azeem321
#help-10
warm shaleBOT
sturdy ledge
also the negtaive
strong vale
Yeh let's focus on the postive first
if we add pi to these values
will get another solution between 0,2pi
sturdy ledge
oh my thank you s much now I understand it now
strong vale
So keep adding pi's to you get all solutions in the domain the question gave
and do the same for the negative
strong vale
it happens
sturdy ledge
yah I'm sorry and thank you so much
timid silo
obtuse pebbleBOT
timid silo
That's the first derivative
graph of 4x^3+3x^2+2x
that's the second derivative right?
obtuse pebbleBOT
@neon bronze Has your question been resolved?
tardy epoch
Yes
obtuse pebbleBOT
@neon bronze Has your question been resolved?
obtuse pebbleBOT
@neon bronze Has your question been resolved?
hybrid gull
Just close this channel and reopen a new one or ask again
tired tartan
Can someone explain me the following statements?
obtuse pebbleBOT
Can someone explain me the following statements?
gilded needle
for the first one, do there exist two scalars a and b, such that (1/2)v = av + bw?
tired tartan
No
gilded needle
why not?
tired tartan
There is no info about it
civic zealot
So you can't pick an a or b that make that equation true?
tired tartan
A yes I can
civic zealot
the by definition, 1/2 v is a linear combination of v and w
gilded needle
A yes I can
what choice of a and b makes it true?
obtuse pebbleBOT
@tired tartan Has your question been resolved?
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
warm hawk
obtuse pebbleBOT
polar elbow
do u know how to get the inverse of a function?
hearty terrace
.close
hearty terrace
what
hearty terrace
ah i see
hearty terrace
isn't the inverse of an inverse function just itself or am i tripping
warm hawk
hearty terrace
and for the first question the two "cancel," because they do the opposite action
warm hawk
you are not tripping
what would questio 12 be
like its the inverse of the inverse?
of 1
hearty terrace
i mean
hearty terrace
isn't the inverse of an inverse function just itself or am i tripping
this one was in response to question 12 not 11 but yeah lol
hearty terrace
if you do the inverse of an inverse function that just might be f(1) im not sure though
i meant that f^-1(f^-1(x))=f(x)
i think, it's been too long
timid pelican
the first step is to find f^-1(1)
hearty terrace
i meant that f^-1(f^-1(x))=f(x)
i say here
sacred sandal
I'm having trouble understanding this following question: "suppose that the echelon form of an augmented matrix has a pivot position in every column except the right most one. how many solutions does the associated linear system have?" The back of the book states that such a system of equations should have exactly one solution but I am trouble seeing how that is true in a general sense. Couldn't such an equation have multiple solutions given there is a free variable or maybe no solutions at all if the system is inconsistent? I might be misunderstanding the question 😅
obtuse pebbleBOT
I'm having trouble understanding this following question: "suppose that the eche...
mental solstice
i feel this is better served if you write out an example matrix
like just come up with an echelon form matrix that fits what you have, and then study that matrix
obtuse pebbleBOT
@sacred sandal Has your question been resolved?
sacred sandal
So I found this arbitrary matrix online that I would like to refer to as an example in echelon form (I don't have my phone on me to send a picture per say at the moment) but in reference to this matrix, it has a zero row at the bottom and no pivot positions on the rightmost column as the question states. Looking at this specific matrix, one could say that there will be free variables...? Wouldn't that imply that there is infinitely many solutions rather than just exactly one solution?
I might be totally misunderstanding though lol
mental solstice
i think you just didn't read the question carefully
there's a certain part you missed
sacred sandal
Wait where might that be 😭 ?
I see echelon form, augmented matrix, and there exists a pivot position in every column with exception to the rightmost one as the conditions for this question; I might have missed a subtlety somewhere
mental solstice
indeed you did, though i dunno if i'd call it a subtlety
there exists a pivot position, where, exactly?
sacred sandal
in every column with exception to the rightmost one..right?
mental solstice
yepp
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
sonic ginkgo
How do I write 5=logb32 in it's equivalent exponential form?
obtuse pebbleBOT
How do I write 5=logb32 in it's equivalent exponential form?
fervent comet
How do I write 5=logb32 in it's equivalent exponential form?
