help-10

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rough ibex]

If I have lets say number 3421(a) and number 38384837173(b) how to I find the smallest number divisible by b by progression of a+67

[rough ibex]

so I need to check if a+(n*67) is divisible by b while n can be any number, but I wanna avoid this looping method

is there a more efficient mathematical way or formula to achieve this?

[obtuse pebble]

@rough ibex Has your question been resolved?

[turbid wing]

yes

(2b-a)/67 = n

or no wait

I am confused

uh

[rough ibex]

(b-a)/67=n worked in some cases

let me take real numbers

[turbid wing]

the smallest natural number divisble by b should be 2b

This is for a program right?

@rough ibex

[rough ibex]

yes

[turbid wing]

what language are you using?

[rough ibex]

curently i do a loop, adding 67 constantly to the number untill its divisible, which is super slow

@turbid wing C#

[turbid wing]

Can I get the exact question?

[rough ibex]

well its an decoding issue. I get a word, and each letter is associated to the number depending on the position. which is computed like index in the alphabet * position of the letter multiplied by the pattern(which is 2,2,4,8,16,32 etc)

so if its l and the position is 5th, it will be 12 * 16 which is 192

and encoded letter is 192 mod 67

which is 58

now i need to decode reversely @turbid wing

[drifting wraith]

@rough ibexadd b instead

when it's 4 mod 67 stop

because 3421 is 4 mod 67

it only takes 8 steps in this case

[rough ibex]

what I did previously is add b if b>a, but then stop and continue adding 67

so i should stop when its 4 mod 67?

why 4?

[drifting wraith]

well we kinda want it to be 3421 mod 67

[rough ibex]

ye but it can be any number

b will most definitely be more than a billion

[drifting wraith]

i don't know what you mean

[rough ibex]

it canbe like b = 2.3 million and a can be like 12

[drifting wraith]

like i know it's not pretty but it probably works

yeah

so?

we increment by b, so it's always divisible by b

mod 67 it needs to be a

[rough ibex]

so keep adding b and check if mod 67 equals a and if so stop, thats what u mean?

[drifting wraith]

a mod 67 instead of a when necessary

yes

like it should take 67 steps at worst, which seems acceptable

[rough ibex]

yes that would be perfect

let me try

[drifting wraith]

|| spoilered for no reason
step = b = 38384837173
a = 3421
target = a % 67
while b % 67 != target:
b += step
||

[rough ibex]

you mean a+=step no?

at the end

[drifting wraith]

no b

b is divisible by b at the start

we just keep it that way

that's all

[rough ibex]

ok but when b%67 = target, then whats my actual result?

[drifting wraith]

b

[rough ibex]

ah

i think i get it

@drifting wraith You are a damn genius

[drifting wraith]

no u

[rough ibex]

speed reduced by 98 percent

i mean increased sorry

lol

thank you bud

How do I close this channel so its available again?

[drifting wraith]

.close

[rough ibex]

.close

[obtuse pebble]

Channel closed

Closed by @rough ibex

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[royal cargo]

hey, can (tantheta)^2 be (1/cos^2-1)?

[shell wind]

What is the exact problem

[royal cargo]

il solving rhs rn

i did lhs

[shell wind]

ok, do you know what m^2 - n^2 algebraic identity

[royal cargo]

nvmm i got it

i can take it common

[shell wind]

ok, cool

[royal cargo]

tyy tho

im gonna close this

.close

[obtuse pebble]

Channel closed

Closed by @royal cargo

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[high flint]

Can someone help me with a log question?

[obtuse pebble]

Please don't occupy multiple help channels.

[high flint]

$p^{c * log_{\frac{1}{p}}n} = \frac{n}{n^{c}}$

[warm shale]

kaw4

[high flint]

Can someone help me understand why this is the case? When I try to compute this I get:

$p^{c * log_{\frac{1}{p}}n} = \frac{1}{n^{c}}$

[teal prawn]

your previous one was was correct

[warm shale]

kaw4

[high flint]

ah.

[teal prawn]

yeah this

[high flint]

Interesting, because I am seeing the n /n^c one given in a solution to a question that I am studying and I'm not sure why:

[shell wind]

You already have a #help-6 to yourself, if u are using this one please close the other channel

[teal prawn]

odd

[high flint]

sorry, I forgot about that channel as the question has not been answered, I will close the other

[shell wind]

np

[high flint]

Looking at it again, it must be 1/n^c as if it were n/n^c then n*n / n^c would be 1/n^c-2, am I correct?

[teal prawn]

$n \cdot p^{c \cdot \log_{\frac{1}{p}}{n}} = \frac{n}{n^{c}} = \frac{1}{n^{c - 1}} \le \frac{1}{n}$ for $c \ge 2$

[high flint]

yep

so the screenshot must be incorrect

[warm shale]

kinglacto

[teal prawn]

yeah but the final step is correct

[high flint]

gotcha, thanks!

.close

[obtuse pebble]

Channel closed

Closed by @high flint

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[balmy torrent]

Need help with this one

I only know that a,b,c,d cannot be the same number as the other numbers

[somber mural]

that is wrong

[balmy torrent]

and that there is no fraction

ok correct me

[somber mural]

you are correct saying that there is no fraction because natural numbers are integers greater than 0

[balmy torrent]

wait the question or what i know

[somber mural]

however no mode means that there isn't 1 number that appears more times than the others

c is between 5 and 6 and it is ordered

so c has to be either 5 or 6

[balmy torrent]

wait what

so 2 numbers that repeats means no mode?

[somber mural]

it means that there is more than 1 number that appears the same number of times

so 5 could appear twice and 6 could appear twice

[balmy torrent]

ooh ok

a is 1 right?

or 2

[somber mural]

for no mode, all numbers must appear exact same amount of times

so 2 must appear same number of times at 5 as well as 6 as well as 9

[balmy torrent]

ooh right

[somber mural]

so what are a,b,c,d?

