help-10

[west sierra]

ohh right that works too

[warm shale]

||𝓚𝓪𝓼𝓹𝓮𝓻||

[west sierra]

I can see the answer now !!

.close

[obtuse pebble]

Channel closed

Closed by @west sierra

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

I need help understanding this question. I have to prove that T is a partial order on the set of all finite length binary strings.

[compact shadow]

And?

Reflexive, anti-symmetric, transitive, which one you have problem with?

[timid silo]

I'm just trying to figure out what I'm doing here

Like, what is a and b in this and so on

[compact shadow]

……

[timid silo]

wait nvm that is my end goal

alright ive had coffee and now i feel like an idiot asking this question

[compact shadow]

😂

[obtuse pebble]

@timid silo Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[half halo]

what test would I use to determine if this is convergent or divergent?

[half halo]

limit comparison test?

can't I derive a simplified version of the function

[hushed moat]

Should work

[half halo]

and then compare it to that?

like, get rid of the terms that are insignificant in the overall magnitude of the function

[hushed moat]

Yea

That should work

[half halo]

maybe 1/(n^3)?

[hushed moat]

Yea

Try it

[half halo]

the limit of the first function divided by the second function is 1/5

so

[half halo]

ratio this channel is taken

[turbid patrol]

mb

[half halo]

okay so I know that they have the same behaviour

now how can I prove that my second function is converging or diverging

the 1/(n^3)

wait

I don't even need the limit comparison test

I can just directly check if the limit of my first function at infinity = 0

but does that prove if it converges?

nvm yeah of course it does

[novel knoll]

No it does not!

[hushed moat]

No

[hushed moat]

Do you know the p series test

[half halo]

ehhh

what

[novel knoll]

Have you seen sum 1/n?

Namely that it diverges

But lim n->inf of 1/n=0

So clearly not enough that limit is 0

[half halo]

now I'm confused

[novel knoll]

What?

Its likely like the first infinite series you ever saw

Called harmonic series, can see several proofs of divergence on wiki (or in your book)

[half halo]

am I misreading this then

if the limit at infinity of s sub n exists and is finite

Then the series is convergent

[novel knoll]

s_n is partial sum

Not lim n->inf of a_n

[half halo]

oh

[novel knoll]

Otherwise it would also be saying 1+1+1+… converges for example

[half halo]

I don't have an intuitive understanding of convergence/divergence

this entire unit confuses me

Also I'm not very good at limits

so should I turn the sum into a real expression?

oh wait frosty said p-series test

was my previous solution right?

[half halo]

this

I got through the whole limit comparison test but then I got confused because, now I know that my a_n function has the same behaviour as 1/(n^3, but I don't know what behaviour 1/(n^3) has

it's the same problem

[novel knoll]

Showing convergence/divergence of 1/n^3 is just reading p-test

And using it

[half halo]

oh

so for the limit comparison test

(I'm rewriting it now)

I just evaluate the limit of a_n divided by 1/(n^3)

If the result is > 0, then they have the same behaviour

and I use the p-series test to show that 1/(n^3) is convergent/divergent

[novel knoll]

Limit can’t be inf either, but yes

[half halo]

ehh

sorry what?

What do you mean by that

[novel knoll]

You said if lim greater than 0

Can’t be inf

[half halo]

Oh I meant if the result of evaluating the limit at infinity is greater than 0

Forgot to write that

wait

how do I do the p-series test

hold on let me look through my notes

so

exactly what does converging/diverging mean

okay

I got it

since 1/(n^3) is a p-series with p = 3 > 0, then 1/(n^3) converges, so by extension, my main function converges

?

ehh

how?

I don't understand

oh

[half halo]

okay so

If I have this limit:

I don't know where to go from here, for calculating it

It diverges

but

okay so, if the limit was n -> some finite number, I could take the limit from the left and right of that number to prove that it diverges

.close

[obtuse pebble]

Channel closed

Closed by @half halo

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

Since
5^2=25 and 5^-2=1/25
Does 5^-2= 1/5^2

[timid silo]

Because in math

If you make a equation multiplication, you have to make other division

like idk how to explain

i dont just go with the formula in math

I must know the reason behind it

[scarlet locust]

yes

In general

$$ a^{-n} = \frac{1}{a^n} $$

[timid silo]

so u just make the ^-2 into 2 and make the whole thing divide by 1/x

[warm shale]

Swas.py

[timid silo]

i dont understnad that

[timid silo]

ohh yes yes

[scarlet locust]

that's just latex

you don't need to understand it

[scarlet locust]

this is enough

[timid silo]

yeah

dang math is so interesting

.close

[obtuse pebble]

Channel closed

Closed by @sullen jungle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[teal horizon]

how do i do the opposite of this

[teal horizon]

i mean instead pf

minusing gx from fx

minus fx from gx

simple question but idk

i just did x^2-5-4

but apperantly thats not right

and i dont know why

[royal basin]

context?

