help-10

[wide oriole]

<@&286206848099549185>

[obtuse pebble]

@wide oriole Has your question been resolved?

[warm canopy]

You are not asking any questions

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[slender osprey]

I need to find the distance between Q and P. Not sure how to find it with only one number.

[nocturne sun]

I'm not sure about the proof, we aren't given that at school, but

$$\frac{OP}{ON} = \frac{OQ}{OM} = \frac{OP}{MN}$$

[warm shale]

Doggo

[nocturne sun]

assuming QP and MN are parallel

[slender osprey]

And you did use the correct lettering? I just want to make sure since this is the first time I've seen this equation.

@nocturne sun

[nocturne sun]

I think so yeah

I'm gonna check my book just to make sure

can't find the page atm

oh nvm found it

[versed turret]

Notice they are similar triangles

And the scale factor is 2

[slender osprey]

I have done a small bit of scale factoring and I have absolutely no clue what im doing

(ignore my unusual name. I'm pranking a friend)

[slender osprey]

please go further into detail. I'm new to scale factors and to the single number sided triangles.

Please do ping me when you respond. Still doing work.

if ABD is the triangle, wouldn't it be 180* or 360*? since they end up connecting on all sides. (D is 46 degrees while B is 38)

@nocturne sun you still active?

[versed turret]

The triangles are similar, meaning the ratio of their corresponding sides are all the same.

So ON/OP = OM/OQ = MN/QP

Notice that ON is twice the length of OP, so ON/OP = 2

Thus, MN/QP = 2 ⟹ QP = MN/2 = 14.4/2 = 7.2

[obtuse pebble]

@slender osprey Has your question been resolved?

[slender osprey]

ty for the original question answered.

[slender osprey]

.close

[obtuse pebble]

Channel closed

Closed by @slender osprey

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[real pebble]

Hey, im struggling with a part of a springs question that is linked to dynamics

[real pebble]

this is the whole question shown

i dont have a clue where to start

[solar trellis]

Consider the forces acting on the ball

But ignore the weight... they should have said that in the question

[real pebble]

yeah, it isnt stated anywhere, just need to derive it all out

the forces would be the F=ma and F=-kx correct?

[real pebble]

^

[solar trellis]

a as in acceleration?

Or in S(k,a)

[real pebble]

yeah newtons second law

so acceleration

[solar trellis]

What does this a refer to?

@real pebble

[real pebble]

just the system i think

im not entirely sure if i need it

[solar trellis]

Let's call acceleration x'' (2nd derivative of x) for consistent naming

[real pebble]

this is the info for the first part

might be useful

ive managerd to workout this part, but its the 2) i havent and in the first i didnt use th S(k,a) stuff

[real pebble]

yeah and -kx being the first derivation of x

[solar trellis]

mx'' isn't a force acting on the ball

Its the result of forces acting on the ball

[real pebble]

yeah, so far ive gotten that ma''=-kx

rearranging would give x''+k/m*x=0 as the final part right?

[solar trellis]

Yes

Usually k refers to the spring constant

[real pebble]

so from this, would i need to do a homogeneous 2nd order ODE to figure out the rest?

[solar trellis]

Yes..

is there an expression for the spring constant in terms of k and a?

[real pebble]

for this module, we use fuck all numbers lol

[solar trellis]

Because I think a should be relevant somewhere

[real pebble]

we've literally only needed to derive the expressions for each unless we are provided with numbers to use

that is the whole question

been given no numbers and only been told to derive the expressions

[solar trellis]

I actually gtg now, hopefully someone else will continue this and help you

[real pebble]

ah okay, np

thanks anyways, think i know what ive got to do now that i can use the second order ODE for it

just stuff i needed to revise for an exam, so no rush really,

.close

[obtuse pebble]

Channel closed

Closed by @real pebble

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stiff bear]

Quick question am I allowed to cross multiple this “1” out it’s the only way I found to get rid of it and don’t know if I am allowed to do so

[silver python]

not quite

[twin sapphire]

well you added a multiplication out of nowhere so no

[silver python]

its not allowed no, the only simplification you can do is turn that sin/cos =tan theta then it would be 1-tan

[obtuse pebble]

@stiff bear Has your question been resolved?

Channel closed

Closed by @stiff bear

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[shell pine]

the apothem is 13.8 correct?

