#help-10

1 messages · Page 553 of 1

dense imp
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0 is its own additive inverse since 0 + 0 = 0

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in the case of 2x2 matrices, you want the 2x2 matrix that gives you the matrix that consists of all 0's

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so the additive inverse of that matrix (-1 ,3) / (-4, 5) ....im writing it as just rows cause i cant do better in this chat...is simply (1, -3) / (4, -5) since you add all those numbers together and you get 0's

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so make that match up with the matrix with the a \b unknowns and youll just get 2 equations in 2 unknowns you can solve

grizzled belfry
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so u mean, we can write that matrix with variable matrix (A) + another with no variable (B) , we should equate with zero i.e A+B=0 ?

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and solve at last equate the corresponding parts?

dense imp
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ok lemme just write the matrix as 4 numbers (-1, 3, -4, 5) what is its additive* inverse?

grizzled belfry
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(-1*-4 + 3*5) ??

dense imp
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?

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what matrix would you add to (-1, 3, -4, 5) to get the (0, 0, 0, 0) matrix?

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(hint: its easier than it seems)

grizzled belfry
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-7 ?

dense imp
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you would add the (1, -3, 4, -5) matrix to (-1, 3, -4, 5) to get (0, 0, 0, 0) all the components add and yield 0

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does that make sense?

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its just all the coordinates with opposite sign

grizzled belfry
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ohh

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i got it

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just the same matrix with changed sign ??

dense imp
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so (-1, 3, -4, 5) is the original and (1, -3, 4, -5) is the inverse, the problem tells us that (a - 1, -3, b+3, -5) is also a way to write the additive inverse

grizzled belfry
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hmm im getting it

dense imp
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so we see that the second and 4th coordinate of the one we got and the one given in the problem are the same, it should be also true for the first and third coordinates we just set the coordinates equal to each other

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a - 1 = 1 and b + 3 = 4

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so we get a = 2, b = 1

grizzled belfry
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wow thanks im all clear now

dense imp
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ok and wherever i said inverse here keep in mind i meant additive inverse

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generally when you just say "inverse" for matrices you use it for multiplicative inverse, so i dont mean to confuse you later, i should be careful and say "additive inverse" when we are talking about this

grizzled belfry
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um ok additive inverse just means a+b=0 right ?

dense imp
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yes and multiplicative inverse means ab = 1, so for example 5 and 1/5 are additive inverses

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or in the case of matrices multiplicative inverses would multiply to an identity matrix (one that has all 1's for the top-left to bottom-right diagonal) and all 0's everywhere else

grizzled belfry
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i havent heard of multiplicative inverse , im reading in grade 9

dense imp
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ok maybe you dont have to worry about it then : ) but its same concept

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0 is special for operation of addition because A + 0 = A

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similarly, 1 is special for operation of multiplication because A * 1 = A so it makes sense that you consider inverses in respect to that special number to the operation

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anyway if you think youre done with your question you can use .close to free up the channel

grizzled belfry
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how do i do it?

dense imp
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just type that msg

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.close

grizzled belfry
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ok and thanks al last

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.close

obtuse pebbleBOT
#
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pallid tinsel
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hi

obtuse pebbleBOT
pallid tinsel
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What does it mean expand?

warm shaleBOT
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kaynsu

timid silo
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multiply*

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that is aids

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mine is better lol

warm shaleBOT
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giannis_money

pallid tinsel
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maybe maybe

timid silo
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lmfao

solar trellis
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expand^

timid silo
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LMFAO

pallid tinsel
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so right here I would multiply 5y by the (7y^2 +9)?

timid silo
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yessir

pallid tinsel
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ayy

astral ivy
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Do you know how to do that

pallid tinsel
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tbh

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well I might

distant moth
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💀

astral ivy
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What is a(b+c)

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@pallid tinsel

timid silo
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distribute the term to each

pallid tinsel
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a x bc

timid silo
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no

astral ivy
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Read

pallid tinsel
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dont do this to me

astral ivy
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3(a+b) = (a+b) + (a+b) + (a+b)

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Following?

warm shaleBOT
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kaynsu

astral ivy
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@pallid tinsel dw we can explain

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Oh

astral ivy
pallid tinsel
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uh

noble yacht
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👁👄👁

pallid tinsel
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okay im gonna try it

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.close

obtuse pebbleBOT
#
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candid sigil
obtuse pebbleBOT
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zenith prawn
#

how many 5 digit numbers can be formed with the numbers 0; 1; 2; 3; 4; 5 if they cant repeat?

haughty coyote
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you have 6 digits, you need to choose 5 in order. I guess you haven't seen combinatorics yet ? Or do you mean the same digit can't appear twice in a row ?

zenith prawn
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lets say the number is 12345 there cant be another 5 in there

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basically the same number cant repeat in the same 5 digit number

haughty coyote
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so you need to count how many ways you can choose 5 numbers and then how many ways they can be ordered

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also sorry for the delay I have a really awful connection right now

zenith prawn
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its okay

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in how many ways can you form a 5 digit number with these numbers (0; 1; 3; 4; 5) without repeating them

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i think that should explain it better

haughty coyote
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count how many options you have for the 1st digit, then how many options for the 2nd digit, etc

zenith prawn
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alright ty

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robust sleet
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rational exponent?