[scarlet locust]

x^2-5-(-4)

[teal horizon]

area between two curves

they combined the graph

[teal horizon]

yeah but you dont have to times it tho do you

[royal basin]

okay so the parabola is below the horizontal

[brave bramble]

The picture performs f(x) - g(x)
And you want g(x) - f(x)?
Then g(x) - f(x) = x² - 5 - (-4)

But that's not the area between the curves ofc

[scarlet locust]

what is the horticultural

[teal horizon]

oh nvm i see what i did wrong

i didnt do - - 4

i did -4

[royal basin]

fuck

[teal horizon]

thank you

[royal basin]

horizontal

[teal horizon]

.close

[obtuse pebble]

Channel closed

Closed by @teal horizon

Use .reopen if this was a mistake.

[royal basin]

autocorrect did a fuck

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[slow viper]

Hi how to differentiate this one?

[robust sleet]

quotient rule

and chain rule for denumerator

[slow viper]

What does it mean when root x is down there

[robust sleet]

?

[slow viper]

I don’t know how to expand this equation

If I can expand it, I can use chain rule

[robust sleet]

oops no chain rule for denumerator

just quotient rule

[slow viper]

First, I wanna expand this equation

How can I do it?

Is it same as this one?

[robust sleet]

no

$\frac{a+b}{c} = \frac{a}{c} + \frac{b}{c}$

[warm shale]

Wew "Fractalogist" Tbh 🐧

[slow viper]

Wait how?

[robust sleet]

:/

third step is completely nonsense

[slow viper]

How can I make it without fraction

[robust sleet]

I'm sure u know

exponent laws

[slow viper]

I think third right part is okay,,,?

[robust sleet]

for first fraction

x^2sqrt(x)+2sqrt(x) is wrong

[slow viper]

Ya

But I don’t know how

[robust sleet]

use exponent rules

[timid silo]

$\frac{x^2}{\sqrt {x}}= x\sqrt{x}$

[warm shale]

Frustrated Cat

[timid silo]

Not x^2*sqrt(x) ig

[robust sleet]

yeah

[slow viper]

How this happen

[robust sleet]

rationalizing the denumerator

[timid silo]

$\frac {x^2}{\sqrt {x}}=\frac {x^2}{x^{0.5}}$

[robust sleet]

it's unnecessary tho, exponent laws work too

[warm shale]

Frustrated Cat

[timid silo]

Ya

[slow viper]

I got this, according to the exponential rule

[timid silo]

Ya

[slow viper]

Is this correct?

[timid silo]

$x^{\frac{3}{2}}= x^{1.5} = x^{1+0.5}= x * x^{0.5}=x*\sqrt {x}$

[warm shale]

Frustrated Cat

[timid silo]

It is

[slow viper]

I think I got it?

[timid silo]

Not really

$\frac {2}{\sqrt {x}}$

[warm shale]

Frustrated Cat

[timid silo]

How is that $2\sqrt {x}$

[warm shale]

Frustrated Cat

[slow viper]

Ah

Ya

[timid silo]

Now I think it's good!

[slow viper]

Wow! Thank you!

[slow viper]

.close

[obtuse pebble]

Channel closed

Closed by @slow viper

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wintry viper]

$\frac|{3x}{x^2-4} <= 1$

[wintry viper]

$\frac\absolutevalue{3x}{x^2-4} <= 1$

$\frac{3x}{x^2-4} <= 1$

[warm shale]

Lemsa

[compact shadow]

I see no question

[wintry viper]

sorry

Quadratic Inequality

[compact shadow]

Can you ask a complete question?

[wintry viper]

There's suppose to be an absolute value sign but I'm not sure how to do that

[compact shadow]

| something |

What is your question anyway?

[wintry viper]

my question? or what I need help with?

[compact shadow]

You claimed this channel, you need to ask a question

[wintry viper]

.close

[obtuse pebble]

Channel closed

Closed by @wintry viper

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[onyx turtle]

have a test in 5 mins plz help

what type of distrubituion would i use

i would do binomial right

p(5)=10C5 0.5^5 0.5^5

like that right?

someone plz help

yo

2 mins till test

can someone just wak me throhg it quick

[compact shadow]

I think it is $\sum_{i+j \geq 5} \binom{5}{i} \binom{5}{j} (\frac{1}{2})^{5} (\frac{1}{4})^{j} (\frac{3}{4})^{5-j}$

[onyx turtle]

what the

i never saw that in my life

[warm shale]

Cogwheels of the mind

[onyx turtle]

what are the j letters

[compact shadow]

I wrote index

[onyx turtle]

what does j represent

[compact shadow]

i,j are non-negative integers

Such that i+j>=5

[onyx turtle]

so what would that equation equal?

or do i do it multiple times

[compact shadow]

?

[onyx turtle]

andddd no more time i gtg

[compact shadow]

I didn’t give any equation

I gave you a number

7886/32768

Didn’t simplify

[obtuse pebble]

@onyx turtle Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[flat adder]

So I’m supposed to multiply by the reciprocal right

And then what

Oh then I just do dominating terms

Sqrt(3^2x)

(3^x)/(2*3^x)

[warm canopy]

You can divide top and bottom by 3^x to see this more clearly

[obtuse pebble]

@flat adder Has your question been resolved?