[timid silo]

,w 8 sqrt(3)

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by CatHashira#5213

[timid silo]

Approximately yes

But that approximation is not needed

Area = $\frac{2a}{\sqrt{3}}3a$

[warm shale]

Pi Creature

[timid silo]

this is the general formula where a is the apothem

For a hexagon

[obtuse pebble]

@shell pine Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[shell pine]

@timid silo

its wrong

[rancid dust]

do you need help with this

hints below

||you want to split this into 6 equilateral triangles||

||each equilateral triangle is congruent to the next||

||the area of an equilateral triangle is s^2 * sqrt(3) / 4||

[shell pine]

i did it

but

its wrong

and i dont know why

i did this

and got 665.895643283

[timid silo]

U inputted the wrong value lol

U gave 665.5 rather than 665.8

[shell pine]

what

https://cdn.discordapp.com/attachments/903430332324405288/976671357146374154/unknown.png

its wrong

[timid silo]

,w (16*sqrt(3)) / sqrt(3) * 3 * 8 * sqrt(3)

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by CatHashira#5213

[timid silo]

It's 665.10....

[shell pine]

yes ik

if ik the sides for a hexagon can i just do x times 6

to get my aswer

[timid silo]

That's not all

That's a part

[shell pine]

so x times 6 then what

[timid silo]

then use the formul area = 0.5a s

Where s is the perimeter or 6x

And 6*0.5 turns into a 3

Which I simplified in the formula

[shell pine]

whats a

sides?

[timid silo]

No 8*sqrt(3)

[shell pine]

what if i only know the side

[timid silo]

Then ig u can calculate the apothem as well

Btw is the last problem solved?

[shell pine]

yes

[timid silo]

Nice

Use the formula
$\frac{2a}{\sqrt{3}}=$side length

[warm shale]

Pi Creature

[timid silo]

And isolate a this time

[shell pine]

so is 6/2 the apothem

?

[timid silo]

Lemme calculate

,w (2*a) / sqrt(3) = 6

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by CatHashira#5213

[timid silo]

No ig

[obtuse pebble]

@shell pine Has your question been resolved?

[obtuse pebble]

@shell pine Has your question been resolved?

Channel closed

Closed by @shell pine

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[minor light]

I am so confused on this please help me

[kindred spoke]

I can help

what exactly is your confusion?

Is it on how to solve the question, what the question means, etc.?

[minor light]

Ik it has something to do with exponents but I always have trouble with it

How to solve

[kindred spoke]

I see

[minor light]

Sorry should've been more clear

[kindred spoke]

There are a couple basic rules you have to know

$a^m \cdot a^n = a^{m+n}$

[warm shale]

Science Done Right

[kindred spoke]

This is the most important one in all of them

[minor light]

I def don't remeber that

[kindred spoke]

next, $(a^m)^n = a^{mn}$

[warm shale]

Science Done Right

[kindred spoke]

This is the second most important one

[kindred spoke]

Using these two things, you can solve this

[minor light]

Ok

[kindred spoke]

$(10w^3)^2 = 10^2 \cdot (w^3)^2$

[warm shale]

Science Done Right

[kindred spoke]

Try to evaluate this

using the above two rules

If you need help you can ask me

[minor light]

Oo

Ok

[kindred spoke]

$10^2 = 100$, and as per our second property $(w^3)^2 = w^6$

[warm shale]

Science Done Right

[kindred spoke]

Did you understand?

[minor light]

Not really

[kindred spoke]

So the numerator looks like $100 \cdot w^6$

[warm shale]

Science Done Right

[kindred spoke]

@minor light Do you know like basic exponent properties?

If no, I can teach it briefly and I can help

[minor light]

I did, but I can't find my notes on them so I vaugley remeber them

[kindred spoke]

I will list them all

these are very important

Please read through this

[minor light]

Alr

[kindred spoke]

$1. a^m \cdot a^n = a^{m+n}$

$2. \frac{a^m}{a^n} = a^{m-n}$

$3. a^0 = 1$, For all a $\neq$ 0.

$4. a^{-m} = \frac{1}{a^m}$

$5. (a^m)^n = a^{mn}$

The second, third, and fourth property are true when a is NOT 0

[minor light]

Ok

[kindred spoke]

But for now, you don't need to know that

[warm shale]

Science Done Right

[kindred spoke]

These are all of them, sorry

Try solving the problem now, and if you have any questions you can ping

[minor light]

Oo

K

[kindred spoke]

Btw, the answer is $20 \cdot w^5$

[warm shale]

Science Done Right

[kindred spoke]

But please try solving it

[minor light]

Ok thanks man

Ok got it

Thank you

.close

[obtuse pebble]

Channel closed

Closed by @minor light

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[nocturne schooner]

Equilateral triangle ABC has sides of length 4. The midpoint of BC is D, and the midpoint of AD is E. The value of EC^2 is

[nocturne schooner]

ping me pls

[kindred oasis]

Have you tried drawing the triangle?