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yes

obtuse pebbleBOT
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@sterile pawn Has your question been resolved?

obtuse pebbleBOT
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carmine bear
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made this derivation of the gaussian copula including mean and variance, is there a way to further simplify the last bit?

carmine bear
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oh and if anyone spots any mistakes let me know please

obtuse pebbleBOT
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@carmine bear Has your question been resolved?

carmine bear
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<@&286206848099549185>

brittle blaze
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this is above my head, sorry man

noble yacht
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maybe try an advanced channel?

obtuse pebbleBOT
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@carmine bear Has your question been resolved?

carmine bear
#

alright

obtuse pebbleBOT
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sharp grotto
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Hello guys, how can a person cut 9x4 rectangle once to fill 6x6 square ?

dense imp
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this is really bothering me, i cant figure it out 😄

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someone enlighten us please

sharp grotto
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it looks like childish problem but im sitting more then 20 minutes trying to solve it 😀

dense imp
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<@&286206848099549185>

sharp grotto
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yeap

dense imp
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and is it implied that it's possible?

sharp grotto
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U got 9x4 rectangle, and u should get 6x6 square with one cut

dense imp
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9x4?

sharp grotto
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yea yea sorry

dense imp
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straight line cut?

sharp grotto
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It is not mentioned.

dense imp
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oh

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that'll do it

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i dont know why i assumed it was supposed to be a straight line for a long time and kept scratching my head

sharp grotto
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yes, same, now that you mentioned it It got a lot easier

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Im pretty sure with straight line it will be impossible

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anyways, thank you

#

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obtuse pebbleBOT
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obtuse pebbleBOT
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nimble latch
#

i have math question pls help

obtuse pebbleBOT
tepid sequoia
restive pilot
nimble latch
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So im trying to understand this quadratic formula

restive pilot
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okay

nimble latch
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y=-0.025(x-20)power of 2 + 10

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y=6.4

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so... 6.4=-0.025(x-20)power of 2 +10

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i need to find x

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according to this website

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that im using to revise

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stuff

restive pilot
nimble latch
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ok

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gimme a minute

restive pilot
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sure chief

nimble latch
restive pilot
nimble latch
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sort of gimme a minute to explain

restive pilot
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sure ^^

nimble latch
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the question hints that there might be multiple answers for x

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the first one being x=32

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that I understand

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because you square root 144 and simplify until you find x=32

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buuuut

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the other value of x is x=8

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this is what I dont understand

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because why would you negativly square root it

restive pilot
# nimble latch

okay so first what you did here is you subtract 10 and then divide by -0.0025 right

nimble latch
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yes

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which cancels -0.025 out

restive pilot
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yes great!

nimble latch
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then -3.6/-0.025 = 144

restive pilot
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okay to answer your question we want to know all solutions for sqrt(144)

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which numbers multiplied with themselves are 144

nimble latch
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yea its x=32 and x=8

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but to find x=8

restive pilot
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answer me my question please

nimble latch
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you have to -square root 144

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ill screen shot what i dont understand

restive pilot
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no need

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you want to understand how the soltion 8 is possible and we will get there

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square root always have 2 solutions

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one positive and one negative

nimble latch
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oooh ok

restive pilot
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because

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-12*(-12) = 144

nimble latch
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makes sense

restive pilot
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and 12 * 12 = 144

nimble latch
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ok

restive pilot
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thats why you have 2 solutions at most quadratic equations

nimble latch
#

ooh ok

restive pilot
#

at least real solutions

nimble latch
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thanks

restive pilot
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sure

nimble latch
#

i understand now

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imma share this discord if thats ok

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many ppl will find it interesting

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how do i leave?

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how

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sry

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.close

obtuse pebbleBOT
#
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obtuse pebbleBOT
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proven plank
obtuse pebbleBOT
proven plank
#

i need help

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with 15

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i understand how I can redraw the diagram into its 10N vectors

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but idk where to go from there

astral marsh
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40-30 = 10 so 10N left

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35 - 25 = 10 so 10N to the top right

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now

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with the 45degree thing uhh

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well they are both 10 in each direction so maybe a little less than 20

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its basically like a spread out 20 thats not efficient i think

proven plank
#

<@&286206848099549185>

obtuse pebbleBOT
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proven plank
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.reopen

obtuse pebbleBOT
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proven plank
#

<@&286206848099549185>

obtuse pebbleBOT
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@proven plank Has your question been resolved?

obtuse pebbleBOT
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@proven plank Has your question been resolved?

obtuse pebbleBOT
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@proven plank Has your question been resolved?

proven plank
#

.reopen

obtuse pebbleBOT
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@proven plank Has your question been resolved?