[balmy torrent]

hold on let me check

i got -33

[somber mural]

correct

[balmy torrent]

damn

so u just check one by one?

no faster way then

alright thanks dude

[somber mural]

yeah ig

[balmy torrent]

.close

[obtuse pebble]

Channel closed

Closed by @balmy torrent

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

I need help. What test statistic should be use in this problem:

The Head of the Mathematics Department announced that the mean score of Grade 11 students in the second periodical test in Statistics was 89, and the standard deviation was 12. One student believed that the mean score was less than this, randomly selected 34 students, computed their mean score, and obtained a mean score of 85. At 0.01 level of significance, test the student’s belief

[timid silo]

I think it's z-statistic but Central Limit Theorem could also be used

<@&286206848099549185>

[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

@timid silo Has your question been resolved?

[timid silo]

.close

[obtuse pebble]

Channel closed

Closed by @jaunty bobcat

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[untold trout]

I'm trying to prove this question:

[untold trout]

I've solved it using GM-HM inequality

However, on AoPS, I see an alternative solution using Jensen's Inequality, and it looks like this:

I have 3 questions regarding this solution,
(1) Why can f(x) be in the form of \sqrt{x^3}{x^3+abc} when x=a is regarded as a variable, while abc can be regarded as a constant when clearly a depends on the value of x?
(2) f is not even concave, is it?

(3) Jensen's Inequality is

then it should follow:

but in the solution above, it is stated: (a flipped version of the above inequality, which doesn't make sense)

It'd be much appreciated if you can answer any of the three questions, I'm trying to understand why the solution drastically deviates from my everyday mathematical thinking, thank you!

additional note: in (2), changing the "a" within f(x) to "x" makes the function concave, but then the problem described in (1) is even less justified; is it just a typo in the solution?

[obtuse pebble]

@untold trout Has your question been resolved?

[untold trout]

<@&286206848099549185>

[obtuse pebble]

@untold trout Has your question been resolved?

[obtuse pebble]

@untold trout Has your question been resolved?

[remote dragon]

Yes I'm sure there is a typo because it just looks bizzare to me that for a concave function f(a+b+c/3)≥3sigma f(a/3). By the graph you can observe if you take any three points and then form a triangle with them. When you locate the centroid you'll get a proof for that identity and that is the opposite of what it is given in the solution.

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[zenith yarrow]

Can I use the limit comparison test on a series if b sub n is smaller than a sub n?

[zenith yarrow]

For example 13x/(2^x-20) would be a sub n

would b sub n be fine if I used x/2^x for b sub n?

like taking the series from n=1 to infinity the integral test is out of the window since it isn't continuous and positive from n=1 to infinity

[tardy epoch]

What is the series here. You wrote functions of x

[zenith yarrow]

summation of x>oo starting from x=1 of 13x/(2^x-20)

[obtuse pebble]

@zenith yarrow Has your question been resolved?

[obtuse pebble]

@zenith yarrow Has your question been resolved?

[tardy epoch]

Your notation is all over the place. You said a sub n and b sub n

Comparison test with your suggestion is fine if you know how to do the integral

[zenith yarrow]

yeah because for limit comparison test you'd have two series being a sub n and b sub n

[tardy epoch]

That's just a definition. You have to apply it appropriately to your problem

[zenith yarrow]

applying it here would entail b sub n being similar to a sub n at least in the highest degree of the terms right?

[tardy epoch]

Ugh no that's not my point

[zenith yarrow]

idfk then brah

[tardy epoch]

Your series doesn't have any n variables

It has x as a variable

[zenith yarrow]

alright a sub x then and b sub x

i was doing another problem where they use n instead so i just got stuck on that

[tardy epoch]

Why isn't x/2^x continuous on [1, infinity)

[zenith yarrow]

it is

[tardy epoch]

So why can't you use it here?

[zenith yarrow]

as the b sub n part of the limit comparison test?

I was concerned because it's smaller than a sub n

[tardy epoch]

Then you picked the wrong function to compare to

Pick a similar function that's larger

Comparing a series that's smaller then the original series converges does not imply anything about the convergence of the original series

Similarly comparing a series that's larger than the original series diverges does not imply anything about the divergence of the original series

It's like comparing any series to 0+0+0+...

Or any series with sum n

[zenith yarrow]

That's what I was thinking too but my professor didn't state anything about b sub n having to be larger or smaller than the function you use for a sub n in a limit comparison test

Only in direct comparison did she state that it has to be smaller than a converging series or larger than a diverging series etc

[tardy epoch]

Read the comparison test statement here
https://tutorial.math.lamar.edu/classes/calcii/SeriesCompTest.aspx

And the Limit comparison test near the bottom

You probably don't need to read the proofs

[zenith yarrow]

Oh shit so yeah you don't have to have one function be larger or smaller than the other one

sec I'm gonna try something

[zenith yarrow]

alright i figured it out

thanks for your help :)

.close

[obtuse pebble]

Channel closed

Closed by @zenith yarrow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[normal drift]

If you put the $100 on a +100 odds side of a bet, and hedge it with $50 on a -100 event in another app, you make $50 profit guaranteed

[obtuse pebble]

Channel closed

Closed due to the original message being deleted

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[low patrol]

What can we do with $\sum_{j = 0,2,4}e^{\frac{2\pi i j}{6}}$?

[warm shale]

mns

[indigo blade]

write it in polar form

[kind hawk]

multiply by $e^{\frac{2\pi i 2}{6}}$

[warm shale]

Denascite

[kind hawk]

and note that you get the same sum back

[obtuse pebble]

@low patrol Has your question been resolved?

Channel closed

Closed by @low patrol

Use .reopen if this was a mistake.