[nocturne schooner]

yea

bottom left conrer is a, top middle is b, right corner is c

[kindred oasis]

It's an equilateral triangle, so the median is also the height

[nocturne schooner]

ye

[kindred oasis]

What's the width of the CDE angle?

[nocturne schooner]

90

wait im tripping

[kindred oasis]

So you can apply Pythagoras theorem

[nocturne schooner]

ye

[kindred oasis]

I don't think this drawing it's right

[nocturne schooner]

wait lemme see

oh yea

[kindred oasis]

Should be something like that

[nocturne schooner]

Oh bruh

i got the edges abc order wrong

[kindred oasis]

Doesn't matter it's the same just rotated

[nocturne schooner]

huh

[kindred oasis]

You can find CD and DE right?

[nocturne schooner]

cd is 2

de is squaretoo of 12 divided by 2

[kindred oasis]

Yep

Yeah sorry it's right

[kindred oasis]

2√3/2 = √3

[nocturne schooner]

MANE I KNOW WHY

IT IS CUS I DREW MY DIAGRAM WRONG

nvm

its not

fuck me

[kindred oasis]

CD = 2, ED = √3, apply Pythagoras theorem and find CE²

[nocturne schooner]

ye i got it

thanks

.close

[obtuse pebble]

Channel closed

Closed by @nocturne schooner

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[acoustic granite]

im having trouble with this q

[gilded needle]

well maybe start by taking the inverse of both sides

[acoustic granite]

i did that

ill send pic

[kindred spoke]

Invert both sides, bring the 9BC-1 to the right

and invert again

What's wrong?

[acoustic granite]

i did that one moment

maybe i jus messed up somewhere im sending a pic

pic didnt send so had to write on laptop, my b for messy writing

[kindred spoke]

Why did you invert 1/8? I don't think you should

wait

they asked for an expression for a-1 btw

No I think he distributed that inverse to both terms

[gilded needle]

if you invert the left hand side of the original equation then you just get A + 9BC^(-1)

and you also need to invert the right hand side

[acoustic granite]

why not 1/9?

[gilded needle]

inverse of (stuff)^(-1) is just (stuff)

[acoustic granite]

i see

why isnt it A^-1?

ur takling that inverse right

[gilded needle]

yes when you invert the LHS, you get another -1 exponent, and the two -1's cancel out

[acoustic granite]

theres only 1 tho

[gilded needle]

$((A+9BC^{-1})^{-1})^{-1} = A + 9BC^{-1}$

[warm shale]

OurBelovedBungo

[gilded needle]

yes, i'm telling you to take inverses of both sides

[acoustic granite]

OH

my bad

[gilded needle]

that gives you a new -1 on each side

[acoustic granite]

ok I see so u get A+9BC-1 on the LS

[gilded needle]

right

the purpose of doing this is that now we can isolate the A on one side of the equation

by subtracting 9BC^(-1) from both sides

[acoustic granite]

i need A^-1 though

so I take inverse again both sides

right

this is the answer btw

[gilded needle]

yes

[acoustic granite]

im getting this

[gilded needle]

in your first equation you didn't invert the RHS

you have to invert (1/8)C

[acoustic granite]

ah f sorry i forgot

is this right now

if so how would I be able to simplify it more to get to that final form

[gilded needle]

the first and second lines are right

the third is not

[acoustic granite]

oh b^-1

[gilded needle]

you can simplify the second line as follows:

$A = (8I - 9B)C^{-1}$

[warm shale]

OurBelovedBungo

[gilded needle]

and therefore $A^{-1} = C(8I - 9B)^{-1}$

[warm shale]

OurBelovedBungo

[acoustic granite]

how u get I ?

[gilded needle]

$8C ^{-1}= 8IC^{-1}$

we need the $I$ because we're gonna pull out the common factor $C^{-1}$ and to do that, both terms of the other factor need to be matrices

[warm shale]

OurBelovedBungo

OurBelovedBungo

[acoustic granite]

I see

how did u split the C from the ^-1

[gilded needle]

in other words, $8 - 9B$ doesn't make sense because $8$ is a scalar and $9B$ is a matrix

[warm shale]

OurBelovedBungo

[gilded needle]

where

[gilded needle]

ah, I used $(XY)^{-1} = Y^{-1}X^{-1}$

[warm shale]

OurBelovedBungo

[gilded needle]

where $X = 8I - 9B$ and $Y = C^{-1}$

[warm shale]

OurBelovedBungo

[acoustic granite]

wait but the ^-1 isnt being applied to the C no more

ion get it

[gilded needle]

right

because $Y^{-1} = (C^{-1})^{-1} = C$

[warm shale]

OurBelovedBungo

[gilded needle]

and $X^{-1} = (8I - 9B)^{-1}$

[warm shale]

OurBelovedBungo

[acoustic granite]

oh so u take the inverse of both sides

[gilded needle]

yes

since we want $A^{-1}$ on the LHS

[acoustic granite]

ah that makes a lot more sense

[warm shale]

OurBelovedBungo

[gilded needle]

we need to take inverses of both sides

[acoustic granite]

gotcha

alright thanks a lot

[obtuse pebble]

@acoustic granite Has your question been resolved?