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gritty light
#

can somebody solve x^3+6x+9 without using the cubic formula

obtuse pebbleBOT
#

@gritty light Has your question been resolved?

royal basin
#

there's nothing to solve here

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did you mean x^3 + 6x + 9 = 42069?

gritty light
#

no

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solve for x

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when =0

royal basin
#

so in fact you meant x^3 + 6x + 9 = 0.

#

it appears that this polynomial does not have any rational roots

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gritty light
obtuse pebbleBOT
royal basin
#

probably impossible to obtain now that you've stipulated the cubic formula may not be used

gritty light
#

so it is imossible

obtuse pebbleBOT
#

@gritty light Has your question been resolved?

obsidian isle
#

(x-a)(x-b)(x-c) =
(x^2 - (a+b)x + ab)(x-c) =
x^3 - cx^2 - (a+b)x^2 +c(a+b)x + abx - abc =
x^3 - (a+b+c)x^2 + (ab + bc + ca)x - abc

-(a+b+c) = 0
ab+bc+ca = 6
-abc = 9

#

This actually might not be so bad

gritty light
#

whats this

obsidian isle
#

Expansion

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c = -9/(ab)

a + b - 9/(ab) = 0
ab - 9/a - 9/b = 6

a^2b + ab^2 = 9
a^2b^2 - 9b - 9a = 6ab

ab(a+b) = 9
ab(ab-6) - 9(a+b) = 0

Let A = ab, B = a+b

AB = 9
A(A-6) - 9B = 0

B = (A^2-6A)/9

(A^3 - 6A^2)/9 = 9
A^3 - 6A^2 - 81 = 0

#

I think this might be solvable

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,w 9-4(sqrt(10)-1)(33-6sqrt(10))

obsidian isle
#

This is tedious

obtuse pebbleBOT
#

@gritty light Has your question been resolved?

obsidian isle
#

Impossible to reduce actually

#

You always end up with another cubic

obtuse pebbleBOT
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finite flame
obtuse pebbleBOT
finite flame
#

How do i do it

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I know there’s something related to n(n+1)/2

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As its sum of n natural numbers

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1 + 1/(6/2) + 1/(12/2) + 1/(20/2) +….

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2/2 + 2/6 + 2/12+ 2/20 +2/30

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2( 1/2 +1/6 +1/12 + 1/20 +…)

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2(1-1/2+1/2-1/3+1/3….+1/2020-1/2021)

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2(1-1/2021)

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4040/2021

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<@&286206848099549185>

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(I knew its useless to ping@ helpers)

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Ban all memebers with @ helpers role banhammer banhammer

#

Lmao

#

No but seriously what’s wrong in my solution

warm canopy
finite flame
#

No not really

obtuse pebbleBOT
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@finite flame Has your question been resolved?

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storm bay
obtuse pebbleBOT
storm bay
#

I'm confused to how they turn cos(2x) into 2cos^2x-1

#

From the top line to the one under

high lily
#

double angle identity

robust sleet
#

^

storm bay
#

Hmm

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I have no idea what that is lol

robust sleet
#

look it up

storm bay
#

Alright I'll watch a vid on it 👍

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Oh there's formula on this thing

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In my formula book

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I lowkey remember this

robust sleet
#

lol

obtuse pebbleBOT
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storm bay
#

yeah theres literally a formula saying that cos (2x) is equal to that in my book

obtuse pebbleBOT
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thorny otter
#

hello again, I have an question the following equation that i get the values u and a from

thorny otter
#

instead of u and a, i would like to get b and x

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I have no idea on how to do this, so any help is greatly appreciated

obtuse pebbleBOT
#

@thorny otter Has your question been resolved?

velvet siren
#

You can start by saying b≠x

thorny otter
#

ok

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im sorry, this is all pretty new to me again, i havent done anything this complex since early 90s

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its a function im trying to work out for my coding project, so i dont really understand what you mean by b≠x

robust sleet
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if x=b then denominator would be zero

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that's not nice

thorny otter
#

So i have written the equation wrong?

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i believe that the equation above is the same as the function GetFutureDataFromAmountIn

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just trying to reverse it

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Sorry if its still convoluted or not in the right terminology. If its to weird, ill just close and try somewhere else

thorny otter
#

Does anyone know if there is a paid service that would help with a question like this <@&286206848099549185> ? or where else i could seek some assistance?

olive hawk
#

It would be helpful if you could explain what exactly the procedure does?

thorny otter
#

no problem

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I should also say the current reservein and out are readily available

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but im not sure if i did it correctly

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@warm canopy still too convoluted?

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<@&286206848099549185> Was fun wasting 8hrs here trying to get some help. Thanks all.

#

.close

obtuse pebbleBOT
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minor cypress
#

which one of the four?

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in a the student needs atleast 5 correct

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so ill subtract 1-(4 correct + 3 correct + 2 correct + one correct+ 0 correct)

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ummm wdym by negative distribution?

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you are correct here

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yeah this isnt wrong

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the student needs atleast 6 questions in b

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40% of 15 is 6

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so just add P(x=5) case in your above problem and subtract from 1

obtuse pebbleBOT
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@crimson kiln Has your question been resolved?