Channel closed

Closed by @flat adder

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[worthy linden]

I have a question on a homework question
Image
The following is finding the area between 2 curves
The answer is supposed to be positive 1/3 but I got negative
And I can’t figure out what I did wrong
Could someone help me out
I know that my original equation is correct due to my professor confirming integral from [0,1] and the equation of -2x^2 + 2x dx

[forest sinew]

,rotate 90

[forest sinew]

dont use u sub

my guess is this is where the sign error is

just polynomials id recommend splitting

[warm canopy]

you didnt change your limits when you did the u sub

they flip, hence the minus sign

[forest sinew]

oh

good spot

yea the u sub is unnecessary

@worthy linden

people sometimes recommend writing "x=..." in the limits when you do usub

to avoid this

[worthy linden]

good catch!

thank you!

[worthy linden]

thank you thank you

[obtuse pebble]

@worthy linden Has your question been resolved?

Channel closed

Closed by @worthy linden

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crystal nova]

How do you do this? (Statistics)

[crystal nova]

pls ping me when ur answering to me

[open sorrel]

You may try $$N\bar{x} = \sum x.$$

[warm shale]

vin100

[crystal nova]

huh?

Like We're doing mean, median and mode

using those method

s

[open sorrel]

there's a similar principle in physics

you hav an object

[crystal nova]

I'm in 8th and we havent learnt about that

[open sorrel]

placed on the table

[crystal nova]

Just using mode, median and mean

[open sorrel]

if the center of mass of the object doesn't exceed the table's edge then it won't fall down

[crystal nova]

mhm

i understand that

[open sorrel]

that's it.

[crystal nova]

wdym?

[warm canopy]

this isnt really relevant to their problem, you are going to confuse them

[crystal nova]

It's not the question

[crystal nova]

this is the question

[crystal nova]

yeah

[open sorrel]

it's a physical analogy to the concept of mean

[crystal nova]

yes but

i just want to know how to solve it

[warm canopy]

thats great and all, but not helpful for this problem and the level of maths this person it at

[crystal nova]

i know mean is basically the average

[open sorrel]

why not helpful? i'm gonna explain

[crystal nova]

I don't need to know it for this question

I just want to know how to solve it

[crystal nova]

Wait do I solve it by giving the experienced workers as x and inexperienced workers as y?

[open sorrel]

you can represent the object with its center of mass, which is one point

[crystal nova]

if that makes sense

[crystal nova]

It's not relevant to the question

[open sorrel]

that's a physical analogy

[crystal nova]

Yes but

I just want to know how to solve it

[open sorrel]

of the phenomenon that i've explained

[crystal nova]

huh

[open sorrel]

u need a find the root cause of the problem

[warm canopy]

@open sorrel you are obfuscating the question by talking about physics and centre of mass

[crystal nova]

yeah but it's not important here

[open sorrel]

the real problem is that you're not familiar with the role of the mean as the measure of central tendency

[crystal nova]

Mean is used to find the average.

[warm canopy]

please stop

[open sorrel]

anyone can use $$N\bar{x} = \sum x$$ to solve the problem, but how can you imagine that?

[warm shale]

vin100

[crystal nova]

huh??

[open sorrel]

why stop?

mean is a measure of central tendency

i'm just telling the truth

[warm canopy]

you are not using language of an appropriate level

[open sorrel]

The $\bar{x}$ is like the center of mass

[warm shale]

vin100

[crystal nova]

what

[crystal nova]

yeah im rlly confused rn

What's the x with the dash on the top?

[warm canopy]

@open sorrel how can you not see you have done nothing but cause confusion?

[open sorrel]

yes i'm explaining

[crystal nova]

vin

[open sorrel]

the physical interpretation of mean

[crystal nova]

i dont understand what youre saying

I dont need to know the physical interpretation of mean

I know mean is the average

in statistics

@open sorrel

Should I ping helpers?

[warm canopy]

you need to talk with people you're helping, not talk at them when they're clearly confused

[open sorrel]

$\bar{x}$ means average

[warm shale]

vin100

[crystal nova]

what

[open sorrel]

$N$ is the population size

[warm shale]

vin100

[crystal nova]

whats n

and where does population size come to play-

[open sorrel]

and $\sum x$ is the sum of data

[warm shale]

vin100

[crystal nova]

whats that

symbol

and " " x is the sum of data

okay im confused

im gonna ping helpers

[open sorrel]

in the first sentence, $N= 7 + 5 = 12$

and $$

[warm shale]

vin100

[crystal nova]

<@&286206848099549185>

[open sorrel]

and $\bar{x} = 1000$

[warm shale]

vin100

[crystal nova]

what

[warm canopy]

i apologise on @open sorrel 's behalf

[crystal nova]

yeah its ok

[open sorrel]

you're not me

why you apologize

i'm done nothing wrong

[chilly peak]

[crystal nova]

bruh

can someone help me?

[warm canopy]

sure

[open sorrel]

i'm helping

[warm canopy]

okay, good luck

[crystal nova]

?

[open sorrel]

so from the first sentence you already know that the sum of data is 1000 * 12 = 12000

[crystal nova]

Okay

wait what

okay yeah i got it

[open sorrel]

coz avg = sum of data / no. of population

[crystal nova]

7x + 5y = 12000

[timid silo]

in my school we learn this in 4th

[crystal nova]

we learnt this in 8th

[crystal nova]

ok so continue?