Channel closed

Closed by @acoustic granite

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

I don’t understand sinusodial functions

[timid silo]

How do sinusoidal functions work?

.close

[obtuse pebble]

Channel closed

Closed by @velvet tundra

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[prisma raft]

help pls

number 6

[prisma raft]

help in number 6 about elimination of elimination of arbitrary constants

[obtuse pebble]

@prisma raft Has your question been resolved?

[prisma raft]

<@&286206848099549185>

[twin sapphire]

i dont understand what you are asked to do with this equation

[prisma raft]

Help me to solve number 6

[twin sapphire]

i get that

[prisma raft]

Ok

[twin sapphire]

but what do you need to do

in 6

[prisma raft]

Eliminate

the arbitrary constants

[twin sapphire]

so you want to get a differential equation only involving y?

[prisma raft]

yes

https://www.youtube.com/watch?v=vw6fzRd-kvs&t=1s

[twin sapphire]

first i think you need to compute the first and second derivative of y

[prisma raft]

like this examples

[twin sapphire]

even the third maybe aswell

do that first

[prisma raft]

I need help only in number 6

[twin sapphire]

i got that but i told you the first step to solve it

[obtuse pebble]

@prisma raft Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[copper marten]

let G be a group. Is it true that if $x \in G$ and $ord(x) = ord(G)$, then $G = \langle x \rangle$ (and thus $G \cong \mathbb{Z}/(ord(x))\mathbb{Z}$?

[warm shale]

Rœmer

[copper marten]

i don't see how the assumptions imply $G = \langle x \rangle$ in particular

[warm canopy]

well you know that $\left<x\right>$ is a subgroup of G right?

[warm shale]

Rœmer

iCaird

[copper marten]

yes

[warm canopy]

and whats the order of $\left<x\right>$

[warm shale]

iCaird

[copper marten]

$ord(x)$

[warm shale]

Rœmer

[warm canopy]

which is?

[copper marten]

$ord(G)$

[warm shale]

Rœmer

[warm canopy]

so you have a subgroup sitting inside G, which is the same size as G

[copper marten]

so they must be equal

makes a lot of sense now

[warm canopy]

bingo

[copper marten]

thanks lol

[kind hawk]

(assuming that the order is finite)

depending on definition infinite might be allowed

[warm canopy]

idd good catch

[obtuse pebble]

@copper marten Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wanton kraken]

"In triangle ABC, CM is median, and straight line AQ crosses the median at its middle, and BC at point Q"

"If BC=a find CQ"

I struggle with this

how do I find CQ

<@&286206848099549185>

[obtuse pebble]

@wanton kraken Has your question been resolved?

[obtuse pebble]

@wanton kraken Has your question been resolved?

[wanton kraken]

I've concluded that this problem is too evil and in my best of hopes I won't meet it in exams

.close

[obtuse pebble]

Channel closed

Closed by @wanton kraken

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[subtle kite]

Help please

Better view

<@&286206848099549185>

[obtuse pebble]

@subtle kite Has your question been resolved?

[obtuse pebble]

@subtle kite Has your question been resolved?

[twilit ivy]

why is v=5?
it’s coming to rest so it should be v=0 no

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[steady summit]

Can any one help me please my math teacher gave this question to me and he told me that it has some physics problem in it so if i am allowed to share this question that would be great but if it is not then i will delete it

[tardy epoch]

,rotate

[tardy epoch]

Can you take a screenshot. That's hard to read

[obtuse pebble]

@steady summit Has your question been resolved?

[steady summit]

Ok one min

[steady summit]

Is it good now ??

I cannot understand any thing from this question and i tried for about one week to solve this question but i failed

@tardy epoch
Can you please help me ??

[obtuse pebble]

@steady summit Has your question been resolved?

[steady summit]

<@&286206848099549185>

[obtuse pebble]

@steady summit Has your question been resolved?