You’ll need to know two forms
a^b=c
b=log_a(c)
Using this, convert it into a^b=c form
@sonic ginkgo
sonic ginkgo
Alright I'll try
So is b of the base of log equal to 10?
Wait nvm that's probably not important
So ngl I'm not getting the answer
I assumed need to rewrite it as 5=log_8(4) but i rewrote it as a^b=c and got 8^5=4 which is not right
Oh wait is it b^5=32
sonic ginkgo
How do I simplify ln_e^(13x)?
obtuse pebbleBOT
How do I simplify ln_e^(13x)?
glossy ibex
$ln(e^{13x})$
warm shaleBOT
DETOX (143 🍓)
glossy ibex
?
sonic ginkgo
Yep
warm shaleBOT
DETOX (143 🍓)
sonic ginkgo
So I just need to rearrange it?
glossy ibex
ln(x) and e^x are inverse of each other
they cancel out
$\ln(e^x)=x \implies \ln(e^{13x}) = 13x$
warm shaleBOT
DETOX (143 🍓)
sonic ginkgo
So thats it's simplified form?
glossy ibex
ancient raven
$\exists!x\in\mathbb{C},x^2=-1$
obtuse pebbleBOT
$\exists!x\in\mathbb{C},x^2=-1$
warm shaleBOT
andrewFTW8
ancient raven
Why is this false?
sterile wyvern
What about i?
ancient raven
What about i?
Well, I'm doing some problems for logic and the says it's logically false
Why is that?
sterile wyvern
Because i^2=-1 in C
ancient raven
Is there more than one number in the complex domain for which the proposition is true
$\exists!x\in\mathbb{C},x^2=-1$
warm shaleBOT
andrewFTW8
ancient raven
it's supposed to be written like this sorry
sterile wyvern
Oh now I see, I misunderstood
Then
x^2=-1=i^2
<=> x^2 - i^2 = 0
<=> (x-i)(x+i)=0
<=> x=i or x=-i
The last line because C is a field
obtuse pebbleBOT
@ancient raven Has your question been resolved?
verbal ermine
“Find the volume generated when the region bounded by y=sqrt(x), y=2, and x=0 is rotated about the vertical line x=4”.
obtuse pebbleBOT
“Find the volume generated when the region bounded by y=sqrt(x), y=2, and x=0 is...
verbal ermine
I am quite confused as I am just learning this
I am assuming we end up with something like
pi int[0,2] (4-y^2)dy ?
balmy mortar
First step is to draw the graph and mark the region
verbal ermine
and then I just solve that out
balmy mortar
After you do that, specially mark the axis of rotation
verbal ermine
Mhmm I got that
balmy mortar
hard for me to answer when im also picturing it in my head - are you able to share your diagram?
verbal ermine
balmy mortar
and which section
verbal ermine
I think it was something like pi(R-r)^2
verbal ermine
and which section
The section touching the y axis
balmy mortar
top left, yes
balmy mortar
I think it was something like pi(R-r)^2
and this sounds right.... for more visualisation
verbal ermine
but I was confused on finding R and r
balmy mortar
draw a varying horizontal line
y = a
0 < a < 2
slider on desmos
thats how you are integrating I believe
And then figure out the corresponding discs involved for each horizontal line
So for a particular height y, you need to figure out what the 2 radii are
The biggest one is 4.
But then the smaller one...
it is the horizontal distance from x = 4 to the function
verbal ermine
Is just sqrtx or y^2 since we are doing with dy?
balmy mortar
,, \pi\int^2_0R(y)^2-r(y)^2 ,\dd y
warm shaleBOT
balmy mortar
I like writing like this
and determining what the functions are so I am clear in my working
and sure of the answer
,, \pi\int^2_04^2-r(y)^2 ,\dd y
warm shaleBOT
balmy mortar
Lets see for r(y)
If you are y up, your x coord is y^2
so the distance is 4 - y^2, I agree
In particular if you are at (x, y) on the function
the little radius is 4-x
so what you did sounds right
,, \pi\int^2_04^2-(4-y^2)^2 ,\dd y
warm shaleBOT
verbal ermine
Okay lol I was about to be so confused
balmy mortar
I think it was something like pi(R-r)^2
I think I disagree with this
uhhh let me adjust this diagram
verbal ermine
Whaa I mean I was basically just saying this but a little different?