[low patrol]

thanks

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[restive pilot]

hello I need to that 68431101 and 1875638303 arent quadratic numbers

[restive pilot]

the tip I given was to look at them with mod 4 and mod 8

[obtuse pebble]

@restive pilot Has your question been resolved?

[restive pilot]

<@&286206848099549185>

[timid silo]

see that every square number has limited mod 4's

and mod 8's

[timid silo]

write out the possible mod 4's for square numbers

[restive pilot]

my questions rather is, why is that enough?

[timid silo]

wym?

[restive pilot]

like I play a little bit with mod 4 or 8 but what does that proof

sadly we didnt do a task like these in our trainings

[timid silo]

what is all the possible values for a square number in mod 4

[obtuse pebble]

@restive pilot Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[high flint]

Can someone help me understand where the 1 is coming from as annotated in the following screenshot?

[obtuse pebble]

@high flint Has your question been resolved?

[obtuse pebble]

@high flint Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[woeful fossil]

so basically i need help understanding polynomial division because the process becomes pretty damn grueling after putting in the first factor correctly

[nocturne minnow]

Google can help pretty well

[woeful fossil]

true but its explained alot differently on google then it was explained to me in class

so its sort of conflicting

and thats where im stuck

[nocturne minnow]

If your teacher taught it a specific way, then ask your teacher for assistance

It's not like we can read yours and your teacher's mind and know how they taught it

[woeful fossil]

eh ur right i cant blame you

teachers dont answer my emails so i aint really have much options

[nocturne minnow]

Do you not school in person?

[woeful fossil]

not since last friday

[fierce lagoon]

Well there's some ways

Usually I would break terms up

But that's grueling to show on latex, let alone me being on mobile

What you can do is this

$\frac{4x^3 -11x^2-6x+9}{x^2-2x-3}$

[warm shale]

Umbraleviathan

[fierce lagoon]

So you have this

And you're gonna have to be patient with me because I'm on mobile

But you can think, "hey, it takes 4x • x^2 to get to 4x^3"

So if I do a bit of math

$\frac{4x^3 + (-8x^2 - 3x^2) + (-12x + 6x) + 9}{x^2-2x-3}$

[warm shale]

Umbraleviathan

[fierce lagoon]

And if I do a bit of rearranging

[valid crown]

You familiar with Horner method?

[fierce lagoon]

$\frac{4x^3 + (8x^2) + (-12x)}{x^2-2x-3} + \frac{4x^3 + (- 3x^2) + (-6x) + 9}{x^2-2x-3}$

[woeful fossil]

nope

[fierce lagoon]

I hate everything

[warm shale]

Umbraleviathan

[valid crown]

try watching first YT video

[fierce lagoon]

$4x^2 + \frac{(- 3x^2) + (-6x) + 9}{x^2-2x-3}$

[valid crown]

takes 3mins

[woeful fossil]

i just need a better method to keep it organized ill try that

[fierce lagoon]

Shit like that

Except you do it to every time and you just gotta be able to organize it

Also I fucketh dip

Fucked yo

Up

[warm shale]

Umbraleviathan

[fierce lagoon]

There shouldn't be a 4x^3 in the second fraction

[woeful fossil]

didnt help that my teacher also made mistakes and expected us to find them

[fierce lagoon]

Atcually this works out nicely

That's just 4x^2 - 3

[nocturne minnow]

It's probably not part of their curriculum which makes it mainly pointless, for now

[fierce lagoon]

Lemme try to show the steps

Again

How do I do the align thing

Because if I space it out, the fractions tend to like blend lol

[valid crown]

when I learned about tactoring polynomials the first way was Horner method

[nocturne minnow]

Everyone's curriculum is different. I never learned this

[valid crown]

I don't see anything besides guessing the solution

[woeful fossil]

i was taught with this box method thing which was fairly easy until i got to dividing polynomials

[fierce lagoon]

$\frac{4x^3 -11x^2-6x+9}{x^2-2x-3}$

$\frac{4x^3 + (-8x^2 - 3x^2) + (-12x + 6x) + 9}{x^2-2x-3}$

$\frac{4x^3 + (8x^2) + (-12x)}{x^2-2x-3} + \frac{(- 3x^2) + (-6x) + 9}{x^2-2x-3}$

$4x^2 + \frac{(- 3x^2) + (-6x) + 9}{x^2-2x-3}$

$4x^2 - 3$

[warm shale]

Umbraleviathan

[fierce lagoon]

Dear god that is messy

Hopefully it's readable

[nocturne minnow]

$$\frac{4x^3 -11x^2-6x+9}{x^2-2x-3}$$

$$\frac{4x^3 + (-8x^2 - 3x^2) + (-12x + 6x) + 9}{x^2-2x-3}$$

$$\frac{4x^3 + (8x^2) + (-12x)}{x^2-2x-3} + \frac{(- 3x^2) + (6x) + 9}{x^2-2x-3}$$

$$4x^2 + \frac{(- 3x^2) + (6x) + 9}{x^2-2x-3}$$

$$4x^2 - 3$$

Does that help?