[timid silo]

ok so the total workers is 12

[crystal nova]

yes

[timid silo]

cuz 7+5

[crystal nova]

yeah yeah

[open sorrel]

it seems that you've got that

[crystal nova]

yes

[timid silo]

so the mean = sum of the observations/number of observations

[crystal nova]

yes

[open sorrel]

so you have the total sum

[crystal nova]

Or if i simplify

[crystal nova]

yes

[timid silo]

now the sum of the workers will be mean * number of workers

which is

[open sorrel]

and the sum of the 7 experienced workers

[timid silo]

1000x12

which is 12000

[crystal nova]

How did you find that?

[timid silo]

now the mean of the 5 inexpreienced workers is 846 right

[crystal nova]

yes

[open sorrel]

oops typo

[timid silo]

so thesum of inexperienced workers monthly wages is mean * number of inexperienced workers which is 846 * 5 = 4230

[open sorrel]

i mean the sum of salary of the 5 experienced

[crystal nova]

yes

okay so u subtract that

and devide that answer by 7

*divide

[timid silo]

so the sum of the 7 expreienced workers = sum of workers monthly ages - sum of 5 inexperienced workers

yes

[crystal nova]

okay

[open sorrel]

yes

[timid silo]

did u get it?

[crystal nova]

okay thanks

[timid silo]

np

[crystal nova]

lemme do the calculations

[timid silo]

alr

[crystal nova]

ty man!

[crystal nova]

ty !

[open sorrel]

u r welcome

[crystal nova]

.close

[obtuse pebble]

Channel closed

Closed by @crystal nova

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lethal spear]

$x\in\mathbb{R}$
$n\in\mathbb{N}$

affine function $mx+p$
$f^2(x)=f(f(x))$
$f^2(x)=m(mx+p)+p$
$f^{n+1}(x)=f^n(f(x))$

$f^0(x)=x$

"Find the only affine function f with m in N and p in N that verify the following property :
it exists n in $\mathbb{N}$ such that for every $x\in\mathbb{R}$, $f^n(x)=2048x-2047$"

how do i solve this?

[warm shale]

Arkitect

[lethal spear]

if the function was in ax+b form, a would be equal to $m^n$ and b to $\sum^{n}_{k=1}m^{n-k}$

[warm shale]

Arkitect

[obtuse pebble]

@lethal spear Has your question been resolved?

[obtuse pebble]

@lethal spear Has your question been resolved?

[obtuse pebble]

@lethal spear Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[median urchin]

<@&286206848099549185> can you explain to me how to explain this question and why its done like that https://media.discordapp.net/attachments/624319985027776514/968569540386652210/IMG_1795.jpg?width=956&height=379

[tardy epoch]

read

[median urchin]

sorry for @

I'm just a bit impatient. I've been annoying myself over this question all afternoon and I have done nothing all afternoon because I've been just looking for a answer for the question. I'm new to this topic.

<@&286206848099549185> Sorry I didn't wait 15 mins at first.

But now it has.

[short spruce]

...

you already pinged them

[median urchin]

Earlier yeah but once he told me to look at something I should have already I did said sorry and he left the channel so I didn't get help so 15 mins later I'm asking for help.

[fierce lagoon]

I mean once you did it, it's done

[median urchin]

Do you mean once I did the @ he wont check again?

[fierce lagoon]

Yup

[median urchin]

So what now?

[median urchin]

Shall I close this help channel and make a new one but it will get me banned? Tbh this is the only way I can think of getting help.

Because I wont get a answer from @.

[thick fog]

Honestly I would say these kind of questions rarely get answered either way. Long word problems with geometry are an automatic nope for a lot of people.

[median urchin]

ok so just don't bother

.close

[obtuse pebble]

Channel closed

Closed by @median urchin

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[signal cobalt]

I need some idea on this problem

[obtuse pebble]

@signal cobalt Has your question been resolved?

[thick fog]

I would probably start by multiplying row 1 by a, row 2 by -b, row 3 by -c and row 4 by -d then adding them all to row 1 and use that with the fact that the sum of squares is nonzero to eliminate everything else in the first column to see if anything nice comes out of it.

[signal cobalt]

ok thanks

.close

[obtuse pebble]

Channel closed

Closed by @signal cobalt

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wintry stream]

how do i solve this?

[obtuse pebble]

@wintry stream Has your question been resolved?

[haughty coyote]

p(3x-9) is convergent iff 3x-9 is in (-1, 1]

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[subtle monolith]

654.875 = 500+105*(3-1)(0.7025+0.0175(3-1))
I just want to understand how this is equal to 654.875

[fierce lagoon]

Ever heard of order of operations?

It just does

Quite literally if you out it into a calculator, it just is

[subtle monolith]

well, when I try to do them, I get answers over 1000 🤮

[fierce lagoon]

Hold up

You prob did some error

What's the original question

Like

Where did such a calculation come from

[subtle monolith]

formula for armor and HP from league

ActualValue=BaseStat+GrowthStat*(Level-1)(0.7025+0.0175(Level-1))

this is the formula

[fierce lagoon]

League of Mid

Uh

[subtle monolith]

its to calculate Akali HP at level 3

[fierce lagoon]

,calculate 500 + 105(3-1)(0.7025+0.0175(3-1))

[warm shale]

The following error occured while calculating:
Error: Undefined symbol ulate

[fierce lagoon]

Fuck yiu

You did some error

[subtle monolith]

well its nice to see I can plug it into calculator and it works

what is the first order?