balmy mortar
i think it is not quite there but one sec, desmos
Ok you agree it is this? spinning around the blue line
We need to calculate the volume of the purple region rotated around it
verbal ermine
Mhmm
balmy mortar
So imagine that black line sliding up and down
We are adding the corresponding annulus
for each of the black line... does that make sense?
verbal ermine
What’s annulus 
verbal ermine
Ye
balmy mortar
disc is the area enclosed by a circle
annulus is if you subtract 1 disc from another
like a ring
2d donut
verbal ermine
Okay yeah makes sense
balmy mortar
and we want that right
So to calculate that we need to subtract the area of one circle from another
We cannot just calculate the area of a circle whose radius is equal to the difference
vary the a slider
that black line is R-r
but pi(R-r)^2 isnt what we need
verbal ermine
Mhm?
balmy mortar
Take this example
to calculate the green region area
You dont just do
pi(3 - 2)^2
that would be the area of a circle of radius 1
but its not quite that
you do
pi(3^2 - 2^2)
You subtract the area of one circle from another
warm shaleBOT
balmy mortar
,, \pi\int^2_0R(y)^2-r(y)^2 ,\dd y\neq \pi\int^2_0(R(y)-r(y))^2 ,\dd y
warm shaleBOT
verbal ermine
yes
I don’t know how to explain the thing I was doing but either way it was not correct
balmy mortar
But also, I think you didnt quite get r(y) right the first time round
yh
Well i highly advise drawing a diagram for these Qs
and identify the axis of rotation
as well as youre slicing
and that will cause less confusion
balmy mortar
https://www.desmos.com/calculator/jv7nf3denj
you need to visualize something like this on paper, basically
verbal ermine
and yeah I don’t get how you got 4^2 - (4 - y^2)^2 still
verbal ermine
you need to visualize something like this on paper, basically
I can do that but I don’t get how r = 4-y^2?
balmy mortar
right ok
Can you edit this picture
and mark on an R
and an r
for arbritrary y
verbal ermine
Uhh i think ik what means but idk
verbal ermine
balmy mortar
no
We talk about r and R, the radius,
first you need to identify the centre
'radius' doesn't make sense without realizing where the center must be
And then if it is a radius, it should start from the center
balmy mortar
Right so if y = 1
the center is (4, 1)
So R refers to the radius going from (4,1) to (0,1)
What about r?
verbal ermine
(4,1) to y^2
balmy mortar
(1, 1)
Does it make sense why this is r
because we want to subtract the smaller disc
balmy mortar
Ok, and then try figuring out what r(y)
is from this
referring to this
R = 3
r = 2
You dont want r = 1
verbal ermine
r = 0-2
balmy mortar
https://www.desmos.com/calculator/jv7nf3denj
The black line marked here represents R-r
And you need to imagine rotating it around x = 4
balmy mortar
https://media.discordapp.net/attachments/903430332324405288/953990488816488478/S...
this creates an annulus like this
And we get a different annulus for every single y between 0 and 2
The resulting solid we get is like
Approximately (the rim should be sharp)
Flip this upside down, and we are slicing this up horizontally
verbal ermine
I think I got a much better understanding but I gotta go to my next class
I appreciate the help
.close
earnest mist
I'm confused on how to convert 1506 (base 10) to base 11
obtuse pebbleBOT
I'm confused on how to convert 1506 (base 10) to base 11
earnest mist
I have been doing it like this for other base conversions
This is base 3 to base 10
Is there a similar way to do this for base 10 to 11
obtuse pebbleBOT
@earnest mist Has your question been resolved?
royal basin
if you know the powers of ten in base 11 and can do arithmetic in base 11 then yes
obtuse pebbleBOT
@earnest mist Has your question been resolved?
earnest mist
I'm more confused about the unknown variable
I know I have to create a new symbol for extra digits because base 11 has more digits than base 10
But I don't get how to implement that
tall turtle
the unknown variable?
tall turtle
also the first digit in base 10 should be 11^3
the second is 11^2
the units digit should always be 1's
and the second digit from the right should be the base #^1
earnest mist
the unknown variable?