[fierce lagoon]

Shit sign error

[valid crown]

Box method seems to be Horner method

as I recall

[fierce lagoon]

Yeah but it should be 6x not -6x in the 3rd and 4th line

That's my bad lol

The 3rd line still has -6 lol

[warm shale]

dldh06

[fierce lagoon]

Lmao there

[fierce lagoon]

@woeful fossil does this make sense at least

The box method can be like

Really grueling

[woeful fossil]

hold on

so it makes sense up to a point

im unsure if the answers i got from answering other problems are just the simplified version of the answer you got

[fierce lagoon]

Uh

What did you get for the first one

4x^2-3 is uh

Uhhh

$(2x-\sqrt{3})(2x+\sqrt{3})$

[warm shale]

Umbraleviathan

[valid crown]

btw you can allways use brute force and first solve it with quadruple/cubic/quadratic formula BUT if the polynomial is of degree 5 or you know that it will produce non zero remainder then it WON'T work

[woeful fossil]

and the answer was x^2-9= (x-3)(x+3)(x-2)(x+2)

and thats where im conflicted about why he puts it back into factored form because any other answer i give him is wrong

[fierce lagoon]

Oh that's a different problem

[fierce lagoon]

I was doing this one in here

But you would do the same process

Either use box or break up terms

[fierce lagoon]

Just follow the same stuff I did here

You might have to do it multiple times though

I'll brb

[woeful fossil]

i see

okay i think i understand

thanks yall 👍

.close

[obtuse pebble]

Channel closed

Closed by @woeful fossil

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[slow cairn]

It should be the latter right?

[timid silo]

if it has a unique solution then that is the only solution. If there is a free variable then there are infinitely many

[slow cairn]

Yep, so if I have no free variables then I will get the non trival answer, which is a unique solution and only unique right?

[obtuse pebble]

Channel closed

Closed due to the original message being deleted

[slow cairn]

.close

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dreamy oasis]

can anyone help?

[obtuse pebble]

@dreamy oasis Has your question been resolved?

[dreamy oasis]

<@&286206848099549185>

[obtuse pebble]

@dreamy oasis Has your question been resolved?

[dreamy oasis]

<@&286206848099549185>

[obtuse pebble]

@dreamy oasis Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[safe saffron]

Can someone help me with this one

[safe saffron]

,rotate

[obtuse pebble]

@safe saffron Has your question been resolved?

[safe saffron]

<@&286206848099549185>

[silk geode]

please tell us what you tried

[solid gate]

4.3.2 try using Thales's theorem

[safe saffron]

I dont even know where to begin

[obtuse pebble]

@safe saffron Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[opaque flicker]

heya

[opaque flicker]

could i please have help with this question

i dont even know where to start with the fractional exponent

[reef grotto]

i'd simplify the inside first

[opaque flicker]

kk

[reef grotto]

just think about it as $\frac{a}{a^3}\times \frac{b^3}{b}$

[warm shale]

Asagao 朝顔

[opaque flicker]

hmm

what do i do with the fractional exponent thing

[reef grotto]

first simplify the inside

[opaque flicker]

its like b squared over a squared right?

[mental ferry]

you can convert exponent 1/2 to a square root when you're done simplifying the inside

[reef grotto]

$a^{-2} \times b^2$

[opaque flicker]

uhhh

[warm shale]

Asagao 朝顔

[opaque flicker]

this gets more complicated

hm

[reef grotto]

$(a^{-2} \times b^2)^{\frac{1}{2}}$

[warm shale]

Asagao 朝顔

[reef grotto]

ok

so basically this is equivalent to

[opaque flicker]

why is a to the negative squared?

ahh because you used the top a

i see now

and you cancel the bottom of the fraction?

[reef grotto]

$(a^{-2})^{\frac{1}{2}} \times (b^2)^{\frac{1}{2}}$

[warm shale]

Asagao 朝顔

[reef grotto]

you multiply the exponents

[opaque flicker]

kk, i havent dealt much with fractional exponents

[reef grotto]

which leaves $a^{-1}\times b$

[warm shale]

Asagao 朝顔

[reef grotto]

which is b/a

[opaque flicker]

woah

i am confuzzled

[reef grotto]

the properties of exponents still work with fractional exponents

[opaque flicker]

so how would i go about something simple like 2 to the 1/2

[reef grotto]

that is equivalent to square root of 2

[opaque flicker]

wait

i seeeeeeee

[reef grotto]

think of it this way

[opaque flicker]

why does this equal b over a?

[reef grotto]

square root undoes squares

and it makes sense

because 2/2 is 1

[opaque flicker]

OH I DIDNT KNOW THAT

sorry im not very good at this stuff

[opaque flicker]

haha

[reef grotto]

2*(1/2) is 1

so yeah

[reef grotto]

a^(-1) is just 1/a

${\displaystyle b^{-n}={\frac {1}{b^{n}}}}$

[warm shale]

Asagao 朝顔

[opaque flicker]

oh, didnt know that one either

thank you so so so so much

for help wiht this

[reef grotto]

btw a^(1/b) is same thing as bth root of a

[opaque flicker]

whats bth

o mb

[reef grotto]

hold on

${\displaystyle {\sqrt[{n}]{x}}=\displaystyle x^{\frac {1}{n}}}$

[warm shale]

Asagao 朝顔

[reef grotto]

ok

there

[opaque flicker]

kk gtg to dinner now

i will look over this again soon

thanks so much

[reef grotto]

yw

[opaque flicker]

.close

[obtuse pebble]

Channel closed

Closed by @opaque flicker

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[neon cliff]

https://cdn.discordapp.com/attachments/359052581022203914/978177050034716692/unknown.png

[neon cliff]

help

[mental ferry]

where are you stuck

[neon cliff]

literally whole activity

[mental ferry]

fair enough

first we need to determine what the hypotenuse, adjacent and opposite sides are

[neon cliff]

hmm

[mental ferry]

hypotenuse is always opposite to the right angle, so h=13

the adjacent side to the colored angle is the one on the right so a=12

the opposite side is the bottom one, so o=5

now just put the numbers in the six formulae

sine = o/h = 5/13

[neon cliff]

ah

[mental ferry]

that's it unless I missed something

[neon cliff]

yea yea, thanks mate

[mental ferry]

np

[neon cliff]

.close

how do i

[obtuse pebble]

Channel closed

Closed by @neon cliff

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[desert summit]

Could someone teach me how to draw faces in a graphing calculator? Emojis to be specific

[obtuse pebble]

@desert summit Has your question been resolved?