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shadow lava
#

Did I do this correctly?

obtuse pebbleBOT
shadow lava
#

Or if I’m going to use 0 for y do I need to divide the entire equation by 2 first?

wide orchid
#

the calculations are correct yeah

shadow lava
#

Hmmm ok it just looks weird.. this is what the instructor got

wide orchid
shadow lava
#

In his he got -3/2x for slope

wide orchid
#

send the full question plz

shadow lava
wide orchid
#

yeah, correct.

wide orchid
shadow lava
#

Both are equal to the same line?

#

Even with different slopes

wide orchid
#

umm wait, i don't think i am the right person to answer that. all i can say is that the equations are correct. idk slope n all , sorry

nocturne minnow
# shadow lava

What you are doing here is finding the x and y intercepts, you know that, right?

shadow lava
#

Yeah, and I feel like -8/3x and -3/2x are different

#

For the same line

nocturne minnow
#

Because they are different

shadow lava
#

OK

#

So if we divide the equation by 2 the lines will be squished smaller?

#

And if we multiply the equation by 2 the lines will be stretched taller?

nocturne minnow
#

It changes the slope, yes

shadow lava
#

However, intercepts to both lines will still be at the same point regardless of multiplying equation or dividing equation by 2?

#

I think that makes sense the more I think about it 🤔

#

I see it on software with Google Analytics or Stocks zoom in or zoom out changing the aspect ratio and scale but not the intercepts

obtuse pebbleBOT
#

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clear cloak
#

Hi

obtuse pebbleBOT
clear cloak
#

Can someone explain 2 to me please

brittle blaze
clear cloak
#

You’re saying 10 is the base?

brittle blaze
#

What is the question asking, you never said

naive owl
#

he wants u to explain 2

clear cloak
#

When I put 10 log (2) in my calculator I get 0.3

#

Not 2

#

So 10 to the power of log2?

brittle blaze
#

Usually the “ default” base is 10

#

Withs logs

clear cloak
#

I know this

brittle blaze
#

I don’t understand what you are trying to do

clear cloak
#

I don’t understand what it says

#

10^log(2) or is 10 the log base here?

#

Because log(2) is not 2

brittle blaze
brittle blaze
naive owl
warm shaleBOT
#

Chunkin
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

clear cloak
#

So it is 10 to the power of log (2)?

naive owl
#

yeah

clear cloak
#

10 is the standard base of log

#

Ok thanks!

#

Yea so when I fill this in on mu calculator I do get 2 now

naive owl
#

,w is 10^log(x)=x

clear cloak
#

What do you mean?

#

Because it cannot be < 1?

obtuse pebbleBOT
#

@clear cloak Has your question been resolved?

clear cloak
#

Am I doing this correctly to inverse?

distant moth
clear cloak
#

As was my thought

naive owl
#

,w is 10^log(x)=x

naive owl
#

,w plot 10^log(x)

distant moth
#

I dont understand why for x=0, it shows 0, it shouldnt be

naive owl
#

,w log(0)

naive owl
#

😳

#

,w 10^log(0)

naive owl
#

ayo 🤨

distant moth
obtuse pebbleBOT
#

@clear cloak Has your question been resolved?

versed turret
#

,w lim 10^(log(x)), x -> 0+

warm shaleBOT
versed turret
#

Similarly, graphing x^x shows y = 1 when x = 0.

#

And for sin(x)/x, (0, 1) is a point on the curve

obtuse pebbleBOT
#
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karmic field
#

Question: Under a rotation through an angle of 45 degrees about the y-axis, the image of the point (-13root2 / 2, 10, -3root2 / 2) has a position vector a . Find the position vector

karmic field
#

Basically I need to find a, I understand how to do the rest of the question but this part has me stumped

#

I have the answer as well, I just need to understand how to do it

#

Just the a= part is the answer

obtuse pebbleBOT
#

@karmic field Has your question been resolved?

candid sigil
#

<@&286206848099549185>

karmic field
#

Thank you

#

<@&286206848099549185>

versed turret
#

@karmic field Have you learned rotation matrices yet?

#

(In 3D)

karmic field
#

Yes I have

versed turret
#

Just use the one for rotations around the y-axis

karmic field
#

How would you convert the vector into the matrix?

versed turret
#

And multiply this by $\begin{bmatrix}
-\frac{13}{\sqrt{2}}\
10\
-\frac{3}{\sqrt{2}}
\end{bmatrix}$

karmic field
#

Hmm okay I’ll give it try

warm shaleBOT
#

castroploiin

karmic field
#

That does not work

versed turret
#

... it should

karmic field
#

You

#

Are correct

#

I am a dumb ass

#

And was doing 45 degrees with rads instead of pi/4

#

Thank you so much for this!

#

.close

obtuse pebbleBOT
#
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neat smelt
#

Hi

obtuse pebbleBOT
neat smelt
#

I saw something like this in a book

#

percentage_change,current_price,last_close_price 13.2, 120.5, 150

#

I'm wondering how they got the 13.2% if anyone can explain

#

Yes of a stock

#

Ok nice. Thank you

#

Pn-1 would be the previous day price right?