This is in the question I am trying to answer
1506 to base 11 [hint: you will need to "make up" a new symbol for extra digits, since base 11 has more digits than base 10]
This is what I'm confused about
tall turtle
oh hm
i think you can ignore that kind of?
so what they mean is theres 11 digits in base 11
and 10 digits in base 10
base 10 digits are 0, 1, 2, ..., 9
base 11 is 0, 1, 2,.., 9, and then another symbol for another digit
earnest mist
i think you can ignore that kind of?
so you don't think it applies to this question?
tall turtle
oh
earnest mist
114a
earnest mist
but why is it needed?
tall turtle
so in base 10
all the numbers can be written using the 10 digits
but since base 11 has 11 digits
you need to make up a new digit
tall turtle
yeah i think so
i take this back btw i wasnt thinking
earnest mist
you need to make up a new digit
is it replacing a number?
or are we just simply writing it for the heck of it
idk why this is so hard for me to wrap my head around
tall turtle
so why don't we think about it in base 2
so base 2 has 2 digits
0 and 1
so a number could be 101010
but if you want to convert that to base 2
ok ykw lets use a smaller number
convert 1000 in base 2 to base 3
so thats
uh
21
thats 21 in base 3
and the 2
that wasn't in base 2
is the same as the A that we added in base 11
im not sure if im making this more complicated
but we're just creating a symbol that is 1 more than 10
so that it could be 11 in base 11
like A in base 11 would be 11 in base 10
does that make sense?
earnest mist
but we're just creating a symbol that is 1 more than 10
I think this makes sense to me
tall turtle
👍
so for base 12 for example
we might create another symbol B that is 12 in base 10
for higher bases we run out of symbols to write the numbers with, so we just make more
obtuse pebbleBOT
@earnest mist Has your question been resolved?
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
patent eagle
What is the formula to solve for intersection of events?
obtuse pebbleBOT
What is the formula to solve for intersection of events?
patent eagle
So i have P(A), P(B), P(AUB) as given
I tried to do P(A)•P(B) and got 0.195
Im just not sure if its correct
brisk grove
Well, no
The events are dependent, since P(A) + P(B) doesn't equal P(A or B)
Note that:
P(A or B) = P(A) + P(B) - P(A and B)
Try plugging in the values
patent eagle
Wait so if P(A)+P(A) doesnt equal P(A or B) its dependet?
If its equal then its independent?
obtuse pebbleBOT
@patent eagle Has your question been resolved?
glass valve
obtuse pebbleBOT
copper latch
hint: $x^{-a} = \frac {1} {x^{a}}$
glass valve
hint: $x^{-a} = \frac {1} {x^{a}}$
Question num 5?
copper latch
Ya
copper latch
Hmm well that will be good idea
brisk grove
like this
copper latch
Ya
sour lantern
But how does that apply on question number 5?
the denominator is incorrect
after you correct it cancel out and you should get a simplified form
obtuse pebbleBOT
@glass valve Has your question been resolved?
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
umbral yacht
inverse fourier transform of 1
obtuse pebbleBOT
inverse fourier transform of 1
umbral yacht
Can someone help me on how to solve the inverse fourier transform of 1?
obtuse pebbleBOT
@umbral yacht Has your question been resolved?
graceful silo
<@&286206848099549185>
novel storm
I ended up applying logs to get
log(y) = log(A) +xlog(k)
which the the equation of the line of the form y=mx+c
and from the graph I plotted
I found the y intercept to be 20
But how do I find the values of A and K ?
every value of A and K I find, seem to be incorrect so far
obtuse pebbleBOT
I ended up applying logs to get
log(y) = log(A) +xlog(k)
which the the equation...
craggy flame
@novel storm One strategy would be to:
Calculate K first, then calculate A.