[azure dagger]

[obtuse pebble]

@desert summit Has your question been resolved?

Channel closed

Closed by @desert summit

Use .reopen if this was a mistake.

[desert summit]

Figured it out

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[static patio]

how to find sum of this series

i see that i can use taylor series of cosx

but i dont know how to get rid of 4^n

[royal basin]

4^n x^(2n) = (2x)^(2n)

[static patio]

got it, thanks

[compact shadow]

(4x^2)sin(4x^2)/4x+cos(4x^2)=xsin(4x^2)+cos(4x^2)

[royal basin]

is it tho

[compact shadow]

No

My bad

[royal basin]

the terms are x^(2n)/(2n)! not x^(2n)/n!

[compact shadow]

Yeah

[obtuse pebble]

@static patio Has your question been resolved?

Channel closed

Closed by @static patio

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stone merlin]

How do you solve this question? ,Here is my thought process:

im stuck from here

[obtuse pebble]

@stone merlin Has your question been resolved?

[obtuse pebble]

@stone merlin Has your question been resolved?

[forest sinew]

@stone merlin made any progress

still around?

[obtuse pebble]

@stone merlin Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[primal kettle]

can i do this

[kind hawk]

no

[primal kettle]

thankyou

.close

[obtuse pebble]

Channel closed

Closed by @primal kettle

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stone merlin]

.reopen

[stone merlin]

How do you solve this question? ,Here is my thought process:

[obtuse pebble]

@stone merlin Has your question been resolved?

[obtuse pebble]

@stone merlin Has your question been resolved?

[obtuse pebble]

@stone merlin Has your question been resolved?

[obtuse pebble]

@stone merlin Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[strong nebula]

how come I can simplify 2x/x^2 to 2/x but cant do
2x/(x^4) +4

[strong nebula]

= 2/x+4

one x on top and 2 x on bottom and cross it out

[nocturne minnow]

No

Read #❓how-to-get-help

No

[nocturne minnow]

How would you get this?

[nocturne minnow]

Also, please format using parentheses

[strong nebula]

Correction, im trying to simply this -> 2x/(x^2) +4

[nocturne minnow]

Because $\verb|2/x+4|$ looks like $\frac{2}{x} +4$

[warm shale]

dldh06

[strong nebula]

and I simplified it to 2/(x+4)

[nocturne minnow]

Because of the plus sign. Addition and multiplication act differently

[strong nebula]

if the +4 was *4 would it be ok in that instance?

[nocturne minnow]

If it was $\frac{2x}{4x}$, you can divide by x

[warm shale]

dldh06

[nocturne minnow]

Because $\frac{2x}{x^2} = \frac{2}{x} \cdot \frac{x}{x}$

[warm shale]

dldh06

[nocturne minnow]

While \frac{2x}{x^2+4}$, you can't break it up

[warm shale]

A random bird

[strong nebula]

alright

.close

[obtuse pebble]

Channel closed

Closed by @strong nebula

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed by @tough light

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[humble umbra]

Did I perform the distributive and associative law correctly?

[civic zealot]

the 3 should be on the sum with u_n, not v_n
and the 1/N should also distribute to the sum of v_n

I don't know if you already did the simplification, but you should also have 1/N(sum 5/8)

[humble umbra]

Okay

I definitely don’t follow.

I will need to think on this. I feel like I understood the laws, but not how to actually apply them.

[civic zealot]

how would you distribute 1/N into (3u-1/2v+5/8)?

[humble umbra]

Can I multiply the 1/N into the numbers inside the parentheses?

[civic zealot]

yep

[tardy epoch]

I love learning about the math of eagles

[humble umbra]

It’s actually a R cookbook

[humble umbra]

Noted

I’ll do that

[tardy epoch]

Oh nice.

[humble umbra]

I lied, it’s a lint eagles. I just didn’t want to admit it

[humble umbra]

What’s the next move? Can I keep the parentheses? Or is it no longer necessary

[obtuse pebble]

@humble umbra Has your question been resolved?

Channel closed

Closed by @humble umbra

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

I will send my work because I got stuck

this is my work for the end, I think this is where I am messing up but idk where

I have never been good with tan, sin, sin, cos, etc lol

help pls lmao

The first thing I see is tan of pi/3 isn’t 0

yeah when I put it into the calc thats wehat it said

I figured it was wrong lol

Otherwise it looks fine integration wise

i just don't know how to find tan and sin

any ideas with that

Unit circle or calculator

the calc said tan was 0 tho

which i figured was wrong like you said

Is it set to radians

[timid silo]

ok nvm it doesn't say 0 but, for tan (pi/3) it says 1.7... some more numbers but I don't think I can have my answer like that

Sqrt(3) and -sqrt(3) is what you want. Memorizing the unit circle would be immensely helpful for trig integrals

[timid silo]

what I want in terms of the answer?

like is that what ur saying

Yeah sqrt(3) is the same as the 1.7…

where am I going to find this with the unit circle

unless I just dont know how to read one

So you see the radians and degrees right?

yes

like the inner circle right

not the numbers on the outside

Well you can see pi/3 correspond to the ordered pair (1/2, sqrt3/2)

you said it was sqrt of 3, but wouldn't it be sqrt 3/2

Well tan=sin/cos so we get tan= (sqrt(3)/2)/(1/2)=sqrt(3)

alright that part makes sense

so what about -8sin(-pi/3) and 8sin(pi/3)

Pi/3 corresponds to?

its what you just showed mne right

okay yeah so sqrt pi/2

or is it 1/2

how do you know which one lol

It’s sqrt(3)/2. Cos corresponds to the x component sin corresponds to the y component

ahhh I see, so how wouldI incorporate the -8

-8(sin(-pi/3)-sin(pi/3)) but you may have gotten your interval swapped let me see