[polar topaz]

a is constant

M is constant

So Centripetal force is constant

F= mv^2/r

@steady summit

Only change in r

you have the radius of both A and B

and you know the angular velocity for A

[steady summit]

Ok then , what

[polar topaz]

F = m r w^2

use the formula and sub the values

r (a) w(a) ^2 = r (b) w (b) ^2

see if that works

[steady summit]

Ok

[polar topaz]

And then you find the rate of change

of w to distance

Change in w / change in distance

[steady summit]

I did all of what you said but i don't know what did i do wrong but my calculations was not correct so i don't know what to dod at this point 😫

[polar topaz]

did you calculate the rate of change

[steady summit]

Yes

[polar topaz]

uh show the steps

[steady summit]

I am sorry but can you tell me the steps again

I am bad at physics 😩

[polar topaz]

ok

we know that m is constant since its the same ball

and it said uniform acceleration so A is also constant

F = ma, so the centripetal force is constant

by formula F = rw^2

we know the force at A is equal to force at B

so F(a) = F(b)

radius of a times angular velocity a squared

r(a) * w(a)^2

equals to the same of b

r(b) * w(b)^2

r (a) is 18.2

r(b) is 5.5

W (a) = 0.28

We dont know w (b)

so we sub the values

18.2 * 0.28^2 = 5.5 * w(b)^2

[steady summit]

That is what i did

[polar topaz]

w(b) = 0.50934539094

New w - old w / 350

0.50934539094 - 0.28 /350

[steady summit]

Oooh

[polar topaz]

0.00065527254

did you do the root

[steady summit]

I get it

[steady summit]

No

I forgot

[polar topaz]

lol

[steady summit]

Thanks

😍

[obtuse pebble]

@steady summit Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cursive shore]

2n-3 is my equation

but the answer sheet thinks its +2

[warm canopy]

Does your equation work for n=1 or n=2?

[obtuse pebble]

@cursive shore Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[charred yew]

Hey, I am stuck on this question. Can anyone help me?

[orchid otter]

i think

you must substitute your intensity

and log bot sides and get x down of the power

and solve for x

@charred yew

[timid silo]

yeah, but since its 40% it has to be in decimals

you could leave it as 40% sure, but that will confuse you further down the line.

[charred yew]

So do I sub 40% for I?

Then just solve for x by taking the log of both sides?

[orchid otter]

yes

[charred yew]

Thank you 🙂

.close

[obtuse pebble]

Channel closed

Closed by @charred yew

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stray quiver]

Hello I have question

[stray quiver]

I will type out the question real quick

Consider two similar solids (3D Figures), whose similarity ratio is 2:3.

If the surface area of the smaller figure is 120 square meters, what is the surface area of the large figure?

[sonic violet]

2/3 = 120/x

[silk geode]

is it 3/2 * 120????

[sonic violet]

Set up the proportion and solve for x

[stray quiver]

does it have something to do with like the formula for surface area

like

[sonic violet]

Don’t think it would matter since they are similar, don’t take my word for it though

[stray quiver]

it says round to the nearest two decimals so

3/2*120 would be 180

[sonic violet]

Sheit

[stray quiver]

and 2/3=120/x would also be 180

so

im confused

[sonic violet]

180.00😝

[stray quiver]

does the fact that they are 3d solids change anything

im pretty sure it does

right

[silk geode]

[sonic violet]

Oh, you have to do 2^2/3^2 = 120/x

nah wait

[stray quiver]

yeah i was thinking of that

and for volume

it would be (2/3)^3

= 120/x

right

[sonic violet]

Ya

[stray quiver]

?

[sonic violet]

Does it give a decimal number

[stray quiver]

let me check

oh no

its 270

;-;

[sonic violet]

Ya that’s why I said nah🥹

[stray quiver]

or is it 2/3 = (120/x)^2

just learned this today

[silk geode]

why dont u try to derive it instead of guessing

[stray quiver]

wat

?

anyone here

[astral ivy]

@stray quiver what’s the “similarity ratio”

What does that mean exactly

[stray quiver]

like

the length of one edge of one side of a cube is 6

and the length of one edge of side of another cube is 9

then the similarity ratio would be 2:3

[stray quiver]

like this

i keep getting 270

but they are telling me to round to 2 decimal places

so i am very confused

[astral ivy]

Ah i see

[stray quiver]

my formula is

(2/3)^2 = 120/x

[astral ivy]

Hm

How did you get 270

Oh

Lol

[stray quiver]

cause

[astral ivy]

Nvm nvm

[stray quiver]

(2/3)^2 = 4/9

[astral ivy]

That’s odd

[stray quiver]

4/9 = 120/x

cross multiple

4x = 9(120)

4x=1080

x=270

[astral ivy]

Yeah

[stray quiver]

le tme take a picture

to show you

could it just be there as deception

the round to nearest 2 decimals

@astral ivy you heree

[obtuse pebble]

@stray quiver Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pallid flame]

do you remember formula for average over an interval

[soft charm]

there is an equation for that

[pallid flame]

yes what it is

[soft charm]

i have no idea

[pallid flame]

ok do you know average rate of change formula

from like algebra 1

[soft charm]

not really

if i saw it i would probably know it

[pallid flame]

ok do you know how to find slope between two points

[soft charm]

yes

[pallid flame]

ok what is that formula

[soft charm]

y1-y2

y2-y1

[pallid flame]

what

[soft charm]

/2

ok give me a sec

change in y/change in x

[pallid flame]

which is what

points (x1, y1) and (x2, y2)

[soft charm]

its obvious

[pallid flame]

?