Do you have any suggestion on how to do that?
novel storm
I know that log(A) is the y intercept
and the estimated y intercept is 20
so is it that A would be e^20?
or would A itself be 20?
like I said
I have attempted it multiple times
and every value of A and K i get seem to be off
craggy flame
You are analysing this:
log(y) = log(A) +xlog(k)
Or this:
y=Ak^x
It depends on what you are doing... could you show your calculations (or explain how you calculated A)?
novel storm
part one of the question stated to to express y=Ak^x in a form suitable for drawing a straight line graph
so I applied logs and got log(y) = log(A) +xlog(k)
which is of the form y=mx+c (the equation of a straight line)
and I plotted the graph
but I honestly don't know how to estimate the values of A and k
craggy flame
How did you calculate the intercept? The 20 you mentioned before
novel storm
the question said to estimate the intercept from the graph
I estimated that the y intercept would be around 20
craggy flame
Try ploting the log(y) chart? How does that looks?
novel storm
craggy flame
That looks better, right?
novel storm
yes, yes it does
craggy flame
Based on this, you can estimate the intercept and m. Those will produce something like log(y) = A + x * m ... That m is the log(k). You can go back to the original equation from that.
split radish
Hi, does this calcul is possible ? ((-4 - (-4)) / 4) - (-4) = 4
obtuse pebbleBOT
Hi, does this calcul is possible ? ((-4 - (-4)) / 4) - (-4) = 4
balmy mortar
,calc ((-4 - (-4)) / 4) - (-4)
warm shaleBOT
Result:
4
yes but are we allowed to divibe 0 by 4 ?
timid silo
((-4 - (-4)) / 4) - (-4) = 4
((-4 + 4)) / 4) - (-4) = 4
(0 / 4) - (-4) = 4
0 - (-4) = 4
0 + 4 = 4
4=4
hidden wigeon
you can divide 0 by 4
you just can't divde by 0
so 0/4 is perfectly fine but 4/0 is not
split radish
So this calcul is ok ?
timid silo
Yes its fine
hidden wigeon
just think of it like "i can distribute nothing to 4 people, but i can't distribute 4 things to nothing"
scarlet silo
Can I ask for help on probability?
obtuse pebbleBOT
Can I ask for help on probability?
scarlet silo
gilded needle
do you have any thoughts on these questions? which ones are you having trouble with?
obtuse pebbleBOT
@scarlet silo Has your question been resolved?
thin grove
For a certain company, the cost for producing x items is 50x+300 and the revenue for selling x items is 90x−0.5x2.
obtuse pebbleBOT
For a certain company, the cost for producing x items is 50x+300 and the revenue...
thin grove
My problem is with equation setup
thin grove
Part a: Set up an expression for the profit from producing and selling x items. We assume that the company sells all of the items that it produces.
Part b: Find two values of x that will create a profit of $50.
drowsy girder
Profit is how much you earned - how much you lost
thin grove
so The problem would be (50x + 300) - (90x-0.5x2) then
drowsy girder
Production i think
thin grove
so switch them around
timid silo
Yes
timid silo
So is the part b more clear now as well?
thin grove
yes
timid silo
Great
obtuse pebbleBOT
@thin grove Has your question been resolved?
fading ivy
What number corresponds to 3489 in the second column?
obtuse pebbleBOT
What number corresponds to 3489 in the second column?
polar elbow
is this like a riddle or what
fading ivy
I just can't find the relationship Q-Q
fading ivy
is this like a riddle or what
A mathematic problem based in logic ¿)
idk i see this in a random page
fading ivy
.close
strong vale
obtuse pebbleBOT
strong vale
To solve this, I said that there are $\frac{30 \times 29 \times 28 \times 40 \times 39 \times 38 \times 37}{7!}$ ways they can form a comittee
warm shaleBOT
azeem321
strong vale
I divided by 7! because the 7 people can arranged in that many different ways. so to account for that i divided by 7!
this is wrong however
waxen otter
Yeah, it's counting it wrong.
Think about, in how many ways can you choose 3 men out of 30 and 4 women out of 40.
strong vale
Yeah, it's counting it wrong.
Think about, in how many ways can you choose 3 men...
That would be $\frac{30 \times 29 \times 28}{3!}$ and $\frac{40 \times 39 \times 38 \times 37}{4!}$
warm shaleBOT
azeem321
strong vale
Now multiply them together and you've solved it
ok, thx. but why was my initial approach wrong? It seems i got the numerator correct, but divide by the wrong thing. don't we have to divide by 7! to get rid of all the overcounts that arise from the permutations?
since 7 people can be arranged in 7! different ways
main lodge
I'm sorry I dont know how to answer that
waxen otter
You didn't overcount. Those seven in total people are chosen from two different groups.