[fierce lagoon]

Parenthesis

So the 3-1

$,calculate 500 + 105(3-1)(0.7025+0.0175(3-1))$

Fuck

[warm shale]

Umbraleviathan

[fierce lagoon]

Uh

$500 + 105(2)(0.7025+0.0175(2))$

[warm shale]

Umbraleviathan

[fierce lagoon]

Then you wojld do parenthesis again

$500 + 105(2)(0.7025+0.035)$

[warm shale]

Umbraleviathan

[fierce lagoon]

$500 + 105(2)(0.7355)$

[warm shale]

Umbraleviathan

[fierce lagoon]

$500 + 105(1.471)$

[warm shale]

Umbraleviathan

[fierce lagoon]

$500+154.455$

[warm shale]

Umbraleviathan

[fierce lagoon]

$654.445$

[warm shale]

Umbraleviathan

[fierce lagoon]

Hold up

[subtle monolith]

you still helped me find my mistake; but yeah;

[fierce lagoon]

Should be 0.7375

My bad

Then it'll get 654.875

[subtle monolith]

it's fine, I added .7025 to 0.0175 before multiplying

[fierce lagoon]

Bruh moment

[subtle monolith]

thanks man XD

Google actually, adds a bracket, so that idiots like me don't do that

It has one extra bracket, exactly there XD

[obtuse pebble]

@subtle monolith Has your question been resolved?

[subtle monolith]

yes

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dark vapor]

I have this math problem and I'm struggling to figure out where I'm going wrong so I can figure out what to fix

[obtuse pebble]

@dark vapor Has your question been resolved?

[dark vapor]

<@&286206848099549185>, so sorry for the ping

[obtuse pebble]

@dark vapor Has your question been resolved?

[dark vapor]

😭

[little scarab]

@dark vapor how do you get sin?

$\cos(x) = \sum_{n=0}^{\infty} (-1)^n \frac{x^{2n}}{(2n)!} = 1- \frac{x^2}{2!}$

[warm shale]

jixana

[little scarab]

so $P_2(x) = 1-\frac{x^2}{2!}$ and $P(0.2) = 0.98$

[warm shale]

jixana

[little scarab]

so your error is $\abs{\cos(0.2) - 0.98}$

[warm shale]

jixana

[dark vapor]

I think the error used a different formula tho? The formula is like

[little scarab]

its inside abs value, it makes no difference about the order

[dark vapor]

No like there’s a formula where we have to find M

[little scarab]

in your picture its written as $\abs{P_2(x) - \cos(x)}$

[warm shale]

jixana

[dark vapor]

It’s called remainder estimation theorem

It’s like $R_n(x)\leq{M|x-a|^(n+1)/(n+1)!}$

[warm shale]

shadowpoet

[dark vapor]

Okay that sucks here is a pic

Where x_0 is actually the a tho

[dark vapor]

I got sin bc I was using the derivative, should it be 1 where I put the sin(.2)?

[little scarab]

yeah so error = $\abs{\frac{f^3(c)}{3!}x^3}$ at $x=0.2$, and $\abs{f^3(x)}\leq 1$ for all x, so $\frac{1}{3!}|0.2|^3$ would be the error

[warm shale]

jixana

[dark vapor]

Okay cool so I just messed up the sin(.2) there? I had a feeling it was 1 bc f(x)= cos(x) and cos(0) is 1 (the center is 0). Idk why I went with sin(.2)

Ty

Idk if you can help with the second part but if you or anyone else knows

The formula is different, it’s the alternating series remainder theorem and idk if I did that one right

[obtuse pebble]

@dark vapor Has your question been resolved?

[dark vapor]

ty for asking bot, no it hasnt 😭

[dark vapor]

maybe I need to refine my question now

I have this math problem and I need help with the second part. Like I'm not sure if I'm doing it right? it involves finding error using alternating series remainder theorem and I just want to make sure I'm doing it right

<@&286206848099549185>

[dark vapor]

sad

.close

[obtuse pebble]

Channel closed

Closed by @dark vapor

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cursive forge]

also want a hint in the direction of how to prove that summing a function over a set is the same as integration wrt the counting measure. not sure how to go about it except from going from definitions and proving that the two sups are equal

[obtuse pebble]

@cursive forge Has your question been resolved?

[astral ivy]

try #advanced-analysis @cursive forge

Or whatever channel this is relevant to

[obtuse pebble]

@cursive forge Has your question been resolved?

Channel closed

Closed by @cursive forge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[naive root]

can anyone help me with b)?

[naive root]

<@&286206848099549185>

[obtuse pebble]

@naive root Has your question been resolved?

[obtuse pebble]

@naive root Has your question been resolved?