[soft charm]

x2 and y2

[pallid flame]

what

that’s not a slope

[soft charm]

this

[pallid flame]

yes

in terms of the points i described

[soft charm]

yes

its y2-y1

[pallid flame]

no

[soft charm]

yes it is, thats exactly what it is

💀

change in y = y2-y1

change in x = x2-x1

to find the slope you put the delta y on top of delta x

because rise over run

[stray quiver]

.reopen

bruh

[nocturne minnow]

I think jnmwn was asking for the full formula and not the formula broken into pieces

[stray quiver]

why was this close alll my question wasnt resolved

[nocturne minnow]

You can't reopen a channel that's taken

[nocturne minnow]

@stray quiver

[soft charm]

that was the formula he was asking for

from algebra I

[nocturne minnow]

I mean, you gave the formula in parts

jnmwn was asking for the entire formula

[pallid flame]

you said slope = y2 - y1 which is incorrect

slope = (y2 - y1)/(x2 - x1)

[nocturne minnow]

Like if you asked me for the formula for area of a triangle, you wouldn't say base times hieght

Then times one half

Would you? You'd say the entire formula, one half base times height

[soft charm]

whatever zzz

[nocturne minnow]

It makes a difference

[astral ivy]

Oh all the questions say that, I’m not sure it means anything

[obtuse pebble]

@soft charm Has your question been resolved?

Channel closed

Closed by @soft charm

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Please don't occupy multiple help channels.

[nocturne minnow]

Don't open multiple channels, even if you have multiple questions

That means, close one of your channels

[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

Channel closed

Closed by @green granite

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tawdry vortex]

i dont get part b

[tawdry vortex]

i was able to slove part i) but idk what to do with part ii)

wait nvm i got it

.close

[obtuse pebble]

Channel closed

Closed by @tawdry vortex

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[delicate sand]

hello

<@&286206848099549185>

[tardy epoch]

read

[delicate sand]

oh sorry

ill wait 30 mins then

[polar topaz]

eh

its dependent probability

for first

total = 2+23 = 25

probability defective : 2/25

non defective 23/25

2/25 * 23/24

@delicate sand

why is there 3 defective toys when there is only 2 defective items in part 2 😱

Oh wait

sheesh its from 3 box

2/25 * 23/25 * 2 part 1

(23/25) ^3 part 2

[obtuse pebble]

@delicate sand Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[delicate sand]

.reopen

[obtuse pebble]

✅

[delicate sand]

what

[delicate sand]

yeah i was like wott

[polar topaz]

@delicate sand

its from seperate boxs

[delicate sand]

oHHH

OKE

[delicate sand]

thank you

[delicate sand]

but why only the non defective ones for part 2

[polar topaz]

oh

i wrote it wrong

[delicate sand]

so for part 2 its (2/25)^3

[polar topaz]

ye

[delicate sand]

okay thank youuu

[delicate sand]

ok last question

is it

(2/25 * 23/25)*2 or to the power of 2

[polar topaz]

times 2

[delicate sand]

oke

thank you sap

.close

[obtuse pebble]

Channel closed

Closed by @delicate sand

Use .reopen if this was a mistake.

[delicate sand]

.reopen

[obtuse pebble]

✅

[delicate sand]

oh jk i have one more

[polar topaz]

One fixed

find prob of one girl in 2 childs

[delicate sand]

1/2?

[polar topaz]

idk whats the prob

1/2 ig if its not given

[delicate sand]

wdym

2 girls in 3 children

and then 2nd child is a girl

[polar topaz]

yeah but one girl is child

[delicate sand]

so

2/3 or 1/2

[polar topaz]

i mean there is always a girl

so you need to find a girl a boy combination

[delicate sand]

boy girl girl

or girl girl boy

those are the two combinations

[polar topaz]

yeah

total 4 combs

b b , b g , g b, gg

1/2

[delicate sand]

but theres three children

so how is that

[polar topaz]

but one girl is always fixed

[delicate sand]

three children with 2 girls with 1 girl being the middle child

[delicate sand]

yes yes

[polar topaz]

normally its

BBB
BGB
BBG
BGG
GBB
GGB
GBG
GGG

second is always G

so

BGB

BGG

GGB

GGG

[delicate sand]

yeah and then we narrow it down to two girls

so

BGG

GGB

[polar topaz]

yeah

2/4

1/2 prob

[delicate sand]

okay

so 1/2 is the probability

of this

[polar topaz]

y

[delicate sand]

none noen thank u

mwamwa

.close

[obtuse pebble]