#

Awesome.

#

!close

obtuse pebbleBOT
#

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#
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strong mauve
#

how did he get from step 1 to step 2? i don't understand what's happening

broken bridge
#

cancelled n! on both sides
simplified 3 and 6! on the left
simplified 4! on the right, 11 become numerator

naive owl
#

how did he bring 3 to the bottom

#

or divide by it ig

broken bridge
#

3/6!=3/(1x2x3x4x5x6)=1/240

naive owl
#

ohhh

strong mauve
#

thank you

#

.close

obtuse pebbleBOT
#
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timid silo
obtuse pebbleBOT
timid silo
#

hi! may i get help understanding how to evaluate this integral please

#

i couldnt seem to understand the method my professor used and i couldnt find any examples similar to this to reference

eternal bloom
robust sleet
#

There's a method for these type of integrals, called trignometric substitutions.

timid silo
timid silo
robust sleet
#

show us what method your prof taught u

timid silo
#

OH WAIT I THINK I GET IT

versed turret
#

It's 1/4th of a circle with radius 1

robust sleet
#

yeah 1345 already told it

timid silo
#

so i think what he did was he took the formula for area of a circle and used 1 as the radius, so that became pi(1)^2 but since its a quarter its pi/4

#

that makes sm more sense now

#

thank you for yalls help! i appreciate it!

eternal bloom
obtuse pebbleBOT
#
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slender totem
#

How would I differentiate $y = \sqrt{x^2 + 1}$ from first principles? I think I remember my teacher saying something about the difference of two squares, but I can't see how that can be applied here.

warm shaleBOT
#

William VII

broken bridge
#

try rationalizing the fraction when you use first principle

slender totem
#

I've tried just doing $y = \sqrt{(x+h)^2 + 1} - \sqrt{x^2 + 1}$, but that hasn't really gotten me anywhere

warm shaleBOT
#

William VII

slender totem
broken bridge
#

$y = \frac{\sqrt{(x+h)^2 + 1} - \sqrt{x^2 + 1}}{h}$

warm shaleBOT
#

exploseph

slender totem
#

oh yeah

broken bridge
#

then, $y = \frac{\sqrt{(x+h)^2 + 1} - \sqrt{x^2 + 1}}{h} \cdot \frac{\sqrt{(x+h)^2 + 1} + \sqrt{x^2 + 1}}{\sqrt{(x+h)^2 + 1} + \sqrt{x^2 + 1}}$

warm shaleBOT
#

exploseph

slender totem
#

Ok, I'll try that and see where it gets me

#

I've got $\frac{2x + h}{\sqrt{(x+h)^2+1} + \sqrt{x^2+1}}$

warm shaleBOT
#

William VII

slender totem
#

I can just substitute h = 0 in now, right?

broken bridge
#

numerator is not correct

#

missing something in the first term

slender totem
#

x^2 + 2xh + h^2 + 1 - x^2 - 1 = 2xh + h^2?

#

I cancelled out an h from the top and bottom

broken bridge
#

ah right my bad

broken bridge
slender totem
#

Alright

#

Looks like I got to the right answer

broken bridge
#

apologies for me overseeing

slender totem
#

np

#

Thanks for the help

broken bridge
#

glad i could help

slender totem
#

.close

obtuse pebbleBOT
#
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amber torrent
obtuse pebbleBOT
amber torrent
#

Does anybody know what the difference is between Lagrange remainder and the big O notation O((x-a)^(n+1))?

royal basin
#

big O is nonspecific, Lagrange remainder gives an actual expression for the error term in terms of the function

obtuse pebbleBOT
#

@amber torrent Has your question been resolved?

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amber torrent
#

thank you!

obtuse pebbleBOT
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zinc cliff
#

is there a problem here with my factoring? (im aware the bottom part hasnt been compressed, i just mean the upper parts)

cunning plaza
#

x² - 2x doesn't equal (x-1)(x-1)

#

you could factor it into x(x-2), if that at all helps

#

but the two things you factor your binomial into need to multiply together to yield the original binomial

#

@zinc cliff is that helpful?

zinc cliff
#

yeye! i see it now
gimme a minute to correct that

#

would -1 and positive 2 work?

#

hmm
im looking at the hyperbola for the original equation rn and i cant seem to get them to match

obtuse pebbleBOT
#

@zinc cliff Has your question been resolved?

tardy epoch
obtuse pebbleBOT
#

@zinc cliff Has your question been resolved?

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#

@timid silo Has your question been resolved?

timid silo
#

<@&286206848099549185> am very lost 😦

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teal fjord
obtuse pebbleBOT
long sinew
#

Maybe you are supposed to use "Constant rate" as a clue

teal fjord
#

well yes

#

but the graph has to show the depth of the water

#

not how much the water is leaking

long sinew
#

Yes, so over time the depth will decrease

teal fjord
#

so is the answer still A?

long sinew
#

It would seem so

teal fjord
#

or could it be D because the shape is a cone

long sinew
#

But I could be wrong

#

What topic is this?

teal fjord
#

i think

long sinew
#

I would assume it to be D actually

#

Because the cone shape

teal fjord
#

alr

#

thanks

long sinew
#

Since, the cones decreasing shape

#

Water would drop faster

#

Water depth*

teal fjord
#

i see

#

thank you

long sinew
#

No problem

#

Honestly seems sort of like a physics question O_O

obtuse pebbleBOT
#

@teal fjord Has your question been resolved?