Yeah your integral should be from -pi/3 to pi/3 which is an easy fix

wait are u sure

alright I think I got it now

thank you

.close

[obtuse pebble]

Channel closed

Closed by @fair swift

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[low lava]

so the problem is to give the particular solution of: dy/dt = e^(y) / y given initial condition y=2 when t=0. Integrating both sides wrt y, the right side by parts, i get t= e^(-y) [1-y] +k where k is a constant. Plugging in i get t-e^(-2)= e^(-y) [1-y] however the solutions in my book gives 3e^(-2) -t= e^(-y) [1-y] as the particular solution. Confusingly, both seem right plugging in for y=2 when t=0 so idk what mistake i've made. Hope i didn't screw up the write up lol

[low lava]

so i'm mildly confused lol

[obtuse pebble]

@low lava Has your question been resolved?

[golden ibex]

satoshi is a liar

he didnt create bitcoin

[low lava]

😢

[tardy epoch]

Can you take a screenshot of the original question

[low lava]

ye sure, one sec

Q2, vi

not a screen shot but whatever ig

<@&286206848099549185>

[tardy epoch]

,rotate

[tardy epoch]

,w integral xe^-x dx

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by riemann#2529

[tardy epoch]

you have a sign error on your antiderivative

[low lava]

ah ok tysm

.close

[obtuse pebble]

Channel closed

Closed by @low lava

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[undone dome]

In this question where i subbed values of x in. am i allowed to do that out of nowhere just by looking at it in the answer

or is there any way of deducing the substitution

thats the above part the question is referring to when differentiating

[civic zealot]

yes. They're asking you what that summation is when x=6/25

[undone dome]

oh i didn't look at it like that when i was doing it. Thanks

.close

[obtuse pebble]

Channel closed

Closed by @undone dome

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[patent shell]

How can I do the second integral of (a)?

[patent shell]

is ∫ß(x) dx = sgn(x)?

[obtuse pebble]

@patent shell Has your question been resolved?

[patent shell]

<@&286206848099549185>

.close

[obtuse pebble]

Channel closed

Closed by @patent shell

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ruby schooner]

would it be between steps 3 and 4 or steps 4 and 5?

[ruby schooner]

.close

[obtuse pebble]

Channel closed

Closed by @ruby schooner

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fiery prawn]

Hi! Kindof a weird question. I'm justwondering what learning path I should take to be able to understand this? Calculus, Trigonometry, Linear Algebra, something else?

Thank you so much for any insight!

[fiery prawn]

Oh I'm sorry I was writing this before it became occupied. I'm leaving

[strong vale]

u occupied it lmao

see your name is on the channel

[reef grotto]

calculus

this is differential equations

[tardy epoch]

depends on your background

calculus and at the same time linear algebra, then ODEs

[strong vale]

i think a full DE course

requires calc 3

which is multivariable calc

[fiery prawn]

ODEs?

I didn't know there was such thing as a course dedicated to Differential equations

(trying to figure out what ODE is) ... This is from a paper on DSP / Audio synthesis

Ok so, calc 3 is something to shoot for then, eh?

My only background is College Algebra and pre-calc

[brave bramble]

You can ODE before calc 3, imo. But you'll at least want integral calculus.

[fiery prawn]

Very cool. Thank you so much for your help

what is ODE though?

oh, Ordinary DE

Have a great day! That's all I needed !

.close

[obtuse pebble]

Channel closed

Closed by @fiery prawn

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[keen bough]

Hey, im working on circle geometry in grade 9, how do i solve this?

[keen bough]

Question 20

[pine sail]

For (a) use inscribed angle theorem.

Once you're done with that, use angle sum to find CAB for (b)

[keen bough]

i forgot the inscribed angle thing

im so confused ngl

[pine sail]

Google “inscribed angle”

[keen bough]

where is central angle on picture

[pine sail]

Assuming C is the centre, it is FCE.

[keen bough]

what is inscribed angle theorum?

[pine sail]

It says any angle inscribed by any arc in a circle is the half of the central angle.

[keen bough]

So what would the answer be?

[pine sail]

And why can't you figure it out for yourself after what I told you?

You aren't even trying.

[keen bough]

Can you just walk me through the steps

[pine sail]

I just did.

[keen bough]

This unit makes zero sense

I’m fail my test tomorrow no lie

can u try explain again?

.close

[obtuse pebble]

Channel closed

Closed by @keen bough

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[worn yacht]

what should i learn before sin, cos and tan and common values of the unit circle?

[pine sail]

Pythagorean theorem.

Then you're good to go.

And similar triangles maybe.

[worn yacht]

I know Pythagorean theorem but I'm still having a bit of trouble?

[pine sail]

With?

[worn yacht]

Common values of the unit circle

I have no clue what the guy is saying in the video

[pine sail]

I see.

Try some other video.

[worn yacht]

ive tried a lot of videos already

like look at this one

https://www.youtube.com/watch?v=V5ArB_GFGYQ

[pine sail]

Yeah I knew you'd be watching this.

[worn yacht]

@pine sail should i find this hard to understand?

[worn yacht]

LOL

[pine sail]

There are no shoulds, it depends on you and I can't say anything without actually knowing much.

However, what grade are you in?

[worn yacht]

8 but i do 9 math

and sometimes 10 math

[pine sail]

Well, what exactly is hard to follow? You may always mention that, and someone in this server will help you with that particularly.

I think, with a few things cleared up, you'd be able to do this nicely.

[worn yacht]

ok so firstly how is pi/6 the same as 30 degrees?

[pine sail]

Do you know pi radians is the same as 180 degrees?

Radian is how you measure angles if you have arc length and radius.

[worn yacht]

no I didnt

so why is the 6 there than?