So we counted how many ways we can get the desired number of men and women out of those two groups
The final multiplication here means that selection from both groups happen simultaneously, which in total gives 7 people
final citrus
what's missing? how do i make only the bounded region shaded
obtuse pebbleBOT
what's missing? how do i make only the bounded region shaded
short spruce
that might be more of a google question
tardy epoch
what's missing? how do i make only the bounded region shaded
bounded by what?
final citrus
by f(y), g(y) and x=-1
obtuse pebbleBOT
@final citrus Has your question been resolved?
safe spade
assumming you want nly the overlap of the gray and red area to be shaded?
obtuse pebbleBOT
@final citrus Has your question been resolved?
harsh nacelle
anyone good at cal 2?
obtuse pebbleBOT
anyone good at cal 2?
nocturne minnow
anyone good at cal 2?
Don't ask if anyone is good at a topic. Just post the question you are stuck on, and what you attempted and someone who can help will come by
obtuse pebbleBOT
@harsh nacelle Has your question been resolved?
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
tacit bronze
Doing old exams and this refers to numerical methods which is a course i did way back and dont remember anything of.. Any help?
obtuse pebbleBOT
Doing old exams and this refers to numerical methods which is a course i did way...
@tacit bronze Has your question been resolved?
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
kind elm
I don't understand what the underlined part means.
obtuse pebbleBOT
I don't understand what the underlined part means.
worthy comet
it means: $\sqrt{\dots}$ is never negative. So for all x the term $\sqrt{2x-1}$ is always nonnegative. But then it is never -5. So there is no solution (and the whole calculation wouldn't be necessary)
warm shaleBOT
Alexander42
low osprey
obtuse pebbleBOT
@low osprey Has your question been resolved?
obtuse pebbleBOT
@low osprey Has your question been resolved?
timid silo
Can someone help me with 17
obtuse pebbleBOT
Can someone help me with 17
timid silo
I also don’t know what to do
I understand the lessons
But some of the problems I just can’t do
I’m thinking maybe translating the question into propositional logic?
But how would something equal the universal set
obtuse pebbleBOT
@timid silo Has your question been resolved?
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
rocky cosmos
A cube of metal weighs 6 kg. How much does a cube weigh (the same metal) where the sides are twice as long as the original cube?
obtuse pebbleBOT
A cube of metal weighs 6 kg. How much does a cube weigh (the same metal) where t...
rocky cosmos
I know that the volume of a cube is = the sides³
rocky cosmos
Yeah
obsidian isle
Then that means its volume would also be 1
rocky cosmos
Yeah
obsidian isle
So its density is 6kg/m^3
rocky cosmos
Ok
obsidian isle
Now find the volume of a cube with side length 2
fallen mantle
basically x^3 = 6
(2x)^3 = ?
rocky cosmos
Where x is the side length?
spiral maple
Volume isn't mass, so no
rocky cosmos
So what do we know about the mass from knowing the formula of the volume?
obsidian isle
Density.
spiral maple
You know it's density
rocky cosmos
What is the density?
fallen mantle
since same metal so density is same
density of old cube = density of new cube
m/V = m/V
6/x^3 = m/(2x)^3
rocky cosmos
Yeah I called it p
spiral maple
Rho but yes
obsidian isle
The density is known
To be fair it's not. We have to make the assumption that this is a unit cube.
rocky cosmos
So the density is doubled?
spiral maple
No??
fallen mantle
So the density is doubled?
no
since same metal so density is same
density of old cube = density of new cube
hence
old mass/old Volume = new mass/new Volume
6/x^3 = m/(2x)^3
rocky cosmos
Okay
spiral maple
hence
old mass/old Volume = new mass/new Volume
6/x^3 = m/(2x)^3
Could be written better
rocky cosmos
So the side length = x, and it's doubled so 2x
spiral maple
Yes.
rocky cosmos
And this is for three sides, so the new volume is 8x^3
spiral maple
Yes
rocky cosmos
since same metal so density is same
density of old cube = density of new cube
m/...