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south geode
obtuse pebbleBOT
#

@south geode Has your question been resolved?

deft carbon
#

what are you having problems with exactly

south geode
#

I’m having problems starting and just making the equation

#

I don’t quite understand the concept displayed in the question

deft carbon
#

well i can try but im not sure my answer will be 100% correct

south geode
#

That’s fine

deft carbon
#

most important thing is to remember the minimums and maximums of trig functions

#

so lets just take sin(x)

south geode
#

Okay

deft carbon
#

what values of sin(x) are smallest and largest?

south geode
#

Like points? I think smallest is -1

deft carbon
#

values

#

its -1 and 1

south geode
#

Oh okayy

deft carbon
#

like no matter what value of x you put in sin(x)

#

it cant be larger than 1, and cant be smaller than -1

#

ok now this is tricky but

#

they want you to create a function with these conditions

#
  1. maximum of 22.13
#
  1. minimum of 6.08
south geode
#

Okayy

deft carbon
#

we will worry about the n'th day of the year later

#

what way do you propose of achieving this @south geode

#

answer quickly i gotta sleep

south geode
south geode
#

Like d and k

deft carbon
#

no dont worry about shifting values for now

south geode
#

Oh

deft carbon
#

thats part of the 'nth day' thingy

#

ok ill spoil it

south geode
#

I’m not sure tbh cuz winter and summer different

deft carbon
#

basically sin(x) has a minimum of -1 and a maximum of 1

#

so some constant in front of k, added to some other value, must equal

#

k(1 [max]) + d = 22.13
k(-1 [min]) + d = 6.08

south geode
#

Okayy

#

How do we find k and d then

deft carbon
#

... this is a simultaneous equation

#

solve it

south geode
#

Omg I think I got it so

#

I can find amplitude using 22.13+6.08)/2

deft carbon
#

.-.

south geode
#

No wait

#

Sorry wrong one amplitude is

#

22.13-14.105

#

Okok ima write it down

deft carbon
#

you got it right (kind of)

#

like i said i gotta sleep so ill gib the answer now

#

k = 8.025, d = 14.105

#

what do these constants mean? well lets look at a curve of ksin(x) + d

south geode
#

I got H= 8.025 sin (2pi/366(t-80.5))+14.105

deft carbon
#

ignore the values of x for now cause we havent done anything to them, but notice how this sinusoidal function has a maximum of 22.13, and a minimum of 6.08 like we wanted to

deft carbon
#

congrats

#

ill go now

south geode
#

Thanks a lot

deft carbon
#

no prob ^_^

#

close the channel

deft carbon
#

.close

obtuse pebbleBOT
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spare vapor
#

how to fully factor?

obtuse pebbleBOT
spare vapor
#

.close

obtuse pebbleBOT
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spare vapor
#

o wel

obtuse pebbleBOT
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lucid fog
#

what is 1+1

obtuse pebbleBOT
lucid fog
#

?

#

@jaunty stream

#

.close

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steady turtle
#

hi

obtuse pebbleBOT
steady turtle
#

on number #34

#

what the formula ?

#

<@&286206848099549185>

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#

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gusty kraken
obtuse pebbleBOT
gusty kraken
#

Kinda just stuck this is my last problem for my final assignment.

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dreamy oasis
obtuse pebbleBOT
dreamy oasis
#

can anyone help?

obtuse pebbleBOT
#

@dreamy oasis Has your question been resolved?

dreamy oasis
#

<@&286206848099549185>

obtuse pebbleBOT
#

@dreamy oasis Has your question been resolved?

broken bridge
#

@dreamy oasis try using tangent properties.
i.e. If a point outside of circle touches the circle at two diffrerent point, the two distance would be the same

#

in this case, ET=ES

#

you can also use this rule in other points of tangency

dreamy oasis
#

okok ty

obtuse pebbleBOT
#

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stray hatch
#

I don't get how x + y > 5 became y > -x + 5 and y = -x +5

obtuse pebbleBOT
#

@stray hatch Has your question been resolved?

obtuse pebbleBOT
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obtuse pebbleBOT
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wispy bramble
#

Can anyone help me solve this, it's asking to determine the transfer function and the poles and zero of the system. Not too sure what to do as this is a new subject I'm being taught poorly

vernal wren
# wispy bramble Can anyone help me solve this, it's asking to determine the transfer function an...