Channel closed

Closed by @naive root

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[glossy sparrow]

hello

[glossy sparrow]

how do i find F(g(11))

assuming t is 11

[robust sleet]

u know composite fuck tons?

functions

[last basalt]

robic

What's wrong

replace x by 4t+52

In f(x)

[glossy sparrow]

do i do that before applying chain rule

[austere knot]

or just solve g(11)

and then f(the number you got)

[last basalt]

No there's more to the problem

He needs to take the derivative

Of the composite

[austere knot]

ah

I see

[last basalt]

Yeah

1/3 (t^2 + 2 t + 7)

Then you can take derivative and evaluate at 11 for the rate

[obtuse pebble]

@glossy sparrow Has your question been resolved?

[timid silo]

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[broken knoll]

so I thought of this question by myself
"1^x=-1,find x"
i tried to solve it, but the answer I derived seems kinda weird
it turned out to be a real number but shouldn't it be an imaginary?
process:

[timid silo]

$1^x=-1$

[warm shale]

Frustrated Cat

[timid silo]

Ya it's ofc imaginary

[lucid flame]

it's true

because 1^(1/2) = + or -1

[timid silo]

oh they didn't meant the x we are talking about tho

Oh wait they did

[timid silo]

No?

[lucid flame]

it is

if you look at both roots of unity

[timid silo]

,w calculate 1^(1/2)

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Frustrated Cat#5213

[timid silo]

See

[lucid flame]

they were interpreting it as sqrt

but we're talking about the ^(1/2)

[timid silo]

$1^{\frac {1}{2}}=\sqrt {1}$ only ig

[warm shale]

Frustrated Cat

[lucid flame]

ok, here's the thing

would you agree that $e^{\pi i}=-1$

[warm shale]

R31_

[timid silo]

Ya

[broken knoll]

I have sth to deal with right now be back later

[warm shale]

R31_

[timid silo]

No

[lucid flame]

whoops

wait lemme redo this

would you agree that $e^{2\pi i}=1$

[warm shale]

R31_

[timid silo]

Ya

[lucid flame]

raise both sides by 1/2

[timid silo]

$e^{ipi}=1^{\frac {1}{2}}$

[warm shale]

Frustrated Cat

[timid silo]

But if 1^(1/2) can he both positive and negative

Then e^(i*pi) can also be both positive and negatice

[lucid flame]

it can't

[timid silo]

But 1^(1/2) is + and - according to u

[lucid flame]

-1 is the 2nd root of unity

doesn't mean that all the 2nd root of unity is -1

same thing with 1^1/3

[timid silo]

Oh

,w calculate 1^x=-1

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Frustrated Cat#5213

[timid silo]

First time i am seeing this result

From wolframalpha

Including this two calculators said no real number solutions

[lucid flame]

it's like asking x^2=1

x=1 and -1

[timid silo]

Ya

[lucid flame]

also,

w, calculate 1^x = (-1)^(1/x)

,w calculate 1^x = (-1)^(1/x)

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by R31_#9293

[lucid flame]

whoops

,w calculate 1 = (-1)^(1/x)

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by R31_#9293

[lucid flame]

it just depends on how you interpret 1^(1/2)

like the equation x^2=1

if you raise both sides by 1/2, x=1^(1/2)

in this case, it should be the 2nd root of unity

[timid silo]

I get it human

[obtuse pebble]

@broken knoll Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[worthy vapor]

Hello, can anyone explain how variance work. Is this correct or no?

$\begin{aligned}R_{i}=B_{i}=Var\left( x\right) \ y=11R_{i}-9B_{i}\ Var\left( y\right) =11^{2}Var(x)-9^{2}\cdot Var(x)\end{aligned}$

[warm shale]

joshjson

[worthy vapor]

.close

[obtuse pebble]

Channel closed

Closed by @worthy vapor

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rose estuary]

I'm having trouble where to start on this one <@&286206848099549185>

[warm canopy]

,rccw

[warm canopy]

do you have any general equations for projectile motion at your disposal?

[rose estuary]

Nvm

Thank for your assistance but I have figured it out

[warm canopy]

good job!

[obtuse pebble]

@rose estuary Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[odd stag]

since there exist homeomorphism from (0,1) to the real line, does that imply that there also exist one from [0,1] to the extended real line?

[warm canopy]

do you know any other interval that is homeomorphic to the extended real line?

[royal basin]

yes

[odd stag]

thanks

.close

[obtuse pebble]

Channel closed

Closed by @odd stag

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[half perch]

if Ax=b what is range and the domain?

[half perch]

here the range is in A and x is the domain?

[warm canopy]

what is A?

[half perch]

A is a matrix

I just need to understand the last secentence

[warm canopy]

they are viewing A as a function from $\mathbb{R}^n \to \mathbb{R}^n$

[warm shale]

iCaird

[warm canopy]

the range is just $A(\mathbb{R}^n)$, everything you can get to by applying A to elements of $\mathbb{R}^n$

[warm shale]

iCaird

[warm canopy]

$\mathbb{R}^n$ is the domain

[warm shale]

iCaird

[half perch]

So if i change my basis then the range changes to that basis? and the domain can change because i can go from r^2 to r^3 or something.

[warm canopy]

the range stays the same, they are just expressing it in a different basis

[half perch]

If i multiply a 3x2 to a 2x3 then I get 3x3 and that increases the range doesnt it?