Thanks this was useful
.close
obtuse pebbleBOT
obtuse pebbleBOT
Available help channel!
random hatch
Quick question, if I multiply both sides of 3^x - 3/3^x = -2 by 3^x I'll get 3^x -3 = -2*3^x right?
obtuse pebbleBOT
Quick question, if I multiply both sides of 3^x - 3/3^x = -2 by 3^x I'll get 3^x...
high lily
no
random hatch
Oh right my bad, (3^x)^2 -3 = -2*3^x , right?
high lily
yes
obtuse pebbleBOT
random hatch
.reopen
obtuse pebbleBOT
✅
random hatch
Actually one more thing if x^2=t then t is greater or equal to 0 not just greater, right?
uncut galleon
if x = 0, t = 0 so yeah
obtuse pebbleBOT
random hatch
.reopen
obtuse pebbleBOT
✅
random hatch
Okay I'm stupid I dunno where I took that from, it's actually 3^x not x^2, then it is actually just greater then 0, right?
obtuse pebbleBOT
floral narwhal
Your question is unspecific. Which aspect do you want to ask about?
From a vector space point of view, both spaces satisfy the same set of axioms for addition and scalar multiplication
obtuse pebbleBOT
@nova marsh Has your question been resolved?
obtuse pebbleBOT
Available help channel!
olive isle
I have 16 slots, I want to know the probability that 3 or more objects that have a 3% chance per tile appear. (so if it's with only one tile with one of these rare objects it's a 3% chance)
There is also another object with an 80% chance per tile.
I'm stuck at the fact that if I used Pascal's triangle it would only be for a case with 3 rare objects and for example 10 common objects, won't combine the other cases that have 9 or 11 common objects.
obtuse pebbleBOT
I have 16 slots, I want to know the probability that 3 or more objects that have...
@olive isle Has your question been resolved?
misty terrace
I have 16 slots, I want to know the probability that 3 or more objects that have...
so >= 3 successes out of 16 trials with each a probability of 0.03 (and 0.80 in another case)?
humble aspen
I need help translating these sentences into a predicate logic forumla
obtuse pebbleBOT
I need help translating these sentences into a predicate logic forumla
royal solar
you should use the "for all" and "exists"
why would you need for all ?
timid silo
doesnt it carry the same connotation of if?
royal solar
doesnt it carry the same connotation of if?
oh yeah, true you could simply use a implies b right
timid silo
oh yeah, true you could simply use a implies b right
id say so
for all dragon has a child
exists dragon is happy
royal solar
have you used if a, then b
translates to a implies b
timid silo
how does this sounds?
humble aspen
idk what signs i need however ahaha
royal solar
-> if you were to use a implies b
timid silo
there exists
royal solar
if it works, it works ig
timid silo
personally find it excessive
tis' used in epsilon delta definition
might need this in such questions i guess
humble aspen
∀ dragon → childof → true ≡ happy
timid silo
is this math or coding lol
humble aspen
math
timid silo
yeah i think thats right
obtuse pebbleBOT
@humble aspen Has your question been resolved?
acoustic pawn
Are physics questions welcome too if they're mainly about the math being used?
(I'll go ahead and ask anyway, if I should remove it please do tell me)
obtuse pebbleBOT
Are physics questions welcome too if they're mainly about the math being used?
...
acoustic pawn
Why does he integrate?
video-link: https://www.youtube.com/watch?v=QpVxj3XrLgk&list=PLyQSN7X0ro2314mKyUiOILaOC2hk6Pc3j&index=5
wary vigil
The electric potential is the negative integral from a reference point to the point you want to find of the electric field
$-\int_{\infty}^{\vec{r}} \vec{E} \ d\vec{l}$
warm shaleBOT
Katharine
wary vigil
often the reference point is set at infinity
acoustic pawn
Oh i didnt know that, i thought it was defined as the potential energy per unit charge so Q/(4.pi.epsilon.R)
(also ig this is a physics question after all since now im conceptually confused
warm shaleBOT
Katharine
warm shaleBOT
Katharine
wary vigil
btw you can rewrite it as the potential energy per charge
acoustic pawn
Hmm i dont really get it yet but i'm gonna look at it again tommorow
thanks for the help!
obtuse pebbleBOT
Available help channel!
dusky mantle
obtuse pebbleBOT
nocturne minnow
<@&286206848099549185>
You have to wait at least 15 minutes before pinging helpers
dusky mantle
oh
warm pine
what is abs(y1-y2) for C (x1,y1) and another point P (-1,y2)?