[pine sail]

If you can swallow pi radians = 180 degrees then it's easy to follow.

Divide both sides by 6.

You get pi/6 = 30 degrees.

[worn yacht]

oh

one last thing I kind of don't understand the coordinates of unit circle like he said 45 degrees is the coordinate of the screenshot I sent

[pine sail]

What do you mean?

[worn yacht]

here is the screenshot

[worn yacht]

I just didnt send the screenshot sry

[pine sail]

Yes.

So 45 degrees on a circle as you can see in the figure.

The coordinates of that point are (x,y) which would be horizontal distance from y-axis and vertical distance from x-axis.

You can verify this using isosceles triangle.

[worn yacht]

why is it square route then

[pine sail]

Since a right angle triangle with one angle 45 degrees is isosceles.

[pine sail]

You have a right angled triangle.

Which is isosceles

The hypotenuse is 1.

(radius)

Use Pythagorean theorem.

You'll get exactly that.

[worn yacht]

oh

thank you

you are so helpfull

https://tenor.com/view/byee-byeee-gif-24785079

https://tenor.com/view/you-are-literally-the-nicest-person-you-are-so-nice-freaked-out-hughie-campbell-jack-quaid-gif-15588419

https://tenor.com/view/thanks-thank-you-gif-20870035

I really appreciate it

.close

[obtuse pebble]

Channel closed

Closed by @worn yacht

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[split notch]

help

[split notch]

<@&286206848099549185>

[floral canopy]

Hi

You need to eliminate one variable

let start with I:
from the first equation you can simplify and get that y = 4-2x
plug it in the second equation and you get: x+(4-2x)=3
therefor 4-x = 3, x = 1.

[runic flume]

You can just add the equations

[floral canopy]

they said substitution method

[runic flume]

I am blind nvm

[tardy epoch]

what do you need help with

[obtuse pebble]

@split notch Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[eager fulcrum]

If X is increased by 25% then by what percent is x^2 increased?

[tardy epoch]

Try it with numbers

[obtuse pebble]

@eager fulcrum Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vast wren]

Find the quadratic polynomial P(x) where P(P(x)) = x^4 + 2 x^3 + 12 x^2 + 11 x + 35

[royal basin]

@vast wren have you made any progress so far?

[obtuse pebble]

@vast wren Has your question been resolved?

[royal basin]

well i guess that's a no.

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[real haven]

helloo can someone help me with letter c? i'm already done with the approximation i'm just confused on how i can show on the graph since the graph looks like this...

[light sand]

Hi

[light sand]

Oh idk this

[frozen willow]

Riemann sum problem?

[real haven]

this is what i've got so far

[real haven]

yes

[real haven]

our teacher told us to put rectangles in the the graph but idk how since the graph is like this

i just wanna know how to put the rectangles in like this one

[frozen willow]

How did you do the last 2? Did you use the left, right, or midpoint?

[real haven]

i used all three

and we were just asked to answer one so i only did letter c but that's what we were taught, we used all three in our lectures

[vast wren]

I tried using P(x) = ax^2+bx+c and found that a=1 (it’s pretty obv), but other than that, the number of equations I got is kinda overwhelming lol

but what if a=b=1

c=5

[royal basin]

...right, we should probably move to a different channel now since this one is taken

[obtuse pebble]

@real haven Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

Why is this a removable discontinuity?

I thought it would be unremovable discontinuity

[scarlet locust]

no, it's non removable if the limit didn't exist

but since the limit is 4, it is removable

[timid silo]

Ah i thought it would be Unremovable when RHS =/= LHS

@scarlet locust and you can only redefine a function when it's a removable discontinuity right?

Like this for example

[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

Hey there, guys. I have a pretty strange question, which i've been trying to answer myself for the past few days. So to calculate fixed-rate (and compounded monthly), monthly mortgage payments, you need to use this formula (pic below, got that from wikipedia "Fixed-rate mortgage" page). My question is: what do the numerator and denominator represent? My guess is that denominator is APY for the whole mortgage period (N), but why is the numerator divided by APY? And if the numerator is APY, why is it keeping the principal (1 is not subtracted) and multiplied by monthly interest rate (or APR/12) (the r in this case) Is this some form of ratio i don't quite understand? (thank you in advance)
And i am aware, that there are simpler formulas, but this question just bothers me too much

[timid silo]

c = monthly payment amount
Po = principal amount (the loan amount you got)
r = monthly interest rate (APR / 12)
N = number of payments in months

[obtuse pebble]

@timid silo Has your question been resolved?

[timid silo]

<@&286206848099549185> Since nobody took a shot, do you guys have any idea?

[obtuse pebble]

@timid silo Has your question been resolved?

[timid silo]

It might have something to do with the loan constant and/or discount factor

[obtuse pebble]

@timid silo Has your question been resolved?

[timid silo]

<@&286206848099549185> Guys?

r*(1+r)^N looks like total amount of interest + compounding payed for the whole period of N as a value of Po, but it isn't a % nor a value, since multiplying Po by it does nothing

[timid silo]

Maybe discount rate has effect here too

[forest sinew]

oh no one helped

why are people so afraid of older channels

[forest sinew]

do you mean the variables?

[timid silo]

Did i say variables?)

[forest sinew]

no 😦

i mean when you say represent

what do you mean represent

like its probable that the formula is a solution to a difference equation and the top and bottom dont mean anything in particular but ill have to check

yea, it i-

its just a solution to a recursive difference equation

[timid silo]

they should mean something.. like you could explain them?

the top / bottom part?

[forest sinew]

the derivation is on the wikipedia page you mentioned

[timid silo]

sure, seen it, so i guess you can't explain this formula by parts then

[forest sinew]

well they might not really mean anything on their own

[timid silo]

ouch

[forest sinew]

or at least not in the way that would be satisfying like youre saying

ouch?