Channel closed

Closed by @delicate sand

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[thorn hearth]

So I be using partial sum and like I go over 3/2

But apparently the answer is 1/3

So I'm like Umm

<@&286206848099549185>

[obtuse pebble]

@thorn hearth Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[icy palm]

i understand that i have to get the exact trig value but i dont get how to get a or b

[brittle blaze]

use when cos is 0 to get b and then you will be able to solve for a

[timid silo]

solve for a and b by a system of equations

[icy palm]

but cos 0 is 1

[timid silo]

probably

[brittle blaze]

exactly so thats b

bc cos(90) is 0 so its just y=b

which is 1

[timid silo]

uhhhhhh

i think

[icy palm]

im lost

[timid silo]

u meant to see at 90

not 0

[brittle blaze]

i thought he was saying when cos is 0

which is 90 yeah

bc the y value is 1

[timid silo]

long story short you know that

$a*cos(90)+b=1$

$\implies 0+b=1$ so $b=1$

[icy palm]

uhm

ye

[brittle blaze]

yeah thats whay i was getting at, so then you will be able to get a now

[warm shale]

Pi Creature

[icy palm]

alr

gimme a min

[timid silo]

now try to solve for a

[icy palm]

so b is 1

[timid silo]

ya

solve for a

now

[icy palm]

OH

2

i subbing b back into that equation

and i was getting 0

._.

is that right?

[timid silo]

No

Sub when x=0

[icy palm]

alr

thx mate

[obtuse pebble]

@icy palm Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[static patio]

converges or diverges ?

[junior nymph]

Converges

[timid silo]

what u can try is n+5n^5>5n^5

[static patio]

but what to do with a numerator ?

[timid silo]

well think of some test

which would be appropriate

there is one that should strike

[junior nymph]

Split it like this and apply the sum rule, to check each if each of them converges.

[warm canopy]

Bound it by something of the form an^k, so it'll cancel with the bound for the denominator

[timid silo]

oh i was leaning towards integral test

u got many options now michal

[warm canopy]

Can just do a straight up comparison I think

[static patio]

i havent learnt yet about integral comparison...

[timid silo]

oh

[static patio]

hmm

[static patio]

i dont get it tbh

[timid silo]

like 3n^2<3n^3

[warm canopy]

See if you can bound it by 5n^3

[static patio]

(3n^2 + 2n^3)/(n+5n^5) <= (3n^2 + 3n^3)/(n+5n^5)

[warm canopy]

Eh you didn't do what Arkos said

[static patio]

hmm

idk

i have to bound only numerator ?

[warm canopy]

Both

[obtuse pebble]

@static patio Has your question been resolved?

[static patio]

(3n^2 + 2n^3)/(n+5n^5) <= (3n^2 + 3n^3)/(5+5n^5)

[static patio]

.close

[obtuse pebble]

Channel closed

Closed by @static patio

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pale apex]

How do I get the unknown parts ( final answers rounded to two decimal places and the angle measure to the nearest minute)

[timid silo]

cos(x)=Adjacent/Hypotenuse
sin(x)=Opposite/Hypotenuse
tan(x)=Opposite/ Adjacent

[carmine kelp]

Trig

For the angle B, 180-90-28

[pale apex]

.close

[obtuse pebble]

Channel closed

Closed by @pale apex

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[glossy island]

W=3n+t
Express w in terms of n and w

[glossy island]

Do i just make t the subject?

[worn ocean]

subject?

[glossy island]

Rearranging equation

[worn ocean]

just take 3n to the other side?

t = w - 3n

[glossy island]

Oh

[worn ocean]

is that what u mean

[glossy island]

in terms of n and w

i didnt get what they meant by this

[glossy island]

ye ik

.close

[obtuse pebble]

Channel closed

Closed by @glossy island

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

@fleet horizon Has your question been resolved?

[broken bridge]

yes

[obtuse pebble]

Channel closed

Closed by @fleet horizon

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[high crow]

Can anyone explain this equation to me

And what a cubic formula is

[charred remnant]

still need help?

[high crow]

Yep

[charred remnant]

you solve the inequalities?

[high crow]

Wait a min

[kindred spoke]

You don't need the cubic formula, btw

[charred remnant]

Hi science!

[kindred spoke]

you can take x^2 out from the first two terms

[high crow]

Oh

[kindred spoke]

Hello!