In this video, i have explained Transfer Function of Differential Equation with following timecodes:

0:00 - Control Engineering Lecture Series
0:20 - Example 1 - Transfer Function of Differential Equation
4:16 - Example 2 - Transfer Function of Differential Equation

Following points are covered in this video:

  1. Transfer Function
  2. Transf...
▶ Play video
obtuse pebbleBOT
#

@wispy bramble Has your question been resolved?

wispy bramble
#

Yh I don't really get it despite watching the example relevant to my question

vernal wren
#

Did you get how to find the transfer function?

vernal wren
wispy bramble
vernal wren
#

Might wanna tag the helpers here as I haven't done this in a while and I'm learning from the vid as well

wispy bramble
#

<@&286206848099549185> I'm kinda stuck as this is a new topic for me

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This is what I've done so far

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Not sure if this is right

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<@&286206848099549185>

#

<@&286206848099549185>

wispy bramble
#

Please help

#

<@&286206848099549185>

obtuse pebbleBOT
#

@wispy bramble Has your question been resolved?

obtuse pebbleBOT
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opal totem
#

how do you find the equation of an already graphed circle

opal totem
broken bridge
#

find its centre by drawing two diameters i guess

#

assuming its tangent to y=2, y=-6, x=-1, x=7

obtuse pebbleBOT
#

@opal totem Has your question been resolved?

opal totem
#

.close

obtuse pebbleBOT
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obtuse pebbleBOT
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small iron
#

Hi everyone! I don't know if this is the right channel where to ask this, so if it isn't, I'm sorry
I'm currently studying successions and I was thinking: Can I write a function like f(x) = f(x-1) + 1?

small iron
obtuse pebbleBOT
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split light
#

Hi can you guys help me with this please. Idk how to solve it

tall turtle
split light
#

1 -3 +6 -10 + 15

tall turtle
#

uhh

#

check that again

#

its squares right

#

not the sum

#

like say n is a super big number

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just keep going

#

it should be

split light
tall turtle
#

1 - 4 + 9 - 16 + 25 - etc

#

makes sense?

split light
#

yes you are right

cedar gull
#

u can replce j=1 by j=0 to understand it better

#

j-1 wll become j

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and j become j+1

split light
#

I don't know how to do that

#

like this?

cedar gull
#

<@&286206848099549185>

split light
#

ohhhh i see

cedar gull
#

how to get out now

#

..

#

u cant just seperate them

#

@split light

#

is there any question behind it?

split light
#

I dont know how to separate them

cedar gull
#

speaking of the question

#

where u find tihs

#

what exercice

#

it can be related

#

plus there are 2 ways that u need to go threw

#

if j=2k and if j=2k+1

#

show me the whole exercice

split light
#

"calculate the following sums"

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they just gave me this

cedar gull
#

there is probleme in that sum

outer hatch
#

Find the eqn of the elipse whose foci at (4,6) and (-6,6) one vertex at (5,6)

cedar gull
#

wat

split light
#

?

cedar gull
#

i think he is dreaming

outer hatch
cedar gull
#

bruh

cedar gull
#

solve it then

outer hatch
split light
#

he's sending it to every channel

cedar gull
#

he is acting like a b ass

#

vicoo

#

i dontt think we can solve taht

#

sry

#

i rly think that there is a probleme

split light
#

symbolab gives me this

cedar gull
cedar gull
#

let me seee

split light
#

but i should not have J in my final answer

#

oh

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i didnt write it

#

ok

cedar gull
#

bro waht

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why i and j

split light
#

i wrote an i

#

mb

#

it was a mistake

cedar gull
#

u gona get a fat error now boy

split light
#

its j not i

#

and symbo can't solve it

cedar gull
#

told u

#

big fat error

#

trust me bro if it was +

#

if it was +

#

it can be solved

split light
#

thanks anyways, i'll try asking my teacher tomorrow

#

yes

cedar gull
#

teach ur teacher

#

tomorrow

#

tell him stop waisting my time with wrong questions

split light
#

hahahah

cedar gull
#

what u getting payed for

#

jk jkjk jkjk jk

split light
#

thanks anyways dude, i've been trying to solve this for the past hour

cedar gull
#

if he can solve that plz tell me

#

nop man anytime

split light
#

k

#

ty

#

.close

obtuse pebbleBOT
#
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glossy ermine
#

h

obtuse pebbleBOT
glossy ermine
#

hello, can someone help me with this

nocturne minnow
#

Where are you stuck on?

glossy ermine
#

i keep trying to do the question from a tutorial

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i think i mess up when i am taking away the 31.9 off 79.2

#

i think the tutorial might be wrong

naive owl
#

how could z be 6.9

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if the height is 8.9

glossy ermine
#

idk

#

the tutorial was sent to me

#

by my maths teacher

naive owl
#

8.9 is the height not the hyptonuse

glossy ermine
#

i know

#

im trying to work out the hyptonuse

#

can someone please work it out for me

#

and then send me their method

naive owl
#

bro it's easy

#

u set the hyp = 8.9

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for some reason

glossy ermine
#

so

#

8.9^2+5.65^2?