[warm canopy]

sure but thats equivalent to composing two functions, which is not whats happening here, we have a single map represented by the matrix A, we are choosing to write the range in a different basis so that the matrix representing our map is diagonal

[half perch]

Thank you got the point

[warm canopy]

Nice:)

[half perch]

.close

[obtuse pebble]

Channel closed

Closed by @half perch

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[half perch]

Ok if i change the domain and range of a A by a basis change i get a diagonal matrix. For example if i change by basis to the eigenvectors then i get a diagonal matrix of the eigenvalues.

[half perch]

Why is this important about the diagnolization?

The book just tells it with no futher context

[warm canopy]

if we can find a basis that diagonalises A, then calculations become alot easier given that the basis elements are eigenvectors so we just scale up basis elements

another reason is that is you can diagonalise a matrix, then it becomes alot easier to calculate powers of A

[half perch]

So calculations become easier. Got it thanks again.

.close

[obtuse pebble]

Channel closed

Closed by @half perch

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[knotty canyon]

If anyone could help me with this please

[versed turret]

What is the area of that one triangle in that Octagon?

[knotty canyon]

thats where im struggling, not sure how to get the area if i only have the two sides being 4cm

Cause its the answer is just the difference between the octagon and circle

[chrome mesa]

You also know the angles

[teal prawn]

and the area of an isosceles triangle is [r^2 sin(theta)]/2 where theta is the angle between the two equal sides
use this as you see fit, you can look up the derivation if you want

[chrome mesa]

no spoonfeeding please

[knotty canyon]

what formula is that?

.close

[obtuse pebble]

Channel closed

Closed by @knotty canyon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[acoustic mulch]

.reopen

.open

[main cargo]

i got that

however for the next one

i thought it would be e^i(pi/9 + 2pi/3)

why is it 4pi not 2 pi?/

like for the z1, we added 2pi/2

so for z2 we should add 2pi/3. no?

OMG

is it to do with 3rd quadrant

om ggggg

.close

[obtuse pebble]

Channel closed

Closed by @main cargo

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lilac glacier]

How do I show that ( 2Z, +, . ) is not a ring with unity

[lilac glacier]

is it sufficient to just say that there exists no element 'a' in 2Z that follows a.b = b.a = b

[obtuse pebble]

@lilac glacier Has your question been resolved?

[lilac glacier]

<@&286206848099549185>

.close

[obtuse pebble]

Channel closed

Closed by @lilac glacier

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[violet heath]

Hi! I have a question. How am I supposed to find cos α, if my sin α=0.6? If possible please explain how to find it❤️

[brave bramble]

sin²(a) + cos²(a) = 1

[violet heath]

How does this work?

[brave bramble]

Never seen the Pythagorean identity before?

Give that a Google

[violet heath]

Never heard of it and got assigned to do this... Thanks though

.close

[obtuse pebble]

Channel closed

Closed by @violet heath

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[obsidian isle]

,w div(5z^2x, 5y^3/3+tan(z), 5x^2z+3y^2)

[warm shale]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by EndTimes#8053

[obsidian isle]

5(x^2+y^2+z^2) = 5

now if we set up the integral in spherical coordinates:

$\int_0^{2\pi} \int_0^{\frac{\pi}{2}} \int_0^1 5\rho^2 \sin\phi d\rho d\phi d\theta$

which gives me the wrong answer

[warm shale]

EndTimes

[obsidian isle]

what the fuck

[warm canopy]

whats is the correct answer

it looks like you've entered it with a minus sign error

[obsidian isle]

i tried both

i don't know what the correct answer is

[warm canopy]

try 0

[obsidian isle]

already did

[warm canopy]

strange

[obtuse pebble]

@obsidian isle Has your question been resolved?

[obtuse pebble]

@obsidian isle Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[misty valve]

I know it's displacement

How do I take the absolute value of the velocity function and then integrate it?

Cuz I tried changing all minus signs to plus signs and then integrating but that got me a wrong answer

[obtuse pebble]

@misty valve Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[storm bay]

There's a bowl with 8 white and 2 black pearls. And we randomly pick 5 pearls.

What's the chance that exactly 1 out of the 5 pearls are black?

[burnt ore]

so the chance of picking a black pearl once is 2/10=1/5

but then the other 4 times you'd have to pick white

right?

@storm bay

[storm bay]

You can pick in whatever order I guess

[burnt ore]

OK but the same rule goes

you have tk pick black once

and white 4 times

in whatever order

[storm bay]

And then multiply them?

The chances

[burnt ore]

yes

so chance of picking a black pearl is?

ugh white I mean

you tell me

[storm bay]

White is 8/10

[burnt ore]

so it's (1/5)(4/5)^4

8/10=4/5

you understand?

[storm bay]

It doesn't give the right answer tho

[burnt ore]

what is the answer?

of the q?