[charred remnant]

that's true

[kindred spoke]

let me write in latex

[high crow]

It said to do them like these

[charred remnant]

i prefer using computer and tricks to solve cubic and higher power

[warm shale]

Science Done Right

[kindred spoke]

Take 4x -1/2 common again

[warm shale]

Science Done Right

[kindred spoke]

Now, this is quite easy to solve. the entire thing is 0, if any of the terms is 0

if 4x - 1/2 = 0, x = 1/8 or 0.125

i x^2 + 1 = 0, x = +/- i

that's imaginary

so we take x = 0.125

So that's the critical point, at which the expression in the image = 0, and not < 0

@high crow are you following me?

[high crow]

Not quite

[kindred spoke]

Okay, read through the text I gave

[high crow]

Ok

[kindred spoke]

go slowly, I will wait :D

[kindred spoke]

start here

[high crow]

How do we know if the entirety is 0?

[charred remnant]

science, i think there's good trick that you could you to solve the cubic

[kindred spoke]

we're taking it as 0

[charred remnant]

it will give you this one in split second without have to do the part above

[high crow]

Oh ok

[kindred spoke]

if we find that, we will get the values for < 0

which was required

[charred remnant]

right @high crow

[high crow]

Mhm

Continue please

[charred remnant]

in order for 2 integer to multiply together and give you a number that is lower than 0

that is lower than 0

Then those 2 integer CANNOT have the same sign

as you know, 2 postive number multiply together will give you a number greater than 0

ex: 5x6=30>0

[high crow]

Yeh

[charred remnant]

2 negative number multiply together will give you a number that is greater 0

[high crow]

Yeh

[charred remnant]

alr you get it the def

[charred remnant]

i believe you're here right?

@high crow

[high crow]

Yeh

[kindred spoke]

Here, it's simple

[charred remnant]

Apply this to the equality

[kindred spoke]

if it's less than 0, the cubic has to be less than or greater than the critical point, 0.125

I hope this all doesn't sound too complex

[high crow]

It will take a while for me to process I don’t come for an English speaking country

[charred remnant]

no worries, science it's really good at explaining in a simple way

[high crow]

Where do you get the x=1/8 if you don’t need the formula?

<@&286206848099549185>

[obtuse pebble]

@high crow Has your question been resolved?

[earnest parrot]

What do you need help with now?

[high crow]

.

[earnest parrot]

It's the zero that corresponds to the factor (4x-1/2)

(4x-1/2)=0, then x=1/8 is a solution

[high crow]

K

[high crow]

Done

.close

[obtuse pebble]

Channel closed

Closed by @high crow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[obtuse pebble]

@royal cargo Has your question been resolved?

[hybrid gull]

@royal cargo ^

[royal cargo]

has it been 15 minutes

oh

<@&286206848099549185>

[hybrid gull]

I mean, what have you tried?

[royal cargo]

ohh, ive tried using the identity and making it 1 but then that makes it 0 which leads me to a dead end

and then ive tried (a+b)^2 identity

that got me no where too

so im not sure how to approach the question really

[hybrid gull]

Find the LHS of the second equation in terms of θ using the first equation

Show your work

[royal cargo]

thats what i dont know how to do..

[hybrid gull]

Okay so take the LHS of the second equation, that expression with m

And replace m with the sec + tan

[royal cargo]

i did that..

[hybrid gull]

Show your work

[obtuse pebble]

@royal cargo Has your question been resolved?

[royal cargo]

sure wait up

[hybrid gull]

Now algebra - expand the parentheses

[obtuse pebble]

@royal cargo Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[warped flume]

Integration problem

Thats all the question gives

[solar trellis]

what have you tried?

[warped flume]

Substituting sinx

Cosx

Sinxcosx

1+sinxcosx

I tried using trig identities to simplify

[robust sleet]

an interesting one

do u have to do it with numerical integration

because finding the integral is very very hard

[gilded needle]

do the double angle trig identities help?

[tardy epoch]

,w integral sqrt(sin^3(x) cos(x))/(1+sin(x)cos(x)) dx

[warm shale]

Wolfram Alpha doesn't understand your query!
Perhaps try rephrasing your question?
Click here to refine your query online

Requested by riemann#2529

[gilded needle]

$\sin(2x) = 2\sin(x)\cos(x)$ and $\sin^2(x) = \frac{1}{2}(1 - \cos(2x))$

[robust sleet]

the answer is very long

[warm shale]

OurBelovedBungo

[solar trellis]

this

also you can factor out sin^2

[warped flume]

Nope

[solar trellis]

u = pi/2 - x might also help

[warped flume]

Tried

[solar trellis]

well.. you don't have to start from scratch after every failed attempt. continue with the simplest expression you have so far