#

or would it be 5.7^2?

craggy cave
#

Hello guys 👋 if you can please help me to solve problem of real analysis 🥺

glossy ermine
#

@naive owl would it be 10.6?

naive owl
glossy ermine
#

what did you use to work it out?

clear cloak
glossy ermine
#

okay

#

thanks

glossy ermine
#

would this be 30.1?

wary magnet
#

Almost

#

U have to square root the 30.05

#

Which is 5.5

glossy ermine
#

so answer is 5.5?

wary magnet
glossy ermine
#

wait

#

so is it

#

30.1

#

or 5.5?

wary magnet
#

5.5

glossy ermine
#

ah okay

#

thanks

wary magnet
#

I replied to the wrong one

#

Np

obtuse pebbleBOT
#

@glossy ermine Has your question been resolved?

obtuse pebbleBOT
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pliant schooner
obtuse pebbleBOT
pliant schooner
#

if this is revolved around the x axis what method do I use

#

(shell, washer etc)

gloomy valve
#

@pliant schooner You can actually use both, but the washer/disk method might be more intuitive if you rotate around x-axis

naive owl
#

,w plot -\sqrt{x-x^{2}}

naive owl
#

like this?

obtuse pebbleBOT
#

@pliant schooner Has your question been resolved?

obtuse pebbleBOT
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tribal iris
obtuse pebbleBOT
tribal iris
#

I tried taking ln of both sides

#

But i get stuck after that

#

What am I supposed to do?

tardy epoch
#

🏥

dreamy scroll
#

re write $2x\ln(x) = \frac{\ln(x)}{\frac{1}{2x}}$

warm shaleBOT
#

JamesH

tribal iris
#

Ok

#

Ohhhhhhh

#

Then 1/2x = inf

#

And the lnx/inf =0

#

Kk

tribal iris
dreamy scroll
#

wait no

#

you need lhopital

pallid flame
#

le hospital

tribal iris
#

My bad

pallid flame
#

🥖🏥

tribal iris
tribal iris
dreamy scroll
#

you dont have to differentiate both sides

#

lhopitals says if L = lim f(x)/g(x) = '0/0' or 'inf/inf' then L = lim f'(x)/g'(x)

tribal iris
pallid flame
#

ye

tribal iris
#

Kk

#

Thx alot

#

I learned alot from this

#

,close

#

.close

obtuse pebbleBOT
#
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warm shaleBOT
#

please request a new nickname

obtuse pebbleBOT
#
Channel closed

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supple pumice
#

For a 2 dimensional vector space.

dreamy scroll
#

what are the requirements for T to be diagonalizable?

supple pumice
#

To find one more eigenvector

dreamy scroll
#

why one more? what eigenvector do we currently have?

supple pumice
#

I figured that if v is an eigenvector for 2, then if I find another eigenvector linearly independent from v then T is diagonalizable?

dreamy scroll
#

that sounds right to me, i was thinking about it differently but there are so many equivalent things to diagonalizability

#

are you studying from axler?

supple pumice
#

yeah

dreamy scroll
#

what exercise is this?

supple pumice
#

oh, this was actually a midterm question that I couldnt solve, and I'm trying to work it out right now.

dreamy scroll
#

ill do a bit of reading, i feel like ive done this exact problem before

supple pumice
#

ahh thanks im still trying myself

obtuse pebbleBOT
#
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livid zinc
#

hello

obtuse pebbleBOT
#

Please don't occupy multiple help channels.

supple pumice
#

hey

livid zinc
#

hi

#

but im not sure which length to use

#

L or K

#

@supple pumice are you here?

#

where is that?

#

okay.

supple pumice
livid zinc
#

its quite inactive

supple pumice
#

oh thats interesting

livid zinc
#

are you not able to do that?

supple pumice
#

no i was using this channel and then it seems to have closed without me knowing

livid zinc
#

okay.

#

.close

obtuse pebbleBOT
#
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strong vale
obtuse pebbleBOT
strong vale
#

For (a), I got g(1/5)

#

for (b) no solutions

#

How do I go about (c) and (d)

dreamy scroll
#

how did you determine there were no solutions to b)?

strong vale
warm shaleBOT
#

azeem321

strong vale
#

Derivative of ln(x) is 1/x

#

and derivative of -1/2x is 1/2x^2

#

wait that doesnt prove anything

#

Well, I guess it's just easier to consider $x\ln{x} = -\frac{1}{2}$

warm shaleBOT
#

azeem321

strong vale
#

xln(x) can be differentiated and the minimum occurs at -0.368

#

which is >-1/2

obtuse pebbleBOT
#

@strong vale Has your question been resolved?

obtuse pebbleBOT
#

@strong vale Has your question been resolved?

strong vale
#

<@&286206848099549185>

obtuse pebbleBOT
#

@strong vale Has your question been resolved?

finite vector
#

Ok i'll write it anyway

warm shaleBOT
#

newbienoob

#

newbienoob

finite vector
#

For (d) have a look at $f\left(ln\left(\frac1{x}\right)\right)$

warm shaleBOT
#

newbienoob

obtuse pebbleBOT
#

@strong vale Has your question been resolved?

obtuse pebbleBOT
#
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tepid depot
#

im a bit confused on how the answer is 57.5

obtuse pebbleBOT
robust sleet
#

what did u try

tepid depot
#

sin(35) * 33