warm pine
pls use another help channel
warm pine
I don't know
C has coords (-4,5)
dusky mantle
I have just been stuck on it for 1 hour
yeah i know the coords on C
its just part B
i cant get my head around
like part B of the coords
i don't know
warm pine
I'll say it means to translate the whole figure so every point (x1,y1) becomes (x1-1,y1-6)
dusky mantle
@warm pine so is the part higlighted -4,5
warm pine
nah
C is (-4,5)
abs(-4-(-1))=abs(-3)=3
so the x of C' is (-1+3)=2
so C' is (2,5)
do you get it
dusky mantle
so what is part B if part A is (2,5)
warm pine
try to explain yourself to me how we can get C;
warm pine
lemme give you B first
(2-1,5-6)=(1,-1)
However, I need you to try to explain how to go from C to C'
dusky mantle
ok
@warm pine nah i still am stuck i think if u give me B ill probably have my head grasped around how we get to the answer
warm pine
ok.
dusky mantle
cuz im so lost
dusky mantle
yeah
warm pine
let's not reflect in x=-1 first
dusky mantle
ok
warm pine
what is the coordinates if C is reflected in x=0
warm pine
no
if a point (x,y) is reflected in x=0 then it becomes (-x,y)
this can be expressed in two ways
dusky mantle
ok
warm pine
the first one is of course (-x,y)
the second one is (x-2x,y)
and if now we're reflecting in x=-1
we would do (x+2(abs(-1-x)),y)
dusky mantle
okay....
warm shaleBOT
dusky mantle
(-4+2(-1--4)
warm pine
,w (-4+2(-1--4))
warm shaleBOT
dusky mantle
ohh
warm pine
<@!892725065127444480> so is the part higlighted -4,5
has anyone explained to you what is the (-1,-6) notation in b
warm pine
good
dusky mantle
but
warm pine
let's now assume the notation means (-1,-6)
dusky mantle
ok
warm pine
since it's not rotation it's translation
x-1 and y-6
so it's (2-1,5-6) which is (1,-1)
dusky mantle
oh u explained that so
easily
.
wait so
is this my answers
lemme type e
m
?
or no
@warm pine
warm pine
that should be correct
dusky mantle
DAM
ITS RIGHT
THANKS BRO I APPRECIATE IT SO MUCH
I WAS STUCK ON IT FROM 12AM
AND ITS 2.17AM
UR EXPLANATION HELPED
@warm pine last question
warm pine
no
warm pine
good
dusky mantle
and irregular isnt
dusky mantle
but i dont understand which shape
warm pine
remember, don't assume anything you're not given
dusky mantle
im messing up on
warm pine
is A a polygon
warm pine
in fact B is a polygon
dusky mantle
D isnt?
warm pine
D is
dusky mantle
b is?
dusky mantle
e is neither
warm pine
exactly
dusky mantle
is A a polygon
A isnt
warm pine
a is a polygon
warm pine
everything except E are polygons
good
I suppose you can close this now, I'm in foot drill online class
and I'm supposed to be paying full attention
warm pine
.close
obtuse pebbleBOT
dusky mantle
thanks tho
obtuse pebbleBOT
Available help channel!
pastel lichen
how do i find a critical point if the domain is x cannot equal zero and f(x) =10x^3 +6/x
obtuse pebbleBOT
how do i find a critical point if the domain is x cannot equal zero and f(x) =1...
waxen otter
What do you mean by critical point?
pastel lichen
A critical point (or number) of a function f(x) is a number c in the domain of f(x) such that
f '(c) = 0
or does not exist. What rules for derivatives are used to find
f '(x)?
that i gues XD
astral ivy
how do i find a critical point if the domain is x cannot equal zero and f(x) =1...
So are you having trouble finding f’(x)?
pastel lichen
well i know f'(x)
astral ivy
What is it
pastel lichen
its (30x^4-6)/x^2
astral ivy
So now you’re looking for x values that either make this undefined or make it 0
The only thing for undefined is x = 0, right
pastel lichen
so do i just plug random numbers into x ?
astral ivy
No lol
pastel lichen
how wouldi make this zero XD besideds plugging in zero ?
astral ivy
You set it equal to 0
pastel lichen
ooo
pastel lichen
0 =30x^4-6/x^2 ?
astral ivy
Yeah
pastel lichen
mkay now i got 2 xs