[storm bay]

5/9

[little scarab]

its ((2 choose 1) * (8 choose 4))/(10 choose 5)

which is 5/9

[storm bay]

What's choose

Wtf

[little scarab]

binomial coefficients

$\binom{n}{k} = \frac{n!}{k!(n-k)!}$

[warm shale]

jixana

[burnt ore]

huh

OK sorry my bad

[storm bay]

That's not how this task is supposed to be solved tho

That's a different chapter

[little scarab]

what chapter are you on right now

[burnt ore]

I feel like there is an easier way

[storm bay]

It's normal probability math

U shouldn't need binomial stuff for this

I haven't even learned it yet lol

And I don't think we're gonna learn it either cause our math teacher skipped that part it seems

[little scarab]

lol what this is one of the fundamental stuffs you need for probability

[storm bay]

There must be an easier way tho

To find the probability that all the five pearls are white you just multiply like this: (8/10)*(7/9)*(6/8)*(5/7)*(4/6)=2/9

To find the probability that AT LEAST one of them is black, you just do 1-(2/9)=7/9

But how do you find the probability that EXACTLY one of the five are black?

There's no way this last part of the task is so much harder

Holy shit I figured it out

[storm bay]

There must be an easier way to write this though..

That took forever

[obtuse pebble]

@storm bay Has your question been resolved?

[storm bay]

My last question would be if there's a way to simplify what I wrote in the image above?

[tacit crest]

Should I take log?

<@&286206848099549185>

[haughty coyote]

Ask in your own channel and wait 15 min before pinging helpers

[tardy epoch]

what mateo said. read #❓how-to-get-help

[tacit crest]

I am new
Didn't knew

[obtuse pebble]

@storm bay Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fervent axle]

How do I do part ii

[fervent axle]

I'm not particularly sure where to start. I have the mark scheme but I don;t understand what they've done

[warm canopy]

what direction is the 100N force being applied from the weight of the rod?

[fervent axle]

Down ig?

[warm canopy]

yeah

and what about the reaction force from C?

[fervent axle]

Straight up

[warm canopy]

yep

we need the forces acting down to equal the forces acting up

so what do you think the reaction force from D should be?

[fervent axle]

25

[warm canopy]

yes well done

[fervent axle]

Thanks. I just don't get why I can't multiply 3.5 by 0.75 and that be x

I mean that's obviously stupid but I can't really picture how it works

So for part ii the answer is 1.875 but idk how to get it

[fervent axle]

<@&286206848099549185> Any ideas?

Well I imagine you have got ideas. But I would like them shared pls

[obtuse pebble]

@fervent axle Has your question been resolved?

[fervent axle]

.close

[obtuse pebble]

Channel closed

Closed by @fervent axle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rotund vector]

I can’t seem to solve for “a” in this inequality, I’ve tried and I got a < -2.8 and it says this is wrong

[rotund vector]

Here’s what I did to get my answer

[obtuse pebble]

@rotund vector Has your question been resolved?

[warm canopy]

How come you put a minus sign infront of the 2.8?

Also check what 156/20 is

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vague sinew]

hello

[vague sinew]

need help with rational expressions

simplify 16xy^4z^6 / 24x^3y^2z

<@&286206848099549185>

[short spruce]

• After 15 minutes, feel free to ping @Helpers.

what have you tried

[obtuse pebble]

@vague sinew Has your question been resolved?

[strong sinew]

$\frac{16xy^{4z}^{6}}{24x^{3y^{2z}}$

[vague sinew]

z is not squared in the numerator

[strong sinew]

Is it multiplication?

You used ^

[vague sinew]

z to the power of 6

[strong sinew]

$\frac{{16xy}^{4z^{6}}}{{24x}^{3y^{2z}}}$

[warm shale]

idk7

[strong sinew]

This?

[vague sinew]

i think so yes

[short spruce]

$\frac{16xy^4z^6}{24x^3y^2z}$

[warm shale]

a disappointing son

[short spruce]

you sure it's not this?

[vague sinew]

yep this is it

fixed

[strong sinew]

Oh better

[vague sinew]

my answer so far is 2y^2z^5/3x^-2

idk if its correct or not

$\frac{2y^2z^5}{3x^-2}$

[warm shale]

Godnut

[vague sinew]

thoughts?

[obtuse pebble]

@vague sinew Has your question been resolved?

[obtuse pebble]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid silo]

Hi! I need some help to simplify this

[timid silo]

I am not sure if the last step is correct

should the v have been inverted?

and the 2/3 be negative

help please

[grizzled igloo]

pretty sure this is the answer i have to go eat rn but maybe itll help\

[timid silo]

thank you

[obtuse pebble]

@timid silo Has your question been resolved?

Channel closed

Closed by @pure nest

Use .reopen if this was a mistake.

[obtuse pebble]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hybrid valve]

please help

[compact shadow]

Let v=arcsin(x^2-1/4) you will have sin(v)=cos(π/2 -v)=x^4 and sin(v)=x^2-1/4

Quadratic function of x^2, the rest is clear

[hybrid valve]

i see

thank you

.close

[obtuse pebble]

Channel closed

Closed by @hybrid valve

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rain socket]

If 𝜃 is small enough to regard 4𝜃 as small, what is the approximation for the following expression:

2𝜃 / sin4𝜃

[rain socket]

I posted this earlier but i couldnt approximate it

what is the significance of this line? "If 𝜃 is small enough to regard 4𝜃 as small"

[civic zealot]

for small enough values sin(x) is approximately x

small meaning close to 0