of force and displacement is just work right

[heady zenith]

Yes

And the vector field here is conservative

[sage iron]

so if the field is doing work it will lose potential energy I think
that's why df is negative

[robust sleet]

Because kinetic energy will rise

Potential will fall

[heady zenith]

The question in the worksheet we have, state this problem as purely mathematical

So I'm not exactly sure

But if the field is conservative, the work will only depend on the end point

[robust sleet]

Begin and end point

[heady zenith]

The notation is a bit different, because this is in French system

But

V in the book is f is the American system

[heady zenith]

Yeah right

[robust sleet]

What u need help with

[heady zenith]

Part b, the professor just started with this expression and solved for f

I don't get from where did he get it

I know this

But I don't know how to solve it without endpoints

[tardy epoch]

,rotate

[tardy epoch]

look in your book for the definition of conservative vector field

[heady zenith]

There's and I understand it

[tardy epoch]

then what are you stuck on

[heady zenith]

Professor just brought this equation out of thin air, and I don't get how did he get here

[tardy epoch]

that physics notation is garbage

https://mathinsight.org/conservative_vector_field_determine

Should be $\grad f = \mathbf{F}$

[warm shale]

riemann

[heady zenith]

Where did the dr go

[tardy epoch]

You don't need it

[tardy epoch]

.

[heady zenith]

Yeah, French system

Thank you @tardy epoch, you really cleared it up to me

[tardy epoch]

.close to free up the channel

[heady zenith]

Yep

.close

[obtuse pebble]

Channel closed

Closed by @heady zenith

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[final sky]

does this work?

[supple basin]

Can someone help me?

2 miles in 10 min or 5km in 20 min math question

[pallid flame]

um? you’re gonna be multiplying by values pretty close to just i as n increases

since i - 1/i^2 -> i

so it’s not gonna stay below 1

did you mean 1 - 1/i^2? @final sky

just use induction

prod (i^2 - 1)/i^2

[final sky]

Hm...

wait what

Oh

Bruh

im stupid

hold on

$\prod_{i=2}^{n}1-\frac {1}{i^{2}} \implies \frac {n+1}{2n}$

[warm shale]

Javaan T aka Lil Plum

[final sky]

There we go.

[pallid flame]

$\prod_{i=2}^{n}1-\frac {1}{i^{2}} = \frac {n+1}{2n}$

[warm shale]

jnmwn

[final sky]

indeed

[pallid flame]

$\prod_{i=2}^{n}\frac {i^2 - 1}{i^{2}} = \frac {n+1}{2n}$

[warm shale]

jnmwn

[final sky]

true true

[pallid flame]

assume it’s true for n, then prove it’s true for n+1

using induction

then verify the base case n=2

[final sky]

so hold on...

(i+1)(i-1)
————
i²

[pallid flame]

assuming $$\prod_{i=2}^{n}1-\frac {1}{i^{2}} = \frac {n+1}{2n}$$
prove $$\prod_{i=2}^{n+1}1-\frac {1}{i^{2}} = \frac {(n+1)+1}{2(n+1)}$$

[warm shale]

jnmwn

[final sky]

Alright let's see this

[pallid flame]

that’s all u need to prove

and verify that n=2 gives (2+1)/2(2)

[final sky]

$1-\frac {1}{4}\
\
(1-\frac {1}{2})(1+\frac {1}{2})\
\
(\frac {1}{2})(\frac {3}{2})\
\
\frac {3}{4}$

[warm shale]

Javaan T aka Lil Plum

[final sky]

yeah that's about it

alright, thanks!

.close

[obtuse pebble]

Channel closed

Closed by @final sky

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hardy holly]

Hi!! i need help with an exercise i saw yesterday in classes

[obtuse pebble]

@hardy holly Has your question been resolved?

[hardy holly]

<@&286206848099549185>

[alpine raven]

hmm if f € Θ(g) then a|g(n)| <= |f(n)| <= b|g(n)| with a,b>0, right ?

[hardy holly]

yes yes

[alpine raven]

h(n) = min{f(n), g(n)}

[hardy holly]

Yeah i was trying that

But tbh i'm pretty bad for this class ahaha so idk what to do next... i don't want it like "solved" and that, i wanna understand it ahhaha

[alpine raven]

hmm we have f(n) >= a*g(n)

a is a positive value

[hardy holly]

yes yes

[alpine raven]

im trying to find a way to express h

[hardy holly]

yeah yeah i wait hehhe, btw the statement can be false too

[alpine raven]

true

but i want to see both cases

[hardy holly]

oke oke

[hexed agate]

@alpine raven Kabuto is that you?

[alpine raven]

who is kabuto

f(n) >= a*g(n), if a>=1, then f(n) is greater than g(n), but if 0<a<1, i cant see how to compare them

[hardy holly]

hey @alpine raven

if f € Θ(g) then g € Θ(f) (i can show that), and i can also prove that | f € Θ(g) ^ g € Θ(h) --> f € Θ(h)

i know the answer is there but i can't seem to connect those two ideas ahahha

let me think it a bit more

let h be max {f,g} maybe?=

[alpine raven]

but they said h = min{f,g} right ?

[hardy holly]

ah ye ye

but i can do like k = max{f,g} and replace h by min{f,g}

h is not really important like

as a concept

[alpine raven]

wdym

[hardy holly]

what i'm trying to prove is that doesn't matter which one is the min , the other one will be either one in the max

[alpine raven]

hmm ok try it

[hardy holly]

ye let me give it a go ahaha

but still if you find someth i'll be thankful too u.u

[alpine raven]

👍

[hexed agate]

Naruto character

https://c.tenor.com/F1AJC13e1-QAAAAM/naruto-shippuden-anime.gif

https://c.tenor.com/-nxrWjUdXRYAAAAM/anime-kabuto-yakushi.gif

[hardy holly]

oh so i get this right herels

idk if im right

[hardy holly]

i know that if f € Θ(g) then g € Θ(f)

also, trivially, f € Θ(f) and g € Θ(g)

doesn't that mean i have all cases and problem is solved?

considering i have to show min{f,g} € Θ(max{f,g})

[obtuse pebble]

@hardy holly Has your question been resolved?

[obtuse pebble]

Channel closed

Closed by @hardy holly

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[reef loom]

The figure shows three circles of centers O, P, and Q, each tangent to the others at points A, B and C, as indicated. The diameter AD of the circle of center O touches the circle of center Q at E. The radii of the circles of center O and center P measure 1 and 2/3, respectively. What is the radius of the circle of center Q?

(A) 1/5 (B) 6/25 (C) 7/25 (D) 8/25 (E) 9/25

[reef loom]

My first thought was to make a triangle like this:

and them do:

PQ = 2/3+x
QE = x

PE^2= PQ^2-QE^2
PE^2= (2/3+x)^2 - (x)^2
PE^2= (x)^2+(2x(2/3))+(2/3)^2 - (x)^2

them a got that PE must be -1/3 and by here i think things started falling apart

if the base of PQE is truly -1/3, then we have

(2/3+x)^2-(1/3)^2=x^2

and from this: x=-1/4

totally wrong, i mean, even if it was positive, theres still no option of 1/4

[obtuse pebble]

@reef loom Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cerulean heart]

Why am I getting #9 wrong? What’s wrong with my work?

[nocturne minnow]

,rotate

[obtuse pebble]

@cerulean heart Has your question been resolved?

[cerulean heart]

<@&286206848099549185>

[obtuse pebble]

@cerulean heart Has your question been resolved?

[cerulean heart]

<@&286206848099549185> anyone able to take a look? It’s a line integral