[timid silo]

the problem was, that they packed so much info in them (compounding / interest rate / loan period etc), that i thought this simplification could be explained as a simple thing divided by thing kinda way

Like there were some mortgage terms i didn't know

[forest sinew]

if you feel okay with algebra you might be able to track the derivation yourself

looks like the most complicated thing is a geometric progression

[timid silo]

sure, but there is no direct explanation to the formula then

[forest sinew]

[timid silo]

Thank you very much though

[forest sinew]

sure

you should try out the derivation it might make it make sense

[timid silo]

Could've spent months trying to find the explanation xD

the derivation makes sense sure

[forest sinew]

well there are things you can do

well there are things i would try because of what makes sense to me

like nondimensionalizing

lol

but thats not like

[timid silo]

Sounds like a difficult word xD

[forest sinew]

theres no assurance itll be helpful to someone else

and nondimensionalizing usually helps like

helps get at fundamental pieces that control behavior

and might not mean anything specific or maybe will

idk

its not helpful here probably

[timid silo]

guess i'll just review the detivation

thank you one more time, you are my saviour ahahah :D

.close

[obtuse pebble]

Channel closed

Closed by @inner hawk

Use .reopen if this was a mistake.

[forest sinew]

i feel like i didnt really help

but

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

(iii)

Only-

101:341?
Well, I should use, A¹/A²= (L¹/L²)², is it?

I can't read anything on the image.

[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[shut island]

Just send the problem dude. And only in one channel

[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[median moon]

Hello smart folks, I had a question. Im stuck in this question which says "Show 2 ways to decide the intersection point for line 1 and line 2" I found the first one but not the second way to do so

[high lily]

graphically

[median moon]

they dont accept that way

is there any other way

[high lily]

elimination instead of substitution

though since y was already isolated the work is pretty much the same after 2 lines

[median moon]

so do you multiply the second equation with -4?

then x is gonna become negative

[high lily]

you could just subtract your equations immediately

[median moon]

what is it that im subtracting then

[high lily]

the equations

[median moon]

you mean the x's?

[high lily]

I mean the equations

[median moon]

i swear to god i dont understand if u cant show it

[high lily]

LHS of first equation - LHS of second equation = RHS of first equation - RHS of second equation

[median moon]

isnt that the subtraction method

[high lily]

it's classified under elimination

"ways" is also very vague

[median moon]

can you show it with numbers, somehow...?

[high lily]

look up solving system of equations using elimination

[median moon]

sure i will

[obtuse pebble]

@median moon Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wide orchid]

how to integrate sinx^3 dx?

[obtuse pebble]

@wide orchid Has your question been resolved?

[wide orchid]

<@&286206848099549185>

[tardy epoch]

Use sine squared equals 1 minus cosine squared and then u sub

[wide orchid]

uh, wouldn't it make more sense to use a trigonometric identity here?
i mean, i don't know how to sub yet :(

[tardy epoch]

Try it

[tardy epoch]

This is a trig identity

[obtuse pebble]

@wide orchid Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[plush minnow]

I'm trying to help my friend's older cousin with coding, but we're stuck on the math exercise I need to code.
Does anyone know what this "4" is for? Or how to solve this overall? Would've been easy if it's a fraction, but doesn't seem like a that and it has some conditions for it.

[plush minnow]

x², at -2 <= x < 2
4, at x < -2 or x >= 2
(translation)

I assume it means that 4 is the solution when the conditions for x are not met, but I don't know.

[pallid flame]

“the conditions” what conditions?

[plush minnow]

^

[pallid flame]

it has its own conditions so there’s no general “the conditions”

x², at -2 <= x < 2
4, at x < -2 or x >= 2

you can very clearly see its own conditions

[plush minnow]

Yeah. Well, not sure. Just assumed that, no idea what it means. Do you know how to solve that?

[pallid flame]

if -2 <= x and x < 2, then x^2

else if x < -2 or x >= 2, then 4

that’s all it means

[plush minnow]

Oh. So my guess was right. Alright, thanks!

[pallid flame]

np

[plush minnow]

❤️

.close

[obtuse pebble]

Channel closed

Closed by @plush minnow

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[split marsh]

Hello, I really am struggling on this problem on my homework. Here’s the question: Voter turnout rates in Texas local elections are normally distributed with a mean of 36%. If 95% of the turnout rates are between 30 and 42 percent, what is
the standard deviation for this data?

[tardy epoch]

do you know the formula for the confidence interval

[split marsh]

The confidence interval is 95%? Or is that not right ?

[obtuse pebble]

@split marsh Has your question been resolved?

[split marsh]

<@&286206848099549185>

[limber quartz]

Did you try to use the confidence interval formula like Rieman said?

[split marsh]

Is the confidence interval not 95? Or is it through an equation

[tardy epoch]

equation of the form $[\mu - a \cdot\sigma, \mu + a \cdot \sigma]$

[warm shale]

riemann

[tardy epoch]

You get a from knowing that it's a 95% confidence interval

Then you get $\sigma$ from knowing mean and turnout rates

[warm shale]

riemann

[split marsh]

Okay give me a sec I’m trying to wrap my head around all this. Thank you for helping me too I appreciate it

[limber quartz]

All the formulas I have seen for CI's involve n. Is a alpha here or something else?

[tardy epoch]

30 seconds in:
https://www.youtube.com/watch?v=sJyZ9vRhP7o

[limber quartz]

a= z/sqrt(n) ?

[keen wadi]

Oh god…

[split marsh]

Is the answer just 3?

Or did I miss something lol

[limber quartz]

@tardy epoch what is a in this formula?

[limber quartz]

^ ? How do you deal with not knowing n?

@tardy epoch

[limber quartz]

?

[tardy epoch]

watch the video